#help-38

1 messages · Page 64 of 1

slow hawk
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im just trying to see if the bot can make the message look better, not like x^2

ionic pendant
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you can use the fact that the tangent line to a circle passes through a point on the circle and is perpendicular to the radius

slow hawk
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I haven't been able to make sense of this

ionic pendant
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this is a problem that can be solved in a variety of ways (calculus, trigonometry, geometry + algebra), so you should solve it using the method you are currently learning

slow hawk
ionic pendant
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it seems that you start with a basic equation of a line passing through the point, in this case, $y = x - 4$ passes through $(4,0)$. then, we introduce a scaling factor variable $R$, then $y = R(x-4)$ will change the slope of that line while still making it pass through $(4,0)$. you then have a system of equations with the equation of the tangent line $y = R(x-4)$ and the equation of the circle $x^2 + y^2 = 8$

solid kilnBOT
ionic pendant
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and you want to find values of $R$ that make that have only 1 solution (in other words, the line and circle only intersect once, which means the line is tangent)

solid kilnBOT
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slow hawk
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Right, i see! He needs to use R to define the slope. Then he substitutes y for r(x-4). But how does he get from that to x^2(1 + R^2) - 8R^2x + 16R^2 - 8 = 0?

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the steps after dont make any sense to me. I dont know why

ionic pendant
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that comes from expanding $(R(x-4))^2$

solid kilnBOT
ionic pendant
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then grouping terms with a common factor of $x^2$ and moving all terms to one side (so that 0 is on the other side)

solid kilnBOT
slow hawk
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Ooooh I understand now. The steps after it too, just b^2 - 4ac, but I specifically struggled with the step from

x^2 + R^2(x^2 - 8x + 16) - 8 = 0

to

x^2(1 + R^2) - 8R^2x + 16R^2 - 8 = 0

But it's just distributing R^2 and then combining the terms like you said.

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Let me recheck to see if I really get it

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Yeah that should be good, thanks for ur help cloud birdheart

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wispy karma
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Hi

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wispy karma
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why does the formula for the solution use a(n+1)/an

river willow
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i mean it's just changing b_n to a_n

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white talon
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Spent 25 valuable minutes on this 😍

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white talon
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sees it not load

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well damn ofifnfofo

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aye it loaded

gaunt wave
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You can solve for the lower part of the upper left angle. Hint the left triangle is an isosceles triangle

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Then from there I think the upper left angle is 90° in total.

gaunt wave
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Then c + that angle + x + 12 = 180, you should be able to get x from the upper left angle. After you all the angles for the upper right triangle add them together to see if it equals 180

white talon
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ah, i kinda reversed that i think with 2x+9+3x+1=180

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-1*

gaunt wave
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That would not equal 180

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It would equal 180 - c

white talon
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ohhh ok

gaunt wave
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Hmmm I don't think the upper left angle is 90°, let me know whay you get so we can compare and go from there

round mango
# white talon

Try finding these and use the angle sum property of a quadrilateral

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For a less messier equation, find this and use exterior angle property

white talon
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ok that sounds slightly easier thank you !!

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lowkey need to redraw this problem because I scribbled all over it ofncofnkd

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sweet atlas
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Arna has x kr. Halla needs 15 kr. to have two times more.

a) how much does Halla have?

sweet atlas
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Is it 15 * 2 * x?

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<@&286206848099549185>

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<@&286206848099549185>

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<@&268886789983436800> no one’s helping me😔

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what can I do?

stoic iron
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Wait patiently

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And please don't ping mods for this

sweet atlas
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I wanna finish my homework as fast as possible

sweet atlas
stoic iron
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No sorry

zinc ginkgo
sweet atlas
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this is easy

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Did I do correct

zinc ginkgo
sweet atlas
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😐

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<@&286206848099549185>

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raw magnet
#

Hi super easy question but want to make sure I’m doing the strong induction properly

raw magnet
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Basically I have to prove for every n >= 8, exists a and b in Z+ such that n = 3a + 5b

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And like I just proved from 8-10 it’s true

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Then n= k+1 = (k-2)+3

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And then I would just simplify it

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(3a+5b)+3 = 3(a+1) + 5b

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@raw magnet Has your question been resolved?

raw magnet
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<@&286206848099549185>

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loud wasp
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loud wasp
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Does this look right?

plain slate
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yea

loud wasp
#

Thank uu

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opal coral
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opal coral
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i cant seem to calculate the answer?

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can someone help?

