#help-36

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remote island
#

which problem are you erferrign to

midnight sparrow
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The 1 you send

remote island
#

there's no transpose in

midnight sparrow
#

Here

remote island
#

wdym by "unchange"?

midnight sparrow
#

I will let ten duce continue I think

remote island
midnight sparrow
#

Like multiply by the Identity do nothing

remote island
#

so both of you can help me

midnight sparrow
#

If I multiply a Matrix by the Identity it will be thé same as befofe

remote island
#

okay, but you're multiplyign it by A^-1

midnight sparrow
nocturne vale
#

yo

remote island
nocturne vale
#

XA=C

midnight sparrow
#

So by multiplying by thé inverse on each side you get the Identity multiply by X

nocturne vale
#

XAA^-1=CA^-1

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XI=CA^-1

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X=CA^-1

remote island
#

ok gothca

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what do you do with this tho

midnight sparrow
#

But you need to make sure A is invertible

nocturne vale
#

Sorry this is my topic pre midterm so I almost forgot

nocturne vale
#

so take the given matrix on LHS

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and take transpost

midnight sparrow
#

The set of invertible matrices is a group so AA-1 gives you the identity

remote island
#

yeah ok got it

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now let's do

nocturne vale
#

sorry one sec

remote island
#

how would you do it without setting up a system

nocturne vale
#

let me just make sure

#

one sec

midnight sparrow
#

Sry I need to go GL 👍

remote island
#

ty, bye

remote island
#

@nocturne vale ynou there?

#

or could sm1 else please come and help me with these 3

remote island
#

X^-1 != X^T tho

final saddleBOT
#

@remote island Has your question been resolved?

nocturne vale
soft zealotBOT
#

Ten-Duce

nocturne vale
#

@remote island yo

#

still there?

remote island
#

yea @nocturne vale

remote island
nocturne vale
#

the inside evaluate to (I) so (I)^2001

remote island
nocturne vale
#

yeah

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I felt like these usully wont be too hard u know

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they are really testing the concept of matrix power

remote island
#

i think you're wrong

nocturne vale
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ok let me ck

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right?

remote island
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oh yeah

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wha about the other two

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for the 2nd just multilpy and subtarct

nocturne vale
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the transpose one is fucking weird

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the other one I haven't try

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like what did you guy learned recently?

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might be some theorem I forgot

remote island
#

it's from an old problem sets o idk

nocturne vale
#

let me try the other one

final saddleBOT
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remote island
#

.reopen

final saddleBOT
#

nocturne vale
#

YO

#

The second one $4IX-2IX=2IX=2X=A$

soft zealotBOT
#

Ten-Duce

remote island
#

how did you figure it out

nocturne vale
#

see the first and 4th term on the lhs is just scaler times identity matrix

#

you see that?

remote island
#

yea

nocturne vale
#

the other one let me have another try

remote island
nocturne vale
#

Si

remote island
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@nocturne vale i have to go in 5min

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can you do it till then

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gotta go

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bye and thanks

#

.close

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modern dome
final saddleBOT
modern dome
#

Integration using U substitution

modern dome
# modern dome

I just gota ask is it always 1 when you move the derivative u and why 1?

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#

@modern dome Has your question been resolved?

shadow tinsel
#

or which 1 are u referring to

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modern dome
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modern dome
#

Du/3 to 1/3

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Sorry it took me long to reply I was cooking

shadow tinsel
#

it wont always be 1

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du/3 is just 1/3 * du

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so thats how they get the 1/3

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it wont always be 1/3 tho, it can be 2/3 it can be pretty much any number rly

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#

@modern dome Has your question been resolved?

modern dome
#

I'm confused cause the video I watch just said 1 and no explanation

modern dome
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mystic zenith
#

hey quick question. Number 1, what does the weird brackets mean? And how to solve a)

final tangle
#

are you referring to the
]a,b[

mystic zenith
#

Yes

final tangle
#

that's old interval notation still used in some places
other places use (a,b)
to represent the set of values between a and b exlcuding a and b

mystic zenith
#

So a and b does not work in function? But numbers between them do?

final tangle
#

well here the words say except for ]a,b[

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so stuff between are the values that don't work

mystic zenith
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Oh ok so a and b does but not in between

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And how would one solve the a question?

