#help-38
1 messages · Page 64 of 1
you can use the fact that the tangent line to a circle passes through a point on the circle and is perpendicular to the radius
cheers
How do I use this to my advantage? I know it hits it at an exact 90 degree angle but the way my professor taught it I havent used that before, maybe I can send what he wrote. One sec
I haven't been able to make sense of this
this is a problem that can be solved in a variety of ways (calculus, trigonometry, geometry + algebra), so you should solve it using the method you are currently learning
Im sorry for being daft like this but what is the method my professor uses here?
it seems that you start with a basic equation of a line passing through the point, in this case, $y = x - 4$ passes through $(4,0)$. then, we introduce a scaling factor variable $R$, then $y = R(x-4)$ will change the slope of that line while still making it pass through $(4,0)$. you then have a system of equations with the equation of the tangent line $y = R(x-4)$ and the equation of the circle $x^2 + y^2 = 8$
cloud
and you want to find values of $R$ that make that have only 1 solution (in other words, the line and circle only intersect once, which means the line is tangent)
cloud
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Right, i see! He needs to use R to define the slope. Then he substitutes y for r(x-4). But how does he get from that to x^2(1 + R^2) - 8R^2x + 16R^2 - 8 = 0?
the steps after dont make any sense to me. I dont know why
that comes from expanding $(R(x-4))^2$
cloud
then grouping terms with a common factor of $x^2$ and moving all terms to one side (so that 0 is on the other side)
cloud
Ooooh I understand now. The steps after it too, just b^2 - 4ac, but I specifically struggled with the step from
x^2 + R^2(x^2 - 8x + 16) - 8 = 0
to
x^2(1 + R^2) - 8R^2x + 16R^2 - 8 = 0
But it's just distributing R^2 and then combining the terms like you said.
Let me recheck to see if I really get it
Yeah that should be good, thanks for ur help cloud 
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Hi
i mean it's just changing b_n to a_n
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Spent 25 valuable minutes on this 😍
You can solve for the lower part of the upper left angle. Hint the left triangle is an isosceles triangle
Then from there I think the upper left angle is 90° in total.
With this you can solve for the remainin angle of the isosceles triangle
Then c + that angle + x + 12 = 180, you should be able to get x from the upper left angle. After you all the angles for the upper right triangle add them together to see if it equals 180
ohhh ok
Hmmm I don't think the upper left angle is 90°, let me know whay you get so we can compare and go from there
Try finding these and use the angle sum property of a quadrilateral
For a less messier equation, find this and use exterior angle property
ok that sounds slightly easier thank you !!
lowkey need to redraw this problem because I scribbled all over it ofncofnkd
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Arna has x kr. Halla needs 15 kr. to have two times more.
a) how much does Halla have?
Is it 15 * 2 * x?
<@&286206848099549185>
<@&286206848099549185>
<@&268886789983436800> no one’s helping me😔
what can I do?
I wanna finish my homework as fast as possible
Can u help
No sorry
So does everyone else
Do it yourself then
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Hi super easy question but want to make sure I’m doing the strong induction properly
Basically I have to prove for every n >= 8, exists a and b in Z+ such that n = 3a + 5b
And like I just proved from 8-10 it’s true
Then n= k+1 = (k-2)+3
And then I would just simplify it
(3a+5b)+3 = 3(a+1) + 5b
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yea
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i cant seem to calculate the answer?
can someone help?
answer is given but i dont know how to get to that
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@opal coral Has your question been resolved?
Yes sure!
