#help-38
1 messages · Page 124 of 1
now what (𝔸dωn𝓲²s)
you had a_n correctly, what happened
what happens as n grows pretty big?
,, \quad 0 < \frac{1}{\sqrt{2n + 3}} < \frac{1}{\sqrt{2n+1}}
you want to do that without hte (-1)^n
0
a_n is the part without the (-1)^n
i need more hints
^ correct, so a_n is decreasing
calc_and_real_anal
now show that it decreases to limit zero
how
what happens to the denominator as n->inf?
infty
approaches 0
wdym
if you prove this algebraically yet, then yea
but how
that's what i mean by "applies"
1 is not proven yet
prove it
how
didn't you show that above
^ here
that's not so obv
is this enough justification?
denominator gets bigger --> fraction gets smaller
well it really depends on the context
whether it's enough justification
i would err on being explicit if you're being graded on this
usually you you would wanna work with this until you get a true statement out like n > 1 or something
at least that was the case for me
how to do that
also this comes from squaring both sides and multiply by -1
and the fact that 1/x is decreasing
okay a moment
,, 0 < \frac{1}{\sqrt{2n + 3}} < \frac{1}{\sqrt{2n+1}} \ 0 < \frac{1}{2n + 3} < \frac{1}{2n+1}
calc_and_real_anal
how do I flip the fractions
multiply both sides by (2n+3)(2n+1), which is positive so the < doesn't flip
positive because n >= 1
,, 0 < \frac{1}{2n + 3}\cdot \frac{(2n + 3)(2n+1)}{(2n + 3)(2n+1)} < \frac{1}{2n+1} \cdot \frac{(2n + 3)(2n+1)}{(2n + 3)(2n+1)}
,, 0 < \frac{1}{2n+1} < \frac{2n+3}{(2n+1)^2}
calc_and_real_anal
wha
^ (2n+3)(2n+1) (the product of the two), not (2n+3) / (2n+1)
,, 0 < \frac{1}{2n + 3} < \frac{1}{2n+1} \quad \big | \cdot (2n+3)(2n+1)
this?
noo
no wayyy
what is that big |
commando line
what next operation we are going to do
| ... means we are going to do ... in the equation/inequality
just a notation
how can we just multiply like that (2n+3)(2n+1) wtf
now that I see this maybe ()^-1 is easier
haha noo
this the common factor
,, 0 < \frac{1}{2n + 3} < \frac{1}{2n+1} \ 0 < \frac{(2n+3)(2n+1)}{2n+3} < \frac{(2n+3)(2n+1)}{2n+1} \ 0 < (2n+1) < (2n+3)
calc_and_real_anal
If you have $$\frac{1}{a} \leq \frac{1}{b}$$ then multiply by the common factor $ab$ on both sides and assume $ab > 0$ yields to $$\frac{1}{a} \cdot ab \leq \frac{1}{b} \cdot ab \implies b \leq a$$
now what (𝔸dωn𝓲²s)
true dat
and counts up integerwise
okay thanks
now what
how can we continue
I mean
,, 0 < \frac{1}{2n + 3} < \frac{1}{2n+1} \ 0 < \frac{(2n+3)(2n+1)}{2n+3} < \frac{(2n+3)(2n+1)}{2n+1} \ -2n < 1 < 3
how about su subtract just 2n on bth sides?
yes
calc_and_real_anal
yes
,, n > \frac{-1}{2} > \frac{-3}{2}
calc_and_real_anal
so for the inequality to hold truth
this has to be
which is the case
our n is at least 1
and that's far greater than -1/2 and even -3/2
and n just gets bigger so you proved
Closed by @urban copper
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only chartbit can use this

why
I've been using it for like 2 weeks now
oh i just associate chartbit with these always haha
fair enough lmao
✅
find $f$ with continuous derivative in $\mathbb{R}$ such that $\\ \begin{cases}f(0) &= 1 \f^{8}(x)f'(x) &= 8x^3 e^{2x^2} \quad , \forall x \in \mathbb{R} \end{cases}$
calc_and_real_anal
chain rule on the left side, as in a similiar example some days ago.
No no, that's the
you're thinking of 
chain rule?
its the same way to solve, the numbers differ.
how do I figure out the derivative of f^8(x)?
ohh a moment
let h(x) = x^8
h(f(x)) = f^8(x)
its function composition
take h(x) = x^9.
yes of course, the left side (f^8 times f') is the derivative. as in the last example (we needed f^3)
calc_and_real_anal
no but f^8 means f . f . f . f . f . f . f . f btw
its not referringg to the 8th derivative btw
I forgot to mention mb
i know. the derivative of x^9 is 9 times x^8. but anyway. take my hint or let it be. good luck.
