#help-36

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forest pagoda
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tranquil pine
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f(x, y) = \begin{cases}
\frac{3x^3 - y^3}{x^2 + y^2} & \text{when } x \neq 0 \text{ and } y \neq 0 \
0 & \text{when } x = 0 \text{ and } y = 0
\end{cases}

soft zealotBOT
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Deleted User 14b4cb6a
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tranquil pine
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f: R^2 -> R

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I should find the partial derivates on the point (0,0).

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How should I approach such question?

magic sparrow
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Try it by the definition

tranquil pine
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with definition, it takes a lot of time.

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I should be able to solve it in a minute. :)

final saddleBOT
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@tranquil pine Has your question been resolved?

scarlet sequoia
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what happens when x = 0 and y not 0 and vice versa?

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i'm guessing you meant $(x,y)\neq (0,0)$ for the first case, which is not the same thing

soft zealotBOT
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rafilou2003

scarlet sequoia
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and yes the only feasible way is using the definition $\lim_{(x,y)\to (0,0)}\frac{f(x,y)-f(0,0)}{x-0}$

soft zealotBOT
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rafilou2003

scarlet sequoia
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(for partial derivative with respect to x, repeat with y)

final saddleBOT
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@tranquil pine Has your question been resolved?

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south wave
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Is this right

final saddleBOT
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Please don't occupy multiple help channels.

south wave
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Anyone

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Please

candid pulsar
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yeah c is right

south wave
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Is A 5 or is it supped to be 2

south wave
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@south wave Has your question been resolved?

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tranquil pine
final saddleBOT
tranquil pine
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Why 10^-x ended up being 1/5 and not -5

tranquil pine
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I know when a exponent os negative we invert it

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Like

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10^-x end up becoming (1/10)^x

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But I dont understand How the five became 1/5

vivid parcel
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They are raising both sides to the power of -1. That gives (10^-x) on the left and 5^(-1)= (1/5) on the right

tranquil pine
vivid parcel
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Raising both sides to the same power? Well, if the two sides are equal, then equal things raised to the same integer power are still equal. I don’t know the name of specific rules.

tranquil pine
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Let me see

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If I'm making an = between two numbers

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And I change the exponent of one

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I have to do the same about the other?

vivid parcel
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Yes. Here you raising both to the -1 power.

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You could even write the whole equation as 1/(10^x) = 1/5. In the previous step, you had 10^x=5 so this is still equal

tranquil pine
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Lets suppose i'm doing

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(X^²)^x = 2^²

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I cut both exponents

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It stay as X^x = 2

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Then i wanna know what is the value of negative x and I make the x negative for that

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It become X^-x

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Is It mandatory for the 2 exponent become negative too? Like X^-x = 2^-1?

vivid parcel
low yew
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a^(-1)=1/a

tranquil pine
vivid parcel
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Great!

tranquil pine
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Thanks

tranquil pine
scenic tree
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if $10^{-x}=\frac{1}{5}$, then $\frac{1}{10^x}=\frac{1}{5}$

soft zealotBOT
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ـDraedon

tranquil pine
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Oh, thanks!

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hearty epoch
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Given this question, I believe we represent the vectors as matrix A, with [x,y,z] as another matrix, say v, so Av=0, I think we somehow apply gauss jordan elimination to get rref, then that spits out numbers to get our answer, im not sure how to apply gauss jordan elimination in this situation, or if it is the correct way to go about it

dusty harness
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Do you know how to do row echalon form?

hearty epoch
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yeah i do

dusty harness
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ok now put them on top of each other, scratch the echalon form

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trying to solve th system what do you see first? note: it should be the 0

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that 0 means that the first and third row should be synchronized for the 3rd column to be 0 in the end

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r u with me?

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for the third column to be 0 you multiply the first row with 2

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-8 + 8 = 0

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now you need to play with the 2nd row to finalize the system

hearty epoch
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i think that makes sense

dusty harness
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when you multiply the first row with 2 and do the summation, u get 8 10 0

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which is a direct multiplication of the second row

hearty epoch
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yes

dusty harness
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seeing these kind of patterns come with time

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well anyways what multiplier do you need for the 2nd row to remove 8 and 10?

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firstly it needs to be negative since you are trying to neutralize positive numbers

hearty epoch
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if its a direct multiplication of row 1 just r2 -> r2 - 1r1?

dusty harness
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we already did 2r1 + r3 + r2

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and made the 3rd column 0

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now we need a multiplier for 2nd row to make the result of 2r1 + r3 + (multiplier)r2 = 0 0 0

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the multiplier is -1

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2r1 - r2 + r3 = 0 0 0

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actually nevermind its hard to do if u are not familiar

hearty epoch
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haha you've lost me, thank you for trying to help, i reckon ill swing by maths help for a few hours to get in person help tomorrow

dusty harness
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yea i didnt like linear systems as well when i was in high school

hearty epoch
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yeah its been the topic i just cant rap my head around

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oh well, thank you

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fiery prism
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can someone help me with c

final saddleBOT
fiery prism
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i need to use cosine law and solve for x

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but i think am doing somthing wrong

fathom walrus
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Send what uve tried

brave shoal
fiery prism
brave shoal
atomic cairn
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Area=
2
1

×side
1

×side
2

×sin(angle)

atomic cairn
brave shoal
brave shoal
# fiery prism

so i think the answee will be 180 minus what you got here

fiery prism
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the answer is 102

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i got 101.5

brave shoal
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Maybe they're rounding up?

atomic cairn
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how is it 164-164??

