#help-36

1 messages · Page 141 of 1

opaque pier
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I don't know what to do after I reach a point

opaque pier
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I reached the point where i*w (where w is a cubic root of unity) = (z+1)/(z-1)

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Any hints on how to proceed?

desert mantle
#

multiply by z-1 and isolate

final saddleBOT
#

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cold wolf
#

Is it possible to calculate y (mod 25) while knowing this information?

desert mantle
#

well not uniquely

cold wolf
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Oh right i forgot to mention, caluclate smallest y(mod25)

desert mantle
#

then yes

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try listing a few numbers with y=1 mod 5

cold wolf
#

👍

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Okay i figured it out, thanks

#

.close

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vernal parcel
final saddleBOT
vernal parcel
#

how would u know when to multiply and add

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for this it's 4C3 + 5C2 or is it multiply?

royal swan
mint arrow
vernal parcel
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how would u know when to use which case

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so basically when one case effects the other u add

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and when they both don't effect each other u multiply

mint arrow
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Yes

vernal parcel
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alright thanks 🐐

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mint arrow
vernal parcel
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would this be 90/91?

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total - them being together

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14! - 11! x 4! all over 14!

mint arrow
vernal parcel
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yeahh

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isn't this the worst math topic ever

mint arrow
mint arrow
vernal parcel
#

like binomials?

mint arrow
#

If you allow me I could give you a question regarding the topic which might invoke some interest

vernal parcel
#

this is four right

vernal parcel
#

just year eleven

mint arrow
mint arrow
vernal parcel
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thanks

mint arrow
vernal parcel
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hmm

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i've done a similar question but nothing with a circular table

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8+7+6+5+4+3+2+1

mint arrow
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Are you giving the answer?

vernal parcel
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nono

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give me a minute

mint arrow
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Ohh

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wut mb take your time

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vernal parcel
#

.

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how do we reclaim the channel

final saddleBOT
mint arrow
#

My advice regarding the problem would be to think that whether there is something special about 8 or it's just arbitrarily given

vernal parcel
#

i'm not sure how to do it

mint arrow
vital crag
vernal parcel
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alrighty

mint arrow
mint arrow
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In combinatorics it might happen that the problem for bigger numbers is closely related to that for smaller numbers ie there exists a || recurrence relation||

vernal parcel
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i think i get what you mean

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but i'm unsure what the question is asking

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how many handshakes can be done with eight people or?

mint arrow
vernal parcel
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7+6+5+4+3+2+1

mint arrow
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wut why so ?

vernal parcel
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as one person can shake everyone's hand seven times

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2nd person six times

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etc

flint parcel
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Hello

mint arrow
vernal parcel
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b or d and why?

vernal parcel
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are u asking for the maximum amount of handshakes possible between eight people?

mint arrow
flint parcel
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Is here anyone from 9th grade?

vernal parcel
mint arrow
vernal parcel
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okay lol

vernal parcel
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it's either b or d but i'm not sure how to conclude

mint arrow
mint arrow
# vernal parcel how would u do this though

Hmm okay so we have a degree 4 polyn and it's given that one of its roots has multiplicity 2 so one part of it must be (x-2)²
And it's given its divisible by x²+x+1 so that forms the other part which gives us the complete polyn as a(x-2)²(x²+x+1)

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a is a constant

vernal parcel
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d as it's concave up yeah

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thanks

mint arrow
vernal parcel
#

.close

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tough light
#

2 rue clos mon désir 69100 Villeurbanne

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severe canyon
final saddleBOT
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@tough light Has your question been resolved?

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crude maple
#

could sum 1 help me do my 7th grade math homework

acoustic bloom
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what's the question

crude maple
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1 sec

atomic moon
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y^b • y^c = y^(b+c)

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Apply it twice

acoustic bloom
# crude maple

you can just add the exponents since the base is the same

crude maple
#

could i get the answer 🙂

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@crude maple Has your question been resolved?

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bold lake
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lapis wedge
#

What does homogenous differential equation mean?

lapis wedge
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tried looking it up but I couldnt really understand

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I know what a homogenous system is

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in case its similar to that

steady yoke
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It’s homogeneous if all the parts that depend on y and it’s derivatives compose the equation entirely

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In other words, you cld place all the y parts on the same side of the equation, and it’d = 0

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It’d be inhomogeneous if there was an f(x) that doesn’t depend on y or it’s derivatives, and f(x) isn’t 0

formal trail
#

a homogeneous system of linear equations is one in the form
Ax = 0
for example
4x - 3y = 0
a homogeneous linear differential equation is similarly in the form
L[y] = 0
for example
4y' - 3y = 0
is a linear homogeneous linear ode

lapis wedge
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oh

steady yoke
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The importance of a homogenous DE comes from the fact that any solution forms part of a basis for the solution space

lapis wedge
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I think I see so the x vector is composted of y and it's derivatives

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and if there was a constant

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we would have no variable for that constant essentially and it'd be like

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3x + 3 = 0

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and that wouldnt be homogenous

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and by linear

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do they mean

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all y and it's derivatives must be raised to only the first power

