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why not tho
because i just realised
(a)(4a) = 4a²
answer should be 3 or -3 for k
which i tested and its correct
<@&286206848099549185>
what
Ask dan
Yes
how -3 tho
Can anyone help me to know how can I develop my math skills?
yeah sure
what grade are you in
Grade 10
im not that great but ill try
from where
Egypt
oh nice
so what do you struggle with
any questions or so you want help trying to solve?
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Thanks for the help
why
What
that dude wants help
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I just want to be good at math in general
Can't he just open a new help channel?
i guess
yeah, do that. #❓how-to-get-help
i can dm you bro
Like I want to know about the skills that I need to know for being nice at math
Just do repetitions for related topics
Practice makes perfect
I can give yall a really good qn
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kind of good
Ok
There's some problem
In my school, I learn mathematics in Arabic
So I think it's difficult some how for me to understand mathematics in English
So it needs time to get uses to it
So can you give me easy qn to practice at it
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how would i differentiate the probability generating function for a binomial distribution X-B(n,p)?
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δy = (u + δu)(v + δv) – uv
= uv + uδv + vδu + δuδv – uv
=uδv+vδu+δuδv
Why do we need to subtract uv
context?
To avoid double counting
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what happened between the second to last step
and the last step
like
how did he end up with sin/cos - cos sin
oh i see
yeah thanks
yup
i have to put a negative sign outside the integral correct ?
so i could get ln
as the product
of the integral
or not ?
wdym
like
the derivative of cos is negative sin
and they're in a fraction
and the integral of anything divided by it's derivative is ln
You mean derivative divided by anything?
uh no not really
this is sinx/cosx
which is tanx
integral of tanx is -ln|cosx|, which is a fairly common integral
yeah well it's the same idea
like the integral of 4x/2x^2 would be ln|2x^2|
bec the derivative of the denominator is the numerator
yes
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Good morning, I'm having trouble with some math in my class that looks like setting a function equal to another function. Here, lg refers to log_2.
Does it actually make sense to say that one function is equal to a modified form of the function? Can I do math on that function in the same way I would with an equation?
For instance, if 2T(n/2) + n = n log_2(n), then does T(n/2) + n = 2n log_2(n)?
To ask a simple version, if f(x) = x + 7, then does f(x) - 7 = x? I was under the impression we must go from x to the outputs of x, not the other way around.
I don't think that's a valid assumption
That's what I'm thinking as well. This is computer science related. Is there a specific place to ask for help on that topic?
Not sure
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My thoughts:- So the ways it can have two solns is that it just touches the x axis once
and intresects the other time
so the derivative must ne negative at some point
so the answer is B ?
I think thats the answer
I'd recommend drawing the cubic and then drawing its derivative
im not certain i follow your logic
so basically, the derivative must be negative on some interval
maybe its easier to think of critical points than signs
as cubics map from R to R, it can't always be negative, or always positive
but it is B yes, because you need two sign changes
I'll try that, thanks
oh yeah, that works very well
thanks both of you!
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so in case 1, the function will have to be a straight line $\frac{\left(y-8\right)}{x-10}=\frac{3}{5}$
Why am. I here
when mapped from R to R instead
why straight line
there are 10 inputs
5 outputs
oh
right
hmm, in case(1) It need not necessarily exist , I think
i.e f(n)=n
same goes for case 2
so B is the answer?
why do you think so
if it doesnt need to exist then surely you can give such an example function
oh
right
for case 1, f(n)=n is necesssary
as there are only 6 number between f(2) and f(10)
7 numbers
and 10 inputs to be mapped
my bad
why does that mean that an input needs to be mapped to itself?
ok and? if the points werent from 0 to 10 but instead from 10 to 20 then it clearly wouldnt hold
yes but you havent used that in your argument so far
OK, so there are 10 elements to be mapped to 7 elements ,such that 7 elements are identical, now , f is increasing on Z. If it's constant, function at f(n)=n is ensured.
