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#help-38
pearl tendon
Do you have a graphing calculator? Or are you familiar with desmos?
actually seeing these curves can be helpful
pearl tendon
Here's the graph of your original function.. notice the x values -8 and 0... notice that y = -122 when x = -4
lofty stone
Yeahh i see
pearl tendon
notice the slope is decreasing from - infinity to -4
stops (slope = 0)
then is increasing from -4 to infinity
It helps
lofty stone
Yes tysm
pearl tendon
np.. good luck
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urban oar
ACT practice
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urban oar
Questions are loading
Having trouble with these
I saw a video for the decimal digit one but didn’t really understand it
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true bridge
For proving ii)
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For proving ii)
true bridge
is thsi correct? I'm not sure if were allowed to exchange expectations and supremums like this ...
can someone explain
<@&286206848099549185>
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zinc ginkgo
is thsi correct? I'm not sure if were allowed to exchange expectations and supr...
You can prove it yourself with dominated convergence theorem
Expectation is just an integral
And Xn are nonnegative L¹ functions
But if you need more explanation, probably should ask in #advanced-analysis
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unique lichen
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unique lichen
proved its not a sub space but i just dont know how to enter two vectors in H whose sums not in H
sorry for the terrible hand writing avg econ major lmao
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true bridge
You can prove it yourself with dominated convergence theorem
ok i see
true bridge
but I dont understand exactly how DCT is applied but my intuitive understanding is since its L1 bounded the expectation < M for some M and that can serve as dominating function ig?
and then u can bring sup outside expectation
is that correct?
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strange lynx
strange lynx
Use the shell method to find the volume of the solid generated by revolving the region bounded by the given curves and lines about the x-axis. y = 3x, y = 6x, y = 3
mb
so because it expanded to 2 quadrants
i have no idea whats going on now
broken pilot
so because it expanded to 2 quadrants
have you drawn the region?
strange lynx
ye i did
broken pilot
Can you send a picture of it here?
strange lynx
broken pilot
Still in the first quadrant
strange lynx
hmmm
mb
i thought when i revovle it
which line should i use for the volume btw
cuz when i go up it hit 6x first
but it gives the wrong answer
3x gives the right one
but idk why we use 3x
broken pilot
which line should i use for the volume btw
What do you mean
strange lynx
so like for the volume right
i have to figure out the height of the solid
cuz the radius is alr x
but the height
idk what is it
broken pilot
The height of the solid of revolution?
strange lynx
yes
strange lynx
broken pilot
Should it not be ((6x)^2 - (3x)^2)?
Not the same thing as (3x)^2
Because the cross section is an annulus
strange lynx
oh i see
strange lynx
Should it not be ((6x)^2 - (3x)^2)?
then isnt it washer method then??
broken pilot
then isnt it washer method then??
oh my bad
strange lynx
ye its asking for shell method
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scarlet peak
this should be easy by the looks of it but i cant wrap my head around it lol
scarlet peak
sadly no solution paper to this one
unless the bottom part i did calculate is the actual combinations but i doubt it? since it doesnt consider the total number
chilly cloak
Your answer could be correct, if it asked different books, instead of categories
In this case, it's simply 3*5 + 5*9 + 3*9
(you can figure out why)
scarlet peak
sorry your formatting got a bit messed up ^^
but thank you!
