#help-38

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long basin
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Take the limit as x approaches -infinity

oblique meadow
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please may you explain what you mean. im not sure

long basin
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$\limit{3 + 4e^{0.5x}}{x}{- \infty}$

solid kilnBOT
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Umbraleviathan

oblique meadow
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still unsure

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wouldnt the number get really big as x tends to infinity

long basin
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Well e^(-infinity) = 1/e^(infinity) = 1/infinity = 0

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So it becomes 3 + 4(0)

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Which equals 3

oblique meadow
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ok thanks

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so why is 1/infinity 0?

long basin
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Think about it

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Which is smaller

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1/2 or 1/5

oblique meadow
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1/5

long basin
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1/5 or 1/67

oblique meadow
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oh

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i see

long basin
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As the denominator gets real big, that 1 ends up being nothing in comparison

oblique meadow
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Also, is it the same as saying "how many infinities go into 1? 0"

long basin
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No

oblique meadow
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why not

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5/2 is how many 2s go into 5

long basin
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Infinity is more of a concept number

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It's not a real number

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It has properties to it

oblique meadow
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so you cant make up 1 with infinity

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so it equals 0?

long basin
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Well 1/infinity infinities go into 1

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Supposedly

oblique meadow
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ok

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thanks

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also why is e so special

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something to do with growth but i dont get it

long basin
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Tbh, not real sure. It just kinda governs growth and probability

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The real special thing about it is that the slope of e^x is itself

oblique meadow
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yeah

long basin
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And I gues s

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Special

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You can google why it's special

oblique meadow
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ok

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.close

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oblique meadow
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.reopen

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oblique meadow
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why isnt the area infinite?

steep yacht
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because you only measure out so many decimal places.

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saying the area is infinite is kinda like saying pi = infinity, since as you solve for new decimals the number gets bigger, and there are an infinite number of decimals. However, you can be certain that pi < 4, so its uncountable infinity as opposed to countable infinity, which I think you were confused with.

oblique meadow
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so does y=e^x cross the x axis

steep yacht
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cross?

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no

oblique meadow
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so how is the area not infinite

steep yacht
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thats the difference between countable and uncountable infinity.

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as you move farther to the left on the graph, you get diminishing returns in area to the point where you can calculate out the total area close enough to the answer to be correct.

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in practice, the area is technically infinite.

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But for the purpose of your calculations, only calculate it out to a max of 4 decimal places unless otherwise instructed.

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The area given is 2.718...

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but it could be 2.718483058304830385038403903029204390859216508761340856

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but at that point all those decimals only make your job harder, so avoid them.

trim joltBOT
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@oblique meadow Has your question been resolved?

dull mountain
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What we’re really looking at is the difference between infinitely large and infinitely precise

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The number e is not infinite because there are finite numbers bigger than it, for example 3. It’s true that the area keeps growing the further we go out, but the amount it grows by shrinks so much that we remain underneath an upper bound

dull mountain
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Nope, countable and uncountable infinities have to do with cardinality

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A countable set is one whose elements can be paired with natural numbers in a one-to-one fashion

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And an uncountable set is one with more elements than natural numbers

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But this doesn’t have much to do with limits or area under a curve

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Maybe the terminology means something else in another part of the world but it’s pretty standardized afaik

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lean lodge
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lean lodge
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How would i find the steady state temperature in the box

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@lean lodge Has your question been resolved?

lean lodge
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.close

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thorny adder
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Help me!

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thorny adder
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<@&286206848099549185>

solar sequoia
thorny adder
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How do I do this task?

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@solar sequoia

solar sequoia
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are you trying to solve a system of equations?

thorny adder
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Yeah

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Can you take a paper and write on it?

solar sequoia
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alright

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i will try to solve it

thorny adder
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Thank you so much!!

solar sequoia
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@thorny adder

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im done

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let me upload it here

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so you can see what I did

thorny adder
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Thank you sooo much @solar sequoia

solar sequoia
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,rotate

solid kilnBOT
solar sequoia
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I hope that helped! 👍

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tribal fractal
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i need help. no idea where to start

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stable drift
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Oh

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Sorry

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I’ll move

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prime shoal
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$f(x,y,z)=2y^2-3z$

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solid kilnBOT
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Senoune

frosty sleet
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hi

prime shoal
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I wanna know what would be thought process towards graphing this function

quartz yoke
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fix each variable and graph

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of course if its a multivariable function I recommend just plugging it into wolfie

prime shoal
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yeah it's a multivariable function but it's an exercise in the book where it's asking to draw this

quartz yoke
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without a calc?

prime shoal
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ya

quartz yoke
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alright

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then what I said

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it's a bit painful but gets you what you want

prime shoal
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so I guess set them to 0?

