help-38

[main sigil]

I'd rewrite the term thats being summed

Using rules for exponents

[fair meteor]

si there something that can explain how to do that since idk how to calaulate geometric series other than writing out the a_1 a_2

[knotty quest]

infinite gp has formula a/1-r

yes

[main sigil]

You need to convert it to form a1 * (r)^(n-1)

Also note that ur seriss starts at n=7

U want it to start at some i=1

Or i = 0

Lets go with this formula and well start at k=0

For that use substitution k = n - 7

Or n = k + 7

[trim jolt]

@fair meteor Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight scarab]

How does the numerator turn into 4 - u when substituted? Is it because x = 4 - (4- x) ?

[wary rampart]

yeah

youre right

[tight scarab]

okay

[wary rampart]

its kind of a weird substitution but its a lot easier when theres multiple terms in the numerator rather than the denominator

since you can then split it up to small fractions

[tight scarab]

so I have to substitute all parts of the function with the variable we're substituting

even if it's not on the same form sort of

[wary rampart]

yeah you cant just leave x at the top

[tight scarab]

makes sense

[wary rampart]

if you do u sub everything has to be in terms of u

cant have x and u in the same integral

[tight scarab]

That makes a lot of sense

[wary rampart]

and it becomes negative because du = -1 dx

[tight scarab]

Yeah, I had that part

It's been so long since I've done this, so I had completely forgotten

I tried treating the x in the numerator as a constant, and putting it in front of the integral🥲

The answer wasn't that far from it, but that was just luck

tysm!

[wary rampart]

oh yea lol constant gotta be a regular number but you probably got that now

no prob

[tight scarab]

yeah hahaha

.close

[trim jolt]

Channel closed

Closed by @tight scarab

Use .reopen if this was a mistake.

[delicate belfry]

$$u=4-x$$ $$x =4-u$$

[solid kiln]

Good

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

can somebody help me with converting litres and gallons and stuff

[wraith hinge]

[ebon plover]

just google it

[wraith hinge]

bruh

[ionic pendant]

,w liters to gallons

[solid kiln]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by cloudedhorizons

[trim jolt]

@wraith hinge Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic pine]

not sure how to start with this

[ebon plover]

I think you can start with evaluate f(0) or f(1) out

[exotic pine]

f(0)=0
f(1)=1

[trim jolt]

@exotic pine Has your question been resolved?

[wraith hinge]

Alright

So

@exotic pine

Substitute 1/2 in first expression

Get that 2f(1/2)=f(1)

[wraith hinge]

From substitution 1

[wraith hinge]

You get that 2f(1/3)=f(1/2)

[exotic pine]

what is this btw?

oh nvm

[wraith hinge]

So when you find f(1/3)

Substitute in 1-x

Find f(2/3)

And find all of them in terms of f(1)

So
Then you have this sequence

And if you substitute each term you get. That
Each subsequent term equals 2 times previous term

So you should get something in terms of f(2/3)

And then evaluate it by knowing f(2/3) in terms of f(1)

I guess

So definitely find f(1/3) and after you can find f(2/3)

In terms of f(1)

Sequence will be such that f(2/3)+2f(2/3)+4f(2/3)....

But yeah f(1)=1 important part

[exotic pine]

$$f(\frac{2}{3})=1-f(\frac{1}{3})=1-\frac{f(\frac{1}{2})}{2}=1-\frac{f(1)}{4}$$

[wraith hinge]

Yeah

I think so

[solid kiln]

Skill_Issue

[exotic pine]

btw f(1) is 1 right?

[wraith hinge]

Yeah

[exotic pine]

btw how do i find the other terms?

[wraith hinge]

It supposed to be geometric sequences up to infinity

I suppose

Because x between 0 and 1

So f(1) is max

Which is 1

So

[exotic pine]

like $f(\frac{2}{5})$

[solid kiln]

Skill_Issue

[wraith hinge]

R<1

https://www.cuemath.com/geometric-sum-formula/

Ah wait

No

Actually

Beuh

We have 2 as a common ration

[exotic pine]

how do i get f(2/5)

[wraith hinge]

Substitute x=2/3 into first equation

[exotic pine]

wait that works?

oh yeah

[wraith hinge]

Yeah but the problem we have common ratio 2 so we can't use equation for infinite geometric sequence

So I am not sure. So yes we can get nth term etc but

[exotic pine]

isnt the common ratio 1/2

[wraith hinge]

Ah yeah

You right

Yeah

Bruh

I was going backwards

Sorry

Bruh

1/2

That's it

We done

[exotic pine]

so (3/4)/(1/2) right

[wraith hinge]

First term f(2/3)
R=1/2
So we have
2f(2/3)?

