help-38

[lost glen]

its a minecraft coin in a server

[bright quarry]

💀

how

[lost glen]

I just saw it and felt like making some money xd

some dude came out with over 500k

without paying taxe

taxes

all usd btw

[bright quarry]

off minecraft.

[lost glen]

yesir

there is a market for everything if oyu look into it

[bright quarry]

maybe i should stop reading textbooks

💀

[lost glen]

there is valornat cheats

Im learning to code

so I can code cheats and macros

and other stuff

[bright quarry]

i’m interested in quant work

[lost glen]

I like coding

[bright quarry]

financial engineering

[lost glen]

coding is good for buessness

[bright quarry]

yea

programming is an essential skill

[lost glen]

people who code make so muhc online

a minecraft macro maker made over like 500k

just selling there macro

[bright quarry]

ridiculous

[lost glen]

off minecraft too

imagine the possiblities

[bright quarry]

we have to close it i think

we’re off topic

[zinc ginkgo]

[lost glen]

alr

[bright quarry]

i gotchu riemann

💀

[lost glen]

how to close

[bright quarry]

.close

watch fight club

[lost glen]

.close

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[lost glen]

alr

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[dusk canyon]

this is division with a remainder. Why is r<|b| ? More precisely, why is r less than the modulus of b?

<@&268886789983436800>

[stoic iron]

uh possibly deleted one of your messages sorry

[dusk canyon]

nah you didn't

all good

[fair bison]

To allow for dividing by negative numbers

[stoic iron]

oh i deleted the bot message 😂

[dusk canyon]

could you put it in simpler terms? Sorry, I'm burned out

[fair bison]

Yeah. So the goal here is you want to divide a by b, right?

[dusk canyon]

yes

[fair bison]

So let's say for example you're dividing 7 by -2

[dusk canyon]

right

[fair bison]

Then you could write 7 as (-2 * -3) + 1

-3 is the quotient, and 1 is the remainder

[dusk canyon]

right, that's always true?

[fair bison]

Which thing are you asking about being always true?

The fact that 7 = (-2)(-3) + 1?

[dusk canyon]

ugh nvm just a stupid thought

ty @fair bison

.close

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[fair bison]

No problem!

It's not stupid 🫡

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[wraith hinge]

To i need desperate help for a qs

[tall trail]

Where are you stuck?

[lapis star]

!status

[trim jolt]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[wraith hinge]

I’ve reached the end which is (5x^2+20)/x+2

But the substitute doesn’t make sense

[lean spear]

Show steps

[wraith hinge]

Bro I used ms paint and deleted it

I can show u via photo maths?

[tepid rock]

Why does it not?

[wraith hinge]

when I try to sub x for 2

I end up with 40

But the answer is 10

[stoic iron]

is this a test?

[wraith hinge]

It’s a practice quiz

Meaning no

It isn’t a text

Test

[tepid rock]

They know the answer, I'd say it's fine.

[wraith hinge]

Bro

This ss is from my friend

I don’t know the answer

[strong zinc]

Can you plug in the 2s and show how you get 40 here?

[tall trail]

You are along the good path

[wraith hinge]

5(2)^2 is 10^2

Right?

[strong zinc]

Ah okay no, so following pemdas, you need to do the exponent first

[wraith hinge]

So it’s 5*4

[strong zinc]

Yep

[wraith hinge]

Which would actually make a lot of sense

Damn thx man

It’s then 20 + 20

Over 4

Which is 10

[strong zinc]

Yep

[wraith hinge]

Thanks bro u saved two lives from their exam tomorrow

.close bye bye

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[dry spear]

you want proof?

hint: just take x=sec t

[zinc ginkgo]

Plug in their hint

Into both sides

Here

It's just a variable

sin(t) represents the same thing as sin(x)

Names of variables are not meaningful

Yes

Use another expression for sec

This was closer

Do this

[dry spear]

remember writing $\iff$ between the equations

[solid kiln]

moriaritie

[dry spear]

when solving an equation say $x^2-1=0$ you would write $$x^2-1=0\implies x^2=1\implies \pm x=1 \implies x=\pm 1$$ right?

[solid kiln]

moriaritie

[dry spear]

in this proof you should write ($\iff$) instead of ($\implies$) in between equations, to make it logically correct.