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won't it be 196=164-160.cosC??

atomic cairn
final saddleBOT
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gloomy locust
final saddleBOT
gloomy locust
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trying to show that $X \cup {\neg \psi}$ is inconsistent

soft zealotBOT
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Waffloid

gloomy locust
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as per the hint ive proven that for any valuation of this, the set below is inconsistent

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but i dont see what this does for us?

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like we can apply deduction theorem and conclude that ${q |q\in Q, v(q) = 1} \cup {\neg q| q\in Q, v(q) = 0} \vdash \neg \phi$

soft zealotBOT
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Waffloid

gloomy locust
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so we have propositions built out of primitives in Q that prove not-phi, with these propositions coming from a model of X u {not psi}

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but so what? if these q were all in X then we'd have a proof of not phi from phi which is a contradiction, but we dont have this...

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onyx sun
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I need to find an m x n matrix where it's columns are linearly independent but its not a basis for R^n. I have come up with the 4x3 matrix [[1,0,0],[0,1,0],[0,0,1],[1,1,1]]. afaik the cols are linearly independent, and it cannot be a basis for R^3 since it has 4 elements in each column, not 3. Is that correct?

hollow iron
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Yeah that's correct...

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It's meaningless to ask whether the columns are a basis for R^n if m != n

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They aren't even vectors in R^n

onyx sun
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yeah I was more concerned about the linear independence part.

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Now, i also need an m x n matrix where the columns are linearly dependent but that Ax=b has a solution for all b in R^n. normally to check that 2nd condition I would find the determinant and if det != 0, then the equation has a solution for all b. but since its a non square matrix it doesnt have a determinant

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im not sure how else to check the second condition

royal gust
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det = 0 implies the system has a unique solution.

You don't necessarily need a unique solution for this question, so even matrices with 0 det can fit

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Note that the columns being linearly dependent implies the det is 0

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This is all if the matrix is square. It doesn't have to be

onyx sun
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ah yes sorry i forgot to write but it needs to be a non-square mxn matrix that is where im hitting the wall

final saddleBOT
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@onyx sun Has your question been resolved?

final saddleBOT
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@onyx sun Has your question been resolved?

final saddleBOT
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@onyx sun Has your question been resolved?

final saddleBOT
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@onyx sun Has your question been resolved?

final saddleBOT
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@onyx sun Has your question been resolved?

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severe cove
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im so confused

final saddleBOT
severe cove
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(ignore the unselected ones)

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so we have learnt to solve this by doing the positive of one absolute, pos of other, etc and solving it

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the 4 permutations of each

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but when i solve for positive |x(4-x)| > positive |x-1| because its the quad formula, i actually get both the intercepts in the graph of x(x-4)

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but one of the intercepts is on the negative |x-1|

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why

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jolly tapir
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heya, I'm trying to prove this question via induction, but I keep running into unwanted negative signs after I evaluate the convolution. e.g. this is my base case but there shouldn't be a (-1) here. what am i doing wrong?

final saddleBOT
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@jolly tapir Has your question been resolved?

jolly tapir
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<@&286206848099549185> 👀

desert mantle
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the inputs in the integral have to add to t0

jolly tapir
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what do you mean by that? the bounds?

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i thought convolution had bounds of -inf and inf

jolly tapir
desert mantle
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you have f(t) delta'(t-t0)

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the inputs add to 2t-t0

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they should add to t0

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they should be f(t)delta'(t0-t)

jolly tapir
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what would "inputs" refer to?

desert mantle
desert mantle
jolly tapir
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ah okay i see. but why add to t0?

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what's the reasoning behind swapping it to f(t)delta'(t0-t)

desert mantle
jolly tapir
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right but then it would be f'(t0-t)delta(t) no

desert mantle
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well doesnt matter in which one of them you place the minus

jolly tapir
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i am confused, why would

  • f(t)delta'(t-t0)
  • f(t)delta'(t0-t)
    be interchangeable?
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sorry, i might be missing knowledge of some properties here

desert mantle
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they arent

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thats the point. you used the first but should use the second

jolly tapir
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ahhh alright i see. but wouldn't the result still have a -1 in front of it?

desert mantle
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no

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you obtain an extra minus from ibp now

jolly tapir
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oops the first term of the second line shouldn't be delta'

desert mantle
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when you integrate delta'(t0-t) with respect to t, you gain a minus

jolly tapir
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ah okay

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i'm guessing you're referring to turning those terms

desert mantle
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well the first term is 0 anyway

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the second term is the important one

jolly tapir
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ah? so the mistake is trying to simplify delta(t0-t) to delta(0)?

desert mantle
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no

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well I mean thats also questionable

jolly tapir
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i thought it was permissible to make t=t0 as that would be where delta(t0-t) is defined

desert mantle
jolly tapir
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I have rectified the inputs, but I still do not see where the -1 is coming from

jolly tapir
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ah you are talking about from line 1 to line 2 after ibp

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oh, thanks!

