i know that there are no horizontal asymptotes
#help-38
golden otter
scarlet escarp
,rccw
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scarlet escarp
the only way this has a discontinuity is if the bottom is 0. is there any real value of x that makes the bottom 0?
golden otter
no
scarlet escarp
then there are no discontinuities for this fun,ction
golden otter
okay thanks
muted maple
rational functions are very well behaved
division of polynomials
if denom not 0 continuous
golden otter
.close
potent monolith
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https://i.imgur.com/pvboedQ.png
potent monolith
stationary points
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zinc ginkgo
(0,0) and (1,0)
Show your work
arctic fjord
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trail condor
Soo
trail condor
Nice
trail condor
It’s supplementary
trail condor
Cause this sun adds up to 180°, right ?
arctic fjord
yes
arctic fjord
Since their |angle| is the same
yes congruent
trail condor
Meaning x=108, 3y=x=108, 3z+18=108
arctic fjord
because x and 3y are correspodning
trail condor
Exactly
trail condor
Mhm
trail condor
x=3y
arctic fjord
ohhh
trail condor
So y=x/3 right ?
arctic fjord
lol
trail condor
In Olympiads I just skip them
trail condor
Yeah xD
lapis cloak
xd
trail condor
I’m in last grade so it wasn’t that difficult lol
Anyway
I’m going to sleep, and don’t forget to close the channel (.close)
It’s 2:40am 💀
wraith hinge
Find all values of m for which the equation has two real solutions.
–(m+1)=–2r^2–8r
Write your answer starting with m, followed by an equals sign or inequality symbol (for example, m<5). Reduce all fractions.
I want to figure out how I am supposed to do this so after this example I could do it on my own
wraith hinge
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wanton sail
How do you convert from a normal distribution to a density curve?
wanton sail
If it is even possible
wanton spade
1^x=3
wanton spade
How do I solve for x
hollow sierra
x=3
wanton spade
Is there some imaginary ln function?
sturdy leaf
solid kilnBOT
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hushed wing
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raven vessel
hi
raven vessel
so
i need help with quadratic functions and quadratic graph
and overall quadratic stuff
anyone down?
frosty anchor
i need help with quadratic functions and quadratic graph
Like?
raven vessel
heres the question
"The diagram below shows the graph of y = px^2 + qx + r"
"Determine the value of p, q and r"
how do i do this
the values on the x axis are -3 and 2
<@&286206848099549185>
wraith hinge
<@&286206848099549185>
Ok
Do you know what zeros are?
Put the zeros back into factor form
raven vessel
Do you know what zeros are?
yeah lol
raven vessel
Put the zeros back into factor form
so use the zero property?
x = 0 and x = 0 for both?
raven vessel
(X + 3) (x-2)
why do we have to make X zero though
pure cliff
you should try x intercept form?
pure cliff
yes
raven vessel
but idk why were supposed to make them zero
pure cliff
you = them to 0 because idk
you just do
you always do
im not much help but i know how to do it
pure cliff
if it doesnt give you the y int then im not sure
raven vessel
x = 0
raven vessel
if it doesnt give you the y int then im not sure
it didnt
so um yeah
how do i find p, q and r now?
raven vessel
"The diagram below shows the graph of y = px^2 + qx + r"
"Determine the value of...
the graph here shows y = px^2 + qx + r
pure cliff
x = 0
wait what
the x is = to 0?
it says that?
who said that
i meant always = the equation to 0
the full equation would be 0 or y=(x+3)(x-2)
oops
(0 or y)=a(x+3)(x-2)
if on the paper it says x is = to 0 then plug it in
raven vessel
it says that?
no
raven vessel
but someone said (x+3) (x-2)
i wanna know why we should do that
because those equal to zero
-3+3 =0
2-2 = 0
pure cliff
do you know box method?
raven vessel
nope
pure cliff
its foiling
raven vessel
well i do know the foil method
pure cliff
foiling out of that should equal the quadratic
but you cant unless you find a
which is the slope multiplier at the beginning
raven vessel
so (x+3) (x-2) = 0
then foil?