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how did it go from log 6^2 to log2?
log 6^2
2 log 6
2 (log 3 + log 2)
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how do i go about this
find which line each expression corresponds to
the shaded region is where each inequality holds at the same time. so find which side of each line is satisfied (e.g. in the first line, does ≥ mean above or below it?)
alternatively, you can pick a "test point" inside the shaded region and check if it satisfies each inequality
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can i pls get help understanding how to do 21
ye
i realized that part
it was my test
i rushed it last minute
its 6 ik
but even if it was 6
how would i get to the answer from there
and is 10 even the right answer
if f was 6 then the equation you use to find y would be 10+6+y=25
yes it's 9
lmao, you figured it out
cya, and do .close
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somebody pls help
ik how to get midpoint and all that stuff
ik the formula
but i keep getting it wrong
i think i keep miscalculating
!show
Show your work, and if possible, explain where you are stuck.
i understand how to do the problem but my calculations are all over the place rn
What would you like help with then?
I suggest you just clean up your calculations and restart more neatly
i'll try doing it one more time 😭
i'll come back if i get it wrong
check ur dms
i got it wrong again :')
i got the slope as -1/2
midpoint is (3,-3)
bisector i calculated as: y=2x-9
how did you get that slope?
y2-y1/x2-x1
so plug the numbers in
so i did: 1+7/-4-10
did i miscalculate....
yes
-4/7?
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a)𝑉 = 𝑊1 ⨁ 𝑊2
b)𝑉 = 𝑊1 + 𝑊2
What is the difference in these sign?
Linear sum of direct sum?
Let me upload the original question
Q.7 If V is a vector space of n x n matrices of real entries over the field R and 𝑾𝟏 and 𝑾𝟐 are the subspaces of symmetric andskew-symmetric matrice respectively, then which one is correct?
a)𝑉 = 𝑊1 ⨁ 𝑊2
b)𝑉 = 𝑊1 + 𝑊2
c) 𝑊1 ∩ 𝑊2 = {0}
d)All of above
I can imagine zero matrix will be mutual in it so Direct sum failed A and C is wrong because we can get zero matrix in common and D wrong
So B can be right no?
Direct sum is when each vector in the sum can be represented uniquely by a sum of a vector in W_1 and a vector in W_2.
The difference is the uniqueness
Yes right
(b) is true if every matrix in V can be represented as a sum of a symmetric matrix and a skew-symmetric matrix
Is that true?
If (b) isn't true, then (a) for sure isn't.
If (b) is true, then (a) is true if that sum is also unique
We can represent any matrix with sum of symmetric and skew
Ok, so you understand why that means (b) is true, right?
It follows directly from the definition of W_1 + W_2
Yes
B is linear sum
And we have zero matrix which means C is true and A also
So D
(c) doesn't just mean 0 is in W_1 + W_2
it's saying 0 is the ONLY vector in BOTH W_1 and W_2
Is that true?
If it is, and you are convinced (a) is true aswell, then the answer would be (d) yes
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Thanks
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The plane euation do/does not any vector sub space
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Hi
Can someone help me with 4)?
So its intergrals with derivative i dont rly get it yet but it this is a good start right?
that's correct (you should work on your handwriting though)
bighead integral
Yes
your work looks right
Idk why its rly readable and good but alr
the tan in particular is hard to read
I dont use sec yet idk what that is
Do i need further steps or am i finished?
I would Think that's it, just write $\int sec^2 (x)$ as an intermediate step
Why am. I here
Its 1/cos^2x = tanx for me
wdym
what is D here? the derivative?
And how will i go about 5)?
Yes
combine the exponents by using exponent laws
It becomes x^4 right?
yes, but that's not something that you should have to ask for confirmation about lol
I forgot first week back to school after Christmas
fair enough i suppose
Thats the final answer nothing more?
yes
Which one is the hardest? So i can learn the hardest ones
10)?
convert the square roots to fractional exponents and simplify
10 becomes 1/x^-1/6 am pretty sure
if you want to see if you got the correct answer, just differentiate the result you get and see if you get the integrand
But whats with the + c at the end?
And u think these questions are any harder?
wdym
U see the + c at the end of my answers right?
I am asking what it stand for and why u know
.
the +C indicates that we can add any constant to the answer and still get a valid antiderivative
"C" is for "constant"
Oh ye ye
And for this page u think i have to use new formulas?
