help-38

[trim jolt]

@echo jasper Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim knot]

(ln(x))^2 = ln(x^2) y/n?

[stoic iron]

no

[vagrant prism]

no

i was like ``wdym $\frac{y}{n}$'' lol

[solid kiln]

artemetra

[vagrant prism]

😭

[whole coral]

Only exceptions are x=1 and x=e^2

[trim jolt]

@slim knot Has your question been resolved?

[slim knot]

alr thanks

.close

[trim jolt]

Channel closed

Closed by @slim knot

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[somber spire]

where did the 7 come from

[orchid wagon]

b?

if b, x=7 is the location on the graph where it reaches maximum y

by subtituting x=7 to the function, we can find maximum y, which is the max height for the rocket

[trim jolt]

@somber spire Has your question been resolved?

[somber spire]

it says l x = 7

let*

there's no 7 in the question

[trim jolt]

@somber spire Has your question been resolved?

[somber spire]

<@&286206848099549185>

[trim jolt]

@somber spire Has your question been resolved?

Channel closed

Closed by @somber spire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[green oak]

Need stats help

[green oak]

Would this be e^(-4) ?

[zinc ginkgo]

!show

[trim jolt]

Show your work, and if possible, explain where you are stuck.

[green oak]

nvm, I think I got it, thx.

.close

[trim jolt]

Channel closed

Closed by @green oak

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny vessel]

Not sure what the bounds are for this problem

[thorny vessel]

Seems like I might need to convert to polar

[trim jolt]

@thorny vessel Has your question been resolved?

[trim jolt]

@thorny vessel Has your question been resolved?

[trim jolt]

@thorny vessel Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sly trench]

what formula did we apply for it to be sqrt of the integrand

[sly trench]

In here

why is it square root

[ionic pendant]

the integrand is y = √x already

[sly trench]

ye

so?

[ionic pendant]

the other square root is the arc length

[sly trench]

what about this

why do we do the arc length

[ionic pendant]

surface area of a revolved surface = circumference × arc length

[sly trench]

i dont get it

[ionic pendant]

that's for volume, not surface area

[sly trench]

oh

ok so for all surfaces areas

i have to use that formula

this

[ionic pendant]

yes

[sly trench]

alr ill keep that in mind

ty

.close

[trim jolt]

Channel closed

Closed by @sly trench

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[merry rose]

need help with a composite function question, i do know how to get the answer but like i’m extremely confused on why its solved like this. so since we do (f) for (h) shouldn’t it be x^2/x^2-1 instead

[nimble stone]

youre describing h o f

(h o f)(x)= h ( f(x) )

(f o h)(x)= f ( h(x) )

in the first, you input f(x) into h

in the second you do the opposite

[merry rose]

yea, but shouldnt my outcome be the the squared one

because like, im combining the f to the h

wait

[nimble stone]

im not entirely sure what you mean

[merry rose]

like listen if im solving for f of h; f[h(x/x-1) right. so if we then want to link the f with the h, both the numerator and the denominator should be x^2/x^2-1 rather than all of it being powered 2, but how is it coming to that outcome instead

do you understand me or do i sound silly

[nimble stone]

(x-1)^2 isnt x^2-1

[merry rose]

i messed up the equation

hold on

[nimble stone]

f(x)=x^2 right?

[merry rose]

yes

[nimble stone]

and h(x)=x/(x-1)

[merry rose]

yes

[nimble stone]

if i sub h into f

[merry rose]

yes

[nimble stone]

then i get (h(x))^2

because f(x)=x^2

f(h(x))=(h(x))^2

[merry rose]

hold on

so we do the x^2 for the h of f

only

and like

(x/x-1)^2 for f to h

but how is that like this for f to h? 😭

[nimble stone]

f of h

f(h(x))= f( x/(x-1)) = (x/(x-1))^2

because f(x)=x^2

[merry rose]

yes

[nimble stone]

if you do h(f(x)) then you sub x^2 into h

which is why you get x^2/(x^2-1)

[merry rose]

i understand it

alralr

so since f is being substituted into the x/x-1 we do (x/x-1)^2, for h of f we substitute the h instead to X^2s

does this make sense

[nimble stone]

i dont really like the word link

its more of a substitution than anything else

[merry rose]

my bad, i will fix it real quick

i do understand your point now tho, i think i was just too dumb to think

[nimble stone]

since its f o h, and f(x)=x^2, we do (h(x))^2=(x/(x-1))^2
for h o f we substitute f into h instead

[nimble stone]

what youve written here now is the reverse of what you meant to say

[merry rose]

yea

[merry rose]

i did the answer on paper, i think i just messed up my phrasing 😭

but i get it

[nimble stone]

👍

[merry rose]

thats it, thank you

.close

[trim jolt]

Channel closed

Closed by @merry rose

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stoic iron]

How did your 2 become 2²?

[daring hawk]

i need the same number at the bottom right so i did 2^2 since that is 4

[stoic iron]

But just changing 2 to 2² and changing nothing else is going to change the overall number

[daring hawk]

.close

[trim jolt]

Channel closed

Closed by @daring hawk

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jovial eagle]

Pls help to find answers.

Statements: 
All allrounders are batsmen. 
All batsmen are cricketers.

Conclusion:

1. All cricketers are batsmen.
2. All batsmen are allrounders.
3. Some batsmen are allrounders.
4. Some cricketers are batsmen.
5. All alrounders are cricketers.
6. Some allrounders are cricketers.

