#help-36

1 messages · Page 138 of 1

ruby shore
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would my thing be right too..?

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or was i totally off

frigid hawk
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technically ur right, but ur answer is too vague

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they were probably looking for something like the p-value is greater than the alpha level

ruby shore
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ohhhh

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thank you

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stark apex
final saddleBOT
stark apex
#

how do i solve this after factoring out the x on tpo

onyx peak
vital surge
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always ask urself if the limit is an indeterminate form

stark apex
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I checekd

onyx peak
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and what did you get?

stark apex
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6/6

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1

onyx peak
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yes

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and thats the final answer

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no need for factoring

stark apex
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ohh ok

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ty

onyx peak
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if its not 0 / 0 or infinity/infinity, then its just the value you get when you plug in

stark apex
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ohh

onyx peak
#

(assuming its continous which most functions you'll deal with are)

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@stark apex Has your question been resolved?

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rapid helm
#

Can you distribute powers on complex numbers?

final saddleBOT
rapid helm
#

For eg is (ω²)^7= (ω)^14?

pure lodge
rapid helm
pure lodge
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let's take an example

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$i^{\frac{4}{4}}$

soft zealotBOT
pure lodge
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is it equal to $(i^{4})^{\frac{1}{4}}$?

rapid helm
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No

soft zealotBOT
pure lodge
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now?

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try for yourself

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you'll get some absurd result

barren hound
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in general no, powers don't work like that in complex numbers, but powers are usually multi valued anyway

final saddleBOT
#

@rapid helm Has your question been resolved?

faint fern
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$$ (e^{i \theta + 2\pi n})^a $$

soft zealotBOT
#

StrangeQuarkAL

faint fern
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$$ e^{i a \theta + 2\pi n a} $$

soft zealotBOT
#

StrangeQuarkAL

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haughty quiver
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could someone please help me out with this question? i've understood up to pi x 6 x l

haughty quiver
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10

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wait why

drifting raptor
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curved surface area = slant height x Perimeter of circle

drifting raptor
haughty quiver
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nah that's crazy 😭

drifting raptor
haughty quiver
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alr

drifting raptor
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u know how to count perimeter on circle right?

haughty quiver
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yessire

drifting raptor
haughty quiver
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i've got

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2pi * 6 = 37.7

past timber
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can someone explain this to me? im so dumb TwT

drifting raptor
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350 cm = slant x 37.7

past timber
drifting raptor
past timber
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sorry im new

drifting raptor
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ask there now shoosh

past timber
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thank you!

drifting raptor
haughty quiver
drifting raptor
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,calc 350 / 37.7

soft zealotBOT
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Result:

9.2838196286472
drifting raptor
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,calc 12 * 3.14

soft zealotBOT
#

Result:

37.68
haughty quiver
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ohh

drifting raptor
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the heigh u can use phytagoras

haughty quiver
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ahh okay i got it

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i've finished writing it down thanks for your help

#

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stiff tendon
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hi

final saddleBOT
stiff tendon
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Can anyone send notes for trigonometry jee?

shell mauve
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jee?

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dont get it tho

cloud raft
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ask this question on that

stiff tendon
#

?

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K

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final saddleBOT
#

@verbal owl Has your question been resolved?

autumn geode
#

log factors??

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I like the proof given by my uni

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it's available online

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@verbal owl Has your question been resolved?

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jagged flare
#

let $a,b,c\in\mathbb{R}^+_{*}$
$$abc(a+b+c)=100$$
find the minimum value of $(a+b)(b+c)$

soft zealotBOT
#

Skill_Issue

jagged flare
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ac(ab+b^2+bc)=100
(a+b)(b+c)=k=ab+b^2+bc+ac
ac(k+ac)=100
k=100/ac-ac

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it would be very nice if i csn just am-gm this but its -ac so :(

scarlet sequoia
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well it's not too bad to analyse the function f(x) = x + 100/x

paper oxide
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isnt it k - ac in line 3?

tranquil pine
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the 3rd line is wrong

jagged flare
scarlet sequoia
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and yeah it's -ac

tranquil pine
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should be ac(k-ac)

jagged flare
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k=100/ac+ac>=2sqrt(10)=20?

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so the ans is 20?

vital surge
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it is 20 yes

jagged flare
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thanks!

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vital surge
#

🎉

paper oxide
#

oh yeah btw make sure to prove ac = 100/ac is possible

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jagged flare
#

how is this A

final saddleBOT
jagged flare
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is it not 1+12+23+34+45+56+67+78+89+100=505?

vital surge
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yeah those answer choices are way too big

jagged flare
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wtf so is the question wrong

tranquil pine
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there is one answer that is none of the above so

vital surge
jagged flare
jagged flare
vital surge
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aight

tranquil pine
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@jagged flare

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your teacher added an extra "0" after the answer ig

