#help-38

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last junco
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it said

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x,y are integer

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x+y+xy=23
x^2y+xy^2=126

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the question

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i finally got the ans

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but still thanks for these tips

last junco
tepid rock
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Yes, mention every one of those details next time you ask any question.

last junco
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thx

tepid rock
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.close if done

last junco
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not rlly

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i hv another question

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its a little hard

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do u get any idea for it

last junco
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pliant warren
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how do i prove inequalities by induction?

pliant warren
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mental lodge
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mental lodge
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Can someone tell me how to solve this problem?

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<@&286206848099549185>

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mental lodge
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<@&286206848099549185> pleases'

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molten pollen
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hi

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molten pollen
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idk how to attempt number 1

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and im confused on whether I integrate for number 2 or something

cursive musk
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might want to charge your battery

molten pollen
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lol

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true

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oh hey

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its you again

cursive musk
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yep

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so theres a neat trick you can do here

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dx and dy can just be numbers

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so you can multiply them

molten pollen
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i got that part

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but how do I find the t value for 1

cursive musk
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well thats the whole idea

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dy/dt / dx/dt = dy/dt * dt/dx = dy/dx

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now you know dy/dt and dx/dt

molten pollen
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aight I got it

molten pollen
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cuz its not given by a dy/dx but it says velocity vector and position

cursive musk
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ah

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so youre given v

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and an initial condiiton

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so you need to integrate from t = 2 to t = 6

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and add that to f(2)

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do each component seperately

molten pollen
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precisely my issue

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why add it to f(2)

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iv never understood that

molten pollen
cursive musk
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because we are integrating from 2 to 6

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the integral is the change in value

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so it ends up being f(6) - f(2)

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but we want f(6)

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so we need to tell it to add the change in value to the original value of f(2)

molten pollen
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okay

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so because ftc

cursive musk
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ye

molten pollen
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and the integral = to f(6)-f(2) so we add f(2)

cursive musk
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ye

molten pollen
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how did I never learn this tho 😭

cursive musk
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are you surprisingly ahead

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4 years of the average american student

molten pollen
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yea but I take the class in school

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so I still need to pass the ap exam

cursive musk
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you dont have to

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itd be great if you did

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but you can always retake the class next year

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you have that cushion

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naive berry
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Hi I have a trigonometric question specifically about finding the angle of a right triangle

naive berry
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My teacher’s answer for the angle is completely different from mine the answer being 49.6 degrees

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I find the missing value for the opposite angle

wraith hinge
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do you know what sin, cos and tan are?

naive berry
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Yes

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I should take another picture of my work

wraith hinge
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Let's first think about which sides of the triangle we know

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opposite, adjacent, and hypotenuse are used in trig calculations

naive berry
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Ouch it’s vertical

wraith hinge
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.rotate

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,rotate

solid kilnBOT
wraith hinge
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there we go

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@naive berry there's an easier way to go about this than that

naive berry
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The teacher’s answer was 49.6 degrees but I kept on getting 86 degrees

wraith hinge
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so we have the hypotenuse and the ajacent side

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you don't need to solve for the unknown side, there's a different trig function from sin that you'd use

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sin cos tan, do you see which one it is?

naive berry
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I don’t see one aside from sin

wraith hinge
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ah

wraith hinge
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you should memorize this

naive berry
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So it would be

cosine theta = (24/37)

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Theta=arccosine(24/37)

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I’m still getting 0.86498

wraith hinge
naive berry
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ARE YOU SERIOUS

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IVE BEEN USING RADIANS

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THIS ENTIRE TIME

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Thankyou

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weak orchid
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how can i do this with angle sum and difference formulas

weak orchid
heavy lion
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use $\tan (a - b)$

solid kilnBOT
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bettim

stark bison
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Note that 1/12 is just 1/3 - 1/4

weak orchid
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ohh ok

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umbral maple
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i know it science but it math

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umbral maple
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(the one i ticked was wrong)

sweet hare
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,rccw

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fiery sleet
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Can smn help how we achived this

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fiery sleet
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4xy, 0 <x< 1, 0 <y< 1,

hallow spruce
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try drawing the region x<y on the xy plane

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@fiery sleet Has your question been resolved?

fiery sleet
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is there a video resource or smth for it

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i have no idea how to do so

hallow spruce
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probably but I don't know one

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just draw the line x=y and identify the region below that

fiery sleet
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._.