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3y - 4y' + y'' = 0

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but 3y^2 isnt linear?

steady yoke
formal trail
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yes, in the same sense that an ordinary linear equation is linear

steady yoke
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But linear simply refers to it must be a linear combination of y and it’s derivatives

lapis wedge
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oh ok

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im taking linear algebra and de currently and this de hw but it seems to incorporate some linear algebra

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thats pretty interesting

opal pelican
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I may be mistaken, but isn't a homogeneous differential equation one in which the solution function y is an homogeneous function of x?

formal trail
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the study of linear differential equations is very dependent on linear algebra

formal trail
opal pelican
formal trail
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in the context of linear odes homogenous means the same thing as it does in linear algebra

opal pelican
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I recall reading something along those lines, but again I may be spouting nonsense

steady yoke
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Homogeneous in context of DE refers to the fact that any solution of the De can for form part of a basis of its solutions space

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You’ll find that you can engineer DEs so any type of function satisfies it

lapis wedge
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  1. y' = 3y
  2. y' = 2 - y should work right
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yeah I believe thats right

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thanks for the explanation on homogenous and linear

final saddleBOT
#

@lapis wedge Has your question been resolved?

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pine ridge
#

is there a mistake in this solution because i got 2.56

vital crag
#

show how you got your answer

pine ridge
#

i just plugged into my calculator

vital crag
#

,rotate

soft zealotBOT
pine ridge
#

hey @vital crag

vital crag
vital crag
pine ridge
#

ok

final saddleBOT
#

@pine ridge Has your question been resolved?

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chrome cipher
final saddleBOT
chrome cipher
#

does this look correct

#

oml

rocky tusk
#

,w (2x^4 + (4-2i)x^3 - (5+4i)x^2 + 5ix)/(x-i)

rocky tusk
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no way it doesn’t show the quotient

chrome cipher
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so 2x^3+(4-2i)x^2-(5+2i)x+i

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yeah

drowsy epoch
chrome cipher
#

u again

drowsy epoch
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exactly my thoughts

chrome cipher
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ok shut up

drowsy epoch
#

so rude

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i wonder why wanted to be my friend

chrome cipher
#

not even

drowsy epoch
#

not f(-x) = f(x) so true

chrome cipher
#

uh what

rocky tusk
rocky tusk
drowsy epoch
#

me too

chrome cipher
#

what do u mean chck it

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it was a diff problem

rocky tusk
#

check the answer by submitting it

chrome cipher
#

its a review one i complete the whole thing then i get see what i missed

rocky tusk
#

so submit?

chrome cipher
#

im like halfway done

rocky tusk
#

consider finishing them first

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then asking if you get any wrong

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🧠

chrome cipher
drowsy epoch
#

blobunamused "just give me the solution"

rocky tusk
#

no

chrome cipher
#

no like help

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omg

drowsy epoch
#

blobunamused "help me"

chrome cipher
#

i hate yall

rocky tusk
#

cool

chrome cipher
#

thanks

rocky tusk
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happy to help

chrome cipher
#

THen help

rocky tusk
#

after you submit

#

👍🏻

chrome cipher
#

aleifght

drowsy epoch
#

maya is afraid she will get backstabbed with a knief

chrome cipher
#

very

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so like i got a 50

#

.close

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dim hazel
#

Am I tripping or does no work need to be done here? I’m asked to find the LU decomposition of\$$A=\begin{bmatrix}
2&4&2\0&5&2\0&0&9
\end{bmatrix}$$\
But because A is already upper triangular, doesn’t that automatically mean L is the identity matrix?

soft zealotBOT
#

KySquared

wary copper
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seems relaly pointless but

#

ig thats it?

#

@dim hazel

final saddleBOT
#

@dim hazel Has your question been resolved?

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delicate sparrow
#

How do I determine if these graphed functions are negative or positive? For normal straight lines I have learned to use something like x < 3 if it is positive and x > 3 if it is negative. I am stuck on these problems because of how they are graphed

delicate sparrow
#

Same for this

sleek quartz
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not sure what you mean "negative function"

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the a value of the quadratic?

delicate sparrow
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Where the function is positive and negative

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Is what I mean

delicate sparrow
sleek quartz
delicate sparrow
#

I think so

sleek quartz
#

1 < x < 2 or whatever

delicate sparrow
#

Something like that

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"...and describe where the function is positive and negative" is what I need to do

sleek quartz
#

i would say that's describing it

delicate sparrow
#

Can you explain

sleek quartz
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"the function is positive when x is less than 2 but more than 1"

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so when x < 2 and 1 < x

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put together that's 1 < x < 2

delicate sparrow
#

So for a parabola

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How would I do that

sleek quartz
#

well can you read the graph

delicate sparrow
#

Okay

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What would I do for an upside down parabola

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Is it just the same thing

sleek quartz
#

just find the parts that are negative and positive

delicate sparrow
delicate sparrow
#

I get the parabola one but an upside down parabola is different

sleek quartz
#

positive = above the x axis, negative = below the x axis

delicate sparrow
#

Like the graph is going above the x axis?

sleek quartz
delicate sparrow
#

Yes

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Pretty sure why

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But an upside down parabola would be like the same thing unless it's not

sleek quartz
#

it would indeed be the same thing

sleek quartz
delicate sparrow
#

So even if it is upsidedown If it goes to the to sides it's positive?

sleek quartz
#

do you know how to read a graph

delicate sparrow
#

Yes?

sleek quartz
#

are you telling me -6 is a positive number?

delicate sparrow
#

But we read if the graph is positive or negative based on the x axis?

