#help-36
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does the fact that an augmented matrix is homogeneous directly make it easier to rref?
well you know that no matter what row operation you do, the augmented column will stay 0
<@&268886789983436800> ad
hmmm
which means you don't even really need to include it in your calculations
can sm1 help me in 49
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Hi! Can someone help me with this problem please
find the tangent line of x^2 - 1 at (-1, 0)
the normal line is the line perp to that tangent line
find the equation of that normal line, and do the rest
so I found that its y=-2x-2
i'm confused on what to do afterwards
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how can I solve this?
substitution x^2 + y^2 = r?
Polar coordinates?
I tried a straight substitution and I got
dr/dx = 1
Do you think this is the correct approach?
Can I see how you did it?
,w dy/dx=(-x+Sqrt[x^2+y^2])/y
I don't understand what you have to do
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hi
How Could I make this porint I do onot know hwere to starht mayve solvuing in the right side?
use u-sub on the right side
the right integral*
if you use u-sub on the rigjt integral you get $\int_{0}^{8} f(x)dx=40$ and than you only need to see the difference between the two integrals
mercidy
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Is there a connective that yields the values of the column at the end?
when in doubt, k maps
what is k maps?
id buy it
Me too
just not P and not Q since it would be true when both P and Q are false and false in all other instances
a method to get a minimized boolean expression from truth tables
I know that it can be constructed using multiple operators. I'm asking if there is a single operator that performs that action.
What type of mathematics is this?
so without using negations too, you mean just P Q and the standard 3 connectives
Is there a single binary operator which, when combined with P and Q, results in the truth values of the last column. Like P ? Q
i mean not P and not Q is just not(P or Q) so maybe there’s something for that
yea
NOR
with a down arrow
$P \downarrow Q$
knief
nor it is. Thank you.
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can someone check over my epsilon delta proof?
i know ive done something wrong but cant tell what
OH
THATS WHY
because the person in the video did this
yeahh that makes sense
wait also
he got |u+2| < 2
but i got |u+2| < 4
did i do another thing wrong

wait ill send the video sorry 😭
These are the detailed solutions to practice problems for Epsilon-Delta definition (precise definition). Try to do as many problems as you can before looking at the solutions.
Problems lineup
00:00 Intro
01:06 Definition
02:49 Problem 1
09:39 Problem 2
18:21 Problem 3
27:44 Problem 4
33:10 Problem 5
37:26 ...
timestamped
oh it didnt timestamp
around 38:52
@weak silo Has your question been resolved?
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i need a ton of help with related rates 
so maybe you should draw a sketch
you’ve only listed the givens
@dusk laurel
we know it’s a rectangular well so you should draw a rectangular prism
standing upright
like a nice rectangular box
with some water in it
ohhhh i was drawing it laying flat LOL
lol i mean it also works it’s just the dimensions will be different because it’s supposed to be deeper than it is wide
this looks good as well
7 examples of related rates for your calculus 1, AP calculus, and GCSE class classes. These are some must-know examples for the applications of derivatives. This is commonly referred to as the hardest topic in calculus 1. Try the problems first 👉 https://docs.wixstatic.com/ugd/287ba5_dc24528101234bc8a2e6075d28b5f90b.pdf
Time Stamps: 0:00
(Q1) ...
this is a good video btw
but if you have more questions you can ask here of course
best way to learn is by doing
@dusk laurel Has your question been resolved?
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What is Area of triangle BCQ when AP:PD=2:3 and AC//PQ , □ABCD = 100
is there a drawing for this
@arctic fiber Has your question been resolved?
Yes
@arctic fiber Has your question been resolved?
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can anyone explain why the +1 exists?
in the last equation? This is simple recurstion
@frank folio Has your question been resolved?
the 1 is from flipping once. then there is a 1/2 chance of being done and a 1/2 chance of expecting E[flips] more flips
i love expectation conditioning
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@trail mango why do we include it tho?
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@trail mango sorry
if ur still here
im lost on the logic behind the 1
even if you can write it both ways
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How do I do this one?
b or c?
@prime halo Has your question been resolved?
