#help-38

1 messages · Page 58 of 1

dark snow
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hi all. could i get a hint/pointer as what im doing wrong here?

dark snow
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im 99% sure i did each part right but im not sure if theres a different methodology for a lin equation?

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modest onyx
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what does this Ce mean? does that say there is a constant value in the function of y inside exponent of e?

full hull
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maybe C is constant and e is exponential

modest onyx
full hull
modest onyx
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wait no it simply shouldn't

ionic pendant
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not generally, but
e^(2x² + 56x + C)
with some arbitrary constant C is equal to
e^(2x² + 56x) * e^C
and e^C is also an arbitrary constant, so we can just call it C

modest onyx
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ah okay got it now

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nocturne kernel
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can someone explaine how the function should look like? so far what i understand is that there is a function H in complex plane which is defined by y=(x+4)/(x+2). i dont understand where is the "i" in y= (x+4)/(x+2)

nocturne kernel
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or is it the same?

nocturne kernel
blissful bison
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$Imz=\frac{Rez+4}{Rez+2}\text{, where: }z\in \mathbb{C}$

solid kilnBOT
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Joanna Angel

nocturne kernel
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nocturne kernel
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.reopen

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nocturne kernel
blissful bison
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listen the H is not a function, it is a set located on complex plane, you can only draw it as a set,

nocturne kernel
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hm

blissful bison
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in other word, it is the set of complex numbers that follow the condtion i wrote above for you

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and that is all what you can take it from

nocturne kernel
blissful bison
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some notificaiot, artificial one is possible, bu t that doe snot change the meaning

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i write such eventual form for oyu

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$H=\left{ z\in \mathbb{C:}f\left( z \right)=0\wedge f\left( z \right)=Imz-\frac{Rez+4}{Rez+2} \right}$

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but that is rather diffeerntr way of writng the same and definign the set H

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maybe explain where did you find this set H ? mayeb it can help to understand why the set H appeard, but from waht you wrote, it is onyl a set, not a function

nocturne kernel
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it was given

blissful bison
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do you rememebr precise text ?

potent bone
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(...what's x here?)

solid kilnBOT
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Joanna Angel

nocturne kernel
# blissful bison do you rememebr precise text ?

so they gave me a function that is in complex plane f(z) = z+2 -i, and this set H, and they ask me to find f(H). So before you explained it to me that H is a set, i thought it is a function and to find was a function composition of foH

blissful bison
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ah yes now all is clear)) but as you can see, the H is a set

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and your task is =

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to find the image of the set H via function f

nocturne kernel
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what do you mean by image of the set H?

blissful bison
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you must find the image

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image is also a set

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located on compelx plane

nocturne kernel
blissful bison
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you can look at it in a such way: take, assume, few complex numbers belonging to the set H

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if yo can do it

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then take them

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and put them into yoru funciton f

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yes

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yoru function f is a complex linear function

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so

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it works like

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paralell shift

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since it adss 2 - i

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to every eleemnt from H set

nocturne kernel
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do you know what this topic is called? i want to read it online, my class is in german and my teacher doesnt upload the script

blissful bison
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do you understand it ?

nocturne kernel
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and i couldnt find it in german

blissful bison
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it can be shown in initial parts of algebra or

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initial parts of analytical functions

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also called comples analysis

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tell me

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what do you study ?

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maybe it helps, to udnertsand why you need it

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mein deutsch ist nicht zu viel aber ihc kann etwas helfen

nocturne kernel
blissful bison
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Bilder von Mengen mit komplexen Funktionen

nocturne kernel
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oooo

blissful bison
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klar ?

nocturne kernel
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oooo

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yes

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i think it is it

blissful bison
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Komplexe Funktionen | geometrische Interpretation

nocturne kernel
blissful bison
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smiles

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🙂

nocturne kernel
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wraith hinge
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wraith hinge
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How do I do the horizontal ?

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I set the bottom to 0 and got x=0

nimble stone
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limits for end behavior

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(tending to +- infinity)

wraith hinge
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?

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ooh wait I gotta factor it rght

nimble stone
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i wouldnt say its necessary

wraith hinge
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there an easier way to go about it?

nimble stone
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do actually know about limits

wraith hinge
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I see how he got -7 and 1 now

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i dont think so

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maybe in dif words idk

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but when he factors it what happens to the x^2

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why is that just gone

nimble stone
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youre asking me about something i cant even see

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quasi void
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Which of the vectors does not belong to the subspace spanned by -2i + 3j + k and i + j + 2k:

a) -4i + 6j + 2k
b) 3i + 8j + 11k
c) 11i -4j + 6k
d) 10i -5j + 5k

fossil kraken
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What does "belong to" mean here?

