hm
#help-36
proud dock
next wraith
and wdym angle between 2 edges?
it's 2 sides
dihedral angle
if you want a better drawing that's all I can do
has it uploaded?
goddamn this internet connection
proud dock
My imagination tells me that the angle between two sides is basically the angle between two edges. lol mmmm
next wraith
proud dock
oh
tetrahedron has 4 faces, pyramids have 5
nvm, triangular pyrmaid has 4
damn terminologies lol
next wraith
yes
proud dock
im thinking, bare with me lol
next wraith
lolll sure
this reminds me of when I read an article where someone wrote that and the comments were all like "I'll keep my clothes on though thank you"
maybe my notes will help
uh okay i think i... got it wrong the first time?
red estuary
brother use a software
next wraith
not a brother
proud dock
My maths feel weak for some reason.
Since all base lengths are equal, my mind wanted to start there.
next wraith
well i misread the whole thing...
its supposed to be between two edges.
so... only one side needs to be taken into account i guess
proud dock
I'm reading from a random image. $V = \frac{1}{3}(BaseArea)(Height)$
soft zealotBOT
HqppyFeet
next wraith
i know the volume formula
thats not the problem
the problem is defining it using alpha and h
but anyway i misread the thing
i think i know how to solve it now
proud dock
aight 💀
final saddleBOT
final saddleBOT
Available help channel!
untold kiln
In this passage, how does the addition of sqrt(z) at the bottom turn turns into a multiplication by 2?
final saddleBOT
In this passage, how does the addition of `sqrt(z)` at the bottom turn turns int...
obtuse hedge
$y + y = 2y$
soft zealotBOT
Coolempire93
obtuse hedge
Anything plus itself is 2 times itself
deep condor
and before that, you evaluate the limit by substitution
untold kiln
oh, one has to understand that sqrt(z) turns into sqrt(x), and then that becomes sqrt(x) + sqrt(x).
Up till that example, was always working with h -> 0, so forgot about that difference.
thanks
.close
final saddleBOT
loud hedge
how smart are u guys 😭
next wraith
how smart are u guys 😭
???
leaden moon
how smart are u guys 😭
Which grade you in
celest crane
how smart are u guys 😭
No smarter than people who study other subjects.
next wraith
i thought that was sarcasm tbh
final saddleBOT
Available help channel!
viscid nacelle
Can anyone help me with part iii I dont really understand what a potential function is
final saddleBOT
Can anyone help me with part iii I dont really understand what a potential funct...
bold turtle
Not gonna be able to help atm, but a potential function P of a vector field F would be some function whose gradient is F
That is, F = grad(P)
viscid nacelle
So dP/dx = 2xy^3 -y^3 -x^3 and dP/dy =3(x^2-lambda x +1)y^2
and then intergrate these both
do i need to select a value for lambda
obtuse hedge
So dP/dx = 2xy^3 -y^3 -x^3 and dP/dy =3(x^2-lambda x +1)y^2
Sounds green theorem related
final saddleBOT
obtuse hedge
No problem! good luck!
final saddleBOT
Available help channel!
rustic wedge
final saddleBOT
rustic wedge
problem i came up with while solving a related question (which can be solved without doing this)
would like someone to check my work
initial v diagram + impulse diagram
final velocity digram
also, obviously rotating with some w and w' respectively
then i did $I_f = m(v_f - v \cos 30^{\circ} )$ and $J_f = I_f*R = MOI (w'-w)$
soft zealotBOT
rak³en
rustic wedge
and solved to get $v_f = \left( \frac{5}{2 \sqrt{3}} - \frac{2}{3} \right) v$
soft zealotBOT
rak³en
final saddleBOT
@rustic wedge Has your question been resolved?
rustic wedge
<@&286206848099549185>
obtuse hedge
discord.gg/physics might be able to answer quicker than here
final saddleBOT
@rustic wedge Has your question been resolved?
final saddleBOT
final saddleBOT
Available help channel!
signal field
How to calculate this
final saddleBOT
How to calculate this
signal field
I have literally no idea how to start with
pliant shore
I have literally no idea how to start with
do you know that:
- tangents to the circle from the same point have the same length?
- power of a point, so for example, VT * VS = VU^2 ?
signal field
do you know that:
1) tangents to the circle from the same point have the same le...
what is power of a point
pliant shore
it's also called the secant-tangent theorem
signal field
it's also called the secant-tangent theorem
I don't think that is include in our school syallabus
pliant shore
signal field
I think I let RU as x
pliant shore
I genuinely think triangles VSQ and PRQ might be similar
signal field
Fun fact: my classmate just let angle PRQ as 90 degree and calculate the answer 💀
pliant shore
wild
pliant shore
so QS*QP=QU^2?
yep
okay this problem is breaking my brain
<@&268886789983436800>
(spam)
heady moon
mute him for 2years
signal field
ok triangle PTS is congrunt to triangle PUS I think (SAS)
ok and the triangle PTU is also similar to triangle PTS (AAA)
proud dock
Following this, I only can apply SV*TV = VU^2, but idk how that info is useful.
I have a feeling ST = new segment SU, but I can't build on assumptions. mm
signal field
nah i ain't using PRQ= 90 degree method
silent shore
Following this, I only can apply SV*TV = VU^2, but idk how that info is useful.
What’s the theorem
proud dock
What’s the theorem
aah! i made a mistake
signal field
wait what
silent shore
I have the formula sheets
proud dock
What’s the theorem
I wrote ST*TV = VR^2, but supposed to be SV*TV = VU^2. Staring at this theorem.
signal field
oh
proud dock
heady moon
I don't think that is include in our school syallabus
are you sure?
heady moon
theorem is high school
signal field
I'm thinking should I use sine law cosine law
heady moon
I'm thinking should I use sine law cosine law
does that get you anywhere?
signal field
well the problem is there is no given angle
proud dock
without angles I can't get my mind to go anywhere. At this point we just have to work with angle=theta at one place.
signal field
ok I need to think I can use VR=33
proud dock
SU = sqrt(40^2 + 40^2 - 2*40*40*cos(theta)) = 40*sqrt(2-2cos(theta)).
