help-38

[rare fox]

Makes total sense now thank you

[potent smelt]

ofc

[rare fox]

.close

[trim jolt]

Channel closed

Closed by @rare fox

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure zenith]

Uhhh

3+0≠6

Perfect proof

[wintry cedar]

If 3=0, then 3x = 0x, therefore 3x = 0, youre saying any number multiplied by 3 is equal to 0 which its not, only 0

[azure zenith]

Perfect proof again

Unless you are talking in context of some mumbo jumbo modern algebra type stuff, 3 ≠ 0

[stark bison]

As it implies successor of some number is equal to 0

And peano axioms states S(n) = 0 is false for any n

(I'm asuming you wanted a proof via peano axioms)

[tame solstice]

it's actually 3 = 0
cuz 3 * 0 = 0*0
=> 0=0
So u r wrong that 3 not equal to 0
3 = 0 is real ngl

(source: trust me bro)

[azure zenith]

Perfect proof again

[stark bison]

If you want to define 3 to be just a relabelling of 0, then sure

But that would be unconventional, only causing difficulties to you and others

[azure zenith]

That new number system would be weird

0,1,2,0,1,2,0

So on

[stark bison]

They don't necessary have to come up with base 3 system

Another letter replacing the successor of 2 could be introduced

[azure zenith]

0,1,2,e

Or pi

https://cdn.discordapp.com/emojis/759987154767052840.gif?v=1&size=64&quality=lossless

[stark bison]

Right, something like that

[azure zenith]

Engineers will celebrate while mathematicians will pull out their hair

[stark bison]

Anyway, @rugged shoal, does that answer your question?

You may close the channel

[trim jolt]

@rugged shoal Has your question been resolved?

Channel closed

Closed by @rugged shoal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

analysis, proofs, stats, cs, cryptography....

wdym exactly?

[trim lichen]

this question is too broad to have a reasonably enlightening answer

this is like asking "what is the letter K used for"

and this sounds like "why do i need to know 13+24=37"

[wraith hinge]

why do you need to know that the derivative of x^2 is 2x

you can ask the same question about literally any math topic. It is up to you if you want to enlighten yourself further on potential applications of it

[trim lichen]

set theory underpins basically all of modern math.

[trim jolt]

Channel closed

Closed by @rugged shoal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse cipher]

Can someone help with the <= directuon please

[terse cipher]

heres what i attempted

[quaint gazelle]

proof by contradiction

[terse cipher]

what would the contradition be?

where exists a x in Both W1 and W2 that is non zero?

[quaint gazelle]

yeah

then x is in V

[terse cipher]

can you explain why that would satisfy both conditions

[quaint gazelle]

i mean W1+W2 =V is already just given

[terse cipher]

oh I see

ok

[quaint gazelle]

so you just need to prove W1nW2={0}

[terse cipher]

is that good enough for condition 2

[quaint gazelle]

yeah

[trim jolt]

@terse cipher Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter tendon]

Write the equation in slope-intercept form of a line perpendicular to 3x -y= 5 and goes (8,-3)

I don’t know how to solve this

[winter tendon]

.closed

.close

[trim jolt]

Channel closed

Closed by @winter tendon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise dune]

u are wrong

answer is 46,3

[prime wraith]

Thanks
Which steps did I miscalculate

[wise dune]

where u get * 7 from?

sorry bad hand writing

[prime wraith]

Oh it's times 9

[wise dune]

u write 7 instead of 9

[prime wraith]

I got this other problem mixed up with this one... oops. Thanks for the help Aldrich, I appreciate it

.close

[trim jolt]

Channel closed

Closed by @prime wraith

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[light robin]

16x² -4x can someone help me understand 4x(4x -1 ) Why is there a -1 there?

[stark bison]

Because -4x = (-1) * 4x

[light robin]

But in my eyes there should be a zero lemme send a picture

[stark bison]

So 4x(4x + 0)?

[viscid crag]

Take 4x common from 16x²-4x

Tell me what r u getting

[light robin]

Well I get 4x (4x -

And then I dont know what to put there

[viscid crag]

Do u know how to take some things common in an equation?

Tell me what would u get from here if u take 2 common

[light robin]

2?

[viscid crag]

Yes take 2 common

[light robin]

two deuces

[viscid crag]

?

[light robin]

2 * 7 * x - 2

Two 2 in common?

[viscid crag]

Yesss

So now after taking 2 common , if we frame an equation, it will be

2(7x-1)

Do u get it?

[light robin]

I get the part where it become 2(7x -

But not how the -1 appears

[viscid crag]

Tell me what is 2*(-1)?

[light robin]

-1

[viscid crag]

No

2 multiplied by -1

[light robin]

oh lmao nvm

-2

[viscid crag]

Yesss

And in my question, the equation was
14x-2

That's why I take 2 common from -2 and I get -1

[light robin]

So 7 times 2 is 14x and -1 times 2 is -2

[viscid crag]

Yes

Ur question is 16x²-4x

Take 4x common

[light robin]

And -1 times 4 is -4

Now I get it

[viscid crag]

[light robin]

Thank you man

Very much

[viscid crag]

Np 😄

[light robin]

.close

[trim jolt]

Channel closed

Closed by @light robin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ashen wind]

can someone help me rq 😭 its due in 20 minutes 😭

[ashen wind]

feck

i go watch yt instead

[devout flame]

instant advice service

please read textbooks or notes if you can

for concepts

meh, i'll get the answers if it's desperate

[ashen wind]

HELLO

I HAVE

6 MINUTES

[devout flame]

OK?

