#help-38
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it will be line -parabola from -16 to 0
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how do i write mathematically that any term of 2^4n-1 -3 are divisible by 5 provided n is greater than 0.
Can i say 1 is a positive integer instead n is greater than 0?
if so, how?
I suppose ∀n ∈ ℕ_≥1. 5 | 2^(4n-1)-3 or something like that?
thank you!
I think ℤ+ works too yes
I don't think so. You don't show anywhere that it's divisible by 5? It almost seems like you're stating it's divisible by ℤ+
It almost seems like you're stating it's divisible by ℤ+
yep, that's what i am trying to do.
i have already proved (or so do i think).
You want to proof it's divisible by every integer greater than 0?
yeah, provided the power n is a positive integer
also wrote a program to verify this.
You mean that for every integer n greater than 0 it's divisible by 5 I hope?
yeah, like if n = 1 then 2^(4-1) -3 = 5
Yeah then what you sent is wrong
You want to show its divisible by 5
So be sure to add the 5 to the left of the bar
Giving
$\forall n \in \mathbb{Z}^+, 5 \mid 2^{4n-1}-3$
Yeetus
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shouldn't be the answer to this is
-csc2x/2 +c
,w int csc2x cot2x dx
how?
okay thank you got it
the answer should be 27(x^2/2 -x)+c
last one
should it be
e^-x/5 . dx?
i got it
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Hi guys can yall help with times and dates
Imma wait some time
While i watch youtube
aND SPEED
Road time speed im going to have a test from tha
Yep
Yeah
I got a test from time speed road
ok
I am gonna get
time speed and distance relation?
Oh you are learning interesting stuff comrade
anyways
for this particular thing
you need to just now one thing
Ok
Distance = Speed × Time
What is distance?
its the amount that youve traveled for a certain speed
for a certain time period
so let's say Jimmy drives 40 minutes at 60 miles per hour (or kilometers whatever)
how many miles/kms has he driven?
60
Yeh
he is driving around at 60 per HOUR so we need to unite the units
at hour
so this would change to:
Jimmy has driven around for 2/3 hours at 60 kms per hour.
then how much has he driven?
Ok
40 x 60
no no
it looks like 40 times 60
but the 40 is in minutes
and the 60 is in hours
so 40 should be two thirds of an hour
Yeah
I am in grade 6
yes
I do
Alrighty then
so we remember that distance = speed × time
then what is speed from this equation?
no no we're talking about the equation distance = speed × time
not the jimmy one
Oh
in distance = speed × time
speed = distance/time
becaus3
we divided both sides of (distance) = (speed) × (time) with (time) to get what speed is
do yiu understand?
Mhm
so then you can do the same with time
distance = speed × time
just divide both sides with speed
distance/speed = time
Oh
ok?
Ok
yup
so lemme ask you a few examples
lets say xavier was driving in his car at 60 miles per hour
and he drove 240 miles
yeah
1h20 minutes
Oh sorry
i thought it was 140
4h
so if we put those 2 numbers into distance/speed = time
yes
you are right
4h
then
let's say richard drove 300 miles at 50 miles per hour
how long has he driven for?
yaa
50 x2 = 100
yes
you saw 300 as 100?
No i am adding
ah ok
ok
would you like to complete that or should I stop you there?
Comp
Yeah
so remember that equation I told you?
Yeah
distance = speed × time
what we want is time rn
so we'll put in the distance
which is 300
and the speed
which is 50
so the equation changes to:
300= 50 × time
YES
divide 300 by 50,and you have your answer right there
YEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEESS
so use the eqquation in your test time
much easier
much faster
just put in the distance speed ans time
whatever the problem gives you the numbers of
and dont forget to unify the units
minutes are not hours
Yeah
you ready?
Wait can i show u somthing
yup!
Was this the xaweir u talke about
Damn i bet hes tires after dat ride
I am ready
Yeah
unite the units
so
someone drove for 30 minutes at 50 mph
but are you going to do a 30 ×50?