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charred warren
#

i need guidance to answer this

final saddleBOT
cloud cloud
charred warren
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180 - 104 - 21

cloud cloud
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Yes

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,calc 180-104-21

soft zealotBOT
#

Result:

55
cloud cloud
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Then you know that b is 1/2(O) bc of arcs

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And solve for w from there

tranquil pine
#

nvm

final saddleBOT
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keen turret
final saddleBOT
keen turret
#

What did I do wrong for my answer to be wrong

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The second calculation is the actual answer

silver roost
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You forgot to change bounds back

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Once you went back to x

keen turret
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Oh

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I actually didn’t know that

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Or forgot

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Thank you

silver roost
#

Np

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thorn minnow
#

R is integrityring need to show those sets are equal, any ideas? 🥺

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vale reef
final saddleBOT
vale reef
#

What does symbol on second line mean

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I thing

desert mantle
#

I thing?

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do you mean $\Phi$?

soft zealotBOT
#

Denascite

long wraith
#

$\phi$

soft zealotBOT
long wraith
#

Oh yeah

past hedge
#

.reopen

vale reef
#

Yeah

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Idk why that’s here

long wraith
#

Your teacher just named it phi thats all

vale reef
#

Oh ok lol

#

Thx

#

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tranquil pine
#

253.52 apples, 5 is 5/10 of 1 apple, 2 is 2/100 of 1 apple (if the whole appks gets divided into 100 equal parts) , 2/100 of one apple is 10 smaller than 5/10 of 1 apple, as , 2/10x 1/10 right guys?

tranquil pine
tranquil pine
#

is it riht

hidden oriole
#

send the actual problem idk what ur saying

tranquil pine
#

guys

tranquil pine
tranquil pine
#

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frail girder
final saddleBOT
frail girder
#

d option?

cold gorge
#

Assuming A, G and H are arithmetic geometric and harmonic means, yeah.

frail girder
#

yup

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o my god dude you got a trippy profile

#

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hidden oriole
final saddleBOT
hidden oriole
#

help

#

i used the IBP but i got an answer way off

thick breach
#

there's no need for that

hidden oriole
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there isnt?

thick breach
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$take lnx = t => x = e^{t}$

soft zealotBOT
#

penguin

hidden oriole
#

OH

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substitution

errant crane
#

what are the chances of getting 5.5% 3x in a row?

thick breach
#

yeah, no need for IBP

hidden oriole
errant crane
#

sorry, idk what im doing tbh

hidden oriole
#

because e^t isnt in the function

hidden oriole
#

its available

lethal bronze
thick breach
#

ah the integral should come out to be
\newline
$\int \frac{t}{e^{2t}}dt$

soft zealotBOT
#

penguin

hidden oriole
#

OH because they are inverse

thick breach
lethal bronze
#

isn’t the denominator e^3t

thick breach
lethal bronze
#

I am stupid carry on

hidden oriole
#

ok i get it

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so then we have u = t

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and v' = 1/e^2t

thick breach
#

no point in taking u = t mate

hidden oriole
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i am not that great with IBP so it helps me remember

thick breach
#

oh my bad you meant the u and v right?

hidden oriole
#

yeah

thick breach
#

yeah you're right, v'= e^{-2t}

hidden oriole
#

so we have
\newline
$ t * \int e^-2t

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for the first term

thick breach
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correct

hidden oriole
#

which is t * -0.5e^-2t

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and for the second term we have the integral of e^-2t

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which is -0.5e^-2t

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so its -0.5e^-2t(t + 1)

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and we just sub in ln(x)?

thick breach
#

yeah just substitute the original variables

hidden oriole
#

0.5e^-2lnx(lnx + 1)

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and evaluating for e gives us e^-2

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and evaluating for 1 gives hs

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0.5(ln(1) + 1))

thick breach
#

$\frac{-2lnx+1}{4x^{2}} + C$

soft zealotBOT
#

penguin

hidden oriole
#

ty

thick breach
#

anytime!

hidden oriole
#

.clised

#

.closed

#

.solved

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tranquil pine
#

yo

final saddleBOT
tranquil pine
#

hi@yoo

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alr so

#

a) 1/2 represwnts half of a sandwich

small linden
#

what

hidden oriole
#

what

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i guess

tranquil pine
#

situation 1:
1:2, ratio representing a scenerio where one over 2 ppl/ one to two ppl, got 1/2 of a sandwhich so one person got half of a sandwhich
situation 2

3:4
3 dogs per 4 cats got got their legs taken away
so
0.75 of their legs got taken away? like what is the decimal representing here?

marble agate
#

is this your hw question or what?

#

i dont get what youre asking

tranquil pine
#

im trying to understand decimals

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verbal wren
final saddleBOT
agile coral
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vapid basalt
whole pecan
#

Ignore the 4

final saddleBOT
#

@verbal wren Has your question been resolved?

