help-38

[feral herald]

Quito esos sin y ya esta no?

Termina en sin/cos

[rugged latch]

Si

[feral herald]

Perfecto

[rugged latch]

Y q llega a ser sin/cos

[feral herald]

Tg

[rugged latch]

Sip

[feral herald]

Muchas gracias amigo por tu tiempo

Gracias a ti he logrado aprender este ejercicio

Llevaba mucho tiempo intentando resolverlo

[rugged latch]

De ninguna problema

[rugged latch]

Sip

Ciao

[feral herald]

Adios

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[wraith hinge]

Anyone know what bibliography matrix means in this context?

Couldn't find much on Google.

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[coral venture]

but instead its x^1/3 I guess?

[whole coral]

That's the inverse of f(x)=x^3

[whole coral]

Differentiate x^(1/3) and compare it to what they have

[coral venture]

well yeah that parts easyt

I guess I don't know how to

get the inverse of a function

[whole coral]

There's also a shortcut to find the derivative of an inverse function:

$$
\frac{d}{dx} f^{-1}(x) = \frac{1}{f'(f^{-1}(x))}
$$

[solid kiln]

chartbit

[coral venture]

I don't know how to find the inverse

I thought it would be like x^-3

but neigh

well actually I can sorta see a cheesed way to do it

[whole coral]

Go on...

[coral venture]

if you have something manipulating x then write the reciprocal

so 5x-13 would just be x/5-13

x^1/3

and tan^-1(x)

[whole coral]

Agree with the latter two

[whole coral]

Not this tho

[coral venture]

how do u find inverses quickly

[whole coral]

Define "quickly"?

[coral venture]

in a fast manner

[whole coral]

I'd just say e.g. let x = 5y+13 and then rearrange for y, at the end

Whether that's "fast" for you, idk

[coral venture]

well if thats the quickest way to do it

then thats a win

thanks

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[brittle blade]

can someone please explain why this is incorrect

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[wraith hinge]

ok

[wraith hinge]

I wanted to know how to answer this tyler series question

I was given the heigh which was h(10) = 25

the speed v(10) = -3

and it's acceleration

a(10) = 1

a'(10) = 3/5

given these values

I was asked to find a function that can approximate the height at t = 11 seconds

how would I go about starting such a question ?

[zinc ginkgo]

you're not given any information about h?

like polynomial or something

[wraith hinge]

thats the info given

nope

I was asked to give a function

[zinc ginkgo]

ohhhh you make it up yourself

[wraith hinge]

yep

[zinc ginkgo]

a cubic should be good

[wraith hinge]

but I am unfamilliar with making taylor series from scrach

[wraith hinge]

cubic ?

[zinc ginkgo]

$h(t) = h_0 + v_0 t + a_0 t^2 + j_0 t^3$

[solid kiln]

riemann

[wraith hinge]

we can do that ?

[zinc ginkgo]

you're supposed to come up with it yourself

sooooo yes?

[wraith hinge]

oh wait yes

[zinc ginkgo]

notice you're given 4 pieces of information

[wraith hinge]

i confused some stuff

[zinc ginkgo]

and there are 4 unknowns here

[wraith hinge]

i thought these were the integrals

😂

now I realise these are the derivatives

of h

[zinc ginkgo]

anti-derivatives don't have as nice notation unfortunately

[wraith hinge]

yeah i know, I just finished with integrals

[zinc ginkgo]

i assume $v = h', a=v'$

[solid kiln]

riemann

[wraith hinge]

my head is about to explode from them

[wraith hinge]

yeah don't worry I am familliar with this

thanks

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[delicate lance]

why'd the teacher start the scale off with pi over 6 ?

[delicate lance]

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[modest shadow]

Hi

[modest shadow]

I've tried so many things I'm still lost

[night zodiac]

Is that a test?

[wary ingot]

@modest shadow

[modest shadow]

No it's a worksheet online

But its a unit I'm leaning

Learning.

[wary ingot]

what have you tried so far

[modest shadow]

I've been just using the numbers 8-2 in all the ways

[wary ingot]

what is the question asking for

[modest shadow]

Multiplying and division and more

Evaluation of the expression

[wary ingot]

alright

so your function is x^2+8

and you want to evaluate when x=16

so plug 16 in the function

can you do that?

[night zodiac]

That's suspicious, because of the angle you took the photo at as well as the fact it states "calculator is allow". Most worksheets wouldn't say that

[modest shadow]

It's a study guide worksheet

Is that allowed?

