#help-36

1 messages · Page 102 of 1

outer yacht
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which still makes no sense

tranquil pine
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why not tho

outer yacht
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because i just realised

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(a)(4a) = 4a²

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answer should be 3 or -3 for k

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which i tested and its correct

wild plank
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Mind if you send the working?

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Still can't solve it

tranquil pine
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i got it

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k=0

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k=10 alpha

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4 alpha square =0

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alpha=0

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k=0

wild plank
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<@&286206848099549185>

tranquil pine
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what

wild plank
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Is k=0 or k=-3

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I'm getting different answers

tranquil pine
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how did you get k=-3

wild plank
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Ask dan

tranquil pine
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you saw my calculation right?

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i got k=0

wild plank
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Yes

tranquil pine
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how -3 tho

wild plank
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It looks the same as my working

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That's why I'm wondering how did he get -3

tranquil pine
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maybe we wrote the qn wrong

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or maybe he did

wild plank
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Oh he assumed ÷2 was +2

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Ok thanks for the help Ig

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I got an exam coming up tmr

tranquil pine
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oh

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nice

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anything else you need help on?

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algebra? trigo?

strong kindle
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Can anyone help me to know how can I develop my math skills?

tranquil pine
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what grade are you in

strong kindle
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Grade 10

tranquil pine
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im not that great but ill try

tranquil pine
strong kindle
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Egypt

tranquil pine
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oh nice

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so what do you struggle with

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any questions or so you want help trying to solve?

wild plank
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.close

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wild plank
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Thanks for the help

tranquil pine
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why

wild plank
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What

tranquil pine
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that dude wants help

wild plank
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.reopen

final saddleBOT
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strong kindle
wild plank
tranquil pine
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i guess

warm python
tranquil pine
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i can dm you bro

strong kindle
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Like I want to know about the skills that I need to know for being nice at math

wild plank
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Practice makes perfect

tranquil pine
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I can give yall a really good qn

wild plank
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tranquil pine
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kind of good

strong kindle
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Ok

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There's some problem

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In my school, I learn mathematics in Arabic

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So I think it's difficult some how for me to understand mathematics in English
So it needs time to get uses to it

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So can you give me easy qn to practice at it

final saddleBOT
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devout dock
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how would i differentiate the probability generating function for a binomial distribution X-B(n,p)?

devout dock
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Gx(t) = (1-p+pt)^n

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nvm i got it

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civic valve
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δy = (u + δu)(v + δv) – uv
= uv + uδv + vδu + δuδv – uv
=uδv+vδu+δuδv

Why do we need to subtract uv

marble agate
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context?

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ruby bough
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ruby bough
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what happened between the second to last step

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and the last step

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like

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how did he end up with sin/cos - cos sin

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oh i see

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yeah thanks

ivory vessel
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the cosx cancels

ruby bough
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yup

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i have to put a negative sign outside the integral correct ?

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so i could get ln

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as the product

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of the integral

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or not ?

ivory vessel
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wdym

ruby bough
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like

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the derivative of cos is negative sin

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and they're in a fraction

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and the integral of anything divided by it's derivative is ln

west berry
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You mean derivative divided by anything?

ruby bough
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yeah

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that

ivory vessel
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this is sinx/cosx

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which is tanx

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integral of tanx is -ln|cosx|, which is a fairly common integral

ruby bough
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yeah well it's the same idea

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like the integral of 4x/2x^2 would be ln|2x^2|

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bec the derivative of the denominator is the numerator

ivory vessel
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yes

ruby bough
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how do i close this thing

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like does this channel lock on its own

ivory vessel
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!done

final saddleBOT
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ruby bough
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.close

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sterile swan
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Good morning, I'm having trouble with some math in my class that looks like setting a function equal to another function. Here, lg refers to log_2.

sterile swan
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Does it actually make sense to say that one function is equal to a modified form of the function? Can I do math on that function in the same way I would with an equation?

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For instance, if 2T(n/2) + n = n log_2(n), then does T(n/2) + n = 2n log_2(n)?

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To ask a simple version, if f(x) = x + 7, then does f(x) - 7 = x? I was under the impression we must go from x to the outputs of x, not the other way around.

timid pollen
sterile swan
sterile swan
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warm python
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My thoughts:- So the ways it can have two solns is that it just touches the x axis once

warm python
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and intresects the other time

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so the derivative must ne negative at some point

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so the answer is B ?

mint orbit
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I think thats the answer

ocean lintel
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I'd recommend drawing the cubic and then drawing its derivative

mint orbit
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im not certain i follow your logic

warm python
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so basically, the derivative must be negative on some interval

mint orbit
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maybe its easier to think of critical points than signs

warm python
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as cubics map from R to R, it can't always be negative, or always positive

ocean lintel
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but it is B yes, because you need two sign changes

warm python
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oh yeah, that works very well

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thanks both of you!