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fossil widget
#

halo guys this is discrete, um, my understanding of vertices are they are like the joints and connect the edges together and edges are just the lines, however im a little confused on how to find the degree of each vertex, and how to identify a pendant, (i assume isolated means a vertex has no edges connected to it)

fossil widget
#

nvm got it ty guys

#

.close

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cyan shoal
final saddleBOT
cyan shoal
#

A country's trade balance, in a given period, is the difference between the total value of exports and imports, in that order. What was the percentage growth rate of the trade balance from 2023 to 2024 for this country?

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and this

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A country's trade balance, in a given period, is the difference between the total value of exports and imports, in that order. What was the percentage growth rate of the trade balance from 2022 to 2023 for this country?

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<@&286206848099549185> pls?

#

20%?

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ohhh ok

cyan shoal
#

tysm bro

#

<3

#

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trail river
#

how do I simplify this?

final saddleBOT
trail river
#

further

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I want to prove its equal

#

to

whole pecan
#

the top

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you can factor

trail river
whole pecan
#

waht

#

well

#

let k=cosx

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k^2 -2k + 1

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factor!

trail river
#

ah

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it wasn't obvious

#

?

trail river
#

what now

#

still can't simplify

lethal bronze
#

factor the denominator

#

difference of squares

trail river
#

nice thakns

#

got it

#

.close

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tranquil pine
#

I just dont even know where to start

final saddleBOT
tranquil pine
#

if anyone can help

tulip coyote
#

y axis sadcat

tranquil pine
#

ok i'd be wrong to say i dont know anything

tulip coyote
#

Do you have that example 3 they refer to?

tranquil pine
#

yea hold on

tulip coyote
tranquil pine
#

so i know $:f'\left(x\right)=\frac{ln\left(x\right)}{x\sqrt{ln^2\left(x\right)-1}}$ if im not wrong

soft zealotBOT
tulip coyote
#

That would be the second derivative of f

tranquil pine
#

$2\pi \int _e^{e^3}x\sqrt{1+\left(f'\left(x\right)\right)^2}dx$

soft zealotBOT
tulip coyote
#

First derivative is as per here via FTC catThumbsUp

tranquil pine
#

oops

tulip coyote
#

Anyways how do you even rearrange an integral function NervousSweat

tranquil pine
#

ummm

#

So this is what i have rn $2\pi \int _e^{e^3}x\sqrt{1+\left(\sqrt{ln\left(x\right)^2}-1\right)^2}dx$

soft zealotBOT
tranquil pine
#

then this $:S=2\pi :\int _e^{e^3}x\sqrt{1+\sqrt{ln\left(x\right)^2-1}}$

soft zealotBOT
tranquil pine
#

wait no

tulip coyote
#

Wouldn't it be dy though, if you're revolving about the y axis sadcat

tranquil pine
#

$S=2\pi :\int _e^{e^3}x\sqrt{1+ln\left(x\right)^2-1}$

soft zealotBOT
tranquil pine
#

hmm true

tulip coyote
#

Also isn't it supposed to be f(x) instead of x on that inside bcaForgiveBeg3

#

Nasty FumizukiCross

tranquil pine
#

idk

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imma just show what i got

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$2\pi \int _e^{e^3}x\sqrt{1+\left(\sqrt{ln\left(x\right)^2}-1\right)^2}dx$
$S=2\pi :\int _e^{e^3}x\sqrt{1+ln\left(x\right)^2-1}$
$S=2\pi :\int _e^{e^3}x\left|ln\left(x\right)\right|dx$

soft zealotBOT
tulip coyote
#

I mean, taking that as is, and noting that cause x > 1 for all the values under consideration, you can get rid of the absolute values catThumbsUp

#

For which it becomes by parts, I'm just gonna assume they messed up and meant x axis tbh catGiggle

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If it were y axis, I'd give up life HangMyself

tranquil pine
#

$\int :xln\left(x\right)dx:=:\frac{x^2}{2}ln\left(x\right)-\frac{x^2}{4}+C$

soft zealotBOT
tranquil pine
#

what do u think of the last thing i posted

#

i think i just plug in e and e^3 into the last part of the problem

tulip coyote
#

Yep seems about right happyCat put the limits in and all

tranquil pine
#

$2\pi \left(\frac{e^6}{2}ln\left(e^3\right)-\frac{e^6}{4}-\frac{e^2}{2}ln\left(e\right)+\frac{e^2}{4}\right)$

soft zealotBOT
tranquil pine
#

$2\pi \left(\frac{5e^6}{4}-\frac{e^2}{4}\right)$

soft zealotBOT
tranquil pine
#

$\frac{\pi }{2}\left(5e^6-e^2\right)$

soft zealotBOT
tranquil pine
#

how is this looking @tulip coyote

tulip coyote
#

Looks good to me I think happyCat

tranquil pine
#

ty ty

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and uhhh

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i think thats all

#

i put the absolute values on the constants u said last tie so i dont think more questions