[night zodiac]

That's fine. I'm just saying, the photo at that angle just makes it look very suspicious, like you're trying to sneak and cheat

[sonic vector]

it might be a test, this looks like a school laptop also

test or not it talks about being graded(ie. if you don't show work [..] you won't get points)

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[sterile stream]

Hi, these aren't my answers. i was wondering if someone could explain each step of this proof im confused about it. The second statement is DA ≅ DA, it kinda looks like an SA

[errant cedar]

@sterile stream da is a common side for both the triangles

[sterile stream]

how

i dont get that

its like on the side

woudn't it like be like DC

or CA

[errant cedar]

Nah not ca

Da common bro

[sterile stream]

wait

[errant cedar]

Seperate both the triangles

In ur mind

[sterile stream]

let me re draw

[errant cedar]

Nd see they are same

In both

Yeee

I can't draw on Android

[sterile stream]

oh

so like because there on the same side

or something

[errant cedar]

Noo

Look

They are a common side

For both the triangles

Both trangles DAE and ABD have side AD common

[sterile stream]

true

but how does it like

OH

gotchu

https://tenor.com/view/facts-brother-true-smoke-gif-23157983

thanks

who you rooting for in wc

[errant cedar]

Wc?

World Cup Or what?

Fifa wc?

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[dreamy harness]

v

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[dreamy harness]

<@&286206848099549185>

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[unreal grotto]

if I am calculating an angle that is related directly to a variable I already know, whilst knowing where the highest value and lowest value of that angle would be, what type of function would I have to use to calculate it?

[unreal grotto]

for example:

would I use absolute or parabola or etc?

[kindred pier]

no idea what you are asking

[unreal grotto]

bacicaly have an angle that is mapped from another variable

and I dont know which type of function I should use to map the variable

@kindred pier

[kindred pier]

not enough information here.

Do you have the original problem?

[unreal grotto]

yes, but this is a much much smaller part in it

the origional equasion is finding a point in space from a mechanism with two lengths and axis than I know the angles and lengths of

[kindred pier]

can you share the original problem as you received it?

[unreal grotto]

could I share you another example of what I am trying to figure out instead, since explaining the problem is harder than explaining what im trying to figure out currently

[kindred pier]

You don't just have the original problem you can send?

Also, sorry but gotta step out now. I'll be back in a few hours, so good luck to ya

[unreal grotto]

ok np thx

should I @ helpers?

[kindred pier]

sure

[unreal grotto]

<@&286206848099549185>

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[unreal grotto]

.reopen

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✅

[unreal grotto]

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[azure moon]

What does "exact solution" even mean here

[random oar]

No decimals

[azure moon]

What's wrong with my answer

[random oar]

You write 1/3 instead of 0.33

Idk

Ask someone else

[azure moon]

...

[digital bison]

Why is it -81?

[azure moon]

I had it as positive before but it was wrong

Nevermind I didn't have the x^2 when i had it was negative

Thanks

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[echo fossil]

4x - 6y = -24 in slope intercept form would be y=4x-6, which would indicate that the y-intercept is (0, -6) correct?

[scarlet escarp]

not quite

[echo fossil]

where am i goin wrong?

[scarlet escarp]

can we see how you got there?

[echo fossil]

Well mx+b where m is the constant rate of change of y when you increase x by 1. B would be the y-int, and -6y would mean that (0, -6) is the y-int?

[scarlet escarp]

im saying you isolated y incorrectly

-6y + 4x = -24
-6y = -24 - 4x
y = ...

[echo fossil]

ooooh i forgot to isolate y first off

ok, so if i subtract 4x from both sides, I can see where I'd get -6y = -24 - 4x

and then divide -24 - 4x by -6 to leave y by itself on the LHS

[scarlet escarp]

yes

[echo fossil]

y = (-24-4x)/-6

so i want to solve that, and the solution is the y-int?

[scarlet escarp]

you want to simplify that, and the term with no x is your solution yeah

it should be 4

can't do math

[echo fossil]

the term with no x?

im actually not sure how i'd go about simplifying that

[scarlet escarp]

y = -24/-6 + (-4x)/-6

-24/-6 = 4

so y = (2/3)x + 4

which is in y=mx + b form

[echo fossil]

ok so id divide both values in the numerator by the denom, not the numerator in it's whole by the denom. 2/3x + 4 I can see how I'd end up with that

which indicates that the y-int is (0, 4), and the slope is 2/3

[scarlet escarp]

yes

[echo fossil]

awesome, i wasn't doin the right steps. thanks for explaining!

