#help-36
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technically ur right, but ur answer is too vague
they were probably looking for something like the p-value is greater than the alpha level
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how do i solve this after factoring out the x on tpo
Try plugging in x = 2
always ask urself if the limit is an indeterminate form
I checekd
and what did you get?
if its not 0 / 0 or infinity/infinity, then its just the value you get when you plug in
ohh
(assuming its continous which most functions you'll deal with are)
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Can you distribute powers on complex numbers?
For eg is (ω²)^7= (ω)^14?
ig it fine if it is an integer
And if it is not?
77²
is it equal to $(i^{4})^{\frac{1}{4}}$?
No
77²
in general no, powers don't work like that in complex numbers, but powers are usually multi valued anyway
@rapid helm Has your question been resolved?
$$ (e^{i \theta + 2\pi n})^a $$
StrangeQuarkAL
$$ e^{i a \theta + 2\pi n a} $$
StrangeQuarkAL
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could someone please help me out with this question? i've understood up to pi x 6 x l
what grade ur in btw?
curved surface area = slant height x Perimeter of circle
its look alike grade 5 question tbh
nah that's crazy 😭
try to do it here
alr
u know how to count perimeter on circle right?
yessire
inform me k if u found anything
can someone explain this to me? im so dumb TwT
350 cm = slant x 37.7
(√√16)² = ...
bruh open new question
sorry im new
thank you!
here
oh did i do the perimeter wrong
,calc 350 / 37.7
Result:
9.2838196286472
,calc 12 * 3.14
Result:
37.68
ohh
here is the slant
the heigh u can use phytagoras
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hi
Can anyone send notes for trigonometry jee?
there should be jee servers on discord
ask this question on that
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@verbal owl Has your question been resolved?
@verbal owl Has your question been resolved?
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let $a,b,c\in\mathbb{R}^+_{*}$
$$abc(a+b+c)=100$$
find the minimum value of $(a+b)(b+c)$
Skill_Issue
ac(ab+b^2+bc)=100
(a+b)(b+c)=k=ab+b^2+bc+ac
ac(k+ac)=100
k=100/ac-ac
it would be very nice if i csn just am-gm this but its -ac so :(
well it's not too bad to analyse the function f(x) = x + 100/x
isnt it k - ac in line 3?
the 3rd line is wrong
oh omg
and yeah it's -ac
should be ac(k-ac)
it is 20 yes
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🎉
oh yeah btw make sure to prove ac = 100/ac is possible
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how is this A
is it not 1+12+23+34+45+56+67+78+89+100=505?
yeah those answer choices are way too big
wtf so is the question wrong
there is one answer that is none of the above so
are there multiple versions of the test? you could try looking at another and seeing if it's written differently
but the answer was A
ill try to dig trough the internet
aight
@jagged flare
your teacher added an extra "0" after the answer ig
i got 505
which is quite "similar" to 5,050
cant even find the original pdf lol, got nothing unfortunately
or perhaps its 505 (sum) x 10 (number of rows/columns) = 5,050
https://seamo.com.br/Paper_E_2020.pdf
unless if you guys can open this somehow, the link is broken for me
yeah i can open it but it's the same issue
i can open and see a TCIMO
looks like they just wrote it wrong
wtf its stuck on downloading for me >:(
this is not for a class
but the example wont hold then
also they alrd know the answer is 505 (cuz they calculated it on their own)
oh
they were just making sure the test was wrong
i mean they had no way of knowing :p
ah
wtf i didnt even see that lmao
ket
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my eyes are broken
fair enough 😭 happens
true
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Hi, how can i find the domain of sqrt of x -6 (the minus 6 is not in the squar root theres a space between them)
,, \sqrt{x} - 6
cloud
when is the sqrt function defined
do you know the domain of sqrt(x)
if udk what that means
plot the graph of root x
and see what x values it can take
domain means
x values
ok
ur gonna kill me but im still not understanding what you mean by defined
im associating it with like vocabulary definitions like a dictionary
inside the root
no
no negative numbers under a root
correct
now domain means
ur asking urself
what x values can the function take
so negative nos. are gone
can i put x = 0
inside a root
yea
and can i put positive nos.
