AND wait after showing you
#help-36
dusty quarry
oh and you have extra information in n
tranquil pine
Nah this question is wrong af
I don't know to do it
Neither we can chnage it into y=mc+c
Or n is given
Plus I don't know if it's 11 or 1
And if that's 2 or 12
Lets move on to next question
dusty quarry
i can't ascertain the question myself so i have no comment
magic coyote
"mom" 💀
dusty quarry
huh.
tranquil pine
Did I say smth bad ?
magic coyote
do you want to get mod pinged
tranquil pine
By mistake
What's mod pinged
No
My friend was saying that.
...
...
Is it wrong ?
Or is it bad ?
Leave it
Look at this
I'll ztrt doing this
Strt
Find slope
Step 1
And it already looks fucking weird
dusty quarry
p sure line 1's gradient doesn't have the negative sign in front
dusty quarry
?
tranquil pine
I can't do this
Its 9 pm
Im sleepy
I domt know shit
I might fail tmrw
But
Ig
Next terminal
I'll be prepared
I don't know how to do it
dusty quarry
idk man. i literally told you that line 1's gradient shouldn't have the negative sign in front of it
tranquil pine
Idk what to do
At all
Please teach someone.
How do I change that then
...
Do I exchange y and x so the sign changes?
dusty quarry
dude
tranquil pine
Yes
dusty quarry
the original equation was (2 - sqrt(3))x - y - 1 = 0
if you would just
move the y over
you'd get (2 - sqrt(3))x - 1 = y
which is the same as y = (2 - sqrt(3))x - 1
there. no negative, is there
dense coral
the goal is to the two lines in slope intercept form and then compare the slopes
two slopes that are negative reciprocals of each other are perpendicular
dense coral
alternatively, you can take two points, one on each line, and take their dot product
tranquil pine
I need a baby explanation
dusty quarry
m1 x m2 = -1
you now have m1
you have m2
find their product
if it's -1, congrats, they are perpendicular
that's all
tranquil pine
But m1 is in - and m2 is in -
dense coral
I need a baby explanation
the slopes y = 5x and y = -1/5 x are perpendicular because 5 and -1/5 are negative reciprocals of each other
dusty quarry
But m1 is in - and m2 is in -
.
dense coral
But m1 is in - and m2 is in -
they are not
dusty quarry
which is the same as y = (2 - sqrt(3))x - 1
^
dense coral
you’ve rearranged incorrectly 
dusty quarry
i've even rearranged line 1 for you good sir
you just need to put those two gradients in a calculator now
tranquil pine
which is the same as y = (2 - sqrt(3))x - 1
Trivial
which is the same as y = (2 - sqrt(3))x - 1trivial
which is the same as y = (2 - sqrt(3))x - 1 trivial
!trivial
Trivia
What.
dusty quarry
you say you're sleepy and lack time
tranquil pine
Ye
dusty quarry
yet instead of focusing on your problem you're wasting time here typing random words
tranquil pine
So what
dusty quarry
it's 11:21pm for me
dusty quarry
finish your work.
dense coral
if you need to take a break, White Leaf, I encourage you to do that
tranquil pine
There are many helpers
I'm already cooked enough loosing half eyesight playing games
I don't need rest now
dense coral
sometimes you just need a half hour off and then it makes sense when you come back
tranquil pine
I just need to work hard everyday like it'd my last day
tranquil pine
sometimes you just need a half hour off and then it makes sense when you come ba...
And what so we do for half and hour?
tranquil pine
All I can think of is scrolling.
tranquil pine
They would probably think I'll go do bad stuff
I desire
How
It is
Or to chnage it to positive
dense coral
let me open my laptop so this is easier for me 
dense coral
gimme 4min
tranquil pine
Me to recipoal
Sure
So
2-root 3 -1
Mhm
So does that mean
If we chnage value of c
It's a recipocal
And the value of sign of m and x chngae ?
tranquil pine
But u did -1
dusty quarry
yeah. m1 x m2 = -1
(gradient of line 1) x (gradient of line 2) = -1
there's no c involved
dense coral
okay, I'm back
tranquil pine
-(2-rooot 3) ?
dense coral
,, (2 - \sqrt{3})x - y - 1 = 0 \ (\sqrt{3} + 2)x + y = -5
soft zealotBOT
higher!
