#help-36
1 messages · Page 110 of 1
b dollars -> a minutes
1 dollar -> a/b minutes
so its C times the cost per minute?
Yes
c dollar -> ca/b minutes
yes
would the cost per minute be B/A?
thats called unitary method
No
no
If you check the units it has units dollars per minute
why not A/B tho
Misread as a/b sorry
You wrote B/A here
check the units
Wait the cost per minute yeah
Sorry we're tired
but lets say the cost for 5 minutes is 10 dollars
for 1 minute it would be 2 dollars
Yeah exactly yep
i did B/A
or 2 dollars for 1 minutes
So that is B/A yes
1 dollar for 1/2 minutes
ohhh
there is a difference between 1 dollar per 0.5 min and 1 minute for 2 dollars
like
let me send you by doing it in paper
okay
Well yeah, 1 dollar per 0.5 min and 0.5 min per 1 dollar
The units are different
Depends if you're trying to find the number of dollars or minutes
yes i am asked tho how many minutes you can buy in C dollars.
Yep so you would use the second one
@glass ember
np
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Calculus: need help with if sum of a series converges or not
the series is: sinx + sin^3(x) + sin^5(x) + ... where x tends to pi/2.
I am getting two different results by 2 different methods:
method 1:
since in this case my common factor is less than 1, I can use the infinite GP sum formula which gives me the result positive infinity.
method 2:
if first, I take the series to be till n terms and use GP sum formula, it gives me 0/0 form. Applying L-hospital to it gives me the sum to be:
n*((sin(x))^(2n-2))
where x tends to pi/2 and n tends to infinity
this gives the sum to be 0 as anything less than 1 to the power 0 tends to be 0.
yelp
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Isn't that Like f(-x) odd function reflection along the origin ?
I don't know transformations tbh
@gloomy thistle Has your question been resolved?
if u have a point (x, y)
what will it transfer unto if u rotate ut 180 around origin
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Let ABCDE be a convex pentagon with side lengths a, b, c, d, and
e respectively on the sides AB, BC, CD, DE, and EA. Suppose it is an inscribed pentagon, meaning there exists an inscribed circle, denoted by k, which is a circle inside the pentagon and touches all of its sides. Let P, Q, R, S, and T be the points of tangency on the respective sides.
Express the lengths of tangent segments drawn from the vertices of the pentagon to circle k in terms of the side lengths.
@crimson sparrow Has your question been resolved?
Draw the shape and set one of the tangent distances to x
Then, you progress around the shape. Knowing the power of a point theorem, two tangents draw to a circle from the same point have the same length. Therefore, you can simply solve around the shape
We get that $e-d+c-b+a-x=x$. You can solve this for x and find the rest.
AkishBrabus
@crimson sparrow
Thank you very much, I had a hunch yesterday to maybe try it like this, but got distracted.
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help
log_2 (x) and 2^x are inverse functions
if you can draw one then you can reflect that over y = x and get the other one
what's 2^(-2)?
to fill this
oh i didn't see what you meant
yes first y point for 2^x not 2x
@jaunty adder Has your question been resolved?
Oh okay got it
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What is the easiest way to solve squares by hand? I’m struggling with squares and square roots and I want to be able to do it by hand for my Math 8 SOL (pre-algebra).
there's a trick for finding squares
Yeah things like that
once you get good at it, you can find squares within 3-4s of 2 digit numbers
you could write it as the sum of simpler squares like (10+7)^2
well the early ones you can just remember
and simplify from there
I’ve had to use Desmos on the practice problems
there's a better trick
if yall pause for a while i'll cook
I tried that for 13^2 and it didn’t work so I think I did it wrong
Show your work, and if possible, explain where you are stuck.
