#help-36

1 messages · Page 118 of 1

final tangle
#

there's no need to introduce x

#

start with
$$\sqrt{33-18\sqrt{2}} = a\sqrt{3} = b\sqrt{6}$$
then square both sides
$$\underbrace{(\sqrt{33-18\sqrt{2}})^2}{33- 18\sqrt{2}} = \underbrace{( a\sqrt{3} = b\sqrt{6})^2}{\text{expand this}}$$

soft zealotBOT
#

ℝαμΩℕωⅤ

final tangle
#

no need to introduce x at all

craggy bane
final tangle
#

whoops just realised i typoed a = instead of a +

craggy bane
final tangle
#

then equate the rational and irrational components

craggy bane
#

Sure this way ?

final tangle
#

not quite

#

the irrational part on the left side is
**-**18sqrt(2)
not just 18sqrt(2)

#

due to how squaring works, the work on the left side isn't really affected

craggy bane
#

yea i correction it

#

is still the same on left hand side 9/a^2

final tangle
#

yes

craggy bane
final tangle
#

that seems way too high

craggy bane
final tangle
#

,rotate

soft zealotBOT
final tangle
#

that won't lead to a being 81 or 4

craggy bane
#

ouh

final saddleBOT
#

@craggy bane Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

delicate fiber
final saddleBOT
delicate fiber
#

how they get 2root3

proud plover
#

probably

delicate fiber
#

blud its a cubic

proud plover
#

oh thats true

#

cubic formula

agile coral
#

No, you find speed with derivative

proud plover
#

oh yeah

#

quadratic formula

agile coral
#

Then you plug in 2 sqrt3

tiny gorge
#

he's asking how they determined t = 2sqrt(3) to begin with

agile coral
#

You don't need quadratic

#

It's given

delicate fiber
#

here is q

tiny gorge
#

i think that's the solution in the first screenshot

#

not the problem statement

proud plover
delicate fiber
#

b

agile coral
#

Yeah, then quadratic

proud plover
#

no

#

initial position is 20 meters

#

so equate the displacement function to 20

delicate fiber
#

O yea

#

Bruh the solution should be 2t^3 - 24t + 20 = 20 then

shadow tinsel
#

You dont equate the displacement to 20

tiny gorge
#

no, = 0 is correct

#

the +20 already encodes the displacement

proud plover
#

solution to 2x^3-24x = 0
is 2√3

#

one of the

#

solutions

delicate fiber
shadow tinsel
tiny gorge
#

plug in t = 0, you get x = 20, which is the initial displacement

#

the solution is wrong though:

#

if you plug in t = 2sqrt(3) you get x = 20, not x = 0

delicate fiber
tiny gorge
#

yea they should have set that equal to 20, not 0

#

it's wrong either way haha

#

that at least makes the problem tractable

delicate fiber
#

so 2root 3 is correct

tiny gorge
#

yea

#

they just wrote the equation wrong

delicate fiber
#

these solutions are so unreliable

#

.close

final saddleBOT
#
Channel closed

Closed by @delicate fiber

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

faint locust
final saddleBOT
#

@faint locust Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silk ibex
#

hey there's an integration which am trying to do

fathom walrus
#

send

silk ibex
#

hey
can anyone help me solve this integration

solar glade
#

IBP

#

What did you try?

tranquil pine
#

@silk ibex Hi Hayao Miyazaki

final saddleBOT
#

@silk ibex Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rich forum
final saddleBOT
rich forum
#

Can someone solve this ?

#

Oh I am sorry Ivan

#

.close

final saddleBOT
#
Channel closed

Closed by @rich forum

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

craggy bane
final saddleBOT
craggy bane
#

Can someone tell what to do next after found a and b ?

#

I kinda confused it ain't work for √a - √b to become a√3 + b√6

final tangle
#

continue from
p=9 or p=2
as mentioned yesterday the two lines you did after are incorrect

craggy bane
#

what do you recommed then ?

final tangle
#

how did you get a= 81 or 4 from

p=9 or p=2

craggy bane
final tangle
#

please read what i'm asking here

#

b is irrelevant to what i asked you

craggy bane
final tangle
#

tell me the exact calculations you did and the reason you did them that got you from
p = 9 or p= 2
to
a = 81 or a=4

#

where did 81 come from

#

where did 4 come from

craggy bane
final tangle
#

but a isn't 9

#

why are you squaring the 9

craggy bane
#

yea i squared

final tangle
#

but why

craggy bane
#

to solve for a ?

