#help-38

1 messages · Page 26 of 1

onyx sky
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rotate

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then integrate

tacit sedge
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?

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as in swap x and y?

onyx sky
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yes

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instead of integrating on x, integrate on y

tacit sedge
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i see

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should i use the linear line to subtract the quadratic

onyx sky
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it will be line -parabola from -16 to 0

tacit sedge
#

i see

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thank you

trim joltBOT
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frozen root
#

how do i write mathematically that any term of 2^4n-1 -3 are divisible by 5 provided n is greater than 0.

frozen root
pearl stream
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I suppose ∀n ∈ ℕ_≥1. 5 | 2^(4n-1)-3 or something like that?

frozen root
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greater than 0
can i replace this with z and plus on top?

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this i think

pearl stream
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I think ℤ+ works too yes

frozen root
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does this works?

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sorry for the handwritten text btw

pearl stream
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I don't think so. You don't show anywhere that it's divisible by 5? It almost seems like you're stating it's divisible by ℤ+

frozen root
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It almost seems like you're stating it's divisible by ℤ+
yep, that's what i am trying to do.
i have already proved (or so do i think).

pearl stream
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You want to proof it's divisible by every integer greater than 0?

frozen root
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yeah, provided the power n is a positive integer

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also wrote a program to verify this.

pearl stream
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You mean that for every integer n greater than 0 it's divisible by 5 I hope?

frozen root
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yeah, like if n = 1 then 2^(4-1) -3 = 5

pearl stream
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Yeah then what you sent is wrong

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You want to show its divisible by 5

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So be sure to add the 5 to the left of the bar

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Giving

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$\forall n \in \mathbb{Z}^+, 5 \mid 2^{4n-1}-3$

solid kilnBOT
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Yeetus

frozen root
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thanks

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thank you

#

.close

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finite tusk
#

shouldn't be the answer to this is
-csc2x/2 +c

wraith hinge
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,w int csc2x cot2x dx

finite tusk
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how?

wraith hinge
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its the same

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csc(x)sec(x)=csx(2x)/2

finite tusk
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there's no sec(x)

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okay another question

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any hints to how solve this?

wraith hinge
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expand the thing

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and then use a certain fact you know about a^3 - b^3 expressions

finite tusk
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okay thank you got it

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the answer should be 27(x^2/2 -x)+c

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last one

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should it be
e^-x/5 . dx?

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i got it

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.close

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blazing niche
#

Hi guys can yall help with times and dates

blazing niche
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Imma wait some time

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While i watch youtube

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aND SPEED

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Road time speed im going to have a test from tha

brittle escarp
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?

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ok

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hello?

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@blazing niche

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@blazing niche

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welp

blazing niche
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Hio

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Sorry

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I am sorry

brittle escarp
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yes

#

@blazing niche

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online?

blazing niche
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Yep

brittle escarp
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ok

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you said you need help with time and dates

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what would be the questionm

blazing niche
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Yeah

brittle escarp
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?

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what is the thing you need help with?

blazing niche
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I got a test from time speed road

brittle escarp
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ok

blazing niche
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I am gonna get

brittle escarp
#

time speed and distance relation?

blazing niche
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YES

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I do

brittle escarp
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Oh you are learning interesting stuff comrade

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anyways

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for this particular thing

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you need to just now one thing

blazing niche
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Ok

brittle escarp
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Distance = Speed × Time

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What is distance?

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its the amount that youve traveled for a certain speed

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for a certain time period

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so let's say Jimmy drives 40 minutes at 60 miles per hour (or kilometers whatever)

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how many miles/kms has he driven?

blazing niche
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60

brittle escarp
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???

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no no

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40 minutes is 2/3 of an hour right?

blazing niche
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Yeh

brittle escarp
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he is driving around at 60 per HOUR so we need to unite the units

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at hour

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so this would change to:

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Jimmy has driven around for 2/3 hours at 60 kms per hour.