I only learned these formulas btw
So do i encounter any other methods i need to use then these?
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convert to metric system i dont speak american
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Definition of cyclic quadrilateral
The perpendicular bisectors will intersect at the circumcenter because the bisectors induce isosceles triangles
a quadrilateral which has all vertices on a circle
never heard of that
Yeah it’s not well known
damn it is
Try angle chasing with the varignon parallelogram
angle chasing?
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How can i start with this
Use the chain rule on (ln(g(x)))'
It'll make a g' pop out
Then go back and use to log rules on ln(g(x)) since it's a product inside
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how would i do this
span is all linear combination of these vectors?
if yes, then you have to make it like this: a(2x+1)+b(x^2+1)+c(x^2+x+1)
and see what polynomials you can get
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What is the domaine of f(x) and why?
Got confused since f(x) do not exist while x exists in [-1;+1].
Isn't supposed to be in 1 and 0 only?
<@&286206848099549185>
like the domain is for sure $$D \subseteq \mathbb C \backslash {-1,0,1}$$
But putting in -1 would make the right 0^0
yeah forgot that
Homelama
but else it is a qestion of what the co-domain of f is
The exercise wanted Df and to study the continuete of f. (Prolongement)
But why -1 is not defined?
you get 0^0
Alright.
Yeah that’s undefined
OHHH
I forgot that case fr.
But when I checked the graph, it seems that the undefined isn't just points
it is an range.
from -1 to 1, why?
that depends of what the co-domain of f is
because if it is real you get a negative number to a fractional exponant which gives a complex number
There is no hint about it in the exercise tbh.
like do you know if $f:\mathbb R \to \mathbb R$?
Homelama
No, it is not even mentioned what is the codomain of f(x).
or is the generally any additional information
the co-domain is the set in which the function maps into
I know it is the image of f(x) but there is no hint as I mentioned.
What do I do in this kind of cases?
idk did you ever work with complex functions?
The exercise is related to continue of a function, I can't use complex concept.
ok so in the real numbers if you have a^b and a is negative and b is not a whole number it is not defined
thats why the intervall [-1,1] was excluded
Because -1 keep switching based if b is odd or even?
no because if you have for example -1^(0.5) it isnt defined in the real numbers
but why does it work noramally in my calculator?
what is the result of your calculator?
-1
ok i think sth is wrong with your calculator cuz $$(-1)^{0.5}=\sqrt{-1}=i$$
exaclty....
Homelama
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I got 4 but I am not sure if thats right
it is not exactly 4
I get a close but not quite that answer using law of sines, did you round up?
Yeah
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because the supports meet in the center of the bridge, we can confirm that they divide it into two identical parts
12.5 ft each
sin(65)=12.5/x
we should get x with that
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@thorny trout Has your question been resolved?
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How many different letter arrangements can be made from the letters in the word
STATISTICS?
Okay so i understand the common argument
with using permutations of indistinguishable objects
but i want to rationalise this using the idea here
I know both theorems yield the same result
but how would you "partition" this into r cells?
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This might seem like a dumb question but how can I construct 2 externally tangent circles that are both internally tangent to a third larger one
I did it with a particular case where both intersection points represented the diameter of the larger circle but I am looking for a more general case
this is what I have so far
what is a problem
i'm sorry?
Yeah the radius of the 3rd largest circle would be the sum of the radii of the 2 smaller circles
okay thanks
but where will i have to put the center exactly
i tried a bunch of different configurations and none of them actually gave me 2 tangent points with the smaller circles
except where all the centers are aligned but that's a special case
hm if we say the coordinates of the 2 smaller circle centers are (x1, 0) and (x2, 0) then it'd be at ((x1+x2)/2, 0)
right but then the centers would just be aligned
if we take this example i found online it can be done without that
@waxen fable Has your question been resolved?
<@&286206848099549185>
oh I see
@waxen fable Has your question been resolved?
