#help-36

1 messages · Page 164 of 1

terse crypt
#

or trig identity

soft zealotBOT
terse crypt
#

thx

rotund iris
#

ari skin chung

arctic fiber
#

Would creating a triangle that has angle A and 90° work using that ratio?

terse crypt
#

it would

#

cosA = adjacent/hypotenuse

#

compare that to the fraction

#

and then pythagorus

arctic fiber
#

Is the tanA √20/√5 then?

terse crypt
#

,calc sqrt(5 - 1)

soft zealotBOT
#

Result:

2
terse crypt
#

ye

lucid nymph
#

you really simplified by de-rationalising the denominator?

terse crypt
#

i love 1 in the numerator

#

[ \sin(\frac{\pi}{4}) = \frac{1}{\sqrt{2}} 😻 ]

soft zealotBOT
maiden vessel
rotund iris
#

do u must need to use english here?

terse crypt
#

nah

rotund iris
#

님 그냥

#

한국어로 물어보셔도 되요

meager mirage
#

하지만 도움을 줄 수 있는 사람을 찾는 것이 더 어려울 수 있습니다.

final saddleBOT
#

@arctic fiber Has your question been resolved?

rotund iris
#

그게 아니라 제가 고등 교육 과정 이내의 수학관련 문제는

#

전부다 풀어드릴 수 있어요

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tawdry eagle
#

<@&286206848099549185> pls help

final saddleBOT
storm haven
#

!15m

final saddleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

tawdry eagle
#

pls help

worthy wren
#

factorize a^3+1

jagged flare
#

let 2024 be a variable call it a

tawdry eagle
#

and then

#

pls show all steps

worthy wren
#

no

#

tell me what you get after factoring

left acorn
#

can someone help me with a question

#

please

zenith cedar
#

!occupied

final saddleBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

tawdry eagle
worthy wren
#

no, just factorize the expression a^3 + 1

tawdry eagle
#

ok got it

#

thx

final saddleBOT
#

@tawdry eagle Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

brave pivot
#

I am getting $4a^2+a-1=0$ where $a=sin^2(x)$; that gives a weird ahh answer. can anybody check...

soft zealotBOT
#

Double_mytrouble

loud sundial
cinder spear
last river
#

How did you simplify the equation? Can you share the process?

tired walrus
tired walrus
brave pivot
#

all became either x or x/2

tired walrus
#

i said show not tell

brave pivot
#

ok

tired walrus
#

i want to rule out any possibility of stupid arithmetic fuckup on your part

brave pivot
tired walrus
#

line 2, what does this say?

brave pivot
#

Cos5x/2 which I changed to cosx/2

#

As they are the same

tired walrus
#

wdym changed

last river
# brave pivot

In step 2, sin(x) + sin(x/2) is 2sin(x)cos(x/2)
And not 2sin(x)sin(x/2)

tired walrus
#

cos(5x/2) is not the same thing as cos(x/2) mate

brave pivot
#

Value wise they are same nah...

tired walrus
#

no they aren't

brave pivot
#

Bruh

last cape
#

You are correct.

brave pivot
#

You are not getting it

tired walrus
#

fym im not getting it

#

where are you getting it from that cos(5x/2) can be just replaced out of the blue with cos(x/2)

brave pivot
#

They aren't same on graph (Obv) but take it in a unit circle

tired walrus
#

you cannot replace cos(5x/2) with cos(x/2) in an equation

brave pivot
tired walrus
#

i do

#

but 5x/2 and x/2 don't differ by 2pi

#

they differ by 2x

#

not the same

brave pivot
tired walrus
#

no

#

2x is not a period nor a multiple thereof

brave pivot
#

You are pmo

tired walrus
#

x is not pi

brave pivot
#

Leave it

tired walrus
#

please do not call me "bro".

brave pivot
#

I did many questions using that. It worked before. Our teacher uses it

tired walrus
#

please edit the word "bro" out of your message.

brave pivot
#

Sure

last river
#

But that is wrong, you know

tired walrus
last cape
#

I am not sure.

tired walrus
# brave pivot You are pmo

i'm pissing you off by doing what exactly? pointing out an instance of you being wrong and/or misremembering some tricks from class?

brave pivot
#

Nahh, not worth it

#

.close

final saddleBOT
#
Channel closed

Closed by @brave pivot

Use .reopen if this was a mistake.

split nebula
#

idk how you're arguing with desmos lol

tired walrus
brave pivot
#

I am asking in our group, if I am wrong, I will admit

last cape
#

Me too.

split nebula
#

yeah that does happen

split nebula
brave pivot
last cape
split nebula
#

it graphs functions

split nebula
brave pivot
#

ohh ok, lemme look it up

last cape
last river
brave pivot
#

Lemme see

last river
#

And not just claim that, "That's how it works, I've used it many times"

brave pivot
#

I am not saying, that it is correct

#

I am saying it worked

tired walrus
tired walrus
brave pivot
#

My bad

tired walrus
#

told ya kekehands

near reef
#

unbelievable argument happening right now. plug in x=pi and it's immediately apparent that it's false because the angle is in different quadrants

brave pivot
#

LOL sorry

#

I am a human too especially with a lot of brain freezes

last cape
#

Me too.