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warm python
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.reopen

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warm python
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so in case 1, the function will have to be a straight line $\frac{\left(y-8\right)}{x-10}=\frac{3}{5}$

soft zealotBOT
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Why am. I here

warm python
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when mapped from R to R instead

spare folio
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why straight line

warm python
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there are 10 inputs

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5 outputs

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oh

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right

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hmm, in case(1) It need not necessarily exist , I think

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i.e f(n)=n

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same goes for case 2

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so B is the answer?

desert mantle
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why do you think so

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if it doesnt need to exist then surely you can give such an example function

warm python
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oh

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right

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for case 1, f(n)=n is necesssary

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as there are only 6 number between f(2) and f(10)

desert mantle
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7 numbers

warm python
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and 10 inputs to be mapped

warm python
desert mantle
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why does that mean that an input needs to be mapped to itself?

warm python
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it's increasing

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say f(1)=2

desert mantle
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ok and? if the points werent from 0 to 10 but instead from 10 to 20 then it clearly wouldnt hold

warm python
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true

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but here I only care about the interval [0,10]

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right?

desert mantle
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yes but you havent used that in your argument so far

warm python
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OK, so there are 10 elements to be mapped to 7 elements ,such that 7 elements are identical, now , f is increasing on Z. If it's constant, function at f(n)=n is ensured.

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if not

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f(n)=n is still ensured as there aren't evough elements(Not sure of how I'd prove this) to ensure $f(n)\neq n$

soft zealotBOT
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Why am. I here

ocean lintel
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try drawing the function

warm python
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how would I do that?

ocean lintel
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take an example

warm python
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for a constant function, (except at the endpoint), f(n)=n is true

ocean lintel
spare folio
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draw y = x

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but not linear

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just mark up to (1,1) (2,2) (3,3).. (10,10)

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and

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draw a function whose y value doesnt greater than 8 when it is between 0<x<10

tiny gorge
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here's something that might be useful

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let g(n) = f(n) - n

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observe that g(n+1) - g(n) >= -1

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now compute g(0) and g(10) for your two examples

warm python
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hmm

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so g(1)

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and g(11)?

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nah, g(11) isn't even defined

tiny gorge
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hmm maybe this doesn't work after all, lemme think again

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oh right, it does work

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haha sorry, operating on like 2 hours of sleep

warm python
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how did you come up with that?

tiny gorge
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just playing around

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notice that in the first example, you have
g(0) = f(0) - 0 = 2 and g(10) = f(10) - 10 = -2

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so g has to go from 2 to -2

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can it avoid 0?

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it can't decrease by more than -1 at a time

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so no, it can't

spare folio
ocean lintel
desert mantle
# tiny gorge let g(n) = f(n) - n

and as a general strategy, its often better instead of f(n)=n where both sides vary, to consider f(n)-n=0 where only one side varies

tiny gorge
warm python
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hmm

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ok

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yeah, this sort of makes sense

warm python
tiny gorge
spare folio
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f(n+1)-f(n) is always greater than or equal to zero

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so plus -1 is always greater than ot equal to -1

warm python
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ok, got it

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let me think of something similar for function 2

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yeah, in function two it's definitely not necessary

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there are more points in the Image set than in the preimage set

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so it's possible to create a function such that $f(n) \neq n$

soft zealotBOT
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Why am. I here

ocean lintel
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then create it

warm python
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$f(0)=f(1)=f(2)....f(9)=-2$ and f(10)=12

soft zealotBOT
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Why am. I here

tiny gorge
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simple but effective

spare folio
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haha yes

warm python
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though I'd like to think of a more rigourous proof

desert mantle
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rigorous for what

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both arguments here are rigorous

warm python
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ok, in that case I'm done

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thanks everyone !

tiny gorge
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for (b) you just needed a single example, and you provided one

warm python
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bold coral
#

There is a site/file with all known primes?

final saddleBOT
celest crane
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The number of prime numbers are infinite.

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But you can find relatively small lists of prime numbers online though.

bold coral
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Yes, but I need to download list(because i found site with 1000 billion primes, but i can`t download all list)

zenith pollen
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we know more primes than there is storage space lol

tardy sigil
bold coral
chrome pawn
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there is a collection of the 5000 largest known primes

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which is updated hourly i think

tiny gorge
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is there a practical upper bound that you can take advantage of

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like, there are files containing all primes that fit into a 32 bit integer for example

chrome pawn
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if it's that urgent u can write a simply python code to limit primes upto a 32 bit integer and then write it onto a file

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i think we can use the Sieve of Eratosthenes algorithm

glad steeple
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anyone has an Idea how to integrate this beauty. I have the feeling substitution might be a thing. but I cant think of any idea how.

vast summit
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x=sin theta or cos theta, either one works

bold coral
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Okay, thanks

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glad steeple
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.reopen how do you see this?

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it seems not natural to me

tiny gorge
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glad steeple
#

ah maybe because you know that the derivative of arcsin has something to do with that sqrt expression?

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ivory barn
#

Question leads: Use the first-order Talylor evolution for a linear approximation of
the value of ln(6/5). Then make an estimate of the maximum error (with
sign) in this approximation and also sketch the graph of the function ln 𝑥
along with the linear fit so that the sign of the error estimate
appears.

So sorry if the english is awful

The conclusion choses a value for a = 1 wich I don't really get why they do! I get to f(a) + f´(a)(x-a) but the cheat sheets answer is ln(6/5) wich i don't get

floral nova
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They choose a = 1 because 6/5 is approximately equal to 1 and you can calculate ln(1) without a calculator.

