#help-38
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x,y are integer
x+y+xy=23
x^2y+xy^2=126
the question
i finally got the ans
but still thanks for these tips
if the ans is 31522, x and y are not integer
Yes, mention every one of those details next time you ask any question.
thx
.close if done
do u get any idea for this question
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how do i prove inequalities by induction?
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@mental lodge Has your question been resolved?
<@&286206848099549185> pleases'
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hi
idk how to attempt number 1
and im confused on whether I integrate for number 2 or something
might want to charge your battery
yep
so theres a neat trick you can do here
dx and dy can just be numbers
so you can multiply them
well thats the whole idea
dy/dt / dx/dt = dy/dt * dt/dx = dy/dx
now you know dy/dt and dx/dt
aight I got it
do you know abt this one
cuz its not given by a dy/dx but it says velocity vector and position
ah
so youre given v
and an initial condiiton
so you need to integrate from t = 2 to t = 6
and add that to f(2)
do each component seperately
why this
because we are integrating from 2 to 6
the integral is the change in value
so it ends up being f(6) - f(2)
but we want f(6)
so we need to tell it to add the change in value to the original value of f(2)
ye
and the integral = to f(6)-f(2) so we add f(2)
ye
how did I never learn this tho š
you'll be fine
are you surprisingly ahead
4 years of the average american student
you dont have to
itd be great if you did
but you can always retake the class next year
you have that cushion
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Hi I have a trigonometric question specifically about finding the angle of a right triangle
My teacherās answer for the angle is completely different from mine the answer being 49.6 degrees
I find the missing value for the opposite angle
do you know what sin, cos and tan are?
Let's first think about which sides of the triangle we know
opposite, adjacent, and hypotenuse are used in trig calculations
The teacherās answer was 49.6 degrees but I kept on getting 86 degrees
so we have the hypotenuse and the ajacent side
you don't need to solve for the unknown side, there's a different trig function from sin that you'd use
sin cos tan, do you see which one it is?
I donāt see one aside from sin
ah
So it would be
cosine theta = (24/37)
Theta=arccosine(24/37)
Iām still getting 0.86498
change your calculator from radians to degrees
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how can i do this with angle sum and difference formulas
use $\tan (a - b)$
bettim
Note that 1/12 is just 1/3 - 1/4
ohh ok
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i know it science but it math
(the one i ticked was wrong)
,rccw
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Can smn help how we achived this
4xy, 0 <x< 1, 0 <y< 1,
try drawing the region x<y on the xy plane
@fiery sleet Has your question been resolved?
oh
is there a video resource or smth for it
i have no idea how to do so
probably but I don't know one
just draw the line x=y and identify the region below that
like this/
yes
now try to convince yourself why that gives you the double integral given in the solution
dx's lower limit would be 0 right but how come its upper limit is y but for y its 1 š¤
for any value of y, x can take on values in the interval [0,y)
since that's what x<y means
(and obviously both x and y are constrained to (0,1))
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Given a graph of a sine or cosine function (really, what's the difference if you just have the graph?), we write multiple sine and cosine functions that generate the graph. We find the sinusoidal axis (midline), amplitude, period, increment, and use the patterns to write the equations. Two full examples are covered in detail.
can someone help me on how he finds the B value
here
Like the 2pi/b = 8 -> B = PI/4
I replayed the part as much as I can
but can't understaand
@fathom meadow Has your question been resolved?
ya but how
what is that
like I dont understand what 2pi/B is
or 10/3
like I dont understand what he means by period
I thought period was the Y value(the thing he marked in dark blue)
that was average between the largest and smallest Y vlue
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i know its a little messy but is this right?
if it loads
specifically the last two steps
can i divide an n from (n/(n+1))^n
the last step is wrong
(1+1/n)^n doesn't go to 1
it's probably a limit you know though
e?
yes
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Ive noticed that if you pick random vectors under magnitude x, and plot them out on a grid with a spacing of 1, with all of them coming from the origin, and you take the average amount of grid lines they pass through, call this f(x), if you then take f(x)/x and limit x to infinity then it converges to 8/(3*pi). Why would this be?
the number of grid lines the 2-d vector (x,y) passes through is floor(x) + floor(y)
in the limit we don't need to consider the floor functions
then paramaterise the vectors by their angle, scale them down to the unit circle to account for your division by x, and integrate over theta
sorta
Unrelated but is there likely to be an elementary solution to f(x)?