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Like in the first picture

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Why doesn't that just apply to the 2nd graph

sleek quartz
#

every value of x has a y value assigned to it

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we want to know where that y value is positive

sleek quartz
delicate sparrow
#

What

sleek quartz
delicate sparrow
#

Sort of

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Yeah I do

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I think

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Depends what graph

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I can read this

sleek quartz
#

ok let's just look at this for now
can you tell me where y = 0?

delicate sparrow
#

Wait no

delicate sparrow
sleek quartz
#

mhm

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and then the other one

delicate sparrow
#

Y = 0 at X = -2

sleek quartz
#

mhm

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and can you tell me where Y > 0?

delicate sparrow
#

Y > 0 at -1 < X and X > -2

sleek quartz
#

very close, the first condition is -1 > x

delicate sparrow
#

Ok

sleek quartz
#

which is this region btw

delicate sparrow
#

Ok

sleek quartz
#

but yeah the idea is that y is positive in -1 < x and -2 < x

delicate sparrow
#

Wait

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How is Y positive if the graph is going under Y at X > -1

sleek quartz
#

i said -1 < x

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which is the opposite of x > -1

delicate sparrow
#

But the arrow is still pointing at X in both of the things

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As in X is greater

sleek quartz
#

i saw a really good explanation for why this is a while ago but i can't find it anymore

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but "-1 is bigger than x" and "x is bigger than -1" are opposite statements

delicate sparrow
#

But -1 is less than X and X is greater than -1 is the same thing

sleek quartz
#

you're right

delicate sparrow
#

Ok

delicate sparrow
sleek quartz
#

nice

delicate sparrow
#

Ty

#

Do I just do .close

sleek quartz
#

yea

delicate sparrow
#

Okay

#

.close

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bright nest
#

So 2 things: I want to make sure what I’m saying is sufficient enough to prove the statement as I am struggling to construct proofs. And I need help with the last statement F: (A n B = C) - I understand that it’s True but I’m not really sure how I would go about proving that (discrete math)

final saddleBOT
#

@bright nest Has your question been resolved?

bright nest
#

<@&286206848099549185>

sturdy frigate
#

Your answers of a-e looks good to me

#

For the last part you need to do two things

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Let x \in BOTH A and B and show its in C

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Let x \in C and show its in BOTH A and B

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which shows A intersects B is a subset of C

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and C is a subset of A intersects B

bright nest
sturdy frigate
#

Yes thats what you need to show

bright nest
#

I’m not rlly too sure what I should write after that

sturdy frigate
#

Yea I realize this is a bit tricky

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First of all you have x=5n=2m right?

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because it is in both A and B

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Then you can look at 5n=2m and see what it means for n

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what you really want is x=2(5k)

bright nest
sturdy frigate
#

Yes

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Have you figured out on how to write x as 2(5k)?

bright nest
#

Not yet I’m still kind of struggling with that

sturdy frigate
#

I guess it requires some knowledge of divisibility of numbers

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From 5n=2m, we see RHS is even (which means it has a factor of 2)

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But 5 has no such factor (coz it's prime)

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so it must comes from...

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Does that help you?

bright nest
#

So n itself has to be even

sturdy frigate
#

Yes, exactly

bright nest
sturdy frigate
#

Yes

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Show x is in A

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and x is in B

bright nest
sturdy frigate
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tired mango
#

Sorry for the blurry picture. I just want to check my answer. "This statement is true because limits are approaching the value of x=0, meaning that it doesn't matter where x=0 is or if it's defined at all."

tranquil pine
#

I think so.

#

Assuming that $g(0) \neq f(0)$, it is still a removable discontinuity

soft zealotBOT
#

icannotdoanymorecauchy

tired mango
#

If that's true, then is this also true based off the same line of reasoning?

tranquil pine
#

Yes

tired mango
#

thank you

#

.close

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vernal spade
#

can we say that all the equal sets are actually each others' subsets?

vernal spade
#

Such as A = {1,2,3}, B = {1,2,3}. Can we say that A subset of B?

vernal spade
#

all equals are subsets but not all subsets are equals?

distant sleet
#

yeah I think so

vernal spade
#

nice

#

thanks

#

!close

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.close

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tranquil pine
#

Sorry guys, I don’t know shit. Can anybody teach me how to do this?

soft zealotBOT
white sphinx
#

you have the dimensions of outer rectangle and you also know how much they subtracted

final saddleBOT
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@tranquil pine Has your question been resolved?

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cedar rapids
#

Hello, I need help with a math homework that I want to solve but I don't understand how to solve some questions.

cedar rapids
#

que

#

.close

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.reopen

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cedar rapids
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.close

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cedar rapids
#

.reopen

final saddleBOT
#

cedar rapids
#

ya entendi

tranquil pine
#

why is weeb

cedar rapids
#

do you know spanish? or do I say it in English?

