WOAHH
#help-36
urban wasp
late rose
i did not expect that to work
urban wasp
wait..
does it do history tho O.o
,w who was the first president of the united states
soft zealotBOT
urban wasp
?
brittle breach
,w current president of Cuba
soft zealotBOT
bold turtle
I was going to say "if you've ever used Siri in the early 2010s..." but then I remembered I'm somehow simultaneously young and old
urban wasp
,w who started the french revolution
dusty quarry
yo folks, might wanna experiment elsewhere.
soft zealotBOT
dusty quarry
not in a help channel.
brittle breach
Nice ✅
urban wasp
I was going to say "if you've ever used Siri in the early 2010s..." but then I r...
yeah but this is a calculator
imagine if ilr calculators could do this
bold turtle
yeah but this is a calculator
No, the conclusion would've been "...Siri would parse questions like how WA's 'input interpretation' works"
In any case, I'm gonna take a punt and assume this question is solved, so
!done
final saddleBOT
If you are done with this channel, please mark your problem as solved by typing .close
bold turtle
Then it'd've done this, wouldn't it
dusty quarry
so what if it said a previous president
if it said a previous president, you can doorslam WA by .closeing the channel
final saddleBOT
dusty quarry
ill just do it in other occupied help channels
i'll report you if you do
urban wasp
i'll report you if you do
its a joke 😭
final saddleBOT
Available help channel!
spare moth
in this for example would the answer be like f(x+2)+1 or do we have to identify what function it is and then do x+2 inside its brackets like if there was graph of √x we would do (√(x+2)) + 1 ?
final saddleBOT
in this for example would the answer be like f(x+2)+1 or do we have to identify ...
final saddleBOT
final saddleBOT
Available help channel!
robust horizon
Problem Statement: Given an array of intervals, merge all the overlapping intervals and return an array of non-overlapping intervals. how do i start with this? i also do not fully understand what it is trying to say.
final saddleBOT
```Problem Statement: Given an array of intervals, merge all the overlapping int...
opal plinth
If for example you're given { [2, 5], [3, 7], [9, 12] }, you need to return { [2, 7], [9, 12] }
robust horizon
what exactly is this type of array called?
also, still did not get the question. are we just printing something which does not get "paired"?
opal plinth
It's just an array of intervals
opal plinth
You can make arrays of whatever you want
See how the red and blue lines overlap, but the green doesn't?
robust horizon
okay, makes sense
opal plinth
The question asks you to return the purple lines
robust horizon
but since there's two values in each of the elements, how exactly do i check what overlaps what? i do not think this can be done with indexing, right?
robust horizon
The question asks you to return the purple lines
yes, that makes sense; thank you
robust horizon
but since there's two values in each of the elements, how exactly do i check wha...
like, for instance, i want to print the second value of [2, 5]
how would i do that?
do we require another data structure for this? or no?
opal plinth
Yes
Well you could do it with one array of integers, where the even indices are starts of intervals and the odd indices are ends
But it's clunky
What you probably want to do is create an "interval" structure with two integer members "start" and "end"
robust horizon
Well you could do it with one array of integers, where the even indices are star...
can you please write that down for me?
opal plinth
Just { 2, 5, 3, 7, 9, 12 }
robust horizon
What you probably want to do is create an "interval" structure with two integer ...
like a struct in c?
opal plinth
Yes
robust horizon
Just { 2, 5, 3, 7, 9, 12 }
okay, this makes it a lot easier but that would not make sense to a third person, no? is this not bad practice?
opal plinth
I did say it's clunky
If you're writing code for your present self and only your present self, then it's fine
Just don't expect other people or even your future self to understand it
That's basically what "bad practice" boils down to
robust horizon
i would still like to write the code down for it though
and after that i will do it with a struct
opal plinth
Like as a challenge?
It won't really teach you anything more than doing it with a struct
robust horizon
okay, so if we do it with a struct
do we do it like this:
we create a struct, say s, which has two variables: "start" and "end"
we check if "start" of the second term is less than "end" of the first term
if yes, we update "end" of the first term with "end" of the second term
and so on
and if we find any element which does not have any other element with "end " > "start" of it, we return that
opal plinth
Yeah but you don't want duplicates, you'd need to delete one of the overlapping intervals
Or just build a new array
robust horizon
{[2, 5], [3, 7], [9, 12]}
opal plinth
Also please don't call it s 
robust horizon
how exactly are we getting duplicate values? are we not just keeping track of the starting and the ending index of each element, and not of the "numbers" they have in-between?
robust horizon
Also please don't call it `s` <:hmmcat:831508801646755850>
what else?
opal plinth
Interval
opal plinth
how exactly are we getting duplicate values? are we not just keeping track of th...
If you're updating the input array in-place, you'll end up with {[2, 7], [?, ?], [9, 12]}, where the ? depend on what you do that you haven't specified yet
opal plinth
is it really that bad?
It gets worse the bigger and more complex the code becomes
robust horizon
If you're updating the input array in-place, you'll end up with `{[2, 7], [?, ?]...
can we do something like
opal plinth
Code should be written to be human-readable first (unless optimization concerns take precedence), and descriptive names, for both variables and types, is one of the most basic ways to do that
(again, if you're writing code for your present self and only your present self, then... whatever)
robust horizon
i get it, i will work on it
robust horizon
can we do something like
so, we have {[2, 5], [3, 7], [9, 12]}
we know that [2, 5] and [3, 7] are going to get merged
and it then becomes [2, 7]
so what we do is, we check if [3, 7] overlaps with any other element
if not, we remove it from our array
if yes, we repeat the same process
opal plinth
If [3, 7] overlaps with something, then so does [2, 7]
robust horizon
correct, sorry
opal plinth
So you can just remove [3, 7] anyway
runic tulip
```Problem Statement: Given an array of intervals, merge all the overlapping int...
this sounds like a lc
robust horizon
So you can just remove [3, 7] anyway
what did you mean by removing duplicates, then?
robust horizon
this sounds like a lc
i just found it online
robust horizon
what did you mean by removing duplicates, then?
ah, is [3, 7] a duplicate here
would "duplicate" be the right term for it?
opal plinth
Maybe not, but you got the point
robust horizon
what impact does creating a new array to store these elements make on space complexity of this algorithm?
