#help-36

1 messages · Page 103 of 1

jagged cosmos
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Using that FRC

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Read this again

rotund glen
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right, it pretty much sais

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the integrals and derivatives cancel out

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and ur left once again back at f(x)

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if u take the derivative of an integral

jagged cosmos
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In part A, if you differentiate the RHS of the equation what do you get

rotund glen
#

This dont look right

jagged cosmos
jagged cosmos
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, w d/dx(int_0^x 1/sqrt(2pi)e^(-t^2/2)dt)

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Wolfram after destroying the competition

rotund glen
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wtf

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just to reiterate

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we express f(x) as a derivative of an integral

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by FTC

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so when we take the derivative of f(x), we are technically taking the derivative of the LHS twice sorta

jagged cosmos
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No

rotund glen
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kms

jagged cosmos
#

Can you write down the Newton's Method formula

rotund glen
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ye its just xn - f(xn)/f'(xn)

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here we already have f(xn)

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its this

jagged cosmos
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Yes

rotund glen
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which is the RHS of this

jagged cosmos
#

Now we are trying to find the derivative of f(x)

rotund glen
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yes

jagged cosmos
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So f'(x) is equal to the derivative of the RHS

jagged cosmos
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That f(x) and your f(x) aren't related by any means

rotund glen
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for here we just do like d/dx over that entire thing?

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nvm that doesnt rlly matter

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how would u compute the derivative by hand

jagged cosmos
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Of the RHS?

rotund glen
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ye

jagged cosmos
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Using this, f(t) is the function 1/sqrt(2pi)e^(-t^2)/2

rotund glen
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rught

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the .45 disappeard

jagged cosmos
#

Puff, yes

final saddleBOT
#

@rotund glen Has your question been resolved?

final saddleBOT
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chrome hemlock
#

hi

final saddleBOT
chrome hemlock
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is this correct way to solve for question d

warm python
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looks right to me

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please don't say wrong in a few minutes

chrome hemlock
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idk combionations are weird

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im behjind ion my whole class

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is this right it feels wrong

warm python
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it;s just 543

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right

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5x 4 x 3

chrome hemlock
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why?

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ok so my thought process was the first value can be 4 of them

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bc it can be

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4, 5, 6 or 8

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and then the second one can be 5 because we include 0 now but take one out casue we used it for the first digit

warm python
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yeah

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oh

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right

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so your first find the number which start with 4

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and then all other numbers

chrome hemlock
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yea

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and then next is just 6 -2 bc we used 2 digits alr

sonic crystal
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hi

chrome hemlock
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GUESS WHAT

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i got 2nd for my physics test

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1 mark away from 1st

sonic crystal
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why not first

chrome hemlock
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ay ay ay commendation letter

sonic crystal
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Jk good job

chrome hemlock
sonic crystal
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Is it the Indian

chrome hemlock
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theres multiple

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LOL

sonic crystal
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Is it a Indian

chrome hemlock
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theyre on scholarships

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nah hong kong warrior

sonic crystal
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Wowie

chrome hemlock
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do u know why part b is wrong

warm python
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I still feel you should split it into twi cases, first find the number of even number greater than 4000 but less than 5000

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and then the number more than 5000

warm python
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becuase your number can't end with 4 when the number is between 4000 and 5000

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but itherwise it can

chrome hemlock
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wthh

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how am i supposed to think of that during a test

hazy hemlock
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Just take cases by ending the no.s with even at end

chrome hemlock
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what no.s?

hazy hemlock
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0,4,6,8

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Wait

hazy hemlock
chrome hemlock
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ohhh

hazy hemlock
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Do u get it?

chrome hemlock
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yes yes

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the 0 part

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also sorry i dont have answers to this past test is it ok if u check if its right?

hazy hemlock
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Since 4,5,6,7,8 are possible

chrome hemlock
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sorry

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this combinations stuff is very confusing to me

warm python
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if it's 11, it's right

chrome hemlock
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11

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lol

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sorry hard to draw with my mouse

hazy hemlock
warm python
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they all seem right to me

chrome hemlock
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AYYY 100%

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lets go

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i think im starting to understand this topic better

warm python
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I suggest you do, there are some really intresting questions on this topic

chrome hemlock
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ima invest in an iPad

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so i can use an apple pencil

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and just draw math

warm python
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espescially when it comes to counting functions

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or use a notebook

hazy hemlock
chrome hemlock
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nooo too ceebs

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i like doing past papers

warm python
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ceebs?

chrome hemlock
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i feel like past papers best way to revise

hazy hemlock
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Which class u in btw

warm python
chrome hemlock
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grade 10 but im doing grade 11