tired walrus
#

do we want to reopen

near reef
#

I have made many silly mistakes before as well, but you were genuinely disrespectful about it imo

brave pivot
#

Class is in a hour so...

near reef
#

even if you are 100% sure that you're right, it's always important to be civil and explain your reasoning in a non-condescending way

last river
#

Now proceed with
$cos(\frac{5x}{2})cos(\frac{x}{2}) = sin(x)cos(\frac{x}{2})$

soft zealotBOT
#

PRAKHAR

tired walrus
#

\cos and \sin

last river
last cape
#

Now proceed with
cos$(\frac{5x}{2})$cos$(\frac{x}{2}) = $sin$(x)$cos$(\frac{x}{2})$

soft zealotBOT
#

Genius

last cape
#

No need for \cos and \sin

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

final saddleBOT
sullen gale
#

!noping

final saddleBOT
#

Please do not ping individual helpers unprompted.

sullen gale
#

sorry wrong factoid

#

!15min

final saddleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

latent dragon
#

You’re supposed to ping members after 15 minutes of your question being unanswered. I don’t see a question.

sullen gale
#

also, please post your question

tired walrus
#

op left the server

#

.close

final saddleBOT
#
Channel closed

Closed by @tired walrus

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

final saddleBOT
#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

brazen gazelle
#

.close

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

strong flax
#

help

final saddleBOT
strong flax
#

simplifying square roots is soo confusing

atomic moon
#

How so

strong flax
#

well i think i got a formula / trick

#

to skip all the algebra

#

but when its numbers like these its crazy

sage osprey
#

Hmm

#

To start, can you list a perfect square (in terms of y) that divides 39y^9?

strong flax
#

so sapien

#

ill tell you my secret technique

#

ive figured something out

#

so

#

basically you can skip all the algebra

tired walrus
#

is the 80b^2 meant to all go under the root symbol

strong flax
#

so

#

its kind of hard to explain

#

if the number is clean like 80

#

we have 16 * 5

#

pick like a perfect square that will equal to 80

tired walrus
#

im asking about your handwriting: in the equation you wrote here, is the 80b^2 meant to all be under the root

#

yes or no

atomic moon
strong flax
#

oh yea

tired walrus
#

in that case:

strong flax
#

wait

tired walrus
#

your root symbols should extend like this and actually physically cover all the shit that goes under them

strong flax
#

im like

#

im very close

#

but i dont know what to do with the exponent

tired walrus
#

hold on, i'm trying to give you a concrete pointer for fixing your handwriting here.

strong flax
#

OHHH

#

I FIGURED IT OUT

#

💁

#

i figured out the secret technique to skip all the algebra

#

but it only works for clean numbres

#

it only works for nice numbres i guess

#

ok

#

u know what

#

im just gonna skip this

#

and come back to it later

#

y'all I GOTTA TAKE A BREAK

magic coyote
#

K

strong flax
#

.close

final saddleBOT
#
Channel closed

Closed by @strong flax

Use .reopen if this was a mistake.

magic coyote
#

!done

final saddleBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

tough pollen
#

hi

strong flax
#

hiiiiii

magic coyote
final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

winged magnet
#

Is 32 the only power of two that is a part of this function? $$P\left(x\right)=\sum_{n=1}^{x}n^{n}$$

soft zealotBOT
#

Vanouper

winged magnet
#

P(1) = 1
P(2) = 5
P(3) = 32
P(4) = 288
P(5) = 3413
P(6) = 50069
P(7) = 873612
...

32 seems to be the only one. Any reason why?

#

Oh wait, excluding P(1)... but that feels trivial.

#

Feels trivial because any number to the zero is one.

final saddleBOT
#

@winged magnet Has your question been resolved?

winged magnet
#

<@&286206848099549185>

kindred sun
#

P(1)

#

thats a power of 2

#

oh wait

#

i didnt read th enext one

#

yea its the only one

winged magnet
#

1 is a trivial case. (x^0=1)

winged magnet
kindred sun
#

for x≥4:

P(x) quickly becomes odd making it not a power of 2
The modular residues of P(x) don’t match any power of 2
The growth of x^x ensures P(x) falls between powers of 2, never equaling one

winged magnet
#

.close

final saddleBOT
#
Channel closed

Closed by @winged magnet

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fiery pine
final saddleBOT
kindred sun
#

proved by mod 2

fiery pine
#

no?

kindred sun
#

even bse to even power = even
odd bse to odd power = odd

#

it proves that

fiery pine
#

it cycles even even odd odd

kindred sun
#

but now we know that if odd then not possible for 2

#

thats one part

fiery pine
#

5,
32,
288,
3413,
50069,
873612,
17650828,
405071317,
10405071317,
295716741928,
9211817190184,
312086923782437,
11424093749340453,

kindred sun
#

The modular residues of P(x) don’t match powers of 2

#

use mod 3 or 4

#

it can bring up inconsitiensies

#

So from

x=4 onward, P(x)mod3 starts hitting 0 proves that it is impossible for any power of 2 except 0

proved: Modulo residues don’t match powers of 2

fiery pine
#

wat

kindred sun
#

also because n^n growth is just too big to stay same speed as any poewr of 2 from n≥5

