#help-36

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proper yoke
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Let f(x, y, z) = ... and A = (1, 1, −4).
(a) Specify the tangent plane to the level surface f(x, y, z) = 19 at point A.
(b) At what rate of change f′ v (A) does f increase or decrease in the direction (−6, 2, −3) away from the point A?
(c) In what limits does the directional derivative f′v(A) depending on the departure direction v away from A?

proper yoke
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does anyone know how to solve this?

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does a have something to do with the gardiant?

final saddleBOT
#

@proper yoke Has your question been resolved?

final saddleBOT
#

@proper yoke Has your question been resolved?

soft zealotBOT
#

𝔸dωn𝓲²s

proper yoke
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Hmm okay what does that mean do I put in A=(1,1,-4)?

drowsy epoch
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Yes

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I think you have formulas dont ya for tangent plane

proper yoke
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i have these

drowsy epoch
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I think the left is the same as mine

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If you do the dot product with the gradient and x-a, y-b, z-c etc

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And f(a,b) is my f(A)

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I just didnt bother to write f(x_A,y_A,z_A) = f(A) every time

proper yoke
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Okay but what is x, y, z, a, b and c?

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Is abc (1,1,-4)?

drowsy epoch
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x,y and z free variables

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yes!

proper yoke
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Okay so f(1,1,-4) • (x -1, y-1, z-(-4))?

drowsy epoch
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It's the same as in yours but one dimension higher

drowsy epoch
#

gradient!

proper yoke
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Yea but I don’t know how to make that symbol

soft zealotBOT
#

𝔸dωn𝓲²s

drowsy epoch
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It's your partial derivatives in column vector form

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If you do the dot product you get the same what I wrote above

drowsy epoch
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x_A is your a
y_A is your b
z_A is your c

proper yoke
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Okay w = fx(A)(x-1) + fy(A)(y-1) + fz(A)(z—4) + f(A)?

drowsy epoch
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yes

proper yoke
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Okay do I solve something out now?

drowsy epoch
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f(A) = 19 btw

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you nees the partial derivatives, plug A into them and thats it for a)

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f_x(A) = f_x(1,1,-4) = ?

And the sams for the others

proper yoke
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Wait I’m confused do I plug in 19 on all the f(A)s?

drowsy epoch
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There is only one..

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The others are again point A plugged in to the partial derivatives

drowsy epoch
proper yoke
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Fx(A)= 4e?

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Fy(A) = 8e?

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And fz(A) =1?

final saddleBOT
#

@proper yoke Has your question been resolved?

proper yoke
#

.closw

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.close

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gaunt condor
#

radius of the circle?

final saddleBOT
nova coral
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radius is just 21

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@gaunt condor

final saddleBOT
#

@gaunt condor Has your question been resolved?

gaunt condor
nova coral
#

r=21

gaunt condor
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its wrong

nova coral
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then you can apply the formula

gaunt condor
#

you cannot add 12+9

its not parallel

limber sundial
#
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gaunt condor
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thx

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gleaming bluff
#

How do i find the area of a parabola can someone explain and give an example

gray acorn
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bright current
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I know these types of questions are easy but I get confused

bright current
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I found one of the points by plugging in 0

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Aand I got (0,-1)

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Not 0

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-2

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tranquil charm
#

how can i find uncertainty of Q when

final saddleBOT
tranquil charm
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$Q=\int_{t_a}^{t_b}-k \left(\left(-12,07e^{-0,0106t}+16,34 \right)-T\right)dt$

soft zealotBOT
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Slowaq

tranquil charm
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i know boudaries of definite integral

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k and T are constants

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and i know uncertainty of T

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magic ether
#

can someone tell me what is a equivalence error in discrete math

magic ether
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i asked for help in this problem earlier and the person corrected it and told me i need to add equivalence errors in each line

mental roost
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he probably means:

soft zealotBOT
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Martin

mental roost
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this is the sign of an equivalence

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meaning that two statements are equivalent to each other

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one could argue that on your paper, you just have a list of statements

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if you have a set of statements, you could do it like this:
statement 1
<=> statement 2
<=> statment 3

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this would imply that all 3 statements are equivalent

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as in, they mean the same thing

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so it's pretty much just an equation but with statements

final saddleBOT
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lyric lichen
#

what gives this equation no real numbers?

final saddleBOT
proud plover
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its domain is from -inf to inf

primal sierra
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x can be any value

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and the output will be real

lyric lichen
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Im not sure what that means

proud plover
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the quadratic function has a domain of all real numbers

lyric lichen
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Okay

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so how is the domain not

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(-inf,-5)U(-5,-1)U(-1,infi)

proud plover
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why are -5 and -1 special here

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its a quadratic

lyric lichen
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why is it (-in,in)

proud plover
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do u know what a quadratic looks like

lyric lichen
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I don't know what you mean

proud plover
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it will keep going up

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forever

lyric lichen
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to find a domain don't I factor

proud plover
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no

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u do that for roots

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domain is all possible values of x

lyric lichen
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it worked for this

proud plover
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that is because there is a quadratic in the denominator

lyric lichen
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okay

proud plover
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so for some values of x, u end up dividing by 0

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which is not allowed

lyric lichen
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making it a domanin

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so not having the top makes it not a real number

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therefore (-inf,inf) ??