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What does spanned by mean here?

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.... And what things do you know how to do with vectors?

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Asking Sam

sharp heart
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Oh, OK.

fossil kraken
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You try. I'm getting no response

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@quasi void Has your question been resolved?

quasi void
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So I think I need to put them in an augmented matrix like:

[-2 1 x
3 1 y
1 2 z ]

sharp heart
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Right.

quasi void
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and then use gaussian reduction to solve it

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and then if I get values for x1,x2,x3 it is within the span of the two vectors

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my understanding was if one of the answer vectors is a linear combination of the other vectors then it is within the span

sharp heart
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Well, what you want is to get two values and a zero.

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You're solving for two variables, what you multiplied the first span vector by and what you multiplied the second span vector by.

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So, you should have:```
[1 0 a]
[0 1 b]
[0 0 0]

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Then you can check that a(-2i + 3j + k) + b(i + j + 2k) equals your vector.

quasi void
sharp heart
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Yes, that's right.

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You have the scalar multiples for each vector in the span, so you have a linear combination of those vectors.

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And all linear combinations of the vectors are in the span.

quasi void
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ahhh okok

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i'll go through them one by one

sharp heart
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OK.

quasi void
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For vector a) I get x1=2 and x2=0 and b) I get x1=1 and x2=5

sharp heart
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OK, so check that those work.

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2(-2i + 3j + k) + 0(i + j + 2k) = (-4i + 6j + 2k)

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And so forth.

quasi void
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ah ok

quasi void
sharp heart
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OK, so far so good.

quasi void
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d) I get x1=-3 and x2=4 and then for c) i'm not getting values so I think c is not spanned within those two vectors

sharp heart
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What do you get for the matrix after Gaussian reduction?

quasi void
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I get:

[ 1 0 0]
[0 1 0]
[0 0 1]

sharp heart
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,w RREF[{{-2, 1, 10}, {3, 1, -5}, {1, 2, 5}}]

sharp heart
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Hmm, I think I did that wrong.

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On second.

quasi void
sharp heart
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Oh!

quasi void
sharp heart
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,w RREF[{{-2, 1, 11}, {3, 1, -4}, {1, 2, 6}}]

quasi void
sharp heart
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That last row means that you have two vectors multiplied by 0 added together to get 0, but you're not getting 0.

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So, that's impossible, so that must not be in the span.

quasi void
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interesting!

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So c) 11i -4j + 6k is the answer

sharp heart
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Yes, that's right.

quasi void
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ah ok thank you so much! This has been very helpful and informative

sharp heart
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If you get less nonzero rows than the number of vectors that are spanned, the spanned vectors are linearly dependent.

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You're welcome.

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You should never get a [0, 0, 0, k] where k isn't 0, though. That's the "it's not in the span" sign.

quasi void
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ah okok that's good to know

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thank you!

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sharp heart
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No problem.

blazing narwhal
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Could I get some help with c plz🙏

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old plank
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old plank
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I am getting Option B

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please help

unique pine
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what's the issue

old plank
unique pine
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what's the doubt

old plank
# old plank

this is what I did and i am getting the answer as B

unique pine
old plank
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I tried it but idk how to do

unique pine
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you got the answer as B, which, to me, seems to be correct, and you solved it by yourself, so what did you not understand

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its right

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the answer is B

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well technically all options are wrong

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but yeah your best match is B

old plank
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But the correct answer according to the solutions is C

wraith hinge
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No the right answer is C

old plank
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How tho

wraith hinge
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For example h=6 satisfies option B but isnt allowed in the problem

unique pine
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all the options are technically wrong

wraith hinge
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You can see |h-a| as the distance between h and a

unique pine
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oh wait yes

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I realized

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what's wrong

inland orbit
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6 1/2 is the "ideal" length for each hot dog, halfway between the min and max lengths allowed. The hot dogs are allowed to vary by up to 1/4

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from that ideal length

unique pine
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yeah, my bad, I'm a bit dumb

inland orbit
# old plank

The problem with this is that the absolute value being less than 1/2 doesn't mean the actual value is between 0 and 1/2, it would mean between -1/2 and 1/2

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If you subtract 6 1/2 instead, you get x-6 1/2 between -1/4 and 1/4

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which is exactly what it means to say its absolute value is less than 1/4

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river shard
#

please help me to prove this one

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sleek canopy
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it was used the triangle inequality |a+b|<|a|+|b|

marble wharf
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in general only <=

river shard
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river shard
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.reopen

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muted harbor
#

Could someone please check if i got these questions correct ?

