#help-36

1 messages · Page 110 of 1

pliant shore
#

That if 1 minute costs you 10 dollars, 5 minutes costs you 50

robust fulcrum
#

b dollars -> a minutes
1 dollar -> a/b minutes

glass ember
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so its C times the cost per minute?

pliant shore
#

Yes

robust fulcrum
#

c dollar -> ca/b minutes

robust fulcrum
glass ember
#

would the cost per minute be B/A?

robust fulcrum
#

thats called unitary method

pliant shore
robust fulcrum
pliant shore
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If you check the units it has units dollars per minute

glass ember
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why not A/B tho

pliant shore
#

Misread as a/b sorry

pliant shore
robust fulcrum
#

check the units

pliant shore
#

Wait the cost per minute yeah
Sorry we're tired

glass ember
#

but lets say the cost for 5 minutes is 10 dollars

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for 1 minute it would be 2 dollars

pliant shore
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Yeah exactly yep

glass ember
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i did B/A

robust fulcrum
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or 2 dollars for 1 minutes

pliant shore
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So that is B/A yes

robust fulcrum
#

1 dollar for 1/2 minutes

glass ember
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ohhh

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there is a difference between 1 dollar per 0.5 min and 1 minute for 2 dollars

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like

robust fulcrum
#

let me send you by doing it in paper

glass ember
#

okay

pliant shore
#

The units are different

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Depends if you're trying to find the number of dollars or minutes

robust fulcrum
#

No further discussion

glass ember
pliant shore
#

Yep so you would use the second one

robust fulcrum
glass ember
#

okay

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thanks

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got it

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.close

robust fulcrum
#

np

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crude tendon
#

Calculus: need help with if sum of a series converges or not
the series is: sinx + sin^3(x) + sin^5(x) + ... where x tends to pi/2.

I am getting two different results by 2 different methods:
method 1:
since in this case my common factor is less than 1, I can use the infinite GP sum formula which gives me the result positive infinity.

method 2:
if first, I take the series to be till n terms and use GP sum formula, it gives me 0/0 form. Applying L-hospital to it gives me the sum to be:
n*((sin(x))^(2n-2))
where x tends to pi/2 and n tends to infinity
this gives the sum to be 0 as anything less than 1 to the power 0 tends to be 0.

yelp

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tranquil pine
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tranquil pine
#

how B = 9 ?

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nvm

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gloomy thistle
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prime mortar
#

Isn't that Like f(-x) odd function reflection along the origin ?

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I don't know transformations tbh

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lunar skiff
# gloomy thistle

if u have a point (x, y)
what will it transfer unto if u rotate ut 180 around origin

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crimson sparrow
#

Let ABCDE be a convex pentagon with side lengths a, b, c, d, and
e respectively on the sides AB, BC, CD, DE, and EA. Suppose it is an inscribed pentagon, meaning there exists an inscribed circle, denoted by k, which is a circle inside the pentagon and touches all of its sides. Let P, Q, R, S, and T be the points of tangency on the respective sides.
Express the lengths of tangent segments drawn from the vertices of the pentagon to circle k in terms of the side lengths.

final saddleBOT
#

@crimson sparrow Has your question been resolved?

wintry talon
#

Draw the shape and set one of the tangent distances to x

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Then, you progress around the shape. Knowing the power of a point theorem, two tangents draw to a circle from the same point have the same length. Therefore, you can simply solve around the shape

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We get that $e-d+c-b+a-x=x$. You can solve this for x and find the rest.

soft zealotBOT
#

AkishBrabus

wintry talon
#

@crimson sparrow

crimson sparrow
#

Thank you very much, I had a hunch yesterday to maybe try it like this, but got distracted.

#

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jaunty adder
#

help

final saddleBOT
jaunty adder
#

i need an explanation on how to graph these

nova iron
#

log_2 (x) and 2^x are inverse functions

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if you can draw one then you can reflect that over y = x and get the other one

jaunty adder
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so the first y point for y=2x is 0.25?

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correct me if im wrong

nova iron
#

to fill this

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oh i didn't see what you meant

nova iron
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jaunty adder
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dire gale
#

What is the easiest way to solve squares by hand? I’m struggling with squares and square roots and I want to be able to do it by hand for my Math 8 SOL (pre-algebra).

warm python
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wdym?

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like finding 17^2?

tranquil pine
dire gale
tranquil pine
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once you get good at it, you can find squares within 3-4s of 2 digit numbers

warm python
#

you could write it as the sum of simpler squares like (10+7)^2

desert mantle
#

well the early ones you can just remember

warm python
#

and simplify from there

dire gale
#

I’ve had to use Desmos on the practice problems

tranquil pine
#

if yall pause for a while i'll cook

dire gale
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dire gale
whole pecan
#

For 13^2 I just do 13x13 = 13 x 10 + (13 x 3)

dire gale
#

So for the other method I got 109?? Cause 10^2 is 100 and 3^2 is 9

whole pecan
#

Idk but that’s wrong

#

It’s 169

dire gale
elder aurora
#

yes conflicts is correct

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13^2=169

dire gale
#

Yeah that works and it’s easy

tranquil pine
#

@dire gale

elder aurora
#

smart!!!

dire gale
#

Thank you

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How do I find it in reverse? From square root to square?

elder aurora
#

hey I joind this group because I got a C- in math I am in 8th grade can you guys help me so I can pass

#

next time

dire gale
#

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dull egret
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dull egret
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need some help with this one

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first, im

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not sure why we're using induction for finite domain

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and second how we do specificy a choice function for picking which f(i) in H(i)

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can we just say any? im not sure

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#

@dull egret Has your question been resolved?