#

This fact that everything is in English is stressing me out :c

unreal anvil
#

😦

#

But I don't understand Spanish

cedar rapids
#

okay

#

thanks everyone

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red basin
#

I need help on 2 problems. The first one is this: a jet leaves the Charlotte North Carolina airport traveling at an average rate of 564 km an hour. Another jet leaves this airport 1/2 hour later traveling at 744 km in the same direction using an equation to find how long the second jet will take to overtake the first.

fast grotto
#

what dyt the variable is

#

aka the thing that is changing

red basin
#

The distance?

fast grotto
#

no the distance is actually gonna be the same because we are setting them up to be at equal distance to see when the faster one overtakes

#

id think of it like this

#

the time is what we need to find right

#

so that can be the thing we change

red basin
#

Oh ok

fast grotto
#

when 30 minutes pass

#

then obviously the plane that started first is far ahead

#

but slowly after the 30 mins pass and maybe an hour passes in total, the planes might be a bit closer right?

red basin
#

Yeah

fast grotto
#

so you can set something up where you get

564*t

#

t is time

#

and that is for the first planes total distance travelled

#

what do you think the equation for the second plane would be

red basin
#

744t+30?

#

Wait I did that wrong

fast grotto
#

all g what u think

red basin
#

744(t+30)

fast grotto
#

ok we close

#

firstly we are looking at kilometers per HOUR

red basin
#

.5 instead of 30?

fast grotto
#

yeyeye

#

BUT!

#

you shouldnt be adding

#

instead you should be subtracting

#

cause lets take it at 1/2 hour

#

then the 564(1/2) will have travelled a good bit

#

but then with the equation you found

#

744(1/2+1/2)

#

that one travelled hella

red basin
#

I see

fast grotto
#

in reality it wouldve travelled nothing

#

so we gotta do minus 1/2

red basin
#

After that wouldn’t it be 564t=744(t-.5)

fast grotto
#

yep

red basin
#

Ight

fast grotto
#

then solve for t

#

ez

red basin
#

Thank you

#

I’ll try the other on my own first

#

See ya

#

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quiet tiger
final saddleBOT
quiet tiger
#

Can someone help me solve this

floral solstice
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@quiet tiger Has your question been resolved?

quiet tiger
#

no

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fathom stream
#

This is what Im thinking for (b):

We already know from (a) that a binomial heap has exactly n - alpha(n) edges so now if we were to insert k keys, the total number of edges will be (n + k) - alpha(n + k):

total number of new edges: [(n+k) - alpha(n+k)] - [n - alpha(n)] = k - [alpha(n+k) - alpha(n)] = k - delta(alpha)

Avg cost per insertion ovr the course of k insertions:

(k - delta(alpha)) / k = 1 - delta(alpha)/k

Now im guessing that delta(alpha)/k is small for large k which would imply that avg cost approaches 1 as k increases? idk

fathom stream
#

My whole group gave on this subpart

#

I feel like Im on the right track but im not sure

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fathom stream
#

noooo

#

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final saddleBOT
#

wary copper
#

happiest math student

#

🙏

fathom stream
#

cs + math can get so annoyin sometimes

#

did I cook?

final saddleBOT
#

@fathom stream Has your question been resolved?

fathom stream
#

fuckit Im done with this question Imma just go with this draft It seems good to me

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stoic fable
final saddleBOT
stoic fable
#

<@&286206848099549185>

#

Need help with the proof

tranquil pine
#

!15min

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vital surge
#

unfortunate probably

final saddleBOT
#

@stoic fable Has your question been resolved?

stoic fable
#

<@&286206848099549185>

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ancient kestrel
final saddleBOT
ancient kestrel
#

I have no idea where to go

#

I've tried a ton of different methods, like drawing out the triangles, drawing out the quadrilateral

#

I dont think it is possible to find the value of x or y separately

stone wagon
#

no need to

ancient kestrel
#

So I was thinking we could just find x+y somehow, but cant figure it out either

stone wagon
#

can you find these angles, or, rather, their sum?

stone wagon
ancient kestrel
#

I got it, but how did you figure we needed that so quickly?

stone wagon
#

correct!

ancient kestrel
#

I was running around in circles trying so many different methods lol

#

Then i figured it wasnt possible to find x & y separately

#

So was trying to do x + y somehow

stone wagon
#

idk

ancient kestrel
#

Ah okay, got it thanks

#

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candid cedar
#

why r=3/5 rejected

final saddleBOT
white tiger
candid cedar
#

so what

ionic venture
candid cedar
#

oh

#

its given in que lol

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tropic nymph
#

Hey can anyone explain this derivation

final saddleBOT
tropic nymph
#

my natural thought would be more this approach if I see a^x

spark kettle
#

Here you have a variable to some constant. Previously you had constant to a variable

tropic nymph
#

is variable always a letter?