Because isosceles, (180-theta)/2 = orange angles.
i give up im sorry. I feel like solving this requires a large system of equations, just working with what's unknown
proud dock
then it's the question's fault. no task is supposed to design something like this and say angle PRQ is a right angle.
signal field
then it's the question's fault. no task is supposed to design something like thi...
there has to be a way to prove that angle is 90
ok wait let me use angle compund formula
ultimate weapon
I gues it's gg
signal field
ok I'm thinking the suggested time for that paper is 1 hour 15 minutes and this question along already used 30 mins
proud dock
It's a challenge, but good to be exposed to those painful points now.
final saddleBOT
@signal field Has your question been resolved?
tiny kraken
there has to be a way to prove that angle is 90
You can't
Cuz it isn't
RU is constant regardless of the angle
calm cloud
how can i do the 61e question, the shape is too complex
final saddleBOT
how can i do the 61e question, the shape is too complex
calm cloud
that 3 planes are red blue yellow
pink is just for 61d question
my teacher only taught some easy parts, then the homework is just nonsense
cant even determine where are I J H
final saddleBOT
@calm cloud Has your question been resolved?
oak forum
So the question is a bit weird sounding but it is straight-forward
when two planes intersect you get a straight line
so the intersection of the combination of the three planes will make a total of three distinct lines
because each of the planes were using points from inscribing the rectangular prism, points will be shared
final saddleBOT
oak forum
.reopen
final saddleBOT
Available help channel!
pseudo cradle
I'm trying to follow this lesson on Khan Academy but am completely confused. Does anyone have a link to a clearer explanation?
final saddleBOT
I'm trying to follow this lesson on Khan Academy but am completely confused. Doe...
digital sable
I'm trying to follow this lesson on Khan Academy but am completely confused. Doe...
what are you confused about? perhaps i could explain
pseudo cradle
what are you confused about? perhaps i could explain
So we have this
digital sable
right
pseudo cradle
How is 1/b = a/ab?
digital sable
so in a fraction, if you multiply the top and bottom by the same thing, it is the same
since, in general we have that anything divided by itself is 1
so 1/b = a/ab is essentially nothing more than 1/b * a/a = 1/b * 1 = 1/b
does that make sense?
proud dock
Example:
1/2 = 2/4 = 6/12 = 25/50. they all share the same value, just that the numerator and denominator is sized proportionally.
From 1/2, you get 2/4 from multiplying the numerator and denominator by 2.
The same reason if you have 1/1, you can size it up to 2/2 = 5/5 = 567/567 = a/a.
pseudo cradle
Alright, so for that section, its because adding or subtracting algebraic fractions, we just follow the same rule for adding or subtracting normal fractions?
digital sable
hmmm could you clarify what you mean
pseudo cradle
1/b - 1/a you would do something like this
digital sable
yes
pseudo cradle
and get a/ab - b/ab
proud dock
Adding and subtracting fractions is hard if the bottom (denominators) are different.
It’s much simpler and easier if both fractions adapt to have the same denominator.
digital sable
and get a/ab - b/ab
yes you can look at it like this
pseudo cradle
and then a second question, why wouldn't the denominator be ab-b²?
proud dock
It can :))
pseudo cradle
or are we just applying distributive property here?
digital sable
and then a second question, why wouldn't the denominator be ab-b²?
they are the same thing
tired walrus
and letting b * (a-b) be just b(a-b)
proud dock
That person just chose to not do the distributive property lol. ab/b(a-b) and ab/(ab-b²) are the same, or in terminology, they are equivalent.
pseudo cradle
and for this question, 1 in both cases would be t/t I'm assuming?
digital sable
yes
pseudo cradle
The questions are coming from Khan Academy's quiz here:
tired walrus
and for this question, `1` in both cases would be `t/t` I'm assuming?
it'd be a good idea to make both 1's into t/t, sure.
but there's a better idea.
expand the outer fraction by t instead, to get:
$\frac{\paren{1-\frac{s}{t}}\cdot t}{\paren{1+\frac{s}{t}}\cdot t}$
soft zealotBOT
Ann
pseudo cradle
What confuses me in the example answer is if we follow the subtraction rule, wouldn't we do (tt) - (st) and get (t2)-(st)?
silent shore
So we have this
The property is 1/b/a= a/b
tired walrus
The property is 1/b/a= a/b
dont write it that way
brackets obligatory there
1/(b/a) = a/b
tired walrus
What confuses me in the example answer is if we follow the subtraction rule, wou...
subtraction with like denominator
silent shore
The property is 1/(b/a)= a/b
tired walrus
you wouldn't subtract $\frac{4}{3} - \frac{2}{3}$ as $\frac{4\times 3 - 2 \times 3}{3^2}$ now would you?
pseudo cradle
subtraction with like denominator
ahhh
soft zealotBOT
Ann
pseudo cradle
Would these kinds of questions come up a lot in a course which has these topics being covered? I'm trying to brush up before start of a semester
(the algebraic nested fractions)
pseudo cradle
Thanks
summer hollow
I need help to understand the process of a fraction problem?
final saddleBOT
I need help to understand the process of a fraction problem?
summer hollow
summer hollow
hybrid adder
do you know how to get lcm?
mint orbit
Yea, using LCM might simplify your life a little
although it seems like your process is fine
soft zealotBOT
Result:
175
rocky tusk
🤔
summer hollow
Sorry no. My math skills are a bit rusty
rocky tusk
im your biggest fan sir
rocky tusk
whats up with the arrows?
summer hollow
I use the process of multiplication of denominator and cross multiplication of numerator
And then try to divide
summer hollow
Yes butterfly method
hybrid adder
it works but it's inefficient
rocky tusk
good ol days
summer hollow
it works but it's inefficient
How so?
rocky tusk
How so?
because you may introduce extra factors that make the simplifying process more complicated
hence why you should multiply by the lcm
inland birch
everything you've done is mathematically correct and the only step you have is to simplify the fraction which i think is what you're asking for help with
when you see a 0 and a 5 in the one's digits respectively this should hint at dividing both sides by 5
whether or not that's the highest common factor we can figure out later, for now we can just do what's most obvious
summer hollow
hence why you should multiply by the lcm
So in this case what would be the method to find the lcm?
inland birch
indeed, it's more efficient to use the LCM but it seems no one has commented on the final simplification
hybrid adder
explaining factors should solve both the issues
rocky tusk
So in this case what would be the method to find the lcm?
you factor each number into primes/power of primes then take the largest power of the primes from each prime
for example here we have 5^2 and 5 * 7
so we need at least two 5s and one 7 to be a multiple of both
hence our lcm is 5^2 * 7
final saddleBOT
@summer hollow Has your question been resolved?
summer hollow
ok got it. Thank you guys
final saddleBOT
final saddleBOT
Available help channel!
warm python
Here does this work:
\
$\sum_{i=1}^{n} (X-X_i)^2 \sim \chi^2(n)$. So $\frac{1}{n} \cdot \sum_{i=1}^{n} (X-X_i)^2 \sim \frac{1}{n}\chi^2(n)$.