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@dull egret Has your question been resolved?

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lime shell
#

Trig simplification help/explanation

final saddleBOT
lime shell
#

I am attempting to perform an operation and simplify the result. I am given cot x (sec x - tan x). First I identified what identities these belonged to so I did cot x = cos/sin; sec x = 1/cos; tan x = sin/cos, I can get to that point every time. However, the part where I am stuck is when it comes to simplifying all of that. I have the answer which is csc x -1, I guess I am just looking to better understand how they simplify: cos x/sin x (1/cos x * sin x/ cos x) --> csc x -1. I understand that 1/sin x is csc

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#

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vale reef
#

For this have they multiplied w transpose and w and (c transpose and c ) separately

vale reef
#

Cause I don’t see how that works

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To get Cw

desert mantle
#

norm(y)^2=y^T y

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here for y=Cw

vale reef
#

What’s norm

desert mantle
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y^T=(Cw)^T=w^T C^T

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$\norm{y}$

soft zealotBOT
#

Denascite

vale reef
#

What does it mean aswell

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Ohhhh

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Oh I get ur working

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Hm I guess I’ll just learn that

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Thanks

#

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heavy grove
#

I need to maximize angle beta

final saddleBOT
heavy grove
#

b and a are constants

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I can change h

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I wrote tan(beta+theta)=(b+a)/h

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That’s where I’m stuck

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swift lynx
#

im curious why the answer would turn out to be -10 instead of 0

tiny gorge
#

what was your reasoning for 0?

swift lynx
#

so basically the way I did it was by simplifying the expression

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$\frac{-(x+5)(x-5)}{x-5}$

soft zealotBOT
#

OneWhoKnocks

tiny gorge
#

yep that's fine

swift lynx
#

mm

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so then

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$-(x+5)=0

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-10

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ahh okay I see

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so it is -10

tiny gorge
#

yep

swift lynx
#

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heavy leaf
#

im looking at the solution of one homework sheet and i am stuck with one step of the solution. Its about Gauss-Lobatto quadrature

heavy leaf
#

With the Gauss quadrature it is possible to calculate integrals over polynomials up to degree 2n + 1
on the interval [-1, 1] exactly. Nevertheless, it can be useful to calculate one or
several quadrature points from the outset. Often the boundary points
are often chosen. This results in the Gauss-Lobatto quadrature. To construct this
quadrature formula, consider a polynomial

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of degree 2n - 1 and write

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with r, s ∈ R and q2n-3 ∈ P2n-3. One then considers

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As in the case of the Gauss quadrature, we can form an orthogonal system with respect to the weight
function

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So at first. We proved that

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is a scalar product on C([-1, 1]).

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Where im stuck is the following question:

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Based on this scalar product, construct a quadrature formula that calculates the
following integral exactly:

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We also got one Hint: Think about the degree of exactness of the quadrature constructed with the scalar product.
product and apply it at a suitable point. The weights
or supporting points do not have to be calculated explicitly.

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So the given answer of this question is:

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Let Pn-1 ∈ Pn-1 be an orthogonal polynomial which, with respect to the scalar product (-, -)w is perpendicular to Pn-2
Note: Because w(x) = (1 - x2) this results (except for one prefactor) in the
Gegenbauer polynomial with α = 3/2, i.e. Pn-1 ≡ G3/2
n-1 ≡ L′
n, where the latter is the
derivative of the Legendre polynomial.
The zeros x1, . . . , xn-1 of Pn-1 are simple, real
and lie in (-1, 1). With ˜w1, . . . , ˜wn-1 we denote the corresponding weights
of the weighted quadrature Iw,n-2. According to Jacobi's quadrature theorem, the
degree of exactness of Iw,n-2 is just 2(n - 2) + 1 = 2n - 3, and in particular

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Insert results in

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now my question is the last equation of the pic above

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why is the wn and w0 the two weights

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the original homework is in german. I can also send a pic when someone can help

final saddleBOT
#

@heavy leaf Has your question been resolved?

final saddleBOT
#

@heavy leaf Has your question been resolved?

final saddleBOT
#

@heavy leaf Has your question been resolved?

final saddleBOT
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@heavy leaf Has your question been resolved?

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@heavy leaf Has your question been resolved?

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tranquil pine
#

I'm trying to understand the significance of determining the linear independence of functions outside of considering vectors explicitly. Say, for example, we want to determine if the functions [
f_1(t) = 1 \q f_2(t) = t \q f_3(t) = t^2
]
are linearly independent on some interval $I$. Usually in linear algebra, if we have a set of linearly independent vectors that implies that they span $\R^n$ with $n$ being the amount of vectors we have, but how does that extend when considering the linear independence of functions rather?

soft zealotBOT
royal gust
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These span some function space

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This space has dimension 3, as your set is a basis

tranquil pine
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are they similar to a vector space

royal gust
#

Fair, my bad I shouldn't have thrown in that wording without making myself clear

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It is just a regular vector space

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Well, at least we can consider it as a vector space

tranquil pine
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(just so this isnt some weird XY i ask because of this)

royal gust
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You'll see "function space", "eigenfunction" etc when we are considering functions as vectors.