#

because what if the thing is 2^2

#

(d/dx) 2^2

spark kettle
#

I mean intuition gives you that
$$(x + 1)^n - x^n = n \cdot x^{n - 1} + ...$$

While
$$a^{x + 1} - a^{x} = (a - 1)\cdot a^{x}$$

soft zealotBOT
#

Pluton

spark kettle
#

I mean this isnt a derivative ofc but you can see the change

tropic nymph
#

thanks

#

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warm prairie
#

If a×b <= 36, when is (that fraction + that fraction => 1) true?

warm prairie
#

(My failed attempt below)

silk wind
warm prairie
#

It just says "when is equality?"

#

They really badly specified what they want

#

"Be that a and b are positive integers with ab<=36
Prove that:
(Sum of them fractions => 1)
When is equality?"

spark kettle
#

So its prove that?

#

You can prob assume ab = 36

drowsy epoch
hollow sorrel
#

fix a, note that RHS is minimised when b = 36/a, hence it suffices to show it's true for ab = 36

#

you could then use calculus to minimise a = free, b=36/a

silk wind
#

Just tried 2 random numbers and it worked but that does not sound too mathemathical

warm prairie
#

It says prove but then asks when is equality

#

I think they want 2 answers

warm prairie
#

I know I read everything, Im just trying to understand

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indigo plover
#

ik some people say its not math sry its chem

indigo plover
#

I just watch organic chem tutor

#

and he use m1p1+m2p2=average atomic mass

#

what is this formula being used then

foggy wren
indigo plover
#

because we have fa idk what that is

#

Oh

#

OH

foggy wren
#

its the atomic mass of the carbon 12 * its abundance

indigo plover
#

THATs the decimal version ok

#

im idiotlol

foggy wren
#

haha

indigo plover
#

thnx so much

#

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narrow yew
#

I have this discrete dataset of a bacteria growth. How can I find an elementary function that aproximates it?

narrow yew
#

these are my points

#

😫

royal gust
#

Looks kind of like a quadratic

narrow yew
#

yeah I got a close quadratic aproximation

#

but I need more precise

#

this is as close as I could get

royal gust
#

You can probably get better with a cubic. Looks like those two right points are at the cubic's inflection point, and the curve will start going up

narrow yew
#

is there anyway I could use fourier series??

#

or no because it's not rlly periodic

royal gust
#

You can make it periodic

narrow yew
#

But how on earth would I go on to find such coefficients

mint orbit
#

wouldnt you be better using some model that was informed by the physical medium blobsweat

mint orbit
#

i mean like, its bacteria right

#

so maybe something like logistic makes sense

narrow yew
mint orbit
#

oh and the assignment is just 'find a function that looks like the data'?

narrow yew
#

well not really but I'm just trying to get extra credit

mint orbit
#

well i guess logistic isnt gonna look like the data

#

so maybe thats a bad choice opencry

narrow yew
#

closest I can get to

mint orbit
#

you can make it exact

#

use an interpolating polynomial

#

usually you dont want your model to be exact

#

sorry i shouldnt have interjected myself into this bearlain

narrow yew
#

is that doable by hand or will I need python

mint orbit
#

you can do it by hand, its not fun but you can do it

narrow yew
mint orbit
narrow yew
#

alright, I'll try it out. Thanks a lot for the suggestions!

narrow yew
vital surge
vital surge
mint orbit
#

yea it has a tendency to behave insanely

vital surge
#

(if this is an assignment i would not recommend using)

final saddleBOT
#

@narrow yew Has your question been resolved?

narrow yew
#

I mean I don,t really see phenomenon in the lagrande interpolation I did

vital surge
#

the problem says “elementary function” so ideally quadratic is preferable to such degree polynomial

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narrow yew
#

.reopen

final saddleBOT
#

narrow yew
vital surge
narrow yew
#

I mean honestly I think I'm making a big deal out of this rn but I found "Chebyshev nodes" that I can apply to fix this little issue

vital surge
vital surge
narrow yew
#

I think I'll be fine with what I have rn. Thanks for the advice!

#

Have a good night or day or idk

#

.close

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tranquil pine
#

A line makes angles $\alpha, \beta, \gamma, \delta$ with the four diagonals of a cube then $\cos^2\alpha+\cos^2\beta+\cos^2\gamma+\cos^2\delta$ is equal to

soft zealotBOT
final saddleBOT
#

@tranquil pine Has your question been resolved?

limpid egret
#

@tranquil pine you can solve it by using direction cosines

#

example, one such diagonal connects the point (0,0,0) to the point (1,1,1) in a unit cube (where each side of the cube has a length of 1).

tranquil pine
#

i dont get it

#

i just cant really visualize it

limpid egret
#

ok np

#

In a cube, each of the four space diagonals connects a pair of opposite corners. All the space diagonals are identical in length and make equal angles with the coordinate axes due to the cube's symmetry.

#

Because of the symmetry of the cube, the angles that the diagonals make with each axis (x, y, z) are the same. The fact that the line makes equal angles with all four diagonals implies that the problem is symmetrical.

#

send ok if you understood the stuff I sent you

tranquil pine
#

ok

limpid egret
#

you know the direction cosine identity ?

tranquil pine
#

like the sum of their squares is equal to 1?