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answer is given but i dont know how to get to that

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@opal coral Has your question been resolved?

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@opal coral Has your question been resolved?

opal coral
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Yes sure!

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delicate lance
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how did it go from log 6^2 to log2?

dull temple
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log 6^2
2 log 6
2 (log 3 + log 2)

delicate lance
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OHHH ok mb i didnt see that

#

ty

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.close

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upbeat jungle
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how do i go about this

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ionic pendant
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find which line each expression corresponds to

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the shaded region is where each inequality holds at the same time. so find which side of each line is satisfied (e.g. in the first line, does ≥ mean above or below it?)

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alternatively, you can pick a "test point" inside the shaded region and check if it satisfies each inequality

upbeat jungle
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so i have to test each expression until i get the line right

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is it B?

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versed talon
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can i pls get help understanding how to do 21

versed talon
restive basin
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are those 2 angles equle?

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equal

versed talon
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which 2

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yes

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sorry

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is that better

restive basin
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can you tell me what 30/5 is?

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take ur time

versed talon
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ye

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i realized that part

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it was my test

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i rushed it last minute

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its 6 ik

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but even if it was 6

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how would i get to the answer from there

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and is 10 even the right answer

restive basin
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if f was 6 then the equation you use to find y would be 10+6+y=25

versed talon
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so its 9?

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im sorry

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6th grade is hard for me

restive basin
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yes it's 9

versed talon
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ok

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thank you

restive basin
versed talon
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ye

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thx

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bye

restive basin
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@versed talon Has your question been resolved?

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stoic sail
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stoic sail
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somebody pls help

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ik how to get midpoint and all that stuff

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ik the formula

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but i keep getting it wrong

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i think i keep miscalculating

knotty locust
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!show

trim joltBOT
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Show your work, and if possible, explain where you are stuck.

stoic sail
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i understand how to do the problem but my calculations are all over the place rn

knotty locust
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What would you like help with then?

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I suggest you just clean up your calculations and restart more neatly

stoic sail
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i'll try doing it one more time 😭
i'll come back if i get it wrong

knotty locust
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Okay, show your work if you do end up coming back

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that way we can help

stoic sail
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i got it wrong again :')

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i got the slope as -1/2
midpoint is (3,-3)
bisector i calculated as: y=2x-9

restive basin
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how did you get that slope?

stoic sail
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y2-y1/x2-x1

restive basin
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so plug the numbers in

stoic sail
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so i did: 1+7/-4-10
did i miscalculate....

restive basin
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yes

stoic sail
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omg

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i see my mistake 😭

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dang it

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-8/14

stoic sail
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-2/7

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wait

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what

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did i

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just do

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lmao

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💀

restive basin
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-4/7?

stoic sail
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yeah thats what i was supposed to do

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yay i got the right solution

#

ty

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.close

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lofty phoenix
#

a)𝑉 = 𝑊1 ⨁ 𝑊2
b)𝑉 = 𝑊1 + 𝑊2

lofty phoenix
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What is the difference in these sign?

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Linear sum of direct sum?

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Let me upload the original question

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Q.7 If V is a vector space of n x n matrices of real entries over the field R and 𝑾𝟏 and 𝑾𝟐 are the subspaces of symmetric andskew-symmetric matrice respectively, then which one is correct?

a)𝑉 = 𝑊1 ⨁ 𝑊2
b)𝑉 = 𝑊1 + 𝑊2
c) 𝑊1 ∩ 𝑊2 = {0}
d)All of above

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I can imagine zero matrix will be mutual in it so Direct sum failed A and C is wrong because we can get zero matrix in common and D wrong

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So B can be right no?

vernal briar
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Direct sum is when each vector in the sum can be represented uniquely by a sum of a vector in W_1 and a vector in W_2.

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The difference is the uniqueness

lofty phoenix
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Yes right

vernal briar
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(b) is true if every matrix in V can be represented as a sum of a symmetric matrix and a skew-symmetric matrix

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Is that true?

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If (b) isn't true, then (a) for sure isn't.

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If (b) is true, then (a) is true if that sum is also unique

lofty phoenix
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We can represent any matrix with sum of symmetric and skew

vernal briar
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Ok, so you understand why that means (b) is true, right?

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It follows directly from the definition of W_1 + W_2

lofty phoenix
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B is linear sum

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And we have zero matrix which means C is true and A also

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So D

vernal briar
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(c) doesn't just mean 0 is in W_1 + W_2

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it's saying 0 is the ONLY vector in BOTH W_1 and W_2

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Is that true?

