#help-38
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please may you explain what you mean. im not sure
$\limit{3 + 4e^{0.5x}}{x}{- \infty}$
Umbraleviathan
Well e^(-infinity) = 1/e^(infinity) = 1/infinity = 0
So it becomes 3 + 4(0)
Which equals 3
1/5
1/5 or 1/67
As the denominator gets real big, that 1 ends up being nothing in comparison
Also, is it the same as saying "how many infinities go into 1? 0"
No
Infinity is more of a concept number
It's not a real number
It has properties to it
ok
thanks
also why is e so special
something to do with growth but i dont get it
Tbh, not real sure. It just kinda governs growth and probability
The real special thing about it is that the slope of e^x is itself
yeah
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because you only measure out so many decimal places.
saying the area is infinite is kinda like saying pi = infinity, since as you solve for new decimals the number gets bigger, and there are an infinite number of decimals. However, you can be certain that pi < 4, so its uncountable infinity as opposed to countable infinity, which I think you were confused with.
so does y=e^x cross the x axis
so how is the area not infinite
thats the difference between countable and uncountable infinity.
as you move farther to the left on the graph, you get diminishing returns in area to the point where you can calculate out the total area close enough to the answer to be correct.
in practice, the area is technically infinite.
But for the purpose of your calculations, only calculate it out to a max of 4 decimal places unless otherwise instructed.
The area given is 2.718...
but it could be 2.718483058304830385038403903029204390859216508761340856
but at that point all those decimals only make your job harder, so avoid them.
@oblique meadow Has your question been resolved?
No, this isn’t what’s happening here.
What we’re really looking at is the difference between infinitely large and infinitely precise
The number e is not infinite because there are finite numbers bigger than it, for example 3. It’s true that the area keeps growing the further we go out, but the amount it grows by shrinks so much that we remain underneath an upper bound
That... is the difference.
Nope, countable and uncountable infinities have to do with cardinality
A countable set is one whose elements can be paired with natural numbers in a one-to-one fashion
And an uncountable set is one with more elements than natural numbers
But this doesn’t have much to do with limits or area under a curve
Maybe the terminology means something else in another part of the world but it’s pretty standardized afaik
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How would i find the steady state temperature in the box
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Help me!
<@&286206848099549185>
yes?
are you trying to solve a system of equations?
Thank you so much!!
Thank you sooo much @solar sequoia
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i need help. no idea where to start
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$f(x,y,z)=2y^2-3z$
Senoune
hi
I wanna know what would be thought process towards graphing this function
fix each variable and graph
of course if its a multivariable function I recommend just plugging it into wolfie
yeah it's a multivariable function but it's an exercise in the book where it's asking to draw this
without a calc?
ya
sure yeah
Set x = f(x, y, z). I think the best you could do now is see what the graph looks like on selected x planes, e.g., x = 0, x = 1, etc.
On each plane x = k, for some k, you get a parabola and they're all connected.
I'll make you a better plot.
One with the mesh too.
This is the surface x = 2y^2 - 3z. For x = 0, z = 2/3y^2, so it would seem as though the parabolas should be arcing the other way doesn't it.
@prime shoal Has your question been resolved?
yeah quite weird
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Let $K$ be a field and $A \in K^{n\times n}b$, where $A\neq 0$. Prove or disprove:
rank(A) = 1 is true iff vectors $x, y \in K^n$ exist, so that $xy^T = A$ is true.
Levens
What dimension would xy^T have in the first place?
nxn
do a few examples, see if you can figure that out
Think about what it means to be rank 1 matrix and what it means to multiply xy^t
if rank(A) = 1, then A is just multiples of the first row.
How do you multiply xy^t, you'd just multiply each entry of x times the whol vector of y to get a row in A.
for example
$\begin{bmatrix} 1 & 2\ 2 & 4\end{bmatrix}$ is a rank 1 matrix.
