#help-36

1 messages · Page 199 of 1

mortal shoal
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are u going on strike?

tranquil pine
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First lets close this chat.

mortal shoal
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Ok, can iadd u?

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Thx alot

gleaming anchor
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!done, as a reminder.

final saddleBOT
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final saddleBOT
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versed crater
#

post your question first

ocean raven
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but if i post it and you dont know how to solve it the timer is gonna run out

versed crater
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you can extend the timer by telling the bot your question isn't solved yet

ocean raven
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wym

versed crater
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there is no timer

ocean raven
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this is my school assingmnet

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and it has a timer

versed crater
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is it graded?

ocean raven
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yea

versed crater
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we cant help with graded assignments, that violates academic integrity

ocean raven
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wym by graded

maiden vessel
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U want us to provide you with the answers?

ocean raven
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no

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wdym by graded tho

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its hw

versed crater
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it wouldn't otherwise make sense that it is timed

ocean raven
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wait u guys dont help w hw

final saddleBOT
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versed crater
ocean raven
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ok

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i just needed help

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not cheating

final saddleBOT
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tranquil pine
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yoo

final saddleBOT
tranquil pine
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my question is for the equation of the generating curve (the radius) how do you know which plane thats on

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for example how do i know that r(z) = y and not r(z) = x

formal trail
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well r(z) should only depend on z, shouldn't it

tranquil pine
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but whats the output

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could be either y or x

formal trail
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neither?

tranquil pine
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wdym

formal trail
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we aren't doing r(z) = x or r(z) = y

tranquil pine
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wait what

formal trail
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we are doing x^2 + y^2 = [r(z)]^2

tranquil pine
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yes but bro

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whats r(z)

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its gonna be some output

formal trail
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it's the radius of the surface at a given z

tranquil pine
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yes but that radius is represented by an output value of the radius function

formal trail
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yeah and we aren't graphing that output value, we're graphing an equation related to the output value

tranquil pine
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wait

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its squared

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so even when from the other direction

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itll be the same

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is that why

formal trail
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i'm not sure what you mean

tranquil pine
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but even then

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the generating curve has to be on a particular plane

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if my generating curve was in the yz plane then my radius would be z

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if it was on the xy plane my radius would be x

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so idk

formal trail
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the intersection of the surface of revolution with any plane containing the axis of revolution gives a generating curve. it doesn't matter which plane because they all give the same curve, just rotated

formal trail
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it just says "an" equation of "a" generating curve

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you can pick any of them

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also you should take the square root to find r(z)

tranquil pine
formal trail
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well its what you have in the bottom right

tranquil pine
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yea

formal trail
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although it should say r(z) =

tranquil pine
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im undoing the square

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Oh yea mistake

tranquil pine
formal trail
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practice

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it's not easy but you get there eventually

tranquil pine
# formal trail practice

would you say someone needs to practice since they were a kid to get to that level or you could manage that within a couple years later along the line? No

formal trail
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not really, you can get there eventually

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we should also note that this is math that i learned years ago and have been continuing to practice since then by helping people out with it. so i'm much better at it now then i was when i was learning it, and i'm better at it than the stuff i'm learning currently

final saddleBOT
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chrome hemlock
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induced emf = rate of change of flux linkage

chrome hemlock
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how do they know its like the yellow one

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and not the blue one

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oh

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its negative derivative

dusky gull
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isnt induced emf = negative rate of change

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yeah

chrome hemlock
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nevermind

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ohhh

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.close

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rain sentinel
final saddleBOT
rain sentinel
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im abit confused about part 3b

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shouldnt tha area for A1 be [....]-2 and -4

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not -2 and 4

willow tiger
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You need to figure out when is y positive

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then substract the integral of the part between -4 and 4 where y is positive with the integral of the part between -4 and 4 where y is negative

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you understand?

rain sentinel
willow tiger
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no because when x is negative, the integral is negative

rain sentinel
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so changing it to positive

willow tiger
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yea but thats just = to what i said

rain sentinel
rain sentinel
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or should it be this instead

willow tiger
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huh

rain sentinel
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im trying to figure out all 3 areas

willow tiger
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yea

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it should be (-4,-2)-(-2,3)+(3,4)

rain sentinel
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so

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Is this how I calculate area 1 then

willow tiger
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yea

rain sentinel
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so the answer to the question is 36.333

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gleaming anchor
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you seem to consider that 6 is the only outcome of your d20

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sure, but then if you know in advance that you're gonna keep rolling 6s, then I guess your strategy works.

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but that's if you are 100% certain you are going to roll nothing but 6s

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oh hm

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that's fair. I think that this strat works with high remaining roll count

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but I remember seeing this exact problem from you and a couple of helpers have given you a good strat as to when to cash out.

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I think you can use the general solution to find your specific case, is that not?

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I see

scarlet sequoia
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if you cash out do you have to reroll on the next round?

final saddleBOT
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@vital kelp Has your question been resolved?

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@vital kelp Has your question been resolved?

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rain sentinel
final saddleBOT
rain sentinel
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is the part in red wrong?

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shouldn't it be x^2(1/x)

severe canyon
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First of all, the dx is missing everywhere

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And that's the first mistake 😬

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Second, yes how did the x² turn into just x?

scenic walrus
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yep

rain sentinel
scenic walrus
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$x^2\left(\frac{1}{x}\right)dx=xdx$

soft zealotBOT
rain sentinel
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also how do i know whether to use IBP or IBS?

severe canyon
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Experience, mainly

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And sometimes you can/have to try both

rain sentinel
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so its not like differentiation where the chain rule is used for composite functions?