For 13^2 I just do 13x13 = 13 x 10 + (13 x 3)
Ok
So for the other method I got 109?? Cause 10^2 is 100 and 3^2 is 9
Ik
Yeah that works and it’s easy
@dire gale
smart!!!
hey I joind this group because I got a C- in math I am in 8th grade can you guys help me so I can pass
next time
Imma close mine and you should open one
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need some help with this one
first, im
not sure why we're using induction for finite domain
and second how we do specificy a choice function for picking which f(i) in H(i)
can we just say any? im not sure
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Trig simplification help/explanation
I am attempting to perform an operation and simplify the result. I am given cot x (sec x - tan x). First I identified what identities these belonged to so I did cot x = cos/sin; sec x = 1/cos; tan x = sin/cos, I can get to that point every time. However, the part where I am stuck is when it comes to simplifying all of that. I have the answer which is csc x -1, I guess I am just looking to better understand how they simplify: cos x/sin x (1/cos x * sin x/ cos x) --> csc x -1. I understand that 1/sin x is csc
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For this have they multiplied w transpose and w and (c transpose and c ) separately
What’s norm
Denascite
What does it mean aswell
Ohhhh
Oh I get ur working
Hm I guess I’ll just learn that
Thanks
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I need to maximize angle beta
b and a are constants
I can change h
I wrote tan(beta+theta)=(b+a)/h
That’s where I’m stuck
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im curious why the answer would turn out to be -10 instead of 0
what was your reasoning for 0?
so basically the way I did it was by simplifying the expression
$\frac{-(x+5)(x-5)}{x-5}$
OneWhoKnocks
yep that's fine
yep
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im looking at the solution of one homework sheet and i am stuck with one step of the solution. Its about Gauss-Lobatto quadrature
With the Gauss quadrature it is possible to calculate integrals over polynomials up to degree 2n + 1
on the interval [-1, 1] exactly. Nevertheless, it can be useful to calculate one or
several quadrature points from the outset. Often the boundary points
are often chosen. This results in the Gauss-Lobatto quadrature. To construct this
quadrature formula, consider a polynomial
of degree 2n - 1 and write
with r, s ∈ R and q2n-3 ∈ P2n-3. One then considers
As in the case of the Gauss quadrature, we can form an orthogonal system with respect to the weight
function
So at first. We proved that
is a scalar product on C([-1, 1]).
Where im stuck is the following question:
Based on this scalar product, construct a quadrature formula that calculates the
following integral exactly:
We also got one Hint: Think about the degree of exactness of the quadrature constructed with the scalar product.
product and apply it at a suitable point. The weights
or supporting points do not have to be calculated explicitly.
So the given answer of this question is:
Let Pn-1 ∈ Pn-1 be an orthogonal polynomial which, with respect to the scalar product (-, -)w is perpendicular to Pn-2
Note: Because w(x) = (1 - x2) this results (except for one prefactor) in the
Gegenbauer polynomial with α = 3/2, i.e. Pn-1 ≡ G3/2
n-1 ≡ L′
n, where the latter is the
derivative of the Legendre polynomial.
The zeros x1, . . . , xn-1 of Pn-1 are simple, real
and lie in (-1, 1). With ˜w1, . . . , ˜wn-1 we denote the corresponding weights
of the weighted quadrature Iw,n-2. According to Jacobi's quadrature theorem, the
degree of exactness of Iw,n-2 is just 2(n - 2) + 1 = 2n - 3, and in particular
Insert results in
now my question is the last equation of the pic above
why is the wn and w0 the two weights
the original homework is in german. I can also send a pic when someone can help

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I'm trying to understand the significance of determining the linear independence of functions outside of considering vectors explicitly. Say, for example, we want to determine if the functions [
f_1(t) = 1 \q f_2(t) = t \q f_3(t) = t^2
]
are linearly independent on some interval $I$. Usually in linear algebra, if we have a set of linearly independent vectors that implies that they span $\R^n$ with $n$ being the amount of vectors we have, but how does that extend when considering the linear independence of functions rather?
oh i had no clue of the existence of such thing
are they similar to a vector space
Fair, my bad I shouldn't have thrown in that wording without making myself clear
It is just a regular vector space
Well, at least we can consider it as a vector space
(just so this isnt some weird XY i ask because of this)
You'll see "function space", "eigenfunction" etc when we are considering functions as vectors.