[solid kiln]

moriaritie

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[barren crescent]

can someone walk me through this?

-3(z-6)>2z-2

-3z+18>2z-2

[pearl plaza]

good

[barren crescent]

-3z+16>2z

[pearl plaza]

ok

[barren crescent]

16>5z

hm

[pearl plaza]

no its not ok

[barren crescent]

yeah i make a mistake somewhere there

[pearl plaza]

this is not good

[barren crescent]

wait wait

-3+20>2z

-3z*

my b

[pearl plaza]

y

[barren crescent]

because i add 2

to get rid of -2

[pearl plaza]

you should get rid of 18

[barren crescent]

ohh

[pearl plaza]

but ok continue

[barren crescent]

-3z+18>2z-2

-3z>2z-20

-2z

-5z>-20

uh

[pearl plaza]

good

[barren crescent]

z>4

[jaunty scarab]

mistake

[pearl plaza]

not good

[barren crescent]

hm

[jaunty scarab]

okay, lemme put a couple of rules here

if you have an inequality, a>b, that inequality keeps if you add the same number to both sides: a+n > b+n

it also keeps if you multiply both sides by the same positive number: a*n > b*n, if n>0

[barren crescent]

mhm

[jaunty scarab]

however, if you multiply by the same negative number, the inequality changes side: a*n < b*n, if n<0

[barren crescent]

so the sign is supposed to fliip somewhere

why..

oh hold on

so both sides

[jaunty scarab]

it's a property of order relationships, like "<"

[barren crescent]

times -1

sign flips

[jaunty scarab]

yes

[barren crescent]

soo

z<4

[jaunty scarab]

you had -5z>-20
Which means that 5z<20

[barren crescent]

ohhhhkay

except

[jaunty scarab]

easier example

[barren crescent]

it would be <

it would be les than or equal to

[jaunty scarab]

2 > 1

we multiply both sides by -1

-2 < -1

[barren crescent]

sign flips

that makes sense thank you thank you

so the one i had selected already by accident was correct lol

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[lusty delta]

.. good question

well i'm not sure because it seems you solved the question correctly

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[grizzled fable]

I am lacking the skills to solve this problem. What do I need to study to solve this problem and also how do you go about solving it?

[light warren]

do you know how to solve quadratics?

because if you do you do not lack the skills to solve this problem

@grizzled fable

[grizzled fable]

I have some level but when it came to the point here.

[light warren]

ok so the trick is to make the problem easier for youself by making a substitution

[grizzled fable]

I got stuck trying to make it into this

[light warren]

what are these images for? this question??

[grizzled fable]

Yes

Is there a better way to solve this problem?

[light warren]

ignore wtvr the hell the answer key us doing

yes absolutely

[grizzled fable]

Alright

[light warren]

solve this equation instead

a^2 + a = 6

solve for a

[grizzled fable]

A-3 A+2?

er

A +3 A-2

[light warren]

ok so a = -3, 2 right?

[grizzled fable]

Yes

[light warren]

now guess what

$a = \sqrt{x^2+3x}$

[solid kiln]

UnknownPaws

[narrow silo]

why is this so simple yet so genius at the same time

[narrow silo]

shouldnt it be plus or minus (\pm)

+

[light warren]

no because in here it’s plus only

it’s a substitution

[grizzled fable]

Ohhhh

This is something I can do

That makes a lot of sense I think

Right because substitution requires you to use the LCM?

[light warren]

that’s one way of think abt it but more than anything if you notice a patter where you have one set of stuff and then that other set of stuff squared, its defo a substitution to make the problem easier. anyway your not done yet because you have ti solve for x so $\sqrt{x^2+3x} = -3, 2 =$ the a values from before

[solid kiln]

UnknownPaws

[grizzled fable]

I think I can figure it out on my own at this point

Thank you and one last question

[light warren]

ok perf

[grizzled fable]

How did you develop that knowledge?