\
$Var(\frac{1}{n} \chi^2(n))= \frac{2n}{n}=2$
final saddleBOT
Here does this work:
\\
$\sum_{i=1}^{n} (X-X_i)^2 \sim \chi^2(n)$. So $\frac{1}{...
soft zealotBOT
wai
plucky rover
The first part is correct
I dont remember the variance of the chi square distribution
warm python
I dont remember the variance of the chi square distribution
Just want to be sure I got he number of degrees of freedom right
.close
strange iron
tuff
fossil kiln
<@&268886789983436800>
rustic wedge
can someone help me make sense of this
final saddleBOT
can someone help me make sense of this
rustic wedge
$\frac{\Delta T}{\Delta t} = c(T_{av} - T_0)$
soft zealotBOT
rak³en
rustic wedge
this is supposedly derived from newtons (ALREADY APPROXIMATE) law of cooling
chilly pollen
Help us out with all the variables please and the setup
near thistle
thats just saying rate of change of temp is proportional to temp diff no?
where c is constant of proportionality
chilly pollen
But there is a Delta on T in the LHS
near thistle
also whats $T_{av}$?
soft zealotBOT
Cera
chilly pollen
Right
rustic wedge
here $c = \frac{4 \sigma \epsilon A T_0^3}{ms}$, where $\sigma$ is stefan's constant, $\epsilon$ is the emissivity, $m$ is the mass, $T_0$ is the temperature of the surroundings, $A$ is the surface area, and $s$ is the specific heat capacity. \
On the above message:
$T$ is temperature, $\Delta T$ is the change in temperature over the time interval $\Delta t$, and $T_{av} = \frac{T_i + T_f}{2}$
soft zealotBOT
rak³en
plucky rover
can someone help me make sense of this
Temperature difference works similarly to radioactivity
The more there is, the faster you lose it
rustic wedge
This was apparently obtained by using $\frac{\mathrm{d} T}{\mathrm{dt}} = c (T-T_0)$
soft zealotBOT
rak³en
rustic wedge
(which is newtons law of cooling)
rustic wedge
Temperature difference works similarly to radioactivity
well i suppose it makes some sense intuitively, but where tf did T_av come from
rustic wedge
**rak³en**
like i thought maybe it involves solving this and then doing some approximation crap on $e^{-ct} = \frac{T_f - T_0}{T_i - T_0}$ ($T_f$ is final temp, $T_i$ is initial temp)
soft zealotBOT
rak³en
rustic wedge
but i have not been able to derive this
plucky rover
Are you sure you're not missing a log on the formula?
rustic wedge
Are you sure you're not missing a log on the formula?
yes
its under 'Alternate Method: for approximate answers to Newtons law of cooling'
rustic wedge
**rak³en**
for a standard numerical using this
rustic wedge
but then they proceed to use it for every question, INCLUDING SYMBOLIC ONES
rustic wedge
Feels like a jugad but what do I know
this shit makes no sense istg
i am just writing formulas and putting stuff to get the answer
do i know why?
plucky rover
Jee moment
rustic wedge
OFC NOT
plucky rover
Extremely jee moment 
rustic wedge
TIME TO ASK CHATGPT 
okay @plucky rover can u verify this
because that seems horribly wrong, even for midpoint rule
final saddleBOT
@rustic wedge Has your question been resolved?
rustic wedge
okay <@321479019134713857> can u verify this
<@&286206848099549185> can someone verify this
obsidian knot
<@&286206848099549185> can someone verify this
It's ok
rustic wedge
It's ok
err why tho?
i have never used an appx like this
would be nice if u could provide a source or a proof
formal harbor
okay <@321479019134713857> can u verify this
what's the question? why T is Tavg?
rustic wedge
what's the question? why T is Tavg?
err it could u pls read from the top
formal harbor
well i can't tell what you're asking
rustic wedge
**rak³en**
how was this derived? i asked chatgpt but i am suspicious of the approach it spat out.
rustic wedge
what's the question? why T is Tavg?
because idfc man 😭
warm python
Have you tried physicrod
formal harbor
it's the heat equation
rustic wedge
Have you tried physicrod
no
warm python
Maybe ask there too
rustic wedge
what do you mean derive it?
uh how can u say that equation holds true
my module needs to prove it
and also tell me what values it will hold true for
because idk when its valid
formal harbor
does it expect thermodynamics?
rustic wedge
does it expect thermodynamics?
does what expect thermo?
formal harbor
like you can get that result from thermodynamics
i still do not understand waht you mean derive
rustic wedge
like you can get that result from thermodynamics
oh rlly?
rustic wedge
https://en.wikipedia.org/wiki/Newton%27s_law_of_cooling
see thats the issue
rustic wedge
**rak³en**
this isnt nlc
rustic wedge
is it physics
phusics
formal harbor
that c is just a constant
rustic wedge
buddy this IS NOT NEWTONS LAW
formal harbor
???
rustic wedge
its an 'alternate form' which obviously is not equivalent
rustic wedge
**rak³en**
this is newtons law
formal harbor
what do you mean alternate form
rustic wedge
**rak³en**
or more precisely this
rustic wedge
what do you mean alternate form
can u pls for the love of god go through the thread i am sure u'll understand it if u read from the top
formal harbor
like you're just listing stuff without direction
rustic wedge
listen.
$\frac{\Delta T}{\Delta t} = c(T_{av} - T_0)$ is a result given in my module which is supposedly derived from newtons law of cooling (which is $\frac{\mathrm{d} T}{\mathrm{dt}} = c (T-T_0)$) but no steps have been given. I need help figuring out when this results hold true (no conditions given sadly) and how would one go about proving it using newtons law of cooling. \
I have asked chatgpt, but it spat out some crap integral approximation which i believe is wrong. \
Symbol guide: \
$c = \frac{4 \sigma \epsilon A T_0^3}{ms}$, where $\sigma$ is stefan's constant, $\epsilon$ is the emissivity, $m$ is the mass, $T_0$ is the temperature of the surroundings, $A$ is the surface area, and $s$ is the specific heat capacity. \
$T$ is temperature, $\Delta T$ is the change in temperature over the time interval $\Delta t$, and $T_{av} = \frac{T_i + T_f}{2}$
chilly pollen
the question is concerning an approximation of Newton's Law I think, thiccfetus
rustic wedge
the question is concerning an approximation of Newton's Law I think, thiccfetus
if this person still does not understand my question, they need to leave.
chilly pollen
I?
soft zealotBOT
rak³en
formal harbor
you're overthinking lol
dt/dt ~ dt/dt
like what are you asking
what are you expecting to get out of this
'where it holds true', is whenever thermodynamics apply
chilly pollen
thiccfetus, are you for real?
rustic wedge
buddy the result is not always true
i have verrified that
mods help me here
get this guy out of my channel
bold turtle
well i suppose it makes some sense intuitively, but where tf did T_av come from
Environmental temperature, if I had to guess?
rustic wedge
Environmental temperature, if I had to guess?
no?? it doesnt depend on it (t_0 is environmental temp)
bold turtle
well, I mean I'm working from this thing...
rustic wedge
well, I mean I'm working from this thing...
oh shit i misstated newtons law
$\frac{\Delta T}{\Delta t} = \frac{c}{ms}(T_{av} - T_0)$ is a result given in my module which is supposedly derived from newtons law of cooling (which is $\frac{\mathrm{d} Q}{\mathrm{dt}} = c (T-T_0)$) but no steps have been given. I need help figuring out when this results hold true (no conditions given sadly) and how would one go about proving it using newtons law of cooling. \
I have asked chatgpt, but it spat out some crap integral approximation which i believe is wrong.