[wraith hinge]

Probably

[exotic pine]

3/2

[exotic pine]

probably

[wraith hinge]

Yeah I guess

[exotic pine]

ok ty lemme check

[wraith hinge]

Plug here

[exotic pine]

ok i think ill close this, tysm and cya 👋

.close

[trim jolt]

Channel closed

Closed by @exotic pine

Use .reopen if this was a mistake.

[wraith hinge]

Have you checked the answer?

[exotic pine]

i asked but they havent responded yet, ill make a new channel and ping you if its incorrect, if thats fine with you

[wraith hinge]

What kind of question is it?

[wraith hinge]

Yeah, thanks

[exotic pine]

my friend posted it in a group chat, it looked fun to try the question so i asked here for help

i think it was from a website called alcumus or smth?

[wraith hinge]

Alright so it doesn't have any known time constraints

Alright thanks

.close

. close

.close

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[celest seal]

cant get the intersection

[trim jolt]

@celest seal Has your question been resolved?

[celest seal]

<@&286206848099549185>

[peak basin]

did you solve the two inequalities separately?

[celest seal]

yea

[wraith hinge]

do you know wavy curve method

[hasty grove]

its multiple choice u can just do trial and error

[celest seal]

how do i use it here tho?

[celest seal]

nah 💀

[hasty grove]

i mean u could

js

[celest seal]

it would take a long time lmao

[hasty grove]

not really

its not d

so u just have to look at the upper bound

and see if its 2, 4 or 1

[celest seal]

💀

i gotta know the method too tho

wait nvm got it lmao

.close

[trim jolt]

Channel closed

Closed by @celest seal

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic pendant]

I have to solve what a is. And it was a while ago since I did this and have 0 idea what I have to do to start.

[normal crest]

Is the piecewise function continuous?

[orchid wagon]

what do you mean "solve for a"

!xy

[trim jolt]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[whole coral]

a is such that f is continuous?

[orchid wagon]

seems like so

[exotic pendant]

"determine the knostant a so that"

WAIT YES

I missed the last part

[exotic pendant]

becomes continuous at the point 0.

[orchid wagon]

are you familiar with the definition of limits and continuity?

[exotic pendant]

I think I am but it was a while

[orchid wagon]

right

lets say i have an arbitrarily function f(x)

[exotic pendant]

Yup

[orchid wagon]

what do you think is the condition for f(x) to be continuous at x = a?

[exotic pendant]

That the value set coherently for the entire function

Or I'm slightly confused

Oh wait, I think I know how to do

Solved it

.close

[trim jolt]

Channel closed

Closed by @exotic pendant

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[waxen sphinx]

yo

[waxen sphinx]

Is my answer correct?

<@&286206848099549185>

[trim jolt]

@waxen sphinx Has your question been resolved?

[trim jolt]

@waxen sphinx Has your question been resolved?

[lean hamlet]

Hey

What u made mistake is with the square

I think you have to find COM for it seperately

And then find for all three combined

[waxen sphinx]

isnt it 3,3

since the hight and width are 6 and 6

6x6

[lean hamlet]

There is a part missing

[waxen sphinx]

yh i minus

quartar

[lean hamlet]

So COM isn't 3,3

[waxen sphinx]

i took massive shape

[lean hamlet]

Yeah you should do it first

[waxen sphinx]

square - quartar

i added it

in the steps

[lean hamlet]

And then do for the three parts

[waxen sphinx]

yh i did that

[lean hamlet]

Oh

Lemme check

No

[lean hamlet]

What u did is for all four

First u have to find find for square seperately

Only then you should do next part

[waxen sphinx]

i added all shapes

then minus quartar

[lean hamlet]

Yes and that's wrong

[waxen sphinx]

that worked in previous qs

[lean hamlet]

That would be for two parts such as square and quarter

Where quarter is removed

I'm pretty sure my method is crct but check with your teacher maybe

[waxen sphinx]

Mind solving the q and compare it with my answers?

Thats a question that i got the answers to and i did using the same method

[lean hamlet]

I mean first check with your teacher or someone, whether the method is correct or not

The answer will differ with my method

[waxen sphinx]

thats the doctors method that taught us

if u solved it

and ur answer is like mine

then its correct

[waxen sphinx]

well? @lean hamlet

[lean hamlet]

Oh

I forgot abt this

Sry abt that, but I'm lazy to do it

I'm not good with phy too

[waxen sphinx]

😂

[waxen sphinx]

its alr

[lean hamlet]

Mb again

[trim jolt]

@waxen sphinx Has your question been resolved?

[waxen sphinx]

anyone?

<@&286206848099549185>

[trim jolt]

@waxen sphinx Has your question been resolved?

[waxen sphinx]

.close

[trim jolt]

Channel closed

Closed by @waxen sphinx

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland jay]

Given Angle a in Quadrant 2 with sinA = 4/5 and angle B in Quadrant 3 with cosB = -5/13 find cos (A-B)

[trim jolt]

@inland jay Has your question been resolved?