rather than updating the elements as you go
robust horizon
what did you mean by removing duplicates, then?
also, here, i was thinking more of
[2, 5] and [3, 7] have 4, and 5 as duplicates
opal plinth
It's kind of an ambiguous question; if you count the input in the space complexity, none; if you don't, then the space complexity becomes constant
opal plinth
[2, 5] and [3, 7] have 4, and 5 as duplicates
Oh I see, sorry that's not what I meant
robust horizon
It's kind of an ambiguous question; if you count the input in the space complexi...
got it, thank you
runic tulip
i just found it online
oh
robust horizon
do i declare the type of array a as int or as interval?
opal plinth
If you made an Interval struct, then use that
robust horizon
#include <iostream>
#include <struct.h>
struct interval
{
int start;
int end;
};
int main()
{
n = 3;
interval a[n];
for (int i = 0; i < n; i++)
{
cout << "enter an interval: ";
cin >> a[i].start;
cin >> a[i].end;
}
}``` does it work like this? or no?Yes
robust horizon
yay
opal plinth
Wait what is struct.h?
opal plinth
No 
opal plinth
A set is a type from the standard library
struct isn't a type, it's a keyword for making types
It's part of the language
opal plinth
It's probably a system file, idk
robust horizon
is it supposed to be like this? also, what do i return in the else block? cpp #include <iostream> #include <struct.h> struct interval { int start; int end; }; int main() { n = 3; interval a[n]; for (int i = 0; i < n; i++) { cout << "enter an interval: "; cin >> a[i].start; cin >> a[i].end; } for (int i = 0; i < n - 1; i++) { if (a[i].start < a[i + 1].end) { a[i].start = a[i + 1].end; a[i + 1] = a[i + 2]; } else { return } } }
opal plinth
I never used MacOS so idk how their C/C++ libraries look
robust horizon
does OS really matter? is it not more about the application?
or language for that matter
opal plinth
Different OSes implement libraries differently
The part of the library you care about doesn't change
struct.h isn't a part you care about
opal plinth
Technically it depends on the compiler, not the OS, but compilers kind of depend on the OS, so...
robust horizon
but when you code a language
do you not have to declare all the in-built libraries and stuff
like if we were talking about windows or linux, would they not have string.h too?
robust horizon
is it supposed to be like this? also, what do i return in the else block? ```cpp...
also, this please?
opal plinth
The standard library has an interface that stays the same for everyone, but its implementation can change
What are you trying to do here ? a[i + 1] = a[i + 2];
opal plinth
That doesn't work
opal plinth
Do you want to solve this question in-place (without creating another array)?
robust horizon
yes; that is what i am doing, right?
opal plinth
Ok but then you will need to use something other than a basic array
You can't change the size of an array
robust horizon
vector?
opal plinth
Yes
robust horizon
that's very convenient
robust horizon
is it supposed to be like this? also, what do i return in the else block? ```cpp...
but, still, if hypothetically speaking that this would work
what would we return? just a[i]?
opal plinth
No you don't return anything
return here will just terminate the program
You want to print the results at the end
robust horizon
we want to print an array of non-overlapping intervals, right?
opal plinth
Yes
opal plinth
Ok, I have to go, good luck
robust horizon
okay, good day! thank you for the help ^^
quaint void
has someone suggested sorting the intervals with respect to the left endpoints yet?
this easily gives an n log(n) complexity algorithm if I'm not mistaken
yeah, just sort the intervals and process them in this order
if the next one intersects the previous one, merge them together
otherwise the last interval is a complete union of overlapping intervals and we start a new component
robust horizon
has someone suggested sorting the intervals with respect to the left endpoints y...
what does one mean by that?
ah
like, ascending order?
final saddleBOT
@robust horizon Has your question been resolved?
deep condor
like, ascending order?
yeah, because you're checking the left endpoints
if you wanted to check the right, you could do descending too, im p sure
coral wedge
Find f^-1(8)
final saddleBOT
Find f^-1(8)
coral wedge
so I’m just assuming that means find inverse of 8?
and we can just look at the point when x =8 , so (8,2)
and then inverse would just be (2,8)
because you just flip them?
or is that wrong
vital crag
what is the blue curve? f or f inverse?
vital crag
you should show all the given information and not guess
worn carbon
in solving this question i have reached a point of confusion. since any vector in Rn can be expressed as a combination of n linearly independent vectors, we can treat the question of a n * (n+1) matrix being consistent or not as the question of whether each column except for the last is independent from each other. however, consider the 1x3 matrices (1,2,0), (2,1,0), (3,1,0). they are all independent yet the matrix is not consistent when augmented by another matrix with all nonzero elements. so im confused where i went wrong
final saddleBOT
in solving this question i have reached a point of confusion. since any vector i...
worthy wren
the two ways to do this on top of my head are:
show a1,a2,a3 are linearly independent (that amounts to solving the relationship ca1 + da2 + ea3 = 0 implies c=d=e=0) -> b can be expressed as a linear combination of a1,a2,a3 as these vectors would span R^3
solve for the augmented system
[a1 a2 a3 | b]
this system arises when you look at the definition of linear combinations
worn carbon
yes, the answer in the solutions is the latter, and my question is regarding the former
however, do 3 linearly independent vectors really span Rn?
worthy wren
they span R^3
R^3 is 3 dimensional
an n-dimensional vector space requires n linearly independent vectors to span it
worn carbon
(1,2,0), (1,3,0), (1,4,0) are all independent right? but they dont span R3
worthy wren
they are not linearly independent
meager hedge
You can stop checking a3. Since a3 = 5a1 + 4a2
I would evaluate the determinant [a1 a2 b]
worn carbon
i know how to solve the question, im just confused on what constitutes being independent
i already solved it by using an augmented matrix
i don't get how (1,2,0) and 1,3,0 are not independent though
worthy wren
there exists a k such that <1,2,0> = k<1,3,0>
worn carbon
wait how
worn carbon
ok that makes sense
worn carbon
the two ways to do this on top of my head are:
show a1,a2,a3 are linearly indepe...
