help-38

[delicate bobcat]

which is the numerator

[marsh burrow]

yeah

ur right

now makes a lot more sense

[delicate bobcat]

and then it's ln(y^2 + 4), good

[marsh burrow]

let me try again

[delicate bobcat]

you did it right

but

since you forgot about 2

2 * 1/2 would give 1

so

[marsh burrow]

wolfram said some other answer tho

[delicate bobcat]

Ah I see

when doing e^() on RHS

you made a mistake

e^(ln(x+1) + C) = e^(ln(x+1)) * e^C

not +

= (x+1)e^C

so finally

y^2 + 4 = (x+1)e^C

[marsh burrow]

why times?

[delicate bobcat]

y = sqrt((x+1)e^C - 4)

[delicate bobcat]

a^(n+m) = a^n * a^m

[marsh burrow]

oh, right

so basic yet i forgot about it

my bad

[delicate bobcat]

then the result is same

[marsh burrow]

ok so

if y(0) = 5^(1/2)

that means that 5 = e^C -4

right?

[delicate bobcat]

exactly

[marsh burrow]

but then C is?

ln of 9

right?

[delicate bobcat]

yes, but e^C is sufficient

[marsh burrow]

how do i calculate this then?

[delicate bobcat]

you have y(x) now

so you can calculate its derivatives and values, whatever you want

[marsh burrow]

i just dont understand the first one

or

wait

give me a second to solve

and can i show after?

[delicate bobcat]

you understood y(0) and y(1) you don't understand?

[delicate bobcat]

yes, take your time

[marsh burrow]

Is this correct?

[delicate bobcat]

well, first of all

[marsh burrow]

my bad for the picture

[delicate bobcat]

$$y(x)=\sqrt{(x+1)e^C - 4}$$

[solid kiln]

Modus

[delicate bobcat]

and you said that e^C = 9, right?

[marsh burrow]

jesus ure good

[delicate bobcat]

substitute, calculate, simplify and then do y(1), y'(1) and y''(1)

(you could also use an equation given but I don't find it a good idea)

[marsh burrow]

if i just derive constans all of them would be o?

[delicate bobcat]

e^C = 9, then:
(x+1)*9 - 4 = 9(x+1) - 4 = 9x + 9 - 4 = 9x + 5

---> y(x) = sqrt(9x + 5)

[marsh burrow]

but if its y(1) dont i plug in the 1 instead of the x?

or i should not do that?

[delicate bobcat]

Yeah, you plug x = 1

[marsh burrow]

but when i derive, i derive this, right?

[delicate bobcat]

but into the y(x) = sqrt(9x-5) not into the previous versions

[delicate bobcat]

Derive? You mean take a derivative?

[marsh burrow]

yes

[delicate bobcat]

y(1) is not a derivative

firstly tell me what's y(1)

[marsh burrow]

so i have to do y'(x) and then plug in 1

[delicate bobcat]

y(x) you already have it

[marsh burrow]

a function:D

[marsh burrow]

y'(x)

[marsh burrow]

i dont really know

i mean, i know its a function, a basic one

[delicate bobcat]

no, a solution to a differential equation is a function not its derivative

[marsh burrow]

makes a lot of sense

[delicate bobcat]

well, maybe something easier at the beginning haha, if f(x) = x + 1 what's f(1)??

[marsh burrow]

f(1) is the solution to the general equation f(x)

a particular solution

[delicate bobcat]

We don't understand each other.
Forget about a differential equation

You've already solve it

[marsh burrow]

im sorry if im upseting you

[delicate bobcat]

That's fine

Sorry if I sound rude or something haha

[marsh burrow]

i lack basic knowledge of math and it shows, but at this point im to embarassed to ask

[delicate bobcat]

What we doing right know has nothing to do with a differential equations, even with derivatives

It's just a value of a function at a point

when they told you before that y(0) = sqrt(5) how did you know what did it mean?

y(1) is exactly same thing in fact

but you're supposed to calculate it and it's not given

[marsh burrow]

oh, i understand

sometimes its a bit harder to make the connection

can i show you one more exercise

if thats ok with you

[delicate bobcat]

but you know how to proceed with this one?

[marsh burrow]

yes, i just take the derrivative of the y'(x) and then plug in 1, and then i do the same with y''(x)

right?

[delicate bobcat]

yes, and y(1) is just y(1) = sqrt(9 * 1 + 5) = sqrt(14)

that's all 🙂

[delicate bobcat]

Yea, let's see

[marsh burrow]

you are a really great help

really

i have to write the differential characteristic system

i know that i have to take the derivative with respect to x, y, and z, right?