Symbol guide:
$c = \frac{4 \sigma \epsilon A T_0^3}{ms}$, where $\sigma$ is stefan's constant, $\epsilon$ is the emissivity, $m$ is the mass, $T0$ is the temperature of the surroundings, $A$ is the surface area, and $s$ is the specific heat capacity.
$T$ is temperature, $\Delta T$ is the change in temperature over the time interval $\Delta t$, and $T{av} = \frac{T_i + T_f}{2}$
soft zealotBOT
rak³en
rustic wedge
should be right now
rustic wedge
What makes capital Delta different here?
wdym? capital delta here is t_f - t_i not t_f - t_o
bold turtle
oh it's just Difference
I thought it was a calculus thing
Some mean value theorem shenanigans perhaps?
rustic wedge
Some mean value theorem shenanigans perhaps?
god knows
rustic wedge
okay <@321479019134713857> can u verify this
this is the only source of :copium: i have
bold turtle
wait a second, this is related to specific heat capacity
energy = mc (delta T)
So rate of heat transfer Q = mc (delta T) over delta t
then...
er...
well shit; there's gotta just be a substitution to make, surely
chilly pollen
What about T_av though
bold turtle
yh, I guess ask your tutor/lecturer? but I'm much more inclined the reasoning for the derivation is from physics principles than raw calculus
rustic wedge
yh, I guess ask your tutor/lecturer? but I'm much more inclined the reasoning fo...
okah
i will go tp physicscord
ty for the help
final saddleBOT
@rustic wedge Has your question been resolved?
tiny kraken
final saddleBOT
next thorn
that sounds very easy.
odd seal
my my, 0d points and a 2d plane in a 3d space? hows that even possible
next thorn
get better.
odd seal
on a more serious note, why do i feel like the plane should be parallel to ABC
tiny kraken
on a more serious note, why do i feel like the plane should be parallel to ABC
I so do have the same feeling, but I also doubt myself if it even true
odd seal
well, time to set up and solve the calculus problem
tiny kraken
That sound painful consider how distance formula looks like
and also there will be 2 variables
My one of my mentor just solve this question in under 10 min wtf
Okay that's fucking smart omg
.close
final saddleBOT
craggy plank
final saddleBOT
Available help channel!
torn dome
final saddleBOT
torn dome
domain is all reals btw
How to write the set for [1/2] in set builder form
what if i dont want to write { ...-3/2, -1/2, 0, 1/2, 3/2, 5/2...}
silver dew
I guess notation wise (1/2)+Z is understandable?
hasty mist
what if i dont want to write { ...-3/2, -1/2, 0, 1/2, 3/2, 5/2...}
well, these are numbers of the form 1/2 + n for n in Z
torn dome
well, these are numbers of the form 1/2 + n for n in Z
wow, list comprehension
hasty mist
lehension
torn dome
i could do that
hasty mist
Indeed
final saddleBOT
hasty mist
diamond$left lbrace , frac12 + n ,middle|, n in mbb Z ,right rbrace$
soft zealotBOT
Sean [Ping On Reply Please!]
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
クーリー
torn dome
why is yours with that theme
trail mango
he’s just so cool
torn dome
indeed
hasty mist
,texroyalgold \TeX it premium for but $89.99 a month!
soft zealotBOT
クーリー
torn dome
I'm good 💀
hasty mist
Too bad
torn dome
pure needs to pay his bills
is the texit a owner a member here
final saddleBOT
Available help channel!
vocal sonnet
ive done part a but part b is where im stuck. I think the solution lies in proving that C or B is 90deg. and the hint says that HBYC is a paralellogram, backing my theory.
final saddleBOT
ive done part a but part b is where im stuck. I think the solution lies in provi...
arctic sand
ive done part a but part b is where im stuck. I think the solution lies in provi...
You can prove BH//CY and ur done
Call the midpoint of HY I then I is the midpoint of BC and therefore HBYC is a paralellogram
vocal sonnet
Call the midpoint of HY I then I is the midpoint of BC and therefore HBYC is a p...
i thought i had to prove HBYC was a rectangle and then use inscribed angle theorem, im so confused
arctic sand
i thought i had to prove HBYC was a rectangle and then use inscribed angle theor...
You can prove triangle HIB equals triangle YIC
Instead to avoid confusion
vocal sonnet
Instead to avoid confusion
im already confused
arctic sand
im already confused
Umm but at least you know the solution now right? 😄
vocal sonnet
Call the midpoint of HY I then I is the midpoint of BC and therefore HBYC is a p...
oh are u trying to prove its a paralellogram? thats already been concluded by the diagonals. the question says to prove ay is a diameter of the circle. so by the inscribed angle theorem that means that triangle acy/aby will be right. which is what im confused on
arctic sand
oh are u trying to prove its a paralellogram? thats already been concluded by th...
Ye AC will be perpendicular to CY bc CY is paralell to BH which is perpendicular to AC making AY the diameter bc of Thales thereom or inscribed angle or sth i dont really remember
Or i found another way to prove this, BC will ve paralell to XY so AX is perpendicular to XY and so on
vocal sonnet
Ye AC will be perpendicular to CY bc CY is paralell to BH which is perpendicular...
ohhh, that makes sense:)
arctic sand
ohhh, that makes sense:)
Thankd
slow maple
Can someone help me with this question?
final saddleBOT
Can someone help me with this question?
pulsar axle
!status
final saddleBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
slow maple
the derivative
slow maple
yeah
thorny canyon
so what do you get when you differentiate that?
slow maple
(-sint, cost, 1)
thorny canyon
Can someone help me with this question?
the point here is at a particular value for t
so plugging that in will give you the tangent vector at the point
geometrically, it tells you in which direction you must travel as you move along the curve
with me so far?
slow maple
I see. So for x(t) we would have smt like (-1/2, -sqrt3/2, 1) since we would differentiate t=5pi/6
is that right?
thorny canyon
that's right
slow maple
do you know why it's wrong?
slow maple
im not sure if i have to write in a specific format or smt
thorny canyon
you could write -sqrt3/2 as cos(5pi/6) and such
but that's redundant
your answer is correct
slow maple
I got it
I was wondering if you would mind if i ever reach out to you for help through dms. i find it much more helpful to work in dms but if u dont provide help through dms i understand
thorny canyon
I was wondering if you would mind if i ever reach out to you for help through dm...
personally, I'm ok with that
slow maple
awesome ty. im gonna study for the next couple hours on this stuff and ill only reach out of i really need help bc i dont wanna annoy u lol
thorny canyon
yup yup sure
final saddleBOT
final saddleBOT
Available help channel!
solid patrol
can someone help me understand branch cuts
final saddleBOT
can someone help me understand branch cuts
solid patrol
i've solved this integral
gotten pi/2, which should be the answer
but i dont really understand the method
we want to avoid the multivalued problem adding 2pi since it adds at (-1)
I dont understand how the fact I've made a keyhole contour changes anything
I am literally still going around the circle i've just decided to go an abitrary distance to the left before completing the rotation
obtuse hedge
<@&268886789983436800>
final saddleBOT
@solid patrol Has your question been resolved?