tulip coyote
#

happyCat perfect SCgoodjob2

tranquil pine
#

have a goodnight gang

#

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wheat hamlet
final saddleBOT
wheat hamlet
#

anyone know what this is

faint monolith
#

double angle trigonometry

#

basically change tan to sin/cos and use sin/cos double angle formula

wheat hamlet
#

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tranquil pine
final saddleBOT
tranquil pine
#

trying to understand why b is S14W

#

I'm getting S14E

timid pollen
tranquil pine
#

oh ok thx

#

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young verge
#

Would this be y = 9 and x = 4?

final saddleBOT
white sphinx
#

no

wanton pine
#

it never specified integers

faint monolith
#

what does it mean its a minimum

white sphinx
#

minima

wanton pine
#

as small as possible

white sphinx
#

write the second equation (x+4y) in terms of one variable then find the minima

wanton pine
#

yeah

young verge
#

oh i see what i did wrong

#

i frogot the squared

#

so should it be 3 and 12

white sphinx
white sphinx
#

x = 12 and y = 3

young verge
white sphinx
#

yes

#

it says first number + 4 times of second number

#

if you take second number as 12

#

it isnt really minima

white sphinx
#

so x must be 12

young verge
#

alr

#

thanks

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young verge
#

A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimensions will produce a box with maximum volume?

young verge
#

Can someone walk me through this

#

im having trouble with the set up

wanton pine
#

aight

#

just a question first? the box mentions having a square base but i assume it doesnt have the same length height?

young verge
wanton pine
#

aight well our first goal should be to setup an equation for the surface area of the box since we are given what it should equal

young verge
#

would the surface area be

#

the base and the top * the sides?

wanton pine
#

if we let x equal the base length of the box and y equal the height what could u create?

#

just the base and the sides

#

its an 'open' box

#

meaning it has no top

young verge
wanton pine
#

right

#

and that equates to 108

young verge
#

yes

wanton pine
#

now we should setup our function to find the maximum for

#

since we want to find the maximum volume we should create a function for the volume of the open box

young verge
#

because the height isnt the same, the volume would be x^2 * h right

wanton pine
#

correct

#

but this creates a problem as we have 2 variables which we dont want

young verge
#

yaeh

#

How ould i seperate this

wanton pine
#

but since we know that 4xh+x^2=108 we are able to find the value of either x or h in terms of the other variable

young verge
#

would it be easier to make it in terms of x or h?

wanton pine
#

h

#

make h in terms of x

young verge
#

so 108/4x - x/4 = h?

#

by moving the x^2 to the other side

#

and dividng by 4x

wanton pine
#

right

#

just for simplification sake 108/4x = 27/x

young verge
#

yea

wanton pine
#

now we can just sub in the values for h into our volume function

young verge
#

ok so v = x^2 (27/x - x/4)

wanton pine
#

right and i'd expand that to make finding its derivative easier

young verge
#

27x - x^3/4

wanton pine
#

yep

young verge
#

derive?

wanton pine
#

yeah since we have a function we are able to find out its Minima and Maxima, to do that we take the derivative of the function and set that equal to 0 to find 'stationary points' which relate to points that have a slope of 0 which are Minima, Maxima and Horizontal Points of Inflection

young verge
#

so would the max value be 6?

wanton pine
#

not the max value, but a max when x=6

#

actually

young verge
wanton pine
#

well we have 27-3x^2/4 =0 right?

#

108=3x^2

#

x^2=36

young verge
#

wait whered 2/4 come from?

#

oh 3/4

wanton pine
#

oh sorry its the notation

young verge
#

Yeah

wanton pine
#

x=+6 or -6

young verge
#

oh and now do i have to find the max / min using second derivative?

wanton pine
#

yeah

young verge
#

so max at -6

wanton pine
#

correct

young verge
wanton pine
#

yep

young verge
wanton pine
#

oh wait im mistaken its 6

#

yeah was bout to say mb

#

second derivative needs to be negative for a maximum

young verge
#

so would h then be 23/6

wanton pine
#

,calc 27/6-6/4

soft zealotBOT
#

Result:

3
wanton pine
#

,calc 108-36

soft zealotBOT
#

Result:

72
young verge
#

oh

wanton pine
#

yeah its 3

young verge
wanton pine
#

just checking if it calculated correctly

young verge
#

ah alr

#

thanks

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teal robin
#

I understand the process of this question but I am unsure how to know which one the average is? why is it v_x = 4/3 and not the v_y or the v_z?