[delicate bobcat]

Huh, I'm not familiar with partial DE haha

[marsh burrow]

me neither, but i have my big exam tomorrow and i dont feel so prepared

[delicate bobcat]

Sorry, but I doubt I'll be able to help, maybe search on the internet or open a new channel and ask

[marsh burrow]

ok, i will

[delicate bobcat]

btw it doesn't seems so hard

and good luck with your exam!

[marsh burrow]

yeah, but after that i have some really questions like

to determine the primal integral?

or the integral curves

primitives, i think

not integrals

or

anyway, im gonna go now

take care

and thanks again

Is the answer that I got here correct?

.close

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[tight pecan]

Having trouble with the implication in red

[trim jolt]

@tight pecan Has your question been resolved?

[tight pecan]

<@&286206848099549185>

[cloud oyster]

.

[trail ingot]

look back at the definition of $h$. $$h = \frac{1}{2}(r- d(p,q))$$ implies $$r-d(p,q) \leq d(p,q)$$

[solid kiln]

slayla

[trail ingot]

$h$ is the min of $\frac{1}{2}(r- d(p,q))$ and $\frac{1}{2}d(p,q)$

[solid kiln]

slayla

[trail ingot]

so whichever one it is, the other one needs to be at least that

[tight pecan]

dsfklanfidfhnas

ooohhhh my gosh

thank you

not like this

[trail ingot]

haha

:3

[tight pecan]

I stared for long

thank you slayla

qwq

[trail ingot]

[tight pecan]

.close

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[wraith hinge]

,rccw

[wraith hinge]

you want 10?

[karmic shuttle]

Yes please

[wraith hinge]

!status

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3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[karmic shuttle]

2

[wraith hinge]

so

send what you have so far

[trail ingot]

[karmic shuttle]

Hello

.close

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[marsh hare]

I need to use these formulas i believe idkk

im rlly confused

[wraith hinge]

!status

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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[marsh hare]

1. ;p

i know how to use the formulas but idk HOW to apply it to the question

like thats what confuses me...

[hallow wren]

it should say somewhere close to the formula what each variable represents

[marsh hare]

yeah ik what each variable represents but idk how to use it for this world problem

[hallow wren]

its asking how much the car was worth originally, you know she paid 1500, then 450 per month for 4 years until it was paid up

[marsh hare]

yeah but she paid interest on it

[hallow wren]

so I guess you would use future value formula

[marsh hare]

so does the actual price of the car incude

the interest

[hallow wren]

you know how much she paid total

with interest

you're supposed to figure out how much she would have paid if she had just paid everything day 1

[sweet hare]

no

[marsh hare]

ok so

first should i do

A = 1500 ( 1 + 0.038 / 12)^48

?

[hallow spruce]

I wouldn't

[marsh hare]

i can send a pic of what i did

[hallow spruce]

At the time the car is purchased, Rachael pays some upfront and pays some in an annuity. You have to find the equivalent value if she paid everything at the start

[marsh hare]

wait what

[hallow spruce]

What about my message was unclear?

[marsh hare]

ok so how do i find the "equivalent value if she paid everything at the start"

what do i do

[hallow spruce]

One of your formulas describes this exact situation

She either pays an annuity over time, or she pays an equivalent lump sum beforehand

[marsh hare]

oh

so the present value formula

..?

[hallow spruce]

That's part of it

[hallow spruce]

The arithmetic seems fine, but this is valuing everything 4 years in the future. You're asked for the price at the start, not at the end

[marsh hare]

right

[hallow wren]

she has the price of future value tho

[hallow spruce]

No she doesn't

[hallow wren]

then im misunderstanding something ig..

[marsh hare]

soo what do i plug into the present formula then

[hallow wren]

she pays 1500+ 450 monthly for 4 years

anyways ima leave it to the experts

[hallow spruce]

These classes really need to explain the time value of money more closely

[marsh hare]

ikr

my teacher did not explain this at alll

[hallow spruce]

Because blind formula plugging and chugging is really not helpful

[marsh hare]

so is this the same

but plug into the present formula

[hallow spruce]

Sure

[marsh hare]

ok

@hallow spruce

I got PV = 20 009.18

• 1500

= the answer

ughhh

im so confused

like iget it

but how am i suppose to know this

[hallow spruce]

,calc 450(1-1/(1+.038/12)^48)/(.038/12)+1500

[solid kiln]

Result:

21509.188425973

[marsh hare]

yep

[hallow spruce]

Yeah seems fine

And you would know this if you had a proper understanding of the time value of money

You're asked to find the value of the payment when she first buys the car

The 1500 is paid at that time, so its value is just 1500

Whereas the annuity takes place each month after that, and so the interest must be taken into account to value it back in time

[trim jolt]

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[simple anvil]

which dotted line is the y displacement of a projectile accelerated off of the incline?

the first or the second?