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math

hazy hemlock
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Oh ok nicee

chrome hemlock
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ok uh

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LAST QUESTION

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why doesnt a = b too

warm python
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the combinatronics function isn't one one

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it's a binomial curve

chrome hemlock
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uh

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SAY WHAT NOW

hazy hemlock
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Two combinatorics are equal if r is n-r and r

warm python
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rather similar to a sigmoid curve

hazy hemlock
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So one of them is either r or n-r

chrome hemlock
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is r the one on top

hazy hemlock
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Here n is 30

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No

chrome hemlock
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o

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n is the one on top

warm python
chrome hemlock
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ohhh waht i nevber knew graphs camke into stuff like combinations

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mi better nevber learn that in my life

warm python
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it isn't continuous, when you plot the points, this is the curve that best descibes the distribution, that's it

chrome hemlock
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soo b = n-r ?

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we have n = 30? and r=10?

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so b = 30 - 10?

hazy hemlock
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Yep

chrome hemlock
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i want to watch a yt video

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i still havent finished the pascals triangle chapter and the pigeon hole principle chapter in my textbook

hazy hemlock
chrome hemlock
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whats PNC?

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i think im going to cry if they ask me to prove something

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in thet est

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like this

hazy hemlock
hazy hemlock
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You know all thiss dw

chrome hemlock
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wait im going to the shops real quick

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i will be back

hazy hemlock
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Okay but don't overthink all these qns

chrome hemlock
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is it wrong

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so dar

hazy hemlock
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No I don't know but the steps look long

chrome hemlock
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oh!

hazy hemlock
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Didn't check yet, but ig could be done in 1-2 lines

chrome hemlock
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WTF

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u need to teach me that

hazy hemlock
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Just see it when u come back

chrome hemlock
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lk i am back

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ok

chrome hemlock
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oh

hazy hemlock
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Yeah

chrome hemlock
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u right

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that was so easy

hazy hemlock
#

It's okay takes time for first time

final saddleBOT
#

@chrome hemlock Has your question been resolved?

final saddleBOT
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past dust
#

help needed

final saddleBOT
past dust
west berry
#

! Status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
past dust
#

idk the formula

final saddleBOT
#

@past dust Has your question been resolved?

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quartz summit
#

have i written this properly and done it correctly? my teacher said the formula was correct but i am unsure

cobalt lodge
#

.28
no, that correspond to a 28% annual interest rate

quartz summit
#

oh, it'd be .028 right

cobalt lodge
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get me the location of that bank so i can immediately transfer my savings over /s

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yes

quartz summit
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ohh, what a stupid mistake, thanks for the help :)

mental roost
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the 2.8% is annual
we compound quarterly
so wouldnt it be 0.7% per quarter of a year?

quartz summit
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that's what the /4 is for

mental roost
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well you already have that, true

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why the 180 in the exponent?

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ah you mean 180 instead of the 4*45, since it's the same?

quartz summit
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yes

mental roost
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kk

quartz summit
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was just writing it so i'd remember

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is the right answer $7019.96?

mental roost
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i got something like 7k

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sounds good

quartz summit
#

alright, thank you!

#

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heavy grove
#

Question 5

final saddleBOT
heavy grove
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I tried substituting x=2u to exploit a trig identity but it doesn’t work

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I think I’m doing it wrong

main prairie
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L hospital is giga chad

heavy grove
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I have to solve it both ways

main prairie
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Which question we talking about

heavy grove
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5

final tangle
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but it doesn’t work
how far did you get, what exactly didn't work

heavy grove
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@final tangle

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Did I make a mistake?

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Because using lhopital it should be 1/2

final tangle
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what happened here

heavy grove
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Trig identity

final tangle
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which one

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what exactly did you aplpy

heavy grove
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I messed up

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It’s /2 not/x

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I’ll fix it

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Okay I fixed it

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Thank you

#

.close

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lime cloak
#

I wonder if i made some mistake...?

final saddleBOT
tawny bluff
#

,rotate

soft zealotBOT
tawny bluff
#

you're finding dy/dx not dy/da yes?

lime cloak
#

Yes

tawny bluff
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a is a constant, not a function of x

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so why are you treating it like a function?

lime cloak
#

Well i got confused

tawny bluff
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I can see that

lime cloak
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X is constant right?

tawny bluff
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x is your independent variable

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y = f(x)

lime cloak
#

Okay

tawny bluff
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a and b are constants, like 2 or 7 or π or 88.12938

lime cloak
#

Aha

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Okay

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So

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Those constans

tawny bluff
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think of it this way

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what is the derivative of 2x?