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umm

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wait

hallow spruce
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yes

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now try to convince yourself why that gives you the double integral given in the solution

fiery sleet
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dx's lower limit would be 0 right but how come its upper limit is y but for y its 1 šŸ¤”

hallow spruce
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for any value of y, x can take on values in the interval [0,y)

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since that's what x<y means

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(and obviously both x and y are constrained to (0,1))

fiery sleet
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okiewww

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fathom meadow
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fathom meadow
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can someone help me on how he finds the B value

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here

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Like the 2pi/b = 8 -> B = PI/4

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I replayed the part as much as I can

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but can't understaand

harsh berry
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2pi/B = 10/3

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@fathom meadow Has your question been resolved?

fathom meadow
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what is that

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like I dont understand what 2pi/B is

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or 10/3

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like I dont understand what he means by period

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I thought period was the Y value(the thing he marked in dark blue)

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that was average between the largest and smallest Y vlue

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surreal eagle
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i know its a little messy but is this right?

surreal eagle
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if it loads

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specifically the last two steps

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can i divide an n from (n/(n+1))^n

dusty hound
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the last step is wrong

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(1+1/n)^n doesn't go to 1

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it's probably a limit you know though

surreal eagle
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e?

dusty hound
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yes

surreal eagle
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ah, little mistake then. thank you!

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.close

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gleaming turret
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Ive noticed that if you pick random vectors under magnitude x, and plot them out on a grid with a spacing of 1, with all of them coming from the origin, and you take the average amount of grid lines they pass through, call this f(x), if you then take f(x)/x and limit x to infinity then it converges to 8/(3*pi). Why would this be?

green sand
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the number of grid lines the 2-d vector (x,y) passes through is floor(x) + floor(y)

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in the limit we don't need to consider the floor functions

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then paramaterise the vectors by their angle, scale them down to the unit circle to account for your division by x, and integrate over theta

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sorta

gleaming turret
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Unrelated but is there likely to be an elementary solution to f(x)?

green sand
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what do you mean

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f((x,y)) = floor(|x|)+floor(|y|)

gleaming turret
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I mean f(x) as the average amount of grid lines vectors under magnitude x go through

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Not the amount of grid lines an individual vector goes through

green sand
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there's an integral expression for it

gleaming turret
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I know, ive also found an infinite summation for it, but im just interested in seeing if there is a nicer solution

green sand
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well since you're summing stuff like floor(ksin(x)) I very much doubt there would be

gleaming turret
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Ah thats annoying

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I found an infinite summation by doing an integral from a to a+1 of sqrt(x^2 - a^2) which is easily solvable, and then doing a summation mulitipled by a of that from 0 to infinity which real part is the amount of vertical lines it passes through in a quarter so you take away the imaginary part and then multiply it by 8 and divide it by the area

green sand
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the annoyingness is self imposed as you're just looking at the x-distance and y-distance when you're looking at the number of gridlines

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you're just looking at the area of a circle ultimately

gleaming turret
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i forgot to type in multiplied by a

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if you multiply each column by a which increases as the summation goes up then it works like the gridlines

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so it works out each 1 wide columns area with the integral and multiplies it by a which goes up each time

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.close

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kind iris
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Hello. How do I turn this
$$\frac{\left(x^{2}+x+1\right)^{2}-2x\left(x^{2}+x+1\right)}{\left(x^{4}+x^{2}+1\right)-2x\left(x^{2}-x+1\right)}$$
into this
$$\frac{\left(x^{2}+x+1\right)^{2}}{x^{4}+x^{2}+1}$$

solid kilnBOT
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lmaowhat

kind iris
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I am pretty sure they are equal

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I just need to do some manipulation to convert it (the top one) to that (the bottom one)

severe wave
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try and assign a new variable to each polynom and see what changes from top to bottom

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and when you have a more visible fraction see if you can reverse what was simplified

silent canyon
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why do you think they are equal?

kind iris
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It could be that it was a coincidence but I don't think so

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This is not the actual problem

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I have to prove that $\ln\left(\frac{x^{4}+x^{2}+1}{\left(x^{2}+x+1\right)^{2}}\right)$ is an odd function

solid kilnBOT
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lmaowhat

kind iris
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(a - b)/(c - d)

kind iris
cosmic meadow
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((x^2+x+1)^2 - 2x(x^2+x+1)) = x^4+x^2+1
((x^4+x^2+1) - 2x(x^2-x+1)) = x^4-2 x^3+3 x^2-2 x+1

is (x^4+x^2+1)/(x^4-2 x^3+3 x^2-2 x+1)
the same like:
(x^4+2 x^3+3 x^2+2 x+1) / (x^4+x^2+1)?