#

that one?

limpid egret
#

it states that the sum of the squares of the direction cosines of a line is 1

tranquil pine
#

yea well i know that identity

limpid egret
#

so using the above concept and the direction cosine identity it can be stated that :
cos^2 α + cos^2 β + cos^2 γ + cos^2 δ=1

tranquil pine
#

yeah

#

but wait

#

how did that delta part come there

limpid egret
#

as given in question

tranquil pine
#

yea but ok

#

i mean

#

if there would have been 10 angles, would it be the same?

#

like just add the other angle part

limpid egret
#

all those 10 angles should be on the same line or equal lines

#

for this direction cosine identity to be applied

#

as here all 4 diagonals are equal

#

got it ?

tranquil pine
#

ohhh ok got it

#

tysm 🙏

limpid egret
#

well then as mentioned in above concept all angles are equal

tranquil pine
#

why are the angles equal

limpid egret
#

cube is symmetrical

tranquil pine
#

oh ur talking about the diagonals

#

i thot u were talking about the line

#

yea wouldnt they make 45 degrees

limpid egret
#

we don't know about that

#

it can be anything

tranquil pine
#

why can it be anything if its a cube?

limpid egret
#

also regarding that doubt of yours of 10 angles

tranquil pine
#

nah wait nvm

tranquil pine
#

got it

limpid egret
#

If there were 10 angles (say, angles a line makes with 10 different directions or lines), the situation would be different. These angles would not correspond to the angles with the coordinate axes, but to some other set of directions (perhaps diagonals, or arbitrary lines). In that case, you wouldn’t use the direction cosine identity directly.

limpid egret
#

cube is a 3d object

#

so it is located on an xyz plane

#

so we will only write cos^2 α + cos^2 β + cos^2 γ = 1

#

Reason on why δ not included :
In this case, δ represents an additional diagonal, but the three direction cosines α, β, and γ fully describe the geometry of the cube's diagonal with respect to the coordinate axes. There is no need for a fourth direction cosine, cosδ, because in three-dimensional space, only three angles can define the orientation of a line or vector.

#

it is just not needed

#

understood ?

tranquil pine
#

yea its making more sense now

#

can i close now?

#

im done with my doubt

vital crag
limpid egret
final saddleBOT
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shell plover
#

Ik this is a weitf question but if I integrate a velocity function into a position function and plug in my numbers and I'll get my position value. But since it is an indefinite integral wouldn't you put a + C and the end of your answer?

formal trail
#

yes, which is why you need to know the position at some point in time so you can solve for the correct value of C

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quartz pelican
#

Hey! So i am in the 8th grade and doing algebra 1 so my question is why is f(x-2) called* shifting to the right instead of shifting to the left?

quartz pelican
#

It just seemed kinda confusing to me

#

If you can answer thank you!

shell mica
#

If the minus is inside the function, it shifts opposite way. If it's outside it, it's same way.

quartz pelican
#

But whenever it's f(x)-5 it is intuitive

#

it shifts y down

shell mica
#

Exactly

quartz pelican
#

but whenever its f(x-5) its counter intuitive

shell mica
#

Yes, that is the exact rule

#

Remember, f(x-5) isn't changing the x value, it's still changing y

#

So you want to know at what x value will the y height be the same as originally, if that makes sense? Honestlly transformations can be really hard to explain, typically you just learn it

quartz pelican
#

Oh

#

So basically like

#

If its f(x-3)

#

you have to add 3 to x to get back at f(x)?

#

so its called shifting to the right because of that?

shell mica
#

If memory serves correct then yes

#

Honestly, it's just easier for your sanity to remember that if it's in the bracket, it's the opposite, if it's outside it, it's the same

#

It could be easier to visualise if you try it with a couple of random functions

quartz pelican
#

True

#

I think desmos might help me out

shell mica
#

But just learn the transformations that should be in your textbook and you'll get it!

quartz pelican
#

Thanks! We took notes on it today, also I just really think math is interesting and im trying to learn alg 1 to pre cal by the end of the year

#

.close

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wet kelp
final saddleBOT
wet kelp
#

Hello, i need help with tge following equation, i have no clue what im doing wrong

#

As you can see ive tried bith the big and the small quadratic formulas and got the same exact result

#

I dont understand

solar birch
#

81+40=121=11^2

wet kelp
#

Thank you

solar birch
#

np

wet kelp
#

Im gonna throw myself out tge window now

#

Hahahhaa

solar birch
wet kelp
#

Thank you again

#

.close

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vital sinew
#

$gcd(a, b) = c \implies gcd(a/c, b/c) = 1$??

soft zealotBOT
fallen vigil
#

kak

vital sinew
#

😢

fallen vigil
#

i think so

vital sinew
#

@fallen vigil its cookedjoever

#

?

#

can i do this

#

and considering k < n, k neq 0

#

tyring to say that the number of k is exactly d

#

which seems almost ovbious kinda

fallen vigil
#

i dont see how they got from one to the other

#

they should show their work

vital sinew
#

wdym

fallen vigil
#

i mean i dont understand

vital sinew
#

its number theory...

