#help-36
1 messages · Page 118 of 1
start with
$$\sqrt{33-18\sqrt{2}} = a\sqrt{3} = b\sqrt{6}$$
then square both sides
$$\underbrace{(\sqrt{33-18\sqrt{2}})^2}{33- 18\sqrt{2}} = \underbrace{( a\sqrt{3} = b\sqrt{6})^2}{\text{expand this}}$$
ℝαμΩℕωⅤ
no need to introduce x at all
i get 3a^2 + 6b^2 + 6ab sqrt 2
whoops just realised i typoed a = instead of a +
yea i notice that
then equate the rational and irrational components
not quite
the irrational part on the left side is
**-**18sqrt(2)
not just 18sqrt(2)
due to how squaring works, the work on the left side isn't really affected
yes
my a = 81 and 4 which is accepted ?
that seems way too high
,rotate
that won't lead to a being 81 or 4
ouh
@craggy bane Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
\
how they get 2root3
blud its a cubic
No, you find speed with derivative
Then you plug in 2 sqrt3
he's asking how they determined t = 2sqrt(3) to begin with
which part r u doing
b
Yeah, then quadratic
You dont equate the displacement to 20
u literally do
solution to 2x^3-24x = 0
is 2√3
one of the
solutions
No it doesnt
it does
plug in t = 0, you get x = 20, which is the initial displacement
the solution is wrong though:
if you plug in t = 2sqrt(3) you get x = 20, not x = 0
Yea thats because the initial position is x = 20, not x = 0
oh wait "initial position"
yea they should have set that equal to 20, not 0
it's wrong either way haha
that at least makes the problem tractable
so 2root 3 is correct
Closed by @delicate fiber
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
@faint locust Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hey there's an integration which am trying to do
send
hey
can anyone help me solve this integration
@silk ibex Hi Hayao Miyazaki
@silk ibex Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Closed by @rich forum
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Can someone tell what to do next after found a and b ?
I kinda confused it ain't work for √a - √b to become a√3 + b√6
continue from
p=9 or p=2
as mentioned yesterday the two lines you did after are incorrect
what do you recommed then ?
how did you get a= 81 or 4 from
p=9 or p=2
b = -3/a
solving higher degree eq ?
tell me the exact calculations you did and the reason you did them that got you from
p = 9 or p= 2
to
a = 81 or a=4
where did 81 come from
where did 4 come from
first a^2 then 9^2 = 81 same as 2^2 = 4
yea i squared
but why
to solve for a ?
note that in the first like
p = a^2
and if p = 9
that gets you the equation
a^2 = 9
oh wait i get wym
to get the possible values of a
that's what you should be solving
should be 3 and -1 instead
where -1 coming from
a = 3 , b = -3/a then b = -3/3 = -1
oh, ok
you should be clear in what you numbers represent
since you replied to a message involving a only
that implied that you got a=-1
,w (3sqrt(3)-sqrt(6))^2
looks good
owhhh
to be more rigorous, you should also ensure that your result
3sqrt(3)-sqrt(6)
is actually positive
you may need to consider the other case as well if its negative
as the solutions to a^2 = 9 are a=3 or a=-3
is that acceptable when sqrt(-3) ??
nah im just curious that how come sqrt (-3) too, since you have mention that other case where a = -3 or 3
wdym how come sqrt(-3) too
there is no sqrt(-3) anywhere here
where did taht come from
is this part of a different question?
nvm prb i still need to do more practice
let me more familiar with this topics
@craggy bane Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
can someone help me understand the part i circled and arrowed?
Meth
Because |a| = a when a >= 0, and -a when a <= 0, they're splitting it up so they can make use of those
Yk the definition of |x|?
yes but i dont understand why its a neccessary step
So this is integration
Which is the area under the curve
But |x| is a piecewise function
So you integrate one part of the function in its domain, and then the other in its domain
|x| = x when x >= 0
So for the case where the inside is greater than 0, you integrate the inside
|x| = -x for x < 0
so you integrate -ve of the inside when it is less than 0
Then you add the areas
ok so its less about something specific with absolute value and more about adding both areas together?