#

so basically modulo residue fails
p(x) becomes odd
and it just grows too fast in general

fiery pine
#

P(x)mod3 starts hitting 0
so what, it is also 1 or 2 mod 3 infinitely often

#

P(x) does not become odd eventually omg

fiery pine
#

the sequence 0,1,2,3,4,5,6,7,8,... mod 3 also starts hitting 0. but it does have powers of 2 in it

kindred sun
#

yea bro idk

#

thats what i think

fiery pine
#

ok

#

well i didn't mean to open a channel for this anyway

#

.close

final saddleBOT
#
Channel closed

Closed by @fiery pine

Use .reopen if this was a mistake.

safe arch
#

Guys what’s hardest math question?

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

drowsy epoch
#

,The 1 million dollar questions.

final saddleBOT
drowsy epoch
#

.close

final saddleBOT
#
Channel closed

Closed by @drowsy epoch

Use .reopen if this was a mistake.

blissful zenith
#

Wait you can earn a million?? Studying this?

drowsy epoch
blissful zenith
final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

safe arch
#

Solve the inequality 4/(|x|+2) > x^2 +3x +1

final saddleBOT
severe canyon
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
old quarry
#

i would suggest doing it graphically

scarlet sequoia
old quarry
#

yes and the solution to this inequality is not very nice

inner acorn
#

I would suggest case aalysis instead

final saddleBOT
#

@safe arch Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

untold elk
#

.

strong flax
#

HELP

final saddleBOT
old quarry
#

w what

sour zealot
#

do you have a question?

severe verge
#

they've done this twice now

magic coyote
#

.close

final saddleBOT
#
Channel closed

Closed by @magic coyote

Use .reopen if this was a mistake.

magic coyote
#

Reopen if u have a question

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

devout meadow
#

A juggler alternately throws three oranges that rise 1.8m above his hands. It takes him 0.3s to move one orange from one hand to the other. When one orange reaches its maximum height, where are the other two? Assume they are evenly spaced in time. Overlay the graphs of the vertical position versus time of the three oranges to verify the answer to the question.

devout meadow
#

please

final saddleBOT
#

@devout meadow Has your question been resolved?

final saddleBOT
#

@devout meadow Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

solar lichen
final saddleBOT
solar lichen
#

can i get help for d im confused

serene panther
#

What are you not understanding?

solar lichen
#

how do it tbh

tired walrus
#

245° is represented by one of those arrows they drew for you in there

solar lichen
tired walrus
#

which quadrant is 245° in?

solar lichen
#

3??

tired walrus
#

was that a guess or was that sheer uncertainty

solar lichen
#

uncertainty

#

tbh im mostly confused about how the unit circle works

tired walrus
#

what range of angles is the 3rd quadrant

solar lichen
#

65

tired walrus
#

...

solar lichen
#

uhm

tired walrus
#

the third quadrant contains the angles from what to what?

solar lichen
#

180-270

tired walrus
#

right

#

does 245 belong to that range

solar lichen
#

yes

tired walrus
#

note also 245=180+65

solar lichen
#

ohh

tired walrus
#

which is the whole reason why that arrow in the 3rd quadrant represents 245 in the first place

solar lichen
#

alright,

#

so now how would i start it off??

#

-0.9??

#

something like that

tired walrus
#

you would read off the y coordinate of the point where that ray and the unit circle intersect

#

which, yes, is -0.9

solar lichen
#

with e though

#

im actually not sure what to do

tired walrus
#

you once again have a whole-ass arrow representing it

#

this time in the fourth quadrant

#

-40° means you walk 40° clockwise

final saddleBOT
#

@solar lichen Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

solar pelican
final saddleBOT
solar pelican
#

Determine natural numbers n for which

#

Can you give me a hint with which to begin?

#

Ive only said that x-1, x-2 ... x-n >= 0

jagged flare
#

my firsr thought is maybe try induction to prove that if we fix n, then if it holds for x=2n then it holds for all x>=2n?

solar pelican
#

Ill try that

jagged flare
#

actually idt this works

final saddleBOT
#

@solar pelican Has your question been resolved?

jagged flare
#

diffrent idea: let $x=2n+a$, let $f(a)=\sum_{i=n+a}^{2n+a-1}\sqrt{i}-a$, so basically it becomes for all $a\geq 0$ then $f(a)<2n$, then we can maybe find what $a$ is when $f(a)$ is maximized

soft zealotBOT
#

skissue.in.a.teacup

jagged flare
#

idk maybe im juat yapping and delulu

severe verge
#

tried using basic AM-GM

#

Eliminated every n>=5

#

but I need to eliminate n=4

vital surge
#

am-gm gets rid of 4

severe verge
#

how tho

#

maybe my restriction is too loose

final saddleBOT
#

@solar pelican Has your question been resolved?

severe verge
#

@solar pelican got the idea

solar pelican
#

tell me

severe verge
#

so use AM-GM on the left side we have
LHS > n.[(x-1)(x-2)...(x-n)]^(1/2n) > n.√(x-n)
Which means x>n√(x-n)

#

from this, prove that this is untrue for n>=5

whole halo
#

tested, this is also untrue for n >= 4, since you need x >= 12.8492 instead of x >= 8

#

additionally,

solar pelican
#

alright ill write it down

#

and see

severe verge
#

for n=4 if you're not allowed to use a calculator...