thank you i get the formula ^^
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full dock
I don’t get it, if u = x+1 why isn’t the numerator just 2u? Where does the +3 come from
full dock
like why doesnt it just $\int\frac{2u}{u^{2}+4}du$
solid kilnBOT
water beam
coral needle
u = x-1
gritty dew
the u is equal to x-1, not x+1. so you get 2u+3 = 2(x-1) + 3 = 2x - 2 +3 = 2x +1
gritty dew
the way it was written is just confusing, all in one line
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marsh forum
let $f:\mathbb{R} \rightarrow \mathbb{R}$ be a differentiable function satisfying $f'(x)=x+f(x)$ if $f(0)=0$ find $\lim_{x\ \rightarrow0}\cdot\frac{f\left(x\right)}{x^{2\ }}$
solid kilnBOT
Why am. I here
solid kilnBOT
Why am. I here
marsh forum
on differentiating again we get $\frac{1+x+f(x)}{2}$
solid kilnBOT
Why am. I here
marsh forum
so the limit is $\frac{1}{2}$
solid kilnBOT
Why am. I here
marsh forum
however my book says the answer is 1
where did I got wrongf
I could probably solve the differential equation to find f(x) instead
would that be a better idea
dusty hound
f''(x) = (x+f(x))' = 1 + x + f(x)
So f''(0) = 1
and therefore f(x) = x²/2 + o(x²)
Also, WA gives that the solution is e^x - x - 1
For which one can easily verify that f(x) / x² -> 1/2
marsh forum
why is what I did wrong though
maiden hare
You're right it's 1/2
dusty hound
I therefore agree with you that it is 1/2
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marsh forum
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maiden hare
**Why am. I here**
You don't need to do L'Hôpital again here, just cancel the x
Wait no never mind
I'm drunk 
marsh forum
oops, sorry for closing as you were typing Nel
raw magnet
I'm drunk <:KEK:586240877358350341>
dont drink and derivate
maiden hare
And the limit of (e^x - x - 1)/x^2 at 0 is 1/2
hallow crane
marsh forum
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fathom warren
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split chasm
no
explain your reasoning for your choices
of why you checked/didn't check a certain box
fathom warren
explain your reasoning for your choices
of why you checked/didn't check a certai...
So to be real i just did it random cuz my teacher dosent explain shit me and another freind ask her about a question he said i dont know
split chasm
start by searching up stuff on
classification of quadrilaterals
properties of parallelograms
properties of rectangles
and try make a genuine attempt
fathom warren
okay
split chasm
also identical markings like that in the first and second figures indicate congruence
fathom warren
also identical markings like that in the first and second figures indicate congr...
okay thank u
random niche
If I want to write $sin \ t$ in terms of $cos \ t$
is this correct?
\
$cos^{2}t = 1 - sin^2t$
\
$\sqrt{cos \ t} = \sqrt{1 - sin^2 \ t}$
split chasm
no
tepid rock
Learn exponent rules.
crimson void
$\sqrt{cos \ t} = \sqrt{1 - sin \ t}$
wanton tendon
Still no?
crimson void
$cos \ t = \sqrt{1 - sin^2 \ t}$
solid kilnBOT
Kariok
wanton tendon
$\sqrt{|\cos t|} = \sqrt{\sqrt{1 - \sin^2 t}}$
wanton tendon
This one
wanton tendon
**ZapMighty**
This is the way
random niche
it should be cos
solid kilnBOT
Tyeshela
split chasm
stop with the spam
isolating cos(t) wasn't your initial problem statement
you'd also need to consider cases for positive/negative
random niche
it is in the second quadrant.
proper kernel
@random niche @crimson void @ember comet you need to type \sin and \cos so that the letters stand upright
split chasm
stop with the spam
random niche
$\sin t = \sqrt{1 - \cos^2t}$
solid kilnBOT
Tomi
wanton tendon
No, $|\sin t| = \sqrt{1 - \cos^2 t}$
solid kilnBOT
ZapMighty
Tyeshela
Tyeshela
$\begin{bmatrix}
a_{11} & a_{12} \\
a_{21} & a_{22} \\
\end{bmatrix}$
split chasm
No, $|\sin t| = \sqrt{1 - \cos^2 t}$
they gave use new info that t is in q2, so abs val not needed
random niche
No, $|\sin t| = \sqrt{1 - \cos^2 t}$
hmm, it is in the second quadrant so it should be positive.
wanton tendon
Oh
split chasm
with all due respect @ember cometplease gtfo
ripe topaz
proper kernel
remember for next time that whether its √ or -√ depends on the quadrant
split chasm
spamming, being intrusive, not contributing anything meaningful to the question
proper kernel
when sin t is positive, do √
when sin t is negative, do -√
old grove
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old grove
what is the angle from the bank using vectors
jaunty scarab
draw it
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@old grove Has your question been resolved?
pearl tendon
oooh, trig
@old grove think about tangent
you have the speed for lateral movement (opposite) and you have the width of the river (adjacent)
you're going to have to do a little math to get the opposite length, but it's just a distance problem.. speed x time
wanton tendon
You want John to end up directly opposite, i.e., move only perpendicular to the bank(or the river's flow). So the vector component of John's velocity parallel to that of the river should be opposite of that of the river (be anti-parallel). Let river's velocity be 1i, and John's velocity be xi+yj. Now solve for x and y, and you'll get the angle as arctan(y/x).
pearl tendon
I think OP bailed
marsh forum
What methods would I use to find the bounds?