[wraith hinge]

Send question

[simple anvil]

im watching this walkthrough video: https://youtu.be/g_yz8gbQF_s?si=dJsC0oHLH03wS2OK&t=1119

and at the timestamp linked, she says the y displacement is 200sin35

[wraith hinge]

By the time it reaches edge of incline it's acceleration would have changed right

[simple anvil]

yes

[wraith hinge]

Wdym greatest range...there is only 1 range

[simple anvil]

i guess bad wording lol

it just wants the total x distance travelled

from the point to the end of the rocket's path

[wraith hinge]

Right

[simple anvil]

i just dont understand why in the video she uses 200sin35 as the y displacement

[wraith hinge]

So yea find net acceleration along incline

[simple anvil]

when 200sin35 is only the height of the incline

[simple anvil]

well accel along the incline is given as 1.97

[wraith hinge]

That's initial acceleration right

[simple anvil]

i think it's just the acceleration for the entirety of the ramp

but it changes once it leaves the ramp

[wraith hinge]

Earth also pulls the object while it's moving up

[simple anvil]

true

[wraith hinge]

Ok fair enough

So the base of the triangle is the first displacement

X1

[simple anvil]

ya

200cos35

[wraith hinge]

And then

[simple anvil]

now i need to find the displacement of the rocket the moment it leaves

[wraith hinge]

U find velocity at the edge

[simple anvil]

so i can add the 2 together at the end

[simple anvil]

ya i got that

[wraith hinge]

Ok

Now find time of flight

[simple anvil]

ye thats the part im stuck on

[wraith hinge]

2u/g

[simple anvil]

whats u

[wraith hinge]

2vsin35 /g

[wraith hinge]

U said u calculated v correct

[simple anvil]

yes

i dont get where that formula is derived from

i just have the 4 kinematic equations

[simple anvil]

ohh i see i see

[wraith hinge]

That's the time for reaching the level of edge of incline plane

Again

[simple anvil]

so i need to find the remaining time

[wraith hinge]

Yup

[simple anvil]

for once it drops below the starting y position

and the ending y pos

is it possible to have like 1 equation for both?

just the total time after leaving the ramp

[wraith hinge]

Not sure

[simple anvil]

hmm ok

i rlly appreciate your help

thanks a lot

[wraith hinge]

Just to summarise

[wraith hinge]

x=X1+X2

X2=Vcostheta (t1+t2)

@simple anvil all clear?

Wlc

[simple anvil]

ye that makes sense

i conceptually understand

[wraith hinge]

👍

[simple anvil]

.close

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[austere totem]

Use this diagram to help decide if this statement is true or false. If two events, A and B, are mutually exclusive then they are also independent.

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[austere totem]

<@&286206848099549185>

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[clear linden]

help

[past river]

Try 2

[clear linden]

oh

im actually dumb i had it the whole tim

i was trying x and y

[maiden zinc]

log rules

then it becomes a quadratic

and you take the positive solution only bc the negative will most likely be extraneous bc the argument has to be positive

[clear linden]

what are log rules

[past river]

No need to make it a quadratic really but yeah sure

[maiden zinc]

oh ye

[clear linden]

how bout this one

[maiden zinc]

bro is doing a roblox math obby but just cheating the entire time

😭😭

[clear linden]

I JUST NEED TO KNOW

[maiden zinc]

same base

[past river]

Then use a calculator

[clear linden]

i guessed it

[maiden zinc]

make 25 into base 5

[past river]

This server is a place to learn

[clear linden]

its -5

[past river]

Not cheat in games

[past river]

You‘tr hogging up a help channel that others could use

[clear linden]

im playing it so i can apply the math

[past river]

You‘re not learning, you said it yourself you‘re guessing and taking other people‘s answers

[clear linden]

god damn it bru just close this help thing

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[austere totem]

At Helena’s conference, a committee is to be chosen containing 12 people. If there are 100 people at the conference, a) find: i) the number of possible combinations of people chosen for the committee. ii) the probability of Helena being chosen for the committee. c) At the conference, there are 56 women and 44 men. Find the probability that the committee will be made up of women only.

[cold crystal]

Have you learnt combinatorics?

[austere totem]

Nope -- never learnt, let only mentioned during class

[cold crystal]

This one...

Do you know what it means?

[austere totem]

Not one bit

[cold crystal]

Which grade are you in?