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i got 505

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which is quite "similar" to 5,050

jagged flare
tranquil pine
jagged flare
vital surge
tranquil pine
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i can open and see a TCIMO

vital surge
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looks like they just wrote it wrong

jagged flare
vital surge
jagged flare
vital surge
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also they alrd know the answer is 505 (cuz they calculated it on their own)

tranquil pine
vital surge
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they were just making sure the test was wrong

jagged flare
tranquil pine
vital surge
jagged flare
jagged flare
vital surge
jagged flare
#

ill close this then, thanks for your time guys

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.close

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tranquil pine
vital surge
#

fair enough 😭 happens

tranquil pine
#

true

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foggy warren
#

Hi, how can i find the domain of sqrt of x -6 (the minus 6 is not in the squar root theres a space between them)

formal trail
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,, \sqrt{x} - 6

soft zealotBOT
foggy warren
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exactly

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how do i find the domain

autumn geode
foggy warren
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idk what that means

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im sorry lol

jagged flare
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do you know the domain of sqrt(x)

pulsar venture
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plot the graph of root x

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and see what x values it can take

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domain means

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x values

foggy warren
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do i start at 0 but move it 6 spaces to the right?

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im new to all this im sorry

pulsar venture
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ukw forget graph

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its really simple

foggy warren
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ok

pulsar venture
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root(x)

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is only defined for

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non negative nos.

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so x>= 0

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is the domain

foggy warren
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ur gonna kill me but im still not understanding what you mean by defined

pulsar venture
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ok

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can u put x as a negative no.

foggy warren
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im associating it with like vocabulary definitions like a dictionary

pulsar venture
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inside the root

foggy warren
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no

pulsar venture
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exactly

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that means

foggy warren
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no negative numbers under a root

pulsar venture
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negative nos. cannot be accepted

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right?

foggy warren
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correct

pulsar venture
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now domain means

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ur asking urself

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what x values can the function take

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so negative nos. are gone

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can i put x = 0

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inside a root

foggy warren
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yea

pulsar venture
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and can i put positive nos.

foggy warren
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cuz its a positive number

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no

pulsar venture
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yes

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why not

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i can put x = 1

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inside

foggy warren
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yea

pulsar venture
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yeah

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so then

foggy warren
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any number thats positive

pulsar venture
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the set

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of all the values is

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0, infinity

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right?

foggy warren
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yup

pulsar venture
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thats the domain

foggy warren
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but what happens to the 6?

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i dont touch it?

pulsar venture
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no that doesnt affect the x values

foggy warren
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so if my hw is asking "Domain where F
is one-to-one and increasing"

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would i put [0, infinity)?

pulsar venture
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this function is always increasing

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lol

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do u know how to check that

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in fact it is one one as well

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i mean increasing implies it is one one but yeah

foggy warren
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ngl im lost again, what sorta answer as an example would i put

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is it asking for a notations?

pulsar venture
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first of all forget the answer

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do u know what one one and increasing means

foggy warren
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one input has its own output

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no x value can have two y values

pulsar venture
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and increasing?

foggy warren
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idk but increasing means its always getting bigger

pulsar venture
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ok but

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how do u check that

foggy warren
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idk but if i had to guess it would be by checking the function, for example its root x MINUS 6 so in this case it would be decreasing?

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idkkkk im so sorry thats just a guess

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im being dumb imma let you explain

pulsar venture
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u differentiate the function

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and check if that is positive or not

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if that is positive always

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then it is increasing

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in this case the derivative is 1/2(rootx)

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which is always positive

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so it is increasing

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and if it is increasing it is one one

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so the domain doesnt change

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if only a part of the function behaved this way

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u would have to chop off the domain

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by some bit where it doesnt obey what the question says

foggy warren
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im trying my hardest to wrap by head around what all that means but its gibberish to me and i hate that

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im not good at math at all im sorry

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literally the only part im good at is finding the f inverse

pulsar venture
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lol its okay

foggy warren
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this whole domain thing is difficult for me

pulsar venture
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but

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just remember that

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0, infinity is ur answer

foggy warren
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ik i said this already but basically i dont touch the 6 at all?

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cuz were looking at root x which shows that all positive numbers including 0 can be graphed

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but dont i like move the start of the graph to a specific area either left or right by 6 units?

pulsar venture
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nope

foggy warren
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i just tried it

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the answer was [-6, infinity)

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😦

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im sorry

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gosh i hate this

pulsar venture
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wait

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nah thats incorrect

foggy warren
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the website i do my hw on says its right tho

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am i missing something?

pulsar venture
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u can graph it on desmos

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if u have a doubt

foggy warren
#

ok

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thank youuuuu

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byeee

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wait how do i close this

pulsar venture
#

.close

foggy warren
#

.close

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cloud raft
#

but if n = 2, we get 0.01 which has many numbers lesser than it

static fractal
#

it's for all n

onyx peak
#

read it like this:
there is no positive number that is (less than 1/10^n for all n)

cloud raft
#

it means any value of n right?

onyx peak
#

It means that there is no positive number that is less than 1/10 and less than 1/10^2 and less than 1/10^3 and less than 1/10^4 ....

onyx peak
#

This (there is no positive number that is less than 1/10^n) for all n
is different from this there is no positive number that is (less than 1/10^n for all n)

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#

@cloud raft Has your question been resolved?