C
try drawing the graph of y = 2|x + 4| - 5
you should find that the limiting case is when l passes through the vertex, (-4, -5)
increase a any more so the line becomes steeper, or the part where x < 0 goes down even more
and there will be no solutions for x < 0
you can adjust the slider to change the value of a
ah and the other part is that two parallel lines never intersect, so your answer should look like
$p \le a$ and $a > q$ for some real $p, q$
south
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So shouldn’t a just be not equal to 2?
I think the answer said a<2
Oh wait no
That would intersect twice if it was greater right?
a > 2 is one part of the answer
exactly that is why
it will intersect if you make the slope larger than 2
Oh was this meant to be the other way round then?
yeah, you want the line to intersect at least once
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$p \le a$ and $a > q$ for some real $p, q$
south
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yo
i can try helping
bro
am i wrong in adding all history students/100 and x by geo students apart pyschology /99
hmm that seems right to me
ohh yeah makes sense
you need to exclude some cases from history students
what was your history students total?
@tranquil pine Has your question been resolved?
no
see there was an overlapping student right?
you removed 1 from the 100
but pure history + geo case becomes repeated too
so remove another
which is why you have 25/100 * 36/99
and not 37
it's two cases probably
overlap or not
should be (25/100)(36/99) + (18/100)(37/99)
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I'm not sure why when I do simultaneous equations that both variables are eliminated???
Yea cuz where did your x go?
you forgot ur x
I did "let x = 1"
uhm idk my teacher taught me to do that and solve for y and z
kk I'll try that
It's not looking too good atm 😬 idk how but somehow I got 6y = 6y
tho I did get x = 0 as one of the coordinates
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can anyone explain why we dont need the -1 at the end?
seems like you're doing geometry, lengths can't be negative
Hey can i post smth here
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using bernoulli inequality i need help with this problem
you need more pixels
i actualy need help to solve lim(n----inf)q^n when |q|<1 using bernoulli inequality
@loud umbra Has your question been resolved?
no 😦
@loud umbra Has your question been resolved?
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yea
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Was watching this video, wouldn't it be easier to use the 1 + tan^2theta trig identity instead of changing everything, or am I missing something?
i mean yes but the point is that you’re showing why that identity holds
@rocky tusk Is cooking
given that sin^2 + cos^2 = 1
Bye ...
like yes obviously tan^2 + 1 = sec^2 as it is a variation of the pythagorean identity but then you wouldn’t show any work
True
they want you to prove it using the assumption only that sin^2 + cos^2 = 1
that’s your toolbox so to speak
in more involved problems no but for something this simple yes
it’s only because you’re trying to prove this property specifically that it would be meaningless to just state it’s true
@knotty night Has your question been resolved?
How come he expanded everything? I thougt we would have to turn Sin^2x + cos^2x into 1. Can anyone explain to me the priorities or rules?
bc the second term on the right side isn’t useful yet until you expand
left side*
Over here, he left (1 + sinx) x cosx. I expanded it
How would I know all this
?
How would I know when to expand, when not to
when to do anything?
What do you mean by isn't useful? Do you mean cannot be converted into a different identity?
or
yes
it’s like a game
you don’t always know what to do
I see
@knotty night Has your question been resolved?
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this may be a completely stupid question but im getting a bit confused:
is there any specific way I have to solve this other than putting it into my calculator?
do u want degress
or radians
thats the only option u got
(u just have to plug it in)
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I'm trying to determine if $\begin{bmatrix} 5&4\0&5\end{bmatrix}$ is diagonizable
A dense set(Ping when reply)
There is one eigenvalue
with a multiplicity of 1
which is why it isn't diagonisable
is that right
what kind of multiplicity?
there are two types of multiplicity for eigenvalues, arithmetic (multiplicity as a root of the char poly) and geometric (dimension of eigenspace)
the geometric multiplicty
Is that right
this isn't sufficient
wait hold on
okay, you said geometric multiplicity
yeah so, if any of the geo multiplicities are less than their respective algebraic multiplicities, then the matrix isn't diagonalizable
cool
I'm gonna take your word for it when you say that the geo mult. of 5 is 1
the alg mult. of 5 is 2 obviously
so not diagonalizable
cool
one more question
Same question but for $\begin{bmatrix} 0&-1 \ 1&0 \end{bmatrix}$
A dense set(Ping when reply)
The eigenvalues are not real
chat is this real?
so it isn't diagonizable
I believe so?