[austere totem]

Tenth

Been absence due to various health issues -- could of possibly missed the unit though

[cold crystal]

Ideally, one would've used combinatorics to solve this question...

But, since you didn't learn it, let's solve it another way

[austere totem]

thanks -- sorry for the inconvenience

[cold crystal]

Now out of 100 people 12 people need to be chosen right?

[austere totem]

Correct

[cold crystal]

So we have 100 choices for first position

Let's say we chose one person

Then we have 99 choices for second person

98 choices for 3rd person and so on

till, 89 choices for 12 person

Ping me when you come back...

[austere totem]

sorry -- i'm back

[cold crystal]

Ok!

Did you get what i said?

[austere totem]

yes -- all understood!!

[cold crystal]

So, number of groups = 100 * 99 * 98 * 97 * ... * 89

Do you know factorial notation?

[austere totem]

yep!

[cold crystal]

so, we can write this as 100!/(100-12)!

But, now we run into a problem
Let's say we have 12 people ABCDEFGHIJKL
We have (12* 11* 10 * ... * 1) ways of arranging these people

So we divide 100!/(100-12)! by 12!

Can you tell me the answer of i part now

[austere totem]

thanks -- one sec

[cold crystal]

Yes?

[austere totem]

Macbooks' almost dead -- could we continue somtime later through DMS?

sorry for the inconvenience

[cold crystal]

Okay

[austere totem]

Sorry. Back in thirty!!

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[maiden crane]

Why did they use 12 and not 13? Not sure how the amount of cards in a suit decreases by 1 for seemingly no reason

[void carbon]

bcoz u already have taken card out

so 52 becomes 51 cards etc

[maiden crane]

we've taken 3 cards out though, so why wouldn't it be 10 instead @void carbon

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@maiden crane Has your question been resolved?

[cold crystal]

@maiden crane we need to take two cards of second rank, so we can't consider all 13 cards, we have to discard the rank we got in first 3 cards

[maiden crane]

but there are still 13 cards from the 2nd required rank

i guess ill just memorize it

[fleet stratus]

SOMEONE HELP

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[fleet stratus]

.reopen

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[fleet stratus]

<@&286206848099549185>

[cold crystal]

!status

[trim jolt]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[fleet stratus]

i havent started, and know i dont know

[cold crystal]

start by simplifying LHS

25^0 = 1

1^3 = 1

[fleet stratus]

kk

anyways

back to the question

[cold crystal]

can you simplify LHS

[fleet stratus]

ion know hwat LHS is...

[stuck dragon]

left hand side

[fleet stratus]

ye, im right handed tho

[stuck dragon]

😭

thats not what it means

[fleet stratus]

so simplyfiy left side first

[stuck dragon]

yes

[cold crystal]

yes

[stuck dragon]

doesnt matter either way right @cold crystal ?

[fleet stratus]

so 1 +_ 3/4 is 7/4

[cold crystal]

you can go either way, but generally i solve left first

Yes

[fleet stratus]

7/4 divided by 7

[stuck dragon]

ah i see

[fleet stratus]

is 1/4

wait is it?

[stuck dragon]

wait bodmas tho u have to divide first

[cold crystal]

NO

[stuck dragon]

and u forgot the x

[stuck dragon]

i mean solve bracket which u already did

[fleet stratus]

oh...

[cold crystal]

it's (7/4)/(7/256x)

[stuck dragon]

and then divide 3/4 divided by 7/256x

[stuck dragon]

yeah

that

[stuck dragon]

u know bodmas or bedmas right?

[fleet stratus]

so baically 7/4 times 256x/7

omg

stupid

srry

[cold crystal]

nope

[fleet stratus]

tryped it wrong

[stuck dragon]

times 256x/7 yes

[cold crystal]

yep

[fleet stratus]

so it becomes 256x/4

cus 7 cancel

[cold crystal]

hmm

[fleet stratus]

and 4^4 equals 256

[cold crystal]

hmm

[fleet stratus]

so the 256 and 4 cancel out

[stuck dragon]

i need to calculate it to verify

[fleet stratus]

so it is 4^3x right?

but we have to square root

[cold crystal]

hmm

[fleet stratus]

we gotta square root the square root

[cold crystal]

hmm

[stuck dragon]

yes so 4x4x4

64x

[fleet stratus]

ye

[stuck dragon]

good job

[fleet stratus]

so square root the 64x

[stuck dragon]

yeah

then square root again

[fleet stratus]

4^3/2

[stuck dragon]

dont forget about the x

[fleet stratus]

4^3/4?