teal robin
#

Here is the introduction to the question, before the parts come into play : )

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teal robin
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.reopen

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haughty moth
#

Show that any rational complex function can be expanded into a power series within any disk where it is defined

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real mesa
#

why he did that 1 x i frac i x i

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candid hull
#

C'est un trick pour rendre le dénominateur réel

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tawny nest
final saddleBOT
tawny nest
#

F2 is a sub vectorial space, how can I determine its base?

midnight sparrow
#

Resolve this system in parametric form

#

It will gives you 2 vector

#

Show there are not colinear and it's your basis

tawny nest
#

I didn't understand the solution either.

midnight sparrow
#

T'es français

tawny nest
midnight sparrow
#

Ah

last palm
#

Can I use integration by parts with more than 3 functions

midnight sparrow
#

Yes it's basicaly that I forgot the z

tawny nest
#

But like how to solve it? How to get those vectors?

midnight sparrow
#

Do you know how to have the nulle space of a matrix

tawny nest
#

Suppose that la combinaison linéaire =0?

tawny nest
midnight sparrow
#

Yeah

#

It's basically the same thing

#

Here t IS the unknown with 3 parameters x,y and z

tawny nest
#

The issue for me is, everything is a variable, there is no constants, Idk how to that...

midnight sparrow
#

Just write t with parameters

#

Make F2 in parametric form

#

And it will gives you the vectors

tawny nest
#

Picture of the beginning of the solution would be helpful...

midnight sparrow
#

Do you understand french or not ?

terse dagger
#

they write t as a function of x and y

#

this means that the subspace only has 3 degrees of freedom

tawny nest
#

You didn't get the issue I'm facing...

terse dagger
#

oh ok

tawny nest
#

How is it useful to apply the algorithm since everything is a variable?

terse dagger
#

,rotate

soft zealotBOT
terse dagger
#

i'm not entirely sure what algorithm you're using

midnight sparrow
#

What do you want

tawny nest
#

Gauss Algorithm to simplify such matrices.

tawny nest
midnight sparrow
#

Your matrices refer to what ?

tawny nest
#

I think la combinaison linear de F2.

midnight sparrow
#

F2 IS the nullspace of this row matrice A= (1 -2 0 1)

honest lily
#

What does this even mean? "You need to provide information about your population and what subset of the population your sample was taken for your study."

tawny nest
#

I made this matrix to find a base by using (famille génératrice et libre).

#

Propriété.*

midnight sparrow
#

Une famille génératrice tu l'as avec ton ensemble

#

Ensuite il faut montrer que cette famille est libre

tawny nest
#

Pour montrer "libre" il faut faire l'algorithme du Gauss, mais comment je faire ça avec tout ces variable....

midnight sparrow
#

Déjà quelle famille veut tu montrer la liberté

tawny nest
#

Xvect + Yvect2 + Zvect3 + Tvect4.

midnight sparrow
#

Vect 1 2 3 et 4 c'est quoi, quelle est la famille

tawny nest
#

Idk, F2?

midnight sparrow
#

Do you understand how WE pass from F2 to its parametric form ?

tawny nest
#

Using combinaison linéaire.

tawny nest
midnight sparrow
#

Yeah it's really simple, WE write t with all parameters

#

So F2 = Vect ( v1,v2,V3 ) right

tawny nest
#

I know, I specified my problem earlier, my problem is how to find the values of each vector so la famille doit être génératrice et libre.

midnight sparrow
#

So it's how they find v1, v2 and V3 ?

tawny nest
#

Exactly.

midnight sparrow
#

Ok

#

So do you understand thé first Line of the proof ?

tawny nest
#

We talked about it earlier.

#

The line where it showed each vector components is confusing me.

#

Is the problem.

midnight sparrow
#

So you understand Line 1 and 2 but not the third

tawny nest
#

2nd line and 3rd.

midnight sparrow
#

Ok

#

So AT the end of thé first Line WE write F2 in a parametric form

tawny nest
#

Show me how.

midnight sparrow
#

So you don't understand also the 1 st Line

tawny nest
#

Bro

midnight sparrow
#

IS this clear

tawny nest
#

You have (X,y,z,2y-x) it is normal.

#

How to go to the 2nd step?

midnight sparrow
#

Do you know that (a,3a,4a) = a(1,3,4) ?

tawny nest
#

Okey?

midnight sparrow
#

So do you understand thé 2nd Line now ?

tawny nest
#

No.