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But these are really just vectors

tranquil pine
#

okay thats very interesting

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so how do you go about determining the linear independence here

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i mean usually with vectors u Gaussian reduce or check if det is nonzero

royal gust
#

So any solution to a linear, homogenous DE is a vector space. The dimension of that vector space is the same as the order of the DE

tranquil pine
#

assuming linear independence i suppose?

royal gust
#

Like, you want to see a proof of theorem 4.1.3?

tranquil pine
#

if it isnt too insane i don't mind, but i guess i also would like to see how it can be applied

royal gust
#

I mean theorem 4.1.3 isn't telling you what the basis vectors are, just that they exist

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It's up to you to find a set that's linearly independent and prove it

tranquil pine
#

i mean I think the (->) case is simple

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it being a fundamental set og solutions implies that the Wronskian is nonzero by definition

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so the system must only really have the trivial solution

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Well im skipping proving thr part where a nonzero determinant implies linear independence lmao

royal gust
#

Sorry, I should have read closer before. I think I am confused. What's a "fundamental set of solutions", if not a linearly independent set of solutions?

tranquil pine
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let me fish out the proper definition but im pretty sure it's said in the way it is because the book doesn't expect you to have linear algebra knowledge

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this "theorem" is very funny to me because it's just like using the identity catthimc

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but yeah i guess thats it KekHands

royal gust
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The fact that solutions to DEs form a vector space isn't that crazy. The derivative is linear, so it's pretty natural that solutions add to make solutions

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The dimension of the space being the order of the DE is nuts to me, though

tranquil pine
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is it?

royal gust
#

Tells you exactly when you're done finding solutions

tranquil pine
#

oh i mean i guess that's a consequence of the existence and uniqueness theorem?

royal gust
#

You know what? I actually don't know why this works. Probably something-something factoring out solutions

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I think I'll look

tranquil pine
#

aight much appreciated

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I'll brb a bit since im on my way back to my room

royal gust
worldly vale
#

Heuristically it's not too surprising that the dimension is n. If we "integrate n times" we'll have n constants I.e. degrees of freedom

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But I wouldn't know how to prove it in general just vibes

tranquil pine
#

aight that solution is understandable

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for me at least

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but okay back to the topic

tranquil pine
# soft zealot

how do u verify that those functions span the interval -infty < t < infty

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for eaxmple

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.close

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tranquil pine
#

(i think its ok now thanks yall)

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azure dew
#

hiya, im needing to do a little math for a program im making and can't figure out how to get it to work the way i'd like it to.

ive got a list of chances (not % but just a list of numbers like [ 1, 2, 4, 8, 16, 32, 64 ]), and i need to have the lower and higher numbers tend towards the midpoint while having a "multiplier" that would make it more quickly tend towards the midpoint, i'd also like it if the numbers further from the midpoint tended towards it quicker

final saddleBOT
#

@azure dew Has your question been resolved?

azure dew
#

<@&286206848099549185>

neat oyster
#

Sounds like simple harmonic motion

elder halo
azure dew
#

ohhh that could work actually yeah

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didn't think of that

neat oyster
#

Lol we have force etc in physics which helps in determing accelerations and the end points...the farther you are more is the acceleration guided towards centre. But I don't really have any i dea how could be based completely on mathematics

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Perhaps this hought process may help you a bit

elder halo
#

Heinsberg uncertainty principle

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If it's just abt finding location it might work

neat oyster
#

Can you eplain a bit?

elder halo
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Like if uk

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The momentum

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U can fig out distance

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But it won't be applicable to this question ig

neat oyster
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Aghh..Yeah I understand it...but I don't think it will help here

neat oyster
azure dew
#

i think honestly i can do something just with sin and map the list of numbers within the bounds of pi

elder halo
#

Which lv question is it

azure dew
#

uhhh its sorta just a personal programming project im working on, but i can't figure out the math for how to get it to work properly

elder halo
#

def adjust_list(numbers, midpoint, multiplier):
adjusted_numbers = []
for num in numbers:
distance_to_midpoint = abs(num - midpoint)
adjustment = distance_to_midpoint * multiplier
if num < midpoint:
adjusted_num = num + adjustment
else:
adjusted_num = num - adjustment
adjusted_numbers.append(adjusted_num)
return adjusted_numbers

numbers = [1, 2, 4, 8, 16, 32, 64]
midpoint = sum(numbers) / len(numbers) # Calculate the midpoint
multiplier = 0.1 # Adjust this value to control the rate of convergence

adjusted_numbers = adjust_list(numbers, midpoint, multiplier)
print(adjusted_numbers)

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Maybe this might help

#

Chat gpt 😅

azure dew
#

writing it in ts aha

elder halo
#

Turbo script

azure dew
#

typescript

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its pretty good lang

elder halo
#

Ohh

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Cool out of my expertise

azure dew
#

im meant to be learning java and python in uni as well but... they're a bit slow at teaching first years

elder halo
#

I only know little bit of basics of c++

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And it was hard asf

azure dew
#

c++ is fun but i only ever use it to write game cheats

elder halo
neat oyster
#

Well I wanted to clarify, universities are after 12th grade correct?

elder halo
#

Yea

azure dew
#

ya

neat oyster
#

So colleges and unis are diff?