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If it is, and you are convinced (a) is true aswell, then the answer would be (d) yes

lofty phoenix
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Yes 0 is in both matrix

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lofty phoenix
#

Thanks

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lofty phoenix
#

The plane euation do/does not any vector sub space

lofty phoenix
#

.close

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wraith hinge
#

Hi

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wraith hinge
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Can someone help me with 4)?

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So its intergrals with derivative i dont rly get it yet but it this is a good start right?

marsh forum
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this is homework right?

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not a test

dull temple
# wraith hinge

that's correct (you should work on your handwriting though)

grim sparrow
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try changing 1/cos^2(x) to sec^2(x)

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oh you already have the answer lol

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mb

frozen plover
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bighead integral

wraith hinge
marsh forum
wraith hinge
dull temple
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the tan in particular is hard to read

wraith hinge
grim sparrow
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oh what

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sec(x) = 1/cos(x)

wraith hinge
marsh forum
#

I would Think that's it, just write $\int sec^2 (x)$ as an intermediate step

solid kilnBOT
#

Why am. I here

wraith hinge
grim sparrow
#

wdym

wraith hinge
grim sparrow
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what is D here? the derivative?

wraith hinge
#

And how will i go about 5)?

wraith hinge
grim sparrow
wraith hinge
#

It becomes x^4 right?

grim sparrow
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yes, but that's not something that you should have to ask for confirmation about lol

wraith hinge
#

I forgot first week back to school after Christmas

grim sparrow
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fair enough i suppose

wraith hinge
wraith hinge
grim sparrow
#

yes

wraith hinge
wraith hinge
grim sparrow
#

uhh

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they all sort of use the same technique

wraith hinge
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10)?

grim sparrow
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convert the square roots to fractional exponents and simplify

wraith hinge
wraith hinge
grim sparrow
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not 1/x^-1/6

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it would be 1/x^1/6 instead

wraith hinge
wraith hinge
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  • c at the end
grim sparrow
#

if you want to see if you got the correct answer, just differentiate the result you get and see if you get the integrand

wraith hinge
#

And u think these questions are any harder?

grim sparrow
wraith hinge
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I am asking what it stand for and why u know

wraith hinge
grim sparrow
#

"C" is for "constant"

wraith hinge
#

Oh ye ye

wraith hinge
#

I only learned these formulas btw

wraith hinge
# wraith hinge

So do i encounter any other methods i need to use then these?

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wraith hinge
#

convert to metric system i dont speak american

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odd oxide
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odd oxide
#

Sure, I proved it by drawing

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but how can I prove it mathematically

main drift
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Definition of cyclic quadrilateral

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The perpendicular bisectors will intersect at the circumcenter because the bisectors induce isosceles triangles

odd oxide
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a quadrilateral which has all vertices on a circle

main drift
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Oops this isn’t circumcenter

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Nvm i think this is mathots point or something

odd oxide
#

never heard of that

main drift
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Yeah it’s not well known

odd oxide
#

damn it is

main drift
#

Try angle chasing with the varignon parallelogram

odd oxide
#

angle chasing?

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wraith hinge
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wraith hinge
#

How can i start with this

unique minnow
#

Use the chain rule on (ln(g(x)))'

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It'll make a g' pop out

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Then go back and use to log rules on ln(g(x)) since it's a product inside

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pseudo coral
#

how would i do this

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#

@pseudo coral Has your question been resolved?

fair juniper
#

span is all linear combination of these vectors?

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if yes, then you have to make it like this: a(2x+1)+b(x^2+1)+c(x^2+x+1)

#

and see what polynomials you can get

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wet cloud
#

What is the domaine of f(x) and why?

trim joltBOT
wet cloud
#

Got confused since f(x) do not exist while x exists in [-1;+1].

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Isn't supposed to be in 1 and 0 only?

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<@&286206848099549185>

worn void
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like the domain is for sure $$D \subseteq \mathbb C \backslash {-1,0,1}$$

trim gorge
#

But putting in -1 would make the right 0^0

worn void
solid kilnBOT
#

Homelama

worn void
#

but else it is a qestion of what the co-domain of f is

wet cloud
#

The exercise wanted Df and to study the continuete of f. (Prolongement)

#

But why -1 is not defined?

worn void
wet cloud
#

Alright.

trim gorge
#

Yeah that’s undefined

wet cloud
#

OHHH

#

I forgot that case fr.

#

But when I checked the graph, it seems that the undefined isn't just points

#

it is an range.