<@&286206848099549185>
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<@&286206848099549185>
hhu
what can i do for you?
Hey!
Do you know if there is a way to construct a circle so that the two circles here would be internally tangent to it?
could you please tell me how?
Five minutes.please
okay, please take your time
@waxen fable Has your question been resolved?
Hey Are you there?
Yup
Sorry for being late.
It’s okay man
I 'll send a answer picture after restarting . okay?
Yeah for sure
Omg thank you so much man!
This is really helpful
I appreciate it
Have a good rest of your day, thank you again!
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Am I correct in doing the calculation as (4!) * (4!-4) * (4!-4-4)?
Also subtracting 4 is removing the already used matchups in both directions
@lament cloud Has your question been resolved?
@lament cloud Has your question been resolved?
why are there 4! ways to schedule in 1 day?
@lament cloud it's not the answer i get
I would start by selecting the order of matchups for e.g. Lakers
right, 4! makes sense, you select the home team and everything, but there's no notion of one match happening earlier, so I assume you would divide by 2 at that point
My new answer is 3! * 2^6 = 384
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how do i do this
what do the angles have to add up to in a triangle?
180
bingo
so what would the angle closet to B be?
(let's label it angle b)
a = 61
b = ?
c = 30
89?
we js started this so im a bit new
no problem.
So law of sines is as follows:
yes
so you take the sine of the angle and then the opposite side and then do an equality
ohh
MellowDramaLlama
now we just solve for x 🙂
by cross multiplying ?
bingo!
so we'll get that x = [8*sin(61)]/sin(89). Just make sure that your calculator is in degree mode
what's the rounding to?
6.99
well be careful. Remember you use next number that's not included in the rounding
so really it's 6.9980234....
oh there ya go
since 9 is in the 100th place we add one more to the 10th place
so it's 7.0
yep that's it!
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Basically calculus i believe . idk how to do them since i missed that class and youtube or anything aint that helpful rn
i need to represent grafic that function
and at 2 i need to find the points of intersection of the functions graphics of the following coordonates
or something like that
i mean it's quite ebident how it works
but the problem is idk how to calculate
without an app
nvm i'll watch some yt videos
or something
that khan idk what site
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<enumitem, tipa >
\textbf{Question:} Let $\m X{e^{j\omega}}$ be the Fourier transform of $\bm xn$. Derive expressions in terms of $\m X{e^{j\omega}}$ for the Fourier transforms of the following signals (Do not assume that $\bm xn$ is real)
\env{enumerate}{[a)]
\ii $\cm{\mathfrak{Re}}{\bm xn}$
\ii $\bm{x^\ast}{-n}$
\ii $\cm{\mathcal{E}\nu}{\bm xn}$
}
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given the quadrant in standard position and a trig value of theta find exact values of indicated functions quadrant 3 sin -.5 sec theta
sin(theta) = -.5?
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how do i find refrence angles of 120, -80, 450
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I need help with hamilton circuits for a test I have a 20 and it is all due tomarrow so I need to finish this as fast as possible and move on to the next test this is my last test so im just more so looking for answers than how to do it
!noans
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Anyone who knows a bit of graph theory who can help me here?
G is a graph whith its incidence matrix I.And Z is the column space of I.We have to show that for every Arborescence A the columns of I(of A) are a base of space Z
I have a few questions about how this question needs to be solved so if u know sth about graphs let me know
also G is a simple directed graph with no "holes"
@vagrant talon Has your question been resolved?
<@&286206848099549185>
What
How are there multiple arborescences?
if the graph is always connected wouldnt there be only one arborescence? And if there are multiple the incidence matrix space of the arborescence would have a much smaller dimension so how can it be a base of Z?
