help-38

[wraith hinge]

[knotty locust]

3*3=64?

[wraith hinge]

okay so i think you need to step back a bit

take a deep breath

and revise some of the earlier topics you studied

clearly your fundementals aren't sufficient to tackle such problems yet

ahhhhhh

i get it

8?

am i right

yes

okayyy

this is the example my teacher gave us earlier

i still don’t get it 😭

[trim lichen]

instructions not clear...

[wraith hinge]

what instructions? 🥹

[trim lichen]

the ones that your teacher didn't write, lol

apparently you were expected to expand (x+15)^2 and (y-1)^2

[wraith hinge]

ngl he's bad at explaining these

he also suggest to watch on yt if we don't get what he's saying

and he also don't explain it to us step by step he just put those numbers which made us confused

[trim jolt]

@wraith hinge Has your question been resolved?

[trim jolt]

@wraith hinge Has your question been resolved?

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@wraith hinge Has your question been resolved?

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[hot flare]

what problem are you getting?

[grave pagoda]

the doubt's solved

[hot flare]

The doubt is still pending I think

[grave pagoda]

that was not a proper question.

they just had to expand which was not even mentioned in the problem.

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@hot flare Has your question been resolved?

[grave pagoda]

.close

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[next night]

i don’t understand what i’m supposed to do for question number 3

[next night]

it just doesn’t make any sense w

[spring hull]

,rotate

[spring hull]

Are you allowed to use calculator for specific values of \theta?

[next night]

yes

[spring hull]

Alright then use the inverse trig functions to get the exact values of \theta

[next night]

?

im confused

[spring hull]

Inverse trig functions are arcsin, arccos, arctan etc

[next night]

yes

but how would i do that

when i only have cos

oh wait

i understand

[spring hull]

Good

[next night]

now that i have the angle

of 1.823

for the first point

how do i figure out the two angles on the unit circle tho

because i only have one

[trim jolt]

@next night Has your question been resolved?

[next night]

no

can i get some help <@&286206848099549185>

?

[toxic elbow]

?

[next night]

i’ve been stuck on the problem number 3

[toxic elbow]

im not good at trigonometry

[next night]

and i got the angle

[toxic elbow]

but i will look through it wait

[next night]

and i’m not sure how to get the other angles

[toxic elbow]

wait

[next night]

thanks

[toxic elbow]

send a pic on how much u have solved

@next night

lol i like ur username

[next night]

that’s what i have so far

for question 3 a

[next night]

lol thanks

[toxic elbow]

uh

tell me what u have done here

[next night]

i used the inverse trig function to figure out the exact radian angle of theta

but my question is telling me to find two angles

and idk what that means

[toxic elbow]

@mystic veldt

[toxic elbow]

yeh..

;-;

im sorry idk

if i get the answer i will mention u and send answer
so that u get the notification

[next night]

no it’s fine

if u can’t i can just ask my teacher tmrw

[toxic elbow]

yehh

[next night]

but yk i wanted to try myself

it’s fine thanks

.close

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[tranquil widget]

i had

[tranquil widget]

a small doubt

integral as infinite sum

i understand how the 3rd expression forms

by putting b=1 and a =0 but how does the 4th expression form?

[grave pagoda]

i think there's something written after 'where'

[tranquil widget]

here

i dont understand this

[solid kiln]

Dyssrupt

[grave pagoda]

we sub the bounds of summation in place of r

to get the bounds of integral

[tranquil widget]

why dont we have a b-a term in the 4th expression

like psi(x)-phi(x)/n

[grave pagoda]

how did you understand the 3rd?

[tranquil widget]

put b=1

a=0

so 1/n

and then a+ (b-a)r/n

would become r/n

is that wrong?

[grave pagoda]

.

[grave pagoda]

.

[grave pagoda]

.

[tranquil widget]

could u show it

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[swift thistle]

I would say so

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[clear ember]

Hey, my statistics is pretty bad but I got a simple question I think.
So there is a lottery with a Grand Prize every year, how likely is it that this prize will get drawn after 6 months already or only in 2 years or 3 years? No other prizes or multiple people, let's say just 1 x 1/365 chance every day.

[dull temple]

so there's a 1/365 chance every day that it gets drawn

and you want to know what's the chance that it gets drawn at least once in:

• 6 months
• a year
• two years?

[clear ember]

Correct!

Thank you!