#

from -1 to 1, why?

worn void
#

because if it is real you get a negative number to a fractional exponant which gives a complex number

wet cloud
worn void
#

like do you know if $f:\mathbb R \to \mathbb R$?

solid kilnBOT
#

Homelama

wet cloud
worn void
#

or is the generally any additional information

worn void
wet cloud
#

What do I do in this kind of cases?

worn void
#

idk did you ever work with complex functions?

wet cloud
worn void
#

ok so in the real numbers if you have a^b and a is negative and b is not a whole number it is not defined

#

thats why the intervall [-1,1] was excluded

wet cloud
worn void
#

no because if you have for example -1^(0.5) it isnt defined in the real numbers

wet cloud
#

but why does it work noramally in my calculator?

worn void
#

what is the result of your calculator?

wet cloud
#

-1

worn void
# wet cloud -1

ok i think sth is wrong with your calculator cuz $$(-1)^{0.5}=\sqrt{-1}=i$$

wet cloud
#

exaclty....

solid kilnBOT
#

Homelama

wet cloud
#

but thanks anyway.

#

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opaque basin
#

I got 4 but I am not sure if thats right

worn void
remote thistle
opaque basin
#

That's what I got

#

Okayyy ty!

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swift totem
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wet ocean
# swift totem

because the supports meet in the center of the bridge, we can confirm that they divide it into two identical parts

#

12.5 ft each

#

sin(65)=12.5/x

#

we should get x with that

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wraith hinge
#

How many different letter arrangements can be made from the letters in the word
STATISTICS?

wraith hinge
#

Okay so i understand the common argument

#

with using permutations of indistinguishable objects

#

but i want to rationalise this using the idea here

#

I know both theorems yield the same result

#

but how would you "partition" this into r cells?

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waxen fable
#

This might seem like a dumb question but how can I construct 2 externally tangent circles that are both internally tangent to a third larger one

waxen fable
#

I did it with a particular case where both intersection points represented the diameter of the larger circle but I am looking for a more general case

#

this is what I have so far

wraith hinge
#

what is a problem

waxen fable
#

i'm sorry?

verbal stream
#

Yeah the radius of the 3rd largest circle would be the sum of the radii of the 2 smaller circles

waxen fable
#

okay thanks

#

but where will i have to put the center exactly

#

i tried a bunch of different configurations and none of them actually gave me 2 tangent points with the smaller circles

#

except where all the centers are aligned but that's a special case

verbal stream
waxen fable
#

right but then the centers would just be aligned

#

if we take this example i found online it can be done without that

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@waxen fable Has your question been resolved?

waxen fable
#

<@&286206848099549185>

verbal stream
#

oh I see

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#

@waxen fable Has your question been resolved?

waxen fable
#

<@&286206848099549185>

trim joltBOT
#

@waxen fable Has your question been resolved?

waxen fable
#

<@&286206848099549185>

ornate citrus
#

hhu

ornate citrus
waxen fable
#

Hey!

waxen fable
waxen fable
#

the centers can't be aligned

ornate citrus
#

yes

#

i know

waxen fable
#

could you please tell me how?

ornate citrus
#

Five minutes.please

waxen fable
#

okay, please take your time

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#

@waxen fable Has your question been resolved?

ornate citrus
waxen fable
#

Yup

ornate citrus
#

Sorry for being late.

waxen fable
#

It’s okay man

ornate citrus
#

I 'll send a answer picture after restarting . okay?

waxen fable
#

Yeah for sure

ornate citrus
#

I will give more detail if you wish

waxen fable
#

Omg thank you so much man!

#

This is really helpful

#

I appreciate it

#

Have a good rest of your day, thank you again!

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lament cloud
#

Am I correct in doing the calculation as (4!) * (4!-4) * (4!-4-4)?

lament cloud
#

Also subtracting 4 is removing the already used matchups in both directions

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#

@lament cloud Has your question been resolved?

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@lament cloud Has your question been resolved?

lusty delta
shrewd ridge
#

@lament cloud it's not the answer i get

#

I would start by selecting the order of matchups for e.g. Lakers

#

right, 4! makes sense, you select the home team and everything, but there's no notion of one match happening earlier, so I assume you would divide by 2 at that point

lament cloud
#

My new answer is 3! * 2^6 = 384

shrewd ridge
#

same

#

3 orders for lakers leaves 2 orders for heat, which fixes the rest

lament cloud
#

Ye ig this question is solved then

#

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somber spire
#

how do i do this

trim joltBOT
lethal anvil
#

what do the angles have to add up to in a triangle?

somber spire
#

180

lethal anvil
#

bingo

#

so what would the angle closet to B be?