I mean f(x) as the average amount of grid lines vectors under magnitude x go through
Not the amount of grid lines an individual vector goes through
there's an integral expression for it
I know, ive also found an infinite summation for it, but im just interested in seeing if there is a nicer solution
well since you're summing stuff like floor(ksin(x)) I very much doubt there would be
Ah thats annoying
I found an infinite summation by doing an integral from a to a+1 of sqrt(x^2 - a^2) which is easily solvable, and then doing a summation mulitipled by a of that from 0 to infinity which real part is the amount of vertical lines it passes through in a quarter so you take away the imaginary part and then multiply it by 8 and divide it by the area
the annoyingness is self imposed as you're just looking at the x-distance and y-distance when you're looking at the number of gridlines
you're just looking at the area of a circle ultimately
i forgot to type in multiplied by a
if you multiply each column by a which increases as the summation goes up then it works like the gridlines
so it works out each 1 wide columns area with the integral and multiplies it by a which goes up each time
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Hello. How do I turn this
$$\frac{\left(x^{2}+x+1\right)^{2}-2x\left(x^{2}+x+1\right)}{\left(x^{4}+x^{2}+1\right)-2x\left(x^{2}-x+1\right)}$$
into this
$$\frac{\left(x^{2}+x+1\right)^{2}}{x^{4}+x^{2}+1}$$
lmaowhat
I am pretty sure they are equal
I just need to do some manipulation to convert it (the top one) to that (the bottom one)
try and assign a new variable to each polynom and see what changes from top to bottom
and when you have a more visible fraction see if you can reverse what was simplified
why do you think they are equal?
I substituted different values for both, they give the same output
It could be that it was a coincidence but I don't think so
This is not the actual problem
I have to prove that $\ln\left(\frac{x^{4}+x^{2}+1}{\left(x^{2}+x+1\right)^{2}}\right)$ is an odd function
lmaowhat
How would that work? That would just give me a weird fraction
(a - b)/(c - d)
@silent canyon
((x^2+x+1)^2 - 2x(x^2+x+1)) = x^4+x^2+1
((x^4+x^2+1) - 2x(x^2-x+1)) = x^4-2 x^3+3 x^2-2 x+1
is (x^4+x^2+1)/(x^4-2 x^3+3 x^2-2 x+1)
the same like:
(x^4+2 x^3+3 x^2+2 x+1) / (x^4+x^2+1)?
(x^4-2 x^3+3 x^2-2 x+1)(x^4+2 x^3+3 x^2+2 x+1) = x^8+2 x^6+3 x^4+2 x^2+1
(x^4+x^2+1)(x^4+x^2+1) = x^8+2 x^6+3 x^4+2 x^2+1
Yes, they are the same
Hint: When you want to know if 2 fractions are equal, cross multiply will give you the solution.
I mean
I don't think you're supposed to do this
It can be shorter
It's an objective question and is supposed to be answered in around a minute
probably, but it doesn't take more than 1 minute
That's true
i would do this way for sure, it's 6 lines
findng a way to make a transformation looks harder and would require to think more
i would call that more like a clean way to solve, not faster
Oh
Lol
I'm done
I found a way better way
$\frac{x^4+x^2+1}{(x^2-x+1)^2} = \frac{x^4+x^2+1}{(x^2+1-x)^2} = \frac{x^4+x^2+1}{(x^2+1-x)^2} \cdot \frac{(x^2+1+x)^2}{(x^2+1+x)^2} = \frac{(x^4+x^2+1)(x^2+1+x)^2}{\left[(x^4+1+2x^2) - x^2\right]^2} = \frac{(x^4+x^2+1)(x^2+1+x)^2}{(x^4+1+x^2)^2} = \frac{(x^2+x+1)^2}{x^4+x^2+1}$
Wasn't that long after all
lmaowhat
Just had to multiply by its conjugate
Yeah I agree, but I was just finding a way to make this easier because I'm just practicing
If I get the hang of finding good manipulations then that would help me in the actual exam
Thank you for your help
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I don't get why E is a sub vector space of R^R and not just R
E consists of functions
ye and
because a vect is a vector space
and?
