help-36

[dense tundra]

My head says that the responses to this question are c) for Question 1 and

a) for Question 2

However, the design of this question is incredibly poor.

What are your thoughts?

For e.g. the range is independent of the value for x.

It should be equal to approximately 80 in both graphs.

[final saddle]

@dense tundra Has your question been resolved?

[shell mountain]

How do you get c for question 1?

There's quite a range of y values in that first graph

[dense tundra]

Yeah, it's an incredibly stupid question. Let me interpret both ways of approaching this question.

[shell mountain]

How so?

It's asking for the range of y values

[dense tundra]

Yes and that is defined as the highest - lowest value. Correct.

Now where things becoming confusing is the following phrase "At a x value of 40"

which I believe is redundant or irrelevant to the calculation of the range.

With this inn mind the range should be approximately 80 in both cases.

For e.g. highest value for y in second graph is approx 95

lowest value for y in second graph is approx 25

95 - 25 = 70

So the closest answer would be 80.

What are your thoughts about this interpretation?

[shell mountain]

But it might be talking about the points on---or close to---x = 40

[dense tundra]

This is what I think the other interpretation is.

which makes more sense given the context of the question.

Which is why I conclude that this question is ultaimtely quite silly.

because it's not exact or definitive

[shell mountain]

Because then, the range is smaller for higher r

[dense tundra]

Correct.

I had provided guidance to a student with this question.

and I provided the former interpretation.

instead of this one.

Thanks for the clarity but at the end of the day, I believe this question is designed badly.

~close

.close

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[sturdy brook]

i actually need help

[sturdy brook]

My question is

[pale oracle]

ooh, ok

[sturdy brook]

8^z = 1/2

[pale oracle]

k..

[sturdy brook]

find the value of z

[pale oracle]

so the name of the section you are working on in class is...(?)

[sturdy brook]

indicies

[pale oracle]

you sure about that?

[sturdy brook]

yep

[pale oracle]

the section you are on is called "Logarithms"

oh.

this is a complex number though

so is this trigonometry?

[weak path]

dont need logs to solve this

[sturdy brook]

No its not

[pale oracle]

or intermediate algebra

[stray wing]

convert 1/2 to a power of 2

[sturdy brook]

just some indicies

[stray wing]

convert 8^z to a power of 2

then solve for z

[pale oracle]

true

both sides can be

[sturdy brook]

wdym a power of two

or am i being dumb

[pale oracle]

1/2 = 2^-1

8^z = (2^3)^z

= 2^3z

[sturdy brook]

what howd we get here

[stray wing]

how can you express the number 8 in terms of multiplying 2 by itself

[sturdy brook]

oh

[pale oracle]

b.c. 8 = 2*2*2

[sturdy brook]

4?

oh no oh wait

2^3

?

[pale oracle]

3 factors of 2

yes

[sturdy brook]

Alright okay

[pale oracle]

so you are still on Exponents in class then

[stray wing]

ok so do you agree that

$8^z = 2^{3z}$

[soft zealot]

IntelligentCake

[sturdy brook]

yes correct

what now

how do I make 1/2 a power of two

[pale oracle]

please pay attention

[stray wing]

do you understand what fractional powers mean @sturdy brook

if you do not understand I suggest you learn this. We are not here to give answers

[sturdy brook]

dont they mean n^-m = 1/n^m

[stray wing]

no

oh wait yeah

ok so what is n and m in this case

[sturdy brook]

Lets start from the front Im so lost here man

[pale oracle]

do you have your Laws of Exponents in front of you?

right now?

[pale oracle]

you need to memorize them

that will come easily the more of these you finish

@sturdy brook

[pale oracle]

?