final tangle
#

note that in the first like
p = a^2

#

and if p = 9
that gets you the equation
a^2 = 9

craggy bane
#

oh wait i get wym

final tangle
#

to get the possible values of a
that's what you should be solving

craggy bane
final tangle
#

where -1 coming from

craggy bane
#

a = 3 , b = -3/a then b = -3/3 = -1

final tangle
#

oh, ok

#

you should be clear in what you numbers represent

#

since you replied to a message involving a only
that implied that you got a=-1

#

,w (3sqrt(3)-sqrt(6))^2

final tangle
#

looks good

craggy bane
#

owhhh

final tangle
#

to be more rigorous, you should also ensure that your result
3sqrt(3)-sqrt(6)
is actually positive
you may need to consider the other case as well if its negative
as the solutions to a^2 = 9 are a=3 or a=-3

craggy bane
final tangle
#

you shouldn't have any sqrt(-3) here

#

where's that coming from

craggy bane
final tangle
#

wdym how come sqrt(-3) too

#

there is no sqrt(-3) anywhere here

#

where did taht come from

#

is this part of a different question?

craggy bane
#

let me more familiar with this topics

final saddleBOT
#

@craggy bane Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

violet mountain
#

can someone help me understand the part i circled and arrowed?

autumn oracle
#

Meth

tulip coyote
#

Because |a| = a when a >= 0, and -a when a <= 0, they're splitting it up so they can make use of those

autumn oracle
violet mountain
autumn oracle
#

Which is the area under the curve

#

But |x| is a piecewise function

#

So you integrate one part of the function in its domain, and then the other in its domain

#

|x| = x when x >= 0

#

So for the case where the inside is greater than 0, you integrate the inside

#

|x| = -x for x < 0
so you integrate -ve of the inside when it is less than 0

#

Then you add the areas

violet mountain
#

ok so its less about something specific with absolute value and more about adding both areas together?

autumn oracle
#

Yes

violet mountain
#

gotcha

autumn oracle
#

Since its a piecewise function, you have to break up the integral

violet mountain
#

i get where 1 and 4 for the integral come from but where is the 3 from or why do we have it

autumn oracle
violet mountain
#

so if it was |t -5| the number would just be 5 instead?

autumn oracle
#

The function $f(t) = t-3$ is less than 0 when t < 3, and greater when t >= 0

soft zealotBOT
#

math X meth ✓

autumn oracle
#

It would depend on the limits of integration

#

But yes

violet mountain
autumn oracle
#

Try to define |t-3|

#

|x| = x, x>=0; |x| = -x, x < 0

#

Try to apply it to t-3

violet mountain
#

i should probably know this but i forgot, do we use b or a in the integral to check if the result of |x| x, x>= 0 or |x| = -x, x < 0

final saddleBOT
#

@violet mountain Has your question been resolved?

#
Channel closed

Closed by @violet mountain

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

old hornet
#

How can we show 2^(n-1) + 2^(n-2) + ... + 4 + 2 + 1 <= 2^n + n by induction?

Base n=1 is good, and we assume the above, but now what? Inequality is less familiar to me.

tulip coyote
#

You'd then have ${\color{green} 1 + 2 + 4 + \ldots + 2^{n - 1} } + 2^n$ and want to show somehow that this is at most $2^{n + 1} + (n + 1)$

soft zealotBOT
#

@tulip coyote

old hornet
tulip coyote
old hornet
tulip coyote
final saddleBOT
#

@old hornet Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real ridge
#

1+1

final saddleBOT
vivid walrus
#

<@&268886789983436800>

sturdy ocean
#

.close

final saddleBOT
#
Channel closed

Closed by @sturdy ocean

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

loud sundial
#

My first instinct is to place triangle BDC over triangle ADC such that BC coincides with AD and BD coincides with DC

#

alternatively you can trig bash

#

🤷‍♂️

tranquil pine
#

can you teach me both ?

loud sundial
#

it's just an idea

loud sundial
tranquil pine
#

if we place the triangle bdc such that ad is common line

#

How do we find the angles in red ?

fallen jasper
#

you can use external angle theorem for triangle adc

tranquil pine
fallen jasper
#

you will find angle adc in terms of x and then equate it in that equation

loud sundial
#

I meant like this [redacted, this is wrong]

tranquil pine
#

oh ok

tranquil pine
# loud sundial

we can apply alternative angle propert y
since
now since bb' || bc

#

i dont understand how they got 60 and 80 degrees

loud sundial
#

the 60 degree angle in the left triangle comes from the fact you have two equal sides (B'C and B'D')

#

and a 60 deg angle in between

#

angle B'D'C' = angle BB'C = 140 deg

#

angle B'D'C = 60

#

so CDC' = 80

tranquil pine
#

equilaterial triangle property ?

loud sundial
tranquil pine
#

we just constructed two a triangle and joined the points together

#

maybe D'C is line bisector , thats why ?

loud sundial
#

These two sides are clearly equal

#

The third side wouldn’t necessarily be equal to those two

#

But the fact that there’s a 60 degree angle in between makes that the case

#

B/c the other two angles:

  • are equal
  • add to 120 deg
tranquil pine
#

sAS criterion?