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and that is like IBS

scenic walrus
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DI method by bprp

scenic walrus
rain sentinel
scenic walrus
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!done

final saddleBOT
#

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scenic walrus
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there’s no chain rule for integration

severe canyon
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Substitution (usually) works well if you have the derivative of some part of the integrand multiplied with the integrand itself

scenic walrus
rain sentinel
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thanks

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.close

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tawny bridge
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Ok theres some stuff here I need clarified

final saddleBOT
tawny bridge
honest carbon
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Where is the question?

tawny bridge
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Im Just trying to understand this concept

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Well

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This concept

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In that idk what they mean by the word "concept" here

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All I've understood so far is that under PAC, we only need the learner be such that it chooses a hypothesis which with high probability gets a low enough loss

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As opposed to exact framework where the loss is expected to be 0, and hypothesis is chosen with a 100% probability

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Also is this class of algos

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Something which is tunable with epsilon and delta params?

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(i.e., the accuracy and confidence parameters)

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<@&286206848099549185>

hot hornet
tawny bridge
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I see

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So in here, in the latter part

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What's example count

hot hornet
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i'm not actually sure..

tawny bridge
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This si the wikipedia artikel im looking at

final saddleBOT
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@tawny bridge Has your question been resolved?

tawny bridge
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No

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🙁

final saddleBOT
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@tawny bridge Has your question been resolved?

tawny bridge
tawny bridge
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Is ts like an fptas

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<@&286206848099549185>

tawny bridge
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Anyone?

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<@&286206848099549185>

final saddleBOT
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tranquil pine
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can someone solve 11 where the limit is in the form of x^m - a^m / x^n - a^n ?

opal plinth
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You can factorize the numerator and the denominator

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It's a little difficult but the limit gives you a big hint

tranquil pine
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Im not sure whats wrong

faint locust
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If you have it available, you can L'Hopital it

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If not, yeah, factor

tranquil pine
faint locust
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Do you know polynomial long division?

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/synthetic division for polynomials

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/Horner's method

tranquil pine
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not that one either

tranquil pine
opal plinth
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I'm not sure about your teacher's method, and I might be overcomplicating this, but if you know a root r of a polynomial P(x), you can rewrite it as (x - r)(Q(x)) where Q(x) is one degree lower than P(x)

floral bronze
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hi

tranquil pine
#

.close

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rain sentinel
final saddleBOT
rain sentinel
#

how do i know there are vertical and horzontal forces at A?

final saddleBOT
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@rain sentinel Has your question been resolved?

formal trail
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pins always have horizontal and vertical reactions

rain sentinel
glossy zephyr
rain sentinel
glossy zephyr
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Well, theres a neat rule about torque, its that its the same everywhere, for this case, considering that the piece is static and not rotating, its 0

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It makes it pretty easy to find the perpendicular components of most parts

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Suppose we use the point C as reference, we know that the torque caused by vertical component of reaction A is equal and opposite to the force in B.

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You can do the same from A, considereding the vertical component of the strut force

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From there, you can find both the horizontal of the strut, and the horizontal of the reaction

glossy zephyr
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Do you know how projections of forces using cosine and sine works?

glossy zephyr
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On a different but similar example.
Lets say I apply a force at an angle you know of, would you be able to tell me the vertical and horizontal components?

glossy zephyr
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But i dont tell you those

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Just the angle and the amount of the force

rain sentinel
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yh

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i have to draw on the axis

glossy zephyr
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Well, yeah, but theres a formula for it

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For this situation, imagine i gave you the Value of "F" and the angle "α"

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You could find the vertical components anyways.

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Fx = F . cos(α)
Fy = F . sin(α)

rain sentinel
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yes ik this

glossy zephyr
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Well, you can also do it the other way around

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Fy / sin α = F

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So, if you know the vertical, and also the angle it comes from, you can know the real force
and by extension, also the horizontal.

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On our problem, you can probably see that the only real force we know is purely vertical
But there is a horizontal reaction, and its because the stunt is pushing against the wall too, so the reaction has to be keeping the bar attached to the wall by tugging on the opposite side

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Thats how you get the true reaction

rain sentinel
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because every action has a reaction

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so because its pushing on the wall the wall pushes back leads to horizontal force

glossy zephyr
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For example, we wouldnt get no horizontal reaction if the stunt was purely vertical too

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On a really "stupid" sense, the horizontal reaction comes from the fact that we have to do extra work to keep the bar static, because some is wasted in pushing the bar away.

rain sentinel
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so

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i know theres a horizontal and vertical force because?

glossy zephyr
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The vertical blue force coming from the bar is the one mantainind the bar from not falling

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But because it comes at an angle, theres some part of the real force that is "wasted" pushing the bar away.

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So the reaction at the left side must be keeping it from just flying away

rain sentinel
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normal force is the blue force?

glossy zephyr
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Yeah

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What we previously called "Vertical Component"

rain sentinel
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and is a consequence of gravity

glossy zephyr
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We are not considering gravity here, just the force at the right side

rain sentinel
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and the purple force?