wait, so aren
aren't these two methods the same ultimately
worthy wren
they are equivalent indeed
another method as shakigras said is to evaluate the determinant and see if it is nonzero
but the determinant requires a lot more theory to justify why this is the case
worn carbon
i don't think i learned that yet
wait, so for the first method, how do you do it exactly? you need to prove that there is no xa1+ ya2 that equals a3, then do this for a1 and a2?
worthy wren
for linear independence?
it is sufficient to show no x,y exist such that xa1+ ya2 that equals a3 and there exists no k such that ka1 = a2
the most general method for linear independence is
by trivial solution, they mean x1=x2=...=x_p = 0
worn carbon
i see
is there a way to do that easily? because i don't see how
like how to prove there is no other solution
worthy wren
in general vector spaces, there are many methods but R^n is the easiest because all u need to do is solve the system of equations that arise from subbing in v1,...,v_p
worn carbon
ok i think i get it. so generally you could create a matrix of the three vectors combined and showing that every column is a pivot column?
worthy wren
sure that works
final saddleBOT
final saddleBOT
Available help channel!
trail ginkgo
final saddleBOT
trail ginkgo
I’m stuck on question D
vital crag
denominator is correct. numerator is not
f(b) = population in year b
f(a) = population in year a
a, b, f(b) and f(a) are numbers given here
or derived from there technically
trail ginkgo
So just remove 1980?
final saddleBOT
Available help channel!
terse horizon
ALR
terse horizon
IM HERE
TO STAY
HELP ME
well acc i kind wanna leave after cuz this is nerdy
BUT HELP ME
I DEMAND HELP
terse horizon
No
split quarry
Then fuck it
split quarry
Im joking
split quarry
Im not even on this level of math
terse horizon
so which words on here do you not get
uh
i dont understand the first one
what its asking
whole halo
alr, what about this part of it
terse horizon
bro it is asking true or false
whole halo
yea
terse horizon
thats easy
whole halo
so you gotta put in true or false for each one
terse horizon
yeah
whole halo
so first one,
you gotta tell if this is true or not
what do you think, do you have an idea
terse horizon
No i dont know
whole halo
alr, what about this portion
whole halo
no
terse horizon
how
whole halo
do you know what the dashed part of the lines mean
whole halo
thats just means the line is behind the plane
thats like if you draw something behind something else by drawing it lighter
so AC is a line that goes through the plane, same with BD
whole halo
why do you trust chatgpt
it cant actually think or look on its own with pictures
not right now at least
your eyes are telling you BD and AC cross at A, thats all you need
whole halo
do you know what "colinear" means
terse horizon
yeah that it is in the same thingy thing
whole halo
all on the same line you mean
terse horizon
yeah
whole halo
so what do you think, true or false
terse horizon
ok wait lemme look at it
BRO THTAT IS FALSE BC IT IS NOT IN THE SAME LINE BC THE LINE BECOME A TRINGALE
whole halo
yep
its false, triangles arent lines
next one, the word "coplanar" means "all on the same plane"
usually this means you can imagine a plane going through the points
terse horizon
Wat
terse horizon
yeah
whole halo
its just a triangle standing up on the plane
terse horizon
yeah it is standing up
whole halo
so you can imagine all the points being on a flat surface, right
(the flat surface is standing up)
terse horizon
Uh
Why would the flat surface stand up
i thougth it is laying down
and a b c are standing up
whole halo
you have to imagine this surface
its not the blue one, since that one doesnt go through all the points
terse horizon
No
whole halo
why not
whole halo
well unfortunately colinear doesnt actually mean that for regular math
terse horizon
Wat
whole halo
colinear just means you can draw a line through the points
these three points are colinear
terse horizon
My teacher doesnt say that
whole halo
then your teacher isnt preparing you for how the rest of us use the word "colinear"
that sucks, but alr
whole halo
sure
whole halo
take a look at the triangle ABC
similarly its possible to imagine a plane through these three points
terse horizon
So all the points are on the same plane
terse horizon
Ohhhh i kind of see it
whole halo
think of the triangle from earlier
that triangle is just a cut-off version of the plane
if you continue the flat surface beyond just the triangle, youd get a plane like that
whole halo
yep
these three points are coplanar, because heres a plane where theyre all on it
terse horizon
Ok i get it i think
whole halo
thats good, next up is this
terse horizon
Yeah
whole halo
"intersection" or "intersect" means "cross at the same point"
do PQ and line k cross at point M?
terse horizon
can it be up or down
terse horizon
what if p q was standing up
whole halo
does it still go through M?
terse horizon
yes
whole halo
then itd intersect
terse horizon
Ok
whole halo
if it didnt go through M
it wouldnt intersect at M
maybe it intersects somewhere else or not at all
whole halo
yea
terse horizon
oh
whole halo
what else would M be
terse horizon
The line
whole halo
all the other things in the picture already have a label next to them
the problem called it "line k"
k cant also be the dot too
whole halo
PQ and k are both lines
they cross at point M
so PQ and line k intersect at M
thats why 4 is true
terse horizon
Yeah thats what i meant
like it goes across it
or inisde or cross idk idc b ut yeah thats what i meant
ok next
whole halo
plane A and plane B now have to "intersect" at PQ
for this, you see plane A and plane B, right
terse horizon
yeah
terse horizon
it corsses them
whole halo
yep
this line is the intersection of plane A and plane B
they cross only at this line
terse horizon
but also pq
whole halo
not every question has the answer "true" you know
you can see Q is not on plane B
line PQ isnt on plane B like the red line is
whole halo
yep
terse horizon
bc i thought it goes like across them both
whole halo
"intersection" has another definition thats useful for us
it means "what these two things have in common"
plane A and plane B have the red line in common
B doesnt have P and Q though, so line PQ couldnt do it
whole halo
bc i thought it goes like across them both
this is something else, it means line PQ is "inside the union of plane A and plane B"
whole halo
what do plane A and line k share in common?