[round mango]

cos(A-B)=cosAcosB+sinAsinB

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dapper hazel]

Hello

[dapper hazel]

I need help with quadratic equations

I need someone to teach me how and the steps to do one

I’m so lost

I need someone to teach me an example of one

[lean hamlet]

Hey

[dapper hazel]

So I can do it on my own

hello

[lean hamlet]

Do you know quadratic formula?

[dapper hazel]

no

wait

ax bx c

[round mango]

<@&268886789983436800>

[dapper hazel]

what

Bro do it somewhere else

I’m trying to get help

I hate my fucking life

[lean hamlet]

<@&268886789983436800>

[merry gyro]

No need to ping more than once

[lean hamlet]

Oh sry

[lean hamlet]

?

So do uk?

[dapper hazel]

Is that it?

[dapper hazel]

yeah

ax2 bx c

Yes

[lean hamlet]

In this formula, suppose inside the root is positive

[dapper hazel]

What’s the root

[lean hamlet]

Root of b^2-4ac

So if b^2-4ac is positive or 0

Then the root can be factorised

It's called real roots

[dapper hazel]

okay

[lean hamlet]

If b^2-4ac is negative it's non factorisable

Since root of -ve value is not a real number

Are you following?

[dapper hazel]

Yes

[lean hamlet]

To find the roots, use the formula

[dapper hazel]

I’m thinking like I didn’t learn this

I have no idea what this means

[lean hamlet]

Ohh

Do you know splitting the middle term ?

[dapper hazel]

I learned the one above bro

[lean hamlet]

But you can't solve many questions otherwise

[dapper hazel]

yeah

[lean hamlet]

For first question

Try it

[dapper hazel]

yes

[lean hamlet]

Try to find the roots

[lean hamlet]

Using this

[dapper hazel]

I don’t know what roots are tho I’m so lost

[lean hamlet]

Hmm np

Just use the formula

[dapper hazel]

I just know ax2 bx c

[lean hamlet]

You'll get X two real values if b^-4ac is positive

Those are called real roots

[dapper hazel]

okay

[lean hamlet]

Ok, now try the formula

For first question

[dapper hazel]

okay

Doing it

I don’t get it

Like what do I put for -4ac

[lean hamlet]

.

[dapper hazel]

Okay thank you for you help

I really appreciate it

[lean hamlet]

Did u get it?

[dapper hazel]

But I will go now

[lean hamlet]

Ok

[dapper hazel]

Nope I’m just accepting my fate thanks tho

Don’t wanna bother u

Close

[trim jolt]

@dapper hazel Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coarse lark]

how to do bii

[knotty quest]

U know differentiation?

@coarse lark

[coarse lark]

yeah

no wait

idk how to diff cos

🙂

HELP

[knotty quest]

Differentiation of cosx is -sinx

Fine leave differentiation

U know that max of cosx is 1 right

So max of that function is 3

Min of cosx is -1

So min of function is -7

He gave Q is max point for min x

Cosx is max at x=0

So point is (0,3)

Or he said as x>0 next maximum of cosx is at x=2pi
So it will be (2π, 3)

[coarse lark]

u rirght

tahts bi

i want bii

[knotty quest]

U can use the same logic for next one also

[knotty quest]

What??

Didnt understand

[coarse lark]

bii

[knotty quest]

Here it is -1

For maximum

Max of y is 5

[coarse lark]

ohh

[knotty quest]

At cosx = -1

[coarse lark]

ok so maximum for a negative curve is negative

[knotty quest]

Yea

Because negative negative is positive

[coarse lark]

i thought i would takae normal maximum of cos curve which is 1 and multiplu by -5

[knotty quest]

Nop

That will be the minimum

[coarse lark]

u right

that makes sense

what abt my x coordinate

[knotty quest]

Yep

Cosx is -1 at

[coarse lark]

180

ohhhhhhh

tysm 🙏

[knotty quest]

X= nπ where n is odd

[knotty quest]

Yepp

[knotty quest]

No problem!

[coarse lark]

.close

[trim jolt]

Channel closed

Closed by @coarse lark

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

How does one find the derivative of x ln x?

[wraith hinge]

I tried using product rule, but that just got me ln x

[dull temple]

yes

[spiral estuary]

product rule is right

[dull temple]

well no it should get you something else though

[spiral estuary]

yes

+1

[wraith hinge]

Ah, thanks

.close

[trim jolt]

Channel closed

Closed by @gentle cave

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vague pollen]

how we define how many balls to draw in probabilities

[vague pollen]

get at least one white ball

[trail ingot]

!original

[trim jolt]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[vague pollen]

its french

[trail ingot]

there must be more to the question

[vague pollen]

Yes

Mb

@trail ingot see now

[trail ingot]

i can’t really enough to help, sorry =S

[vague pollen]

alright

[trim jolt]

@vague pollen Has your question been resolved?