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is a result of fv and fh?

glossy zephyr
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its the combination of the two

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aka, the real force which is coming at an angle and we decomposed into the horizontal and vertical

final saddleBOT
#

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final saddleBOT
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dusty schooner
#

How can i find the derivatives of sin cos and tan?

tiny gorge
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well for sin and cos it depends on how you have defined them

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(assuming you're asking how to prove that sin' = cos, for example)

dusty schooner
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Yeah

tiny gorge
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there are a couple of standard approaches

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one defines sin and cos as the solutions to certain differential equations
another defines sin and cos as certain power series

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and in both cases you can rigorously show that sin' = cos and cos' = -sin

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for tan, it's easy, just write tan = sin/cos and use the quotient rule

dusty schooner
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Ahhh i see

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Preashh

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.closed

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.close

ember ether
#

😂

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craggy plank
#

Claim your own channel

final saddleBOT
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exotic shale
#

why is u+ υ = M?

final saddleBOT
exotic shale
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isnt it u + υ = t

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i dont understand how we went from the first region to the second with the substitution

runic tulip
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v = t-u

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As we are replacing t with v

exotic shale
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?

drowsy epoch
exotic shale
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like on the graph u and υ how do i find the new region

drowsy epoch
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t runs from 0 to M

exotic shale
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ok

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so u+υ runs from 0 to M

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but in the picture it states thats allways true

exotic shale
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frank folio
#

Im having trouble understanding the surjectivity of this proof:

frank folio
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The existance of T should not have such importance unless its a basis right?]

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thats the lemma they are talking about

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neither of these are the basis so im lost as to how they made the connection

formal trail
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the linear map lemma guarantees that for every matrix, there is a linear map corresponding to it

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so let's say we have a fixed matrix $A$, and pick fixed bases $v_1,\ldots ,v_n$ and $w_1,\ldots,w_m$. then we define a second list of vectors in $W$, $w_1',\ldots w_n'$ by
[ w_k' = \sum_{j = 1}^m A_{j,k} w_j ]
then we are saying there exists a linear map $T$ such that
[ T v_k = w_k' ]
by the linear map lemma, and by definition $A = \mathcal M(T)$

soft zealotBOT
#

κλαουντ ☁ (cloud)

frank folio
#

or are we going through the linear combinations

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ok nvm that makes sense

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so it garenttes that for any matrix there is a lienar map corresponding to it

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through linear combinations of the basis?

formal trail
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yes

frank folio
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ok we just took A to be arbrtraty here

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and showed that there is a linear map to every T

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from A

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@formal trail

formal trail
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well we are saying that the map which rakes in a linear map and spits out its matrix is bijective. in this phase we are saying it is surjective because every output (matrix) has an input (linear map)

frank folio
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oh because the elements of the matrix are just coefients, and legit all elements and combinations in R are included here

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?

formal trail
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well we are saying that if we use the entries of the matrix in a particular way that gives us a list of outputs w_k which, when paired with the basis v as inputs, uniquely specify a linear map (by 3.4)

final saddleBOT
#

@frank folio Has your question been resolved?

frank folio
#

.close

final saddleBOT
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winged ember
#

i cant seem to figure out how to evaluate this

frank folio
plucky rover
final saddleBOT
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rustic narwhal
#

hi, teachers, do you know where i can find a proper proof about this equility

rustic narwhal
#

1

severe verge
#

use set builder

desert mantle
#

double inclusion

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cloud zephyr
#

I tried it in two ways and I got different answers. I am off by one (-) sign and I can't figure out from where its seeping in into my answer.

cloud zephyr
#

The correct answer is (1)

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.close

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robust mulch
#

@cloud zephyr did you figure it out?

cloud zephyr
robust mulch
#

why close then

cloud zephyr
#

but i dont know how to send in my solution because i cant send a picture of my work rn and its hard to explain what i did via text

robust mulch
#

ok where you at so far?

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.reopen

final saddleBOT
#

robust mulch
#

physics is fine

violet junco
#

oh mb

thin cloud
violet junco
#

so what you want to do here is take force perunit length as lamda times g

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you want to assume a pully system with mass

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assum,e the pulley si the sphere with a mass

robust mulch
#

the sphere is practically irrelevant except for it being a smooth round surface

cloud zephyr
violet junco
craggy plank
violet junco
#

can you check your signs?

robust mulch
violet junco
robust mulch
#

-# /j in case you couldnt tell

thin cloud
cloud zephyr
robust mulch
#

im curious where the minus came from

cloud zephyr
#

me too bleakkekw

robust mulch
#

can you explain your thought process a little more?

violet junco
#

yeah

#

ADRIEN CAN YOU SEND A picture of your soln>?\

#

sorry caps

cloud zephyr
#

Okay I assume a small element of length dl, mass dm, subtending a small angle dθ at an angle (θ) from the vertical .
dl = Rd(θ), dm = (λ)dl. so dm = Rλd(θ).
small gravitational force on this is dF = g* dm. The component of that force we're concerning with here is gsin(θ)dm. so basically gsin(θ)Rλd(θ). Then i integrated it

robust mulch
#

ah there it is

#

check your triangles

#

oh angle from the vertical

#

i need to be better at reading physics

cloud zephyr
#

i took my angles from the vertical

#

F_net - λg/2 = integration of gsin(θ)Rλd(θ) (limits pi/2 o 0)

robust mulch
#

so its just a sign thing

#

but the weird thing is if you integrate backwards, the idea is the same, but the sign flips

cloud zephyr
#

wait wait

robust mulch
#

and i cant tell you whats making the difference

cloud zephyr
robust mulch
#

yeah that works

#

but it still doesnt fix the issue that the direction of integration flipping will change your answer

cloud zephyr
#

I've been going crazy

robust mulch
#

wait i might just be silly

#

integral of sin is -cos

#

-cos(pi/2)-(-cos(0))=0-(-1)