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then how much has he driven?

blazing niche
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Ok

brittle escarp
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simple

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2/3 × 60

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40 kms

blazing niche
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40 x 60

brittle escarp
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no no

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it looks like 40 times 60

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but the 40 is in minutes

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and the 60 is in hours

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so 40 should be two thirds of an hour

blazing niche
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Yeah

brittle escarp
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to unite the units

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yes you understand?

blazing niche
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I am in grade 6

brittle escarp
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yes

blazing niche
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I do

brittle escarp
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Alrighty then

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so we remember that distance = speed × time

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then what is speed from this equation?

blazing niche
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60 m per h

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Liles

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Miles

brittle escarp
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not the jimmy one

blazing niche
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Oh

brittle escarp
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in distance = speed × time

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speed = distance/time

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becaus3

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we divided both sides of (distance) = (speed) × (time) with (time) to get what speed is

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do yiu understand?

blazing niche
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Mhm

brittle escarp
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so then you can do the same with time

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distance = speed × time

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just divide both sides with speed

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distance/speed = time

blazing niche
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Oh

brittle escarp
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ok?

blazing niche
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Ok

brittle escarp
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yup

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so lemme ask you a few examples

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lets say xavier was driving in his car at 60 miles per hour

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and he drove 240 miles

blazing niche
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yeah

brittle escarp
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then how long has he driven for?

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remember

blazing niche
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1h20 minutes

brittle escarp
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distance/speed = time

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no

blazing niche
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Oh sorry

brittle escarp
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distance - 240 miles

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no need to be sorry

blazing niche
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i thought it was 140

brittle escarp
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ah sorry

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well the distance is 240 miles

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and his speed was 60 miles

blazing niche
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4h

brittle escarp
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so if we put those 2 numbers into distance/speed = time

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yes

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you are right

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4h

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then

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let's say richard drove 300 miles at 50 miles per hour

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how long has he driven for?

blazing niche
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Ok

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So

brittle escarp
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yaa

blazing niche
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50 x2 = 100

brittle escarp
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yes

blazing niche
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2h

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and

brittle escarp
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you saw 300 as 100?

blazing niche
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No i am adding

brittle escarp
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ah ok

blazing niche
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100+50= 150

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=3h

brittle escarp
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ok

blazing niche
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150+50=200

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=4H

brittle escarp
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would you like to complete that or should I stop you there?

blazing niche
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Comp

brittle escarp
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ok

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go ahead

blazing niche
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200+50= 250

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=5H

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He drove for 6h

brittle escarp
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yes.

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but that way is a bit too hard dont you think?

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you have to add everything

blazing niche
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Yeah

brittle escarp
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so remember that equation I told you?

blazing niche
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Yeah

brittle escarp
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distance = speed × time

blazing niche
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richard

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Yep

brittle escarp
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what we want is time rn

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so we'll put in the distance

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which is 300

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and the speed

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which is 50

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so the equation changes to:

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300= 50 × time

blazing niche
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YES

brittle escarp
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divide 300 by 50,and you have your answer right there

blazing niche
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YEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEESS

brittle escarp
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so use the eqquation in your test time

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much easier

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much faster

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just put in the distance speed ans time

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whatever the problem gives you the numbers of

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and dont forget to unify the units

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minutes are not hours

blazing niche
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Yeah

brittle escarp
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you ready?

blazing niche
#

Wait can i show u somthing

brittle escarp
#

yup!

blazing niche
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Was this the xaweir u talke about

brittle escarp
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LOL

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YES

blazing niche
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Damn i bet hes tires after dat ride

brittle escarp
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Yeah

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Anyways

blazing niche
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I am ready

brittle escarp
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Just remember distance = speed × time

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think logically

blazing niche
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Yeah

brittle escarp
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and remember that minutes are not hours

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unite the units

blazing niche
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What does that mean

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Unite the unite

brittle escarp
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unite the units

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so

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someone drove for 30 minutes at 50 mph

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but are you going to do a 30 ×50?