[pine wave]

what do u think

lets start with 1.

[jovial eagle]

1. True/false
2. T/false
3. T.
4. T
   5 T
   6 T

[pine wave]

start with 1

what do u think

[jovial eagle]

I think it may be true or false but mostly true

[pine wave]

its a binary

True or False and give ur reasoning

[jovial eagle]

I think if cricketers are batsman then also batsman are cricketers. But i am confusing maybe

[pine wave]

∀x P(x) -> Q(x)

does that mean

∀x Q(x) -> P(x)

[jovial eagle]

I think no

[pine wave]

explain

[jovial eagle]

Actually not always

Am i true

[pine wave]

okay so if I tell you that ∀ is non commutative, whats the answer to my question

[pine wave]

Im not just gonna give u the answer, u gotta work it out

All cats are animals

does that imply

all animals are cats

[jovial eagle]

No

[pine wave]

yes exactly

[jovial eagle]

Yes i got know

Is it means first one false

[pine wave]

Statements:
All allrounders are batsmen.
All batsmen are cricketers.

let P(x) be x is a allrounder
Q(x) be x is a batsmen
R(x) be x is a cricketer

Then we can write the statements as:

∀x P(x) -> Q(x)
∀x Q(x) -> R(x)

Question 1 is asking:

does this imply that

∀x R(x) -> Q(x)

which we know is false

okay now u try question 2

[jovial eagle]

Okay

Same

No

It's same as cat as animal)

But animal is not cat

[pine wave]

yes

[jovial eagle]

In this case third one true?

[jovial eagle]

And 4. Also true

[trim jolt]

@jovial eagle Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cunning aspen]

In parallelogram MATH, find the values of x and y and the measures of all the angles if
m∠M = 4x+5y+3, m∠A=5x+12y-7, and m∠T=10x-5y-13.

[tepid hamlet]

what do you know about parallelograms and relationships of their angles?

[cunning aspen]

<m+<a=180 and then <A+<T=180 and <m=<t

BUT i keep getting fractions

and decimals

[tepid hamlet]

yes so you used 4x+5y+3 = 10x-5y-13 ?

[cunning aspen]

yeag

yeah

it would simplify to 10y+16=6x

right?

[tepid hamlet]

yeah

[cunning aspen]

and then i did <m+<a=180

4x+5y+3+5x+12y-7=180

9x-17y=184

[tepid hamlet]

yeah

you mean +17y?

though?

[cunning aspen]

wait

oops

[tepid hamlet]

so 9x + 17y = 184

[cunning aspen]

made this into x=10/6y+16/6

and plugged it in

[tepid hamlet]

yeah the numbers are kinda ugly, we should be able to solve from 2 equations, but lets just get a 3rd equation and see if we can combine them to something nicer maybe

for angle A + angle T = 180

that ones 5x+12y-7+10x-5y-13 = 180
15x-7y=200

so we have
-6x+10y-16
9x+17y=184
15x-7y=200

make sure im not making mistakes copying those 😅

ok im gonna change 2nd one to negative by multiplying everything by -1

[cunning aspen]

-6x+10y-16?

[tepid hamlet]

-6x+10y-16
-9x-17y=-184
15x-7y=200

[cunning aspen]

OH

[tepid hamlet]

sorry, i rewrote 10y+16=6x so it just looks like the others

[cunning aspen]

okay

[tepid hamlet]

and now i multiplied 2nd one by -1, following?

[cunning aspen]

i think we can divide the first one by 2

so its easier

[tepid hamlet]

well

what im trying to do is see how we have -6x -9x and 15x? if we add them all together the x's will disappear

[cunning aspen]

ohh

[tepid hamlet]

so now basically add up all the left sides and all the right sides let's see what we get

(-6x-9x+15x) + (10y-17y-7y)=-16-184+200

0x - 14y = 0 hm lol

[cunning aspen]

man

i got Y=80 when i did it on my own LOL

but got y as a decimal

x

[tepid hamlet]

let's see if there really is a solution with y = 0 or maybe im just doing something dumb

[tepid hamlet]

so then M = 4x + 3, A = 5x - 7, T = 10x - 13

4x + 3 + 10x - 13 = 180

14x - 10 = 180

x = 190 / 14 ?

[cunning aspen]

decimal

13.57142857142857

[tepid hamlet]

nah that is a nonsense answer, i must have made a mistake

the angles dont end up adding to 180 or anything

[cunning aspen]

o

WAIT

i figured it out i think?

[tepid hamlet]

so y = 80 worked?

[cunning aspen]

y=5

oops

messed up

[tepid hamlet]

lol

close

[cunning aspen]

because i accidentally put -17

[tepid hamlet]

and x = ?

[cunning aspen]

instead of +17

so i messed it up

finding out rn

x=11

i think i just lost braincells from that question 😭

ty for the help

.close

[trim jolt]

Channel closed

Closed by @cunning aspen

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusk summit]

is everything correct here?

[dusk summit]

<@&286206848099549185>

[blissful bison]

it is trivial and y = 3 is a horizontal asymptote, but you have to find secodn oen too

a vertcial one

x = 9, you wrote so ok

[dusk summit]

did i not write that?

it's x = 9

[blissful bison]

i did not see at once )

[dusk summit]

oh ok

[blissful bison]

but i wud comoptue limits in 9 but mayeb you do not need to do it

that depends on yoru insrtuctor

[dusk summit]

wym?