I mean, this depends on what field you're working over
$\mathbb{C}$?
if you're taking the vsps to be real, then sure
utop!a
if you consider them complex, then the char poly always splits
and so you'd need to check the geo multiplicites again
$\R$
A dense set(Ping when reply)
No idea what a Jordan form is
just the "next best thing" to diagonalizability 
Eh, will either do it over the winter break, or i9n year 3
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I'm not understanding what my prof is doing, I don't get why z = -3 sin(t)
I dont get why the direction vector is that of:
( -3 sin(t), 0, -3cos(t))
Ah I see this doesn't give the givens:
Let S be the surface defined by y = 10 - x^2 - z^2 with y >= 1, oriented with rightward-pointing normal.
Let F = (2xyz + 5z) i +(e^(x)) * cos(yz) j + x^2*y k
Determine the double integral over S of the Divergence x F dot dS.
This problem utilizes stokes theorem and sets a curve C
@ancient wharf do you think you can help w/ this?
What is this class lol
Integrals ?
Sorry I got no clue in this topic 😔
You in college ?
yea
I am in hs lol
Man I wanna help with ez math what is this😭
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I'm not sure how I should go about the proof for Exercise 3.25. I found that the statement is equivalent to the converse of theorem 3.24.
think about the word cyclic
@astral moss Has your question been resolved?
Cyclic groups havent been covered yet. Like i kinda have intuition for why the statement is true but i don't know how to prove it
wdym havent been covered
Z_n is the "only" cyclic group
cyclic groups are the most simple groups, how can you not talk about them
have you talked about the order of elements
and dont ignore the bot
yes
i know the order of elements
and we proved two groups can only be isomorphic if they have the same number of elements with given order
for example in Z_4, the element 1 has order 4, but in Z_2 x Z_2, the highest order of any element is 2
good
aka Z_2×Z_2 is not isomorphic to Z_4
now do it for p and q instead of 2 and 2
So in Z_pq, the element 1 has order pq, but in Z_p x Z_q the highest order of any element is something which is not pq
idk why im struggling to generalise it
if you have an element (n,m) in the product, what is the order of n and m? so what is the order of (n,m)?
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Is x 113?
Yes
Can anyone else also approve?
@quick axle Has your question been resolved?
Yes it's correct
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Is this integration correct?
Mistake in x
x(A+B-2C)
2A-A = A, not 3A
@fathom stratus Has your question been resolved?
Its -2A-A
=-3A
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
2A-A+2A +B
ok
What do u mean by ok?
ok: used to express agreement or acceptance
Ok
<@&286206848099549185>
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After substituiting -2c as 2A
It becomes 2A-A+B+2A
Whixh is 3A+B
@solar glade
In the previous steps i showed of A=-C
Hence 2(-c)=2A
U get?
No
That is not correct
Which part
Solve again
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@solar glade
Please check this
I tried correcting my mistake
Thank u for telling me where i had gone wrong
A, B and C now look correct
No
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Can someone please help with the part ii of this question? thank you
@carmine crow Has your question been resolved?
<@&286206848099549185>
What have you tried?
No but I can just use the alternating series criteria, right?
just gotta show that 1/sqrt(n) is decreasing null sequence
@worn wave I basically just multiplied it into a cauchy product
and idk if a made a mistake or not
but idk how to proceed
can it be, that I have to keep the index starting from 0 when doing the product?
I'd try starting from 0. You have a small issue of the last term being undefined
yeah
and for n=1, all the terms are undefined
sorry
for each n, the nth term is undefined
Controlling the inner sum is the hard part. I think you need to find a bound away from zero in terms of n.
lemme try with leaving the the inner sequece as a_n
The partial sums all have the same sign regardless of the parity of n
and keeping the index starting from 0
do you think that will help?
keeping the sequence as a_n?
I think reindexing is good so that all the terms are defined
ok lemme try
I failed
it didn't work
Reindex the original sum
wdym
Oh, the original question had a_0=0
The term under k=n is zero
You need to get a bound for your c_k. I suggest writing out partial sums for n=8 and 9 to see what it looks like
what is c_k
do you mean the series in my series?
ah ok
@worn wave actually, I think I'm gonna give up on this question for now. Do you think you might be able to help me w another question?