#

which is 1

violet junco
#

isnt the limit 0 to pi.2?

cloud zephyr
violet junco
#

t1 is 0 adn t2 is pi/2

violet junco
cloud zephyr
#

I adjusted the RHS accordingly

#

At least i think i did

#

but idek atp

robust mulch
#

right

#

im being extra silly

#

just use magnitude

#

you know the sphere isnt removing any forces

cloud zephyr
#

This is still bothering me though. I would've gone : (4) None of the above, in a high stakes situation. How would I know to take the magnitude?

violet junco
#

is it a olympiad?

cloud zephyr
#

No

violet junco
#

Uni phy?

#

or AP phy?

cloud zephyr
#

No no, i am prepping for some medical school entrance tests and came across this question

#

and couldnt resist

violet junco
#

( T + dT = T + (dm)g \cos\theta ), ( N = (dm)g \sin\theta )

soft zealotBOT
#

qfalcon_

violet junco
#

is this right

#

$$
\int_{T_1}^{T_2} dT = R \lambda \int_0^{\pi/2} \cos \theta , d\theta
$$

soft zealotBOT
#

qfalcon_

violet junco
#

ok yay the converter is working

cloud zephyr
#

do you mind explaining a little bit?

final saddleBOT
#

@cloud zephyr Has your question been resolved?

robust mulch
#

the chain links pull on the rope, adding to the tension still

#

they dont relax the tension

#

thus, take magnitude

worldly pendant
#

🍆

final saddleBOT
#

@cloud zephyr Has your question been resolved?

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rain sentinel
#

ou will need to create a plot that:
• has Temperature along the X-axis and Impact Energy along the Y-axis
• Y-axis crosses X-axis at -120 deg C
Impact Energy (J)
Temperature, T (°C)
• includes three series of data – representing the lowest, mid and highest
results for Impact Energy at each temperature
• uses different styles of marker for each series, and includes a legend

rain sentinel
#

however when ive tried plotting this in excel the axis looks like this

#

im not sure how to change it to look like this

final saddleBOT
#

@rain sentinel Has your question been resolved?

bold zenith
#

In the excel data put rows below for the minimum using MIN and maximum using MAX and the one in between (which tbh I can’t think of how to get easily)

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cloud zephyr
#

Assuming the pulleys are massless, find the time at which the 2kg Block will lift from the ground.

cloud zephyr
#

I had too many variables and I looked at the solution, they didnt consider net accelerations for either block. Why is that?

#

Like I was made the equation:
For the 2kg block:
N + 2T - 20 = 2a
And then N = 0 (condition for leaving contact)
2T - 20 = 2a

I know that T = 5t/3. and even if I make equations for the 8 kg block as well, I would have too many variables and too few equations

final saddleBOT
#

@cloud zephyr Has your question been resolved?

crisp mason
#

and now im making myself learn classical dynamics in a month and a half 😃

swift bone
#

Maybe u forgot that for the block to just lift off, the forces have to be balanced?

runic tulip
#

Did you use string constraint?

#

Using that you can find the relation between the acc of the blocks

#

@cloud zephyr

cloud zephyr
runic tulip
#

Mb

cloud zephyr
runic tulip
#

Oh nkce

#

Nice

cloud zephyr
#

okay so if i want it to just lift, I just need to consider the bare minimum scenario with net force = 0 ?

runic tulip
#

Yes

#

You need to do a > 0
Which means Fnet > 0

#

So solve for Fnet = 0 to get the limiting case

swift bone
#

yep

cloud zephyr
#

okay what if the Force was like 1000N (constant and huge). Wouldnt that cause a sudden acceleration when liftoff?

runic tulip
#

It would

swift bone
#

Yeah. The second it leaves the ground, the normal force is gone, so u get a sudden net upward force.

cloud zephyr
#

but then wouldnt i need to give at an initial acceleration the moment the N = 0?

runic tulip
#

?

swift bone
#

nah, a=0 is the condition for it to just start moving. If the upward force is bigger than the weight, there's a net force, and that's what causes the acceleration.

cloud zephyr
#

I am just a little confused that the Normal reaction if 0 the moment it leaves the ground, and it experiences an upward acceleration the moment it leaves the ground, why do i not include acceleration in my equations?

swift bone
#

It's cuz you're solving for the tipping point. The exact moment the upward force equals its weight. At that single instant, a=0. The acceleration kicks in right after.

cloud zephyr
#

okay, that makes a little more sense to me

#

i'll try to process that

#

thank you so much:)

#

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cloud zephyr
#

I am getting an answer different from the options, and would like to find my mistake.

I am denoting vector quantities in bold here. i and j are unit vectors along x axis and y axis respectively.
ds is the small displacement.
ds = dx i + dy j
small work $$dW = ydx-xdy$$
$$y^2 + x^2 = a^2 $$
$$y = \sqrt{a^2 - x^2} $$ and $$ x= \sqrt{a^2 - y^2} $$

$$dW = \sqrt(a^2 - x^2) dx - \sqrt(a^2-y^2)dy $$
$$W = \int_{\a}^{\0} \sqrt{a^2 - x^2} dx - \int_{\0}^{\a}\sqrt{a^2-y^2}dy$$

$$W = (\frac{a^2}{2} - \frac{a^2 \times pi}{4}) - (\frac{a^2 \times pi }{4} - \frac{a^2}{2})$$

soft zealotBOT
#

Adrien-Marie Legendre
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

cloud zephyr
formal trail
#

I am getting an answer different from the options, and would like to find my mistake.