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No

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30 mins is in Minutes and 50 mph is in Hours

blazing niche
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Yewh

brittle escarp
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1 hour = 60 minutes

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Im sure you know this

blazing niche
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Yhe

brittle escarp
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yaa

blazing niche
#

I was told at in 1st grade

brittle escarp
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lol yes

blazing niche
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And my teacher looked like dis

brittle escarp
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LOL

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SHREK FTW

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lmaoooo

blazing niche
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I gave him onion to back away bc he STINKY STANK

brittle escarp
#

LMAO

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but fr now

blazing niche
#

oK

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Ok

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Ko

brittle escarp
#

do good on that test

blazing niche
#

Ok

brittle escarp
#

good day my good friend

#

remember to close

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.close

blazing niche
#

Yes

brittle escarp
#

byeee

blazing niche
#

Byeee

brittle escarp
#

friend

#

remember to close

blazing niche
#

Yeah

brittle escarp
#

.xlose

blazing niche
#

Ok'

brittle escarp
#

.close

blazing niche
#

Wait before u go

brittle escarp
#

?

blazing niche
#

Can u make another example

brittle escarp
#

alright

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anna drove around 100 miles at 25 mph

blazing niche
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Yeha

brittle escarp
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how many hours did she drive for?

blazing niche
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4

brittle escarp
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good!

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alright then..

blazing niche
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Imma show u anna

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Her she is

brittle escarp
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LOL

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LMAOOOO

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alright but last one

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actually no

blazing niche
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Ok ^^

brittle escarp
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2nd last

blazing niche
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YAY

brittle escarp
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someone drove for 200 miles and the time he drove for was 2 hours

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how fast was he going?

blazing niche
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Mmm

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This one is hard

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Imma try

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I don't understand

brittle escarp
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ok

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remember

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distance = speed × time

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so

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speed = distance/time

blazing niche
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So it's the same'

brittle escarp
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yes

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kind of..?

blazing niche
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200 mph

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He was 200mph

brittle escarp
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....?

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no but

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we're trying to get the speed he was going right?

blazing niche
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Yeah

brittle escarp
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so speed = distance/time

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theres no need to unite units

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both in hours

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so speed would be

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distance/time = 200/2

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=100

blazing niche
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Ooh

brittle escarp
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get it?

blazing niche
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So i just need to do the miles 200/2

brittle escarp
#

yes.

blazing niche
#

/2*

brittle escarp
#

check that theyre both in miles first

blazing niche
#

Ok

brittle escarp
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if not you need to unite em

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and if they are

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out the numbers in the equation

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put

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put the numbers in distance = speed × time

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in our problem

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200 was the distance and 2 was the time

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so 200=2×speed

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-> speed =100

blazing niche
#

Ohhhhhh

brittle escarp
#

ya

blazing niche
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Good that i came here

brittle escarp
#

well Im glad you think so

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is that all?

blazing niche
#

Ya

brittle escarp
#

alright then

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take care my guy

#

have a good day

blazing niche
#

Can i friend u

brittle escarp
#

sure why not

blazing niche
#

What is ur hashtag

brittle escarp
#

I sent a request

#

check

#

yup

blazing niche
#

Can we talk in the chat

brittle escarp
#

well I have to go to bed so not for long

blazing niche
#

Ok

brittle escarp
#

but ok for now

blazing niche
#

🙂

brittle escarp
#

close this though

#

.close

blazing niche
#

hOW

#

How*

brittle escarp
#

type thos

#

.close

blazing niche
#

.close

trim joltBOT
#
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brittle escarp
#

yu

blazing niche
#

Ok

trim joltBOT
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thorny roost
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thorny roost
#

I need help

wraith hinge
#

lhopital

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#

@thorny roost Has your question been resolved?

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jovial flower
#

If $\vec{a} \cdot \vec{b}$ and $\vec{a} + \vec{b}$ are two unit vectors, then what is the value of $\vec{a} - \vec{b}$?

solid kilnBOT
#

innocently.innocent.soul

kindred pier
#

How is the scalar dot product a unit vector?

jovial flower
#

May be they mean $\vec{a} \cdot \vec{b} = 1$?

solid kilnBOT
#

innocently.innocent.soul

zinc ginkgo
jovial flower
vernal briar
#

Maybe $\vec{a} \times \vec{b}$

solid kilnBOT
#

RedstonePlayz09

vernal briar
#

i mean

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$\cross$

solid kilnBOT
#

RedstonePlayz09

vernal briar
#

$\vec{a} \cross \vec{b}$

solid kilnBOT
#

RedstonePlayz09

jovial flower
#

How would that help?

vernal briar
#

maybe thats what they mean

zinc ginkgo
jovial flower
solid kilnBOT
#

innocently.innocent.soul

zinc ginkgo
#

Cross product would explain that

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But you likely have a typo

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Either through your transcription or a typo in the text

zinc ginkgo
jovial flower
#

Wait... let me

#

1.)

zinc ginkgo
#

Yea that's a typo in the text

zinc ginkgo
#

Or find an errata online

jovial flower
#

Can you check my method?