Zybikron
,w {{a},{b},{c}}{{x, y, z}}
so then it should be true right?
since that would mean all columns are linear dependent on one other column
which basically means it has the rank of 1
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<@&286206848099549185>
whats the question
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For context, this is the problem:
I'm being asked: What is Terry’s opportunity cost of risotto (in terms of pie)? What is Terry’s opportunity cost of pie
(in terms of risotto)?
This is my answer, but I'm unsure if my thought process is correct: "Terry's opportunity cost of producing one unit of risotto is 2 units of pie, as his PPF is given by P = 4 - 2R. This means that for every unit of risotto he produces, he must give up 2 units of pie production.
Terry's opportunity cost of producing one unit of pie is 1/2 unit of risotto, since the equation of his PPF can be rearranged to R = 4/2 - P/2. This means that for every unit of pie he produces, he must give up 1/2 unit of risotto production."
Can anyone let me know if I'm correct?
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Can I get some guidance on the last step?
Now that you've simplified all the ugly stuff, you can evaluate the limit
Just allow h to approach 0
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more of a physics thing but i am confused about the math so i am asking here, i just wanna confirm that the velocity v = -v_max.sin(wt) here comes from differentiating the component/tangent that is made in the direction equaling Acos(wt) right?
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part B i understand
but idk how to get OC
guys is this solvable
i made the question
pls anyone help
<@&286206848099549185>
@quaint lynx Has your question been resolved?
<@&286206848099549185>
you...made the question?
why would you not know how to solve a question you made
for a hint, let OC = x + iy, and notice CB is parallel to OA
what do u mean
yes
so let point C be x + iy
sorry, i wrote the one before wrongly
and the idea is to find x and y
yep
you have to use B somehow
and so we notice OCB is a triangle
so what is OB, as a vector, equal to?
AC ?
3+8i
i want to represent OB as OC plus some other vector
tell me what that vector is, in terms of the letters of the diagram
OB = OC + CB
right
and now we know OC, but we have no idea what CB is
luckily, we know that, as a vector, CB = OA
because they have the same length and are parallel
yep agreed
so now the question is what is OA
and to find OA we can notice that OA is precisely a 90 degree rotation of OC
can you fill in the rest?
so OA = i x OC ?
the rotation is backwards, so i think it's -i, no?
i thought multiplying by i is anticlockwise
sure, but you have OC: x + iy, and you want to get OA, which is 90 degrees clockwise from OC
then this is where you tell me what you get and what you think you should be doing
sure, it'll just be in terms of x and y
and that's fine, because we still need to look back at what we did to find x and y
rip need to change the questipn
waht one value would make OC solvable
in terms of integers
But i need to create a question
that will work for part b
then good luck lol
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At point P, the orbital arms of the Earth and comet intersect Find the component of the comet's velocity that is tangent to the Earth's orbit at that point Hint: Consider the comet's angular momentum
Does anyone have an approach for me?
sounds like physics #old-network
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This is a T/F question
The contrapositive of this statement is: If $(a_n)$ is bounded, then there exist $M$ for all $N$ such that if $n \ge M$, then $|a_n| \le N$
But that just seems like a stronger statement for this
but yes thats right
oh yeah, ty
KN
the dependence on N is the difference, you can use that definition to show it's unbound for $n\in (N, \infty)$
Max..
not sure
Max..
yeah, so the contrapositive part matches with the definition for bounded. But that is just when n > N, right?
and they should be logically equivalent
so the problem is when n < N
Is that wrong?
Or maybe if I just negate the definition for bounded
Ok. I think I have some idea
Ty
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Ehh
please close the channel if you don't need help in math
.close
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help
EN; 1. Cn is the sum of the squares of the first n non-zero natural numbers, where n belongs to N*.
C4 = 1² + 2² + 3² + 4² = 1 + 4 + 9 + 16 = 30.
Define the sequence (Cn) by recurrence.
- Un = n(n+1)(2n+1)/6
A. Calculate U1
B. Express Un+1 as a function of n.
C. Deduce that Un+1 - Un = (n+1)².
D. What can be said about the sequences (Cn) and (Un)?
FR; 1. On note Cn la somme des carrés des n premiers nombres entiers naturels non nuls, où n appartient à N*.