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i got it hahaha, can't believe i just missed a small chain rule

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thank you so much

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brittle nova
#

Does anyone know why, if I take some $v\in \bC^n$, the summation $$\sum_{j,k}v_j^*v_k$$ always seems to be greater than or equal to $\norm{v}^2$?

soft zealotBOT
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wicked badger
#

can someone sent me some grade 8 lessons????

wicked badger
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or like notes

native valve
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bro what?

wicked badger
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our math teacher didnt teach us anything

native valve
#

bro you can search that yourself in google, why you asking it on discord? searching on google would give you endless resources

wicked badger
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i tried that but after that all the lesson arent in the exam

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bold coral
#

What is best/fastest way to check big number is prime in python?

chrome pawn
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ah

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there are multiple methods to do this

bold coral
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Bruh

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I know better way to find primes

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But not check one number

chrome pawn
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Miller-Rabin primality test

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it may occasionally give wrong answers but is very faster for large numbers and is ubiquitous

bold coral
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Hmm

chrome pawn
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if you want to check for primes numbers upto a certain limit; you can use Sieve of Eratosthenes

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i think i mispelled it but just search for it

native valve
chrome pawn
#

Yeah that’s what I suggested 😭

native valve
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stiff willow
#

Suppose that g(x) is a function which is 1-1 and that the slope of the tangent to the graph of g(x) at x = 2 is 3. Define the function f(x) by f(x) = g(4cos(x)) for x ∈ (0,π).

a) Find an expression for f −1(x) in terms of g−1(x).

b) What is the value of the derivative f′(π/3)?

west berry
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By f-1(x) you mean the inv function right?,

stiff willow
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oh yeah it didnt format correctly

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for both f and g

west berry
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kk

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What have you tried

stiff willow
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honestly im not sure where to start

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i can get it when its just normal questions but when its worded it stumps me

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what does a 1-1 function mean?

west berry
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We have f(x)= g(4cosx)

west berry
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For ex y=x² isn't 1-1

stiff willow
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ohh so like the horizontal line test thing?

west berry
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But y=x³ is

west berry
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But anyway

west berry
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And we need f^-1 x

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In terms of g^-1 x

stiff willow
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do i ignore the g when solving ?

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im not sure what thats doing there

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is it like a composite function ?

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wait no

west berry
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g(4cosx)?

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Here?

stiff willow
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yeha

west berry
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Oh no

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It's a composite function yeah

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f(x)= g(4cosx)

stiff willow
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sorry lemme just find the inverse rq

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thats just

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arccos(x/4)

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well g(arccos(x/4)

west berry
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But it said in form of g^-1

west berry
stiff willow
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y/4 = cos(x)

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arccos(x/4)

west berry
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What's y

stiff willow
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f(x)

west berry
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Oh

stiff willow
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like the swapping y and x thingy

west berry
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f(x)= g(4cosx)

stiff willow
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i ignored the g and just inversed 4cosx

west berry
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Ok.....

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So

west berry
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As f^-1 x?

stiff willow
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yeah

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but like the g makes it confusing tbh

west berry
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Hmm

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It needs to be in terms of g^-1 x, so clearly smth is wrong

west berry
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And then proceed

stiff willow
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wdym by taking on both sides

west berry
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I mean like

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f^-1 f(x)= f^-1 g(4cosx)

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And then proceed

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Idk what to call it so

stiff willow
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ive never done smt like that before

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how would i go about it

west berry
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By definition

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I just used it

stiff willow
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so

west berry
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So if f(x)=g(4cosx),

west berry
stiff willow
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wdym by acts as y

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as it the f(x) will be g(4cosx) ?

west berry
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Yeah and x= f^-1 (y)

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In this case our y is g(4cosx)

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So what will f^-1 (y) be?

stiff willow
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wouldnt this just the be inverse of g(4cosx)

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how would i go about that

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cos i thought it would have smt to do arccos(x/4)

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which is the inverse of 4cosx

final saddleBOT
#

@stiff willow Has your question been resolved?

stiff willow
#

.close

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teal robin
#

Would anyone be able to verify a few calculus problems? I will send one at a time

silver maple
#

use an online calculator if possible

cyan hawk
#

you can use mathway, wolfralpha, photomath, etc.

teal robin
#

just need to know if I am interpreting the questions correctly

silver maple
#

I see

rocky tusk
#

!da2a

final saddleBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

teal robin
#

okay sorry

silver maple
rocky tusk
#

^

teal robin
#

Just want to make sure I did it right

teal robin
# silver maple Explain your working out

Well for the a and b I know that these are the slopes a being the slope with respect to x, and b being the slope with respect to y. So I chose 2 points that look easy to distinguish and used the slope formula to find the slopes. Then I picked a point on the graph to find the z-intercept

silver maple
#

It is very hard to see the image clearly

teal robin
#

I'm really sorry about that. It was sent from someone else so that is all I have : (

final saddleBOT
#

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teal robin
#

.close

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hushed ice
#

Hey, so I need help with this. It’s said to calculate the derivative of these functions. It is also that said that the answer should be simplified, factored (if possible) and should not have any negative or fractional exponents. I’ve done something but I wanted to do it with someone so I can compare it to my work

rocky tusk
hushed ice
#

That’s what I’ve done

rocky tusk
hushed ice
rocky tusk
hushed ice
#

So would that just be it ?

rocky tusk
#

yea

native portal
#

why did your 3x^3 become 3x^2

#

from 3rd step onwards

hushed ice
#

Oh you’re right

rocky tusk
hushed ice
#

9x^2

rocky tusk
#

you put 3x^2

#

3rd line

#

should be 4x^2 as well

hushed ice
rocky tusk
#

not 4x

rocky tusk
hushed ice
#

Whoops@

#

Holdup let me fix this

rocky tusk
#

you multiply by that but the inside function stays the same with a mere power reduction by 1

hushed ice
#

Wait

#

I wrote it like that because I factored the x

rocky tusk
#

nono

#

x(3x^2+5)^7≠(3x^3+5x)^7

hushed ice
#

Then what would it be?