#

oh ok

loud sundial
tranquil pine
#

what about 80 ?

loud sundial
tranquil pine
tranquil pine
#

which property tells us that ?

loud sundial
#

So the angles will be the same

tranquil pine
#

and what was the 50 deg?

tranquil pine
#

thanks @loud sundial

#

understood it

#

i have one more question

#

should i send the ss

loud sundial
#

Yeah

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

.close

final saddleBOT
#
Channel closed

Closed by @shrewd flume

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

arctic forge
#

hello. How come that exponential functions can be inverted into logarithmic functions? their range is not equal to all real numbers, so it sdhouldnt be inversible. right?

sleek quartz
#

did you mean domain? the domain of $\sqrt x$ is also not that of $x^2$

soft zealotBOT
arctic forge
#

the range of an exponential functions is restricted

sleek quartz
#

oh mb lol

arctic forge
#

this one for instance

sleek quartz
#

the range is (0, infinity)

arctic forge
#

yes

#

but

warm ether
#

you mean if y=2^x and then the inverse is y=log_2 (x)

the range of 2^x is all the positives
thats also the domain of logs, no issue

sleek quartz
#

and the domain of ln is (0, infinity)

arctic forge
#

in order for a function to be resversible

#

one of the conditions is that the range must be all real numbers

#

in spanish the name is

#

sobreyectiva

warm ether
#

thats not a condition for something to be reversible, it just has to be a one to one function

arctic forge
#

what ive been taught is this

#

"To make a function reversible, it must be injective and surjective. In other words, it must be bijective."

warm ether
#

that is true

#

that doesnt mean the range has to be all of R

arctic forge
#

exponential functions arent surjectibe

trail hearth
#

The exponential function is not invertible as a function from R to R, but it is invertible as a function from R to (0,infty)

#

Under the definition you gave

arctic forge
#

how can I restrict a function to reverse it

#

it seems arbitrary

#

what are the steps

#

does it also mean that I must limit the range of a logarithmic function?

versed crater
#

You want to restrict it so that it becomes surjective on the domain

arctic forge
#

wow so many helpers

versed crater
#

And monotonic as well

midnight sparrow
#

Exponential is bijective under certain conditions

trail hearth
versed crater
#

You could if you wanted to

sleek quartz
#

like sqrt(x) earlier, i think it makes sense to say that we always pick the positive solution

#

but ultimately it is arbitrary

arctic forge
#

what are the steps

#

how do I restrict the range

#

lets say that I am asked to find the inverse of the following function:\

#

f(x)=(5 to the power of x+3) - 2

#

how would you do it

sleek quartz
#

that's just $x=\log_{5}\left(y+2\right)-3$
mathematicians have already decided that the range on ln should be restricted to (0, infinity)

soft zealotBOT
sleek quartz
#

it's not really something you decide yourself

midnight sparrow
#

It's bijective on ]-2, +inf[ that's your domain when you Can have an inverse

sleek quartz
#

^
i forgot to say that because you use ln(y+2), you should note that the range is now (-2, infinity)

final saddleBOT
#

@arctic forge Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

raven obsidian
#

brain fart, i cant find numbers for 245

final saddleBOT
raven obsidian
#

i know 9 works as 2 log base7 3

#

but what terms include 3 and 5 to get 245 ;-;

#

this is what i tried the first time and realized i couldnt use 7

tulip coyote
raven obsidian
#

que...

#

is it not like this previous problem

abstract bramble
#

which means...?

raven obsidian
#

oh.

raven obsidian
#

how tf did that work

raven obsidian
#

welp now i know. thanks

#

.close

final saddleBOT
#
Channel closed

Closed by @raven obsidian

Use .reopen if this was a mistake.

raven obsidian
#

.reopen

final saddleBOT
#

raven obsidian
#

ln 1 -> ln e 1 = 0, e^0 = 1

sqrt e = blah blah

division of 0 by any number = 0 no?

blissful meadow
#

$\frac{1}{\sqrt{e}} = e^{\frac{-1}{2}}$

soft zealotBOT
#

Azyrashacorki

blissful meadow
#

And ln(e) = 1

#

Does that help?

raven obsidian
#

oh hold on, let me think that through

#

would = -1/2 because ln and e cancel out

#

i see

raven obsidian
#

im trying to expand it on paper

blissful meadow
#

1/x = x^{-1}

raven obsidian
#

took me a bit but i think i get it now

#

thanks

#

.close

final saddleBOT
#
Channel closed

Closed by @raven obsidian

Use .reopen if this was a mistake.

arctic forge
#

do all log functions have their range equal to R

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shadow tinsel
#

f is continuous on the domain [0, 2]. f(0) = 0 and f(2) = 4. does there exist some value c (in the domain of course), such that f(c) = c^3?

dusk loom
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
shadow tinsel
#

1

grim nebula
#

c nonzero right

#

otherwise f(0) = 0^3

shadow tinsel
#

yeah nonzero

#

<@&286206848099549185> anyone reckon they could come up with a solution and reasoning ?

mental dragon
#

what's the question again?

shadow tinsel
#

f is continuous on the domain [0, 2]. f(0) = 0 and f(2) = 4. does there exist some value c (in the domain of course), such that f(c) = c^3?

foggy minnow
#

Yeah

#

like c=1

shadow tinsel
#

how do you know?

mental dragon
#

The domain is inclusive

foggy minnow
#

also like

#

It’s a random function right

#

What if my function was literally f(x) = x^3

#

Then for all values in the domain wouldn’t c be any value or something

shadow tinsel
mental dragon
#

Every value from 0 to 2, inclusive. Now, just think of a number that when cubed, is equal to itself. There are only two numbers like this: 0 and 1

foggy minnow
#

Ohhh u right

#

What about the sqrt function

#

wait that’s not square root bye

shadow tinsel
#

the condition f(c) = c^3 just means that a point (c, c^3) exists on the function

#

c doesnt have to equal c^3

mental dragon
#

what was the question? c = c^3 right?