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and work my way up towards like 3

quartz yoke
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sure yeah

prime shoal
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uhm this is still a bit unclear

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suppose you take (1,1,1) what is f(x,y,z)?

light crystal
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Set x = f(x, y, z). I think the best you could do now is see what the graph looks like on selected x planes, e.g., x = 0, x = 1, etc.

prime shoal
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alright I'll try that

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,w plot f(x,y,z)=2y^2-3z

prime shoal
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so like

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even with this I don't understand

light crystal
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On each plane x = k, for some k, you get a parabola and they're all connected.

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I'll make you a better plot.

prime shoal
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alright

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wait would it be something a bit like that?

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for all x?

light crystal
prime shoal
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alright thanks

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so like

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this plane is for all y?

light crystal
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One with the mesh too.

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This is the surface x = 2y^2 - 3z. For x = 0, z = 2/3y^2, so it would seem as though the parabolas should be arcing the other way doesn't it.

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@prime shoal Has your question been resolved?

prime shoal
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yeah quite weird

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snow bone
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Let $K$ be a field and $A \in K^{n\times n}b$, where $A\neq 0$. Prove or disprove:
rank(A) = 1 is true iff vectors $x, y \in K^n$ exist, so that $xy^T = A$ is true.

solid kilnBOT
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Levens

snow bone
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What dimension would xy^T have in the first place?

digital bison
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nxn

snow bone
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hm yeah what i thought

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is the statement true

digital bison
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do a few examples, see if you can figure that out

snow bone
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im not sure where to start

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since its any vectors

digital bison
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Think about what it means to be rank 1 matrix and what it means to multiply xy^t

if rank(A) = 1, then A is just multiples of the first row.

How do you multiply xy^t, you'd just multiply each entry of x times the whol vector of y to get a row in A.

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for example
$\begin{bmatrix} 1 & 2\ 2 & 4\end{bmatrix}$ is a rank 1 matrix.

solid kilnBOT
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Zybikron

digital bison
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the second row is double the first row.

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,w {{1},{2}}{{1, 2}}

digital bison
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,w {{a},{b},{c}}{{x, y, z}}

digital bison
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so each row is a multiple of [x y z]

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,w {{a},{b},{c},{d}}{{w,x,y,z}}

snow bone
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so then it should be true right?

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since that would mean all columns are linear dependent on one other column

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which basically means it has the rank of 1

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@snow bone Has your question been resolved?

snow bone
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<@&286206848099549185>

wraith hinge
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@snow bone Has your question been resolved?

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strong horizon
#

For context, this is the problem:

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strong horizon
#

I'm being asked: What is Terry’s opportunity cost of risotto (in terms of pie)? What is Terry’s opportunity cost of pie
(in terms of risotto)?

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This is my answer, but I'm unsure if my thought process is correct: "Terry's opportunity cost of producing one unit of risotto is 2 units of pie, as his PPF is given by P = 4 - 2R. This means that for every unit of risotto he produces, he must give up 2 units of pie production.

Terry's opportunity cost of producing one unit of pie is 1/2 unit of risotto, since the equation of his PPF can be rearranged to R = 4/2 - P/2. This means that for every unit of pie he produces, he must give up 1/2 unit of risotto production."

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Can anyone let me know if I'm correct?

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<@&286206848099549185>

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@strong horizon Has your question been resolved?

strong horizon
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<@&286206848099549185>

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gritty zodiac
#

Can I get some guidance on the last step?

inland orbit
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Now that you've simplified all the ugly stuff, you can evaluate the limit

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Just allow h to approach 0

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zinc wagon
#

more of a physics thing but i am confused about the math so i am asking here, i just wanna confirm that the velocity v = -v_max.sin(wt) here comes from differentiating the component/tangent that is made in the direction equaling Acos(wt) right?

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@zinc wagon Has your question been resolved?

zinc wagon
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actually

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.close

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quaint lynx
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pls help

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quaint lynx
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part B i understand

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but idk how to get OC

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guys is this solvable

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i made the question

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pls anyone help

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<@&286206848099549185>

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@quaint lynx Has your question been resolved?

quaint lynx
#

<@&286206848099549185>

north mirage
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you...made the question?

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why would you not know how to solve a question you made

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for a hint, let OC = x + iy, and notice CB is parallel to OA

quaint lynx
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what do u mean

north mirage
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you want to find OC, no?