#

Look at the solution....

midnight sparrow
tawny nest
#

Exactly, how the did he reach the 2nd line?

midnight sparrow
#

Can't you see

#

Just factorise by X, y and z

#

(x,y,z,-x+2y) = x(1,0,0,-1) + (0,y,z,2y) right ?

tawny nest
#

oH

midnight sparrow
#

Factorise by y and Z after

tawny nest
#

But how is that possible and X,y,z are vectors not scalaires?

midnight sparrow
#

Look again what is x,y,Z and t

tawny nest
#

It belongs to R^4

midnight sparrow
#

So what is x

#

What is y

#

What is z

#

And what is t

tawny nest
#

Oh

#

Vectors.

midnight sparrow
#

No🥲

tawny nest
#

lol jk

midnight sparrow
#

They are reals, scalars

tawny nest
#

They are scalaires since they are multiplied to a vector components.

midnight sparrow
#

You said it belongs to R 4

#

Yesssssss

tawny nest
#

Lmao

midnight sparrow
#

😂

#

So 2 nd Line IS ok ?

tawny nest
#

Everything is ok lol.

midnight sparrow
#

👍

tawny nest
#

Thanks mate.

#

,close

#

.close

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brittle sail
final saddleBOT
brittle sail
#

Can someone please help me solve number B or C of number 8

hybrid heath
#

,rccw

soft zealotBOT
midnight sparrow
#

Just developp for B

#

And use the fact that cos ^2 + sin ^2 = 1

#

For c, Idk what is cosec

final saddleBOT
#

@brittle sail Has your question been resolved?

azure trellis
#

Cosec is 1/sin

#

There are rules you can derive from the base trig equation by dividing by sin^2 or cos^2

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tawny vault
#

what have you tried so far? can you send your working?

#

ok i found y pretty easily so there must be something you have done wrong :0

#

we can say e^5y = x and 4ln(x) = 7 - y

#

for the second equation, we can isolate 'x' by dividing both sides by 4 and raising both sides to 'e'

#

x = e^(1/4(7-y))

#

then sub x = e^(1/4(7-y)) into e^5y = x

#

does this help you progress further?

#

:) good luck

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final saddleBOT
#

@crisp epoch Has your question been resolved?

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@crisp epoch Has your question been resolved?

crisp epoch
#

.close

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coral prawn
#

In #help-28 , some other people concluded that this function is not continuous at x=0.

However, if you write e^x as k then you get (1+xk^n)/(1+k^n)

= (1/k^n + x k^n) / (1/k^n + 1)

coral prawn
#

and as far as I can see, for negative x<0, k<1 and thus by the original expression you get (1+0)/(1+0) = 1

#

oh yeah nevermind lol

#

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naive shoal
final saddleBOT
naive shoal
#

x^2-14x+40

#

symbollab says thats wron

#

but isnt what i did correct?

#

NVM

#

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remote ingot
#

how would i go about finding the derivative of this?

coral prawn
#

chain rule

#

(cos(2x))^2

#

2(cos(2x)) times the derivative of the inner function

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remote ingot
#

thank you!

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sacred lynx
#

Need to find m every values sum so that (2m,0,4) vectors length is less then (sqrt3 *m,3sqrtm,2sqrt13) vector length

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#

@sacred lynx Has your question been resolved?

sacred lynx
#

<@&286206848099549185>

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peak kernel
final saddleBOT
peak kernel
#

why is part a not differentibale at x = 0 but part b is

nocturne ravine
#

is it continuous at 0

#

u could ask urself that

peak kernel
#

ahh and if discontinuous then its not differentiable?

nocturne ravine
#

yes

peak kernel
#

im just struggling to wrap my mind around the function

#

am i meant to try and visualise it?

nocturne ravine
#

umm i guess it would be hard to visualize it

#

take derivative

#

of each

#

compare the two for each question

peak kernel
#

ok

#

im still confused

nocturne ravine
#

what dont u get

peak kernel
#

after i get derivative

#

how does that help me with the question?

nocturne ravine
#

what makes a function differentiable at x = 0

#

or at x = a

peak kernel
#

continuous and doesnt have a sudden change in gradient

nocturne ravine
#

like a corner or cusp?

peak kernel
#

ye

#

ohh

nocturne ravine
peak kernel
#

ah so part a has a sudden change in gradient

nocturne ravine
#

Sure

#

how do you know?

peak kernel
#

is that cuz the powers differ by alot

#

on the limit

nocturne ravine
#

Honestly i dont think u can use that explanation here

#

My approach would be determining the derivative of each part of the piecewise function