C4 = 1² + 2² + 3² + 4² = 1 + 4 + 9 + 16 = 30.
Définir la suite (Cn) par récurrence.
- Un = n(n+1)(2n+1)/6
A. Calculer U1
B. Exprimer Un+1 en fonction de n.
C. En déduire que Un+1 - Un = (n+1)².
D. Que peut on dire sur les suites (Cn) et (Un) ?
FR;
-
La définition de la suite (Cn) par récurrence est: Cn = Cn-1 + n², avec C1 = 1.
-
A. U1 = 1 * 2 * 3 / 6 = 1.
-
B. Un+1 = (n+1)(n+2)(2n+3) / 6 = (n+1)^2 (2n+3) / 6 + (n+1)(n+2) / 2.
EN;
-
The definition of the sequence (Cn) by recurrence is: Cn = Cn-1 + n², with C1 = 1.
-
A. U1 = 1 * 2 * 3 / 6 = 1.
-
B. Un+1 = (n+1)(n+2)(2n+3) / 6 = (n+1)^2 (2n+3) / 6 + (n+1)(n+2) / 2.
who can help me for Deduce that Un+1 - Un = (n+1)².
i have issue in the calcul
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To derivate this , do i apply the rule f'(x) * g'(x) =f' (x) * g(x) + f(x) * g'(x)* ?
Yes, you have to use the product rule here.
do i apply the rule f'(x) * g'(x) =f'* (x) * g(x) + f(x) * g'(x) ?
this rule is incorrectly written
on multiple counts
but yes, to take the derivative of your function, the natural choice of rule is product
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Can someone explain how the top and bottom parts of C turn into what it turns into?
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Please don't occupy multiple help channels.
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I got two different answers here.. did I not factor the conjugate correctly?
0/0 is not an answer
only an indication that direct substitution does not work as is
But it lead me to 0/0
maybe L'Hopital's rule is useful here?
When I kept it as factor it led me to 2
why did you foil is step 3
Haven’t learned that yet
you couldve done the cancellation already
How so?
only foil the bottom line, keep the top line in factor form
Yeah but my point is when I foil I get 0, when I leave numerator in factored form I get 2
That’s normal? Or weird
show
So this sort of stuff happens all the time?
try this: lim x-> 4 (x^2-16)/(x-4)
when you take limit x -> 1, that means x is approaching 1 from either side but NEVER equal to 1
Yes I know
So, you can't have 0/0
yeah
But then I also get a different answer if I use difference of two squares
so when you do some algebra, it will show you the coordinates of the hole
8 is the answer?
That means there is still a hole at x=4
dividing by 0 is weird like that
Does it indicate the y coordinate for the hole?
yes, but if you were looking at the function, the hole is incredibly small, that we can use limits to assume its position
yup
How would I find the y coordinate for the hole at x=4?
the limit
8?
yes
yup
in your original problem, the hole is at (1,2)
It is?
yes
How did you get(1,2)?
lim x->1 (function)=2
yes, its a sign you have to do more work
Interesting! Thank you!
youre welcome 
@vagrant marsh Have you ever had a problem where the final answer is 0/0?
Just curious
Or it always means you can do more work to solve it
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how do you solve this
monikanicity
,w ln(71088884/6)
is that the answer? lol
@dense breach its still wrong
also how do you do the one under that>
the one under it you just plug in 2 to find p(2) and then plug in p(2) to get f(p(2))
okay
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How do u do q4?
Draw a trinagle
Remember what sec is defined as, then as they said, double angle formula
Sec is 1/cos
So 1/cos2x
1/cos²-sin²
1/(cos²-sin²)
Then do i use a calculator?
Remember there are three versions of the double angle formula for cos(2x)
Ohh yea
...and we are given sin(x)
...well technically you could, but there's no need
Oh
chartbit
...