4^3/4 x 'x'

[cold crystal]

No, leave it there and simplify RHS

[fleet stratus]

bruh

[stuck dragon]

ah

yes do that

[cold crystal]

No

[fleet stratus]

so just leave it like 64^1/4 x?

[cold crystal]

it gives root(8x) = RHS

now simplify RHS

[fleet stratus]

ok

[cold crystal]

This problem is not hard, just calculation mess

[fleet stratus]

yep

[cold crystal]

Do you know what 5! means?

[fleet stratus]

5 x 4 x 3 x 2 x 1

240?

1/2?

[cold crystal]

no

120

[fleet stratus]

oops

im so dumb....

[stuck dragon]

its ok

[fleet stratus]

so thats basically 1^256 = 1

[stuck dragon]

just double check ur answers always

[stuck dragon]

ye

[fleet stratus]

so now it is (4x^2 + 256)^1/4

[cold crystal]

yeh

[stuck dragon]

es

[fleet stratus]

256/4

[stuck dragon]

u can cancel out now i think

[fleet stratus]

64

[cold crystal]

raise both sides to power of 4

[fleet stratus]

oh ye

what was other side..

8x?

root(8x)?

[stuck dragon]

64x in 2 square roots wasnt it

[fleet stratus]

wait left side is (8x)^1/2?

[stuck dragon]

idr actually

wasnt it 1/4 not 1/2

oof i forgot

[fleet stratus]

oh ye

so left is 8^1/4 times x

right is (4x^2 +256 ) ^ 1/4

[stuck dragon]

wait how 8

[fleet stratus]

so times both sides by

IM SO DUMB

[stuck dragon]

i thought u left it at 64

[fleet stratus]

its 8 ^1/2

[stuck dragon]

nahh ur not dumb im only asking

yeah

i think thats right

[fleet stratus]

so 8x^4= (4x^2 + 256

)

8x^4= x^2 + 64

oh wiar

bruh

[stuck dragon]

i think u should write it down

[fleet stratus]

2x^4= x^2 + 64

so close yet so far

[stuck dragon]

ohh its a quadratic

[fleet stratus]

OH YEAH

[stuck dragon]

u cant find one solution

[fleet stratus]

mmmm

[stuck dragon]

u can only simplify

[fleet stratus]

ok

whats 2x^4-x^2?

[stuck dragon]

cant be solved

u have to write it like that

[fleet stratus]

divided everything by ^2?

[stuck dragon]

nah nah

[fleet stratus]

oh

[stuck dragon]

so for quadratics u have to put everything to one side

so that means

[fleet stratus]

ye so 2x^4 - x^2 - 64

[stuck dragon]

2x^4-x^2-64=0

correct

now u can try and factorise it

oh wait u cant

ok so then instead u should

ou this is a little confusing

wait ill try solving it my way

and if it works ill tell u

[fleet stratus]

what if we did a wrong step along the way/...

[stuck dragon]

we may have

[fleet stratus]

noooooo

[stuck dragon]

we have to double check always

[fleet stratus]

this is a question on a math roblox obby game btw. sorry for wasting time...

silence

[random pollen]

It is x^2(2x^2-1)

[stuck dragon]

howd u get x^2 out

64 doesnt have it

[stuck dragon]

nothing wrong with that lol

[trim jolt]

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[trim jolt]

Please don't occupy multiple help channels.

[knotty locust]

@limpid dawn

[limpid dawn]

@knotty locust

[scenic raft]

can anybody help me with this

[knotty locust]

!occupied

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[limpid dawn]

!occupied

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@tepid kayak Has your question been resolved?

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[tepid kayak]

<@&286206848099549185>

[tepid kayak]

My question

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[tepid kayak]

Bruh

[sacred sapphire]

can you find all the angles that you possibly can?

[tepid kayak]

Yeah

It's an trapezium adjacent angles = equal

Still don't know the others

[sacred sapphire]

well maybe label it out and we'll go from there

[frail yarrow]

Hey, maybe move this to an active channel?
It's already closed, so it might automatically lock you out soon

[trim jolt]

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[tepid kayak]

ok

[tepid kayak]

I'll send it here @sacred sapphire

[sacred sapphire]

isnt CE = FE?

[tepid kayak]

Yeah

[sacred sapphire]

so what should those angles be?

[tepid kayak]

Well, we only got half of those angles (or whatever degrees) for ce

[tepid kayak]

This is the main question btw

[sacred sapphire]

CE and FE is the same

so ECF and EFC should be the same

no?

[tepid kayak]

no.. it's CE and FD isn't it?

It's a trapezium

opposite angles are = 180

Right..

?

[tepid kayak]

Yeah

That's a scalene triangle

right

or isoceles

[sacred sapphire]

yeah

if its isoceles that means the other two angles must be the same right?