#

x>4[(x-1)(x-2)(x-3)(x-4)]^1/8
x^4 > 256(x-2)(x-4)
Plug in x=8 and it'll be false

#

You might have to prove that the inequality is true for n = 1,2 and 3 as well

solar pelican
#

so i'll have to check individual cases

#

for n = 1,2,3

severe verge
#

yeah

final saddleBOT
#

@solar pelican Has your question been resolved?

severe verge
#

@solar pelican are you stuck anywhere?

solar pelican
#

Sorry, Ill try now

#

No, I havent tried

severe verge
#

oh lol

solar pelican
#

I did another problem

#

sorry loil

severe verge
#

I just solved like 60% of the problem

solar pelican
#

Thanks again! I wouldve never thought of am-gm honestly

severe verge
#

ye at first I thought of using Minkovsky or sth

#

until I realize that using loose inequalities works really well for some reason

solar pelican
#

i spun around with square root conditions and achieved nothing

#

thanks again, ill close this now

#

have a good day

#

!

#

.close

final saddleBOT
#
Channel closed

Closed by @solar pelican

Use .reopen if this was a mistake.

severe verge
#

np

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

magic coyote
#

@undone tiger how did u get diffb??

undone tiger
#

I simplified first function as 1+4x+x^2/2

Derivative will he 4+2=6

And second equation derivative is 5

magic coyote
#

Wut

warm python
#

!xy

final saddleBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

magic coyote
#

How did u simplify $\int_0^x 5+|1-t| dt$ to that

soft zealotBOT
magic coyote
#

What fr

undone tiger
#

and integrated

#

Is it necessary to be equal to differentiable?

magic coyote
#

Yes sully

magic coyote
#

Alr

undone tiger
#

I read somewhere that it's not necessary

#

Maybe I am wrong or mixing things

magic coyote
#

Re read notes

#

.close

final saddleBOT
#
Channel closed

Closed by @magic coyote

Use .reopen if this was a mistake.

serene panther
undone tiger
#

To differentible at some point

serene panther
#

well RHD = LHD always for differentiability at any point

undone tiger
#

Koi point par function agar differentible hoga agar uske LH derivative and right derivative ka exist hona chahiye

#

Equal hona v compulsory h kya?

serene panther
#

yes

#

yes

#

obviousl

#

y

#

take |x|

#

LHD not equal toRHD

#

but they still exist

#

and |x| is not differentiable at 0

#

differentiability implies the function must be smooth

#

no cusps, sharp peaks

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

teal swallow
#

$\text{Let } P(x) \text{ be a polynomial of degree } n \geq 1 \text{ with } n \text{ distinct real roots.} \
\text{Prove that } Q(x) = P'(x) - 2x P(x) \text{ has exactly } n+1 \text{ distinct real roots.}$

soft zealotBOT
#

TargetVN

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
teal swallow
#

im typing

#

give me time

#

This has to be the weirdest problem I have ever encountered.

  • First of all, why is this in Calculus I? Yes, I know, there's that P'(x), but this problem seems so innocent that it looks like it should not be solved using calculus
  • Now, if I let Q(x) = 0, it seems like it's a very normal ODE problem, but that doesn't look like it'll help anything, at least that's what I thought.
#

Also, where the hell am I supposed to start???

dusty quarry
#

this sounds like a job for the polynomial factor and remainder theorems

loud sundial
#

Consider the derivative of ||e^(-x^2) P(x)||

dusty quarry
#

this actually sounds quite simple

dusty quarry
teal swallow
#

still no idea

teal swallow
loud sundial
teal swallow
#

since its basically G'(x)=0

loud sundial
teal swallow
#

it is?

#

hold on

#

ah, so rolle's theorem for every (x_k, x_{k+1}) (x_i is root of P(x) = 0)

dusty quarry
# loud sundial What’s your solution? Because mine is just using what I said above followed by |...

i didn't know about this, but my initial instinct was this (probably doesn't apply for all polynomials, but i'll word my instinct anyway)
P(x) has n roots.
P'(x) should then have n-1 roots (degree of first derivative is 1 less than degree of original function
xP(x) should then have n+1 roots (because of the extra x being multiplied in)
addition / subtraction operations involving two polynomials, one of degree n-1 and the other of degree n+1, should create a polynomial of degree n+1

loud sundial
#

Which is the main part of the question

dusty quarry
#

ok that's a fair point i didn't consider

loud sundial
#

Finding the degree of the polynomial is mainly a trivial/fleeting thought

#

You use it at the end but it’s not particularly interesting

teal swallow
loud sundial
#

mhm

teal swallow
#

where are the other 2

loud sundial
#

Think about ||splitting up the real number line into intervals||

#

What have you not considered yet

teal swallow
#

oh

#

im stupid

#

(-inf; x_1) and (x_n; +inf)