#

I'm sending

#

$$|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2\vec{a} \vec{b}$$
$$1 = |\vec{a}|^2 + |\vec {b}|^2 + 2$$
$$-1 = |\vec a|^2 + |\vec{b}|^2$$

Now, $$|\vec{a} - \vec{b}|^2 = |\vec a|^2 + |\vec{b}|^2 - 2\vec{a} \vec{b}$$
$$|\vec{a} - \vec{b}| ^2= -1 - 2 = -3$$

solid kilnBOT
#

innocently.innocent.soul

jovial flower
#

Now? |a - b| = sqrt(-3) ?

jovial flower
jovial flower
zinc ginkgo
#

$$|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2\vec{a} \vec{b}$$

What does $2\vec{a} \vec{b}$ mean

solid kilnBOT
#

riemann

jovial flower
#

2 \vec{a} \cdot \vec{b}

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$\vec{a} \cdot \vec{b}$ is given to be 1 as per the question.

solid kilnBOT
#

innocently.innocent.soul

jovial flower
#

ab is dot product of a and b.

zinc ginkgo
zinc ginkgo
jovial flower
#

$|\vec{a} \cross \vec{b}| = ||\vec{a}| |\vec{b}| \hat{n} \sin(\theta)|$

#

Now what to do? Squaring?

solid kilnBOT
#

innocently.innocent.soul

jovial flower
#

What to do 😭

trim joltBOT
#

@jovial flower Has your question been resolved?

trim joltBOT
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@jovial flower Has your question been resolved?

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fickle ledge
trim joltBOT
fickle ledge
#

so AB=5sqrt2

#

if I made FD parallel to CB, angle DFC=90 degrees

#

angle FDC=60 degrees

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so CD=2*FD

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CF=sqrt3*FD

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since AF=FD, 5=AC=sqrt3*FD+FD

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so do I then find FD, CD, use pythag on CD and DE to find the base?

#

the height at angle C is 5rt2/2

trim joltBOT
#

@fickle ledge Has your question been resolved?

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fallow lagoon
#

The width of the Circumference River is 3100 meters. The Square Root Bridge spans the Circumference River. If 1/8 of the bridge stands on one side of the river, and 1/10 of the bridge is on the other side, how long is the Square Root Bridge?

trim joltBOT
#

@fallow lagoon Has your question been resolved?

fallow lagoon
#

@fervent thorn

#

oops..

#

<@&286206848099549185>

leaden nacelle
#

the bit of the bridge that is above the river is the left over bit

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so you have 1/8 + 1/10 + bit over river

#

= 1

#

1 being the entire bridge

trim joltBOT
#

@fallow lagoon Has your question been resolved?

#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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magic bobcat
#

Hey I'm stuck on this problem, I can't calculate the limit when (x,y) -> (0,0)

magic bobcat
lone locust
#

Did you try this

#

L'Hôpital's rule( Bernoulli's rule)

#

Hmm or not

magic bobcat
#

yo thanks for helping but we didn't learn about this rule for multivariate functions yet so I'm not supposed to use it

lone locust
#

What about polar coordinates?

nimble stone
#

may run into the same problem, Sin(R)->0 as R->0 again so undefined

magic bobcat
#

we didn't see the polar coordinates yet too but I found the answer, we have to use the taylor expansions after using y = mx

#

thanks for reaching out though !! :))

#

.close

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#
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Ask your math question in a clear, concise manner.
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edgy abyss
#

Can someone guide me through this problem

leaden nexus
#

it wants you to isolate x

#

Are you familiar with PEMDAS?

