#help-36
1 messages · Page 103 of 1
right, it pretty much sais
the integrals and derivatives cancel out
and ur left once again back at f(x)
if u take the derivative of an integral
In part A, if you differentiate the RHS of the equation what do you get
No limits
Symbolab?
, w d/dx(int_0^x 1/sqrt(2pi)e^(-t^2/2)dt)
Wolfram after destroying the competition
wtf
just to reiterate
we express f(x) as a derivative of an integral
by FTC
so when we take the derivative of f(x), we are technically taking the derivative of the LHS twice sorta
No
kms
Can you write down the Newton's Method formula
Yes
which is the RHS of this
Now we are trying to find the derivative of f(x)
yes
So f'(x) is equal to the derivative of the RHS
Forget that, that's the formula for FRC
That f(x) and your f(x) aren't related by any means
for here we just do like d/dx over that entire thing?
nvm that doesnt rlly matter
how would u compute the derivative by hand
Of the RHS?
ye
Using this, f(t) is the function 1/sqrt(2pi)e^(-t^2)/2
Puff, yes
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hi
idk combionations are weird
im behjind ion my whole class
is this right it feels wrong
why?
ok so my thought process was the first value can be 4 of them
bc it can be
4, 5, 6 or 8
and then the second one can be 5 because we include 0 now but take one out casue we used it for the first digit
yeah
oh
right
so your first find the number which start with 4
and then all other numbers
hi
hi
GUESS WHAT
i got 2nd for my physics test
1 mark away from 1st
why not first
ay ay ay commendation letter
Jk good job
ok ITS NOT MY FAULT THERES A CHILD GENIUS IN MY YEAR
Is it the Indian
Is it a Indian
Wowie
I still feel you should split it into twi cases, first find the number of even number greater than 4000 but less than 5000
and then the number more than 5000
hmm why?
becuase your number can't end with 4 when the number is between 4000 and 5000
but itherwise it can
Just take cases by ending the no.s with even at end
what no.s?
ohhh
Do u get it?
yes yes
the 0 part
also sorry i dont have answers to this past test is it ok if u check if its right?
Btw I made a error the first box should be 5!
Since 4,5,6,7,8 are possible
I will try
Yep looks good to me
they all seem right to me
I suggest you do, there are some really intresting questions on this topic
lol
ceebs?
Which class u in btw
they are
Oh ok nicee
Two combinatorics are equal if r is n-r and r
rather similar to a sigmoid curve
So one of them is either r or n-r
is r the one on top
something like this(This is continuous though(
ohhh waht i nevber knew graphs camke into stuff like combinations
mi better nevber learn that in my life
it isn't continuous, when you plot the points, this is the curve that best descibes the distribution, that's it
Yep
do u know what these are called
i want to watch a yt video
i still havent finished the pascals triangle chapter and the pigeon hole principle chapter in my textbook
Just PNC would work..the second part of this chap is combinatorics
whats PNC?
i think im going to cry if they ask me to prove something
in thet est
like this
Permutations and combinations
am i on the right track?
wait im going to the shops real quick
i will be back
Okay but don't overthink all these qns
No I don't know but the steps look long
oh!
Didn't check yet, but ig could be done in 1-2 lines
Yeah
It's okay takes time for first time
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help needed
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7. None of the above
idk the formula
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have i written this properly and done it correctly? my teacher said the formula was correct but i am unsure
.28
no, that correspond to a 28% annual interest rate
oh, it'd be .028 right
get me the location of that bank so i can immediately transfer my savings over /s
yes
ohh, what a stupid mistake, thanks for the help :)
the 2.8% is annual
we compound quarterly
so wouldnt it be 0.7% per quarter of a year?
that's what the /4 is for
well you already have that, true
why the 180 in the exponent?
ah you mean 180 instead of the 4*45, since it's the same?
yes
kk
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Question 5
I tried substituting x=2u to exploit a trig identity but it doesn’t work
I think I’m doing it wrong
L hospital is giga chad
Which question we talking about
5
but it doesn’t work
how far did you get, what exactly didn't work
I’ll send a pic
@final tangle
Did I make a mistake?
Because using lhopital it should be 1/2
what happened here
Trig identity
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I wonder if i made some mistake...?