#

Both those interval have 2 more

#

Alright, q.e.d

#

Thanks for help

#

❤️

#

.close

final saddleBOT
#
Channel closed

Closed by @teal swallow

Use .reopen if this was a mistake.

loud sundial
teal swallow
#

pretty fun problem tbh

loud sundial
#

Yeah it’s a cute one

#

Nice way to spend the first part of my train ride lol

#

Oh good timing the second train just arrived

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

sullen gale
#

<@&268886789983436800>

#

spam opening channels

#

and then deleting the first message

#

@short radish <--

barren hound
#

it was tripping the automod but not actually muting sadcatthumbsup

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven yacht
#

z^4 = -4, find all solutions

final saddleBOT
edgy mauve
#

Is that possible

exotic shale
serene panther
#

Do you know abt roots of unity

tired walrus
solar crest
exotic shale
solar crest
serene panther
#

I mean its z so prolly complex

exotic shale
#

Using Eulers identity

uneven yacht
exotic shale
#

You can write it as 4e^iπ

serene panther
exotic shale
#

Then take the 4th root of that

solar crest
#

is roots of unity
🤩 or 🥀

idk if i should be excited for when i learn it or scared

uneven yacht
serene panther
#

What you said are not the entire roots of unity

exotic shale
#

Actually wait i made a mistake

serene panther
#

The eqn z^n = 1 has n roots

exotic shale
#

z^4 = 4e^i(2kπ +π)

serene panther
#

All of the form e^(i * 2pi/n)

exotic shale
#

z= 4th√4 e^((2κπ +π)/4)

#

For k from 0 to 3 natural numbers

#

So for κ ={0,1,2,3}

#

Can also do it in cis(θ) form but they are the same with moivre theorem

#

Not sure if i spelled name correctly

uneven yacht
#

how can a number have roots? only equation can have roots

solar crest
uneven yacht
#

1 is a constant

exotic shale
serene panther
exotic shale
#

Its a vector rotating splitting the 360° in n equal angles

#

And vectors of same length from 0 point to all roots with nθ angle

exotic shale
#

Just write stuff using Eulers identity either trigonometric or exponential

solar crest
#

i mean i heard complex is js algebra but harder

#

can u testify

exotic shale
#

Nah not really

#

I mean unless you are going in stuff like complex analysis etc

#

The basics you learn in complex numbers aren't that advanced

#

You just have to think that imaginary numbers cover a plane not a line

#

Its good to watch yt videos

uneven yacht
#

How do i solve this x^2 - y^2 + 2xyi = +-2i it's getting messed up

solar crest
exotic shale
#

What

#

Nah idk thb the popular channels i wouldn't suggest

solar crest
#

oh?
interesting

exotic shale
#

Their goal is to get views so they just make it so that anyone can get a rough understanding

#

Id just look for videos analysing and explaining rigorously as much as possible atleast

uneven yacht
exotic shale
#

in R or C

uneven yacht
#

x = -yi +- sqrt(2i)

uneven yacht
exotic shale
#

Ok so x,y are real numbers

#

Ok then you just match real and imaginary parts

#

x^2 -y^2 = 0

#

And 2xyi = +-2i

#

And solve the system

#

It should be all combinations of 1 and -1 for each x and y

uneven yacht
#

i forget to match parts and go for quadratic formula idk why D:

#

ok got the answers

#

thanks

#

.close

final saddleBOT
#
Channel closed

Closed by @uneven yacht

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

old drum
#

Pls solve this

final saddleBOT
dusty quarry
#

unless i'm dreaming or have lost my eyesight, i don't think you've sent the question

old drum
#

I have sended it now

dusty quarry
#

what have you tried?

severe verge
dusty quarry
severe verge
#

heheh

old drum
#

Nothing

#

I knew how to solve

dusty quarry
#

wait so you know how to solve but have tried nothing? am i misunderstanding or

old drum
#

Is it 145°?

#

Is it 145°?

dusty quarry
#

looks like it

old drum
#

Yeah

magic coyote
magic coyote
final saddleBOT
# old drum Yeah

If you are done with this channel, please mark your problem as solved by typing .close

#

@old drum Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

thin cloud
#

Given a tetrahedron. How many tetrahedrons can we form using the vertices, the midpoint of lines, the centroids of the faces, and the centroid of the given tetrahedron?

thin cloud
#

I had a hard time counting invalid cases when 4 points are in the same plane

severe verge
#

the centroids of the sides???

tired walrus
#

the centroids of the faces i think is what's meant

thin cloud
#

Yeah

#

I don't work with solid geometry much in English. My bad

tired walrus
#

what's your native language?

severe verge
#

Vietnam

tired walrus
#

hmm ok so

#

my thinking is that if 4 points are coplanar then the plane they determine is unique