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If there is another value you know that is closer to 6/5 that you can calculate exactly without a calculator, you can use that instead.

ivory barn
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Ahhh ok I get that how do they get it so the first-order is equal to ln(6/5) I don't know if my calculations are way off or if I am doing something wrong here

floral nova
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It won't be equal to that. You are linearly approximating a curve that is not a line.

ivory barn
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sorry I'm just confused on how they get to the conclusion

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f'(x) is 1/x I accidentaly cut it out

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hoary oxide
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hoary oxide
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I am confused for the second statement

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I know that the answer is True, but WHY?

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I thought dimension is number of vectors in a basis

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there are only 3

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how can it be greater?

low cargo
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it doesnt say only containing 3 linearly independent vectors. it could be a 5 dimensional space which will contain 3 lin independent vectors (as well as 2 more)

formal trail
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any subspace (other than the subspace only containing the zero vector) will have infinitely many vectors, so it must contain more than just the 3 vectors overall

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so there may or may not be additional linearly independent vectors in the space (if there aren't then it's 3D, if there are it's higher dimensional)

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@hoary oxide Has your question been resolved?

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slate jasper
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warm wraith
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
slate jasper
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1

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Differentiation

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Or should I divide it?

warm wraith
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You could divide it. That would spare you using the quotient rule

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But either way you would get to the same result

slate jasper
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(x+3) + 36/(x-10)

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@warm wraith

fallow folio
slate jasper
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Yes u/v

fallow folio
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once you differentate, set your function = 0

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it's a quadratic so you get 2 roots

slate jasper
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But what about this method rationalization

fallow folio
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you get the same result but you still need to differentiate

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you should get a fraction with numerators having roots 4 and 16

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after you differentiate

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replace x = 4 into your original eq., so f(4) = 1

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then go for f(16) = 25

slate jasper
fallow folio
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you need to use the quotient rule to differentiate that

slate jasper
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Yesss

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I got it now

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Found the same roots

fallow folio
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good, then f(4) and f(16) should give you 1 and 25

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which is answer b

slate jasper
#

,w close

#

,close

fallow folio
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edgy ore
#

what did I do wrong?

final saddleBOT
edgy ore
#

answer sheet says a = 16 and b = 4

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I know there are different ways of solving this, but I wanted to know what was the mistake here

pseudo knot
#

what is that

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-8-r

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they're said to be in gp and ap but it is not said that the common ratio and common difference are equal

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those are 2 separate quantities

edgy ore
#

hmmm i see

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thanks

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limber isle
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limber isle
#

this is a new concept for me so i feel i ought to check if im getting it right before i move forward

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i only get the answers back once the teacher grades them unfortunately and im going to be completing the unit today so no such luck

sturdy cypress
#

the first one is weird

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i think the formula would have 0.011

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the second one is extra super dumb

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the last one is hard to guess

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it does work for negatives, and it wouldn't make sense if x >= 0 is right but not y >= 0

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so i would guess all real numbers

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but maybe you guessed right

limber isle
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i thought the same for the 1st

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by sumb u mean crazy simple right?

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or am i missing smth

sturdy cypress
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i mean it could be anything

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the third one has the same problem really

limber isle
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<@&286206848099549185> second opinions?

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hm..

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they seemed fine to me

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if not a little simple

onyx lagoon
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Yeah

sturdy cypress
#

they aren't telling you anything about the function in the second one, you have no way to know it's actually guessing

limber isle
#

you have to make the function no

sturdy cypress
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the last one is interesting there's like meta deduction, it can't be option 2 because then option 3 is wrong, it can only be option one

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just it would be a wrong guess, i suppose

limber isle
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sigh

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guess ill try em

limber isle
onyx lagoon
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Just chilling

limber isle
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all correct

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take that guessing game

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tranquil charm
#

why is $\sum^{\inf}{n=1} \frac{1}{n+2}$ divergent sum when $\frac{1}{n+2} \leq \frac{1}{n^2}$ for $n \geq 3$ and $\sum^{\inf}{n=1}\frac{1}{n^2}$ is convergent?

solar glade
#

Put between $

soft zealotBOT
#

Slowaq

thorny tendon
#

If n = 100, that inequality is false

tranquil charm
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ah yes my bad

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so how should i show that it is divergent?

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ah nvm got it

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sonic crystal
#

I’m not sure what I did wrong

final saddleBOT
sonic crystal
#

I don’t know what to do from here

royal gust
#

Consider a u-sub instead

sonic crystal
#

Ohhhh

#

yeah that would work from the start

#

I forgot I could just do that

#

This chapter is about IBP so I was only thinking in terms of that method lol

#

Thanks

#

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royal tusk
#

How would I do 11?

final saddleBOT
royal tusk
#

Everything after the integral I used mathway to help me, but I’m not sure how it even got these values nor how I can isolate y

magic sparrow
#

do you know how to solve those

royal tusk
#

I don’t think so

#

I’m currently taking ap calc ab

magic sparrow
#

that is exactly how you solve these

#

it's even what you started doing in your work on the right

#

You don't need to isolate y

#

to have a solution

royal tusk
#

So where should I stop?