(x^4-2 x^3+3 x^2-2 x+1)(x^4+2 x^3+3 x^2+2 x+1) = x^8+2 x^6+3 x^4+2 x^2+1
(x^4+x^2+1)(x^4+x^2+1) = x^8+2 x^6+3 x^4+2 x^2+1

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Yes, they are the same

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Hint: When you want to know if 2 fractions are equal, cross multiply will give you the solution.

kind iris
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I mean

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I don't think you're supposed to do this

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It can be shorter

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It's an objective question and is supposed to be answered in around a minute

cosmic meadow
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probably, but it doesn't take more than 1 minute

kind iris
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That's true

cosmic meadow
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i would do this way for sure, it's 6 lines

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findng a way to make a transformation looks harder and would require to think more

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i would call that more like a clean way to solve, not faster

kind iris
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Oh

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Lol

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I'm done

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I found a way better way

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$\frac{x^4+x^2+1}{(x^2-x+1)^2} = \frac{x^4+x^2+1}{(x^2+1-x)^2} = \frac{x^4+x^2+1}{(x^2+1-x)^2} \cdot \frac{(x^2+1+x)^2}{(x^2+1+x)^2} = \frac{(x^4+x^2+1)(x^2+1+x)^2}{\left[(x^4+1+2x^2) - x^2\right]^2} = \frac{(x^4+x^2+1)(x^2+1+x)^2}{(x^4+1+x^2)^2} = \frac{(x^2+x+1)^2}{x^4+x^2+1}$

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Wasn't that long after all

solid kilnBOT
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lmaowhat

kind iris
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Just had to multiply by its conjugate

kind iris
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Thank you for your help

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cerulean hearth
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I don't get why E is a sub vector space of R^R and not just R

marble wharf
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E consists of functions

cerulean hearth
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ye and

marble wharf
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R consists of numbers

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how should E be a subspace

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its not even a subset

cerulean hearth
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because a vect is a vector space

marble wharf
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and?

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its a vector space spanned by those three functions

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but that doesnt mean that those functions are suddenly numbers

cerulean hearth
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and what would be the sub vector space then

marble wharf
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hmm?

cerulean hearth
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if a function is R -> R
the sub vector is R for me, seem logical

marble wharf
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there is a copy of R inside R^R, the constant functions

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but otherwise you are talking nonsense

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do you mean that the vector space is over the field R?

cerulean hearth
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well when i'm talking of sub vector space of R that mean that the vector space of E is inside R

marble wharf
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for that it first would need to be a subset

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which it is not

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the element of E are functions

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they are not numbers

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they are not included in R

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E is not a subset of R

cerulean hearth
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well that's true

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but what it is so?

verbal gulch
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why are you calling it a sub vector space instead of a vector subspace

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unless you actually don't mean it?

cerulean hearth
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no i mean it

verbal gulch
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are you talking about a vector subspace or something else?

cerulean hearth
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hum e.g E = {(x,y,z)€R^3, x = y +z}
are you calling that a sub vector space of R^2 or a vector subspace of R^2

marble wharf
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thats not even proper set notation

cerulean hearth
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now?

marble wharf
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no

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yes

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that would be a subspace of R^3

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because its elements are in R^3

cerulean hearth
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and what's a sub vector space then

verbal gulch
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I don't even know what you mean by a "sub vector space"

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do you mean vector subspace or not

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that's what I've been trying to ask

cerulean hearth
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that's what i'm trying to clear

verbal gulch
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huh???

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I'm asking you about the definition of some weird terminology you're using

cerulean hearth
verbal gulch
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how am I supposed to know what it means

cerulean hearth
verbal gulch
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In mathematics, and more specifically in linear algebra, a linear subspace or vector subspace is a vector space that is a subset of some larger vector space. A linear subspace is usually simply called a subspace when the context serves to distinguish it from other types of subspaces.

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this tells you what a vector subspace is

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is that the same thing as what you call a "sub vector space" or not?

cerulean hearth
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yes

marble wharf
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they clearly mean that

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dont put too much attention on that word swap

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could come from translation or something

verbal gulch
cerulean hearth
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i used vector sub space on this serv and they were not any misunderstood so i thought that was the good term

verbal gulch
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vector subspace or linear subspace or just subspace is common terminology

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but sub vector isn't

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sometimes people say things that seem like they're something, but they turn out to be completely different

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in any case, a very succinct definition of a subspace is some set that is a subset of a vector space and is a vector space in itself

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your E is not a subset of R, and therefore it cannot be a subspace of R

nova spire
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eh, in french it's called "sous-espace vectoriel" so literally sub vector space

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not every language is english-centered

verbal gulch
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yeah sure, but if you say it in English, then it's weird

nova spire
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so we must forgive him

cerulean hearth
marble wharf
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you really are focusing on the wrong thing. I've seen some people mess terminology up way worse

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R^R is the space of all functions R->R