[dull temple]

easiest way to do this is to think about the chance that it doesn't get drawn in that time

[clear ember]

Ah, so 1 minus something, right?
My naive thinking would be that half a year would be like 50% because, idk, just thinking and that is probably wrong xD

[dull temple]

which means it has to not get drawn every single day, so what's the chance that it doesn't get drawn on each day?

[dull temple]

yeah but if you think about like rolling a 🎲 6 times you won't always see a 4 one time

[clear ember]

364/365 is the chance!
But how do I translate that into months/years? xD
Sorry, Probability is not my strong suite

[dull temple]

yeah that's fine, so if the prize has a 364/365 chance of surviving every day

then the chance of it surviving for six months is just that to the 183rd power

(or however many days you think six months should be)

[clear ember]

LoL, can it be rly that simple, other stuff got me rly confused, like sometimes you multiply, sometimes you take the X power.
Gotta check my text book again!
Thank you!

[dull temple]

yeah probability is kind of tricky! it's often helpful to think about really small cases

so like imagine it were a 1/2 chance every day

that sort of thing

[clear ember]

KK, nice, will try that! 🙂

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[woven cave]

R my answers correct?
And also I need help with f(f(16))

[spring hull]

,rotate

[spring hull]

Yes your answers are correct

[woven cave]

What about f(f(16))?

Should the answer be 2?

[spring hull]

Yes

[woven cave]

Ok ty!

[wraith hinge]

i got a different answer

[woven cave]

Which question?

[spring hull]

?

[wraith hinge]

im going to check my work

[spring hull]

Don't worry your answers are correct

[woven cave]

Ok ty

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[mystic veldt]

100j_hat times t^2 = 200i_hat

[mystic veldt]

how do i find t?

[spring hull]

t is a vector?

[mystic veldt]

time

no

[spring hull]

No value of t can make this equality true

kx i_hat is not equal to y j_hat for any k in F

[mystic veldt]

that means i made wrong equation

[spring hull]

Yeah probably

[mystic veldt]

this was the ques 1

and this is what i did

i dont think i did anything wrong

you can just re check my vector calculation

and tell if i did something wrong

[spring hull]

Ahh you don't have i_hat and j_hat after the dot product

It's scalar product

So it should be -200 + 100(t^2) = 0

(a i_hat + b j_hat).(c i_hat + d j_hat) = ac + bd

[mystic veldt]

yeah now the ans is matching

[mystic veldt]

oh yeah, a vector dot product b vector is a.b cos \theta

[spring hull]

Yeah it's a scalar (element of a field)

[mystic veldt]

yeah got it now

thanks

.close

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[rustic drum]

i understand my problem with the second question but the first is stumping me

[nimble stone]

y is in thousands

if you divide everything by 1000 in the first 2 answers i believe youll be fine

[rustic drum]

what

i’m talking about the first problem

not the second i got that fixed

[nimble stone]

change 494000 to 494

[rustic drum]

why?

[nimble stone]

y is in thousands, so when y=494 that corresponds to a population of 494000

[rustic drum]

i’m sorry i’m not understanding what ur saying

could u please envision yourself explaining this to a 3rd grader

the starting point is 494000 why make it 494??

y=494000(10.3)^t

[nimble stone]

in the question, it says 'the population y (in thousands)', this means that a unit of y is 1000, for example if y=1, that means a population of 1000, if y=494 that is a population of 494000. So when writing out your equation for y, although the population at the start is 494000, in terms of y that would be 494 instead

actual population = y *1000

[rustic drum]

ohhhh so just 494

[nimble stone]

yeah

[rustic drum]

that clears up a lot of confusion

thank you so much!

[nimble stone]

no worries

[rustic drum]

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[hexed thunder]

I am currently working on part three and need a little assitance setting it up, but I would also like the first two parts checked as well

If at all possible

[stoic iron]

what is troubling you with setting up 3

[hexed thunder]

I think I am second guessing myself, but I think I also just set up the integral correctly based on the information that was given to me in the problem.

[stoic iron]

how did you set it up?

[hexed thunder]

dx

[stoic iron]

do you know the value of the function when c > x?

[hexed thunder]

I was only told that x>=c

[stoic iron]

indeed

so it wouldnt make much sense to try and integrate the function from 0

[hexed thunder]

I would need to integrate from c to infinity?

[stoic iron]

yep, thats the range on which the function is defined

[hexed thunder]

Darn it, I'll try it from there and come back if I get stuck.
Thank you for the help setting it up!