[light warren]

u might hate this answer but practice

[grizzled fable]

I've just picked math back up so I understand yeah

Well thank you

.close

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[lusty delta]

answer is 2

funny wolfram

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[lusty delta]

seems plausible yes

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[exotic pine]

f(x)=(x+2)a+3
f(x)=(x+3)b+2
what i need to find is r in
f(x)=(x+2)(x+3)c+r

and r's degree is less than 2

thats how much i'v gotten

[empty wharf]

(x+2)(x+3)+(x+5)

[lusty delta]

this question is basically telling you f(-2) = 3, f(-3) = 2

[exotic pine]

what

how does that work

[lusty delta]

well what happens when you plug in -2 and -3 to these equations

[exotic pine]

hm

ok

but what if you plug in f(-2) and f(-3) into the bottom equation

wont r be 2 diffrent solutions

oh, r isnt a constant

[lusty delta]

that, it is not

[exotic pine]

do i just try to find a pattern
f(-2)=3=r
f(-3)=2=r

oh yeah

so r would be x+5 right?

[lusty delta]

yes

[exotic pine]

how bout number 25

do i try to factor?

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@exotic pine Has your question been resolved?

[lusty delta]

try smth!

[exotic pine]

wdym

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@exotic pine Has your question been resolved?

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@exotic pine Has your question been resolved?

[exotic pine]

<@&286206848099549185>

[silk dawn]

i dont quite get the question. does it ask you to find every pair of (x, y) that satisfies the equation?

[exotic pine]

i think it wants us to find the ammount of (x,y) that satisfied the equation

[exotic pine]

num 25

[silk dawn]

well (0,0) is a solution

when you put it into a graphing calculator, it gives you this.
It looks like it has 6 solutions.

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[exotic pine]

i cant use graphing calculators

[silk dawn]

yes but now you have a solution to check your results

[scenic delta]

Try moving the xy to the other side

[exotic pine]

x^2+y^2-xy=x+y

[scenic delta]

Assuming x!=-y, multiply both sides by x+y

[exotic pine]

wdym x!=-y

[scenic delta]

"x is not y"

And for that, first check the cases where x=-y

[exotic pine]

oh

[exotic pine]

x^2+y^2+4xy=x^3+y^3+2xy

[scenic delta]

Nevermind I thought that would lead to some kind of division

[scenic delta]

Maybe adding 2xy to both sides?

Or maybe moving the x^2 to left and y to right and factor an x then divide?

[exotic pine]

uh

what

[scenic delta]

x+xy-x^2 = y^2-y
x(y+1-x)=y(y-1)

Maybe this?

If nothing works, just leave y alone and graph it I guess

[lusty delta]

when i said this message i meant just try it for a bit

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[quasi current]

Hi

[quasi current]

How do you know when to use

A or B values

I got the wrong answer as mine were reverse

<@&286206848099549185>

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[quasi current]

.close

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[frigid bloom]

I have a question about an answer for a problem

[frigid bloom]

My work is

But the answer sheet says

The term 1/sqrt 3 just vanishes?

This is the original problem BTW

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[little garden]

Surface integral bro

You need to take a class on surface integral ,you cannot just change ds to dx dy

[frigid bloom]

Yea I saw

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[hot mirage]

reviewing some old math from an old high school math workbook and this one confused me a bit

[hot mirage]

the answer is supposed to be C

[bright quarry]

so im assuming the r is supposed to not be included in the log

notice how they both have log base 6

since they have the same base

we can use some log laws

to combine the two into one log

what do u think the first step is

[hot mirage]

ohhhh okay, r not included in the log makes so much sense

[bright quarry]

c is the only answer that makes sense just from looking at it

but what do u think u should do first

[hot mirage]

I get it now, D was what I had thought because I had read it as log_6 (q+r)

[bright quarry]

oh ok yea so u know to subtract the log over

to isolate r

then use the quotient rule for log

logs

log_6(p/q)=r

6^r=p/q

and c is the obvious chocie

choice

[hot mirage]

thanks!

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[gilded kelp]

need help with both of the questions

idk any of them

like no clue

[wraith hinge]

for i) do you know the law of cosines

ya know

[
c^2 = a^2 + b^2 -2ab\m\cos C
]

[wraith hinge]

rings a bell?

[gilded kelp]

no that’s not for my level

[gilded kelp]

nope

[steady oracle]

1st question can be done with drawing a right triangle

[gilded kelp]

ok i drew one

[steady oracle]

with hypotenuse (c) = 5 cm and adjacent sides (a,b) = 3,4

now name the vertices

[gilded kelp]

yep

[steady oracle]

and sides

[gilded kelp]

huh

what formula do i apply

[steady oracle]

you need to do construction in these 2 questions

idt formula will be used to solve them

[gilded kelp]

ok

what to do after

[steady oracle]

did you drew a triangle ABC?