muted harbor
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Also i have a problem for the IVT question

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where when i used -2 and 2 i got two negatives

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but when i used -3 and 3 i got one negative and positive

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not sure what i am supposed to do there

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and for 5 (iii) i got a minimum but also 0 = 0 so does that mean it doesnt have a max or a min when x = 0 ?

trail obsidian
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Which question do you have a problem

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Exactly

muted harbor
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muted harbor
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@hazy light

torn mantle
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Hey

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Not sure i can hep you with all the questions but I'll do what i can

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The first limit was done correctly

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The second one, idk why you just said directly that it equals to

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1

torn mantle
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So for 5 a), we know that the equation has at least one real root between x=-3 and x=3

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The only thing I would think of, though I'm not sure it's the smartest approach, would be to get two other intervals that are outside of the interval [-3,3] in which IVT also lets us say there must exist some number c such that f(c)=0

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@muted harbor

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Can you please @ mention me if you text back

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echo jasper
#

so i did this problem

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echo jasper
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well not really problem lol

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BUt how come

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On desmos if i plug in that function the graph looks different from what is provided for me

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Like -_

trail obsidian
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What is the problem

echo jasper
trail obsidian
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I don't see anything wrong

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Are you worried they aren't curvy enough?

echo jasper
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Yeah

trail obsidian
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😭🙏

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It's the same graph

echo jasper
#

o

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lol

trail obsidian
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Just know the characteristics of sine graph

ripe topaz
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zoom in the desmos graph (it will look the same)

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red loom
#

Ok, there's gonna be something elementary I'm just missing how do I evaluate: $\lim_{h\to0}\frac{a^{h}-1}{h}$ to be $\ln(a)$, I can't use l'Hôpital's nor can I use the exponent rule of derivatives

solid kilnBOT
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PajamaMamaLlama

red loom
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for some reason all websites/resources I look at take this to be a given/trivial

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I am really struggling to find anything that shows why this is the result without using the above two metioned

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@red loom Has your question been resolved?

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wraith hinge
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how did they get the h

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wraith hinge
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h=0.1686

silent canyon
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h = c it says

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So they found c

onyx plover
silent canyon
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c = a * e

onyx plover
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And c = sqrt(a²-b²)

onyx plover
wraith hinge
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ohhh okay

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thanks for the help guys!

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ima close this now for the next person 🫡

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lofty arch
#

Using cylindrical coordinates (R, ϕ, z), where R2 = x
2 + y
2
, find the volume of a hyperboloid R2 = z
2 + a
2 between z = 0 and z = b.

lofty arch
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all the tvariables are squared not multiplied by 2

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i got 2pib^3divided by three

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but i swear it should depend on a

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for R limits i got a to sqrt(b^2+a^2)

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for z 0 to b

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and phi from 0 to 2pi

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but the answer sheet i have says 0 to sqrt(b^2+a^2) for R but i dont understand

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craggy sinew
#

Is this statement true or false? for any M that belongs to the set of real numbers, 1/2 > M. I think its false.

wraith hinge
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You are right

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Its indeed false

craggy sinew
#

ok

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hazy olive
#

Hi, I've been on and off with this probelm for about a month now and am really stuck on it. I've tried using the fact that the area of the quadrilateral is between 0 and 1 (as shown), and stuff to do with the sum of 2 sides of a triangle being longer than the third side in all cases, but I got stuck with that too. Any suggestions on things I could try or inequalities related to geometry? Thanks!

hazy olive
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It wasn't my first thought, but I got stuck and wanted to try different things

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And say that the perimeter of the quadrilateral is between 0 and 4?

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oh wait

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i think i get you

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gimme a sec

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Is this what you were talking about?

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Not sure how to form an inequality for that tho

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I guess some can be factored as like (a - 1)^2 but ultimately interpreting the square terms to form an inequality in this geometric context is kinda unclear to me

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I can find a logic for why that should be smaller than or equal to 4, but not a rigorous logic for why they should be greater than or equal to 2

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ohh wait

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hazy olive
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I think that suffices as a proof, but I just wanna be sure

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wanton meteor
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wanton meteor
#

I know what an indirect proof is, but I don't know where to go from there

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wheat cypress
#

Q: graph the INVERSE of y-4=3^(x-2)
so would the inverse be: log_3(x-2) + 4?

wheat cypress
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idk how to convert exponential fxn's to log fxn's? can someone help me out please

wooden mural
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Let me see if I can give it a try.

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So inverse functions are reverse engineering

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where input becomes output and output becomes input.

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got it.

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Do you know the base change rule?