[ashen wind]

plz

very

desperate

[devout flame]

ok i am solving for instant

Vertex: (2,7)
Equation of the Line of symmetry: x = 2
y-intercept: -1

wait..

is that picture exact?

[ashen wind]

yes

[devout flame]

is there any equations like y = ax^2 + ~~~

because i cannot get exact values of the next answers

[ashen wind]

nope

all from the graph

[devout flame]

(wth)

i cannot answer you x-intercepts

[ashen wind]

i got one done earlier

[devout flame]

Domain: all real number

[ashen wind]

im not

too sure

if correct tho

[devout flame]

wait..

as well

(well, do it as you learnt)

domain is all read number

range is y >= -1

and Minimum value is -1

not y = -1

[ashen wind]

is this for 1-7

[devout flame]

i am commenting your very picture there

[ashen wind]

oh oke

[devout flame]

equation of the line of symmetry is x = -2

[ashen wind]

OH YES

I

accidentally switched the

[devout flame]

i think you changed order between

Lol

[ashen wind]

yes

lol

[devout flame]

for 1-7

Vertex: (2,7)
Equation of the Line of Symmetry: x = 2
y-intercept: -1
x-intercepts: ???(i don't know because there's no mark)
Domain: x is every real number
Range: y<=7
Maximum Value: 7

(i think for y-intercept, I am supposed to write down with a constant number. But i don't know what exactly it is, do it as you learnt)

[ashen wind]

okay

i just asked teach

for

extra 10 mins

[devout flame]

lol

[ashen wind]

9

now

ig

wait no

[ashen wind]

thanks for this 😭

8-14

[devout flame]

for 8-14

Vertex: (3,1)
Equation of the Line of Symmetry: x = 3
y-intercept: 7
x-intercepts: none
Domain: every real number x
Range: y>=1
Minimum Value: 1

[ashen wind]

i actually love u 😭

we have like 3 workshits per quarter

so

this greatly

affects

written works

thank u fr

[devout flame]

thanks myself

?afk

[ashen wind]

thanks

allat

.close

[trim jolt]

Channel closed

Closed by @ashen wind

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glass ridge]

Hi

[glass ridge]

This is the answer sheet to the test review. I understand up to “we will prove this is true for all integers n = k+ 1” but after that I don’t understand what my teacher is doing

[torn obsidian]

😔 💀

[nimble stone]

we want to show that 7^(k+1)-2^(k+1) is divisible by 5, everything after that until 'by hypothesis' is just getting the above into a form where 7^k-2^k being divisible by 5 can be useful

[torn obsidian]

You should tell your teacher this is poorly written, especially the part in blue (and even the line after)

[glass ridge]

I’m trying to pass my test, not get points deducted for the rest of the year 😭

[torn obsidian]

😔

How comfortable do you feel with induction proofs?

In general

[glass ridge]

Like a 4/10 sadly. Teacher was out sick for a whole week before the test so we missed review days.

All I have are her notes and hw I struggled on

And the book is different from what she taught

[torn obsidian]

Ok, well you first need to understand that the part written in blue is very bad to write out in the proof. Because you are basically assuming what you are trying to show

And same for the line after

[glass ridge]

So for the equation part, do I just force the equation to look like 5|7^k - 2^k?

[torn obsidian]

For the second step (after the base case), you need to assume it's true for a given k. Not for all k (as it is mentionned)

You don't actually know if that is true for the rank k. But if you assume it is true, then it has to be true at the rank (k+1). That's what you have to show

[torn obsidian]

And then, yes, so since you are assuming that 5 | 7^k - 2^k

You must try to write out things so 7^k - 2^k appears

Starting from 7^(k+1) - 2^(k+1)

And this is where often you have to be creative

But with few practice you should be able to come up with an idea 🙂

[glass ridge]

Ty. I’m struggling so much 😞

I’ll reopen another help channel if I need help, but with the answer sheet I think I just need to study it

.close

[trim jolt]

Channel closed

Closed by @glass ridge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tulip hamlet]

<@&286206848099549185>

[trim jolt]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[wraith hinge]

so this is finding the area the shape?

[tulip hamlet]

Yhh

[tulip hamlet]

Idk where to put the numbers

[wraith hinge]

wym?

if its the area of the whole shape, starting with the trapezoid, then you need to first separate the rectangle from the triange

[tulip hamlet]

How abt the area of the triangle the first one

[wraith hinge]

oh then all you need to do is act like they are both rectangles

so you multiply the height of it and length

then from there divide that area by 2 to find the area

@tulip hamlet

[tulip hamlet]

Lemme try it

[wraith hinge]

buut that only really works when it is a right triangle

[tulip hamlet]

So it won’t work on that one?

[wraith hinge]

no, they are both right triangles, meaning that it has a 90 degree angle

[tulip hamlet]

So what am I supposed to do?

A= 1/2 bh

Is that formula correct?

[wraith hinge]

what is Bh?