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[plush minnow]

how should i approach this problem

[neat vine]

remvoe all the powers of 10

like put them all on one side where you can ignore them for a moment

focus on the other ones

[plush minnow]

so i don't need to worry about them for now?

[neat vine]

Yes, for now

YOu have 4.3*3.1/5.0214

What does that gives you

[plush minnow]

2.654?

[neat vine]

Also, may I ask if you need to worry about significant figures?

[dull temple]

(you can do this because all we're doing here is multiplying and dividing; if we had any addition or subtraction going on that would be different)

[plush minnow]

this is scientific notation

[neat vine]

Ok, now deal with the 10

much easier now since you just add / subtract the exponents

[plush minnow]

so 9-3

then 6/5

?

[neat vine]

no

if the exponent is in the denominator you subtract

if it's in the numerator, you add

[plush minnow]

6-5

[neat vine]

it just so happen that the number you're adding is negative

Yes

[plush minnow]

so the answer is 2.654x10^1 ?

[neat vine]

Yes

[plush minnow]

oh ok thx

[neat vine]

actually

before you go

[plush minnow]

?

[neat vine]

The number you gave me is rounded up

Is that alright with you?

[plush minnow]

yes

[neat vine]

Ok

just checking

[plush minnow]

ye thats all

thx

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[pulsar jackal]

hi

[pulsar jackal]

i have my work and the homework question

im currently lost as to how those answers are even possible

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[frosty glacier]

I've no idea where to start

[trim lichen]

,rccw

[trim lichen]

angle CBD = 5pi/2??

the problem is botched

[frosty glacier]

Yes

[trim lichen]

how obligated are you to do it

cause i'd skip tbh

[frosty glacier]

How about if 5alpha/2

I think they mistyped

[trim lichen]

not your job to correct their typos

[frosty glacier]

No but suppose

If it is 5a/2 how do we do it

I still want to give this practice question a try

[trim lichen]

do you know how to find the area of a sector generally

[frosty glacier]

Yes

0.5r^2 theta

[trim lichen]

ew

why write one half in such a disgusting manner

[frosty glacier]

I don't know how to use latex

Or texit

[trim lichen]

why not write 1/2 r^2 theta

[frosty glacier]

Yes

[trim lichen]

or r^2 theta/2 for even less symbols

anyway

yes you are right

write out the areas of both sectors and equate the second one to 90% of the first one

[frosty glacier]

Like this right?

[trim lichen]

yes

[frosty glacier]

Alpha becomes 0

Oh wait I'm solving for r

Nvm

I found r

[frosty glacier]

How do I find alpha?

[trim jolt]

@frosty glacier Has your question been resolved?

[frosty glacier]

<@&286206848099549185>

[tame solstice]

hi?

[rain owl]

yes?

[frosty glacier]

...

[tame solstice]

question?

[frosty glacier]

...

[tame solstice]

k let's seee

[frosty glacier]

Oh wait my question is part b

<@&286206848099549185>

[rain owl]

bro

[tame solstice]

I guess u can figure it out by 2 methods

one is
The central angle subtended at the same pressure is twice the subtended angle

do u know that?

[frosty glacier]

I know that radius is 5

[tame solstice]

which radius ?
The small one?

[frosty glacier]

Oh wait I am showing wrong question

Imma open a new channel

.close

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[normal leaf]

Guys is this a function or not?

[normal leaf]

I know how to solve these but this one got me a bit confused

Because at the end of each line, it curves a little

[neat vine]

To me it looks like it fails the VLT

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Please don't occupy multiple help channels.

[jovial wing]

Already solved a, all working out is for b
I am not getting the same answer as the answer sheet
trying to figure out where I went wrong.
My thought was to find the sector CAB including the white triangle. Then minus the area of the white triangle.

arg whoops/

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[gilded kelp]

can someone make an equation of question 2

im confused

x-y=3.5?

and 2(x+y)=67

??

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[gilded kelp]

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[sage anvil]

Guys this 2 is equal?

[grave pagoda]

no

[sage anvil]

:3

chatgpt say it is

[grave pagoda]

chatgpt ahhh

[wraith hinge]

Dumb GPT

[lethal anvil]

Don’t rely on chatgpt too much for math. It’s often wrong

[sage anvil]

first result is my calculation

and second was chat gpt's

[grave pagoda]

send your work

[sage anvil]

this was original problem

w8 i take picture

1min

ok so

there is maximisation problem of max of π (profit) = p*y - wL(y) - rK <- ignored

so condition is derivation must be 0

and i calculate

this my result

[sage anvil]

🍷

im math noob?

or math pro?