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wheat cypress
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wraith hinge
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wraith hinge
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fervent loom
#

how does one factor this? and in general, if ac and b dont factor nicely, what should i do? thanks

nimble stone
#

do you want to solve it?

#

or do you literally just want (x+a)(x+b)

fervent loom
#

just want that form yeah

#

i can solve it from there

nimble stone
#

itll be messy

fervent loom
nimble stone
#

youd have to use the quadratic formula

#

but then you would have already solved it

orchid wagon
fervent loom
#

the b squared b^2 -4ac etc thing?

nimble stone
#

this has irrational roots so theres no nice factorisation

nimble stone
#

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

solid kilnBOT
#

AℤØ

fervent loom
#

x^2 +10x +12 = 0 ?

balmy matrix
#

if the problem doesnt specify u dont have to set it to 0

#

u would js leave it as (x-a)(x-b)

orchid wagon
#

pretty ugly roots

#

but its the solution soo

fervent loom
#

here ill send the whole problem

#

not sure how they want me to fill in this table when i would have to use the quadratic formula

fathom ivy
#

oh, then this works like any other complete the square
only you get to put in radicals instead of nice whole numbers

fervent loom
#

wdym by radicals

nimble stone
#

surds

#

roots

fervent loom
#

ye

#

roots of what tho squint

#

how do i show the root of the 10x and 12

nimble stone
#

the bottom right shouldnt be 12

#

the columns and rows should be x and 5

#

bottom right as 25

fervent loom
#

where does the 12 go?

nimble stone
#

its not there yet

#

youre just working with x^2+10x

fervent loom
#

big_think interesting

nimble stone
#

you add a value to correct it to 12 later

fervent loom
#

so what goes in the ohter spaces?

#

oh 10x and 2x

#

wait

nimble stone
#

no

fervent loom
#

5x nvm

#

where do i go from here?

#

where does the 12 come in

#

?

nimble stone
#

-13 somewhere

fervent loom
#

what number goes in front?

#

also its telling me that we didnt add -13 to not change the expression..

trim joltBOT
#

@fervent loom Has your question been resolved?

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#

@fervent loom Has your question been resolved?

fervent loom
#

<@&286206848099549185>

brittle otter
#

Hey

#

You want help or not

#

???

fervent loom
#

yes

brittle otter
#

Aight

#

Looking at the way they formatted the answer

#

We'll be completing the square

#

There is no specific a value

#

So we won't be needing that first value

#

Keep it at 1

#

The value after the (x+5)^2

#

Should be the value that makes it so that x^2+10x+25 (your squared x+5) is equivalent to x^2+10x+12

#

In this case it'd be...

#

@fervent loom

fervent loom
#

1

brittle otter
#

(12-25)

fervent loom
#

-13

brittle otter
#

Yayyy

fervent loom
#

but wesubtract that at the end thought rightr/

#

?

#

that doesnt go in front

brittle otter
#

Uh sorry reword that

#

Don't understand lol

fervent loom
brittle otter
#

We already have our value

brittle otter
brittle otter
brittle otter
fervent loom
#

hmm

#

ah i see

brittle otter
#

:)

fervent loom
#

weird that it needs me to specify that but ok big_think

#

thanks!

brittle otter
#

Yep

fervent loom
#

if there was something like a 3x^2 would a 3 go in place of it or something?

brittle otter
#

Kind of

#

You would put a 3 in front

#

But

#

You would also multiply the expanded values by 3 as well

#

So don't forget that

fervent loom
#

ah right

brittle otter
#

As an example, 3x^2+36x+19

#

Is the same thing as 3(x+3)^2-8

#

Oh wait shit mb

#

Change the values rq

fervent loom
#

hmm

#

so what waould be the process for figuring that out

#

taking 36 cubed or something

#

?

brittle otter
#

Factor out 3 from the first two values

#

To get 3(x^2+12x)

fervent loom
#

ohh

brittle otter
#

Mhm

#

That's how I taught myself

#

They might do it differently

fervent loom
#

what if it doesnt factor nicely like 3x^2 + 35 cursedface

#

just put he square root in front i assume?

#

actually/

#

maybe you could do like..

brittle otter
#

If it doesn't factor nicely?