[tulip hamlet]

Base x height

[wraith hinge]

oh, yeah, sorry

[tulip hamlet]

But which one is the base

[wraith hinge]

then divide it by 2 because a right triangle is essentially 1/2 a rectangle

then do that for both triangles then add the 2 together to get the area of the whole

did you get it?

[tulip hamlet]

I got this idk what else’s should I multiply it by one then divide it by 2

[wraith hinge]

I think thats correct, the original screenshot was blurry, so plugging in the numbers should be easy

right triangle formula: A=1/2 B*H

[tulip hamlet]

So I am dividing it by 2? But why they put ft square at the end

[wraith hinge]

the line between the 2 bisects it

meaning the base is 450

so the equation here is A=1/2 450*250

[tulip hamlet]

Is this correct?

[wraith hinge]

A=1/2 112500

the area of one triangle is 56250

[tulip hamlet]

How are we multiplying?

[wraith hinge]

where?

[tulip hamlet]

How you got 56,250?

[wraith hinge]

because 1/2 of 112500

is 56250

its half

[tulip hamlet]

Ahh but we had 225,000 and we cut in half first

[wraith hinge]

the base is 450

of one triangle

so you multiply like that

then you do the same for the other triangle and add

but I do have to go

sorry

but you should be able to solve it from there

[tulip hamlet]

But there’s no space for all that in the blank

[trim jolt]

@tulip hamlet Has your question been resolved?

Channel closed

Closed by @tulip hamlet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild knot]

Vis at akselerasjonen til en gjenstand som faller med luftmotstanden L=k⋅v2, er gitt ved formelen a=g−(km)⋅v2. Hvilken retning er valgt som positiv?

[mild knot]

Sorry, Show that the acceleration of an object falling with air resistance L=k⋅v2 is given by the formula a=g−(km)⋅v2. Which direction is chosen as positive?

Since a is positive in the formula given the positiv direction must be down right?

[trim jolt]

@mild knot Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven steeple]

hello, I need to show that \rho induces a finer topology than d_2

[uneven steeple]

so I need to show that if U is an open set in (X,d_2) its open in (X.\rho)

but seems like the only balls I could construct in (X,rho), seems to be around the origin, so not sure what I'm doing/the question is wrong(unlikely)

[trim jolt]

@uneven steeple Has your question been resolved?

[trim jolt]

@uneven steeple Has your question been resolved?

Channel closed

Closed by @uneven steeple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting flame]

hi

[trim jolt]

@drifting flame Has your question been resolved?

Channel closed

Closed by @drifting flame

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elder owl]

Hi I have a problem, I need to prove that phi(x) = phi(x+1)

[elder owl]

<@&286206848099549185>

.close

[trim jolt]

Channel closed

Closed by @elder owl

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal stirrup]

is P(AB) the same (just different notation) as P(A|B)? this seems like its used interchangably in the notes im reading but i dont think that thats true?

[rugged latch]

Ye

[crystal stirrup]

ok

[rugged latch]

Wait

[austere cedar]

P(AB) is short for P(A ∩ B)

[rugged latch]

No

Oml

[crystal stirrup]

ah

ok

[rugged latch]

SORRY LOL

[crystal stirrup]

i saw a note saying

P(AB)=P(AnB)/P(B)

that is a typo correct

[austere cedar]

Typo

[crystal stirrup]

should be P(A|B)=P(AnB)/P(B)

ok cool

that had me so confused for like 10m lol

thanks guys take care

.close

[trim jolt]

Channel closed

Closed by @crystal stirrup

Use .reopen if this was a mistake.

[rugged latch]

oopsies

Misread

It’s great that I have a midterm on intro probability tmrw and this is what it’s about!

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis magnet]

if the triangles are similar how to do find x
i've been struggling on this and cannot find the proportion

[trim jolt]

@lapis magnet Has your question been resolved?

[gloomy warren]

hey @lapis magnet , i'm not an official helper, but i can try to help 🙂

you should be able to use pythagorean theorem. i listed the bottom of the large triangle as b_1 and the bottom of the triangle with the hypotenuese of x as b_2

and then use pythagorean theorem from there

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting rose]

Could someone figure out why I did this

[drifting rose]

Why did I add up all of them to find the coefficient of x?

Couldnt I have just find k and r in terms of 1?

[trim jolt]

@drifting rose Has your question been resolved?

[drifting rose]

.close

[trim jolt]

Channel closed

Closed by @drifting rose

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grim spear]

help i cant get an answer im stuck

[trim jolt]

@grim spear Has your question been resolved?

[grim spear]

<@&286206848099549185> ]

[wraith hinge]

Ok

@grim spear

Let’s call g(x)=lnx - x +sqrt(x)

And then show g(2) is the opposite sign of g(3)

[grim spear]

wdym

if i use the intermediate value theorem im supposed to just find f(2) and f(3) right

[wraith hinge]

Yes

And show that they are opposite signs

[grim spear]

but there isnt a clear answer to ln2 = 2 - sqrt2 is there

im confused

[wraith hinge]

Doesn’t matter just show one of the answers is positive and one is negative even if you can’t find exact

Also you are not trying to solve that equation

ln2=2-sqrt(2) is not right because it never said 2 was a solution it just said it had to be in the interval

[[[[[Rearrange the original equation so that one side has 0 on it]]]]]]

[trim jolt]

@grim spear Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[vast stag]

Who tryna help me with some freshman math

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[clear sail]

$$\forall x, y, z \in S.\ x R y \land y R z \implies x R z$$

[clear sail]

$$\forall x, z \in S.\ (\exists y \in S.\ x R y \land y R z) \implies x R z$$

[solid kiln]

gkn1

gkn1

[clear sail]

are those two statements equal. R is a relation on S

if so is there a generalisation of what happened here

like for all y in S. P(y, ...) => Q(...) is identical to (exists y in S. P(y, ...)) => Q(...) maybe?

