#help-36

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jagged flare
final saddleBOT
jagged flare
#

i know $c=a^2+b^2$
using AM-QM, i can get
$$\sqrt{\frac{a^2+b^2}{2}}\geq\frac{a+b}{2}$$
$$\frac{a^2+b^2}{2}\geq\frac{(a+b)^2}{4}$$
$$\frac{2}{a+b}\geq\frac{a+b}{a^2+b^2}$$

soft zealotBOT
#

Skill_Issue

jagged flare
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is this correct? do i answer like 2/a+b

languid yoke
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Well you have c^2 on the RHS denominator, not c

jagged flare
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oh

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uh so what do i do to get ris of the ^2 on the c

languid yoke
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$$\sqrt{\frac{a^2+b^2}{2}}\geq\frac{a+b}{2}$$
$$ \implies \frac{\sqrt{a^2+b^2}}{a+b} = \frac{\sqrt{2}}{2}$$

soft zealotBOT
languid yoke
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so just flip both sides

jagged flare
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o

languid yoke
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or it should be >= not = mb

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Also generally remember equality holds when a=b, which usually helps you find the upper bound when you don't need to be really rigorous

jagged flare
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fuck damn i got it right but i typod sqrt so it was wrong :(

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.close thanks

final saddleBOT
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ember maple
final saddleBOT
ember maple
#

,rotate

soft zealotBOT
ember maple
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Did I interpret the question properly

scarlet sequoia
#

you did, but your computation is wrong

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you didn't multiply denominators

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and forgot about one of them

ember maple
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Oh Yh

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I still dot my ink that’s right this

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Think

final saddleBOT
#

@ember maple Has your question been resolved?

ember maple
#

<@&286206848099549185>

dusky spade
ember maple
#

no

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i did the original equation wrong somwhow

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lambda is (3 +- sqrt(5))/2

final saddleBOT
#

@ember maple Has your question been resolved?

ember maple
#

<@&286206848099549185>

final saddleBOT
#

@ember maple Has your question been resolved?

ember maple
#

<@&286206848099549185>

split socket
#

LMAO

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@ember maple Has your question been resolved?

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tranquil pine
#

integrate the following

cot^-1 ( 1 - x + x^2)

gritty solar
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you're gonna have to split it

tranquil pine
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how

jagged flare
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integrate the following

$\cot^{-1} ( 1 - x + x^2)$

soft zealotBOT
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Skill_Issue

jagged flare
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this?

tranquil pine
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yeah

gritty solar
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[ \arctan \left ( \f{x - (x - 1)}{1 + x(x - 1)} \right ) ]

soft zealotBOT
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Sadie Carnot (η = -1)

gritty solar
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does this look familiar

tranquil pine
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ofc

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.close

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tranquil pine
#

thanks

final saddleBOT
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radiant spoke
#

at what R does a circle with a center (2; -4) and radius R have 2 common points with a straight line passing through point (6; -3)

final saddleBOT
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radiant spoke
#

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meager violet
#

how many ways to split n people into 2 groups which may (all or any) be empty

meager violet
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my brain is fried

covert tree
meager violet
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same

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2 unlabelled groups

jagged flare
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are the people distinct

covert tree
meager violet
meager violet
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what do you mean make the group unlabelled

sturdy cypress
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you just divide the result by 2

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it will be odd

covert tree
meager violet
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still

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so each person has 3 options (group a or b or none)

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so 3^n/2

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thats not right

covert tree
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does every person have to be in a group?

meager violet
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yeah but they can be empty

meager violet
sturdy cypress
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except for {},{}, every possibility will appear twice

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you just do (3^n−1)/2+1

meager violet
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why n-1

sturdy cypress
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(3^n)−1

meager violet
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also why haha

covert tree
sturdy cypress
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because there's one split, namely {}{} that has no pair

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the rest are all paired

meager violet
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what if 3^n-1 is odd?

sturdy cypress
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so you divide only that part of it

meager violet
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oh wait

sturdy cypress
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3^n is odd

covert tree
meager violet
#

yeah yeah

meager violet
covert tree
# meager violet what do you mean?

in our counting process, both ({a,b},{c}) and ({c},{a,b}) are counted, so we essentially counted {a,b},{c} twice. However this is not the case for {},{}.

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we only counted ({},{}) once

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because that is exactly when everyone chose to be left out

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there is only one possible way of doing that

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in all other cases you can have a paring: when all the people who chose group A chose group B instead, and all the people chose group B chose group A instead.

meager violet
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righttt

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thanks

#

.close

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fast salmon
final saddleBOT
fast salmon
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This is a normal textbook question, not even a competition one... But I do not understand how to do it

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And this is apparently the answer

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But I cannot follow the steps...

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Also by first thoughts were herons formula but I found it pretty disgusting to deal with

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<@&286206848099549185>

final saddleBOT
#

@fast salmon Has your question been resolved?

fast salmon
#

<@&286206848099549185>

thorn dragon
#

guys can u help me with this task

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G-center of gravity (median)

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Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

final saddleBOT
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@fast salmon Has your question been resolved?

fast salmon
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<@&286206848099549185>

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@fast salmon Has your question been resolved?