Yes
gotcha
Since its a piecewise function, you have to break up the integral
i get where 1 and 4 for the integral come from but where is the 3 from or why do we have it
We have to split up the function based on the values of x
so if it was |t -5| the number would just be 5 instead?
The function $f(t) = t-3$ is less than 0 when t < 3, and greater when t >= 0
math X meth ✓
Kinda
It would depend on the limits of integration
But yes

i should probably know this but i forgot, do we use b or a in the integral to check if the result of |x| x, x>= 0 or |x| = -x, x < 0
@violet mountain Has your question been resolved?
Closed by @violet mountain
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
How can we show 2^(n-1) + 2^(n-2) + ... + 4 + 2 + 1 <= 2^n + n by induction?
Base n=1 is good, and we assume the above, but now what? Inequality is less familiar to me.
You'd then have ${\color{green} 1 + 2 + 4 + \ldots + 2^{n - 1} } + 2^n$ and want to show somehow that this is at most $2^{n + 1} + (n + 1)$
@tulip coyote
How can we replace it when we have an inequality? I only know how to replace it when we have an equality, not an inequality.
Similar to equalities: you know e.g. that if you had c <= d, that c + p <= d + p (similar for reversed or strict inequalities)
Thoughts on my proof?
<= 2^k + 2^k + k
<= 2^(k+1) + k
<= 2^(k+1) + (k+1) ∎
that's it, yep! the last line basically using that 0 < 1 after all haha
@old hornet Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
1+1
<@&268886789983436800>
.close
Closed by @sturdy ocean
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
AD= BC
BD =CD
Angle DBC = ANGLE DCB = 20°
find x
I have solved it a bit
but im now confused
i need to find angle x
but i havent found angle dac
My first instinct is to place triangle BDC over triangle ADC such that BC coincides with AD and BD coincides with DC
alternatively you can trig bash
🤷♂️
can you teach me both ?
well there isn't rlly any specific concept to teach here
it's just an idea
let BD=DC=1 without loss of generality, then you can get BC using basic trig
then just bash the living daylights out of the law of sines
if we place the triangle bdc such that ad is common line
How do we find the angles in red ?
you can use external angle theorem for triangle adc
that would give me angle dac + x = 40
yea and you can find angle dac using sum of angles in triangle adc
you will find angle adc in terms of x and then equate it in that equation
I meant like this [redacted, this is wrong]
oh ok
we can apply alternative angle propert y
since
now since bb' || bc
@loud sundial @fallen jasper
someone did the question. can you confirm if its correct
https://cdn.discordapp.com/attachments/1230158901555757149/1230551105461817446/rn_image_picker_lib_temp_ec2aa4d1-49df-447b-b51c-17c6ed0bf877-2.jpg?ex=6633bb06&is=66214606&hm=18619de4d804d16d74cc4388578e1d6feeaa5d27c4ef0a8c821c9d73684d3d71&
i dont understand how they got 60 and 80 degrees
yeah that's fine
the 60 degree angle in the left triangle comes from the fact you have two equal sides (B'C and B'D')
and a 60 deg angle in between
angle B'D'C' = angle BB'C = 140 deg
angle B'D'C = 60
so CDC' = 80
equilaterial triangle property ?
yeah that triangle is equilateral
but how are we so sure that D'C =DC =DD'
we just constructed two a triangle and joined the points together
maybe D'C is line bisector , thats why ?
These two sides are clearly equal
The third side wouldn’t necessarily be equal to those two
But the fact that there’s a 60 degree angle in between makes that the case
B/c the other two angles:
- are equal
- add to 120 deg
Meaning they’re both 60 deg -> triangle is equilateral
what about 80 ?
.
exterior angle property ?
These two are both 140
which property tells us that ?