if not
f(n)=n is still ensured as there aren't evough elements(Not sure of how I'd prove this) to ensure $f(n)\neq n$
Why am. I here
try drawing the function
how would I do that?
take an example
for a constant function, (except at the endpoint), f(n)=n is true
if you wanna be efficient, try making a function that doesn't work
If you can, you're done
If you can't, you should now know why
draw y = x
but not linear
just mark up to (1,1) (2,2) (3,3).. (10,10)
and
draw a function whose y value doesnt greater than 8 when it is between 0<x<10
here's something that might be useful
let g(n) = f(n) - n
observe that g(n+1) - g(n) >= -1
now compute g(0) and g(10) for your two examples
hmm maybe this doesn't work after all, lemme think again
oh right, it does work
haha sorry, operating on like 2 hours of sleep
how did you come up with that?
just playing around
notice that in the first example, you have
g(0) = f(0) - 0 = 2 and g(10) = f(10) - 10 = -2
so g has to go from 2 to -2
can it avoid 0?
it can't decrease by more than -1 at a time
so no, it can't
why
if you're looking for a fixed point and don't think of looking at f - Id, you lack experience
and as a general strategy, its often better instead of f(n)=n where both sides vary, to consider f(n)-n=0 where only one side varies
g(n+1) - g(n) = f(n+1) - (n+1) - f(n) + n
= f(n+1) - f(n) - 1
>= -1
yeah, I do, never solved a problem like this before
hmm
ok
yeah, this sort of makes sense
great
I follow until the second step, what did you do in step 3
just used that f is nondecreasing, which means f(n+1) >= f(n)
ah, got it
f(n+1)-f(n) is always greater than or equal to zero
so plus -1 is always greater than ot equal to -1
ok, got it
let me think of something similar for function 2
yeah, in function two it's definitely not necessary
there are more points in the Image set than in the preimage set
so it's possible to create a function such that $f(n) \neq n$
Why am. I here
then create it
$f(0)=f(1)=f(2)....f(9)=-2$ and f(10)=12
Why am. I here
simple but effective
haha yes
though I'd like to think of a more rigourous proof
for (b) you just needed a single example, and you provided one
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There is a site/file with all known primes?
The number of prime numbers are infinite.
But you can find relatively small lists of prime numbers online though.
Yes, but I need to download list(because i found site with 1000 billion primes, but i can`t download all list)
we know more primes than there is storage space lol
prove it
yes
there is a collection of the 5000 largest known primes
which is updated hourly i think
is there a practical upper bound that you can take advantage of
like, there are files containing all primes that fit into a 32 bit integer for example
if it's that urgent u can write a simply python code to limit primes upto a 32 bit integer and then write it onto a file
i think we can use the Sieve of Eratosthenes algorithm
anyone has an Idea how to integrate this beauty. I have the feeling substitution might be a thing. but I cant think of any idea how.
x=sin theta or cos theta, either one works
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ah maybe because you know that the derivative of arcsin has something to do with that sqrt expression?
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Question leads: Use the first-order Talylor evolution for a linear approximation of
the value of ln(6/5). Then make an estimate of the maximum error (with
sign) in this approximation and also sketch the graph of the function ln 𝑥
along with the linear fit so that the sign of the error estimate
appears.
So sorry if the english is awful
The conclusion choses a value for a = 1 wich I don't really get why they do! I get to f(a) + f´(a)(x-a) but the cheat sheets answer is ln(6/5) wich i don't get
They choose a = 1 because 6/5 is approximately equal to 1 and you can calculate ln(1) without a calculator.
If there is another value you know that is closer to 6/5 that you can calculate exactly without a calculator, you can use that instead.