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bleak forge
final saddleBOT
bleak forge
#

I read one says to prove a function continous, it must be
lim f(number) = f(number)

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or lim f(number) from left = lim f(number) from right

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which one is correct?

warm ether
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both

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the second one is the limit existing

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which is a condition for the first to even be checkable (otherwise its just not continuous)

final saddleBOT
#

@bleak forge Has your question been resolved?

final tangle
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second is insufficient

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first is notated poorly

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if $\lim_{x\to a} f(x) = f(a)$ then the function is continuous at $x=a$

soft zealotBOT
#

ℝαμΩℕωⅤ

final saddleBOT
#

@bleak forge Has your question been resolved?

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thick oracle
#

what type of angles are these

final saddleBOT
hollow sable
thick oracle
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what ttype

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like

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inscribed

hollow sable
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insribed angle and a central angle

final saddleBOT
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quaint stratus
final saddleBOT
quaint stratus
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how do i solve this

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i got one solution thats x=1

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when x is between -1 and 1

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but for the other case, i am getting a 4 degree equation

void valley
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first of all

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notice that two first terms starting from the left side are nonnegative for any x

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well, square root as well, but there we have a minus sign

quaint stratus
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yeah

void valley
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mhm, looking for a smart solution, because as you've mentioned squaring both sides leads to some algebra stuff

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and 4th deg polynomial

quaint stratus
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and also the solution to the 4th degree is also 1 (from desmos)

dusty dock
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okay so there's a way to simplify the left terms if we split it into two situations

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where x^2 - 1 is positive, and where it is negative

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when x^2 - 1 is a positive value, we get to keep x^2 - 1

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but when it's negative, we flip it over the x axis

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so we get

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-x^2 + 1

quaint stratus
dusty dock
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i have the answer

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so you can actually get two solutions out of the case between 1 and -1

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now i have zero clue how to simplify the 4th degree polynommial and im honestly too lazy to try lmfao

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but

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what's funny is the 1 as a solution came out as an extraneous solution. it just appeared by squaring both sides

final saddleBOT
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@quaint stratus Has your question been resolved?

quaint stratus
#

the problem here is the 4th degree polynomial

dusty dock
#

did manage to decrease it down to a cubic

final saddleBOT
#

@quaint stratus Has your question been resolved?

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tranquil pine
#

what is it ? a chessboard
what are those arithmetic signs all over it ?

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okay i think i get it

onyx peak
#

Is this something divided by 14 divided by something?

tranquil pine
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the operation should give the summation which matches to that of the end

onyx peak
#

yeah

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whats the order of operations?

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If there was e.g. 1 + 5 x 3 ÷ 1 - 2, what would this result to

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can you use code?

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or do you have to do this manually

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it seems too complicated

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backtracking could solve this quite easily

tranquil pine
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its gonna take time

frank cloud
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it seems kind of impossible

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theres 99 spaces

onyx peak
frank cloud
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and 20 equations

onyx peak
frank cloud
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no?... 100 spaces in total, but one is filled with 14

tranquil pine
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isnt this somewhat like sudoku with toughness of ♾️

onyx peak
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there are additional constraints

onyx peak
frank cloud
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OH THE 5

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I SEE IT

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OOPS-

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stiil, 98 spots, 20 equations

onyx peak
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yeah, and there are additional constraints (such as using only 1, 2, 3 ... 100)

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so it might have an unique solution

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show me the script

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ah

frank cloud
onyx peak
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It's kinda late for me, so I can't write the script

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but I'd suggest you to look at backtracking

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i think that it's gonna be helpful here

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And doing it in this order will help too

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(red first, then green, then blue...)

final saddleBOT
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@snow oak Has your question been resolved?

final saddleBOT
#

@snow oak Has your question been resolved?

final saddleBOT
#

@snow oak Has your question been resolved?

final saddleBOT
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final saddleBOT
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ivory vessel
#

Given a pyramid $S.ABCD$, $SA$ is perpendicular to the base, the base $ABCD$ is a rhombus. Let $M$, $I$ be the midpoint of $AB$ and $AS$ respectively, $N$ belongs on $SB$ such that $SN = 3NB$. The plane $(\alpha)$ passes through $MN$ and is perpendicular to the plane $(SAC)$, $(\alpha)$ cuts $SC$ at $E$. Given that the volume of the tetrahedron $CMNE$ is V, calculate the volume of the tegrahedrom $IMNE$ in V.

soft zealotBOT
ivory vessel
#

this is my current diagram

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i idealized ABCD to be a square, since technically square is also a rhombus

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other than that im stumped

vital surge
#

unfortunate diagram

bright tangle
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Chaotic diagram 💀

ivory vessel
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how else would you draw it lol

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this is all the information given

bright tangle
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Yeah im reading 😅

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My brain can't process 3D 🥲💀... wait for someone else sorry 😅🥲💀

ivory vessel
#

diagram if anyone wanna see for themselves

vital surge
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it helps that the tetrahedrons CMNE and IMNE share three vertices

ivory vessel
#

yup

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the diagram reveals the answer is ||2V/3||, but not sure how to arrive to this answer

vital surge
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are you trying to a find a solution that doesn't make use of ABCD being a square

ivory vessel
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no, i want ABCD to be a square

vital surge
#

alright

ivory vessel
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i dont want to make my life harder

vital surge
#

then coordinate geometry is a pretty easy and accessible way to do this

ivory vessel
#

hm, ill give this some more thoughts. thanks for the suggestion!