lime cloak
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2

tawny bluff
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what is the derivative of 8x?

lime cloak
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8

tawny bluff
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what is the derivative of ax?

lime cloak
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a

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Aha

tawny bluff
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yup

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so for something more complex

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you can do it in two ways: one is simple, one is complicated

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the simple method is to factor out the coefficients

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if you want to find the derivative of 32x^2 or 12ax^3, you write them as (32)(x^2) and (12a)(x^3)

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giving derivatives of (32)(2x) and (12a)(3x^2) respectively

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notice how the contant coefficients are untouched

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if you want to do it the hard way, you use the product rule

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(32)(x^2) = 0(x^2) + (32)(2x) = (32)(2x)
(12a)(x^3) = 0(x^3) + (12a)(3x^2) = (12a)(3x^2)
(derivative of 32 and 12a are both 0)

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I recommend the first method though

lime cloak
#

Yes i see

tawny bluff
#

it makes more sense

lime cloak
#

Yeah i get the first one better

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Thank you very much

#

. close

#

.close

final saddleBOT
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lime cloak
#

I think i messed up at step where i circled

final saddleBOT
lime cloak
#

,rotate

soft zealotBOT
cunning glen
#

the second line should read y = u^2 - 2u^(3/2)c + c^2u. This is from combining u*u^(1/2) to give us u^(3/2)

#

but what you have written is still correct to the second line at least

cunning glen
#

yes, so one justs adds the exponents

lime cloak
#

ahhhhhhhhhh okay

cunning glen
#

and then use normal power rule to differentiate

lime cloak
#

okay

#

thanks

#

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soft zealotBOT
#

died_of_cringe

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torpid vigil
#

$$2^{x}+x^{2}+4+\frac{1}{x^{3}}=(2^{x})^{2}$$

soft zealotBOT
#

died_of_cringe

torpid vigil
#

need help on this equation

#

i dont even know where to start

west berry
torpid vigil
#

i know it has multiple real solutions (wolframalpha)

stuck tide
torpid vigil
#

oh sorry

#

.reopen

stuck tide
#

Well that didn't work

#

You might have to claim another channel

torpid vigil
#

ok

final saddleBOT
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zenith furnace
#

Can someone help me get to this step?

final saddleBOT
#

@zenith furnace Has your question been resolved?

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vital lagoon
final saddleBOT
#

@vital lagoon Has your question been resolved?

vital lagoon
#

<@&286206848099549185>

final saddleBOT
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@vital lagoon Has your question been resolved?

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What step are you on?
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vital lagoon
#

I don’t know where to begin

#

Answer must be 90 degree but I cannot prove it

loud sundial
#

You can length chase and show that $$KF^2+FC^2=KD^2+DC^2$$

soft zealotBOT
#

Civil Service Pigeon

vital lagoon
#

I couldn't build any relation between lenght

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I tried to find same angle

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But I cannot manage it

final saddleBOT
#

@vital lagoon Has your question been resolved?

final saddleBOT
#

@vital lagoon Has your question been resolved?

cunning warren
#

Picture the correct angle

final saddleBOT
#

@vital lagoon Has your question been resolved?

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half rampart
final saddleBOT
half rampart
#

How did they get 18?

#

Isnt this what the top looks like?

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Bottom right? Why is it the top right?

fallen vigil
#

wait this doesnt even make sense :0

ivory ermine
#

fr

fallen vigil
#

frfr

ivory ermine
#

why does the left look like that

zenith pollen
#

uhh to help you build it remember that the blocks have to stack up because of gravity, so all the top view blocks are at the bottom layer

#

I get 10 blocks though

fallen vigil
#

how did u? i did not manage to find a block configuration that fits the diagram

ivory ermine
#

fr

fallen vigil
#

nvm no solutions so if u found one good,

zenith pollen
#

the real secret is to do it in minecraft

fallen vigil
#

omg one moment

final saddleBOT
#

@half rampart Has your question been resolved?

fallen vigil
#

@zenith pollen I got it but it was hard TnT

half rampart
#

you got 18?

fallen vigil
#

i got 10..

#

well idk how else to hint it so heres it

flat mason
#

visualise it from 3 directions

half rampart
#

ohhhh yeah I see how you got it

#

thanks

#

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fallen vigil
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long escarp
#

Hi

final saddleBOT
long escarp
#

I understand this is mathematics but i had a quick question about physics: when drawing the triangular vector diagrams, do all arrow heads have to meet at one point?