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What methods would I use to find the bounds?
marsh forum
I was thinking of using taylor expansions
intuitively I feel it's between 1 and e
as $e^{x^2}$ is an increasing function
solid kilnBOT
Why am. I here
light karma
intuitively I feel it's between 1 and e
nice
marsh forum
ok, so the minimum value the function takes in the interval is 1
light karma
its right
light karma
this is the easiest way
idk any other
generally we look at the maxima or minima and estimate
marsh forum
like how would I write it if this were a subjective question
ripe valley
is there any more formal way of doing this?
Try evaluating it ig
Should be just a simple u sub
tepid rock
As if lmao
ripe valley
Integral of e^x from 0 to 1 * 2
light karma
we cant integrate
marsh forum
Should be just a simple u sub
pretty sure $e^{x^2}$ isn't integrable in terms of elementary functions
solid kilnBOT
Why am. I here
light karma
say that e^x is increasing (0,1)
minima at x = 0
maxima at x = 1
so 1 < e^x^2 < e
integrate now
marsh forum
hmm, thanks!
tepid rock
say that e^x is increasing (0,1)
minima at x = 0
maxima at x = 1
so 1 < e^x^2...
(this is applicable as long as this is true in the entire interval, you can integrate and the inequality still holds true)
marsh forum
so if I were finding the bounds between $0$ and $n$ the bounds would be $(1, e^{n^2})$?
solid kilnBOT
Why am. I here
tepid rock
(As long as n > 0)
light karma
yeah
marsh forum
(As long as n > 0)
here as it's an even function, I just multiply the bounds by 2, right?
light karma
symmetric about origin
tepid rock
y axis*
tepid rock
here as it's an even function, I just multiply the bounds by 2, right?
That's if the integral is from something negative to something positive.
Not 0 to n
But -n to n, yeah
marsh forum
ah, OK. Thanks!
light karma
btw is (-ve)^irrational defined
tepid rock
yes.
light karma
but
tepid rock
But let's not use someone else's channel.
light karma
okie
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carmine gate
names of the topics in these questions?
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names of the topics in these questions?
marsh forum
Q28?
carmine gate
huh
marsh forum
ok, q28 is exponents
carmine gate
idk i just need the topics
hallow spruce
scientific notation it seems
carmine gate
thanks
jovial fox
why does he drop the kx^2?? i dont get that part
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why does he drop the kx^2?? i dont get that part
jovial fox
he determines its >=0 and says because of that we can get rid of it but that makes no sense
zinc ginkgo
why does he drop the kx^2?? i dont get that part
What's the original problem
lament reef
why does he drop the kx^2?? i dont get that part
he doesn't get rid of it, he uses an inequality
jovial fox
so where does it go?
also isnt the inequality always there? the = is just him expanding the right side of it no?
lament reef
yes that's true
you agree kx^2 is positive right?
if we add any positive number to something, it'll always get bigger
jovial fox
yes
heres the video if it makes any more sense https://www.youtube.com/watch?v=e0WvgwfZXyc&ab_channel=AndrewRechnitzer
jovial fox
i understand kx^2 is positive
that part makes sense
i just dont get why it disappears
sleek canopy
because he want to write something smaller so he just delete the positive amount kx^2
jovial fox
because he want to write something smaller so he just delete the positive amount...
i dont get it
isnt it on the smaller end of the inequality too?
how can you just remove it
lament reef
take a tiny example
lament reef
how can you just remove it
do you agree that $3 + x^2 \geq 3$
solid kilnBOT
doaby
jovial fox
yes i agree w that but isnt the kx^2 on the opposite end of the inequality??? isn't it more akin to 3>= 3+kx^2??