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you have B

quaint lynx
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yes

north mirage
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so let point C be x + iy

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sorry, i wrote the one before wrongly

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and the idea is to find x and y

quaint lynx
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yep

north mirage
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you have to use B somehow

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and so we notice OCB is a triangle

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so what is OB, as a vector, equal to?

quaint lynx
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AC ?

north mirage
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no, try again

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as a vector

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OB is now a vector

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from O to B

quaint lynx
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3+8i

north mirage
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i want to represent OB as OC plus some other vector

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tell me what that vector is, in terms of the letters of the diagram

quaint lynx
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OB = OC + CB

north mirage
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right

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and now we know OC, but we have no idea what CB is

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luckily, we know that, as a vector, CB = OA

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because they have the same length and are parallel

quaint lynx
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yep agreed

north mirage
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so now the question is what is OA

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and to find OA we can notice that OA is precisely a 90 degree rotation of OC

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can you fill in the rest?

quaint lynx
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so OA = i x OC ?

north mirage
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the rotation is backwards, so i think it's -i, no?

quaint lynx
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i thought multiplying by i is anticlockwise

north mirage
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sure, but you have OC: x + iy, and you want to get OA, which is 90 degrees clockwise from OC

quaint lynx
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oh true.

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my bad

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correct

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then what

north mirage
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then this is where you tell me what you get and what you think you should be doing

quaint lynx
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ok sec

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what

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is it even possible

north mirage
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sure, it'll just be in terms of x and y

quaint lynx
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dang

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prob shgould change the q

north mirage
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and that's fine, because we still need to look back at what we did to find x and y

quaint lynx
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rip need to change the questipn

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waht one value would make OC solvable

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in terms of integers

north mirage
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no idea what you mean, but i think the question is fine as-is

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it's not difficult

quaint lynx
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But i need to create a question

north mirage
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well, it needs a bit of intuition and geometry

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but it's not fundamentally hard

quaint lynx
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that will work for part b

north mirage
#

then good luck lol

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lucid raven
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lucid raven
#

At point P, the orbital arms of the Earth and comet intersect Find the component of the comet's velocity that is tangent to the Earth's orbit at that point Hint: Consider the comet's angular momentum

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Does anyone have an approach for me?

north mirage
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short star
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short star
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This is a T/F question

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The contrapositive of this statement is: If $(a_n)$ is bounded, then there exist $M$ for all $N$ such that if $n \ge M$, then $|a_n| \le N$

subtle lava
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close n > N not n > M

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but i think u know that

short star
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But that just seems like a stronger statement for this

subtle lava
#

but yes thats right

short star
#

oh yeah, ty

solid kilnBOT
subtle lava
#

the dependence on N is the difference, you can use that definition to show it's unbound for $n\in (N, \infty)$

solid kilnBOT
subtle lava
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but what about n < N?

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how can u show it's unbounded

short star
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not sure

solid kilnBOT
short star
#

yeah, so the contrapositive part matches with the definition for bounded. But that is just when n > N, right?

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and they should be logically equivalent

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so the problem is when n < N

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Is that wrong?

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Or maybe if I just negate the definition for bounded

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Ok. I think I have some idea

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Ty

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mellow hull
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Ehh

slow swallow
tepid rock
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.close

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reef walrus
#

help

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reef walrus
#

EN; 1. Cn is the sum of the squares of the first n non-zero natural numbers, where n belongs to N*.
C4 = 1² + 2² + 3² + 4² = 1 + 4 + 9 + 16 = 30.

Define the sequence (Cn) by recurrence.

  1. Un = n(n+1)(2n+1)/6
    A. Calculate U1
    B. Express Un+1 as a function of n.
    C. Deduce that Un+1 - Un = (n+1)².
    D. What can be said about the sequences (Cn) and (Un)?
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FR; 1. On note Cn la somme des carrés des n premiers nombres entiers naturels non nuls, où n appartient à N*.
C4 = 1² + 2² + 3² + 4² = 1 + 4 + 9 + 16 = 30.

Définir la suite (Cn) par récurrence.

  1. Un = n(n+1)(2n+1)/6
    A. Calculer U1
    B. Exprimer Un+1 en fonction de n.
    C. En déduire que Un+1 - Un = (n+1)².
    D. Que peut on dire sur les suites (Cn) et (Un) ?
#

FR;

  1. La définition de la suite (Cn) par récurrence est: Cn = Cn-1 + n², avec C1 = 1.

  2. A. U1 = 1 * 2 * 3 / 6 = 1.

  3. B. Un+1 = (n+1)(n+2)(2n+3) / 6 = (n+1)^2 (2n+3) / 6 + (n+1)(n+2) / 2.


EN;

  1. The definition of the sequence (Cn) by recurrence is: Cn = Cn-1 + n², with C1 = 1.

  2. A. U1 = 1 * 2 * 3 / 6 = 1.

  3. B. Un+1 = (n+1)(n+2)(2n+3) / 6 = (n+1)^2 (2n+3) / 6 + (n+1)(n+2) / 2.

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who can help me for Deduce that Un+1 - Un = (n+1)².