#

or was it f(c) = c^3?

shadow tinsel
#

read the question

mental dragon
#

my bad I'm not wearing my glasses

mental dragon
#

So basically

#

Let's get a function, g(x) = x^3

#

you need a value in the interval [0, 2] where f(x) = g(x)

#

aka an intersection point

shadow tinsel
#

nonzero

mental dragon
#

according to the intermediate value theorem, if g(x) takes on all the values between g(0)=0^3 and g(2)=2^3=8.

shadow tinsel
mental dragon
#

there must be one value, x, in [0,2], such that g(x) will have a value between 0 and 8, which is the range of this function

#

Am i misunderstanding something?

shadow tinsel
#

it is a criteria, is there a non-zero value of c i.e (0, 2]

mental dragon
#

do you need a specific number?

#

or just reasoning as to whether or not that number exists

#

what did I say that was incorrect?

shadow tinsel
#

how can f(x) be x^3/2 when f(2) = 4?

mental dragon
#

not x^(3/2)

shadow tinsel
#

so the answer is there does not exist a number c such that f(c) = c^3?

#

due to a counterexample being sufficient to prove its false

#

yeah the function isnt specified f is just every function that goes thru (0,0) and (2,4), so sometimes f(c)=c^3 and sometimes its not

#

but the answer is still a general no?

#

.close

final saddleBOT
#
Channel closed

Closed by @shadow tinsel

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

peak kernel
#

how would i simplify this?

final saddleBOT
peak kernel
#

ive made arctanh into arcsinh/arccosh but where to from there?

#

or is it a different way entirely?

final saddleBOT
#

@peak kernel Has your question been resolved?

shadow minnow
#

With logarithms

#

And then use the formula for sinh with exponents to cancel them

#

Also I don’t believe that arctanh=arcsinh/arccosh

final saddleBOT
#

@peak kernel Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

whole pecan
#

If I have log base 2 of x = 3

final saddleBOT
whole pecan
#

I know 2^3 is 8

#

But can I do logx/log2 = 3

#

logx=3/log2

#

x=10^(3/log2)

fathom walrus
#

Logx/log2 = 3

#

logx = 3log2

#

10^(3log2) = x

#

3log2 not 3/log2

whole pecan
#

Wait nvm

#

Yea

#

I messed up

#

Ty

#

.close

final saddleBOT
#
Channel closed

Closed by @whole pecan

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

earnest yew
#

is there a way to solve this limit without fully facotring the denominator cuz it would be too long

agile coral
#

Why are you factoring?

earnest yew
agile coral
#

If the denominator is going to 0
...

mystic night
#

This limit is just a limit of a fraction so you look at the top part : what is its limit ?
and same for the bottom part
You only have to do fancy stuff if it's a special form like 0/0 or infinity/infinity
But here it is not the case

earnest yew
mystic night
#

yes both -3 and 3 cancel the denominator so they will be vertical asymptotes

final saddleBOT
#

@earnest yew Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tranquil pine
#

what type of function is a floor / ceil

final saddleBOT
#

@tranquil pine Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wind needle
#

i dont understand why if A is invertible matrix then its row equivalent to matrix I

wind needle
#

and does it go both ways too ?

#

as if I is row equivalent to A that means A is invertible matrix ?

blissful meadow
#

If it's invertible, the equation Ax = b has a unique solution, so in particular when you row reduce it there has to be n pivots. The matrix is nxn, so n pivots means exactly that the result is the identity.

#

But you can think of it in terms of row operations as well. Row equivalence of A to X means that you have elementary row operation matrices such that En ... E2 E1 A = X. Then if A is invertible, we can RREF it to some matrix that is also invertible, but the resulting matrix is already row reduced, and since it's invertible it has to have n pivots, i.e. it's the identity.

wind needle
#

now wait i didnt rlly understand everything u said since im still learning all that but

#

i understood that if A is invertible matrix

#

that means it has only on solution

#

if its not

#

then it has either 0 solutions or infinite

#

so wait

#

A is our matrix

#

x is the thing

#

this

blissful meadow
#

If A is invertible, then the equation Ax = b has a unique solution. For any b

#

The point is, you can RREF it, and the only way it has a unique solution for any b is that the RREF has n pivots.