pure cliff
if it doesnt give you x then im not sure if it is possible
pure cliff
okay look at your graph
raven vessel
so if like
pure cliff
ill explain why you do that
raven vessel
ill explain why you do that
ok pls do
pure cliff
so you knwo that they are on the x intercept right?
pure cliff
that would make the cordinates -3,0 and 2,0
raven vessel
your name is pronounced mystical right?
pure cliff
yes
pure cliff
loll
raven vessel
it still is in some servers
pure cliff
nicee
raven vessel
yes
pure cliff
well the x-intercept equation is an equation made if you have both x intercepts
it is made to be the opposite of the symbol infront of the number
so if its -3
then its 3
because if you look at the equation
you are trying to set it up like this]\
(-3+?)=0
-3 is the x int and 0 is the y int
which makes the dot -3,0
the intercept equation comes from the ?
so its positive 3 in this case
because you are looking at what would turn -3 into 0
-3+3=0
so you would write the equation (x+3)(X-2) because if you plug in -3 it makes 0 and if you plug in 2 it makes 0
because 0 times anything ='s 0
raven vessel
so basically
just fo find the number thatd turn it into 0?
so for -3
adding 3 would turn it into 0
pure cliff
yes
exactly
so adding -2 to 2 would make it 0
thats just the logic behind it
another easy way to think of it is just flip the symbols
raven vessel
-3 is the x int and 0 is the y int
ok this was the root of the problem
pure cliff
\so the intercepts are (-3,0) and (2,0)
pure cliff
ok this was the root of the problem
yes
raven vessel
so 0 was the y int because when it intersects the x axis
raven vessel
its a 0 because it doesnt go down more on the graph, if that makes sense
okay
cool
pure cliff
Yes
exactly
now im probably forgetting something
on anywhere on the paper does it say a dot that the line is on?
raven vessel
so (-3,0). we wanna turn the 3 into a 0 to make it into the y intercept?
raven vessel
on anywhere on the paper does it say a dot that the line is on?
yeah
pure cliff
is it just asking to automatically assume that the a is 1?
because you need at least 3 dots to be able to find the standard form
wraith hinge
is it just asking to automatically assume that the a is 1?
You can check A using Axis of Symmetry
pure cliff
You can check A using Axis of Symmetry
wouldnt you need to know b for that?
wraith hinge
You can know b though without a by doing the foiling
pure cliff
how would you get the axis of symmetry with just 2 dots
pure cliff
You can know b though without a by doing the foiling
you cant foil yet because you don't know a
its a hidden multiplier
right??
i swear
i think im right\
wraith hinge
?
pure cliff
well isnt the equation a(x+3)(x-2)
wraith hinge
px^2 + qx + r is all she’s asked to find right
pure cliff
you cant foil because of a being there
pure cliff
px^2 + qx + r is all she’s asked to find right
yes
wraith hinge
well isnt the equation a(x+3)(x-2)
by a I meant p, where did you get that a from?
wraith hinge
the a is something you always have to account for
You can check the multiplier using vertex after you get the equation
pure cliff
You can check the multiplier using vertex after you get the equation
but you cant get the equation if you dont know the multiplier
wraith hinge
but you cant get the equation if you dont know the multiplier
Alright imma write this out lol 1 sec
pure cliff
yea same
i believe it is just making us assume a is = 1
because i did the problem with a being = to 1 and it looks correct
wraith hinge
.cv do you have the scales of the x and y axis?
pure cliff
you're good
raven vessel
because you need at least 3 dots to be able to find the standard form
yeah but
but they didnt really ask for the standard form
just to find p, q and r
and the intercepts of x were -3 and 2
basically thats the info we got
i do get that were supposed to do (x+3) (x-2)
but what else?
pure cliff
i guess you just need to assume a is = 1
raven vessel
well, p is a 1
but we had to calculate to get that
i already have the working
i just dont get how it works, basically
pure cliff
p is 1??