[gilded kelp]

yes

[steady oracle]

with longest side (hypotenuse) = 5cm

[gilded kelp]

btw they say A=3 cm so is the side AB=3cm?

[steady oracle]

now name the vertices

[steady oracle]

AB = 3cm

[gilded kelp]

ok i did

[steady oracle]

it used different variable for AB which is a here

[gilded kelp]

ok

[steady oracle]

now b = BC

[gilded kelp]

yea

[steady oracle]

and c = AC

did you found point B in the triangle?

[gilded kelp]

yes

[steady oracle]

whats angle ABC?

[gilded kelp]

how am i supposed to know the angle

that’s what i want to know

[steady oracle]

oh

didnt your teacher taught you this?

[gilded kelp]

no i missed classes

[steady oracle]

ok

[gilded kelp]

is there some short cut pls

this came in my test and i didn’t do it

[steady oracle]

this is angle ABC

[gilded kelp]

i know what’s an angle

…

[steady oracle]

in ABC, A and C are end points and B is the angle which should be measured

[steady oracle]

i have asked the same thing tho

now, can you find angle ABC?

[gilded kelp]

with a protractor?

[steady oracle]

yes

[gilded kelp]

no

my teacher said don’t use them…

i’m in grade 10th

[steady oracle]

do you not know properties of right angle triangle?

[gilded kelp]

i do

90 degree angle

[steady oracle]

ok

[steady oracle]

yes

thats the answer

[gilded kelp]

but why did they give me the sides then

they could have wrote in a right triangle what’s the angle

[steady oracle]

you had you find out its a right angle triangle

[gilded kelp]

ummm

wait

[steady oracle]

you had to figure it out yourself

[gilded kelp]

but

[steady oracle]

do you still have questions?

[gilded kelp]

if i apply pythagoras theorem it doesn’t agrees that it’s a right angle triangle

[steady oracle]

why?

c^2 = a^2 + b^2

[gilded kelp]

oh nvm

[steady oracle]

c=5
b=4
a=3

[gilded kelp]

so in these typ of question do i have to apply pythagoras theorem first

[steady oracle]

yes

[gilded kelp]

and if it doesn’t agree then what do i do

how do i find angle then

[steady oracle]

generally, its not the case at your level

if it is, then you have got another hints in questions

[gilded kelp]

ok btw are u sure answer is 90 degree?

[steady oracle]

like an isosceles triangle

[steady oracle]

yes

[gilded kelp]

oh yah ok

thank u so much ☺️

[steady oracle]

np

[gilded kelp]

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[earnest harbor]

clueless

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[potent edge]

What is the probability that all three children born in a family will have same birthday

[potent edge]

So this is what I tried

Let's say we find the probability of the kids having birthday on 1st Jan:
1/365 * 1/365 * 1/365

They could also have birthday on second Jan and so on

So the total probability is somewhat like

1/365 * 1/365 * 1/365+...+1/365 1/365 1/365

[odd parcel]

isnt it 1/365^2

because it doesnt matter which day the 1st child lands on

[potent edge]

Yes

[odd parcel]

alruight

[potent edge]

No i mean that's what I am getting

I am not sure if it's right

[odd parcel]

i think it should be

[potent edge]

Okayyy

[odd parcel]

yippiee

[potent edge]

Thanks

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[potent edge]

Is the answer to q2 equal to 8/5!?

Total number of ways they can sit is 5!

And this is the total number of ways ab can sit with the empty boxes showing anyone else sitting

Is my ans and approach rigut

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[gilded raven]

can someone solve without using L'hopital

[wraith hinge]

conjugates seem like a good idea to go with

preemptively

[worldly wing]

the result $\lim_{x\to a} \frac{x^n-a^n}{x-a}=n\cdot a^{n-1}$ should work nicely for this

[solid kiln]

kheerii

[broken belfry]

interesting

[gilded raven]

rationalised it, made it weird, the x^n-a^n/x-a thing also couldn't figure out how to go on

[gilded raven]

yeah i did try but got stuck on the next step

[worldly wing]

!show

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[haughty oasis]

I would just substitute t = sqrt(x) and then the denominator cancels

[worldly wing]

yeah that also works

many ways to approach this

[gilded raven]

its tilted :/

[wraith hinge]

,rccw

[gilded raven]

would you be able to send the solution

might understand better

[worldly wing]

!nosols

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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[gilded raven]

oh lol

if you convert the original as root(x) as it, then it's (t^9-t)/t-1

t^6?

but even then what do i do next

wouldn't it just become complicated

did think of that

ok cool got it

how do i close this

-close

,close

.close

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[little egret]

hello i need help with question 8a

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[prime lynx]

you want to find the value of l and k?

