#help-36

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final hedge
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since the text says nabil's age was equal to shuvo's current age in the past, nabil is older than shuvo so let the age difference between them is (N - S) years

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and we know nabil's current age is double of shuvo's age back then

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right

final hedge
#

and the difference is (N-S)

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right

final hedge
#

so what was shuvo's age N-S years ago?

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this q ong sucks 😭

#

what is that holy language

cinder vapor
final hedge
#

no like the framing

final hedge
cinder vapor
cinder vapor
final hedge
#

like you're confused at a step or

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smth?

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or message didnt load?

cinder vapor
cinder vapor
final hedge
cinder vapor
#

N is older than s

cunning ridge
final hedge
final hedge
cinder vapor
final hedge
#

hmm wait

#

im forming a perfect explanation

final hedge
cinder vapor
final hedge
#

lol

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well not like im not gonna help u understand

cinder vapor
#

Still I can't understand shi

final hedge
#

so its telling us that nabil in the past was shuvo's present age

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right?

cinder vapor
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Yea

final hedge
#

exactly

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so whos older

#

?

cinder vapor
#

N

final hedge
#

see

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you understood it yourself

cinder vapor
final hedge
cinder vapor
#

Right?

final hedge
cinder vapor
#

And when N was in past he was equal to to our present S

final hedge
#

read this

#

and can you form

#

an equation

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N is nabil's current age

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S is shuvo's current age

#

so what can we say from that statement

#

??

cinder vapor
final hedge
cinder vapor
#

Lemme see my native text for a sec

final hedge
#

i mean

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zavier confirmed that

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so im using that

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lol

cinder vapor
cinder vapor
cinder vapor
final hedge
#

so umm is the q language im referring to correct or

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wrong

bold turtle
#

okay this text looks shit ngl

final hedge
#

its originally a bengali q

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but idk bengali

cinder vapor
bold turtle
#

Srsly I'm trying to translate it by myself and it's a fokken minefield

final hedge
#

we can get an ans tho

#

ig

bold turtle
#

Like ik relative clauses are weird in Bangla but tf is this even KEK

cinder vapor
final hedge
#

even tho they prob arent logical

bold turtle
#

I'm not trying to rely on the provided translation fwiw

final hedge
#

lol

bold turtle
#

Because I'm doubting the translations given

cinder vapor
#

Like I tried watching the native ans vid but I didn't get the logic

final hedge
#

or smth

#

so i can verify my ans

cinder vapor
final hedge
#

whts the final ans

cinder vapor
final hedge
cinder vapor
final hedge
#

ight

#

back to our step

cinder vapor
final hedge
#

yep

cinder vapor
#

Ok

final hedge
cinder vapor
#

N is double= when S was

final hedge
cinder vapor
old saddle
#

Can I add some details?

cinder vapor
final hedge
final hedge
cinder vapor
final hedge
#

oh

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crap

#

mb

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sorry 😭

cinder vapor
#

Isn't N the current age ?

final hedge
cinder vapor
final hedge
#

where N and S being current ages of Nabil and Shuvo

cinder vapor
final hedge
cinder vapor
final hedge
#

shuvo's age (N-S) years ago was double

#

of

#

nabil's current age

cinder vapor
cinder vapor
cinder vapor
final hedge
#

N-S is the age difference

cinder vapor
bold turtle
#

"When Nabil's age was equal to Shubho's current age, Shubho's age then was [double (dbiguno)] of what Nabil's current age. When Shubho's age becomes what Nabil's current age is, if the sum of their ages becomes 63, what is each person's current age?"

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I feel like this must be a typo

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That or idk what dbiguno should mean

old saddle
#

Np - Nabil's present
Sp - Shuvo
Np - d = Sp --> 1
Sp - d = 2Np -->

But the third line "Subho's age is the same as Nabil's present age" doesn't exactly mention when.

To me it should not be the difference of the present times but a totally d years ago

cinder vapor
bold turtle
#

Wait so, 2x?

final hedge
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i think

cinder vapor
#

Can we talk like

bold turtle
#

Then that must be a typo in the question

cinder vapor
#

Understanding like this is kind ahard

cinder vapor
old saddle
final hedge
cinder vapor
old saddle
bold turtle
# cinder vapor No actually if I m not wrong

So, like:
"When Nabil's age was equal to Shubho's current age,"
means that Nabil is older than Shubho; so how can Shubho's age, then or now, be double Nabil's age?
Hence my thinking that this must be a typo

final hedge
#

meaning the gap we taking is N-S

bold turtle
#

or maybe I'm really messing with the relative clauses

final hedge
#

its solvable

bold turtle
#

"Shubho's which-age[x] it-was, Nabil's current age[y] its [referent, r] double"

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okay I can see how r = x here

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I'd taken it at face-value and gone r = y (which incidentally is how Yoru's Google Lens translation took it to mean)

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okay I'll leave you to it lol, you guys seem to have it under some control thumbsupanimegirl

bold turtle
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-# sure but the question is whether Yoru has it solved

final hedge
#

yah

cinder vapor
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But I can't understand that how this resulted that equation

bold turtle
#

-# No disrespect, I mean that it's meaningless if Velt has it solved if Yoru didn't

old saddle
bold turtle
# cinder vapor What ?