#

But if the RREF has n pivots, it has to be the identity

wind needle
#

ok so if the RREF has no row that is all 0 and A belongs to Mij(R) (i=j) that means it for sure have one solution

#

and thats why to find out the invertible A we do this A=I and then we change their places

#

like

#

[A|I]

#

then if we switch their places we get the invertible A

#

and thats why if A is row equivalent to I then its invertible

#

right ?

blissful meadow
#

Yeah exactly.

#

It's like that method of finding inverses you've probably seen where you rref [A | I] and the right side becomes the invese.

#

Then you can see that the A and Ainv are both row equiv. to I

wind needle
#

oh ok tysm man

#

appreciate it

#

ur de best

#

.close

final saddleBOT
#
Channel closed

Closed by @wind needle

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine ferry
final saddleBOT
alpine ferry
#

hello, I need help with my homework I feel like Im doing something wrong

final saddleBOT
#

@alpine ferry Has your question been resolved?

alpine ferry
#

<@&286206848099549185>

alpine ferry
#

<@&286206848099549185> \

#

<@&286206848099549185>

final saddleBOT
#

@alpine ferry Has your question been resolved?

alpine ferry
#

<@&286206848099549185>

final saddleBOT
#

@alpine ferry Has your question been resolved?

digital steeple
#

whats the qeustion?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stone rivet
#

ok so there are 5 calcul like this on but i understand nothing realy nothing so if someone can explain me one calcul to do the rest

carmine current
#

$$
(a+b)^2
$$

soft zealotBOT
#

notwish

carmine current
#

?

stone rivet
#

i dont know this one

carmine current
#

$$
(a+b)^2 = a^2 + 2ab + b^2
$$

soft zealotBOT
#

notwish

carmine current
#

$$ (10 + _)^2 = _ + _ + 16a^2 $$

soft zealotBOT
#

notwish
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

stone rivet
#

ok but what im censed to put in the calcul

carmine current
#

we can convert it to (4a)^2

#

right?

stone rivet
#

mmmmhhh i thing yes

carmine current
#

to get (4a)^2

#

we need 4a in the left hand side tooo

#

so the first box will have ?

stone rivet
#

(10+4a)^2 ?

carmine current
carmine current
stone rivet
#

it is (10+4a)^2=4a^2+10+16a^2 ?

carmine current
sleek quartz
#

or taking more steps

carmine current
#

take 10 as a and 4a as b

#

then one by one

#

find the values

stone rivet
#

(10+4a)^2=10^2+4a^2=16a^2

carmine current
#

16a^2 is just (4a)^2

sleek quartz
carmine current
#

so the middle one should be 2 x 10 x 4a

sleek quartz
#

using $a$ ambiguously probably isnt helping

soft zealotBOT
sleek quartz
#

$(x + y)^2 = x^2 + 2xy + y^2, x = 10, y = 4a$

soft zealotBOT
stone rivet
#

im lost

sleek quartz
#

How to Expand a Binomial by using a Special Formula: (a + b)^2 = a^2 + 2ab + b^2

If you enjoyed this video please consider liking, sharing, and subscribing.

Udemy Courses Via My Website: https://mathsorcerer.com
My FaceBook Page: https://www.facebook.com/themathsorcerer

There are several ways that you can help support my channel:)

Consider ...

▶ Play video
carmine current
stone rivet
#

(10+4a)^2=10^2+40a+16a^2

sleek quartz
#

👍

#

where $10^2$ is just $100$ obviously

soft zealotBOT
stone rivet
#

so i write 100?

#

cuz if i write something false im dead

sleek quartz
#

yeah you can just do 100 lmao

stone rivet
#

it writed its not 40 a its 80

sleek quartz
#

oh i didn't catch that

#

yeah the middle part is $2ab$

soft zealotBOT
stone rivet
#

i have this one now

#

so the first case is (49-5z)^2?

#

.close

final saddleBOT
#
Channel closed

Closed by @stone rivet

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tranquil pine
#

guys

final saddleBOT
tranquil pine
#

limit e^n/(1+1/n)^n

#

n tends to infinity

#

any idea how to evaluate ?

static plinth
#

$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^n}$?

soft zealotBOT
tranquil pine
#

yea

#

sorry

#

there is an n^2

static plinth
#

do you remember what the definition of e was?

tranquil pine
#

in the denominator

static plinth
#

oh

tranquil pine
#

in the power of denominator

#

i mean

static plinth
#

$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^{2n}}$

soft zealotBOT
tranquil pine
static plinth
#

is the entire thing raised to the second power or only n

tranquil pine
#

its rasied to n^2

static plinth
#

no parenthesis?

tranquil pine
#

nope

tranquil pine
static plinth
#

$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^{n^n}}$

tranquil pine
#

i know several definitions

scarlet sequoia
#

$\lim_{n\to \infty}\frac{e^n}{\left(1+\frac{1}{n}\right)^{n^2}}$

soft zealotBOT
#

rafilou2003

tranquil pine
#

YES

#

THIS

tranquil pine
#

i tried binomial approximation

scarlet sequoia
#

not sure this would work well, depending on what binomial approximation you used

#

I think first take the ln

#

(natural log)