and keep in mind that the question's answer can be "True"
terse horizon
yeah ik it can be true or false
uh
they have the line
bc k is the l
line
and a had that line bc the last question asked what was in common between them and that red line was in common
so that means line k and plane a have \line k so it is true
whole halo
yep
whole halo
part of this is that line k is entirely inside plane A
so anything they share in common would just be line k again
its not like it can be smaller than line k
terse horizon
wait it is the same for plane b right
terse horizon
BRO TYSM
whole halo
np
terse horizon
Wait i have one more question
whole halo
sure
terse horizon
why is this wrong
whole halo
the order of the letters matter for the ray
first letter is where it begins
second letter is where it goes
so you should be doing DB instead of BD
whole halo
well you just missed this little detail
its the only asymmetrical notation youre seeing, for now
later on the order that you write triangles in will matter too
triangle ABC vs triangle ACB
youll see what thats about when you learn congruence
whole halo
np
whole halo
.close good luck
final saddleBOT
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Available help channel!
vapid haven
my own q:
lim sin(x^0)/x
x-->0
im getting ans as lim x--> 0 x^(x-1) (basically 0^-1 = infinity)
can any1 check and let me know?
tired walrus
$\lim_{x \to 0} \frac{\sin(1)}{x}$ ?
soft zealotBOT
Ann
tired walrus
is that what you're saying? @vapid haven
final saddleBOT
@vapid haven Has your question been resolved?
desert mantle
final saddleBOT
final saddleBOT
Available help channel!
nocturne agate
Are these probabilities correct for the base probability below?
How would I calculate the probability for a fire event that runs 15 mins past every hour?
675 pets spawn per hour normally from the normal, gold, crystal and rainbow types.
During the 15 minute event only fire and normal spawn. They alternate between fire and normal for the full 15min.
final saddleBOT
Are these probabilities correct for the base probability below?
How would I cal...
final saddleBOT
@nocturne agate Has your question been resolved?
versed crater
Okay let’s break this down
First question: how do I know if the base probabilities are true, how did you calculate them
nocturne agate
I counted the type and rarity that come out during the first hour. Twice. Averaged them both
final saddleBOT
@nocturne agate Has your question been resolved?
ivory bear
final saddleBOT
@nocturne agate Has your question been resolved?
nocturne agate
No
minor mica
meow
maiden birch
Are these probabilities correct for the base probability below?
How would I cal...
It looks pretty reasonable, what are you trying to calculate about the "fire event"
final saddleBOT
@nocturne agate Has your question been resolved?
nocturne agate
It looks pretty reasonable, what are you trying to calculate about the "fire eve...
The projected estimated time to pull X rarity out of the event.
Since only fire and normal type spawn, initial conclusion is that the probability would be halved and the projected time would basically be doubled.
But im having a hard time understanding why. Especially when i project the rarity probability into the fire event, it doesnt match my real life tests.
And since i need to wait 1 hour before i can even start the event how does that get factored into the expected pull time?
maiden birch
in what way is it not matching your real life tests?
nocturne agate
It seems to be overprojecting the expected wait times. For example a common pet spawns much more often than its prediction. Let me go get the answers
nocturne agate
in what way is it not matching your real life tests?
Sorry i have made a mistake in the above tables. The top right is the base probability for fire/candy, not the drop rate. I will calculate the drop rate now and its projected wait time
This is what im coming up with
so these times are way off from my real life tests. Example the commons still remain at a very high chance like the normal event. At around 10 secs average.
And the secrets are no where near 47 hours. They should be way rarer than the normal "event".
This is just a visualization of the event
Fixed the table
shut charm
Sry, what is "fire" here?
Like fire is a variant of normal type with proportional spawn rates?
ripe jewel
what game is this btw\
shadow bluff
what game is this btw\
fortnite
slate narwhal
from what i gather, the projected wait times are calculated from the probabilities.
if that's the case, how consistently short of your projections are the actual wait times? if it's a one-off event it might be an outlier.
final saddleBOT
@nocturne agate Has your question been resolved?
final saddleBOT
final saddleBOT
Available help channel!
keen hound
Help
vivid walrus
!da2a
final saddleBOT
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
severe canyon
With what?
severe canyon
!noans
final saddleBOT
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
valid carbon
!nosols
final saddleBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
keen hound
I js need to know the solution
vivid walrus
do u know how to find the sum and product?
keen hound
Cuz i know how to do everything else but this one
keen hound
do u know how to find the sum and product?
Yea but in this case A isnt equal to 1
tired walrus
I js need the solution and answer
!noans
final saddleBOT
I js need the solution and answer
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
keen hound
What do u do when A isnt equal to 1
tired walrus
also there's no actual question here, all you're given is a quadratic but not told to do anything w/ it...
did you actually mean that you need to factorize it?
vivid walrus
Yea but in this case A isnt equal to 1
where's 1 coming from
keen hound
where's 1 coming from
From the x
tired walrus
this is a vid for the general method
however, in this case you can notice something
a 3 can be factored out
leaving 3(x^2 + x - 20)
and then x^2 + x - 20 is now monic and so much easier
pliant shore
yes, so if it's easier for you, think about dividing (3x^2 + 3x - 60) by 3
term by term, that's 3x^2 / 3 + 3x / 3 - 60 / 3
slate narwhal
because 3, 3, and 60 all have a common factor of 3
pliant shore
then you can multiply everything by 3 at the end
so the 3 goes on the outside of the brackets
keen hound
Can u use a times c method tho?
pliant shore
Can u use a times c method tho?
there's no need to here
if you can factor x^2 + x - 20, you can factor 3 times that
keen hound
But can you?
pliant shore
you can
keen hound
Can u show me that way
pliant shore
Can u show me that way
why do you want the harder way?
keen hound
Cuz its the way my teacher taught us and for a future test that might be the only solution he accepts
pliant shore
I feel your teacher wants you to use your brain more than anything
that if there's an easier way, you should just use that instead
vivid walrus
But can you?
i mean u can but it's gonna give u a lot of time to figure out the big two numbers and that takes forever
cold herald
lebron lebron lebron james
keen hound
Nah he only accepts A times C method i think
cold herald
lebron lebron lebron james
tired walrus
Cuz its the way my teacher taught us and for a future test that might be the onl...
is your teacher known to reject solutions that don't follow his methods to the letter?
keen hound
And i dont know if i can factor it efficiently or constantly without using A and C
tired walrus
like did that happen before?
severe canyon
What do u do when A isnt equal to 1
Also from here it seems you have learnt the method only with monic quadratics. So you have to factor out the 3 if you want to use the method that has a=1
keen hound
is your teacher known to reject solutions that don't follow his methods to the l...