wraith hinge
$test$
wraith hinge
LaTex is down
raven vessel
probably
pure cliff
you just multiply everything together and then add up all the like terms
so you multiply x and x to get x^2
and then you multiply both x's by -2 and 3
so you get -2x and 3x
and add them together
and then multiply -2 and 3 and get -6
and then you put that all into an equation
raven vessel
wait
but isnt that foiling (x+3) into (x-2)?
since x(x-2) +3(x-2) = x^2 -2x + 3x -6
which is what u got
pure cliff
YES
raven vessel
ok
pure cliff
wait no
raven vessel
well, its 0 bc
pure cliff
0 = x^2-2x+3x-6
pure cliff
yes im dumb lmao
raven vessel
so (x+3) foiled into (x-2) = 0
pure cliff
lol
pure cliff
0 = x^2-2x+3x-6
just simplify and you have your answers
wraith hinge
A multiplier would be taken out anyway, finding it is largely trivial since it would be simplified
pure cliff
thats what im saying
wraith hinge
Yeah, so you don’t need to find a multiplier
Just the zeros would suffice to get a matching equation
I don’t know why you’d need a third point unless you’re dealing with x^3
pure cliff
wouldnt the a be multiplied on both polynomials
wraith hinge
No
pure cliff
yes
pure cliff
yes
robust skiff
heyyy\
raven vessel
SO THATS HOW P = 1
wraith hinge
Yes
robust skiff
i dont need it lmao
wraith hinge
.close 
robust skiff
im just here
pure cliff
anyways
raven vessel
why take one channel if you can take 4
pure cliff
happy to help
pure cliff
also thanks <@456226577798135808> and <@744620730796212314>
np
wraith hinge
NP^2
raven vessel
lol
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dreamy sonnet
Hi, I need to find x using thales theorem for this workshop
dreamy sonnet
im not asking for the answer, the problem is that I've never seen a thales problem like this
I always had the idea of a paralel line that makes a smaller triangle and is similar to the original one
but in that problem I can't see such triangles
the teacher also said that there are similar angles in point E
but don't know what that meana
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dreamy sonnet
I already found something: https://en.wikipedia.org/wiki/Angle_bisector_theorem
well how do i close this
❌
.close
timber osprey
It asks for AB length, I think this problem is wrong because I've found $\sqrt{712}$ with distance formula.
solid kilnBOT
Robin S.
timber osprey
Could you guys check it please?
The ones I draw with green show the ordinates and abscissas.
By the way, C is on the intersection point of the parabolas and on the y-axis.
timber osprey
Alright I just see it lol
quaint gazelle
you could tell this was your error
timber osprey
I just messed up my multiplication
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quaint gazelle
what do you get in the end?
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iron cradle
I have to solve arccos12/13 + 2arctg5
The problem is that I get 0 but the answer is pi
What am i doing wrong?
iron cradle
keen plover
tan(2β) = -5/12?
iron cradle
Isn't it?
keen plover
Why do you think it is?
iron cradle
tan(2β) = -5/12?
I use the formula. I've written how i get tan(2β) = -5/12 on the line below
Just using the formula for tan(2beta)
keen plover
0 isn't the only angle where tan(θ) = 0
iron cradle
0 isn't the only angle where tan(θ) = 0
Yes, but 0 is the only one where acrtg is defined, right? That being [-п/2, п/2]
keen plover
And? You took the tangent of your equation. To undo that, you don't use arctan, unless you want to lose potential solutions
It's like if you had x² = 4, you don't just take the square root, you take ± square root
iron cradle
So what am i supposed to do?
iron cradle
0 isn't the only angle where tan(θ) = 0
tg(theta) =0 when the angle is 0 and п
I don't see how this could help
keen plover
tan(π) is also 0
keen plover
Yes
keen plover
Both arccos(12/13) and arctan(5) is positive so the answer is definitely > 0
iron cradle
So in these types of problems what should i do to catch all the solutions?