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[zinc ginkgo]

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[kindred pier]

@wraith hinge I thought you needed help?

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[lethal anvil]

bro language

[fiery goblet]

who hurt you

sounds like a you problem

try harder next time

if you have a question you can post it here

[lethal anvil]

so how this server works is that you come with specific concepts or problems and you post it here

[fiery goblet]

else you can close the channel

[lethal anvil]

last warning about the language

sounds like you have an attitude problem to be honest. This server is a free service to help tutor specific problems. Like if you have a question on your HW that you need help with

like if you don't understand cross multiplying, as an example, you can post a problem and someone here who volunteers can help you work it out

nah you can leave on your own accord. Nobody is keeping you here

[night mango]

bro who are these ppl??

Bruh

[stoic iron]

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[stoic iron]

(Muted)

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[tough lantern]

hello, can someone refer me to a video or explain why raising a number to the reciprocal of the power it was raised to, ex. 2^3 = 8, and 8^(1/3) = 2, "undoes" the power?

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[maiden zinc]

On part f

What if was f (5x-1)

Instead of f(x-1)

[little garden]

You have to find the point where graph is -3/2

Then put 5x-1 equal to that points

You get x

[maiden zinc]

What

[little garden]

Tell. Me points where graph is -3/2

[maiden zinc]

Just one

[little garden]

What is that point

[maiden zinc]

When x= -2.8

[little garden]

So f(5x-1)=-3/2

f(5x-1)=f(2.8)

5x-1=2.8

X=3.8/5

[maiden zinc]

So the value of b

Like the 5x

Doesn’t affect the amount of solutions

When I mean the value of b

I mean this equation.

[little garden]

Ya that's right

[maiden zinc]

g(x)= af (b(x+c)) +d

Ok Ty

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[rancid nebula]

Can I get help with algebra 2?

[autumn trout]

u have to ask the question

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[rancid nebula]

\sqrt[6]{sc^2}d^8

6th root of 2c^2 d^8

and I need to write it in exponential form

[old zinc]

Hey do any of u guys do statistics

[exotic pine]

$\sqrt[6]{sc^2}d^8$

[solid kiln]

Skill_Issue

[rancid nebula]

yep that'd be it

[exotic pine]

what do you mean exponential form
like (example) $s^2c^3d^4$

[solid kiln]

Skill_Issue

[exotic pine]

?

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This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[rancid nebula]

yeah I beleive so

so is that just breaking down the root?

[exotic pine]

uhh

yeah, you can rewrite it as 1/6

[rancid nebula]

ok

[exotic pine]

dont give the sols, let them learn

[rancid nebula]

and what is simplest radical form?

[exotic pine]

tbh i domt even know what radical is

[lapis star]

square root

etc

[rancid nebula]

like root 245 would be 7 root 5

[lapis star]

root5 is the radical

[rancid nebula]

yeah

in simplest form right?

[lapis star]

yes

else 245 is also the radical

but the radicand 245 can be simplified

[rancid nebula]

ok so how do i do cubed root of 250a^15b^2 In the simplest radical form?

$\sqrt[3]{250a^15}b^2$

[solid kiln]

瑞安

[rancid nebula]

^15 not ^1 5

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[vernal warren]

u can distribute the cube root to all of the terms

$\sqrt[3]{250a^{15}} \cdot b^2$ =$ \sqrt[3]{250} \cdot \sqrt[3]{a^{15}} \cdot b^{2}$

[solid kiln]

JustToPro

[vernal warren]

and then simplify each term seperately

[rancid nebula]

ok

also how do you find numbers that factor well with the radical

[vernal warren]

i just take the LCM of the number and then see

$ \sqrt[3]{250} $ = $\sqrt[3]{2\cdot5\cdot5\cdot5}$

[solid kiln]

JustToPro

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[tough lantern]

can someone explain how to solve this question? the correct answer is B, but I have no idea how to figure out which transformations would be needed without the original point...