I am not sure
So right now we basically have said that $\sec(2x) = \frac{1}{1 - 2({\color{green} \sin(x)})^{2}}$, and we have that ${\color{green} \sin(x)} = \frac{3}{5}$, right?
Note the careful way I wrote it...
...If I said to work out something like 3y^2 - 4 when y = 5, could you do that for me?
chartbit
Was my bad for not doing it in the first place, sorry about that!
You don't need to find x here
What are we trying to find
sec(2x), given that sin(x) = 3/5
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Have you learned law of cosines yet?
pythagorean theorem?
Yes both
you can use either
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Hello I need help with a projectile motion question
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@frank axle Has your question been resolved?
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Are these lines both equal?
the first one is abuse of notation
The first is how Professor Leonard teaches it
By coincidence yes
There must be some context to it
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i do
oh u just gotta type?
slay
https://screenrec.com/share/zvw2WAICu9 Anyways thats my assignment and I wanna check its right pls
Its trig
and
radians
9someone help pls
maybe you should submit and then you'll find out
😭 i cant afford to lose points im already failing
just screenshot and upload
Are you saying that this is a graded assessment?
Kinda but not really
i get teacher points if i get this right
not like in my actual grade
is that allowed?
Oh alright, fair enough, think that should be fine then, carry on!
As long as it's not on your grade then you should be fine I think 
Read the question carefully
oh mb
Same here
is it like 12 something?
Yep, the number you gave is correct, but it should be in terms of a multiple of pi [which you have given it just now!]
How are you getting this one?
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OOOH OKIE
Seeing we have the channel back, wanna tell me how you got this?
lemme look for my workk
oh mb
its 24
is that still wrong?
This here 
Right for this one you may need to help me a bit, not used to the terminology
[I think the rest have been catReacted to already
]
What do they mean by "coterminal angles"?
coterminal angles are angles that differ by an integer multiple of a full turn
i.e. their terminal rays are the same
yay
Ah, thank you for that
in that case...
to this one then?
yay
also can u explain how i could fix this? dont give out the solution but rather what i did wrong?
Again, read the question, what they ask for, and check your calculator
You're technically correct, but you didn't answer the question they asked
tl;dr ||you had your calculator set to radians but the question asks for degrees||
ahh
hence my
and spelling out deg[rees] as reacts
But other than that, I think you have everything there, right?
gotcha
yess I have another quizz too tho
Cool cool, well feel free to do it and then send the questions here, you'll be alright! 
thank youu
also is it 12.5 for this one?
pi
12/pi?
I'm confused
ahh
[can be written as 12pi, hence my reacts there too!]
but thats my answer 37.68
Don't worry, if you're around long enough, you'll get used to me! 
Read the question!
im sorry bro i'm stupid 😭
You aren't
just make sure you take things slowly and make sure you check what they ask of you!
You're alright for the most part, most of the ones you didn't get here are because you didn't check the question, not because you didn't know how to do it!
See this one was correct but in the wrong units...
...this one was correct but not in the form asked, and...
...this one was assumedly a small error you made in your working out!
do i just put 12 pi or something then?
is that ok cause theresinches afterwards
``$12\pi \text{ in}$" is fine to write
chartbit
okieokie
also how do i fix this
again, really sorry for bugging you
oh mb
you told me
degrees
Yep make sure your calculator is set to degrees then!
There ya go, you have that one 
this is the other quiz- for the second one idk what 4 is
i hate this kinda division, my other answers wre- and another one
Domain restrictions is a 
incomplete simplification
what does track mean
both of them?
You have the right idea [you're "on the right track" to the answer] but [in this case] you need to keep going
also for this 2x_2/3x+5?
, with the way you've written it, not quite
is this right?
@whole coral u thereee
sorry if im annoyyinggg
Hey hey, sorry, tiny bit multitasking!
nonono dw bout it im so grateful for your help sis
[I'm also going though your questions in the "easiest to hardest" way too lol]
hahaha totally understandable
I was just asking cause I need to submit it sooon
my teacher's waiting for me haha
Try to substitute the solutions you found back into the original equation, and see how that turns out 
you right it's 2 and 1 as extraneous?