Idk
Besides i find A times C easier
severe canyon
<@&268886789983436800>
cold herald
oops
keen hound
a _3_ can be factored out
Wait so if they all have the same common factor u can do that instead?
pliant shore
Wait so if they all have the same common factor u can do that instead?
exactly!
slate narwhal
yeah. in this case you can factor out a 4 from everything
valid carbon
<@&268886789983436800>
what happened here
tired walrus
Wait so if they all have the same common factor u can do that instead?
sure you can
severe canyon
So lets say 4x-4+44
This is not a quadratic, though 🤔
tired walrus
unless you're paralyzed by the fear it might not be considered kosher by your teacher
with which i cant help you
keen hound
So if EVERYTHING in the equation is a common factor u can just make it equal to 1?
severe canyon
Wdym you can make it?
valid carbon
...no
keen hound
If they have the same common factor u can just make the leading coefficient equal to 1?
Like can u just factor it to 1
severe canyon
what happened here
Just a spammer, started from #help-36 message and #help-36 message
severe canyon
If they have the same common factor u can just make the leading coefficient equa...
You have a really bad wording, even if I believe you have the right idea in your mind
You don't make anything
keen hound
They all have the same gcf of 3 right?
severe canyon
You don't make anything
You only factor out
keen hound
So u can just factor out a 1 from the 3x2
pliant shore
for example, if I have 8x^2 + 10x + 12
I can only factor this as 2(4x^2 + 5x + 6)
and then you would have to just go with 4x^2 + 5x + 6
there's no factorisation that is simpler
keen hound
leaving 3(x^2 + x - 20)
Does it have to be 3(x2+x-20) or can i remove the 3?
Then what did ann do at the start?
tired walrus
you can't thanos-snap the three, no.
keen hound
What did u do with the first one tho
tired walrus
i pulled it out as a common factor
keen hound
So u can pull out 4x-4+44?
severe canyon
????
final tangle
yes
as mentioned last time
it'll just be a pain if you do it directly
which is why everyone is recommending that if you can factor something out,
in this case 3,
you should do that first
keen hound
But can u try tho
keen hound
which is why everyone is recommending that if you can factor something out,
in t...
Yea but what if i cant factor something out
final tangle
then go with ac with what you have
common factor is the first thing you should always look for when factorising
final tangle
i know it'd work, i'd prefer not to
keen hound
But then u have to find a number that multiplies to 180 and adds up to 3
final tangle
multiplies to -180
keen hound
And i asked chat gpt but it said theres no real number for that
keen hound
multiplies to -180
Yea
keen hound
Then u js gotta do groupings
keen hound
missing those x
Yea but il add them at the end
final tangle
no
slate narwhal
you have to add them here
final tangle
you keep them present throughout
slate narwhal
otherwise it looks like you're adding and subtracting numbers
keen hound
you keep them present throughout
Theyre absent in the paper but present in my mind
slate narwhal
examiners can't read your mind
final tangle
make them present on the paper
keen hound
But u js gotta factor by groupings now
keen hound
examiners can't read your mind
My mind propells to the paper
final tangle
make sure they're present on the paper before you do
and i'll refuse to continue unless they are
keen hound
Yea il remember
valid carbon
But u js gotta factor by groupings now
you cant if you dont write your x's
keen hound
So 3x^2+15x-12x-60
final tangle
ok good,
keen hound
Then divide or find out the common factor
final tangle
now as I've also said yesterday/last time
this step ALSO requires factoring out common factor
which if you know how, would've been more ideal if you did it at the very start
keen hound
Its js 3x^2 divide by 15x=5x and 12x divide by 60 is 5x
What do u do when u cant factor/divide them tho
valid carbon
Its js 3x^2 divide by 15x=5x and 12x divide by 60 is 5x
so none of that is true
keen hound
Wdym
severe canyon
He means you wrote wrong statements
severe canyon
Its js 3x^2 divide by 15x=5x and 12x divide by 60 is 5x
These are wrong 🤷♂️
valid carbon
even if i squint and misread the first in a way that makes it seem right, the second is still wrong
keen hound
Oh wait u cant do both x+5 right
valid carbon
Oh wait u cant do both x+5 right
those are wrong because $\frac{3x^2}{15x}$ is like $\frac3{15}x$.
soft zealotBOT
Percy
valid carbon
note that 3/15 is not 5
keen hound
(3x^2+15)
gritty prawn
what's this about? I can probably try helping ^^
final tangle
where did the x on the 15x go
valid carbon
what's this about? I can probably try helping ^^
quadratic factorisation
gritty prawn
quadratic factorisation
ahh
Honestly if you wanna make it easy, I usually divide the quadratic to a much way more simpler form
slate narwhal
Honestly if you wanna make it easy, I usually divide the quadratic to a much way...
been raised to OP
valid carbon
Honestly if you wanna make it easy, I usually divide the quadratic to a much way...
for some reason he does not wanna factor out the gcd lol
keen hound
So should the full equation be (3x^2+15)(-12x-60)
gritty prawn
for some reason he does not wanna factor out the gcd lol
yikes
keen hound
for some reason he does not wanna factor out the gcd lol
Whats a gcd
slate narwhal
So should the full equation be (3x^2+15)(-12x-60)
no. for sure no.
expanding this gives you a cubic
valid carbon
So should the full equation be (3x^2+15)(-12x-60)
thats a cubic
valid carbon
Whats a gcd
hcf
keen hound
This is a times c method tho
severe canyon
Not at all
keen hound
3 times 60 is 180 and find number that multiplies to -180 and adds to 3
gritty prawn
This is a times c method tho
Bro trust me, divide it that equation by 3
And from there, you can use that times C method
keen hound
Which is 15-12
severe canyon
Which referring to what??
keen hound
Bro trust me, divide it that equation by 3
And from there, you can use that time...
Yea but what im getting at is when i know whether or not to use a times c or divide it by 3 first
final tangle
and the grouping stage requires you to know common factor
gritty prawn
Yea but what im getting at is when i know whether or not to use a times c or div...