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that is what that notation means

cerulean hearth
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ok it's just that

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thx

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civic basin
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civic basin
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i started by x = sin theta substitution

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then i got here and im stuck

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need help on how to continue this integral

wraith hinge
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you can get away without doing trig sub here

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try using u=(1-x^2)

civic basin
civic basin
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sry for pinging alot btw

wraith hinge
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what did you get to?

civic basin
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is it readable

wraith hinge
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looks fine

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so we have $-\frac12\int \frac{\sqrt u}{\sqrt{1-u}^5}du$

solid kilnBOT
wraith hinge
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hmm lemme think

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,w int sqrt(1-x^2)/x^4

granite cove
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That looks much harder than x = cos u

civic basin
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lol

wraith hinge
civic basin
granite cove
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Right from the beginning

civic basin
granite cove
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Can you try it?

civic basin
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alright ill try

granite cove
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Yes. What's sin/cos?

civic basin
#

tan^2 theta / cos ^2 theta

granite cove
#

Note that (tan x)` = 1/(cos x)^2

civic basin
#

oooohh

#

wait let me see if i can continue from there

#

this makes this integral - u^2 du

#

is the final answer - (tan theta )^3 / 3

#

how to check

granite cove
#

Now you can sub back I think

civic basin
#

doing the triangle of x = cos theta

#

tan theta = sqrt(1-x^2)/x

civic basin
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echo jasper
trim joltBOT
echo jasper
#

should i add the 3

#

on the other side first

#

and make it (x+1)^2+3?

#

btw i am graphing

knotty locust
#

Don't open multiple channels for the same question, next time stick to your original channel

echo jasper
#

or find vertex first and not do that

#

I close it

hollow bloom
#

Add the 3??

echo jasper
#

other one because i change this question

knotty locust
#

This is the same question

#

Either way, you can stick to the same channel

echo jasper
#

I close the other channel

knotty locust
#

In the future I mean

echo jasper
#

Is ok

knotty locust
#

Anyways, if you are trying to graph this function you need to find its vertex

echo jasper
#

I wont make it again

knotty locust
#

do you know what vertex form of a quadratic function is?

#

Actually, I'll start by asking if you know what the vertex is

echo jasper
#

yeah we get the -k and h right

knotty locust
#

Like this

echo jasper
#

o -h and k

#

ok

knotty locust
#

Where (h, k) is the vertex

echo jasper
#

yep

knotty locust
#

So for your question here, it is already in vertex form

#

can you find what the vertex is?

echo jasper
#

is -1,0

hollow bloom
knotty locust
#

Yes the vertex is (-1, 0)

#

Now, do you know if the graph is opening up or down?

echo jasper
#

is down

knotty locust
#

Yes

#

because "a" is -3, which is negative

#

so it opens down

#

Can you graph it now?

echo jasper
#

So to graph it

#

i make table first?

#

or just plug -1 in x

knotty locust
#

you just have to know some sample points to graph it

echo jasper
#

ok

knotty locust
#

so start with labeling the vertex

echo jasper
#

ok

knotty locust
#

which is at x=-1

echo jasper
#

ok labled that one

hollow bloom
#

You just plot points such as x intercept y intercept then draw a curve through them

echo jasper
#

so i pick them

#

from the left of the vertex and right of vertex right

knotty locust
#

yes

echo jasper
#

like if i picked -2 as an X i just plug it like this one -3(-2+1)^2

knotty locust
#

yes

#

and that tells you the y-value of the graph at x=-2

#

so you could then plot that point

echo jasper
#

Ok nice thank a lot for assist

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#

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rich mason
#

The number of students at a school increases by 40% in one year. The following year, the number decreases by 25%. The total increase in the number of students is 23. How many students were there at the school before the increase?

0.75 * 1.4x = 1.05x.
1.05x - x = 23
answer 460

x * (1 + 0,40) = x * 1,40.
x * 1,40 * (1 - 0,25) = x * 1,05

  • 1,05 - x = 23
    answer 437

which of these are right?

rich mason
#

Hi

plain slate
#

you're doing the same calculation

#

idk why you are getting different results

#

although you dropped an x here

rich mason
#

my friends have wrote them for our homework

#

which is right tho?

harsh berry
#

you're doing the same calculation

plain slate
#

460 is right, how did you get 437?

rich mason
#

calculator from 1934

cursive night
#

your final eqns for both is the same, yet you have two different numerical values

rich mason
#

which should i write on my homework for a better grade?

harsh berry
#

it doesn't matter

#

prob

rich mason
#

which seems more advanced for grade 7

#

@harsh berry

harsh berry
#

first

cursive night
#

how did you get 437 anyway

rich mason
#

Let x be the number of students before the increase. After the first year, the number of students is x * (1 + 0.40) = x * 1.40. After the second year, the number of students is x * 1.40 * (1 - 0.25) = x * 1.05. Since the total increase is 23 students, we have x * 1.05 - x = 23. Solving for x gives x = 437 students.