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what does tr mean?
is it some matlab command im so confused 💀
matrix trace
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(P ∧ ¬Q) ∨ P ≡ P
is this because p and not q = p, and p or p = p?
my thought process:
P and NOT Q = P (because q is excluded)
New fxn P v P
P or P = P (because whatever you choose it's P)
p and not q ≠ p
how come
,w truth table p and not q
the truth table disagrees in one row
im coming from the logical standpoint of saying for example, it is hot and not cold
therefore it is hot
but why is it that way
you are assuming p and q are incompatible. but what if they are not, e.g. "it's hot and not raining"
mm
that makes sense
so then what would be the proper simplification
i know there's a rule called absorption law but I kinda wanna know how you'd do it step by step
and distributes over or, & or distributes over and
bcz idt i'll memorize it 😭
wdym
P or P and not Q or P?
P and not Q or P
^ I'm fairly new to logic so forgive me if I'm mistaken
that's valid. although i was thinking of first writing P = (P or 1) then "factoring out P" from the expression (basically distributive law in reverse)
ok so then after we have P and not Q or P how do we simplify
to get only P
ok according to chatgpt
this is how you do it
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are you supposed to use stokes theorem
$n = \nabla (z - \sqrt{x^2 + y^2})$
riemann
oop wait nvm
i think its stokes
is stokes theorem curl (F) ?
my bad i always confuse green's with divergence
similar problem here https://math.stackexchange.com/questions/3026712/divergence-theorem-cone
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What is the l1 norm of f(x)=x1^2+x2^2+3x3^2 at (1,1,1)?
I will find you.
what's the definition of a norm at a single point
What is it?
yes
L1 norm
you gave a point
what's the definition of the L1 norm of a function at a point
idk
......
||x||_1
sum of absolute value of xi
for 1 case
so how do you find it if is a function
the L1 norm is defined for functions yes
so you evaluate it at (1,1,1) first?
ah yes so sum up the absolute vlaues
because this definition does not incorprorate a function
i dont see any functions in that def
but you have a function
show the original question
picture or screenshot
no idea what it's asking then ¯_(ツ)_/¯
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what formulas were you given
just this one?
and you're just algebraically solving for $x_0$ ?
riemann
Yes
yes
you messed up your signs in this step.
Exf - Ex0 = delta v
add Ex0 to both sides
Exf = delta v + Ex0
subtract delta v both sides
Exf - delta v = Ex0
now you can divide by E
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Would you not just use trig functions?
we didnt even learn that though
let width = w
tan 50 = w/35
tan50 * 35 = w
im not at that stage 💀 this is about hinge theorems
try using your intuition for the first question in terms of how the side lengths & angles given will relate with the width
ohhh.
tried that
so the triangle is a right triangle right?
yea
wait
nvm lol
i just dk the 50 part
nor how u get the more than 35 less than 50
180
ye
think of the opposing angles for each triangle, remember that the side length adjacent to the larger angle will always be shorter than the other
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how to do qeastion one \
,rotate
you already did this
was it?
idk
i am not sure
the answer was like 2/7
but that is the ratio for the lines i think
.-.
.-. how you do that
what do that
dot hyphen dot?
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Pls help asap how do i do this
wait i will get a more clear pic
How do i do nukber 3
How do i start it
i think i can like put all the points down but is there a way to like solve it by just subtracting or adding and flipping the signs and switching x and y?
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When I'm calculating part a, I would have to take the curl of F, right?
can anyone help me?
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put it in a different channel, this one is being used
kk
were you trying to use this one and i stole it from you? if so, im sorry
No
oh ok
I could have in no time opened another one
thats fair, i just feel bad when i do it because i find it annoying when it happens to me
ok
Hey just you know asking
Is the answer 0?
im sorry?
im not certain i quite understand what youre asking
The Flow rate of hot air
Is it 0?
when i used stoke's theorem i got 0, and so i should also get 0 when i do part a
but im trying to figure out why i didnt get 0 for part a
Hmmm wait...
because when i solved this, i didnt take the curl of F. and i think thats why i didnt get 0
Okay so here we need the surface integral
Which is flux
Flux is integral of F•n dS
For sphere we take $ndS = r^{2}sin{\phi}d\phi d\theta$
@upbeat harbor
Here curl(W) = F
Okay
are you telling me that i solved part a and b backwards?