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bitter pike
#

Can someone help me with some of these?

final saddleBOT
bitter pike
#

I have some idea but need help

craggy plank
#

Which one?

bitter pike
#

all, ill run down my answers

craggy plank
#

Alr

bitter pike
#

so as x approaches -4, whats the value, right?

craggy plank
#

Correct

bitter pike
#

and at -4, there is a closed circle at -2, meaning the limit DNE

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is my guess

craggy plank
#

Correct

bitter pike
#

alright, jotting down one sec

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ok, as x approaches 3, its at the origin

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so the limit is 0?

craggy plank
#

Correct

bitter pike
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got it, jotting down

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so at f(3), its at origin but there is a black dot, so -1?

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ill get stuff wrong later, just wait

bitter pike
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ok, as x approaches -1, it goes infinite, and infinity cant be a limit

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so DNE?

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or -1?

craggy plank
#

Yes

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The limit doesn’t exist

bitter pike
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so as x approaches 0 (from right) its at 1

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so limit is 1

craggy plank
#

yes

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You look familiar with it

bitter pike
#

i did very bad on a test and my grade is very very poor

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and my parents dont like it at all

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so im trying my best

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just a couple more, thanks for sticking with me

bitter pike
craggy plank
#

Notice that limit is a concept of "approaching something"

bitter pike
#

oh, and approaching left its a closed circle

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so DNE?

craggy plank
#

Check where would it approach when from the left side

craggy plank
#

There is a value given

bitter pike
#

it hits 2, but its a closed circle?

craggy plank
#

Yes, it’s just 2

bitter pike
#

but i thought closed circles were DNE?

craggy plank
#

The exact value has nothing to do with limit

craggy plank
bitter pike
#

thats what i did for number 1

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and said DNE

craggy plank
#

Bruh… I thought you said -2

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mb, my apologies

bitter pike
#

no worries

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so it is dne?

craggy plank
#

No, it’s not

bitter pike
#

is it 1

craggy plank
#

DNE only appears when left limit ≠ right limit

bitter pike
#

ok, so whats the reasoning for 1) being DNE?

craggy plank
#
  1. is not DNE
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It’s -2

bitter pike
#

oh ok

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i see

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so for 0^- it would be 2?

craggy plank
#

yes

bitter pike
#

ok, lets skip down to 10)

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f(-2) would be 1 right

craggy plank
#

No

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Empty circle stands for empty, which the function yields no result

bitter pike
#

ohh

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so und?

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or dne

craggy plank
#

DNE

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Closed circle stands for a certain value

bitter pike
#

ok ran thru 11) in my head, it is true

craggy plank
#

Before that, lemme ask you a question rq to confirm you actually knows how it works

bitter pike
#

ok

craggy plank
#

What’s f(0)?

bitter pike
#

2

craggy plank
#

Correct

#

Move on :))

bitter pike
craggy plank
#

Correct

bitter pike
#

and 12 is false, as at x->3, it is 0, and f(3) is -1

craggy plank
#

Decent

#

Ig that’s all

bitter pike
#

thank you so much, just talking about it helps, and you really wanted me to learn it

#

i really appreciate you!

craggy plank
#

For sure, np

#

Have a good one

bitter pike
#

you too!

#

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vital valve
final saddleBOT
vital valve
#

can someone check this

#

i need to make sure its right

bleak granite
#

,w dist((-25,-25),(-10,15))

bleak granite
vital valve
bleak granite
#

well unless wolframalpha is wrong, then yes

vital valve
bleak granite
#

the points are barely visible, idk where K is 😅

vital valve
#

this shit got me tripping

vital valve
#

it changed for some reason

#

are the cords on this not 2,2 and -1-1?

bleak granite
#

they are

vital valve
#

ok

#

so what the fuck do i do on this

final tangle
#

distance formula / pythagoras

vital valve
final tangle
#

ideally you'd use the unrounded value when converting units

#

,calc 4 * sqrt(2)

soft zealotBOT
#

Result:

5.6568542494924
final tangle
#

,calc 4 * sqrt(2) * 0.25

soft zealotBOT
#

Result:

1.4142135623731
final saddleBOT
#

@vital valve Has your question been resolved?

vital valve
#

can anyone help with thias

vital valve
#

i dont understand

#

.close

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jade fable
#

Given P is the centroid of triangle ABC, there’s a line passes point P and intersects with line AB and lineAC at point Q and point R respectively. If vector AQ = a vector AB, and vector AR = 3a/2 AC, then a=?

jade fable
#

I can only find that Q lies upon the pink line and R is upon the yellow line

#

I try to put the circumstances into xy plane then I can analyze it using coordinates

#

I think I should use the property of P being the centroid

#

<@&286206848099549185>

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#

@jade fable Has your question been resolved?