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stark apex
final saddleBOT
stark apex
#

how do I get 48.86 ? do i need to be on a certain mode

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I do 1.5^1/3 and i get 1.144

tulip coyote
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Degrees mode - what do you get when you inverse tan that 1.144...?

stark apex
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I was supposed to inverse it this whole time!?!?

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wait how do i know when to inverse it ?

white night
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use inverse tan function on your calculator

stark apex
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ok

tulip coyote
stark apex
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ohhh

white night
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yeah sorry i didnt explain that well

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like tan^-1(tan(x))=x

stark apex
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ohh

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plucky scaffold
final saddleBOT
plucky scaffold
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am i good

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?

sturdy cypress
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i think 3 is wrong

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it is one of those

plucky scaffold
sturdy cypress
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also 10 is wrong

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kinda

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if you start at 2 or 3, that's a different cycle from the other numbers

final saddleBOT
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@plucky scaffold Has your question been resolved?

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unique estuary
final saddleBOT
rare halo
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dont do that

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lmao

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ok

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so

ivory vessel
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what was that? i didnt see his deleted msg

rare halo
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what happens when u multply dem and num with the (1-root(3))

rare halo
ivory vessel
unique estuary
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rationalise the denominator by multiplying by the conjugate

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i realise now my mistake isn't not knowing how to do it but in my working 😭

rare halo
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oops

soft zealotBOT
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_basudev

rare halo
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now expand lisayay

unique estuary
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yeah my mistake is in my working

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wanton crypt
#

how do you find the missing length on a triangle with the hypotenuse and leg only

ivory vessel
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right triangle, use Pythagorean

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normal triangle, only when you also know the angle of two known sides

wanton crypt
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wait so a^2+b^2=c^2

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it would be a^2=c^2-b^2

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right

glad kraken
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yes but you know a^2 and c^2 so you need to solve for b

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or that

wanton crypt
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correct?

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i assume so

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thanks for the help yall

#

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tranquil pine
#

how would you differentiate this? We just learned about power rule, constant multiple rule, product rule, chain rule for powers of polynomials, sum and difference rule. I'm still very confused so I would appreciate any help on this question.

tranquil pine
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bro I'm so cooked if I keep solving this question

final saddleBOT
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@tranquil pine Has your question been resolved?

barren bay
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I mean, if you haven't learned the quotient rule, you can rewrite the question as 1500(1 + 5t(t^2+30)^-1)

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That way you can just use product rule and chain rule

tranquil pine
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This is where I’m stuck

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I kept going in circles like this. I don’t even know where I did wrong.

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my brain is fried at this point lmao

barren bay
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Lol, it's kinda awkward to type, gimme a second to look at this

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Looks like you're right, just make sure to multiply by 1500 at the end still

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If you want to check it in the future, the derivative of a fraction f(x)/g(x) is just (f'(x)g(x) - f(x)g'(x))/(g(x)^2)

tranquil pine
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oh ok, thank you so much. We didn't learn about quotient rule yet so I'll keep that in mind.

barren bay
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Yeah, I got a final derivative of 7500(30-t^2)/(t^2+30)^2 through both methods

tranquil pine
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I haven't arrived at a final answer yet

barren bay
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sure

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your answer at the bottom right is correct, you just need to simplify and multiply by the 1500 from the original prompt

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1500(f'(x)g(x) - f(x)g'(x))/g(x)^2

(7500(t^2 + 30) - 7500t(2t))/(t^2+30)^2
7500(t^2 + 30 - 2t^2)/(t^2 + 30)^2
7500(30 - t^2)/(t^2 + 30)^2

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Jeez, that's kinda ugly to type lmao

tranquil pine
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thanks a lot bro. It's a lot of work so I appreciate the help.

barren bay
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Nah, I'm just surprised they didn't teach quotient before chain since it's just a formula

tranquil pine
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yeah there's no quotient rule yet idk why

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look at this

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this is what we got

barren bay
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Yikes, not even any proofs lol

tranquil pine
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I mean this is just a summary of all the rules at the end so

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proofs were shown in the beginning

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anyways, thanks for the help. I'll close this

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barren bay
#

np

final saddleBOT
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tranquil pine
#

When we say the initial velocity is 3i + 4j
What does it actually mean

tranquil pine
#

Kindly represent through a graphing tool like desmos etc

mellow axle
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you get a right triangle

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x = 3, y = 4

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so hypotnuse is 5

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and use any inverse trig you like to get the angle