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[wraith hinge]

yo how do i get marchzins

[wraith hinge]

im tryna get marchzins

but i forgot the formel

[vagrant marsh]

Whats marchzins in english

[wraith hinge]

accrued interest@vagrant marsh

[vagrant marsh]

Hmm

[wraith hinge]

its the capital stiff

stuff

with zins

[vagrant marsh]

I cant remember the formula sorry

[wraith hinge]

with interest

ight

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[wraith hinge]

no

im asking my grandma now

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[bold island]

Attempted and got 153

Not sure how yo answer b

[digital bison]

the discriminant tells you how many roots a quadratic has

if it's positive, then there are two real roots,
if it's 0, then there's one real root,
if it's negative then there are two complex roots.

[bold island]

Is 153 correct as the discriminant?

If so that means two real roots right

[digital bison]

looks right, yeah

[bold island]

I got it, thanks

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[mellow hull]

Sin-1(2√13/13) = x

Sinx=2√...

Draw triangle

[spring thorn]

the square of (2 root 13) is 52

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[dry canopy]

Am I approaching this right?
Because my lecturer said we are never supposed to get decimals on any of the questions he uploads but I feel like I will end up with unexact values at this rate

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[dry canopy]

<@&286206848099549185>

[dry canopy]

<@&286206848099549185>

[dry canopy]

<@&286206848099549185>

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<@&286206848099549185>

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[calm gull]

Hi

I don't see the need for you to 'solve those equations'. Just continue your matrices until you get 1s and 0s.

[willow steeple]

You can solve it by matrix inverse

[dry canopy]

How?

What would I do with the inverse of the matrix?

@willow steeple @calm gull

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[austere cedar]

@dry canopy
Your question isn't very clear. It seems to me like you know what to do, and just haven't done it yet

You are about to solve simultaneously. I suggest instead doing a row reduction, but that's really the same thing

,w eigenvalues of {{1,2},{2,-1}}

[solid kiln]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[austere cedar]

So far so good

[dry canopy]

But I don't know how to do so without decimals

[austere cedar]

?

Can you rephrase the question there?

[dry canopy]

Usually we are expected to do a method that gives us exact values

If I go ahead with how I'm thinking I will not get an exact value

[austere cedar]

sqrt(5) is an exact value

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[warm kindle]

A test has 13 multiple choice questions; each multiple choice question has four responses, A, B, C, and D. There are 4 A's, 1 B's, 1 C, and the rest are D's. How many different ways can these questions be arranged to create a different answer key?

[warm kindle]

not sure how to work through this one

how would i find how many different ways they can all be arranged

[frozen plover]

Do you know how to group and arrange

[warm kindle]

yea but im not sure for this one because all the letters can be in different spots

they dont have to be together

[frozen plover]

For example if you're arranging 6 identical books on math and 5 identical books on science in a shelf, the total number of ways would be $\frac{11!}{6!5!}$

[solid kiln]

NEONPerseus

[warm kindle]

ohh so just 13!/4! * 1! * 1! * 7 !

[frozen plover]

Yes that should be it

[warm kindle]

thanks

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[wraith hinge]

Hello I need help

[velvet cedar]

what do you think the constant term represents

[wraith hinge]

what is a constant term

[zinc ginkgo]

A number without a variable

For lines like y=mx+b, b is the constant term

[wraith hinge]

ohhhh

well

26 is the constant term ig?

what about the second qs

"How long is the diver in the air?"

[glossy turret]

What's the driver's height when they stop being in the air?

[wraith hinge]

uhm

idk

[glossy turret]

Would be 0, right?

Since when they are not in the air anymore, they are on the ground and so have a height of 0

[wraith hinge]

WAIT

all i need to do is factor right??

[glossy turret]

Yes

[wraith hinge]

i got two answers

[glossy turret]

What are they?

[wraith hinge]

t = 1, 13/8

[glossy turret]

Would it make sense for them to hit the ground again after they already hit it?

[wraith hinge]

nope

[glossy turret]

So you can safely eliminate the second answer

Also I'm just assuming you factored correctly 🙏

[wraith hinge]

okay yes i did

but wdym carefully eliminate

[glossy turret]

Safely eliminate

Just that it's not a valid answer

[wraith hinge]

uhm

how

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[wraith hinge]

uh

that isnt teaching me how to eliminate @glossy turret

[glossy turret]

does it make sense for them to hit the ground at both 1 second and 13/8 seconds?

[wraith hinge]

No

but how do i know which one is true and which one is not

[glossy turret]

just think about it for two seconds. If it hits the ground at 1 second, it will stop, and it will not hit the ground at 13/8 seconds

[wraith hinge]

so

t = 1 is correct?