(Velt'er answer jodi ache, labh nai tumi jodi bujcho na)
-# (There's no benefit to Velt having an answer if you don't understand it)

old saddle
bold turtle
#

-# sipping into the recesses of what Bangla I can muster lol

cinder vapor
cinder vapor
bold turtle
#

So, N is Nabil's current age, and S is Shubho's current one, right?

cinder vapor
bold turtle
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First part - "when Nabil was Shubho's age" - i.e. N-S years ago

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Is this part clear?

sterile marsh
#

are we still on this problem 😭

cinder vapor
final hedge
bold turtle
#

now shut

bold turtle
old saddle
final hedge
#

πŸ’”

cinder vapor
sterile marsh
cinder vapor
bold turtle
#

Presumably Keshab Chandra Nag

old saddle
old saddle
bold turtle
#

Indian Bengali mathematician - but the source of the problem is irrelevant

cinder vapor
old saddle
cinder vapor
final hedge
bold turtle
#

Bangladesh's exam board

final hedge
#

ohh ok

bold turtle
#

well, a government ministry tbh

sterile marsh
#

!redir

final saddleBOT
#

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

bold turtle
#

Secondly:

cinder vapor
final hedge
bold turtle
cinder vapor
cinder vapor
bold turtle
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So for example

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Suppose Alice was 24 and Bob was 20, then "When Alice was Bob's age" is 4 years ago, right?

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Where'd this 4 come from?

cinder vapor
bold turtle
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Right

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So Nabil's current age is N and Shubho's is S

cinder vapor
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Yes

bold turtle
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So when Nabil was Shubho's age, that's N - S years ago

cinder vapor
#

Okay now I get it

bold turtle
#

Shubho's age at the same time would be S (his current age), minus N - S (how many years ago)

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i.e. S - (N - S) = 2S - N

cinder vapor
#

Okay let me write it down first

bold turtle
cinder vapor
bold turtle
#

At the same time, Bob's age then would be 20 (his current age) minus 4 (how many years ago)

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i.e. his age then was 20 - 4 = 16

cinder vapor
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Okh

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Got it

bold turtle
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Same logic, just with some algebra because we haven't actually got their ages yet

old saddle
#

@bold turtle
Np - d = Sp
Sp - d = 2Np
d = Ns - Sp

Are these logically correct?

bold turtle
# cinder vapor Yea

Then the bit after, "Whatever Shubho's age then was [ 2S - N, what we've just said ], Nabil's current age is double this"

cinder vapor
#

Okh

bold turtle
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That's just gonna complicate things

bold turtle
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We can say N = 2 ( 2S - N )

cinder vapor
#

Okh

bold turtle
#

Try and simplify this?

old saddle
#

@bold turtle

N - ( N - S) = S
S - (N - S) = 2N

Are these logically correct?

cinder vapor
bold turtle
#

-# And on that last point - I'm literally going over this with the helpee, could you not try and interrupt with this

cinder vapor
bold turtle
#

ye

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We're gonna need to get another equation so that we can solve (simultaneous equations)

#

Looking at the rest of the question:

cinder vapor
old saddle
bold turtle
#

"When Shubho becomes Nabil's current age, if the sum of both their ages then is 63..."

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First, can you see how many years in the future this will be?

bold turtle
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"When Shubho becomes Nabil's current age" - start from this

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Shubho's currently S years old, and Nabil is N years old

cinder vapor
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Wait so we got 3n is equal 4S

bold turtle
#

Yes that's one equation; we're trying to make another

bold turtle
cinder vapor
cinder vapor
#

Can we talk about it tomorrow

#

I am expressing my gratitude to all that tried to help me to today. I will not forget your help that have benefited me

bold turtle
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sure; .close this channel and pick it up later

cinder vapor
final hedge
#

waes help 42 has to be a troll right

cinder vapor
#

I appreciate your help brother

final hedge
bold turtle
#

(restate the problem and the translation;

"When Nabil's age was equal to Shubho's current age, Nabil's current age is double what Shubho's age then was. When Shubho's age becomes what Nabil's current age is, if the sum of their ages becomes 63, what is each person's current age?"

#

)

final hedge
#

i only showed you how

bold turtle
cinder vapor
#

Bye

#

.close

final saddleBOT
#
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bold turtle
final hedge
bold turtle
#

nah dw I can see why

final hedge
#

do i modping

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and they arent even telling whats the exact doubt

bold turtle
#

I was about to lol

final hedge
#

oh go on

final saddleBOT
#
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hardy beacon
#