,, \frac{1}{9} \cdot \frac{d}{dx} {x^9} = x^8
calc_and_real_anal
h(f(x)) = f^8(x)
i am thinking of all cat appearances lol
$\int f^8f' dx = \frac{f^9}{9}+C$
Boi
what
true
oh nvm thats function composition not exponent
is f^8(x) here f(x) * f(x) * f(x) ... or f(f(f( ... ?
ah I see
f . f . f .f .f . f . f .f
the former
oh okay then it still stands what i said
let f(x) = u; then f'(x)dx = du, so that f^8(x) f'(x) dx = u^8 du
$\int f^8(x)f'(x)dx = \int u^8 du = \frac{u^9}{9}+C = \frac{f^9(x)}{9} + C$
Boi
,, \frac{f^9(x)}{9} + C = \int 8x^3 e^{2x^2} dx
calc_and_real_anal
you need to simplify the integral on the right side using u-sub as well
u = 2x^2
du = 4x dx
yep
,, \frac{f^9(x)}{9} + C = \int ue^{u} du
thats right
calc_and_real_anal
,, \int f \cdot g' dx = f \cdot g - \int f' \cdot g dx
calc_and_real_anal
calc_and_real_anal
,, e^{x}(x - 1)
calc_and_real_anal
,, \frac{f^9(x)}{9} = e^{2x^2}(2x^2-1) + C
now you let x = 0 and find C
since f(0) = 1 is given, it shouldn't be too difficult
,, \frac{1}{9} = C
oh wait nope you made a mistake
the right side here should be e^u(u-1), not e^x(x-1)
since u = 2x^2 is your substitution you must remember to resubstitute
u = 2x^2
calc_and_real_anal
,, \frac{1}{9} = C
calc_and_real_anal
,, \frac{f^9(x)}{9} = e^{2x^2}(2x^2-1) + \frac{1}{9}
calc_and_real_anal
,, f(x) = \sqrt[9]{9e^{2x^2}(2x^2-1) + 1}
calc_and_real_anal
,w Solve[D[(9E^(2x^2)(2x^2-1)+1)^(1/9), x] == 8x^3E^(2x^2)/((9E^(2x^2)(2*x^2-1)+1)^(8/9)), x]
.close
using the identity$\sum_{n = 0}^{\infty} x^n = \frac{1}{1-x} \quad , |x| < 1$ deduce the formula $\ 1 + 2x + 4x^2 + . . . + 2^n \cdot x^n + . . . = \frac{1}{1-2x} \quad , |x| < \frac{1}{2}$
calc_and_real_anal
just replace x with 2x?
more hints
.close
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Any hints for this?: If $G \neq {e}$ acts properly discontinuously on $\mathbb{R}$, show that $G \approx \mathbb{Z}$
CoffeeMan
@barren ocean Has your question been resolved?
@barren ocean Has your question been resolved?
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Can someone tell me what I did wrong??
/how to fix it
omg
Omg ur right 😭😭 I thouight i was multiplying for some reason
Tyyyy
.close
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Cos(cosx) min and max value
Pls help
Do you know the maximum and the minimum value of $cos \theta$
Sufferrrrring rn D:
1 and -1 i think
No, you don’t need to memorize it
1 at 0 degrees
It’s not degree, it’s cosine1
What’s the approximate value of pi/2?
90 degree i think
I don't know teacher hadn't teach me that
I am little weak in maths so I granted help
Although my dad is a maths teacher
Yes
3.14/2 is 1.5~, do you agree?
Yeah approximately
Sorry i did not get the answer
Cospi/2 is 0 and cos(-pi/2) is also zero
Then explain and give the answer
P
Ls
Pls
I request
I need the explanation and answer
It is
Is this a test?
No i was solving a problem set and this problem appeared
I see
How about I just give you how to approach it
And you’ll figure it out yourself
Ok
Alr

You shouldn’t find the minimum and the maximum with the concept "with what I plug in, I’ll get the maximum and the minimum"
Instead, see the cosine on the inside as K
-1<K<1
No, I’m not joking lol
Give some more hints
There you’ll find cosineK -1<K<1
That’s all you need to know for approaching this question
What does it mean cos function inside a cos function i mean cos(cosx)
wdym
I did mention it
See cosx as K
Oh
-1 to 1 ?
That’s how you get this graph
I am thinking something
Cosx max value is 1
Then cosk max value at 90 is 1
And minimum is cos1
Pls don't angry i am weak inteligent
If this answer gets wrong
I just think about it and understand this
No, why would I be angry lol
Is my answer also?