But these are really just vectors
okay thats very interesting
so how do you go about determining the linear independence here
i mean usually with vectors u Gaussian reduce or check if det is nonzero
So any solution to a linear, homogenous DE is a vector space. The dimension of that vector space is the same as the order of the DE
assuming linear independence i suppose?
Like, you want to see a proof of theorem 4.1.3?
if it isnt too insane i don't mind, but i guess i also would like to see how it can be applied
I mean theorem 4.1.3 isn't telling you what the basis vectors are, just that they exist
It's up to you to find a set that's linearly independent and prove it
i mean I think the (->) case is simple
it being a fundamental set og solutions implies that the Wronskian is nonzero by definition
so the system must only really have the trivial solution
Well im skipping proving thr part where a nonzero determinant implies linear independence lmao
Sorry, I should have read closer before. I think I am confused. What's a "fundamental set of solutions", if not a linearly independent set of solutions?
let me fish out the proper definition but im pretty sure it's said in the way it is because the book doesn't expect you to have linear algebra knowledge
this "theorem" is very funny to me because it's just like using the identity 
but yeah i guess thats it 
The fact that solutions to DEs form a vector space isn't that crazy. The derivative is linear, so it's pretty natural that solutions add to make solutions
The dimension of the space being the order of the DE is nuts to me, though
is it?
Tells you exactly when you're done finding solutions
oh i mean i guess that's a consequence of the existence and uniqueness theorem?
You know what? I actually don't know why this works. Probably something-something factoring out solutions
I think I'll look
This answer seems strong
https://math.stackexchange.com/questions/2659254/why-a-n-th-order-linear-homogeneous-ode-has-exactly-n-linearly-independent-solut?rq=1
Heuristically it's not too surprising that the dimension is n. If we "integrate n times" we'll have n constants I.e. degrees of freedom
But I wouldn't know how to prove it in general just vibes
aight that solution is understandable
for me at least
but okay back to the topic
how do u verify that those functions span the interval -infty < t < infty
for eaxmple
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hiya, im needing to do a little math for a program im making and can't figure out how to get it to work the way i'd like it to.
ive got a list of chances (not % but just a list of numbers like [ 1, 2, 4, 8, 16, 32, 64 ]), and i need to have the lower and higher numbers tend towards the midpoint while having a "multiplier" that would make it more quickly tend towards the midpoint, i'd also like it if the numbers further from the midpoint tended towards it quicker
@azure dew Has your question been resolved?
<@&286206848099549185>
Sounds like simple harmonic motion
Ikr
Lol we have force etc in physics which helps in determing accelerations and the end points...the farther you are more is the acceleration guided towards centre. But I don't really have any i dea how could be based completely on mathematics
Perhaps this hought process may help you a bit
Can you eplain a bit?
Like if uk
The momentum
U can fig out distance
But it won't be applicable to this question ig
Aghh..Yeah I understand it...but I don't think it will help here
You should tag again I feel, maybe someone else may help you betterr
i think honestly i can do something just with sin and map the list of numbers within the bounds of pi
Which lv question is it
?
Like high school uni etc
uhhh its sorta just a personal programming project im working on, but i can't figure out the math for how to get it to work properly
def adjust_list(numbers, midpoint, multiplier):
adjusted_numbers = []
for num in numbers:
distance_to_midpoint = abs(num - midpoint)
adjustment = distance_to_midpoint * multiplier
if num < midpoint:
adjusted_num = num + adjustment
else:
adjusted_num = num - adjustment
adjusted_numbers.append(adjusted_num)
return adjusted_numbers
numbers = [1, 2, 4, 8, 16, 32, 64]
midpoint = sum(numbers) / len(numbers) # Calculate the midpoint
multiplier = 0.1 # Adjust this value to control the rate of convergence
adjusted_numbers = adjust_list(numbers, midpoint, multiplier)
print(adjusted_numbers)
Maybe this might help
Chat gpt 😅
Which language
writing it in ts aha
Turbo script
im meant to be learning java and python in uni as well but... they're a bit slow at teaching first years
c++ is fun but i only ever use it to write game cheats
Genius 🤣 i learned c++ for almost a yr and all ik at most is looping programm and till Matrix idk how to even make the most basic game like snake and ladder
Well I wanted to clarify, universities are after 12th grade correct?