[dull temple]

i don't think they're equivalent

[clear sail]

do you have an idea of a counterexample?

[dull temple]

ok never mind they can be turned into each other

easiest to see if you negate them

[clear sail]

$$\exists x, y, z \in S.\ x R y \land y R z \centernot\implies x R z$$

[solid kiln]

gkn1
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dull temple]

remember how to negate things like this

$\overline{\forall x. P(x)} === \exists x. \overline{P(x)}$

[solid kiln]

Haylsune Miku

[clear sail]

isn't that what I did

[dull temple]

no you didn't negate the implication

[clear sail]

I just don't know how to typeset =/=>

[dull temple]

oh you can do \not\implies

[clear sail]

Thx

$$\exists x, y, z \in S.\ x R y \land y R z \not\implies x R z$$

[solid kiln]

gkn1

[dull temple]

good enough

what i did was translate that into the boolean equivalent

[clear sail]

$$\exists x, z \in S.\ (\exists y \in S.\ x R y \land y R z) \not\implies x R z$$

[solid kiln]

gkn1

[dull temple]

at least the implication

[clear sail]

A and not xRz

I don't have paper rn sorry

They still seem equivalent

[dull temple]

would always recommend having scratch paper when doing math

yeah they're equivalent

but you can prove that

by transforming one into the other

[clear sail]

Can you move existential operators outside and to the left freely?

[dull temple]

sometimes

you can move Ax past Ay

and you can move Ex past Ey

but not if they're mixed

[clear sail]

Yeah you can't move Es to the left of As

Right?

But that's the only restriction

[clear sail]

How do you properly do this?

It's probably

[solid kiln]

gkn1

gkn1

[clear sail]

I guess this is the question being asked, whether these two are the same

[dull temple]

nor the other way if you want it to be reversible

[clear sail]

I really don't think those two are the same

[dull temple]

those are definitely not the same

although

what is Q?

is it not parameterized?

[clear sail]

No I don't think it needs to be

[clear sail]

Here x and z don't matter right

[clear sail]

And here

When it comes to this transformation

Idk I have no idea what's going on

[trim jolt]

@clear sail Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trim jolt]

@velvet bolt Has your question been resolved?

[velvet bolt]

<@&286206848099549185>

[cold dust]

sorry i cant read german

[velvet bolt]

i provided the translation

[cold dust]

ooooh

my b

is the ascent up a constant speed or does it change?

[trim jolt]

@velvet bolt Has your question been resolved?

[velvet bolt]

It changes

[trim jolt]

@velvet bolt Has your question been resolved?

[broken pilot]

What do Zeit and Tiefe mean?

[shrewd ridge]

time, depth

[broken pilot]

for a you’re right

[broken pilot]

and for 2, yes, after you put in parentheses

[velvet bolt]

And why is the speed negative

[broken pilot]

Because down is positive

[velvet bolt]

But he goes up

[broken pilot]

It would be positive if you took the height to be -39 instead of 39

[velvet bolt]

Oh ok

[broken pilot]

The depth is 39, which means that the diver is below sea level, so the height is negative

[velvet bolt]

Ok

[trim jolt]

@velvet bolt Has your question been resolved?

Channel closed

Closed by @velvet bolt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed by @tulip parcel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest egret]

yo

!status

[trim jolt]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[forest egret]

let's do a simpler case

consider 0.33...

we can do a trick by consider 10 times 0.33...

we get 3.33...

and 3.33..-0.33...=3

since 3.33.. is 10 times 0.33.., 9 times 0.33..=3

thus 0.33..=3/9

multiply the 0.201717... by 10000 and cancel the repeating decimals

show your work?

oh wait

you should get an equation

also actually multiplying 100 is simpler

ok lemme do another example

let's calculate 0.11...

for simplicity let x = 0.11...

now 10x = 1.11...

thus 10x-x=1.11..-0.11..

notice their decimal cancels out

we get 9x=1

x=1/9

try to cancel the decimals using this trick

good

correct

now simplify 19.97/99

you want to solve for 0.201717...

so divide to get rid of 99 on right hand side

[trim jolt]

Channel closed

Closed by @tulip parcel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest egret]

I hate combinatorics

I'd just brute force this by listing all ways

[livid thunder]

nah no way u can brute force this quickly

[forest egret]

I don't see why not

[livid thunder]

brother i saw a question similar to this except there were 11 steps, no broken steps and u could only climb up to 2 at a time and it had like 144 possibilities

[dull temple]

no broken steps makes it take longer to brute force but easier to calculate

imagine David was on the 10th step

how many ways could he go to the top?