Ahhh ok I get that how do they get it so the first-order is equal to ln(6/5) I don't know if my calculations are way off or if I am doing something wrong here
It won't be equal to that. You are linearly approximating a curve that is not a line.
sorry I'm just confused on how they get to the conclusion
f'(x) is 1/x I accidentaly cut it out
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I am confused for the second statement
I know that the answer is True, but WHY?
I thought dimension is number of vectors in a basis
there are only 3
how can it be greater?
it doesnt say only containing 3 linearly independent vectors. it could be a 5 dimensional space which will contain 3 lin independent vectors (as well as 2 more)
any subspace (other than the subspace only containing the zero vector) will have infinitely many vectors, so it must contain more than just the 3 vectors overall
so there may or may not be additional linearly independent vectors in the space (if there aren't then it's 3D, if there are it's higher dimensional)
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
You could divide it. That would spare you using the quotient rule
But either way you would get to the same result
Do you know how to differentiate the function you posted?
Yes u/v
But what about this method rationalization
you get the same result but you still need to differentiate
you should get a fraction with numerators having roots 4 and 16
after you differentiate
replace x = 4 into your original eq., so f(4) = 1
then go for f(16) = 25
If i differentiate it
you need to use the quotient rule to differentiate that
you need to type .close
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what did I do wrong?
answer sheet says a = 16 and b = 4
I know there are different ways of solving this, but I wanted to know what was the mistake here
what is that
-8-r
they're said to be in gp and ap but it is not said that the common ratio and common difference are equal
those are 2 separate quantities
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this is a new concept for me so i feel i ought to check if im getting it right before i move forward
i only get the answers back once the teacher grades them unfortunately and im going to be completing the unit today so no such luck
the first one is weird
i think the formula would have 0.011
the second one is extra super dumb
the last one is hard to guess
it does work for negatives, and it wouldn't make sense if x >= 0 is right but not y >= 0
so i would guess all real numbers
but maybe you guessed right
i thought the same for the 1st
by sumb u mean crazy simple right?
or am i missing smth
<@&286206848099549185> second opinions?
hm..
they seemed fine to me
if not a little simple
Yeah
they aren't telling you anything about the function in the second one, you have no way to know it's actually guessing
you have to make the function no
the last one is interesting there's like meta deduction, it can't be option 2 because then option 3 is wrong, it can only be option one
just it would be a wrong guess, i suppose
wdym by ya?
Just chilling
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why is $\sum^{\inf}{n=1} \frac{1}{n+2}$ divergent sum when $\frac{1}{n+2} \leq \frac{1}{n^2}$ for $n \geq 3$ and $\sum^{\inf}{n=1}\frac{1}{n^2}$ is convergent?
Put between $
Slowaq
If n = 100, that inequality is false
ah yes my bad
so how should i show that it is divergent?
ah nvm got it
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I’m not sure what I did wrong
I don’t know what to do from here
Consider a u-sub instead
Ohhhh
yeah that would work from the start
I forgot I could just do that
This chapter is about IBP so I was only thinking in terms of that method lol
Thanks
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How would I do 11?
Everything after the integral I used mathway to help me, but I’m not sure how it even got these values nor how I can isolate y
#11 is a seperable ODE
do you know how to solve those
that is exactly how you solve these
it's even what you started doing in your work on the right
You don't need to isolate y
to have a solution
So where should I stop?
,w y'=e^(x)sin(2y)
I was taught to answer this by separation of variable method
ah, looks you can solve for y explicitly somehow
yes, because it is a "seperable" ODE like I said earlier
your method is right
you just need to figure out how to simplify it, assuming you did your integrals properly
I plug integral of dy/sin2y into mathway but got this weird ln(…) as an outcome
that is the correct integral
Oh ok
But then I got stuck on (1-cos2y)/sin2y= e^(2e^x+c)
How would I go from there?
cos(2y) is a trig identity you should know
There are a couple
I did this
Would this be correct?