[tepid kayak]

yeah

your saying its 50 the other two

[sacred sapphire]

so what should they be

yes

[tepid kayak]

ok so 50+42 = 92 so 88 degrees should be the middle angle?

ACD

so.. option E.

[sacred sapphire]

yep

[tepid kayak]

damn, thats easy

What about ACB now..?

[sacred sapphire]

well you have two out of the three angles in triangle ACD

right?

[tepid kayak]

yeah

88

and is the other one 118

but if you add it it surpasses the rule of 180

[sacred sapphire]

triangle ACD

[tepid kayak]

..

[sacred sapphire]

where is it?

[tepid kayak]

Oh

I'm talking about

[sacred sapphire]

you have 88 and 62

[sacred sapphire]

thats ABC

[tepid kayak]

Oh.. your going that way

[tepid kayak]

ACB, same thing.

[sacred sapphire]

i was saying ACD

not ACB lol

[tepid kayak]

oh ok

[sacred sapphire]

so whats the last angle

[tepid kayak]

30

(88+62) - 180

[sacred sapphire]

ok good 30

now do you notice that BC and AD are parallel?

[tepid kayak]

Yeah

wait

Isn't only BD and AC parallel as the trapezium rule (adjacent = same)

[sacred sapphire]

not sure

the diagram labels BC and AD as parallel

since they are parallel, can you tell me what ACB is?

[tepid kayak]

I don'

[sacred sapphire]

ACB is the top one

[tepid kayak]

Oh

That's 118 right..?

[sacred sapphire]

nope

[tepid kayak]

$180-62=118..$

[solid kiln]

sarvvyy

[sacred sapphire]

this one

[tepid kayak]

Oh

that one

I can't as I only have 30, not the other side of the angle

[sacred sapphire]

does alternate angle theorem come to mind?

[tepid kayak]

no..

[sacred sapphire]

do you remember what it is?

[tepid kayak]

Sadly, no

[sacred sapphire]

remember this?

[tepid kayak]

Yeah.

[sacred sapphire]

can you use it here?

[tepid kayak]

Yes

but, I don't know how

[sacred sapphire]

oh wait i gave you another variation of it

you remember this one?

and can you apply it here?

[tepid kayak]

so thats 30

[sacred sapphire]

yep

[tepid kayak]

Oh damn

so E again.

[sacred sapphire]

yep

[tepid kayak]

Thanks!

.close

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[tepid kayak]

.reopen

[trim jolt]

✅

[tepid kayak]

just checking

[solid kiln]

sarvvyy

[trim jolt]

@tepid kayak Has your question been resolved?

[tepid kayak]

<@&286206848099549185>

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@tepid kayak Has your question been resolved?

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[lavish cosmos]

studying for semester exam and not sure if i’m doing this correctly and if i would need to somehow simplify my answer. Just realise i forgot plus c

[lavish cosmos]

question 4b btw

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[tepid kayak]

.

[hybrid kernel]

My answer is 2^8 = 256. However, the solution at the back of this textbook is: 8!/(5!3!)= 56

[shy nacelle]

Hii

@hybrid kernel There ?

[hybrid kernel]

yes!

[shy nacelle]

Ok so see we can either go up or right

Maximum time we can go up is 3 and maximum right moves is 5

[hybrid kernel]

okay

[shy nacelle]

So its UUURRRRR

How many ways can you arrange those letterz ?

8!/(3!*5!) No?

[hybrid kernel]

oh...lemme process it for a moment

[shy nacelle]

ofcourse

@hybrid kernel Is this problem from A. Das Gupta ?

[hybrid kernel]

Nope this is a government textbook from Malaysia

[shy nacelle]

Oh Okay

@hybrid kernel Got this ?

Can ask questions

[hybrid kernel]

Okay but can you see why is my approach wrong? I thought that when the object is at point A, it has two choices,

and then

[shy nacelle]

Yeah continue

[shy nacelle]

After you consider three two ways, let it be three up's ,then will it be again two ways or that is a separate case ?

I think you got the fallacy

[hybrid kernel]

after it has moved one unit, it faces two choices again. And then, I counted that, whatever route the object takes, it always has 8 units to go through

[shy nacelle]

understood this ?

[hybrid kernel]

oooooohhhhh

[shy nacelle]

Yeah so we will have a lot of distinct cases

And thats why the method doesnt works

[hybrid kernel]

alright mate 👍🏻 I understand that now

Thanks a lot!!!