#

I’m confused now

rocky tusk
#

literally just the left hand side

#

(3x^2+5)^7 is (3x^2+5)(3x^2+5)…(3x^2+5)

hushed ice
#

Ohhhh

rocky tusk
#

if you multiplied it by x you’d get (3x^3+5x)(3x^2+5)…(3x^2+5)

hushed ice
#

So would it be (3x^3+5)^6 ?

rocky tusk
#

yea change both

#

the inside is always 3x^3+5

#

4x^2+1

#

for the other

hushed ice
#

alright I’ll fix that

#

I think it’s fixed?

rocky tusk
#

you have to fix all the lines below it too but yea

hushed ice
#

Whoooopsssss

#

Alright NOW it should be fixed

#

But what I’m also confused is why do I remove the x in the last two lines

final tangle
#

you shouldn't

hushed ice
#

and do I need to keep the (3x^3+5)^6 (4x^2+1)^4 ? If so why

hushed ice
final tangle
#

stuff doesn't just disappear

hushed ice
#

Fair

#

Alright thanks

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lofty kindle
final saddleBOT
lofty kindle
#

just a quick question but i can just say that by symmetry, the above integral is equal to 0

#

or is there another term for it?

#

like, I dont even need to prove it. i can just simply state it

rocky tusk
#

what symmetry are you using

lofty kindle
#

oh nvm, its not 0 because its symmetrical

rocky tusk
#

i mean it will be zero

lofty kindle
#

yea

rocky tusk
#

because you’ll get xsinx

lofty kindle
#

i messed up visualizing it in my head

rocky tusk
#

and sinx is zero at those two values

#

and integral of cosx between those two gives zero

#

because cos(2pi)=cos0

lofty kindle
#

yea, thank you!

signal patrol
lofty kindle
#

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slate jasper
#

I want to visualise something polygon structure if possible

slate jasper
#

Lowest angle is 120°

#

And other angles are in difference 5° in a AP

#

And sides are n=16 and n=9

#

Can anyone send me a link with it

#

Desmos

warm python
#

two different polygons?

slate jasper
#

Yes

warm python
#

hmm, not too sure

#

sorry

slate jasper
#

I don't know how to use desmos for polygon

#

Nevermind

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gray agate
#

could someone help explain this problem to me?

gray agate
#

Can we just add all the variances up?

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final saddleBOT
final saddleBOT
#

@vague yew Has your question been resolved?

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@vague yew Has your question been resolved?

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@vague yew Has your question been resolved?

vague yew
#

<@&286206848099549185>

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#

@vague yew Has your question been resolved?

terse siren
#

yes

#

but you still need the homogenous solution for the complete solution

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#

@vague yew Has your question been resolved?

tranquil pine
#

hello

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maiden whale
#

for the last part i’m having trouble visualising what angle they are talking about. Using inverse tan on the velocity components at t = T is giving me 90 less than the answer smthn like -26 degrees instead of 63

gritty solar
#

yeah thats fine

#

angles are directional

#

depends on where you're measuring it from

#

your measure might have been with the horizontal normal

maiden whale
#

would u be able to explain which angle we are actually trying to find?

gritty solar
#

there's might have been with the wall

gritty solar
maiden whale
#

i just used inverse tan on the components and got -26 degrees

#

ig that’s the angle from the normal?

gritty solar
#

yeah from the normal (to the wall)

#

its negative because the angle was probably below the normal

#

ie the ball was descending when it struck the wall

maiden whale
#

so is this the angle i found

#

the arrow is my attempt at drawing the velocity vector at the point it hits the wall

gritty solar
#

yeah

#

so you can say "64 degrees with the wall" or "26 degrees with the normal to the wall"

#

both should be accepted

maiden whale
#

would it be the same thing if the angle from inverse tan was positive

#

i.e. still with upwards trajectory

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ruby lake
#

is there a good way to solve this kind of problems

#

maby this one is not particularly hard

#

but should i use a Ven diagram

#

the part b is particularly confusing

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jagged flare
final saddleBOT
soft zealotBOT
jagged flare
#

assume you can fill in the blank squares with unique prime numbers under 25

#

and N is a positive integer

#

if there are x possible values of N, where y is the largest and z is the smallest, what is x+y+z
a.25
b.15
c.26
d.14
e.24

craggy plank
#

2 3 5 7 11 13 17 19 23

#

@shrewd vector You must check this 🙂

candid pulsar
#

interesting

#

again

#

i loove number theory

#

so I'll try

craggy plank
#

Same

jagged flare
candid pulsar
jagged flare
#

oh wait, it has to be diffrent

#

sorry forgot to clarify

candid pulsar
#

oh

#

all 9 of it?

jagged flare
#

yes

candid pulsar
#

damn

#

that makes it much easier

slim barn
#

um this seems like a simple brute force program?

candid pulsar
#

cause there are like only 9 prime numbers lesser than 25

jagged flare
#

wait hold on, brb for like 10 mins

craggy plank
candid pulsar
#

nice clue i found

slim barn
#
1. Create all possible permeutations.
2. Sum the first 7 -> x
3. Sum the other 2 -> y
4. x/y
5. Profit??
candid pulsar
#

anyways

slim barn
#

it will give all answers

candid pulsar
#

which takes like 9C2 number of time

#

36 ways

#

pretty time consuming

craggy plank
#

Indeed

#

But I assume there is a method which helps fasten the progress

slim barn
#

<1s on any modern computer?