tranquil pine
**higher!**
It ain't loading
dense coral
let's take this from the top
tranquil pine
Sufe
dense coral
It ain't loading
dense coral
our lines are currently in standard form
tranquil pine
Yes
dense coral
Ax + By + C = 0
dense coral
I uh, don't know what that means 
dense coral
I want you to focus more on rearranging the equations rather than using formulae
dense coral
because the rearrangement is why the formulae exist at all
tranquil pine
Oh oh
dense coral
,, (2 - \sqrt{3})x - y - 1 = 0
soft zealotBOT
higher!
dense coral
so we have this line 
tranquil pine
Yes
dense coral
we want to write it in the form y = mx + b
tranquil pine
Ik
dense coral
as of right now, y is stuck with the x term and the constant term
we want it by itself
tranquil pine
-y ?
dense coral
can you show me how you deduced that?
dense coral
sure, that works
alternatively, you can move y to the other side and change it's sign
but what's really going on is that we're adding terms to both sides 
dense coral
,, (2 - \sqrt{3})x - y - 1 + \color{red}y \color{black}= 0 + \color{red}y
tranquil pine
We got slope
soft zealotBOT
higher!
tranquil pine
Wait
dense coral
on the left hand side, the -y and +y cancel out
tranquil pine
Can
You
Tell me
How there are 2 ys
Since
All we did was
Take one to other side
dense coral
Take one to other side
"taking y to the other side and changing signs" is a shortcut
tranquil pine
Can't we stick to the short cut ?
dense coral
what's really going on is that we're adding +y to both sides, and then simplifying
dense coral
Can't we stick to the short cut ?
yes, but I want to make it clear what's going on
we can use the shortcut from here on out
after you move y to the other side, we have...
tranquil pine
Why u using so many emoji
dense coral
,, (2 - \sqrt{3})x - 1 = y
soft zealotBOT
higher!
dense coral
Why u using so many emoji
that's a me thing, sorry :p
dense coral
**higher!**
,, y = (2 - \sqrt{3})x - 1
tranquil pine
In just too tired to focua
soft zealotBOT
higher!
tranquil pine
Bit I do get u
tranquil pine
Wait
How did u do that for the second one
Did u do the first line or second line ?
I thi k this is just the fire line
soft zealotBOT
higher!
tranquil pine
Shift?
dense coral
same idea as before; what should we do? 
tranquil pine
I think
-(root3 +2
And if
We
Chnage sig
And do here and there
We could get
(2+root 3 ?
dense coral
it's a little hard to follow what you mean, but I think you've applied the sign change incorrectly
dense coral
well, I'll show you what happens without the shortcut
because I think it's more constructive
tranquil pine
Ok
dense coral
,, (\sqrt{3} + 2)x + y \color{red} - (\sqrt{3} + 2)x \color{black} = -5 \color{red} - (\sqrt{3} + 2)x
soft zealotBOT
higher!
dense coral
doing it slowly, without the shortcut, helps us keep track of the sign more easily
dense coral
Now do next step sir.
so you know that the left hand side is just y now
on the right hand side, we'd like to write it in the form m_2x + b_2
so we just simplify
tranquil pine
Wait
dense coral
,, y = -(\sqrt{3} + 2)x - 5
tranquil pine
Did we just
soft zealotBOT
higher!
dense coral
are we on the same page?
soft zealotBOT
higher!
dense coral
these are our two lines, in slope intercept form
dense coral
to show that they're perpendicular, we need to show that m_1 and m_2 are negative reciprocals of each other
dense coral
there're multiple things you could do to show this
you could divide one by the other and show that we get -1
you could also choose one of them, multiply it by -1, flip the fraction, and then see if we get the other
dense coral
these are both valid steps
dense coral
Multiply =-1
oh actually, this might be correct 
my preference isn't to multiply or divide
dense coral
you could also choose one of them, multiply it by -1, flip the fraction, and the...
it's to do this
dense coral
you could also choose one of them, multiply it by -1, flip the fraction, and the...
I still prefer this method though, because it doesn't confuse me
tranquil pine
Thanks
stiff briar
Can someone try this question and explain it to me
It is form arithmetic progression
shrewd nexus
you should create your own help ticket
dense coral
Can someone try this question and explain it to me
It is form arithmetic progre...
hi there! welcome to the mathcord!
unfortunately, you gotta open your own help channel
magic coyote
Can someone try this question and explain it to me
It is form arithmetic progre...