You copied the same triangle over…
So the angles will be the same
thanks @loud sundial
understood it
i have one more question
should i send the ss
Yeah
^translation: O centered half circle, AOBC is a square. What is the angle DEA
@tranquil pine Has your question been resolved?
.close
Closed by @shrewd flume
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hello. How come that exponential functions can be inverted into logarithmic functions? their range is not equal to all real numbers, so it sdhouldnt be inversible. right?
did you mean domain? the domain of $\sqrt x$ is also not that of $x^2$
b
no, I mean the range
the range of an exponential functions is restricted
oh mb lol
the range is (0, infinity)
you mean if y=2^x and then the inverse is y=log_2 (x)
the range of 2^x is all the positives
thats also the domain of logs, no issue
and the domain of ln is (0, infinity)
in order for a function to be resversible
one of the conditions is that the range must be all real numbers
in spanish the name is
sobreyectiva
thats not a condition for something to be reversible, it just has to be a one to one function
what ive been taught is this
"To make a function reversible, it must be injective and surjective. In other words, it must be bijective."
exponential functions arent surjectibe
The exponential function is not invertible as a function from R to R, but it is invertible as a function from R to (0,infty)
Under the definition you gave
okay getting somewhere
how can I restrict a function to reverse it
it seems arbitrary
what are the steps
does it also mean that I must limit the range of a logarithmic function?
You want to restrict it so that it becomes surjective on the domain
wow so many helpers
And monotonic as well
Exponential is bijective under certain conditions
You don't need to since the logarithmic function has range equal to R
You could if you wanted to
because it is
like sqrt(x) earlier, i think it makes sense to say that we always pick the positive solution
but ultimately it is arbitrary
what are the steps
how do I restrict the range
lets say that I am asked to find the inverse of the following function:\
f(x)=(5 to the power of x+3) - 2
how would you do it
that's just $x=\log_{5}\left(y+2\right)-3$
mathematicians have already decided that the range on ln should be restricted to (0, infinity)
b
it's not really something you decide yourself
It's bijective on ]-2, +inf[ that's your domain when you Can have an inverse
^
i forgot to say that because you use ln(y+2), you should note that the range is now (-2, infinity)
@arctic forge Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
brain fart, i cant find numbers for 245
i know 9 works as 2 log base7 3
but what terms include 3 and 5 to get 245 ;-;
this is what i tried the first time and realized i couldnt use 7
I think they want you to evaluate log7(7)...
the base is the same as its argument
which means...?
oh.
would just equal the 2 if im interpreting what you're saying
how tf did that work
guessing it wouldve worked for this as well with 2 log base 2
welp now i know. thanks
.close
Closed by @raven obsidian
Use .reopen if this was a mistake.
.reopen
✅
what
ln 1 -> ln e 1 = 0, e^0 = 1
sqrt e = blah blah
division of 0 by any number = 0 no?
$\frac{1}{\sqrt{e}} = e^{\frac{-1}{2}}$
Azyrashacorki
oh hold on, let me think that through
would = -1/2 because ln and e cancel out
i see
wait where did the -1 come from? qoutient property?
im trying to expand it on paper
1/x = x^{-1}
Closed by @raven obsidian
Use .reopen if this was a mistake.
do all log functions have their range equal to R
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
f is continuous on the domain [0, 2]. f(0) = 0 and f(2) = 4. does there exist some value c (in the domain of course), such that f(c) = c^3?
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
yeah nonzero
<@&286206848099549185> anyone reckon they could come up with a solution and reasoning ?
what's the question again?
f is continuous on the domain [0, 2]. f(0) = 0 and f(2) = 4. does there exist some value c (in the domain of course), such that f(c) = c^3?
c=1
how do you know?