Aha I think I can help you, let me read it thoroughly
how is aborescence defined in your course ?
okay so there are several in my graph lets say n.
how can this work with the basis?
the incidence matrix for the arborescence cant be a basis because the span of it will never reach the span of the column space Z or am i on the wrong path because in my head the statement doesnt make sense rn :/
np^^
or maybe they mean all arborescences spans combined build a basis of Z? That would make more sense to me
ok so I think thats not what the question is targeting
or wait
I need time Im sorry
I lack basic skill in linear algebra so I am slow with imagining vectorspaces
no problem 🙂
so this is how I understand exercise (a)
where G is the graph and A is the arborescence
and I think the idea is to build a connection between the edges that were deleted to get the arborescnece and linear dependency
but I am way too bad at linear algebra to come up with a better proof idea right now
@vagrant talon
i have no idea either rn :7 i think i gotta take the next few days to think about it and maybe ask again another time but thank u very much for your help ! ^^
np, Im sorry I couldnt help more. Good luck !
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I need help checking if I'm on the right track I'm trying to find the scale factor and I'm wondering if this is the correct way to set up the equation it would also be helpful if you could check if I did <d correctly
<@&286206848099549185>
This is my new work
I'm getting 1/3 and 3/4 for my sf so I'm doing something wrong
<@&286206848099549185>
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I just started finding the volumes of shapes around the x axis like this and im kinda confused
were suppsed to use integrals
$V=\pi\int_{a}^{b}R(x)^2\dd x$
PajamaMamaLlama
Do you know how to calculate the area of this region?
kinda
not really
i get whats going on logically but im struggling to compute it mathmatically
if that makes any sense
sorry i need to go
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im just not understanding how this set of equations results in the graph
i understand the zeros part. but not the rest
what does it mean for the derivative to be negative?
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$f(x) = 3^x, g(x) = \log_2(x), h(x) = f(x)^{g(x)}$
riemann
use $a^b = e^{b \log(a)}$
riemann
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Pls help
<@&286206848099549185>
Just curious before I help to kind of get a gist of what you know, did you guess on your answer or did you figure it out and want to know if it is correct?
no I tried solving this one
but got wrong
Show me your process
2/5 + 1/3 + 2
not exactly
thats what I did
oh
and then the like "remaining amount" of the fraction is Ruben's work
Yes
keep it in fractions
4/15
yes, and it took Ruben 2hrs to complete 4/15ths of the entire project, how much for 1/15
1/15 is for 1 hour?
not quite what is 2/4?
yes, so 1/15ths of the entire project takes 0.5 hrs so how long does the entire project take?
2 hours?
no, that's for Ruben's work time, take 0.5 and multiply it by 15
where you get 15 from?
the denominator
1/15 + 1/15.... = 15/15
if 1/15 worth of work is 0.5 hrs
0.5 + 0.5 + 0.5...
So to figure this out we had to calculate the amount of time it took for 1 fraction of the work (1/15) and we figured that out is 0.5 hrs, so if you have 15 units of work, you also have 15 units of time
oh
Did you get an answer?
@cold kindle Has your question been resolved?
no
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use CRT
No no
I have solved it by CRT but i want to save some more time by options
Can we not solved it by options?
sure but why
what year are u
thats irrelevant
Because it's an exam questions
We don't need to write or prove crt there 😆
We just need to save some time
Methods aren't important
uh use it and choose the appropriate options
Like how?
use crt what else
ok
Can we not go through options?
if you really wish not to use CRT, just check each option and see if it satisfies the conditions
Yes. How to check but?
yeah
420/10 =10 ?
no
Should I divide options by 42?
like in option a
it could be written as
420t+170 and t belongs to set of integers
so if t = 0
ok bot
try to transpose 170 in original equation
170t+420?