No
30 mins is in Minutes and 50 mph is in Hours
Yewh
Yhe
yaa
I was told at in 1st grade
lol yes
I gave him onion to back away bc he STINKY STANK
do good on that test
Ok
Yes
byeee
Byeee
Yeah
.xlose
Ok'
.close
Wait before u go
?
Can u make another example
Yeha
how many hours did she drive for?
4
Ok ^^
2nd last
YAY
someone drove for 200 miles and the time he drove for was 2 hours
how fast was he going?
So it's the same'
Yeah
so speed = distance/time
theres no need to unite units
both in hours
so speed would be
distance/time = 200/2
=100
Ooh
get it?
So i just need to do the miles 200/2
yes.
/2*
check that theyre both in miles first
Ok
if not you need to unite em
and if they are
out the numbers in the equation
put
put the numbers in distance = speed × time
in our problem
200 was the distance and 2 was the time
so 200=2×speed
-> speed =100
Ohhhhhh
ya
Good that i came here
Ya
Can i friend u
sure why not
What is ur hashtag
Can we talk in the chat
well I have to go to bed so not for long
Ok
but ok for now
🙂
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yu
Ok
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I need help
lhopital
@thorny roost Has your question been resolved?
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If $\vec{a} \cdot \vec{b}$ and $\vec{a} + \vec{b}$ are two unit vectors, then what is the value of $\vec{a} - \vec{b}$?
innocently.innocent.soul
How is the scalar dot product a unit vector?
May be they mean $\vec{a} \cdot \vec{b} = 1$?
innocently.innocent.soul
Show the original question. Screenshot or picture is best
I'm on PC rn... can't send picture from my textbook... but it's exactly the same as the printed question in book.
Doubt
Maybe $\vec{a} \times \vec{b}$
RedstonePlayz09
RedstonePlayz09
$\vec{a} \cross \vec{b}$
RedstonePlayz09
How would that help?
maybe thats what they mean
Do you know the difference between dot product and cross product?
Oops... it asks to find $|\vec{a} - \vec{b}|$
innocently.innocent.soul
This is what you need to resolve
Cross product would explain that
But you likely have a typo
Either through your transcription or a typo in the text
Until you do this, there's no way to tell
Yea that's a typo in the text
Try solving it with this suggestion
Or find an errata online
Can you check my method?
I'm sending
$$|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2\vec{a} \vec{b}$$
$$1 = |\vec{a}|^2 + |\vec {b}|^2 + 2$$
$$-1 = |\vec a|^2 + |\vec{b}|^2$$
Now, $$|\vec{a} - \vec{b}|^2 = |\vec a|^2 + |\vec{b}|^2 - 2\vec{a} \vec{b}$$
$$|\vec{a} - \vec{b}| ^2= -1 - 2 = -3$$
innocently.innocent.soul
Now? |a - b| = sqrt(-3) ?
With the given choices may be answer is sqrt(3)
@zinc ginkgo
$$|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2\vec{a} \vec{b}$$
What does $2\vec{a} \vec{b}$ mean
riemann
2 \vec{a} \cdot \vec{b}
$\vec{a} \cdot \vec{b}$ is given to be 1 as per the question.
innocently.innocent.soul
I applied the formula here.... (a+b)^2 = a^2 + b^2 + 2ab
ab is dot product of a and b.
No that's the typo I said above
.
$|\vec{a} \cross \vec{b}| = ||\vec{a}| |\vec{b}| \hat{n} \sin(\theta)|$
Now what to do? Squaring?
innocently.innocent.soul
What to do 😭
@jovial flower Has your question been resolved?
@jovial flower Has your question been resolved?
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so AB=5sqrt2
if I made FD parallel to CB, angle DFC=90 degrees
angle FDC=60 degrees
so CD=2*FD
CF=sqrt3*FD
since AF=FD, 5=AC=sqrt3*FD+FD
so do I then find FD, CD, use pythag on CD and DE to find the base?
the height at angle C is 5rt2/2
@fickle ledge Has your question been resolved?