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hard frost
#

I genuinely don'T get it

final saddleBOT
#

@hard frost Has your question been resolved?

rare estuary
#

you got c correct

#

and imo, its the hardest one

#

a and b and easier, try

#

consider the first displacement as a vector A with magnitude ||A||=6 and the second displacement as a vector B with mag ||B||=8

hard frost
#

Yeah I tried using the formula "A * B = AB Cos" but i was horribly wrong at first

rare estuary
#

thats the dot product, i dont think it has anything to do here

hard frost
#

yeha I realized that after the first attempt

rare estuary
#

you want the magnitude of A+B

#

to be 14

#

what angle must be between A and B to have that?

hard frost
#

isn't there a formula for that

rare estuary
#

notice 6+8=14

hard frost
#

OH

#

0?

rare estuary
#

exactly xd

hard frost
#

since cos0 = 1

rare estuary
#

what does cos have to do with anything heeeere

#

its 0 degrees cuz

hard frost
#

LISTEN 😭

rare estuary
#

the two vectors will be alligned

#

and therefore the magnitude of their sum

#

will be simply 6 + 8 = 14

hard frost
#

Okayy yeah that makes a lot of sense

#

now, 6 + 8 = 2

#

i could've sworn there's like a formula for this

#

oh it's a tight angle

rare estuary
#

they chose 14, 10, and 2 in this exercise cuz they result in special angles

#

after you do this exercise, if you got time, try to generalize it :p

hard frost
#

I see,

rare estuary
#

okay, how about 2m

hard frost
#

it should be 8-6

#

but i can'T change can I

#

wait

#

180 deg?

#

since it's the opposite of

#

i have no idea wrtf I'm sayting

rare estuary
#

exactly, if you walk forward 8m then backward 6m

#

youll end up 2m forward

#

from where you started

#

think of these displacements as vectors

hard frost
#

It is vectors :D

#

thank you sm, I appreciate your explanation

#

it was very helpful

rare estuary
#

me horribe at explaining, but ty gl

hard frost
#

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tranquil pine
#

Hi i need help graphing a parabola with only vertex and focus/directrix given

tranquil pine
#

i got this example but idk how to process

#

I need to know the step by step process🥹

rocky tusk
#

ask your teacher

vital crag
#

Or classmates

rocky tusk
#

the guy in the green hoodie ought to know

tranquil pine
#

😭

#

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ancient basalt
final saddleBOT
ancient basalt
#

Dunno how to start

rare girder
#

evaluate derivatives of f at 0 and see what happens

ancient basalt
rare girder
#

o

#

multinomial theorem maybe?

ancient basalt
rare girder
#

that's what multinomial theorem does, it expands powers of polynomials by referencing multinomial coefficients

#

like how binomial theorem expands powers of binomials by referencing the n choose k's

rare girder
#

I think my suggestion is naive, maybe there's something prettier out there but whatever lol

ancient basalt
#

So how would it apply here like what would we get after we apply it

final saddleBOT
#

@ancient basalt Has your question been resolved?

muted prairie
#

Do you know how to find a_0 + a_1 + ... + a_n ?

#

There's a certain complex number that can be plugged in for x here that's very useful

muted prairie
muted prairie
#

That's for you to find out

#

What gives you a pattern of 1, -1/2, -1/2

#

as you take powers

ancient basalt
#

Lemme think

#

Dunno ;-;

muted prairie
#

how would you find a_0 + 2a_1 + 4a_2 + 8a_3 + ...

ancient basalt
#

I'd expand the polynomial upto a few terms and see if there's a pattern in the coefficients and solve

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#
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muted prairie
#

.reopen

final saddleBOT
#

muted prairie
#

you're supposed to react to the bot message to keep the channel open

ancient basalt
#

Oh mb

muted prairie
#

what do you get when you plug in 1 to the polynomial

ancient basalt
#

4^1959

muted prairie
#

How to find a_0 + a_1 + ...

ancient basalt
#

Don't really know any techniques ;-;

muted prairie
#

Not really sure why you said you knew how to solve it then

ancient basalt
#

I thought you meant like finding the coefficients

muted prairie
#

finding the sum of the coefficients

#

that's what the + signs mean

ancient basalt
#

Ye mb

muted prairie
#

what do you get on the right side when you plug in x=1

ancient basalt
#

Ohhhh

#

The sum of coefficients

muted prairie
#

yes

#

how can you get a_0 + 2a_1 + 4a_2 + ...

ancient basalt
#

By putting x=2?

muted prairie
#

Right

#

Now what complex number has powers that look like 1, -1/2, -1/2, 1, -1/2, -1/2, 1, ...

#

not exactly like that but close enough

ancient basalt
muted prairie
#

Ah

#

Idk where you're getting these problems from but this one is way too hard for you

ancient basalt
#

Most of them are hard af

muted prairie
#

Plug in x = -1/2 + isqrt(3)/2

#

take the real parts of both sides

#

the answer will magically emerge

ancient basalt
#

Oh alr

#

Thank you so much

muted prairie
#

yw

ancient basalt
#

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#
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novel schooner
#

I need help with y=mx+b

final saddleBOT
novel schooner
#

I need help find the “mx” part and creating an equation based on the slope

#

This is what i have now.