azure dew
#

but i don't do much maths doing a cs degree

elder halo
#

I just finished 11 rn so I can't be blamed for not knowing and shit we were recommending physics and chem for programming

elder halo
azure dew
neat oyster
azure dew
#

in the UK, where i live, we only have universities and college is pre-uni (year 12 and 13)

elder halo
neat oyster
elder halo
azure dew
#

grade

neat oyster
elder halo
#

Ohhh

neat oyster
elder halo
#

She genius

elder halo
#

Cs are the top course in every uni tho idk abt un it's hard asf to get into it in india

neat oyster
# azure dew yep

How's your exp? there is a lot of rush in cs category here ngl

neat oyster
azure dew
#

well, i've been programming independent from academic study for 5 years now so everything they teach me is really easy and even 3rd year knowledge is... quite easy

neat oyster
elder halo
#

Obv brother

#

Sent frnd req

neat oyster
elder halo
azure dew
#

ethical if they give me money A_HuTaoWink

neat oyster
neat oyster
#

Sent ya friend req!

elder halo
#

Where does hacking stand in coding

#

Can u tell me the ans

#

Like i learned c++ but idk how to hack

#

Is it a different concept or something

azure dew
#

hacking is an extremely broad term and within the cyber security community its not really called hacking

elder halo
#

Then

azure dew
#

usually we call it reverse engineering since we're taking apart programs and finding vulnerabilities in them

elder halo
#

How long it usually takes

#

Normally

azure dew
#

i've found a couple vulnerabilities in games but usually the higher paid ones are within game companies main infrastructure, not the game

elder halo
#

My cs man told like 2-3 months are needed to find loopholes and all

azure dew
neat oyster
azure dew
#

i actually have a vulnerability that i haven't disclosed to the papermc development team for a movement exploit aha

#

its been in thir server software for about 3-4 years?

elder halo
neat oyster
#

I have very less interest in coding or computer related stuffs😂. Ya'll continue..I'll join you later!

azure dew
elder halo
#

Oo

azure dew
#

im doing more ethical stuff with minecraft development recently though

elder halo
#

U can sell it then right

azure dew
#

yeah i could sell them

elder halo
#

I got a nice business plan

#

Which lang do think got the most amt of prospect in future

azure dew
#

honestly that doesn't really matter too much for me, i've learnt enough langs now that i can transfer most of the skills from each if i just spend a month or two learning a different lang

elder halo
#

I don't wanna be clean slate when i go to uni gotta flex when I reach there

azure dew
#

realistically no lang is the best, it depends on what you want to go into and what the industry uses

#

java is massively used just because its old (even if its not that good)

#

anyway we should probs stop using the help channel for non-help things 😛

#

.close

final saddleBOT
#
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elder halo
final saddleBOT
#
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tranquil pine
#

im trying to solve the ODE [
2y'' + (x+1)y' + 3y = 0, \q x_0 = 2
]

soft zealotBOT
tranquil pine
#

So so our recurrence relation has conditions $a_2 = 0, a_1 = 0, a_0 = 0$ and then the recurrence relation itself is [
2(n+2)(n+1)a_{n+2} + 3(n+1)a_{n+1} +(3+n)a_n = 0
]
So how do I evaluate this?

soft zealotBOT
tranquil pine
# soft zealot

u dont have to look at this, I just put it there in case my recurrence relation is sus

rustic wedge
pliant shore
#

Yep you will get a quadratic equation for your characteristic equation

tranquil pine
#

But like this is nonlinear no?

rustic wedge
pliant shore
#

Wolfram Alpha also gives me an answer using erfi(x) for your original ODE

tranquil pine
pliant shore
#

Fair enough

rustic wedge
tranquil pine
soft zealotBOT
rustic wedge
#

bruh u have linear too then no

tranquil pine
#

n varies

#

c is a constant

rustic wedge
#

then why did u put c_n bruh

hollow iron
#

@tranquil pine are u learning from a book?

tranquil pine
#

so i answered that by showing what linear is

hollow iron
#

if you're gonna get a nonlinear weird recurrence every question, surely there's a way you are supposed to solve them

rustic wedge
tranquil pine
#

the solution steps are pretty much the same in the sense u retreieve a recurrence relation and solve it

#

its 11

hollow iron
#

Wronskian??

#

what kind of secrets are you keeping from us

#

so there IS a method to solve these or what

tranquil pine
#

the wronskian is just to verify if our solutions are linearly independent so dont worry about that

#

like

#

the steps are the same i can show an example if u want

hollow iron
#

ok show

nova iron
#

and is that green background by default?

rustic wedge
#

qylo try this:
$$ \mathcal \frac{df}{dx} = \sum_{k=1}^{\infty} \frac{(-1)^{k-1}}{k}f^k(x)$$

hazy hemlock
#

..

rustic wedge
#

<@&268886789983436800>

tranquil pine
rustic wedge
tranquil pine
hollow iron
#

they're literally just trying out values

#

so that's what you should do

nova iron
#

thanks

soft zealotBOT
#

rak³en
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

rustic wedge
#

wtf i happening to my latex

hollow iron
#

tf

nova iron
#

tf

inland kettle
#

heh?

solar glade
#

$q$

soft zealotBOT
#

Samuel

rustic wedge
#

$\frac{df}{dx}$

soft zealotBOT
#

rak³en

rustic wedge
#

wth

#

$$ \frac{df}{dx} = \sum_{k=1}^{\infty} \frac{(-1)^{k-1}}{k}f^k(x)$$

#

mb

soft zealotBOT
#

rak³en

solar glade
#

Lol

rustic wedge
#

shouldnt have used \mathcal

hollow iron
#

where did you get this from

rustic wedge
tranquil pine
# soft zealot

Something is iffy here. a_2 shouldnt be an independent term

rustic wedge
tranquil pine
#

ah actually maybe its fine

hollow iron
#

wouldn't you?