[grave pagoda]

where is the question?

[sage anvil]

both chat gpt and photomath give me different result

i mean this is what i calculated

[sage anvil]

what question you think?

[grave pagoda]

the problem showing the fraction which you need to simplify

show me just that

[sage anvil]

hmmmmm

i dont understand

This is Labour as function of production

This is maximisation problem with first order condition that derivation of this all must be 0

I set problem like this

and this how i solved

guys

can someoen tell me

if i made mistake here?

or its nice?

chatGPT keeps confirming to me that its good

guys please :(II

😦

im dying to find out if my calculation is the truth

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[twin mortar]

How do I do this task?

[tidal finch]

this is j exponent rules

apply them

learn and apply

[twin mortar]

Is it right so far

,rotate

[twin mortar]

@tidal finch

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@twin mortar Has your question been resolved?

[twin mortar]

Anyone?

[trim jolt]

@twin mortar Has your question been resolved?

[tropic smelt]

Hello! Mmm what happened to 9x^2? also the multiplication in the denominator is wrong. x just multiplies 3

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@twin mortar Has your question been resolved?

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[wraith hinge]

Please help

I’ve tried everything but This division is too difficult for me
I get stuck after the two 11

I don’t understand long division I’ve watched a video and doesn’t help

[maiden zinc]

long division is lowkey hard

[wraith hinge]

Yea it’s confusing, in elementary I never learned

[serene mountain]

yeah, it's a lot of steps

[maiden zinc]

alright

u got the 157

[serene mountain]

I'd say first write out your 83 times table up to 9

[maiden zinc]

157-83

[wraith hinge]

Yeah

[maiden zinc]

is

74

carry down the 6

[wraith hinge]

OHHH

Is 74???

[maiden zinc]

?

[wraith hinge]

Oh wait ya

[maiden zinc]

157-83

is 74

so thats the step after

wait are you doing remainders

or decimals

[wraith hinge]

Remainder

[maiden zinc]

alright

so

you carry down the 6

so now you have 746

[wraith hinge]

Do I subtract 83

[maiden zinc]

how many times does 83 go into 746

[wraith hinge]

Oh

Uhhh

14?

[maiden zinc]

.

you know its less than 10

[wraith hinge]

Wait no

Yea my bad

[maiden zinc]

because 83 times 10 is 830

[wraith hinge]

9

[maiden zinc]

close

not quite tho

[wraith hinge]

Oh 8

[maiden zinc]

ye

so 746-664

is this all no calc?

[wraith hinge]

So then suptract that

[wraith hinge]

Yea

[maiden zinc]

damn thats just painful

ok so i would 80 times 8

with is 640

and then 3 times 8

which is 24

so 664

[wraith hinge]

Where does the three come from

Oh right

Sorry

[maiden zinc]

So 746-664

is what

[wraith hinge]

Is uhhh

132

[maiden zinc]

.

82

[wraith hinge]

Oooh

Wait what

[maiden zinc]

664+6= 670

670+30= 700

700+46= 46

46+30=76

76+6= 82

thats just how i would do that in my head

[wraith hinge]

Ooooh

Ok so 82

Bring the 3 down?

[maiden zinc]

ok so finally we carry down what?

yes

so 823

[wraith hinge]

Yes

[maiden zinc]

how many times does it fit

[wraith hinge]

And subtract

[maiden zinc]

this one is easy

[wraith hinge]

Oh

One

[maiden zinc]

10 times 83 is 830

so if 823 which is just below 10 then how many times

[wraith hinge]

Oh 8?

[maiden zinc]

.

[wraith hinge]

9

[maiden zinc]

yes

9 times 83 is what?

think

8 times 90

is 720

[wraith hinge]

Ye

That’s 103

[maiden zinc]

3 times 9 is 27

720 plus 27 is 747

[maiden zinc]

bro

.

[wraith hinge]

IM SORRRYY

[maiden zinc]

LOL

alright

so

823

[wraith hinge]

😭😭

[maiden zinc]

-747

is what

823-747

[wraith hinge]

103

[maiden zinc]

.

it has to be less than 100

[wraith hinge]

Oh ok hold on

[maiden zinc]

747+100 = 847

[wraith hinge]

83?