[shy nacelle]

You re welcome

[hybrid kernel]

.close

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[meager tinsel]

help c) i get -2/-1

<@&286206848099549185>

[split chasm]

,rotate

[split chasm]

show your work

[meager tinsel]

hold up

looks like shit

[split chasm]

just simplify that further

[meager tinsel]

bru

-2/-1

[split chasm]

yes, simplify that further

[meager tinsel]

how

[split chasm]

basic division

[meager tinsel]

2/1??

[split chasm]

simplify that even further

[meager tinsel]

how

[split chasm]

don't overthink

[meager tinsel]

1/0.5

[split chasm]

that makes things worse

you're overthinking

if you wanted to divide 2 apples amongst one person, how many apples will they get?

[meager tinsel]

2

[split chasm]

yes

2/1 is simply just 2

[meager tinsel]

idk im stupid as f

ok tnx

.close

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[azure gale]

tan^(2)x-1-sec^(3)xcosx=0

I'm unsure how to solve

[wraith hinge]

google gemini says:

We can solve the equation by using trigonometric identities and factoring. Here's how:

Utilize the identity: We know the trigonometric identity tan²(x) + 1 = sec²(x). Let's use this in the equation:
tan^(2)x - 1 - sec^(3)x cos(x) = 0
(sec²(x) - 1) - sec^(3)x cos(x) = 0 ( Substitute tan²(x) + 1 for sec²(x) )

Factor by sec(x): Notice all the terms have sec(x) in them. Let's factor it out:
sec(x) (sec²(x) - 1 - sec(x) cos(x)) = 0

Factor the remaining expression: The expression inside the parenthesis is in the form (a² - b²) - (a)(b). This can be factored as (a + b)(a - b). In our case, a = sec(x) and b = cos(x):
sec(x) [(sec(x))² - (cos(x))² - sec(x) cos(x)] = 0
sec(x) [(sec(x) + cos(x)) (sec(x) - cos(x))] = 0

Separate the solutions: Now we have two possibilities:
sec(x) = 0 (This is not a valid solution because sec(x) is 1/cos(x) and cosine is never zero)
(sec(x) + cos(x)) (sec(x) - cos(x)) = 0
This gives us two separate equations:

sec(x) + cos(x) = 0
sec(x) - cos(x) = 0
Solve for each equation:
sec(x) + cos(x) = 0:
Rewrite sec(x) as 1/cos(x): (1/cos(x)) + cos(x) = 0 1 + cos²(x) = 0 (This has no solutions because cos²x is always non-negative and adding 1 makes it positive)
sec(x) - cos(x) = 0:
Rewrite sec(x) as 1/cos(x): (1/cos(x)) - cos(x) = 0 1 - cos²(x) = 0 sin²(x) = 1 (Use the identity sin²(x) + cos²(x) = 1) sin(x) = ±1 (Take the square root of both sides)
Therefore, the solutions for the original equation are:

x = π/2 + 2πn (where n is any integer) for sin(x) = 1
x = 3π/2 + 2πn (where n is any integer) for sin(x) = -1

These solutions represent all the angles where the given equation holds true.

@azure gale

[azure gale]

Okay looking this over

Makes sense, somehow I got no solutions exist

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[polar quarry]

Help !

[polar quarry]

Were back

@tall kernel

My people that were helping me

[tall kernel]

oh

[polar quarry]

They vanished

[tall kernel]

rip

[polar quarry]

can you help me

is that

can you

[tall kernel]

for this?

[polar quarry]

yeah

and like

4 other similar questions

[tall kernel]

ok so first we have to find the midline

u got 712

[polar quarry]

yeah

[tall kernel]

yep

😭

[polar quarry]

wait so am i right

[tall kernel]

well i havent checked transformations

[polar quarry]

ah alr

but so far

im righit

[tall kernel]

yes

now

im just used to sine ngl

but uh

now amplitude

ok amplitude is right

now your transformations must be wrong

[polar quarry]

if we do sing

sin

[tall kernel]

then everything woudl be same except transformation

[polar quarry]

we just do a transformation

oh

[tall kernel]

yes

[polar quarry]

but

cos = no transformation

[tall kernel]

idk about cosine

i never use it

i just use sine with transofmraitons

we shoudl have

120sin(x + 3) + 712

but

there mgiht be frequency cahgne

*change

[polar quarry]

uhhuh

[tall kernel]

the period is 12 aka 1 year

so i think it should just be

[tall kernel]

this

[polar quarry]

thats wrong

i put it in and its wrong

hm.

wheres the period

we dont have a period

[tall kernel]

period is a year

OHH

[polar quarry]

??!?!?!!