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so arcsin(4/5)

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so you have a vector having magnitude 5

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and the angle of the vector is arcsin(4/5)

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that's the velocity vector

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you're going 5 units of distance per unit of time initially

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and the direction of the distance is given by arcsin(4/5)

tranquil pine
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Let's say if initial velocity is (1i + 1j)m/s
Then I would be going with 1 m/s in 45°
Right?

mellow axle
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no

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what is the magnitude of i+j

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it's the sqaure root of 1^2 + 1^2

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which is sqrt(2)

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so you're going sqrt 2 m/s

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in 45 degree = pi/4 radians

tranquil pine
#

Cool, and why in some cases velocity and acceleration are at different angles when both are positive?

mellow axle
#

in general is accerlation and velocity always equal?

tranquil pine
mellow axle
#

so we shouldn't expect how they're represented to be equal as well

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i can have a very small acceleration but a very high velocity

tranquil pine
mellow axle
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nop, take for example in the real line

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if i have an acceleration of 1

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my veloctiry should be increasing right?

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say my instantaneous velocity is -1 though

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so im travelling to the left right now

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but if i don't change my acceleration, i will slow down going left, stop completely, then begin travelling to the right

tranquil pine
#

Didn't get, plz explain

mellow axle
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are you familiar with derivatives

tranquil pine
#

@mellow axle

mellow axle
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ok so

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if i have a(x) = x then v(x) = x^2 right

tranquil pine
mellow axle
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x^2 /2

tranquil pine
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If v(x) is x^2 then a(x) would be 2x

mellow axle
#

let's say that im initially going v(0) = -1

tranquil pine
mellow axle
#

wdym how

tranquil pine
mellow axle
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ok so

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$v(x) = \frac{x^2}{2} - 1, a(x) = x$

soft zealotBOT
#

chebyshev's infinite pee norm

mellow axle
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what is the acceleration and velocities at time x = 1/2?

tranquil pine
mellow axle
#

yes

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so the velocity is going in the negative direction

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so it has angle -pi

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on the real number line

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and acceleration is going in the positive direction

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so it has angle pi on the real nubmer line

tranquil pine
tranquil pine
#

How +pi degree?

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@mellow axle

mellow axle
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oh sorry

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ye velocity has pi angle

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and acceleration has 0 angle

tranquil pine
# mellow axle oh sorry

Oh thanks..
But because acceleration is positive, so as time passes
They both will have 0 degrees no?

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@mellow axle last question
What exactly is unit vector
Like unit vector of 3i + 4j is 3/5i + 4/5j
But what does it mean

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<@&286206848099549185>

final saddleBOT
#

@tranquil pine Has your question been resolved?

steep tendon
#

the parallel vector from origin to the unit circle

tranquil pine
steep tendon
#

nah thats just uh i know what it means

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thats all, now u know too

tranquil pine
steep tendon
#

well yea

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unit for a reason

final saddleBOT
#

@tranquil pine Has your question been resolved?

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gleaming bluff
#

how do i find the domain of $$f(x) = \frac{1}{\sqrt{4-2x-x^2}}$$

soft zealotBOT
#

ghiolimer

gleaming bluff
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idk where to start

spare glacier
#

Factor the denominator

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The roots of that polynomial is part of the bounds of the domain

tranquil pine
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The denominator can not be 0 and the stuff inside sqrt must be positive

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Or in other words Domain can be a subset of 4-2x-x²>0

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upper silo
#

this is a question on hypothesis testing

final saddleBOT
upper silo
#

I have gotten to $\bar X $~$ N(65, \frac{9^2}{35})$

soft zealotBOT
#

sealpup321

upper silo
#

i cant put squiggly T-T

static plinth
#

what are you stuck on exactly?

upper silo
static plinth
#

so first let’s list out our null and alternative hypotheses

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what are they?

upper silo
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null is $\mu = 65$

soft zealotBOT
#

sealpup321

static plinth
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yep

upper silo
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alternative is $\mu < 65$

soft zealotBOT
#

sealpup321

static plinth
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yep that’s correct

upper silo
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great 🙂

static plinth
#

also by any chance, do you have to check the conditions or no

upper silo
#

what do you mean?

static plinth
#

to perform a one sample z test, we have to make sure that our sample is random and that the sample size is bigger than 30

upper silo
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btw probably wont change much but we get access to smart calculators so you dont need to use the massive data table

static plinth
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alright

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so then we can just use the calculator for this

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we have all the numbers

upper silo
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do i do $P(x <= 61.5)$?

soft zealotBOT
#

sealpup321

static plinth
#

on your calculator, do you have an option to do a one sample z test?

upper silo
#

because if so i got 0.065

static plinth
#

if you can calculate the probability of a normal distribution, you should be able to do that

upper silo
static plinth
#

wait what?

upper silo
#

?

static plinth
#

can your calculator do a one sample z test or do you have to use normalcdf

upper silo
#

is that not how you do a sample test

static plinth
#

your calculator should have an option to do one

#

and all you have to do is just plug in the numbers and the hypotheses

upper silo
#

cool....