[glossy turret]

uh

you didn't factor correctly

can i see your factorization

[glossy turret]

this should be t = -1 , 13/8

in which case it doesn't make sense to have a negative time , so 13/8 is your only valid answer

[wraith hinge]

oh

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[hasty yew]

Does anyone know how to solve part bii)? (Leslie Matrix question).

[hasty yew]

Do I just do xk = L^k * x0

where x(subscript k) is the population vector after k years, and x0 is the initial population vector

so x0 = [54, 6, 1]

Is there a way to solve this question without doing trial and error, i.e. doing several multiples of L and x0, then summing all of the components of the resultant vector until I get a sum greater than 10,000 (I feel like this will take forever)

[trim jolt]

@hasty yew Has your question been resolved?

[austere cedar]

Not certain what a leslie matrix is. Does multiplying by it advance population by a year?

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[austere cedar]

Note that x0 is an eigenvector of L. What does that mean for you? Can that help here?

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[austere cedar]

Sorry, confused it for mean value theorem

Okay, so by ivt, there exists some f'(c) = -2

It wants you to find it, which is easy to do algebraically

3c² + 14c + 6 = -2

Yes. Note that by ivt, there exists a c somewhere in [-6, -3]. You want that value

No since ivt doesn't take the derivative of said function.

f' being the derivative of some other function doesn't matter to ivt at all, really. Could have called it g(x)

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[austere cedar]

y-int is when x = 0

[spring otter]

i think the change of base of lig formula is incorrect

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@weak orchid Has your question been resolved?

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[hushed stirrup]

similar triangles

[midnight wind]

how do I find x

[trim lichen]

have you made any progress thus far or are you stuck not knowing how to start?

there is a clever way to do this.

[midnight wind]

so what I know or have tried is

I first did 6/10-y to find a side

[mortal breach]

iirc there's a theorem about that that includes geometric mean

[midnight wind]

6/10-y = 10/6

[trim lichen]

what's y?

[midnight wind]

the side which I don't know

[trim lichen]

okay...

[midnight wind]

can I not do that?

[hushed stirrup]

its like the lower part of the hypotenuse ig

[trim lichen]

multiple issues w/ that.

i mean you kind of can, it will just be messy...

[trim lichen]

the clever way i had in mind is to express the area of your triangle (the big triangle) in 2 different ways.

[hushed stirrup]

try to find two different similar triangles

[midnight wind]

what's be easier

[trim lichen]

i just said it

[midnight wind]

oops

[midnight wind]

so like this?

[trim lichen]

i mean ok like

if youre gonna go the similar triangles route

then AT LEAST label the diagram

[trim lichen]

something like this, perhaps.

that's if you choose to ignore my suggestion.

[midnight wind]

no no

tell me how you do it

I want to learn the easier way if possible

so I can use it in the future

[trim lichen]

.

i mean, i already did

[broken cave]

Area of the big triangle is
1/2×6×8=24
So x is the altitude or the height then
10x=24 {cause 1/2×bh is the formula for area of the ∆} {also 10 is the base here x is the height}

[trim lichen]

but you chose not to ask me to elaborate

[midnight wind]

mb

[midnight wind]

hmm

[broken cave]

So this is the easiest way

[midnight wind]

but these side lengths don;t seem to be half in length

[trim lichen]

yeah, that's exactly what i had in mind

which "these" sides??

[midnight wind]

the y side

[trim lichen]

...

what

i don't understand your question

[midnight wind]

the base

[trim lichen]

also you do realize that there's a reason why i gave names to all points in the problem??

why do you disrespect the diagram by not using the names written on it?

[midnight wind]

bruh

okay I'll use them

so the 1/2 comes from where

is it to represent half of 10?

[trim lichen]

the half-base-times-height formula for the area of a triangle.

[broken cave]

Area of right angled triangle is
1/2×base × height

[trim lichen]

no it's not to represent half of ten.

[midnight wind]

ok

[trim lichen]

are you familiar with this formula

[midnight wind]

oh ok

[broken cave]

My bad

[trim lichen]

arnab, there exist many formulas for the area of a triangle.

[midnight wind]

yes Its been a while since my school began, we're doing a review so I'm beginning to remember

[broken cave]

You can take out the following triangle by 3 known methods

1. by area ( easiest )
2. Similar triangles ( not too easy )
3. inverse Trigonometry ( fuking hard )@midnight wind

[midnight wind]

jeez

[broken cave]

So you have to use the formula of area of right angled triangle for find x@midnight wind

[midnight wind]

ok

[broken cave]

I already explained that

And your triangle is right angled so there will be no problem

[midnight wind]

so if I were to do this then

[broken cave]

Same method

[midnight wind]

I would do 1/2 * 48 * 20

480

[broken cave]

Yeah

Then?