its a vector space spanned by those three functions
but that doesnt mean that those functions are suddenly numbers
and what would be the sub vector space then
hmm?
if a function is R -> R
the sub vector is R for me, seem logical
there is a copy of R inside R^R, the constant functions
but otherwise you are talking nonsense
do you mean that the vector space is over the field R?
well when i'm talking of sub vector space of R that mean that the vector space of E is inside R
for that it first would need to be a subset
which it is not
the element of E are functions
they are not numbers
they are not included in R
E is not a subset of R
why are you calling it a sub vector space instead of a vector subspace
unless you actually don't mean it?
no i mean it
are you talking about a vector subspace or something else?
hum e.g E = {(x,y,z)ā¬R^3, x = y +z}
are you calling that a sub vector space of R^2 or a vector subspace of R^2
thats not even proper set notation
now?
and what's a sub vector space then
I don't even know what you mean by a "sub vector space"
do you mean vector subspace or not
that's what I've been trying to ask
that's what i'm trying to clear
then that's what i meant
how am I supposed to know what it means
that's why i give an example to know
this tells you what a vector subspace is
is that the same thing as what you call a "sub vector space" or not?
yes
they clearly mean that
dont put too much attention on that word swap
could come from translation or something
I mean I thought so, but then they insisted on calling it something else, which is weird
i used vector sub space on this serv and they were not any misunderstood so i thought that was the good term
vector subspace or linear subspace or just subspace is common terminology
but sub vector isn't
sometimes people say things that seem like they're something, but they turn out to be completely different
in any case, a very succinct definition of a subspace is some set that is a subset of a vector space and is a vector space in itself
your E is not a subset of R, and therefore it cannot be a subspace of R
eh, in french it's called "sous-espace vectoriel" so literally sub vector space
not every language is english-centered
yeah sure, but if you say it in English, then it's weird
so we must forgive him
then it's a subset of what
there must be something to refer to functions
you really are focusing on the wrong thing. I've seen some people mess terminology up way worse
R^R is the space of all functions R->R
that is what that notation means
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i started by x = sin theta substitution
then i got here and im stuck
need help on how to continue this integral
hmm let me try this first
what did you get to?
im not sure if it's even right but let me type it out
is it readable
Toby
That looks much harder than x = cos u
lol
yeah lol, do this instead 
from here?
Right from the beginning
shouldnt i be using the first one
There is a reason why I suggest this here
Can you try it?
Yes. What's sin/cos?
tan^2 theta / cos ^2 theta
Note that (tan x)` = 1/(cos x)^2
oooohh
wait let me see if i can continue from there
this makes this integral - u^2 du
is the final answer - (tan theta )^3 / 3
how to check
Now you can sub back I think
yup that's correct
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should i add the 3
on the other side first
and make it (x+1)^2+3?
btw i am graphing
Don't open multiple channels for the same question, next time stick to your original channel
Add the 3??
other one because i change this question
I close the other channel
In the future I mean
Is ok
Anyways, if you are trying to graph this function you need to find its vertex
I wont make it again
do you know what vertex form of a quadratic function is?
Actually, I'll start by asking if you know what the vertex is
yeah we get the -k and h right
Where (h, k) is the vertex
yep
So for your question here, it is already in vertex form
can you find what the vertex is?
is -1,0
That's just completed square form does it have 2 names then
is down
Yes
because "a" is -3, which is negative
so it opens down
Can you graph it now?
you just have to know some sample points to graph it
ok
so start with labeling the vertex
ok
which is at x=-1
ok labled that one
You just plot points such as x intercept y intercept then draw a curve through them
yes
like if i picked -2 as an X i just plug it like this one -3(-2+1)^2
yes
and that tells you the y-value of the graph at x=-2
so you could then plot that point
Ok nice thank a lot for assist
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The number of students at a school increases by 40% in one year. The following year, the number decreases by 25%. The total increase in the number of students is 23. How many students were there at the school before the increase?
0.75 * 1.4x = 1.05x.