!occupied
final saddleBOT
Can someone try this question and explain it to me
It is form arithmetic progre...
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
dense coral
this one is occupied
final saddleBOT
dense coral
@shrewd nexus welcome to the mathcord too c:
stiff briar
Sorry I am freshie
I had not seen all instruct
shrewd nexus
Thank you! :)
final saddleBOT
Available help channel!
dull grotto
In an acute triangle ABC, let I and G be its incenter and centroid. Let I ≠ G and IG || BC. Let r be the radius of incircle. Prove that the distance from A to BC is 3r.
final saddleBOT
In an acute triangle ABC, let I and G be its incenter and centroid. Let I ≠ G an...
dull grotto
How do i prove this? Do i use the centroid 2 : 1 property?
Another tool: the distance from G to BC is r
tired walrus
making a diagram can't hurt, right
dull grotto
k sure
severe verge
How do i prove this? Do i use the centroid 2 : 1 property?
yep
drop the perpendicular from A and you'll see
severe verge
ye
dull grotto
hmm
dull grotto
got it
AHM = GEM = 90
AMH = GME
so they are similar
Using the property of the centroid AG/GM = 2/1
so AM/GM = 3/1 = AH/GE
3 = AH/r
so AH = 3r
alr ty
.close
final saddleBOT
final saddleBOT
Available help channel!
winged bobcat
why is it that
suppose T: V->W
if we split a vector space using direct sums as V = V_0 + ker(T)
then
p: V_0 -> im T
is an isomorphism
final saddleBOT
why is it that
suppose T: V->W
if we split a vector space using direct sums as V...
winged bobcat
show that p is injective by taking an element of ker p and showing that it is {0}
this is what my friend told me
I dont know how to do this
reef depot
why is it that
suppose T: V->W
if we split a vector space using direct sums as V...
You want the proof?
Have you thought of anything for this yet?
winged bobcat
i dont really understand the statement
reef depot
V = V_0 + ker(T) means V = {v\in V | v = v_0 + u for v_0 in V_0 and u in ker(T)}
V_0 is some other vector spce.
Do you know what the kernel is?
winged bobcat
yes
worthy wren
i dont really understand the statement
take v in ker(p). Is v an element of ker(T) as well?
winged bobcat
maybe
worthy wren
we need to realize that p is just a restriction on T
everything p maps is the same as what T maps for that domain
reef depot
Do you know what the kernel of an isomorphism is?
winged bobcat
okay so yes
winged bobcat
Do you know what the kernel of an isomorphism is?
i know kernel of linear maps
worthy wren
is ker(p) in V_0?
winged bobcat
yes
winged bobcat
v is in ker(p) so v is in V_0
worthy wren
and?
worthy wren
take v in ker(p). Is v an element of ker(T) as well?
.
worthy wren
direct sum hypothesis
winged bobcat
thank you!
worthy wren
do you know how to show surjectivity?
final saddleBOT
wet acorn
can anyone help me with some homework
Let
𝑓
(
𝑥
)
{
𝑥
2
sin
(
1
𝑥
)
,
𝑥
≠
0
0
,
𝑥
0
f(x)={
x
2
sin(
x
1
),
0,
x
=0
x=0
thats weird hold up
deep condor
i think you turned your question into a vector
magic coyote
!occupied
final saddleBOT
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
deep condor
-# oop thanks exes
reef depot
Let
𝑓
(
𝑥
)
=
{
𝑥
2
sin
(
1
𝑥
)
,
𝑥
≠
0
0
,
𝑥
=
0
f(x)={
x
2
sin(
x...
What the helly
vivid walrus
Let
𝑓
(
𝑥
)
=
{
𝑥
2
sin
(
1
𝑥
)
,
𝑥
≠
0
0
,
𝑥
=
0
f(x)={
x
2
sin(
x...
cursed
sullen gale
Let
𝑓
(
𝑥
)
=
{
𝑥
2
sin
(
1
𝑥
)
,
𝑥
≠
0
0
,
𝑥
=
0
f(x)={
x
2
sin(
x...
first, you can send a screenshot, second this help channel is not in the available category. see #❓how-to-get-help for details
final saddleBOT
Available help channel!
lethal tapir
how is the answer negative?