Channel closed

Closed by @vague pollen

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid kiln]

Daisuke

[dusk sundial]

So it's correct to say that "the greater the difference between onside and the sum of the other ones in a triangle, the less the measure of the angle opposite to the first side" and vice-versa?

[trim jolt]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[dusk sundial]

.

[white kestrel]

a

[dusk sundial]

I'm gonna post it on another channel

my bad

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white kestrel]

h

[white kestrel]

hello

can someone

asnwer me how to find limits of a function

do I need simplify it and then replace variable with value which it approaches?

[wraith hinge]

It would help if you provide a question

[trim jolt]

@white kestrel Has your question been resolved?

[white kestrel]

here that we did

he simplified to make the equation valid and just putted value

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz fulcrum]

hello

[quartz fulcrum]

i need help with this i have 0 idea im doing this online so i dont have a textbook for any info i am going to cry

all i know is to simplify

<@&286206848099549185>

[lyric sphinx]

what do you do when you subtract or add fractions and the denominator is different?

[quartz fulcrum]

what

no

im stuck with

[quartz fulcrum]

making the denominator all the same

but idk how to do thay

[lyric sphinx]

ok, if you have 1/2 + 1/4 what could you do?

[quartz fulcrum]

because the demoniatior of 2 of them gotta b (x+3) then the other (2x-1)

[lyric sphinx]

in order to get them the same

[quartz fulcrum]

what

[lyric sphinx]

in order to get the denominator to be the same

[quartz fulcrum]

no ik but its the fact that its (x+3)

yes ik u need to multiply

[lyric sphinx]

can you flip the photo rq

ill solve it and help out, cause i need to fully read it

[lyric sphinx]

it's hard tilting my head

ty

[quartz fulcrum]

tried simplifying them first to make it easier

but no

[lyric sphinx]

so you already have 3 correct?

(x+3) (x-7) (2x-1)

those are the three

now apply the method use for fractions (subtraction and addition) in order for them to share a common denominator

[quartz fulcrum]

yea i dont get words

[lyric sphinx]

alright,

[quartz fulcrum]

could u write down please

im a visual learner

[lyric sphinx]

you see how the first fraction has (2x-1)(x-7)

[quartz fulcrum]

mhm

ik u multiply x+3

[lyric sphinx]

so it's missing (x+3)

[quartz fulcrum]

but hoe

how*

[lyric sphinx]

mhm

[quartz fulcrum]

into that

[lyric sphinx]

(x+3) / (x+3)

because that is the same as multiplying by 1/1

[quartz fulcrum]

am i over complicating it that i have to put it to trinomials

yea

but im confused

[lyric sphinx]

so you multiply the numerator and denominator by that value

[quartz fulcrum]

cus how is it going to cancel out

[lyric sphinx]

you're basically multiplying by 1/1

so the overall fraction isn't affected

(the value you'd get would be the same regardless)

[quartz fulcrum]

im confused

my brain is acheing

because

[lyric sphinx]

ok lemme draw it out

[quartz fulcrum]

thabk u

doesnt the multiplcation just effect that whole x/(2x-1)

so om

[lyric sphinx]

if both the numerator and denominator get multiplied, you can always cancel them out; meaning they represent 1. However, in order to add or subtract fractions you must have the same denominator

[quartz fulcrum]

im confused how did it go back to x/(2x-1)(x-7)

[lyric sphinx]

(x+3) / (x+3) = 1

You can cancel them out

[quartz fulcrum]

yes but then thay wouldnt do anything

if u do that it js stays the same

[lyric sphinx]

yes, but in order to add the fractions, you must share a common denominator

[quartz fulcrum]

then

omg

😭

[lyric sphinx]

meaning you must first multiply all of the denominators by whats missing

then you can add up the numerator

[quartz fulcrum]

yk what

are u free right noe

[lyric sphinx]

ye

[quartz fulcrum]

could we call

[lyric sphinx]

alr

[quartz fulcrum]

im calling

[trim jolt]

@quartz fulcrum Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz fulcrum]

hello guys

[quartz fulcrum]

i dont get it

at all

[wraith hinge]

👋

[modest slate]

Don't get what ?