magic sparrow
#

,w y'=e^(x)sin(2y)

royal tusk
#

I was taught to answer this by separation of variable method

magic sparrow
#

ah, looks you can solve for y explicitly somehow

magic sparrow
#

your method is right

#

you just need to figure out how to simplify it, assuming you did your integrals properly

royal tusk
#

I plug integral of dy/sin2y into mathway but got this weird ln(…) as an outcome

magic sparrow
#

that is the correct integral

royal tusk
#

Oh ok

#

But then I got stuck on (1-cos2y)/sin2y= e^(2e^x+c)

#

How would I go from there?

magic sparrow
#

cos(2y) is a trig identity you should know

royal tusk
#

There are a couple

#

I did this

#

Would this be correct?

#

Oh wait it should arctan not arcsin

#

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north spear
#

hi

final saddleBOT
north spear
#

so its says the plane Π contains the points (−1, −3, 2) and (1, 0, 1) and is parallel
lelt with the vector

#

a) i have solved

#

but on b

#

it say count the distance between the point (10, 1 ,1) to II

#

i dont understand how to do that

#

!help

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spare bone
#

Is there an algorithm to check periods of xorshift with different parameters? Like different shifts or number of rounds. It's hard to bruteforce because input is 64bit.

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paper hamlet
#

I'm struggling alot with quadratic equation (grade 10)

paper hamlet
#

Ever since they started the chapter I've not been able to do it without lots of helps

karmic kindle
#

send problem

#

or ask question

paper hamlet
#

Example of the kind of stuff I get

karmic kindle
#

better photo plz

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dense pumice
#

(a_1 a_2 a_3 a_4) + (a_2 a_3 a_4 a_5) + ... + (a_n a_1 a_2 a_3) have n terms , since each of these terms are either +1 or -1, and the sum of all n terms equals 0, there are equal number of +1 and -1 terms in this sum, this implies n is even, that means n is either of the form 4k (divisible by 4) or 4k+2 (not divisible by 4). I am trying to come up with an explanation for why n = 4k+2 would not work, but I have not got anything so far, can someone help me out?

cobalt lodge
#

how many products are there if n=4k+2

dense pumice
cobalt lodge
#

oh wait a minute i thought it didn’t wrap

vital surge
dense pumice
vital surge
#

huh?

dense pumice
#

For n = 6

vital surge
#

where are you getting 7 and 8 from

#

the sequence only goes up to n, meaning there are 6 terms

dense pumice
#

Yeah that's what I'm saying, it doesn't work, we need two more terms for it work,

vital surge
#

i'm not sure what you mean by "it doesn't work"

#

do you mean the statement cannot be true? yes that's what the problem tells us. it's also what we wish to prove

dense pumice
#

Ohh my bad I did some mistake in laying out cases

cobalt lodge
#

ok proof by contradiction works to eliminate n=4k+2

#

by counting the number of all 4(4k+2) values that must be -1

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daring juniper
#

The area of Laatoka is approximately 18,300 km2. Calculate the area of Laatoka with a map ball with a diameter of 30 cm. The diameter of the Earth is 12,700 km.

map scale

daring juniper
#

ive been tryna solve this

#

since yesterday

warm ether
#

how have you been going about it

daring juniper
#

i got 0 clue

warm ether
#

you need to find the area scale of the map to reality
even though big E isnt a sphere

anywho, how do you think you could do that

daring juniper
#

2 people tried to help and failed too

daring juniper
#

ygm?

warm ether
#

maybe

daring juniper
#

yeah but idk the order

#

help me out

#

aint no way none of yall know how to

tall mantle
#

I think what you can do is assume your area is a disk sitting on the sphere. When you ratio down the radius of the sphere, assume you ratio down the radius of the disk in the same way

#

the area of your disk should be shrinking something quadratic with r, not linear

tall mantle
#

A' = A(r'/r)^2 where A is the "old area" and r is the "old radius"

#

the primes are the "new"

#

make sense?

final saddleBOT
#

@daring juniper Has your question been resolved?

daring juniper
tall mantle
#

the new...

#

oh the symbol?

#

A' for example is called "A prime"

final saddleBOT
#

@daring juniper Has your question been resolved?

tall mantle
#

I don't understand the issue, but you should check that it's been resolved

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low magnet
#

I need help understanding items 3, 4 and 5. I have tried solving for items 1 and 2 but idk if they're correct

low magnet
#

item 1

#

item 2

warm ether
#

,calc (1.610^(-19))/(8.85410^(-12))

soft zealotBOT
#

Result:

1.8070928393946e-8
warm ether
#

1 is fine

warm ether
#

what were you doing in 2

#

ah i see

#

seems alright

#

for 3 what does gauss law state

#

for 4, thats quite simple if you just work out the area of that section

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amber crane
#

Hi! these are 2 questions for our homework. The problem is, our professor purposefully doesnt teach the appropriate lesson or math concept beforehand. So far, ive been doing okay in answering the activity, but I'm having a bit of trouble in terms of how to approach these 2 items.