#

.close

final saddleBOT
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final saddleBOT
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hollow trellis
#

How do I evaluate this

final saddleBOT
dense coral
hollow trellis
dense coral
#

looks good to me thumbsupanimegirl

hollow trellis
#

🙏 Ty

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dense coral
fathom walrus
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doesnt look good to me

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the correct answer is xe

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dont bleak me

dense coral
#

Xenon gas...

hollow trellis
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Is it wrong to think that the e and ln “cancel” each other out (bc their inverse)

fathom walrus
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not wrong

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functionally inverse

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they do cancel

hollow trellis
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🙏 ty

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.close

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.close

fathom walrus
#

the correct answer is xe

hollow trellis
#

GET AWAY FROM ME

dense coral
final saddleBOT
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slim olive
#

Can someone help me w the u substitution, not sure if i was supposed to choose x^2 or 3-4x

dense coral
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I wouldn't use a u-sub personally

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well, not if the integral is in this form at least

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I suggest distributing the x^2 thumbsupanimegirl

slim olive
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cat_nom i cant tell where i supposed to use u sub or nah

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lemme try that first

dense coral
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usually one uses u-sub when there is a composition of functions

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in this case, there is a product

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so algebraic tricks (like distributing) or IBP will probably be your best bet

slim olive
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Would i need for this problem then?

dense coral
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possibly

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eh, probably

slim olive
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Which one do i take tho

dense coral
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well, first things first

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we should simplify before any tricks like u-sub

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the integrand is a sum rn

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that's hard to work with

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can you think of a way to make it so we don't have that sum as our integrand?

slim olive
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take it out of the root and fraction forms?

dense coral
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ehh

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I was thinking simpler

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the integral is linear

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so $\int_{a}^{b}f(x) + g(x)$ = $\int_{a}^{b}f(x) + \int_{a}^{b}g(x)$

soft zealotBOT
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higher!

slim olive
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oh

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how would i take antiderivitive of g(x) tho cos i have x^-1 doesnt that become a zero?

slim olive
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Like this part

dense coral
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oh yes

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try a u-sub here catthimc

slim olive
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is the inner func the u?

dense coral
slim olive
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im confused on what to do after i get dy

dense coral
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sub it back into the integrand

slim olive
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im not sure how to get rid of the 7 though

dense coral
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the integral is linear, so $\int_{a}^{b} c \cdot f(x) = c \cdot \int_{a}^{b} f(x)$

soft zealotBOT
#

higher!

slim olive
#

Like this?

dense coral
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yes

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take the -1/2 out too

slim olive
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how do i take that oiut

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do i multiply it by 7?

dense coral
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it's also a constant

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yes

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take it out and combine it with the 7

slim olive
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would the u become lnu?

dense coral
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the u doesn't become ln(u), but the antiderivative of u^-1 is ln(u)

slim olive
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i am taking antiderivitibe of u right when i want to integrate it?

grave hatch
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hey ! that's the formula 1/(a^2 - y^2) isn't it..

slim olive
#

wdym

grave hatch
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it's just the formula of integration for the u^-1

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where (a ) is constant ( y) is a function of y

slim olive
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is there a name for the formula

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i can google

grave hatch
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just type special formulae for integration...... you will find a list of 6 formulae which are in fraction.

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this is from google.

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you have 2nd type of problem..

final saddleBOT
#

@slim olive Has your question been resolved?

final saddleBOT
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olive burrow
#

in the b part of this sum i am getting the wrong answer

olive burrow
#

the answer is supposed to be 4

safe spindle
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5600-100P

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i mean

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line 5

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100A-100P

olive burrow
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in line 5?

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how?

safe spindle
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-100 on boths sides

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to put the 100 over pr, you need to times 100 by p

olive burrow
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but whats wrong in what i did

safe spindle
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that is whats wrong

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line 5 in ur wrking

olive burrow
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why cant i just move 100 from RHS and make it -100 is LHS

safe spindle
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yea

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but youre putting it over P

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???

olive burrow
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ohh

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i get it

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im still getting the wrong answer

safe spindle
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t=(100A-100P)/PR?

olive burrow
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no

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100A / PR - 100 = T

safe spindle
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no

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-100r

soft zealotBOT
#

faiyrose

olive burrow
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$\frac{100A}{PR} - 100 = T$

safe spindle
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divide r both sides

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you get 100/R

soft zealotBOT
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Rohith M

safe spindle
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this is simple algebra..

olive burrow
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oops

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i forgot simple alegbra lol

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tysm i got the answe

#

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steep cargo
#

someone help me understand how to do differential equations using Laplace transform

marsh temple
#

You'll have better luck if you post a specific question you're stuck on

steep cargo
#

how do u get the bottom part

#

I know u gotta write out the y's and the put their coefficients in but idk how I'm supposed to get the bottom part

#

like I look at videos and they do different stuff idk what anything is reffering to