[wraith hinge]

cant really help with that

the answer is probably 3

[quartz fulcrum]

its still sending

i dont know why its not working

omg y the pic no send

😢

[wraith hinge]

whats the topic

[quartz fulcrum]

its rationals

precalc 11

[sweet hare]

fire and blood 😅

[quartz fulcrum]

im gon cry

the pic no send

finally

[wraith hinge]

quality book

could talk for HOURS about fire and blood if anyone wants help with that

[wraith hinge]

oh

[quartz fulcrum]

yea

[wraith hinge]

okay facctorise everything as much as u can

find a common denominator

[quartz fulcrum]

yea the thing id idk

is*

[wraith hinge]

oh ok

lets start with the first term

[quartz fulcrum]

yes

[wraith hinge]

you can see theres a difference of two squares at on the denominator

so we can express c^2 - 36 = (c - 6)(c + 6)

[quartz fulcrum]

this is what ive done so far

[wraith hinge]

nice

okay

so the first term

4x/(x^2-36)

we can express as i just said

[modest slate]

You don't need to find a common denominator tho do you?

[wraith hinge]

omg why did i read the divide as addition

💀

[quartz fulcrum]

idk i solved one by smo helping me on call but it was trinomial and this is noy

not&

not**

[wraith hinge]

ignore the common denominator part

[quartz fulcrum]

so i dont know how to solve

cus its not trinomial

😢

[wraith hinge]

okay just factorise the bottom

so its (x + 6)(x - 6)4x(3x -1)

[quartz fulcrum]

ok do the 4x will b 1 and demoninator will be x-

nvm

[wraith hinge]

a function is undefined if the denominator is 0

[quartz fulcrum]

ok

[wraith hinge]

so (x + 6)(x - 6)4x(3x -1) = 0 but things will cancel at the top

find the values of x where this equals 0

[quartz fulcrum]

whete did 4x(3x-1) come frm

[wraith hinge]

factorising 12x^2 - 4x

take a factor of 4x out so it becomes 4x(3x - 1)

[quartz fulcrum]

wait what

😭

wait step by step slow pls

[wraith hinge]

you have the equation 12x^2 - 4x

[quartz fulcrum]

im still on the 1 thing

not 2 yet

[wraith hinge]

first you can take a factor of x out

so x(12x - 4)

12 and 4 have a common factor of 4

so we can also take a factor of 4 out

so its 4x(3x - 1)

[quartz fulcrum]

this is where im at

[wraith hinge]

because if you expanded 4x(3x - 1), it would give you 12x^2 - 4x

okay on the next fraction

factorise the bottom

doing what i just said

[quartz fulcrum]

yes but

u teach so fast

i have a head ache on my left side

[wraith hinge]

read slow then

[quartz fulcrum]

yes but

did i do it right

[wraith hinge]

yes

now move onto the second fraction and factorise

[quartz fulcrum]

if u factor 2nd then wouldnt the x-6 be affected

so u cant factor by 4

[wraith hinge]

no

because youre only factorising on the denomiator

youre not changing the top

[quartz fulcrum]

ok

hold on

ok i did it

im confused the the 3

what do u do w 3

[wraith hinge]

nothing

[quartz fulcrum]

oh

[wraith hinge]

now put brackets around the things at the top

and combine into one fraction

[quartz fulcrum]

i now have more head ache what do u mean

😢

[wraith hinge]

youll now see that you have 4x, (x-6) and (x+6) on both the numerator and the denominator so you can just cancel those

[wraith hinge]

ill write it out

[quartz fulcrum]

thank u

[quartz fulcrum]

ohhh

idk why i get very scared doing math

wait what

how is -1 stil same

wouldnt it be 9x-3

[wraith hinge]

what

[quartz fulcrum]

so

idk what to do

idk how to like do it

[wraith hinge]

youre missing brackets around the (x-4)

[quartz fulcrum]

wdym

coudl u circle it

pls

[wraith hinge]

2nd from bottom line far left

[quartz fulcrum]

ph

oh*

so u mean this thing

i dont know how to factor into trinomials if its like this

like i know how to do 2

but not 3

3 is scary

🧍‍♀️

<@&286206848099549185>

[trim jolt]

@quartz fulcrum Has your question been resolved?

[quartz fulcrum]

kinda i did it on my own

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell notch]

limit of Vn

[trim jolt]

@shell notch Has your question been resolved?

[slate oak]

I think it can be viewed as an integral in the limit

using b=1 a=0 in the defined integral

[shell notch]

u mean Riemann integral ?

[slate oak]

Yes

[trim jolt]

@shell notch Has your question been resolved?

Channel closed

Closed by @shell notch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal meteor]

did i get it wrong or did i input it wrong?

[true bane]

lmao this isn't really a math problem

clearly there was something wrong with the format

[formal meteor]

ik hut

u guys are math experts

and idek what they mean by real number

like how would u have put it

[true bane]

yeh it doesn't look like your fault. looks like oversight from whoever wrote the problem/code

[formal meteor]

ohh ok

.close

[trim jolt]

Channel closed

Closed by @formal meteor

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral relic]

how is(-2,0) and v=(2,4) obtained blanking out rn

[ionic pendant]

by plugging in the values of x and y at the corners

[spiral relic]

forgot abt those, spent too much time looking at the sol. thx

.closed

.close

[trim jolt]

Channel closed

Closed by @spiral relic

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pure rover]

5 dg/m to dag/cm

[pure rover]

would i solve using 10^-2/10^1 * 10^2/1

[wary rampart]

stoicheometry

uhh

just convert one at a time and cancel out units

[pure rover]

my friends said you flip the last part because of something

[wary rampart]

5dg/ 1m x 1m/100cm

[pure rover]

why is cm at the bottom?