#

factor nicely

tranquil pine
#

i got this after using it

#

is it valid

scarlet sequoia
#

oh no it doesn't work at all

tranquil pine
#

as i can put 1/n = h where h tends to 0

tranquil pine
scarlet sequoia
#

you can't select a few well chosen n to tend to infinity first

tranquil pine
#

wdym

#

can't select a well chosen n

scarlet sequoia
tranquil pine
#

wouldn't it mean the same thing h tends to 0 or n tends to infinity

#

in this case

#

as we are only talking about +ve infinity here

tranquil pine
#

now i applied binomial approximation

#

as 1/n would tend to 0

scarlet sequoia
#

So you used $(1+x)^\alpha$ as $x\to 0$ right?

soft zealotBOT
#

rafilou2003

tranquil pine
#

yes

scarlet sequoia
#

That's when alpha is CONSTANT

tranquil pine
#

oh

#

right

#

blunder

#

sorry

#

okay

scarlet sequoia
#

anyways

tranquil pine
#

so what were you suggesting

scarlet sequoia
#

take the natural log

tranquil pine
#

why

#

lol

scarlet sequoia
#

you wanted a suggestion? Or an explanation of the whole solution?

tranquil pine
#

do you mean i write it again in the exponential form

#

like

#

take ln

#

then

#

apply the limits

scarlet sequoia
#

well yeah you have lim (...) and you could write it as lim (e^ln(...))

tranquil pine
#

ues

#

i wrote it

#

i got e^(n - n^2(ln(1+1/n)))

scarlet sequoia
#

yep

#

now factor the exponent nicely

#

and you can use expansion of ln. Be careful to include ENOUGH terms

tranquil pine
#

hmm true

#

i can use it

#

what is it ?

#

lol

#

i dont remember

#

and i dont wanna work out all derivatives to compute it rn

scarlet sequoia
#

look it up if you don't remember

#

ln(1-x) = sum(x^(n+1)/(n+1))

tranquil pine
#

i there is also negative sign

#

in this

#

ln(1-x) expansion

scarlet sequoia
#

yep

#

so you should easily figure out how to get ln(1+1/n) from the expansion I gave you

tranquil pine
#

2 terms will do ?

scarlet sequoia
#

See what happens when you get two terms

tranquil pine
#

i guess they will do

#

lol

#

i got e^1/2

#

as the limit

scarlet sequoia
#

yes

tranquil pine
#

hey i wanted an advice

#

should i solve less problems and learn further topics

#

or solve tons of problems on the topics i learn then move on to the next ones

#

i dont really know how much to solve

scarlet sequoia
#

That really depends on how fast of a learner you are, and how you learn the quickest
Try everything and see whether you understand topics better with a lot of exercises or not

tranquil pine
#

whats better

tranquil pine
#

i use book so i don't really get an idea about it

scarlet sequoia
#

you're free to go learn other topics and go back to that one at any time, and compare whether you know more about some topics than others

tranquil pine
#

you mean i can learn multivariable calculus without practicising tons of integrals

#

in single variable calculus

scarlet sequoia
#

If you feel like you're ready then attempt it

#

and if you don't or feel like you're lost while learning, practice more

tranquil pine
#

from where do you know a good source

scarlet sequoia
#

I have no good sources for you I'm afraid

tranquil pine
#

okay

#

thanks

#

.close

final saddleBOT
#
Channel closed

Closed by @raw grotto

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

waxen pine
final saddleBOT
waxen pine
#

is there a formula for this?

abstract bramble
#

rewrite as a geoseries

#

maybe

#

yeah

#

the denominator factors

#

oh but it's not a perf square

waxen pine
#

how

#

tihs doesnt seem like common ratio

#

oh you said canno tnvm

static plinth
#

limit comparison test

abstract bramble
#

how do you find the sum

static plinth
#

no idea

abstract bramble
#

ok

static plinth
#

doesn’t seem like something you should find the sum for honestly

final tangle
#

factorise denominator
then pfd

waxen pine
#

whats pfd?

final tangle
#

partial fraction decomposition

abstract bramble
#

it'll be telescoping

terse folio
#

Telescoping series

static plinth
#

oh then that’s even better

final tangle
#

🔭

terse folio
#

look at first 2 terms

final saddleBOT
#

@waxen pine Has your question been resolved?

waxen pine
#

okay i did psf

#

sorry was doing smth else

#

yeah

#

i see the telescoping

#

i think thats the name

#

thats crazy

#

its like magic

#

-1 +3 makes it connect

#

wait

#

it doesnt

#

becuase the psf the tops are differnet

#

did i do my pfd

#

wrong

#

found the mistake

#

ty for the help guys

#

.close

final saddleBOT
#
Channel closed

Closed by @waxen pine

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tranquil pine
final saddleBOT
tranquil pine
#

I rearranged both for sint and cost

#

Addition formula for the y parametic

#

Then subbed in the x parametic

#

Then equated sin^2 t + cos^2t

#

Then switched it for 1 and cancelled down

#

It didn't get me the answer

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

<@&286206848099549185>

sharp goblet
#

@mahdi_gd hii

tranquil pine
#

Huh

#

What the flip

sharp goblet
#

You only need to get the eqn right

#

Let me see

tranquil pine
#

?

sharp goblet
#

?