[blissful bison]

let me write it , as an additonal exopalanation

if you have suich fucntion liek you a raiotnal fucntion, then you identify th edomain

adn yoru domain is

all real set withotu {9 }

since x = 9 is a restriced value

of yoru fucntion

adnnow

to professioanklykl

invesituagte that it is vertical asymtptooe

[dusk summit]

maybe speak english?

i can't understand u bro

[blissful bison]

soryr i am in rush )

moment

[dusk summit]

but

i dont think they want a lot its only algebra 2

[blissful bison]

you need to calculate the limits of the function at the point x = 9 on the left and right sides

yes ok i am teling you this how i demand frm my students at uni

but yoru solutin is correct

[dusk summit]

how would i do that

[blissful bison]

have you ever seen term limits ? limes ? it is written like lim f(x) = ..

?

[dusk summit]

is my end behavior correct?

like the 3

[blissful bison]

yes, but you did it infornally

[dusk summit]

i think

[blissful bison]

you were not using this term explicite

give me 5 minutes and i make a PDF for you i paste it here, you wil see if you liek ofc

[dusk summit]

okay

[blissful bison]

ok

that is typical justificaitn that is needed if you have Calculus

[knotty locust]

!nosols

[trim jolt]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[knotty locust]

.close

[trim jolt]

Channel closed

Closed by @knotty locust

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel vortex]

How to solve

[trim jolt]

@novel vortex Has your question been resolved?

[shrewd knot]

from what i can see it's about finding the third angle given the two other angles in a triangle

the sum of the angles of a triangles is equal to 180 degress

this ^

use this fact and solve it

the places where they have a box to depict the angle, they are saying it's 90 degrees

So for the first triangle you have:

$63^\circ+90^\circ+\text{something}=180^\circ$

[solid kiln]

Ab

[shrewd knot]

find this "something"

and do the same kind of thing for the other triangles

--

it's hard to understand how much you understood the problem, if you don't respond @novel vortex

[novel vortex]

So is it really i have to find any number on the missing side that makes 180?

[shrewd knot]

yeah

[novel vortex]

What would be the equation

[shrewd knot]

this one

as for why it's 180 degrees, people just decided it is from the olden days. it comes from the deciding a "half-circle" is 180 degrees.

too large image*

but you get the point i think

[novel vortex]

Oh ok i get it now

[shrewd knot]

the half-circle triangle stuff comes this figure, if you are curious

(not proving it, but showing you in case you are curious)

[novel vortex]

On the top where it say c= is that when i put the number that makes 180 there?

[shrewd knot]

yeah

your two other angles can be A and B

[novel vortex]

Oh ok i get it now

[shrewd knot]

and the missing angle is C

and the sum of those add up to 180

you can also look it as

$C=180-A-B$

[solid kiln]

Ab

[shrewd knot]

where C is your missing angle

think of how

180 = A + B + C

so if you subtract A and B from 180

you get C

[novel vortex]

Do i need to do extra steps after i find the missing side number?

Oh ok

[shrewd knot]

for these* problems*, i think just calculating and filling in the answer, which is the missing angle, is enough

[novel vortex]

So i can do that instead of finding a random #?

[shrewd knot]

let's say this like this

take any triangle

and if you add up it's angles

that is if it's angles are A, B, and C

then the sum of it's angles is 180

so A+B+C=180

so

for this triangle you have

$63+90+\text{something}=180$

[solid kiln]

Ab

[shrewd knot]

you can find this "something" by subtracting 63 and 90 from 180, so

$\text{something}=180-63-90$

[solid kiln]

Ab

[shrewd knot]

so <C = 27, since 180-63-90 = 27

sorry if i am too abstract haha

tell me if you have any questions. anything that makes you confused

[shrewd knot]

and i am not quite sure what you meant here

if my new explanation helped clear up any confusion, then great. if not then ask again : )

[novel vortex]

When i have angles a and b can i subtract them and thats when i would i find angle c ?

[shrewd knot]

yeah

[novel vortex]

Could i do that if there was any missing angle.

Just making sure 😃

[shrewd knot]

sorry did not see. yeah, if it's a triangle.

[trim jolt]

@novel vortex Has your question been resolved?

Channel closed

Closed by @novel vortex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trim kestrel]

does anyone know which rule this is?

[stark bison]

Looks like an application of the definition of a logarithm

[maiden hare]

Taking 3^x on both sides, except they also swapped the sides

[trim jolt]

@trim kestrel Has your question been resolved?

Channel closed

Closed by @trim kestrel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[digital storm]

If so how do you break up a 7? Just 1 and 7?

[digital storm]

What is thr first step of solving this? Do I need to break up the radians?

[trim jolt]

@digital storm Has your question been resolved?

Channel closed

Closed by @digital storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[edgy cedar]

[thorny stirrup]

this aint really a homework help q

[trim jolt]

Channel closed

Closed by @flat carbon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ebon raven]

https://tenor.com/view/wtf-confused-look-gif-24835232

[ebon raven]

.close

[trim jolt]

Channel closed

Closed by @ebon raven

Use .reopen if this was a mistake.