yea
any number thats positive
yup
thats the domain
no that doesnt affect the x values
so if my hw is asking "Domain where F
is one-to-one and increasing"
would i put [0, infinity)?
this function is always increasing
lol
do u know how to check that
in fact it is one one as well
i mean increasing implies it is one one but yeah
ngl im lost again, what sorta answer as an example would i put
is it asking for a notations?
and increasing?
idk but increasing means its always getting bigger
idk but if i had to guess it would be by checking the function, for example its root x MINUS 6 so in this case it would be decreasing?
idkkkk im so sorry thats just a guess
im being dumb imma let you explain
no
u differentiate the function
and check if that is positive or not
if that is positive always
then it is increasing
in this case the derivative is 1/2(rootx)
which is always positive
so it is increasing
and if it is increasing it is one one
so the domain doesnt change
if only a part of the function behaved this way
u would have to chop off the domain
by some bit where it doesnt obey what the question says
im trying my hardest to wrap by head around what all that means but its gibberish to me and i hate that
im not good at math at all im sorry
literally the only part im good at is finding the f inverse
lol its okay
this whole domain thing is difficult for me
ik i said this already but basically i dont touch the 6 at all?
cuz were looking at root x which shows that all positive numbers including 0 can be graphed
but dont i like move the start of the graph to a specific area either left or right by 6 units?
nope
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but if n = 2, we get 0.01 which has many numbers lesser than it
it's for all n
read it like this:
there is no positive number that is (less than 1/10^n for all n)
what is meant by "all n"
it means any value of n right?
It means that there is no positive number that is less than 1/10 and less than 1/10^2 and less than 1/10^3 and less than 1/10^4 ....
The order in which you read it is important
This (there is no positive number that is less than 1/10^n) for all n
is different from this there is no positive number that is (less than 1/10^n for all n)
@cloud raft Has your question been resolved?
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Can someone help me with some of these?
I have some idea but need help
Which one?
all, ill run down my answers
Alr
lets start at one
so as x approaches -4, whats the value, right?
Correct
Correct
alright, jotting down one sec
ok, as x approaches 3, its at the origin
so the limit is 0?
Correct
got it, jotting down
so at f(3), its at origin but there is a black dot, so -1?
ill get stuff wrong later, just wait
Yep
ok, as x approaches -1, it goes infinite, and infinity cant be a limit
so DNE?
or -1?
im a struggling calc student
i did very bad on a test and my grade is very very poor
and my parents dont like it at all
so im trying my best
just a couple more, thanks for sticking with me
so as x approaches 0 from the left its at a closed circle, so DNE? or is it 1 since theres an open circle below it
Notice that limit is a concept of "approaching something"
Check where would it approach when from the left side
it hits 2, but its a closed circle?
Yes, it’s just 2
but i thought closed circles were DNE?
The exact value has nothing to do with limit
Nah
No, it’s not
is it 1
DNE only appears when left limit ≠ right limit
ok, so whats the reasoning for 1) being DNE?
yes
ok ran thru 11) in my head, it is true
Before that, lemme ask you a question rq to confirm you actually knows how it works
ok
What’s f(0)?
2
11 is correct, at lim x approaches -4, it is -2, and f(-4) is also -2
Correct
and 12 is false, as at x->3, it is 0, and f(3) is -1
thank you so much, just talking about it helps, and you really wanted me to learn it
i really appreciate you!
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,w dist((-25,-25),(-10,15))

so im right>
well unless wolframalpha is wrong, then yes
what am i doing wrong on thsi one
the points are barely visible, idk where K is 😅
this shit got me tripping
it changed for some reason
are the cords on this not 2,2 and -1-1?
they are
distance formula / pythagoras
Result:
5.6568542494924
,calc 4 * sqrt(2) * 0.25
Result:
1.4142135623731
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Given P is the centroid of triangle ABC, there’s a line passes point P and intersects with line AB and lineAC at point Q and point R respectively. If vector AQ = a vector AB, and vector AR = 3a/2 AC, then a=?
I can only find that Q lies upon the pink line and R is upon the yellow line
I try to put the circumstances into xy plane then I can analyze it using coordinates
I think I should use the property of P being the centroid
<@&286206848099549185>
@jade fable Has your question been resolved?