[tall kernel]

this is dumb

[polar quarry]

what

[tall kernel]

we have to use t

not x

😡

[polar quarry]

what the hell

https://tenor.com/view/ronaldo-cr7-angry-annoyed-cristiano-gif-21024834

[tall kernel]

😭

[polar quarry]

goofy ahh deltamath

[tall kernel]

check if it works

real

[polar quarry]

i press t?

[tall kernel]

use t instead of x

[wraith hinge]

Physics entered the chat lol

[polar quarry]

oh this is great

we have two people now

[tall kernel]

it works?

[polar quarry]

wait did i put it right

[tall kernel]

if not jsut use your regular one

yes

im like 69% sure thats right

[polar quarry]

yeah your a fraud

[tall kernel]

wrong? 💀

[polar quarry]

what the hell

ooops

[tall kernel]

the frequency was wrong then

[polar quarry]

where did 2.5 come from

[glossy cargo]

phase shift

[polar quarry]

this guy came back from the dead

@tall kernel i was tlaking about this guy

[glossy cargo]

i have other work 💀

[polar quarry]

thers 3 helpers whats going on

[polar quarry]

you died

i needed you

alr

i need help though

[tall kernel]

ok you got 2 other helpers im out

[polar quarry]

nOP

NO

@wraith hinge

help me out

nobodys here

does anybody have ai or sometihgn

HELLO?

https://media.discordapp.net/attachments/880581119643373588/941237797451354132/banana_3_1.gif

.close

[trim jolt]

Channel closed

Closed by @polar quarry

Use .reopen if this was a mistake.

[wraith hinge]

.reopen

[polar quarry]

this guys back.

[wraith hinge]

Damnit I can’t do it for u

[polar quarry]

why not

[wraith hinge]

Yo

So they talked about phase shift

[polar quarry]

you can do it

[wraith hinge]

Basically

[polar quarry]

oh yeah how do i find that

[wraith hinge]

Have you ever studied electrical systems in Alternative current before ? If you have I can use an analogy which might speak to you more

No answers ?

[polar quarry]

no

i dont

[wraith hinge]

I’ll take that for a no

Ok

[polar quarry]

yeah

[wraith hinge]

So let’s start easy what’s the general formula for your cosinus function

Also sorry if I don’t always answer I’m cooking at the same time 😭

[polar quarry]

oh nah go do that

hold up

im gonna go check osemthing out real quick

this could be big

[wraith hinge]

Ok so dude focus

The general formula is the following:

$$y=Acos(B(x-D))+C$$

[solid kiln]

maëbe

[wraith hinge]

Now

A is your amplitude

How do you find amplitude on a graph?

[polar quarry]

distance from midline

[wraith hinge]

Yes sorry

So

Then B is your period

How do you find a period

[polar quarry]

2pi / thing

[tall kernel]

B would be frequency, not period? you get period from frequency

[wraith hinge]

No

[wraith hinge]

Frequency is 1/T

[wraith hinge]

To do it the easy way just take two crests and do xcrest1-xcrest2

Basically the time in between one crest to another

Then next

D is your phase shift

Do you know how to find phase shift?

And if you don’t do you want me to explain what it is

@polar quarry ?

[wraith hinge]

Bro disappeared

[polar quarry]

alright

y=230cos (pi/9 (t- c) + 240

all that good good stuff

[wraith hinge]

What’s c ?

[polar quarry]

i dont know

thats the thing

can you tell me

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[subtle ether]

Where did the bounds of 5 and 6 come from

[silver furnace]

The 5->6 represents the outer bound between the parabola and the line

[subtle ether]

yeah no i got it now

i j forgot about B coordinate

thx

.close

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[rain grove]

am i trippin?

[true sierra]

yup

[rain grove]

crossed out a 7 because i input it to see the answer

[rain grove]

whats wrong?

doesnt it mean the same

[true sierra]

pay attention to the !

!!!!!!!!!!!

[rain grove]

oh shit

i am lol

thanks

.close

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal summit]

I am stuck, can someone help me?

[alpine saffron]

let u = lg x

[past river]

You have a quadratic in terms of logx

[alpine saffron]

Equation should then take on a more familiar form

[past river]

so close to golden ratio

[trim jolt]

@crystal summit Has your question been resolved?

[wraith hinge]

?

[wraith hinge]

Did this n9t help you ?

[crystal summit]

I know it’s a quadratic but Idk how to solve

I know how to solve a quadratic eq but completing the square isn’t an option here

[wraith hinge]

Are you aware of the formula
-b+-sqrt......

[crystal summit]

Not sure

[wraith hinge]

Hmm

[alpine saffron]

You can factor

[wraith hinge]

Okay

Yes

[crystal summit]

Factor what?