bc the inequality is (1+x)^k+1 >= 1+(k+1)x +kx^2 no? how can you just remove kx^2 if its on the "less than" side of the inequality
oh wait i think it just clicked
hes saying either way we're operating under the assumption that the left is >= to the right. so even if we take away kx^2, the left will still be >= to the right because the right simply shrunk
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plush igloo
I have 3 points A, B and C and i need to change B's positions so that A, B and C are on the same line, B's distance to C remains the same and B is not in the middle of the 2 other pointsd
plush igloo
i have point A in (0,0) here but it can be anywhere and it will be anywere. the red is point C and blue is point B, i need to move point B such that it is on the outside of the circle and still has the same distance between point C
i first tried to just 2C - B but that just makes it inverse
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plush igloo
nope
tried some other stuff myself in the meanwhile but no results
2A - C - B seemed to kind of work but also not really
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@plush igloo Has your question been resolved?
plush igloo
no but i don't think anyone's willing to help or try anyway
short trellis
y equals 1+x/x how can i draw thsi function graphyccly
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y equals 1+x/x how can i draw thsi function graphyccly
delicate belfry
Find asymptotes, x- and y-interceptions.
wraith hinge
can you draw and show me
put it into desmos
delicate belfry
What x value is unvalid here?
short trellis
i would say 0
delicate belfry
That is your x-asymptote. When the function closes x = 0, it would just approach, but not be f(0).
short trellis
it will get closer and closer but never be 0 right?
delicate belfry
For y-asymptote, you divide the whole fraction (numerator and denominator) with the variable in denominator that has the biggest power.
delicate belfry
it will get closer and closer but never be 0 right?
Yes, due to 1/0 is undefined.
short trellis
ok next what
delicate belfry
For y-asymptote, you divide the whole fraction (numerator and denominator) with ...
This.
short trellis
firs how would i draw the asymptotes can you show me?
delicate belfry
firs how would i draw the asymptotes can you show me?
For x-asymptote that you just found, x = 0.
short trellis
y is 1+x?
delicate belfry
For y-asymptote, you divide the whole fraction (numerator and denominator) with ...
You'll be using this for your y-asymptote $$\lim_{x \to \infty} \frac{x+1}{x}$$
solid kilnBOT
Good
delicate belfry
so can you show me how would i draw thoes asymptotes
Those are just lines.
short trellis
thoes are the asymptotes?
delicate belfry
Yeah.
short trellis
x line is like that becous x cant be 0 right?
delicate belfry
Yes.
short trellis
what about y
delicate belfry
Denominator restrictions.
short trellis
wym?
delicate belfry
For y-asymptote, you divide the whole fraction (numerator and denominator) with ...
The step.
short trellis
1?
delicate belfry
$\lim_{x \to \infty} \frac{x+1}{x} = \lim_{x \to \infty} \frac{1+\frac{1}{x}}{1}=\frac{1+0}{1}=1$
solid kilnBOT
Good
delicate belfry
It's.
Those are the restrictions. Now you could just plug in numbers and get points, out of those points, sketch the graph.
short trellis
the one and 0 are restrictions?
so y cant be on 1 and x cant be on 0?
now i can use basic function graphics right
delicate belfry
Sketching a graph? Yeah.
short trellis
it should be like a prabola right?
delicate belfry
In a way, but it's not. Use desmos to visualize.
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true coral
is n!+1 a prime infinetly often?
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is n!+1 a prime infinetly often?
true coral
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snow oyster
did you have a math related question?
yes
what is the equation for bonemshing
¿?
i have an exam tomorrow
lethal anvil
yeah not in the mood. good luck
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livid dune
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digital bolt
yes
livid dune
👍
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hard grove
$\sum_{i=1}^n f_i = f_{n+2}-1$
How would I prove this, ik i would prolly have to use induction
solid kilnBOT
JWIVY
hard grove
but how would i get the base case etc.
dull temple
base case would probably be n=1
spice fulcrum
is this for a sequence?
dull temple
what's f?
hard grove
the function
spice fulcrum
im assuming it has something to do with fibonnaci
yes, i think it does have something to do with fibonnaci
do you know what it is and how it is defined?