Yep, dividing by zero, very illegal 👮♀️
Anyways other than one I think I've answered them all for you?
what does telephoen cat mean
oh wait this one too, give me a sec
It's just a placeholder to remind myself I've done that for you
also is it -2/3x+1
oo okie
was it right tho
,w (x+1)/x + (x^2 + 5x)/(x^2 + 4x - 5)

i think x is the number of loaves because that seems like the only thing variable here
Actually this isn't total cost but average cost
oo u right
You want the total cost
4+(x-1)?

Matter of fact that seems fine to me I think!
[n.b. I cannot be held liable if I've made stupid mistakes or anything lol]
also what was the answer to this
never ily
Try it out again, I shall say to you
You have the same denoms do just add the numerators
it is!
oh lol you said that here, I'm blind 
Sorry for that 
ahh i got this wrong its the 4th option
dw bout it at alll
you're amazing
Yea actually you say that, they're really sneaky for that
I literally wrote down the fourth but didn't notice yours was different, sorry!
I got $\frac{3x+4}{2(x-1)}$ on my paper here
chartbit
Awww thank you 
ikrrrr
dwwwww
atleast i submitted it thank youuu
No worries, hope you have a good one! Best of luck with everything! 
Thank youuu have a wonderful nighttt

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u must integrate
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Which graph is better
,rotate
How should I do this
How do I take the area of this
I goofed the second graph
Fixed it
But how can I take the area
Whilst accounting for the y=1 bound
Should I take with respect to x or y
@wraith hinge Has your question been resolved?
<@&286206848099549185>
@wraith hinge Has your question been resolved?
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i have no clue how to do this
is this a test?
sounds like they want you to differentiate
how would i go about doing tht
use the fact that the vertex of a parabola is a local min/max
and the derivative at a local min/max is zero (Fermat’s theorem)
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how do i find the derivative of tanx using product rule
Please don't occupy multiple help channels.
.close
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Hi, i need help on that Limit
I dont know what to do with the factorial x tbh
the exp() way probably doesnt lead to anywhere, but i dont see anything i can do with the lim
for first divide everywhere by x^x
notice that x! = o(x^x) ie x!/x^x -> as x -> infinity
yes, just use what I mentioned
yes, but i dont understand what you mentioned
$\lim_{x \to \infty} \frac{x!}{x^x} = 0$
numbpy
Seems like this limit diverges
yes, its infinity
That's not hard, use sterling approximation
or take log both sides then use sterling approximation
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how can calculate alpha and beta if i know that the sum = 47 degrees. 4 lb is a force vector, as well as 19 lb, and 21.924 is the resultant, 19 lb vector is on the x-axis
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Hi
So its confusing me where cotangens tangens sin and cos have to be
Translation Exercises 1) Draw the 4 trigonometric numbers in one trigonometric circle for an angle E II
You are confused why the tangent and cotangent are on the place where they are?
Ye but i mainly asking where they should be idk if i noted it correct on my papers
No look each seperate line is named
Is this thing tan?
There is tan cos and sin but also cos B sin B Tan B and Costg B that should be put on each line
Idk its wrong i think but thats Tan B its either bottom or above the circle where it should be
I don't really get how did you conclude that length of that segment is tan but it seems wrong
It all also depends on this number always give its either 1 2 3 or 4 its where u should make a line
U see what i circled u see above t thats stand for tangens just a shortening for me
I already said there is tan cos sin and sin B tang B Cos B and Cotangens B
Between the 2 yellow lines is 1 tang B and where i drew an arrow pointed at t is tan
what does tan even mean?
Tan is a function
it's possible to show tan(B) but how do you show tan on the picture
Drawing tan is the same as drawing ². You can graph x² but not just ²
As well as you can graph/visualize tan(B) but not just tan
this is tan(B)
I already posted a pic for quadrant I. the length is tan because of the right triangle. Tan(a)=opposite/adjacent=orange/1=orange
This thing you posted is perfect. It shows everything
I already saw these pic online thats why i came on this server those pics dont show what i need
And what do you need?