1.05x - x = 23
answer 460
x * (1 + 0,40) = x * 1,40.
x * 1,40 * (1 - 0,25) = x * 1,05
- 1,05 - x = 23
answer 437
which of these are right?
Hi
you're doing the same calculation
idk why you are getting different results
although you dropped an x here
you're doing the same calculation
460 is right, how did you get 437?
calculator from 1934
your final eqns for both is the same, yet you have two different numerical values
which should i write on my homework for a better grade?
first
you should write the right answer obviously
how did you get 437 anyway
i asked bing ai chat bot how they got 437 heres what they said
Let x be the number of students before the increase. After the first year, the number of students is x * (1 + 0.40) = x * 1.40. After the second year, the number of students is x * 1.40 * (1 - 0.25) = x * 1.05. Since the total increase is 23 students, we have x * 1.05 - x = 23. Solving for x gives x = 437 students.
So there were 437 students at the school before the increase.
dont use such chat bots to do math, they're pretty terrible
nah we wanted to see if we were right we got 460 but how does the bot get 437?
@cursive night how?
idk man its clearly wrong
The bot interpreted the question wrong
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hii guys!!! im in year 10 and this question is really confuisng me? i asked my teacher about it and they said to work it out yourself :/ i already worked out that the first question is 1400pi over 3 + 1000m2 thanks in advance ā¤ļø
B?
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Given a parallelogram with area 480 square inches, and side lengths 24 and 40 what is the measure of the obtuse angle?
draw a picture
one can find the acute angle and then find the obtuse angle
you can find the acute angle using trig
do you know how to do this?
@forest axle
I do not
so one can find the height, and then solve for the acute angle using trig
I don't know how to solve for the height either
480/40?
yes!
12
yup
Would i do adjacent/opposite
so we have the hypotenuse
and i believe the opposite
wouldnt we do 12/24
yeah sin theta = 12/24
yes, arcsin
correct
yes!
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no problem!
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Why is it not C or D ?
c can't be cause on the specificed intervals the derivative is the opposite of the requirements
d isn't also cause f' of 2 exist
this also applies for d
but its still continuous
for a derivative to not exist there are 2 cases
non continuity that you mentioned and limit of f' being infinite
and that function is continuous since it's left and right limit on x =2 is the same
but the sudden change mimics undefined derivative basically
a function like that doesn't really exist tho unless it's a composite function @mossy quarry
limit is not infinite tho
for c
and even tho theres a sudden change
it still touching
if i were to trace that line
with a pencil
my pencil will always be in contact
with the line
unless theres a hole
that i cant see
then sure
undefined
i think theres a hole there tbh
but u say its cause of the unexpected turn
no it's not about a hole
there's no hole
going beyond the rule of
"sharp turns have no derivative"
I'll try and explain where it comes from
now before that, i said it's continuous and to prove that if we had the original function fx we would analyze the x=2 with left and right limit
and if both limits go to the same value it's a continuous function
now if we talk about derivative definition
it's limit for a small change
when we have a smooth curve, no matter how small you analyze this "small change" you will have values to compute this limit
but when you try and compute the limit of derivative left and right you will get different values
since the shape is not smooth the point literally has no small change it's sudden
yeah
when i wrote it out
the values
(-inf,-9)(-9,-5)(-5,8)
first and last set is negative
mind you this is the derivative
the graphs are just regular functions
not the dy/dx
so like
u flip these signs right
yes?
and u get +, -, +
wait wait
abcd are functions
for the given intervals
lets take first
inf to -2
it states that the derivative is negative
that information means that the function values are heading towards negative values
np
negative derivative means function is changing to lower values in respect with x
so y decreases
don't try and apply mechanic rules try and logically think what the derivative represents for a function
so when the problem states those facts
we imagine a graph going on a downward slope then upward and downward again
sure
the derivative
not the regular function tho
those graphs
a-d
are y(X)
not y ' (X)
yes and that's what I'm saying
2x
yes but derivative doesn't say that for a function it states the trend a function follows when you go through x values
which means
what happens to y values
and you increase x values
for plug in -2 it's -4
for -1 (increase x with 1)
it goes -2
we see for x increase y increases aswell specifically with number 2
and that's what the derivative said by being a positive 2
it's sign said the original function is positive trend
and it's number literally told us how y values increase/decrease
in your case you don't have any derivative value or function you are just told it stays positive
which assures you that for your original yx function when you move left to right on x axis
y values go down then up and then down
on those specific intervals
your issue is just miss understanding what derivative means for the function just watch some YouTube videos if what i said still is confusing and you will get the hang of it
heres why im confused
you see this new problem here?