#

so im cooked

#

fuck it im using a trivially

fallen vigil
vital sinew
#

prof can lick my balls

#

.close

final saddleBOT
#
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fallen vigil
#

that is equ to

#

for some r, s,

ra+sb=c

#

if they are all divisible by c then u can simplify it by dividing yea

#

@vital sinew

vital sinew
#

its joever ngl 😔

fallen vigil
#

joever

vital sinew
#

im just gonna restart the question LOL

#

kms

#

.close mylife

fallen vigil
#

lol

final saddleBOT
#
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vital sinew
#

let $G$ be a cyclic group of order $n$, generated by the element $a$.
\begin{enumerate}
\item (3 pts) For any integer $i$, determine the order of $a^i$ in $G$ (in terms of $i$ and $n$).

\item (3 pts) Show that every subgroup of $G$ is cyclic and that for any $d\mid n$, $G$ has a unique (cyclic) subgroup of order $d$.

\item (3 pts) The Euler $\phi$ function is defined by
[
\phi (n) = | { 1\le a \le n, \ \gcd(a,n) =1 }
]
Give a formula for $\phi(n)$ in terms of the prime factorization of $n$ and show that $\phi$ is multiplicative, i.e., $\phi (mn) = \phi (m) \phi (n)$ if $ \gcd (m,n) =1$.

\item (4 pts) Show that for any $d \mid n$, the number of elements of $G$ of order $d$ is exactly $\phi (d)$. Deduce that
[
\sum_{d\mid n} \phi (d) = n.
]

\item (3 pts) Show that $\Aut (G) \simeq (\Z/n\Z)^\times$, where the latter is the multiplicative group of classes mod $n$ that are coprime to $n$. In particular, $|\Aut (G)| = \phi (n)$.

\item (4 pts) Let $m$ and $n$ be positive integers. Show that $C_m \times C_n \simeq C_{mn}$ if and only if $m$ and $n$ are coprime.

\end{enumerate}

soft zealotBOT
#

kaxi
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vital sinew
#

Specfically, for 4., how can this statement be true?

#

$\phi(d)$ for $d = n$ is $\phi(n) = n$?

soft zealotBOT
vital sinew
#

or nvm

#

.close

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vital sinew
#

😔

ivory vessel
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velvet condor
#

i need help 😦

final saddleBOT
rustic sinew
final saddleBOT
# velvet condor i need help 😦
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
velvet condor
#

3

rustic sinew
#

Can you show your work?

velvet condor
#

i went by the formula (a-b)(a^2+ab+b^2)

#

a being a^3 and b being 5^3

ivory vessel
velvet condor
#

so what did i do wrong?

#

@rustic sinew

#

<@&286206848099549185>

rustic sinew
final saddleBOT
# velvet condor i went by the formula (a-b)(a^2+ab+b^2)

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

rustic sinew
#

Can you show what you mean by a is a^3?

velvet condor
#

whoops i meant x^3

#

.close

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rustic sinew
velvet condor
#

yeah i had to use the quadratic formula

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low storm
final saddleBOT
tranquil pine
#

what exactly is the question

#

you want to graph these?

low storm
#

Yea

tranquil pine
#

what did you try

low storm
#

Substitution

#

@tranquil pine

tranquil pine
#

can you show your work?

low storm
#

Are you asking if i am allowed to?

tranquil pine
#

no, i meant "please show your work"

low storm
#

alright

#

But thats the tthing

#

idk how tot do this

tranquil pine
#

you dont know how to substitute ?

low storm
#

Nver really focused on it

tranquil pine
#

i would recommend watching a video on youtube to clear your concepts

#

and then attempting the question

low storm
#

Uh

tranquil pine
#

unless you have a lot of time and wanna mess around with every method you can

low storm
#

ok..

#

I mean nah

#

.close

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final saddleBOT
#
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sullen relic
#

I've been trying to do this problem with the surface area formula I've learnt (attached in image), but I'm having trouble integrating it. I've gotten up to the point where I plugged everything in, and now im unsure where to even start from. Any advice would be appreciated.

formal trail
#

note that the expression inside the square root is a perfect square

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#

@sullen relic Has your question been resolved?

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gritty nest
#

Apologies in advance if my explanation isn't clear.

Say you have a bracelet of 12 equally spaced out beads or similarly a regular dodecagon.
What would be the general formula for the amount of possible ways a fixed triangle can fill the vertices of this bracelet/regular dodecagon with its shape and without occupying the same vertex?
Also, inversions or mirror images are considered the same.

The image posted is an example of one possible configuration of this.

In this example there's a triangle whos fixed shape occupies all vertices once. Of course given its a triangle filling a 12 sided shape in such a way, you will always need four of them.
However, this is apparently one of many configurations that this triangle can make to fill the vertices of the bracelet.