#

I'm afraid Im still a little confused

static plinth
#

so what did you put in your calculator

upper silo
#

this is an online version of the calculator i am using

#

sorry i know its a bit of a hassle but Im unsure of what you mean

static plinth
#

oh my

#

i’ve never seen this calculator before

static plinth
upper silo
#

so thats confusing

static plinth
#

i see

upper silo
#

thatll be why

static plinth
#

alright

upper silo
#

ok yeah I got the right answer this time 🙂

#

thanks

#

.close

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#
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tranquil pine
#

Can someone explain to me the range of a matrix and how can I study a matrix with 1 unknown constant value

tranquil pine
#

Show that this matrix range is 3

vapid basalt
tranquil pine
vapid basalt
#

It's the rank

tranquil pine
#

Bruh sorry

#

I am noob

tranquil pine
vapid basalt
tranquil pine
#

Rank is not the min(n, m)?

#

Or am I wrong

vapid basalt
tranquil pine
#

Bruh I am really stupid sorry

vapid basalt
#

do you know what linear dependence is?

tranquil pine
#

No can you explain

vapid basalt
tranquil pine
#

Can you tell me

vapid basalt
tranquil pine
#

A vector is like a multiple numbers? 1x1

#

{ 1, 2, 3, 4}

tranquil pine
vapid basalt
tranquil pine
vapid basalt
tranquil pine
#

Of that definition

tranquil pine
vapid basalt
# tranquil pine Ok so give me an example

Say you have 2 vectors u,v. If there exist 2 numbers a,b not equal to 0 such that au+bv=0, then the vectors are linearly dependent. If not then they are linearly independent

vapid basalt
#

Geometrically, if the vectors are pointing in the exact same direction (they are on the same line), they're linearly dependent. If they don't, they're linearly independent

tranquil pine
#

So coming back to the problem

tranquil pine
#

?

vapid basalt
vapid basalt
#

Okay now you use the definition of linear independence to figure out how many of them are linearly dependent from each other

tranquil pine
#

{ a - 1 / 2, b , c}

#

{c, a - 1/ 2, b}

tranquil pine
#

Ok

vapid basalt
#

Yep

tranquil pine
#

So now let's see

#

So I need to check the position one of the first vector with position one of the second

tranquil pine
#

And check with c

vapid basalt
#

No

#

You need to check if there are 3 numbers d,e,f which make the sum of these vectors 0

vapid basalt
#

Ideally start with d,e and then f

tranquil pine
#

a - 1/ 2 e + b f + ck = 0

vapid basalt
vapid basalt
vapid basalt
vapid basalt
#

Try finding out if there are any numbers d,e such that du+ev=0

tranquil pine
#

Ohhh

#

I understand

vapid basalt
#

Yes

tranquil pine
#

How do I find the constant after

tranquil pine
vapid basalt
tranquil pine
#

Oh

#

So I need 2 ecuations

#

For the system

#

I will use the third vector

tranquil pine
vapid basalt
#

So for vectors u,v and numbers d,e:
d(a-1/2)+ec=0
db+e(a-1/2)= 0
dc+eb=0

tranquil pine
#

So u took the first vector

#

And made the sum adding a

#

Constant

#

And = 0

#

Ok

#

So you check

#

The dependency

vapid basalt
#

Yeah you sum the multiples of their components and check if they can equal 0

vapid basalt
#

In this case you can immediately see that you simply can't multiply u with any number to get v or w and vice versa so therefore the matrix has full rank

#

But it's a good exercise

tranquil pine
#

I have to do that for every other vector (in my case the other vector have same components

tranquil pine
#

So*

#

Here

#

But in a hard cases do I need to that for every vector?

vapid basalt
#

but if you know that u,v are linearly dependent and w is linearly independent, then you know that both u and v are linearly independent from w

#

Beginning the linear algebra series with the basics.
Help fund future projects: https://www.patreon.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Home page: https://www.3blue1brown.com/

Correction: 6:52, the screen should show [x1, y1] + [x2, y2] = [x1+x2, y1+y2]

Full series: http://3b1b.co/eola

Fu...

▶ Play video
tranquil pine
#

Ok let me look

#

Will come back

vapid basalt
#

watch this series andyou will understand immediately what i mean

tranquil pine
#

After I look

vapid basalt
tranquil pine
#

Ok

final saddleBOT
#

@tranquil pine Has your question been resolved?