#

I can identify B, but i’m having trouble identifying mx

#

I’m unsure if “mx”, or just the “m”, is the refers to the slope.

#

But what do i do when i do find the slope? Do i leave it as a fraction, or is there another step after that?

short swift
#

do u know the formula to find the slope?

novel schooner
#

Rise over run is what i hear alot

#

But not really. I do not know it

short swift
#

are u familiar with this? the second one i mean

novel schooner
#

Yes i have seen this before

short swift
#

yeah use this one to find the slope, m

#

just take any 2 points from the graph then plug it in this equation

novel schooner
#

Ok i’ll give it a try

#

So for the Y, i did 5 - 9 = -4
And for X, i did 45 - 39 = 6
But it feels like i did something wrong

short swift
#

are those the points from the table?

novel schooner
#

I got these numbers from the table above the graph

short swift
#

yeah but, u should take the points from the graph get it?

novel schooner
#

The points from the table are the points that are on the graph. So i assumed that both would give the same answer

#

But many of the points don’t fall directly on the line, so i wasn’t to confident trying to eyeball the graph

short swift
#

hm but what i observed is that the points from the table were scattered points, and the graph is like the best fit line, am i corrrect?

short swift
#

the graph u constructed is a best fit line

novel schooner
#

Yes. The line is a line of the best fit.

#

Ohh i think i might have said the wrong then

#

I want to find the equation for the line of best fit

short swift
#

yep thats why we need to take a point (any point) from the line, not the table

#

bcs, if we want an equation for the line, then we need the gradient of the line, therefore we need to take 2 points from the line

#

do u get my point?, the values from the table and from the line is not the same

novel schooner
#

i think i get what you mean. So i’m taking an x and y point from the best fit line?

short swift
#

yeppp

novel schooner
#

Oh. That makes much more sense. I’ve been focusing on the wrong thing the whole time

short swift
#

mhm but its okay

novel schooner
#

So the gradient of this line would be 14/22.5? With 14 as the Y and 22.5 as the x.

#

Can rounding be used with coordinates? Or should i try and be as accurate as i can?

short swift
#

based on my observation, i assume u took the points (14, 30) and (22.5, 15)?

novel schooner
#

Yeah

short swift
#

ahh so shouldnt it be...

#

15/-8.5 ?

short swift
novel schooner
#

What do you by the -8.5?

short swift
#

14 - 22.5

sour socket
#

.

novel schooner
#

Ohh i see. I see what you mean

#

Yeah and that would be the y point of the gradient needed for the equation. So the x point would be 15 (30 - 15)?

#

So i think it would be -8.5/15 ?

short swift
#

u got it but its the other way around now😭

#

u reed the coordinates x first, then y right?

novel schooner
#

Yeah i was about that doesn’t the x come first in the coordinates?

#

Since 14 and 22.5 are the first coordinate in the parenthesis

short swift
#

well um thats bcs 14 and 22.5 are the x points

novel schooner
#

So what do you mean them? Not sure i understand

#

Oh wait nevermind. I think i see it now

#

Called 15 the x coordinate. I mean that 15 should be the Y coordinate and -8.5 should be the X coordinate

novel schooner
#

So now that i have y=-8.5/15(x)+55
What would the x be?

short swift
#

it should be 15/-8.5

short swift
short swift
novel schooner
#

So as a recap, in the equation y=mx+b the -8.5/15 is the “m” part of the equation correct? And the 55 would be the “b” part of the equation. And the “x” part of the equation is a variable i leave blank?

#

Just to make sure i fully understand it

short swift
#

yeahh

short swift
novel schooner
#

Oop

novel schooner
#

Gotcha. And is that the same with all problems that use the coordinate plane?

#

All throughout middle school, i’ve always done the x coordinate first and haven’t been corrected on it being incorrect.

short swift
#

it's like this, dont get confused

#

to READ a coordinate, we read the x first, then y

#

but to find gradient, we put y first, then x, as in m = (y2 -y1) / (x2 - x1)

#

got it?

novel schooner
#

Ah ok. I think i understand

short swift
#

good

novel schooner
#

So my last question would be, how would i find a point that isn’t on the graph. I’m assuming that is what the x variable is used for?

short swift
#

exactly

#

so if u have a y point and u want an x point just plug the y point into the equation then solve it

#

or vice versa

novel schooner
#

So if i wanted to find the x point for 40 minutes, i would have to construct this equation to find it? Y=15/-8.5(40)+55?

short swift
#

u want to find the x point or the y point?

novel schooner
#

I’m assuming it would find the Y point .

#

Since the number of students was 0 after 32 minutes, how many students would there be after 40 minutes.

short swift
#

logically still 0

#

but mathematically

#

negative something

#

but ofc we need to use logic

novel schooner
#

Gotcha. So does that mean that an x coordinate can found this way also?

short swift
#

yeps

novel schooner
#

So if i wanted to find an X coordinate, would i place my Y coordinate that i’m using to find the X coordinate, in that same variable?