Yea
ya
So colleges and unis are diff?
but i don't do much maths doing a cs degree
I just finished 11 rn so I can't be blamed for not knowing and shit we were recommending physics and chem for programming
That what I never knew the diff
Same heree!!
depends on where you are, in the US colleges just don't have masters/phd
Oh I seee... good to know
in the UK, where i live, we only have universities and college is pre-uni (year 12 and 13)
Damn bro which state
I am from India
Yea which state
Ohhh
12 and 13 grade or old
grade
Maharasthra, Mumbai
Ohhh
So you are doing your degree in Computer science?
She genius
Cs are the top course in every uni tho idk abt un it's hard asf to get into it in india
How's your exp? there is a lot of rush in cs category here ngl
Ikr...Infact talking about JEE.. you need to get above 200 rank to get into the best insitute for cs, competing with almost 21-22 lacks ppl
Yea
well, i've been programming independent from academic study for 5 years now so everything they teach me is really easy and even 3rd year knowledge is... quite easy
U too frm India brother?
Ayoo that;s something cool...
Future ethical hacker prolly
ethical if they give me money 
😂😂😂😂 Or else we k
Sent ya friend req!
Where does hacking stand in coding
Can u tell me the ans
Like i learned c++ but idk how to hack
Is it a different concept or something
hacking is an extremely broad term and within the cyber security community its not really called hacking
Then
usually we call it reverse engineering since we're taking apart programs and finding vulnerabilities in them
i've found a couple vulnerabilities in games but usually the higher paid ones are within game companies main infrastructure, not the game
My cs man told like 2-3 months are needed to find loopholes and all
well, coming across a new AAA game, i could find a vulnerability of some sort in about 2-3 weeks if im seriously looking for one?
This sounded way more cool and logical ngl
i actually have a vulnerability that i haven't disclosed to the papermc development team for a movement exploit aha
its been in thir server software for about 3-4 years?
U get payed for finding vulnerability?
I have very less interest in coding or computer related stuffs😂. Ya'll continue..I'll join you later!
nah i was just writing some cheats and found it
Oo
im doing more ethical stuff with minecraft development recently though
U can sell it then right
yeah i could sell them
I got a nice business plan
Which lang do think got the most amt of prospect in future
honestly that doesn't really matter too much for me, i've learnt enough langs now that i can transfer most of the skills from each if i just spend a month or two learning a different lang
But for a beginner like me ?
I don't wanna be clean slate when i go to uni gotta flex when I reach there
realistically no lang is the best, it depends on what you want to go into and what the industry uses
java is massively used just because its old (even if its not that good)
anyway we should probs stop using the help channel for non-help things 😛
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Oo ok
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im trying to solve the ODE [
2y'' + (x+1)y' + 3y = 0, \q x_0 = 2
]
So so our recurrence relation has conditions $a_2 = 0, a_1 = 0, a_0 = 0$ and then the recurrence relation itself is [
2(n+2)(n+1)a_{n+2} + 3(n+1)a_{n+1} +(3+n)a_n = 0
]
So how do I evaluate this?
u dont have to look at this, I just put it there in case my recurrence relation is sus
try a_n = r^n ig
Yep you will get a quadratic equation for your characteristic equation
But like this is nonlinear no?
not really ig? i forgot what nonlinear is
Wolfram Alpha also gives me an answer using erfi(x) for your original ODE
shet
well i am trying to find a series solution
Fair enough
try umbral calculus might be easier 🙂
its linear if you have something like [
c_na_n + c_{n-1}a_{n-1} + \dots + a_0 = 0
]
aka a linear combination of the terms afaik
bruh u have linear too then no
then why did u put c_n bruh
@tranquil pine are u learning from a book?