[edgy cedar]

Your getting banned Chris

[ebon raven]

i failed my physics test

it's unfortunate

[edgy cedar]

Inappropriate use of help channel

[ebon raven]

ok

[edgy cedar]

There’s always next time

[ebon raven]

[edgy cedar]

Where ull fail again

🙏

[ebon raven]

ty

[edgy cedar]

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal lily]

help me plz

[trim jolt]

Please don't occupy multiple help channels.

[formal lily]

.close

[trim jolt]

Channel closed

Closed by @formal lily

Use .reopen if this was a mistake.

[ebon raven]

bruh

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant pike]

how am i supposed to know what the stable solution is? what should i be doing?

[shrewd knot]

a stable solution is probably a decimal number whose digits does not change to 4 places.

you can perform newtons method again, but it only changes the next digit (so the 5th? place change)

if any more iterations of newtons method does not change the first four places, then you found the stable solution

i would guess

(since i am not 100% sure)

[buoyant pike]

so stable means the next iteration will give the same decimal values up to the specified point?

cause my issue rn is idk when to stop

[shrewd knot]

yeah. i think so

well do it until it does not change the 4th place

[buoyant pike]

alr i tried just putting in the x2 value, that didnt work

[shrewd knot]

(not sure what it means by place. not a native speaker, but i think you get it)

[buoyant pike]

guess it wants me to iterate on my own until i find that stable answer?

[shrewd knot]

perhaps it's the x3 value

but you can try on paper to test

[buoyant pike]

yeah im gonna try doing that

[shrewd knot]

also check if you are doing newtons method correctly

[buoyant pike]

right

i think i am doing it correctly because it says my first two iterations are correct

[shrewd knot]

but you do seem to have the correct x1 and x2

yea

[buoyant pike]

so ive been trying for a while

but it seems like the value just keeps going down rather than stabilizing anywhere

[shrewd knot]

so i cheated a bit haha

[buoyant pike]

lol

[shrewd knot]

perhaps try 0.2

as your guess

and see if it stabilizes

[buoyant pike]

sure

didnt work

it does say that i need 4 decimal places

[shrewd knot]

(in theory, since there are no weird *bumps, it should go towards 0.185) hmmm

[buoyant pike]

so i guess ill keep iterating until i get closer to that value

yeah i got it

[shrewd knot]

i will try writing some code to use the initial value they told. the code should be possible to do in maple too, if you have that.

[buoyant pike]

it stabalized around that point

[shrewd knot]

since i am kinda curious

(after like 20* iterations)

[buoyant pike]

yeah thats the thing

[shrewd knot]

100 is prob too much

haha

but 20

i bet

[buoyant pike]

it was only this fast thanks to the desmos calculator

[buoyant pike]

yeah about there

[shrewd knot]

the thing is it's what newtons method approximates

it approximates the point where the function cuts the x-axis

i think desmos kind of does it implicitly or something similar.

[buoyant pike]

oh i see

[shrewd knot]

(the program has to do it in some way, haha. it's not magic)

anyways i will take a little moment to write the code

[buoyant pike]

good luck, im going to keep moving forward with my questions

let me know if you find something interesting

[shrewd knot]

so this is python code

but you need around 11 or 12 iterations

haha

after 12 it says: 0.1845

so around 0.185

[shrewd knot]

good luck with them

: )

and the python code above, you can do software similar to maple, if your school provides it. maybe there is a newton approximation function buitlin in the software.

i just did it in python since i did not have maple installed

[trim jolt]

@buoyant pike Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tough silo]

hi can someone explain why my method is wrong

[tough silo]

the red ink is a comment

the answer is the same but my process is apparently wrong

[maiden hare]

,w cot(pi-(3pi)/14)

[tough silo]

here is the correct process

[solid kiln]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nelfeal

[maiden hare]

I mean you're correct, I'm not sure what the comment is trying to say

Maybe you just took a detour

[tough silo]

😭

Sadge

all i did was change it to first quadrant

my teacher doesnt like anything to be different from how she does it

rip

tysm

.close

[trim jolt]

Channel closed

Closed by @tough silo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sour field]

Hi. I got this drawing for the question but don’t know where to start off. Here’s the question:

ABC is a right triangle, ∡C = 90◦. D is the midpoint of BC. Prove the ∡DAB can not be measured 30◦.

[sour field]

<@&286206848099549185>

[trim jolt]

@sour field Has your question been resolved?

Channel closed

Closed by @sour field

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[hollow niche]

I'm using this stats table page 3

https://www.ocr.org.uk/Images/174103-unit-h869-02-statistical-problem-solving-statistical-tables-st1-.pdf

i keep typeing the question but it keeps getting deleted, why?

[mystic veldt]

can u share a ss rather than this link

[hollow niche]

sure

one sec

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid heart]

you can row reduce and see what sequence of operations you to get to take you all the way to something like an elementary matrix

The only thing Mat3(Z/3Z) matters for here is to remember what operations are valid, and just to continuously take things mod 3

Since it Mat3(Z/3Z) it is also useful to note the inverse of 2 is 3 (and vice versa)

wait sorry

ignore that "useful note" lmao

but yes just be careful with your operations

Okay let's try one step

Let's take -2 times the first row and add it to second row

the second row becomes 0 1 -2 right?

which you can write as 0 1 1

Probably should be 1 1 in the second row? or how do you have -1 in the last entry in the second row?

But that looks good so far!

now take -2 times the second row and add it to the last row

Im not completely following how the -2 is in the second row still but barring all that

So the only thing you have to be careful about is you said multiuplied by 0.5

there's no element 0.5 in Z/3Z!

but a quick shows that 2 is its own (multiplicative) inverse!