Oh wait it should arctan not arcsin
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hi
so its says the plane Π contains the points (−1, −3, 2) and (1, 0, 1) and is parallel
lelt with the vector
a) i have solved
but on b
it say count the distance between the point (10, 1 ,1) to II
i dont understand how to do that
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Is there an algorithm to check periods of xorshift with different parameters? Like different shifts or number of rounds. It's hard to bruteforce because input is 64bit.
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I'm struggling alot with quadratic equation (grade 10)
Ever since they started the chapter I've not been able to do it without lots of helps
Example of the kind of stuff I get
better photo plz
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(a_1 a_2 a_3 a_4) + (a_2 a_3 a_4 a_5) + ... + (a_n a_1 a_2 a_3) have n terms , since each of these terms are either +1 or -1, and the sum of all n terms equals 0, there are equal number of +1 and -1 terms in this sum, this implies n is even, that means n is either of the form 4k (divisible by 4) or 4k+2 (not divisible by 4). I am trying to come up with an explanation for why n = 4k+2 would not work, but I have not got anything so far, can someone help me out?
how many products are there if n=4k+2
4k+2
oh wait a minute i thought it didn’t wrap
simple way to get started is to consider what happens when n = 6
alright, there should be two more terms a_7 and a_8
huh?
For n = 6
where are you getting 7 and 8 from
the sequence only goes up to n, meaning there are 6 terms
Yeah that's what I'm saying, it doesn't work, we need two more terms for it work,
for n = 6 (i'm omitting the "a"s)
1234 + 2345 + 3456 + 4561 + 5612 + 6123
i'm not sure what you mean by "it doesn't work"
do you mean the statement cannot be true? yes that's what the problem tells us. it's also what we wish to prove
Ohh my bad I did some mistake in laying out cases
ok proof by contradiction works to eliminate n=4k+2
by counting the number of all 4(4k+2) values that must be -1
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The area of Laatoka is approximately 18,300 km2. Calculate the area of Laatoka with a map ball with a diameter of 30 cm. The diameter of the Earth is 12,700 km.
map scale
how have you been going about it
i got 0 clue
you need to find the area scale of the map to reality
even though big E isnt a sphere
anywho, how do you think you could do that
2 people tried to help and failed too
i gotta do the comparison then do parabels and cross them
ygm?
maybe
I think what you can do is assume your area is a disk sitting on the sphere. When you ratio down the radius of the sphere, assume you ratio down the radius of the disk in the same way
the area of your disk should be shrinking something quadratic with r, not linear
so what do i do
A' = A(r'/r)^2 where A is the "old area" and r is the "old radius"
the primes are the "new"
make sense?
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what r primes
@daring juniper Has your question been resolved?
I don't understand the issue, but you should check that it's been resolved
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I need help understanding items 3, 4 and 5. I have tried solving for items 1 and 2 but idk if they're correct
,calc (1.610^(-19))/(8.85410^(-12))
Result:
1.8070928393946e-8
1 is fine
what were you doing in 2
ah i see
seems alright
for 3 what does gauss law state
for 4, thats quite simple if you just work out the area of that section
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Hi! these are 2 questions for our homework. The problem is, our professor purposefully doesnt teach the appropriate lesson or math concept beforehand. So far, ive been doing okay in answering the activity, but I'm having a bit of trouble in terms of how to approach these 2 items.
For the first one, I tried doing 6! / 6 as my solution but I'm not too sure I'm understanding the question right, particularly the part where it says "non crossing"
For the second one, what I tried doing is dividing the area hidden by the total area of the smaller rug, this gave me 25% going directly off the numbers provided. I am just not sure if its right to assume that 1/4 of the smaller rug is automatically the hidden area just because it said that the corner falls on the center.