Because u said you dont know what nonlinear means
so i answered that by showing what linear is
if you're gonna get a nonlinear weird recurrence every question, surely there's a way you are supposed to solve them
maybe
no i mean i thought c_n meant a sequence of constants dependent on n
the solution steps are pretty much the same in the sense u retreieve a recurrence relation and solve it
its 11
Wronskian??
what kind of secrets are you keeping from us
so there IS a method to solve these or what
the wronskian is just to verify if our solutions are linearly independent so dont worry about that
like
the steps are the same i can show an example if u want
ok show
what book is this, if you're okay to share?
and is that green background by default?
qylo try this:
$$ \mathcal \frac{df}{dx} = \sum_{k=1}^{\infty} \frac{(-1)^{k-1}}{k}f^k(x)$$
..
<@&268886789983436800>
(this is called method of generating function iirc)
"Elementary differential equations and boundary value problems" and no i invert the colour using my PDF viewer
oh okay i guess i was interested in the inverting color more than the book then 
thanks
rak³en
Compile Error! Click the
reaction for more information.
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wtf i happening to my latex
tf
tf
heh?
$q$
Samuel
$\frac{df}{dx}$
rak³en
rak³en
Lol
shouldnt have used \mathcal
where did you get this from
operational calculus 🙂
Something is iffy here. a_2 shouldnt be an independent term
btw this might not work because convergence
ah actually maybe its fine
oh ok
thats our actual condition, but like, you need to
decide on what are the independent terms
well all I can say is that I think you're supposed to just find the pattern
aight will do
and yeah i guess u express it as
a_2 = -3/4 a_1 - 3/4 a_0
so like
a_1 and a_0 are independet
and the terms are expressable using those
so we like
,, a_n = \4{-3(n-1)a_{n-1} - (n+1)a_{n-2}}{2n(n-1)}, \q n \ge 3
btw qylo solving for a_n and putting it into ur definition of y, u dont get the standard series for erfi
i doubt that gives u the erfi series expansion
you dont?
nope, standard series involves n!, urs doesnt
some manipulation might be at play tho
i mean it doesnt seem to be JUST erfi so i can see why the series solution might differ from what erfi(x)'s series alone looks like?
there doesnt seem to be anything that could get rid of the n! in the denominator of erfi(x) from that..
this might be wrong btw
Anyways WA sometimes writes stuff in a very weird form
u missed r = x^n in the quadratic u put in WA
nvm am just being dumb
the first few terms of the solution seem like they coincide
idk how to make WA give u series solutions
it gives something messed up because its trying to calculate it explicitly
coefficients differ
ask nlp thingy to give u series solution
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How do they know that fn converges to f point wise?
Aren’t they two different things?
@pulsar wind Has your question been resolved?
well they are a bit imprecise
when doing measure theory you basically always mean a.e.
null sets dont matter
Do you mind elaborating, I’m quite confused as to why this is true? Are you saying semantically they’re the same thing
well reread the second paragraph
Oh yes, I kept thinking to normal point wise convergence not pointwise a.e
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Main issue is how do I rotate, scale factor, reflect etc from a point not in the triangle.
Also what's the x+y = 6 line
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Did i answer this question correctly
the 2pi(k)/5 part seems about right
haven't learned about the second half of the problem though
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I am having trouble finding the u, whether it be 3x or cos^2(3x)
You'll need to open up your trig identities for this integral
sin^2 (3x)
I wouldn't go with that identity, since now you need another identity
Try an identity that removes the ²
(1-cos(2x))/2
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How do i take the derivative of this
product rule?