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i have issue in the calcul

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sage anvil
#

To derivate this , do i apply the rule f'(x) * g'(x) =f' (x) * g(x) + f(x) * g'(x)* ?

sage anvil
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And lnx being g(x) , content of () being f(x)?

sour quest
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Yes, you have to use the product rule here.

trim lichen
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do i apply the rule f'(x) * g'(x) =f'* (x) * g(x) + f(x) * g'(x) ?
this rule is incorrectly written

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on multiple counts

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but yes, to take the derivative of your function, the natural choice of rule is product

sage anvil
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yes

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i stumble upon new conundrum

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@sage anvil Has your question been resolved?

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slim forge
#

Can someone explain how the top and bottom parts of C turn into what it turns into?

slim forge
#

<@&286206848099549185>

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@slim forge Has your question been resolved?

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@slim forge Has your question been resolved?

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@slim forge Has your question been resolved?

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lone mauve
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lone mauve
#

I got two different answers here.. did I not factor the conjugate correctly?

trim lichen
#

0/0 is not an answer

#

only an indication that direct substitution does not work as is

lone mauve
#

But it lead me to 0/0

chilly bobcat
#

maybe L'Hopital's rule is useful here?

lone mauve
#

When I kept it as factor it led me to 2

vagrant marsh
#

why did you foil is step 3

lone mauve
vagrant marsh
#

you couldve done the cancellation already

lone mauve
vagrant marsh
#

only foil the bottom line, keep the top line in factor form

lone mauve
#

That’s normal? Or weird

vagrant marsh
#

show

lone mauve
#

I must have messed up somewhere

vagrant marsh
#

no

#

thats classic limit shenanigans

lone mauve
#

So this sort of stuff happens all the time?

vagrant marsh
#

try this: lim x-> 4 (x^2-16)/(x-4)

lone mauve
#

0/0

#

Or

sour token
#

when you take limit x -> 1, that means x is approaching 1 from either side but NEVER equal to 1

sour token
#

So, you can't have 0/0

lone mauve
#

At x = 4 I think

vagrant marsh
#

yeah

lone mauve
#

But then I also get a different answer if I use difference of two squares

vagrant marsh
#

so when you do some algebra, it will show you the coordinates of the hole

lone mauve
vagrant marsh
#

yup

#

so in the original problem 2 is the correct answer

lone mauve
vagrant marsh
#

dividing by 0 is weird like that

lone mauve
#

Does it indicate the y coordinate for the hole?

vagrant marsh
lone mauve
#

How would I find the y coordinate for the hole at x=4?

vagrant marsh
#

the limit

lone mauve
#

8?

vagrant marsh
#

yes

lone mauve
#

Hmmm

#

So the hole is (4,8)? Or…

vagrant marsh
#

yup

lone mauve
#

Hmmmm

#

Interesting

vagrant marsh
#

in your original problem, the hole is at (1,2)

vagrant marsh
#

yes

lone mauve
#

How did you get(1,2)?

vagrant marsh
#

lim x->1 (function)=2

lone mauve
#

Oh right lol sorry

#

So the 0/0 is kind of a dead end in a way

#

It indicates a hole

vagrant marsh
#

yes, its a sign you have to do more work

lone mauve
#

Interesting! Thank you!

vagrant marsh
#

youre welcome happy

lone mauve
#

@vagrant marsh Have you ever had a problem where the final answer is 0/0?

#

Just curious

#

Or it always means you can do more work to solve it

#

<@&286206848099549185>

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lone mauve
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.close

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glass basin
#

how do you solve this

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glass basin
#

help

dense breach
#

5a should have an exponent

#

$6e^{4p^2}$

solid kilnBOT
#

monikanicity

dense breach
#

,w ln(71088884/6)

solid kilnBOT
glass basin
#

is that the answer? lol

#

@dense breach its still wrong

#

also how do you do the one under that>

dense breach
#

the one under it you just plug in 2 to find p(2) and then plug in p(2) to get f(p(2))

glass basin
#

okay

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arctic fjord
#

How do u do q4?

