#help-38
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im 99% sure i did each part right but im not sure if theres a different methodology for a lin equation?
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what does this Ce mean? does that say there is a constant value in the function of y inside exponent of e?
maybe C is constant and e is exponential
do you mean like they re multiplied?
ye
Is x*C and x+C same when you want to represent constants?
wait no it simply shouldn't
not generally, but
e^(2x² + 56x + C)
with some arbitrary constant C is equal to
e^(2x² + 56x) * e^C
and e^C is also an arbitrary constant, so we can just call it C
ah okay got it now
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can someone explaine how the function should look like? so far what i understand is that there is a function H in complex plane which is defined by y=(x+4)/(x+2). i dont understand where is the "i" in y= (x+4)/(x+2)
or is it the same?
no, apperently not, i inputed it in calculator, they are not the same
$Imz=\frac{Rez+4}{Rez+2}\text{, where: }z\in \mathbb{C}$
Joanna Angel
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but will it be correct if i subtract from both side im(z)
listen the H is not a function, it is a set located on complex plane, you can only draw it as a set,
hm
in other word, it is the set of complex numbers that follow the condtion i wrote above for you
and that is all what you can take it from
so it not possible to rewrite it in f(z) form yeah? i mean something like f(z) = z -2 +i
some notificaiot, artificial one is possible, bu t that doe snot change the meaning
i write such eventual form for oyu
$H=\left{ z\in \mathbb{C:}f\left( z \right)=0\wedge f\left( z \right)=Imz-\frac{Rez+4}{Rez+2} \right}$
but that is rather diffeerntr way of writng the same and definign the set H
maybe explain where did you find this set H ? mayeb it can help to understand why the set H appeard, but from waht you wrote, it is onyl a set, not a function
it was given
do you rememebr precise text ?
(...what's x here?)
Joanna Angel
so they gave me a function that is in complex plane f(z) = z+2 -i, and this set H, and they ask me to find f(H). So before you explained it to me that H is a set, i thought it is a function and to find was a function composition of foH
ah yes now all is clear)) but as you can see, the H is a set
and your task is =
to find the image of the set H via function f
what do you mean by image of the set H?
so its like the set, which i get after i plug the set H in f(z)? yes?
you can look at it in a such way: take, assume, few complex numbers belonging to the set H
if yo can do it
then take them
and put them into yoru funciton f
yes
yoru function f is a complex linear function
so
it works like
paralell shift
since it adss 2 - i
to every eleemnt from H set
do you know what this topic is called? i want to read it online, my class is in german and my teacher doesnt upload the script
do you understand it ?
and i couldnt find it in german
it can be shown in initial parts of algebra or
initial parts of analytical functions
also called comples analysis
tell me
what do you study ?
maybe it helps, to udnertsand why you need it
mein deutsch ist nicht zu viel aber ihc kann etwas helfen
oh, i dont study yet, its like school for foreigners, whose school leaving certificate is not acknoledged in germany
Bilder von Mengen mit komplexen Funktionen
oooo
klar ?
Komplexe Funktionen | geometrische Interpretation
thank you stranger danger 🙏
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i wouldnt say its necessary
there an easier way to go about it?
do actually know about limits
I see how he got -7 and 1 now
i dont think so
maybe in dif words idk
but when he factors it what happens to the x^2
why is that just gone
youre asking me about something i cant even see
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Which of the vectors does not belong to the subspace spanned by -2i + 3j + k and i + j + 2k:
a) -4i + 6j + 2k
b) 3i + 8j + 11k
c) 11i -4j + 6k
d) 10i -5j + 5k
What does "belong to" mean here?
What does spanned by mean here?
.... And what things do you know how to do with vectors?
Asking Sam
Oh, OK.
You try. I'm getting no response
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@quasi void Has your question been resolved?
So I think I need to put them in an augmented matrix like:
[-2 1 x
3 1 y
1 2 z ]
Right.
and then use gaussian reduction to solve it
and then if I get values for x1,x2,x3 it is within the span of the two vectors
my understanding was if one of the answer vectors is a linear combination of the other vectors then it is within the span
Well, what you want is to get two values and a zero.