Because i didn't think outside 1st quadrant for the 2arctg5 part
keen plover
arctan(5) is in the first quadrant
But when you take the tan of everything, you need to consider all solutions when you undo it
earnest copper
how old are you
iron cradle
1st year in university
iron cradle
I had 8 hours of math lectures today.... Quite overwhelming
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wraith hinge
Is this correct?
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Is this correct?
silent canyon
Seems right
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wraith hinge
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wraith hinge
hello
Do I have to convert to quadratic form
and do -b/2a
or is there a method to find here
plain slate
no no
this form that is already in
is called vertex form becuause it's easy to find the vertex
wraith hinge
oh wow
plain slate
the theory is that, the smallest value (x+5)^2 can take is 0
so the minimum value would be when 3(x+5)^2 is 0
so the minimum value of f(x) would be -2
aka the y coordinate of the vertex
plain slate
the theory is that, the smallest value (x+5)^2 can take is 0
try find x coordinate yourself using this
wraith hinge
why wouldnt the minimum value be 5/3
if x is -2 then 5 times -2 =-6
-6 +5 = -1
-1^2=1
sorry
.close
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plain slate
if x is -2 then 5 times -2 =-6
huh what are you talking abotu bro
where'd you get x is -2 from and how is 5x -2 = -6
plain slate
idk for 3(x+5)^2 to equal 0
x needs to be -5
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plain slate
wait so you go od?
wraith hinge
no
plain slate
did you understand the solution
wraith hinge
u told me -2 is x
plain slate
no I didn't
wraith hinge
y
plain slate
yes y is -2
plain slate
ok lemme try explain again
wraith hinge
how do u know so much
plain slate
ok so this is just a random parabola, your f(x) would look something like this
as you can see the verex, is also the minimum point
it's a minimum when x^2 has a positive coefficient
atomic tapir
the vertex can also be the maximum point if theres a rotation
can the bot display graphs?
,ask graph -2x^2
plain slate
the vertex can also be the maximum point if theres a rotation
yes if x^2 has a negative coeffficient, but it doesn't here
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atomic tapir
yes if x^2 has a negative coeffficient, but it doesn't here
yup! was just explaining that as its written min/max so it can be either
plain slate
a square number is always postiive, or 0. So therefore the smallset value it could be is 0
we are looking for the smallest value as we are seeking the minimum, the vertex
plain slate
yup! was just explaining that as its written min/max so it can be either
👍
if (x+5)^2 is 0 then 3(x+5)^2 - 2 = -2
@wraith hinge do you follow?
atomic tapir
so this in vertex form. f(x) = a(x – h)^2 + k,
simplest way would just be locating h and k in the graph, remember that its "-h"
tiny kayak
I'm struggling at getting started with this, I believe I need to use a vector function, but I know little to nothing about them, and I'm not even sure if that's the method I should use to solve this, please help 
Two carriages, A and B, are connected by a 12 m
long rope passing over a pulley P. (See
the figure.) Point Q is on the floor 4 m directly below
P and between the carriages. Cart A is pulled away from
Q with a speed of 0.5 m/s. How fast
cart B is moving towards Q at the instant when
cart A is 3 m from Q?
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tiny kayak
<@&286206848099549185>
wraith hinge
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wraith hinge
If $f(x)=5x-3$ and you're trying to find an $x$ such that $f(x)=7$, you merely need to solve $5x-3=7$.
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3317
lethal anvil
where did you get 2x?
wraith hinge
5x - 3 is 2
wraith hinge
is that wrong or sum
lethal anvil
the way to confirm that is something like
7 = 5x -3
10 = 5x
2 = x
just to show your work
the answer is 2
you're solving for x
lethal anvil
bingo
wraith hinge
9 = 1
wraith hinge
what?
lethal anvil
how does 9 = 1?
lethal anvil
think about what you're saying
wraith hinge
yeah
lethal anvil
9 can never equal 1
lethal anvil
... is this a bit?
lethal anvil
9 = 4x - 3
add 3 to both sides and then divide by 4
wraith hinge
No, bro, you are confusing, lmao.