I usually do it by dividing first, then factorizing it
slate narwhal
you know... if you had factored out a 3, your a times c would become a multiplication to -20 and an addition to 1...
which is way smaller than what you have now, isn't it?
gritty prawn
you know... if you had factored out a 3, your a times c would become a multiplic...
This.
final tangle
you can use whatever valid method
keen hound
I usually do it by dividing first, then factorizing it
No like give me a problem and how do u know whether or not if u can divide it or a times c
final tangle
these are all justified by algebra
valid carbon
you are still using ac even if you factor out...
severe canyon
The common factor is 3
Then why do you not want to factor it out? 
final tangle
you can always do either
keen hound
Then why do you not want to factor it out? <:cat_happycry:636407813144576010> <:...
Huh
Like 3 divide by 15
final tangle
sometimes its better to apply one first over the other
valid carbon
Like 3 divide by 15
NO
keen hound
Wait everyone stop
valid carbon
15 divided by 3
keen hound
How do u know if u can divide it?
valid carbon
why do you have your divisions backwards
gritty prawn
No like give me a problem and how do u know whether or not if u can divide it or...
I'll take your question
3x^2 + 3x - 60
I divide the quadratic, which is A B and C by three
3(x^2 + x - 20)
keen hound
Like everyone told me to divide it by 3 or factor it by 3 but how do u know when
severe canyon
why do you have your divisions backwards
Let's hope it's language issue
keen hound
why do you have your divisions backwards
Cuz i rise from the bottom all the way to the top
gritty prawn
Cuz i rise from the bottom all the way to the top
Huh?
valid carbon
I'll take your question
3x^2 + 3x - 60
I divide the quadratic, which is A B an...
try not to have your x become an X
severe canyon
Cuz i rise from the bottom all the way to the top
What does this even mean?
valid carbon
What does this even mean?
song lyrics id gues
gritty prawn
~~try not to have your x become an X~~
oh yea, different things
final tangle
Like everyone told me to divide it by 3 or factor it by 3 but how do u know when
you can do it if you can identify there's a common factor between all terms
final tangle
if you can see that 3,3,60 has a common factor of 3, you should factor 3 out to make life easier for yourself
valid carbon
yes
gritty prawn
Now here we cant divide it right or factor it?
If it's this case, then yes, you should do the A x C method
valid carbon
OP needs to learn about gcds.
keen hound
So if the equation given to me has a common factor i should factor it?
final tangle
yes
gritty prawn
Definitely
final tangle
common factor is the first thing to look for for factorisation
gritty prawn
It'll ease your work, as you have smaller numbers
final tangle
in pretty much all cases
not limited to just quadratics, in pretty much everything in the future
keen hound
Ok so lets focus on this now what do u get when u factor it?
gritty prawn
Ok so lets focus on this now what do u get when u factor it?
x^2 + x - 20
valid carbon
x^2 + x - 20
3(x^2+x-20)*
gritty prawn
3(x^2+x-20)*
ye this, my bad
keen hound
3(x^2+x-20)*
What happens to the 3 tho
keen hound
Like do u just do a times c then add a 3 at the end?
valid carbon
Like do u just do a times c then add a 3 at the end?
multiply.
keen hound
Multiply everything by 3?
keen hound
3(x^2+x-20)*
Wait so now i can do a times c?
valid carbon
yes.
keen hound
Does the leading coefficient not equal to 1?
valid carbon
it is
keen hound
Or is it bc its squared
keen hound
If its equal to 1 shouldnt u do sum and product?
severe canyon
Now you have to focus ONLY on the x² + x - 20
severe canyon
If its equal to 1 shouldnt u do sum and product?
Sure
keen hound
So b equals to x
severe canyon
No no
severe canyon
A, b, c are numbers!!
keen hound
A, b, c are numbers!!
Wdym
severe canyon
Oh wait b=1
Yep
keen hound
I just used A meaning that the first one is equal to 1 and B is the second one
So A=1 B=1 C=20
severe canyon
So A=1 B=1 C=20
C is **-**20
keen hound
Yea mb
gritty prawn
So A=1 B=1 C=20
Don't forget the signs of the positive / negative
severe canyon
There you go, awesome
keen hound
Where does the 3 go
gritty prawn
So (x+5)(x-4)
Yep! That's the factor of the x^2 + x - 20
severe canyon
Yep!
keen hound
Aight fosho
gritty prawn
Well done, that's how you do it ^^
severe canyon
It doesn't get deleted
final tangle
these don't get deleted.
make a message link and keep it somewhere
final tangle
or copy the important notes you got from here
keen hound
Aight fosho thanks guys
severe canyon
I recommend you to copy the link of your first message
keen hound
or copy the important notes you got from here
Everything here was important
severe canyon
https://discord.com/channels/268882317391429632/908076393198419988
Otherwise this redirects you just to the chat and you'll have to scroll until you find this conversation
valid carbon
https://discord.com/channels/268882317391429632/908076393198419988
channel link will be useless
severe canyon
https://discord.com/channels/268882317391429632/908076393198419988/1413083197687...
But copy this somewhere, not here
keen hound
Yea i copied it
severe canyon
Awesome 👍
plucky rover
Yall can close this now
!done
final saddleBOT
Yall can close this now
If you are done with this channel, please mark your problem as solved by typing .close
keen hound
.close
final saddleBOT
final saddleBOT
Available help channel!
left trail
what is wrong with desmos?
final saddleBOT
what is wrong with desmos?
trail crest
Probably worked with square root, then approximated it. Then thats error
left trail
but how was is it able to get it correct when I used it to see what an equation with sin and cos evulatled to
trail crest
You mean when using the sin(3x) formula?
$$\cos \frac{\pi}{6} = \frac{\sqrt{3}}{2}$$
soft zealotBOT
casework
trail crest
Those are number bigger than what you get before
Like if desmos calculated 1 + 4e-16 it will just say its 1
If it calculates 4e-16 now its not it will give you that
left trail
Those are number bigger than what you get before
wdym?
by before do you mean the stuff in the first picture?
trail crest
what is wrong with desmos?