You're solving for two variables, what you multiplied the first span vector by and what you multiplied the second span vector by.
So, you should have:```
[1 0 a]
[0 1 b]
[0 0 0]
Then you can check that a(-2i + 3j + k) + b(i + j + 2k) equals your vector.
and if I get it in that form that means the vector is within the span of the other two?
Yes, that's right.
You have the scalar multiples for each vector in the span, so you have a linear combination of those vectors.
And all linear combinations of the vectors are in the span.
OK.
For vector a) I get x1=2 and x2=0 and b) I get x1=1 and x2=5
OK, so check that those work.
2(-2i + 3j + k) + 0(i + j + 2k) = (-4i + 6j + 2k)
And so forth.
ah ok
Yes it works for both
OK, so far so good.
d) I get x1=-3 and x2=4 and then for c) i'm not getting values so I think c is not spanned within those two vectors
What do you get for the matrix after Gaussian reduction?
I get:
[ 1 0 0]
[0 1 0]
[0 0 1]
,w RREF[{{-2, 1, 10}, {3, 1, -5}, {1, 2, 5}}]
this is for C
Oh!
I got the same answer for D
,w RREF[{{-2, 1, 11}, {3, 1, -4}, {1, 2, 6}}]
that's so cool woah
That last row means that you have two vectors multiplied by 0 added together to get 0, but you're not getting 0.
So, that's impossible, so that must not be in the span.
Yes, that's right.
ah ok thank you so much! This has been very helpful and informative
If you get less nonzero rows than the number of vectors that are spanned, the spanned vectors are linearly dependent.
You're welcome.
You should never get a [0, 0, 0, k] where k isn't 0, though. That's the "it's not in the span" sign.
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what's the issue
what's the doubt
^
you got the answer as B, which, to me, seems to be correct, and you solved it by yourself, so what did you not understand
its right
the answer is B
well technically all options are wrong
but yeah your best match is B
But the correct answer according to the solutions is C
No the right answer is C
How tho
For example h=6 satisfies option B but isnt allowed in the problem
all the options are technically wrong
You can see |h-a| as the distance between h and a
6 1/2 is the "ideal" length for each hot dog, halfway between the min and max lengths allowed. The hot dogs are allowed to vary by up to 1/4
from that ideal length
yeah, my bad, I'm a bit dumb
The problem with this is that the absolute value being less than 1/2 doesn't mean the actual value is between 0 and 1/2, it would mean between -1/2 and 1/2
If you subtract 6 1/2 instead, you get x-6 1/2 between -1/4 and 1/4
which is exactly what it means to say its absolute value is less than 1/4
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Ahhh ok Thanks so much guys!
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please help me to prove this one
it was used the triangle inequality |a+b|<|a|+|b|
in general only <=
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Could someone please check if i got these questions correct ?
Also i have a problem for the IVT question
where when i used -2 and 2 i got two negatives
but when i used -3 and 3 i got one negative and positive
not sure what i am supposed to do there
and for 5 (iii) i got a minimum but also 0 = 0 so does that mean it doesnt have a max or a min when x = 0 ?
5(a) and (b)(iii)
@muted harbor Has your question been resolved?
@hazy light
Hey
Not sure i can hep you with all the questions but I'll do what i can
The first limit was done correctly
The second one, idk why you just said directly that it equals to
1
Ah OK you want help in these ones
So for 5 a), we know that the equation has at least one real root between x=-3 and x=3
The only thing I would think of, though I'm not sure it's the smartest approach, would be to get two other intervals that are outside of the interval [-3,3] in which IVT also lets us say there must exist some number c such that f(c)=0
@muted harbor
Can you please @ mention me if you text back
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so i did this problem
well not really problem lol
BUt how come
On desmos if i plug in that function the graph looks different from what is provided for me
Like -_
What is the problem
Yeah
Just know the characteristics of sine graph
zoom in the desmos graph (it will look the same)
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Ok, there's gonna be something elementary I'm just missing how do I evaluate: $\lim_{h\to0}\frac{a^{h}-1}{h}$ to be $\ln(a)$, I can't use l'Hôpital's nor can I use the exponent rule of derivatives
PajamaMamaLlama
for some reason all websites/resources I look at take this to be a given/trivial
I am really struggling to find anything that shows why this is the result without using the above two metioned
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how did they get the h
h=0.1686
Isn't h = c
c = a * e
And c = sqrt(a²-b²)
Or that better
ohhh okay
thanks for the help guys!