final saddleBOT
how is the answer negative?
tiny gorge
shouldn't the numerator be f'g - g'f, not g'f - f'g?
dapper hull
how is the answer negative?
tbh I prefer chain rule here
sage meteor
chain rule never fails :trust:
lethal tapir
shouldn't the numerator be f'g - g'f, not g'f - f'g?
ohhhh, thank you
how do ou use the chain rule for ln?
im new to it
tiny gorge
btw you can also do a quick sanity check in this case to see why the sign is wrong... you know that ln(x) is increasing, so 1/ln(x) is decreasing, so its derivative should be negative
sage meteor
how do ou use the chain rule for ln?
erm d(1/ln)dx= d(1/ln)/dln * dln / dx something so
dapper hull
how do ou use the chain rule for ln?
for any composite function
f(g) it’s derivative is equal to
f'(g)*g'
In this case g is lnx and f is x^-1
lethal tapir
btw you can also do a quick sanity check in this case to see why the sign is wro...
So if ln(x) was in the numerator, it would be increasing?
astral fulcrum
guys im going into 8th grade and doing algebra 2 next year how do I learn it this summer so next year I have a smooth year in math.
tiny gorge
So if ln(x) was in the numerator, it would be increasing?
yep!
sullen gale
guys im going into 8th grade and doing algebra 2 next year how do I learn it thi...
!occupied
final saddleBOT
guys im going into 8th grade and doing algebra 2 next year how do I learn it thi...
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
tiny gorge
guys im going into 8th grade and doing algebra 2 next year how do I learn it thi...
try asking in #math-discussion
lethal tapir
ok, thank you guys
dapper hull
it’s .close
final saddleBOT
final saddleBOT
Available help channel!
ancient ice
peak wing
.reopen
floral drift
final saddleBOT
sullen gale
Yeah, that seems correct
floral drift
tyy for comfinrimng
sullen gale
!done
final saddleBOT
If you are done with this channel, please mark your problem as solved by typing .close
sullen gale
Welcome to the mathcord btw 
floral drift
.close
final saddleBOT
final saddleBOT
Available help channel!
nova jay
"on a flat surface there are 2 boxs with masses of M and m (M>m), there a force dragging m to the right like seen in the image and this whole thing is moving at an accelerating rate
describe using whats known the acceleration of the boxes and the tension of the rope thats connecting them"
final saddleBOT
"on a flat surface there are 2 boxs with masses of M and m (M>m), there a force...
terse crypt
the two boxes must be moving at the same acceleration
nova jay
yeah but somehow i got T (the force between them) to be 0
terse crypt
how
nova jay
sigmaFm = F-T = ma
a = (F-T)/m
sigmaFM = F = ma
a = F/M
terse crypt
the two boxes must be moving at the same acceleration
.
nova jay
so then F/M = (F-T)/m
terse crypt
F is applied to m
nova jay
so then then its also on M
nova jay
no
terse crypt
so is the force becuz of tension or the force
nova jay
tension?
terse crypt
yes
nova jay
and which forces are applied on m?
nova jay
not -T
terse crypt
-T, yes
terse crypt
yes
timber plume
for this question, it is confirmed
final saddleBOT
for this question, it is confirmed
timber plume
am i correct?
fiery bluff
for this question, it is confirmed
erm... the question says it is supposed to be correct to confirm
thin cloud
I don't see you check the point of inflextion but your work of checking second derivative change sign seems right
timber plume
I don't see you check the point of inflextion but your work of checking second d...
I did use the table see if its a point of inflexion
the second derivative changed sign between the inflexion point
thin cloud
Okay, but you don't have conclusion so it's kinda confusing a bit
I can't read what you wrote sorry, your handwriting is kinda bad
timber plume
alr
thin cloud
I have no idea what you trying to do after the 5th step
Oh okay
mb
you missing an x here
timber plume
oh true
thin cloud
It suppose to be 12x(x-2)=0
thin cloud
Yes
thin cloud
Seems right to me
Also we have x=2 isn't a repeated root of f''(x) so it's definitely P.O.I
timber plume
wdym
@thin cloud also is thsi correct
becuase the second derivative has not given me
an answer of 0
which means (0,0) is not a point of inflexion
thin cloud
y'' at x= 2 isn't equal to 24
final saddleBOT
@timber plume Has your question been resolved?