So there were 437 students at the school before the increase.

cursive night
#

dont use such chat bots to do math, they're pretty terrible

rich mason
#

@cursive night how?

cursive night
#

idk man its clearly wrong

limpid snow
#

The bot interpreted the question wrong

trim joltBOT
#

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thorn grail
#

hii guys!!! im in year 10 and this question is really confuisng me? i asked my teacher about it and they said to work it out yourself :/ i already worked out that the first question is 1400pi over 3 + 1000m2 thanks in advance ā¤ļø

harsh berry
#

B?

thorn grail
#

Yeah B :P

#

ahhhh

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forest axle
#

Given a parallelogram with area 480 square inches, and side lengths 24 and 40 what is the measure of the obtuse angle?

forest axle
#

<@&286206848099549185>

quasi wasp
#

you can find the acute angle using trig

quasi wasp
#

@forest axle

forest axle
quasi wasp
#

so one can find the height, and then solve for the acute angle using trig

forest axle
#

I don't know how to solve for the height either

quasi wasp
#

area is given
and the base is given

#

so?

forest axle
#

480/40?

quasi wasp
#

yes!

forest axle
#

12

quasi wasp
#

yup

forest axle
#

Would i do adjacent/opposite

quasi wasp
#

taking the acute angle as theta

#

we have opposite and hypotenuse

forest axle
#

and i believe the opposite

#

wouldnt we do 12/24

quasi wasp
#

yeah sin theta = 12/24

forest axle
#

and then i suppose we do the inverse of sin (0.5)

#

so its 30 degrees

quasi wasp
forest axle
#

then uhh

#

180-30

quasi wasp
forest axle
#

150

#

answer is 150 degrees?

quasi wasp
forest axle
#

yes

#

yay

forest axle
#

.close

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#
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quasi wasp
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mossy quarry
#

Why is it not C or D ?

trim joltBOT
severe wave
#

d isn't also cause f' of 2 exist

mossy quarry
severe wave
#

for a derivative to not exist there are 2 cases

#

non continuity that you mentioned and limit of f' being infinite

#

and that function is continuous since it's left and right limit on x =2 is the same

#

but the sudden change mimics undefined derivative basically

#

a function like that doesn't really exist tho unless it's a composite function @mossy quarry

mossy quarry
#

limit is not infinite tho

#

for c

#

and even tho theres a sudden change

#

it still touching

#

if i were to trace that line

#

with a pencil

#

my pencil will always be in contact

#

with the line

#

unless theres a hole

#

that i cant see

#

then sure

#

undefined

#

i think theres a hole there tbh

#

but u say its cause of the unexpected turn

severe wave
#

no it's not about a hole

#

there's no hole

#

going beyond the rule of

#

"sharp turns have no derivative"

#

I'll try and explain where it comes from

#

now before that, i said it's continuous and to prove that if we had the original function fx we would analyze the x=2 with left and right limit

#

and if both limits go to the same value it's a continuous function

#

now if we talk about derivative definition

#

it's limit for a small change

#

when we have a smooth curve, no matter how small you analyze this "small change" you will have values to compute this limit

#

but when you try and compute the limit of derivative left and right you will get different values

#

since the shape is not smooth the point literally has no small change it's sudden

mossy quarry
#

oh the left and right test makes sense

#

gotcha

#

yo so

#

back to the photo

severe wave
#

yeah

mossy quarry
#

when i wrote it out

#

the values

#

(-inf,-9)(-9,-5)(-5,8)

#

first and last set is negative

#

mind you this is the derivative

#

the graphs are just regular functions

#

not the dy/dx

#

so like

mossy quarry
severe wave
#

yes?

mossy quarry
#

and u get +, -, +

severe wave
#

wait wait

#

abcd are functions

#

for the given intervals

#

lets take first

#

inf to -2

#

it states that the derivative is negative

mossy quarry
#

u mean -9?

