#help-36
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k
thx
ari skin chung
Would creating a triangle that has angle A and 90° work using that ratio?
it would
cosA = adjacent/hypotenuse
compare that to the fraction
and then pythagorus
Is the tanA √20/√5 then?
,calc sqrt(5 - 1)
Result:
2
ye
you really simplified by de-rationalising the denominator?
yes
i love 1 in the numerator
[ \sin(\frac{\pi}{4}) = \frac{1}{\sqrt{2}} 😻 ]
k
it looks better like that
do u must need to use english here?
nah
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<@&286206848099549185> pls help
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factorize a^3+1
let 2024 be a variable call it a
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sqrt of 2024(2024^2+1/2025)
no, just factorize the expression a^3 + 1
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I am getting $4a^2+a-1=0$ where $a=sin^2(x)$; that gives a weird ahh answer. can anybody check...
Double_mytrouble
No
How did you simplify the equation? Can you share the process?
#discussion or #chill please.
show work for how you did that 
used product to sum
all became either x or x/2
i said show not tell
ok
i want to rule out any possibility of stupid arithmetic fuckup on your part
line 2, what does this say?
wdym changed
In step 2, sin(x) + sin(x/2) is 2sin(x)cos(x/2)
And not 2sin(x)sin(x/2)
cos(5x/2) is not the same thing as cos(x/2) mate
Value wise they are same nah...
Bruh
You are correct.
You are not getting it
fym im not getting it
where are you getting it from that cos(5x/2) can be just replaced out of the blue with cos(x/2)
They aren't same on graph (Obv) but take it in a unit circle
you cannot replace cos(5x/2) with cos(x/2) in an equation
Bruh, don't you know cos(2π+x)=cosx
I can... I will just take period back
You are pmo
x is not pi
Leave it
please do not call me "bro".
I did many questions using that. It worked before. Our teacher uses it
please edit the word "bro" out of your message.
Sure
But that is wrong, you know
can you show me at least one where cos(5x/2) (not cos(5pi/2) or any other expression) was replaced with cos(x/2) (not cos(pi/2) or anything else)?
I am not sure.
i'm pissing you off by doing what exactly? pointing out an instance of you being wrong and/or misremembering some tricks from class?
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idk how you're arguing with desmos lol
ive seen it happen sometimes that ppl dont want to admit their own wrongness
I am asking in our group, if I am wrong, I will admit
Me too.
yeah that does happen
do you know what desmos is?
No...
It is a website.
it graphs functions
so these are graphed and you can't exactly debate this
ohh ok, lemme look it up
Ok, can you prove it? Can you give a legit proof that cos(5x/2) = cos(x/2) generally?
Lemme see
And not just claim that, "That's how it works, I've used it many times"
you've yet to show us any fully worked solution in which it worked
Shit, I am wrong... in the previous question as putting x I was getting sinx=0. so, it worked as x=0 was solution
My bad
told ya 
unbelievable argument happening right now. plug in x=pi and it's immediately apparent that it's false because the angle is in different quadrants
Me too.
do we want to reopen
I have made many silly mistakes before as well, but you were genuinely disrespectful about it imo
nah, sir said, he will discuss it in class
Class is in a hour so...
even if you are 100% sure that you're right, it's always important to be civil and explain your reasoning in a non-condescending way
Now proceed with
$cos(\frac{5x}{2})cos(\frac{x}{2}) = sin(x)cos(\frac{x}{2})$
PRAKHAR
\cos and \sin
Oh, thanks
Now proceed with
cos$(\frac{5x}{2})$cos$(\frac{x}{2}) = $sin$(x)$cos$(\frac{x}{2})$
Genius
No need for \cos and \sin
this is atrocious.
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!noping
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You’re supposed to ping members after 15 minutes of your question being unanswered. I don’t see a question.
also, please post your question
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help
simplifying square roots is soo confusing
How so
well i think i got a formula / trick
to skip all the algebra
but when its numbers like these its crazy
so sapien
ill tell you my secret technique
ive figured something out
so
basically you can skip all the algebra
is the 80b^2 meant to all go under the root symbol
so
its kind of hard to explain
if the number is clean like 80
we have 16 * 5
pick like a perfect square that will equal to 80
im asking about your handwriting: in the equation you wrote here, is the 80b^2 meant to all be under the root
yes or no
Do it to the question then
oh yea
in that case:
wait
your root symbols should extend like this and actually physically cover all the shit that goes under them
hold on, i'm trying to give you a concrete pointer for fixing your handwriting here.