ima close this now for the next person 🫡
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Using cylindrical coordinates (R, ϕ, z), where R2 = x
2 + y
2
, find the volume of a hyperboloid R2 = z
2 + a
2 between z = 0 and z = b.
all the tvariables are squared not multiplied by 2
i got 2pib^3divided by three
but i swear it should depend on a
for R limits i got a to sqrt(b^2+a^2)
for z 0 to b
and phi from 0 to 2pi
but the answer sheet i have says 0 to sqrt(b^2+a^2) for R but i dont understand
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Is this statement true or false? for any M that belongs to the set of real numbers, 1/2 > M. I think its false.
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Hi, I've been on and off with this probelm for about a month now and am really stuck on it. I've tried using the fact that the area of the quadrilateral is between 0 and 1 (as shown), and stuff to do with the sum of 2 sides of a triangle being longer than the third side in all cases, but I got stuck with that too. Any suggestions on things I could try or inequalities related to geometry? Thanks!
It wasn't my first thought, but I got stuck and wanted to try different things
And say that the perimeter of the quadrilateral is between 0 and 4?
oh wait
i think i get you
gimme a sec
Is this what you were talking about?
Not sure how to form an inequality for that tho
I guess some can be factored as like (a - 1)^2 but ultimately interpreting the square terms to form an inequality in this geometric context is kinda unclear to me
I can find a logic for why that should be smaller than or equal to 4, but not a rigorous logic for why they should be greater than or equal to 2
ohh wait
@hazy olive Has your question been resolved?
I think that suffices as a proof, but I just wanna be sure
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I know what an indirect proof is, but I don't know where to go from there
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Q: graph the INVERSE of y-4=3^(x-2)
so would the inverse be: log_3(x-2) + 4?
idk how to convert exponential fxn's to log fxn's? can someone help me out please
!!
Let me see if I can give it a try.
So inverse functions are reverse engineering
where input becomes output and output becomes input.
got it.
Do you know the base change rule?
@wheat cypress Has your question been resolved?
ohhh okay, thank you
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how does one factor this? and in general, if ac and b dont factor nicely, what should i do? thanks
itll be messy

find the roots of the equation when it = 0, then rewrite it in (x-x1)(x-x2) form
the b squared b^2 -4ac etc thing?
this has irrational roots so theres no nice factorisation
yeah
$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
AℤØ
so i can set it equal to 0 and solve from there?
x^2 +10x +12 = 0 ?
if the problem doesnt specify u dont have to set it to 0
u would js leave it as (x-a)(x-b)
here ill send the whole problem
not sure how they want me to fill in this table when i would have to use the quadratic formula

oh, then this works like any other complete the square
only you get to put in radicals instead of nice whole numbers
wdym by radicals
the bottom right shouldnt be 12
the columns and rows should be x and 5
bottom right as 25
interesting
you add a value to correct it to 12 later
no
-13 somewhere

what number goes in front?
also its telling me that we didnt add -13 to not change the expression..
@fervent loom Has your question been resolved?
@fervent loom Has your question been resolved?
yes
Aight
Looking at the way they formatted the answer
We'll be completing the square
There is no specific a value
So we won't be needing that first value
Keep it at 1
The value after the (x+5)^2
Should be the value that makes it so that x^2+10x+25 (your squared x+5) is equivalent to x^2+10x+12
In this case it'd be...