#

Well then

#

That's when we either factor normally

#

Or use the quadratic formula

fervent loom
#

oh right

brittle otter
#

Steps to factor quadratics

#
  1. Try using basic factoring into two basic factors
#
  1. Try completing the square
#
  1. Use the quadratic formula
#

Quadratic formula should be last method

fervent loom
#

completing the square as in what i did above?

brittle otter
#

Mhm

fervent loom
#

thats actually so helpful to remember

#

thanks

brittle otter
#

Glad I helped :)

fervent loom
#

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jolly sail
#

hi

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jolly sail
#

need help with this

#

i know deriv is just slope

#

but its hard to tell slope in that graph

#

I got these so far

#

but I can't tell the rest

thorn trout
#

you can use decimals

#

kind of a bad question imo, it is a bit hard to estimate the gradient

#

just draw a linear line at the point and estimate the gradient of it

#

f’(2) looks like -1

jolly sail
thorn trout
#

anything that represents the slope

#

like 0.5

jolly sail
#

so it said a and d were wrong

#

what should I put for those 2

#

nvm got it

#

put in 3/4 and -1.75

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jolly sail
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.close

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timber bronze
#

this is a graph of the second derivative of a function where i am asked to find where it is concave up and concave down, i can see the intervals of concavity from the graph but how would i determine them mathetmatically?

timber bronze
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lofty arch
#

A car park attendant loses the name tags for a set of seven car keys, so hands out
the keys randomly when the seven owners return.

lofty arch
#

) How many ways are there of returning the keys so that nobody receives their
own keys? #

#

i got 7!-6! but i think im wrong

frozen plover
#

lol dearrangement

#

$7!\sum_{k = 0}^7 \frac{(-1)^k}{k!}$

solid kilnBOT
#

jan Nejon

frozen plover
#

why does my sigma look stunted

lofty arch
#

weird this is in past paper but we never covered dearrangements in class

#

thank you

#

How many ways are there of returning the keys so that at least two people
receive their own keys?

#

i got 5! for this or is it also derangments

#

@frozen plover

#

.close

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runic ferry
#

As n grows, which would result in smaller values, log_2(n) or 2*log_3(n)? Why would that be the case?

dull temple
#

use log rules to make those comparable

runic ferry
#

I’m not sure what u mean, i guess i could have log_2(n) compared to log_3(n^2)?

split chasm
#

consider change of base law

runic ferry
#

Ah ok, so i would compare log_2(n) to 2*log_2(n) / log_2(3)? And here 2/log_2(3) gives about 1.26

#

So log_2(n) gives a smaller value

#

When compared to 2*log_3(n)

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#

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proven violet
#

hi

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proven violet
#

i'm doing this question

#

integral test might work because it's monotonically decreasing, but the integral i need to calculate has no answer in terms of standard elementary functions (and we haven't done integrals in analysis yet so i'm not expected to bound it in terms of another integral)

#

ratio test is looking terrifying

#

cauchy convergence criterion is looking terrifying

#

comparison test idk what to compare it with

#

i am very stuck on how to approach this

#

okay so i've made some very handwavey progress

#

$\forall x\geq 2: \frac{x^{-a}}{1+a^{-x}}\leq \frac{1}{1+a^{-x}} \therefore \int_0^\infty \frac{x^{-a}}{1+a^{-x}}\mathrm{d}x \leq \int_0^\infty \frac{1}{1+a^{-x}}\mathrm{d}x=\lim_{n\rightarrow\infty}\log(a)\log\Big(\frac{a^n+1}{a^2+1}\Big)$

solid kilnBOT
#

george clooney real account

proven violet
#

and clearly the limit at the end doesn't shoot off to infinity only in the case that $0<a\leq1$

solid kilnBOT
#

george clooney real account

proven violet
#

but proving those inequalities in my big step was done entirely by looking at the graphs on desmos

#

not at all rigorously, which is what this course expects

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graceful river
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graceful river
#

<@&286206848099549185>

unique pine
#

It's basic substitution

graceful river
#

I dont get itpl

#

Pls help

#

I dktn got a calcultor

#

<@&286206848099549185>

wraith hinge
#

here's a clue

graceful river
#

It didnt work

#

Its 9 and it worn woro

wraith hinge
#

just keep going

graceful river
#

I dotn get it

#

Hmm

wraith hinge
#

plug in n = 1

graceful river
#

Ty

wraith hinge
#

then n = 2

graceful river
#

I get it now

#

How can I do the others

wraith hinge
#

same method

graceful river
#

Can u help me on 3d

wraith hinge
#

kk

graceful river
#

Ty

wraith hinge
graceful river
#

Is it 9

wraith hinge
#

no idea

#

it says 2 dp

#

so there must be a decimal

graceful river
#

Can u do 3e or 3f then

wraith hinge
#

might as well say do all xD

graceful river
#

Oh alr

wraith hinge
#

it's the same method I use

#

basic substitution

graceful river
#

I still dotn understand srry

wraith hinge
#

kk

graceful river
#

My teacher never taught us this and expects us to learn on our own

wraith hinge
#

oof

#

gl typing this into your calc

graceful river
#

Dayum

wraith hinge
#

pretty much

#

substitution

graceful river
#

Bruh it didnt work

#

I hate my teacher

wraith hinge
#

did you put it to 3 d.p?

graceful river
#

Would it be

#

4.57894

#

Ao

#

4.58

wraith hinge
#

no

#

4.579

#

3 dp xD

graceful river
#

YESSS

wraith hinge
#

it worked?

graceful river
#

What would be

#

6.1538

#

To 2d0

#

Dp

#

6.15?