#

If that makes sense

short swift
#

that makes absolute sense

#

but hold on, wdym by the "same variable"?

novel schooner
#

The X variable. I replaced it with an X coordinate to find a Y coordinate

short swift
#

oh yeah that is correct

novel schooner
#

So i would replace the X variable with a Y coordinate to find a X coordinate?

short swift
#

well technically its not replacing but substituting

#

okay let me give u an exmple

#

say we have a coordinate (x,10) and we want to find x, usng the same equation, Y=15/-8.5X+55, we substitute the 10 value to the Y term, then, solve the equation to find X

novel schooner
#

Not too sure i’m understanding.
Would the 15 become 10? Or is the actual Y letter of the equation being substituted?

short swift
novel schooner
#

Ah ok, i understand now.

#

That should be all that i need help with.

short swift
#

well its a pleasure to help, u can reach me if u need any more help

novel schooner
#

Will do. Thanks alot for talking me through. It was very very helpful. Have a great rest of your night or morning.

#

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orchid coral
#

is is ((sec(c))^2 always greater than ((tan(c))^2

orchid coral
#

becaues i have proved this:

root(1-sin^2) = cos^2
cos^2 * sec^2 = 1
root(sec^2 - tan^2) = 1
sec^2 = tan^2 + 1

orchid coral
#

ok thank oui

#

also

#

is this correct too:

cosec^2 > cot ^2

tranquil pine
#

Yes

#

cosec²A = 1 + cot²A

orchid coral
#

kk

#

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haughty rampart
#

Hey im trying to solve: Prove by induction that for all positive integers n, k=0 to n Σ k(k!) is equal to (n+1)! -1
ive gotten my base but when i try to plug in n=m+1 I cant find the right way to the answer

rocky tusk
#

$\sum_{k=0}^n k(k!) = (n+1)! - 1$

soft zealotBOT
rocky tusk
#

and you did the base case to get 0 = 0

haughty rampart
#

ye

#

s

rocky tusk
#

then you assumed that for n=m it is true

#

and you’re verifying that it works for n=m+1

haughty rampart
#

yeah

rocky tusk
#

so did you try rewriting $\sum_{k=0}^{m+1} (k)(k)!$

#

oops wait

haughty rampart
#

m?

soft zealotBOT
rocky tusk
#

yea sorry i’m used to assuming n=k

haughty rampart
#

nw, yeah

#

then i went for k(k!) + (m+1)((m+1)!)

rocky tusk
#

the k(k!) under the summation though yes

haughty rampart
#

yeah

rocky tusk
#

so you can rewrite that

#

because you assumed $\sum_{k=0}^m k(k!) = (m+1)! - 1$

#

or n

#

m

#

not not n+1

#

m+1

soft zealotBOT
rocky tusk
#

so then you have $(m+1)! -1 + (m+1)(m+1)!$

soft zealotBOT
rocky tusk
#

do you know how to rewrite that

haughty rampart
#

yeah or well thats where im confused

rocky tusk
#

well if you had $x - 1 + (m+1)x$

soft zealotBOT
rocky tusk
#

how could you rewrite that

haughty rampart
#

yeah i know that i can factor it out but i dont get like shouldnt (m+1)(m+1)! be on the other side

rocky tusk
#

so you’d have $(m+2)(m+1)! - 1 = (m+2)! -1$

soft zealotBOT
rocky tusk
#

which is precisely what you wanted to show

haughty rampart
#

i mean like like sum... k(k!) + (m+1)(m+1)! = (m+1)! -1

rocky tusk
#

because $1(m+1)! + (m+1)(m+1)!$ is $(1+(m+1))(m+1)!$

soft zealotBOT
rocky tusk
#

which is $(m+2)(m+1)!$

soft zealotBOT
haughty rampart
#

Yeah but im confused with sum... k(k!) + (m+1)(m+1)! = (m+1)! -1, so when you move (m+1)(m+1)! shouldnt it be negative?

rocky tusk
#

what

#

why would it negative

haughty rampart
#

cause when you are here $\sum_{k=0}^n k(k!) = (n+1)! - 1$

soft zealotBOT
#

daveslave

haughty rampart
#

and then $\sum_{k=0}^{m+1} (k)(k)!$

soft zealotBOT
#

daveslave

haughty rampart
#

making it $\sum_{k=0}^{m} (k)(k)! + (m+1)(m+1)!$ no?

soft zealotBOT
#

daveslave

haughty rampart
#

cause thats what i did for another proof

#

$\sum_{k=0}^{m} (k)(k)! + (m+1)(m+1)! = (m+1)! -1$

soft zealotBOT
#

daveslave

rocky tusk
#

$\sum_{k=0}^{m+1} (k)(k)! = \sum_{k=0}^m k(k!) + (m+1)(m+1)!$ but we know $\sum_{k=0}^m k(k!) = (m+1)! - 1$ from our first assumption during the induction step

soft zealotBOT
rocky tusk
#

so we have $(m+1)! - 1 + (m+1)(m+1)!$

soft zealotBOT
haughty rampart
#

ohh

#

right

rocky tusk
#

then you follow what i did earlier

#

to get (m+2)!

haughty rampart
#

yeah breaking it down was pretty east

#

alr thanks

rocky tusk
#

you’re welcome

haughty rampart
#

.close

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unique fable
final saddleBOT
unique fable
#

Can someone check my answer please

solemn bear
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@unique fable Has your question been resolved?