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vagrant marsh
#

Draw a trinagle

whole coral
#

Remember what sec is defined as, then as they said, double angle formula

arctic fjord
#

1/cos²-sin²

#

1/(cos²-sin²)

#

Then do i use a calculator?

whole coral
#

Remember there are three versions of the double angle formula for cos(2x)

arctic fjord
#

Ohh yea

whole coral
#

...and we are given sin(x)

arctic fjord
#

1/(1-sin²x)

#

Ohh

#

1/(1-2sin²x)

#

1/(1-2sin²(inverse sin(3/5))?

whole coral
#

...well technically you could, but there's no need

arctic fjord
#

Oh

solid kilnBOT
#

chartbit

whole coral
arctic fjord
#

I am not sure

whole coral
#

So right now we basically have said that $\sec(2x) = \frac{1}{1 - 2({\color{green} \sin(x)})^{2}}$, and we have that ${\color{green} \sin(x)} = \frac{3}{5}$, right?

whole coral
arctic fjord
#

Ohh equate the 2

#

3/5 =1/(1-2(sinx)²

whole coral
#

...If I said to work out something like 3y^2 - 4 when y = 5, could you do that for me?

arctic fjord
#

Yea 3(5)²-4
3(25)-4
75-4
71

#

I put x in?

solid kilnBOT
#

chartbit

arctic fjord
#

Ohhhhhhhhhhh

#

Ty for putting in in green

whole coral
#

Was my bad for not doing it in the first place, sorry about that!

arctic fjord
#

No no I appreciate it

#

Does x=3.571

#

I mean

#

No

whole coral
#

You don't need to find x here

arctic fjord
#

What are we trying to find

whole coral
arctic fjord
#

Oh now this topics makes sense to me
It clicked

#

Lop

#

Lol

#

Tyty.

#

.close

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wraith hinge
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wraith hinge
#

How do i get the diagonal Ac

#

It's a similar side trapeziod

#

The Area is 24√3

kindred pier
#

Have you learned law of cosines yet?

vagrant marsh
#

pythagorean theorem?

wraith hinge
#

Yes both

kindred pier
#

you can use either

wraith hinge
#

Ah yes

#

I'm blind

#

.close

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frank axle
#

Hello I need help with a projectile motion question

frank axle
#

This is my working out can someone explain what I did wrong?

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@frank axle Has your question been resolved?

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@frank axle Has your question been resolved?

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@frank axle Has your question been resolved?

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lone mauve
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lone mauve
#

Are these lines both equal?

zinc ginkgo
#

the first one is abuse of notation

lone mauve
#

The first is how Professor Leonard teaches it

random citrus
wraith hinge
#

There must be some context to it

lone mauve
#

Commutative property

#

.close

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dry ginkgo
#

i do

trim joltBOT
dry ginkgo
#

oh u just gotta type?

#

slay

#

Its trig

#

and

#

radians

#

9someone help pls

stoic iron
#

maybe you should submit and then you'll find out

dry ginkgo
zinc ginkgo
#

just screenshot and upload

dry ginkgo
#

there's like 12 questions

#

but bet

whole coral
dry ginkgo
#

i get teacher points if i get this right

#

not like in my actual grade

#

is that allowed?

whole coral
#

As long as it's not on your grade then you should be fine I think happyCat

dry ginkgo
#

okie

#

thanks fam

#

what does deg mean

whole coral
dry ginkgo
#

oh mb

whole coral
dry ginkgo
whole coral
whole coral
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@dry ginkgo Has your question been resolved?

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trim joltBOT
whole coral
# dry ginkgo

Seeing we have the channel back, wanna tell me how you got this?

dry ginkgo
#

oh mb

#

its 24

dry ginkgo
whole coral
whole coral
# dry ginkgo

Right for this one you may need to help me a bit, not used to the terminology

#

[I think the rest have been catReacted to already catGiggle]

#

What do they mean by "coterminal angles"?

inland orbit
#

coterminal angles are angles that differ by an integer multiple of a full turn

#

i.e. their terminal rays are the same

dry ginkgo
whole coral
whole coral
dry ginkgo
#

yay

dry ginkgo
# dry ginkgo

also can u explain how i could fix this? dont give out the solution but rather what i did wrong?

whole coral
#

You're technically correct, but you didn't answer the question they asked

#

tl;dr ||you had your calculator set to radians but the question asks for degrees||

whole coral
#

But other than that, I think you have everything there, right?

dry ginkgo
whole coral
#

Cool cool, well feel free to do it and then send the questions here, you'll be alright! catthumbsup

dry ginkgo
#

pi

#

12/pi?