I am wheezing out...
I have only studied annihilator approach to solve these types of differential equations...Its a bit lengthy pls help😭

willow cliff
#

well first off you wanna solve for the roots of the $D$ poly right

soft zealotBOT
#

TestTickler

hardy beacon
#

Yes lemme send you a ss

willow cliff
#

i also only know the annhilator method but lets see what i can do

hardy beacon
#

Too complex

willow cliff
#

be careful in the begining

hardy beacon
#

I feel like this question uses an another approach

willow cliff
#

a repeated root means that it has general solution $y=(a+bx)e^{2x}$, a and b are constants

soft zealotBOT
#

TestTickler

willow cliff
#

oh wait i think u got it later on, nvm

hardy beacon
#

I did this question while being stressed

trail mango
hardy beacon
#

I literally have my finals two days after

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Let me do it again

final saddleBOT
#

@hardy beacon Has your question been resolved?

hardy beacon
#

Annihilator doesnt seem right for this type of question

#

.close

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#
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final saddleBOT
supple jolt
#

<@&268886789983436800>s

#

Mr. Least

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floral moth
final saddleBOT
floral moth
#

how to solve it using synthetic geometry

#

i already did a proof showing that the area of FEG is equal to the area of EDC, but using coordinate bash

final saddleBOT
#

@floral moth Has your question been resolved?

severe verge
#

notice that triangles FGD and FCD have the same area

floral moth
#

damn

severe verge
#

(since they share the base FD and their altitudes are the same length)

floral moth
#

yeah im blind

#

yeah buts trivial now

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thank you

#

.close

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vital crag
#

<@&268886789983436800>

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opaque pagoda
#

Hello! Can someone please help me explaining how can I find the order and degree of an equation?? πŸ™ I really dont get it

vital crag
#

have you learned these definitions

opaque pagoda
#

So to identify order I need to find the highest derivative?

#

I’d guess is 3… and for the degree it must be also 3 right???

#

Wait I think I got it

#

Tyyyy!!!

#

.close

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shadow smelt
#

how do i do

final saddleBOT
ornate token
#

What is the total angles of pentagon.

#

This is a regular pentagon and OA=..=OE, can appeal to the fact that OA,OB,..., OE they all dissect A,B,...,E by half.

shadow smelt
#

6

ornate token
#

Total measurements of those angles?

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Then for each angle, what is the measurement?

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Eh, not in this case, total angles of pentagon is not 360 though.

cyan sandal
#

i meant around O

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but u got it

ornate token
#

Well there are 2 approaches.

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1, if you go from bases angles of A,B,...,E.

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Or 2, just argue that the lines OA,..,OE cut angle O equally.

broken field
#

I thought there was a formula for it

final saddleBOT
#

@shadow smelt Has your question been resolved?

broken field
#

Nvm this is just viewing center as a circle

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shadow smelt
#

how do i do this

final saddleBOT
broken field
#

Ur just finding middle right

#

Meaning u can view O as a part of a whole circle

shadow smelt
#

yes

broken field
#

So it would be the circle total angle dividing the number of center angles right

shadow smelt
#

so 72 degrees

broken field
#

Yes should be

shadow smelt
#

how do i do

broken field
#

Ok u first find the angle of the hexagon

timber leaf
#

Then take 180 - that angle to get B,C in triangle BCG

stable dew
#

or

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extend ED

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and apply the parallel lines rule thingy(i forgot the name)

shadow smelt
timber leaf
#

total is 720

broken field
#

n-2 x 180

shadow smelt
#

ok

#

so

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180 degrees for each angle then

broken field
#

How many angles are there to find in the hexagon

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Eh I will just count for u 720 dividing 6 is 120

timber leaf
shadow smelt
#

excuse me

timber leaf
#

6 angles, total is 720

broken field
#

My first time seeing a helpful acting out holoapple

shadow smelt
#

by 6

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you get for each angle

timber leaf
#

yes

shadow smelt
#

ok

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so am I NOT THINKING

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ok

timber leaf
#

Unfortunately yes

shadow smelt
#

good

broken field
shadow smelt
#

so what happens after that

broken field
#

180 - the answer u got

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Since ABG or DCG is a straight line

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It means 180

shadow smelt
#

ok

#

so bgc is

timber leaf
#

You want to find GBC and BCG first

shadow smelt
#

bro what

#

its the same thing

timber leaf
#

what i mean here is the angle

broken field
#

On this one the triangle is the same luckily

timber leaf
#

wdym same?

broken field
#

I meant

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It's equal

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So what's ur answer better dogr

timber leaf
#

you mean equilateral

broken field
#

Yea I'm tryna find that auto correct blobcry

#

It didn't appear so I don't dare say it

shadow smelt
#

ok

#

so

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180-144

broken field
#

Where did u get 144

shadow smelt
#

so if

timber leaf
#

what is 720 divides by 6.

shadow smelt
#

120

timber leaf
#

Then where did that 144 come from

shadow smelt
#

ok so

#

ok its 120

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so 60 degrees

broken field
#

Yesir

shadow smelt
#

for BC

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its 60 degrees SIR

broken field
#

Ye so u would add both B and C

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And take the triangle full angle and minus both

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To get x

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So what do u get

shadow smelt
#

how do i get the triangle full angle

broken field
#

Using the formula (n-2) x180

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Triangle has 3 angles to be found