timber plume
oops
@thin cloud what about now
oh wait
ik the mistake
i need to do it between 0 and 2
timber plume
thin cloud
Seems right now
thin cloud
Let say we have a function f(x), and it has 2 roots with no undefined value
I will call two roots a and b and a<b
It is possible that when f(x) past through x=a, it change it sign
The same for b
But between a and b, negative infinity and a, b and positive infinity we know the sign don't change
thin cloud
Yup, it's right
timber plume
But between a and b, negative infinity and a, b and positive infinity we know th...
negative infinity and a, b and positive infinity we know the sign don't change
i dont understand this last phrase
thin cloud
A function can only change its sign when it go over its roots or where it's undefined
so If it's between 2 roots , it won't change its sign
the same if it between a root and an undefined point
or between 2 undefined point
thin cloud
Imagine it like this, while you walking forward If you want to go backward you have to slowdown
stop in a moment
and only after that you can move backward
The point when you stop is when your speed is 0, while you go with positive speed, you have to slow down to when your speed is 0 and only after that you can move with negative speed
So if a function want to change from positive or negative, It has to go over a point where it's 0 ( or where we have roots)
Actually it's also happen when the point is undefined but it's kinda hard to visualize
timber plume
where we have roots of the stationary ponts u mean?
timber plume
@thin cloud
for the first question
"a zero"
its a bit vague
on what its asking
does it mean te x intercepts?
thin cloud
I think so
timber plume
which is A,, E, G
@thin cloud I got E wrong
I only said D
well a P.O.I is defined as when it is neigther concave up nor convave up, and changes concavity
thin cloud
B and D are two possible P.O.I
timber plume
but what happens before B
thin cloud
Idk how to break down it to u, let me think
I found this online, this would be easier to visualize
Point B is where f(x)'' change from negative to positive and point D is where f(x)'' change from positive to negative
Both are inflexion point ( we assume what we saw from the diagram is true )
timber plume
@thin cloud but you know the difference between point B and D
timber plume
I found this online, this would be easier to visualize
point B doesnt relate to this this graph here
this has to be concave down
this part is fine because its concave up
timber plume
this has to be concave down
we need a concave down as well before B
thin cloud
thin cloud
we need a concave down as well before B
we don't need it
thin cloud
Remove the part like I did here and that point's still an inflexion point
timber plume
in the left side and right side of the dot, is there any concavity??
timber plume
Remove the part like I did here and that point's still an inflexion point
im confused of wym
thin cloud
in the left side and right side of the dot, is there any concavity??
It's, the left side concave up and the right side concave down
I'm not really good at explaining thing especially about inflexion point
They have never taught me inflexion point in class before 
final saddleBOT
@timber plume Has your question been resolved?
timber plume
It's, the left side concave up and the right side concave down
Oh i never knew that
Because I thought it would be in a u shape
thin cloud
Because I thought it would be in a u shape
By definition concave down is when f''(x) <0 and concave up is f''(x)>0, It doesn't relate to how the graph should shape like u shape
timber plume
By definition concave down is when f''(x) <0 and concave up is f''(x)>0, It does...
So give me like a mathematical example to back this up with
timber plume
in the left side and right side of the dot, is there any concavity??
this graph here
thin cloud
the left side is where f''(x)>0 and the right side is f''(x)<0
timber plume
the left side is where f''(x)>0 and the right side is f''(x)<0
Yea I understand that but i mean with numbers
thin cloud
Yea I understand that but i mean with numbers
wydm
timber plume
Like a specific math problem maybe
timber plume
in the left side and right side of the dot, is there any concavity??
Similar to the graph here
thin cloud
Similar to the graph here
idk dude, I haven't been taught inflexion point or concavity in school so i don't have any exercise source
timber plume
idk dude, I haven't been taught inflexion point or concavity in school so i don'...
Oh mb its okay
severe verge
idk dude, I haven't been taught inflexion point or concavity in school so i don'...
giỏi quá
xứng đáng làm sv
final saddleBOT
@timber plume Has your question been resolved?
tired walrus
!1q
final saddleBOT
It is suggested that you limit yourself to one question per help channel, opening a new one once your original question is answered and your original channel has been closed. This is to make your channel easier to follow for potential helpers and can bring attention to the fact that your question has changed.
exotic shale
By definition concave down is when f''(x) <0 and concave up is f''(x)>0, It does...