Same thing basically

cause 2*2 = 4 = 1 mod 3

it does the same thing like your matrix is correct, just you have to keep track of every single row operation you do! and so the operation where you said "multiuply by 0.5" you actually mean multiply by 2

I'm not fully following some of your steps but I'm only here to give you the idea. Once you reduce it to something in triangular form with 1's down the diagonal, then just think about how that comes from row operations that are adding one row to the other

and then that gives you a full sequence of elementary row operations (so elementary matrices) that takes you the idenitty

ah okay, also note that that every time you see -2 or whatever you need to change it back to 1

and its better that you do it sooner

so for example

if you had 0 1 1 in Z2 earlier

anyway

Your final matrix looks right so far

definitely the next thing tod o but it's kind of not useful to have changed Z2 to 2Z2 because you're going to have to change it back to just Z2 again later since you want 1s down the diagonal and end up at the identity

you need more than that

you want to write the matrix as a product of elementary matrices

more than that too

you need to take it all the way to the identity

cause than basically you've shown

A = E1E2E3E4E5.... I

where each of the E a row operation you've done

so then you've shown A as a product of elementary matrices

yeah so you can keep going. It's clear you know how to row reduce, so the final answer basically looks like this

Suppose you started with A

and you did E1 then E2, i.e. E1 is the elementary matrix associated to the first row operation you did, and then E2 is the elementary matrix associated to the second row operation you did

all teh way to En to get to the identity

and you know all of E1 through En because yoy're tracking your operations obviously

Then you get

$A = E_n^{-1} E_{n-1}^{-1}...E_2^{-1}E_1^{-1}$

Yes

[solid kiln]

OssihLikesBlue

[limpid heart]

Because basically you've shown that

$E_nE_{n-1}...E_2E_1 A = I$

[solid kiln]

OssihLikesBlue

[limpid heart]

If you've seen LU factorization and kind of know the theory behind why the LU factorization works, its a similar idea

if you don't know it dw about it

but I'm just explaining why you go all the way to the identity

and then how to express A as a product of elementary matrices

that's all you need

Yup!

It's a bit of work I admit

If you wanta nother example - here's it worked out for a different matrix 2x2

https://math.stackexchange.com/questions/2157090/write-the-given-matrix-as-a-product-of-elementary-matrices

it's not over Z/3Z but that doesn't matter too much

Yeah I thought maybe

which is why I sent that link

so you can explicitly see a worked out example (over R)

No worries! here's an example for a 3x3 matrix https://math.stackexchange.com/questions/677556/express-the-following-invertible-matrix-a-as-a-product-of-elementary-matrices

[trim jolt]

@fiery schooner Has your question been resolved?

[trim jolt]

@fiery schooner Has your question been resolved?

Channel closed

Closed by @fiery schooner

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dry canopy]

Not certain if I did the infinity subbing correctly but also don’t know what to do with the infinity symbols in the gamma function or how to progress the proof from here

[trim jolt]

@dry canopy Has your question been resolved?

[dry canopy]

<@&286206848099549185>

[dry canopy]

<@&286206848099549185>

[zinc ginkgo]

you should probably be using stirling's formulas for both gamma

[zinc ginkgo]

https://www-users.cse.umn.edu/~garrett/m/mfms/notes_2013-14/02d_asymptotics_of_integrals.pdf

[dry canopy]

is what i did with the other stuff ok as well or should 1/ sqrt(pi) have turned into 0 as well?

[zinc ginkgo]

no idea what you did

[dry canopy]

(1+t^2/infinity) ^-infinty+1 /2 became 1

and for 1/square root (piinfinity) i got rid of the 1/pi cause it turns 0

[zinc ginkgo]

yea that's all wrong

[dry canopy]

how

dont things become 0 when u divide by infinity?

[zinc ginkgo]

you have to be more careful

also what's t^2

[dry canopy]

probably t value

[zinc ginkgo]

where is there a t here?

[dry canopy]

that's not the formula i was using yet

[zinc ginkgo]

[dry canopy]

it's forumla for the density of t distribution function

[zinc ginkgo]

that's like the main thing in your screenshot

what is your actual question

[dry canopy]

here

click it

no

it says

to prove the density function of t distribution converges....

so i think the formula given

[zinc ginkgo]

oh

[dry canopy]

is supposed to help me in some form to get the t distribution function to look like the n(o,1)

[zinc ginkgo]

next time upload one at a time

[dry canopy]

standard normal distribution

i am suspection i need to get

[zinc ginkgo]

this entire step is wrong

,tex .limit rules

[solid kiln]

riemann

[zinc ginkgo]

you have to use product and quotient rule more carefully

use binomial theorem or taylor expansion on that

[dry canopy]

I do have to go for a few hours and I know this will automatically close.
Thanks for ur help so far
I'll check out ur tips @zinc ginkgo

[blissful bison]