tranquil pine
#

yeah rather

#

its

#

,, 4a_2 + 3a_1 + 3a_0 = 0

soft zealotBOT
hollow iron
#

oh ok

tranquil pine
#

thats our actual condition, but like, you need to

#

decide on what are the independent terms

hollow iron
#

well all I can say is that I think you're supposed to just find the pattern

tranquil pine
#

aight will do

#

and yeah i guess u express it as

#

a_2 = -3/4 a_1 - 3/4 a_0

#

so like

#

a_1 and a_0 are independet

#

and the terms are expressable using those

#

so we like

#

,, a_n = \4{-3(n-1)a_{n-1} - (n+1)a_{n-2}}{2n(n-1)}, \q n \ge 3

soft zealotBOT
rustic wedge
#

btw qylo solving for a_n and putting it into ur definition of y, u dont get the standard series for erfi

rustic wedge
tranquil pine
#

you dont?

rustic wedge
#

some manipulation might be at play tho

tranquil pine
#

i mean it doesnt seem to be JUST erfi so i can see why the series solution might differ from what erfi(x)'s series alone looks like?

rustic wedge
#

there doesnt seem to be anything that could get rid of the n! in the denominator of erfi(x) from that..

pliant shore
#

Anyways WA sometimes writes stuff in a very weird form

rustic wedge
#

nvm am just being dumb

tranquil pine
#

the first few terms of the solution seem like they coincide

#

idk how to make WA give u series solutions

#

it gives something messed up because its trying to calculate it explicitly

rustic wedge
rustic wedge
final saddleBOT
#

@tranquil pine Has your question been resolved?

#
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pulsar wind
#

How do they know that fn converges to f point wise?

desert mantle
#

well thats what the assumption says

#

converging mu-a.e. means pointwise a.e.

pulsar wind
final saddleBOT
#

@pulsar wind Has your question been resolved?

desert mantle
#

well they are a bit imprecise

#

when doing measure theory you basically always mean a.e.

#

null sets dont matter

pulsar wind
desert mantle
pulsar wind
#

Oh yes, I kept thinking to normal point wise convergence not pointwise a.e

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#

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bronze oxide
#

Main issue is how do I rotate, scale factor, reflect etc from a point not in the triangle.

bronze oxide
#

Also what's the x+y = 6 line

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#

@bronze oxide Has your question been resolved?

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#

@bronze oxide Has your question been resolved?

bronze oxide
#

.close

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stable inlet
#

Did i answer this question correctly

final saddleBOT
stable inlet
crisp epoch
#

the 2pi(k)/5 part seems about right

#

haven't learned about the second half of the problem though

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#

@stable inlet Has your question been resolved?

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rose pulsar
final saddleBOT
rose pulsar
#

I am having trouble finding the u, whether it be 3x or cos^2(3x)

royal gust
#

You'll need to open up your trig identities for this integral

royal gust
#

I wouldn't go with that identity, since now you need another identity

#

Try an identity that removes the ²

final saddleBOT
#

@rose pulsar Has your question been resolved?

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cloud portal
#

How do i take the derivative of this

final saddleBOT
rotund badge
cloud portal
#

I think i found it

#

Btw what happens if you have yet another function like c(x)

rotund badge
#

You suffer

cloud portal
#

Aight thanks

and with a fourth and fifth and so on the same logic?

rotund badge
#

you can think of a(x)b(x)c(x) as a(x)d(x) where d(x) = b(x)c(x)

#

So the derivative would be a'(x)d(x) + a(x)d'(x)

#

but then d'(x) = b'(x)c(x) + b(x)c'(x)

#

and so it keeps being recursive

cloud portal
#

.clsoe

#

.close

final saddleBOT
#
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cloud portal
#

Why do derivatives work

I get what they do and that there are different rules achieve it with but can someone please explain

final saddleBOT
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obtuse pagoda
final saddleBOT
obtuse pagoda
#

Could someone help

lucid marsh
#

whats the question

obtuse pagoda
lucid marsh
#

my approach to this would be

  1. angle adding formula
  2. black magic algebra and trig identities
  3. get answer
#

not sure what the answer is tho

rotund badge
#

I would just bring out the table and see what angle gives you cos = 2sin lmao

obtuse pagoda
broken dock
# obtuse pagoda

In the first step you're using the double angle identity, but there's no "double angle" here.

obtuse pagoda
#

Oh 💀

#

I'm so lost 😭

broken dock
#

Just apply the angle sum identity to both sides and simplify.

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#

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fleet cove
#

Any help with part c?

final saddleBOT
#

@fleet cove Has your question been resolved?

fleet cove
#

<@&286206848099549185>

cedar bobcat
fleet cove
#

it does

#

but umm

#

i think i need to find h

fleet cove
#

how do i find h?