@fervent loom
(12-25)
-13
Yayyy
This
This
This
:)
Yep
Yeah ik right
if there was something like a 3x^2 would a 3 go in place of it or something?
Kind of
You would put a 3 in front
But
You would also multiply the expanded values by 3 as well
So don't forget that
ah right
As an example, 3x^2+36x+19
Is the same thing as 3(x+3)^2-8
Oh wait shit mb
Change the values rq
hmm
so what waould be the process for figuring that out
taking 36 cubed or something
?
ohh
what if it doesnt factor nicely like 3x^2 + 35 
just put he square root in front i assume?
actually/
maybe you could do like..
If it doesn't factor nicely?
Well then
That's when we either factor normally
Or use the quadratic formula
oh right
Steps to factor quadratics
- Try using basic factoring into two basic factors
- Try completing the square
- Use the quadratic formula
Quadratic formula should be last method
completing the square as in what i did above?
Mhm
Glad I helped :)
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hi
need help with this
i know deriv is just slope
but its hard to tell slope in that graph
I got these so far
but I can't tell the rest
you can use decimals
kind of a bad question imo, it is a bit hard to estimate the gradient
just draw a linear line at the point and estimate the gradient of it
f’(2) looks like -1
so like what decimals would I use
so it said a and d were wrong
what should I put for those 2
nvm got it
put in 3/4 and -1.75
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this is a graph of the second derivative of a function where i am asked to find where it is concave up and concave down, i can see the intervals of concavity from the graph but how would i determine them mathetmatically?
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A car park attendant loses the name tags for a set of seven car keys, so hands out
the keys randomly when the seven owners return.
) How many ways are there of returning the keys so that nobody receives their
own keys? #
i got 7!-6! but i think im wrong
jan Nejon
why does my sigma look stunted
weird this is in past paper but we never covered dearrangements in class
thank you
How many ways are there of returning the keys so that at least two people
receive their own keys?
i got 5! for this or is it also derangments
@frozen plover
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As n grows, which would result in smaller values, log_2(n) or 2*log_3(n)? Why would that be the case?
use log rules to make those comparable
I’m not sure what u mean, i guess i could have log_2(n) compared to log_3(n^2)?
consider change of base law
Ah ok, so i would compare log_2(n) to 2*log_2(n) / log_2(3)? And here 2/log_2(3) gives about 1.26
So log_2(n) gives a smaller value
When compared to 2*log_3(n)
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hi
i'm doing this question
integral test might work because it's monotonically decreasing, but the integral i need to calculate has no answer in terms of standard elementary functions (and we haven't done integrals in analysis yet so i'm not expected to bound it in terms of another integral)
ratio test is looking terrifying
cauchy convergence criterion is looking terrifying
comparison test idk what to compare it with
i am very stuck on how to approach this
okay so i've made some very handwavey progress
$\forall x\geq 2: \frac{x^{-a}}{1+a^{-x}}\leq \frac{1}{1+a^{-x}} \therefore \int_0^\infty \frac{x^{-a}}{1+a^{-x}}\mathrm{d}x \leq \int_0^\infty \frac{1}{1+a^{-x}}\mathrm{d}x=\lim_{n\rightarrow\infty}\log(a)\log\Big(\frac{a^n+1}{a^2+1}\Big)$
george clooney real account
and clearly the limit at the end doesn't shoot off to infinity only in the case that $0<a\leq1$
george clooney real account
but proving those inequalities in my big step was done entirely by looking at the graphs on desmos
not at all rigorously, which is what this course expects
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<@&286206848099549185>
It's basic substitution
plug in n = 1
Ty
then n = 2
same method
Can u help me on 3d
kk
Ty
Is it 9
Can u do 3e or 3f then
might as well say do all xD
Oh alr
I still dotn understand srry
kk
My teacher never taught us this and expects us to learn on our own
Dayum
did you put it to 3 d.p?
YESSS
it worked?
5.906?