lilac moat
I dont understand how the fact I've made a keyhole contour changes anything
because there is a branch cut on the positive real axis
You should've gotten two different values for your two line integrals above and below the real axis anyways, so it does change things. The "arbitary distance to the left" you mention is because we wish to not cross the branch cut, which is the point of a keyhole contour
In case you don't know where the branch cut comes from, $$\frac{1}{\sqrt{z}\left(z+4\right)}=\frac{z^{-\frac{1}{2}}}{z+4}=\frac{e^{-\frac{1}{2}\operatorname{Log}\left(z\right)}}{z+4}$$
soft zealotBOT
Roy
final saddleBOT
@solid patrol Has your question been resolved?
scenic nest
What would be the simplest form of projection with a spherical geometry 4 dimensions+ where any direction only goes in a straight circle back to start, there are no spirals? Not urgent but anyone?
final saddleBOT
What would be the simplest form of projection with a spherical geometry 4 dimens...
scenic nest
Like view at point to plane in spherical 3d like stuff?
Maybe let's start with given a point on circle and a direction 2d, what is the results equation for after a distance?
Sum(coordinates squared)=constant squared. X E.
tepid ridge
Try to ping helpers for help
scenic nest
Why? I don't want to bother people. X E.
thin sequoia
What would be the simplest form of projection with a spherical geometry 4 dimens...
you want specifically spherical? then just like a 5D sphere's surface
otherwise, a few more object fit the description
like something toroidal
scenic nest
<:pandathink:524885344995508235> you want specifically spherical? then just lik...
Yes. X E
But any dimensional. X E.
thin sequoia
then take 'any dimensional'-sphere
scenic nest
I know how that works. X E.
thin sequoia
note: 3D' sphere's surface gets you 2D space, so you want a (n+1)-D sphere's surface to get the n- dimensional space
scenic nest
Maybe N rotations. X E.
Or N+1 coordinates. X E.
Any one point can be said to be using only N rotations. X E.
Should I just test this?
I have had luck with that. X E.
Okay. X E.
Well, more DM. .close X E.
.close X E.
warm python
Hi, so I've written some code for the bisection method, would like some help understanding the errors thrown at me
import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
import math as m
print("Please enter your function as a function of the variable 'x'")
f=input("Enter your function\n")
f=sp.simplify(f)
print("The function you input has been registered as:", f)
print("Please enter the interval over which you'd like to find roots, along with the error as prompted ")
a=input("Enter the lower bound of the interval\n")
a=sp.simplify(a)
b=input("Enter the upper bound of the interval\n")
b=sp.simplify(b)
print("The lower bound has been registered as:",a,"\nThe upper bound has been registered as",b)
print("Please enter the error upto which you want the root")
e=input("enter the error\n")
e=sp.simplify(e)
#n is the number of iterations to be performed
n=sp.ceiling(sp.log(((b-a)/e),2))
print("The number of iterations used will be :",n)
#m will be used to denote the mid point
m=(a+ b)/2
for i in range(n):
if(f.subs(x,a)>0 and f.subs((a+b)/2)>0):
a=a
b=m
elif((f.subs(x,b)>0 and f.subs((a+b)/2>0))or (f.subs(x,b)<0 and f.subs((a+b)/2<0))):
a=m
b=b
print("The solution is",m,"upto an error of",e)
And this is the error I get :
ValueError:
When a single argument is passed to subs it should be a dictionary of
old: new pairs or an iterable of (old, new) tuples.
what does this error mean and how do I fix it
obtuse hedge
Oh you did say you wanted to try sympy
And of course I'm not familiar
Let's see it looks like you passed it
Ah
Is it the fact that you didn't write it as a tuple
i.e. f.subs(x: b) (old: new pair) or f.subs((x,b))
warm python
wait, so what did I do wrong?
obtuse hedge
Let me run it before I say anything
But if I'm right it's just that you wrote f.subs(x,b) instead of f.subs((x,b))
warm python
uh, I did make one math mistake
justa. min
import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
import math as m
print("Please enter your function as a function of the variable 'x'")
f=input("Enter your function\n")
f=sp.simplify(f)
print("The function you input has been registered as:", f)
print("Please enter the interval over which you'd like to find roots, along with the error as prompted ")
a=input("Enter the lower bound of the interval\n")
a=sp.simplify(a)
b=input("Enter the upper bound of the interval\n")
b=sp.simplify(b)
print("The lower bound has been registered as:",a,"\nThe upper bound has been registered as",b)
print("Please enter the error upto which you want the root")
e=input("enter the error\n")
e=sp.simplify(e)
#n is the number of iterations to be performed
n=sp.ceiling(sp.log(((b-a)/e),2))
print("The number of iterations used will be :",n)
#m will be used to denote the mid point
m=(a+ b)/2
for i in range(n):
if(f.subs(x,a)>0 and f.subs((a+b)/2)>0 or (f.subs(x,a)<0 and f.subs((a+b)/2)<0 )):
a=a
b=m
elif((f.subs(x,b)>0 and f.subs((a+b)/2>0))or (f.subs(x,b)<0 and f.subs((a+b)/2<0))):
a=m
b=b
print("The solution is",m,"upto an error of",e)
Oh yeah I didn't check any of the math jfyi
obtuse hedge
Oh I see a little syntax thing though
warm python
seems to work now
plucky rover
What editor are you using
obtuse hedge
Anyway I fixed it as well XD
warm python
What editor are you using
colab
obtuse hedge
for i in range(n):
if(f.subs('x',a)>0 and f.subs('x',(a+b)/2)>0):
a=a
b=m
elif((f.subs('x',b)>0 and f.subs('x',(a+b)/2)>0)or (f.subs('x',b)<0 and f.subs('x',(a+b)/2<0))):
a=m
b=b
This changed fixed it for me
I recognized it once it said variable x is not defined
And I'm like why is x a variable
ah, it should be a string to substitute
plucky rover
Idk what colab is
But vs code would show brackets in different colours
And that's helpful to notice these
obtuse hedge
Colab does as well
plucky rover
Cool then
warm python
Move to pycharm or vscode.. colab is so badd
I tried vscode
I couldn't set up sympy 🥀
warm python
Colab does as well
TYSM for the help!
obtuse hedge
I like colab just fine
obtuse hedge
TYSM for the help!