#

<@&286206848099549185>

fleet cove
#

@unkempt moon

jolly tapir
#

the face AEHD is a square and so is BFGC

fleet cove
#

i alr considered that

#

but i still dk how to find h lol

jolly tapir
#

what exactly did you consider

fleet cove
#

that this shape is a cuboid

jolly tapir
#

AD=2acm

#

this is on the screenshot

fleet cove
#

ad is not 2cm

#

yea ad=2acm

#

dc = bcm

#

we know a and b

jolly tapir
#

so we know AD

#

what do we know about GC in relation to AD

fleet cove
#

earlier u said AEHD is a square

#

it's not a square

#

idk the relationship between GC and AD

jolly tapir
#

wait a minute

#

can we assume the information given from the first question applies to the second

fleet cove
#

i think we can

#

what information do you want to assume tho?

jolly tapir
#

you can now solve for the volume of the paperweight

#

and given that a and b are still the same you can find the third edge

fleet cove
#

The volume of the paperweight will be $2ab^2 + \frac{1}{2} \pi a^2b$

soft zealotBOT
fleet cove
#

Volume = $2(6\sqrt{5})(10\sqrt{3} - 6\sqrt{5})^2 + \frac{1}{2} \pi (6\sqrt{5})^2(10\sqrt{3} - 6\sqrt{5})$

soft zealotBOT
fleet cove
#

now what?

soft zealotBOT
jolly tapir
#

assuming the volume of the new shape is equal to that

#

find the third edge by division

#

(i really hope when they said "melted down" they meant retains the same volume, otherwise I'm not sure how you'd solve this)

fleet cove
#

oh yea

#

i could try that

#

originally, by "melted down"

#

i thought they just like melted away a piece of the original shape

#

as if they completely removed the semi-cylinder

#

and a small portion of the cuboid

jolly tapir
#

they probably could've clarified it but that's what they meant i think

#

otherwise its back to me assuming it's a square cuz how else would you find h

fleet cove
#

that means the design of the question is poor, no?

jolly tapir
#

just a little bit yea breadpensive

fleet cove
#

so i get h being 14cm

#

and i get angle GAC being about 28 degrees

#

thx for the help

#

.close

final saddleBOT
#
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boreal robin
final saddleBOT
boreal robin
#

Need help solving this integral

lavish river
#

take the sub u = (x-2)/2
use 1 + (sinh u)^2 = (cosh u)^2
finally use the def: cosh u = (e^u + e^-u)/2

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#

@boreal robin Has your question been resolved?

lavish river
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@boreal robin Has your question been resolved?

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raven obsidian
#

Hi, when testing the rational root theorem with synthetic divison and none of the rational roots give a remainder of zero (remainder theorem stating r= 0 means k from x- k is a factor), how do i find the real numbers?

raven obsidian
#

my head genuinely hurts testing all positive and negative numbers that i cant recall other ways to do this

raven obsidian
#

+-{1, 2, 4, 7, 8, 14, 28, 56}

#

I started by putting them in for f(x), since the theorem states that k of (x-k) is a factor, so if the answer results in 0, it works

#

but none of them worked

grand kiln
#

I graphed it and some of them work

raven obsidian
#

watching the given guide video isnt helping because they have numbers that work

raven obsidian
grand kiln
#

maybe your arithmetic was wrong somewhere

raven obsidian
#

give me a point/x-value that worked for you so i can try it again

grand kiln
#

-2 and -4 should work

raven obsidian
#

no way it worked, where tf did i go wrong

final saddleBOT
#

@raven obsidian Has your question been resolved?

raven obsidian
#

.close

final saddleBOT
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carmine thistle
#

Log Proofs;

If a^x=b^y=c^z=d^w=K , (a does not equal 1) , show that log(base a)abcd=x(1/x+1/y+1/z+1/w)

I have first solved for a,b,c, and d. a=k^1/x , b=k^1/y , c=k^1/z , d=k^1/w . I've tried substituing some things into different places, but I really just need some help on the next step, where to take the equation next.

dry light
#

Where did the x come from

#

I mean lemme tjink

#

Because I know a^x b^y c^z d^w = K^4

#

Oh wait I'm dumb I see where the x is from lol

#

Lemme cook

#

Actually well

#

Hold on

#

Eh nvm

spring haven
#

.tex log rules

dry light
#

i was thinking and then I didn't

spring haven
#

I forgot the command

dry light
#

,tex log rules

spring haven
#

Guess I’ll have to write this out by hand

soft zealotBOT
#

Peter Griffin

dry light
#

Fuck man

spring haven
#

No

dry light
#

.w log rules

#

,w log rules

spring haven
#

$\log_a(abcd)=\frac{\log_k(abcd)}{\log_k(a)}$

soft zealotBOT
#

kheerii

spring haven
#

Use this

dry light
#

Or ln(k)

dry light
soft zealotBOT
#

Peter Griffin

carmine thistle
#

huh

dry light
#

Actually this should work with what you've also been doing

carmine thistle
#

im uh

#

not quite at that level

#

i dont think

#

im in algebra 2

spring haven
#

They just took the log on both sides

carmine thistle
#

and my teacher has really just been giving us problems to tinker with one side or the other so that the given looks like the proved

#

Im trying to digest what those text thigns are

#

take the log on both sides

#

that is a familiar thing

dry light
#

Well I'm just trying different things

#

I'm legit lying in bed lol so like i cannot grab paper and pencil

carmine thistle
#

Im thinking i substitute what i have for a b c and d into the log_a(Abcd)

#

but im not sure what good that would do me

#

My teacher generally wants us to solve the equations step by step, by doing something to one side of the equation until it looks like what we are trying to prove

dry light
#

Hm

carmine thistle
dry light
#

Well let's look at what you've done so far

#

a = K^(1/x), etc etc

#

What i am seeing is that if you take the log base A of both sides

#

For all four

#

You get

spring haven
#

You can’t really do this without it

#

I mean, you can

#

But it’ll be more complicated

carmine thistle
#

i see

#

I interpereted that wrong then

#

my mistake

spring haven
#

Write $abcd=K^{1/x+1/y+1/z+1/w}$

soft zealotBOT
#

kheerii

carmine thistle
spring haven
#

You already got the answer on the second last line

#

Just take an x common from all the terms

carmine thistle
#

erm

#

elaborate please

spring haven
#

You got 1+x/y+x/z+x/w

carmine thistle
#

and im also not entirely sure how i got there

#

So 1 + x/y + x/z +x/w = x(1/x+1/y+1/z+1/w)?