#

(let's label it angle b)

#

a = 61
b = ?
c = 30

somber spire
#

89?

lethal anvil
#

yep!

#

So that's the angle

#

now we can use the law of sines 🙂

#

do you know that?

somber spire
#

we js started this so im a bit new

lethal anvil
#

no problem.
So law of sines is as follows:

somber spire
#

yes

lethal anvil
#

so you take the sine of the angle and then the opposite side and then do an equality

somber spire
#

ohh

lethal anvil
#

so we have $\frac{\sin(89^\circ)}{8} = \frac{\sin(61^\circ)}{x}$

solid kilnBOT
#

MellowDramaLlama

lethal anvil
#

now we just solve for x 🙂

somber spire
#

by cross multiplying ?

lethal anvil
#

bingo!

#

so we'll get that x = [8*sin(61)]/sin(89). Just make sure that your calculator is in degree mode

somber spire
#

i got 6.9

#

is that correct

lethal anvil
#

what's the rounding to?

somber spire
#

6.99

lethal anvil
#

well be careful. Remember you use next number that's not included in the rounding

#

so really it's 6.9980234....

somber spire
#

o

#

it says

#

in the question

#

"round your answers to the nearest tenth"

lethal anvil
#

oh there ya go

#

since 9 is in the 100th place we add one more to the 10th place

#

so it's 7.0

somber spire
#

ohh

#

so thats it?

lethal anvil
#

yep that's it!

somber spire
#

thank you so much

#

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mild scroll
#

Basically calculus i believe . idk how to do them since i missed that class and youtube or anything aint that helpful rn

mild scroll
#

i need to represent grafic that function

#

and at 2 i need to find the points of intersection of the functions graphics of the following coordonates

#

or something like that

#

i mean it's quite ebident how it works

#

but the problem is idk how to calculate

#

without an app

#

nvm i'll watch some yt videos

#

or something

#

that khan idk what site

#

--close

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!close

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wraith hinge
#
<enumitem, tipa >
\textbf{Question:} Let $\m X{e^{j\omega}}$ be the Fourier transform of $\bm xn$. Derive expressions in terms of $\m X{e^{j\omega}}$ for the Fourier transforms of the following signals (Do not assume that $\bm xn$ is real)

\env{enumerate}{[a)]
\ii $\cm{\mathfrak{Re}}{\bm xn}$ 
\ii $\bm{x^\ast}{-n}$ 
\ii $\cm{\mathcal{E}\nu}{\bm xn}$
}
solid kilnBOT
wraith hinge
#

I think i worked out b and c

#

but how do u do a

#

.close

#

nvm

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lament arch
#

given the quadrant in standard position and a trig value of theta find exact values of indicated functions quadrant 3 sin -.5 sec theta

digital bison
#

sin(theta) = -.5?

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#

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lament arch
#

how do i find refrence angles of 120, -80, 450

trim joltBOT
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olive talon
#

I need help with hamilton circuits for a test I have a 20 and it is all due tomarrow so I need to finish this as fast as possible and move on to the next test this is my last test so im just more so looking for answers than how to do it

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vagrant talon
#

Anyone who knows a bit of graph theory who can help me here?

vagrant talon
#

G is a graph whith its incidence matrix I.And Z is the column space of I.We have to show that for every Arborescence A the columns of I(of A) are a base of space Z

#

I have a few questions about how this question needs to be solved so if u know sth about graphs let me know

#

also G is a simple directed graph with no "holes"

trim joltBOT
#

@vagrant talon Has your question been resolved?

vagrant talon
#

<@&286206848099549185>

wraith hinge
#

yes

#

what is it?

foggy fractal
#

What

vagrant talon
#

How are there multiple arborescences?