For the first one, I tried doing 6! / 6 as my solution but I'm not too sure I'm understanding the question right, particularly the part where it says "non crossing"

For the second one, what I tried doing is dividing the area hidden by the total area of the smaller rug, this gave me 25% going directly off the numbers provided. I am just not sure if its right to assume that 1/4 of the smaller rug is automatically the hidden area just because it said that the corner falls on the center.

Any insight or help would be greatly appreciated! tyia

chrome pawn
#

in the first problem i think non crossing could mean that the line segments joining two points dont intersect?

amber crane
#

do u think 6!/6 would still be a possible solution ?

chrome pawn
#

what i would do is probably first calculate all possible hand shakes which is 6!/6 since its a ciruclar permutation

#

and then subtract the crossing handshakes

amber crane
chrome pawn
#

of the top of my head

#

i notice that if two dots are adjacent there is no crossing

amber crane
#

hmm, i still seem to be stuck. im trying to figure out a formula to solve this based on what u said

chrome pawn
#

wait i think i was wrong

#

its not gonna be 6!/6 thats the number of ways 6 people can sit in a circle

#

the number of handshakes possible is 6 choose 2

#

@amber crane

amber crane
#

okay that makes sense

chrome pawn
#

so since each person is adjacent to only two people those are the only non crossing handshakes possible

amber crane
chrome pawn
#

wait i fucked up

#

the answer is 9\

#

@amber crane

amber crane
chrome pawn
#

yep

#

may i ask what grade math is this tho

#

because it was easy but i confused myself

amber crane
#

im in 12th grade

#

we have this maths subject but no one really knows the exact concepts it covers

#

its pretty random

chrome pawn
#

oh ok

amber crane
chrome pawn
#

im not that sure about the 2nd one

#

sorry

#

<@&286206848099549185>

sterile vector
#

Guys anyone want to see my face

inland kettle
#

please don't spam/occupy help channels if it isn't relevant.

sterile vector
#

U saying me?

round hinge
#

i mean lerty

amber crane
round hinge
#

😔😔

amber crane
amber crane
round hinge
#

nothing

amber crane
#

wait @chrome pawn sorry follow up question if thats alright

chrome pawn
#

ye

#

go ahead

amber crane
#

how did you get 6 again

#

for all the crossing handshakes

chrome pawn
#

like tbh sinces it only 6 it was easy to manually count it but i guess we can derive a formula for it as well

#

6 choose 2 total number of handshakes
then total number of crossing handshakes
and then total number of non crossing handshakes

since its the difference

#

is that fine?

amber crane
chrome pawn
#

yeah thats what i got

#

9 crossing

#

and 15 total

#

so u subtract

#

and u get 6

#

or u could just count the total number of adjacent pairs

amber crane
chrome pawn
#

ye sorry

amber crane
#

ahhhh

chrome pawn
#

the problem is that since its 6 its easy to count them manually

amber crane
#

okay i get it now

#

thanks

chrome pawn
#

but if the number is large

#

then we need a formula for it

chrome pawn
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#

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royal horizon
#

GM

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manic void
#

Can someone help me with d simplifying algebraic expressions

chrome pawn
#

,rotate

soft zealotBOT
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midnight hill
#

how to express y as a fucntion of x : 1/x + 1/y =1/f

stone wagon
#

and then isolate y

midnight hill
#

oh yeah yeah i did that but i have a hard time isolating y how do you flip 1/y like does it become -y?

zealous holly
#

cross multiplication

stone wagon
#

cross-multiply or raise both sides to power of ^-1 (flip)

midnight hill
#

i am doing this right my answer is y/1 = fx/y - (x-f)/fx

#

oh nevermind is it y = xf -x -f

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hushed dust
#

Hello, I have to find the solutions of the following trigonometric equation.

hushed dust
#

The solutions according to the book are:

#

But I came to this:

#

Here is my resolution, I don't know how to get to the solutions in the book:

#

sen is the same as sin

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#

@hushed dust Has your question been resolved?

hushed dust
#

?

final saddleBOT
#

@hushed dust Has your question been resolved?

final saddleBOT
#

@hushed dust Has your question been resolved?

hushed dust
#

?

analog zealot
#

yo

hushed dust
hushed dust
hushed dust
#

.close

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tawny dagger
#

i dont really understand how the teacher worked this out

the second hand of a watch moved from 2pm to 7pm the same day, if the length of the hand is 12 cm taking pi is 3.14, calculate:

a) the length of an arc defined by this movement
b) the area of the minor sector formed by this movement

zenith pollen
#

the idea is that 2 to 7 is 5/12 of the clock, so the length and area would be 5/12 of the circumference and circle area

tawny dagger
#

could you explain the formulas for this question pls 😶

neon slate
#

you just need the formulas for area and circumference of a circle, do you remember those?

tawny dagger
#

yes!

neon slate
#

so if the length of the clock's hand is 12cm as stated in the problem, what would be the area\circumference of the whole circle?

#

(we can afterwards get the 5/12 part from that)

#

@tawny dagger you understanding the circle we are talking about?

tawny dagger
#

so for circumfrence 2x3.14x12 = 75.36 and area is 3.14x12x12 = 452.16

tawny dagger
#

ok yay i got that part

neon slate
#

but between 2pm and 7pm, it goes just between 5 of the numbers on the clock (out of 12) so all you would have to do is calculate 5/12 of each of those numbers

neon slate
neon slate
#

theres not much to it

#

if it was like...half the clock...you would just multiply by 1/2 right cause it would be half of the area and half of the circumference right?