Any insight or help would be greatly appreciated! tyia
in the first problem i think non crossing could mean that the line segments joining two points dont intersect?
ohh makes sense
do u think 6!/6 would still be a possible solution ?
what i would do is probably first calculate all possible hand shakes which is 6!/6 since its a ciruclar permutation
and then subtract the crossing handshakes
how would i be able to calculate all possible crossing handshakes?
hmm, i still seem to be stuck. im trying to figure out a formula to solve this based on what u said
wait i think i was wrong
its not gonna be 6!/6 thats the number of ways 6 people can sit in a circle
the number of handshakes possible is 6 choose 2
@amber crane
OH
okay that makes sense
so since each person is adjacent to only two people those are the only non crossing handshakes possible
but im not sure how id come up with a formula for calculating all possible crossing handshakes based on what u said
oh this is already with the crossing handshakes subtracted?
yep
may i ask what grade math is this tho
because it was easy but i confused myself
im in 12th grade
we have this maths subject but no one really knows the exact concepts it covers
its pretty random
oh ok
also, is my approach to the 2nd question valid?
Guys anyone want to see my face
please don't spam/occupy help channels if it isn't relevant.
U saying me?
i mean lerty
all good no worries. thanks for helping me with the first ques!
😔😔
yup I just need some verification that my approach to the 2nd item that I sent is valid
i was about to answer
wdym
nothing
wait @chrome pawn sorry follow up question if thats alright
like tbh sinces it only 6 it was easy to manually count it but i guess we can derive a formula for it as well
6 choose 2 total number of handshakes
then total number of crossing handshakes
and then total number of non crossing handshakes
since its the difference
is that fine?
but i manually counted 9 crossing handshakes. orrr am i counting this the wrong way
yeah thats what i got
9 crossing
and 15 total
so u subtract
and u get 6
or u could just count the total number of adjacent pairs
but non crossing would be the adjacent ones no?
ye sorry
ahhhh
the problem is that since its 6 its easy to count them manually
no problem
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GM
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how to express y as a fucntion of x : 1/x + 1/y =1/f
subtract 1/x from both sides
and then isolate y
oh yeah yeah i did that but i have a hard time isolating y how do you flip 1/y like does it become -y?
cross multiplication
no
cross-multiply or raise both sides to power of ^-1 (flip)
i am doing this right my answer is y/1 = fx/y - (x-f)/fx
oh nevermind is it y = xf -x -f
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Hello, I have to find the solutions of the following trigonometric equation.
The solutions according to the book are:
But I came to this:
Here is my resolution, I don't know how to get to the solutions in the book:
sen is the same as sin
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@hushed dust Has your question been resolved?
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yo
a?

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i dont really understand how the teacher worked this out
the second hand of a watch moved from 2pm to 7pm the same day, if the length of the hand is 12 cm taking pi is 3.14, calculate:
a) the length of an arc defined by this movement
b) the area of the minor sector formed by this movement
the idea is that 2 to 7 is 5/12 of the clock, so the length and area would be 5/12 of the circumference and circle area
could you explain the formulas for this question pls 😶
you just need the formulas for area and circumference of a circle, do you remember those?
yes!
so if the length of the clock's hand is 12cm as stated in the problem, what would be the area\circumference of the whole circle?
(we can afterwards get the 5/12 part from that)
@tawny dagger you understanding the circle we are talking about?
so for circumfrence 2x3.14x12 = 75.36 and area is 3.14x12x12 = 452.16
a bittt i js need help along the way
ok yay i got that part
yes that's exactly right, so that's the circumference \ area of the circle traced by the clock's hand if it was moving all the way around the clock
but between 2pm and 7pm, it goes just between 5 of the numbers on the clock (out of 12) so all you would have to do is calculate 5/12 of each of those numbers
ohhhh
wait im lost 💀
you just multiply the area\circumference you got by 5/12 lol
theres not much to it
if it was like...half the clock...you would just multiply by 1/2 right cause it would be half of the area and half of the circumference right?
but in this case the part that youre interested in is 5/12 so thats what you multiply by
so circumference: 75.36 (5/12)
area: 452.16 (5/12)
@tawny dagger does that make sense?