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tall crow
#

what i do wrong here

final saddleBOT
tall crow
languid yoke
#

I don't think the first limit evaluates to 0

rose hamlet
#

and for sin use the basic stuff

tall crow
#

1-cosx/x^2 where u get this

tall crow
rose hamlet
#

u gotta

#

make that

#

duh

#

remember this

#

and sinx/x when x tending to 0 is 1

#

now go ahed and do the algebraic manipulations to find the form and solve

#

or use lhopitals rule

tall crow
#

what is wrong with waht i did

rose hamlet
#

makes 0/0

#

which is indeterminate

#

u know about indeterminate forms right?

tall crow
tall crow
final saddleBOT
#

@tall crow Has your question been resolved?

final saddleBOT
#

@tall crow Has your question been resolved?

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summer dragon
final saddleBOT
summer dragon
#

can someone explain the meaning of this here

#

i think im reading the line of reasoning wrong maybe

#

im thinking this is more of an abuse of notation

#

but still it doesnt make too much sense

#

from chatgpt: The left-hand side refers to the functional derivative, which describes how the loss changes when the function H is perturbed at x_i ...... The right-hand side focuses on how the loss changes with respect to the value of H(x_i) treating the prediction as a scalar quantity.

#

this makes sense but if someone smarter can verify/not

final saddleBOT
#

@summer dragon Has your question been resolved?

final saddleBOT
#

@summer dragon Has your question been resolved?

summer dragon
#

meep meep

#

i accept chatgpt's answer

#

if this is a mistake pm me

#

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unreal knoll
final saddleBOT
unreal knoll
#

Help

#

I get to this point in middle then don’t know what to do

flat saddle
#

product rule is $uv'+vu'$

soft zealotBOT
#

Carter

unreal knoll
#

Yeah thats what i did

#

My primes are just switched places is all

#

With the non prime

flat saddle
#

why do you have dy on both then?

#

you only implictly differentiate sin(y) on one

unreal knoll
#

Because for one i was told to do that by dumbass in the last help thing

flat saddle
#

lmao no you weren't

unreal knoll
unreal knoll
flat saddle
#

get rid of the dy from the first term because you didn't implictly differentiate y there

unreal knoll
#

So i should remove dy from cosy then yes?

flat saddle
#

no whenever you differentiate sin(y) you need it

#

but when you differentiate just x

#

it should be $1 \cdot \sin(y)$

soft zealotBOT
#

Carter

unreal knoll
#

So no dy on the siny

flat saddle
#

yes

#

the whole point of implicitly differentiation is that you're basically doing the chain rule whenever you differentiate y

#

because $y$ in implicit differentiation is an implicitly defined, differentiable function of x

soft zealotBOT
#

Carter

unreal knoll
#

Okay

#

And i thought it didnt make sense i had dy on both cuz i need to move smth to the other side to get dy by itself

flat saddle
#

so what do you have now?

unreal knoll
flat saddle
#

good

unreal knoll
#

Now i can plug in my points?

flat saddle
#

so actually instead of dy write dy/dx because we are differentiating with respect to x

unreal knoll
#

Ik that i just shortcut it

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Unless i have multiple respects

#

Like dy/dt then ill specify

flat saddle
#

the point is to find $dy/dx$

soft zealotBOT
#

Carter

flat saddle
#

so isolate it

unreal knoll
#

Thanks

#

Was just that dumb dy thing

#

Could you explain one more time why it was we didnt dy the siny in the formula

flat saddle
#

because you didn't differentiate y you differentiated x

#

in your mind whenever you see $y$ you should instead see $f(x)$

soft zealotBOT
#

Carter

flat saddle
#

because whenever you differentiate $sin(y)$ and get $cos(y)\frac{dy}{dx}$

soft zealotBOT
#

Carter

flat saddle
#

that's just like $\sin(f(x)) \implies \cos(f(x))\cdot f'(x)$

soft zealotBOT
#

Carter

flat saddle
#

it's just different notation that's all

unreal knoll
#

Chain rule

flat saddle
#

so your $f'(x)$ is your $\frac{dy}{dx}$

soft zealotBOT
#

Carter

flat saddle
#

yes chain rule

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that's what it all is

#

the only reason we write $y$ is so it's easier to read

soft zealotBOT
#

Carter

flat saddle
#

but don't let that implicitly confuse you. it's very logical in terms of derivatives.

unreal knoll
#

Hm ok then

#

Ty for the help

#

.close

final saddleBOT
#
Channel closed

Closed by @unreal knoll

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

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cloud portal
#

How do i know with sequences if they start at 0 or 1

final saddleBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

cloud portal
#

i dont have context really, im just wondering

#

Is it 1 by default?