#

why did it go from b^2 to s^2

#

why is the s only what

#

does anyone have a name for what this stuff is called so I can like Google it

#

I really don't get it

#

wait I kinda get it bow

#

now

#

so like

#

whats this subject called with the Laplace transforms so I can go in the channel and talk ab it there

sour umbra
steep cargo
#

oh nice ty

#

I still don't get this specific exercise though

#

wrong pic

#

why is Y(s) equal that

#

<@&286206848099549185>

#

why is Y(s) equal to that

#

2/(s+b)^2+4*(s+b)^2

frosty cedar
#

Because

#

Well basically

steep cargo
#

Last one idk if it's right

#

(s+b)^2 +4

#

how do i recover the original of an thing

#

I feel like I'm close to getting the logic of it

#

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shadow garnet
#

What is the area of the region bounded by y = 4 - 2x^2 and y=0.
(My answer is (16sqrt(2))/3)

shadow garnet
#

I just want to check my answer

odd rivet
shadow garnet
#

Thanks

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wet drum
final saddleBOT
wet drum
#

It says in the expansion of it power m cofficient will be

#

59

tranquil pine
#

i dont see m anywhere

spring haven
#

,rccw

soft zealotBOT
wet drum
#

58,59

#

Both

warm python
#

translate 58 please

wet drum
#

58 says in the expansion of (1+x)^2n the greatest term coffiecient will be greatest and x>0 then x will be in interval

#

@warm python

#

Is there any short idea like fake solve?

#

Putting random numbers n=1 and satisfied?

warm python
#

I don't follow

#

like the middle term is the greatest

final saddleBOT
#

@wet drum Has your question been resolved?

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olive burrow
#

I found the answer to (a) which is 25x² + 60x + 36 but i cant figure out how to equate the second one

final tangle
#

first consider area addition/subtraction

woven slate
#

Seems enough

olive burrow
woven slate
olive burrow
#

why did you multiply it from 3 instead of 4

#

there are 4 sides

olive burrow
#

like none of the steps

woven slate
olive burrow
#

ok

#

then?

olive burrow
#

and your answer is wrong

#

the answer is 900cm²

final tangle
#

first consider area addition/subtraction
area of picture PQRS + area of shaded frame/border = total
right?

olive burrow
#

i used that formula itself

final tangle
#

wait, your a) is wrong

olive burrow
#

wait whatt

#

its correct

#

here is the solution

final tangle
#

who says

olive burrow
#

the textbook sats

final tangle
#

which isn't what you wrote

olive burrow
#

oops lol

#

i typed wrong

#

i mixed up another questions answe when typing

woven slate
#

So the x is 6….
And the area is 25*36=900 my goodness

olive burrow
#

ok then?

#

5x

#

25x^2

#

but how does area of border mean the entire picture?

#

doesn't area of boarded mean just the outer boarder

#

oh ok

#

60x+36

#

oh i get it now

#

tysm i got the answer

#

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warm python
#

so I'm doing linear algebra and this is one of the first exercises in the book ( LDR 4e) , I could use eular's formula but is there something else I'm expected to use

warm python
#

other than painstaickingly multiplying it by hand

spring haven
#

polar form

#

or multiply it by hand

#

i dont see any other way

warm python
#

I know

#

but this is from a linear algebra book

#

am I expected to use vectors or lists or something ?

spring haven
ocean lintel
#

surely this is just chapter 1
no

warm python
ocean lintel
warm python
#

👍

#

thanks

#

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hoary meteor
final saddleBOT
hoary meteor
#

how to find b and c

#

I gotta cover probability n sets in 6 hours

warm ether
#

have you found x?

hoary meteor
#

yeah irs just 11

#

is itv

#

?

warm ether
#

i dont believe so

hoary meteor
#

i thought it means complement of b and c

#

so everything that doesnt include b or c

#

not sure rho

warm ether
#

which includes the 4

hoary meteor
#

ohh

#

so 7

warm ether
#

yeah

hoary meteor
#

i still dont get how you do the rest

#

idk how to do 3 way diagram

warm ether
#

its the same logic as a two way one really, i wouldnt overthink it

#

what do you think A and B is

hoary meteor
#

x+1 + 4?

warm ether
#

yeah

hoary meteor
#

oh yh i got it thanks

hoary meteor
#

yk how a sideways parabola is x = y^2

#

how would you write the vertical and horizontal dilation now

#

like for a normal parabola vertical dilation would be af(x) and horizontal dilation would be 1/a f(ax)

#

how would u write both of those for a sideway

final saddleBOT
#

@hoary meteor Has your question been resolved?

silver pewter
#

Hello

#

Is anyone available to answer my question?

final saddleBOT
#

@hoary meteor Has your question been resolved?

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wet delta
#

hey this is like a general question i have, so i get stuck at math a lot, i look at the solution and i do the question again, what do i do about this

tranquil pine
#

don't look at the solution until you're done with the problem and have tried everything

#

getting "stuck on math a lot" is the essence of improving

wet delta
tranquil pine
#

Because the solution actually gives you the step-by-step model answer. But your teachers will (hopefully) drop hints instead of doing that.

#

In fact, now that I think about it, that's even better

wet delta
#

so i just move on then?

tranquil pine
#

Yes, or ask for hints on the math server

wet delta
#

its just that i think what if i dont get that question either

#

what do i do

#

i mean the next problem

tranquil pine
#

This server has a no-answer-giving policy

#

So you'll get hints

tranquil pine
#

this is a friendly server, i'm sure people will be happy to help you

#

what's the question on?

wet delta
#

i mean i was asking generally

#

the concept part i usually get

#

but its the simplification

#

that i go wrong in

tranquil pine
#

can you give an example?

wet delta
#

like

#

calculus

tranquil pine
wet delta
#

find the common normal between two curves

#

i know what i need to do

#

but

#

i go wrong while simplifying

#

and sometimes i have no clue on where tos tart

tranquil pine
#

i think that's just an issue with algebra, no? that is something that improves with practice

tranquil pine
#

practice

#

do more problems

#

if you know how to do them but struggle with simplification

#

then focus on that part

wet delta
#

currently i write everything step by step to not go wrong

tranquil pine
#

focus on improving your algebra skills

wet delta
#

alright thanks

final saddleBOT
#

@wet delta Has your question been resolved?