[maiden zinc]

no

close

little less

[wraith hinge]

Hold on I’m gonna like write down subtracting it

76

[maiden zinc]

yes

[wraith hinge]

Huzzuh

[maiden zinc]

now u have nothing else to pull down

so thats ur remainder

[wraith hinge]

11 R76?

[maiden zinc]

1189?

[wraith hinge]

Thx so much bro

[maiden zinc]

the other two digits dont drop

[wraith hinge]

Oh wait what

Where did the 89 come from

[maiden zinc]

.

[wraith hinge]

I’m sorry

Ok so then 76

[maiden zinc]

no

76 is your remainder

[wraith hinge]

Ok

How did I get 89

[maiden zinc]

remeber the 746-664

we did

[wraith hinge]

Ohhh yea

[maiden zinc]

and how 83 goes into 746 8 times

and how it goes into 823 9 times

[wraith hinge]

Oh ok so it’s correct now

I’m a genius!! Yipee! Huzzah!

[maiden zinc]

ye good work

👍

[wraith hinge]

One more question sorry

If it’s allowed

I just don’t understand like how u get the x and stuff

Like uuuh

I don’t even understand this

So do I like uhhh

On C do I multiply 867 by 289

[night zodiac]

Knowing your times table is useful

[wraith hinge]

Yea I kinda do

[night zodiac]

No

[wraith hinge]

I know 9x9

[wraith hinge]

I don’t actually nvm

[night zodiac]

For C and G, you can do long division, or if you know your times tables, you can make guesses

[wraith hinge]

Oh ok opposite operations

[night zodiac]

And D and H you can just use multiplication

[wraith hinge]

So like 40x 15 for D?

[night zodiac]

Yeah

Because it's remainder 0

[wraith hinge]

Ooooh ok

[night zodiac]

I can already tell you B and E are wrong

[wraith hinge]

Aw dang it

Thank you

[maiden zinc]

673-914

would give you a negative number

[wraith hinge]

Oh

I’m sorry for being terrible in math

In elementary and middle school I would get bullied everyday and it was extremely hard to concentrate

And now picking it back up is difficult too

But I’m trying really hard now

[maiden zinc]

you arent bad

673-914 is negative 241

[serene mountain]

so long as you're making a genuine effort and don't get frustrated, that's all we ask

[wraith hinge]

So for b, would I add 673 and 241?

Opposite operation?

[night zodiac]

No it's much easier than you think

3 minus what equals 1?

[wraith hinge]

1

2

2?

[night zodiac]

Yes 3 - 2 = 1

That means the ones digit is a 2

Apply that logic to the tens place

7 minus what equals 4?

[wraith hinge]

3

[night zodiac]

Now the hundreds, 6 minus what equals 2?

[wraith hinge]

4

[night zodiac]

So your answer for B is?

[wraith hinge]

431?

Damn, it is really that easy? My answer was completely off

2 I meant

[night zodiac]

And you can check it, check and see if 673 - 432 = 241

[wraith hinge]

Wow that is easy..

Thank you for teaching me that

[night zodiac]

For C, it's easy too, you don't really need division

You have the work given that makes it easy

Do you understand the concept of multiplication?

[wraith hinge]

Ahhh define the concept of it

Like
I know how it works

[night zodiac]

Basically the process in C

[wraith hinge]

Like I’m just not great at big numbers

[night zodiac]

If you had all the numbers given

Where you do the ones digit of the multiplier times the multiplicand, then you add that zero, then do the tens digit of the multiplier, and so on

[wraith hinge]

Ok hold on let me try this

Hhhhuh

I multiply these two?

[night zodiac]

No

Do you understand the concept of multiplication?

[wraith hinge]

I don’t think so

Not multi digit that much

[night zodiac]

That process

Where I took the ones digits, multiplied them, and if it's greater than 10, then you write down the ones digit, carry the tens. And if you have a two digit number, you add in that padding zero (blue zero)

And continue that process

[wraith hinge]

Ok uuuuh

[night zodiac]

Do you understand that process?