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So 3-2 is 1 which x 180 means 180 angle

timber leaf
#

Re-read your notes please, if you cant get this then harder problems will be unsolvable

shadow smelt
#

ok so basically

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if i add 120 + 120

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240 - 180

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60

#

degrees

broken field
#

Ok so 180-120 means 60

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U got 60 for each B and C

#

A triangle full 180 means u minus B and C to get x which in this case 180-120 which u would get 60

shadow smelt
#

ok ty

broken field
shadow smelt
#

imma do this one rq

timber leaf
#

Same concept, but instead of hexagon it is pentagon

broken field
#

Able to find the Pentagon angle using (n-2) x 180?

shadow smelt
#

yes

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ok so i got

#

180 degrees

broken field
#

For what

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Ok u tell me how many angles are there to find in pentagon

shadow smelt
#

5

shadow smelt
broken field
#

Well BFC is in a triangle so it would be impossible for itself to be 180

#

Ok so u got 5 meaning u input it into (n-2) x180 u get?

#

And after u got the total angle for pentagon calculate one of it's interior

shadow smelt
#

that would be

#

108

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for an interior

broken field
#

Correct now using that try to find B or C

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At the triangle

shadow smelt
#

72 degrees

broken field
#

Nice so now u take the triangle full angle and minus both B and C

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To get x

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Which in this case both ur B and C is 72 rn

shadow smelt
#

so

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x would be 36 degress then

broken field
#

Yes

shadow smelt
#

wow...

#

πŸ˜ƒ

broken field
#

If ur finished make sure to close

shadow smelt
#

.close

final saddleBOT
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night basin
#

Hello, can someone explain why this method is incorrect for solving this problem?

loud sundial
night basin
#

Umm cause like the big square is cut into three parts so it also divided the side of the tilted square into three parts

timber leaf
#

I think you should find the area of 4 full small squares first

night basin
#

Right Yoh mb

#

Thanks

#

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ruby crypt
#

hi, idk where to begin

final saddleBOT
ruby crypt
#

what is even measure 0 intuitively speaking

final saddleBOT
#

@ruby crypt Has your question been resolved?

timber leaf
ruby crypt
#

null as in empty?

timber leaf
#

Yes

ruby crypt
#

wth

#

there is no way right?

timber leaf
#

Well but i read here, it probably mean that the set is so small such that its length is considered 0

ruby crypt
#

yes the length, so set shouldn't be empty

#

but what I dont understand is actually the concept of measure 0 itself

final saddleBOT
#

@ruby crypt Has your question been resolved?

sand barn
#

List all numbers of the set in sequence. Chose a number such as 0.1.

#

Place a interval of 0.05 around the first element

#

Then 0.025 around the next and so on

#

Its called measure

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Understand @ruby crypt

ruby crypt
#

hi im eating rn

#

so u mean, by placing interval of x, this means [0.1-x, 0.1+x]?

wintry mantle
#

You can prove a) by contradiction using the fact that x^2 is bijective

ruby crypt
#

just got back

ruby crypt
#

ok this is just basic vocabulary meaning of measure

#

lol

#

what am I even questioning

#

but what does it mean when a set is of measure 0? Does it mean the distance between points/values inside the interval is very very close to 0?

whole halo
ruby crypt
#

0

whole halo
#

bro

#

Im talking about the function

#

do you know what measure function youre using for the problem

#

like what would the measure of [0, 1] be

ruby crypt
#

um 1...?

whole halo
#

you dont know then

#

go look in your notes or the book and find what measure youre using

ruby crypt
#

what?

whole halo
#

"a set of measure 0" only means that you put it through the measure and you ge t0

ruby crypt
#

all I was taught is lebesgue

whole halo
#

well yea

#

thats your measure then

#

the lebesgue measure is a function, it tells you how big things are

ruby crypt
#

is it stupid if i ask there are more than one measure

whole halo
#

πŸ€” well given we have to name this one after someone's name...

#

what do you think, is it just the one?

ruby crypt
#

no i was saying like cm, mL, and stuffs are measure right

whole halo
#

no

#

those are called units

#

a measure function and a unit are not the same thing

ruby crypt
#

ok this goes deep

whole halo
#

bro did you even learn what the lebesgue measure is in school

ruby crypt
#

oh is it like length, weight and stuff

whole halo
#

no it isnt

ruby crypt
#

this is for lebesgue measure 0

whole halo
#

ok look around for the word "lebesgue" or "borel"

#

do you see anything like that in your school book or the school notes

ruby crypt
#

and I dont understand this theorem

whole halo
#

just googling things then showing them to me doesnt count, I want to see if you need to know this stuff for the course or not

ruby crypt
#

no borel

whole halo
#

any lebesgue?

ruby crypt
#

ok so in my lecture notes

#

they didn't really say "Lebesgue measure 0 set is..."

#

the only thing that defines lebesgue measure 0 set is this

#

in my lecture notes ofc

#

and heck how am I supposed to understand

whole halo
#

you can swear bro

#

they didnt tell you shit about lebesgue

#

here watch this:

#

see the 0 in "measure 0"?