#

and determining fi they are equal or not

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midnight trellis
#

Ik this is physics but I trying to figure out if the algebra is off

midnight trellis
#

find v_af and v_bf

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Just need someone to tell me this algebraically correct

zenith pollen
#

uh which equations did you start with

midnight trellis
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I’m solving for v_bf

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As of now

zenith pollen
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like the 2 starting equations

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you can plug into something like wolframalpha to verify the algebra

final saddleBOT
#

@midnight trellis Has your question been resolved?

midnight trellis
#

missed a negative

#

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waxen jay
#

how is the derivative of $e^t=e^t$?

final saddleBOT
soft zealotBOT
long wraith
#

2 things

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First: d(e^t)/dt = e^t

waxen jay
#

Ok

long wraith
#

Second, e is define as the value such that when the rate of change of a^x = x itself

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When this happen

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a somehow = 2.718281..

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We call this special value e

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Thats all

#

So d(e^x)/dx = e^x

waxen jay
#

ok i see

#

thank you

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waxen jay
#

is it the derivative of the deriviative? lmao

tranquil pine
#

yes

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you can keep taking derivatives infinitely

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i mean eventually you'll hit 0

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doesn't mean you can't take the derivative of it

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lmao

waxen jay
#

ok thank you, haha

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good to know

fathom walrus
#

@waxen jay if f(x) = -7, find f’’’’(x)

waxen jay
#

0?

fathom walrus
#

yes

waxen jay
#

yeye, cause the deriviative of -7 is 0 and the deriviative of 0 is 0

fathom walrus
#

if f(x) = e^x, find f^(1000000)(x)

tranquil pine
#

oh yeah

fathom walrus
#

@waxen jay

waxen jay
tranquil pine
#

forgot abt e^x and the sin and cos functions

fathom walrus
#

correct

tulip coyote
tranquil pine
#

yup

fathom walrus
tranquil pine
#

you can still take them infinitely tho

fathom walrus
#

are there more functions for which lim n-> inf f^(n)(x) = 0 or lim n -> inf f^(n)(x) != 0?

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@tulip coyote

tranquil pine
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there's by extension ae^x

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and e^-x will alternate between -e^-x and e^-x

tulip coyote
fathom walrus
#

no im saying like

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how many functions exist such that they fulfill that property 1

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compared to the number of functions that fulfill the second property

tranquil pine
#

don't all functions eventually bottom out to some repeating pattern

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well ig not e^ax

waxen jay
#

would it be correct to say if i take the derivative of e^x an infinite amount of times, it will always be e^x

fathom walrus
#

are there more functions that satisfy lim n-> inf f^(n)(x) = 0 or more functions that satisfy lim n -> inf f^(n)(x) != 0? Or do they have the same cardinality? @tulip coyote this is what i meant, sorry its badly worded

waxen jay
#

ok thanks guys

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heavy tundra
#

Need help please

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@heavy tundra Has your question been resolved?

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waxen jay
#

Do I need the product rule to find the derivative for $-2x^4\sqrt{x}$

soft zealotBOT
rustic sandal
#

no you do not

waxen jay
#

why?

signal shell
#

What is sqrt(x)?

waxen jay
#

x^1/2

rustic sandal
#

you can rewrite $\sqrt(x)$ as $x^{\frac{1}{2}}$

soft zealotBOT
#

Brennenberg

waxen jay
#

but if two things are multiplying, you need the product rule dont you?

#

such as $-2x^4 \cdot \sqrt{x}$?

soft zealotBOT
waxen jay
#

isnt the first part f(x) and the second part g(x)

rustic sandal
#

you can also do that

#

yes

signal shell
#

You can definitely use product rule but you don’t strictly need it ^

waxen jay
#

ok i see, thank you

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snow temple
#

Hey! Just wondering what the variable “k” is in this equation

snow temple
#

And how we would find the half life based on the polynomial

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#

@snow temple Has your question been resolved?

zenith pollen
#

idk why there's a polynomial in this question

snow temple
#

What the heck

#

Okay thank you

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wind bough
#

I tried using the pythagorean theorem to solve this and ended up with 40.5(sqr3) and i dont know if i did something wrong or if i am missing a step or if im not even supposed to use the pythagorean theorem 😭 help please

magic rampart
#

cant use pythagoras

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not a right angled triangle

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use area of hexagon

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formula

wind bough
#

the only explanation i was provided for this was a hexagon inscribed in a circle

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i couldnt find the formula

magic rampart
#

regular hexagon yes

magic rampart
wind bough
magic rampart
#

yes

wind bough
#

okay, thank you very much 🙂

magic rampart
#

this works too simplifying it will give the area of a hexagon formula though

magic rampart
wind bough
#

i did have one more thing i was confused on if you dont mind, i think its just because they dont organize the formulas well and i cant find them 😭

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how do i find the area of a pentagon or hexagon from the apothem?

magic rampart
#

what's the apothem

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is that the centre of the shape

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oh

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line drawn to midpoint from the side

wind bough
#

yes

magic rampart
#

yeah so with the hexagon formula for example

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do u know the formula for an equilateral triangle

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a regular hexagon can be divided into 6 equilateral triangles

wind bough
magic rampart
#

yes that

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u have 6 equilateral triangles

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wtf

soft zealotBOT
#

taro

so its simplify \$\frac{6\sqrt{3}}{4}$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.49 so its simplify \$\frac{6\sqrt{3}}{4}
                                          $
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.