The domain is inclusive
also like
It’s a random function right
What if my function was literally f(x) = x^3
Then for all values in the domain wouldn’t c be any value or something
it is random but f(2) = 4 so it cant be x cubed
Every value from 0 to 2, inclusive. Now, just think of a number that when cubed, is equal to itself. There are only two numbers like this: 0 and 1
@shadow tinsel this help?
the condition f(c) = c^3 just means that a point (c, c^3) exists on the function
c doesnt have to equal c^3
read the question
my bad I'm not wearing my glasses
Intermediate value theorem
So basically
Let's get a function, g(x) = x^3
you need a value in the interval [0, 2] where f(x) = g(x)
aka an intersection point
nonzero
according to the intermediate value theorem, if g(x) takes on all the values between g(0)=0^3 and g(2)=2^3=8.
stated up here mb
there must be one value, x, in [0,2], such that g(x) will have a value between 0 and 8, which is the range of this function
Am i misunderstanding something?
it is a criteria, is there a non-zero value of c i.e (0, 2]
do you need a specific number?
or just reasoning as to whether or not that number exists
what did I say that was incorrect?
how can f(x) be x^3/2 when f(2) = 4?
he probably means (x^3)/2
not x^(3/2)
ohhh yeah ur right
so the answer is there does not exist a number c such that f(c) = c^3?
due to a counterexample being sufficient to prove its false
yeah the function isnt specified f is just every function that goes thru (0,0) and (2,4), so sometimes f(c)=c^3 and sometimes its not
but the answer is still a general no?
.close
Closed by @shadow tinsel
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how would i simplify this?
ive made arctanh into arcsinh/arccosh but where to from there?
or is it a different way entirely?
@peak kernel Has your question been resolved?
You could try to use the formula for arctanh
With logarithms
And then use the formula for sinh with exponents to cancel them
Also I don’t believe that arctanh=arcsinh/arccosh
@peak kernel Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
If I have log base 2 of x = 3
Closed by @whole pecan
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
is there a way to solve this limit without fully facotring the denominator cuz it would be too long
Why are you factoring?
how do u do it then
If the denominator is going to 0
...
This limit is just a limit of a fraction so you look at the top part : what is its limit ?
and same for the bottom part
You only have to do fancy stuff if it's a special form like 0/0 or infinity/infinity
But here it is not the case
ohh okay
also, is the vertical asymptote -3 and 3 in this question since it's a square number?
yes both -3 and 3 cancel the denominator so they will be vertical asymptotes
alright thank you
@earnest yew Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
what type of function is a floor / ceil
@tranquil pine Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
i dont understand why if A is invertible matrix then its row equivalent to matrix I
and does it go both ways too ?
as if I is row equivalent to A that means A is invertible matrix ?
If it's invertible, the equation Ax = b has a unique solution, so in particular when you row reduce it there has to be n pivots. The matrix is nxn, so n pivots means exactly that the result is the identity.
But you can think of it in terms of row operations as well. Row equivalence of A to X means that you have elementary row operation matrices such that En ... E2 E1 A = X. Then if A is invertible, we can RREF it to some matrix that is also invertible, but the resulting matrix is already row reduced, and since it's invertible it has to have n pivots, i.e. it's the identity.
now wait i didnt rlly understand everything u said since im still learning all that but
i understood that if A is invertible matrix
that means it has only on solution
if its not
then it has either 0 solutions or infinite
so wait
A is our matrix
x is the thing
this
If A is invertible, then the equation Ax = b has a unique solution. For any b
The point is, you can RREF it, and the only way it has a unique solution for any b is that the RREF has n pivots.
But if the RREF has n pivots, it has to be the identity
ok so if the RREF has no row that is all 0 and A belongs to Mij(R) (i=j) that means it for sure have one solution
and thats why to find out the invertible A we do this A=I and then we change their places
like
[A|I]
then if we switch their places we get the invertible A
and thats why if A is row equivalent to I then its invertible
right ?
Yeah exactly.
It's like that method of finding inverses you've probably seen where you rref [A | I] and the right side becomes the invese.
Then you can see that the A and Ainv are both row equiv. to I
Closed by @wind needle
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hello, I need help with my homework I feel like Im doing something wrong
@alpine ferry Has your question been resolved?
<@&286206848099549185>
@alpine ferry Has your question been resolved?