#

i mean 36 is nothing right?

candid pulsar
#

we know that all prime numbers are odd right

#

excluding 2

#

so if the numerator has all odd

#

it sums up to odd

#

since there are 7 numbers

#

but if there's 6 odd numbers and a 2

#

we'll get even

#

and denominator is even

#

and in first case

#

denominator is even

#

but odd/even is not a whole number

#

so 2 is always in the numerator

jagged flare
#

wait can you just do this
assume the bottom primes are a and b, so $$\frac{100-(a+b)}{a+b}=\frac{100}{a+b}-1$$

soft zealotBOT
#

Skill_Issue

jagged flare
#

@candid pulsar

#

cause the top is just the sum of all the primes up to 25 minus 2 of the primes, and those 2 primes are at the bottom

candid pulsar
#

so we need to find two primes such that their sum is a factor of 100

jagged flare
#

we just have to check a+b=1,2,4,5,10,20,25,50,100, since 1,2,4,50,100 is obviously not possible, we have to check 5,10,20,25

#

for 25 it can be 2+23, that means n=3
for 20 it could be 13+7
for 10 it could be 7+3
for 5 ot could be 2+3, that means n=19

#

thats it right? 25+5+4=34

#

which is not in the msq 😭

#

oh wait

candid pulsar
#

you need to subtract 1

jagged flare
#

22+4=26

#

yay

slim barn
#

(19, 3, 5, 11, 17, 23, 2) on the top and( 7, 13) gives N=4
(5, 11, 17, 23, 7, 19, 13), on the top and ( 2, 3) gives N=19.0

jagged flare
#

how about this, you can put +, -, ×, / in those blank squares

slim barn
#
import itertools
perm = list(set(list(itertools.permutations([2,3,5,7,11, 13, 17, 19, 23,
]))))

for p in perm:
    if ((sum(p[:7])/sum(p[-2:]))==int((sum(p[:7])/sum(p[-2:])))):
        print(p, (sum(p[:7])/sum(p[-2:])))
jagged flare
slim barn
#

i know, i gave the complete program above

candid pulsar
slim barn
#

i just posted some solutions

jagged flare
candid pulsar
#

in the options

jagged flare
#

oh, its the possible ways that the symbols can be put and the equation stays true

candid pulsar
#

oh

#

thats tough

#

so 2024 is 2³ * 11 * 23

jagged flare
#

wair

jagged flare
#

so it had to be even

#

wait they dont have to be whole sully

shrewd vector
#

26

jagged flare
#

erm what the scallop howd you get dat

shrewd vector
#

for the prime question

jagged flare
#

oh ok

shrewd vector
#

3+19+4 = 26 with a bonus point for getting 4 in 2 different ways

jagged flare
#

ok that simplifies things a lot

#

each of them has to be even, we just have to find the ways to permute them

#

though i dont see a way for the first one is either 2, 22, 46, 572 if im not mistaken?

candid pulsar
#

wait i got one solution

shrewd vector
#

middle is 22

#

or right is 176

jagged flare
#

actually the right one can be 23

#

+//

candid pulsar
#

(2 + 0 * 2 * 4) * (20 - 2 + 4) * (20 + 24 - 2 + 4)

jagged flare
#

and the left one can be 4 (××+)

jagged flare
#

for the left one could you cange it to ×/, /×, //?

#

(2×0×2+4)(20-2+4)(20+24/2/4)
(2×0/2+4)(20-2+4)(20+24/2/4)

#

(2+0/2/4)(20×2+4)(20+24/2/4)
(2+0/2×4)(20×2+4)(20+24/2/4)
(2+0×2/4)(20×2+4)(20+24/2/4)
(2+0×2×4)(20×2+4)(20+24/2/4)

#

(2+0/2/4)(20-2+4)(20-24+2+4)
(2+0/2×4)(20-2+4)(20-24/2+4)
(2+0×2/4)(20-2+4)(20-24+2+4)
(2+0×2×4)(20-2+4)(20-24+2+4)

vague yew
final saddleBOT
#

@jagged flare Has your question been resolved?

final saddleBOT
#

@jagged flare Has your question been resolved?