[sturdy brook]

Yes

[pale oracle]

ok, you should see a few on there you can use

Power Rule: $(a^m)^n = a^{mn}$

[soft zealot]

Disorganized

[sturdy brook]

okay

[pale oracle]

Reciprocal Rule: $a^{-m} = \frac{1}{a^m}$

[soft zealot]

Disorganized

[sturdy brook]

perhaps a^1/n - n/a

[pale oracle]

I don't think you typed that right

definition of a root

[sturdy brook]

/ being the square root

[pale oracle]

let me just type it

[sturdy brook]

Yeah good idea

[pale oracle]

nth root definition: $a^{1/n} = \sqrt[n]{a}$

blech

knew I would mess that up

one sec

[strange shore]

$a^{1/n} = \sqrt[n]{a}$

[soft zealot]

Ｈｅｒｅｌｓ

[strange shore]

eh

[pale oracle]

yup

[sturdy brook]

Yep

So now

Will this index law help us solve our question

[soft zealot]

Disorganized

[sturdy brook]

8^z = 1/2

[stray wing]

ok so you had the left hand side earlier

[sturdy brook]

First step is to put 8 into terms of n^2

Why?

[stray wing]

in terms of 2^n

[strange shore]

$(2^3)^z = 2^{-1}$

[stray wing]

because both sides of the equation can be expressed as a powers of 2

[soft zealot]

Ｈｅｒｅｌｓ

[sturdy brook]

Yeap

[stray wing]

@strange shore why

we are trying to teach

[sturdy brook]

idc

[pale oracle]

another Law of Exponents

[stray wing]

not give answers

[sturdy brook]

I want to know why

[pale oracle]

read your laws of exponents

[strange shore]

if I was giving answer I would have said what z is equal to tho

[stray wing]

but @sturdy brook is confused as to why powers of 2

it doesn't help just stating the form we want it in

[pale oracle]

he should know from Laws of Exponents why it is advantageous to have the same base on both sides

[strange shore]

doesnt he know about this ? :
$a^{-1} = 1/a$

[soft zealot]

Ｈｅｒｅｌｓ

[sturdy brook]

I know that

[strange shore]

then the rest is piece of cake

[stray wing]

@sturdy brook what is 1/2 expressed as 2^n then

[pale oracle]

why don't you type what we have right now

[sturdy brook]

Im finished imo

i realised why

[pale oracle]

ooh, tell us

[sturdy brook]

Its 2^-1 because if I wanted to solve that I would get

1/2^1

which is a half

[pale oracle]

that is true

I don't know about the solve part thouhg

it's just another way to write it

[sturdy brook]

so now its in terms of 2^n

[pale oracle]

we are solving for z

[stray wing]

yes

[sturdy brook]

we can find z?

[stray wing]

yes

[sturdy brook]

so (2^3)^z = 2 ^-1

[pale oracle]

getting there..

nice

[sturdy brook]

would I make z the subject and solve?

[stray wing]

so now what do you notice about the exponents

[pale oracle]

no

[stray wing]

and base

if base is same what does that allow you to do

[pale oracle]

use the rules we talked about

[sturdy brook]

nothing

Im stuck here

[stray wing]

both bases are same

so therefore to make both sides equivalent, the powers must be the same

[sturdy brook]

Oh yeah

Is the base 2?

[stray wing]

yes

[sturdy brook]

sorry if my questions seem dumb

[stray wing]

its ok

we are here to help

[pale oracle]

use the Laws of Exponents we talked about

[sturdy brook]

How would I make the exponents of 3 and -1 the same

[stray wing]

3z = -1

do you agree

[pale oracle]

what happened to letting him think?

[stray wing]

that is why I ask do you agree

[pale oracle]

you didn't even let him know why we could do that

or look it up

[stray wing]

I want to see if homebound can reason why

[pale oracle]

Homebound isn't even reading his Laws of Exponent cheat sheet

[stray wing]

he clearly wants to understand

[sturdy brook]

could law 7 help?

Wait

so if 2^3 = 2^-1, wouldnt 3 = -1?

[stray wing]

that's clearly false but yes I see what you are trying to get at

but your left hand size is not 2^3

what is it

[sturdy brook]

its 8

[stray wing]

not just 8

[sturdy brook]

8 to the power of z

[stray wing]

yes

and we already discussed how we can rewrite this as a power of 2

and what was that

[sturdy brook]

2^3^z

[stray wing]

yes

$2^{3z}$

[soft zealot]

IntelligentCake

[stray wing]

yes?