#

Would it?

#

Hello?

wraith hinge
#

uh

#

ye

graceful river
#

Wiat

#

Try this

#

Might be better

#

Easier

wraith hinge
#

my man Ill leave that one to u

#

try that method

#

xD

#

I used

graceful river
#

Which

#

K

wraith hinge
#

the one you showed me

#

show me your working

#

ill tell you what's going wrong

graceful river
#

Just curious

#

What is

#

5.09566 to 3dp

#

5.90566

#

I meant

wraith hinge
#

take the third decimal place

#

and round it up

graceful river
#

5.906?

wraith hinge
#

5.9 that's 1 dp

#

yep

graceful river
#

Didjt wlro

#

Work

#

Rip

#

Ite not event hats it's so hard to put in calculator

#

Cna ut ry it for me

wraith hinge
#

kk

graceful river
#

I gotta go bed soon

#

Wwit

#

It changed here

wraith hinge
graceful river
#

Calculator shutdown

#

Uh oh

wraith hinge
#

xD

#

online calc

graceful river
#

Just to ask

#

What type of method is this

wraith hinge
#

basic plug in and substitution xD

#

if the teacher ask what you did

#

just say

graceful river
#

Is substitution this minus sighn

wraith hinge
#

I just plug in n from until a number

#

it's like saying

#

x + y = 1

#

y = 3

#

then you substitute it in

#

x + 3 = 1

#

x = -2

graceful river
#

Can u dot his kn calcultor

wraith hinge
#

dont know

#

use symbollab

trim joltBOT
#

@graceful river Has your question been resolved?

graceful river
#

Ye

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mortal coyote
#

Find the function for a secondary function, that crosses y-axis in 2 and only has one zero point 2

trim joltBOT
#

@mortal coyote Has your question been resolved?

mortal coyote
#

<@&286206848099549185>

warped jasper
#

<@&268886789983436800> are you guys all nerds?

merry gyro
#

yes. Don't ping mods for memes

mortal coyote
#

.close

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wicked quartz
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clever ferry
#

Anyone able to help me?

wicked quartz
#

Oops

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#

@wicked quartz Has your question been resolved?

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@wicked quartz Has your question been resolved?

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@wicked quartz Has your question been resolved?

runic cloak
#

whats the question even

trim joltBOT
#

@wicked quartz Has your question been resolved?

tall aurora
#

its prob sin of that

#

for 1

#

sorry i got it wrong

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@wicked quartz Has your question been resolved?

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clever wind
trim joltBOT
clever wind
#

i couldnt find a way to do it without using the cosine theorem

#

i will be glad if i get help before 12 because i have an exam about this type of questions at 12 😬 stressing myself realy

wide ruin
#

@clever wind i’m in the same boat as u lmao, are u in pre calc

clever wind
#

the class code is calculus 101 so you can say that i guess

wide ruin
#

ohhh

#

i have a quick question not sure if you’d know the answer

#

do u know what a period in a graph is?

clever wind
#

if i see the graph maybe i can help

wide ruin
#

u mind if i dm u?

clever wind
#

u can dm let me check if my dm's are open or not

wide ruin
#

idk if it’s against the rules to post stuff in ur help channel lmao

clever wind
#

i domt know too

haughty tundra
#

you can post i think

wide ruin
#

ohh ight

clever wind
#

okay you can dm me

wide ruin
#

its not working i’ll just post it in here

#

so this is my graph, the period is 8 and idk what that means tbh. i don’t know how the period correlates to the graph

clever wind
clever wind
#

perios is

#

period* is when something

#

finishes the action where they begin,

odd onyx
#

@clever wind DM me for a second

clever wind
#

so period is you can think like

wide ruin
haughty tundra
wide ruin
#

it restarts at 26 pi/3

haughty tundra
#

yes it also starts at 2pi/3

wide ruin
#

Oh.