#

Is this acceptable for a vector diagram in terms of where the arrowheads are?

dire solar
#

yes

final saddleBOT
#

@long escarp Has your question been resolved?

long escarp
#

O really i thought my teacher said that would not be good

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ivory vessel
#

$z$ is a complex number such that $|i\bar{z}+3-2i| =4$

soft zealotBOT
#

Fungus 34A05

ivory vessel
#

the set of all points represent $w=2i\bar{z}+5-6i$

soft zealotBOT
#

Fungus 34A05

ivory vessel
#

is a circle with the center $I(a, b)$ and radius R

soft zealotBOT
#

Fungus 34A05

ivory vessel
#

calculate a+b+R

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so i find that z is represented by

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$(x-2)^2+(y+3)^2=16$

soft zealotBOT
#

Fungus 34A05

ivory vessel
#

but i dont know where to go from here

final saddleBOT
#

@ivory vessel Has your question been resolved?

ivory vessel
#

<@&286206848099549185>

rain compass
#

the equation for a circle in general is
(x - a)^2 + (y - b)^2 = r^2

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where the center is (a,b) and the radius is r

#

locate those in the equation you found

ivory vessel
#

the problem is, this is the circle representing z, not w

rain compass
#

ah

#

i see

ivory vessel
#

<@&286206848099549185>

proud harness
#

what is problem?

tribal brook
#

oh

proud harness
#

yes, I think so

ivory vessel
proud harness
#

a=2 b=-3 r=4

ivory vessel
#

uh

#

did you not read my messages?

#

<@&286206848099549185>

final saddleBOT
#

@ivory vessel Has your question been resolved?

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round heath
#

i gotta find out the the number of ways certain points be connected to each other following certain rules and using the minimum number of connection lines:

We have A,B,C,D,E that is five different points.

It's a network that will utilize direct lines to link certain areas, but it is imperative that each area can communicate with every other area, either directly or through a chain of connections.

rules:
A cannot be directly connected to D
B must be directly connected to E
C can only be directly connected to either D or A but not both

round heath
#

I can hit and trial and do it but on a timed test

graceful badger
#

how do i do financhial maths???

round heath
round heath
#

the answer to this is 8 ways

#

how can I make sure I'm not missing any way when doing hit and trial and is there a better way

gloomy locust
#

okay well

#

so the question is asking how many ways can it be done in the minimal number of connections?

#

firstly you want to know what this minimum is

#

i think this is 4 connections right

#

so then you can do some counting, starting by asking where the connection from D goes to

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#

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royal basin
#

Hey!
i need help with Prove or disprove:
Given A,B,C Sets.

$A\cap B\cap C\subseteq A\Delta B\Delta :C

soft zealotBOT
half shard
#

I would do something like:

Suppose x is any element in A n B n C.

This means x is an element in A n B. This means it is not included in A ∆ B.

x is also an element of C (given). It is in C, but not in A ∆ B, so it is included in the symmetric difference of A ∆ B and C (as it is not in their intersection).

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tawny ivy
final saddleBOT
tawny ivy
#

Have I performed djikstras correct

sturdy cypress
#

you clearly meant to mark this edge

#

and you ignored this one

#

just never did anything with it

#

it's still mostly sensible

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#

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tawny ivy
tawny ivy
sturdy cypress
#

when you change the bold number to a lower number, you mark the efge that caused it

#

the weight of the edge doesn't matter

#

so it was marked before you went B→C, and you don't unmark it because you didn't find a better path to C

#

you did the right thing here am i wrong?

#

f→c has weight 1, so it would be the minimal edge that goes to C

#

and it doesn't matter, you keep BC and don't mark FC

#

oh nvm you can't even look at fc, c is examined, you can't go there

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shrewd vector
# ivory vessel but i dont know where to go from here

@craggy plank
the way I interpret 2i*z_bar + 5 -6i is as an order set of 2D transformations of Z

as you guys said, z = C + Di where where C,D are reals is a complex circle defined by (D+3)^2+(C-2)^2 = 16

  1. z_bar is reflection about the real axis
  2. multiplying by i is a rotation of 90deg from the origin
  3. multiplying by 2 is a dilation from the origin
  4. adding (5-6i) is a transposition

so lets think of our complex circle as a center (I) and radius (r). Then lets do the transformations in order

  1. I = [2,-3]; r = 4
  2. I = [2,3]; r = 4
  3. I = [-3,2]; r = 4
  4. I = [-6,4]; r = 8
  5. I = [-1, -2]; r = 8

==>
w = M + Ni s.t. M,N are reals and (M+1)^2 + (N+2)^2 = 64

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tranquil pine
#

How to solve 2?