[livid thunder]

bit more than that

nvm

theres 11 steps

thought there was 13

[dull temple]

great
what if he was on the 9th step (pretend it's not broken for a sec) use the previous result

actually no, what if he was on the 8th and let's remember the 9th is broken

again, use that result from step 10 explicitly

no, more than one

because he could either go all the way up or go via the 10th step

if he's standing on step 8

what are his immediate options?

yes but that's not the question i asked

yes, he can either go to

• step 11, or
• step 10

once he's on step 11 he's done

once he's on step 10 how many ways can he get to the top?

(remember we already calculated that)
yeah

so starting on step 8, how many different ways can he get to the top?

ok cool

now what about if he's starting on step 7? what are his options?

how's that?

yeah, see how you were able to reuse previous results?

keep doing that, and keep going down until you've calculated the number of ways starting at the 1st step

like

from step 7, our immediate options are:

• step 8 (this was worth 2)
• step 9 (this is broken, worth 0)
• step 10 (this was worth 1)

so the total is 3

[dull temple]

yep! now keep going, it's much easier now that you don't have to redo all those intermediate results

[trim jolt]

Channel closed

Closed by @tulip parcel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viral tartan]

I got my equation but it’s been two years since I’ve taken algebra 1 and I forgot how to do this. Help?

[viral tartan]

<@&286206848099549185>

[trim jolt]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[uneven seal]

Rule 1 if you give x a 0, that would give the value of the only term without the x, basically the last term

Rule 2 if you give x a 1, that would give the sum off all coefficients in the equation, because x will always multiply the coefficients with 1 no matter the power

So if height at the time 0 is 10, we know the only term without the x is 10, because all other terms are made zero, as the contain the value x

So it is ax^2 + bx + 10

And according to rule two, sum of all coefficients are 6

As at t 1, the value is 6

That means a+b+10= 6

Meaning a+b is -4

Now, the way we can find the values for a and b , while it is a painful process, we will have to use a value which will differ in x^2 and x, thus giving away which one is which

At time 0.2 its height is 11.76

Meaning a(0.2)^2 + b(0.2) + 10 = 11.76
And we also still know that a+b= -4

The equation of the top will be 0.04a+ 0.2b = 1.76

We can multiply both sides with 25 so it is simpler

1a+5b = 44

And a+b is still -4

Which means 4b= 48, b being 12

And so a must be -16 as a+b are still -4

So, it asks when it will be 0

We now have understood that the formula is -16x^2+12x+10 , and it asks when it will be 0

To find the roots (the values that make it zero) we use the quadratic formula

it is (-b±√b²-4ac)/ 2a

[trim jolt]

@viral tartan Has your question been resolved?

[uneven seal]

The a b c in the formula express the coefficients

ax²+bx+c

So our formula of -16x²+12x+10 , -16 is a , 12 is b and 10 is c

[viral tartan]

Math teacher looked at what you said, but we’re gonna go over it after lunch. She said that wasn’t how to do it

[trim jolt]

@viral tartan Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

I want to know how to find the area of a triangle

[crisp kraken]

1/2 * base * height

[dull temple]

,tex .plane geom

[solid kiln]

Haylsune Miku

[crisp kraken]

1/2absin(c)

[flint sluice]

heron's formula

[crisp kraken]

ask the triangle nicely

[wraith hinge]

thanks!

Luis bought 8 notebooks at 25 dolars each and 7 pens. In total he spent 298 dolars, how much did each pen cost?

[crisp kraken]

just assign a variable to each item

i.e. x for price for notebook and y for price of pen

[wraith hinge]

okay, thanks again

[trim jolt]

@wraith hinge Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nova wadi]

this a example of a max flow cut.

I was wondering when a cut is not allowed. so I thought of a example is it allowed to have a cut where B = {b,d,c} and P = {a,e,p}

from the definition it seems like it's possible but from the drwaing it's not

[marble wharf]

well I suppose you could make a drawing like this https://i.imgur.com/i10kGMZ.png

whether you can draw it isnt really the point tho

for more complicated graphs that will be quite hard

[nova wadi]

oh so any possible partition is allowed?

[marble wharf]

well thats what the definition says

[nova wadi]

as long as b is in B and p is in P ofcourse

[nova wadi]

ye I thought so I just was not sure about this one but the way u drew it made it clear for me thanks

[marble wharf]

if you changed the position of c and e in the drawing, the cut might look a bit more natural

[nova wadi]

is it btw also allowed to do multiple cuts?

[marble wharf]

wdym with multiple cuts

[nova wadi]

as in doing for example 2 cuts

[marble wharf]

I am still not sure what you mean

graphically two cuts?

[nova wadi]

so for example

is this allowed?

[marble wharf]

so a partition with more than two sets?

no

[nova wadi]

it is only allowed if they were done independty?

[nova wadi]

ye is that also possible?

[marble wharf]

.

[nova wadi]

ah okay

[marble wharf]

well at least its not considered in this context

you can try building a theory on it

[nova wadi]

I saw this on google is this even allowed?

I assume they are just indepndent cuts right?