#

and the "< epsilon" in the last line?

ruby crypt
#

ye

whole halo
#

if you change those to "measure L" and "< L + epsilon", thats how you find how big something is

#

the L needs to be as large as possible while still allowing for any epsilon > 0 like that

sand barn
#

List all numbers of the set in sequence. Chose a number such as 0.1.

whole halo
#

do not do that

sand barn
#

Place a interval of 0.05 around the first element

whole halo
#

oh you mean the set in the problem, I see

sand barn
#

Then 0.025 around the next and so on

whole halo
#

generally you cant go around and "list all numbers" for most sets, but for this one you can

ruby crypt
#

he is just repeating what he said

#

nice job teach

sand barn
#

That's an intuitive explanation

whole halo
#

thats not generally how you write down an interval around x

ruby crypt
#

so is it with x/2 instead?

whole halo
#

should instead be [x - 0.1, x + 0.1] or (x - 0.1, x + 0.1)

#

remember, this is around x

ruby crypt
#

oh around x got it

whole halo
#

so for example if x is 5, this would be (4.9, 5.1)

sand barn
#

That's what I said

ruby crypt
#

so is that measure 0.1

whole halo
#

oh I see

ruby crypt
#

and btw I just found out measure is not covered for my exam bruh

whole halo
#

measure of x woud be x/2 yea

ruby crypt
#

but its good to kno

sand barn
#

Then next element is [x -0.05,x+0.05]

whole halo
#

man this is messy

ruby crypt
#

right

whole halo
#

we're going to stick to using x for "elements of the set" from now on

#

not "what the measure/length is"

#

(4.9, 5.1) = (5 - 0.1, 5 + 0.1) has measure 0.2 for example

ruby crypt
#

alr

sand barn
#

I see

ruby crypt
#

so by measure 0, we want the number around x to be as small as 0

#

like very close to 0

sand barn
#

Yes

ruby crypt
#

?

#

I don't get the purpose

whole halo
#

yea, the left side tells you that "S can be completely covered up by intervals"
then the right side tells you those intervals have a total length that can be made as small as possible

ruby crypt
#

is it to list all real numbers

whole halo
#

now because of that, its not like S can contain an interval

#

if it contained [0, 0.1] for example, its measure is at least 0.1

#

because of that [0, 0.1] there

ruby crypt
#

I see

sand barn
#

But can't we divide x by anything like 3 or 1679?

whole halo
#

well I mixed "x being the 'epsilon'" with "x being the element"

#

you could do that, but we're just not calling it x anymore

#

call it delta instead or something

ruby crypt
#

huh

sand barn
#

Ok we'll call it e

whole halo
#

not a popular choice

ruby crypt
#

call what e?

sand barn
#

e/2 or e/3

sand barn
whole halo
#

ok vins remember when we had (4.9, 5.1) = (5 - 0.1, 5 + 0.1)?

ruby crypt
#

yse

whole halo
#

you started off calling x the 0.1

ruby crypt
#

AAA

#

yes

whole halo
#

this is a weird decision, and I misread what you said

ruby crypt
#

so now we call e

whole halo
#

x is intended to be used for points, or for parts of the set

#

not for how big something is

#

we're calling it e now, so (x - e, x + e)

#

this has length or measure 2e

#

(e > 0)

ruby crypt
#

ofc

sand barn
#

Correct lets stick to 2e

whole halo
#

now you can always do e/3 or e/whatever as coder said

#

this makes the set smaller...

ruby crypt
#

aslongas 2>0

whole halo
#

but youre making an assumption here

ruby crypt
#

e

whole halo
#

now a common example of a set of lebesgue measure 0 are sets that have finite or countable elements

#

have you heard of this before

ruby crypt
#

nope

whole halo
#

think about the set {0, 1, 2}

#

this set has a grand total of 3 elements

#

it is lebesgue measure 0

#

can you see why

ruby crypt
#

what

#

ooo

whole halo
#

go to the definition and think about what coder is saying

ruby crypt
#

uh because pick a number

sand barn
#

We use curly brackets for finite sets and intervals are []/()

ruby crypt
#

then pick a small e > 0, then it can't have anything other than that number

whole halo
#

and more importantly, see here you can only pick a countable amount of these intervals at a time

#

for example, youre picking 3 intervals because theres 3 elements

ruby crypt
#

well I can pick more no? try with different e

sand barn
#

Of course

whole halo
#

well you need to be able to do this for all e > 0

#

not just "different e thats easy for me to do"

ruby crypt
#

so its not only 3 intervals

whole halo
#

thats not what I said

ruby crypt
whole halo
#

the number of intervals is separate from e

sand barn
#

Nope as long as you can feasibily calculate

whole halo
#

its a normal choice to do that

ruby crypt
whole halo
#

(-0.1, 0.1) U (0.9, 1.1) U (1.9, 2.1)

#

no?

ruby crypt
#

yes that true

whole halo
#

read this

ruby crypt
#

but thats for measure 0.2

whole halo
#

this is saying "the length of the intervals add up to a number less than e"

#

it doesnt tell you how big each interval is

#

just that they have to add up to be less than e

#

so (-0.1, 0.1) U (0.9, 1.1) U (1.9, 2.1) would be good for e = 0.7, 0.8, 0.60001, etc.

whole halo
#

yea

ruby crypt
#

I see

whole halo
#

coder is using e to be short for epsilon

#

typing out the whole word gets tedious

#

I am too

ruby crypt
whole halo
#

vins uh

ruby crypt
#

0.6

whole halo
#

how long is (-0.1, 0.1)?