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#

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wild yew
final saddleBOT
wild yew
#

/rotate

#

Welp

#

I want to know if that reduction is ok; what should I do next?

dire solar
#

,rotate

soft zealotBOT
wild yew
#

There’s an infértil

#

Identity*

#

The sun of the squares of tan and sec equals 1

final saddleBOT
#

@wild yew Has your question been resolved?

wild yew
#

<@&286206848099549185>

#

If there’s a mistake please let me know 🙏🏾

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unique aspen
final saddleBOT
unique aspen
#

Help

muted prairie
#

dy/dt should be -3 based on the problem

#

dx/dt is what you're trying to find

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tranquil pine
#

If the number of degrees of freedom for a chi-square distribution is 4, what is the population mean and standard deviation? (Round your answers to four decimal places.)

vital surge
tranquil pine
#

no

vital surge
#

for chi-square dist. with degrees of freedom k,
mean is k
variance is 2k

tranquil pine
#

df is like n - 1 right?

vital surge
#

that's in context of hypothesis testing with the t-distribution

tranquil pine
#

oh

#

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placid birch
#

6 balles numbered 1-6 are in a box. if I take 2 different balls out at random, what is the expected value of the sum of both balls and what is the expected value of product

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stable thorn
#

Please help, I am stuck at this part

final saddleBOT
fathom walrus
#

i mean ur on the right path

royal gust
#

You're so close

stable thorn
fathom walrus
#

know that $(a^b)^c = a^{bc}$

royal gust
#

Make sure to keep your exponent laws nearby

soft zealotBOT
#

Stephen

stable thorn
#

Multiply them

#

So its A?

#

thanks

#

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ivory vessel
#

Given a cube ABCD.A'B'C'D' with length a. Let M be a point on BB' such that $BM=2MB'$, K is the midpoint of DD'. The plane (CMK) divides the cube into two polyhedra. Calculate the volume of the polyhedron containing the vertex C' in terms of a.

soft zealotBOT
#

Fungus 34A05

ivory vessel
#

my goal is to find the point where AA' and the plane intersects, but i dont know how to do so

vital surge
#

to do that u can consider vector addition

ivory vessel
#

what do you mean?

vital surge
#

CM + CK lands on line AA' and is inside the plane

ivory vessel
#

but they arent vectors though, they are segments

#

and this isnt in a coordinate system

#

this is a more quality image

vital surge
#

is there anything i said u don't understand or would like me to rephrase

ivory vessel
#

so, i calculate CM and CK, but i can only get its magnitude, not their directions

vital surge
#

misunderstanding here

vital surge
# ivory vessel

imagine like

u consider segment CK

u shift that segment up (in the direction along segment CM) so that point C eventually lies on point M

ivory vessel
#

ah

#

i see what you mean

vital surge
#

i said vector addition at the start since that was easiest way to visualize this

#

but this explanation doesn't use vectors and achieves the same effect so ig

ivory vessel
#

so i need to calculate the distance between M and K if they belong on the same side

#

and add that to BM in order to get the distance of A and that point?

vital surge
#

no

vital surge
ivory vessel
#

yes, i understand it

vital surge
ivory vessel
#

so lets say after the transformation, the new point K is called K', who lies on AA'

#

so K' shall be the intersection of (CMK) and AA', and i can now calculate AK' and A'K'

#

ok got it

#

it seems to lie outside the cube though

#

i got AK' = 7a/6

#

now we got that, how in the world am i supposed to calculate the upper polyhedron

#

<@&286206848099549185>

vital surge
#

actually i guess that's not needed

ivory vessel
#

i also cant calculate the other polyhedron

vital surge
#

hint: ||make use of symmetry||

ivory vessel
#

their shapes are too unusual

ivory vessel
#

but they arent though right?

vital surge
#

well the shapes ofc aren't symmetric

#

my suggestion is to consider what symmetries exist in the problem that may be beneficial to you

ivory vessel
#

hmm

#

maybe the plane inside the cube?

vital surge
# ivory vessel their shapes are too unusual

following that line of thought of symmetry, the shapes are only unusual because ||they are arbitrarily cut off by plane A'B'C'D'||

(this spoilered message is larger of a hint than the others)

vital surge
#

clarification on what i mean by that, you only need to consider the portion of the plane that lies above the ABCD square

ivory vessel
#

hmmmmmm

#

let me think a bit

ivory vessel
#

you want me to protrude AA' such that it cuts (CMJ), which creates a prism, whose volume i can calculate?

#

wait, OH

#

wait no

#

it isnt a prism, at least not one created by the cube vertices

#

@vital surge hm, i would like some more explanations

#

<@&286206848099549185>

#

.close

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prisma lantern
#

Can someone help?

final saddleBOT
#

Please don't occupy multiple help channels.

celest crane
#

You need to account for the area on the interval that is a negative space.