LaTeX Font Info:    Trying to load font information for OT1+lmr on input line 4
9.
(/usr/local/texlive/2023/texmf-dist/tex/latex/lm/ot1lmr.fd```
magic rampart
#

so its simplify $\frac{6\sqrt{3}}{4}}a^2$

soft zealotBOT
#

taro
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

magic rampart
#

ok give me a sec

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$\frac{6\sqrt{3}}{4} \cdot a^2$

soft zealotBOT
magic rampart
#

then u reduce that

#

$\frac{3\sqrt{3}}{2} \cdot a^2$

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which is the formula for area of a hexagon

soft zealotBOT
magic rampart
#

simply put, its the area of an equilateral triangle * 6

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beacuse you have 6 equilateral triangles in the hexagon

wind bough
#

ohh

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but for the pentagon would it no longer be the equalateral

magic rampart
#

for a pengaton the area formula i think is

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ap/2

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where a is the apothem

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and p is the perimeter

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i dont think its possible to work out the area of a pentagon with just the apothem

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since as you said if u were to cut it into triangles they wouldnt be equilateral

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it would be isoceles

wind bough
#

thats all they give me 😭

magic rampart
#

a stop sign has 8 sides though

wind bough
#

ohh

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so iot would be like the hexagon but *8 right?

magic rampart
#

hold on give me a moment

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i think youd need trig to solve this

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hmmm ok @wind bough do u know simple trig?

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i cant think of an easier way to solve this with just the apothem

wind bough
#

yes a little but i may need to be reminded i havent done it in like 6 months

magic rampart
#

alr

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so the way we're gonna do it

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is using the ap/2 forumla

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but we need to find the perimeter

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we're given the apothem

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which is 39.5

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yes?

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ok wait im ac gonna redraw that give me a second

magic rampart
wind bough
magic rampart
#

does that diagram somewhat make sense

wind bough
#

yes it does

magic rampart
#

okay

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knowing that all sides of the octagon are equal

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do u think theres a way we could figure out what that angle is

wind bough
#

do we use tanjent

magic rampart
#

if you had this for example

magic rampart
#

each triangle is the same

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and since those angles add up to 360 (its a revolution) and each angle is the same

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u can work out what each angle is equal to

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which is?

wind bough
#

45

magic rampart
#

yes

magic rampart
#

what would this angle be

wind bough
#

would it not be 45? I'm sorry im confused

magic rampart
#

the isoceles triangle (in the photo angle O) overall is 45 degrees

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but in our diagram

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ours is cut in half

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to make a right angled triangle

wind bough
#

so it would be 22.5?

magic rampart
#

yes

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almost there

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now

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we have the angle

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we have adjacent

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and we're looking for opposite

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which means we're using which trig function?

wind bough
#

tan

magic rampart
#

yep

#

so setup ur equation and solve for x

wind bough
#

i forgot how to set up the equation 😰

magic rampart
#

tan theta = o/a

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whats our angle

wind bough
#

22.5

magic rampart
#

whats our o and a

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tan22.5 = o/a

wind bough
#

ohh

magic rampart
#

then isolate x

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it should look like tan22.5 = x/39.5

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then bring 39.5 over

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x = ?

wind bough
#

when i bring 39.5 over am i not supposed to subtract it

magic rampart
#

multiply

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because its x divided by 39.5

wind bough
#

ohh

magic rampart
#

so u gotta do the reverse which is multiply by 39.5

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x = ?

wind bough
#

tan888.75

magic rampart
#

nono

#

ur doing 39.5 * tan(22.5)

wind bough
#

ohh

magic rampart
#

so put that into ur calc

wind bough
#

16.36

magic rampart
#

39.5 * tan(22.5) isnt the same as tan(22.5 * 39.5)

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okay so u found x

magic rampart
#

so the side length is 2 * 16.36

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= 31.72

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which is ur side length

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now the formula for area is ap/2

#

again where a is apothem

#

and p is perimeter