hard grove
nah jus how do i prove it is all
lime yew
Do you have original task from which this problem came from?
lime yew
This is a well known identity for fibonacci sequence but it's not given that {f(n)} is a fibonacci sequence
More it's not even given how f(n) is defined
hard grove
oh i believe its defined as f_0 = 0, f_1 = 1, f_2 = 1...
would i use that to prove it?
hard grove
ngl idek wuts happening 💀
lime yew
Oh you edited
It looks like fibonacci sequence but it's missing that f(i) = f(i-1)+f(i-2)
hard grove
oh i believe its defined as f_0 = 0, f_1 = 1, f_2 = 1...
is this all i need
to prove?
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earnest breach
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earnest breach
11.5, can I just rewrite the (a x b) * a as (a x a ) * b?
If yes, I can use the fact that the cross product, (a x a) is just 0.
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patent socket
this simplification isn't possible right?
trim joltBOT
this simplification isn't possible right?
patent socket
i'm finding mixed answers online and in the book i'm using
spice fulcrum
why wouldnt it be psosible
patent socket
because
in the first premise
either "there exists a x such that P(X)" or "there exists a x such that Q(X)" or both of them can be true to satisfy it, but it's possible that it's only "there exists a x such that Q(X)" that is true, so sim;lifying the premise to "there exists a x such that P(X)" would be false
low gazelle
Whats the context
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deft pebble
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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
austere cedar
Consider cases.
- What if Alan's two numbers are different?
- What if Alan's two numbers are the same?
jade berry
what did you try
shrewd ridge
yes
shrewd ridge
probably not 1/3
deft pebble
isn't it cuz 1/6+1/6
shrewd ridge
if you add probabilities, you get expected value
deft pebble
how did youget 11/36
shrewd ridge
when she gets two, it makes up for a case where she gets none
and it's an overestimate
i found probability of not getting the number
5/6 on the first roll, and 5/6 on the second, so 25/36 overall
deft pebble
yea
shrewd ridge
now you can solve it
deft pebble
so 37/72?
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crimson rover
why isnt this being rotated clockwise 45 degrees? or am i subbing this in wrong
still plinth
it's rotated counterclockwise 45 degrees?
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flint zephyr
Hello guys, beginner question here. I am aware of the steps needed but the numbers confused me. What should i do here?
split chasm
describe the steps you think are needed
flint zephyr
well i saw that one u write them all down , and then i think u find the common number between them and multiply the 17 and 16 after right? Im sorry im new to this
nevermind it was explained to me by someone else
thank you for your time
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warm ginkgo
Is this calculation valid/correct?
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Is this calculation valid/correct?
warm ginkgo
$\begin{aligned}
&\lim_{x\rightarrow+\infty}{\ln{\left(\frac{x}{\sqrt{1+x^2}}\right)}} = \
&\lim_{x\rightarrow+\infty}{\ln{\left(\frac{x}{\sqrt{1+x^2}}\right)}} + \ln{\left(\frac{\frac{1}{x}}{\frac{1}{x}}\right)} = \
&\lim_{x\rightarrow+\infty}{\ln{\left(\frac{1}{\sqrt{\frac{1}{x^2}\left(1+x^2\right)}}\right)}}
\end{aligned}$
solid kilnBOT
Bennxy
tardy hemlock
Is this calculation valid/correct?
Could've multiplied numerator and denonimator in the fraction by 1/x right away, but yes
potent bone
$$\frac x{\sqrt{1+x^2}} = \frac1{\sqrt{\frac1{x^2}(1+x^2)}}$$
solid kilnBOT
bee [it/its]
warm ginkgo
Could've multiplied numerator and denonimator in the fraction by 1/x right away,...
Did you mean without the need of writing it down explicitly?
tardy hemlock
Did you mean without the need of writing it down explicitly?