[marble wharf]

hmm apparently it is a thing

didnt know that

[nova wadi]

wait so this is not independt?

if it's independend I still can like udnerstand it since u partiition it with 2 sets every time

but the cuts can't be happening at the same time I think otherwise u won't get 2 sets where source is in 1 set and sink in another

[marble wharf]

this is another definition of whats allowed

I am not sure what you want to hear

for the max flow min cut there is only one cut

[nova wadi]

all right that's enough for me then

[trim jolt]

@nova wadi Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rough dew]

hello I need help with a problem, it involves some trig. here is an example of what I need help with
https://gyazo.com/b467dee82199ea96da7c2a7f3c7312f0

[rough dew]

how do I get the length of c, and b

[gilded glacier]

basically, you should use definition of cosine*

[viscid flower]

you can express them using trig functions and the given angle information

do you know your soh cah toa

[rough dew]

yeah

[viscid flower]

so tell me how to get b using 20 length and 22.5 degrees

you have 20 right

[rough dew]

you'd use toa correct?

[gilded glacier]

b = 20 tan 22.5 deg

[viscid flower]

!nosols

[trim jolt]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[viscid flower]

[viscid flower]

yes

[rough dew]

would it be tan(22.5) = 20/b?

[viscid flower]

close

[rough dew]

its been like two years since I did this trig I don't remember it honestly

[viscid flower]

tangent = opposite / adjacent

[rough dew]

oh

so b/20

[viscid flower]

yea

$\tan (22.5) = \frac{20}{b}$

[solid kiln]

jan Niku

[viscid flower]

weird

bots weird

anyways

yea

tangent of an angle comes from a calculator, so call it known

20 is known

so if you wanna express it like known = unknown, you just rearrange a little

[rough dew]

so if its tan(22.5) = b/20

its tan(22.5) * 20 = b?

[viscid flower]

yes

[rough dew]

so b = 11.15 approx

[viscid flower]

unknown expressed in terms of stuff you know

,calc tan(22.5)

[solid kiln]

Result:

0.55785173935219

[viscid flower]

this is radians

,calc tan(22.5 degrees)

[solid kiln]

Result:

0.4142135623731

[viscid flower]

there we go

,calc 20 * tan(22.5 degrees)

[solid kiln]

Result:

8.2842712474619

[viscid flower]

@rough dew

[rough dew]

oh I was in rad

I see

alright thank you this is helpful

[viscid flower]

np

you can get c then i guess?

[rough dew]

yeah I can

[trim jolt]

@rough dew Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shrewd kindle]

hello, can someone help me to find the asymptote of the given function?

[shrewd kindle]

.close

[trim jolt]

Channel closed

Closed by @shrewd kindle

Use .reopen if this was a mistake.

[shrewd kindle]

hello, can someone help me to find the asymptote of the given function?

<@&286206848099549185>

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old musk]

What do i do?

[warm kernel]

a b or c

[old musk]

b

[warm kernel]

Have you done a?

just plot down the coordinates you have if you have done a.

and draw a curve through all of the points.

[old musk]

Oh

What do those mean?

this is correct for a right?

[mystic veldt]

thats given the domain of this function, you only have to plot the graph from x=0 to 5

[mystic veldt]

yes

[old musk]

Ohh thanks

[old musk]

Is this correct for C?

[mystic veldt]

dont you just have solve this quadratic?

[old musk]

Wdym?

[mystic veldt]

,, x^2-6x+7=0

[solid kiln]

!Yajat!

[old musk]

Where did the 5x and x go?

[mystic veldt]

in LHS

[old musk]

oh u add them to get 6x>

?

[mystic veldt]

,, x^2-5x-x+7=0

[solid kiln]

!Yajat!

[old musk]

Oh and then u get this?

[old musk]

x^2-5x-x+7=0

x^2-6x+7=0
So this is the answeR?

x^2-6x+7=0

[mystic veldt]

you need to factorise it now

[old musk]

im stuck..

.

@mystic veldt ^

[trim jolt]

@old musk Has your question been resolved?

[old musk]

.close

[trim jolt]

Channel closed

Closed by @old musk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[humble thorn]

x=(6±√36-28)/2
x=(6±√8)/2

[stark bison]

!nosols

[trim jolt]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[humble thorn]

mb

[stark bison]

.close

[trim jolt]

Channel closed

Closed by @stark bison

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager barn]

Exc 44

[vagrant prism]

translation pls

solve in $\mathbb{R}$?

[solid kiln]

artemetra

[vagrant prism]

convert everything to polar form

[meager barn]

I think I got it

.close

[trim jolt]

Channel closed

Closed by @meager barn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid yacht]

How would i solve 59 a)?

[livid yacht]

i was thinking to sub in 0 for xsin(1/x) but wouldnt that be undefined

[sturdy heron]

What's the question

[livid yacht]

Second picture a)

Show that f and g are both continuous at 0

.close

[trim jolt]

Channel closed

Closed by @livid yacht

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

Can I get a more elaborate explanation of this

[crisp kraken]

theres no reason to view one outcome as more likely than another

so the probability of each outcome would be the same

i.e. 1/n

[wraith hinge]

Huh, that's an actual established thing?

I often thought this way but never knew it had a name

[crisp kraken]

yeah it seems pretty intuitive

[wraith hinge]

i see

thanks

.close

[trim jolt]

Channel closed

Closed by @ionic frigate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic vessel]

Does this just mean a^5c^-1 times a^9c^-3

[spark linden]

so drug per cell

= drug / cell

[trim jolt]

@mystic vessel Has your question been resolved?