#
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indigo pilot
#

anyone know the stepts to do this?

final saddleBOT
indigo pilot
#

this too

#

ill try that

#

is this answer d-540/0.5=p or p=2d-1080

#

which one is correct?

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#

@indigo pilot Has your question been resolved?

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hoary meteor
final saddleBOT
green ibex
#

,rcw

soft zealotBOT
hoary meteor
#

i took 2 out and applied sin subtraction identity on the inside so far

#

idk where to go frm there

green ibex
#

what happens when you distribute the 2?

hoary meteor
#

wym

wet delta
#

simplify

#

multiply the bracket with 2

green ibex
hoary meteor
#

ohh

#

would that just leave us with the roots or would it still be 2 times root 2

green ibex
#

what is $\f{\sqrt{2}}{2} \cdot 2$ equal to

soft zealotBOT
#

🫎 Chmoosey 🫎

hoary meteor
#

yeah i got it thank you

final saddleBOT
#

@hoary meteor Has your question been resolved?

visual wigeon
#

close the server

#

if your question's resolved @hoary meteor

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remote island
#

Show that the functions have local extrema at these points:

"dla" means for

remote island
#

f(1) = 2 = f(0) -> f(1) < f(x) : x > 0

#

so i don't really udnerstand this question

remote island
#

because the interval isn't specified

remote island
young bridge
#

you can differentiate the piecewise function

#

so differentiate (x+2) and 2

#

then find where the derivative = 0

remote island
#

at 2

coral prawn
#

the function is not continuous at x=1 so it is also not differentiable at x=1

remote island
#

at x + 2 it's 1

coral prawn
#

therefore any conclusions made from the derivative are kinda sus

remote island
#

i don't understand the interval it wants me to use

#

because i guess, if x > 0, then it's a local minimum

#

in previous problems this is self-evident, for example:

f(x) = x^20 - 3 at x_0 = 0
f(0) = -3 < f(x) : x != 0 -> local minimum

#

here it doens't matter what interval we choose, it's the smallest attainable value by the function

scarlet sequoia
#

global minimum => local minimum yes. Here the interval you choose will matter

remote island
#

yeah so what exactly is it asking me

coral prawn
#

It does matter which interval you choose. Consider for instance epsilon=3. Now there do exist values within that interval that are in fact smaller than h(1)

remote island
#

it doesn't specify an interval

#

It just says to show that they have local extrema at these points

scarlet sequoia
#

it's up to you

remote island
#

okay but then tehre are different types of extrema

coral prawn
#

Here's the definition. Note that d_X(x, x0) = |x0-x|

remote island
#

like idk what it's called in english, but an extremum can either be >= or >

#

the latter is translated to "proper extremum" here

#

and i'm guessing there's only one correct answer

coral prawn
#

I haven't heard of that distinction before

scarlet sequoia
#

well a local proper extremum is possible

coral prawn
#

but h(1) is a proper local extremum point

remote island
#

yeah so here the correct answer is that it's a local proper extremum

scarlet sequoia
#

yes

remote island
#

but what if i would choose that x>= 0

#

then f(1) <= f(x)

scarlet sequoia
#

so you have to find an interval $I$ centered around $a$ such that $h_{|I}$ has a proper extremum at $a$

soft zealotBOT
#

rafilou2003

remote island
#

it just wants me to prove that local extrema exists at these points

scarlet sequoia
#

well if you want to prove that

scarlet sequoia
remote island
#

i don't think you udnerstand

scarlet sequoia
#

you want to prove that there is a local extremum at point 1 for example

scarlet sequoia
remote island
#

my point is that i can prove it for either the proper or "improper" (?) extrema

scarlet sequoia
#

if you have another way then go with it

remote island
#

f(1) = 2 = f(0) -> f(1) < f(x) : x > 0
proves it for local proper minimum extremum
f(1) = 2 = f(0) -> f(1) <= f(x) : x >= 0
proves it for local improper minimum extremum

coral prawn
#

You have to find epsilon such that |x-1|<epsilon implies h(1)<h(x) for all x in R