OHHH
I FIGURED IT OUT
💁
i figured out the secret technique to skip all the algebra
but it only works for clean numbres
it only works for nice numbres i guess
ok
u know what
im just gonna skip this
and come back to it later
y'all I GOTTA TAKE A BREAK
K
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!done
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hi
hiiiiii
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Is 32 the only power of two that is a part of this function? $$P\left(x\right)=\sum_{n=1}^{x}n^{n}$$
Vanouper
P(1) = 1
P(2) = 5
P(3) = 32
P(4) = 288
P(5) = 3413
P(6) = 50069
P(7) = 873612
...
32 seems to be the only one. Any reason why?
Oh wait, excluding P(1)... but that feels trivial.
Feels trivial because any number to the zero is one.
@winged magnet Has your question been resolved?
<@&286206848099549185>
P(1)
thats a power of 2
oh wait
i didnt read th enext one
yea its the only one
1 is a trivial case. (x^0=1)
How can it be proven though? That 32 is the only power of two that is a part of the function?
for x≥4:
P(x) quickly becomes odd making it not a power of 2
The modular residues of P(x) don’t match any power of 2
The growth of x^x ensures P(x) falls between powers of 2, never equaling one
That explains it. Thanks.
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how do you prove any of those 3 things?
px becomes odd for x≥5
proved by mod 2
no?
it cycles even even odd odd
5,
32,
288,
3413,
50069,
873612,
17650828,
405071317,
10405071317,
295716741928,
9211817190184,
312086923782437,
11424093749340453,
The modular residues of P(x) don’t match powers of 2
use mod 3 or 4
it can bring up inconsitiensies
So from
x=4 onward, P(x)mod3 starts hitting 0 proves that it is impossible for any power of 2 except 0
proved: Modulo residues don’t match powers of 2
wat
also because n^n growth is just too big to stay same speed as any poewr of 2 from n≥5
so basically modulo residue fails
p(x) becomes odd
and it just grows too fast in general
P(x)mod3 starts hitting 0
so what, it is also 1 or 2 mod 3 infinitely often
P(x) does not become odd eventually omg
like did you look at this?
the sequence 0,1,2,3,4,5,6,7,8,... mod 3 also starts hitting 0. but it does have powers of 2 in it
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Guys what’s hardest math question?
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,The 1 million dollar questions.
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Wait you can earn a million?? Studying this?
I was referring to the millenia problems.
I didn’t know them I just searched 😢
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Solve the inequality 4/(|x|+2) > x^2 +3x +1
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i would suggest doing it graphically
if you don't know how to solve cubics, I suggest you content yourself with approximate graphic values
yes and the solution to this inequality is not very nice
I would suggest case aalysis instead
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.
HELP
w what
do you have a question?
they've done this twice now
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A juggler alternately throws three oranges that rise 1.8m above his hands. It takes him 0.3s to move one orange from one hand to the other. When one orange reaches its maximum height, where are the other two? Assume they are evenly spaced in time. Overlay the graphs of the vertical position versus time of the three oranges to verify the answer to the question.
please
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can i get help for d im confused
how do it tbh
245° is represented by one of those arrows they drew for you in there
how do i figure out which??
which quadrant is 245° in?
3??
was that a guess or was that sheer uncertainty
what range of angles is the 3rd quadrant
65
...
uhm
the third quadrant contains the angles from what to what?
180-270
yes
note also 245=180+65
ohh
which is the whole reason why that arrow in the 3rd quadrant represents 245 in the first place
you would read off the y coordinate of the point where that ray and the unit circle intersect
which, yes, is -0.9
you once again have a whole-ass arrow representing it
this time in the fourth quadrant
-40° means you walk 40° clockwise
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Determine natural numbers n for which
Can you give me a hint with which to begin?