#

there you go

ruby crypt
#

0.6

#

0.6

whole halo
#

this interval works for epsilon > 0.6

#

now keep in mind you know what e is in advance

#

you then use this e to make intervals as small as you need

ruby crypt
#

ofc

whole halo
#

that still cover up S = {0, 1, 2} here

#

so what intervals would you go with

ruby crypt
#

err 0.05

whole halo
#

as a reminder you dont know how small e is

ruby crypt
#

or e/2

#

e/3

#

e/100

whole halo
#

lol

#

just e/6 is enough

ruby crypt
#

ok

#

why 6 tho

whole halo
#

πŸ€”

#

lets see

ruby crypt
#

oh

#

u wann add it up to epsilon?

whole halo
#

what else would I be doing lol

ruby crypt
#

ik ur trick buddy πŸ˜›

winter birch
#

wot

ruby crypt
#

eo actually we let e = eps/6

whole halo
#

you were already supposed to know the trick, but Im glad you feel happy about this

whole halo
#

again we're just having e be short for epsilon

ruby crypt
#

ok

sand barn
#

e = e/6 or eps= eps/6

ruby crypt
#

ok lets do e = epsilon

whole halo
#

vins

sand barn
whole halo
#

we're not having e mean how big an interval is from its center anymore

#

we're having e just be short for epsilon, which is how big the intervals are in total

ruby crypt
#

yes ok

whole halo
#

e/6 = epsilon/6 will be how big the intervals are

#

alr I want you to write down the intervals that:

  • cover S = {0, 1, 2} up entirely
  • have lengths that add up to be < e
ruby crypt
#

entirely?

#

im dead

whole halo
#

???

#

S only has 3 elements

#

did you forget about (-0.1, 0.1) U (0.9, 1.1) U (1.9, 2.1)?

#

doesnt that cover S up? entirely?

ruby crypt
#

but thats only one

#

um yea

#

ok

#

oh

#

the word "entirely" sounds scary

whole halo
#

bro

#

you sound like youre in high school this is crazy

ruby crypt
#

(0 - e/6, 0 + e/6) U (1 - e/6, 1+ e/6) U (2-e/6, 2+e/6)

ruby crypt
whole halo
#

yea thats the idea

whole halo
ruby crypt
#

ok

whole halo
#

so for example S has 3 elements, and you just - e/6, + e/6 each of them

#

if S had 10 elements, youd do - e/20, + e/20

ruby crypt
#

wow nice touch of 2n

whole halo
#

you can see we have something that works here

#

because of this, if S only has a finite number of elements

#

it has lebesgue measure 0

#

it makes sense, S should have 0 length, and see here the measure agrees with what we think

ruby crypt
#

cuz by definition, we take n -> inf

#

?

whole halo
#

no

#

n here is just how many elements S has

#

think about what we just used n for

sand barn
#

Which can go till inf

ruby crypt
#

oh right yea its number of elements

whole halo
#

it can still go towards inf though, but be careful

#

some infinities are bigger than others

#

this will only work for the smallest infinity, which is the one coder is assuming

sand barn
whole halo
#

coder you need to confirm that S is countable first

sand barn
#

It is already confirmed it has measure 0

whole halo
#

youre saying to go through every element

ruby crypt
#

isn't it supposed to be measure e/3

whole halo
#

do you remember how the notes defined "measure 0"?

whole halo
#

remember, e is how big it is in total, not how big each one is

sand barn
#

Total is 3*e/3

whole halo
#

now see here the first half of the definition

#

we were able to cover S up with intervals, with lengths that added up to e, for any e > 0

#

that means you could make e as small as you want

#

and the length just gets smaller

ruby crypt
#

so our (a1, b1) = (-0.1,0.1) and so on?

whole halo
#

yea

ruby crypt
#

and making e as small as possible, aaaa

#

yea S is still inside that union

whole halo
#

the measure of the set is how small we can make it

#

here, the measure is 0

ruby crypt
#

ah got it

#

got it

whole halo
#

alr now for another interesting example

#

have you heard of a countable set yet

ruby crypt
#

yes a set is countable if a set is countably infinite or finite

#

iff actually

whole halo
#

yep, now this definition only allows you to use a countable number of intervals

#

you gotta be able to count them from (a1, b1) to ...