#

I'm confused

whole coral
#

12*pi

#

Multiply them

dry ginkgo
#

ahh

whole coral
#

[can be written as 12pi, hence my reacts there too!]

dry ginkgo
#

but thats my answer 37.68

whole coral
#

Don't worry, if you're around long enough, you'll get used to me! catGiggle

whole coral
dry ginkgo
#

im sorry bro i'm stupid 😭

whole coral
whole coral
#

You're alright for the most part, most of the ones you didn't get here are because you didn't check the question, not because you didn't know how to do it!

whole coral
# dry ginkgo

See this one was correct but in the wrong units...

whole coral
# dry ginkgo

...this one was correct but not in the form asked, and...

whole coral
# dry ginkgo

...this one was assumedly a small error you made in your working out!

dry ginkgo
#

is that ok cause theresinches afterwards

whole coral
#

``$12\pi \text{ in}$" is fine to write

solid kilnBOT
#

chartbit

dry ginkgo
#

okieokie

dry ginkgo
#

again, really sorry for bugging you

#

oh mb

#

you told me

#

degrees

whole coral
dry ginkgo
#

is it 108.66?

#

yayyy

#

thanks

whole coral
#

There ya go, you have that one happyCat

dry ginkgo
#

this is the other quiz- for the second one idk what 4 is

#

i hate this kinda division, my other answers wre- and another one

whole coral
whole coral
dry ginkgo
#

what does track mean

dry ginkgo
whole coral
dry ginkgo
dry ginkgo
whole coral
dry ginkgo
#

2(x+2)

#

3(x+5)

#

okiee

dry ginkgo
#

@whole coral u thereee

#

sorry if im annoyyinggg

whole coral
dry ginkgo
whole coral
#

[I'm also going though your questions in the "easiest to hardest" way too lol]

dry ginkgo
#

I was just asking cause I need to submit it sooon

#

my teacher's waiting for me haha

whole coral
# dry ginkgo

Try to substitute the solutions you found back into the original equation, and see how that turns out catThimc

dry ginkgo
#

you right it's 2 and 1 as extraneous?

whole coral
#

Anyways other than one I think I've answered them all for you?

dry ginkgo
whole coral
whole coral
dry ginkgo
whole coral
whole coral
whole coral
#

Only one is this one here, for which, I'm confused lol

dry ginkgo
whole coral
#

Actually this isn't total cost but average cost

dry ginkgo
#

oo u right

whole coral
#

You want the total cost

dry ginkgo
#

4+(x-1)?

whole coral
#

Matter of fact that seems fine to me I think!

#

[n.b. I cannot be held liable if I've made stupid mistakes or anything lol]

dry ginkgo
whole coral
#

You have the same denoms do just add the numerators

dry ginkgo
#

i think it was -2/3x+1

#

is that wrong

whole coral
whole coral
#

Sorry for that sad_think

dry ginkgo
dry ginkgo
#

you're amazing

whole coral
#

I literally wrote down the fourth but didn't notice yours was different, sorry!

#

I got $\frac{3x+4}{2(x-1)}$ on my paper here

solid kilnBOT
#

chartbit

whole coral
dry ginkgo
#

atleast i submitted it thank youuu

whole coral
#

No worries, hope you have a good one! Best of luck with everything! catlove

dry ginkgo
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winter bluff
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hushed stirrup
#

u must integrate

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#

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wraith hinge
#

Which graph is better

trim joltBOT
wraith hinge
#

.rotate

#

Bruh

night zodiac
#

,rotate

wraith hinge
#

How should I do this

solid kilnBOT
wraith hinge
#

How do I take the area of this

#

I goofed the second graph

#

Fixed it

#

But how can I take the area

#

Whilst accounting for the y=1 bound

#

Should I take with respect to x or y

trim joltBOT
#

@wraith hinge Has your question been resolved?

wraith hinge
#

<@&286206848099549185>

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#

@wraith hinge Has your question been resolved?

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lone flax
#

i have no clue how to do this

trim joltBOT
lone flax
#

qestion

#

pls help

vagrant marsh
#

is this a test?

lone flax
#

no

#

its a assignment

#

R & S = 0

quartz yoke
#

sounds like they want you to differentiate

lone flax
quartz yoke
#

you should know

#

"use calculus"

lone flax
#

yk why im here buddy

haughty oasis
#

use the fact that the vertex of a parabola is a local min/max

#

and the derivative at a local min/max is zero (Fermat’s theorem)

lone flax
#

mm

#

how do i expand y=a(x-r)(x-s)

#

to find y'=0s

wraith hinge
#

isn't this basically by definition of a quadratic function?