Actually definition is f' is decreasing or increasing
f''(x)>0 is just a theorem not defintion
Can be concave down without f" existing
thin cloud
Actually definition is f' is decreasing or increasing
Idk, I just self taught this topic so I didn't really study definition much
thin cloud
Actually definition is f' is decreasing or increasing
But thanks
exotic shale
Similar to the graph here
Try sinx from π to 2π
Similar to your image graph with concavity changing
fleet willow
I'm just having a hard time understanding the chain rule. I'm basically trying to learn how to find the derivatives of simple sinusoidal functions, like cos(2x).
final saddleBOT
I'm just having a hard time understanding the chain rule. I'm basically trying t...
eager shore
Do you know the statement of the chain rule?
fleet willow
no I know nothing
terse crypt
bruh
lyric obsidian
Interesting
strong atlas
can you differentiate both cos x and 2x?
lyric obsidian
I'm just having a hard time understanding the chain rule. I'm basically trying t...
Why don't you search up what it is first?
fleet willow
Why don't you search up what it is first?
chatgpt is confusing me
shrewd nexus
dont use chat gpt
strong atlas
chatgpt is confusing me
yeah it's not really the best way to learn from
dusty quarry
chatgpt is confusing me
!nogpt
final saddleBOT
chatgpt is confusing me
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
strong atlas
I just asked chatgpt who gave two different answers with 2 methods and i pointed that out, they decided that the wrong method was the right one
terse crypt
For ${f(g(x))}$
[ \frac{\dd}{\dd x}(f(g(x)) = \frac{\dd f}{\dd g} \frac{\dd g}{\dd x}]
soft zealotBOT
k
terse crypt
have u seen this before
lyric obsidian
chatgpt is confusing me
You kinda didn't answer my question
dusty quarry
how did the derivative fly to the right
eager shore
For ${f(g(x))}$
\[ \frac{\dd}{\dd x}(f(g(x)) = \frac{\dd f}{\dd g} \frac{\dd g}{...
\dv{f}{x} is faster :P
soft zealotBOT
;(
eager shore
hyperparenthetosis
terse crypt
[ D_x f]
soft zealotBOT
k
dusty quarry
i wonder if it would help if i gave you an example
then you show me how to get it
using the chain rule
lyric obsidian
can you guys do an example rq with this
I can, but I don't know how to format it properly
I'll just use the other notation
terse crypt
Let ${f(x) = x^2}$, ${g(x) = 2x}$. So, ${f(g(x)) = (2x)^2}$. Using chain rule,
[ \frac{\dd}{\dd x}(2x^2) = \frac{\dd f}{\dd g} \frac{\dd g}{\dd x} = 2(2x) \cdot 2 = 8x]
lyric obsidian
$\dv{x}\cos(x^2)=\dv{(\cos(x^2))}{x^2}\cdot\dv{(x^2)}{x}=-\sin(x^2)\cdot (2x)$
terse crypt
this is wrong
soft zealotBOT
k
magic coyote
Too many cooks in the kitchen
dusty quarry
i'll watch for now
soft zealotBOT
;(
old quarry
Too many cooks in the kitchen
ive heard it makes the broth better
fleet willow
so the derivative of cos(x^2) = -2x(sin(x^2))?
terse crypt
yes
final saddleBOT
lyric obsidian
so the derivative of cos(x^2) = -2x(sin(x^2))?
Yes
final saddleBOT
Available help channel!
final saddleBOT
final saddleBOT
tame eagle
.close
final saddleBOT
Available help channel!
terse crypt
,w sum from k=1 to infty (-1)^ke^(1/k)
final saddleBOT
,w sum from k=1 to infty (-1)^ke^(1/k)
soft zealotBOT
terse crypt
what does the '-1.80379' mean
vital crag
you'd have to read wolfram's code to know the answer
terse crypt
how
vital crag
inland stream
Hey.