i fliped the signed they said
of derivatives
from "+ , - , + "
to the opposites
- , + , -
at (-inf,-9)(-9,-5)(-5,8)
with your analogy then A should be your answer
- -> x is min
but it's not
- -> - is max
recheck the question
true but the min
this is A
first derivative has no relation to min and maxes
it's just the slope of the line
idk who gave you the method of flipping but it's wrong and it won't teach you proper derivative notion
question is literally saying
what piece of line goes up and then down and then up and then down
A is not it cause it goes down first not up
same for B
D has only 3 states
where as the exercise specified 4
so it's just C
read all this again till it makes sense
I'm gonna go sleep
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Hey i have got a question
How do i define Sine function without triangles
I mean
Not like Sin x = that expansion
so here how do i define Sin A in second case ?
Because as long is its angle is acute we can make a right angle triangle then Sin = perpendicular /hypotenuse
But whag if angle itself is obtuse
sin x = sin 180-x
You can also calculate sin using the area of a triangle. A = ab* sin x/2
Ohh do we can define x or y coordinate
With its angles
So it was defined so right angles initially

Yeah, kind of
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How to solve for x?
It's in a triangle, which would have a total angle of 180. Find the two other angles in the triangle and you will find x.
How do I find those angles?
39
For the angle in the bottom-right of the triangle:
- The 68 is on a line. The angle next to it would be 180-68
- The angle we just found is itself on a line. Find the angle on the opposite end and youve gotten the bottom-right angle.
For the anlge in the bottom-left of the triangle:
- the 107 is on a line. The angle next to it would give it.
@sage mural
It's a little hard describing it using text, lmk if that was clear.
If two lines are intersecting opposite angles in between lines are equal
So left bottom of triangle is 68
Oh right, thats faster. I only remember the basic properties.
180-107is bottom right
It's fine it only changes speed of output not the output itself
73?
is x= 39 ?
If you have further doubts DM me
Absolutely right you are great man
Yay
So umm close the help box and free it for others?
thanks so much! Have a nice day, God bless! Jesus loves you :3
Thanks man and welcome
.close
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help
I couldn't understand why second sum is
ln(2)
also this too
I think reasoning behind these same can somebody explain thx
Comes from the power series of ln(1-x)
The 2nd one is just the above series without the first 2 terms
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a) Area = (2 x rectangle) + (arc length x 25) + (1 x sector) (find more about radians on TLmaths) = (2 x rectangle) + ( r x Īø x25) + (1/2 x r^2 x Īø) [Īø = Ļ/180 x angle in degrees ] = (2 x 25 x 20) + (20 x Ļ/3 x 25) + (1/2 x 20 x 20 x Ļ/3) [ arc length = r x Īø ] = 1000 + 700Ļ/3 m^2 [ area of sector = 1/2 x r^2 x Īø] (not 1000 + 1400Ļ/3, 'note that the top is open' in the question) b) Cost = 54 x (1000 + 700Ļ/3) =
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@brave oasis Has your question been resolved?
Basically im using modulo congruence to try to figure out the missing digit
using modulo 11
Basically:
a_mod_11 * a_mod_11 will be congruent to c_mod_11
So they have the same value i think
and since c is missing x, we can find x
but if theres both x and y, how do i find that?
like 2677xy53
where x is 7 and y is 3
@brave oasis Has your question been resolved?
You have to use mod 9 as well I believe
for 2 missing digits
Ah ok, could you elaborate?
I know the rule that adding up the digits of a number will give you the remainder of the number when dividing by 9
yeah
so essentially you know what your two missing digits add up to (mod 9)
if you know their difference as well that should be enough to compute them, except for 00 and 99 which get confused with each other
Ah thatās smart, ok. Would I just find the difference using the mod 11 rule?
yeah
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Hello, I want to ask what does "floor" and "ceiling" means? I have polish education in my school.