No no
because i used F*n dS for part b
See
The formula for flux is
$\int_{S}F.ndS$
@upbeat harbor
right
Since here the surface is a sphere
We can say $ndS = R^{2}sin(\phi)d\phi d\theta$
@upbeat harbor
And since we just shifted to spherical coordinates
We need to rewrite $W = <-y,x> = <-R^{2}sin(\phi)sin(\theta),R^{2}sin(\phi)cos(\theta)$
@upbeat harbor
Now if we do $\int_{S}W.ndS \$
It is
$\int_{0}^{2\pi}\int_{0}^{\pi}W.R^{2}sin(\phi)d\phi d\theta$
@upbeat harbor
wait whyre we using W instead of F?
This can be also written as
Flux = $-\int_{0}^{2\pi}\int_{0}^{\pi}R^{4}sin^{2}(\phi)sin(\theta)d\phi d\theta + \int_{0}^{2\pi}\int_{0}^{\pi}R^{4}sin^{2}(\phi)cos(\theta)d\phi$
Of u first integrate w.r.t. $\theta$ here , you'll get 0 ig
@upbeat harbor
Because in the formula of flux, F is the vector field, which in your question is W , and F in your question is curl(W)
Which is used in stokes' theorem
hm
This
Okay wait yeah it is useful...
Did you use that information while solving part B?
well i think i solved both parts incorrectly now so i cant really answer that.
what i can say though is that im asking if its relevant to part a?
Yeah it is
Yk the answer has to be 0
No matter what
Because have you ever seen the vector field <-y,x,0>
no
Look for it on Google
It's a stirring like motion
I.e. concentric circles
So that means all particles will just revolve around in a circle of fixed radius
So nothing goes in or out
is it like the vortex field?
One thing we can do is
We found the flux of whole surface with this
Just subtract the flux of the surface below z = -R/4 from this
And I think it should still be 0
Kind of
But it's like concentric circles
Or or we just change the bounds!
Ok but it’s at least similar then
What the vector field?
Yeah, i was just asking so I could get like a general idea of what it looked like
I mean all we’d need to do is change the bounds of phi to make it be above -R/4 right?
That shouldn’t be too hard
This is it
Exactly
Wow you got it!
It’s just changing the bounds kinda sucks lmao
Now notice
We get 0 at the very moment we first integrate with d(theta)
So like the bounds for phi don't even matter
Fair, but I’d still like it to be correct just so I don’t risk having points knocked off
Yeah its a good habit
Hey btw
What bounds did you get for phi?
would the -R/4 change this at all?
working on that right now
I got 0<phi<arccos(-1/4)
but im not certain that thats correct
Hmmm
I get arccos(3/4)
how so?
Oh mb
But it should be arccos(1/4) then
Oh yeah I'm so sorry
I calculated for the other one
You're correct
ok, so it is arccos(-1/4)?
Yeah surely
maybe. let me try and fix the rest of part a, and then ill look over part b again
Alright
ok so for part b, i parametrized the curve as <Rcos(theta),Rsin(theta),-R/4>
then I found the normal vector using that, and dotted it with F to get 0
Dotted...?
Curl is gradient cross vectorField
?
wait hold on, i forgot i solved these backwards
for b, id use F because thats the curl of W, right?
Yeah
ok
What value did you get of F?
<0,0,2>
How........
W is <-y,x,0>
this means that when you take the curl of it, you get:
<0-0, 0-0, 1--1>
,w curl of vector field <-y,x>
Oh ok yeah we can parameterize
Fine
Ok
did i do something wrong? or something that doesnt make sense?
well we know what the curl is then. so now we'd just need to dot it with n, right?
Okay yes
ok, now we just need n then
could I use the surface <Rcos(theta),Rsin(theta),-R/4> for this?
because this is supposed to be only one integral isnt it?
Umm yes
But
Is the fluid or smoke whatever it was
It isn't flowing through this surface....
Okay see here our normal vector will be a vector which yk like goes out the sphere and is normal to the surface of the sphere
mhm
ok
With components dependent on phi and theta
ok so wed end up with <Rcos(t)sin(p),Rsin(t)sin(p),Rcos(p)>?
(t is theta and p is phi, i just wrote it like that to try and make it look a little neater)
oh wait no thats the curve
not the normal
hm
ok yeah i really am not sure now how to do that. would i take the derivatives with respect to theta and phi and then cross them?