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I genuinely don'T get it
@hard frost Has your question been resolved?
you got c correct
and imo, its the hardest one
a and b and easier, try
consider the first displacement as a vector A with magnitude ||A||=6 and the second displacement as a vector B with mag ||B||=8
Yeah I tried using the formula "A * B = AB Cos" but i was horribly wrong at first
thats the dot product, i dont think it has anything to do here
yeha I realized that after the first attempt
you want the magnitude of A+B
to be 14
what angle must be between A and B to have that?
isn't there a formula for that
notice 6+8=14
exactly xd
since cos0 = 1
LISTEN 😭
the two vectors will be alligned
and therefore the magnitude of their sum
will be simply 6 + 8 = 14
Okayy yeah that makes a lot of sense
now, 6 + 8 = 2
i could've sworn there's like a formula for this
oh it's a tight angle
they chose 14, 10, and 2 in this exercise cuz they result in special angles
after you do this exercise, if you got time, try to generalize it :p
I see,
okay, how about 2m
it should be 8-6
but i can'T change can I
wait
180 deg?
since it's the opposite of
i have no idea wrtf I'm sayting
exactly, if you walk forward 8m then backward 6m
youll end up 2m forward
from where you started
think of these displacements as vectors
me horribe at explaining, but ty gl
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Hi i need help graphing a parabola with only vertex and focus/directrix given
i got this example but idk how to process
I need to know the step by step process🥹
ask your teacher
Or classmates
the guy in the green hoodie ought to know
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Dunno how to start
looks like taylor series helps
evaluate derivatives of f at 0 and see what happens
I haven't been taught this ;-;
Probably but I don't know how to properly expand f(x) here
that's what multinomial theorem does, it expands powers of polynomials by referencing multinomial coefficients
like how binomial theorem expands powers of binomials by referencing the n choose k's
Oh i see
Yea
I think my suggestion is naive, maybe there's something prettier out there but whatever lol
So how would it apply here like what would we get after we apply it
Oh ;-;
@ancient basalt Has your question been resolved?
Do you know how to find a_0 + a_1 + ... + a_n ?
There's a certain complex number that can be plugged in for x here that's very useful
And it turns the problem into a more difficult version of this
Yea
Which one?
That's for you to find out
What gives you a pattern of 1, -1/2, -1/2
as you take powers
how would you find a_0 + 2a_1 + 4a_2 + 8a_3 + ...
I'd expand the polynomial upto a few terms and see if there's a pattern in the coefficients and solve
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Oh mb
what do you get when you plug in 1 to the polynomial
4^1959
And I assume you do not actually know this then
How to find a_0 + a_1 + ...
Don't really know any techniques ;-;
Not really sure why you said you knew how to solve it then
I thought you meant like finding the coefficients
Ye mb
what do you get on the right side when you plug in x=1
By putting x=2?
Right
Now what complex number has powers that look like 1, -1/2, -1/2, 1, -1/2, -1/2, 1, ...
not exactly like that but close enough
I haven't really learned many complex numbers , i only know the general form and stuff like z = a+ib
Ah
Idk where you're getting these problems from but this one is way too hard for you
Olympiad mock test ;-;
Most of them are hard af
Plug in x = -1/2 + isqrt(3)/2
take the real parts of both sides
the answer will magically emerge
yw
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I need help with y=mx+b
I need help find the “mx” part and creating an equation based on the slope
This is what i have now.
I can identify B, but i’m having trouble identifying mx
I’m unsure if “mx”, or just the “m”, is the refers to the slope.
But what do i do when i do find the slope? Do i leave it as a fraction, or is there another step after that?
its only the m
do u know the formula to find the slope?
what about if ure given coordinates?
are u familiar with this? the second one i mean
Yes i have seen this before
yeah use this one to find the slope, m
just take any 2 points from the graph then plug it in this equation
Ok i’ll give it a try
So for the Y, i did 5 - 9 = -4
And for X, i did 45 - 39 = 6
But it feels like i did something wrong
are those the points from the table?
I got these numbers from the table above the graph
yeah but, u should take the points from the graph get it?
The points from the table are the points that are on the graph. So i assumed that both would give the same answer
But many of the points don’t fall directly on the line, so i wasn’t to confident trying to eyeball the graph
hm but what i observed is that the points from the table were scattered points, and the graph is like the best fit line, am i corrrect?
yeah that's it
the graph u constructed is a best fit line
Yes. The line is a line of the best fit.