edgy abyss
#

I alr know how to solve for x

#

I don’t think thats what its asking for

#

@leaden nexus

#

U have to do it based off of a table

leaden nexus
#

I'm not sure what table it's talking about then, sorry

#

maybe some weird wolframalpha thing to break down the steps...?

night zodiac
edgy abyss
#

Its Linear Algebra

night zodiac
edgy abyss
#

They gave the same ans

#

As jukelyn

#

Buts that not correct

night zodiac
#

I honestly don't know what a finite field is, sorry

edgy abyss
#

Do you know anyone who does?

night zodiac
#

That's why I suggested #linear-algebra because someone there might know what a finite field would be

leaden nexus
#

I took lin alg

nimble stone
#

its a field with a finite number of elements (A set that fulfills certain conditions) here it has 9 elements

leaden nexus
#

^

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dim dawn
#

I'm not sure what I'm supposed to do, I skipped the class because I was with the principal

formal sand
#

Well, do you have any ideas about how we can solve this?

dim dawn
#

Some formula?

formal sand
#

Perhaps later on, do you notice something the logarithms have in common?

#

For the second exercise for example

dim dawn
#

Their base is the same and they're both logarithms of x

sturdy leaf
#

I would just complete the square here

formal sand
#

Yes, so what if we express log3(x) as y

#

or any other variable

dim dawn
#

y² - y - 2 = 0

#

So it's quadratic equation

#

Ooh

#

Alright, I got it

formal sand
#

Nice.

dim dawn
#

y1 = 2, y2 = -1. log3(x) = 2 and log3(x) = -1 what now?

formal sand
#

Well, you solve it, x = 3^2

#

and x = 3^-1 = 1/2

trim joltBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

formal sand
#

Btw if you get that x = negative number, that would not be a solution

dim dawn
#

Alright

formal sand
#

x > 0

dim dawn
#

Thanks!

#

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severe stump
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severe stump
#

This is the problem I am confused about.

#

This is what I've tried. I'm just a little confused because I have a (2x/u)dxdu term, which I'm not entirely sure how to isolate.

#

I feel like a messed up a step in the process

zinc ginkgo
#

,rotate

solid kilnBOT
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@severe stump Has your question been resolved?

severe stump
#

<@&286206848099549185> Sorry for the ping, was just wondering

stiff crescent
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fringe plover
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fringe plover
#

pls help

#

I have to calculate F'(1)

mighty gazelle
#

i suggest

cyan lotus
#

try this formula F'(x) = ((g o f)(x))' = g'(f(x)) . f'(x)

mighty gazelle
#

maybe trying to differentiate using chain rule

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#

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fringe plover
#

@mighty gazelle @cyan lotus

#

I got it?

mighty gazelle
#

looks great

cyan lotus
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dire kraken
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dire kraken
#

int from -1 to 0 (x+1) = 1/2
int from 0 to 1 (cos(pi)) = -1
1/2 - 1 = -1/2

#

what am I doing wrong?

#

man this is by collegeboard

#

are you sure

#

VulcanOne

#

pls help

#

lmao

long basin
#

Oh gell naw Ohio

#

,w integrate cos(pi x) from -1 to 0

solid kilnBOT
long basin
#

Well

#

@dire kraken found your error

#

Oh wait I'm dumb

dire kraken
#

cos (pi x)?

long basin
#

I saw cos(pi x) for some reason

long basin
#

Yeah then everything else is fine

pure hatch
#

Wow nice the spam is gone

#

Thank you mods! :)

dire kraken
#

lmfao

#

alright thanks guys

#

5 more % on my grade

#

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pure hatch
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ancient aspen
#

Im really confused on how to expand bonomial used pascals triange/ Please help me

inland orbit
#

Do you have a formula for the binomial theorem?

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#

@ancient aspen Has your question been resolved?

inland orbit
#

Hm, you got this in an assignment?

#

$(a+b)^n = \sum_{k=0}^n\binom{n}{k}a^k b^{n-k}$

solid kilnBOT
#

tatpoj

inland orbit
#

If this came from school, surely you've been exposed to this before?

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ancient aspen
#

.reopen

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#

ancient aspen
#

im in 8th grade studying alg 2 rn they havent thought binomial therem

inland orbit
#

or some of them anyway?