I am denoting vector quantities in bold here. $\vb i$ and $\vb j$ are unit vectors along $x$ axis and $y$ axis respectively.

$d\vb s$ is the small displacement.
$$ d\vb s = dx \vb i + dy \vb j $$
small work $dW = ydx-xdy$
\begin{gather*}
y^2 + x^2 = a^2 \
y = \sqrt{a^2 - x^2} \quad \text{and} \quad x= \sqrt{a^2 - y^2} \
dW = \sqrt{a^2 - x^2} dx - \sqrt{a^2-y^2}dy \
W = \int_{a}^{0} \sqrt{a^2 - x^2} dx - \int_{0}^{a}\sqrt{a^2-y^2}dy \
W = \left(\frac{a^2}{2} - \frac{a^2 \times \pi}{4}\right) - \left(\frac{a^2 \times \pi }{4} - \frac{a^2}{2}\right)
\end{gather*}

soft zealotBOT
#

κλαουντ ☁ (cloud)

cloud zephyr
#

I found my mistake

#

i did a/2 instead of x/2 in my integration formula

formal trail
#

since both of those essentially integrating the area under the circle for 1 quadrant they should each contribute a quarter circle area (negative)

cloud zephyr
#

magnitude understood, negative why?

#

OHHHH

#

I couldve gotten the -ve by analysing the direction of force and displacement

#

is that right?

formal trail
#

well just noting that [ \int_0^a \sqrt{a^2 - x^2} \dd{x} ] is the area of the quarter circle; the first one has the bounds reversed and the second one is being subtracted so they both contribute negatively

soft zealotBOT
#

κλαουντ ☁ (cloud)

cloud zephyr
#

wow thats clever

#

thank you so much

#

i appreciate it

#

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#
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warm python
#

Am I tripping here

final saddleBOT
warm python
#

So $x'=x^{-1}$ for convention's sake.
\
$xx' =e \implies xx'(x'') = x'' \implies x(x'x'')=x'' \implies x''=x$.
\
Then $xx'=e=x'x''=x'x$

soft zealotBOT
warm python
#

Like Is is this right, I feel like It''s too easy

#

oh shit

#

I have to show ex''=x''

warm python
warm python
#

If I can show the left identity is the right identity then I'm done

warm python
onyx peak
# soft zealot wai

Yeah, this looks fine. I'd just write (xx')x'', parens around a single element are a bit pointless

warm python
#

I suppose I use the hint to prove that

onyx peak
#

yeah, that's a good idea

#

that hint actually gives u sth slightly different, but you can get ex = x from that

warm python
#

$ee=e\implies e(xx')=xx' \implies (ex)x'=xx' \implies ex=x$

soft zealotBOT
warm python
#

This works too I think

onyx peak
#

yep, that looks fine

warm python
#

cool :D. I know this is an easy problem, but kind of proud of myself for doing it

onyx peak
#

||x'xx'x'' = x'(xx')x'' = x'ex'' = x'x'' = e
x'xx'x'' = (x'x)(x'x'') = x'xe = x'x
so e = x'x||

This is what they intended to do with the hint btw

onyx peak
#

took me like an hour when i first tried it

warm python
#

I had first seen this long ago

onyx peak
#

so u can be rightly proud of urself

warm python
#

never got it then

warm python
#

I'll eat lunch now, thanks for the help again!

#

,ti

soft zealotBOT
#

The current time for math_rocks is 12:21 PM (IST) on Wed, 01/10/2025.

warm python
#

.close

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plain rain
#

I have a math uni- related question if thats okay. I am first semester and I wanna take a course that is available a few years later normally. Is it okay to take it from now? And can I also take the exams if I wanna?

plain rain
#

Whoever answers answer in terms of experience, because I know it prolly depends

worldly mesa
#

you can take the course if:
1 - your uni lets you
2 - you are ready in terms of mathematical maturity and prerequisites

plain rain
#

it is set theory, but its for 6th semester for sum reason

odd seal
#

Some courses require knowledge taught in previous courses, so unless you are good with these prerequisites, you would find it difficult to keep up with the pace of the course

worldly mesa
#

you should check online to see if this is the case

plain rain
plain rain
worldly mesa
plain rain
#

its a choice subject thats why its so later on

odd seal
#

those prerequisites need not be the courses, but might also come in the form of mental juggling that gets taught during the lectures, like some specific way to handle a specific type of problem, and that comes with the practice which you might lack right now

odd seal
#

might help you later on, if you do good in the course and if you are interested to pursue it further, in terms of finding undergrad research opportunities or thesis or any such thing

plain rain
#

anyways ill ask the people here too

#

thank you

#

.solved

final saddleBOT
#
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plain rain
#

.reopen

final saddleBOT
odd seal
#

talk to your seniors who have taken the course, if you know any (might be tough since you are just starting uni) it might help you more if you are able to find videos of lectures from the prof (might give you an idea of what the prof expects and how the stuff is going to be paced)

candid hull
#

do you have a syllabus for that 3rd year class ? I'd assume it's much different than what you've seen about now, starting from ZFC and all that

plain rain
plain rain
candid hull
#

the content of the course

#

what topics are in it ?