4x - 3
is 1x
Jeez, man, calm down.
No, it's not.
lethal anvil
wraith hinge
3 to both sides
Yep.
oh so 7x - 6
1x
NO MY MAN
You're adding three units, not three times x.
what in the heck are you saying
if its 4x - 3
and we add 3 to 4x
its 7x
You're adding $3$, not $3x$.
add 3 to 3
No, man.
its 6
solid kilnBOT
3317
wraith hinge
bro ☠️
lethal anvil
9 = 4x - 3
means
"9 is equal to 4 times some number minus 3"
solid kilnBOT
3317
wraith hinge
oh i get it now
9x = 4x - 3
meaning 9x - 4x is 5
5 - 3 = 2
oh i see i was doing it wrong
$4x-3=9$, add three to both sides, $4x=12$.
solid kilnBOT
3317
lethal anvil
9x = 4x - 3
there's no x on the 9's side
dire kraken
oh i see i was doing it wrong
9 = 4x - 3
does not convert to
9x = 4x - 3
you can't just place an x there randomly
this isn't some sort of magic lol
dire kraken
yes
lethal anvil
9 = 4x - 3
12 = 4x (add 3 to both sides)
3 = x (divide both sides by 4)
no the answer is 3
x is your unknown number
you're trying to find out what that is
wraith hinge
mk
so 4x is 12
-3
thats 9
i get it now
but they dont show the value of x still then
its hidden
It isn't hidden, my man.
wraith hinge
12
lethal anvil
now subtract 3
wraith hinge
9
wraith hinge
$x=2x$ doesn't make ANY sense.
solid kilnBOT
3317
wraith hinge
hm
ig its not 2x
i dont know why i added the x to 2
It isn't two either.
See, let me put it clearer.
Say I've got a mystery number. I tell that my mystery number times four, and minus three is equal to nine.
4 minus 3 is 1
so 1 is equal to 9
Yep.
OH
lethal anvil
so 1 is equal to 9
no
wraith hinge
that makes it all more clear
ty
bro what? he just said 9 = 1
You're trolling, aren't you?
lethal anvil
no he didn't
wraith hinge
I fell for it.
why would i be trolling im tryna find out the answer but i keep getting mixed signals
wraith hinge
algebra 2
lethal anvil
why would i be trolling im tryna find out the answer but i keep getting mixed si...
to be honest I think that you're jumping the gun when we provide answers
take a moment and think about what we're saying and digest it
wraith hinge
Say I've got a mystery number. I tell that my mystery number times four, and min...
.
four
minus three
= 1
1 is equal to nine
lethal anvil
so, for one thing, $1 \neq 9$. Never ever in a million years in algebra 2
solid kilnBOT
MellowDramaLlama
lethal anvil
that's like saying that I can pay for a $9 movie ticket with $1
wraith hinge
I mean
lethal anvil
or that a 9 pound cat equals a 1 pound cat
wraith hinge
the equation makes more sense than irl
but yeah i see your point
so wouldnt that mean 9 has to be 9x
1 = 9x
maybe x is times a negative number
lethal anvil
nope
wraith hinge
so 9 times a negative number and it brings it down to 1
9x = 1
that seems more logical
lethal anvil
no it's not. That would imply x = 1/9
which is wrong in the equation
you want to isolate x by itself
wraith hinge
yeah
lethal anvil
```
9 = 4x - 3
12 = 4x (add 3 to both sides)
3 = x (divide both sides by 4)
```
refer to this
wraith hinge
9 times 0.1111 is equal to 1
that might explain the 9x being equaled to 1
because 9 - 4x - 3
4x - 3 is 1
then we transfer the x to the 9
lethal anvil
@wraith hinge @dire kraken help plz
wraith hinge
so that would make sense where we multiply the x
in retrospect it means x = 0.1111
Yeah, there exists a number $x$ such that $9x=1$, but it is NOT the same x you're trying to find.
solid kilnBOT
3317
lethal anvil
wraith hinge
i was doing some other equation then
lethal anvil
YES EXACTLY
wraith hinge
mb
what about graphing domains though
for example the domain of this shape is all around it right
a domain is a vicinity
You're definitely trolling.