,rotate
you're finding dy/dx not dy/da yes?
Yes
Well i got confused
I can see that
X is constant right?
Okay
a and b are constants, like 2 or 7 or π or 88.12938
2
what is the derivative of 8x?
8
what is the derivative of ax?
yup
so for something more complex
you can do it in two ways: one is simple, one is complicated
the simple method is to factor out the coefficients
if you want to find the derivative of 32x^2 or 12ax^3, you write them as (32)(x^2) and (12a)(x^3)
giving derivatives of (32)(2x) and (12a)(3x^2) respectively
notice how the contant coefficients are untouched
if you want to do it the hard way, you use the product rule
(32)(x^2) = 0(x^2) + (32)(2x) = (32)(2x)
(12a)(x^3) = 0(x^3) + (12a)(3x^2) = (12a)(3x^2)
(derivative of 32 and 12a are both 0)
I recommend the first method though
Yes i see
it makes more sense
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I think i messed up at step where i circled
,rotate
the second line should read y = u^2 - 2u^(3/2)c + c^2u. This is from combining u*u^(1/2) to give us u^(3/2)
but what you have written is still correct to the second line at least
oh yeah like u^1*u^1/2
yes, so one justs adds the exponents
ahhhhhhhhhh okay
and then use normal power rule to differentiate
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died_of_cringe
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$$2^{x}+x^{2}+4+\frac{1}{x^{3}}=(2^{x})^{2}$$
died_of_cringe
.
i know it has multiple real solutions (wolframalpha)
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Can someone help me get to this step?
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<@&286206848099549185>
@vital lagoon Has your question been resolved?
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
You can length chase and show that $$KF^2+FC^2=KD^2+DC^2$$
Civil Service Pigeon
I couldn't build any relation between lenght
I tried to find same angle
But I cannot manage it
@vital lagoon Has your question been resolved?
@vital lagoon Has your question been resolved?
Picture the correct angle
@vital lagoon Has your question been resolved?
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How did they get 18?
Isnt this what the top looks like?
Bottom right? Why is it the top right?
wait this doesnt even make sense :0
fr
frfr
why does the left look like that
uhh to help you build it remember that the blocks have to stack up because of gravity, so all the top view blocks are at the bottom layer
I get 10 blocks though
how did u? i did not manage to find a block configuration that fits the diagram
fr
nvm no solutions so if u found one good,
the real secret is to do it in minecraft
omg one moment
@half rampart Has your question been resolved?
@zenith pollen I got it but it was hard TnT
you got 18?
visualise it from 3 directions
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Hi
I understand this is mathematics but i had a quick question about physics: when drawing the triangular vector diagrams, do all arrow heads have to meet at one point?
Is this acceptable for a vector diagram in terms of where the arrowheads are?
yes
@long escarp Has your question been resolved?
O really i thought my teacher said that would not be good
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$z$ is a complex number such that $|i\bar{z}+3-2i| =4$
Fungus 34A05
the set of all points represent $w=2i\bar{z}+5-6i$
Fungus 34A05
is a circle with the center $I(a, b)$ and radius R
Fungus 34A05
Fungus 34A05
but i dont know where to go from here
@ivory vessel Has your question been resolved?
<@&286206848099549185>
the equation for a circle in general is
(x - a)^2 + (y - b)^2 = r^2
where the center is (a,b) and the radius is r
locate those in the equation you found
(2, -3) and 4
the problem is, this is the circle representing z, not w
<@&286206848099549185>
what is problem?
the analytic centre of the circle is (2,-3) and the radius is 4
oh
yes, I think so
this is w, whose numbers i need to find
a=2 b=-3 r=4
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i gotta find out the the number of ways certain points be connected to each other following certain rules and using the minimum number of connection lines:
We have A,B,C,D,E that is five different points.