worldly mesa
#

and homework/exam format

plain rain
worldly mesa
#

thats our point

plain rain
#

its weird

#

the system

odd seal
plain rain
#

thank you chat

#

.solved

final saddleBOT
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worldly mesa
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warm python
#

I don't get how ths is differnt from a partial order

faint edge
#

Not sure how you defined partial order but the usual difference is that two elts of a poset need not be comparable

#

Ur case (i) ensures this never happens.

warm python
plucky rover
faint edge
#

If you've ever seen a tree describing a tournament that's a partial order which is not total for ex

#

Oh the powerset is a good one too.

warm python
plucky rover
#

A total order is just a partial order where all elements are comparable

warm python
#

ah, just realised

#

cool

faint edge
#

Yah so in this case if I give u a and b, nothing tells you a<=b or b<=a

warm python
#

so in a partial order a can be NOT related to b

faint edge
#

Yah!

warm python
#

oh, cool.

#

I wish my courses covered all this

#

😔

#

Thanks !

#

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#
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warm python
#

(I'm using a variety of other books to study)

plucky rover
warm python
#

Total order in class and partial order in the notes

faint edge
#

It's hit or miss whether you do this.

plucky rover
#

Yeah same

faint edge
#

Often you just start with a linear order or something that has one because delving into order theory stuff is kinda niche and unproductive if you're focused on other stuff

warm python
#

But it allows for fun problems 😭

#

Oh well

faint edge
#

Order theory is cool in general. I think the first time I saw these things was set theory or discrete math.

warm python
#

I've to eat and then head to a class , see y'all !

plucky rover
#

It's 7 pm what fucking class lol

#

See ya, good luck lmao

warm python
plucky rover
#

Yeah figures

warm python
#

Taken by students

plucky rover
#

It's also dussehra

#

Insane

#

Good luck lol

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vague anchor
final saddleBOT
tired walrus
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vague anchor
tired walrus
#

do you know what a matrix is

#

do you know how to multiply matrices

vague anchor
#

Ofc😭

tired walrus
#

do you know what trace is

vague anchor
#

Yes

tired walrus
#

i don't think there's any fancy theory here

#

or at least i don't see anything

#

maybe there is some stupid bs trick but i would just bash

#

write sth like $A=\bmqty{a_1&a_2\a_3&-a_1}$ and similar for $B$

soft zealotBOT
tired walrus
#

you want to check AB vs BA for if they are equal

vague anchor
tired walrus
vague anchor
vague anchor
#

Thank you

#

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vague anchor
#

30
Assuming A to be I_4
Or all elements to be zero except 1 elements (which is one)
It can be known
But proving in a proper way I need help

vague anchor
#

,rccw

soft zealotBOT
tired walrus
#

let u = [1; 1; 1; 1]
(ie u is the vector of size 4 with all coordinates 1)

#

then your condition is equivalent to saying Au = u

#

think about why that is based on what you know about multiplying matrices

#

$\bd{u}=\bmqty{1\1\1\1}$

vague anchor
soft zealotBOT
tired walrus
#

then pretend i said 4×1 matrix.

vague anchor
tired walrus
#

then your condition is equivalent to saying Au = u

#

in fact it is a general fact that Au, with my u here, is a 4×1 matrix containing the row sums of A as entries

#

so you will want to look at A^10 u

#

think about what that must be

#

don't try to descend back into what'stheformulaism

vague anchor
tired walrus
#

...

#

question asks for total element sum in A^10

vague anchor
tired walrus
#

do you mean "be" or "become"

vague anchor
tired walrus
#

well i don't speak Hindi so we are a bit stuck here

#

& can't figure out how to say same thing again but in simpler form

vague anchor
#

Thats not a big difference
If it becomes A
It will be equal to A

tired walrus
#

already saying simply as best i can

#

yet failure

vague anchor
#

😵😵‍💫

#

<@&286206848099549185>

gray yacht
gray yacht
vague anchor
#

Pls Help me solve question no. 30

jovial grotto
#

ok so where are you getting stuck?

#

as in which step of the problem?

vague anchor
#

Can you see Ann's great approach

#

I just want to prove A=A^10

tired walrus
jovial grotto
#

only the sums are the same

#

the matrices A and A^10 may not be same

vague anchor
#

Oh there she comes

vague anchor
jovial grotto
#

one way to solve is to take advantage of the generality of the problem

#

and consider an identity matrix

vague anchor
#

It's not a way to solve it that's completely hit n trial like

ivory bear
vague anchor
#

30

ivory bear
#

nice

#

will try

jovial grotto
#

see, we have Ae=e

#

where e is the [1 1 1 1] matrix from before

tranquil pine
#

I have a question, can someone help me with absolute value functions? I don't understand and have tried many things

vague anchor
#

occupied!

final saddleBOT
tranquil pine
#

Sorry new!

jovial grotto
#

@vague anchor but then this implies that A^ke = e

#

right?

tired walrus
#

not e

#

just to be clear on that

vague anchor
jovial grotto
#

oh sorry

jovial grotto
#

multiply A by both sides

#

then A^2e=Ae

#

but Ae =e

#

so A^2e = e

vague anchor
#

Oh

#

I'm foolish

jovial grotto
#

do you see how this can be continued

vague anchor
#

Freakingly hell

jovial grotto
#

now, remember that multiplying by e is effectively summing the rows

#

now how do you sum the columns?

#

do you have any idea?