#

bc we don't have any four collinear pts in the picture

solar crest
severe verge
#

I know him

solar crest
#

ah

tired walrus
#

so what can we have then

#

we can obviously have 4 points sharing one face

severe verge
#

if we have midpoints only then we have 4 maybe?

tired walrus
#

and we can also have them share a bisecting plane that runs through one edge and the midpoint of its opposite

#

lemme take a pic

thin cloud
#

I know that each face has 7 coplanar points

tired walrus
#

there are 6 such planes, one for each possible contained edge

#

however we can also have a different kind of plane that goes through the midpoints of a loop of 4 edges

thin cloud
tired walrus
#

i think these only contain the centroid of the whole tetrahedron

#

and no other points we care about

#

there are 3 such planes, one for each pair of edges they're parallel to

thin cloud
#

So we have 4 planes for the faces, 6 planes for edge and 3 planes for what you just said

tired walrus
#

yes

#

though notice that the face and red planes contain 7 pts each while the blue ones contain only 5

#

this affects counting

thin cloud
#

Still missing something, I do 15C4-7•7C4-3•5C4=1000

#

It's a multiple choice and it doesn't have 1000 as an answer

severe verge
#

@thin cloud Má a tưởng đếm hình tứ diện đều

tired walrus
#

yeah look at this

#

we were missing planes like these

thin cloud
#

Okay we forgot about plane that include 1 vectice, 2 centroids of two faces and two midpoints

tired walrus
#

these go through... a vertex and two of the opposite face's side midpts

severe verge
thin cloud
severe verge
#

để a nhìn lại

thin cloud
#

6 thì phải

#

Ý là 3+6

#

À tutu

severe verge
#

7C4 6 lần đi trên cạnh + 4 mặt

#

10 lần

#

5C4 3 lần

thin cloud
thin cloud
severe verge
#

15 đâu ra

thin cloud
#

Mỗi đỉnh ứng với 3 cặp đường trung bình của tam giác đối diện và nó cũng đi qua trọng tâm luôn

severe verge
#

à đợi a nhìn đã

#

nhiều vcl

thin cloud
#

I figured it out, it's 15C4 - 10•7C4 - 15•C4=940

severe verge
#

6 thôi mà????

thin cloud
#

15 xd

#

Em check đáp án đúng rr

#

Mỗi đỉnh có 3 mặt phẳng đi qua đỉnh đó và đi qua 1 trong đường trung bình của mặt đối diện

#

Và mặt phẳng đó cũng đi qua trọng tâm 2 mặt bên luôn

severe verge
#

đme quên

#

ok nhận

#

lấy tử đâu bài bỏ con thế

thin cloud
thin cloud
severe verge
#

vcl

#

TSA dell có bài như thế này đâu

thin cloud
#

Thật à

severe verge
#

uk

thin cloud
#

Là khó hơn hay dễ hơn

severe verge
#

Độ khó quá cao so với TSA

thin cloud
#

Ohhhh, XD okayyy, nghe có động lực hẳn

severe verge
#

thôi m 90 TSA đi là vừa

#

hè đến mà m học kinh vc

#

out trình anh

thin cloud
thin cloud
#

H em đi ngủ đây

severe verge
#

a có 72 nói làm j

thin cloud
#

Muộn lắm rồi

severe verge
#

ok ngủ đi e nhé

#

.close đi e

thin cloud
#

.close

final saddleBOT
#
Channel closed

Closed by @thin cloud

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gusty sedge
#

i have a question regarding those who are studying math at university. what math should i study to make myself ready?

vital crag
#

Help channels are for specific math problems or questions

gusty sedge
#

pkay nice

#

thank you

#

.close

final saddleBOT
#
Channel closed

Closed by @gusty sedge

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive snow
final saddleBOT
restive snow
#

I am working on the first one right now

#

Since AB=BE, triangle ABE is isosceles, which means that angle AEB = BAE = 46­°
This makes angle ABE 180-92 = 88°
This makes angle EBC = 180-88=92

#

I dont know where to go frmo here

severe verge
#

now what does angle EBC and EDC add to?

#

their sum I mean

restive snow
#

erm

#

180??

severe verge
#

yep

restive snow
#

wait

#

oh

#

wait

#

yeahg

severe verge
#

EBCD is sth special

restive snow
#

trapeziod?

severe verge
#

no

#

it's a cyclic quadrilateral

restive snow
#

ohh

#

can i use ptolemys??

severe verge
#

no

restive snow
#

wait

#

no

#

hmmm

severe verge
#

since the quadrilateral is cyclic you can imagine E,B,D and C all lying on a circle

#

now what is angle EBD equal to

restive snow
#

92-26=76

#

wait

#

no

#

66

severe verge
#

alr 66

#

now since EBCD is a cyclic quadrilateral

#

Is angle EBD = ECD?

restive snow
#

uhhh

#

idk

#

im not good at cyclic quadritlaterls

severe verge
#

well as you can see

#

B and C are on the same side with respect to ED right?

restive snow
#

yeah

severe verge
#

and since angle EBD and ECD both covers the arc CD

#

they must be equal

restive snow
#

ohhh

#

so that means ECD = 66??

severe verge
#

precisely

restive snow
#

woah

#

its cyclic because the opposite angles add up to 180

severe verge
#

actually do you know the ways to prove that a quadrilateral is cyclic?

restive snow
#

if the opposite angles are supplementray?

severe verge
#

and?