viscid stirrup
# soft zealot

||for this problem, we have the sum of seven unique prime numbers less than 25 divided by the sum of the other two unique values that happen to equal a positive integer. Notice that the sum of all 9 primes less than 25 is 2+3+5+7+11+13+17+19+23=100. so we have this sum, however, we have to exclude two primes from here since we want the sum of seven primes in the numerator and instead place them as a sum in the denominator. Let us call these primes from the selection of primes less than 25 p_1 and p_2. We thus have that (100-(p_1+p_2))/(p_1+p_2) = N, simplifying further we get (100/(p_1+p_2))-1 = N for N is a positive integer. Notice that 100/(p_1+p_2)>1 since p_1+p_2 must be less than 100 for any selection of primes, thus we don't have to worry about N being less than 1. We also have that p_1+p_2 must add to a divisor of 100 which is 1, 2, 4, 5, 10, 20, 25, 50, 100 for N to be an integer. We notice that p_1+p_2 cannot equal to 1,2,4,50 and 100 hence we eliminate those possibilities. If p_1+p_2=5, we see that one of the primes is 2 and the other is 3. If p_1+p_2=10, one of the primes is 3 and the other is 7. If p_1+p_2=20, we see that one is 17, the other is 3, or one is 13 and the other is 7. If p_1+p_2=25, we see that one of the primes is 23 and the other is 2. All these cases should produce positive integers N. Note that we only care about the sum of p_1+p_2 here. If we had p_1+p_2=5, N=(100-5)/5=19. If p_1+p_2=10, N=(100-10)/10=9, If p_1+p_2=20, N=(100-20)/20=4, if p_1+p_2=25, N=(100-25)/25=3. Thus N could either be 3, 4, 9 or 19. The number of possible values for N are 4, the largest value of N is 19 and the smallest value of N is 3. Thus x+y+z=4+19+3=26||

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rustic trench
#

How do I describe the following area in polar coordinates. (One square = one unit of length.)?

rustic trench
#

.close

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versed vapor
#

fourier transform

final saddleBOT
#

@versed vapor Has your question been resolved?

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#

@versed vapor Has your question been resolved?

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#

@versed vapor Has your question been resolved?

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@versed vapor Has your question been resolved?

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#

@versed vapor Has your question been resolved?

cyan kayak
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
cyan kayak
#

!show

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Show your work, and if possible, explain where you are stuck.

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edgy ore
#

.close

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low magnet
#

A uniform electric field of magnitude 1.1×104N/C
is perpendicular to a square sheet with sides 2.0 m long. What is the electric flux through the sheet?

low magnet
#

is this correct?

formal trail
#

slightly ambiguous wording of the problem, but when we talk about the angle between a surface and a field we usually mean the angle between the normal vector of that surface and the field

low magnet
#

sorry I dont get it

west berry
#

theta is the angle between electric field and area vector

#

The area vector is perpendicular to the plane of the square sheet

#

Try drawing it out

low magnet
#

English isn't my first language, I'm having a hard time understanding your instruction sorry

west berry
#

Ok, let's start with this
θ is the angle between which two vectors according to you?

low magnet
#

Electric field and surface area?

west berry
#

Right

#

And how do we get the vector for surface area?

low magnet
#

I don't know

hazy hemlock
hazy hemlock
#

Do you get it?

low magnet
#

what does the upsidedown T mean

white tiger
#

perpendicular

low magnet
#

Electric field is perpendicular to the surface?

low magnet
#

that's why I used cos90

#

is my solution correct though

hazy hemlock
# low magnet

Here what do you see? What's the angle between those two lines?

low magnet
#

none?

delicate fiber
#

it should be cos 0

hazy hemlock
delicate fiber
#

The angle theta is the angle between the area vector and the electric field

low magnet
#

so it's 44000 nm^2/c?

hazy hemlock
#

yes if that's what you get with cos0°

low magnet
#

would it be like this if the electric field wasn't perpendicular to the sheet

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@low magnet Has your question been resolved?

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timber pike
#

a washing machine was available for 15000 rs but was purchased under an instalment plan after paying 2250 as cash down payment followed by two equal half yearly instalments . if interst charged 8% per annum compounded semi annually , find the value of each instalment

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junior storm
# timber pike a washing machine was available for 15000 rs but was purchased under an instalme...

this is simple interest , find interest for each add up the value and then find the interest for the new value according to the given conditions.... would love to see u doing on ur own, because this has to be very basic and once you do it, i guarentee you that u can skip this chapter for the next, but if u still need an answer will solve it and post the picture... cause it is one of the hardest questions the chapter has to offer

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jovial fjord
final saddleBOT
jovial fjord
#

how would i set out the integration?

white tiger
#

function above - function below

jovial fjord
#

oh

#

wow i really overthought it then

#

theres areas below the x axis so i thought you had to split it up

final tangle
#

split if one function isn't always above the other

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candid pulsar
#

looks pretty tough

final saddleBOT
#

@viscid stirrup Has your question been resolved?

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#

@viscid stirrup Has your question been resolved?

cobalt lodge
#

i can’t tell if this is incredibly complex or incredibly basic but im leaning towards the latter

i feel there’s very little things you can say other than simple upper/lower bounds thinkies

#

unless we’re gonna calculate the number of possible sequence pairs again opencry

#

ye i remember that lmao

vital surge
#

what kind of statement do you want in "is there anything we can say about the digit sequences"

wise crescent
#

What's the source

#

This seems math camp pset-ish

vital surge
#

more or less what it sounds like: "a problem set from a math camp"

#

ah that explains it too

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covert hornet
#

i know it may be a weird question but is this form of writing correct?

covert hornet
#

about the union

rain compass
#

looks fine, though im not sure what f is

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covert hornet
#

f is a function and df is the domain so f(df) is the range of the function

#

.close

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strong field
#

Hello! Is anyone available to help

final saddleBOT
tranquil pine
#

no

lucid marsh
#

Anyway i am

strong field
#

.close

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primal kettle
final saddleBOT
primal kettle
#

could someone help me with this one? not sure if strong induction is the way to go or if it can be done with it normally