#
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clever epoch
#

can anyone help me with this 3. Given the quadratic and linear equations below, determine the point(s) of intersection
using 2 different algebraic methods. Hint: remember systems of linear equations from
grade 10)
i. X
2
– 2x + 3y + 6 = 0
ii. 2x + 3y + 6 = 0

warm wraith
#

Have you tried anything?

clever epoch
#

yes

#

i tried to subsitute them

#

to equal each other

#

and i ended up with x^2 - 4x + 0

#

but im prtty sure that is not the right answer

warm wraith
#

Are you able to send a picture of your work?

clever epoch
#

sure

#

this could be a bit lesss blurry

warm wraith
#

Ah thanks

#

Well, i don‘t see an issue with doing it this way, did you go all the way through with that method?

clever epoch
#

i think so i again i got to x^2 - 4x

warm wraith
#

Also, i think you put a + instead of an =

clever epoch
#

after thee 6?

warm wraith
#

After x^2-4x

clever epoch
#

oh yeah

#

i dont know if that answer would be right because guath math gave me different answer but i want to understand it

#

also how would i get the coordinates from x^2-4x

warm wraith
#

You get the x coordinate from x^2-4x=0

clever epoch
#

what would it tbe

warm wraith
#

I don‘t know, solve for x

clever epoch
#

ok one sec

#

i just factored out x

#

im not sure if that would work but my x coordinate is there now

warm wraith
#

Hm? What are the possibles values of x if you know x(x-4) = 0. there are 2

clever epoch
#

0 and 4?

warm wraith
#

Correct. So your x coordinate is either 0 or 4. You‘re gonna have to try them afterwards. But now you can use this to find the possible y coordinates

clever epoch
#

ok so i would plug both into the equation i found?

warm wraith
#

What do you mean by "equation I found"?

clever epoch
#

x^2-4x=0

#

im notsure what i would plug them into

warm wraith
#

Well, you know X, and you want to find Y. Do you know of any equations in this problem that connect X and Y together?

clever epoch
#

ohhh

#

this? x^2-2x+3y+6=2x+3y+6

warm wraith
#

No, because in this the y cancel out, so there‘s no point. But if you pick one that the question gives you, you‘ll be fine

clever epoch
#

ok

#

let me do it ill send a photo in a second

#

so far i got this

#

before i go any further im just wondering if the steps are good so far

warm wraith
#

So, you picked equation I and plugged 0 for X?

clever epoch
#

yes

warm wraith
#

Then you‘re on the right track

clever epoch
#

ok ill finish it and send

#

i got y=2

#

for that equation so my first intercept would be

#

(0,2) right?

warm wraith
#

You had 3y = 0 and you found y=2?

clever epoch
#

sorry i miss wrote it

#

it is 3y=-6

#

because there was a +6

#

iso i moved it over and divided it by 3

warm wraith
#

And -6/3 is?

clever epoch
#

-2

#

bruh

warm wraith
#

:p

clever epoch
#

ok ok so (0,-2)

warm wraith
#

Okay, so one potential intersection is (0, -2). Now you had another X point so you have to try that one as well

clever epoch
#

ok

#

i got -14/3

#

for y

warm wraith
#

Great, so you have 2 potential intersections now. Last thing to do is plug them in the equation that you haven‘t used to make sure they work

clever epoch
#

wdym?

#

i just think i did it

#

but they both = 0

warm wraith
#

Well, you have 2 points, which do work in the first equation, the one with x^2. but you need to check i. The other

warm wraith
clever epoch
#

oh

#

so i have 2 intercepts?

warm wraith
#

Yeah it‘s possible. When you think about it, you have a parabola and a line

#

So it‘s very possible that the line cuts the parabola in 2 places

clever epoch
#

ok thank you sm

#

can i give you like a vouch or somethingg this is my first ttime using the server

warm wraith
#

I don‘t think this server has a reputation bot or somwthing like that, but thanks I appreciate it :)

clever epoch
#

ok ty

#

.close

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#
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jaunty anchor
#

I have a coding problem. I am looking to find the coordinates of an area in a grid. Currently I am doing something like this:

Corner1 = 10, 0, 10 (x, y, z)
Corner2 = 20, 0, 20
Area = Corner2 - Corner1
BlocksPerArea = 10
Block = Area / BlocksPerArea

This means that Block = 1, 0, 1
and when block is multiplied (1, 2, 3, 4, etc up to 10) I recieve a number of 1, 0, 1 | 2, 0, 2 | 3, 0, 3 etc... However I need to get the numbers of 1, 0, 1 | 1, 0, 2 | 1, 0, 3 | etc...
I am not really sure how to go about this thanks
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#

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orchid hill
#

Am I correct in saying the following

final saddleBOT
orchid hill
#

For any $n$-tuple of natural number $v=(v_1 \ldots v_n)$ it can be mapped to the natural numbers via the mapping $$\prod^{n}_{i=1}p^{v_i}_n$$ where $p_n$ is the $n^{\text{th}}$ prime number. So $p_1 = 2, p_2 = 3$. This is true the via "unique factorization theorem".

soft zealotBOT
orchid hill
#

this for a formal logic course, im trying to write it more formally but i think i might have might have left some parts ambigious i.e. i dont know if this a mapping or it actualyl does work to being with

mellow axle
#

are you claiming that this mapping is a bijection?