#

wow

#

im very tired

#

and the more i look at this problem the less i understnad

#

and im not really solving

#

im proving something is equal to something else

#

why is a#1 important

final saddleBOT
#

@carmine thistle Has your question been resolved?

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ivory vessel
#

i have a doubt

final saddleBOT
ivory vessel
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does there exist a formula that can calculate the length of a sine wave

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i tried deriving it myself but im stumped, i can only calculate the area, but not the length

terse siren
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length?

ivory vessel
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yes

terse siren
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as in line integral?

ivory vessel
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is that what its called?

terse siren
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not sure

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but you do need an integral

distant ridge
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arc length?

terse siren
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yeah

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that

ivory vessel
formal trail
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arc length of a curve $y = f(x)$ between $x=a$ and $x=b$ is [ L(a,b) = \int_a^b \sqrt{1+(f'(x))^2} , dx]

soft zealotBOT
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pnoןɔ

distant ridge
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if you need it with respect to time

formal trail
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unfortunately such an integral is not elementary

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it falls into a category called "elliptic integrals" (named because they can arise from calculating the arc length of ellipses)

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,w arc length of sin(x) between 0 and pi

soft zealotBOT
ivory vessel
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holy hell

formal trail
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The complete elliptic integral of the second kind, illustrated above as a function of k, is defined by E(k) = E(1/2pi,k) (1) = pi/2{1-sum_(n=1)^(infty)[((2n-1)!!)/((2n)!!)]^2(k^(2n))/(2n-1)} (2) = 1/2pi_2F_1(-1/2,1/2;1;k^2) (3) = int_0^(K(k))dn^2(u,k)du, (4) where E(phi,k) is an incomplete elliptic integral of the second kind, _2F_1(a,b;...

ivory vessel
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i see thank you sir for resolving my doubt

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god i fucking wish my math sirs taught me arc lengths for hours

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.close

final saddleBOT
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Channel closed

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final saddleBOT
#
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sacred lynx
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F(g(x)+3)=g(f(x)-3) need to solve this equation if f(x)=3x+1 and g(x)=2-x

lunar skiff
lunar skiff
sacred lynx
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Ok wait il let you know what i get

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So far i got f(5-x) and g(3x-2)

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Do i need to remove f and g now?

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@lunar skiff

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Wait i think its wrong

lunar skiff
lunar skiff
sacred lynx
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how tho im kinda confused

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g(6-3x-2)?

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anf f(5-3x+1)

lunar skiff
sacred lynx
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no wait let me rewrite it

lunar skiff
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g(f(x) -3) = g((3x+1) -3)
= g(3x -2)

sacred lynx
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welll i did that i just need to get rid og g now

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3(2-x)-2

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right?

lunar skiff
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the g part or the f part

sacred lynx
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g(x)=2-x this

lunar skiff
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this is what u ended up with ,right

f(5-x) = g(3x -2)

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lets try the left hand side, the f part

lunar skiff
sacred lynx
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16-3x

lunar skiff
sacred lynx
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and 4-3x

lunar skiff
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yepp

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but...

sacred lynx
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but thats not true

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we didi something wrong

lunar skiff
sacred lynx
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yes

lunar skiff
sacred lynx
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its the same

lunar skiff
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no its different, f and F is different things

sacred lynx
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both are f

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my keyboard wrote F

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its suppost to be f

lunar skiff
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there us something worng with the question

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the math is correct

sacred lynx
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coud the answer be that

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?

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that there is no solution?

lunar skiff
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maybe, if u ended up with a true equation like 4 = 4, with no x in it, we would say that there is an infinite number of solutions

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but instead we got 16 = 4 which is not correct

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so here there is no solution

sacred lynx
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ok

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can you help me wit another problem?

lunar skiff
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alright

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it would be easier if u could send a picture of the question, instead of just typing the whole thing

sacred lynx
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the pool using the first pipe fills up in 30 minutes with the second pipe it fills up in 20 minutes . what time would the amount of water be the same if we turn the first one ate 9 am and the second one ate 9.05 am

sacred lynx
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you wouldnt udnerstand

lunar skiff
sacred lynx
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30/x?

lunar skiff
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lets divide the pool into 30 part

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then it can fill 1 part in 1m, right?

sacred lynx
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ok

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x/30?

lunar skiff
sacred lynx
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second is x/20

lunar skiff
lunar skiff
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now since the two pipes didnt start at the same time

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we have first to know how much the poll is filled during the first 5 minutes

sacred lynx
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how?

lunar skiff
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x/30, tells u how much of the pool is filled during x minutes

sacred lynx
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5/30

lunar skiff
sacred lynx
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1/6

lunar skiff
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now we need to know hiw much time is needed to fill up the rest of the pool using the two pipes together

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what the equation that tell u how much is filled using the two pipes?

sacred lynx
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add them

lunar skiff
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yes

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add them and equal them to the rest unfilled space

sacred lynx
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add what tho

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x/30+x/20=1?

lunar skiff
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cuz x/30 and x/20 is how much is filled in x minutes

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and when u add them up u get the total amount

sacred lynx
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do i need to replace x with something?