This is
0.0000000000000004
(If i didnst miss any zero)
Desmos was correct for first 15 decimals or so
left trail
Lean?
trail crest
And so is here. But it doesnt show you
left trail
oh so your saying sometimes it rewrites it strangely but sometimes not?
trail crest
I mean it rounds in some way. Idk what
But it surely doesnt compute the whole sqrt{3}
left trail
ok I see
gritty drift
Just a floating point error
trail crest
what is wrong with desmos?
Idk why it didnt round to zero here
gritty drift
Happens when you have transcendental functions since it uses their Taylor approximation
No way to exactly establish why it happens for some cases but not others since all calculators are programmed differently
left trail
.close
final saddleBOT
final saddleBOT
Available help channel!
nocturne agate
my problem isnt solved yet.
final saddleBOT
my problem isnt solved yet.
nocturne agate
Sry, what is "fire" here?
Fire/candy is a type of pet.
The pets all come in different types and rarities.
Fire/candy pets only spawn in during a fire or candy event. This fire or candy event is only active 15 minutes past every hour of a "normal" event.
The pets only spawn in as normal, gold, crystal and rainbow during the "normal" event for the first hour.
1 hour runtime normal
15 minutes special event
1 hour runtime normal
15 minutes special event
etc...
versed crater
Are you here @nocturne agate
slate narwhal
from what i gather, the projected wait times are calculated from the probabiliti...
i think this question still stands
on top of the fact that you should probably restate your problem
nocturne agate
from what i gather, the projected wait times are calculated from the probabiliti...
Yes. the wait time is based on a rate of 675 pets per hour. Based on the probability of each pet type and rarity.
These are the projected wait times i was given for a special event.
Rarity Minutes per drop H:M:S
Normal Special(fire/candy)
Common 0.583 0:00:35
Rare 1.394 0:01:23
Epic 3.950 0:03:57
Legendary 10.15 0:10:09
Mythic 47.43 0:47:26
Supreme 142.3 2:22:18
Secret 2,845.8 47:25:48
In no way shape or form is a secret pet dropping every 47 hours. I have played the game over 250hrs and have only gotten 1 event pet.
versed crater
Okay hold up
nocturne agate
Are you here <@401521413456003095>
yes
versed crater
Can you describe the set up of this a bit more
Like what makes a pet drop, how does one wait, are there restrictions, do some times matter more than other etc
Are there bonuses or something
slate narwhal
so 675 pets per hour, combined with the probability of dropping a pet, gives you this projected wait time chart?
versed crater
Is it like there’s a clock and every second there is a chance for an event to occur (a drop) and then bla bla bla
slate narwhal
but... the event only runs 15 minutes for every 75 minutes
did you take that into account?
versed crater
You should describe this more carefully because I feel like I’m getting xy’d
nocturne agate
You should describe this more carefully because I feel like I’m getting xy’d
i will
slate narwhal
maybe start from how a pet is dropped
versed crater
Don’t talk about your projected or estimated probabilities yet
That has to do with statistics we’ll worry about that later
nocturne agate
The game involves collecting pets of different types and rarities There is a wall in front of you with a tunnel. From that tunnel pets will spawn randomly. They just walk out of it. The rate at which they walk out is 675 per hour. Or roughly 1 pet spawning randomly every 5.5 sec.
All you do is collect the pets you are missing untill you have filled out the pet rarities for each type of category.
There are 6 types of pets.
Normal
Gold
Crystal
Candy
Fire
Rainbow
There are 7 types of rarities
Common
Rare
Epic
Legendary
Mythic
Supreme
Secret
Everytime you play the game, you spawn in front of the tunnel that has spawned 0 pets until you load in. You sit in front of the tunnel and wait for pets that you dont have to collect and sell.
under "normal" conditions. (lets just call it "normal event").
Only Normal, Gold, Crystal, Rainbow will spawn out of the tunnel every hour. You can acquire a Normal, Gold, Crystal, Rainbow pet of any of the 7 rarities.
After every hour is finished you have a "special event" that runs for 15 minutes. This special event is going to fire OR candy. It alternates back and forth based on the previous special event. If you just load into the game you have a 50/50 chance of it being fire or candy.
During this special event, the pets spawn at the same rate.
You can still acquire pets of all 7 rarities BUT, the pet types alternate between only:
Normal type and Fire type (if its a fire event)
or
Normal type and Candy type (if its a candy event)
During these special events, The pets will ALWAYS walk out in a line as 1 normal type, and 1 candy/fire type.
After 15 minutes have passed the special event is over and we return back to the 1 hour long "normal event" and the cycle repeats.
slate narwhal
is that all we need to know?
versed crater
What does during a special event, …walk out in a line as 1 normal type and 1 candy/fire type
Like alternating or like side by side 2 at a time
nocturne agate
is that all we need to know?
No there are some modifiers but those arent taken into consideration of the probability. For example there are 3 timers with 3 rarities that will countdown to 0. And when they do It will spit out a pet of the rarity on the timer but of a random type. I am not taking this into consideration because it is a 100% guarantee, not a probability.
There is also a spin wheel, which works the opposite. You spin a wheel with different pet types on it. It will change the pet thats in "limbo" and hasnt spawned yet, into whatever type category the spin wheel lands on. I did not take this into consideration because it is not probability unless you interact with it.
versed crater
No there are some modifiers but those arent taken into consideration of the prob...
Deterministic things are random things with 0 variance
slate narwhal
No there are some modifiers but those arent taken into consideration of the prob...
that affects times too...
versed crater
So what do we want to calculate from this set up
nocturne agate
What does during a special event, …walk out in a line as 1 normal type and 1 can...
The pets all march out of the tunnel in a straight line. in both normal and special events.
During the normal event the associated types and rarities will spawn randomly, as previously described.
During the special event they will always walk out as 1 normal 1 fire 1 normal 1 fire 1 normal 1 fire etc
nocturne agate
that affects times too...
they do but only slightly, since im not counting the guaranteeds into probability. Estimated only around 5 guaranteed pets or 25 seconds of lost time.
versed crater
What is a normal event
nocturne agate
normal conditions
under "normal" conditions. (lets just call it "normal event").