#

or are you just saying you can make this map

orchid hill
#

hmm just a map with no restrictions

#

i think it would have to be injective

#

tho

#

but then i would have to show that?

#

my objective was to prove that all n-tuples can be mapped to the naturals numbers

mellow axle
#

well if you're writing a proof for something then yeah you generally want to prove your claims

orchid hill
#

as in there exists a map $f : X \to \mathbb{N}$

soft zealotBOT
orchid hill
#

where X is any n-tuple of natural numbers

#

i think thats equilvnent to what i want to prove

mellow axle
#

if there's no conditions that f need to satisfy there are many maps that can take an n-tuple to a natural number

orchid hill
#

so if i can demonstrate one of them exists does that also mean my orignial statment is true (the statement being "that all n-tuples can be mapped to the naturals numbers")

mellow axle
#

yeah

orchid hill
#

based

mellow axle
#

and i think you using the prime decomposition is overthinking it

orchid hill
#

oh fr?

#

i saw a proof for 2d case

mellow axle
#

just take $f:\mathbb N^n \rightarrow \mathbb N,f(x) = 1$

soft zealotBOT
#

chebyshev's infinite pee norm

orchid hill
#

ohhh okay

#

my orginal statement was flawed then

#

actually i was trying to show that the set of all n-tuples for some specific is countable

#

hence why i said there exist a map from that (the n-tuples for a specific n) the naturals?

mellow axle
#

n-tuples for some specific is countable
do you mean for some specific set is countable?

orchid hill
#

all sets of sets of n-tuples? so like all 2-tuples are countable and all 3-tuples are countable indivdiually

#

not all at once

#

but

#

with one proof

mellow axle
#

ok well

orchid hill
#

if that makes sense

mellow axle
#

first of all

#

to show a set is countable, you need a bijection with N

#

not just any random mapping

#

second of all

#

probably induction

orchid hill
#

huh, oh right cause i could just map the same element if were not injective

mellow axle
#

that or just show the product of countable sets is countable

orchid hill
#

product of a countable sets as in cartesian prodcut?

mellow axle
#

yea

orchid hill
#

alr thank you some much brev

#

+rep

#

.close

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bleak bone
#

2+2=5?

final saddleBOT
tranquil pine
#

Please don't troll

gray acorn
long wraith
tight quail
#

.close

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graceful lantern
final saddleBOT
#

@graceful lantern Has your question been resolved?

graceful lantern
#

#help

#

<@&286206848099549185>

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tired glen
final saddleBOT
tired glen
#

i need to find CD and area of the quadrangle

#

im kind of stuck, the only thing i was able to find was BD which is root of 189 and AC which is root of 37

#

AD is 12 AB is 3 BC is 4 and there are only 2 of these angles given

#

nothing else

final saddleBOT
#

@tired glen Has your question been resolved?

tired glen
#

<@&286206848099549185>

iron coyote
tired glen
tired glen
#

<@&286206848099549185>

final saddleBOT
#

@tired glen Has your question been resolved?

graceful lantern
#

<@&286206848099549185>

tired glen
#

bruh

#

.close

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sturdy cloak
final saddleBOT
sturdy cloak
#

how is this 0?

#

2k+1 is odd

#

which means u will be at an odd step

#

but that would have taken u even steps to get to that odd step

zenith pollen
#

I'd post the original example but it seems like you're moving on a number line so you'll only hit even numbers at even timesteps

sturdy cloak
#

x2k+1 is odd step

#

ie 3 5 7 9 etc

#

to go from 1 to an odd step

#

u need to have taken an even number of steps

#

or bets

#

by the example

zenith pollen
#

do you want it to be X2k instead of X2k+1

#

I kind of see your point

sturdy cloak
#

ie

#

yes

#

if thats 2k

#

than 2k - 1 ( the first step)

#

is an odd number of steps

#

however

#

going by this

#

we can only return after an even number of steps

#

hence

#

that probability would be 0

#

do u see my point?

zenith pollen
#

but like clearly it alternates between nonzero and 0

zenith pollen
#

idk what X is yet

sturdy cloak
#

wait

#

once sec

zenith pollen
#

example 3.3 I think

sturdy cloak
#

sry]

sturdy cloak
zenith pollen
#

oh ok

sturdy cloak
#

this is how it alternates

sturdy cloak
#

heres the next part

#

but this doesnt make sense

#

2k bets havent happened

#

in facts 2k-1 bets have happened no?