#

LOL

clever wind
#

a time value or a number like time per lap while running etc. If you need to understand the logic,

wide ruin
#

broooooo okay that’s what was throwing me off so much

#

ty

haughty tundra
#

Let h be the distance between the point x and the heli

wide ruin
#

stressing for this pre calc exam, i always study last minute like an idiot

haughty tundra
#

It is known dh/dt=20

#

let v be h's velocity

#

vx=20costheta

#

vy=20sintheta

#

Thus

#

hx = 20tcostheta

#

hy=20tsintheta

#

actually

#

nvm

#

The total distance from the observer to heli position on the x axis

#

is given by

#

100+(heli speed in x)*t right?

#

and the distance from the obs. to heli on the y axis is given by 0 + (helispeed in y)*t

#

right

#

?

#

@clever wind

clever wind
#

i just came back lst me look

haughty tundra
#

k

clever wind
# haughty tundra right

i guess right but arent we gonna turn back to the theorem to find the values again how can i do it without that

#

o wait

haughty tundra
#

wha tis the cosine theorem?

#

nvm

clever wind
#

cosine theorem is basically phytogoran thorem Expressed in terms of cosine

haughty tundra
#

ok

clever wind
#

if you use geometry we always have to use it in my question but

#

i am trying not to bacuse eacher said there is a way

haughty tundra
#

ok

clever wind
#

but whoever i ask doesnt matter if they are an other teacher they sah i cant I can't deal with this stuff u shouldnt too like what 💀

haughty tundra
#

I am not going to use this: c=a2+b2﹣2abcosγ

#

to solve it

#

is this what your teacher is talking about?

smoky path
haughty tundra
#

x cannot be 100?

smoky path
#

as @haughty tundra said v_x = 20cos(120) which means x shouldn't be constant?

haughty tundra
#

sorry

#

i meant

#

v_x is a variable

#

not v(x)

#

or x

#

or whatever

smoky path
#

v_x is the speed in the x direction right?

haughty tundra
#

x is defined as the distance from obs. to that point

clever wind
haughty tundra
#

in this situation

#

total x is smthn else

smoky path
haughty tundra
#

anyway

clever wind
clever wind
smoky path
#

oh is that what it means

#

gotcha

haughty tundra
#

It is known dh/dt=20
let v be h's velocity
vx=20costheta
vy=20sintheta
Thus
hx = 20tcostheta
hy=20tsintheta
actually
nvm
The total distance from the observer to heli position on the x axis
is given by
100+(heli speed in x)*t right?
and the distance from the obs. to heli on the y axis is given by 0 + (helispeed in y)*t
right
?

#

so

#

the positin in x

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lets call it

clever wind
#

yes, but yhthe hthing is i cant find numerical values without using geometry i guess

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o kay im listening

haughty tundra
#

the teacher said no geometry whatsover?

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or no cosine theorem specifically

clever wind
#

no but phytogoran and cosinus etc is not allowed

#

everything you can find similar woth cosine is forbidden

#

teacher said that you should think it like physics

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analyze with maths

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not geometry whatsoever

haughty tundra
#

so a^2+b^2=c^2 cannot be used?

clever wind
#

i guess it can i mean if we dont use that we cant use anything i suppose

haughty tundra
#

I'd like to see your teacher solve it without geometry

clever wind
#

me too lol

haughty tundra
#

Because the answer is expressed with pythagoren theorem

clever wind
#

i mean there is a geometry but we cannt use something with cosine similarly

haughty tundra
#

wdym

clever wind
#

yes but teacher wants us to find a deriative equation gives ius the change

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of the distancd

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we are going to use some geometry-like logic but explain it with deriatives

haughty tundra
#

ok

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it wanys the velocity?

#

from the obs.?

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thats easy

#

it already tells you

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actually nvm

clever wind
#

not exactly, becauseteacher doesnt wants relative velocity more like just the equation eith deriatives which gives us the change of distance between the h and the observer relates with time

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related*

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We need to define something like dx/dy but without cosine theorem

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maybe i can tag helpers idk it has been 30 minutes

haughty tundra
#

ok

clever wind
#

almost

clever wind
haughty tundra
#

Theyre gonna tell you the same thing

clever wind
#

i think so but

#

idk really

haughty tundra
#

Let's try to find the angle between the hypoteneuse and the ground at any time t

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the velocity will then be given by dh/dt*cos(that angle (t)

clever wind
#

Yep

haughty tundra
#

good luck

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solving a geometric problem

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without geometry

clever wind
#

Thank u lol i am thinking the problem is the teacher too

trim joltBOT
#

@clever wind Has your question been resolved?

smoky path
#

@clever wind did you find the answer?

trim joltBOT
#
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#
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wraith garden
#

Hello, I am a noob at math looking to improve my basics/foundations on math. Anyone have a order on what to learn?