I wouldn’t even be here if I would get irritated by helpee’s question
I understand
My answer?
CosK has the maximum value when K=0
Because cos0=1
That is 1
Your minimum is correct
And minimum cos1 at k = 90
The minimum is cos1, but at that moment, k≠90
Yeah you are right
If you are done with this channel, please mark your problem as solved by typing .close
It take a little long time as I am fool but ok bye sir you also have a nice one
.close
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I learning desomos and don't understand what the meaning of the f(x) someone can teach what f mean?
The f(x) is pretty much just a way to name the function, and for most intents and purposes, is the exact same thing as y
and with that, f(x) and g(x) are two perfectly valid ways to name a function
what's inside the f(x) is what you're trying to solve for
take the function f(x)=2x+6,
say you want to solve for when the x-axis equals 10
To do this, you would use f(10)=2x+6
with Desmos, as far as I'm aware, I don't think you'll be using it too much in that way, but it'd still be useful to know for later when you start getting to use function more often
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just want to check my answers and i have some additional questions on this
\documentclass{article}\usepackage{amsmath}\begin{document}The equations of motion for the two-degree-of-freedom system are given by:For the sprung mass ( m_S ):\begin{equation}m_S \ddot{x}S = -k{\text{eq}} (x_S - x_U) - b_{\text{eq}} (\dot{x}S - \dot{x}U) + f{b{\text{eq}}}\end{equation}And for the unsprung mass ( m_U ):\begin{equation}m_U \ddot{x}U = k{\text{eq}} (x_S - x_U) + b_{\text{eq}} (\dot{x}_S - \dot{x}_U) - k_T (x_U - x_R) + f_T\end{equation}\end{document}
luke1
Compile Error! Click the
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do these equations seem correct
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Yes linear independent
We need scaler so that i can represet one vector in terms of another
no idea , sorry
for the first part, you want to find a scalar c such that $\alpha = \beta c$
Bungo
looking at just the first component you see that you need $c = 1+i$
Bungo
so now just check that $2i = c(1+i)$
Bungo
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Could someone help me with this question
@mossy cove Has your question been resolved?
ok... consider k = 0, do you agree that it is true?
what makes that true?
what about -100?
what makes that false?
@mossy cove Has your question been resolved?
Ill come back to the question later. Im gonna sleep now
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Any good books for university level calculus and statistics ?
I hope this is the correct channel if not please redirect me to the channel where I can ask this. Ping or reply with ping on so I get notified.
Thanking You in advance.
@night estuary Has your question been resolved?
okie
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My b ii) is wrong can any1 explain why
It’s actually 66
,rotate
think about what can yield a term of order x^3
you can get 2 * term in x^3 - 5x * term in x^2 + x^2 * term in x
I'll do the first term for you. So $2 \cdot \binom{11}{3} \left(x\right)^3 \left(1\right)^8$
45
@graceful zenith
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Yes please
ok one sec
Okayyy
What is that
All of that
Uhh
What is gradient
What
0
Huh?
Gradient and slope is the same thing
Yea
In ur question its gradient
Mb if I got u confused
Ok so u want me to use the term gradient or slope
In this case I’ll use gradient since the question ask
Okay okay
Oh okay okay
What is that
Wait Sandra do yk how to read coordinates of ur points
What is rise over run
No?
What is that
Bro
oh
U understand?
Why is it so blurry
Yes yes
I know that
Huh
Girl u rise upwards
What does rise and run mean?
then you put the value of rise over run
So u count upwards
Bro what
do you see how he got 3 and 8?
What is rise and run
yeah
AHH
you can count the squares on the grid
Can u re word that
We have a graph yes
IS IT 7
It’s 6
Huh
WHOOPS
How did u get that
it’s 6 I counted wrong
What is the 7 for?
😂
Is that rise?
Ur making her so confused
I MEANT 6
ok here
so on a grid sandra
So what does that do
you know how thers squares on the grid
Just fill in the values
No I don’!!
what the hell
Don’t
Ofc u don’t
Flipping yes I do
ok
Where
now you count how high the triangle goes
What do I solve
by counting the squares
Okay one sec guys
Oh okay okay
So do I count that small thing?
What small thing
The little thing o the side
???
Yk how for one of the squares
Yes
HUH?
WHAT GRADE R U
BRO
STOP
BROTHER
so you foun dout
What formula
that rise = 8 and run = 4
Rise/run
Oh okay
now put it in the formula Rise
Run
Wait so 8/4?
GOOD JOB
Yes
2?
Oh
Brother
Yes it does
right
NO
Oh
Yall need to stop
RISE IS ON TOO
What?