[wraith hinge]

Sorry

No I don’t

[night zodiac]

https://www.youtube.com/watch?v=yiZ3r9T_OJs&ab_channel=MathwithMr.J

I suggest viewing that

[wraith hinge]

Yea I know multi digit, I’m not sure how to incorporate it into the question

Because the numbers you multi digit multiply by are xx

[night zodiac]

That's what I was asking, do you know the concept of multiplication

[wraith hinge]

Yes

If it’s multi digit I know how to, but I will review the video in case

[night zodiac]

Because what I'm trying to point out is the green circles are related to each other, correct?

[wraith hinge]

Yea

[night zodiac]

So for the green circle, 9 times what would result in a potential 7 in the ones place?

[wraith hinge]

3? Cause 27

[night zodiac]

Yes

[wraith hinge]

YIPEE

[night zodiac]

Now same process for the red circle

9 times what would result in 6 in the ones place?

[wraith hinge]

9x4=36

[night zodiac]

So what do you think those x's would be now?

[wraith hinge]

76

[night zodiac]

Where did 76 come from?

You said 3 and 4

[wraith hinge]

Because the ones place for 7 and 6 and you put them together I don’t know

Ooooooopoh

It’s 34?

[night zodiac]

Not quite

[wraith hinge]

Math hurts my brain sometimes

😞

[night zodiac]

The green circle was where we started first, and I asked 9 times what would result in a 7 in the ones place, and you said 3, that green circle is the ones place, therefore 3 is in the ones place

[wraith hinge]

Oh ok and now I need to figure out the tens place

[night zodiac]

You already did

[wraith hinge]

Oh

[night zodiac]

.

[night zodiac]

.

[wraith hinge]

363?

Or 63

[night zodiac]

No

[wraith hinge]

OH

ITS JUST 3

there’s one x

[night zodiac]

It was the same process for the green circle that we did, but applied to the red circle

There's two x's

[night zodiac]

.

[wraith hinge]

Uuhhh oh your right

[night zodiac]

What digit should the tens be?

[wraith hinge]

36

[night zodiac]

No

9 times what would result in 6 in the ones place?
The "what" represents the x

What did you say the "what" was?

[wraith hinge]

3

[night zodiac]

No

Reread that

[wraith hinge]

No wait

Yeah

Hold on I gotta rewind

4

So the sends would be 4

And ones 3

So it’s 43?

[night zodiac]

Yes

And you can check the math

[wraith hinge]

YIPPPE!

[night zodiac]

Do 289 x 43 to check

[wraith hinge]

Okokok

Omg

Ur so smart

I aspire to be you

Ok now I need to use that same process for g

So would it be 2x4 for the ones place

So 8

[night zodiac]

That one is a slightly harder process

[wraith hinge]

Then 7x2 14

So 148?

Argh it’s not

So confusing

[night zodiac]

Tbh for that one, it might be easier to do the long division with 36864 and 72

[wraith hinge]

Ok I will do that

Crap I put the wrong 30000 number whoops

I don’t think I did this correctly

[night zodiac]

No you did not

That's what you have as the beginning, correct?

[wraith hinge]

Yes

[night zodiac]

So can 72 go into 3?

[wraith hinge]

Nope

It can go in to 368 4 times

[night zodiac]

If you do 72 * 4, what do you get?

[wraith hinge]

288

Wait one more time

It can go 5 times

For 360

[night zodiac]

So now you have something like this, right?

[wraith hinge]

Yes

Subtract the 368 and 360

Bring down 6

86

I always mess up after this

And then I have no idea what to do

[night zodiac]

You repeat that process with that "new" number

How many times does 72 go into 86?

[wraith hinge]

1 time

[night zodiac]

So you write one at the top

[wraith hinge]

Yup

Then 72x51?

[night zodiac]

72 under the 86

[night zodiac]

No

[wraith hinge]

Ohh

It’s 144 after bringing down

[night zodiac]

You take that digit, the amount times it went into that number times 72

[night zodiac]

How many times does 72 go into 144?

[wraith hinge]

And then 72 goes in twice

2x 72 is 144?

[night zodiac]

Yes

So you write the 2 at the top

[wraith hinge]

And no more numbers to bring down

[night zodiac]

144 at the bottom

[night zodiac]

Subtract the two, first, before do this step

[wraith hinge]

Oh ok so

72x2

Then subtract by 144?

[night zodiac]

You write the 144 at the bottom, underneath the 144

Subtract the two

[wraith hinge]

And 0 is my remainder

[night zodiac]

Yes, so the number at the top is your answer

[wraith hinge]

Thank you so much.. I think I finally understand long division

So then, for xxx my answer is 512?