#

so its not like you can do this () trick with any uncountable set

#

you can do it for countable sets, like {1, 2, 3, 4, ...} or the rational numbers

ruby crypt
#

yseh

whole halo
#

so as a result, any countable set has lebesgue measure 0

ruby crypt
#

I understand it now

whole halo
#

however, you dont necessarily need countable to get lebesgue measure 0

ruby crypt
#

I wanna move to one more topic after this, do u still hv time

whole halo
#

maybe

#

I first gotta show you how you do this problem, though

ruby crypt
#

ehh i think I prioritize my other topic rather than this, cuz this other topic is included in exam

whole halo
#

alr

ruby crypt
#

just quick question

#

very quick

#

why uniformly continuous and continuous everywhere is a different thing

whole halo
#

uniformly continuous is being specific on the kind of continuity you have

#

continuous everywhere is just saying "its continuous everywhere", doesnt really tell you which kind

#

those are separate things, you can have one, the other, both, or neither

ruby crypt
#

wdym which kind

whole halo
#

uniformly continuous you can think is a better or a stronger version of continuity

runic needle
#

doesn't unfiormly continous imply continunuos everywhere

ruby crypt
west orbit
runic needle
#

continous means continuous at x for all x in the domain

ruby crypt
#

thats where im confused

whole halo
#

sign(x - 1) √x is uniformly continuous on [2, 4] but not continuous everywhere on its domain

#

remember youre using the word "everywhere"

#

you could yknow just leave it out

ruby crypt
#

sign(x-1)?

whole halo
#

function that can cause a discontinuity at x = 1

#

this function is:

#

sign(positive number) = 1
sign(0) = 0
sign(negative number) = -1

#

so sign(x - 1) would be:
1 if x > 1
0 if x = 1
-1 if x < 1

ruby crypt
#

ok

whole halo
#

also,
uniform continuity => continuity
uniform continuity everywhere you want => continuity everywhere you want

#

but you cant say uniform continuity => continuity everywhere you want

ruby crypt
whole halo
#

it still is

ruby crypt
#

what

whole halo
#

it doesnt need to be a closed set

#

who told you that

#

oooh did you think that one rule was all there was to it

#

theres more to this than just "continuous on compact set means uniformly continuous on that compact set too"

ruby crypt
#

ok I know nothing, carry on

whole halo
#

you could just have uniformly continuous for other reasons

#

ok you should relearn what uniform continuity is

#

you know continuity has epsilon-delta?

ruby crypt
#

yes

#

uniform cont. too

whole halo
#

now an issue is that the delta depends on epsilon and on x

#

hold on there Im still going

#

so for example for √x, you need to make your delta smaller as x gets smaller

#

you cant just make a delta based on epsilon

#

wait a minute

#

screwed up, √x is uniformly continuous

#

the usual counterexample is 1/√x instead

#

1/√x is continuous everywhere but not uniformly continuous everywhere

#

youre gonna have to swap out all the times I said √x with 1/√x

ruby crypt
#

uh

whole halo
#

anyway 1/√x depends on epsilon and x for the delta
for example if you want to confirm 1/√x is continuous at x = 0.001, youre gonna have to pick a much smaller delta than with x = 1000

#

the value of delta then doesnt stay the same depending on the x

#

uniform continuity means the value of delta is uniform, you pick an epsilon and theres a delta that always works, regardless of x

#

you can think of it as "if you change x by delta, then f(x) will never change beyond epsilon"

ruby crypt
whole halo
#

I didnt say that

#

one delta works for all x

ruby crypt
#

nvm

whole halo
#

one delta works for all x and, at least, this epsilon we got that delta from

#

(and all bigger epsilon than that too)

runic needle
#

the difference just comes down to switching the order of quantifiers lol

whole halo
#

thats reductive

ruby crypt
#

can u tell me where a function is continuous but not uniform and a function that's uniform

whole halo
#

1/√x is continuous but not uniformly continuous

ruby crypt
#

I haven't seen the clear picture of the difference

whole halo
#

see here in this picture for example

#

say you know epsilon = 0.5

#

you pick delta = 0.2

#

now when you look at g(x) = √x, which is uniformly continuous on [0, ∞),

#

youll notice the red curve never crosses the black lines on the red rectangle

#

however, when you look at f(x) = 1/√x, which is not uniformly continuous on [0, ∞),
youll notice the blue curve crosses the black line atop the blue rectangle

ruby crypt
#

oh oh oh

#

interesting

whole halo
#

now these rectangles represent the epsilon and delta that was picked

#

the rectangles are 0.4 wide and 1 tall

#

(2 delta and 2 epsilon)

ruby crypt
#

ah yes ofc

whole halo
#

so you can think of them as confirming that, if you only move x by less than 0.2, then y in that area only moves by less than 0.5

#

for the red curve, this always happens

ruby crypt
#

yes

whole halo
#

for the blue one, you just move left enough and it will shoot up through the ceiling

#

doesnt matter how small your delta is

#

so we cant just settle with a uniform choice of delta = 0.2 like we did for √x

ruby crypt
#

DANNGGGGGG

whole halo
#

so 1/√x is not uniformly continuous

ruby crypt
#

interesting

whole halo
#

uniform continuity is really convenient because then we dont need to care about the x anymore