It's a network that will utilize direct lines to link certain areas, but it is imperative that each area can communicate with every other area, either directly or through a chain of connections.
rules:
A cannot be directly connected to D
B must be directly connected to E
C can only be directly connected to either D or A but not both
I can hit and trial and do it but on a timed test
how do i do financhial maths???
ask on #discussion
i may just not be sure if I've checked every way possible
the answer to this is 8 ways
how can I make sure I'm not missing any way when doing hit and trial and is there a better way
okay well
so the question is asking how many ways can it be done in the minimal number of connections?
firstly you want to know what this minimum is
i think this is 4 connections right
so then you can do some counting, starting by asking where the connection from D goes to
@round heath Has your question been resolved?
yes
ohkay
okay
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Hey!
i need help with Prove or disprove:
Given A,B,C Sets.
$A\cap B\cap C\subseteq A\Delta B\Delta :C
Kingo
I would do something like:
Suppose x is any element in A n B n C.
This means x is an element in A n B. This means it is not included in A ∆ B.
x is also an element of C (given). It is in C, but not in A ∆ B, so it is included in the symmetric difference of A ∆ B and C (as it is not in their intersection).
sounds good
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Have I performed djikstras correct
you clearly meant to mark this edge
and you ignored this one
just never did anything with it
it's still mostly sensible
@tawny ivy Has your question been resolved?
Oh didnt see
But don’t I only keep the one that is minimal
when you change the bold number to a lower number, you mark the efge that caused it
the weight of the edge doesn't matter
so it was marked before you went B→C, and you don't unmark it because you didn't find a better path to C
you did the right thing here am i wrong?
f→c has weight 1, so it would be the minimal edge that goes to C
and it doesn't matter, you keep BC and don't mark FC
oh nvm you can't even look at fc, c is examined, you can't go there
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@craggy plank
the way I interpret 2i*z_bar + 5 -6i is as an order set of 2D transformations of Z
as you guys said, z = C + Di where where C,D are reals is a complex circle defined by (D+3)^2+(C-2)^2 = 16
- z_bar is reflection about the real axis
- multiplying by i is a rotation of 90deg from the origin
- multiplying by 2 is a dilation from the origin
- adding (5-6i) is a transposition
so lets think of our complex circle as a center (I) and radius (r). Then lets do the transformations in order
- I = [2,-3]; r = 4
- I = [2,3]; r = 4
- I = [-3,2]; r = 4
- I = [-6,4]; r = 8
- I = [-1, -2]; r = 8
==>
w = M + Ni s.t. M,N are reals and (M+1)^2 + (N+2)^2 = 64
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How to solve 2?
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,rotate
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If the number of degrees of freedom for a chi-square distribution is 4, what is the population mean and standard deviation? (Round your answers to four decimal places.)
r u familiar with properties of chi-square distribution
no
for chi-square dist. with degrees of freedom k,
mean is k
variance is 2k
df is like n - 1 right?
that's in context of hypothesis testing with the t-distribution
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6 balles numbered 1-6 are in a box. if I take 2 different balls out at random, what is the expected value of the sum of both balls and what is the expected value of product
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Please help, I am stuck at this part
i mean ur on the right path
You're so close
fr?
know that $(a^b)^c = a^{bc}$
Make sure to keep your exponent laws nearby
Stephen
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Given a cube ABCD.A'B'C'D' with length a. Let M be a point on BB' such that $BM=2MB'$, K is the midpoint of DD'. The plane (CMK) divides the cube into two polyhedra. Calculate the volume of the polyhedron containing the vertex C' in terms of a.
Fungus 34A05
my goal is to find the point where AA' and the plane intersects, but i dont know how to do so
to do that u can consider vector addition
what do you mean?
CM + CK lands on line AA' and is inside the plane
but they arent vectors though, they are segments
and this isnt in a coordinate system
this is a more quality image
i'm asking u to treat them like vectors
is there anything i said u don't understand or would like me to rephrase
so, i calculate CM and CK, but i can only get its magnitude, not their directions
misunderstanding here
imagine like
u consider segment CK
u shift that segment up (in the direction along segment CM) so that point C eventually lies on point M
i said vector addition at the start since that was easiest way to visualize this
but this explanation doesn't use vectors and achieves the same effect so ig
so i need to calculate the distance between M and K if they belong on the same side
and add that to BM in order to get the distance of A and that point?