[astral tangle]

Can we check sequence convergence by putting an+1/an?

I meant limit n tends to infinity an+1/an

[tough lantern]

sorry, I'm not familiar with sequence convergence

[astral tangle]

Opps wrong channel sorry

[tough lantern]

its ok lol

[forest egret]

let y=f(x)
a horizontal stretch by a units means it becoms y=f(x/a)

Moving b units up means y=f(x)+b

Combine the two transformations and check which option pass through the point (3,5)

[tough lantern]

ius there a way to do this algebraically or would that just be more complicated?

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[broken belfry]

there is an infinite number of transformations you can do, not possible

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[hallow crane]

hi, is this question wrong?

[hallow crane]

the answer should be -1 < x < 0 right?

the best two answer i could choose be A and E

but E isn't a must be true answer on its own (?)

[left oriole]

both must be true

condition E alone allows -1 < x < 0 or 0 < x < 1, but the latter won't work in this case

[hallow crane]

guess i misread it

sure thanks

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[burnt heart]

How do you find f(x) ?

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[burnt heart]

<@&286206848099549185>

[burnt heart]

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[real gale]

We have a Matrix A over F2
A is also a linear function A(v) = A*v
The task is to find the basis of A/ker(A)

[real gale]

ker(A) are vectors (1,1,1) and (0,0,0)

im(A) are vectors (x, y, x + y)

How do I find A/ker(A)?

A is not a vector space, is it?

Or do I have to find im(A)/ker(A)?

Which is just [(1,0,1)], [(0,1,1)], [(1,1,0)], [(0,0,0)]

And the basis is ((1,0,1), (0,1,1))

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[tribal marten]

Why didn't she just go straight to dividing it with 8?

[tribal marten]

I dont get the long thingyy

The blue stuf

[delicate belfry]

Prime factorization.

[tribal marten]

What does it mean?

[delicate belfry]

Or factorization in general. You find the primes that makes up the number. 112 for instance, it may be as $$2 \cdot 56$$ $$2\cdot2\cdot28$$

[solid kiln]

Good

[tribal marten]

But 112 can also go for
112
8 14
2x4 2x7
2x2

[delicate belfry]

Yeah, also a way.

[tribal marten]

This can go for anyway?

[delicate belfry]

The purpose of this is to factorize, no matter it's 8 14, or 2 56 you start with, you end with the smallest factors.

[tribal marten]

I need to start with the smallest?

So 2?

[delicate belfry]

You don't have to. You could start as your way, 8 14.

[tribal marten]

But can it also be used in other number?

[delicate belfry]

If it can be factorized, then yes, use 3 if you want.

[tribal marten]

Give me a number

[delicate belfry]

63

[tribal marten]

3 21
3x7

Correct?

[delicate belfry]

Yeah.

The smallest factors will always be prime, that's why this is called prime factorization.

[tribal marten]

If it's 108 then how does she know she can start at 6?

She said 8 + 1 = 9,then she said it's divisible by 3 then why she start at 6?

[delicate belfry]

As I mentioned, there's a reason why it's called prime factorization, because you'll end with primes.

Yes, you may start with 6, but till end, you'll have that in 2 3.

[tribal marten]

Oh okay, but is it needed to use prime Factorization?

Or i can do whatever i want as long as it can be divided i mean prime can be divided

[delicate belfry]

You may do whatever you want to start with. 108, start with 2, that's alright, start with 3, that's alright, 6? Also works. 12? Also works.

[tribal marten]

Oh okay as long is i can divide it?

[delicate belfry]

As long as you can divide, you end the same.

[tribal marten]

Oh okay thxxx

[delicate belfry]

Welcome.

[tribal marten]

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[graceful zenith]

if ax+b=y and -ax+b=y was plotted on the same graph, would the graphs reflecting off the y intercept against the x axis or y axis

[dull temple]

try it and see

[graceful zenith]

i got both

but a question is asking me which transformation is applied

and idk which one to write

[dull temple]

looks like x is being replaced by -x

,tex .transformation rules

[solid kiln]

ヘイリー

[graceful zenith]

yea

[graceful zenith]

would the transformation be -f(x) or f(-x) in my case?