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#

@prisma lantern Has your question been resolved?

prisma lantern
#

@celest crane how would I write that?

#

Since 3 goes negative

#

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final saddleBOT
wind badger
#

Do you know the distance formula?

jagged flare
#

you could use pythagoras

wind badger
#

Use that; you essentially have coordinates relative to an origin point already

jagged flare
#

you can use that then

wind badger
#

Yes; make sure to pay attention to east/west and north/south though

#

You need to make sure to change the sign depending on if it’s east or west, north or south

#

As 100 km east is not the same as 100 km west for example

#

Yes

#

Yes

#

Then you can find (b) using simple Pythagorean theorem (which is really just distance formula with (x1,y1) = (0,0)

#

Looks good

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jagged flare
#

find the number of positive integers of x, y, and z where x>y>z and x+y+z=2025

jagged flare
#

i thought this was a stars and bars question but im struggling on how to apply it to here

chrome pawn
#

I would’ve done that too

jagged flare
#

yeah but they have to be ordered and diffrent, as far as i know there are no stars and bars with that limitation

chrome pawn
#

Yeah we have to deal with the inequality

jagged flare
#

how tho

#

honestly i dont know if its worrying that im getting used to multitasking watching a youtube video, chatting on discord while asking questions on math, and playing a game at the same time

chrome pawn
#

Wait we can take z, z+d-1 and z+d where d is x - z

#

3z + 2d = 2026

jagged flare
#

why z+d-1

chrome pawn
#

Wait

#

There might be a error

#

Lemme think

#

We can do something like that

rain compass
#

naively you could just use stars and bars then remove the number of solutions that have repeats, then divide for symmetries

chrome pawn
#

Yeah

jagged flare
#

using stars and bars for distinct has 6 symetries, but with 2 of the same has 3, and 3 of the same has 1 right, so how do you take account that

rain compass
#

remove the counts with repeats first

#

then divide by 6

#

e.g. let x = y, count the number of solutions, multiply by 3, remove that from the original total

#

let x = y = z, count the number of solutions, remove that from the current total

#

divide by 6

#

that said, im not sure if we are double counting based on the assumptions stars and bars uses, im not too familiar with combinatorics
but the logic here should be sound

jagged flare
#

hm, makes sense but how do we count for x=y, x=y=z doesent have a sol

rain compass
#

x = y gives
2x + z = 2025

#

z must be odd

#

so you now have
2x + 2k + 1 = 2025, or 2x + 2k = 2024, or x + k = 1012

gritty solar
#

maybe do y = x + A1 and z = x + A2

jagged flare
#

.close

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rugged cobalt
#

Hello, if the only given in a polygon are angles, it would be impossible to determine the length of one side right? Because with just angles as a reference the ratio of the sides is the only thing we could figure out and not the length of the sides themsleves?

rugged cobalt
#

Assuming it's a regular polygon

stone wagon
rugged cobalt
#

Thanks a lot

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primal geode
#

shape ΑΒΓΔ is a square and M is a point of the arc AB. calculate the angle AMB

primal geode
#

I can't understand how to solve this type of question anyone can help

#

?

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#

@primal geode Has your question been resolved?

primal geode
#

<@&286206848099549185>

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primal geode
#

.reopen

final saddleBOT
#

primal geode
#

If you want me to tell you

white tiger
#

yeah im asking for that

#

i got an answer but idk if its right

primal geode
#

ΑMΒ=135⁰

white tiger
#

alright nice

#

are you better familiar with degrees or radians

primal geode
#

Degrees

white tiger
#

alright first connect the center with A and B

primal geode
#

So I make a triangle with AOB

white tiger
#

yep

#

now whats angle OAB

primal geode
#

90?since it's 1 fourth of circle?

white tiger
#

i was asking for OAB but thats even better

#

thats the central angle

primal geode
#

Oh 45?

white tiger
#

yeah but since you already got the central angle then its irrelevant

primal geode
#

Oh

white tiger
#

now whats the arc of AB

primal geode
#

90

white tiger
#

arc length

#

you remember the arc length formula?