<@&286206848099549185>
@alpine ferry Has your question been resolved?
whats the qeustion?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
ok so there are 5 calcul like this on but i understand nothing realy nothing so if someone can explain me one calcul to do the rest
you know the formula?
$$
(a+b)^2
$$
notwish
?
i dont know this one
well there is a formula
$$
(a+b)^2 = a^2 + 2ab + b^2
$$
notwish
this follows same pattern
$$ (10 + _)^2 = _ + _ + 16a^2 $$
notwish
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
ok but what im censed to put in the calcul
so now see we got 16a^2
we can convert it to (4a)^2
right?
mmmmhhh i thing yes
so now compare this pattern
to get (4a)^2
we need 4a in the left hand side tooo
so the first box will have ?
(10+4a)^2 ?
yesss
now use this formula and find the rest
it is (10+4a)^2=4a^2+10+16a^2 ?
no-
i suggest showing more work
or taking more steps
(10+4a)^2=10^2+4a^2=16a^2
which are equal?
so the middle one should be 2 x 10 x 4a
see this
using $a$ ambiguously probably isnt helping
b
$(x + y)^2 = x^2 + 2xy + y^2, x = 10, y = 4a$
b
im lost
here just watch this tbh https://www.youtube.com/watch?v=4OhmtEDCFAA
How to Expand a Binomial by using a Special Formula: (a + b)^2 = a^2 + 2ab + b^2
If you enjoyed this video please consider liking, sharing, and subscribing.
Udemy Courses Via My Website: https://mathsorcerer.com
My FaceBook Page: https://www.facebook.com/themathsorcerer
There are several ways that you can help support my channel:)
Consider ...
right
@sleek quartz hey can you come to #help-7|zen1thxyz
so if i understand it good the result is
(10+4a)^2=10^2+40a+16a^2
b
yeah you can just do 100 lmao
b
Closed by @stone rivet
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
guys
$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^n}$?
y0shi
do you remember what the definition of e was?
in the denominator
oh
$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^{2n}}$
y0shi
no (1+1/n)n^2
is the entire thing raised to the second power or only n
its rasied to n^2
no parenthesis?
nope
what definition
$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^{n^n}}$
i know several definitions
$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^{n^2}}$
rafilou2003
not sure this would work well, depending on what binomial approximation you used
I think first take the ln
(natural log)
factor nicely
(1-n)e^n
i got this after using it
is it valid
oh no it doesn't work at all
as i can put 1/n = h where h tends to 0
why
if your h is 1/n then when h tends to 0, ALL of the n tend to +infinity at the same time
you can't select a few well chosen n to tend to infinity first
Rewrite clearly what you tried to do
wouldn't it mean the same thing h tends to 0 or n tends to infinity
in this case
as we are only talking about +ve infinity here
e^n ( 1 + 1/n)^-n^2
now i applied binomial approximation
as 1/n would tend to 0
So you used $(1+x)^\alpha$ as $x\to 0$ right?
rafilou2003
yes
That's when alpha is CONSTANT
anyways
so what were you suggesting
take the natural log
you wanted a suggestion? Or an explanation of the whole solution?
do you mean i write it again in the exponential form
like
take ln
then
apply the limits
well yeah you have lim (...) and you could write it as lim (e^ln(...))
yep
now factor the exponent nicely
and you can use expansion of ln. Be careful to include ENOUGH terms
hmm true
i can use it
what is it ?
lol
i dont remember
and i dont wanna work out all derivatives to compute it rn
yep
so you should easily figure out how to get ln(1+1/n) from the expansion I gave you
2 terms will do ?