Wait I'm just going to submit my suggestions for readability
worldly mesa
I tried vscode
Pycharm is another option
warm python
Pycharm is another option
works on mac>
obtuse hedge
More could be done but I think these changes are minimal
import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
import math as m
print("Please enter your function as a function of the variable 'x'")
f = input("Enter your function\n")
f = sp.simplify(f)
print()
print("The function you input has been registered as:", f)
print("Please enter the interval over which you'd like to find roots, along with the error as prompted ")
a = input("Enter the lower bound of the interval\n")
a = sp.simplify(a)
b = input("Enter the upper bound of the interval\n")
b = sp.simplify(b)
print()
print("The lower bound has been registered as:", a)
print("The upper bound has been registered as", b)
print("Please enter the error upto which you want the root")
e = input("enter the error\n")
e = sp.simplify(e)
#n is the number of iterations to be performed
n = sp.ceiling(sp.log((b-a)/e, 2))
print("The number of iterations used will be :",n)
#m will be used to denote the mid point
m = (a + b)/2
for i in range(n):
if f.subs('x', a) > 0 and f.subs('x', (a+b)/2) > 0:
a=a
b=m
else:
a=m
b=b
print()
print("The solution is",m,"upto an error of",e)
Yep pycharm is what I use on my mac
warm python
cool, I'll get it then
obtuse hedge
Downloaded it for my ML class (after taking a DS class that used colab 😂)
So now I just use colab mostly and pycharm every once in a while
warm python
More could be done but I think these changes are minimal
```py
import sympy as s...
I think import math as m and then using it as a variable might cause issues, no?
obtuse hedge
Oh right import math isn't used at all I don't think
obtuse hedge
I think import math as m and then using it as a variable might cause issues, no?
And no it ran fine for me
obtuse hedge
Oh right import math isn't used at all I don't think
Unless it's required for some of the inner workings of sympy
Which I know sqrt is based on math and such
But yeah usually you just import math
And write math.whatever
obtuse hedge
And no it ran fine for me
But if you tried to use m.sqrt for example it would have been overwritten
If that's what you mean
warm python
Uh there's a slight issue.
The code indicates a soln exists even if one doesn't. I guess there's no simple way around that right
obtuse hedge
So yes 'issues' in the sense that you won't be able to math anything later
obtuse hedge
Uh there's a slight issue.
The code indicates a soln exists even if one doesn'...
Technically this should just cause the interval never to converge right?
So you just add in an extra line
if sign a = 1 and sign b = 1 and sign m = 1 or they're all negative print no solution
Or that the interval chosn was bad
obtuse hedge
Because that can only happen if there are an even number of solutions or no solution by IVT
obtuse hedge
I do suppose I have to import log
Log worked fine for me, I think math might be inside of sympy
warm python
I don't think this works for very precise clac though
heck it's wrong I think 🥀
Please enter your function as a function of the variable 'x'
Enter your function
x^3+5
The function you input has been registered as: x**3 + 5
Please enter the interval over which you'd like to find roots, along with the error as prompted
Enter the lower bound of the interval
-3
Enter the upper bound of the interval
3
The lower bound has been registered as: -3
The upper bound has been registered as 3
Please enter the error upto which you want the root
enter the error
0.2
The number of iterations used will be : 5
The solution is 0 upto an error of 0.200000000000000
oops
Well this is wrong
Please enter your function as a function of the variable 'x'
Enter your function
x3+5
The function you input has been registered as: x3 + 5
Please enter the interval over which you'd like to find roots, along with the error as prompted
Enter the lower bound of the interval
-3
Enter the upper bound of the interval
3
The lower bound has been registered as: -3
The upper bound has been registered as 3
Please enter the error upto which you want the root
enter the error
0.2
The number of iterations used will be : 5
The solution is 0 upto an error of 0.200000000000000
oops, looks like I never update m either , right
tired walrus
your condition for updating the thing is kinda fucked too
obtuse hedge
Time to put in print statements and investigate, like I said I never actually checked the math
warm python
your condition for updating the thing is kinda fucked too
that should be moved into the loop, right
obtuse hedge
that should be moved into the loop, right
Ah haha now I see that
Yes
I mean the updating m
Should be in the loop
I wonder how in the world it was finding the answer before then
warm python
for liner equations one midpoint worked well enough
obtuse hedge
Not that that's correct either but still
I see now
if statements flipped
Of course if both are > 0 we don't want to bring it in the range of no zeros
obtuse hedge
There we go
obtuse hedge
I don't follow
If f(a) > 0 and f(m) > 0, does the interval become [a,m] or [m,b]
warm python
[m,b]
warm python
I think the entire code is wrong
obtuse hedge
Ah right because this function is increasing the conditions are backwards
obtuse hedge
Yeah the rest is fine
Actually all that needs to change is it should become f(a) and f(m) same sign -> [m,b]
Because if it's increasing, f(a) < 0 and f(m) < 0 we undershot, [m,b]
If it's decreasing, f(a) > 0 and f(m) > 0 we overshot, [m,b]
I think all you're doing is increasing functions though because your method didn't include both
obtuse hedge
Yep and that cahnge did fix it
obtuse hedge
lemme fix it
My code for comparison once you finish
import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
import math as m
print("Please enter your function as a function of the variable 'x'")
f = input("Enter your function\n")
f = sp.simplify(f)
print()
print("The function you input has been registered as:", f)
print("Please enter the interval over which you'd like to find roots, along with the error as prompted ")
a = input("Enter the lower bound of the interval\n")
a = sp.simplify(a)
b = input("Enter the upper bound of the interval\n")
b = sp.simplify(b)
print()
print("The lower bound has been registered as:", a)
print("The upper bound has been registered as", b)
print("Please enter the error upto which you want the root")
e = input("enter the error\n")
e = sp.simplify(e)
#n is the number of iterations to be performed
n = sp.ceiling(sp.log((b-a)/e, 2))
print(f"The number of iterations used will be: {n}".rstrip("0"))
#m will be used to denote the mid point
for i in range(n):
m = (a + b)/2
if f.subs('x', a) < 0 and f.subs('x', m) < 0: a=m
else: b=m
print()
print(f"The solution is {m}".rstrip("0"), f" upto an error of {e}".rstrip("0"))
okay, that's kind of simple and neat
thanks!
obtuse hedge
Do you love coding now 😊
obtuse hedge
np 🙂
warm python
.close
restive sinew
final saddleBOT
storm haven
1/1000(a^2-b^2)/(1/10)(a-b)
well a^2-b^2 = (a-b) • (a+b)
final saddleBOT
final saddleBOT
Available help channel!
warm python
here I basically have to find the interval it goes to?
final saddleBOT
here I basically have to find the interval it goes to?
warm python
or the exact root
tired walrus
you have to simulate the bisection method yourself
whole halo
it names a root, so it wants the root that the method would yield
tired walrus
until your interval narrows down to one that contains only a single odd multiple of pi/2
then return that root
it may in fact be prudent to try and find the roots of cos(pi x/2) on [0, 130/pi] in this way
warm python
it may in fact be prudent to try and find the roots of cos(pi x/2) on [0, 130/pi...
wait, I don't get this
on [0, 130/π]?
tired walrus
that right end is 65*2/pi
all im doing that for is to make the roots into odd integers
obtuse hedge
That's a nice transformation 🤯
I also realize this bisection method is like binary search method but for a metric space 😆 how interesting
final saddleBOT
final saddleBOT
Available help channel!