Ive only said that x-1, x-2 ... x-n >= 0
my firsr thought is maybe try induction to prove that if we fix n, then if it holds for x=2n then it holds for all x>=2n?
Ill try that
actually idt this works
@solar pelican Has your question been resolved?
diffrent idea: let $x=2n+a$, let $f(a)=\sum_{i=n+a}^{2n+a-1}\sqrt{i}-a$, so basically it becomes for all $a\geq 0$ then $f(a)<2n$, then we can maybe find what $a$ is when $f(a)$ is maximized
skissue.in.a.teacup
idk maybe im juat yapping and delulu
am-gm gets rid of 4
@solar pelican Has your question been resolved?
@solar pelican got the idea
tell me
so use AM-GM on the left side we have
LHS > n.[(x-1)(x-2)...(x-n)]^(1/2n) > n.√(x-n)
Which means x>n√(x-n)
from this, prove that this is untrue for n>=5
tested, this is also untrue for n >= 4, since you need x >= 12.8492 instead of x >= 8
additionally,
for n=4 if you're not allowed to use a calculator...
x>4[(x-1)(x-2)(x-3)(x-4)]^1/8
x^4 > 256(x-2)(x-4)
Plug in x=8 and it'll be false
You might have to prove that the inequality is true for n = 1,2 and 3 as well
yeah
@solar pelican Has your question been resolved?
@solar pelican are you stuck anywhere?
oh lol
I just solved like 60% of the problem
I just solved it
Thanks again! I wouldve never thought of am-gm honestly
ye at first I thought of using Minkovsky or sth
until I realize that using loose inequalities works really well for some reason
i spun around with square root conditions and achieved nothing
thanks again, ill close this now
have a good day
!
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np
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@undone tiger how did u get diffb??
I simplified first function as 1+4x+x^2/2
Derivative will he 4+2=6
And second equation derivative is 5
Wut
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How did u simplify $\int_0^x 5+|1-t| dt$ to that
And even by this it means they're not differentiable 😭
What fr
I broke it down 0 to 1 and 1 to x?
and integrated
Is it necessary to be equal to differentiable?
Yes 

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for what
To differentible at some point
well RHD = LHD always for differentiability at any point
Koi point par function agar differentible hoga agar uske LH derivative and right derivative ka exist hona chahiye
Equal hona v compulsory h kya?
I doubt
yes
yes
obviousl
y
take |x|
LHD not equal toRHD
but they still exist
and |x| is not differentiable at 0
differentiability implies the function must be smooth
no cusps, sharp peaks
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$\text{Let } P(x) \text{ be a polynomial of degree } n \geq 1 \text{ with } n \text{ distinct real roots.} \
\text{Prove that } Q(x) = P'(x) - 2x P(x) \text{ has exactly } n+1 \text{ distinct real roots.}$
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im typing
give me time
This has to be the weirdest problem I have ever encountered.
- First of all, why is this in Calculus I? Yes, I know, there's that P'(x), but this problem seems so innocent that it looks like it should not be solved using calculus
- Now, if I let Q(x) = 0, it seems like it's a very normal ODE problem, but that doesn't look like it'll help anything, at least that's what I thought.
Also, where the hell am I supposed to start???
this sounds like a job for the polynomial factor and remainder theorems
Consider the derivative of ||e^(-x^2) P(x)||
this actually sounds quite simple
but i think by mentioning this, do you now have an idea? @teal swallow
still no idea
i can probably work around this tho
What’s your solution? Because mine is just using what I said above followed by ||some rolle’s theorem and behavior at infinity|| and type arguments
since its basically G'(x)=0
Or are you just spitballing
Yeah basically - the rest is fairly straightforward after that
it is?
hold on
ah, so rolle's theorem for every (x_k, x_{k+1}) (x_i is root of P(x) = 0)
i didn't know about this, but my initial instinct was this (probably doesn't apply for all polynomials, but i'll word my instinct anyway)
P(x) has n roots.