[dull temple]

f(-x), you're replacing x with -x

so where you once had f(x) you now have f(-x)

[graceful zenith]

ohh right

alr

[graceful zenith]

so it would be reflecting of y axis right

[dull temple]

yeah

[graceful zenith]

though could it be both y axis reflecting and reflecting of y intercept against x axis?

or should i just write y axis

i used desmos and they both were the case

[graceful zenith]

anyways thx

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[pliant flint]

Could someone help me with this problem?
You have to make "a" the subjec

[little garden]

a what I don't get it

[wet ocean]

i think he means "a = ...", right?

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[pliant flint]

yes

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[pliant flint]

<@&286206848099549185>

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[wraith hinge]

How do I do this?

[broken belfry]

all 3?

[wraith hinge]

Yeah…

[empty wharf]

By using angle sum property of triangle, linear pair, parallel line transversal property

[broken belfry]

starting with a), assuming that's a straight line, you know what b and 135 should add up to?

[wraith hinge]

145?

[wet ocean]

think what's the angle of a straight line

[wraith hinge]

180

[wet ocean]

right!

[broken belfry]

right 180

b and 135 should add up to 180

[wraith hinge]

How about for A?

[broken belfry]

what's the sum of angles in a triangle

[lapis star]

a + 35deg = 135deg

[wraith hinge]

Yeah

So 180-35?

[lapis star]

subtract b too

@wraith hinge How old are you?

I have some more theorem

[broken belfry]

[wraith hinge]

Almost 14

[lapis star]

srry for interrupt

[lapis star]

cool

[wraith hinge]

How do I find a?

[wet ocean]

the sum of all internal angles of a triangle is always equal to 180

[wraith hinge]

Yes

[lapis star]

use it

[wet ocean]

what's the value of b, first

180-135?

[wraith hinge]

Wait the value of b is 135?

It’s the other angle no?

[wet ocean]

no. the value of b is the result of 180-135

remember the straight line angle?

[wraith hinge]

Oh yeah

45

[wet ocean]

nice!

so we have the angle 35º and the angle b, that we just found out is 45º

let's see the rule again: the sum of all internal angles of a triangle is always equal to 180

so 35+45+a=180

[wraith hinge]

80+a so a should be 100?

[wet ocean]

should be 180, yes

[wraith hinge]

Thank you

[wraith hinge]

The second one looks intimidating

[wet ocean]

did you already calculated the result of the first one?

[wraith hinge]

Yeah 45+35+100=180

[wet ocean]

oh, my bad

so let's see the second one

[wraith hinge]

A is 40?

Since its the opposite

[wet ocean]

correct!

we can even find d now

see the 45º below?

[wraith hinge]

Yeah

Ohhhh

Wait

Sooo 45+40?

[wet ocean]

yep

45+40+d=180

[wraith hinge]

45+40+95=180

[wet ocean]

nice!

d would be 95 then

so we only got b and c left

[wraith hinge]

Yep

[wet ocean]

let's take a look at this set of rules

since the lines are parallel, all angles are equal

alright?

[wraith hinge]

Then c=95?

[wet ocean]

not quite... pay attention to the second rule

look for a "Z" shape on the figure

[wraith hinge]

Oh

Then b=40

[wet ocean]

right!

c is an external angle

[wraith hinge]

So the third rule

[wet ocean]

look, it forms a straight line

[wraith hinge]

Or do I use the triangle with b to find it?

[wet ocean]

we can use that, it might be simpler

so, 45+40+x=180

[wraith hinge]

So 45+40+95=180

[wet ocean]

right! but c is external

pay attention: it forms a straight line

[wraith hinge]

Ohhh 180-??

[wet ocean]

yes!!

[wraith hinge]

180-95

[wet ocean]

[wraith hinge]

85

[wet ocean]

what would it be then?

nice!!

you did it

[wraith hinge]

Thank you

Finally the third one

[wet ocean]

let's combine all the knowledge we earned this far

let's start with e

[wraith hinge]

Yeah a=35

[wet ocean]

nice!

"e" it's part of a straight line, so...

[wraith hinge]

So 180-35

[wet ocean]

uhum

[wraith hinge]

145

[wet ocean]

nice

alright, lets see our rules again

pay attention to the first rule

d is above a 45º angle

[wraith hinge]

Oh d=45

[wet ocean]

yes :)

we already got a and d

to find c, the sum should be 180

[wraith hinge]

C=100

[wet ocean]

nice!