#

and im having trouble setting up number 5

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tranquil pine
#

loaded question

final saddleBOT
tranquil pine
#

as with most of these starting it is the hardest part

#

I do notice two triangles forming if that's of any significance

marble agate
#

isnt this just optimization problem?

tranquil pine
#

it is

marble agate
#

what have you tried?

tranquil pine
#

trying something I think it'll work

marble agate
#

ok

tranquil pine
#

ok got everything labelled rn

tranquil pine
#

$x=\sqrt{x^2+(5-y)^2}-(5-y)$

soft zealotBOT
#

Remlis

tranquil pine
#

$y=(13-\sqrt{x^2+(5-y)^2}-(12-x)$

soft zealotBOT
#

Remlis

loud sundial
#

Hint: Similar triangles

tranquil pine
#

yeah that idea also popped up for me where if the triangles are matching in size then that would mean the rectangle is as big as it can be

#

but then I can't incorporate optimizaiton

#

or maybe I can

#

since you could either have the smallest or the largest rectangle that way

loud sundial
#

Using similarity, (5-x)/y = x/(12-y)

#

which makes your life much easier

#

b/c now you can just do it in 1 variable

tranquil pine
#

wait a min realizing something

#

so in my triangle y is also equal to 5-y?

#

how would that work

loud sundial
#

the logic is the same if you wanna label it your way

#

it doesn't rlly matter

tranquil pine
#

where would we go form here

#

we don't have a 2nd eqn to solve in terms of a specific variable

loud sundial
#

like how you would find the max/min of any other single-variable function?

tranquil pine
#

yeah usually you would need two equations to substitute the other variable in in terms of the first variable

#

then you'd take the derivative and set = 0

#

but problem is

#

we only have 1 equation

#

$Area= (\sqrt{x^2+(5-y)^2}-(5-y))((13-\sqrt{x^2+(5-y)^2}-(12-x))$

soft zealotBOT
#

Remlis

loud sundial
#

you have $\frac{5-y}{x}=\frac{y}{12-x}$ and you need to maximize $xy$

soft zealotBOT
#

Civil Service Pigeon

loud sundial
#

that's it.

#

(if we use your labeling)

tranquil pine
#

I don't get the division

#

I mean I get that the two sides are equal that way

#

if the triangles are the same

#

or is that all you wanted to do with that

loud sundial
#

these triangles

tranquil pine
#

yeah

#

I see it's like setting a/b = a/b

#

same thing technically

loud sundial
#

sure

tranquil pine
#

so how would we get this in terms of

#

1 variable

#

$\frac{5-y}{x}=\frac{y}{12-x}$

soft zealotBOT
#

Remlis

loud sundial
#

you can solve for x in terms of y (or vice versa with that)

#

then substitute the result into the area function

#

and then you have a single variable function

tranquil pine
loud sundial
#

just do xy

#

it's way easier

tranquil pine
#

that works too

#

$\frac{5-y}{x}(12-x)=y$

soft zealotBOT
#

Remlis

tranquil pine
#

$\frac{(5-y)(12-x)}{x}=y$

soft zealotBOT
#

Remlis

tranquil pine
#

$\frac{(60-5x-12y+yx)}{x}=y$

soft zealotBOT
#

Remlis

tranquil pine
#

minor problem, idt we can isolate for a variable using this

loud sundial
#

you can

#

tho it's easier to just go with ||xy=(5-y)(12-x)||

tranquil pine
#

$y=\frac{(5-y)(12-x)}{x}$

soft zealotBOT
#

Remlis

tranquil pine
#

I don't see what you mean

loud sundial
#

xy=(5-y)(12-x)

#

expand both sides

tranquil pine
#

$xy=(60-5x-12y+yx)$

soft zealotBOT
#

Remlis

tranquil pine
#

$0=(60-5x-12y)$

soft zealotBOT
#

Remlis

tranquil pine
#

$12y=(60-5x)$

soft zealotBOT
#

Remlis

tranquil pine
#

$y=\frac{(60-5x)}{12}$

soft zealotBOT
#

Remlis

loud sundial
#

yup

#

now you can substitute that into xy

#

and it's smooth sailing from there

tranquil pine
#

mm I see

#

thank you good sir

#

.close

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flat furnace
#

For Calculus, how would I go about optimizing/maximizing the area of a rectangle within a semicircle?

loud sundial
#

Did you draw a diagram? If so, can you send it? (I'm too lazy to draw it lol)

flat furnace
#

My camera on my phone acting up for some reason so I can't post a pic

loud sundial
#

here's your walmart diagram

#

I'm going to assume that the semicircle is fixed for convenience, let's call the radius r

flat furnace
#

Alright

loud sundial
#

what lengths can we find in the rectangle using this

flat furnace
#

X and Y, right?

loud sundial
#

in terms of the radius*

flat furnace
#

I'm not too sure

loud sundial
#

draw in some radii

west berry
#

Ig the angle subtended can be a parameter here

#

Or no actually assuming them as x and y works too, but you need to write x in terms of y or vice versa