ok ok so multiply 75.36 x 5/12 and 452.16 x 5/12?
yes like...the circumference is divided into 12 parts right? (the arc length between each hour on the clock) and you go between 5 of them, so total of 5 out of 12
and same with area, it's like a pizza of 12 slices, but youre only eating 5
i think if you did the formula like
2x3+2x1
6+2 = 8
i would understand more 😭 im so confused like i just need a working out of this so i can practice more
what's the confusion?
it's just 5 parts out of a total of 12
it's just 5/12 times whatever the whole thing is
you already have the answer here
would that be for a and b
one is the arc length one is the area yes...
alrightt ty!!
i got ittt i got another one :>
A clock is reading 11:30 hr. The radius of a circle forming the face of a clock is 15 cm, taking pi is 3.14, calculate:
a) the length of the minor arc defining time
b) the area of the minor arc defining time
in this working out 165 was divided by 360 x etc i js wanna know how the area 165 was derived
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makes sense?
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Express the probability distribution of the random variable of the sum of the outcomes on rolling 2 dice. The sample space of the discrete random variable for the sum of the outcomes on rolling 2 dice is 6
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
It's whats stated in the instructions so im asking for help since I dont get it either
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how in the world would i do this?
could i get a hint please
i believe this has a name
if thats helpful
its a form of the ||leibniz integral rule|| but i could be mistaken
I’ll search it up but I don’t think we learned it
pretty sure this can be easily proven by FTC and chain rule
Do FTC on what?
The integral?
yes
I wonder if chain rule will produce the same result though
Because it would become F(h(x))-F(g(x))
Oh wait
Yeah this is easy
Thanks!
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Hello! Could you guys give me a hint about where this solution is wrong?
The steps, I mean, I was able to solve it by difference of squares
However I must correct the first solution, but I cannot find the error
how x^2+x became x^2(1+1/x)?
Factorised out x^2
I don't understand the step after, facyorising x out of the square root
under what conditions does it hold that lim f(x)g(x) = lim f(x) lim g(x)?
is it because both f and g must be continuous?
no
and as far as we’re concerned f and g are continuous in the region we’re interested in here
for a sillier example
$\lim_{x \rightarrow \infty} 1 = \lim_{x \rightarrow \infty} x \cdot \frac{1}{x} = \lim_{x \rightarrow \infty} x \cdot 0 = 0$
IV
spot the error
you have lim (x) = infinity and lim of what was evaluated to the right is 0, but thats an indeterminate form (i.e. lim f(x) = infinity and lim g(x) = 0, you do not have lim [f(x)g(x)] = 0, it is indeterminate and you have to look for some other way to evaluate it
I see the error clearly, but I can't justify exactly why it's wrong in a solid conceptual way
at which point we go back to this
you probably want to either look at notes or google limit laws
I'm doing exactly that, ashhashas, I'm still trying to understand what's the case here
this isn't equals to 0, this only evaluates to 0 if you take the limit
you split the limit in 2 then you evaluated the limit of the right part
but then you slide that 0 back inside the left limit
as if it wasnt a separate limit
but the left factor is giving you a limit of inifnity and the right factor is giving you a limit of 0, which is indeterminate
which 0?
yes, you cannot randomly slide a constant into a limit if doesn't exist, and well lim as x-> infty of x doesn't exist
so sliding that 0 back into the left limit isnt valid
before trying to evaluate the limit
@real quarry are you familiar with lim x-> 0 of sin x / x ?
ok so what happens if you consider the limits separately:
lim x to 0 (sin x) * lim x to 0 (1/x )
if you decide the first one is 0
then multiply that 0 back in and decide 0 * 1/x is 0, now try to evaluate the limit...you'd get 0, but the lim of sin x / x = 1
this product law for limits is ONLY valid if the limits exist, so you cannot think of it that way
the 1/x limit doesnt exist, so you cannot think of it as the product of two separate instances in this case, because if you do the individual limits of sin x and 1/x you get 0 and infinity, again 0 * infinity is an indeterminate form, so the sin x / x limit must be evaluated some other way, not considering it as a product of two limits
do you get your mistake yet @real quarry ?