#

since X1 is the initial state

zenith pollen
#

yea there's some weird consideration for if you're doing it after or before a bet

#

that changes things from even to odd

sturdy cloak
zenith pollen
#

here it's before where usually I'd write it as after I think

#

calling the first step 1 instead of 0 is also a convention so it's annoying to sort which is which lol

#

before first bet means even number of wins/losses

sturdy cloak
#

oh i see

zenith pollen
#

so is before all odd bets

#

really annoying haha

sturdy cloak
#

thanks

final saddleBOT
#

@sturdy cloak Has your question been resolved?

sturdy cloak
#

how is the expectation equal to this?

#

same question as op

zenith pollen
#

each visit is +1 to N_0

sturdy cloak
#

ye

zenith pollen
#

so it's like 1*chance of going to 0

#

summed over any time

sturdy cloak
#

but here we r just adding probabilities

zenith pollen
#

each time is like 1*P(x=0) + 0*P(x!=0)

sturdy cloak
#

yh kl makes sense

#

thanks

final saddleBOT
#

@sturdy cloak Has your question been resolved?

#
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tranquil pine
#

how am i supposed to solve w/o a function?

tranquil pine
tranquil pine
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#

@tranquil pine Has your question been resolved?

tranquil pine
#

.close

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umbral shuttle
final saddleBOT
umbral shuttle
#

am i correct with everything here?

#

please let me kno

#

it looks right to me just need someone to verify

#

<@&286206848099549185>

hallow wasp
#

If its an equals then yes that is correct

#

but unholy levels of inefficient

umbral shuttle
#

thats the answer

hallow wasp
#

eh solve using matrices, yeah ig u did it the right way

hallow wasp
#

i know y = -2

#

if its an equals

#

because we have
2x +7y = 4
2x +6y = 6

#

subtract bottom from top

#

for y = -2

#

solved

#

teacher doing u guys dirty if theyre not allowing that

umbral shuttle
umbral shuttle
#

same problem basically with diff numbers

hallow wasp
#

yeah I recommend seeking the best way first

hallow wasp
umbral shuttle
hallow wasp
#

yes just like in algebra 2 you can cancel out things in a system of equations

#

you multiply out the matrix for

#

[2x +7y] = [4]
[2x +6y] = [6]

#

and then just "subtract bottom row from top row"

#

you know its an option when one of the variables is cancellable

#

like 2x = 2x

umbral shuttle
#

damn i see what u mean

hallow wasp
#

hell even if it was like

umbral shuttle
#

way easier

hallow wasp
#

[4x +7y] = [4]
[2x +6y] = [6]

hallow wasp
#

u can say "subtract 2x the bottom row from top row"

umbral shuttle
#

wow ok

hallow wasp
#

thatll give u some constant*y = something

#

solve for y

#

if u need x then u can just plug in for y and isolate x

#

bol on future questions 👍

umbral shuttle
#

like i had a similar one i just did 20 mins ago and it was so much

#

had to solve for x and y tho

umbral shuttle
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zealous yoke
final saddleBOT
zealous yoke
#

can someone help me convert this to a rectangular equation

#

idk how to start

stray rose
#

multiply botjh sides by sint+2cost

#

$r(sint+2cost) = 1$

soft zealotBOT
stray rose
#

does this make sense

#

then distribute r and use the identities that x=rcost and y=rsint

zealous yoke
#

ohh

#

y+2x = 1?

stray rose
#

yeah

zealous yoke
#

i like know the identities and stuff but i can never think of what to do

#

thank you

stray rose
#

in the future find ways to group r together with sin and cos

#

that way you can use the identities

zealous yoke
#

okay tysm

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raw sundial
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.close

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solemn hornet
#

help

final saddleBOT
solemn hornet
#

I need help figure out what to put into this simlarity I have been on it for forever

#

.

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smoky bane
#

Wait what’s the correct path of multiplying?
If I have
3x + 3
Times 5x + 2
——————————-

Would I do 3 times 2 and then 3x times 2 and then 5x times 3 or 3x times 5x next?

robust mulch
#

you do all of those

#

the order doesnt matter, just make sure you combine like terms in the end

smoky bane
#

Oh ok

pliant shore
#

This is how you do it

smoky bane
#

Thx

pliant shore
#

No worries

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sage kindle
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sage kindle
#

I don’t know what i did

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sage kindle
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<@&286206848099549185>

#

Answer

sage kindle
#

how to solve question 3. 4. 5.

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magic ether
#

y''+2y'+2y=0 y(0)=0 y'(0)=pi
is c1=0 and c2=pi?

scarlet sequoia
#

what are c1 and c2? need more context

scarlet sequoia
#

so plug in y(0) = 0 you indeed get that -c1 = 0 so c1 = 0

#

and then compute y'

#

y'(t) = c2e^(-t)(cos(t)-sin(t))

#

but now that y'(0) = pi, it means -c2 = pi...