There is no way you're not trolling.
No, man.
A function is a thing that relates two sets.
It maps elements from the first set to the second.
In this case, the domain is a range, a subset of the real numbers.
Notice the two circles at each end.
dire kraken
There is *no way* you're not trolling.
i wouldn't jump to that conclusion, he may not have payed attention in classes or something
wraith hinge
They mean that point is not in the domain of the function and are therefore not in the image.
No such thing as blocks in here.
$x$ most of the time.
solid kilnBOT
3317
wraith hinge
No geometrical shapes involved, man.
No, the domain isn't a single number, unless the domain is a set of only one element.
It's a range, it ranges from the left tail to the right tail.
See, it's $(4,5)$
solid kilnBOT
3317
wraith hinge
Notice the parentheses, they mean that $4$ and $5$ are not in the range.
solid kilnBOT
3317
wraith hinge
It shows a range of numbers for which the property $-4<x<5$ holds.
solid kilnBOT
3317
wraith hinge
See, the function has no definition for $f(-5)$, because it's outside of its domain.
solid kilnBOT
3317
wraith hinge
Its domain is restricted to numbers that are strictly greater than $-4$ and strictly less than $5$.
solid kilnBOT
3317
wraith hinge
With parentheses to symbolize the strict comparison.
Less than or equal to -> nonstrict
Less than -> strict
No, $(-4,5)$, with the parentheses.
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wraith hinge
If it wasn't strict, it'd be $[-4,5]$, because $-4$ and $5$ would be in the range.
solid kilnBOT
3317
wraith hinge
As I've said, $-4$ and $5$ aren't in $(-4,5)$.
solid kilnBOT
3317
wraith hinge
$(-4,5)$ for this question.
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dire kraken
parentheses -> non inclusive of the outer points (they are open holes)
square parentheses -> inclusive of them (closed holes)
wraith hinge
Yep, but now $-7$ and $5$ are in the domain.
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3317
wraith hinge
parentheses -> non inclusive of the outer points (they are open holes)
square pa...
Couldn't have said better myself.
That's it.
dire kraken
is it parentheses or square brackets?
no, there is always one or the other
in a domain
dire kraken
yep
man is your teacher teaching anything? it seems like we have to teach it to you like it's a new concept lol
sorry I didn't mean that in a harsh way
just wondering
ah
long dew
Alright my math question is
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Alright my math question is
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long dew
.reopen
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long dew
So I need help
uncut aspen
do you get a refund for returning rabbits?
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@long dew Has your question been resolved?
long dew
Yes
split chasm
jeez
zinc ginkgo
stop abusing help channel
ramonov and i already explained it
you don't put f(-2) in your answer
you ignored us all 4 times
what part of "don't put f(-2) in your answer" doesn't make sense?
split chasm
you are being asked for the y-coordinate of the point on the graph with an x-coordinate of -2
what is the y-coordinate of that point
zinc ginkgo
why
split chasm
enter that value and ONLY that value and NOTHING ELSE
split chasm
what value did you enter
zinc ginkgo
you don't put f(-2) in your answer
.
split chasm
f(-2)-5 is not the y-value of the point at the specified location
zinc ginkgo
you keep putting f(-2) in your answer
zinc ginkgo
like i said, it's against the rules to give answers
split chasm
f(-2) = -5
don't write f(-2)
write the y-coordinate of the point
don't open/close/make channels like this
its extremely rude too
trim joltBOT
@rancid lotus Has your question been resolved?
split chasm
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ancient vortex
hi
gloomy barn
Im insanely confused
Question number 14
I figured it out and did the math but i have no idea what letter it is
And why is it that letter
P.s sorry for horrible writing
ancient vortex
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ancient vortex
Im insanely confused
type sth
gloomy barn
sth
gloomy barn
.sth
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✅
gloomy barn
Hmmm
So i graphed it but im confused on what the letter is
I chose d because i had no idea what i was doing
night zodiac
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lone mauve
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lone mauve
To find the area of the Trapezium on the left, can I use ((b1+b2)h)/2?
lone mauve
Or do the bases need to be parallel for that formula to work
inland orbit
Yes
split chasm
it's a trap
edgy cedar
You basically split the shape into two triangles
tiny kayak
Do you have any measurements?
inland orbit
You basically split the shape into two triangles
This is like, 90% of what high school geometry consists of lol
split chasm
it's horrid that different places use trapezium/trapezoid differently
lone mauve
Do you have any measurements?