[wary rampart]

cause you cancel out the m

you cant have m at the bottom or else it wont cancel out

then apply the same thing to dg and dag

[pure rover]

wouldnt dg and dag flip too

so you flip the whole thing?

[wary rampart]

you have dg/cm now and you multiply by dag/dg

however many dag are in a dg

idek the units

[pure rover]

oh oops

[wary rampart]

you need to cancel out the dg and replace with dag basically

just take the initial value and multiply by the metric conversions while making sure you cancel out units ur not gonna use

[pure rover]

wouldn't dg and m be att the bottom

to cancel it out

[wary rampart]

dg/m x m/cm -> dg/cm

then

dg/cm x dag/dg -> dag/cm

two steps to cancel out the old units

[pure rover]

huh

smth like this right

[wary rampart]

yep

same approach

do exactly that

but with ur units

[pure rover]

so i flip it AGAIN?

[wary rampart]

wdym flip

its just multiplying

[pure rover]

whats the full equation

like in the image form

[wary rampart]

theres no flipping or anything

[pure rover]

huh

[wary rampart]

ur just multiplying by conversions

[pure rover]

wait hol on

ok so say if i wanna do kw/h to jules
1w/10^-3 * 3600/1 right

you dont flip that

[wary rampart]

i forgot how those units work

[pure rover]

5 dg/m3 = dag/cm3

thats the question

[wary rampart]

meters cubed?

[pure rover]

ye

[wary rampart]

oh well thats a different conversion i didnt know that

uhh 100 cm in a meter so theres 100^3 cm3 in 1 m3

[pure rover]

yes

[wary rampart]

there

same logic

now you just do the math to find the answer

(5 x 100) / 100^3

[pure rover]

hmm ok

.close

[trim jolt]

Channel closed

Closed by @pure rover

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal halo]

answer according to textbook: $\frac{5}{11}\newline$

$P=\frac{\text{lines that don't intersect}}{\text{all lines}}\newline$
total number of lines = $\binom{12}{2}\times\binom{12}{2}$ because Alice and Bob each choose 2 points out of 12 on the clock
case 1: Alice chooses the same point twice
Bob can choose any point except the ones Alice chose. hence, there are $\binom{11}{2}$ ways to make a line which doesn't meet Alice's "line"

all of these cases go clockwise just for my convenience :)

case 2: Alice's points are adjacent
same as case 1, but Bob can only choose 10 points
$\binom{10}{2}$
case 3: Alice's points have 1 space apart
$\binom{9}{2}$
case 4: Alice's points have 2 spaces apart
$\binom{8}{2}+\binom{2}{2}$ because Bob can choose the 2 points in between the points Alice chose
so for this, i generalise:
case n:
$\binom{12-n}{2}+\binom{n-2}{2}$
if the choose function isn't defined for that, then it's 0 (ie, $\binom{1}{2}$ will just be 0 here)
adding all the cases up:
$\binom{11}{2}+\binom{10}{2}+\binom{9}{2}+(\binom{8}{2}+\binom{2}{2})+\binom{7}{2}+\binom{3}{3}+...+\binom{9}{2}+\binom{10}{2}=385$
so in the end, i got $\frac{285}{4356}$

[surreal halo]

hold on i accidently clicked enter:

[formal turret]

Just copy and continue?

[solid kiln]

ـDraedon

[surreal halo]

oh at the end, it's meant to be $\frac{385}{4356}$ not 285 on the top

[solid kiln]

ـDraedon

[surreal halo]

i hope you can make sense of my "working out"

[trim jolt]

@surreal halo Has your question been resolved?

[surreal halo]

@pliant seal combinatorics 😔

[trim jolt]

@surreal halo Has your question been resolved?

[surreal halo]

<@&286206848099549185>
it's been 40 minutes since the last ping so i hope it's ok to ping again!

[trim jolt]

@surreal halo Has your question been resolved?

[trim jolt]

@surreal halo Has your question been resolved?

[trim jolt]

@surreal halo Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frosty heron]

How did they come up this equation

[severe stump]

Area A is the area of a trapezoid. Area B is a triangle

Area of a Trapezoid = height times the average of the two base lengths

$A_{Trapezoid}=height\times \frac{base_1+base_2}{2}$

[solid kiln]

Narutoes

[severe stump]

$A_{trapezoid}=(4)\times\frac{10+u}{2}$

[solid kiln]

Narutoes

[frosty heron]

Oh

[severe stump]

And then the triangle is straightforward.