(this would show that x0 is a proper extremum, and obviously that also means that it's a "regular" extremum as well)

remote island
#

the corerct answer is "local proper minimum extremum"

scarlet sequoia
#

it just proves that it's a local minimum

remote island
#

wut

scarlet sequoia
#

if you want to prove that it's improper

#

you have to prove that there DOESN'T EXIST

remote island
#

wut no

scarlet sequoia
#

an interval where it's proper

remote island
#

definition of a local proper maximum

#

improper

coral prawn
#

note that proper implies improper

remote island
#

so like my issue is that if they're giving me choice, then i can prove it for either proper or improper extrema

coral prawn
#

well take that choice then

scarlet sequoia
#

then with those definitions, proper => improper

remote island
#

wait

#

you're right

#

so

coral prawn
#

Of course you should prove whichever is easier if you're given both options

remote island
#

whenever i have these quedstions i can just try to prove it for proper

coral prawn
#

and improper is easier to prove

remote island
#

okay gotcha

#

sorry for wasting ur time

scarlet sequoia
#

it doesn't make a lot of sense though

#

improper should be the opposite of proper

#

meaning there doesn't exist an interval where it's proper

coral prawn
#

but of course you can also notice that the proper extremum is also incredibly easy to prove and you can flex on your teacher by proving a possibly stronger result than what they wanted

remote island
#

btw

#

is there a shorthand for writing local proper minimum

coral prawn
#

I don't think so

#

it's good practice to get used to writing some stuff out "manually"

remote island
#

like
∃ local min(f(x))
or something lolz

coral prawn
#

math in school tends to be 95% algebraic symbols and equations and expression manipulation

#

whereas math in the "real world" is more like 80% text 20% math

remote island
#

isn't it just a linear algebra textbook

coral prawn
#

I mean the text is also math but basically it makes no sense to try to define a special symbol for everything and just have like logical symbols

coral prawn
remote island
#

seems informal

#

for a thesis

#

"a little boring"

coral prawn
#

yeah

#

I'm cute and quirky like that

scarlet sequoia
#

Another example, still 80% text

remote island
#

okay ty all

#

i will close this channel and ask new quesitons in another

#

once i have any

#

.close

final saddleBOT
#
Channel closed

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simple mauve
#

@coral prawn can u help me

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errant thistle
#

This was a multiple choice, product, question that appeared in am exam I wrote yesterday. Unfortunately I can't remember 'd', but if I recall, option d was >= 1 (provided value).

My assumption, using the following working-out, is that the correct answer is 'a', however, I'd appreciate it if someone could confirm or support my answer.

errant thistle
#

I suspect that the product tends towards 1/2, but never quite gets there, am I right or wrong?

shell skiff
errant thistle
#

I'll check that out quickly

#

I find I get the same result as prior, unless there's a way to develop it further with diff. of squares

shell skiff
#

Write down more terms

native flame
#

dont look for a pattern, look for cancellations

shell skiff
#

Try to find a pattern

errant thistle
#

I do wonder if there is a way to prove without calculating the entire product equation, or if multiplying it out is the only way

native flame
#

oh

errant thistle
#

uh oh

errant thistle
#

I am conflicted

shell skiff
#

Yeah no look for a pattern so you can use cancellation

#

Don't look for a pattern to guess the answer

native flame
#

yeah like dont look for something like "tends to 1/2" or anything is what i meant

errant thistle
#

I see now, the initial difference across the Numerators and Denominators is 5, then 7, then 9 ... d+2

#

can I use this?

#

My brain is not computing rn 🥲

native flame
errant thistle
#

I'm seeing this ...

native flame
#

it should be simpler than that

#

but youre on the right track

errant thistle
#

I'll keep digging for a couple minutes, otherwise, I'll have to contact the university lmao

#

This, that I found, does confirm my answer, although it has no explanation ofc ...

woven slate
#

try to make a^2-b^2=(a+b)(a-b)
gives you the solution

native flame
#

wdym

#

do you understand why

errant thistle
#

no

native flame
#

so on the bottom you have 2 copies of each natural number except for n + 1 (no copies) and on the top you have two copies of each natural number except for n and 2 (one copy of each). you also have only 1 copy of n + 1 on the top. everything in the middle cancels out, so youre left with 101/2(100)

errant thistle
#

give me one, just one, minute to understand 😂 😭

native flame
#

yeah sure. if you need clarification on anything, just ask

errant thistle
#

I'll be back in 5, I think i've got it

#

Showing a classmate the progress to get his input haha

#

My friend gets it, I don't, I may need a visual representation of the cancelling-out

#

He says its "difficult to explain in words" 🥲

#

Okay, after a long look, I finally get it, thank you @native flame 🙏

errant thistle
#

.close

final saddleBOT
#
Channel closed

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mental root
#

Determine whether the set of rational numbers in lowest terms whose denominators are odd under addition is a group.

final saddleBOT
mental root
#

I don't know how to approach the problem

stone wagon
#

let me think how to give you a hint without giving away the answer

mental root
#

i have reached $\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$

soft zealotBOT
#

The د

stone wagon
#

great

#

if b and d are both odd, can bd be not odd?

mental root
#

it must be odd

stone wagon
#

yep

#

so closure is satisfied

mental root
#

but this might not be in lowest terms

#

ohh you cant divide any odd number to get an even one!