B is just a name i can be A or C
okay and what do you need to do?
This
Knowing where tan B cos B cot B Is
what between the 2 yellow lines is 1 tang B
? Ye there are 2 line one of them is NOT IMPORTANT AND WRONG the other is Tan B
B is just a name its can be named Tan Hh
just reposted the question for helpers
Oh ok
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"Analytically determine" in this question means to calculate this by hand right?
Yes
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"Thanks Giannis!"
_money
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Hello, I would like to know how I can get some sort of "slight" version of a direction vector. Say an object is moving in a direction, i want it to move in that direction, but not directly, kinda like slightly towards it.
that doesn't quite make sense
are you saying an object is moving in a direction A, and you want it to slightly deviate to direction B?
No no
the object is moving forward constantly
like, wherever it's facing
but it is supposed to slowly turn in the direction of another object
oh
then slowly deviate to the other
i guess
there's many different ways to achieve this. can you give more context to what you're looking for?
i have the direction vector of that other object, however i dont known how i can make it not "directly" go to that direction
hard to explain
okay
ill give u an illustration
you want it to accelerate in the direction of the other object i imagine
not just change velocity to it's direction
take the current velocity vector and add to it the vector pointing at the second object from the first object
this has too many variables i thnk
like the same algorithm could give you both, it just depends on the strength of the acceleration
and the starting velocity of the object
it's in 3d space
uuuuhhhhhhhhh
f:R->R^3 is a curve
it seems that what you want is:
given objects A and B, where A is moving with some velocity v
take the directional vector AB, scale it by some factor, and add it to v
if you want a path its f:[0, 1] -> R^3
sounds about right
this uses time, no?
what time?
i think this is beyond what they're talking about
deity is this for some kind of computer program
then im 99% sure what i said here is what you want
just know that it's very much dependent on your starting positions, velocities, and how you scale the acceleration
you might also want to look at some kind of distance-based acceleration
where the scaling factor depends inversely to the distance, or something similar
Theoretically the object is constantly moving forward, slowly tilting it's direction towards the other object
that is what i want to achieve
yes, and what i shared should give you that effect. it just depends very heavily on the starting parameters and acceleration scaling
ok
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Greetings, what did I do wrong?
@rough linden Has your question been resolved?
<@&286206848099549185>
if you do not say what was asked, how should someone know what is wrong? You are caclulating the height in a triangle. and there are triangles with this height.
Calculate the total surface area of a regular quadrangular pyramid with a base edge of length 18 cm and a side edge of 15 cm. Give your result in square centimeters.
4x12x9 instead of 4x12
Why x9?
what is the area of the triangle?
you are asked to calculate the surface of the pyramid.
the surface is the base-quadrat + 4 times the triangle
the base-quadrat you have calculated with 324
Let’s skip that
now you need the area of the triangle.
I have difficulty with this
The figure shows one of the lateral scans of a regular hexagonal pyramid. Calculate the lateral surface area of this solid.
@final coyote
you do not know how to calculate the area of a triangle?
then look at this:
you have the baseline (18) you have calculated the height (12), so it should be possible to calculate the area of one triangle.
Don't ping random users for help.
is 18*40/2 really 320?
1920
1/2 x 18 x12 = 108, this ist the area of one triangle.
no.
what are you talking about?
"The figure shows one of the lateral scans of a regular hexagonal pyramid. Calculate the lateral surface area of this solid."
@wraith hinge this.
Of how many triangles of area 360 does the lateral surface of the hexagonal pyramid consist?
the task was calculating the surface of a quadrangular pyramid. I dont know why youre talking about hexagonal pramid.
sounds good
i dont think so.
if 2160 is correct you posted the wrong example. Just waste of my time.
2160 is indeed the answer to the question posted in #help-38 message
360 cm^2 whole triangle area and it’s hexagonal pyramid 6 * 360 cm^2
its a very bad style to change the example in a discussion. the original example was #help-38 message
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