$\lim_{v \to \infty } \frac{\Gamma\left( \frac{v+1}{2} \right)}{\sqrt{\pi}\sqrt{v}\Gamma\left( \frac{v}{2} \right)}\left( 1+\frac{t^{2}}{v} \right)^{-\frac{v+1}{2}}= \text{let }x=\frac{v}{2}\text{ then we get that: } \frac{1}{\sqrt{\pi}}\lim_{x \to \infty }\frac{\Gamma\left( x+\frac{1}{2} \right)}{v^{\frac{1}{2}-0}\Gamma\left( x \right)}\left( 1+\frac{t^{2}}{2x} \right)^{-x-\frac{1}{2}}=\frac{1}{\sqrt{\pi}}\cdot 1\cdot \lim_{x \to \infty }\left( 1+\frac{1}{\frac{2x}{t^{2}}} \right)^{\frac{2x}{t^{2}}\cdot \frac{t^{2}}{2x}\cdot \left( -x-\frac{1}{2} \right)}=$

[solid kiln]

Joanna Angel

[blissful bison]

$\frac{1}{\sqrt{\pi}}\cdot 1\cdot \lim_{x \to \infty }\left( 1+\frac{1}{\frac{2x}{t^{2}}} \right)^{\frac{2x}{t^{2}}\cdot \frac{t^{2}}{2x}\cdot \left( -x-\frac{1}{2} \right)}=$

[solid kiln]

Joanna Angel

[blissful bison]

$\frac{1}{\sqrt{\pi}}exp\left[\lim_{x \to \infty }\frac{t^{2}\left( -x-\frac{1}2{} \right)}{2x} \right]=\frac{1}{\sqrt{\pi}}exp\left( -\frac{t^{2}}2{} \right)$

[solid kiln]

Joanna Angel

[blissful bison]

$\text{ and that is the density of N(0,1))}$

[solid kiln]

Joanna Angel

[trim jolt]

@dry canopy Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland fox]

Can someone explain 4

[edgy cedar]

just binomial and compare coefficients

[boreal thorn]

多项式系数可以用组合数来计算

[trim jolt]

@inland fox Has your question been resolved?

[inland fox]

How did they get the N

[trim jolt]

@inland fox Has your question been resolved?

[zinc ginkgo]

Equating coefficients of the polynomial expansion

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tribal fractal]

how do you solve equations like these? x(y−28) = 5y−59

[tribal fractal]

is this a diophantine equation?

[merry bluff]

You have to factor it

something like this $$ab - a - b + 1 = (a - 1)(b - 1)$$

[solid kiln]

Jelle

[merry bluff]

yeah

[tribal fractal]

and what do i do after i factor

[merry bluff]

What do you have after factoring?

You are supposed to have a single number on the other side of the equation and use its divisors to find the solutions

[cyan zinc]

xy - 28x - 5y + 59 = 0

(ax + b)(cy + d) = xy - 28x - 5y + bd

ac = 1, a = c = 1

ad = -28, bc = -5

d = -28, b = -5

(x-5)(y-28) - 140 = -59

(x-5)(y-28) = 81

[merry bluff]

It should be xy - 28x - 5y + 59 = 0

[cyan zinc]

better?

[merry bluff]

yeah sure

[cyan zinc]

then you just have to solve XY = 81

[trim jolt]

@tribal fractal Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deft crescent]

does anyone do well with optimization

[deft crescent]

im looking to get my math checked the problem is already done

can someone tell me where my math went wrong?

somehow i ended up with a multiple of ten

for my area optimization

adjoining rectangular pens of equal dimensions in which to breed your goats and you want the result
to cover 38,400 square feet (for reference purposes only: an acre is 43,560 square feet). The
fencing on the outside of the pens will cost $10 per foot and the fencing on the interior (between
pens) will cost $5 per foot. Find the dimensions of the pens which minimize the overall cost of
construction.```

.close

[trim jolt]

Channel closed

Closed by @deft crescent

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

.reopen

[wraith hinge]

Hi

Could someone do the working out and solution for this

<@&286206848099549185>

!close

[trim jolt]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[wraith hinge]

.close

[trim jolt]

Channel closed

Closed by @outer karma

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair zealot]

Guys, I'm having a confusion with finding the cosine of 225 using the unit circle, now I got to the point where I identify the reference angle which is 45, then i will try to compute the cosine of 45 which for me came out as 1, what am I doing wrong?

[edgy cedar]

Why is this 1?

[digital bolt]

ah

basically adjacent and hypotenuse get a bit weird

for angles bigger than 90

instead of literally the length of the sides, you want to use the x and the y instead

x-value instead of adjacent, y-value instead of opposite

so the x-value when it's at 225 is -sqrt(2)/2

and the hypotenuse is always 1

so it's (-sqrt(2)/2)/1 which is still just -sqrt(2)/2

[edgy cedar]

Well they thought the adjacent was 1 so that’s the issue here

[digital bolt]

i mean that too

[fair zealot]

what do you mean by x and y value?

[fair zealot]

How did you compute that?

what's wrong with mine?

[fair zealot]

well yeah, i just dont know how did he come up with the solutions that the adjacent is \sqrt{2}\2

[digital bolt]

basically it looks like this right

because it's isoceles, so the two short sides are equal

then a^2 + a^2 = 1, by pythagoras

so a = sqrt(2)/2 after you do the calculation

then it's to the left of the y-axis, so it's a negative value

so it's -sqrt(2)/2

[fair zealot]

why wouldnt my sketch be correct, how do you decide that what way you draw the sketch?

[digital bolt]

you just decided a was 1

but it isn't

i sorta worked my one out

essentially, you know the angle is 45 degrees

and another angle is 90 degrees

so the last angle is 45 degrees

[fair zealot]

but it is subjective that how you draw it, isnt it?