You suffer
Aight thanks
and with a fourth and fifth and so on the same logic?
you can think of a(x)b(x)c(x) as a(x)d(x) where d(x) = b(x)c(x)
So the derivative would be a'(x)d(x) + a(x)d'(x)
but then d'(x) = b'(x)c(x) + b(x)c'(x)
and so it keeps being recursive
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Why do derivatives work
I get what they do and that there are different rules achieve it with but can someone please explain
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Could someone help
whats the question
my approach to this would be
- angle adding formula
- black magic algebra and trig identities
- get answer
not sure what the answer is tho
I would just bring out the table and see what angle gives you cos = 2sin lmao
I tried the angle adding formula but get stuck 💀
In the first step you're using the double angle identity, but there's no "double angle" here.
Just apply the angle sum identity to both sides and simplify.
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Any help with part c?
<@&286206848099549185>
doesn't GAC look like a right triangle to you
@unkempt moon
the fact that the shape is a "cuboid" is a pretty big clue
the face AEHD is a square and so is BFGC
how have you considered it and not know how to find h
what exactly did you consider
that this shape is a cuboid
earlier u said AEHD is a square
it's not a square
idk the relationship between GC and AD
wait a minute
can we assume the information given from the first question applies to the second
you can now solve for the volume of the paperweight
and given that a and b are still the same you can find the third edge
The volume of the paperweight will be $2ab^2 + \frac{1}{2} \pi a^2b$
hoax
Volume = $2(6\sqrt{5})(10\sqrt{3} - 6\sqrt{5})^2 + \frac{1}{2} \pi (6\sqrt{5})^2(10\sqrt{3} - 6\sqrt{5})$
hoax
now what?
hoax
assuming the volume of the new shape is equal to that
find the third edge by division
(i really hope when they said "melted down" they meant retains the same volume, otherwise I'm not sure how you'd solve this)
oh yea
i could try that
originally, by "melted down"
i thought they just like melted away a piece of the original shape
as if they completely removed the semi-cylinder
and a small portion of the cuboid
they probably could've clarified it but that's what they meant i think
otherwise its back to me assuming it's a square cuz how else would you find h
that means the design of the question is poor, no?
just a little bit yea 
so i get h being 14cm
and i get angle GAC being about 28 degrees
thx for the help
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Need help solving this integral
take the sub u = (x-2)/2
use 1 + (sinh u)^2 = (cosh u)^2
finally use the def: cosh u = (e^u + e^-u)/2
@boreal robin Has your question been resolved?
thx
ill try that

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Hi, when testing the rational root theorem with synthetic divison and none of the rational roots give a remainder of zero (remainder theorem stating r= 0 means k from x- k is a factor), how do i find the real numbers?
my head genuinely hurts testing all positive and negative numbers that i cant recall other ways to do this
what numbers have you tried
+-{1, 2, 4, 7, 8, 14, 28, 56}
I started by putting them in for f(x), since the theorem states that k of (x-k) is a factor, so if the answer results in 0, it works
but none of them worked
I graphed it and some of them work
watching the given guide video isnt helping because they have numbers that work
.-.
maybe your arithmetic was wrong somewhere
give me a point/x-value that worked for you so i can try it again
-2 and -4 should work
no way it worked, where tf did i go wrong
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Log Proofs;
If a^x=b^y=c^z=d^w=K , (a does not equal 1) , show that log(base a)abcd=x(1/x+1/y+1/z+1/w)
I have first solved for a,b,c, and d. a=k^1/x , b=k^1/y , c=k^1/z , d=k^1/w . I've tried substituing some things into different places, but I really just need some help on the next step, where to take the equation next.