$\ln(\frac a b) = \ln(\frac a b \cdot \frac{c}{c})$
warm ginkgo
Aha yes. That's like what I did, without the extra step ln((1/x)/(1/x))
But thanks for confirming that it's correct
Have a nice day👋
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steep oak
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steep oak
I’ve got this for 3. And 4. To get 5. Do I just substitute 4 where x is in my answer to 4.
steep oak
<@&286206848099549185>
steep oak
once
steep oak
and still no reply
onyx forge
so
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trim kestrel
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trim kestrel
ik i have to use this identity but idk how
well sin 2x = 2 sin x cos x
1/2 * [2sin 3/16 * cos 3/16]
so the x value is 3pi/16
sin 2(3pi/16) is 3pi/8 which you cant really do
deft flame
4sin(3pi/8)cos(3pi/8) = 2 x 2sin(3pi/8)cos(3pi/8)
trim kestrel
So my problem is that I was doing it by the entire expression
When its really just 2 * 2 sin
trim kestrel
4sin(3pi/8)cos(3pi/8) = 2 x 2sin(3pi/8)cos(3pi/8)
So is my answer sin 270?
deft flame
uh
4sin(3pi/8)cos(3pi/8) = 2 x 2sin(3pi/8)cos(3pi/8) = 2 x (2sin(3pi/8)cos(3pi/8))
evaluate the stuff inside the outermost parentheses first
trim kestrel
evaluate the stuff inside the outermost parentheses first
How do I do that
wouldn't 2sin(3pi/8)cos(3pi/8) = sin2x
deft flame
yea
trim kestrel
Then I plug 2 back in to double it
deft flame
the 2 from outside doesnt double sin2x to sin4x
trim kestrel
well what do I do with it
trim kestrel
So 2 times 135
deft flame
2 times sin of 135
trim kestrel
Yea mb
deft flame
yea
trim kestrel
So its -1?
trim kestrel
Yea cause of the reference angle
wait
Oh so I do the sin of 135
Times 2
so it'd be sqrt2
deft flame
yes
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wanton pilot
I have to find the general solutions to this problem. But I don't know how to get the particular solutions
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lament reef
I have to find the general solutions to this problem. But I don't know how to ge...
first of all, I hate this. second of all, you could either use Laplace transforms OR power series solutions, that's what I'd recommend
if i were you I'd try Laplace first
wanton pilot
I mean there is this, but i am really trying my best to avoid it lmao
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wanton pilot
.reopen
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wanton pilot
<@&286206848099549185>
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slim mountain
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slim mountain
Ok so which is wrong here
vagrant marsh
youre all good
light karma
yeah
slim mountain
But it says there’s at least one not correct
slim mountain
So what is it
light karma
6 doesnt
slim mountain
actually its 3
I don’t get how
light karma
3 does
vagrant marsh
try factoring
slim mountain
-2x^3+2x /-x^3+4x^2?
light karma
2 times the denominator is numerator
slim mountain
-2x(x^2-1) / -x^2(x-4)
@vagrant marsh
vagrant marsh
check your numbers
vagrant marsh
thats not the right factorung
vagrant marsh
still not right
slim mountain
Dude how
slim mountain
I made it so x becomes -x first
vagrant marsh
ok sure
vagrant marsh
there you go
slim mountain
What now
vagrant marsh
what can you do now
slim mountain
Neither
vagrant marsh
does f(x) = f(-x)?
slim mountain
No
vagrant marsh
what is f(x)?
slim mountain
2
vagrant marsh
what is f(-x)?
slim mountain
Nothing
slim mountain
So it’s even?
vagrant marsh
ok
slim mountain
So odd
slim mountain
Ok it worked
vagrant marsh
awesome
slim mountain
.close
faint canopy
Hi uhhh so im here because im hoping someone could help me understand differentiability, derivatives, the difference quotient, and extremes. ive gone through the derivation rules and am able to determine extremes and derivatives using them but i honestly have no idea what im doing and why it works. don't really know what derivatives are either, but i do know how to form them. while I could certainly look up explanations online, id find it so much more fun to discuss these things (or some of em) with someone who would enjoy talking about them. however i also understand that these are broad topics, and i dont want to impose
slender shard
Hi uhhh so im here because im hoping someone could help me understand differenti...
A broader discussion like that should probably be done in #calculus. I think these channels are for more specific questions.