[sturdy brook]

yep

[stray wing]

so now which law are you going to use

$2^{3z} = 2^{-1}$

[soft zealot]

IntelligentCake

[stray wing]

you are so close to finishing

[sturdy brook]

im looking through the laws

[stray wing]

you said which one earlier

[sturdy brook]

How would law 7 apply here though

[stray wing]

m = 3z

n = -1

a = 2

[sturdy brook]

yes

so then

m = n?

[stray wing]

yes

[sturdy brook]

so 3z = -1

[stray wing]

yes!

so what is z

[sturdy brook]

-1/3?

[stray wing]

correct!

good job

[sturdy brook]

https://tenor.com/view/soccer-cheer-yes-portugal-uefa-gif-5770439

[stray wing]

Lol

[sturdy brook]

lets do another one

im getting it in 5 minutes this time

Okay so

Would the first step to put 16 in terms of 4^n?

Or something like that

so 4^2 = 4^-1

right ? @stray wing

wait

4^2q = 4^-1

so 2q = -1

so q = -1/2

https://tenor.com/view/ronaldo-ronaldo-manchester-siuu-villarreal-ronaldo-celebration-gif-23270437

IT WAS RIGHTTTTTTTT

@pale oracle I love this game fr

okay last one even though im basically talking to myself

4q=1/16

Okay guys I need help now

@tranquil pine

Wait disorganized are you still here

[pale oracle]

yeah, you solved it, why are you stuck

[sturdy brook]

Okay for this one its quite technical

[pale oracle]

are you on a different one

[sturdy brook]

its a different question

Yes and it got real

[pale oracle]

you haven't posted it yet

[pale oracle]

ok

[sturdy brook]

its kinda crazy cause 1/16 in index form would be 16^-1

[pale oracle]

that's true

but it's not the only way you can write it in index form

[sturdy brook]

but how would I put 4 into a form where its equal to 16?

Whats another way

[pale oracle]

focus on the 16

how can 16 be in terms of 4?

[sturdy brook]

4^2?

[pale oracle]

a power of 4

yes

[sturdy brook]

so (4^2)^-1

?

[pale oracle]

uh-huh.

[sturdy brook]

So

[pale oracle]

how about using those laws of exponents to simplify

just a little bit

[sturdy brook]

4q=(4^2)^-1

[pale oracle]

the exponent

clean up the right side ("RHS")

also left should be 4^q

[sturdy brook]

-1 x 2

yep

[pale oracle]

and what is that

[sturdy brook]

4^-2

[pale oracle]

ok good

[sturdy brook]

so 4^q=4^-2

so q is -2

[pale oracle]

nice job

I was wrong about you

[sturdy brook]

everything is hard before its easy

[sturdy brook]

whatd u think before

[pale oracle]

that is the most important lesson in high school math

[pale oracle]

that you weren't thinking about your tools

like you were waiting for us to remind you what they are and reasons to use to use them

but you're clearly doing your own thinking and I want to recognize you for that

and say I was wrong

[sturdy brook]

good teachers 💯

[pale oracle]

ok, keep it up

[sturdy brook]

okay im trying to get 100 percent on this hw

and this question is kinda easy but

better safe

(16/25)^3/2

Now thinking normally

Itd be (16/25)^1/3)^3

So id cube root 16/25

to

wait what the fuck

This looks so goofy

wait i messed up

its

hahaha

(9/5)^2

How would I do that

would i just square 9 and 5

so would it be 81/25

no wait lmfao

4/5

itd be 16/25

wrong but cba

thanks guys

.close

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Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zealous lagoon]

i already know the first pair is Aunt 1 with Grandma 1, pair 2 will be Mom and Aunt 2, and pair 3 is you and Grandma 2

but i dont know how to explain using rational expressions

and i dont know how to write out the equation

to find the average time between pairs

.close

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Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[untold crypt]

What’s your question

[ebon dew]

@tranquil pine maybe since ABC are fixed, triangle ABC is fixed, so it will have the same area no matter what

figure out that area, and then find the area of triangle DAC in terms of x

then you can deduce the maximum area for the whole shape

[final saddle]

@tranquil pine Has your question been resolved?

[final saddle]

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