#

I can draw for you

restive snow
#

uhh

#

idk the other one

severe verge
#

alr

#

so there are 2 sub categories

#

proofs based on angles and proofs based on length

restive snow
#

mhm

severe verge
#

let's start with angles

restive snow
#

okay

severe verge
#

so as you can see A and B lie on the same side with respect to the chord CD

#

if CAD = CBD then ABCD is a cyclic quad

restive snow
#

hmm

#

so if alpha = beta then its cyclic?

#

oh i get it

severe verge
#

if the two opposite angles add up to 180° then it is cyclic

restive snow
#

mhm

severe verge
#

consequently if the angle is equal to the exterior angle of the opposite side then it is cyclic

restive snow
#

would this mean that if angle B is equal to the exterior angle of C rhe. its cylic

severe verge
#

yep

restive snow
#

ooh

severe verge
#

moving on to proof based on length

#

(which are rarely used)

hasty sleet
severe verge
#

if IA.ID = IB.IC or KA.KB = KC.KD then cyclic quad

restive snow
severe verge
#

wait did the image send

restive snow
hasty sleet
#

oh okay

restive snow
#

yea

severe verge
restive snow
#

ohh

#

is k the extension of the sfes

#

like the point

severe verge
#

yep

restive snow
#

where thye meet

#

alr

severe verge
#

I and K are intersections

#

it is occasionally useful

restive snow
#

i see

severe verge
#

not in this case tho

#

now going back to the square one

#

there's an angle you can easily calculate

#

since ABCD is a square, what angle is BDC?

restive snow
#

uh

#

DAE = 14

severe verge
#

we don't care about DAE

restive snow
#

oh shoot

#

its just 45

#

whoops

severe verge
#

alr

#

now can you spot a cyclic quad here?

restive snow
#

hmmm

severe verge
#

there are 2 angles that are 45°

#

one of the mistakes I see when people look at angles is they pay too much attention to the end points

#

like you know angle BDC = 45°

restive snow
#

yeah

severe verge
#

but staring at B and C doesn't help much in this casr

#

what do I see at B and C? Nothing. Because the angle is at D

restive snow
#

awit

#

i think

#

i know which one

severe verge
#

alr what is it

restive snow
#

nopee

#

i thought it was DCGF

#

but i tested it and its not

severe verge
#

there are 2 angles that are 45

restive snow
#

AEG

#

and BDC

severe verge
#

AEG?

restive snow
#

wait no

#

gAE

#

GAE

severe verge
#

alr good

#

so which quadrilateral is cyclic?

restive snow
#

DEGA??

#

wait

severe verge
#

correct

restive snow
#

yea

severe verge
#

you see angle at A and D = 45°

restive snow
#

mhm

severe verge
#

now from this you can actually calculate EGF

#

remember the exterior angle rule?

restive snow
#

wait is it 90

severe verge
#

Yep

restive snow
#

wait so it EGCF also cyclic

severe verge
#

Yep

#

nice spot

#

we need to calculate AEG tho

#

what angle does AEG equal to

restive snow
#

45?

severe verge
#

nice job

restive snow
#

hurrayy

severe verge
#

it's amazing

#

like when you look at the diagram at first, E,F and G are just 3 random points

#

and you managed to find the angles on them

#

we also didnt use the 31° angle at all

restive snow
#

its pretty cool

#

yeahh

#

woah

#

tysm for your help

#

you helped me yesterday too

#

im gonna close it now

#

thank you so mcuh

#

.close

final saddleBOT
#
Channel closed

Closed by @restive snow

Use .reopen if this was a mistake.

severe verge
#

np

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quartz wind
#

A satellite of m is rotating around a planet of M on a circular orbit of R. Due to space dust, it gradually decreases the radius of the orbit to R/2. Assume that the satellite performs uniform circular motion at any moment. How much energy is dissipated because of space dust?

magic coyote
#

Do you know the formula for TE

quartz wind
magic coyote
#

yes, total mech energy

quartz wind
#

I think its kinetic plus potential right

magic coyote
#

yes, that's correct, but have you derived it for satellites specifically?

quartz wind
#

so your asking if i had found the kinetic and potential energies for the satellite?

magic coyote
#

sure

quartz wind
#

for both initial and final positions?

magic coyote
#

yes

quartz wind
#

yea

magic coyote
#

can you send a pic or write it down

#

welcome to mathcord btw Wave

quartz wind
#

k(ini) = mv(ini)^2/2
k(fin) = mv(fin)^2/2
UG(ini) = -GMm/r
UG(fin)= -2GMm/r

magic coyote
#

ok, sure, but whats the initial and final speeds

magic coyote
#

yes, but u do know how to find them?