No, just wondering if there is a formula to follow for area with them both
tiny kayak
You basically split the shape into two triangles
What pure said
inland orbit
No, just wondering if there is a formula to follow for area with them both
No, for an irregular shape like that, you'd probably split it up into triangles like Pure said
lone mauve
But isn't that what this does? ((b1+b2)h)/2
split chasm
there's no simple formula for area of an irregular quadrilateral
lone mauve
So this would only work for the trapezoid on the right? ((b1+b2)h)/2
trim lichen
that is a formula for a 4-gon with a pair of parallel bases, i.e. a trapezoid (🇺🇸)
it does not even make SENSE to apply this same formula on the left. you understand that, don't you?
inland orbit
But isn't that what this does? ((b1+b2)h)/2
That formula models the trapezoid as half of a parallelogram, basically. It only works because the bases are parallel
lone mauve
OK
so for the left trapezium what information do i need to solve the area?
make it into two triangles, bottom left corner to top right corner, split it in half
but what formula would I use?
inland orbit
Uhhh, could be a variety of things.
lone mauve
thats what I used already
tiny kayak
tiny kayak
grøn=green
orange=orange
lone mauve
these images are only helpful for parallel trapezoid
inland orbit
So for the trapezium on the left? what formula would you recommend?
There isn't one. It depends entirely on the information you're given
lone mauve
OK, this math problem sounds like a lot of fun
I will close it here. TY for your help
tiny kayak
But isn't that what this does? ((b1+b2)h)/2
I think you might be right about this
lone mauve
only works for trapezoids with a parallel base
trapezium with circumference lines in all directions does not work with this formula
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wraith hinge
help pls
inland orbit
What's the question?
inland orbit
Looks good
inland orbit
help pls
If this is the only information you have, then there are a bunch of functions you can draw
wraith hinge
ok
inland orbit
But yeah, you satisfied the two things it says
wraith hinge
how do i do this
evaluate
ik there's asymptote at 3
and it's going from the left
inland orbit
Okay, so from the left
wraith hinge
positive infinite?
inland orbit
Yeah, because near 3 the expression will be positive
wraith hinge
bruh answer key wrong
inland orbit
What does the answer key say?
inland orbit
what about this
Did you try anything for this one?
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@wraith hinge Has your question been resolved?
inland orbit
Could rewrite it as $\frac{1}{x\cos x}$ if that helps
solid kilnBOT
tatpoj
inland orbit
@wraith hinge think about what happens to cos(x) at x=pi/2
inland orbit
Hm
wraith hinge
wait i meant 0
inland orbit
cos(pi/2) = 0
Yeah
So imagine
$\frac{1}{\left(\frac{\pi}{2}^+\right) \cos \left(\frac{\pi}{2}^+\right)}$
solid kilnBOT
tatpoj
inland orbit
I'm abusing notation a little here, but I'm using $\frac{\pi}{2}^+$ to represent a number very close to $\frac{\pi}{2}$ on the positive side
wraith hinge
ok
solid kilnBOT
tatpoj
inland orbit
cos(x) is actually negative for x just greater than pi/2
inland orbit
Okay
I think you kind of just need to be familiar with trig functions honestly
You're probably expected to just kind of know that
inland orbit
Oof, yeah that would make it harder
inland orbit
I guess just make sure you're familiar with the graphs of sin x and cos x
There's not really a good way to figure it out otherwise
serene mantle
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dawn trellis