no
applying this transformation, where point K ends up is on line AA'
does this statement make sense
yes, i understand it
then this goal is effectively achieved
so lets say after the transformation, the new point K is called K', who lies on AA'
so K' shall be the intersection of (CMK) and AA', and i can now calculate AK' and A'K'
ok got it
it seems to lie outside the cube though
i got AK' = 7a/6
now we got that, how in the world am i supposed to calculate the upper polyhedron
<@&286206848099549185>
hint: ||complementary counting||
actually i guess that's not needed
i also cant calculate the other polyhedron
hint: ||make use of symmetry||
their shapes are too unusual
well the shapes ofc aren't symmetric
my suggestion is to consider what symmetries exist in the problem that may be beneficial to you
following that line of thought of symmetry, the shapes are only unusual because ||they are arbitrarily cut off by plane A'B'C'D'||
(this spoilered message is larger of a hint than the others)
in this case, i'd say outside matters too
clarification on what i mean by that, you only need to consider the portion of the plane that lies above the ABCD square
ok so, heres my understanding
you want me to protrude AA' such that it cuts (CMJ), which creates a prism, whose volume i can calculate?
wait, OH
wait no
it isnt a prism, at least not one created by the cube vertices
@vital surge hm, i would like some more explanations
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Do you know the distance formula?
you could use pythagoras
Use that; you essentially have coordinates relative to an origin point already
you can use that then
Yes; make sure to pay attention to east/west and north/south though
You need to make sure to change the sign depending on if it’s east or west, north or south
As 100 km east is not the same as 100 km west for example
Yes
Yes
Then you can find (b) using simple Pythagorean theorem (which is really just distance formula with (x1,y1) = (0,0)
Looks good
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find the number of positive integers of x, y, and z where x>y>z and x+y+z=2025
i thought this was a stars and bars question but im struggling on how to apply it to here
I would’ve done that too
yeah but they have to be ordered and diffrent, as far as i know there are no stars and bars with that limitation
Yeah we have to deal with the inequality
how tho
honestly i dont know if its worrying that im getting used to multitasking watching a youtube video, chatting on discord while asking questions on math, and playing a game at the same time
why z+d-1
naively you could just use stars and bars then remove the number of solutions that have repeats, then divide for symmetries
Yeah
using stars and bars for distinct has 6 symetries, but with 2 of the same has 3, and 3 of the same has 1 right, so how do you take account that
remove the counts with repeats first
then divide by 6
e.g. let x = y, count the number of solutions, multiply by 3, remove that from the original total
let x = y = z, count the number of solutions, remove that from the current total
divide by 6
that said, im not sure if we are double counting based on the assumptions stars and bars uses, im not too familiar with combinatorics
but the logic here should be sound
hm, makes sense but how do we count for x=y, x=y=z doesent have a sol
x = y gives
2x + z = 2025
z must be odd
so you now have
2x + 2k + 1 = 2025, or 2x + 2k = 2024, or x + k = 1012
ok makes sense, im too lazy to calculate trough so ima close this, thanks everyone!
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Hello, if the only given in a polygon are angles, it would be impossible to determine the length of one side right? Because with just angles as a reference the ratio of the sides is the only thing we could figure out and not the length of the sides themsleves?
Assuming it's a regular polygon
yes
well, in that case all the sides will be the same but you can't get the length if you are simply given the angles
Thanks a lot
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shape ΑΒΓΔ is a square and M is a point of the arc AB. calculate the angle AMB
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✅
Anyone can help
do you have the answer
It's not given in the exercise but it's in the back of the book
If you want me to tell you
ΑMΒ=135⁰
Degrees
alright first connect the center with A and B
So I make a triangle with AOB
90?since it's 1 fourth of circle?
Oh 45?
yeah but since you already got the central angle then its irrelevant
Oh
now whats the arc of AB
90
Oh θ is the angle right?
ye
I had forgotten it
well now you remember(hopefully)
So I put 90/360*2πr
I will write it down
Wait how will it be used since we don't know the radious
we dont need to know it
just leave it as r
so the arc length of AB is πr/2 yeah?
I guess
90/360 is 1/4
1/4 * 2 is 1/2
so πr/2
ok now you said M was the midpoint of arc AB yes?