See what happens when you get two terms
yes
hey i wanted an advice
should i solve less problems and learn further topics
or solve tons of problems on the topics i learn then move on to the next ones
i dont really know how much to solve
That really depends on how fast of a learner you are, and how you learn the quickest
Try everything and see whether you understand topics better with a lot of exercises or not
whats better
also how do i even know if i learned it completely or not
i use book so i don't really get an idea about it
That's up to your intuition, it builds up over time
you're free to go learn other topics and go back to that one at any time, and compare whether you know more about some topics than others
you mean i can learn multivariable calculus without practicising tons of integrals
in single variable calculus
If you feel like you're ready then attempt it
and if you don't or feel like you're lost while learning, practice more
from where do you know a good source
I have no good sources for you I'm afraid
hmm never tried this ive learned things linearly
okay
thanks
.close
Closed by @raw grotto
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
is there a formula for this?
rewrite as a geoseries
maybe
yeah
the denominator factors
oh but it's not a perf square
yeah
how
tihs doesnt seem like common ratio
oh you said canno tnvm
limit comparison test
how do you find the sum
no idea
ok
doesn’t seem like something you should find the sum for honestly
factorise denominator
then pfd
partial fraction decomposition
it'll be telescoping
Telescoping series
oh then that’s even better
🔭
look at first 2 terms
@waxen pine Has your question been resolved?
okay i did psf
sorry was doing smth else
yeah
i see the telescoping
i think thats the name
thats crazy
its like magic
-1 +3 makes it connect
wait
it doesnt
becuase the psf the tops are differnet
did i do my pfd
wrong
found the mistake
ty for the help guys
.close
Closed by @waxen pine
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I rearranged both for sint and cost
Addition formula for the y parametic
Then subbed in the x parametic
Then equated sin^2 t + cos^2t
Then switched it for 1 and cancelled down
It didn't get me the answer
@tranquil pine Has your question been resolved?
<@&286206848099549185>
@mahdi_gd hii
?
.close
Closed by @bitter aurora
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hello! Does anyone how to use Mathematica 6.0 with Decarta2D? I have an exercise to solve for tomorrow and I don't know how.
Thank you. Imma post it soon.
The converse of Ceva's theorem states the following: Let ABC be a triangle, and let points A' lie on (BC), B' lie on (CA), and C' lie on (AB). If: (A' B | A' C) * (B'C|B'A)*(C'A|C'B)=1, then the lines AA', BB', CC' are concurrent.
I have also the problem solved, i need it in Mathematica
@real reef Has your question been resolved?
@real reef Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
why did the base change to 2 on step 2? i thought the change base formula stated: log (base b) of x = log (base a) of x / log (base a) of b
that was on google's calculator
Yes it does state that
They just chose a to be 2
Has nothing to do with the 2 as the parameter
could i do the same even though the original base is 8?
Yeah, the original base doesn't matter
because i see thjey used it to make the top of the fraction to equal 1 in the following step
oh
The new base can be any number
?
so it's my choice to make it into whatever number that works for me?
odd... i guess that makes sense?
can you clearly say your question ?
here
i was just wondering why the base went from 8 to 2
you got the answer maybe
without prior knowledge of that, it seems like the method isnt useful if i cant envision the rest of the steps
But theres an easier way go compute your result
i figured i could also try inverse property
yeah that way i understand, thanks. just had to make sense of the other one but oh well
.close
Closed by @raven obsidian
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Is ABCD a square? If so, 3D Pythagorean theorem.
yea ik pythageoream
but
i duno
whixh ones to take
like which linea
bec bh
i duno
The height is kinda obvious
For the two other sides, assuming ABCD is a square, it doesn’t matter
Since all the sides are the same anyway
.close
Closed by @jolly vector
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
stuck on the graphing part
What exactly do you need help with the graphing
If it’s not asking to label everything on the graph, then I think simply graph the ellipse
It is
(x+3)^2 means the x goes from 0 to -3, and (y-6)^2 means they goes from 0 to 6
Also, the distance from the vertex to vertices and co-vertices is the square root of the numbers below the squared x and y
Rotate it 90 degrees
Yes
Np
how i close
.close
Closed by @potent lance
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hello, Im trying to do the Quine McCluskey method to simplify an expression and I was wondering if it can happen that you are eliminating more than one variable for example with 2 and 3 here I would only get wy, no?