Didjt wlro
Work
Rip
Ite not event hats it's so hard to put in calculator
Cna ut ry it for me
kk
Is substitution this minus sighn
I just plug in n from until a number
it's like saying
x + y = 1
y = 3
then you substitute it in
x + 3 = 1
x = -2
Can u dot his kn calcultor
@graceful river Has your question been resolved?
Ye
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Find the function for a secondary function, that crosses y-axis in 2 and only has one zero point 2
@mortal coyote Has your question been resolved?
<@&286206848099549185>
<@&268886789983436800> are you guys all nerds?
yes. Don't ping mods for memes
.close
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Anyone able to help me?
Oops
@wicked quartz Has your question been resolved?
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@wicked quartz Has your question been resolved?
whats the question even
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i couldnt find a way to do it without using the cosine theorem
i will be glad if i get help before 12 because i have an exam about this type of questions at 12 😬 stressing myself realy
@clever wind i’m in the same boat as u lmao, are u in pre calc
the class code is calculus 101 so you can say that i guess
ohhh
i have a quick question not sure if you’d know the answer
do u know what a period in a graph is?
if i see the graph maybe i can help
u mind if i dm u?
u can dm let me check if my dm's are open or not
idk if it’s against the rules to post stuff in ur help channel lmao
i domt know too
you can post i think
ohh ight
okay you can dm me
its not working i’ll just post it in here
so this is my graph, the period is 8 and idk what that means tbh. i don’t know how the period correlates to the graph
ughhh i need an answer i will take any ideas helpers
so,
perios is
period* is when something
finishes the action where they begin,
@clever wind DM me for a second
okay
so period is you can think like
yeah but how does the graph finish at 8? or is it just an approximation
period is how long it takes for one full wave to complete
it restarts at 26 pi/3
yes it also starts at 2pi/3
a time value or a number like time per lap while running etc. If you need to understand the logic,
Let h be the distance between the point x and the heli
stressing for this pre calc exam, i always study last minute like an idiot
It is known dh/dt=20
let v be h's velocity
vx=20costheta
vy=20sintheta
Thus
hx = 20tcostheta
hy=20tsintheta
actually
nvm
The total distance from the observer to heli position on the x axis
is given by
100+(heli speed in x)*t right?
and the distance from the obs. to heli on the y axis is given by 0 + (helispeed in y)*t
right
?
@clever wind
i just came back lst me look
k
i guess right but arent we gonna turn back to the theorem to find the values again how can i do it without that
o wait
cosine theorem is basically phytogoran thorem Expressed in terms of cosine
ok
if you use geometry we always have to use it in my question but
i am trying not to bacuse eacher said there is a way
ok
but whoever i ask doesnt matter if they are an other teacher they sah i cant I can't deal with this stuff u shouldnt too like what 💀
I am not going to use this: c=a2+b2﹣2abcosγ
to solve it
is this what your teacher is talking about?
how can x be constant 🤔
x cannot be 100?
as @haughty tundra said v_x = 20cos(120) which means x shouldn't be constant?
v_x is the speed in the x direction right?
x is defined as the distance from obs. to that point
it means that observer is not moving
yeah but the heli is?
anyway
Of course, the horizontal distance changes, only the distance of the observer to the starting point does not change.
yea
It is known dh/dt=20
let v be h's velocity
vx=20costheta
vy=20sintheta
Thus
hx = 20tcostheta
hy=20tsintheta
actually
nvm
The total distance from the observer to heli position on the x axis
is given by
100+(heli speed in x)*t right?
and the distance from the obs. to heli on the y axis is given by 0 + (helispeed in y)*t
right
?
so
the positin in x
lets call it
yes, but yhthe hthing is i cant find numerical values without using geometry i guess
o kay im listening
no but phytogoran and cosinus etc is not allowed
everything you can find similar woth cosine is forbidden
teacher said that you should think it like physics
analyze with maths
not geometry whatsoever
so a^2+b^2=c^2 cannot be used?