Only Normal, Gold, Crystal, Rainbow will spawn out of the tunnel every hour. You can acquire a Normal, Gold, Crystal, Rainbow pet of any of the 7 rarities.
versed crater
So no event
nocturne agate
no but the normal conditions only last an hour at which point they change to special event
versed crater
Like it’s either special event or normal conditions
nocturne agate
yes
versed crater
So normal conditions is just when there’s no special event
nocturne agate
yes
nocturne agate
The probabilites and estimated wait times for all pet rarities and types
versed crater
Okay
And is it true that during the special event, you get 1 normal 1 fire 1 normal etc
So you can’t get the non normal non fire types
nocturne agate
true
0% chance of a gold, crystal, rainbow and depending on the special event. The opposite event type.
versed crater
Right
nocturne agate
(if its a fire event 0% chance of getting a candy)
versed crater
my problem isnt solved yet.
Ok now what is this
Presumably you sat there for hours and looked at the totals you got?
nocturne agate
Yes i sat there and counted all the pet rarities and types that came out of the tunnel for every hour. Then i averaged them.
This gave me the base probability of both the type and rarity for normal conditions
versed crater
Yes i sat there and counted all the pet rarities and types that came out of the ...
How many were there in total?
nocturne agate
675 every hour (rounded)
versed crater
As in can you put them in count instead of in %
nocturne agate
versed crater
Yes i sat there and counted all the pet rarities and types that came out of the ...
This is 1 hour?
nocturne agate
yes
versed crater
Do you have more data than 1 hour
nocturne agate
only 2 hours
versed crater
The estimation for the higher rarity ones will be very poor
With the data you have
nocturne agate
yes i know
versed crater
Is that a concern?
nocturne agate
slate narwhal
so if in 2 hours you didn't get a single secret, how did you got the probability for the secret pets?
nocturne agate
Because secret pet data would take an ungodly amount of hours to record it is estimated based on my and several others opinions
Those of us who have acquired secret pets
versed crater
Would you be interested in combining some of these together into 1 bucket
Like putting legendary mythic supreme and secret together into 1 category
nocturne agate
I dont think that will work well because the difference in probabilities between them is so large
versed crater
No but it’ll give a better estimate
nocturne agate
Using the previous probabilities i came up with these numbers for the normal event.
I can agree with these numbers for the most part. The problem i have is when i try to get the numbers for the special event.
what i want to understand is what i should be doing to calculate the probability, drop rate, and wait time for the special event. Because from what ive calculated it seems wrong.
versed crater
Using the previous probabilities i came up with these numbers for the normal eve...
is this for the special event?
nocturne agate
no this table is for normal event
versed crater
ah you're saying these numbers here you can understand
versed crater
okay what data have u got for the special events
i assume you have at least 1 data set for fire and 1 for candy?
nocturne agate
none
-
Because the probability of rarity would still remain the same for the event.
-
Because only normal and (special event) type spawn during the special event. the probability of type would be 50/50?
Wouldnt it not matter if only 150 pets come out during the 15minutes compared to 675 during the 1 hour? The probability of rarity would remain the same if only 1 pet comes out compared to 1000?
versed crater
do you know if this is true?
versed crater
Wouldnt it not matter if only 150 pets come out during the 15minutes compared to...
i dont understand this
versed crater
Wouldnt it not matter if only 150 pets come out during the 15minutes compared to...
it's different for estimation if you dont know that the probabilities are the same
nocturne agate
I dont know it to be true because i didnt create the game.
I am saying that just because the special event is shorter in time, and doesnt produce 675 pets like the normal event does, doesnt mean it changes the base probability.
I would still expect to the see these rarity probabilites for the special event, even if it only produces 150 pets during 15mins
(minus the type since only normal and special come out then the probability would 50/50)
50%
final saddleBOT
@nocturne agate Has your question been resolved?
slate narwhal
well, i think GPT may have misunderstood you
nocturne agate
Wouldnt it be x5 longer since its 15 mins past each hour not during
slate narwhal
the event is only active 20% of the time, isn't it? it's 60+15 minutes from what i understood
so really we are talking 15 minutes out of every 75 minutes
nocturne agate
yes
slate narwhal
so ultimately, special event or not, the rarity drop rate does not change, correct?
so rarity is independent of type?
nocturne agate
yes (assumption)
I am also confused about the 50/50 drop rate during the special event. Is it really 50/50 (50% chance) when the pets are always alternating?
slate narwhal
i don't know, i don't play the game. it seems like (from your own description anyway) that the pets will always alternate between normal and the special type during the special period
i'm working entirely based off your description
nocturne agate
i don't know, i don't play the game. it seems like (from your own description an...
correct.
wouldnt 50% pet chance mean that when every pet spawns it has a 50% chance of being either. That would mean i would eventually see maybe two fire pets come out or two normal pets come out in a row but that never happens. They always alternate so is that really 50% chance?
slate narwhal
yes. it's still random, but determined, i suppose
either way, the type isn't gonna help us here if my understanding is correct
nocturne agate
but i am basing my wait times off of half of the base probability because its supposedly 50/50 chance
slate narwhal
Using the previous probabilities i came up with these numbers for the normal eve...
wait. you said the type and rarity are independent, correct? then there's quite the difference between a secret normal and a secret pet of any other type if this table is correct
in fact, why is a rainbow common only 0.61% when a normal common is 55.15%?
dusty quarry
I dont know it to be true because i didnt create the game.
I am saying that ju...
i think we can just work off this table
slate narwhal
but i am basing my wait times off of half of the base probability because its su...
but that 50/50 chance only applies to types
nocturne agate
i calculated the probability independently. This is my counter for 1 hour.
For the hour whenever a rare gold would come out, i would tick two boxes, 1 for gold and 1 for rare.
At the end when i calculated the base probability. I calculated the rarity percentages independently of the types.
which gave me this.
both of these percentages are out of 675 pets
slate narwhal
you're looking for rarities
and as mentioned by you, rarity is independent of type
so we still have a bit of confusion regarding the true probability of a secret if that's the case.
because we have no data on it
nocturne agate
yes basically none (estimated)
slate narwhal
i see a couple of things here.
one, and the most likely, is that because we have insufficient data, the probability of getting a secret pet is incorrectly estimated
and is much lower than it seems
because at 0.0125%, that's 1 in 8000. the expected time is, if i didn't fuck up my calculations, less than a day
second thing that could be happening is that special events affect the rarity probabilities