P'(x) should then have n-1 roots (degree of first derivative is 1 less than degree of original function
xP(x) should then have n+1 roots (because of the extra x being multiplied in)
addition / subtraction operations involving two polynomials, one of degree n-1 and the other of degree n+1, should create a polynomial of degree n+1
Yes but you need to argue that all of those roots are real and distinct
Which is the main part of the question
ok that's a fair point i didn't consider
Finding the degree of the polynomial is mainly a trivial/fleeting thought
You use it at the end but it’s not particularly interesting
hold on, this covers only n-1 roots
mhm
where are the other 2
Think about ||splitting up the real number line into intervals||
What have you not considered yet

oh
im stupid
(-inf; x_1) and (x_n; +inf)
Both those interval have 2 more

Alright, q.e.d
Thanks for help
❤️
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pretty fun problem tbh
Yeah it’s a cute one
Nice way to spend the first part of my train ride lol
Oh good timing the second train just arrived

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<@&268886789983436800>
spam opening channels
and then deleting the first message
@short radish <--
it was tripping the automod but not actually muting 
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z^4 = -4, find all solutions
Is that possible
Hay
Do you know abt roots of unity
in the complex numbers, it is
is z some complex stuff?
So one way to do this is write -4 in exponential form
oh
I mean its z so prolly complex
Using Eulers identity
+1
You can write it as 4e^iπ
What
Then take the 4th root of that
is roots of unity
🤩 or 🥀
idk if i should be excited for when i learn it or scared
u r confusing me why ur asking roots of unity
Because its related to solving the problem
What you said are not the entire roots of unity
Actually wait i made a mistake
The eqn z^n = 1 has n roots
z^4 = 4e^i(2kπ +π)
All of the form e^(i * 2pi/n)
Then
z= 4th√4 e^((2κπ +π)/4)
For k from 0 to 3 natural numbers
So for κ ={0,1,2,3}
Can also do it in cis(θ) form but they are the same with moivre theorem
Not sure if i spelled name correctly
bro, are u asking square root of 1 or some equation?
how can a number have roots? only equation can have roots
but it’s complex
1 is a constant
Think he is talking about the plane representation
Sigh
Its a vector rotating splitting the 360° in n equal angles
And vectors of same length from 0 point to all roots with nθ angle
All you really need to do is swap forms
Just write stuff using Eulers identity either trigonometric or exponential
Nah not really
I mean unless you are going in stuff like complex analysis etc
The basics you learn in complex numbers aren't that advanced
You just have to think that imaginary numbers cover a plane not a line
Its good to watch yt videos
How do i solve this x^2 - y^2 + 2xyi = +-2i it's getting messed up
which would u recommend to learn early?
the organic chem tutor?
im gna go on khan academy and learn it earlier there
oh?
interesting
Their goal is to get views so they just make it so that anyone can get a rough understanding
Id just look for videos analysing and explaining rigorously as much as possible atleast
ok wait i actully got something nice
x,y are what
in R or C
x = -yi +- sqrt(2i)
z = x + yi; x,y belongs to Real
Ok so x,y are real numbers
Ok then you just match real and imaginary parts
x^2 -y^2 = 0
And 2xyi = +-2i
And solve the system
It should be all combinations of 1 and -1 for each x and y
ah, thanks
i forget to match parts and go for quadratic formula idk why D:
ok got the answers
thanks
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Pls solve this
unless i'm dreaming or have lost my eyesight, i don't think you've sent the question
what have you tried?
wait this is a sticker here? got it
heheh
wait so you know how to solve but have tried nothing? am i misunderstanding or
looks like it
Yeah

!done
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Given a tetrahedron. How many tetrahedrons can we form using the vertices, the midpoint of lines, the centroids of the faces, and the centroid of the given tetrahedron?
I had a hard time counting invalid cases when 4 points are in the same plane
the centroids of the sides???
the centroids of the faces i think is what's meant
what's your native language?
Vietnam
hmm ok so
my thinking is that if 4 points are coplanar then the plane they determine is unique
bc we don't have any four collinear pts in the picture
how did u know
I know him
ah
if we have midpoints only then we have 4 maybe?
and we can also have them share a bisecting plane that runs through one edge and the midpoint of its opposite
lemme take a pic
I know that each face has 7 coplanar points
there are 6 such planes, one for each possible contained edge
however we can also have a different kind of plane that goes through the midpoints of a loop of 4 edges
I also thought of it.