I need a blending mode, that lets me do closest possible bit-packing: need to pack 2 8-bit images, convert them into 4-bit channels. 4+4bit essentially.
the lower channel (0000 XXXX)
and the upper channel (XXXX 0000)
With a bit of jippidying i have created a demo that does that using shadertoy:
https://www.shadertoy.com/view/33G3zV
Now to the problem: I want to achieve this in html :D using svg filters and, blending modes.
the problem is simple: there is no such blending mode as "add" in css. there are bunch of blending modes tho and i think that while i have to sacrifice some information due to non linear blending,
decided to go for plus-lighter but it's still not perfect:
https://codepen.io/Cubiq-ish/pen/myeJEoG
the main thing is to figure out the formula for the right blending.
while a bit of a programming job, i still think this channel suits the purpose enough.
many thanks!
final saddleBOT
Hey.
I need a blending mode, that lets me do closest possible bit-packing: need ...
runic quartz
hello chat
rapid sky
It looks like they have two images where the channels from each are eight bits (like red for a pixel can be from 0 to 255) and they want to turn them into four bits each (like red can be from 0 to 15) and then they want to combine each four bit channel from the two images into an eight bit channel (a + 16b, where a is the 0 to 15 value from image 1 and b is the 0 to 15 value from image 2).
final saddleBOT
@inland stream Has your question been resolved?
final saddleBOT
inland stream
.reopen
final saddleBOT
✅
inland stream
sorry i was in the shower lol
inland stream
It looks like they have two images where the channels from each are eight bits (...
exactly
final saddleBOT
@inland stream Has your question been resolved?
final saddleBOT
@inland stream Has your question been resolved?
inland stream
oh well, guess this question is not suitable for this channel then?
<@&286206848099549185> i summon you :o could be fun to figure out while my question is still quite advanced though..
thanks really much!
deep condor
you can keep it open, but i can't promise anyone will know since it's not strictly math 💔
vital crag
<@&286206848099549185> i summon you :o could be fun to figure out while my quest...
try #old-network for CS server
inland stream
thank you, i will try it. first gotta figure out which server do i leave :D
arduino server it was..
ill let it open there if someone still tries to figure it out but will ask there.
sick flame
steams cormmunity yes
vital crag
<@&268886789983436800> spam
final saddleBOT
@inland stream Has your question been resolved?
scenic geyser
how does 1/5 make it undefined
final saddleBOT
how does 1/5 make it undefined
deep condor
what do you get when you sub in k = 1/5?
scenic geyser
5(1/25)+1/5
old quarry
how does 1/5 make it undefined
It does not
dapper hull
how does 1/5 make it undefined
there should be extra context cuz k=1/5 doesn't seem to make it undefined
deep condor
thought it did at a glance, but yeah no
scenic geyser
huh thats weird... ive never seen khan academy be wrong
dapper hull
how does 1/5 make it undefined
could you provide the whole question ? if you can
old quarry
Probably a typo in the expression or the answer
scenic geyser
could you provide the whole question ? if you can
ahh... sorry i moved on i can try
imma keep the chanel open for like 10 min cuz i mgiht get it
5k^2 -26k + 5 / 25k^3 -k
dapper hull
5k^2 -26k + 5 / 25k^3 -k
that's the original expression ?
dapper hull
5k^2 -26k + 5 / 25k^3 -k
yea k=1/5 would indeed make the denom zero
dapper hull
the simplified expression still have the originial expression restrictions
dapper hull
5k^2 -26k + 5 / 25k^3 -k
in other words if the k value doesn't work here
it won't work for the simplified expression you gave
deep condor
most likely, at some step in the simplification, you assumed k =/= (1/5), otherwise you were dividing by zero
dapper hull
someone explain this im not getting it
25k^3-k=0 when k is either 1/5 ,-1/5 and 0
so you can't plug those k values
in the original expression because the denom. would be zero
scenic geyser
.close
final saddleBOT
dapper hull
the room didn't refresh yet send it into another help channel
mint mulch
Refresh what
mint mulch
K
scenic geyser
.close
final saddleBOT
Available help channel!
bright atlas
If ΔABC ≅ ΔFDE, which of the following statements is true?
(i picked A since there both starting points, other than that i have no clue.)
final saddleBOT
If ΔABC ≅ ΔFDE, which of the following statements is true?