lunar skiff
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x is the time

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thats what u need to find

lunar skiff
sacred lynx
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1/6

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insted of 1?

lunar skiff
sacred lynx
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5/6

lunar skiff
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yes

sacred lynx
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x is 10

lunar skiff
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yep

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then what is the total time needed

sacred lynx
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so thast the answer

lunar skiff
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look, u have two stages, the first is when u have 1 pipe only, and the second u have 2 pipes

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u need to get the time of each stage and add them up

sacred lynx
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there are no 2 pipes

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its always seperate

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fist one we turn on at 9am ans the second one in a seperate pool ate 9.05

lunar skiff
sacred lynx
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Yea 2 pools

lunar skiff
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in this case its the same approach

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we stll know that the first pool would fill up to 1/6 of its volume in 5 minutes

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so one has 1/6 and the other is still empty

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so for the first one, it would be 1/6 +x/30

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and the empty one x/20

sacred lynx
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so how would we set the equation up

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or would it be a system

lunar skiff
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u need to know when they are equal

lunar skiff
lunar skiff
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when they are equal?

sacred lynx
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5/6+x/20?

lunar skiff
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do u understand what x/30 means?

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x/30 is the percentage of how much the pool is filled in x minutes

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lets forget about the x for a sec, 1/30 is how much the pool is filled in 1 minute, right?

sacred lynx
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yes

lunar skiff
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so after t minutes how much the pool will be filled?

sacred lynx
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t/30

lunar skiff
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alright so t/30 is how much is filled after t minutes

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u agree?

sacred lynx
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yes

lunar skiff
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for the second it will be t/20, ok?

sacred lynx
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yea

lunar skiff
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then lets see, the first is filled for 5 minutes

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so we want to know how much is filled in these 5 mins

lunar skiff
sacred lynx
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1/6

lunar skiff
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so 1/6 of the pool will be filled

sacred lynx
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of the first one in 5 mins yea

lunar skiff
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now what will be the amount of water in the first pool then after t minutes?

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after u fill it up with 1/6

sacred lynx
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t/30+1/6

lunar skiff
lunar skiff
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now the second pool, its still empty

sacred lynx
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t/20

lunar skiff
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now u know the amount of water in the two pool after t minutes

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and we need to know when they will equal each other

sacred lynx
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mhhh when?

lunar skiff
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u just equal them

lunar skiff
sacred lynx
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well t is still 10

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its the same thing we did earlyer

lunar skiff
sacred lynx
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was the first one we did not correct?

lunar skiff
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its just a coincidence

sacred lynx
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ok so what was the point of doing the second one?

lunar skiff
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i thought it was the same pool

sacred lynx
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but now i need what time would they have the same amount of water

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so what time would it be

lunar skiff
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u know how how much is need for both of them to fill up

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add it to the start time

sacred lynx
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9.30 and 9.25

lunar skiff
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incorrect

sacred lynx
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first one starrts at 9.00 and i t needs 30 mins no?

lunar skiff
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30 minutes??

sacred lynx
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and the second at 9.05 and needs 20 mins

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yes

lunar skiff
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nooo, thats when they will completely be filled up

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he asks about when they will be the same level

sacred lynx
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yea

lunar skiff
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i mean obviously they will be the same level when they are filled up

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but thats not a question

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thats easy

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but they will have the same level befor even they are filled up

sacred lynx
lunar skiff
sacred lynx
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ok explain

lunar skiff
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i already tried to explain it to u

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which what all of theses messages above are

sacred lynx
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yea but how do i find the time

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explain again pls

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sorry for the trouble

lunar skiff
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what dose the 10 mins that we get means?

lunar skiff
sacred lynx
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amount of water

lunar skiff
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10 is the amount of water?

sacred lynx
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in the given time

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10/20 lets say

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10 alone is just time

lunar skiff
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already, im gonna go through it, but dont let me go over a point that u don't with out interrupting me

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if u dont understand type a massage dont take too much time to respond if u can

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okay?

sacred lynx
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ok

lunar skiff
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the amount of water in the first pool after the first 5 mins

sacred lynx
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yes

lunar skiff
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so u know that since the first pool already has 1/6 of water, then the amount of water in it after will be 1/6 + the water coming from the pipe

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so it will be 1/6 + t/30

sacred lynx
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ok

lunar skiff
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and for the second since its still empty it will be just t/20

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now we have the amount of water in each pool after t minutes (which is (1/6 + t/30) and (t/20)) , and we need to know when they will be equal

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agree?

sacred lynx
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yea but what is t seperetly/

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?

lunar skiff
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nope, t is not seperate

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they are the same t

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t is the minutes passed after the start time which is 9:05

sacred lynx
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ok

lunar skiff
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so we need when they are equal

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literally u make the two equations equal to each other

sacred lynx
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ok i get this so far

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but how do i find at what time like 9.....?

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what AM would they be equal

lunar skiff
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no wait

sacred lynx
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so 10 minutes passed

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so they would be equal at 9.15

lunar skiff
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correct

sacred lynx
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ok thanks

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sorry to ask but do you got time for just 1 more problem its a geometri one

lunar skiff
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in this case i'd prefer if u close this help and open a new one

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this this one is old and down in the help chats

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so if u one new one it will top up and people will be able to see ur question, cuz i need to do something

sacred lynx
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.close

final saddleBOT
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Channel closed

Closed by @sacred lynx

Use .reopen if this was a mistake.

final saddleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.