Channel closed

Closed by @mystic vessel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic vessel]

I'm confused about this question, i dont know what the question wants me to do so can anyone tell me what im supposed to do with this question?

[loud bough]

what grade are you in

?

[sharp heart]

It wants you to factorize the numbers all the way into primes.

Do you know about prime numbers?

[loud bough]

i think the fact that it listed out the prime numbers was quite confusing

[sharp heart]

@mystic vessel

[last rune]

man prolly is in his rank up match

[sharp heart]

Their status was green but now it's grey, so they're probably having connection problems or they left.

[full dock]

diamond lobby defo

[sharp heart]

1. Write out the first several prime numbers, like 2, 3, 5, 7, 11, 13, etc.
2. Start with the first prime number, 2.
3. Divide the number, like 54, by the current prime number.
4. If there's no remainder, write the current prime number down and replace the number with the result of the division (like 54/2 = 27, so now the number is 27).
5. If there is a remainder, leave the number alone and go to the next prime number (like just after the prime number 2 is the prime number 3).
6. Go back to step 3 unless the number is now 1.
7. Now, you'll have something like 2 times 5 times 7 times 7.
8. Convert it to index form and that'll be your answer.

[trim jolt]

@mystic vessel Has your question been resolved?

[sharp heart]

@mystic vessel So, with 490, we have:```
Prime number: 2
The number: 490
Answer: [blank]

490/2 = 245, which has no remainder, so we add the prime to the answer and change the number

Prime number: 2
The number: 245
Answer: 2

245/2 = 122 r 1, which has a remainder, so we go to the next prime number

Prime number: 3
The number: 245
Answer: 2

245/3 = 81 r 2, which has a remainder, so we go to the next prime number

Prime number: 5
The number: 245
Answer: 2

245/5 = 49, which has no remainder, so we add the prime to the answer and change the number

Prime number: 5
The number: 49
Answer: 2 times 5

49/5 = 9 r 4, which has a remainder, so we go to the next prime number

Prime number: 7
The number: 49
Answer: 2 times 5

49/7 = 7, which has no remainder, so we add the prime to the answer and change the number

Prime number: 7
The number: 7
Answer: 2 times 5 times 7

7/7 = 1, which has no remainder and leaves us with 1, so we add the prime to the answer, convert it to index form and stop

Answer: 2 times 5 times 7 times 7
Index form: 2^1 times 5^1 times 7^2

@mystic vessel You can check the answer by doing the multiplications in the answer and seeing if you get the original number, 490.

[mystic vessel]

ty

[sharp heart]

No problem.

@mystic vessel I added a step at the end to get index form.

[mystic vessel]

alr ty

[sharp heart]

You're welcome.

[mystic vessel]

arent we just doing prime factorization

[sharp heart]

Yes, that's what it is, but converting it to index form at the end.

[mystic vessel]

oh ok

ty tho

[sharp heart]

No problem.

[mystic vessel]

do you agree that the wording of this problem is a bit confusing

[sharp heart]

It's a bit confusing.

[mystic vessel]

ok so for a) i got 2*3^3

[sharp heart]

Yes, that's correct.

You can check by evaluating 2 * 3^3 and seeing if you get 54.

[mystic vessel]

yea ik ty

[mystic vessel]

im immortal

[mystic vessel]

immortal

but not rankup match

just unrated

.close

[trim jolt]

Channel closed

Closed by @mystic vessel

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic ore]

Menelaus theorem failed

<@&286206848099549185>

[dusky sleet]

EDA and EFB look like similar triangles

[trim jolt]

@arctic ore Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trim jolt]

@last sandal Has your question been resolved?

[trim jolt]

@last sandal Has your question been resolved?

[trim jolt]

@last sandal Has your question been resolved?

[high heron]

What is your question?

[last sandal]

idk where im going wrong

its something with the a & r

i know it diverges

[high heron]

I assume you're getting marked feedback? you have an error with the limit of the ratio too

[last sandal]

not really feedback it just says that its wrong

[high heron]

ok yeah I figured

the error is in the limit, not your a and r

[last sandal]

hm

i dont know how it could be something besides 1

i can try and type out what i did

[high heron]

your error is probably to do with the fact an has powers n, but bn has powers n**-1**

[last sandal]

oo possibly

i dont really understand why they even ask for the value of the limit when you only need to confirm if the limit exists or not

[high heron]

aka something in the denominator gets multiplied by 1/6, so the whole limit (should) get multiplied by a 6

[last sandal]

let me rework it real quick because 2-3 other problems are flagged wrong and they all boil down to geometric series

[high heron]

(this is a kind of weird question anyways because limit comparison is overcomplicating things)

[last sandal]

exactly

but i understand now

thanks for the help @high heron

i may have some more questions later but im gonna close this now

.close

[trim jolt]

Channel closed

Closed by @last sandal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy granite]

what does the delta x mean here..?

[dusky sleet]

it's just a variable, call it h if you want

[balmy granite]

oh ok thanks :))

.close

[trim jolt]

Channel closed

Closed by @balmy granite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slate crow]

i need some help with this

[slate crow]

i took the derivative of x(t)

and i think i need to get the critical points but im not sure how

x'(t)=4t^3-10t+2

oh wait am i supposed to u sub?

[sleek canopy]

no i don't think so

[slate crow]

what do i do then?