Ohh i think i might have said the wrong then
I want to find the equation for the line of best fit
yep thats why we need to take a point (any point) from the line, not the table
bcs, if we want an equation for the line, then we need the gradient of the line, therefore we need to take 2 points from the line
do u get my point?, the values from the table and from the line is not the same
i think i get what you mean. So i’m taking an x and y point from the best fit line?
yeppp
Oh. That makes much more sense. I’ve been focusing on the wrong thing the whole time
mhm but its okay
So the gradient of this line would be 14/22.5? With 14 as the Y and 22.5 as the x.
Can rounding be used with coordinates? Or should i try and be as accurate as i can?
okay how do u get 14 and 22.5?
sure ig, but mostly ppl jus leave it in a fraction form
based on my observation, i assume u took the points (14, 30) and (22.5, 15)?
Yeah
again we need to use this
What do you by the -8.5?
14 - 22.5
.
Ohh i see. I see what you mean
Yeah and that would be the y point of the gradient needed for the equation. So the x point would be 15 (30 - 15)?
So i think it would be -8.5/15 ?
u got it but its the other way around now😭
u reed the coordinates x first, then y right?
Yeah i was about that doesn’t the x come first in the coordinates?
Since 14 and 22.5 are the first coordinate in the parenthesis
well um thats bcs 14 and 22.5 are the x points
So what do you mean them? Not sure i understand
Oh wait nevermind. I think i see it now
Called 15 the x coordinate. I mean that 15 should be the Y coordinate and -8.5 should be the X coordinate
yeah u got it haha
So now that i have y=-8.5/15(x)+55
What would the x be?
it should be 15/-8.5
x and y are variables, we dont need to find them
we need to take the Y first, then the X, m = Y/X
hre
So as a recap, in the equation y=mx+b the -8.5/15 is the “m” part of the equation correct? And the 55 would be the “b” part of the equation. And the “x” part of the equation is a variable i leave blank?
Just to make sure i fully understand it
yeahh
but then again😭
Oop
Y first then X
Gotcha. And is that the same with all problems that use the coordinate plane?
All throughout middle school, i’ve always done the x coordinate first and haven’t been corrected on it being incorrect.
it's like this, dont get confused
to READ a coordinate, we read the x first, then y
but to find gradient, we put y first, then x, as in m = (y2 -y1) / (x2 - x1)
got it?
Ah ok. I think i understand
good
So my last question would be, how would i find a point that isn’t on the graph. I’m assuming that is what the x variable is used for?
exactly
so if u have a y point and u want an x point just plug the y point into the equation then solve it
or vice versa
So if i wanted to find the x point for 40 minutes, i would have to construct this equation to find it? Y=15/-8.5(40)+55?
u want to find the x point or the y point?
I’m assuming it would find the Y point .
Since the number of students was 0 after 32 minutes, how many students would there be after 40 minutes.
ure right
logically still 0
but mathematically
negative something
but ofc we need to use logic
Gotcha. So does that mean that an x coordinate can found this way also?
yeps
So if i wanted to find an X coordinate, would i place my Y coordinate that i’m using to find the X coordinate, in that same variable?
If that makes sense
The X variable. I replaced it with an X coordinate to find a Y coordinate
oh yeah that is correct
So i would replace the X variable with a Y coordinate to find a X coordinate?
well technically its not replacing but substituting
okay let me give u an exmple
say we have a coordinate (x,10) and we want to find x, usng the same equation, Y=15/-8.5X+55, we substitute the 10 value to the Y term, then, solve the equation to find X
Not too sure i’m understanding.
Would the 15 become 10? Or is the actual Y letter of the equation being substituted?
oh 10 is just an example
yeah the actual y letter is being subsituted
well its a pleasure to help, u can reach me if u need any more help
Will do. Thanks alot for talking me through. It was very very helpful. Have a great rest of your night or morning.