Everyone stop
ok
CAUSE U RISE ON TOO
And just stop msging
soryr
Y’all are confusing me
STOP
STOP
STOP
Or hee
HIM?
Stop
HIM?
sandra if you get pressed im gonna lose my shits
Bro
What u mean
Yes
Cause yall also don’t understand
WHAT
They making me not wanna end it all
OH MY GYAT
Or I will get super super sad 😞
How old r u guys
im 14
19
Nuh uh
yep
Why u so young
mummy told me not to tell people on internet my age
19? Dang u learning this late 💀
Yeah…
Ok
Your 14
no
Got pulled back
Bro
I don’t know u gf
shes in grade 9
Tf
The Evan kid is my brother and the shrunk my sister
Me and Evan r twins
We one big happy family
just fucking do your maths
Yeah
That why we both 14
Yeahhh
now hes gone
I’m the oldest
Is he actually
STOP ACTUALLY?
stfu and he might come back
Please don’t leave
prolly not anymore
I really need help
He is trust
Bro are u happy now
I’m gonna fail
I love u perseus ❤️
YAY
SEE
HES BACK
Wait how did u get the 1/2?
How do u know when to stop counting the small part
persues put it on a grid
and show her
how to fucking count the grid
the triangles drawn on
Bro you don’t have to be so moody
cuz the school dont give you the value of rise or run they put it on a grid
Because that’s what 2/4 is.
and you have to find it
It’s 1/2 or also known as 0.5
and they teach you to count the grid squares
TELL ME PERSEUS
No it doesn’t
How did u get that
Did u divide the 2 and 4?
Line
Divide the 2 by 4
ya I give up
NO PLEASE
I’m literally telling dad to get u a tutor
Don’t
Where u guys from
No actuals Perseus can u explain why certain small parts of the small don’t count
This ain’t make no sense that u don’t get this 💀
Like how do u know when to stop counting it
Amirca
YOUR IN GRADE 10
ARE YOU SPECIAL
SAME
Jesus
WHEN DO U STOP COUNTING ?
Do I bring a calculator to my test?
I don’t think I have one
American education is mad
ask the teacher for one
What am I ment to do
its australian
Brother I was learning this at 7
The teacher don’t have
lmao
No way
its not that hard sandra
How many yrs did u stay back
WHY DOESNT THIS SQAURE COUNT
What
Then u explain it
Oh my god
TH EUCK
I DID
No u didnt
ok so
here
Does that small thing count??
wait
Good luck
ill explain one sec
I THINK IT COUNTS
Evan not gonna know
WHY FOESNT A SMALL BIT OF SWAURE DONT COUNT
Ya good luck
Are u leaving 😞
2/6
AHAHAHAHAH
2/6 is 1/3
Wait
U Simplifi the fraction
surley not me :(
Both numbers go into 2
WHAT DO I DO TO GET 1/3
So 2/2 is 1
You
6/2 is 3
So 1/3
Bro just put in ur calculator 2/6
That’s 6 squares
GUYS I THINK I BECAME STUPID LIKE SANDRA TALKING TO HER
I COUNTED IT WRONG
oh all g
AHAHAHA
This is crazy
what?
EVAN REALLY THOUGHT
bro I can hear Evan in his room crying cause he got it wrong
How do I get the fucking 1/3
Shush twin bro
Same
BRO
What the flip
your mistake
JUSY PUT IT IN UR CALCULTOR
but sure
?
I don’t have a calculator
Crazy crazy crazy
No persuesu u gotta help
What r the two x axis bunbers
Trust ill learn
SANDRA
Ok
WHAT?
WHAT R THE 2 X AXIS NUMBERS
What?
Yo
8 and 2
Okay I’m sorry
this guys finished helping other people with harder shit
And then u divide by 2
before you understand rise over run
So the first part of midpoint is 5
jeneeta shut the fuck up
Now u gotta find second part
No ur going too fast
let the other guy do it
Don’t Go so fast
OH MY GYAT
she came to this server to get help from another person
OKAY THEN
ya gl
Persuadus can u try
Filp u guys
bye ybe
Then shut up
Okay okay
Okay okay
This is a graph
Okay okay
Yes
Yayyy
Okay
I’m done
HELO ME
💀
thats 5
hall someone else joined
on the x axis
@harsh surge 🙏🙏🙏🙏🙏
please
OH
faiy
okayyy
you got both x and y right
There
good joooob
Th Ak you
Ok
OKAY EVACHI SHUSH NOW
was until you talked
YALL I almost got it
Yes yes
What?
When I connect to plints
I’m tweaking