#

try to find a vector similar to e

vague anchor
#

Now further I can do it myself

jovial grotto
#

nice

vague anchor
#

Thank you🙇‍♂️🙂‍↕️

jovial grotto
#

👍

vague anchor
#

.close

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ember escarp
#

log2(x-1)+log2(x-1)=3

How to solve this?

final saddleBOT
tall cape
#

First the left hand side can be added directly

#

cause
well
both are the same log2(x-1)

tired walrus
soft zealotBOT
ember escarp
#

yep

tired walrus
#

ok then yes as @tall cape said the first step is definitely to add them as $$2 \log_2(x-1) = 3$$

soft zealotBOT
tall cape
#

chomp are you okay from here or you need hint for next step

ember escarp
#

i really do need guidance in solving it

tall cape
#

okok

#

so

#

think about the end goal

#

we want
x = ???????

#

so look at what we have, our x is trapped in log right?

#

is it possible to take it out?

ember escarp
#

yes?

tall cape
#

so how would we do it

#

Do tell me if u need more hint

tired walrus
#

do you know how to solve logarithmic eqs in general

ember escarp
#

yes

tired walrus
#

ok right

#

so if you had something that looked like $\log_b(x) = k$ how would you rewrite it

soft zealotBOT
tired walrus
#

(dont worry about your original eq yet; we will tie back to it shortly)

#

(i wanna see whether you know the key step)

ember escarp
#

(b)(k) = x correct me if im wrong

tall cape
#

what do you mean by (b)(k)

#

do you mean

#

$b^k$

ember escarp
#

oh just remove the ()

soft zealotBOT
#

Progameyen

ember escarp
#

yes

tall cape
#

yea then u are right

#

so back to our original eq

#

we got

#

$2 \log_2 (x-1) = 3$

tired walrus
#

you should use ^ for exponents btw

tired walrus
soft zealotBOT
#

Progameyen

tall cape
#

okok tq

tired walrus
#

yeah so how can we get the log term on its own here

#

(just basic algebra, no log-law manipulation yet)

past cairn
#

!helpm on maths

final saddleBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

past cairn
#

new here

tall cape
#

?

ember escarp
#

wait, how did we get the 2log₂?

tired walrus
tall cape
#

so like

tired walrus
#

like a + a = 2a

tall cape
#

you have $\log_2 (x - 1) + \log_2 (x - 1)$

#

at left hand side

past cairn
#

annn need help for yr8 hw

soft zealotBOT
#

Progameyen

tired walrus
tall cape
#

so we can just add them together

#

as if $a + a = 2a$, where a = $\log_2 (x - 1)$

soft zealotBOT
#

Progameyen

tall cape
#

@ember escarp Do i need to clarify anything more?

ember escarp
#

nonee

tall cape
#

okay so

#

now we are at

#

$2 \log_2 (x - 1) = 3$

soft zealotBOT
#

Progameyen

tall cape
#

And you know that if your expression is in the form of
$$\log_a b = c$$
Then you can rewrite it as:
$$a^c = b$$

soft zealotBOT
#

Progameyen

tall cape
#

Where a, b, c can be constant (just number) or any variable (any expression that as x)

#

So far so good?

ember escarp
#

yupp

tall cape
#

Now

tall cape
tall cape
#

Then we can 'take out' the x right?

#

cause the x is sitting inside log()

#

we have to take it out

#

Now the question is

#

Is it possible to arrange our expression $2 \log_2 (x - 1) = 3$ to the form of $\log_a b = c$?

soft zealotBOT
#

Progameyen

tall cape
#

Note: There are multiple ways to do so, we could just choose one

ember escarp
#

i think yes

tall cape
#

Hm how would you do so then?

ember escarp
#

combining like terms?

tall cape
#

Hm how would you combine then?

#

Like where is the like terms

ember escarp
#

the (x-1)

tall cape
#

When we talk about like term__s__, we need at least two of them tho 🤔

#

So for your information, I cannot see where is the like terms hm

#

Unless you do think there are like terms, you can point it out to me
Otherwise we try other method

ember escarp
#

what is the other method?

tall cape
#

Lets go to our goals in case we forgot

#

Is it possible to arrange our expression $2 \log_2 (x - 1) = 3$ to the form of $\log_a b = c$?

soft zealotBOT
#

Progameyen

tall cape
#

First subquestion:

#

Is this expression $2 \log_2 (x - 1) = 3$ already in the form of $\log_a b = c$?

soft zealotBOT
#

Progameyen

tall cape
#

Do tell me if you dont understand what im saying

ember escarp
#

not yet

tall cape
ember escarp
#

oh wait, i think it is

#

cuz c = 3, b = (x-1)?

tall cape
#

and a = 2 right?

ember escarp
#

yea

tall cape
#

But dont forget the 2 that is sitting outside

#

it is extra

#

so both of them isnt the same thing yet

#

cause the 2 sitting outside of log

#

So if we want to make both same thing, we have to eliminate the extra 2 (or move it somewhere)

#

So any idea?

ember escarp
#

noopee

tall cape
#

We want to get rid of this right?

ember escarp
#

yea

tall cape
#

So is it possible to somehow make the 2 no longer stay there?

ember escarp
#

hmmm, yea?

tall cape
#

do tell me how

ember escarp
#

by dividing?

tall cape
#

yup

#

divide by?

ember escarp
#

2

tall cape
#

yup

#

so tell me what u get

ember escarp
#

log₂ (x-1) = 3/2 ?

tall cape
#

yup

#

now

#

Is our expression $\log_2 (x - 1) = \frac{3}{2}$ in the form of $\log_a b = c$?

soft zealotBOT
#

Progameyen

ember escarp
#

yes

tall cape
#

yup

#

a = 2
b = x - 1
c = 3/2

#

So we can finally apply the rules that we are waiting for!