#

@ancient aspen

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lyric turtle
#

.ask

#

Huh

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lyric turtle
#

.close

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lyric turtle
#

.ask

#

How do i find the number of complex roots of a function such as

f(x) = z³-6z²+15z-28

#

Ummm

vivid cloud
#

.ask doesnt do anything

lyric turtle
#

What do i do

vivid cloud
#

ur channel is open, someone will help. sorry i dont think i would be able to, still learning this concept

lyric turtle
#

Oh ok

#

How do i pin the question

#

Currently "huh" is pinned

inland orbit
#

you closed the channel

#

.reopen

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#

lyric turtle
#

.reopen

#

Ah

inland orbit
#

Just ask your question, someone will see it

lyric turtle
#

How do i find the number of complex roots of a function such as

f(x) = z³-6z²+15z-28

kindred pier
#

fundamental theorem of algebra should help you out

lyric turtle
#

K let me check

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bronze moat
#

where did this come from

trim joltBOT
zinc ginkgo
#

evaluate the left side using the definition of variance

#

or use a theorem if you've proven it

bronze moat
#

oh

#

got it

#

thanls

#

thanks*

#

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junior sail
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idle aurora
#

What are you having trouble with?

junior sail
#

um im finding that question above hard

idle aurora
#

Starting of. Which one is the rectangle?

junior sail
#

nah idk witch one is the parallelogram

#

sorry im not the smartest

idle aurora
#

Well if you know the other 3 you could figure it out

junior sail
#

and the trapezium

idle aurora
#

Just study the differences of this.

junior sail
#

ok thanks

#

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wraith hinge
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wraith hinge
#

How do I simply so I can evaluate

#

can someone help pls, to figure out these questions

wraith hinge
#

see what u get

wraith hinge
#

this channel is already occupied and your message kind of clogs it up

#

I think u sub makes it more complicated?

wraith hinge
#

just

#

I did it

#

[
-10 \int \f{\s x}{x^2 +x} \dd{x} = -10 \int \f{\s x}{x(x+1)} \dd{x}
]

solid kilnBOT
wraith hinge
#

nice

#

Yeah that’s what I got

#

Is this also partial

#

i mean, u can make it be? but why make ur life harder

#

how do you simplify $\f {\s x}{x}$

solid kilnBOT
wraith hinge
#

Like divide ?

#

yeah

#

sure

#

like just think of it as exponents with $\ds \f{x^{\f12}}{x}$

solid kilnBOT
wraith hinge
#

You subtract exponents

#

It’s like 1/sqrt(x) then

#

yeah

#

so like

#

[-10 \int \f{1}{\s x (x+1)} \dd{x}]

solid kilnBOT
wraith hinge
#

can you see how the sub u = sqrt(x) makes more sense now?

#

try subbing it in and see what u get

#

Change remaining variables to be in terms of u, too

#

I get 2/(x+1)

#

I think my answer is wrong

wraith hinge
#

after simplifying?

#

or as ur antiderivative?

#

Apparently my anti derivative SHOILD be arctan

#

also just ping me if i dont respond btw

wraith hinge
#

thats the right answer

#

so like

#

how was the u = sqrt(x) sub

#

what did u get

#

and what were u steps

#

Well it’s 2sqrt(x)/sqrt(x)(x+1)

#

right

#

Which is just 2/(x+1) after u simplify ?

#

yeah

#

thats correct

#

but

#

we are integrating with respect to u

#

so get that x in terms of u

#

remember our sub of u = sqrt(x)

#

i hope that made sense lol

#

Yeah sorry it makes sense

#

Tbh I’ve never really integrated like that

#

yeah integrals can be versatile

#

but anyways we can also do it using partial fractions

#

but lets finish this way first

#

what do u get after you get the u in terms of x

#

Well u just integrate 1/u

#

And pull the rest out rigut

#

💀💀💀💀💀

#

so maybe

#

let's rewind a bit

#

You’re integrating in respect to u

#

So why would the rest matter

#

we have [
2 \int \f{1}{x+1} \dd{u}
]
The $x$ does not match the integration variable of $\dd u$