I believe I'm almost there, give me a minute
Ah, so the error is considering 1 + 1/x as a valid limit, but it doesn't exist given its one sided limits?
how did you get 0? you split up the red thing into two parts and decided that the limit of f(x)g(x) is equal to the limit of f(x) * the limit of g(x) and evaluated the limit of g(x) to be 0, but the limit of f(x)g(x) is equal to lim of f(x) * lim g(x) ONLY if the limits of f and g exist, but they dont (at least not both), so this assumption you can split off the big product and evaluate the factors separately is erronous
But why doesn't the limit of g(x) exist?
its the limit of f(x) = x that doesnt exist...
Ahhh
got it, got it
because otherwise it would be infinite * 0, which, as you said, is not determined
right, those various limit theorems you learn only apply when the limits exist, important fine print
Thank you! I believe the main problem was that I didn't know 0 * infinity is undefined, but those will surely help
note that limits that evaluate to "+/-infinity" use a different definition than the standard delta epsilon stuff and function a bit differently. some textbooks will say "the limit doesnt exist, but this kind of limit describes the behavior of the function," some might say the limit exists and is infinite or something, but important to know it is a distinctive type of limit than the ones that actually evaluate to a number. I personally like to stick with the idea that the limit doesnt exist but if we have the lim -> infinity then its more describing what the function does
Ah, okay. I will read some stuff on that specific matter because it has got me curious now
Thank you so much for your help (and patience!)
and also thanks to @cobalt lodge
it’s the tiny details that matter
and 0*(+-)infty is the only case where product law doesn’t apply
that’s surprisingly fine, -infty
I read a less rigorous but clear explanation. 1/x (Usually aproximated to 0) is not exactly zero but something very small, which, multiplied by infinity gets arbitrarily big and thus, 0 * infinity is not defined
Is it a wrong explanation? Or okay-ish?
uhhhhh
i dunno if that's a good way to think about it, kinda fudgy at best
if you write a justification like that, probably 0 marks, maybe 1
but if it helps with understanding sure
Oh, yeah, definetely, ashhasheashs. I was more worried if it was actually true, even though it's not a mathematical proof
Thank you again, guys!
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how did they find the line segments?
I know when you plug in 0 you get the point (-5,-3) and 1 you get (0,2)
but how did they find the parametric representation
Are you familar with the whole parametric a + t(b - a) equation for a line segment from the point a to the point b (with t being from 0 to 1)? If so then it's just that but slightly reframed
this one?
Ive definitely learnt this before in lin alg I think?? but I forgot lol
I'll do a quick search
for a quick reminder
Yea that's the one 
Replace r0 with (-5, -3) and r1 with (0, 2) and then split the line equation into the x and y components and it should hopefully be clearer 
@flint perch Has your question been resolved?
staying here for a bit..
although i think I'll sleep soon because im very sleep deprived
have been for a few weeks now but mideterm season is over!!
so yea time to become a normal human again
i do realize tho, because Im lacking so much sleep I can't think properly anymore cause everything just feels foggy
ok thats my little rant for the day
Me too
only slept for less than an hour yesterday
(also sorry, I fell asleep on you the other day
)
Awwww
definitely can get that. make sure you get some rest soonish 
Just felt like changing it haha
Also hi @magic sparrow 
Ahh i liked your old one lol
everytime I see it im like
ahh
thats chartbit
yayyyyyyyyyyyyy
Awwww
maybe I might put it back at some point 
lol ok
also its soo funny but basically there was a question on the real analysis midterm and it was like xn = (-1)^n and yn is cauchy, will xn(yn) also be cauchy.. smth like that
I literally showed how xn(yn) could diverge
and then I was like yup
thats CAUCHY🤩
I dont remember the exact conditions
I think they also gave some other detail but I literally proved and concluded the opposite
Awww
was it like a "it must be true/must be false/may be either true or false" type question or something?
yea, but I dont know why I thought they strictly wanted us to prove xn(yn) is also cauchy
but after discussing it with some friends after exam, I was like oh...
yea so I guess it was a must be true/must be false type of question
Awww
I see 
we'll see how I do..