#

that it's symmetrical

lone flax
#

oh i got it

#

.close

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lone flax
#

how do i find the derivative of tanx using product rule

trim joltBOT
#

Please don't occupy multiple help channels.

lone flax
#

.close

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ionic jasper
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ionic jasper
#

could someone check my work

#

to see where i went wrong

#

.close

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inner cradle
#

Hi, i need help on that Limit

trim joltBOT
inner cradle
#

I dont know what to do with the factorial x tbh

#

the exp() way probably doesnt lead to anywhere, but i dont see anything i can do with the lim

sour token
#

notice that x! = o(x^x) ie x!/x^x -> as x -> infinity

inner cradle
#

I don't get it

sour token
#

yes, just use what I mentioned

inner cradle
#

yes, but i dont understand what you mentioned

sour token
#

$\lim_{x \to \infty} \frac{x!}{x^x} = 0$

solid kilnBOT
#

numbpy

inner cradle
#

Yes, that solves the problem

#

but i would have to prove that to use it

sour token
#

Seems like this limit diverges

inner cradle
#

yes, its infinity

sour token
#

or take log both sides then use sterling approximation

inner cradle
#

ok, thanks a lot!!

#

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rugged latch
#

how can calculate alpha and beta if i know that the sum = 47 degrees. 4 lb is a force vector, as well as 19 lb, and 21.924 is the resultant, 19 lb vector is on the x-axis

rugged latch
#

this is what ive done

#

.close

trim joltBOT
#
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trim joltBOT
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wraith hinge
#

Hi

trim joltBOT
wraith hinge
#

So its confusing me where cotangens tangens sin and cos have to be

#

Translation Exercises 1) Draw the 4 trigonometric numbers in one trigonometric circle for an angle E II

main sigil
#

You are confused why the tangent and cotangent are on the place where they are?

wraith hinge
#

Ye but i mainly asking where they should be idk if i noted it correct on my papers

main sigil
#

Can you determine the orange length

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Orange=opposite, 1=adjacent

wraith hinge
#

No look each seperate line is named

main sigil
#

Is this thing tan?

wraith hinge
#

There is tan cos and sin but also cos B sin B Tan B and Costg B that should be put on each line

wraith hinge
main sigil
#

I don't really get how did you conclude that length of that segment is tan but it seems wrong

wraith hinge
#

It all also depends on this number always give its either 1 2 3 or 4 its where u should make a line

main sigil
#

This orange length is tan

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so just do the same for II quadrant

wraith hinge
#

U see what i circled u see above t thats stand for tangens just a shortening for me

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I already said there is tan cos sin and sin B tang B Cos B and Cotangens B

main sigil
#

I cant see t in there, sorry

#

Maybe try to highlight the segment, you think is tan B

wraith hinge
#

Between the 2 yellow lines is 1 tang B and where i drew an arrow pointed at t is tan

main sigil
#

what does tan even mean?

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Tan is a function

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it's possible to show tan(B) but how do you show tan on the picture

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Drawing tan is the same as drawing ². You can graph x² but not just ²

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As well as you can graph/visualize tan(B) but not just tan

wraith hinge
#

Huhh? Idk whym?

#

Can u show tan(B)?

main sigil
#

this is tan(B)

#

I already posted a pic for quadrant I. the length is tan because of the right triangle. Tan(a)=opposite/adjacent=orange/1=orange

#

This thing you posted is perfect. It shows everything

wraith hinge
#

I already saw these pic online thats why i came on this server those pics dont show what i need

main sigil
#

And what do you need?

wraith hinge
#

B is just a name i can be A or C

main sigil
#

okay and what do you need to do?

wraith hinge
main sigil
#

what between the 2 yellow lines is 1 tang B

wraith hinge
#

No i drew two yellow lines one of them is surely Tan B idk which

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Thats my question

main sigil
#

Both of them are exactly length 2

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by definition of unit circle

wraith hinge
#

U clearly didn’t learn this

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<@&286206848099549185>

main sigil
wraith hinge
# main sigil

? Ye there are 2 line one of them is NOT IMPORTANT AND WRONG the other is Tan B

#

B is just a name its can be named Tan Hh

main sigil
wraith hinge
#

Oh ok

trim joltBOT
#

@wraith hinge Has your question been resolved?

trim joltBOT
#
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#
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short spruce
#

"Analytically determine" in this question means to calculate this by hand right?

random citrus
#

Yes

short spruce
#

.close

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stoic iron
#

"Thanks Giannis!"

random citrus
trim joltBOT
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pale lynx
#

Hello, I would like to know how I can get some sort of "slight" version of a direction vector. Say an object is moving in a direction, i want it to move in that direction, but not directly, kinda like slightly towards it.

scarlet escarp
#

that doesn't quite make sense

#

are you saying an object is moving in a direction A, and you want it to slightly deviate to direction B?

pale lynx
#

No no

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the object is moving forward constantly

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like, wherever it's facing

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but it is supposed to slowly turn in the direction of another object

scarlet escarp
#

yes what i said

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its moving in one direction

pale lynx
#

oh

scarlet escarp
#

then slowly deviate to the other

pale lynx
#

i guess

scarlet escarp
#

there's many different ways to achieve this. can you give more context to what you're looking for?