#

oh

#

mb

#

soz

#

go on

severe wave
#

that information means that the function values are heading towards negative values

mossy quarry
#

i got wrong numebrs

#

mb

severe wave
#

np

#

negative derivative means function is changing to lower values in respect with x

#

so y decreases

#

don't try and apply mechanic rules try and logically think what the derivative represents for a function

#

so when the problem states those facts

#

we imagine a graph going on a downward slope then upward and downward again

mossy quarry
#

sure

#

the derivative

#

not the regular function tho

#

those graphs

#

a-d

#

are y(X)

#

not y ' (X)

severe wave
#

yes and that's what I'm saying

mossy quarry
#

u gotta flip the sign :/

#

signs

severe wave
#

let's say we have derivative of a yx function be 2

#

what's the original function

mossy quarry
#

2x

severe wave
#

2 is positive

#

2x is positive

#

did you flip anything?

mossy quarry
#

ok no but

#

if u plug in -2

#

ur gonna get -4

#

and from -4 to 2

#

thats a sign flip

severe wave
#

yes but derivative doesn't say that for a function it states the trend a function follows when you go through x values

#

which means

#

what happens to y values

#

and you increase x values

#

for plug in -2 it's -4

#

for -1 (increase x with 1)

#

it goes -2

#

we see for x increase y increases aswell specifically with number 2

#

and that's what the derivative said by being a positive 2

#

it's sign said the original function is positive trend

#

and it's number literally told us how y values increase/decrease

#

in your case you don't have any derivative value or function you are just told it stays positive

#

which assures you that for your original yx function when you move left to right on x axis

#

y values go down then up and then down

#

on those specific intervals

#

your issue is just miss understanding what derivative means for the function just watch some YouTube videos if what i said still is confusing and you will get the hang of it

mossy quarry
#

heres why im confused

#

you see this new problem here?

#

i fliped the signed they said

#

of derivatives

#

from "+ , - , + "

#

to the opposites

#
  • , + , -
#

at (-inf,-9)(-9,-5)(-5,8)

severe wave
#

with your analogy then A should be your answer

mossy quarry
#
  • -> x is min
severe wave
#

but it's not

mossy quarry
#
  • -> - is max
severe wave
#

recheck the question

mossy quarry
#

it goes down then up and down again

#

its c

severe wave
#

c is going up first tho

#

and then goes down slightly

mossy quarry
#

true but the min

severe wave
mossy quarry
#

is there

#

on c

#

at the point

#

and max is there too

#

on right

severe wave
#

first derivative has no relation to min and maxes

#

it's just the slope of the line

#

idk who gave you the method of flipping but it's wrong and it won't teach you proper derivative notion

#

question is literally saying

#

what piece of line goes up and then down and then up and then down

#

A is not it cause it goes down first not up

#

same for B

#

D has only 3 states

#

where as the exercise specified 4

#

so it's just C

severe wave
#

I'm gonna go sleep

mossy quarry
#

ty

#

.close

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#
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dim jewel
#

Hey i have got a question

trim joltBOT
dim jewel
#

How do i define Sine function without triangles

#

I mean

#

Not like Sin x = that expansion

#

so here how do i define Sin A in second case ?

#

Because as long is its angle is acute we can make a right angle triangle then Sin = perpendicular /hypotenuse

#

But whag if angle itself is obtuse

frigid stump
#

sin x = sin 180-x

dim jewel
#

Yep

#

What if someone Doesn't kow that

frigid stump
#

You can also calculate sin using the area of a triangle. A = ab* sin x/2

dim jewel
#

OH yeah!

#

How was Sin function defined initially

#

Like when it has just discovered

frigid stump
#

I think on a unit circle called the trigonometric circle

dim jewel
#

Ohh do we can define x or y coordinate

#

With its angles

#

So it was defined so right angles initially

frigid stump
#

Yeah, kind of

dim jewel
#

Ohh thank you then!

#

.close

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#
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sage mural
#

How to solve for x?

trim joltBOT
cloud portal
brave shell
#

39

cloud portal
#

For the angle in the bottom-right of the triangle:

  • The 68 is on a line. The angle next to it would be 180-68
  • The angle we just found is itself on a line. Find the angle on the opposite end and youve gotten the bottom-right angle.

For the anlge in the bottom-left of the triangle:

  • the 107 is on a line. The angle next to it would give it.
#

@sage mural

#

It's a little hard describing it using text, lmk if that was clear.

brave shell
#

If two lines are intersecting opposite angles in between lines are equal

#

So left bottom of triangle is 68

cloud portal
#

Oh right, thats faster. I only remember the basic properties.

brave shell
#

180-107is bottom right

brave shell
sage mural
brave shell
#

Now total sum of angles in triangle is 180

sage mural
#

is x= 39 ?

brave shell
#

If you have further doubts DM me

brave shell
sage mural
#

Yay

brave shell
#

So umm close the help box and free it for others?

sage mural
#

thanks so much! Have a nice day, God bless! Jesus loves you :3

brave shell
#

Thanks man and welcome

sage mural
#

.close

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#
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thick kayak
#

help

trim joltBOT
thick kayak
#

I couldn't understand why second sum is

#

ln(2)