(i picked A since th...
sour zealot
that should be right, is it telling you otherwise?
bright atlas
that should be right, is it telling you otherwise?
no, it doesnt tell me the asnwer until the end
i js wanna make sure its right
sour zealot
ok then yes its right
bright atlas
ok then yes its right
I assume i find the distance between all the points on this one?
using distance formula?
so a and b, then b and c
which takes forever :/
wait
sour zealot
for this one you only need ac
bright atlas
no im stupid
sour zealot
ping when you do! thanks
sour zealot
did you forget to take the square root?
bright atlas
did you forget to take the square root?
well y2 is 1 and y1 is 1 so i subtracted them
i got 0
and 0 squared is still 0
sour zealot
mhm
bright atlas
and for x, x2 is 3 and x1 is -1
sour zealot
yep
bright atlas
which is positive 4
sour zealot
yes
sour zealot
yea and then you take the square root afterwards
bright atlas
yea and then you take the square root afterwards
what
i thought u just add both values??
sour zealot
if you have two points (a1,b1) and (a2,b2), the distance formula is $\sqrt{(a_1-a_2)^2+(b_1+b_2)^2}$
soft zealotBOT
Frances
sour zealot
no worries
sour zealot
bright atlas
<:catthumbsup:614540188747563008>
just in case, is this right?
sour zealot
yes
bright atlas
yes
and this one as well?
i said 5 because i dont think u can move to a square root unless if u simplify it
yk
sour zealot
a translation doesnt alter side lengths
sour zealot
i said 5 because i dont think u can move to a square root unless if u simplify i...
and you cant simplify any of these square roots
bright atlas
a translation doesnt alter side lengths
ah so its square root of 10 regardelss?
sour zealot
mhm
sour zealot
np
bright atlas
damn ur smart
sour zealot
yea
bright atlas
i usually get help from like uni math
sour zealot
nah im not lol
bright atlas
or graduate or sm
bright atlas
nah im not lol
im the one doing summer school fam 💔
sour zealot
i did geo last year so i still remember some stuff
bright atlas
i did geo last year so i still remember some stuff
ic
im doing geo over this summer
sour zealot
ah, good luck!
fringe vault
hwllo
sour zealot
subtract the constant to the left side
raven marsh
soft zealotBOT
Carbonite
sour zealot
you can simplify the radical
severe verge
you're doing good so far
fringe vault
what would i do from here with the division and addition
because i can't add unless it has a common variable / radical right
fringe vault
wdym
errant basin
edgy mauve
On both numerator and denominator
edgy mauve
fringe vault
ohh factor out the 2
edgy mauve
If u divide 4root (2) by 2 u get 2root (2)
Note that 4root(2) is a number not two separate numbers
Well now u get two values from here
2+2root(2) and 2-2root(2)
timber plume
ohh factor out the 2
what are u confused with
edgy mauve
Yes
U understand how this works
I noticed that when u divided 4(sqrt(2)) by 2
U divided both 4 and (sqrt(2)) by 2
But that's not how it works
4(sqrt(2)) itself is a term
So u hv to divide thee whole thing by 2
4 and (sqrt(2)) r in multiplied form here
final saddleBOT
@fringe vault Has your question been resolved?
tranquil pine
van i facto this
Now think
What is an easy solution for this that u can solve it with ur eyes
fringe vault
no im braindead
tranquil pine
Oh ig im late
I thought ur trying to factorise this
tranquil pine
What u have already answered to
edgy mauve
van i facto this
Js use (a-b)²
edgy mauve
What u have already answered to
Quadratic done
tranquil pine
Quadratic done
Graphically ? Really
He had already the graph ig
edgy mauve
Graphically ? Really
He had already the graph ig
I only see quadratic done
fringe vault
i did the complete the square by myself
edgy mauve
complete the square and
Yeah so u got the values?
fringe vault
same values yep
same roots
edgy mauve
I see what u mean
Yeah u can factorize that
Ok so do u know how to factorize theough middle term splitting
fringe vault
Ok so do u know how to factorize theough middle term splitting
i think so
like the way you would if teh function is ax^2+bx+c?
fringe vault
?
edgy mauve
Like how would u proceed
fringe vault
uh
edgy mauve
If u had to do middle term split
fringe vault
i would have to
break down
the -4x
but -2x-2x
those terms dont multiply to the c value
right
edgy mauve
Yeah ryt
fringe vault
so how can i break it down
fringe vault
fringe vault
im not really sure 😓
edgy mauve
Yea
fringe vault
?
edgy mauve
Gimme a sec
fringe vault
okay
edgy mauve
Yes
edgy mauve
is that -2(2x)(2)+2^2?
It is
fringe vault
wait why did you dothat
fringe vault
oki