#

so yeah

stone wagon
mental root
#

right?

stone wagon
#

like 1/3 = 3/9

mental root
#

yeah

#

like the fractions must be in lowest terms

stone wagon
#

idk man

#

1/3 + 1/3 + 1/3 wouldn't be in lowest terms

muted prairie
#

probably they mean the set of rational numbers which have odd denominators when written in lowest terms

#

well i shouldn't say probably but obviously

stone wagon
muted prairie
#

but yeah seems like you got it

#

unless you want to check the other axioms catgiggle

stone wagon
#

associativity, identity and inverses come for free from rationals

mental root
#

yeah makes sense

muted prairie
#

associativity comes free from the rationals

#

the other 2 not so much catgiggle

mental root
#

but for example if it was even denomiatots I would nit have closure

muted prairie
#

correct

mental root
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perfect

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thanks 😊

muted prairie
#

you should justify identity and inverses too though

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they aren't free

#

though i mean they're pretty easy

mental root
#

yeah they're quite simple

muted prairie
#

but {0, 1, 2, ...} is closed under addition without being a group due to problems with inverses

#

but ye u got the hard part

mental root
#

yes yes I see

#

ty

#

.close

final saddleBOT
#
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muted prairie
#

np

final saddleBOT
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muted prairie
#

first, do you know all of the info you have about bcd

#

can you list it

digital steeple
#

bd an two angles should be enough to calc everything in bcd.

final saddleBOT
#

@tranquil pine Has your question been resolved?

safe spoke
#

You know calc?

muted prairie
safe spoke
#

Is it possible

muted prairie
#

not without using the exact same trig you could just use to solve it instead

#

refer to my first 2 messages here

safe spoke
#

calculus unironically seems simpler to me

muted prairie
#

good luck lmao

#

you know all lengths?

#

I would recommend constructing an altitude somewhere (probably from the obtuse angle for simplicity)

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and then calculating the length of the altitude using trig

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Yeah

safe spoke
muted prairie
#

construct a line going through B perpendicular to DC

safe spoke
digital steeple
muted prairie
safe spoke
#

life of a college student I forgot how to do basic hs math

#

Then do this

muted prairie
#

yeah that's an area formula

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It forms one side of a right triangle, you know the hypotenuse and the other angles

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Those are line segments, so they don't have a base or height

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ah

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that's why I wanted to use CD

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the other 2 altitudes lie outside of the triangle

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it's the line from the top that's perpendicular to the line you get by extending the other side into an infinite line

#

if you google obtuse triangle altitudes you'll probably see it

#

still works in the base*height/2 formula though

final saddleBOT
#

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crimson stirrup
#

May h ask where did I go wrong?

final saddleBOT
final saddleBOT
#

@crimson stirrup Has your question been resolved?

crimson stirrup
#

another question

#

for question c^

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jagged flare
final saddleBOT
jagged flare
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.close

final saddleBOT
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final saddleBOT
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crimson stirrup
#

a

final saddleBOT
crimson stirrup
#

help

warm python
vocal forge
#

is this your question?

fathom walrus
#

clearly not lol

vocal forge
fathom walrus
#

looks like theyre solving for m, not k or a

#

also the number 3 doesnt show up in the problem u posted

vocal forge
#

umm these are images posted by OP, i just reposted them

fathom walrus
#

bro just read what his first picture in this channel has

crimson stirrup
sonic crystal
crimson stirrup
#

first image is the insert

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second image is my working for second last question

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third image is my working for last question

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I wanted to ask where did I go wrong

fathom walrus
crimson stirrup
#

This is the insert for my second question

final saddleBOT
#

@crimson stirrup Has your question been resolved?

crimson stirrup
#

help?

final saddleBOT
#

@crimson stirrup Has your question been resolved?

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barren basin
#

Given two different but similar plots (let's assume in 2d and the plot is Given by discrete values), translate plot A so that it overlaps on plot B with the smallest error possible.

barren basin
#

My question is what would an algorithm to complete this task would look like. What if we are allowed to translate in any direction ? What if we allow stretching ?

digital steeple
#

the question is too unspecific. which translations do you have in mind?

native flame
#

im guessing theyre talking about something like gradient descent?

barren basin
#

Well, think about it as if you have done the same experiment twice, the data should look similar, but it likely won't begin at the same origin.

native flame
#

so youre trying to find a function of best fit?

digital steeple
#

hmm if you have two sets of n points you can always translate errorless one into the other.

barren basin
#

In my actual case, I am trying to compare two curves. I can translate those curves on top of each other visually/manually, but I'd prefer to automate that part

barren basin
digital steeple
barren basin
#

I'm not quite sure I understand.
I have two set of data that I'm trying to fit one on top of another

native flame
#

so wdym fit

#

i strongly suspect youre looking for gradient descent. but if you could clarify your problem statement a little bit it would be helpful

#

basically, youre looking for a way to generalize something like linear regression, right?

#

where you have a two sets of data points and you want a function that minimizes average error over both sets

barren basin
#

Sorry for the whitespace, best I can do on mobile opencry

digital steeple
#

you said you have given the function by discrete points, so you do not really have curves.

barren basin
#

Yes i don't have f(x) = y, I only have the coordinates of points making the curve

digital steeple
#

you have a set of n Points P1, ... PN and a set of Q1, ..., QN. and you want a function PI->QI.

barren basin
#

In my problem I kind of have to find irregularities in my data, in my example my data had two bumps, a larger one followed by a smaller one
Both sets of data have these characteristics

digital steeple
#

in this case you can find a polynom of (at least) degree n-1 which fits exactly to the gven points.