#

also this too

#

I think reasoning behind these same can somebody explain thx

lavish hawk
#

The 2nd one is just the above series without the first 2 terms

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#

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upper panther
# thorn grail hii guys!!! im in year 10 and this question is really confuisng me? i asked my t...

a) Area = (2 x rectangle) + (arc length x 25) + (1 x sector) (find more about radians on TLmaths) = (2 x rectangle) + ( r x θ x25) + (1/2 x r^2 x θ) [θ = π/180 x angle in degrees ] = (2 x 25 x 20) + (20 x π/3 x 25) + (1/2 x 20 x 20 x π/3) [ arc length = r x θ ] = 1000 + 700π/3 m^2 [ area of sector = 1/2 x r^2 x θ] (not 1000 + 1400π/3, 'note that the top is open' in the question) b) Cost = 54 x (1000 + 700π/3) =

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#

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brave oasis
#

This is my answer for the first part

#

For the second part, idk what to do

trim joltBOT
#

@brave oasis Has your question been resolved?

brave oasis
#

Basically im using modulo congruence to try to figure out the missing digit

#

using modulo 11

#

Basically:

a_mod_11 * a_mod_11 will be congruent to c_mod_11

So they have the same value i think

#

and since c is missing x, we can find x

#

but if theres both x and y, how do i find that?

#

like 2677xy53

#

where x is 7 and y is 3

trim joltBOT
#

@brave oasis Has your question been resolved?

dense breach
#

for 2 missing digits

brave oasis
dense breach
#

yeah

#

so essentially you know what your two missing digits add up to (mod 9)

#

if you know their difference as well that should be enough to compute them, except for 00 and 99 which get confused with each other

brave oasis
dense breach
#

yeah

brave oasis
#

.close

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sharp gull
#

Hello, I want to ask what does "floor" and "ceiling" means? I have polish education in my school.

harsh berry
#

4.1 floor = 4
4.1 celling = 5

sharp gull
#

thanks

#

.close

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vagrant marsh
#

floor means round down

#

ceiling means round up

#

if its an integer already, do not round

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idle pewter
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sweet hare
#

what is your question

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#

@idle pewter Has your question been resolved?

gray quarry
#

!status

trim joltBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
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6. None of the above
#
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safe yacht
#

Determine the center and radius of the circle if the equation of the circle is x^2+y^2-10y=0

safe yacht
#

Not sure what to do there are no real numbers

#

I know the circle equation

#

.close

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kindred pier
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azure pebble
#

how to prove this?

trim joltBOT
azure pebble
#

using this

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#

@azure pebble Has your question been resolved?

vestal turtle
azure pebble
#

and

vestal turtle
#

oh

azure pebble
#

yeah it's just in dutch haha

vestal turtle
#

this one is straightforward

#

just sub them and it looks like they cancel

azure pebble
#

yeah but this doesn't need to be proved

azure pebble
vestal turtle
#

right, so when we sub, most of the terms cancel

#

we get a simple sum of a and b, and then we have to use the angle sum formulae

azure pebble
#

yeah i tried using the sum formula but i cannot get to the answer on the right side

vestal turtle
#

i think its better to do right side to left in this case

#

then literally just write your proof in reverse and you go from left to right

#

if you need a left to right

azure pebble
#

okay, i'll try it now

#

from the right side

#

ty

#

i got it

#

thanksss

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#

@azure pebble Has your question been resolved?

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#
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knotty quiver
#

How do we solve problems like this?

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dire vortex
#

Solve $x + \frac{1}{x} = 5$

solid kilnBOT
dire vortex
#

To find x

knotty quiver
#

I got the roots to be

dire vortex
knotty quiver
#

(15 ± √21)/2

knotty quiver
dire vortex
# solid kiln **Rub05**

You can transform $x^3 + \frac{1}{x^3}$ to look like somthing similar to the other expression

solid kilnBOT
knotty quiver
knotty quiver
dire vortex
knotty quiver
#

I just felt like things'd get messy if I do that

#

so was confused as to what to do

wraith hinge
#

Nope, there's an easier way

knotty quiver
wraith hinge
#

Do you know the (a+b)³ formula?

knotty quiver
#

a^3+b^3+3ab(a+b)

wraith hinge
#

Oh, nice, sharp!

knotty quiver
#

Thanks!

wraith hinge
#

I thought of a³+b³+3a²b+3ab² and then factorise it later on

knotty quiver
#

ah

#

understood

wraith hinge
#

It's way faster dw

#

Your way

#

So. Do it then.

knotty quiver
#

okay man thanks

wraith hinge
#

(x+1/x)³=5³

knotty quiver
#

makes much more sense

#

thanks

wraith hinge
#

Got it already?

knotty quiver
#

nah didn't complete it

#

but its more sensible

wraith hinge
#

Ah

#

Any time buddy.

knotty quiver
#

yeah i got it

#

thanks @wraith hinge

wraith hinge
#

110?

knotty quiver
#

yep

wraith hinge
#

Nice job brother

knotty quiver
#

šŸ¤

#

.close

wraith hinge
#

Have a nice one!