Or even #math-discussion
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wintry anchor
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wintry anchor
help plz
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scarlet escarp
what have you tried
wintry anchor
Im not sure on how to set up the integral
scarlet escarp
why not
wintry anchor
cuz idk
scarlet escarp
try your best and i'll let you know if it is correct or not
and if not we can go over how to fix it
scarlet escarp
both 1 and 2
scarlet escarp
this looks fine for area 1
scarlet escarp
i believe so
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wraith hinge
I need help with an algebra problem. I am not that good at math and I need help solving an equation on my math homework that I need to get done for school. I am doing common factors. The directions state: "Factor the common factor out of each expression." The problem is: 60n⁷ + 42n⁶ + 6n⁵ + 36n⁴
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fluid hound
wraith hinge
What?
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maiden parrot
I need help with an algebra problem. I am not that good at math and I need help ...
okeh me helpe u
maiden parrot
whats common in all of them menaing what ecah term has?
maiden parrot
How do I solve it
yeah
wraith hinge
Yes?
wraith hinge
Are you okay?
maiden parrot
so whats common in all of them
maiden parrot
Are you okay?
no sorry
wraith hinge
variable
maiden parrot
and whats the lowest exponent
wraith hinge
4
maiden parrot
4
hey
come look
ok so u see i took out the n^4
but its wrong
do you know why?
@wraith hinge
wraith hinge
No
wraith hinge
Uhhh
wraith hinge
.
gleaming forum
@wraith hinge Do you still need help?
wraith hinge
Tomorrow sadly I have school tomorrow. So I am going to sleep here soon.
gleaming forum
I wrote it down for you, if you can’t read my writing let me know
If you need further explanations dm me because im likely in school when you wake up
If anyone would like to add or explain this better feel free
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zenith panther
can someone help me with this question pls
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can someone help me with this question pls
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zenith panther
<@&286206848099549185>
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zenith panther
!status
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
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zenith panther
<@&286206848099549185>
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zenith panther
<@&286206848099549185>
restive arrow
?
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zenith panther
can someone help me with this question pls
Can someone help me with this question please
zenith panther
Do u not use one variable
So let’s assume that m is the total no. of men
I don’t understand the 3rd sentence which starts from “Half…”
supple sun
sorry i misunderstood thirty as 30%
supple sun
So let’s assume that m is the total no. of men
so basicly the question is what part of them men were married with wifes?
and how many women were married with husbands at the party?
supple sun
1/4 of the qunatity of man which were married went to the party with their wifes
and 1/2 of women which were unmarried were at the parrty with their husbands
so basicly they were mathced
and here the number of these perticuall women is euqal to these particullar man
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supple sun
some part of the man went with theirs wifes
and some women went with their hsubands
so basicly we can bring one women under every married husband who went with his wife
it works like this
rare kestrel
Do u not use one variable
not sure but if you try making an equation for unmarried women and then find out the total number of men...
zenith panther
not sure but if you try making an equation for unmarried women and then find out...
i'm trying to bring everything in terms of 'm'
supple sun
solo-married but went alone, not solo married with their couple
zenith panther
^^^
zenith panther
solo-married but went alone, not solo married with their couple
oh so they r married... but didn't go to the gathering
i mean like the married men without their wives
supple sun
i mean the number of men and women with this specific is equal because they went together
zenith panther
oh ye now i get it
rare kestrel
i'm trying to bring everything in terms of 'm'
Does this imply that 40% of women were unmarried or 40% of men were unmarried... I thought it meant former but in your calculation...
zenith panther
half of the women = quarter of the men
zenith panther
Does this imply that 40% of women were unmarried or 40% of men were unmarried......
oh ye i now that this question is a bit ambiguous...but i think 40% of men were unmarreid.
as 'men' was the last subject mentioned
rare kestrel
I see... yeah...
zenith panther
and if u do try 40% of the women were unmarried, u don't really get an integer solution
so... half of the married women = quarter of the married men
rare kestrel
right.... sorry i didnt calculate
zenith panther
so... half of the married women = quarter of the married men
as they went together they r equal
is that right
?