Where did the x come from
I mean lemme tjink
Because I know a^x b^y c^z d^w = K^4
Oh wait I'm dumb I see where the x is from lol
Lemme cook
Actually well
Hold on
Eh nvm
.tex log rules
i was thinking and then I didn't
I forgot the command
,tex log rules
Guess I’ll have to write this out by hand
Peter Griffin
Fuck man
No
$\log_a(abcd)=\frac{\log_k(abcd)}{\log_k(a)}$
kheerii
Use this
Hm what happens if you solve for log_a(k)
Or ln(k)
Following up on this:
$e^{x \ln(a) + y \ln(b) + z \ln(c) + w \ln(d)} = e^{4 ln(K)}$
Peter Griffin
huh
Actually this should work with what you've also been doing
They just took the log on both sides
and my teacher has really just been giving us problems to tinker with one side or the other so that the given looks like the proved
Im trying to digest what those text thigns are
take the log on both sides
that is a familiar thing
Well I'm just trying different things
I'm legit lying in bed lol so like i cannot grab paper and pencil
Im thinking i substitute what i have for a b c and d into the log_a(Abcd)
but im not sure what good that would do me
My teacher generally wants us to solve the equations step by step, by doing something to one side of the equation until it looks like what we are trying to prove
Hm
less using formulas like this
Well let's look at what you've done so far
a = K^(1/x), etc etc
What i am seeing is that if you take the log base A of both sides
For all four
You get
This is just base change
You can’t really do this without it
I mean, you can
But it’ll be more complicated
Write $abcd=K^{1/x+1/y+1/z+1/w}$
kheerii
You already got the answer on the second last line
Just take an x common from all the terms
You got 1+x/y+x/z+x/w
and im also not entirely sure how i got there
So 1 + x/y + x/z +x/w = x(1/x+1/y+1/z+1/w)?
wow
im very tired
and the more i look at this problem the less i understnad
and im not really solving
im proving something is equal to something else
why is a#1 important
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i have a doubt
does there exist a formula that can calculate the length of a sine wave
i tried deriving it myself but im stumped, i can only calculate the area, but not the length
length?
yes
as in line integral?
is that what its called?
arc length?
yes
arc length of a curve $y = f(x)$ between $x=a$ and $x=b$ is [ L(a,b) = \int_a^b \sqrt{1+(f'(x))^2} , dx]
pnoןɔ
unfortunately such an integral is not elementary
it falls into a category called "elliptic integrals" (named because they can arise from calculating the arc length of ellipses)
,w arc length of sin(x) between 0 and pi
holy hell
where E is given as follows https://mathworld.wolfram.com/CompleteEllipticIntegraloftheSecondKind.html
The complete elliptic integral of the second kind, illustrated above as a function of k, is defined by E(k) = E(1/2pi,k) (1) = pi/2{1-sum_(n=1)^(infty)[((2n-1)!!)/((2n)!!)]^2(k^(2n))/(2n-1)} (2) = 1/2pi_2F_1(-1/2,1/2;1;k^2) (3) = int_0^(K(k))dn^2(u,k)du, (4) where E(phi,k) is an incomplete elliptic integral of the second kind, _2F_1(a,b;...
i see thank you sir for resolving my doubt
god i fucking wish my math sirs taught me arc lengths for hours
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F(g(x)+3)=g(f(x)-3) need to solve this equation if f(x)=3x+1 and g(x)=2-x
plug the functions,
remove each f(smth)
and put (3 * smth + 1)
the same way with g(x)
Ok wait il let you know what i get
So far i got f(5-x) and g(3x-2)
Do i need to remove f and g now?
@lunar skiff
Wait i think its wrong
thats right
yes, as u did before
where are u getting the 6?
no wait let me rewrite it
g(f(x) -3) = g((3x+1) -3)
= g(3x -2)
g(x)=2-x this
this is what u ended up with ,right
f(5-x) = g(3x -2)
lets try the left hand side, the f part
what will it be based on what i told u?
16-3x
yes!
and 4-3x
u sure about the question itself?
yes
wait, is it f or F on the left side?
its the same
no its different, f and F is different things
maybe, if u ended up with a true equation like 4 = 4, with no x in it, we would say that there is an infinite number of solutions
but instead we got 16 = 4 which is not correct
so here there is no solution
alright
it would be easier if u could send a picture of the question, instead of just typing the whole thing
the pool using the first pipe fills up in 30 minutes with the second pipe it fills up in 20 minutes . what time would the amount of water be the same if we turn the first one ate 9 am and the second one ate 9.05 am
its in another language
you wouldnt udnerstand
alright, lets analyse the question, the first pipe fills in 30m which means that how much of the poill it can fill in 1m?