[night zodiac]

Yes

[wraith hinge]

Tusk

Tysm *

I have one more equation on my sheet, it’s in division

I’ll try on my own and then text if I need help

[night zodiac]

Try that and send your work

[wraith hinge]

Okay

I’m close but I missed something in the tens digit

But, I am getting better

And I am very grateful, thank you

[night zodiac]

Why did write 2 in the tens place, in your answer but you wrote 21 at the bottom? Because 7 x 2 = 14, not 21

[wraith hinge]

Yeah

I guess I did it too fast

But I do understand long division now, for the most part

I just need to practice more

This next question confused me but I think i understand it

3572 divided by something (xx) will give me 63 with a remainder of 44

[night zodiac]

It's a bit easier than you think

[wraith hinge]

This sheet is due tomorrow, along with another one 😪 I don’t know what to do.. the school week has just begun and I’m behind in math

[wraith hinge]

Really?

[night zodiac]

You remember the process of long division, on taking the number to the very left (in that practice problem I gave, it was the 7) and you multiply it by that digit at the top?

[wraith hinge]

Yeah

[night zodiac]

Then you write that result on the bottom

You have 336, which digit at the top what used to multiply for 336?

[wraith hinge]

63?

[night zodiac]

Which digit from the 63 was used to multiply with the divisor to get 336?

[wraith hinge]

6?

[night zodiac]

Yes

So that means 6 times the divisor got 336

So that means you can do 336 divided by 6 to get that divisor

[wraith hinge]

So do I divide it

Yes

Yay

It’s 595?

[night zodiac]

No

[night zodiac]

.

[wraith hinge]

Oh right!

Thanks so much

I understand now, I will just need to practice more often

Could I screenshot these messages for future reference?

[night zodiac]

Sure

[wraith hinge]

Thank you

I only have 8 questions now, which is using prime factorization

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[cunning trench]

what have you done so far

[wraith hinge]

All I did was times the 8 3 times

Where I got 513

[cunning trench]

ok so what is the area of the right hand square

can you work it out?

[unkempt dagger]

heey guys

i know this is a maths server

[wraith hinge]

Heyy

[unkempt dagger]

but i need a little help with physics

[wraith hinge]

Your in the wrong channel

[unkempt dagger]

alr

then where can i get help for physics

?

[wraith hinge]

#help-31

Go to help forum

[unkempt dagger]

thanks

[wraith hinge]

513-233

280

@cunning trench

[cunning trench]

you shouldnt need the 513 (idk how you calculated it)

233 is the total area of the small and large square added together

the small square you work out by doing length times width

so 8 x 8

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@wraith hinge Has your question been resolved?

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[real saddle]

Can someone help show how to get 5/8 from (5 * 1/2c)/4

I'm really not sure how they get to this conclusion

[trim lichen]

5 * 1/2 * 1/4 = 5/8

[real saddle]

feel like im missing something here

trying to do the same thing with 2pi/3 i get it wrong

[trim lichen]

wym "same thing"

is that a different problem? show the new problem.

[real saddle]

if i replace pi with 1/2c as i did here and do

(2 * 1/2C)/3
2 * 1/2 * 1/3

same problem different numbers

[trim lichen]

simplified

[real saddle]

wlep

i just went thro the entire text and they never showed how to do this

math makes me sad

ty tho

[trim lichen]

never showed how to do what?

simplify fractions?

[real saddle]

find the fraction of the circumference of the unit circle

[trim lichen]

you talk about this as if it is a special procedure specifically for circles

it's not

you know that the circumference of a full circle is 2pi

what fraction of 2pi is 2pi/3

does the answer not lie on the surface

[real saddle]

not to me no

[trim lichen]

what fraction of 2pi is 2pi**/3**

[real saddle]

fractions is one of the hardest things in math to me lul

ah thats true

[trim lichen]

sounds like you need more practice with fractions specifically

[real saddle]

i do but unforunately i do not have said time for that between all my classes

[trim lichen]

💀

[real saddle]

sooo i tried doing sin (12/13) in the calculator got 0.797

seems like it wants a fraction what steps am i missing?

[trim jolt]

@real saddle Has your question been resolved?