[digital bolt]

so it's an isoceles triangle

i mean

how you draw it is sorta subjective

but how you label the actual lengths is not subjective

there's an objective answer to how long the things are

which you can work out

rigorously

it is impossible for it to be 1

you can prove the length to be sqrt(2)/2, and then it's on the left of the y-axis so you use -sqrt(2)/2

like, you can draw it inaccurately but so long as you label it with the right lengths then you'll get the right answers out

[fair zealot]

hmm

interesting

so for the cos(45) we take the adjacent and divide it with the hypotenuse, but how do you know that its an isoceles? you dont know what a is do you?

[fair zealot]

also what did you use to draw this?

[digital bolt]

basically

you know that one angle is 45 degrees

and you know you want a right-angled triangle

so the second angle is 90 degrees

so the third angle is 180 - 45 - 90 = 45 degrees also

[fair zealot]

ohh yeah the other one is then 45

okay gotcha

[digital bolt]

right

[fair zealot]

how did you calculate this though?
a^2+a^2=1^2?

[digital bolt]

pythagoras' theorem

it's isoceles, so you know the two short sides are equal

so let them be equal to a

[fair zealot]

yeah

[digital bolt]

then by pythagoras', the sum of the two short sides squared is equal to the square of the hypotenuse

[fair zealot]

and then?

[digital bolt]

ie. a^2 + a^2 = 1^2

[fair zealot]

yeah

thats clear

but how do you know what a is?

🙂

[digital bolt]

oh lol

i mean ok it's easy now it's just calculation

a^2 + a^2 = 2a^2

1^2 = 1

so it's 2a^2 = 1

so a^2 = 1/2

so a = 1/sqrt(2) = sqrt(2)/2

i mean, if you want positive a

for negative a it'll be -sqrt(2)/2

[fair zealot]

how is 1 equal to 2a^2?

ohh my bad

i know

[fair zealot]

okay so this is cosine of 45 which is the same as cosine of 225?

[digital bolt]

not quite

essentially this gives the length of the side

but the length is always positive

when what you want is the x-value

so you look at the diagram to see whether the x-value is positive or negative

so you can see this is to the left of the y-axis

so the x-value should be negative

so you just decide to slap a - sign on

and you get -sqrt(2)/2

or actually i drew the wrong thing

you care about this point actually

but it has the same x-value so whatever

[fair zealot]

isnt it because its in the third quadrant and there only tan is positive, everything other than that is negatve?

[digital bolt]

i mean

but this is how you show that everything else is negative in the third quadrant

[fair zealot]

Not sure what that point mean

[fair zealot]

why would you want the x-value?

[digital bolt]

essentially

the x-coordinate of the point is equal to cos

and the y-coordinate of the point is equal to sin

that's why you care about this circle at all

the coordinates give you the trig functions

[fair zealot]

ohh yeah thats clear

but what i have a confusion with is if we calculate the cos of 45, why is that the same as the cos of 225?

[digital bolt]

it's not

to be clear

we got the length to be sqrt(2)/2

but the x-value, which is what we actually want to use, is -sqrt(2)/2

so cos(225) = -sqrt(2)/2

if it was cos(45), the x-value would be positive

it would be sqrt(2)/2

[fair zealot]

ohhh

shit

got it now

[trim jolt]

@fair zealot Has your question been resolved?

Channel closed

Closed by @fair zealot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty scarab]

you started with A^-1?

that's not what it says at the very top left

also, your first operation is wrong

[atomic socket]

u started witt the inverse?

u want to find A?

or th inverse?

[jaunty scarab]

and i'm pretty sure your elemental matrixes dont correspond to your operations

post the full instructions

[atomic socket]

what is the question?

if u can explain please

i would first check the det

determinant i mean

and its wrong what u have done

Z_2 - 2Z_1

u will get this:
1 0 1
0 1 -2
1 2 1

not
1 0 1
0 1 1
1 2 1

what you mean mod 3?

and why is that?

[jaunty scarab]

wow, that problem is so badly stated

also, kind of important to mention that you were on 3Z

wait, lemme check it slowly

why is your E_1 the identity?

your E_1 would be the matrix associated to your first row operation

E_2 would be the matrix associated to your second row operation, and so on

so it basically looks like none of your elementary matrixes are correct

none

neither of those matrixes corresponds to the row operation that you're doing

because they dont represent them?

go look up again how elementary matrixes for row operations are constructed

not really, it's pretty long to explain over discord

matrixes + discord = bad

[trim jolt]

Channel closed

Closed by @fiery schooner

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rigid tide]

Q3
I want to do it with the dot product method
Though you can do it by the limit definition as well
But there seems to be a problem
Please share solution because I am getting 0/0 form after putting the value at origin which I don't know if I am supposed to take a limit or do what

[rigid tide]

Kinda late here
I need the solution asap since it's like 3 am
And this channel would close by the time I wake up

So

<@&286206848099549185>

[trim jolt]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[rigid tide]

Ok sorry

Take ur time

[trim jolt]

@rigid tide Has your question been resolved?

[rigid tide]

<@&286206848099549185>
Hope it's okay now guys 😴

[rigid tide]

What about the next 30 minutes?

[trim jolt]

@rigid tide Has your question been resolved?