Ohhhh, that's what i missed
i think these only contain the centroid of the whole tetrahedron
and no other points we care about
there are 3 such planes, one for each pair of edges they're parallel to
So we have 4 planes for the faces, 6 planes for edge and 3 planes for what you just said
yes
though notice that the face and red planes contain 7 pts each while the blue ones contain only 5
this affects counting
Still missing something, I do 15C4-7•7C4-3•5C4=1000
It's a multiple choice and it doesn't have 1000 as an answer
@thin cloud Má a tưởng đếm hình tứ diện đều
Okay we forgot about plane that include 1 vectice, 2 centroids of two faces and two midpoints
these go through... a vertex and two of the opposite face's side midpts
Sao lại trừ 7C4 7 lần
10 lần,ghi lộn đó 😂
để a nhìn lại
Khi nhầm, đã nói rr mà
15 lần lận cơ
15 đâu ra
Mỗi đỉnh ứng với 3 cặp đường trung bình của tam giác đối diện và nó cũng đi qua trọng tâm luôn
I figured it out, it's 15C4 - 10•7C4 - 15•C4=940
6 thôi mà????
15 xd
Em check đáp án đúng rr
Mỗi đỉnh có 3 mặt phẳng đi qua đỉnh đó và đi qua 1 trong đường trung bình của mặt đối diện
Và mặt phẳng đó cũng đi qua trọng tâm 2 mặt bên luôn
I figured it out Ann, we have 12 planes like that and each plane have 5 points. Thanks for your help
Đề ôn thi TSA 😂
Thật à
uk
Là khó hơn hay dễ hơn
Độ khó quá cao so với TSA
Ohhhh, XD okayyy, nghe có động lực hẳn
Thanks anh xd
a có 72 nói làm j
Muộn lắm rồi
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i have a question regarding those who are studying math at university. what math should i study to make myself ready?
Help channels are for specific math problems or questions
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I am working on the first one right now
Since AB=BE, triangle ABE is isosceles, which means that angle AEB = BAE = 46°
This makes angle ABE 180-92 = 88°
This makes angle EBC = 180-88=92
I dont know where to go frmo here
yep
EBCD is sth special
trapeziod?
no
since the quadrilateral is cyclic you can imagine E,B,D and C all lying on a circle
now what is angle EBD equal to
yeah
precisely
actually do you know the ways to prove that a quadrilateral is cyclic?
if the opposite angles are supplementray?
alr
so there are 2 sub categories
proofs based on angles and proofs based on length
mhm
let's start with angles
okay
so as you can see A and B lie on the same side with respect to the chord CD
if CAD = CBD then ABCD is a cyclic quad
mhm
consequently if the angle is equal to the exterior angle of the opposite side then it is cyclic
would this mean that if angle B is equal to the exterior angle of C rhe. its cylic
yep
ooh
has someone worked on the square?
not yet im gonna do that one afterwards
wait did the image send
are you multiplying ia and id
oh okay
yea
yep
yep
i see
not in this case tho
now going back to the square one
there's an angle you can easily calculate
since ABCD is a square, what angle is BDC?
ahem
we don't care about DAE
hmmm
there are 2 angles that are 45°
one of the mistakes I see when people look at angles is they pay too much attention to the end points
like you know angle BDC = 45°
yeah
but staring at B and C doesn't help much in this casr
what do I see at B and C? Nothing. Because the angle is at D
alr what is it
there are 2 angles that are 45
AEG?
correct
yea
you see angle at A and D = 45°
mhm
wait is it 90
Yep
wait so it EGCF also cyclic
45?
nice job
hurrayy
it's amazing
like when you look at the diagram at first, E,F and G are just 3 random points
and you managed to find the angles on them
we also didnt use the 31° angle at all
its pretty cool
yeahh
woah
tysm for your help
you helped me yesterday too
im gonna close it now
thank you so mcuh
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np
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A satellite of m is rotating around a planet of M on a circular orbit of R. Due to space dust, it gradually decreases the radius of the orbit to R/2. Assume that the satellite performs uniform circular motion at any moment. How much energy is dissipated because of space dust?