30/x?
yes
second is x/20
so x here is the number of minutes passed
yes
now since the two pipes didnt start at the same time
we have first to know how much the poll is filled during the first 5 minutes
how?
using what u have just come up with
x/30, tells u how much of the pool is filled during x minutes
5/30
yepp, which simplify to 5/6
1/6
soryy, 1/6 correct
now we need to know hiw much time is needed to fill up the rest of the pool using the two pipes together
what the equation that tell u how much is filled using the two pipes?
add them
like that, but that would tell u how much time to fill the whole pool
cuz x/30 and x/20 is how much is filled in x minutes
and when u add them up u get the total amount
do i need to replace x with something?
and also it will not equal 1
1/6 is the filled space
5/6
yes
x is 10
so thast the answer
no
look, u have two stages, the first is when u have 1 pipe only, and the second u have 2 pipes
u need to get the time of each stage and add them up
there are no 2 pipes
its always seperate
fist one we turn on at 9am ans the second one in a seperate pool ate 9.05
"what time would the amount of water be the same" these are two pools then?
Yea 2 pools
in this case its the same approach
we stll know that the first pool would fill up to 1/6 of its volume in 5 minutes
so one has 1/6 and the other is still empty
so for the first one, it would be 1/6 +x/30
and the empty one x/20
u need to know when they are equal
so if this is how much is the first pool is filled
5/6+x/20?
?
do u understand what x/30 means?
x/30 is the percentage of how much the pool is filled in x minutes
lets forget about the x for a sec, 1/30 is how much the pool is filled in 1 minute, right?
yes
so after t minutes how much the pool will be filled?
t/30
yes
ok, that for the first pipe
for the second it will be t/20, ok?
yea
then lets see, the first is filled for 5 minutes
so we want to know how much is filled in these 5 mins
based on what we got.
1/6
so 1/6 of the pool will be filled
of the first one in 5 mins yea
now what will be the amount of water in the first pool then after t minutes?
after u fill it up with 1/6
t/30+1/6
yes so thats the amount of water for the first pool
t/20
good so far
now u know the amount of water in the two pool after t minutes
and we need to know when they will equal each other
mhhh when?
u just equal them
thats the question!
and whats the problem with that :-\
was the first one we did not correct?
yeah, but that doesn't mean the second is incorrect
its just a coincidence
ok so what was the point of doing the second one?
cuz the approache is wrong for the first one
i thought it was the same pool
but now i need what time would they have the same amount of water
so what time would it be
9.30 and 9.25
first one starrts at 9.00 and i t needs 30 mins no?
30 minutes??
nooo, thats when they will completely be filled up
he asks about when they will be the same level
yea
i mean obviously they will be the same level when they are filled up
but thats not a question
thats easy
but they will have the same level befor even they are filled up
yea but how do i finds that?
then what was i trying to explain to you 
ok explain
what dose the 10 mins that we get means?
.
amount of water
10 is the amount of water?
already, im gonna go through it, but dont let me go over a point that u don't with out interrupting me
if u dont understand type a massage dont take too much time to respond if u can
okay?
ok
so, u understand the 1/6 part?
the amount of water in the first pool after the first 5 mins
yes
so u know that since the first pool already has 1/6 of water, then the amount of water in it after will be 1/6 + the water coming from the pipe
so it will be 1/6 + t/30
ok
and for the second since its still empty it will be just t/20
now we have the amount of water in each pool after t minutes (which is (1/6 + t/30) and (t/20)) , and we need to know when they will be equal
agree?
nope, t is not seperate
they are the same t
t is the minutes passed after the start time which is 9:05
ok
so we need when they are equal
literally u make the two equations equal to each other
ok i get this so far
but how do i find at what time like 9.....?
what AM would they be equal
no wait
this
correct
ok thanks
sorry to ask but do you got time for just 1 more problem its a geometri one
in this case i'd prefer if u close this help and open a new one
this this one is old and down in the help chats
so if u one new one it will top up and people will be able to see ur question, cuz i need to do something
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