#

if the graph is always connected wouldnt there be only one arborescence? And if there are multiple the incidence matrix space of the arborescence would have a much smaller dimension so how can it be a base of Z?

cunning cairn
#

Aha I think I can help you, let me read it thoroughly

cunning cairn
vagrant talon
#

its defined as a connected branching

cunning cairn
#

in my course its defined like this

#

so of course there are more than one usually

vagrant talon
#

okay so there are several in my graph lets say n.

vagrant talon
#

the incidence matrix for the arborescence cant be a basis because the span of it will never reach the span of the column space Z or am i on the wrong path because in my head the statement doesnt make sense rn :/

cunning cairn
#

I have to admit that I am not exactly good in linear algebra

#

so give me a second

vagrant talon
#

np^^

#

or maybe they mean all arborescences spans combined build a basis of Z? That would make more sense to me

cunning cairn
#

ok so I think thats not what the question is targeting

#

or wait

#

I need time Im sorry

#

I lack basic skill in linear algebra so I am slow with imagining vectorspaces

vagrant talon
#

no problem 🙂

cunning cairn
#

so this is how I understand exercise (a)

#

where G is the graph and A is the arborescence

#

and I think the idea is to build a connection between the edges that were deleted to get the arborescnece and linear dependency

#

but I am way too bad at linear algebra to come up with a better proof idea right now

#

@vagrant talon

vagrant talon
#

i have no idea either rn :7 i think i gotta take the next few days to think about it and maybe ask again another time but thank u very much for your help ! ^^

cunning cairn
#

np, Im sorry I couldnt help more. Good luck !

vagrant talon
#

thank u!

#

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fierce shuttle
#

I need help checking if I'm on the right track I'm trying to find the scale factor and I'm wondering if this is the correct way to set up the equation it would also be helpful if you could check if I did <d correctly

fierce shuttle
#

<@&286206848099549185>

#

This is my new work

#

I'm getting 1/3 and 3/4 for my sf so I'm doing something wrong

#

<@&286206848099549185>

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fair herald
#

I just started finding the volumes of shapes around the x axis like this and im kinda confused

fair herald
#

were suppsed to use integrals

red loom
#

$V=\pi\int_{a}^{b}R(x)^2\dd x$

solid kilnBOT
#

PajamaMamaLlama

red loom
#

Do you know how to calculate the area of this region?

fair herald
#

kinda

#

not really

#

i get whats going on logically but im struggling to compute it mathmatically

#

if that makes any sense
sorry i need to go

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crystal siren
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crystal siren
#

im just not understanding how this set of equations results in the graph

#

i understand the zeros part. but not the rest

wraith hinge
#

what does it mean for the derivative to be negative?

crystal siren
#

decreasing

#

well i think i get it like the f'(x) < 0 means its decreasing?

wraith hinge
#

mhm

#

so f'(x) > 0 is resolved as well

crystal siren
#

ahhhh ok. now i get how it shows on the graph thank you.

#

🙂

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zinc ginkgo
#

$f(x) = 3^x, g(x) = \log_2(x), h(x) = f(x)^{g(x)}$

solid kilnBOT
#

riemann

zinc ginkgo
#

use $a^b = e^{b \log(a)}$

solid kilnBOT
#

riemann

zinc ginkgo
#

yes that's wrong

#

middle term

#

graph both of them

#

you typod

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cold kindle
#

Pls help

trim joltBOT
#

@cold kindle Has your question been resolved?

cold kindle
#

<@&286206848099549185>

gaunt wave
#

Just curious before I help to kind of get a gist of what you know, did you guess on your answer or did you figure it out and want to know if it is correct?

cold kindle
#

but got wrong

gaunt wave
#

Show me your process

cold kindle
#

2/5 + 1/3 + 2

gaunt wave
#

not exactly

cold kindle
#

thats what I did

gaunt wave
#

you are on the right track

#

2/5 + 1/3

cold kindle
#

oh

gaunt wave
#

and then the like "remaining amount" of the fraction is Ruben's work

cold kindle
#

oh

#

1 - (2/5 + 1/3)

#

?

gaunt wave
#

Yes

cold kindle
#

that's like 0.26

#

something

gaunt wave
#

keep it in fractions

cold kindle
#

4/15

gaunt wave
#

yes, and it took Ruben 2hrs to complete 4/15ths of the entire project, how much for 1/15

gaunt wave
#

not quite what is 2/4?

cold kindle
#

1/2

gaunt wave
#

yes, so 1/15ths of the entire project takes 0.5 hrs so how long does the entire project take?

cold kindle
#

2 hours?

gaunt wave
#

no, that's for Ruben's work time, take 0.5 and multiply it by 15

cold kindle
gaunt wave
#

the denominator

#

1/15 + 1/15.... = 15/15

#

if 1/15 worth of work is 0.5 hrs

#

0.5 + 0.5 + 0.5...

gaunt wave
#

So to figure this out we had to calculate the amount of time it took for 1 fraction of the work (1/15) and we figured that out is 0.5 hrs, so if you have 15 units of work, you also have 15 units of time

gaunt wave
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cold kindle
cold kindle
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.close

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#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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astral tangle
trim joltBOT
#

Please don't occupy multiple help channels.

astral tangle
#

Can we not apply firect approach in this question?