Do you know the formula for TE
like Mechanical energy?
yes, total mech energy
I think its kinetic plus potential right
yes, that's correct, but have you derived it for satellites specifically?
so your asking if i had found the kinetic and potential energies for the satellite?
sure
for both initial and final positions?
yes
yea
k(ini) = mv(ini)^2/2
k(fin) = mv(fin)^2/2
UG(ini) = -GMm/r
UG(fin)= -2GMm/r
ok, sure, but whats the initial and final speeds
untold
yes, but u do know how to find them?
are you sure the term rotating is used
i mean it feels like orbiting must be mentioned
yea i think its just a typo
its rotating but it prob means orbiting
same thing kek, pri obviously gravitation qn
yeah fair , otherwise would be insufficient data

?
like isolate them?
$v_{orbit}=?$
actualy your U values are wrong
it says that it's rotating at a distance of R and R/2 from the surface
so the radius of rotation is the radius of the earth+that distance
Think of r as the center of mass
?
no?
wait
its orbiting at r yeah
he wrote d , should have been r tho
sorry?
how can it rotate at r/2
r/2 would mean inside the earth
it's 3r/2
we dont know that?
bro radius is not r
you assumed the radius of earth is r
unconciously
R is not radius of earth
yeah focus on what executor was asking tho
energy is conserved
and idk wym by bringing com into it
does space dust not do work?
lets just remove everything from the question
and lets assume this
A spherical mass (M) with Radius R , a small spherical mass (m) orbiting around the spherical mass at a distance d from the centre of the spherical mass M
(M>>>>>m)
whats the velocity at which spherical mass is traveling at to maintain its orbit radius
so were isolating v?
Minimum velocity, mind you
from the energy conservation equation you'll come up with by considering the earth's center as U=inf, yes
Wait so we are not going to consider space dust a force right
ans this first
v(ini) = sqrt(2GM/R)
define R real quick
is this the distance between the object and the satelite
distance from center of mass to orbit
nah thats not it . you are confusing escape velocity with weird orbiting velocity
That's the escape velocity
oh lmfao automod deleted that spam message
it's actually the gravitational center, but that usually doesn't make a difference in such problems
why the small g
bro these mistypes are not that deep
yeah even if thats G its wrong
dimentionally too
just come back to basics
no muging up
i have a satalite on earth surface , earth mass is M , radius is R
whats the energy of the satalite which is still on the earth surface
am i supposed to set it as centripetal force
you can do that to derive orbital velocity too yeah
just equate things properly
try
why is it not v = sqrt(GM/R)
yea ik i typed the wrong thing 😭
yeah thats the orbital velocity , can you try to define the orbital velocity again
(its just so you dont forget it )
Howd u find this
thats the formula not the definition
i set Universal gravitation to centriptal force
Just tell me what you guys got and give me the process
Why can't i just add up TE of initial and subtract it by TE of final
which is what i was trying to get you to do
but you didnt know velocities
and hence this
bro 💀
show us your attempt of doing this
you said everything right about the initial final kinetic potential energy, (you had the wrong idea of the velocity but thats corrected now i hope)
I got -GMm/2R for dissapated energy
show work
i mean yeah thats right
is there any doubt you had regarding this?
ah freindly advise, dont skip over concepts man , you are doing great , just try to understand what things mean
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Really not enough information to help
@vital kelp Has your question been resolved?
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i swear im not stupid but this question is throwing too much information at me
Please don't occupy multiple help channels.
add up the amount of time spent in the shower for each girl
this should give u the amount of time elapsed from 7 o clock to the last girl finishing her shower
do you understand the question
@brisk moth Has your question been resolved?
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a scienst has 2 radioactive substances each decaying at an exponential rate (not neccessealy 1/2 ). at 1 pm, he notes that the mass of first substance is 3 times that of the second. Later that day at 3 pm, he notes that the second substance now has 4 times the mass of the first. To the nearest minute, at what time did the two substances have equal masses
no calculator