#

So after apply the formula, what we will get?

ember escarp
#

2^2 = 3/2 ?

tall cape
#

ermmmm not really tho...

ember escarp
#

do we have to add x-1?

tall cape
#

And you know that if your expression is in the form of
$$\log_a b = c$$
Then you can rewrite it as:
$$a^c = b$$

soft zealotBOT
#

Progameyen

tall cape
#

In case you forgot

ember escarp
#

2^3/2 = x+1?

tall cape
#

yup

#

Our end goal is get x = ?????

#

We are so close

ember escarp
#

oh i thought we done

tall cape
#

Almost
but not done

#

cause our goal is to solve it

#

We have to get it to x = ???

#

@ember escarp

ember escarp
#

hello

tall cape
#

Have you got the answer?

ember escarp
#

wait

#

do we convert here?

tall cape
#

?

#

we dont need to tho

#

We got:

#

$$2^\frac{3}{2} = x - 1$$

soft zealotBOT
#

Progameyen

tall cape
tall cape
ember escarp
#

oh right, srry

tall cape
#

We want to get x = ???

#

So how

ember escarp
#

uhm

tall cape
#

in case you still havent see it
we can swap both sides

#

$$x - 1 = 2^\frac{3}{2}$$

soft zealotBOT
#

Progameyen

tall cape
#

how to get the expression x = ???

ember escarp
#

square root?

tall cape
#

no need

#

x is at left side right?

#

so to get form of x = ???

#

we can just move that -1 to right side

#

$$x= 2^\frac{3}{2} + 1$$

soft zealotBOT
#

Progameyen

tall cape
#

And we got form of x = ??? already!

#

Do i explain it clearly tho?

ember escarp
#

oh so transpose?

tall cape
#

errrr you just +1 from both sides

ember escarp
#

oh

tall cape
#

$$x - 1 + 1 = 2^\frac{3}{2} + 1$$

soft zealotBOT
#

Progameyen

tall cape
#

It preserves equality

#

so yea

#

any more question

ember escarp
#

so thats the answer?

tall cape
#

yup

#

$$x= 2^\frac{3}{2} + 1$$

soft zealotBOT
#

Progameyen

ember escarp
#

im still kinda confused but I understand the point

tall cape
#

which part you are confused tho

#

i could reexplain

ember escarp
tall cape
#

It is a formula for logarithm

#

And it is basically how logarithm is defined

#

Wait are you asking how this formula work?
Or you are asking how to apply it?

ember escarp
#

both, bcuz this was given to us without prior knowledge huhu

#

I only know the basics

tall cape
#

hmmm...

#

Cause like, the logarithm itself is an inverse of exponent

#

Like its existance is basically the "reverse" of exponent

late rose
ember escarp
#

nop

tall cape
#

Hm...someone has to teach you about log again tho...

#

I wish i can do that but im about to sleep ;-;

late rose
#

do these look completely foreign to you?

ember escarp
#

nope

#

we haven't started talking abt those

late rose
#

oh alright

#

youll probably be taught it later in your class ig

#

you dont need it for this problem though

ember escarp
tall cape
#

$$\log_2 (x - 1) + \log_2 (x - 1) = 3$$
$$2 \log_2 (x - 1) = 3$$
$$\log_2 (x - 1) = \frac{3}{2}$$
$$2^{\frac{3}{2}} = x - 1$$
$$x = 2^{\frac{3}{2}} + 1$$

soft zealotBOT
#

Progameyen

ember escarp
#
  1. add the same term
  2. divide both sides by 2
  3. Convert logarithm form to exponential form
  4. put +1 both sides
#

is that all or did I miss any?

tall cape
#

Convert logarithm form to exponential form

#

$$\log_a b = c$$
becomes
$$a^c = b$$

soft zealotBOT
#

Progameyen

ember escarp
#

what step is that

tall cape
#

After you divide both side by 2

ember escarp
#

anything else?

tall cape
#

nope

ember escarp
#

is there anything else I should remember or take note of?

tall cape
#

for now try to understand what log do

tall cape
ember escarp
#

okayy

#

thank u so much for the help, i learned a lot

tall cape
#

ye np

#

.close

#

hm

#

you need to close lol

ember escarp
#

.close

final saddleBOT
#
Channel closed

Closed by @ember escarp

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tulip panther
#

I don't even know how to start this, can someone break it down for me into manageable chunks?

solid notch
#

draw a visual representation while reading the question out

#

use different shapes to represent a group type and write a number ( frequency ) for the group type in thoese shapes

tulip panther
#

okay, i got the total amount of combinations possible, how do i restrict it to only 3 substitutes possible?

#

.close

#

.close

final saddleBOT
#
Channel closed

Closed by @tulip panther

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

eager shore
final saddleBOT
eager shore
#

@blissful condor @sick roost right I'd like to formulate a thought process for this now

#

I'll try proving that bounded continuous functions are UC

final saddleBOT
sick roost
#

hold on!

#

you have a continuous periodic function

#

consider your compact period interval

#

show UC and bounded on that first

#

then, since its UC and bounded on that interval, periodicity implies UC and bounded everywhere

onyx peak