[frosty heron]

Gotcha

Thank you

[severe stump]

Np

[frosty heron]

.close

[trim jolt]

Channel closed

Closed by @frosty heron

Use .reopen if this was a mistake.

[severe stump]

If you're curious, the second Area A is just them chopping it into a rectangle+triangle

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen sable]

Can someone explain why the following questions are wrong. The correct answer is in pink. #2 I had put what i thought the answers were for each option. #6 why is statement 1 true? #21 why is it C and not E? Can it never be option E? #18 I dont know where i went wrong

[knotty locust]

in 21

"If 2=3, then I do not have a penny"

P is the event 2=3
Q is the event you not having a penny

P => Q

an equivalent statement would be the contrapositive

not Q => not P

not Q is the event of you not not having a penny, i.e, you having a penny

not P is the event 2 != 3

so

I have a penny => 2 != 3

which is option (c)

It looks like your work for problem 18 matches the answer, so I'm confused what you're confused about for that.

@keen sable

for problem 2, you selected N \ (2,5) which is N disjoint from 3, and 4, which is not the set {2, 3, 4, 5}

[trim jolt]

@keen sable Has your question been resolved?

[knotty locust]

@keen sable why hit the ❌ but not respond to my attempt to answer your questions?

[trim jolt]

@keen sable Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steel birch]

can someone pls explain this pls

[unreal loom]

what specifically do you not understand

[steel birch]

Um i dont understand the tip at the bottom

Actually i dont understand how to do matrix exopnential very well

Currently cramming and panicking lol

I need someone to explain step by step how to do it please

@unreal loom

Lije what is it referring to

What would splitting into diagonal part and nilpotent look like for example

[unreal loom]

so basically I think you need to split it into D+N

where N is nilpotent

so when you do e^(D+N) you get e^(D)e^(N)

which is easy to compute

[unreal loom]

do you get the taylor series definition

[steel birch]

Yes i ubderstand that

[unreal loom]

do you get why we want a nilpotent matrix

or a diagonalizable matrix

[steel birch]

Not really

[unreal loom]

well using the taylor series definition

we can calculate the exponential if we know all the powers

and for a nilpotent it will be a finite sum since at some point the power will be the zero matrix

[steel birch]

uhh

can i get an example

[unreal loom]

like e^[[0,1],[0,0]]

because A^2=0

you can just do I+A

since all higher terms will vanish

[steel birch]

so that's a nilpotent matrix? also int he example i provided above at a glance did they just expand out the taylor seeries of the 3 by 3 matrix

[wooden plover]

• [[0,1],[0,0]] is nilpotent yes.
• which part are you talking about specifically ?

[steel birch]

erm they mentioned that the matrix is diaganolizable by said eigen values

[wooden plover]

yea

[steel birch]

did they use that fact to find the answer? im not sure how to diagonalize the matrix using the eigens and how to incorporate that into the "splitting into diagonal part and nilpotent"

[wooden plover]

"splitting into diagonal part and nilpotent" the matrix A is already diagonalizable, you don't have any 'split' to do here

[steel birch]

how do you know if it's diagonalizable?

[wooden plover]

there's 3 distinct eigenvalues

so that's a dead giveaway it's diagonalizable

(but I'm not saying all diagonalizable matrices have distinct eigenvalues)

[steel birch]

so what are the conditions that give awawy if a matrix is not diagaonlizable

[wooden plover]

gotta find the eigenspaces then

so essentially attempt to diagonalize your matrix, if you don't have enough eigenvectors in the end, you're cooked

[steel birch]

alright then

i dont think that im gonna do that well on that question for my test

[wooden plover]

well if you're fine for the other questions, there's nothing else you can really work on...

can you bring a cheat sheet or no ?

cause if you can, just jot down everything you think you'll forget about matrix exponentials

[steel birch]

no

its closed book

[wooden plover]

rip

[steel birch]

what is the matrix called where its fx gx fy and gy again?

[wooden plover]

jacobian?

[steel birch]

ah right

uh last question before i have to go

for the jacobian of this

would it be fx gx hx fy gy hy fz gz hz

since its a 3 by 3

[wooden plover]

yes it will be 3x3

[steel birch]

alright then

fx means differentiating wrt to x right?

so y and z are constants

[wooden plover]

yep partial derivatives

[steel birch]

alright tyvm!

i have to go now

ty for the help!

.close

[trim jolt]

Channel closed

Closed by @steel birch

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark granite]

how do I set this up??

[trim jolt]

@dark granite Has your question been resolved?