[wraith hinge]

Then b=100

[wet ocean]

yes

[wraith hinge]

So e is a straight line so 180-100?

[wet ocean]

wait... it's a bit confusing

we already have the value for e

[wraith hinge]

Yep, but it’s somehow there wait I will check if it’s an error

[wet ocean]

yes... it might be

e must be 145, as it's part of a straight line

[wraith hinge]

I will just try skipping that.

[wet ocean]

ok

[wraith hinge]

Mind if you could help me with 2 last problems?

[wet ocean]

not at all! let's see them

[wet ocean]

ok. do you know sohcahtoa?

[wraith hinge]

Yes

Yes sin=o/h and so on

[wet ocean]

alright

so we need to solve cos(b)-sin(a)

let's find the angles first

[wraith hinge]

So A=143

[wet ocean]

no... 143 is external

[wraith hinge]

Oh sorry

[wet ocean]

no problem

[wraith hinge]

How can we find s,c and t when we don’t have the angles?

[wet ocean]

see, A is part of a straight line

[wraith hinge]

Yes

So 180-143?

[wet ocean]

yes!

[wraith hinge]

137

[wet ocean]

nice

we found angle A

we already know that C is 90º, right?

[wraith hinge]

Yeah since it’s the right angle

[wet ocean]

yes, so what should be B?

[wraith hinge]

Do we use the theorm?

[wet ocean]

remember that the sum of internal angles is 180

[wraith hinge]

Oh

But if I sum 137 and 90 it becomes 227?

[wet ocean]

remember what we did earlier

wait

[wraith hinge]

Don’t we have to a^2+b^2=c^2

[wet ocean]

ooh we did a mistake calculating a

[wraith hinge]

Oh

[wet ocean]

180-143

[wraith hinge]

37

[wet ocean]

yes!

ok, now that all is correct, it should work

37+90+b=180

[wraith hinge]

43

Wait

53

[wet ocean]

alright! it's correct

53

so our equation should be cos(b)-sin(a)

[wraith hinge]

So we use sohcahtoa

[wet ocean]

cos(53)-sin(37)

[wet ocean]

yes

[wraith hinge]

Oh

I will use calculator

[wet ocean]

ok

[wraith hinge]

0

[wet ocean]

really? thats funny

[wraith hinge]

Wait but it says cos (cba) - sin(bac)

[wet ocean]

yes, the angle that the points C, B and A form when conected in this order

basically, B

[wraith hinge]

So do I just enter all the three angles?

[wet ocean]

no. see the points C, B and A

mentally conect them in this order

c, b, a

it forms an angle, right?

[wraith hinge]

Yeah

[wet ocean]

that's angle B

[wraith hinge]

Cuz angle B is the one connecting them?

[wet ocean]

yeah

[wraith hinge]

Which is 53

[wet ocean]

yes

its other ways of writing it
∠CBA = ∠B

[wraith hinge]

So 0.4 if I round up?

[wet ocean]

thats cos(37)?

[wraith hinge]

Cos(53)-Sin(90)

[wet ocean]

bac, isn't 90

90 would be ACB

[wraith hinge]

Ah so it’s 37

I get 0

[wet ocean]

alright! that's the answer

let's go for numb 2

all good?

[wraith hinge]

So for 2 it’s sin(53)

[wet ocean]

yes

[wraith hinge]

Number 3 it’s 1

[wet ocean]

correct!

[wraith hinge]

Oh yes apparently the e is supposedly f

So it’s 80

[wet ocean]

ooh ok that makes more sense

[wet ocean]

ok

[wraith hinge]

D=90?

[wet ocean]

yes

are you aware of equilateral triangles?

[wraith hinge]

Yes, if one side is x then there rest is x?

[wet ocean]

yes

all equilateral triangles have one specific angle actually

they're equal, and must add up to 180

[wraith hinge]

So AC=12?

[wet ocean]

yes, the side right?

[wraith hinge]

Yeah

[wet ocean]

three equal angles that must add up to 180

do you know what that would be?

[wraith hinge]

But we’re not supposed to add the sides to find that right? We should find the angles first?

[wet ocean]

right, thats what we're doing

[wraith hinge]

Then 90+b+a=180