#

but in this case the part that youre interested in is 5/12 so thats what you multiply by

#

so circumference: 75.36 (5/12)

#

area: 452.16 (5/12)

#

@tawny dagger does that make sense?

tawny dagger
#

ok ok so multiply 75.36 x 5/12 and 452.16 x 5/12?

neon slate
#

and same with area, it's like a pizza of 12 slices, but youre only eating 5

tawny dagger
#

i think if you did the formula like
2x3+2x1

6+2 = 8

i would understand more 😭 im so confused like i just need a working out of this so i can practice more

neon slate
#

it's just 5 parts out of a total of 12

#

it's just 5/12 times whatever the whole thing is

neon slate
tawny dagger
neon slate
#

one is the arc length one is the area yes...

tawny dagger
#

alrightt ty!!

#

i got ittt i got another one :>

#

A clock is reading 11:30 hr. The radius of a circle forming the face of a clock is 15 cm, taking pi is 3.14, calculate:
a) the length of the minor arc defining time
b) the area of the minor arc defining time

#

in this working out 165 was divided by 360 x etc i js wanna know how the area 165 was derived

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#

.close

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limber isle
final saddleBOT
limber isle
#

makes sense?

final saddleBOT
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@limber isle Has your question been resolved?

limber isle
#

<@&286206848099549185>

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.close

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verbal karma
#

Express the probability distribution of the random variable of the sum of the outcomes on rolling 2 dice. The sample space of the discrete random variable for the sum of the outcomes on rolling 2 dice is 6

tiny gorge
#

what do you mean the sample space is 6

#

!original

final saddleBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

verbal karma
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eager stirrup
#

how in the world would i do this?

final saddleBOT
eager stirrup
#

could i get a hint please

mint orbit
#

if thats helpful

#

its a form of the ||leibniz integral rule|| but i could be mistaken

eager stirrup
#

I’ll search it up but I don’t think we learned it

mint orbit
#

We did a half proof on my homework this semester

#

lemme see

ivory vessel
#

pretty sure this can be easily proven by FTC and chain rule

mint orbit
#

yea

#

i just wanted to be sure

eager stirrup
#

The integral?

ivory vessel
#

yes

eager stirrup
#

I wonder if chain rule will produce the same result though

ivory vessel
#

you also use chain rule

#

ftc and chain rule

eager stirrup
#

Because it would become F(h(x))-F(g(x))

#

Oh wait

#

Yeah this is easy

#

Thanks!

#

.close

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final saddleBOT
thick swan
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real quarry
#

Hello! Could you guys give me a hint about where this solution is wrong?

real quarry
#

The steps, I mean, I was able to solve it by difference of squares

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However I must correct the first solution, but I cannot find the error

marble agate
fast heart
#

Factorised out x^2

marble agate
#

ok i see

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im stupid 💀

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im going to sleep

fast heart
#

I don't understand the step after, facyorising x out of the square root

cobalt lodge
#

under what conditions does it hold that lim f(x)g(x) = lim f(x) lim g(x)?

real quarry
cobalt lodge
#

no
and as far as we’re concerned f and g are continuous in the region we’re interested in here

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for a sillier example

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$\lim_{x \rightarrow \infty} 1 = \lim_{x \rightarrow \infty} x \cdot \frac{1}{x} = \lim_{x \rightarrow \infty} x \cdot 0 = 0$

soft zealotBOT
cobalt lodge
#

spot the error

neon slate
#

you have lim (x) = infinity and lim of what was evaluated to the right is 0, but thats an indeterminate form (i.e. lim f(x) = infinity and lim g(x) = 0, you do not have lim [f(x)g(x)] = 0, it is indeterminate and you have to look for some other way to evaluate it

real quarry
cobalt lodge
#

you probably want to either look at notes or google limit laws

real quarry
neon slate
#

you split the limit in 2 then you evaluated the limit of the right part

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but then you slide that 0 back inside the left limit

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as if it wasnt a separate limit

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but the left factor is giving you a limit of inifnity and the right factor is giving you a limit of 0, which is indeterminate

real quarry
neon slate
# real quarry which 0?

yes, you cannot randomly slide a constant into a limit if doesn't exist, and well lim as x-> infty of x doesn't exist

#

so sliding that 0 back into the left limit isnt valid

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before trying to evaluate the limit

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@real quarry are you familiar with lim x-> 0 of sin x / x ?

neon slate
#

ok so what happens if you consider the limits separately:
lim x to 0 (sin x) * lim x to 0 (1/x )

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if you decide the first one is 0

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then multiply that 0 back in and decide 0 * 1/x is 0, now try to evaluate the limit...you'd get 0, but the lim of sin x / x = 1

#

this product law for limits is ONLY valid if the limits exist, so you cannot think of it that way

#

the 1/x limit doesnt exist, so you cannot think of it as the product of two separate instances in this case, because if you do the individual limits of sin x and 1/x you get 0 and infinity, again 0 * infinity is an indeterminate form, so the sin x / x limit must be evaluated some other way, not considering it as a product of two limits