Yeah there's a formula to find the unit normal vector for this
taking it with respect to theta gives
<-Rsin(t)sin(p),Rcos(t)sin(p),0>
taking it with respect to phi gives: <Rcos(t)cos(p),Rsin(t)cos(p),-Rsin(p)>
Cross them
working on it
this is disgusting
<-R^2sin^2(p)cos(t),-R^2sin^2(p)sin(t),...>
the z component is gonna take me a good minute
Huh, why do I think something's getting wrong here
Will you give me some time please
Normal vector will be <smthng,smthng,cos(phi)> ig
-Rsin(p)<Rcos(t)sin(p), Rsin(t)sin(p), Rcos(p)>?
I found something in my notes that helped me get this
Oh wait that points inward doesn’t it
I mean we could just multiply by -1 and fix it
What do you mean?
@finite delta Has your question been resolved?
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@finite delta Has your question been resolved?
@finite delta Has your question been resolved?
@finite delta Has your question been resolved?
<@&286206848099549185> can I have a hand with this please?
@finite delta Has your question been resolved?
@finite delta Has your question been resolved?
First let's calculate F = curl(W)
I think it's (0, 0, 2) (verify that)
Now let's compute the flux
Luckily the normal vector to the sphere is parallel to the radius vector
In spherical coordinates, n = (sin(theta)cos(phi), sin(theta)sin(phi), cos(theta))
The surface element in spherical coordinates is R^2 sin(theta) dtheta dphi
So the flux is
$$\int_{-\pi}^\pi \int_0^{\arccos(-1/4)} 2 \cos(\theta)R^2\sin(\theta)d\theta d\varphi$$
EQUENOS
In order to solve (b) just add a flat circular "cap" on the bottom of the sphere and note that div(F)=0
Why is it from -pi to pi?
From pi/2 to pi, 2cos(theta) is negative and will zero out the integral.
Wouldn’t it be 0 to 2pi though? Because it’s a sphere?
I'm basing that on the 2*cos(theta) that Equenos wrote.
Mm. I’ll try and calculate it using this, and 0 to 2pi, and I’ll see if my result changes
Where did that cos() come from in Equenos equation?
The cos(theta)?
Yeah.
That’s from the normal vector I think
Because each horizontal section of the balloon is a full circle
By horizontal section I mean a section parallel to the XY plane
Right, so wouldn’t 0 to 2pi give the same result?
Of course it would
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- Determine the real zeros and state the multiplicity of any repeated zeros
- list the x intercepts where the graph crosses the x axis and those where it does not cross the x axis
- Sketch the graph
All the terms have an x so you can factor
@vital crag am i on the right path? I use these as my zeros right
,w factor x^4+x^3-4x^2-4x
ok cool um
how would I sketch the graph out
I know there are concepts to find when it increases and decreases do u know abt that
@vital crag ?
This precalculus video tutorial explains how to graph polynomial functions by identifying the end behavior of the function as well as the multiplicity of each zero or x intercept.
Algebra - Free Formula Sheets: https://bit.ly/3CBeZMY
Get The Full 50 Minute Video on Patreon:
https://www.patreon.com/MathScienceTutor
Direct Link...
They might be referring to differentiation
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why does triple integrating a 1 (constant) give us the volume?
think about how integrating $\int_a^b 1 dx$ gives us $b-a$ which is the length of the interval $[a,b]$ over which we are integrating
Denascite
yours is the same thing, just 3d
if K is for example a cube you can easily compute the integral and see that you indeed get the product of the side lengths
if you do a single integral of 1, you are multiplying base * a height of 1, which means you get an area which is numerically the same as the length.
similarly if you double integrate 1, you are multiplying area of base * a height of 1, so you get a volume which is numerically the same as area.
so if you triple integrate 1 specifically, you will get the volume. if you were to triple integrate 2, you would instead get twice the volume
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is there supposed to be a "t" when forming the integral next to -r?
Please don't occupy multiple help channels.
Likely yes
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Idk how to do this
<@&286206848099549185>
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Ahhh
I keep forgetting
Mb
hi
hi
how ya doin
good u?
Take ur time
where u from?
is that h = 21 - 20 cos(pi t) or - 20 cos(ht)
born in brazil live in switzerland
I wanna live in Switizerland, I live in Canada tho
This country is shit
1st one
It's h=21-20cos(3pi t)