[midnight wind]

52x = 480

[broken cave]

Yeah

[midnight wind]

~ 9.2

rounded

[broken cave]

,w 480/52

[solid kiln]

Results provided by WolframAlpha

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Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[broken cave]

Yea

[midnight wind]

ok ty

[broken cave]

Welcome

[midnight wind]

.close

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[charred marsh]

hi

[steep sail]

Hi

[charred marsh]

i tried to solve integral of sin(x)/x from -infinity to infinity but i got 2π instead π

i can't find the mistake

[trim jolt]

@charred marsh Has your question been resolved?

[zinc ginkgo]

Your integral doesn't even converge

Don't know how you even got a finite number

Use e^(-tx) instead

[wraith hinge]

[zinc ginkgo]

Oh you're assuming t<0?

[amber python]

[zinc ginkgo]

If you didn't this, you don't need the whole Laplace transform thing

[wraith hinge]

fun times with the sine integral lmao

[wraith hinge]

im not sure if i can see this correctly, but cant u represent this using a gamma function?

okay well

an incomplete one

[zinc ginkgo]

Don't think you need gamma function either

The whole proof OP is trying to do is in Rudin

[wraith hinge]

oh i see thats why they made that double integral

okay

makes sense

[amber python]

[zinc ginkgo]

Lots of gaps in your work, like limits, and simplification of the Laplace transform. Don't recommend using that at all

[zinc ginkgo]

Don't you have cooler emojis from other servers

[amber python]

i do but

[zinc ginkgo]

[amber python]

which do you want me to use

[zinc ginkgo]

A cute thonk

[amber python]

[trim jolt]

@charred marsh Has your question been resolved?

[charred marsh]

no i'm assuming t=0

[charred marsh]

which limits

why no Laplace transform

i mean it's way easier than to do it with integration by parts of something

[zinc ginkgo]

No integration by parts is necessary

[zinc ginkgo]

When you introduce the integral for dt

[trim jolt]

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[charred marsh]

why is it closed :(

[charred marsh]

i'm assuming t=0

[amber python]

dont ignore the bot

you cant differentiate I(t) assuming t=0

[charred marsh]

bro can't handle rejection

[amber python]

there must be an open interval on which I(t) is defined

[charred marsh]

e^(-tu) would work tho right

[amber python]

u?

[charred marsh]

i mean x

[amber python]

[charred marsh]

was looking at another integral with u, sorry

[amber python]

assuming t>0

or e^(tx) assuming t<0

[charred marsh]

t>=0 and t<= right

using e^(-xt) just makes the arctan(t) negative

[abstract stag]

if you assuming t > 0, and using e^(-xt), from scratch I thought maybe problem comes from double integral

[charred marsh]

Wait no

maybe it will work

ahh it works

negative sign made it arccot instead of arctan

and since arccot(0) = π/2

2I(0) = π

[abstract stag]

why arccot,

In your last step, $\int_0^{\inf}\frac{1}{1+t^2}dt$ should be $\arctan \inf - \arctan 0 = \pi/2$

[solid kiln]

请务必再休息一天

[abstract stag]

by the way, in your first line in draft, arctan0 should be 0

[charred marsh]

-1/(1+t^2)

[charred marsh]

the integral with respect to t isn't from 0 to infinity

[trim jolt]

@charred marsh Has your question been resolved?

[abstract stag]

Okey, then last line might be -arctant + C, and use limitation to solve C?

If Indefinite Integration as your way

assuming t > 0, and I(t) = e^(-xt)

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[wraith hinge]

can someone explain to me how my teacher got the angles

[wraith hinge]

like 130

like from the bearing

how do we know it’s a 90 and then it’s another 20 at that point

like why should we apply that 😭

[night zodiac]

Bearing is the angle from N going clockwise

So 200 degree bearing, start from N, go 200 degree clockwise

[wraith hinge]

i’m talking abt the large angle

sry if i didn’t make it clear

[night zodiac]

Same process

250 degree bearing, start from N, go 250 degree clockwise

[wraith hinge]

not that, ik how to get the bearing

135

mb 13

130

[wraith hinge]

this

like how do ik when to apply that

[trim jolt]

@wraith hinge Has your question been resolved?

[wraith hinge]

<@&286206848099549185>

[wraith hinge]

i’m not getting how we get the 20-90-20

.close

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[wise jay]

using the derivative of (x+y)^n and a particular choice of y, show that:

[trim jolt]

Please don't occupy multiple help channels.