#

do you get your mistake yet @real quarry ?

real quarry
#

Ah, so the error is considering 1 + 1/x as a valid limit, but it doesn't exist given its one sided limits?

neon slate
# real quarry I believe I'm almost there, give me a minute

how did you get 0? you split up the red thing into two parts and decided that the limit of f(x)g(x) is equal to the limit of f(x) * the limit of g(x) and evaluated the limit of g(x) to be 0, but the limit of f(x)g(x) is equal to lim of f(x) * lim g(x) ONLY if the limits of f and g exist, but they dont (at least not both), so this assumption you can split off the big product and evaluate the factors separately is erronous

real quarry
neon slate
#

its the limit of f(x) = x that doesnt exist...

real quarry
#

got it, got it

#

because otherwise it would be infinite * 0, which, as you said, is not determined

neon slate
#

right, those various limit theorems you learn only apply when the limits exist, important fine print

real quarry
neon slate
# real quarry Thank you! I believe the main problem was that I didn't know 0 * infinity is und...

note that limits that evaluate to "+/-infinity" use a different definition than the standard delta epsilon stuff and function a bit differently. some textbooks will say "the limit doesnt exist, but this kind of limit describes the behavior of the function," some might say the limit exists and is infinite or something, but important to know it is a distinctive type of limit than the ones that actually evaluate to a number. I personally like to stick with the idea that the limit doesnt exist but if we have the lim -> infinity then its more describing what the function does

real quarry
#

Thank you so much for your help (and patience!)

#

and also thanks to @cobalt lodge

cobalt lodge
#

it’s the tiny details that matter
and 0*(+-)infty is the only case where product law doesn’t apply

neon slate
#

what about -infty * +infty

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i guess thats -infty? :p

cobalt lodge
#

that’s surprisingly fine, -infty

neon slate
#

never thought about 0 * infty being the only problem

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fun chart

real quarry
#

I read a less rigorous but clear explanation. 1/x (Usually aproximated to 0) is not exactly zero but something very small, which, multiplied by infinity gets arbitrarily big and thus, 0 * infinity is not defined

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Is it a wrong explanation? Or okay-ish?

cobalt lodge
#

uhhhhh

neon slate
#

i dunno if that's a good way to think about it, kinda fudgy at best

cobalt lodge
#

if you write a justification like that, probably 0 marks, maybe 1
but if it helps with understanding sure

real quarry
#

Thank you again, guys!

#

.finish

neon slate
#

.close

final saddleBOT
#
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final saddleBOT
#
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flint perch
final saddleBOT
flint perch
#

how did they find the line segments?

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I know when you plug in 0 you get the point (-5,-3) and 1 you get (0,2)

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but how did they find the parametric representation

tulip coyote
#

Are you familar with the whole parametric a + t(b - a) equation for a line segment from the point a to the point b (with t being from 0 to 1)? If so then it's just that but slightly reframed

flint perch
#

this one?

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Ive definitely learnt this before in lin alg I think?? but I forgot lol

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I'll do a quick search

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for a quick reminder

tulip coyote
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Replace r0 with (-5, -3) and r1 with (0, 2) and then split the line equation into the x and y components and it should hopefully be clearer OathLove

flint perch
#

ohh my

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wow how can i forget..

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its so easy

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ok yea..

final saddleBOT
#

@flint perch Has your question been resolved?

flint perch
#

staying here for a bit..

#

although i think I'll sleep soon because im very sleep deprived

#

have been for a few weeks now but mideterm season is over!!

#

so yea time to become a normal human again

#

i do realize tho, because Im lacking so much sleep I can't think properly anymore cause everything just feels foggy

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ok thats my little rant for the day

tulip coyote
#

(also sorry, I fell asleep on you the other day bcaForgiveBeg3)

flint perch
#

haha no worriess

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lol off topic whyd you change your profile pic?

tulip coyote
tulip coyote
#

Also hi @magic sparrow Hiii

flint perch
#

Ahh i liked your old one lol

#

everytime I see it im like

#

ahh

#

thats chartbit

#

yayyyyyyyyyyyyy

tulip coyote
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Awwww OathLove maybe I might put it back at some point dw1

flint perch
#

lol ok

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also its soo funny but basically there was a question on the real analysis midterm and it was like xn = (-1)^n and yn is cauchy, will xn(yn) also be cauchy.. smth like that

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I literally showed how xn(yn) could diverge

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and then I was like yup

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thats CAUCHY🤩

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I dont remember the exact conditions

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I think they also gave some other detail but I literally proved and concluded the opposite

tulip coyote
flint perch
#

yea, but I dont know why I thought they strictly wanted us to prove xn(yn) is also cauchy

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but after discussing it with some friends after exam, I was like oh...

#

yea so I guess it was a must be true/must be false type of question

tulip coyote
#

Awww sadcat I see SCGhugkitty

flint perch
#

we'll see how I do..