#

θ/360 * 2πr

primal geode
#

Oh θ is the angle right?

white tiger
#

ye

primal geode
white tiger
#

well now you remember(hopefully)

primal geode
#

So I put 90/360*2πr

primal geode
primal geode
white tiger
#

just leave it as r

#

so the arc length of AB is πr/2 yeah?

primal geode
#

I guess

white tiger
#

90/360 is 1/4

#

1/4 * 2 is 1/2

#

so πr/2

#

ok now you said M was the midpoint of arc AB yes?

primal geode
#

Yes

white tiger
#

ok so now AM = MB

#

and those two are equal to?

primal geode
#

AMB

#

?

white tiger
#

no the lengths of them

#

what is the length of AM

primal geode
#

I don't know

white tiger
#

well since M is the midpoint of AB

#

you just divide AB by 2

#

so AM and MB are both equal to πr/4

primal geode
#

Oh you meant the arc AM

#

Thought the line AM

white tiger
#

yeah arc

#

now connect the center to M

#

you should have two sectors OAM and OMB

primal geode
#

Yes

white tiger
#

which one you use doesnt matter

#

you'll get the same thing anyways

primal geode
#

Then

white tiger
#

now we need to find AOM

#

or the central angle again

#

you see that this angle forms the arc AM right?

primal geode
#

Yes

white tiger
#

so we use the arc length formula again

#

we know AM = πr/4

#

πr/4 = θ/360 * 2πr

#

makes sense?

#

θ here is the central angle

primal geode
#

And it's 45?

white tiger
#

ok good

#

its 45

#

now look at the triangle AOM

#

its an isoceles triangle right?

primal geode
#

Cant we use sin45 which is √2/2

primal geode
white tiger
#

if its an isoceles triangle, the other two angles must be the same

#

yes?

primal geode
#

Yes

white tiger
#

so 45 + 2y = 180

#

y is the other angle

#

and you get?

primal geode
#

Yeah

#

So we find 2y and it's basically AMB

#

?

white tiger
#

yes

primal geode
#

Ohh

#

Ok thank you I think I understood it

#

.close

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crystal lotus
#

i need help to draw the triangle with the given details. city D is 30km west to city T. the angle from city D to K is 150 and from T to K is 235

final tangle
#

by angle do you mean bearing?

crystal lotus
crystal lotus
final tangle
#

clockwise angle of rotation from north

crystal lotus
final tangle
#

google bearings

crystal lotus
#

i did but the exercise doesnt mention that

#

oh wait

#

yes it does

crystal lotus
#

@final tangle

final tangle
#

did you make any attempt at a drawing

crystal lotus
#

yes

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the line that represent the city D and T

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@final tangle

#

idk how to continue

final tangle
#

draw compass axes at D.

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measure/eyeball an angle of 150° clockwise from north

crystal lotus
#

whats drawcompass

final tangle
#

sorry, there's supposed to be a space in between

#

i'm referring to one of these

crystal lotus
#

wait im confsued

final tangle
crystal lotus
#

yeah

final tangle
#

which should've come up when you looked at bearings

crystal lotus
#

i understand

final tangle
#

draw on of those centred at D

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on that measure an angle of 150° going clockwise from that north line

crystal lotus
#

wait i dont understand how am i going to draw it going clockwise

final tangle
crystal lotus
final tangle
#

not quite

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NE would be exactly 45° of rotation

crystal lotus
#

north 59 east

final tangle
#

yes

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or a true bearing of 59°

crystal lotus
#

yep i got this step

final tangle
#

keep going for a higher angle

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in this case, you want 150°

crystal lotus
#

yes

final tangle
#

then same idea
draw another axis at T, and this time do a rotation of 235°

crystal lotus
#

smth like this?

final tangle
#

yes

crystal lotus
#

thats 150 right?

final tangle
#

close enough

crystal lotus
#

how do i know if city K is north or south

final tangle
#

the bearing / angle tells you

#

K is somewhere along that red line you drew

final saddleBOT
#

@crystal lotus Has your question been resolved?

crystal lotus
#

@final tanglei dont understand

final tangle
#

which part

crystal lotus
#

can we draw the lines

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that represent the cities

final tangle
#

the lines between the cities represent the direct path between them

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the angle from city D to K is 150
that tells you that K will be somewhere on the line you drew above

#

and then same idea for the

from T to K is 235
you'll get another line

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the intersection of those will give you the location of K

final saddleBOT
#

@crystal lotus Has your question been resolved?

crystal lotus
#

ok i got

#

.close

final saddleBOT
#
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shy grove
#

hi, can anyone pls explain cubic sequence?

final saddleBOT
shy grove
#

where do we get the 12a + 2b for the 2nd difference?

wise relic
#

It should be (3^3-2^3)-(2^3-1^3) multiplied by a and (3^2-2^2)-(2^2-1^2)multiplied by b

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So the difference of the first two first differences

final saddleBOT
#

@shy grove Has your question been resolved?

shy grove
#

i still don't get it, like i have 0 knowledge about cubic sequences

final saddleBOT
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brisk mulch
final saddleBOT
brisk mulch
#