@supple sun @rare kestrel
<@&286206848099549185>
frosty galleon
as they went together they r equal
Assuming monogamous relationships then yes.
zenith panther
WDYM by 'monogamous relationships'
frosty galleon
WDYM by 'monogamous relationships'
A women (man) does not have more than one husband (wife).
zenith panther
oh k
rare kestrel
so... half of the married women = quarter of the married men
yeah... i think that's right
men=60???
zenith panther
so lemme try to solve it using variables in terms of 'm'
rare kestrel
do you have the answer with you??
zenith panther
no
zenith panther
wait lemme do it
rare kestrel
alrighty
zenith panther
so no. of men = 60
no. of women = 48
no. of married men = 36
no. of unmarried men = 24
no. of married women = 18
no. of unmarried women = 30(from the question)
30 + married women = (4/5)m
30+18=(4/5)(60)
so 48=48
(2/5)m + married men = m
(2/5)60 + 36 = 60
so 60=60
rare kestrel
so... we got it right, yeah?
rare kestrel
i did... yes
rare kestrel
Dont worry about itt
zenith panther
.close
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deft crescent
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deft crescent
ok so basically heres the question
blazing geode
Which one got you stuck
deft crescent
heres the triangle and i have the notes for this aswell
well, im confused on how to get the measurements for this triangles side lengths and height at the peak, ill send a picture to explain
blazing geode
well, im confused on how to get the measurements for this triangles side lengths...
The y-coordinate would be its height
I suppose it can be seen from your graph?
deft crescent
i guess that makes sense now that i think about it... because no matter what direction its flipped from the bottom its always going to be 4 units tall
okay well thats a start, now i need width so i can make w(h) dw which would im assuming be the height of the intersection point aswell
so is the width also the y at that point ?
not the other one but the one at the top
being 6, 16
blazing geode
You just put 4, as a input, into these two inclined lines
Then the difference of these two outputs would be the width of the triangle
deft crescent
Then the difference of these two outputs would be the width of the triangle
im gonna be honest with you
im confused on the problem overall
unless you want to spend like 20 minutes helping me understand what im doing ill probably just ask at school in the morning
like
i know what to do
but looking at my notes it makes no sense
blazing geode
unless you want to spend like 20 minutes helping me understand what im doing ill...
I will help you tho
deft crescent
alright im not giving up on this
blazing geode
I’m going to drop the term to explain (justify) why you are unable to solve it.
“Confirmation bias”
blazing geode
“Confirmation bias”
That makes no sense, do not mind me
It is just because you are not familiar with geometry that results in failing to solve it
blazing geode
I’m drawing my approach now, it might take 5 to 10 minutes to finish them.
Maybe you can have a break, I will @ you when it is done
deft crescent
okay. Thankyou. I appreciate this, I feel like i know what i’m doing but the “slicing” horizontally and vertically is throwing me off
i know it doesn’t mean anything more than taking intervals from x and y axis
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deft crescent
Maybe you can have a break, I will @ you when it is done
hello
blazing geode
To figure out how to solve the c
So first I drew the graph according to the description
To help me visualize the question
The graph I mean
blazing geode
Then I will skip to the integral part tho
deft crescent
yes
blazing geode
One way to solve it is by “shifting”
So you don’t have to bother with the blue area
blazing geode
Yes
blazing geode
translate down 4 units
On these two inclined lines
Then we integrate the new lines as shown in the picture
The very bottom should be the answers for c
deft crescent
this makes alot of sense, its also very similar to whats in my notes now. the shifting is a really smart idea that i wouldnt have thought og
of
blazing geode
this makes alot of sense, its also very similar to whats in my notes now. the sh...
I suggest you to watch 3b1b’s videos, it could help you to illustrate these geometric manipulations more easily
deft crescent
I suggest you to watch 3b1b’s videos, it could help you to illustrate these geom...
ill definitely do that
let me try this own my own quickly now with the changed triangle
blazing geode
Sure
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blazing geode
Yes, it is, in effect, flipping the plane
So you can integrate it like you usually do with the graph
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tardy blaze
If a+b+c = 1 and a,b,c are positive real numbers
Find the minimum value of a+b/abc
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Find the minimum value of a+b/...
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plush skiff