[wise jay]

im not

[zinc ginkgo]

Close this one or close #help-6

[fiery spade]

you quite literally are my friend

[wise jay]

i can not see my channels

something is wrong or idk

here is where i arrived

who can help me please?

tell me what to do next

.

[austere echo]

what are you doing @wise jay

[wise jay]

what do ur eyes see

[austere echo]

the sum of something with limits

it reminds me of the bionomial expansion though

[wise jay]

Yes and what else

[austere echo]

the general one?

[trim jolt]

@wise jay Has your question been resolved?

[trim jolt]

@wise jay Has your question been resolved?

[trim jolt]

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[grim spear]

Hello, kinda stuck on this. I only have 1 more attempt and my teacher didn't really teach how to do this, she just gave out a video explaining how to make a box plot on "Desmos."

[trim jolt]

@grim spear Has your question been resolved?

[pure hatch]

Okay do you know how to make a list?

[grim spear]

completely clueless

[pure hatch]

<@&268886789983436800> spamming the same message on multiple help channels

[pure hatch]

Alright

Let's explore making lists later

But for now

Do you know how to get the mean and median?

[grim spear]

very little, this is the first assignment on this topic

[pure hatch]

Hmm

[grim spear]

one of the first*

[pure hatch]

Okay do you know what's a mean?

[grim spear]

yes

the average

[pure hatch]

Do you know how to get it?

[grim spear]

sorta, very confused.

I wouldn't be able to explain it

[pure hatch]

But what would you do to find the mean of let's say the Spudnik list?

[grim spear]

dividing the sum of values?

[pure hatch]

Dividing the sum of values by what?

[grim spear]

just watched a short help video I found, I would divide the sum by the number of values in the data set

So would I take Spudniks values, add them up to 1965 then divide by 8?

[pure hatch]

Yep

Same with Later Tater

[grim spear]

Alright, how would I get the median?

[pure hatch]

You would arrange your data from least to greatest

And see which value is in the middle

If you have 2 values in the middle, you find their mean

[grim spear]

240.5 and 243.5?

[pure hatch]

240.5 is for which and 243.5 is for which?

[grim spear]

240.5 for spud 243 for tater

[pure hatch]

Okay

Yep

240.5 is for spudnik and 243.5 is for tater

Those are the medians

Now do you know how to get the standard deviation?

[grim spear]

yes I think I understand that quite well but not so much Interquartile Range

[pure hatch]

Okay interquartile range requires you to get the 1st quartile and the 3rd quartile values

How to do that? Those need you to divide your data into 2 halves (after arranging them). Then you'd find the median for each half.

[grim spear]

31.0 for spud? still working on tater

and I believe 24.3 for tater

for the standard deviation I got 23.1 for spud and 12.9 for tater

[pure hatch]

How did you find it?

[trim jolt]

@grim spear Has your question been resolved?

[grim spear]

I first took the 8 values and put them least to greatest. I then split the data in between the 239 and 242. I found the Q1 (lower quartile) which is 227 and Q3 (upper quartile) 258 I then subtracted 258-227 and got 31

31 rounded to the nearest tenth 31.0

sorry for the wait I had to take my dog out

[pure hatch]

222 225 233 239 242 243 263 298
0.5(225+233) = 229 and 0.5(243+263) = 253
253-229 = 24

[grim spear]

it's not 24.3 for tater?

[pure hatch]

225 229 234 241 246 253 255 265
0.5(229+234) = 231.5 and 0.5(253+255) = 254
254-231.5=22.5

[grim spear]

is that for tater? I'm confused

[pure hatch]

This is for spudnik

[pure hatch]

This is for later tater

[grim spear]

Thank you, does that finish up part 1?

[pure hatch]

Yeah

[grim spear]

Iwas looking at Question 2 and this is what I came up with

The distribution of the distances for Later Tater is symmetric because the mean and median values are equal.

The mean and standard deviation are better measures of center and variability for the Later Tater distances.

The distribution of the distances for Spudnik is skewed left because of the outlier.

The distances for Spudnik are more variable than those for Later Tater.

Scared to submit because this is my last try can you confirm?

[pure hatch]

Hmm

[pure hatch]

These sentences seem good

[grim spear]

8/9 thank you better than my previous 4 haha

[pure hatch]

Wow what went wrong?

[grim spear]

One of the statements were incorrect

[pure hatch]

Ooo

[grim spear]

The mean and standard deviation are better measures of center and variability for the Later Tater distances.

[pure hatch]

Oo

[grim spear]

No biggie though I'm happy with it thanks!!!