[real saddle]

found it im crazy

ty for all the previous help

.close

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
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[hot thistle]

https://cdn.discordapp.com/attachments/1149351347032965132/1149351347171373076/7ED3B275-139F-4DB5-99B4-750BA65CE5E9.jpeg

[hot thistle]

how do i completely solve this?

i know i need to set up the resulting vector but i dont know how to actually set it up

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@hot thistle Has your question been resolved?

[sand obsidian]

Do you know how to calculate weight from N?

anyway you have the force, 20N, you have the angle of 37. You can calculate the horizontal force by F*sin(angle)

use that and the gravity to get N

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

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[oblique perch]

So When I was doing this question. I assumed that every letter can be used one. Which means, even the repeating are allowed to be used, thus giving us a total of 7 letters to use. With that in mind, I did the quesion in 2 cases.

Case 1: 4 Letters

7x6x5x4 = 840

Case 2: 5 Letters

7x6x5x4x3 = 2520

But the answer to the whole question is 1800. I dont get how it would be one answer, and even if that was the case, how it was acheived

[crimson pebble]

The problem here is you have to factor in the two Es

Because ACHE and ACHe are the same (Es are in different cases for emphasis)

[oblique perch]

so, 7!/(2!)? type of format

[crimson pebble]

Yeah sorta

You’ll probably need casework as to the amount of Es in your words

[oblique perch]

hmm, ok one sec

[nova spire]

the question becomes easier once you start with the amount of words that can be formed with A C H I E V E'

where E' is a different letter

[oblique perch]

7! ?

[nova spire]

And then consider when E and E' are both used

[oblique perch]

7! / 2! ?

[nova spire]

not of length 4 or 5

[oblique perch]

oh, like 4! / 2! vs 5! / 2!?

[nova spire]

Uh let's start with a different question

So how many words of length 4 can you make with the word A C H I E V E' ?

[oblique perch]

765*4 = 840

assuming the 2 e's are sepearte

[nova spire]

yes exactly (put a backslash \ before * to stop it from making italic)

[oblique perch]

okok

[nova spire]

So

out of those 840 words, how many use both E and E'?

[oblique perch]

ummm... do we divide by 2?

[nova spire]

not now

[oblique perch]

2/7 of tyhe words?

im like blanking. But i need to understand for an exam haha. Let me see:

840 words.
2 E's
7 words.
2/7 of the words will have both?

okok

okok

[nova spire]

No you're right it's 2/7 my bad

[oblique perch]

okok

[nova spire]

Oh sorry I'm having it the wrong way around

How many words have at least E or E'?

[oblique perch]

840 words
Case 1: 1 E, meaning 1/7
Case 2: 2 E meaing 2/7?

[nova spire]

1 E is not 1/7 here

So actually it's easier to consider first how many words have neither E nor E' in them

[oblique perch]

alright let me wrtite this down and try

woah woah woah haha

let me see how you got this, stats making me confused

[nova spire]

I think I'm not in my right mind today XD

It's 1/7 sorry

(5 x 4 x 3 x 2)/(7 x 6 x 5 x 4)

[oblique perch]

huh

[nova spire]

is this better?

[oblique perch]

but whats the asnwe?

[nova spire]

Well 120 words are made without E nor E'

So 720 words are made with at least E or E'

[oblique perch]

so 840?

for 4?

fyi, the answr is 1800

[nova spire]

that's the final answer with length 5 as well, we're not here yet

Ok

So out of the 720 words with at least E or E' in them

we can swap E by E' and vice versa and get back to the "same" word

[oblique perch]

ngl, i got 840 originally for 4 letters as well

ok

swapping will do what?

make it, one E?

[nova spire]

So when we don't distinguish E and E', we're overcounting those words exactly once

So there are exactly 360 words we can make with at least one E

is this part alright for you?

[oblique perch]

yes

[nova spire]

Alright, so the real total number of words of length 4 is?

[oblique perch]

we want to make sure its not overcounting

well, if the total is 840 by overcounting, then 420?

or 360 for single E

im actually lost haha

[nova spire]

no, this is missing the point of what we just did, the other 120 words aren't overcounted!

120 + 720 becomes 120 + 360

[oblique perch]

ye, thats what I wrote

oh wait

480

[nova spire]

exactly!

[oblique perch]

and then repeat for 5 letters?

[nova spire]

yep, the same thing applied for 5 letters, ping me if you're having trouble reapplying the same logic

[oblique perch]

ok thanks

i will try

wel, the second part will be 600 + 720

[nova spire]

I don't think this is it for length 5

[oblique perch]

would it not be 600