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The width of the Circumference River is 3100 meters. The Square Root Bridge spans the Circumference River. If 1/8 of the bridge stands on one side of the river, and 1/10 of the bridge is on the other side, how long is the Square Root Bridge?
@fallow lagoon Has your question been resolved?
the bit of the bridge that is above the river is the left over bit
so you have 1/8 + 1/10 + bit over river
= 1
1 being the entire bridge
@fallow lagoon Has your question been resolved?
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Hey I'm stuck on this problem, I can't calculate the limit when (x,y) -> (0,0)
yo thanks for helping but we didn't learn about this rule for multivariate functions yet so I'm not supposed to use it
What about polar coordinates?
may run into the same problem, Sin(R)->0 as R->0 again so undefined
we didn't see the polar coordinates yet too but I found the answer, we have to use the taylor expansions after using y = mx
thanks for reaching out though !! :))
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I alr know how to solve for x
I don’t think thats what its asking for
@leaden nexus
U have to do it based off of a table
I'm not sure what table it's talking about then, sorry
maybe some weird wolframalpha thing to break down the steps...?
What math is this?
Its Linear Algebra
Try asking in #linear-algebra
I alr did
They gave the same ans
As jukelyn
Buts that not correct
I honestly don't know what a finite field is, sorry
Do you know anyone who does?
That's why I suggested #linear-algebra because someone there might know what a finite field would be
I took lin alg
its a field with a finite number of elements (A set that fulfills certain conditions) here it has 9 elements
^
Can you help
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I'm not sure what I'm supposed to do, I skipped the class because I was with the principal
Well, do you have any ideas about how we can solve this?
Some formula?
Perhaps later on, do you notice something the logarithms have in common?
For the second exercise for example
Their base is the same and they're both logarithms of x
I would just complete the square here
Nice.
y1 = 2, y2 = -1. log3(x) = 2 and log3(x) = -1 what now?
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
Btw if you get that x = negative number, that would not be a solution
Alright
x > 0
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This is the problem I am confused about.
This is what I've tried. I'm just a little confused because I have a (2x/u)dxdu term, which I'm not entirely sure how to isolate.
I feel like a messed up a step in the process
,rotate
@severe stump Has your question been resolved?
<@&286206848099549185> Sorry for the ping, was just wondering
looks like you did y times sqrt(x^2+y^2)?
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Was I not supposed to? It was the original problem at the top
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i suggest
try this formula F'(x) = ((g o f)(x))' = g'(f(x)) . f'(x)
maybe trying to differentiate using chain rule
@fringe plover Has your question been resolved?
looks great

@fringe plover Has your question been resolved?
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int from -1 to 0 (x+1) = 1/2
int from 0 to 1 (cos(pi)) = -1
1/2 - 1 = -1/2
what am I doing wrong?

man this is by collegeboard
are you sure
VulcanOne
pls help
lmao
I saw cos(pi x) for some reason
This is correct
Yeah then everything else is fine
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Im really confused on how to expand bonomial used pascals triange/ Please help me
Do you have a formula for the binomial theorem?
@ancient aspen Has your question been resolved?
no
tatpoj
If this came from school, surely you've been exposed to this before?
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✅
im in 8th grade studying alg 2 rn they havent thought binomial therem
no I havent
Do you understand what the pieces of this formula mean?
or some of them anyway?
@ancient aspen
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.close
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.ask
How do i find the number of complex roots of a function such as
f(x) = z³-6z²+15z-28
Ummm
.ask doesnt do anything
What do i do
ur channel is open, someone will help. sorry i dont think i would be able to, still learning this concept
✅
Just ask your question, someone will see it
How do i find the number of complex roots of a function such as
f(x) = z³-6z²+15z-28
fundamental theorem of algebra should help you out
K let me check
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where did this come from
evaluate the left side using the definition of variance
or use a theorem if you've proven it
thm 3.3
https://www.probabilitycourse.com/chapter3/3_2_4_variance.php#:~:text=The variance of a random,−μX)2%5D.