stone wagon
#

"sequences" is a super broad term

#

sequences can start with anything

#

0, 1, 2, 10000, -3, x

#

or do you mean the indexing?

cloud portal
#

i mean the ones with a natural number giving the position

#

probably yes

stone wagon
soft zealotBOT
#

artemetra

stone wagon
#

is that what you are asking?

cloud portal
#

Exactly

stone wagon
#

just a matter of style really

cloud portal
#

How do i know?

stone wagon
#

sometimes it's that, sometimes it's the other

stone wagon
cloud portal
#

ok thx

#

.close

final saddleBOT
#
Channel closed

Closed by @cloud portal

Use .reopen if this was a mistake.

stone wagon
#

so really no one definitive answer

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp cliff
#

Question ten, I’m stuck I multiplied out the brackets but idk where to go from there cus I got like x^4 + x^-2 + x^-2 + 1 dunno if I add the two x^-2 ‘s together or not and like if I did would I get 2x^-2 or like what

sharp cliff
#

Grinding at 2 am to get the homework done 😈

#

Also I used rule of indices or whatever yall wanna call it

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To simplify

#

Powerssss

vivid walrus
#

which rule did you use?

sharp cliff
#

Uhhh

#

Hold on let me show you

vivid walrus
sharp cliff
#

When a^-m = 1/a^m

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But I sorta assumed the -m would be 2

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Idk if I’m right probably not 😞

vivid walrus
#

have you learned the chain rule?

sharp cliff
#

Nope

vivid walrus
#

,tex .diff rules

sharp cliff
#

Please do tell tho if it’s important

soft zealotBOT
vivid walrus
#

last two

sharp cliff
#

What’s the little circle mean

#

f o g

vivid walrus
#

it means evaluate g at x, then evaluate f at the result g(x)

#

in another words, composition functions

sharp cliff
#

Oh composite functions

#

Okay okay

#

Question, how does this have anything to with what I’m doing like not in a mean way it’s just I’m really new to this stuff so idk

trail mango
#

kensukeken in help channel kongouderp

vivid walrus
#

hai

trail mango
vivid walrus
#

are you familiar with f'(x)? like what does it mean

sharp cliff
#

Ermmmm nope 🤷‍♀️

#

I mean I’ve seen it before

#

Idk what it means

vivid walrus
#

I think first thing they tell you it is inverse of function but in calc it is the rate at which the function is changing at a given point

sharp cliff
#

I swear it’s got something to do with the steepness of the curve or wherever

#

whatever

#

Differentiation is crazy :(

vivid walrus
#

nah it is fun if you practice a lot

#

This calculus video tutorial explains how to find derivatives using the chain rule. This lesson contains plenty of practice problems including examples of chain rule problems with trig functions, square root & radicals, fractions, ln, product rule, and quotient rule. This video gives you a simple way to find the derivative of a function using ...

▶ Play video
sharp cliff
#

Okay so like I’m like a minute into the video and the man says that the derivative of 5x + 3 is 5 and I’m lost how’d he pull out a five where 😰😰

#

Maybe I should accept my fate and fail 😞

#

Only eight months till exam anyways

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This only the beginning too 😞

shut gazelle
sharp cliff
#

I do not have any knowledge on those words accept for the power rule

shut gazelle
#

What method have you been taught for taking derivatives?

sharp cliff
#

Uhm this but lowkey idk the difference between dy/dx and d/dx, my teacher just sorta told me to copy it down so I did 🤷‍♀️

#

I mean there’s more

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But it’s basically like the same thing

#

Guys I might be doomed

#

Smart ppl pls help 🙏

dusty dock
sharp cliff
#

Uh

dusty dock
#

Because if we're looking at the same question, it's not possible via just power rule

proud parrot
#

yeah, to me it seems the problems that are being given don't match what you currently know ^

sharp cliff
#

🤷‍♀️

proud parrot
#

do you know the product or quotient rule?

sharp cliff
#

I think if I did I would be able to do the question 😞

dusty dock
#

Or is this independent

sharp cliff
#

It’s school stuff

dusty dock
#

??? What kind of shitty ass curriculum

sharp cliff
#

so guided?

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British

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THATS why

proud parrot
#

are you working ahead perchance? lol

sharp cliff
#

😞

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nope

dusty dock
#

Are you sure your teacher didn't tell you to solve specific problems or maybe you missed a reading?

sharp cliff
#

No

dusty dock
#

There's no shot 😭

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Don't feel down this isn't your fault

#

Wtf

sharp cliff
#

She lit said it’s that question

#

And like I’m just super lost 😞

proud parrot
#

yeah question 10 would use the chain rule which appears to have not been taught to you lol

#

you could also use the product rule by splitting it into 2 terms if im not mistaken

dusty dock
#

Wait

#

Its.. technically possible

proud parrot
#

couldnt you foil it out?

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and solve using the power rule?

dusty dock
#

Yeah

dusty dock