@raven ember Has your question been resolved?
<@&286206848099549185>
@raven ember Has your question been resolved?
@raven ember Has your question been resolved?
@raven ember Has your question been resolved?
.close
Closed by @raven ember
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hello how to do this question
Also is the determinant of a matrix equal to the scalar triple product of its rows?
Like somebody has said that to me
invertible is matrix that has an inverse ryt
what is ryt
yes
@plucky bridge Has your question been resolved?
Closed by @plucky bridge
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
please explain both the "addition" and the multiplication by 12
They are properties of the determinant
Do you have notes on the properties of determinants?
I’m asking you
Do you know what the definition of the determinant is?
just that if it's != 0 then the matrxi is invertible
i was absent
this is from the notes
I actually don’t know any good videos that explains determinant nicely
could you plz just can say the relevant things to solving exercises
i don't have to intuitvely understadn what determinants are
at least rn
It’s a sort of thing you can do to a matrix
It has some interesting properties
Notably, it’s linear in every row and column
And if you swap 2 rows the sign changes
If you imagine the 2 straight lines is a function that takes a bunch of column vectors in and returns a number
The first line where they merged the 2 determinants together they use linearity
wdym by using linearity
what exactly do you mean that it's linear in ever yrow and column
Just like how if A(x+y) = A(x) + A(y) this is linearity
It’s linear in its (first and only) entry
But say my function takes more than 1 input
i don't udnerstand what you mean
Have you not been studying linear algebra
for me linearity is y = mx + b
Do you know what a vector space is?
don't remember
but could you plz
just note all the things i need to know for solving problems
Do you know what a linear transformation is?
You should learn the theory first or it won’t make much sense
i dont have time
If you don’t have time to learn something you won’t be able to learn it
You don’t tell the IRS I didn’t file my taxes because I didn’t have time
just expalin this qwuickly pls
I can’t because you lack the background knowledge to understand the explanation
You’re asking how a plane flies without knowing any physics
There really isn’t much to say besides “it just does”
dude just explain ther ule
without saying why it works
like you have two determinants
when can you add them
and how do you do so?
i know how to compute determinants
<@&286206848099549185>
also what does D mean here
In linear algebra, a minor of a matrix A is the determinant of some smaller square matrix, cut down from A by removing one or more of its rows and columns. Minors obtained by removing just one row and one column from square matrices (first minors) are required for calculating matrix cofactors, which in turn are useful for computing both the dete...
ok so it's just a different notation
i'm familiarw ith it
@versed crater could you pls say how did they compute all these determinants so quickly?
you just look at it and do it in your head
3x3's are not too hard when it's all 1's and 0's
ok, when do you use this method andw hen gaussian elimination?
also is there any name for the above?
how do you solve stuff like
@remote island Has your question been resolved?
For the first question, let's try to simplify our systems
also, what does this ^-1 mean here
ok, how?
like wdym by simplify here?
It's thé inverse of the Matrix like if you multiply it by the original you get the identity
oh gotcha
Maybe for the transpose write the coefficients and try to solve the system
It's the same for the second
And I think for the third if you multiply both matrices you will get something maybe
it ought to be somethign else
this was before systems of equations
3rd what?
? Wdym
we didn't do systems of equatiosn before this problem
so the teachers wants you to solve it another way
For the third multiply both matrices and you'll get a diagonal matrices maybe which IS very easy
So what's your lesson
transpose is this, right?
but im not sure to what problems are you referring to with other questions
sorry my phone dead
no worries
but yh take transpost
Maybe I don't use thé right term I'm not english
just say what are you referring to
you just said "second" and "third"
second and third what
Of what you have send
how? idk what X is
i sent 4 pics
ok for the first, set the second term as A
3rd in order or thed one marked 3
XA*A^-1=XI=X
nothing below the above was solved
what's the point
When multiply by identity it do nothing
where did you get A^-1 from
A^-1 is A transpost
Here it's the case