quiet zinc
#

i mean it feels like orbiting must be mentioned

quartz wind
#

its rotating but it prob means orbiting

magic coyote
quiet zinc
magic coyote
magic coyote
quartz wind
magic coyote
#

$v_{orbit}=?$

soft zealotBOT
magic coyote
#

find it through energy conservation

quartz wind
#

I thought energy wasn't conserved

#

since space dust is there

magic coyote
#

it says that it's rotating at a distance of R and R/2 from the surface

#

so the radius of rotation is the radius of the earth+that distance

quartz wind
#

Think of r as the center of mass

magic coyote
#

?

quiet zinc
#

wait

#

its orbiting at r yeah

#

he wrote d , should have been r tho

quiet zinc
quartz wind
#

oh yea i wrote it wrong

#

but i mean the same thing

quartz wind
#

the distance there

magic coyote
#

r/2 would mean inside the earth

#

it's 3r/2

quiet zinc
#

bro radius is not r

#

you assumed the radius of earth is r

#

unconciously

magic coyote
#

Ah

#

oops

quartz wind
#

R is not radius of earth

magic coyote
#

ok well then those are correct

#

just swap d out with r

quiet zinc
#

yeah focus on what executor was asking tho

magic coyote
#

and idk wym by bringing com into it

quartz wind
#

does space dust not do work?

quiet zinc
#

lets just remove everything from the question
and lets assume this

A spherical mass (M) with Radius R , a small spherical mass (m) orbiting around the spherical mass at a distance d from the centre of the spherical mass M
(M>>>>>m)
whats the velocity at which spherical mass is traveling at to maintain its orbit radius

quartz wind
#

so were isolating v?

magic coyote
#

Minimum velocity, mind you

magic coyote
quartz wind
#

Wait so we are not going to consider space dust a force right

magic coyote
#

No

#

Leave all that

quartz wind
#

v(ini) = sqrt(2GM/R)

quiet zinc
#

is this the distance between the object and the satelite

quartz wind
quiet zinc
magic coyote
quiet zinc
#

oh lmfao automod deleted that spam message

magic coyote
#

yh

#

i saw tons of pics

#

then gone

#

kek

quiet zinc
#

yuh

#

flickered

magic coyote
quartz wind
#

bruh

#

v = sqrt(GM/R)

#

?

quiet zinc
#

why the small g

quartz wind
#

bro these mistypes are not that deep

quiet zinc
#

yeah even if thats G its wrong

#

dimentionally too

#

just come back to basics

#

no muging up

#

i have a satalite on earth surface , earth mass is M , radius is R

#

whats the energy of the satalite which is still on the earth surface

quartz wind
#

am i supposed to set it as centripetal force

quiet zinc
#

you can do that to derive orbital velocity too yeah

#

just equate things properly

#

try

quartz wind
#

why is it not v = sqrt(GM/R)

quiet zinc
#

it is that

#

you wrote sqrt(GM/2) before

#

thats what confused me

#

mb

quartz wind
#

yea ik i typed the wrong thing 😭

quiet zinc
#

yeah thats the orbital velocity , can you try to define the orbital velocity again

#

(its just so you dont forget it )

quartz wind
#

dude

#

v = sqrt(GM/R)

magic coyote
magic coyote
quartz wind
#

i set Universal gravitation to centriptal force

#

Just tell me what you guys got and give me the process

#

Why can't i just add up TE of initial and subtract it by TE of final

quiet zinc
#

you can do that

#

did you try ?

magic coyote
#

which is what i was trying to get you to do

#

but you didnt know velocities

#

and hence this

quartz wind
#

bro 💀

quiet zinc
#

you said everything right about the initial final kinetic potential energy, (you had the wrong idea of the velocity but thats corrected now i hope)

quartz wind
#

I got -GMm/2R for dissapated energy

magic coyote
#

show work

quiet zinc
#

is there any doubt you had regarding this?

quartz wind
#

it was just for the velocity

#

cuz i am bad at memory

quiet zinc
#

ah freindly advise, dont skip over concepts man , you are doing great , just try to understand what things mean

magic coyote
#

have fun in mathcord

#

!done

final saddleBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

quartz wind
#

.colse

#

.

#

.close

final saddleBOT
#
Channel closed

Closed by @quartz wind

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vital crag
#

Really not enough information to help

final saddleBOT
#

@vital kelp Has your question been resolved?

#
Channel closed

Closed by @vital kelp

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

brisk moth
#

i swear im not stupid but this question is throwing too much information at me

final saddleBOT
#

Please don't occupy multiple help channels.

worthy wren
#

this should give u the amount of time elapsed from 7 o clock to the last girl finishing her shower

runic needle
final saddleBOT
#

@brisk moth Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

old nacelle
#

a scienst has 2 radioactive substances each decaying at an exponential rate (not neccessealy 1/2 ). at 1 pm, he notes that the mass of first substance is 3 times that of the second. Later that day at 3 pm, he notes that the second substance now has 4 times the mass of the first. To the nearest minute, at what time did the two substances have equal masses

old nacelle
#

no calculator