#

you want an epsilon, you just need a delta for it

#

that way you can be more global about the facts you can get out of the function

ruby crypt
#

but then seeing this blue line, since small changes in delta can cause the value to change more than epsilon, how is it still continuous πŸ€”

whole halo
#

continuity lets you also have it depend on x

#

youd get to change the delta as the box moves

#

uniform continuity wouldnt let you do that

#

1/√x is still continuous because you just make the box thinner as you move further to the left

ruby crypt
#

but they should have delta in terms of x and e right

whole halo
#

yea

ruby crypt
#

ok ok

whole halo
#

many problems you do work with uniformly continuous functions to keep the load easy on you

#

so thats why you didnt need to know what x was

#

for 1/√x, youd have to

#

for example polynomials are uniformly continuous everywhere (on a bounded set)

ruby crypt
#

like from the question

whole halo
#

you didnt need to use what x was for the delta, you could pick the same delta = # for any epsilon and have it work

#

ok thats not really true nvm

#

usually you do practice on straight lines

#

those ones are uniformly continuous

#

for parabolas and other polynomials though, theres a hidden way you do use the x in your delta

ruby crypt
whole halo
#

yea I messed up again

ruby crypt
#

i dont think so

whole halo
#

you have to restrict f(x) to only be "-100 ≀ x ≀ 100" or "-10000 ≀ x ≀ 10000"

#

this is because f(x) slopes steeper and steeper

ruby crypt
#

thats very demanding

#

well anyways, ik the difference now lel, got the full pic

whole halo
#

alr

ruby crypt
#

and maybe one more b4 i close

#

how to prove that a function is continuous everywhere

#

usually in Qs they just say "prove it's continuous at 2"

whole halo
#

alr

#

"continuous at x = 2" has you check for continuity at x = 2

#

"continuous on [1, 2]" has you check for continuity at every x in [1, 2]

#

so continuity at x=1, at x=2, at any x in between

#

you dont look further than [1, 2] though I believe

#

well thats hard to say actually, it might depend on who you ask

ruby crypt
#

alr go on

runic needle
#

why would you look further

whole halo
#

because itd be disingenuous to say "this function is continuous at A and at B, so its continuous at A U B"

ruby crypt
#

u mean (A,B)?

runic needle
#

wat

whole halo
#

A and B are sets here, you can see that with the U

#

the U is union

#

,,\cup

soft zealotBOT
whole halo
#

man I cant believe I typed that

ruby crypt
#

why would a set be continuous

whole halo
#

oh whoops

#

should be "on A" not "at A"

ruby crypt
#

oh

#

ok

whole halo
#

this function is continuous on nonnegative numbers and on negative numbers, but its not continuous on both

ruby crypt
#

alr that makes sense

whole halo
#

now if youd prefer this to be true, we have to be more specific on this "continuous on" stuff

runic needle
whole halo
#

you uh

#

moved the goalposts

whole halo
#

now thats why we would look further

#

but thats not really the same thing as saying "on" is it

#

more of "in"

ruby crypt
#

oml

runic needle
#

idk dude

ruby crypt
whole halo
#

yea continuous everywhere doesnt have anything to do with uniformly continuous

#

continuous everywhere just means its continuous everywhere you care about

ruby crypt
whole halo
#

uniform continuous => cont

#

uniform continous everywhere => cont everywhere

#

ok to be more specific

#

usually when we use on, we dont look further

ruby crypt
#

on an interval right

whole halo
#

on a set, could be an interval

#

when you say "continuous on something", that something is a set

#

then you look within that set and see if theres anything discontinuous

ruby crypt
#

like the previous ones we talked abt? (x-e, x+e)?

whole halo
#

you dont look outside the set, it can cause unexpected behavior but thats not what we need

#

(x - e, x + e) is an interval, I can tell you that

ruby crypt
#

yes

whole halo
#

dont know what you mean specifically beyond that

#

its an interval, thats for sure

ruby crypt
#

nope yep thats what I meant

whole halo
#

it really just is the word everywhere

#

for example if I have √x, I can call that "continuous everywhere"

#

here, its "continuous on its domain [0, ∞)"

ruby crypt
#

yes how to prove that

whole halo
#

because I dont really have a reason to put in x = -1 and go "aha its discontinuous at x = -1" when I dont even have √x be real there

#

everywhere just cuts words out

#

so people then usually add whatever interval or set they mean right after it anyway

#

"continuous everywhere on [0, ∞)"

#

just means "continuous on [0, ∞)"

#

everywhere here is just a feeling kind of word, its to tell you the scope of what we're talking about

#

sometimes people use this in vague statements like

#

"1/x is continuous everywhere"

ruby crypt
#

exactly

whole halo
#

1/x is continuous on (-∞, 0) U (0, ∞)
1/x is not continuous on all of R

#

but you can feasibly consider either of those everywhere

#

because you dont have a good reason to do 1/0, so why consider it

#

1/x is continuous everywhere
1/x is not continuous everywhere

ruby crypt
#

so can I be sure that this typa question asking continuity everywhere would have a low chance to come out in exam πŸ˜…

whole halo
#

its just a word, itll be clear when you read it

ruby crypt
#

ok

whole halo
#

they should tell you an interval, or just tell you the one point they care about

ruby crypt
#

ok ok

#

thanks bro

whole halo
#

np

ruby crypt
#

whats that pfp btw