uh
im not seen that equation before
15k+8
31 is not 8 congurent moduli 15
Ohh
@astral tangle
cheers
I am thinking about it actually
😀😀
Let's take options now
Only d works
As we take 173-3 =170 is divisible by 10
good
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the area of a rectangle can be respresnted by the trinomial (2x^2)-4x+2. If the length is twice as long as the width, write the expressions that respresnet the length and width in factored form
i don't know if this is the answer
but when you factor the trinomial
you get 2(x-1)(x-1)
2(x-1)= length
and (x-1)= width
length is twice the width
factor the 2 first
u get x^2-2x+1
and factoring that you get (x-1)^2
or 2(x-1)(x-1)
the 2 coming from the 2 we factored out initially
how u get this
i did this and got like 100 on it but then forogr
(x-a)^2=x^2-2ax+a^2
or think of two numbers that multiply to 1
but add to negative two
-1,-1
x-1,x-1
are your factors
ok
what do I do next
x-1 is a side rightttt
so 2x-2 is the other side?
wut
I dont get
yes
it tells u the length is twice the width
so if we have 2(x-1)(x-1)
we can say this is 2(x-1) * (x-1)
where x-1=W
so 2(x-1)=2W=L
yes
forgor that too
a^2-b^2
and how this factors
it’s
(a-b)(a+b)
in this case we can let a=2x+y
and let b=(2x-y)
kk
using this formula we get
((2x+y)-(2x-y))((2x+y)+(2x-y))
2x on the left cancels
y- -y=2y
and 2x+2x=4x
y-y=0
so we get (2y)(4x)
=8xy
are you following?
so its just 0?
kk
does this make sense
yes
youre subtracting the entire(2x-y)
so essentially just change the sign
u get -2x+y
I got it thanks
yup
im a little bit slow since I havent slept in like 2 days
you must be tyler durden
who is tyler duden
you don’t get the reference??
xd
I dont watch that
fight club
the movie
ok don’t worry about it
you should watch it tho
great movie
any other questions
I hardly have the time to watch a movie
school is prison
literally 1/3 of your life is spent suffering in school
i hate it
preach
then the next few is spent working
you should have some time on your hands tho
who makes more students suffer
NO LIKE FR
and the loop goes on
you would love fight club
i’m telling you
if I was going to make a society where im the only one profitting
it’s like 2 dollars to watch it maybe
this is the exact shit i would pull
I have good movie pirate site
i used to use umm what’s it called
i forgot something with a b
but they shut down
@bright quarry
alr so
even if u spent 10 years
making 400k a year
youll still barely have 3 million
yes 33% is 133k
expenses add up
its cursed
it’s been rigged from the start my friend
how is 400k a year not enoygh
system is rigged
They make you spent 1/3 of your life in school too
make you spend the other 2/3 working for barely any income
you can live off of nothing 🤷🏼♂️
zamn
don’t use electricity
If it came down to it I can make a decent amount doing illegal stuff
bathe in a lake
zamn
well
thats not good
the people that make money like serious money have done illegal stuff to make it
atleast a good amount
of them
fr?
of course
my friends dad has decen tmoney
well
i don’t mean like 1 million
or luck through stock, crypto or husing
i mean like billions
oh for sure
they most likely do illegal stuffs
dont know why they need that much

yea i mean i’m just going to get some stem job and work like a slave for 15-20 years investing nearly all of my income
and then hopefully retire as soon as possible
bruhhh
they don’t know either
im going to stream or do whatever I can to make money
in my free time
imnot going to pull some gay shit
I fucking hate being taken advantage of
and the goverment taking 33% of my income
sounds like taken advantage of
im going to tax evade
im going to put it all into crypto
bitcoin is stable enough
yea i used to be one of those not need college guys and anti institution guys who said i’d make it big in real estate
but as time goes on
i realize that entrepreneurship is all luck mostly
you can work as hard as you possibly can
and stay broke
eh
I kind of know how to make money
and I kind of dont
like I know how to make shit online
more then my friends
and all of those youtube videos on how to get rich r pyramid schemes
ik
when I was 12 I made like 2k online
dropshippong bro!
that never works
how
skyblokc coins
yup it only works if you buy someone’s course🤣
is that crypto
nah