#

Like divinding by options?

stoic gale
#

use CRT

astral tangle
#

No no

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I have solved it by CRT but i want to save some more time by options

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Can we not solved it by options?

stoic gale
#

sure but why

limpid tulip
stoic gale
#

thats irrelevant

astral tangle
#

We don't need to write or prove crt there 😆

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We just need to save some time

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Methods aren't important

stoic gale
#

uh use it and choose the appropriate options

astral tangle
#

Like how?

stoic gale
#

use crt what else

astral tangle
#

No no

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It's time consuming

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I am here to unnatural methods

stoic gale
#

ok

astral tangle
#

Can we not go through options?

stoic gale
#

I am not

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wdym

worldly wing
#

if you really wish not to use CRT, just check each option and see if it satisfies the conditions

astral tangle
#

Yes. How to check but?

stoic gale
#

yeah

astral tangle
#

420/10 =10 ?

stoic gale
#

no

astral tangle
#

Should I divide options by 42?

stoic gale
#

like in option a

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it could be written as

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420t+170 and t belongs to set of integers

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so if t = 0

limpid tulip
#

ok bot

stoic gale
#

try to transpose 170 in original equation

astral tangle
#

170t+420?

stoic gale
#

uh

limpid tulip
#

umm ithnk thats 1442cm3

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wt is the question

stoic gale
#

a general form to represent a linear congruence a(modn) is nt+a

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@astral tangle

limpid tulip
#

im not seen that equation before

astral tangle
#

But i didn't see it

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X=3 mod 10 will be
3k+10 no?

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X=8 mod15 will be
8k+15?

stoic gale
#

15k+8

stoic gale
astral tangle
#

Ohh

stoic gale
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@astral tangle

astral tangle
#

Got it

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Thanks

stoic gale
#

cheers

astral tangle
#

I am thinking about it actually

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😀😀

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Let's take options now

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Only d works

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As we take 173-3 =170 is divisible by 10

stoic gale
#

good

astral tangle
#

.close

trim joltBOT
#
Channel closed

Closed by @astral tangle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lost glen
#

the area of a rectangle can be respresnted by the trinomial (2x^2)-4x+2. If the length is twice as long as the width, write the expressions that respresnet the length and width in factored form

lost glen
#

i already know 2w^2 = (2x^2)-4x+2

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what do I do next

ebon dagger
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i don't know if this is the answer

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but when you factor the trinomial

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you get 2(x-1)(x-1)

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2(x-1)= length

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and (x-1)= width

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length is twice the width

lost glen
#

where did the -4x go

bright quarry
#

factor the 2 first

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u get x^2-2x+1

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and factoring that you get (x-1)^2

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or 2(x-1)(x-1)

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the 2 coming from the 2 we factored out initially

lost glen
#

i did this and got like 100 on it but then forogr

bright quarry
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(x-a)^2=x^2-2ax+a^2

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or think of two numbers that multiply to 1

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but add to negative two

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-1,-1

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x-1,x-1

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are your factors

lost glen
lost glen
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x-1 is a side rightttt

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so 2x-2 is the other side?

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wut

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I dont get

bright quarry
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yes

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it tells u the length is twice the width

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so if we have 2(x-1)(x-1)

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we can say this is 2(x-1) * (x-1)

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where x-1=W

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so 2(x-1)=2W=L

lost glen
#

kk

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so whats the facroted form

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just 2(x-1(x-1)?

bright quarry
#

yes

lost glen
#

next question:

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factore (2x+y)^2-(2x-y)^2

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without expanding first

bright quarry
#

difference of two squares

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are u familiar with

lost glen
#

forgor that too

bright quarry
#

a^2-b^2

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and how this factors

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it’s

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(a-b)(a+b)

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in this case we can let a=2x+y

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and let b=(2x-y)

lost glen
#

kk

bright quarry
#

using this formula we get

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((2x+y)-(2x-y))((2x+y)+(2x-y))

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2x on the left cancels

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y- -y=2y

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and 2x+2x=4x

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y-y=0

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so we get (2y)(4x)

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=8xy

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are you following?

lost glen
#

2x-2x=0

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and y-y is 0

bright quarry
#

yes

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no

lost glen
#

so its just 0?

bright quarry
#

distribute the negative

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youre subtracting negatige y

lost glen
#

kk

bright quarry
#

does this make sense

lost glen
#

yes

bright quarry
#

youre subtracting the entire(2x-y)

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so essentially just change the sign

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u get -2x+y

lost glen
#

I got it thanks

bright quarry
#

yup

lost glen
#

im a little bit slow since I havent slept in like 2 days

bright quarry
#

you must be tyler durden

lost glen
#

who is tyler duden

bright quarry
#

🤫

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💀

#

first rule of fight club

lost glen
#

?????