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is is ((sec(c))^2 always greater than ((tan(c))^2
becaues i have proved this:
root(1-sin^2) = cos^2
cos^2 * sec^2 = 1
root(sec^2 - tan^2) = 1
sec^2 = tan^2 + 1
Yes
That's correct
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Hey im trying to solve: Prove by induction that for all positive integers n, k=0 to n Σ k(k!) is equal to (n+1)! -1
ive gotten my base but when i try to plug in n=m+1 I cant find the right way to the answer
$\sum_{k=0}^n k(k!) = (n+1)! - 1$
knief
and you did the base case to get 0 = 0
then you assumed that for n=m it is true
and you’re verifying that it works for n=m+1
yeah
m?
knief
yea sorry i’m used to assuming n=k
the k(k!) under the summation though yes
yeah
so you can rewrite that
because you assumed $\sum_{k=0}^m k(k!) = (m+1)! - 1$
or n
m
not not n+1
m+1
knief
so then you have $(m+1)! -1 + (m+1)(m+1)!$
knief
do you know how to rewrite that
yeah or well thats where im confused
well if you had $x - 1 + (m+1)x$
knief
how could you rewrite that
yeah i know that i can factor it out but i dont get like shouldnt (m+1)(m+1)! be on the other side
so you’d have $(m+2)(m+1)! - 1 = (m+2)! -1$
knief
which is precisely what you wanted to show
i mean like like sum... k(k!) + (m+1)(m+1)! = (m+1)! -1
because $1(m+1)! + (m+1)(m+1)!$ is $(1+(m+1))(m+1)!$
knief
which is $(m+2)(m+1)!$
knief
Yeah but im confused with sum... k(k!) + (m+1)(m+1)! = (m+1)! -1, so when you move (m+1)(m+1)! shouldnt it be negative?
cause when you are here $\sum_{k=0}^n k(k!) = (n+1)! - 1$
daveslave
and then $\sum_{k=0}^{m+1} (k)(k)!$
daveslave
making it $\sum_{k=0}^{m} (k)(k)! + (m+1)(m+1)!$ no?
daveslave
cause thats what i did for another proof
$\sum_{k=0}^{m} (k)(k)! + (m+1)(m+1)! = (m+1)! -1$
daveslave
$\sum_{k=0}^{m+1} (k)(k)! = \sum_{k=0}^m k(k!) + (m+1)(m+1)!$ but we know $\sum_{k=0}^m k(k!) = (m+1)! - 1$ from our first assumption during the induction step
knief
so we have $(m+1)! - 1 + (m+1)(m+1)!$
knief
you’re welcome
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Can someone check my answer please
for the area you can also use heron's formula if yk what that is, other than that it seems to be correct
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what i do wrong here
I don't think the first limit evaluates to 0
1-cosx/x^2 should evaluate to 1/2
and for sin use the basic stuff
1-cosx/x^2 where u get this
?
u gotta
make that
duh
remember this
and sinx/x when x tending to 0 is 1
now go ahed and do the algebraic manipulations to find the form and solve
or use lhopitals rule
what is wrong with waht i did
1-cos4x/4x when tending to 0
makes 0/0
which is indeterminate
u know about indeterminate forms right?
hello
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can someone explain the meaning of this here
i think im reading the line of reasoning wrong maybe
im thinking this is more of an abuse of notation
but still it doesnt make too much sense
from chatgpt: The left-hand side refers to the functional derivative, which describes how the loss changes when the function H is perturbed at x_i ...... The right-hand side focuses on how the loss changes with respect to the value of H(x_i) treating the prediction as a scalar quantity.
this makes sense but if someone smarter can verify/not
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product rule is $uv'+vu'$
Carter
Yeah thats what i did
My primes are just switched places is all
With the non prime
Because for one i was told to do that by dumbass in the last help thing
lmao no you weren't
I figured to do dy to cosy too bc it had a y on it
I asked and bro said “yes”
get rid of the dy from the first term because you didn't implictly differentiate y there
So i should remove dy from cosy then yes?
no whenever you differentiate sin(y) you need it
but when you differentiate just x
it should be $1 \cdot \sin(y)$
Carter
So no dy on the siny
yes
the whole point of implicitly differentiation is that you're basically doing the chain rule whenever you differentiate y
because $y$ in implicit differentiation is an implicitly defined, differentiable function of x
Carter
Okay
And i thought it didnt make sense i had dy on both cuz i need to move smth to the other side to get dy by itself
so what do you have now?