pale lynx
#

i have the direction vector of that other object, however i dont known how i can make it not "directly" go to that direction

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hard to explain

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okay

#

ill give u an illustration

scarlet escarp
#

you want it to accelerate in the direction of the other object i imagine

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not just change velocity to it's direction

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take the current velocity vector and add to it the vector pointing at the second object from the first object

pale lynx
#

on the right is what i want

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on the left is what i have

scarlet escarp
#

this has too many variables i thnk

#

like the same algorithm could give you both, it just depends on the strength of the acceleration

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and the starting velocity of the object

wraith hinge
# pale lynx

this is not a vector, path is what you probably want

#

or a curve

pale lynx
#

uuuuhhhhhhhhh

wraith hinge
#

f:R->R^3 is a curve

scarlet escarp
#

it seems that what you want is:
given objects A and B, where A is moving with some velocity v
take the directional vector AB, scale it by some factor, and add it to v

wraith hinge
#

if you want a path its f:[0, 1] -> R^3

pale lynx
#

sounds about right

pale lynx
wraith hinge
#

what time?

scarlet escarp
#

deity is this for some kind of computer program

pale lynx
scarlet escarp
pale lynx
#

Okay

#

ill look at it

#

thanks

scarlet escarp
#

just know that it's very much dependent on your starting positions, velocities, and how you scale the acceleration

#

you might also want to look at some kind of distance-based acceleration

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where the scaling factor depends inversely to the distance, or something similar

pale lynx
#

Theoretically the object is constantly moving forward, slowly tilting it's direction towards the other object

#

that is what i want to achieve

scarlet escarp
#

yes, and what i shared should give you that effect. it just depends very heavily on the starting parameters and acceleration scaling

pale lynx
#

ok

trim joltBOT
#

@pale lynx Has your question been resolved?

#
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rough linden
#

Greetings, what did I do wrong?

trim joltBOT
#

@rough linden Has your question been resolved?

rough linden
#

<@&286206848099549185>

final coyote
#

if you do not say what was asked, how should someone know what is wrong? You are caclulating the height in a triangle. and there are triangles with this height.

rough linden
final coyote
#

4x12x9 instead of 4x12

rough linden
#

Why x9?

final coyote
#

what is the area of the triangle?

rough linden
#

Ok nvm

#

Can you help me with this one?

final coyote
#

you are asked to calculate the surface of the pyramid.

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the surface is the base-quadrat + 4 times the triangle

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the base-quadrat you have calculated with 324

rough linden
#

Let’s skip that

final coyote
#

now you need the area of the triangle.

rough linden
#

I have difficulty with this

#

The figure shows one of the lateral scans of a regular hexagonal pyramid. Calculate the lateral surface area of ​​this solid.

#

@final coyote

final coyote
rough linden
#

Ok and?

#

What am I doing wrong?

#

@dire charm help me

final coyote
#

you have the baseline (18) you have calculated the height (12), so it should be possible to calculate the area of one triangle.

dire charm
#

Don't ping random users for help.

rough linden
#

I did so.

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320 cm

wraith hinge
#

is 18*40/2 really 320?

rough linden
#

1920

final coyote
rough linden
#

Thank you.

#

I mislead

#

The calculation

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It’s 360

#

Thank you

final coyote
wraith hinge
#

additionally, there is more than one triangle

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(remember: hexagonal pyramid)

final coyote
wraith hinge
#

"The figure shows one of the lateral scans of a regular hexagonal pyramid. Calculate the lateral surface area of ​​this solid."

wraith hinge
#

Of how many triangles of area 360 does the lateral surface of the hexagonal pyramid consist?

final coyote
rough linden
#

I got it right

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2160

#

Cm

wraith hinge
#

sounds good

rough linden
#

^2

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Yeah

#

Thanks y’all

final coyote
rough linden
#

It is

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Now I check on my test it was the correct

final coyote
#

if 2160 is correct you posted the wrong example. Just waste of my time.

rough linden
#

read all of the example

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What to calculate

wraith hinge
rough linden
#

360 cm^2 whole triangle area and it’s hexagonal pyramid 6 * 360 cm^2

final coyote
#

its a very bad style to change the example in a discussion. the original example was #help-38 message

rough linden
#

Yeah

#

But I gave up

trim joltBOT
#

@rough linden Has your question been resolved?

#
Channel closed

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trim joltBOT
#
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tacit sedge
#

hi, can somebody help me to crack part d

#

the answers for a b c are:

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a, s=(4,0)

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b, 1

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c, y=-4/3x+16/3

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d, so far, i have coordinate of Q as (16,-16)

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then i don't know what to do