[pure hatch]

Hope you ace the assignments next time :)

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[bleak moth]

.close

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[feral canopy]

Is this true?

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@feral canopy Has your question been resolved?

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@feral canopy Has your question been resolved?

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[last ore]

pretty self explanatory from there

[heady summit]

What class are you in?

[trim jolt]

@last ore Has your question been resolved?

[last ore]

algevra 2

find the domain

of these 2

and the one above

[heady summit]

If I’m being honest with you, I only know how to solve the first problem with calculus lol I do not remember how to go about it in terms of algebra 2

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@last ore Has your question been resolved?

[sterile egret]

Do you know how to find min and max of a quadratic function?

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[wind frost]

a(x+4)^2+2 with vertex (-4,2) which y intercept = 16

[inland orbit]

You're trying to find a?

[wind frost]

replace a with a number

to make the y intercept of the equation = 16

[inland orbit]

Okay so you have y=a(x+4)^2+2

(the y is important)

what does it mean if the y intercept is 16?

[wind frost]

isnt y intercept when x=0

[inland orbit]

yes

[wind frost]

so a(4)^2+2=16?

[inland orbit]

Yeah, exactly

[wind frost]

oh nvm wrong question

it was change a so the equation passes through the origin

[inland orbit]

Okay, that's a very similar question

[wind frost]

is it making x intercept 0

[inland orbit]

Yes

[wind frost]

so when y=0

-2=a(x+4)^2

[inland orbit]

The origin is (0,0)

so plug in 0 for both x and y

[inland orbit]

this is right, but you need to plug in 0 for x as well

[wind frost]

-1/8?

[inland orbit]

yep 👍

[wind frost]

alright thanks i just didnt multiply by a in the right order lol

.close

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[agile prism]

how do i integrate this

[inland orbit]

Seems like a u-substitution should do the trick

What have you tried so far?

[agile prism]

turned it into

cosx+cotx

idk how to integrate cotx

[gritty harness]

[inland orbit]

Hmm, that doesn't seem quite right

You can't break up a fraction over its denominator like that

[gritty harness]

That works as well

[inland orbit]

for example 1/2 + 1/2 is not 1/4

[agile prism]

o

how can i integrate this then

[inland orbit]

Have you covered u-sub?

[agile prism]

ye kinda

make 1+sinx u?

du=cosxdx

[inland orbit]

Yes

beautiful

[agile prism]

alr lemme try

got it thanks

.close

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[desert junco]

(0,-1) is supposed to be open circle right?

[sour token]

,rotate

[desert junco]

oh my bad

[sour token]

This looks a bit messy without proper labelling

Make the cartesian plane a bit wide as in, increase the width between successive marks

[desert junco]

okay let me redraw it

[sour token]

It's definitely not to the scale but pretty good for hand-drawn graph

Here is desmos for comparison

The only issue I can think of is the steep decline of e^x but it's gonna be hard to draw by hand

[desert junco]

yea youre right my e^x looks different

(0,-1) is an open circle right?

[sour token]

Yeah, the open circle at (0, -1) isn't visible cause you need to click on the graph to see it

Don't worry, it is still there

[desert junco]

ahh i see ty for the help! i rlly appreciate it

.close

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[sleek grove]

for graphing a cube root function, how do i know when the graph shifts directions

[split chasm]

wdym by shifts direction

[sleek grove]

lemme send a pic rq

like here

[split chasm]

you could consider the transformation of the parent cbrt function

[sleek grove]

heres the equation

not sure what a parent cbrt function is tho

im in algebra 2 rn

nvr mind ig its (h, k)

ty tho

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[hazy light]

A retailer marks his goods at 25% above the cost price. He sells three-fourth of the goods at the marked price and the remaining at 40% discount on the marked price. What will be his total gain/loss percent?

[hazy light]

Let the cost price of the goods be x.

Then, marked price is 5x/4

The selling price of (3/4)th of goods is 5x/4 and (1/4)th of goods is 3x/4

Profit on (3/4)th of goods will be 25%

Loss on (1/4)th of goods will 25%

How do I go about finding total gain/loss from here?

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@hazy light Has your question been resolved?

[dense cave]

wait

where did u pull up 6x/5

25% above s.p means 1.25x

,w 6/5

[solid kiln]

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[dense cave]

it shud be 5/4

,w 5/4

[solid kiln]

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[dense cave]

@hazy light

[hazy light]

BAD MATH DAY

[dense cave]

isok

u dont hav to deal with org chem tho

[hazy light]

[dense cave]

firstly whats 40% of 1.25 x

[hazy light]

Why 40% percent?