good
Now i can plug in my points?
so actually instead of dy write dy/dx because we are differentiating with respect to x
Ik that i just shortcut it
Unless i have multiple respects
Like dy/dt then ill specify
the point is to find $dy/dx$
Carter
so isolate it
Thanks
Was just that dumb dy thing
Could you explain one more time why it was we didnt dy the siny in the formula
because you didn't differentiate y you differentiated x
in your mind whenever you see $y$ you should instead see $f(x)$
Carter
because whenever you differentiate $sin(y)$ and get $cos(y)\frac{dy}{dx}$
Carter
that's just like $\sin(f(x)) \implies \cos(f(x))\cdot f'(x)$
Carter
it's just different notation that's all
Chain rule
so your $f'(x)$ is your $\frac{dy}{dx}$
Carter
yes chain rule
that's what it all is
the only reason we write $y$ is so it's easier to read
Carter
but don't let that implicitly confuse you. it's very logical in terms of derivatives.
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How do i know with sequences if they start at 0 or 1
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
context?
"sequences" is a super broad term
sequences can start with anything
0, 1, 2, 10000, -3, x
or do you mean the indexing?
like if the first term is $a_0$ or $a_1$
artemetra
is that what you are asking?
Exactly
just a matter of style really
How do i know?
sometimes it's that, sometimes it's the other
context and what that author is using already
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so really no one definitive answer
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Question ten, I’m stuck I multiplied out the brackets but idk where to go from there cus I got like x^4 + x^-2 + x^-2 + 1 dunno if I add the two x^-2 ‘s together or not and like if I did would I get 2x^-2 or like what
Grinding at 2 am to get the homework done 😈
Also I used rule of indices or whatever yall wanna call it
To simplify
Powerssss
which rule did you use?

When a^-m = 1/a^m
But I sorta assumed the -m would be 2
Idk if I’m right probably not 😞
have you learned the chain rule?
Nope
,tex .diff rules
Please do tell tho if it’s important

last two
it means evaluate g at x, then evaluate f at the result g(x)
in another words, composition functions
Oh composite functions
Okay okay
Question, how does this have anything to with what I’m doing like not in a mean way it’s just I’m really new to this stuff so idk
kensukeken in help channel 
hai

you should try watching a video or just look at the rule
are you familiar with f'(x)? like what does it mean
I think first thing they tell you it is inverse of function but in calc it is the rate at which the function is changing at a given point
I swear it’s got something to do with the steepness of the curve or wherever
whatever
Differentiation is crazy :(
nah it is fun if you practice a lot
This calculus video tutorial explains how to find derivatives using the chain rule. This lesson contains plenty of practice problems including examples of chain rule problems with trig functions, square root & radicals, fractions, ln, product rule, and quotient rule. This video gives you a simple way to find the derivative of a function using ...
Okay so like I’m like a minute into the video and the man says that the derivative of 5x + 3 is 5 and I’m lost how’d he pull out a five where 😰😰
Maybe I should accept my fate and fail 😞
Only eight months till exam anyways
This only the beginning too 😞
Do you know the shortcuts, ie power rule, quotient rule, etc or just limit definition?
I do not have any knowledge on those words accept for the power rule
What method have you been taught for taking derivatives?
Uhm this but lowkey idk the difference between dy/dx and d/dx, my teacher just sorta told me to copy it down so I did 🤷♀️
I mean there’s more
But it’s basically like the same thing
Guys I might be doomed
Smart ppl pls help 🙏
How much of calc do you know?
Uh
Because if we're looking at the same question, it's not possible via just power rule
yeah, to me it seems the problems that are being given don't match what you currently know ^
🤷♀️
do you know the product or quotient rule?
I think if I did I would be able to do the question 😞
Are you doing a guided course?
Or is this independent
It’s school stuff
??? What kind of shitty ass curriculum
are you working ahead perchance? lol
Are you sure your teacher didn't tell you to solve specific problems or maybe you missed a reading?
No
yeah question 10 would use the chain rule which appears to have not been taught to you lol
you could also use the product rule by splitting it into 2 terms if im not mistaken
you gave me an idea by saying wait aswell
couldnt you foil it out?
and solve using the power rule?
Yeah
FYI by foil we mean distribute