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knotty quiver
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wraith hinge
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wraith hinge
#

.close

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flat wing
#

Can someone help me out

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onyx mist
#

!status

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#
What step are you on?
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onyx mist
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#

@flat wing Has your question been resolved?

flat wing
#

I tried using 200cos 35

flat wing
#

Not sure how I find it

onyx mist
#

do you remember the formula for the amplitude of transmitted light from incoming amplitude, angle of incidence, and transmission coeffecient?

#

from that, you just need the formula for trans coef, then its straightforward to solve

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onyx mist
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proud tendon
#

Hi i need help with solving this

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proud tendon
stark bison
#

Is this y = ax again?

proud tendon
#

Yea but diffrent

#

Somehow

#

inverse dependence

#

Or somthing

stark bison
#

Oh

#

Does it say y = a/x?

proud tendon
#

Yea

stark bison
#

Ah, then you each if the products of x and y is the same everywhere

#

Because y = a/x can be rewritten as xy = a

proud tendon
#

I get it

#

The first one dosent have inverse dependence because the answers are different

#

And on the second one there is inverse dependence because they are all the same 0.24

#

A=xƗy

stark bison
#

Yup

proud tendon
#

Tyy

#

.close

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vale obsidian
#

Im just having trouble with part B of the question

vale obsidian
#

I dont really know what to do

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#

@vale obsidian Has your question been resolved?

vale obsidian
#

<@&286206848099549185>

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@vale obsidian Has your question been resolved?

vale obsidian
#

someone help please

vale obsidian
#

damn

#

.close

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solid kilnBOT
#

ilegosking

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vague axle
#

I need to give my answers in scientific notation.

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What step are you on?
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6. None of the above
vague axle
#

I don't know where to begin, how do i start to simplify the process?

#

<@&286206848099549185>

rustic oxide
vague axle
#

alr

#

For the divisions do i make two separate fractions? 4.6/2.3 * 10^8/10^-6?

vague axle
#

Thank you

#

.close

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dark turtle
#

not sure how to treat this.

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dark turtle
#

would i be correct to do the root test for x^n?

twin swan
#

yep, that should work

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#

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scarlet goblet
#

Quick question what is μ in a T-Test? Is it the number I am testing on? I can't get a clear answer

knotty locust
#

mu is the mean or average

#

I believe

scarlet goblet
#

Here's an example of what the equation looks like

#

what is the difference between xbar which is the sample mean vs mu

knotty locust
#

mu is the population mean

#

xbar is the sample mean

scarlet goblet
#

What if the data set I have is a sample of a population?

knotty locust
#

then xbar would be the mean of the sample

#

and mu would be the mean of that population

scarlet goblet
#

So hypothetically I have a population that is recording the years fathers spent in education, and there are two variables white and nonwhite. The sample mean is that of the variable I'm testing and the population mean (mu) is of all the fathers?

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#

@scarlet goblet Has your question been resolved?

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@scarlet goblet Has your question been resolved?

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steep cypress
#

What's this?

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crude blaze
#

a limit

wise dagger
#

a picture

steep cypress
trim lichen
#

have you done anything with limits before?

steep cypress
#

Yes

trim lichen
#

so do you know, say, what 1/x goes to as x grows larger and larger?

steep cypress
#

no

#

0 something

#

0.?????????????????????????

crude blaze
#

@steep cypress no

inner orbit
#

Indeed

trim lichen
#

0

#

just 0

inner orbit
#

0

crude blaze
#

wait nvm

#

yes

steep cypress
trim lichen
#

as x grows without bound, 1/x gets arbitrarily close to 0.

#

you might have heard something along these lines especially if you have been introduced to the formal definition of limits

#

(also whatever small but positive number you can think of, 1/x eventually gets smaller than that)

steep cypress
trim lichen
#

no

inner orbit
# steep cypress why just zero?

I love this analogy
Imagine you walking to a wall. You keep walking towards it but never actually reaching it. You are tending to that wall which has a definite value, but you may never reach that value.

trim lichen
#

that's a different matter

steep cypress
#

but you said 1/x is zero?

#

so 1^x is 1