lusty osprey
final saddleBOT
obtuse hedge
,rccw
lusty osprey
So uhh, I dont know how to solve this…
soft zealotBOT
obtuse hedge
Oh lord it's an integer problem
lusty osprey
Yep
obtuse hedge
So uhh, I dont know how to solve this…
Rest assured, there are a lot of integer experts in the server (just not me), they will surely be able to help!
lusty osprey
I suck at this kind of math
silver dew
First of all you can assume x,y are rationals
hasty mist
diamond$x^4 + 2x^3 + 2x^2 + x + 3 = (x^2+x)^2 + (x^2 + x + 3)$
soft zealotBOT
クーリー
hasty mist
Quadratic moment
silver dew
Since f(x,y) is primitive, the y^2-x^4-… thing
hasty mist
Well
you have
diamond$y^2 = t^2 + t +3 <=> 4y^2 = 4t^2 + 4t + 12$
Complete the square
lusty osprey
And… I suppose to find y^2 < (x^2 + x+2)^2?
silver dew
x^4+2x^3+2x^2+x=(x^2+x)^2+(x^2+x)
soft zealotBOT
クーリー
silver dew
y^2-(x^2+x+1/2)^2=11/4 can be solved over rationals. Rational solutions will lead you to integer solutions
lusty osprey
Um
silver dew
y^2-(x^2+x+1/2)^2=11/4 can be solved over rationals. Rational solutions will lea...
This thing multiplied by 4 is what クーリー is saying
lusty osprey
I dont know abt ts
silver dew
-11 I think
hasty mist
Ah yes
soft zealotBOT
クーリー
lusty osprey
The answer is (1,3) (1,-3)(-2;3)(-2;3)
hasty mist
I dont know abt ts
Use difference of two squares
silver dew
The answer is (1,3) (1,-3)(-2;3)(-2;3)
Yes
silver dew
=11, 1 or 1, 11 or -1, -11 or -11, -1 type of argument
hasty mist
What’s wrong with this way?
lusty osprey
0_0
soft zealotBOT
soft zealotBOT
hasty mist
only -1,0,1
final saddleBOT
lusty osprey
I think its right though
final saddleBOT
Available help channel!
vale vigil
would a line be able to be depicted with an equation in 3 dimensional space at all?
final saddleBOT
would a line be able to be depicted with an equation in 3 dimensional space at a...
onyx peak
would a line be able to be depicted with an equation in 3 dimensional space at a...
You can use 2 equations
y = 0, z = 0 gives a line (namely the x-axis)
left echo
would a line be able to be depicted with an equation in 3 dimensional space at a...
Yes, you can use a parameter, or an equation like A = B = C
valid carbon
would a line be able to be depicted with an equation in 3 dimensional space at a...
vectors.
hasty mist
Blud thinks he can command us
valid carbon
fuucckinggg shit 
im not gonna allow myself to get completely side tracked today and do fucking work
but might check in between because pure shitshow
have a picture of a cute bear for palate cleanser
digital sable
have a picture of a cute bear for palate cleanser
yo that’s me
did you see the name of the bear
valid carbon
,av wojcjech
soft zealotBOT
soft zealotBOT
digital sable
:)
vale vigil
would a line be able to be depicted with an equation in 3 dimensional space at a...
So, the general idea is that; if I wanted to say an equation, like y = mx + b, then in 3 dimensional space I have a different need to specify the directions of each of those axis. There are infinite directions, and you would need to define y axis and x axis ( I am pretty sure you are only supposed to define the direction of these two, for me personally.. Z direction is far more different but hey!)
Let us suppose that, the directions you are defining for x and y, are to be given in an equation y = mx + b (what else are you giving here mister? are u gonna do u some bullshit like draw line from a to b I give u their co ordinates, that's x axis one dimension, but hey! u need to define a line indefinitely which,I don't think ur gonna achieve without a y = mx + b)
vale vigil
So, the general idea is that; if I wanted to say an equation, like y = mx + b, t...
but to give an equation of direction x in terms of a line
you would have to define x and y axis directions for that line as well
since we did not jump back into 2d
We are still in 3d and direction matters a lot more and a lot more peculiarly
vale vigil
you would have to define x and y axis directions for that line as well
and if u see the pattern here
you would realize, it is impossible to define a direction, indirectly because, impossible to define a line in 3d space with an equation
vale vigil
I do know what these vectors are, they are NOT enough to be able to be considered as a line with equation in 3d space
digital sable
you guys got destroyed… put some respect on his name
left echo
Is your problem just the way we define a third dimension?
onyx peak
is your problem that we have to arbitrarily place x and y axis (there are infinitely many possibilities) or what?
vale vigil
is your problem that we have to arbitrarily place x and y axis (there are infini...
no, I don't care if I take x to North or south (just for visual purposes, there's no North or south here absolutely)
vale vigil
Is your problem just the way we define a third dimension?
no
it is that, a y = mx + b, or indirectly, an equation for a line, is impossible to depict
in 3 dimension space
blissful ore
Oh but a line can be defined in 3D with one point and one direction vector you don’t need to redefine x-,y-, and z-axes for each line. 
unless I’m misunderstanding your point
warped hollow
cant you do something like
x=y=z is a line
candid pulsar
it is that, a y = mx + b, or indirectly, an equation for a line, is impossible t...
if you use a single equality sign
then yes
onyx peak
this is x = y = z, once you place the axes, the line is completely determined
candid pulsar
yeah..
vale vigil
Oh but a line can be defined in 3D with one point and one direction vector you d...
oh, have u believed direction vectors so easily now? u run into the same problems with defining the axis for which the vector runs through, if u don't define the axises with direction and say some things like, HELLO MY LITTLE FRIENDS; WE ARE TAKING 2 POINTS AND DRAWING CHALK IN BETWEEN THEM, therefore we are obliged to pick another point and check if it's in that line cause my exam teacher said so, if it's not we take that as a basis vector from our first point, etc.. We get 3 basis vectors
vale vigil
oh, have u believed direction vectors so easily now? u run into the same problem...
but over here
u do get a good, legible
co ordinate system
the problem is just that you can't locate or depict it in numbers
onyx peak
oh, have u believed direction vectors so easily now? u run into the same problem...
So your problem actually is with placing the axes? Or what is it?
vale vigil
the problem is just that you can't locate or depict it in numbers
u can't locate where it is
it will be algebraic
valid carbon
I do know what these vectors are, they are NOT enough to be able to be considere...
uh huh
why not
digital sable
bro you’re not even at uni yet, it’s too early to become a crank
vale vigil
and u will have ur answer
valid carbon
you would realize, it is impossible to define a direction, indirectly because, i...