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#

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marsh temple
#

$\binom nk = \frac{n!}{(n-k)!k!}$

soft zealotBOT
#

Steakanator

marsh temple
#

and it's illustrating that the two expressions are equivalent due to symmetry

#

specifically nCk

marsh temple
#

any one of what

#

the two are equivalent yes

#

it can be shown pretty succinctly if you know that $\binom nk = \binom{n}{n-k}$

soft zealotBOT
#

Steakanator

marsh temple
#

it's not that deep

#

what is $\binom{n}{n-k}$?

soft zealotBOT
#

Steakanator

marsh temple
#

which is...

soft zealotBOT
marsh temple
#

eeh, careful

#

i'd add a couple pairs of parentheses, what you have isn't accurate

#

you have a { after cdot

#

you want a (

soft zealotBOT
marsh temple
#

this can be simplified

#

no

#

distribute the negative

#

yes

#

but what is this thing?

soft zealotBOT
marsh temple
#

this new expression

#

it has a name, one you've said before

#

$\frac{n!}{k!(n-k)!} = ?$

soft zealotBOT
#

Steakanator

marsh temple
#

there we go

marsh temple
#

the command is in my message above

#

not afaik since it's less common

#

short for binomial coefficient

#

which is exactly the context of the question

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#

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full night
#

how can I solve this integral?

final saddleBOT
full night
#

I rewrote the integral as this

blissful condor
#

i doubt this has a nice form (don’t quote me on that)

full night
#

I agree with you on that

tranquil pine
#

what is F

full night
#

just some constants for Final and Initial

tranquil pine
#

,w integrate sqrt(8sin^2(x)+1)

tranquil pine
blissful condor
# full night I agree with you on that

are you being asked by someone else to do this integral? i take it you’re just trying to find the circumference of an ellipse, which is pretty well-known that doesn’t have a nice closed form

blissful condor
#

where WA doesn’t give you a nice answer because there isn’t one

full night
blissful condor
#

the elliptic integral is defined exactly as what you wrote

full night
#

but how do I even get any value from it?

blissful condor
#

like because there isn’t a closed form it just said “let E be the solution to the elliptic integral”

blissful condor
#

it’s sort of like asking how to get the value of pi

#

“well idk we’ll just call it pi and approximate it the best we can, and if it comes up in other calculations that’s pretty cool as well”

full night
#

the only other option I had in mind was to get the normal vector of the elipse, make a integral for the magnitude of the normal vectors, put the integral inside the limit as the magnitude approaches 0, and then say that is the length

#

so it would be basically giving the ellipse "thickness" and then making it infinitesimally small thickness

full night
#

It might still be the case, though i thought it was a whole different branch of integral calculus I was missing out on

royal gust
#

Are you being asked to do this, with the expectation that there's a computable final answer?

blissful condor
#

because there isn’t one

#

also it was said earlier i think

full night
royal gust
#

Gotcha

blissful condor
#

i’ll find it 1 sec

#

oh yeah it’s called “(almost) impossible integrals, sums, and series”

#

lol

full night
#

my idea is basically to get the area of a elipse, then subtract it by the area of the same elipse, but infinitesimally smaller if that makes sense?

#

that would be one idea but idk how well it would work

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vast arrow
#

pls i need help with this
determine (E) the set of points M with affixes z such that

tiny gorge
#

,rotate

soft zealotBOT
tiny gorge
vast arrow
#

edit we have the rotation R such that Z, = exp(-ipi/4) and the D the image of A with d = isqrt(2) and a = -1+i

vast arrow
tiny gorge
#

hint: it's the set of all points z that are equidistant from the two points ...

vast arrow
#

but we can rewrite the equation to: abs(z-a) = abs(z+d)

vast arrow
#

ok i will try something and come back to you

vast arrow
tiny gorge
#

it's a set of points

#

try a simpler example

#

say |z-1| = |z+1|

#

what points z satisfy this?

vast arrow
#

0

vast arrow
tiny gorge
#

how about z = i?

#

check it

vast arrow
#

i don't know if we can say abs(i-1) = i-1

tiny gorge
#

yep, the whole imaginary axis

#

now for your problem the answer will be similar

#

geometrically, it's the perpendicular bisector of the line segment between a and b

vast arrow
#

I got it now

final saddleBOT
#

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nocturne vale
final saddleBOT
nocturne vale
#

^this is what I got, but it feels like a poorly phrased argument

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@nocturne vale Has your question been resolved?

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@nocturne vale Has your question been resolved?

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@nocturne vale Has your question been resolved?

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@nocturne vale Has your question been resolved?

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@nocturne vale Has your question been resolved?

desert mantle
# nocturne vale

no that doesnt work at all. in the first direction you are just claiming that a has to be positive from nowhere. and for the other direction, how does it matter that 1 in S

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olive socket
final saddleBOT
olive socket
#

I finished step 1

#

I'm stuck doing step 2

final saddleBOT
#

@olive socket Has your question been resolved?

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#

@olive socket Has your question been resolved?

olive socket
#

.close

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random scaffold
final saddleBOT
random scaffold
#

I completed the procedure, but I really don't understand what they mean by "no edge in G connects a red vertex and a blue vertex". They right after say to assign red to a and assign blue to c,e,f,g

#

isn't "a" connected to the 4 of those vertices in G?

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#

@random scaffold Has your question been resolved?

random scaffold
#

<@&286206848099549185>

#

Just want to know if i'm misinterpreting that line

#

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deft palm
#

gm

final saddleBOT