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r u high

bright quarry
#

you don’t get the reference??

lost glen
#

xd

bright quarry
#

ugh

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movie reference

lost glen
#

I dont watch that

bright quarry
#

fight club

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the movie

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ok don’t worry about it

#

you should watch it tho

#

great movie

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any other questions

lost glen
#

I hardly have the time to watch a movie

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school is prison

#

literally 1/3 of your life is spent suffering in school

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i hate it

bright quarry
#

preach

lost glen
#

then the next few is spent working

bright quarry
#

you should have some time on your hands tho

lost glen
#

in which the goverment takes your money

#

through tax

#

which is spent on teachers

bright quarry
#

🗣️🗣️

#

YOU WOULD LOVE THIS MOVIE

lost glen
#

who makes more students suffer

bright quarry
#

NO LIKE FR

lost glen
#

and the loop goes on

bright quarry
#

you would love fight club

lost glen
#

while goverment takes the money

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and profit

bright quarry
#

i’m telling you

lost glen
#

if I was going to make a society where im the only one profitting

bright quarry
#

it’s like 2 dollars to watch it maybe

lost glen
#

this is the exact shit i would pull

lost glen
bright quarry
#

i used to use umm what’s it called

#

i forgot something with a b

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but they shut down

lost glen
#

bro I calculated

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how much do you get taxed if u make 400k a year?

bright quarry
#

hmm maybe like 100?

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100k

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more maybe? 120k

lost glen
#

@bright quarry

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alr so

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even if u spent 10 years

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making 400k a year

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youll still barely have 3 million

bright quarry
#

yes 33% is 133k

lost glen
#

which is way les then 3 or 1 mil by then

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spent on a home

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and living expenses

bright quarry
#

expenses add up

lost glen
#

its cursed

bright quarry
#

yea lol

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it’s a lot less

lost glen
#

400k a year is barely enough

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thats actually gay

bright quarry
#

it’s been rigged from the start my friend

lost glen
#

how is 400k a year not enoygh

bright quarry
#

system is rigged

lost glen
#

They make you spent 1/3 of your life in school too

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make you spend the other 2/3 working for barely any income

bright quarry
lost glen
#

please tell

bright quarry
#

eat air

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😹😹😹

lost glen
#

zamn

bright quarry
#

don’t use electricity

lost glen
#

If it came down to it I can make a decent amount doing illegal stuff

bright quarry
#

bathe in a lake

lost glen
#

zamn

bright quarry
#

well

lost glen
#

thats not good

bright quarry
#

the people that make money like serious money have done illegal stuff to make it

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atleast a good amount

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of them

bright quarry
#

of course

lost glen
#

my friends dad has decen tmoney

bright quarry
#

well

lost glen
#

the only way to make decent money

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is either buessness

bright quarry
#

i don’t mean like 1 million

lost glen
#

or luck through stock, crypto or husing

bright quarry
#

i mean like billions

lost glen
#

they most likely do illegal stuffs

#

dont know why they need that much

bright quarry
#

and then hopefully retire as soon as possible

bright quarry
lost glen
#

im going to stream or do whatever I can to make money

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in my free time

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imnot going to pull some gay shit

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I fucking hate being taken advantage of

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and the goverment taking 33% of my income

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sounds like taken advantage of

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im going to tax evade

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im going to put it all into crypto

#

bitcoin is stable enough

bright quarry
#

yea i used to be one of those not need college guys and anti institution guys who said i’d make it big in real estate

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but as time goes on

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i realize that entrepreneurship is all luck mostly

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you can work as hard as you possibly can

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and stay broke

lost glen
#

I kind of know how to make money

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and I kind of dont

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like I know how to make shit online

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more then my friends

bright quarry
#

and all of those youtube videos on how to get rich r pyramid schemes

lost glen
#

when I was 12 I made like 2k online

bright quarry
#

dropshippong bro!

lost glen
bright quarry
lost glen
bright quarry
lost glen
#

others made 200k or so

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or 40k

bright quarry
#

is that crypto

lost glen
#

nah