#

Im doing one min

#

Is there any mistake ?

tranquil pine
#

.close

final saddleBOT
#
Channel closed

Closed by @bitter aurora

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real reef
#

Hello! Does anyone how to use Mathematica 6.0 with Decarta2D? I have an exercise to solve for tomorrow and I don't know how.

candid hull
#

post your exercise, ppl are more likely to help if you do

#

@real reef

real reef
#

Thank you. Imma post it soon.

#

The converse of Ceva's theorem states the following: Let ABC be a triangle, and let points A' lie on (BC), B' lie on (CA), and C' lie on (AB). If: (A' B | A' C) * (B'C|B'A)*(C'A|C'B)=1, then the lines AA', BB', CC' are concurrent.

#

I have also the problem solved, i need it in Mathematica

final saddleBOT
#

@real reef Has your question been resolved?

final saddleBOT
#

@real reef Has your question been resolved?

final saddleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

raven obsidian
#

why did the base change to 2 on step 2? i thought the change base formula stated: log (base b) of x = log (base a) of x / log (base a) of b

raven obsidian
#

that was on google's calculator

fast arrow
#

Yes it does state that

#

They just chose a to be 2

#

Has nothing to do with the 2 as the parameter

raven obsidian
#

could i do the same even though the original base is 8?

fast arrow
#

Yeah, the original base doesn't matter

raven obsidian
#

because i see thjey used it to make the top of the fraction to equal 1 in the following step

raven obsidian
fast arrow
#

The new base can be any number

sharp goblet
#

?

raven obsidian
#

so it's my choice to make it into whatever number that works for me?

#

odd... i guess that makes sense?

sharp goblet
#

can you clearly say your question ?

raven obsidian
#

i was just wondering why the base went from 8 to 2

fast arrow
#

You get to choose c which is independant of a and b

sharp goblet
raven obsidian
#

without prior knowledge of that, it seems like the method isnt useful if i cant envision the rest of the steps

sharp goblet
#

But theres an easier way go compute your result

raven obsidian
#

i figured i could also try inverse property

sharp goblet
#

8 = 2³ and 16 = 2⁴

#

So ypu can write log 8 base 8^(4/3)

#

And answer is 4/3

raven obsidian
#

yeah that way i understand, thanks. just had to make sense of the other one but oh well

#

.close

final saddleBOT
#
Channel closed

Closed by @raven obsidian

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jolly vector
final saddleBOT
jolly vector
#

how do i find bh

#

ab=3cm

#

ae=8cm

loud sundial
#

Is ABCD a square? If so, 3D Pythagorean theorem.

jolly vector
#

yea ik pythageoream

#

but

#

i duno

#

whixh ones to take

#

like which linea

#

bec bh

#

i duno

loud sundial
#

The height is kinda obvious

#

For the two other sides, assuming ABCD is a square, it doesn’t matter

#

Since all the sides are the same anyway

jolly vector
#

.close

final saddleBOT
#
Channel closed

Closed by @jolly vector

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

potent lance
#

stuck on the graphing part

final saddleBOT
karmic kindle
#

You have everything

#

If you have the vertices

remote mauve
#

What exactly do you need help with the graphing

potent lance
#

do i graph it like normal tho

remote mauve
#

If it’s not asking to label everything on the graph, then I think simply graph the ellipse

potent lance
#

idk it feels wrong

remote mauve
#

It is

#

(x+3)^2 means the x goes from 0 to -3, and (y-6)^2 means they goes from 0 to 6

#

Also, the distance from the vertex to vertices and co-vertices is the square root of the numbers below the squared x and y

potent lance
remote mauve
#

Rotate it 90 degrees

potent lance
#

ohhhh

#

im use to it being (0,0)

remote mauve
#

Yes

potent lance
#

i get it now

#

thx man

remote mauve
#

Np

potent lance
#

how i close

remote mauve
#

.close

potent lance
#

.cloe

#

.close

final saddleBOT
#
Channel closed

Closed by @potent lance

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

raven ember
#

Hello, Im trying to do the Quine McCluskey method to simplify an expression and I was wondering if it can happen that you are eliminating more than one variable for example with 2 and 3 here I would only get wy, no?

final saddleBOT
#

@raven ember Has your question been resolved?

raven ember
#

<@&286206848099549185>

final saddleBOT
#

@raven ember Has your question been resolved?

final saddleBOT
#

@raven ember Has your question been resolved?

final saddleBOT
#

@raven ember Has your question been resolved?

raven ember
#

.close

final saddleBOT
#
Channel closed

Closed by @raven ember

Use .reopen if this was a mistake.

wild geyser
#

ক ষ।

#

@yawshuhs

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

plucky bridge
#

hello how to do this question

final saddleBOT
plucky bridge
#

Also is the determinant of a matrix equal to the scalar triple product of its rows?