solid kilnBOT
wraith hinge
#

we want to make it be in terms of u for the integration to work

#

we can know what x is in terms of u

#

from our original sub of
[
\s x = u \textss{so in that case:} x = ?
]

solid kilnBOT
wraith hinge
#

Oh wait it’s u^1/2

wraith hinge
#

so like

#

Okay I think I need to take a break

#

My brain is not working

#

yeah maybe ur brain is a bit fried from integrals lol

#

Thanks for attempting to help

#

no worries, good luck

#

oh btw

#

u can still do this with uh

#

partial fractions too

wraith hinge
#

.close

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viscid flower
#

I'm trying to make heads or tails of this answer

viscid flower
#

on A and B, like how would you even know thats how?

#

I was thinkign you would have to use a t table or something

#

struggling to find anything about it in the notes.

#

also, is it saying that the values we got for A and B are small or large? how do we know 0.05 should be the cut off here?

#

shouldnt it be something like 1.96?

#

@devout furnace

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hexed holly
#

Help please I’m confused

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severe stump
#

This is the problem I'm confused about. The instructions are Solve the given initial value problem. The differential equation is a Bernoulli equation.

severe stump
#

I showed the steps I've tried at the bottom.

#

If I integrate this function like I'm supposed to though, I have both an x and a u, and I'm not sure which one I'm supposed to use.

#

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whole coral
#

.reopen

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whole coral
#

I can’t sleep catscream

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severe stump
#

Got it right, yee.

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chilly imp
#

Does anyone know how to discover the b here?

chilly imp
#

I know that we discover a by multiplying all the eigenvalues

#

and we discover a by know that the determinant is the sum of all the eigenvalues

zinc ginkgo
#

you know $det(A - 7I) = det(A + 7I) = 0$

solid kilnBOT
#

riemann

zinc ginkgo
#

that's only 2 equations thinkies

marble wharf
#

so I guess you wanna do it but refuse to just compute the char polynomial?

stiff crescent
#

cant we do the char polynomial of the matrix and equate coeffs?

zinc ginkgo
stiff crescent
#

o

#

no it isnt woops 💀

chilly imp
#

I am not sure if I am following

#

wait

#

I misspeled

#

I meant b

#

c and a I already know how to find

zinc ginkgo
chilly imp
#

yes I am aware

#

i didnt understood the $ symbol

zinc ginkgo
#

Don't read the code, read the image

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#

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@chilly imp Has your question been resolved?

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hollow bay
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hollow bay
#

Would somebody mind to check if the calculation is correct?

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#

@hollow bay Has your question been resolved?

leaden nexus
leaden nexus
#

,w 92/5

wise sinew
solid kilnBOT
#

Andrea276

hollow bay
#

Should be 2 x (1/6)^k

wise sinew
#

Maybe I made a mistake calculating it in my head, but that's not what I get

hollow bay
#

Should be like this

wise sinew
#

No, the same mistake is still there

#

$2^{2k+1}≠4^{k+1}$

solid kilnBOT
#

Andrea276

wise sinew
solid kilnBOT
#

Yohnson

hollow bay
#

But isnt it 4^k * 2^1

wise sinew
#

$2(4^k)$

solid kilnBOT
#

Andrea276

hollow bay
wise sinew
solid kilnBOT
#

Andrea276

wise sinew
hollow bay
#

I dont understand what you mean

wise sinew
# hollow bay

These are the steps:
$$2^{2k+1}=$$
$$2^{2k}\times 2^1=$$
$$4^k\times 2=$$
$$2(4^k)$$

solid kilnBOT
#

Andrea276

wise sinew
#

$2×4^k≠4^{k+1}$ though, so that's the mistake you made

solid kilnBOT
#

Andrea276

hollow bay
#

I see but why does it not work with $$4^k\times 2=$$

solid kilnBOT
#

Yohnson

hollow bay
#

Divided by 6^k individually

wise sinew
#

It does work, that's exactly the result I found

wise sinew
wise sinew
hollow bay
#

So we have:
2 * (4/6)^k
is the same as
(4/6)^k * (2/6)^k

wise sinew
#

The first is already the correct simplified expression, you don't get to the second by simplifying something more, they're just two different expressions