Yes
I don't know
well since M is the midpoint of AB
you just divide AB by 2
so AM and MB are both equal to πr/4
Yes
Then
now we need to find AOM
or the central angle again
you see that this angle forms the arc AM right?
Yes
so we use the arc length formula again
we know AM = πr/4
πr/4 = θ/360 * 2πr
makes sense?
θ here is the central angle
And it's 45?
Cant we use sin45 which is √2/2
Yes
Yes
yes
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i need help to draw the triangle with the given details. city D is 30km west to city T. the angle from city D to K is 150 and from T to K is 235
by angle do you mean bearing?
whats bearing
i think so
clockwise angle of rotation from north
it doesnt mention that , but maybe its the language barrier
google bearings
did you make any attempt at a drawing
yes
the line that represent the city D and T
@final tangle
idk how to continue
whats drawcompass
wait im confsued
yeah
which should've come up when you looked at bearings
i understand
draw on of those centred at D
on that measure an angle of 150° going clockwise from that north line
wait i dont understand how am i going to draw it going clockwise
thats north east right
north 59 east
yep i got this step
yes
then same idea
draw another axis at T, and this time do a rotation of 235°
yes
thats 150 right?
close enough
how do i know if city K is north or south
@crystal lotus Has your question been resolved?
@final tanglei dont understand
which part
the lines between the cities represent the direct path between them
the angle from city D to K is 150
that tells you that K will be somewhere on the line you drew above
and then same idea for the
from T to K is 235
you'll get another line
the intersection of those will give you the location of K
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hi, can anyone pls explain cubic sequence?
where do we get the 12a + 2b for the 2nd difference?
It should be (3^3-2^3)-(2^3-1^3) multiplied by a and (3^2-2^2)-(2^2-1^2)multiplied by b
So the difference of the first two first differences
@shy grove Has your question been resolved?
hmm...
i still don't get it, like i have 0 knowledge about cubic sequences
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This integral is confusing
I tried doing an integration by parts
But its seems to be repeating
yes. that will happen
when you see repetition,
solve for / isolate the original integral expression
what do you mean by this exactly, I will post my work 1 sec so you can see
Just look at the top part, I was doing something else right below it
you haven't achieved the repetition you mentioned yet
I saw it in my head I was thinking oh, just sin / cos flipping
after the first integral
but I will work it out to there 1 sec
you've also made a sign error
-e^-x
I see it
I get something like this now
and I think it's a repetition because I bring the 1/6 out on the last integral
and the negatives cancel
note that you're integral appears within here
for convenience, let your original integral be I
you'll have
I = all thht stuff you've written
then solve for I
$$I = \int f(x)\dd{x}$$
e.g. if after doing several iterations of ibp,
$$I = p - qI$$
$$I + qI = p$$
$$I = \frac{p}{1 + q}$$
ℝαμΩℕωⅤ
I'm not seeing the connection between the two
I'll come back later to this problem I need to go somewhere, thank you for the insight though I have a more clear idea of what I need to search on youtube
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can someone try and solve this
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Guys, if
E(x) = (x + 1)/((x - 1) ^ 2)
Solve the inequality in R
The second image
I don' t know why is ≤,
It can't be qual to 0
What's 1/E equal to?
@tranquil pine Has your question been resolved?
yeah
@tranquil pine Has your question been resolved?
So
Basically
1/E = (x-1)²/(x+1)
Right @tranquil pine
And we want this to be negative
We know that (x-1)² is always positive, irrespective of the value of x
So
We just need to make x+1 negative
So x < -1
Why is that?
So the solution set will be x = ( - infinity, -1) + {1}
E(x) is (x-1)²/(x+1)
No
E(x) = (x+1)/(x-1)²
According to the photo
Which you have sent
Yeah
So...do you understand the rest of my solution?
No
What part
Why is 1/E= (x-1)²/(x+1)
1/ 4/5
Which is equal to.....?
5/4
Let's look at this another way
x = 4/5
1 = 4/5x
Right?
Have you learnt cross multiplication
Yeah
That's what I did
Naaah
Which class are u in?
Eight
I heavily advise revising / re-learning the entirety of maths of grades 1 to 7th
Because if your basics are so weak, you won't be able to do linear inequalities
4×n=5×1
please revise
No
do you get this?