[rigid tide]

<@&286206848099549185>
Been an hour 🪦

[trim jolt]

@rigid tide Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[loud wasp]

im not sure what to do

i think its exponential funciton tho

[unreal river]

roughly x2 every 10 years

[silent canyon]

Fucking Moore's law

[unreal river]

yep

[verbal gulch]

except the numbers are actually completely wrong lol

it's like they just made them up

[loud wasp]

so it's linear function?

[unreal river]

nope exp

[loud wasp]

0.046 * (2)^t/10

Something like this?

[unreal river]

2 in 2020, 4 in 2030, 8 in 2040, 16 in 2050

yes

where t = year - 1960, i guess

[loud wasp]

okayy tysmmm

.close

[trim jolt]

Channel closed

Closed by @loud wasp

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solar parcel]

I need help to find out what the binary number is for 640, i have all the indexes but i dont know where to put the 1's and the zeeros

[solar parcel]

640= 12^9 + 02^8 + 1+2^7 and the rest is zeros but i dont know how to write it into nibbles like for example 0010 1110

[stoic iron]

well you know the number starts 101 and then like you said the rest are zero

how many zeros? well until you get down to 2^0

[solar parcel]

yeah but my teacheer needs me to fill out zeros before 101 aswell bcus im going to conveert to hexa decimals afterwards so then he wants me to have like 4 nibbles

I think

[stoic iron]

well fill in all the zeros after 101

[stoic iron]

and then fill in with zeros before 101 until you have 4 nibbles

[solar parcel]

0101 0000 0000 0000?

[stoic iron]

no thats now a way bigger number

[solar parcel]

oh

how would u do it

[stoic iron]

write out what binary number you currently have from your picture

[solar parcel]

1010000000

[stoic iron]

okay now fill in zeros before the 101 (i.e. the left) until you have 4 nibbles

[solar parcel]

is it 0010 1000 0000?

[stoic iron]

is that 4 nibbles?

although tbf if youre converting to hex maybe you only need 3

yeah 3 is fine

[solar parcel]

It is?

[stoic iron]

well if you added another 0000 at the start to get 4 nibbles that would just mean adding a 0 at the start of your hex which you dont need

[solar parcel]

would it have been 0000 0010 1000 0000 if i neeeded all the nibbles?

Yeha

Bcuz the first 4 zereos are irrelevant anyways, corrrect?

[stoic iron]

yeah

like how you wouldn't write 0123 in decimal

[solar parcel]

yeah

thanks!!

[stoic iron]

do .close if you have no more questions:)

[solar parcel]

oh sorry

close

how do i do that lol

.close

[trim jolt]

Channel closed

Closed by @solar parcel

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proven violet]

hi

[proven violet]

im doing a question on branching processes

i've finished parts a and b

and i don't know how to do the bit in part c where it asks me to deduce the recurrence relation

$G(s)=\frac{1+s^2}{2}$

[solid kiln]

george clooney real account

[trim jolt]

@proven violet Has your question been resolved?

[proven violet]

okay i've expressed the probability a generation dies out as the chance that each member of the previous generation takes the 0.5 route that leads to dying

so $\mathbb{P}(X_n=0)=(\frac{1}{2})^{X_{n-1}}$

[solid kiln]

george clooney real account

[proven violet]

and then I've written the probability it survives at least n generations as $1-\sum\limits_{i=1}^n{\mathbb{P}(X_i=0)}=1-\sum\limits_{i=1}^n{(\frac{1}{2})^{X_{i-1}}}$

[solid kiln]

george clooney real account

[proven violet]

i'm just not sure how to put the second bit in a closed form !!

or what it has to do with the recurrence relation lol

[trim jolt]

@proven violet Has your question been resolved?

[trim jolt]

@proven violet Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable crag]

11 is the question itself on the right side photo but i need help with c which is the left photo

To be more specific the answer key says 95 and 265 and i need help understanding why 85 isnt also an answer( i thought all values are positivr in Q1)

Still just learned trig so alot of confusion

Also if anyone can guide me to some videos they think explain trig really well it would be appreciated

[trim jolt]

@stable crag Has your question been resolved?

[stable crag]

<@&286206848099549185>

[trim jolt]

@stable crag Has your question been resolved?

[stable crag]

<@&286206848099549185>

[trim jolt]

@stable crag Has your question been resolved?

[stable crag]

.close

[trim jolt]

Channel closed

Closed by @stable crag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gaunt musk]

can someone help me with this problem?

[gaunt musk]

im pretty confused

[trim jolt]

@gaunt musk Has your question been resolved?

[trim jolt]

@gaunt musk Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sly salmon]

i got a 16 instead of 34

[sly salmon]

NVM I GOT IT

.close

[trim jolt]

Channel closed

Closed by @sly salmon

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coral crystal]

This is how is solved this different equation, should I do anything else?

[trim jolt]

@coral crystal Has your question been resolved?

[zinc ginkgo]

what does the question ask for

[coral crystal]

just to solve it

and I dont think there is a way to get a formula like y =....

[zinc ginkgo]

yea what you have looks fine

[coral crystal]

ok ty

.close

[trim jolt]

Channel closed

Closed by @coral crystal

Use .reopen if this was a mistake.

[edgy cedar]

just note that you dont have to write 2 cs

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid raven]

how can i calculate this integral when the path consists of the segments [0, i], [i, 1 + i] ?

[zinc ginkgo]

$z = e^{it}$

[solid kiln]

riemann

[trim jolt]

@lucid raven Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.