barren basin
#

Visually I could stretch and translate the shape so that they "sort of" fit onto each other

native flame
#

okay hold on is this what youre looking for

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the green line is the function youre looking for, the red and blue points are different datasets

barren basin
#

Yes exactly, except the blue points are not necessarily aligned on top of each other already

forest ember
#

I think what is looking for is to keep the 2 curves separate, but have the points of interest on the curves align

barren basin
digital steeple
native flame
mellow axle
native flame
barren basin
mellow axle
#

if $f(x)$ and $g(x)$ are two discrete functions over set $A$, determine for which $a, b$ minimizes $\sum_{x\in A} f(x) - (g(x - a) + b)$

soft zealotBOT
#

pee norm maxxing

digital steeple
#

well it makes a difference if youre searching for a transformation from one line to another:

barren basin
#

If you drop the basketball at the same height and plot the height, which was measured discretely, then visually you could observe that the two curves are very similar

mellow axle
#

is that what you're trying to ask?

native flame
#

i think i see what you're getting at. basically you want to approach this by taking the mean at each point, and for that you want the points on the x axis to line up

digital steeple
#

or if your searching for a common function.

barren basin
native flame
#

youll want to get more than two samples for this

barren basin
#

In the simplest case, I have function 1 in blue and function 2 in purple. Visually we can see that the trapezoidal shape thingy is my region of interest, thus I could translate f2 so that the trapezoids are ontop of one another

#

Now, I have 200 such curves

native flame
#

right but how do you pick which one to translate

barren basin
#

Well, that wouldn't be too important since my goal is to compare them

native flame
#

oh

#

hmm

digital steeple
# barren basin

i repeat this.#help-36 message this is (theoretically) errorless possible. but mostly it doesnt make sense (google overfitting), so you should typically say something about wanted transformations (linearity for example).

barren basin
#

Yes it would have to be linear translation or stretching

native flame
#

stretching?

#

so you want to compare them by analyzing the function that maps one curve to anothrr

digital steeple
digital steeple
barren basin
#

For translation, you could likely try every possible translations possible(since you can't translate more than the size of the data), but I'm assuming there's a smarter solution than trying AxB possibilities

native flame
#

a naive approach could be mapping each point from A and B to their mean

#

instead of one function that takes A to B, you have two functions that take A and B to a common curve

native flame
barren basin
native flame
#

lets just consider translations first

$E = \sum |a_i - b_i|$

you want to find the translation of B that minimizes this error?

soft zealotBOT
#

esca (@ with reply)

barren basin
#

Exactly correct

digital steeple
# barren basin Exactly correct

just for completeness: you also have to define your error function which you want to minimize. you can do the sum of the absolute errors, mostly its the sum of square of the errors. the result depends on the error functioon you choose.

#

you could measure by maximize correlation fore example.

native flame
#

in general for two variables youll just want to take the derivative of the error function and use that as your next translation

#

iirc

barren basin
digital steeple
#

typically this decission depends on the structure of the data. sum of squares tends to give extreme outliners more impact then just taking the absolut errors. is like a mean vs. median discussion.

native flame
#

i think some error functions are also easier to minimize than others

digital steeple
#

to sum up (from my practie view): there is no general advice someone can give you. it really depends on your data, on your experiment generating the data, and the purpose you wanna to with this.

So to go on further I would need more details.

barren basin
#

In my experiment, I have measured the throttle cycle of a car going from 0 to 100 mph
On the x-axis you would have the time and the y-axis is the speed.

I have over 100 samples curves, taken with the same car, same pavement, same tires, and a bunch of other controlled variables.
I am trying to trace the envelope of possible outputs, and to do that I need to overlap those 100 curves.

The time of recording won't always be the same, and the speeds will slightly differ, but will look really similar

digital steeple
#

well you have something in the range of some seconds on the x-axis, a renge 0 to 100 on the y-axis and n general the same conditions (same car, same tires, etc.)

shouldnt it then be identical curves (nearly)?

barren basin
digital steeple
#

well thats a completely different task fro my point of view. it looks for me that the experiment has some "troubles" (there's a little bit of roll before the tires latches into the ground and so on), so I wont do a transformation on the resulting data to fit similarity, i would try to adjust the data to get rid of this "experiment-troubles": So if youre not sure that the measure starts a the same point/time, try to adjust this.

#

for "there's a little bit of roll before the tires latches into the ground" it would just shift to the left with this "little bit".

barren basin
#

Well we can't control everything. I think people who've experimented on tensile tests have had to solve a very similar problem.
There's always irregularities in the material that changes slightly the values.

And you're right, it would shift to the left a little bit, the question is inherently about "how much" should you shift to minimize the error

digital steeple
#

i do fully agree. but handling errors in the setting of an experiment is a complete different task to "transform similar curves".

You can try to ignore this errors first, do so as wouldnt there such setting-errors and assume that the resulting curves should be nearly the same. the determine the "mean curve" of all resulting curves, determine the difference from each resulting curve to the theoretical mean curve. make a error distribution an then for example discard the most 5%, 10%, 15 % percent error curves.

Maybe the setting errors equals each other and you can ignore them therefore.

But as said before, i guess this needs much more time to spent with the settings, the data, and the purpose you want to achieve. thats much to detailed for discussing here I guess.

#

or you could do the following: if you curves go from 0 t0 100 mph, you could adjust all with a first value speed of your choive, eg initialize all curves with the time of the first value above 5mph.

final saddleBOT
#

@barren basin Has your question been resolved?

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serene rain
#

help

final saddleBOT
serene rain
#

so

tranquil pine
#

so

serene rain
#

my idiot ahh forogt how to do these

#

and i got a final tommorow