hollow bay
#

I thought I can do it like this

#

But I guess we need to do this

wise sinew
solid kilnBOT
#

Andrea276

wise sinew
hollow bay
#

So i can just split the division when dealing with sums and not multiplications

#

And thats why the other approach does not work

wise sinew
#

Yes, $\frac{a+b}{c}=\frac ac + \frac bc$

solid kilnBOT
#

Andrea276

wise sinew
#

But with multiplication you mustn't split the fraction like that

hollow bay
#

$\frac{ab}{c}=a \frac bc$

solid kilnBOT
#

Yohnson

wise sinew
#

Yep, exactly

hollow bay
#

Yeah I see it now

#

Highly appreciate the help!

wise sinew
#

You're welcome!!

hollow bay
#

Have a good evening!

wise sinew
#

You too :)

hollow bay
#

.close

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covert arch
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covert arch
#

For this problem do you just find the derivative

#

Why can’t you do this for the derivative?

leaden nexus
#

how did u get that

covert arch
#

Of this

leaden nexus
#

show ur steps bc I think u messed up the chain rule somewhere

covert arch
#

This pic won’t load

#

Isn’t the rule d/dx(a^x)=(ln(a))a^x

#

So I did ln(x)x^sinx

#

Multiplied by the derivative of sinx

#

@leaden nexus

leaden nexus
#

hmmmm

#

I took the derivative by taking the log and then going from there

#

I see what u mean tho

#

,w derive x^sinx

leaden nexus
#

I got the expanded form

covert arch
#

Oh

#

Is what I did correct?

#

Because my teacher did it by taking the natural log of both sides

#

Then doing implicit differentiation

#

To find dy/dx

leaden nexus
#

No bc a is supposed to be a number

#

Not another variable

covert arch
#

Oh

#

A has to be a constant

leaden nexus
#

yep

covert arch
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Ohh

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It has to be a constant

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Thank you

leaden nexus
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Yup np

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jaunty topaz
#

hi could someone explain how this is in rref? because in x4 there is no pivot. thanks

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marble wharf
#

not every column needs to have a pivot

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x1 doesn't have a pivot either

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that said there aren't 0s above the 1 in the last column...

leaden nexus
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brittle blade
#

im trying to convert this 14 bit binary number to decimal: 11 1111 1100 1000.
what are the steps in doing this? im confused if this would be positive or negative.

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candid vessel
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candid vessel
#

i know the formula is A(t)=Pe^rt

#

but like how do i make it get 10k

whole rover
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I would probably do (8000x1.035)^x=10000 where x is the number of years to solve for x right?

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Unless I’m just completely misunderstanding the question idk what formula you’re going on about ngl

neon meadow
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Yea

candid vessel
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gotca

neon meadow
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Wait

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Wait

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Wait

candid vessel
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;-;

neon meadow
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No

candid vessel
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im waiting

neon meadow
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Don't use that

candid vessel
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i was just reading the equation

neon meadow
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What is the equation substituted by the numbers

whole rover
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Oh it’s monthly mb lol

neon meadow
whole rover
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Yeah that’s some crazy interest rate

neon meadow
candid vessel
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I am

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but i think his equation is wrong

neon meadow
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It is

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Does the compound interest formula work?

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A=P(1+(r/n))^nt

whole rover
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Yeah sorry my formula would have x has the months instead of the years

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As*

candid vessel
#

yeps

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surreal eagle
#

to flip it, dont you need to factor out a negative? so it would look like this instead

surreal eagle
cunning cliff
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youve flipped it and applied 2 minus signs, thats not right either

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just one.

surreal eagle
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alright, thanks! wasnt so sure

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.close

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surreal eagle
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.reopen

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surreal eagle
#

one more question, why do they flip the integral if the x=1/4 which should be the lower bound?

cunning cliff
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direct application of FTC

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needs x as the upper bound

surreal eagle
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always? no matter what the x must be the upper bound even if x is smaller than the lower bound?

cunning cliff
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check the statement of FTC

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It may require the upper bound to be greater/equal than the lower bound

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I dont think it does

surreal eagle
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alright, once again thanks!

#

.close

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narrow sky
#

I'm not the best at solving for variables. Thanks in advance.