#

Like somebody has said that to me

tranquil pine
#

invertible is matrix that has an inverse ryt

plucky bridge
#

what is ryt

final saddleBOT
#

@plucky bridge Has your question been resolved?

#
Channel closed

Closed by @plucky bridge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

remote island
#

please explain both the "addition" and the multiplication by 12

versed crater
#

They are properties of the determinant

#

Do you have notes on the properties of determinants?

versed crater
#

I’m asking you

remote island
#

nah, idk where does it stem from

#

just fond this vid

#

watching it rn

versed crater
#

Do you know what the definition of the determinant is?

remote island
#

just that if it's != 0 then the matrxi is invertible

versed crater
#

Hmm

#

Have you learned about the determinant in class?

remote island
#

i was absent

remote island
versed crater
#

I actually don’t know any good videos that explains determinant nicely

remote island
#

i don't have to intuitvely understadn what determinants are

#

at least rn

versed crater
#

It’s a sort of thing you can do to a matrix

#

It has some interesting properties

#

Notably, it’s linear in every row and column

#

And if you swap 2 rows the sign changes

versed crater
remote island
#

all i know about properties

versed crater
remote island
#

wdym by using linearity

#

what exactly do you mean that it's linear in ever yrow and column

versed crater
#

Just like how if A(x+y) = A(x) + A(y) this is linearity

#

It’s linear in its (first and only) entry

#

But say my function takes more than 1 input

remote island
versed crater
#

Have you not been studying linear algebra

remote island
#

for me linearity is y = mx + b

versed crater
#

That’s not linear that’s affine

#

Are you taking linear algebra at the moment?

remote island
#

yea

#

i was sick so there's that

versed crater
#

Do you know what a vector space is?

remote island
#

don't remember

#

but could you plz

#

just note all the things i need to know for solving problems

versed crater
#

Do you know what a linear transformation is?

remote island
#

not the theory

#

i will learn it later

versed crater
#

You should learn the theory first or it won’t make much sense

remote island
#

i dont have time

versed crater
#

If you don’t have time to learn something you won’t be able to learn it

#

You don’t tell the IRS I didn’t file my taxes because I didn’t have time

remote island
#

just expalin this qwuickly pls

versed crater
#

I can’t because you lack the background knowledge to understand the explanation

#

You’re asking how a plane flies without knowing any physics

#

There really isn’t much to say besides “it just does”

remote island
#

dude just explain ther ule

#

without saying why it works

#

like you have two determinants

#

when can you add them

#

and how do you do so?

#

i know how to compute determinants

#

<@&286206848099549185>

#

also what does D mean here

versed crater
remote island
#

ok so it's just a different notation

#

i'm familiarw ith it

#

@versed crater could you pls say how did they compute all these determinants so quickly?

versed crater
#

you just look at it and do it in your head

#

3x3's are not too hard when it's all 1's and 0's

remote island
remote island
#

how do you solve stuff like

final saddleBOT
#

@remote island Has your question been resolved?

remote island
#

OR THIS

nocturne vale
remote island
#

also, what does this ^-1 mean here

remote island
#

like wdym by simplify here?

midnight sparrow
midnight sparrow
#

Maybe for the transpose write the coefficients and try to solve the system

#

It's the same for the second

#

And I think for the third if you multiply both matrices you will get something maybe

remote island
#

this was before systems of equations

midnight sparrow
#

? Wdym

remote island
#

so the teachers wants you to solve it another way

midnight sparrow
#

For the third multiply both matrices and you'll get a diagonal matrices maybe which IS very easy

remote island
#

3rd what?

#

2nd what?

midnight sparrow
#

So what's your lesson

remote island
#

but im not sure to what problems are you referring to with other questions

midnight sparrow
#

No a transpose IS just the X^t

#

It's the transpose of X

remote island
#

ok

#

but what do you mean by "second" and "third"?

nocturne vale
#

sorry my phone dead

remote island
#

no worries

nocturne vale
#

but yh take transpost

midnight sparrow
#

Maybe I don't use thé right term I'm not english

remote island
#

you just said "second" and "third"

#

second and third what

midnight sparrow
#

Of what you have send

remote island
midnight sparrow
#

And the other IS third

remote island
nocturne vale
remote island
#

3rd in order or thed one marked 3

nocturne vale
#

XA*A^-1=XI=X

midnight sparrow
#

But the other 2 were solved no ?

#

Sry for the confusion so

remote island
remote island
midnight sparrow
#

When multiply by identity it do nothing

remote island
midnight sparrow
#

So X IS unchange

#

But make sure A is invertible

nocturne vale
#

A^-1 is A transpost

midnight sparrow
#

Here it's the case