Definition and examples of variance
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What are you having trouble with?
um im finding that question above hard
Starting of. Which one is the rectangle?
Well if you know the other 3 you could figure it out
and the trapezium
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How do I simply so I can evaluate
can someone help pls, to figure out these questions
recommend making a sub of u = sqrt{x}
see what u get
open ur own channel and delete this
this channel is already occupied and your message kind of clogs it up
I think u sub makes it more complicated?
well
just
I did it
[
-10 \int \f{\s x}{x^2 +x} \dd{x} = -10 \int \f{\s x}{x(x+1)} \dd{x}
]
ah okay
nice
Yeah that’s what I got
Is this also partial
i mean, u can make it be? but why make ur life harder
how do you simplify $\f {\s x}{x}$
Like divide ?
yeah
sure
like just think of it as exponents with $\ds \f{x^{\f12}}{x}$
You subtract exponents
It’s like 1/sqrt(x) then
yeah
so like
[-10 \int \f{1}{\s x (x+1)} \dd{x}]
can you see how the sub u = sqrt(x) makes more sense now?
try subbing it in and see what u get
Change remaining variables to be in terms of u, too
I get 2/(x+1)
I think my answer is wrong
like
after simplifying?
or as ur antiderivative?
Apparently my anti derivative SHOILD be arctan
also just ping me if i dont respond btw
yeah
thats the right answer
so like
how was the u = sqrt(x) sub
what did u get
and what were u steps
Well it’s 2sqrt(x)/sqrt(x)(x+1)
right
Which is just 2/(x+1) after u simplify ?
yeah
thats correct
but
we are integrating with respect to u
so get that x in terms of u
remember our sub of u = sqrt(x)
i hope that made sense lol
Yeah sorry it makes sense
Tbh I’ve never really integrated like that
yeah integrals can be versatile
but anyways we can also do it using partial fractions
but lets finish this way first
what do u get after you get the u in terms of x
Well u just integrate 1/u
And pull the rest out rigut

💀💀💀💀💀
so maybe
let's rewind a bit
You’re integrating in respect to u
So why would the rest matter
we have [
2 \int \f{1}{x+1} \dd{u}
]
The $x$ does not match the integration variable of $\dd u$
we want to make it be in terms of u for the integration to work
we can know what x is in terms of u
from our original sub of
[
\s x = u \textss{so in that case:} x = ?
]
Oh wait it’s u^1/2

so like
Okay I think I need to take a break
My brain is not working
yeah maybe ur brain is a bit fried from integrals lol
Thanks for attempting to help
no worries, good luck
oh btw
u can still do this with uh
partial fractions too
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I'm trying to make heads or tails of this answer
on A and B, like how would you even know thats how?
I was thinkign you would have to use a t table or something
struggling to find anything about it in the notes.
also, is it saying that the values we got for A and B are small or large? how do we know 0.05 should be the cut off here?
shouldnt it be something like 1.96?
@devout furnace

@viscid flower Has your question been resolved?
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Help please I’m confused
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This is the problem I'm confused about. The instructions are Solve the given initial value problem. The differential equation is a Bernoulli equation.
I showed the steps I've tried at the bottom.
If I integrate this function like I'm supposed to though, I have both an x and a u, and I'm not sure which one I'm supposed to use.
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I can’t sleep 
How comes you divided here?
@severe stump Has your question been resolved?
I closed it because I realized what I did wrong lol. I got it right now (I think)
Got it right, yee.
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Does anyone know how to discover the b here?
I know that we discover a by multiplying all the eigenvalues
and we discover a by know that the determinant is the sum of all the eigenvalues
you know $det(A - 7I) = det(A + 7I) = 0$
riemann
that's only 2 equations 
so I guess you wanna do it but refuse to just compute the char polynomial?
cant we do the char polynomial of the matrix and equate coeffs?
is that different from what i wrote?