GODDAMNIT
ISNT THIS
THE SAME THING
AGAIN
FFS
candid pulsar
its all connected
vale vigil
bro you’re not even at uni yet, it’s too early to become a crank
is that the most of your concerns?
digital sable
yes
vale vigil
I understood how you would make a co ordinate systsem
before in our previous conversation
silver dew
p a point, v a vector, q is (x,y,z)
((q-p) cross product v)•((q-p) cross product v)=0. One single equation, that defines a line
vale vigil
Without having to define these directions
vale vigil
but I DID NOT UNDERSTAND how to make a computable, locatable, non algebraic co ordinate system
that doesn't put an object at x, y, z where we don't know what x, y, z are
plucky rover
Define locatable
blissful ore
oh, have u believed direction vectors so easily now? u run into the same problem...
what I mean is once a coordinate system is fixed once, vectors don’t need their own axes. A direction vector is defined relative to the existing basis that’s the whole point of coordinates. I’m not sure about the chalk metaphysics talk though 😭😭
onyx peak
but I DID NOT UNDERSTAND how to make a computable, locatable, non algebraic co o...
Once we place the axes, it's obvious where (x,y,z) = (1,2,3) is gonna be, isnt it?
So your problem is with placing the axes?
vale vigil
Define locatable
locatable as in getting the co ordinates as to number, and knowing where it is (I'm sure knowing where it is is more mathematically conveyable to you if I show u some drawings rn)
plucky rover
Those are all in fact words
valid carbon
Those are all in fact words
that exist, even
vale vigil
one sec
plucky rover
<@&268886789983436800> I'm 100% sure this is a troll, your call now
onyx peak
wait i wanna see the pics
tired walrus
"There are infinitely many possible coordinate systems that can be introduced on 3 dimensional space, but there is no objective way to pick out one as the True one. This upsets me ontologically."
this is all i hear
vale vigil
digital sable
Xavier’s small brain cannot comprehend true mathematics… might be cooked
onyx peak
Anyway, here is something to think about, the same thing is true in 2D. There are many ways to place the axes
vale vigil
onyx peak
Does that make 2D also wrong?
valid carbon
Guys I have an equation that has the potential to impact the future
blissful ore
These are certainly drawings 😭
valid carbon
(a, b, c)x + AI
onyx peak
Yeah, now that you have the axes lines, you need to label them with x, y, z and place some units on them
vale vigil
Does that make 2D also wrong?
I haven't argued about 2d yet, and if u wanna provide me a valid argument, u should give the proof to the correct question instead of guilt tripping me "IS OUR MATHS WRONG IN 2D ALSO THEN"
vale vigil
@plucky rover So
onyx peak
I was trying to reduce it to something simpler, but sure, lets stay in 3D
vale vigil
I showed u 2 different pictures
hushed sequoia
What's the matter?
plucky rover
What's the matter?
I was 90% sure this is a troll, after seeing the drawings I'm a 100% sure now
atomic moon
Just ignore ig
clear moon
i like your drawings bro i get it now
onyx peak
its not like the drawings are worse than mine
valid carbon
im still only 90% sure
clear moon
i like your drawings bro i get it now
it's all a matter of perspective, axes and coordinates don't exist
hushed sequoia
HereC, you already made some silly help channels yesterday, do you have genuine questions?
digital sable
What's the matter?
this guy is a bit cranky and everyone gathered for entertainment value
vale vigil
What's the matter?
there's so many people talking at once, when I wanna reply to one person another barges in saying something totally different before giving me time to reply, then the original person who I wanted to reply to would mis understand everything and then I wouldn't be able to reply to anyone at all
valid carbon
this guy is a bit cranky and everyone gathered for entertainment value
about true
hushed sequoia
There are too many people in this help channel indeed; if you don't plan on helping, don't fuel this and just watch ig 
vale vigil
If y'all can please let me talk in peace and have patience if u wanna say something
here I go
steep hatch
God gave y’all the block button for a reason, use it
vale vigil
vale vigil
here I've showed you 2 representations
there's the same object
and here comes the problem if u don't define the direction of the axises
vale vigil
and here comes the problem if u don't define the direction of the axises
indirectly, even if u give the co ordinates literally and say "it doesn't matter which direction axises are, it's located like right there
these both pictures WOULD be the same
with the mathematical formulation that u did
but hey here's the twist
to any observer, (other than the object's pov itself (that too when no other object exists at all))
this would not be the same
that is why I argue heavily
towards a direction of the axises
because in 3d space, even if u give the co ordinates or vectors
u can literally get many points, infinite infact
by just twisting and keeping the axises wherver u want
the centre can be the same****
keep this in mind
and now reply me
onyx peak
towards a direction of the axises
Jsyk, we work with directed axes for this reason
vale vigil
Jsyk, we work with directed axes for this reason
wait u do?
like u
u u
u say that
that
onyx peak
indeed
vale vigil
OMG YOU DO!?
onyx peak
look at this, there are the arrows for this exact reason
vale vigil
indeed
what if I twist the axieses and keep x in the place of y where
and do the same for others linearly
in 3d space it would be the same
do u have like an actual direction?
onyx peak
twist them how?
vale vigil
twist them how?
well I'm not too sure how I'm gonna explain u this, but please don't be annoyed if this picture troubles u
clear moon
that doesn't tell me the direction
my guy they're pointing in the direction. obviously if you rotate your directions, your directions change
vale vigil
onyx peak
Now this is a POV of another observer, you are looking at the same thing from a different angle
vale vigil
here's the thing okay
candid pulsar
ok so you mean to say that
if i have a space and a marked coordinate system, and i mark a point (1, 1, 1)
now if i change the basis vectors (that is, the x, y and z axes) and then find the "new" position of the point, you seem to get a new and "wrong" coordinate for the same point
so you say that the coordinate of the point is impossible to find
clear moon
hey quick question, when you turn your head 90 degrees, does the object you're looking at fundamentally change
vale vigil
Now this is a POV of another observer, you are looking at the same thing from a ...
that is
really
absurd on your behalf, let me just show u why
clear moon
like if you have an apple in front of you, the apple exists. you can superimpose any cooridnate system if for some reason you want to identify locations on the apple, and you can define anything as your directions and axes, but regardless of what you picked, the apple is still kind of just there
you can walk circles around the apple and rotate your head and stuff but like
it's an apple
vale vigil
This right here, is 1,1,1 for a specific direction of axises x, y, z
we don't know what that direction is
cool? so we don't know what that direction is
lemme show u another pic
vale vigil
this right here is a different point
(I know it kinda looks in the same place, but pls believe me it's at a different place, it aligning to the previous picture was a co incidence)
vale vigil
this right here is a different point
but, it is 1,1,1
for x, y and z axis defined in that direction
now when you defined a co ordinate, with a centre
but u forget to define which direction each axis should go towards
THIS is what happens
vale vigil
Now this is a POV of another observer, you are looking at the same thing from a ...
and, u can argue this; this is a pov from another observer
that is a pretty decent argument, I agree
vale vigil
but it's IMPOSSIBLE for u to "correct" This different pov