[dense cave]

for loss

i mean

discount

[hazy light]

40% is the discount.

[dense cave]

yea on marked price of 1.25 x

where x is cost price

1.25=5/4

[hazy light]

Yeah

[dense cave]

so it’ll be?

[hazy light]

0.5x

[dense cave]

ok nice

so he sells 3/4th of total goods at 1.25x price

and

1/4 of goods at 0.5x price

[hazy light]

No.

[dense cave]

but he bought all of his goods for x price

[dense cave]

wdym

?

[hazy light]

The selling price of (1/4)th of the goods will be 60% of the marked price

40% is the discount.

@dense cave

[dense cave]

oh hm wait yea sry my bad

[hazy light]

Now you have no credibility

[dense cave]

[hazy light]

<@&286206848099549185>

[frosty anchor]

Is the answer around 13 percent gain?

[hazy light]

12.5% Gain

Yes.

@frosty anchor

[frosty anchor]

I see

Ok i got it i think

Is total goods=4 assumption allowed?

[hazy light]

I know how to get answers by assuming the total number of goods.

[frosty anchor]

Then?

[hazy light]

Can I not get answer by doing something like this ^ ?

[frosty anchor]

Are you saying cost price of all goods x?

Or one good?

[hazy light]

[frosty anchor]

💀 im making sure

[hazy light]

One good seems commendable

[frosty anchor]

As in you mean each good costs x right?

[hazy light]

Yeah

[frosty anchor]

I think you would still need to do something like let total goods be n

[hazy light]

I have done similar kinds of problems by this way

But, I can't figure where I'm going wrong here.

,w ((755-253)/4-100))*100)

[solid kiln]

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Requested by hazysleet#7757

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@hazy light Has your question been resolved?

[trim jolt]

@hazy light Has your question been resolved?

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@hazy light Has your question been resolved?

[trim jolt]

@hazy light Has your question been resolved?

[woven horizon]

@hazy light let Cost Price = 4x

Marked price = 125%(C.P) = 5x

3/4 of goods at M.P = $$3/4*5x = 15x/4$$

[solid kiln]

Cubopia

[woven horizon]

Discounted price = 60% of M.P

60% of 5x = 3x

1/4 of goods at D.P = $$1/4*3x = 3x/4$$

[solid kiln]

Cubopia

[woven horizon]

Total sales = $$15x/4 + 3x/4 = 4.5x$$

[solid kiln]

Cubopia

[woven horizon]

%gain = Profit/C.P * 100 = 0.5x/4x * 100 = 12.5%

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[hollow elk]

I did 3(2h+5) > 4(4h+2)

im cooked

the brackets are wrong

should be 4(2h+5) < 3(4h+2)

[iron oyster]

Why? A square has four sides and a triangle three

[chilly lintel]

But

nvm

.close

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[hollow elk]

Bro what the fuck

AYO MODS @potent leaf

[chilly lintel]

IM JOKING

[hollow elk]

.reopen

[trim jolt]

✅

[hollow elk]

@grizzled mango GET THIS MF

[chilly lintel]

IM JOKING

IT WAS A PRANK

[hollow elk]

i realised my mistake

I got a >4.5

would the smallest possible integer value be 4?

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[hollow elk]

.close

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[sweet crater]

i have no clue on how to do this

[fresh pecan]

sin/cos

oh it says at the bottom

i would try to find an explanation of what the sine and cosine function mean graphically

on a circle

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[stiff girder]

Hey! need help in trying to find the point that is equidistant from A and B and lies on the X axis

[split chasm]

never consult chatgpt for math

[stiff girder]

will remember for future

can you help with the question though?

I found chatgpt super helpful for standard deviation but ig not everything is good

[split chasm]

since the point lies on the x-axis, you already know one of the coordinates

[stiff girder]

yup

[split chasm]

then apply distance formula to determine the other

[stiff girder]

Distance formula is

[sour token]

chatgpt and in fact any neural models are bad at inference so, they don't really know what they are doing

[stiff girder]

ah ic ic

wont use them in the future ig

[sour token]

inference isn't the correct word

[stiff girder]

No but I understand what you mean

and considering that 2 people are saying so I think it makes sense

[sour token]

I meant causal inference, as in they can't understand cause and effect

[stiff girder]

anyways gimme a second? i want to try what Ramonov suggested

Since value of x will always be 0

[split chasm]

no

[stiff girder]

?

value of y will always be 0*

sry sry

[split chasm]

yes

[stiff girder]

wait im confused

[stiff girder]

what are the second values of x?

[split chasm]

wdym