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All I want to do, is to get better than class average for real analysis

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hahahahhaa

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but yea

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but also the class size is super small and everyone is pretty smart

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last exam I got the class average grade😂

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this time... we'll have to see

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but not much hope cause I messed up that question

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and we literally had 3 questions total😂

opaque ember
#

T/F questions are the worst

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they can also be pretty bad to grade keka

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unless you dont ask for counterexamples, then its just binary credit

flint perch
#

ahhhahahha ok I'll be back

#

I might do more stuff or I might just sleep

#

we'll see

#

likely the latter

final saddleBOT
#

@flint perch Has your question been resolved?

flint perch
#

okie goodnight

#

.close

final saddleBOT
#
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final saddleBOT
#
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snow flax
#

hi, could someone help me with the steps on how to solve this? im struggling to think after working on assignments all day and am burning out😭

snow flax
#

or if there is some type of video or content online i can read/watch to come across my answer, please link it 🙏🏾

signal shell
#

Hold on let me ask my sir

#

@magic sparrow help

magic sparrow
#

What is your doubt

signal shell
#

How to evaluate $\int_{-\infty}^\infty f'(t)e^{-st}dt$?

soft zealotBOT
signal shell
#

Using IBP

magic sparrow
#

What have you tried?

#

I suggest you let dv=f'(t)dt

signal shell
#

😮

#

@snow flax you should try that

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I would expect that would lead to a swift answer

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(One line after this)

snow flax
soft zealotBOT
#

weezy🤴🏾

snow flax
#

this is another form of $\mathcal L(f')(s)$ am i correct?

signal shell
#

The lower limit should be 0 (I misremembered)

soft zealotBOT
#

weezy🤴🏾

signal shell
#

But this should just be the definition of the laplace transform applied to the function f'

snow flax
#

$\mathcal L(f')(s)=\int_0^\infty f'(t)e^{-st}dt\
=\int_0^{f'}e^{-st}dt\
=-\frac1s[e^{-sf'}-e^0]\
=\frac1s[1-e^{-sf'}]$

soft zealotBOT
#

weezy🤴🏾

snow flax
#

i feel like i might have gone wrong on the f'?

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or is this good?

signal shell
#

No

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You cant put the function as the top index

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@magic sparrow

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Let me have my sir explain

magic sparrow
#

@snow flax

#

Let me help clear your doubt

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Do you know how to do integration by parts for a simpler function like say maybe, $$\int_{0}^{\pi}x\cos{x}dx$$

soft zealotBOT
#

Austin

snow flax
magic sparrow
#

That's not right

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do you know what integration by parts is?

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It's not the same as u-substitution

snow flax
#

ohh whoops i know what youre saying

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integration from 0 to pi for x then integration from 0 to pi for cos x?

magic sparrow
#

No

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I don't think you know what integration by parts is

snow flax
#

bruh dang i thought ive done it before

magic sparrow
#

Does this look familiar

snow flax
#

yes it looks very familiar

magic sparrow
#

Okay that is the integration by parts formula

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have you done that before?

snow flax
#

yes i have, i think i got my order mixed up before

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or my brains just not braining

signal shell
snow flax
#

so would u be x and dv be cos x then?

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then du =1 and v =-sin x

magic sparrow
#

basically yes

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but you have to evaluate the bounds still

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which is a mistake you were making earlier

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I'll let my protegee take over from here @signal shell

signal shell
#

My friend try watching that video on integration by parts to refresh your memory.

snow flax
#

mr sir and mr protege @magic sparrow @signal shell i might have gotten it

#

hows this ??

magic sparrow
#

I think you left offf the bounds of integration

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and why did you say du=0

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you have not gotten it

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hate to be the bearer of bad news

snow flax
snow flax
magic sparrow
#

..

final saddleBOT
#

@snow flax Has your question been resolved?

final saddleBOT
#
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#
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rotund glen
final saddleBOT
rotund glen
#

Can someone lend a help with part a pls

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#

@rotund glen Has your question been resolved?

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rotund glen
#

.reopen

final saddleBOT
#

rotund glen
#

<@&286206848099549185>

jagged cosmos
#

Start by differentiating the function f(x) using Fundamental Theorem of Calculus

#

$$\dfrac{d}{dx} \int_0^x f(t)dt =f(x)$$

soft zealotBOT
#

Ericsson

jagged cosmos
#

Next write down the Newton Method using the derivative you just calculated

rotund glen
#

Let me work it otu

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wait, should we have f'(x) on the RHS?

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im lowkey confused

jagged cosmos
#

Yes

#

The RHS of the part A is f'(x)

final saddleBOT
#

@rotund glen Has your question been resolved?

rotund glen
#

bro i am lost ngl

#

@jagged cosmos

#

u are my only hope

final saddleBOT
#
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rotund glen
#

.reop

#

.reopen

final saddleBOT
#

rotund glen
#

<@&286206848099549185>

jagged cosmos
rotund glen
#

yes ur back

#

i am losing my mind LOL

#

im sorry

jagged cosmos
#

$$f'(x) = \dfrac{1}{\sqrt{2\pi}} e^{-x^2/2}$$

soft zealotBOT
#

Ericsson

jagged cosmos
#

That's your derivative

#

Plug that in the Newton's method

rotund glen
#

I completely agree, i think i am a bit lost how u got that