[gray rapids]

it says with calculator

[slate crow]

yea i got that answer with mathway but im not going to have mathway on the test

is gonna be some graphing calculator

that idk how to use

.close

[trim jolt]

Channel closed

Closed by @slate crow

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid thunder]

let f(x)=x^3 - 3x^2 + kx + 8 , where k is a constant. Find the values of k for which f(x) is an increasing function

[livid thunder]

well i got the derivative but im stuck with what to do next

[buoyant sluice]

essentially its asking

when is the derivative positive

[livid thunder]

yeah i get that

but im not sure how to show that

[buoyant sluice]

so find f'(x) and make that >0

ok what's the derivative

[livid thunder]

3x^2 - 6x + k

oh fuck

i gave the question as the derivative

nvm

im blind

ignore what i said

[buoyant sluice]

f'(x)=3x^2-6x+k

[livid thunder]

yuh

[buoyant sluice]

$3x^{2}-6x+k>0$

[solid kiln]

annyeong

[livid thunder]

yeah and how do i solve for k?

[buoyant sluice]

now

if a quadratic is always positive

it must have no roots right

[livid thunder]

ah i see

[buoyant sluice]

so consider the discriminant

and also consider the other condition of a in ax^2+bx+c is positive so a>0 too

you should get k>3 though, the a>0 actually isn't even necessary

[livid thunder]

i dont get the second condition

oh

[buoyant sluice]

dw about it but if it was something like 3kx^2 where k is also in the quadratic term then you need to consider that but here no need

[livid thunder]

aight

thx

.clsoe

.close

[trim jolt]

Channel closed

Closed by @livid thunder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp vine]

Can anyone help? which ones are wrong?

[sharp vine]

aaaaaaaaaaaaanyone?

[hazy panther]

@sharp vine what up bro

[sharp vine]

Ion geddit
Which ones are wrong

[hazy panther]

I can see a few which are wrong

[sharp vine]

yeah which and also how

[hazy panther]

Okay so bottom right, y = 4 + sin(x)

[split chasm]

show reasoning for each of your choices

[sharp vine]

yeah but how

like why

[hazy panther]

Have a look at the y axis

[sharp vine]

oh so it should vertically shift up 4?

[hazy panther]

correct

You also need to re think the way your functions have been shifted

[sharp vine]

man this is confusing

Alright lemme try one second

[hazy panther]

Just for insight, I'm in my 2nd year of uni and I did not truley understand it until my last year of highschool

[sharp vine]

damn. Okay Good to know i'm not completely f*cked then

[hazy panther]

Nah man you'll get it, it just takes a while to consolidate

I think all of you problems would be solved if you watched a youtube video

[sharp vine]

hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

any you reccomend specifically?

[sharp vine]

how do I find -4 + sin x then

[hazy panther]

https://youtu.be/bm8oYKKlCXI?si=kfUw-luaPihuGsle

I am more than happy to help for now

[hazy panther]

Okay so I would recommend starting at the y axis and find the line at which the function is going to oscillate around

Do you have any idea what that could be ? @sharp vine

[sharp vine]

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh nope

[hazy panther]

Alright so lets just start with a normal sin(x) function

[sharp vine]

it starts at x axis right?

[hazy panther]

What is the y value that it starts at when x = 0

[sharp vine]

also 0?

[hazy panther]

well yeah it starts at the origin (0,0)

So then where would sin(x) - 4 starts

knowing that sin(x) starts at y = 0

[sharp vine]

y = -4?

[hazy panther]

correct

[sharp vine]

ooo

correcto?

[hazy panther]

There ya go

[sharp vine]

oooooooooooooooooo

[hazy panther]

Can you sorta see how that works now

[sharp vine]

kiiiiinda yeah its starting to pick up on the ol' smooth brain

[hazy panther]

Lets do another one together

[sharp vine]

these two

soo the period here is (for the left side one)

x = pi/4

hm

[hazy panther]

Thats not quite the period

[sharp vine]

oh yeah right

8 is the period

[hazy panther]

the period is the what comes directly before the x

not quite either

[sharp vine]

isn't period like 2pi/b

[hazy panther]

Theres a fromula

yes

[sharp vine]

yeah so

isn't that what I did

[hazy panther]

Since 1 is the number infront of the x it would be 2pi

[sharp vine]

4*2pi/pi = 8

oh

[hazy panther]

What we are doing here is called a phase shift

Similar to what we would do for the function y = (x - 2)^2

[sharp vine]

ohhh

[sharp vine]

right right

phase shift

[hazy panther]

So cos(x - pi/4) shifts the whole function to the right by pi/4

[sharp vine]

yes

how do I check for that

[hazy panther]

It is simply by observing the function in that form

[sharp vine]

nah i mean like

how do I look for it in theseee

[hazy panther]

You pick one and tell me why knowing its going to be phase shifted to the right by pi/4

[sharp vine]

this one I think? Not sure why, its an educated hunch ig

[hazy panther]

Not quite

Actually wait

[sharp vine]

damb

[hazy panther]

Okay no thats not it

What you've picked there is y = sin(x + pi/4)

I suggested starting with the normal trig function and then applying the changes that you want

so start with cos(x) and then shift it pi/4 in the positive direction

[sharp vine]

hmm