#

so c2 = -pi

magic ether
#

wait let me see where i messed up

#

ok i havent

#

so basically
pi=-1(c1·1+c2·0)+1(-c1·0+c2·1)

#

pi=-1·c1+c2·1

#

pi=-c1+c2

#

pi=0+c2

#

pi=c2

#

@scarlet sequoia

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scarlet sequoia
scarlet sequoia
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peak sorrel
#

Determine the dimension of the column space of matrix A

peak sorrel
#

Don't know if my calculations are right

urban maple
#

,w rref {{1,-4,-3,-4},{3,4,-9,4},{-7,-7,21,-7},{5,-4,-15,-4}}

soft zealotBOT
urban maple
#

Seems like there may have been some issues in your row reduction

peak sorrel
#

Thank you

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bold jungle
#

In geometry, what does it mean when senθ = 0,60 and cosθ = 0,80? I need the degrees to solve a certain exercise but im not sure what this means

warm ether
#

is that 0.6 and 0.8?

#

it means the corresponding ratios

final saddleBOT
#

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bold jungle
#

Im not quite sure, i know the hyp is 5, so in this case would i just like, cosθ = adj/5,

#

and then adj = 5 . 0,8?

iron coyote
#

yep

bold jungle
#

PHEW, thats a relief

#

In this case tho, is there a way to find the exact angle?

iron coyote
#

inverse cosine i suppose

bold jungle
#

That sounds very disturbing so ill just stick with what the exercise asked me, thank you for helping tho

iron coyote
#

np hype

bold jungle
#

(how do i close this channel again?)

iron coyote
#

type “.close”

bold jungle
#

.close

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faint locust
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glossy pewter
#

Hello
I'm trying to write a bot to play nim perfectly. I'm using multiple heaps with a restriction of only taking 1 or 2 tokens at a time under normal play.
If I do it without a limit my code works perfectly fine however I'm struggling to impose the limit correctly.

I'm following this part on the wiki page, they call it the subtraction game: https://en.wikipedia.org/wiki/Nim#The_subtraction_game
As far as I can tell all I need to do is:

  • Takes all the piles, mod them by 3 (grundy number)
  • Nim sum them by xoring them together
  • Check the total off all the piles after modding them by 3, if equal to 0 then treat the nim sum as 1
  • Find any pile where nimSum xored with pile < the pile count and remove the extra tokens from there

I think that sums up my issue, I'm really not sure what goes wrong. Any help would be appreciated

Nim

Nim is a mathematical game of strategy in which two players take turns removing (or "nimming") objects from distinct heaps or piles. On each turn, a player must remove at least one object, and may remove any number of objects provided they all come from the same heap or pile. Depending on the version being played, the goal of the game is either ...

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@glossy pewter Has your question been resolved?

junior token
junior token
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restive copper
#

wondering if correct

final saddleBOT
primal sierra
#

i don't think either are correct

restive copper
primal sierra
#

wait

#

thats my bad

#

they are right

#

srry

restive copper
#

😭

#

was rethinking my life

primal sierra
#

lol

#

misread the problem

restive copper
#

all good thx anyways

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marsh shuttle
#

hii, this is 8th grade math, don't come for me, but i need help. The first one asks for the green area, and the 2nd one asks for the green area perimeter (has options), could someone help?

glossy pewter
#

You just need to break it into parts.
The end caps are semi circles so put together they are just a circles area. The inside bit is a square - circle
So if you can work out the area/perimiter of a circle and square you got it 🙂

marsh shuttle
#

thanks:)

#

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pearl wraith
#

what is diracdelta(0) is it 1 or infinity

final saddleBOT
pearl wraith
#

because sometimes in discrete it becomes 1

#

ohh wait

#

nvm

#

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weary oar
final saddleBOT
weary oar
#

Just use implicit differentiation right

versed crater
#

Just go for it yeah

final tangle
#

yeh and a crapton of product and chain rule

weary oar
#

Thanks

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long sequoia
#

help me

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late pumice
#

Okay let's see

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soft zealotBOT
#

Flux Fissionist

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novel walrus
#

how is the divisor 1200 when the cost is $1.80

sterile pollen
#

the bottle is 1.2 L, and that costs 1.80

#

dividing it by the size of the bottle you get the price per L

supple jolt
#

1.2 liters = 1.8 pounds
1 liters = x pounds

#

divide the 2 equations and find x

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novel walrus
#

1.80 is the divisor

supple jolt
#

well how would you find x

novel walrus
#

by dividing

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novel walrus
#

.reopen

final saddleBOT
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novel walrus
#

@supple jolt by dividing right

supple jolt
#

yeah

#

set up fractions

#

simply draw a fraction line between the first and second equation

soft zealotBOT
#

Oogy Boogy

novel walrus
#

ok

#

how about this one

#

i divided 54 by $8.10 which gave me 0.15

and then divided 1000 by 1300 which gave me $13

supple jolt
#

540 g = 8.10 dollars
1 kg = x dollars

#

right?

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novel walrus