[dark granite]

<@&286206848099549185>

[silk dawn]

I cant help you with your question, but since this looks more like a physics question to me you might want to check #old-network

[dark granite]

thought process is that as velocity reaches lightspeed, the mass will increase and therefore will become infinitely heavy

and thanks! It's from a math homework set

[sweet hare]

I think that is the case, yes

[dark granite]

is there a way to prove numerically here?

[sweet hare]

what if you make it one fraction under the square root? i.e., (c^2 - v^2) / c^2

[dark granite]

hmmmmm

if I use c^2-v^2/c^2

it'll just get really big as vincreases

[sweet hare]

c is a constant

[dark granite]

*v

[sweet hare]

you can pull out the denominator there

[dark granite]

so rewrite it as c^2(c^2- v^2)

[sweet hare]

no

[dark granite]

not sure

[sweet hare]

$\frac{m_0}{\sqrt{\frac{c^2 - v^2}{c^2}}} = \frac{m_0 c}{\sqrt{c^2 - v^2}}$

[solid kiln]

cwatson

[dark granite]

how do we simplify further?

[sweet hare]

not sure yet

you have to prove it numerically?

[dark granite]

It just asks what happens

I think this is enough

thanks

[sweet hare]

oh, yeah in that case the mass increases to infinity

since v < c always, as v gets closer and closer, the denominator will be a very small number. so dividing by that results in a very large number

[dark granite]

thanks

makes more sense now

gotcha

.close

[trim jolt]

Channel closed

Closed by @dark granite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steep grove]

why do we have to add a term z^2 to our boundry function if it's an inequality when dealing with lagrange mulitpliers?

[steep grove]

let's say f(x,y) is the function we want to take the min and max for
with g(x,y) being the boundry x^2 + y^2 =< 3 for example

why does g(x,y) become g(x,y) + z^2 = 0

[trim jolt]

@steep grove Has your question been resolved?

[trim jolt]

@steep grove Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal epoch]

how do i do the third question

[vocal epoch]

i tried doing it but someone in another help channel said it was all wrong so idrk what to do

[sharp herald]

Ok.

Um

[vernal warren]

check whats cos30

and where 30 lies in the quadrant

ig u dont wanna answer so i will

Quadrant I = all trig are positive
Quadrant II = sin only positive
Quadrant III = tan only positive
Quadrant IV = cos positive
using these help u solve those question

[vocal epoch]

did i do the cos=(-1/3) thing right

[vernal warren]

yes

cos theta = -1/3 , means that cos is negative

[vocal epoch]

one of the angles is gonna be in quadrant 1 cuz thats always positive but like

how do i know if its in 2 or 3

[vernal warren]

is -1/3 positive?

[vocal epoch]

no but thats cuz its cos

[vernal warren]

doesnt matter

-1/3 is not positive , its negative

means it lies in either Quad II or Quad IV

[vocal epoch]

why quadrant 2

[vernal warren]

read what i sent

[vernal warren]

.

[vocal epoch]

why would it be in quadrant 4 if its negative and cos

[vernal warren]

oh f , my bad

Quad III

[vocal epoch]

???

[vernal warren]

cos theta = -1/3

its negative

that means it either lies in Quad II or Quad III

[vocal epoch]

what do i do with that information

[vernal warren]

have u never truely learnt this then

[vocal epoch]

i have i just cant remember anything

[vernal warren]

would be better if u can review ur notes

Quad I = general angle
Quad II = 180 - general angle
Quad III = 180 + general angle
Quad IV = 360 - general angle

[vocal epoch]

so are the angles 210 and 150

.close

[trim jolt]

Channel closed

Closed by @vocal epoch

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Show your work, and if possible, explain where you are stuck.

[main flower]

I tried doing RREF and it gives me -a-10 but that doesnt work for some reason

[sharp herald]

Do you know the definition of a span?

[main flower]

yes, why?

[sweet hare]

double-check your arithmetic

[main flower]

I didnt really do it i used online RREF calculators

[sharp herald]

I mean check if span(S) is P^3(R)

If it is then all a’s work.

[main flower]

cant i do this?

[sharp herald]

Actually you are missing a basis vector lol

Like for it to span the whole P3(R)

[sweet hare]

no they're not

[sharp herald]

It has dimension 4

[main flower]

I dont quite follow

[sharp herald]

Wdym

It has dimension 4 tho

[sweet hare]

it's asking if v is in the span of S

[sharp herald]

Oh

Right

[sweet hare]

not the span of P3 or whatever

[sharp herald]

I mean there is one choice that says like the every value of a works or something

Well it eliminates that choice

[main flower]

from that it gives me this

[sweet hare]

that's not what I got

[main flower]

its the second last step

the last step is just RREF

[main flower]

what did you get?

[sweet hare]

a = -6

[main flower]

strange

@sweet hare

[sweet hare]

I got a = -9 actually

[main flower]

Its correct. But how?