I tried applying a combination of consecutive and non consecutive selection, but I got stuck in trying to figure out how to maintain a fixed shape. Perhaps there isn't a general equation to this question and needs to be solved using several different steps.

final saddleBOT
#

@gritty nest Has your question been resolved?

steep timber
#

Well, 2 triangles are equal if and only if all 3 sides are equal, and the chords of a circle are only equal if they have the same arc length

final saddleBOT
#

@gritty nest Has your question been resolved?

final saddleBOT
#

@gritty nest Has your question been resolved?

final saddleBOT
#
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restive beacon
final saddleBOT
restive beacon
#

The f’(x)

#

I tried the U substitution and get it wrong

terse crypt
#

+c

restive beacon
#

Yes

#

But do i need to expand the (1-x^2)^2?

terse crypt
#

No need

#

Just substitute 1 in

restive beacon
#

1-1)

#

0?

#

C should be 1/6

spare hazel
#

(1-x^2) or (1+x^2)?

restive beacon
#

What

#

Its a minus

spare hazel
#

oh

restive beacon
#

1-1 is 0

#

Wont work

#

I think i need to expand it

#

Sooo weird man

spare hazel
#

differential equation

restive beacon
#

?

spare hazel
#

expand it

restive beacon
#

Nopp

#

I tried

#

How can the answer be 1/6????

spare hazel
#

correct answer is -1/4*(1-x^2)^2 +C

restive beacon
#

That C should be 1/6

#

We want to solve for C

spare hazel
#

expand (1-x^2)^2

restive beacon
#

I did the easy way

#

Just multipler x in

#

Multiplied

spare hazel
#

solve it

restive beacon
spare hazel
#

correct

restive beacon
#

Ye, But i wonder what i did wrong with the substitution

spare hazel
restive beacon
#

Ok But what i needed to do is just expand it

spare hazel
#

yea

restive beacon
#

And then solve for C

spare hazel
#

yes

restive beacon
#

Ok

#

Thank you !

#

.close

final saddleBOT
#
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#
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scenic pendant
#

How can i graph xy-y-2x ≥ -1

final saddleBOT
gentle barn
#

Isolate y

final saddleBOT
#

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shrewd mist
#

Let (S, <=) be a POSET then for x, y E S, "x <= y" and "y <= x" are equivalent right?

shrewd mist
#

because x <= y means that either (x, y) E <= or (y, x) E <= and same thing goes for y <= x

barren hound
#

no

#

an example of a poset is the real numbers

scarlet sequoia
#

"x <= y" and "y <= x" are kinda the opposite of equivalent

#

the only x,y that verify both at the same time are such that x = y

#

an order is antisymmetric

#

and x <= y only means (x,y) is in your relationship set

shrewd mist
#

Let (S, <=) be a poset and x,y E S, y covers x if x <= y, x != y and there are no elements z E S such that x < z < y

#

In the above definition

#

they have mentioned specifically about "x <= y" and not "y <= x"?

scarlet sequoia
#

uh huh

shrewd mist
#

So if S = {1, 2, 3} and P(S) denotes power set of S, P(S) = {phi, {1}, {2}, {3}, {1,2}, {2,3}, {3,1}, {1,2,3}}

#

(P(S), <=) is a POSET where <= denotes the set-subset relation

#

how does {1} cover phi?

scarlet sequoia
#

well

#

(first of all emptyset's notation is usually not a phi just to be clear)

#

we do have emptyset as a subset of {1} right?

#

and a proper subset at that

shrewd mist
scarlet sequoia
#

ok

#

so " x <= y, x != y"

#

is there a proper subset of {1}, call it z

#

such that emptyset is a proper subset of z?

shrewd mist
#

but for {1} to cover empty set, x = {1}, y = empty set, x !<= y

#

as {1} is not a subset of an empty set

scarlet sequoia
#

y covers x if x <= y, x != y

#

you're looking at "x covers y"

shrewd mist
#

ohhhh

shrewd mist
#

yess

scarlet sequoia
#

we wanna know if {1} covers emptyset

shrewd mist
#

so an empty set does not cover {1} right?

scarlet sequoia
#

so emptyset = x

scarlet sequoia
#

because {1} is not a subset of emptyset to begin with

#

we wanna know if {1} covers emptyset, so emptyset = x and {1} = y

#

we do have x < y

#

is there some z such that x < z < y?

shrewd mist
#

also, just to clear some confusion, in a poset, x <= y implies that (x, y) must exist in <= right?

scarlet sequoia
shrewd mist
#

similary {1,2} does not cover empty set as z = {1} exists such that empty set < z < {1,2}

scarlet sequoia
#

yep

shrewd mist
#

also why are posets even studied? Like what do they represent? I heard its something about comparing elements to each other

scarlet sequoia
#

an order relation is literally a "hierarchy" between elements

#

imagine S = employees of a corporation

#

and <= being "takes orders from"

#

that'll create multiple chains of command

#

with for example the CEO at the top (I'm guessing)

#

where two people don't necessarily take orders from one another

#

but if you have A taking orders from B

#

and B taking orders from C

#

A technically needs to take orders from C as well

shrewd mist
#

Oh I see, you can set <= as some sort of a comparision and then represent models of data using hasse diagrams

scarlet sequoia
#

for example

#

and then we have other examples

#

such as R, the real numbers

#

where we have a POSET, even better it's a TOSET