i guess it can i mean if we dont use that we cant use anything i suppose
I'd like to see your teacher solve it without geometry
me too lol
Because the answer is expressed with pythagoren theorem
i mean there is a geometry but we cannt use something with cosine similarly
wdym
yes but teacher wants us to find a deriative equation gives ius the change
of the distancd
we are going to use some geometry-like logic but explain it with deriatives
ok
it wanys the velocity?
from the obs.?
thats easy
it already tells you
actually nvm
not exactly, becauseteacher doesnt wants relative velocity more like just the equation eith deriatives which gives us the change of distance between the h and the observer relates with time
related*
We need to define something like dx/dy but without cosine theorem
maybe i can tag helpers idk it has been 30 minutes
ok
almost
<@&286206848099549185>
Theyre gonna tell you the same thing
Let's try to find the angle between the hypoteneuse and the ground at any time t
the velocity will then be given by dh/dt*cos(that angle (t)
Yep
Thank u lol i am thinking the problem is the teacher too
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Hello, I am a noob at math looking to improve my basics/foundations on math. Anyone have a order on what to learn?
I'm done with basic algebra
I have lots of trouble with variables on weird places
Complex functions trouble me also, and rational inversion??
I also have trouble with weird symbols....
And geometry (lots of formulas)
And many more, idk i suck
An example of levels I can't reach yet but supposed to be:
@wraith garden Has your question been resolved?
@wraith garden Has your question been resolved?
$|x| \le c$ means $-c \le x \le c$
south
just curious, what makes you want to improve your maths foundations?
it's useful to have a goal in mind to study all of this
I imagine you're at the precalc stage if I'm not wrong
I want to improve because we are learning so much more complex stuff that requires to need basic stuff first, but i seem to have forgotten.\
Yes, but my foundations suck
like are you still in high school or at uni?
is senior high school counted
yeah
ok ok
my subjects are gen math and pre cal
ahhhh I see
but my teacher said
u need to have basics first
so it will be easier
so i came here
thats all for my story
Khan Academy has decent practice: it's useful for testing your understanding which is super important in maths
i dont have miney
what?
money
oh it's free
oh
what courses should i take other than that
Paul's Maths Notes is better but has fewer practice problems
this is much more standard
basically listen to your teacher's feedback
like after each test review all your mistakes and then study from that
there are a few big misconceptions people who aren't used to algebra have
can't find a complete list but these are some of them
my teacher kinda sucks
a big thing is with operations, like 1/(x + y) is not 1/x + 1/y
e^(x + y) is not e^x + e^y
that really sucks
yeah
you should start with the basics like this
if you want to understand the laws of indices
these are with whole numbers
and then move on to like fractions and later irrational numbers like e
i understand that
how do i do with fractions
so like $(a/b)^n = \frac{a^n}{b^n}$
south
maybe
all i know is u cant do something with the other exponent unless the "a" or "b" is equal
could you give an example of this?
$9^x = 81$
Inuji
$9^x = 9^x$
Inuji
because 9 and the other 9 is equal
you can do that cause 9^x is one-to-one
that means it's always increasing
(one-to-one also can be always decreasing)
yeah, like with quadratics right
yes
ok
Inuji
how do i find x
you need logarithms
a logarithm undoes an exponential
log9 8 = x
yep
but how do i do it manually
ah so take log9 on both sides
without calculator
you can't find it without a calculator
yeah, you need to go back to your rules of indices
there are only a few rules right
yeah
there's also (a/b)^n = a^n / b^n which I mentioned earlier
so if we have like $4^x + 3 \cdot 2^x + 4 = 0$
south
the first step would be to realise this is a quadratic
the next step is $4^x = (2^2)^x = 2^{2x} = (2^x)^2$
(here we did 2 * x = x * 2)
south
Inuji
Inuji
$2^{2x}$
south
which part don't you understand?
how do u add $4x = 2^2x$ if the other exponent 2^x has to multiply with 3
Inuji
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
so 4^x = (2^x)^2 right
yes
yeah