4.1 floor = 4
4.1 celling = 5
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floor means round down
ceiling means round up
if its an integer already, do not round
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what is your question
@idle pewter Has your question been resolved?
!status
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2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
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6. None of the above
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Determine the center and radius of the circle if the equation of the circle is x^2+y^2-10y=0
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how to prove this?
using this
@azure pebble Has your question been resolved?
do you know what en means?
and
oh
yeah it's just in dutch haha
yeah but this doesn't need to be proved
it's this that needs to be proved
right, so when we sub, most of the terms cancel
we get a simple sum of a and b, and then we have to use the angle sum formulae
yeah i tried using the sum formula but i cannot get to the answer on the right side
i think its better to do right side to left in this case
then literally just write your proof in reverse and you go from left to right
if you need a left to right
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How do we solve problems like this?
Solve $x + \frac{1}{x} = 5$
Rub05
To find x
I got the roots to be
You can transform the other expression to have the form of this one too
(15 ± ā21)/2
I didn't understand you there
You can transform $x^3 + \frac{1}{x^3}$ to look like somthing similar to the other expression
Rub05
Do I just input the values into the next expression and solve them?
Could you help me do so or elaborate how should I do so?
That's more hard
Oh okay
I just felt like things'd get messy if I do that
so was confused as to what to do
Nope, there's an easier way
guide me messiah š
Do you know the (a+b)³ formula?
Oh, nice, sharp!
Thanks!
I thought of a³+b³+3a²b+3ab² and then factorise it later on
okay man thanks
(x+1/x)³=5³
Got it already?
110?
yep
Nice job brother
Have a nice one!
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šš»
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.close
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Can someone help me out
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
since you do have something, could you show me your work to get that?
@flat wing Has your question been resolved?
I tried using 200cos 35
But it says it a different angle
Not sure how I find it
do you remember the formula for the amplitude of transmitted light from incoming amplitude, angle of incidence, and transmission coeffecient?
from that, you just need the formula for trans coef, then its straightforward to solve
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@flat wing , you forgot to react to the bot here
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Hi i need help with solving this
Is this y = ax again?
Yea
Ah, then you each if the products of x and y is the same everywhere
Because y = a/x can be rewritten as xy = a
I get it
The first one dosent have inverse dependence because the answers are different
And on the second one there is inverse dependence because they are all the same 0.24
A=xĆy
Yup
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Im just having trouble with part B of the question
I dont really know what to do
@vale obsidian Has your question been resolved?
<@&286206848099549185>
@vale obsidian Has your question been resolved?
someone help please
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ilegosking
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I need to give my answers in scientific notation.
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
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6. None of the above
I don't know where to begin, how do i start to simplify the process?
<@&286206848099549185>
you can reorder the multiplication so that you have (2.4*1.8)*(10^4*10^-2)
exactly
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not sure how to treat this.
would i be correct to do the root test for x^n?
yep, that should work
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Quick question what is μ in a T-Test? Is it the number I am testing on? I can't get a clear answer
Here's an example of what the equation looks like
what is the difference between xbar which is the sample mean vs mu
What if the data set I have is a sample of a population?
then xbar would be the mean of the sample
and mu would be the mean of that population
So hypothetically I have a population that is recording the years fathers spent in education, and there are two variables white and nonwhite. The sample mean is that of the variable I'm testing and the population mean (mu) is of all the fathers?
@scarlet goblet Has your question been resolved?
@scarlet goblet Has your question been resolved?
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What's this?
a limit
a picture
What's its value?
have you done anything with limits before?
Yes
so do you know, say, what 1/x goes to as x grows larger and larger?
@steep cypress no
Indeed
0
why just zero?
as x grows without bound, 1/x gets arbitrarily close to 0.
you might have heard something along these lines especially if you have been introduced to the formal definition of limits
(also whatever small but positive number you can think of, 1/x eventually gets smaller than that)
So this is equal to 1?
no
I love this analogy
Imagine you walking to a wall. You keep walking towards it but never actually reaching it. You are tending to that wall which has a definite value, but you may never reach that value.
that's a different matter