This integral is confusing

#

I tried doing an integration by parts

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But its seems to be repeating

final tangle
#

yes. that will happen

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when you see repetition,
solve for / isolate the original integral expression

brisk mulch
#

Just look at the top part, I was doing something else right below it

final tangle
#

you haven't achieved the repetition you mentioned yet

brisk mulch
#

after the first integral

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but I will work it out to there 1 sec

final tangle
#

you've also made a sign error

brisk mulch
#

-e^-x

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I see it

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I get something like this now

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and I think it's a repetition because I bring the 1/6 out on the last integral

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and the negatives cancel

final tangle
#

note that you're integral appears within here

#

for convenience, let your original integral be I

#

you'll have
I = all thht stuff you've written
then solve for I

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$$I = \int f(x)\dd{x}$$
e.g. if after doing several iterations of ibp,
$$I = p - qI$$
$$I + qI = p$$
$$I = \frac{p}{1 + q}$$

soft zealotBOT
#

ℝαμΩℕωⅤ

brisk mulch
#

this ones difficult

brisk mulch
#

I'll come back later to this problem I need to go somewhere, thank you for the insight though I have a more clear idea of what I need to search on youtube

#

.close

final saddleBOT
#
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final tangle
#

your original integral appeas again, that part is also I

final saddleBOT
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fading zephyr
#

can someone try and solve this

final saddleBOT
fading zephyr
#

<@&286206848099549185>

warm python
#

!15m

final saddleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

fading zephyr
#

.close

final saddleBOT
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tranquil pine
#

Guys, if
E(x) = (x + 1)/((x - 1) ^ 2)

final saddleBOT
tranquil pine
#

What is 1/(E(x)) <= 0

rain crane
#

Huh

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What is it really asking for

tranquil pine
#

Solve the inequality in R

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The second image

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I don' t know why is ≤,

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It can't be qual to 0

rain crane
#

What's 1/E equal to?

tranquil pine
#

Idk

#

It doesn' t say

#

1/E
1/ (x + 1)/(x - 1)²

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Fuck

#

My bad

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
timber hedge
final saddleBOT
#

@tranquil pine Has your question been resolved?

wise crescent
#

So

#

Basically

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1/E = (x-1)²/(x+1)

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Right @tranquil pine

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And we want this to be negative

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We know that (x-1)² is always positive, irrespective of the value of x

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So

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We just need to make x+1 negative

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So x < -1

tranquil pine
wise crescent
#

So the solution set will be x = ( - infinity, -1) + {1}

tranquil pine
#

E(x) is (x-1)²/(x+1)

wise crescent
#

E(x) = (x+1)/(x-1)²

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According to the photo

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Which you have sent

tranquil pine
wise crescent
#

So...do you understand the rest of my solution?

tranquil pine
#

No

wise crescent
#

What part

tranquil pine
#

Why is 1/E= (x-1)²/(x+1)

wise crescent
#

If x = 4/5

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What is 1/x

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You tell me

tranquil pine
#

1/ 4/5

wise crescent
#

Which is equal to.....?

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5/4

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Let's look at this another way

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x = 4/5

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1 = 4/5x

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Right?

tranquil pine
#

1= 4/5 × 4/5 ?

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Why?

wise crescent
#

What

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No

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You listen to my steps @tranquil pine

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x = 4/5

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So 1 = 4/5x

tranquil pine
#

Ok

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How that come?

wise crescent
#

Have you learnt cross multiplication

tranquil pine
#

Yeah

wise crescent
#

That's what I did

tranquil pine
#

The denominator of x is 1?

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Yeah

wise crescent
#

Do you get these 4 steps

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@tranquil pine

tranquil pine
#

Naaah

wise crescent
#

Which class are u in?

tranquil pine
#

Eight

wise crescent
#

I heavily advise revising / re-learning the entirety of maths of grades 1 to 7th

#

Because if your basics are so weak, you won't be able to do linear inequalities

tranquil pine
#

Idk

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This just don' t have sense
If n=4/5, then 4n=5

wise crescent
#

no

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n = 4/5 implies that 5n = 4

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and not 4n = 5

tranquil pine
#

4×n=5×1

wise crescent
#

no

#

that is not how cross multiplications work

tranquil pine
#

I fucking did

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This is the rule

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1 cannot be 4/5n

wise crescent
#

1 is 4/5n

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but congrats on learning cross multiplication

#

so now

tranquil pine
wise crescent
wise crescent
#

just do the cross multiplication the other way around

tranquil pine
#

How

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Wait

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I dont think this is possible

#

Oooh