0$?
I am not sure if I am following
wait
I misspeled
I meant b
c and a I already know how to find
That's the definition of an eigenvalue
That's latex for typesetting math equations
Don't read the code, read the image
@chilly imp Has your question been resolved?
@chilly imp Has your question been resolved?
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Would somebody mind to check if the calculation is correct?
@hollow bay Has your question been resolved?
,w 6/2 * 24/5 + 18/5
,w 92/5
ur off by .4
Check how you simplified $2^{2k+1}$
Andrea276
How did you find 1/6?
Maybe I made a mistake calculating it in my head, but that's not what I get
Andrea276
That's what I was trying to say before
Yohnson
But isnt it 4^k * 2^1
Andrea276
It's correct, but it's different from $4^{k+1}$
Andrea276
So that's the mistake
I dont understand what you mean
These are the steps:
$$2^{2k+1}=$$
$$2^{2k}\times 2^1=$$
$$4^k\times 2=$$
$$2(4^k)$$
Andrea276
$2×4^k≠4^{k+1}$ though, so that's the mistake you made
Andrea276
I see but why does it not work with $$4^k\times 2=$$
Yohnson
Divided by 6^k individually
It does work, that's exactly the result I found
.
Here you don't have that though
So we have:
2 * (4/6)^k
is the same as
(4/6)^k * (2/6)^k
The first is correct, the second is not, how did you find that?
The first is already the correct simplified expression, you don't get to the second by simplifying something more, they're just two different expressions
Wait, it's not a sum, everything is multiplied together!! Once you have the first step of the second line, you can then write that as $2×(\frac 46)^k$ and you're done.
Andrea276
That's the correct way to do it 👍
So i can just split the division when dealing with sums and not multiplications
And thats why the other approach does not work
Yes, $\frac{a+b}{c}=\frac ac + \frac bc$
Andrea276
But with multiplication you mustn't split the fraction like that
$\frac{ab}{c}=a \frac bc$
Yohnson
Yep, exactly
You're welcome!!
Have a good evening!
You too :)
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For this problem do you just find the derivative
Why can’t you do this for the derivative?
how did u get that
Of this
show ur steps bc I think u messed up the chain rule somewhere
This pic won’t load
Isn’t the rule d/dx(a^x)=(ln(a))a^x
So I did ln(x)x^sinx
Multiplied by the derivative of sinx
@leaden nexus
hmmmm
I took the derivative by taking the log and then going from there
I see what u mean tho
,w derive x^sinx
I got the expanded form
Oh
Is what I did correct?
Because my teacher did it by taking the natural log of both sides
Then doing implicit differentiation
To find dy/dx
That’s the right way
yep
Yup np
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hi could someone explain how this is in rref? because in x4 there is no pivot. thanks
@jaunty topaz Has your question been resolved?
not every column needs to have a pivot
x1 doesn't have a pivot either
that said there aren't 0s above the 1 in the last column...
aka rows of 0s are actually allowed... they just need to be moved to the bottom of the matrix
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im trying to convert this 14 bit binary number to decimal: 11 1111 1100 1000.
what are the steps in doing this? im confused if this would be positive or negative.
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I would probably do (8000x1.035)^x=10000 where x is the number of years to solve for x right?
Unless I’m just completely misunderstanding the question idk what formula you’re going on about ngl
Yea
gotca
;-;
No
im waiting
Don't use that
i was just reading the equation
What is the equation substituted by the numbers
Oh it’s monthly mb lol
Sheesh like in 2 years you are rish
Yeah that’s some crazy interest rate
You doing the question or what
yeps
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to flip it, dont you need to factor out a negative? so it would look like this instead
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one more question, why do they flip the integral if the x=1/4 which should be the lower bound?
always? no matter what the x must be the upper bound even if x is smaller than the lower bound?
check the statement of FTC
It may require the upper bound to be greater/equal than the lower bound
I dont think it does
so i think yes
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I'm not the best at solving for variables. Thanks in advance.