I'm done with basic algebra
I have lots of trouble with variables on weird places

Complex functions trouble me also, and rational inversion??
I also have trouble with weird symbols....
And geometry (lots of formulas)

And many more, idk i suck

wraith garden
#

An example of levels I can't reach yet but supposed to be:

trim joltBOT
#

@wraith garden Has your question been resolved?

trim joltBOT
#

@wraith garden Has your question been resolved?

dapper swift
solid kilnBOT
dapper swift
#

it's useful to have a goal in mind to study all of this

#

I imagine you're at the precalc stage if I'm not wrong

wraith garden
wraith garden
dapper swift
wraith garden
dapper swift
#

yeah

wraith garden
#

philippines

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yes

dapper swift
#

ok ok

wraith garden
#

my subjects are gen math and pre cal

dapper swift
#

ahhhh I see

wraith garden
#

but my teacher said

#

u need to have basics first

#

so it will be easier

#

so i came here

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thats all for my story

dapper swift
#

Khan Academy has decent practice: it's useful for testing your understanding which is super important in maths

wraith garden
dapper swift
wraith garden
#

money

dapper swift
#

oh it's free

wraith garden
#

oh

wraith garden
dapper swift
#

Paul's Maths Notes is better but has fewer practice problems

#

this is much more standard

dapper swift
#

like after each test review all your mistakes and then study from that

#

there are a few big misconceptions people who aren't used to algebra have

#

can't find a complete list but these are some of them

wraith garden
dapper swift
#

a big thing is with operations, like 1/(x + y) is not 1/x + 1/y

#

e^(x + y) is not e^x + e^y

dapper swift
wraith garden
#

i also have problem with the e thing

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e has value of 2.71

#

something

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right

dapper swift
#

yeah

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you should start with the basics like this

#

if you want to understand the laws of indices

#

these are with whole numbers

#

and then move on to like fractions and later irrational numbers like e

wraith garden
#

i understand that

dapper swift
#

cool

#

you're not doing too badly then

wraith garden
#

how do i do with fractions

dapper swift
solid kilnBOT
dapper swift
#

(2/3)^4 = (2/3 * 2/3 * 2/3 * 2/3)

#

= (2^4/3^4) for example

wraith garden
#

maybe

#

all i know is u cant do something with the other exponent unless the "a" or "b" is equal

dapper swift
wraith garden
#

$9^x = 81$

solid kilnBOT
wraith garden
#

$9^x = 9^x$

solid kilnBOT
wraith garden
#

here we can say

#

x=x

dapper swift
#

yeppp

#

ahhh

wraith garden
#

because 9 and the other 9 is equal

dapper swift
#

yeah, so 9^x = 81 means 9^x = 9^2

#

so x = 2

dapper swift
#

that means it's always increasing

wraith garden
#

thats all i know

#

but

#

when it gets complicated than that

dapper swift
#

(one-to-one also can be always decreasing)

wraith garden
#

it gets harder

#

for example

dapper swift
wraith garden
#

yes

dapper swift
#

ok

wraith garden
#

for example

#

what if

#

$9^x=8$

solid kilnBOT
wraith garden
#

how do i find x

dapper swift
#

a logarithm undoes an exponential

wraith garden
#

log9 8 = x

dapper swift
#

yep

wraith garden
#

but how do i do it manually

dapper swift
#

ah so take log9 on both sides

wraith garden
#

without calculator

dapper swift
wraith garden
#

oh

#

how about when its quadratics

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is there something i skipped

dapper swift
#

yeah, you need to go back to your rules of indices

wraith garden
#

indices?

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whats that

dapper swift
#

exponents

wraith garden
#

there are only a few rules right

dapper swift
#

yeah

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there's also (a/b)^n = a^n / b^n which I mentioned earlier

#

so if we have like $4^x + 3 \cdot 2^x + 4 = 0$

solid kilnBOT
dapper swift
#

the first step would be to realise this is a quadratic

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the next step is $4^x = (2^2)^x = 2^{2x} = (2^x)^2$

#

(here we did 2 * x = x * 2)

solid kilnBOT
dapper swift
#

so we can substitute u = 2^x

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to get u^2 + 3u + 4 =0

wraith garden
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lol

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i understand none

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except for the fact

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$4x = 2^2x$

solid kilnBOT
wraith garden
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oof

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$4x = 2^(2x)$

solid kilnBOT
wraith garden
#

??

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its broken

dapper swift
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$2^{2x}$

solid kilnBOT
dapper swift
wraith garden
#

how do u add $4x = 2^2x$ if the other exponent 2^x has to multiply with 3

solid kilnBOT
#

Inuji
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

dapper swift
wraith garden
#

yes

dapper swift
#

yeah