All I want to do, is to get better than class average for real analysis
hahahahhaa
but yea
but also the class size is super small and everyone is pretty smart
last exam I got the class average grade😂
this time... we'll have to see
but not much hope cause I messed up that question
and we literally had 3 questions total😂
T/F questions are the worst
they can also be pretty bad to grade 
unless you dont ask for counterexamples, then its just binary credit
ahhhahahha ok I'll be back
I might do more stuff or I might just sleep
we'll see
likely the latter
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hi, could someone help me with the steps on how to solve this? im struggling to think after working on assignments all day and am burning out😭
or if there is some type of video or content online i can read/watch to come across my answer, please link it 🙏🏾
What is your doubt
How to evaluate $\int_{-\infty}^\infty f'(t)e^{-st}dt$?
rbmuk
Using IBP
😮
@snow flax you should try that
I would expect that would lead to a swift answer
(One line after this)
so integrate $\int_{-\infty}^\infty f'(t)e^{-st}dt$?
weezy🤴🏾
this is another form of $\mathcal L(f')(s)$ am i correct?
The lower limit should be 0 (I misremembered)
weezy🤴🏾
But this should just be the definition of the laplace transform applied to the function f'
$\mathcal L(f')(s)=\int_0^\infty f'(t)e^{-st}dt\
=\int_0^{f'}e^{-st}dt\
=-\frac1s[e^{-sf'}-e^0]\
=\frac1s[1-e^{-sf'}]$
weezy🤴🏾
i used a littlesomething from my notes, how does this look
i feel like i might have gone wrong on the f'?
or is this good?
No
You cant put the function as the top index
@magic sparrow
Let me have my sir explain
@snow flax
Let me help clear your doubt
Do you know how to do integration by parts for a simpler function like say maybe, $$\int_{0}^{\pi}x\cos{x}dx$$
Austin
yes if im not wrong, take u=cos x and du the derivative
That's not right
do you know what integration by parts is?
It's not the same as u-substitution
ohh whoops i know what youre saying
integration from 0 to pi for x then integration from 0 to pi for cos x?
bruh dang i thought ive done it before
yes it looks very familiar
Integration by parts by using the DI method! This is the easiest set up to do integration by parts for your calculus 2 integrals. We will also do 3 integrals to illustrate the 3 stops of the DI method.
Dear calculus teachers, please let students use the DI Method (& why it is really the same as integration by parts) 👉 https://youtu.be/8xPfNuXLS...
basically yes
but you have to evaluate the bounds still
which is a mistake you were making earlier
I'll let my protegee take over from here @signal shell
My friend try watching that video on integration by parts to refresh your memory.
mr sir and mr protege @magic sparrow @signal shell i might have gotten it
hows this ??
I think you left offf the bounds of integration
and why did you say du=0
you have not gotten it
hate to be the bearer of bad news
ahh thats another part i need a brush up on
is du just e^-st again? this e rule is so crazy
..
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Can someone lend a help with part a pls
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Start by differentiating the function f(x) using Fundamental Theorem of Calculus
$$\dfrac{d}{dx} \int_0^x f(t)dt =f(x)$$
Ericsson
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<@&286206848099549185>
Write
$$f'(x) = \dfrac{1}{\sqrt{2\pi}} e^{-x^2/2}$$
Ericsson
I completely agree, i think i am a bit lost how u got that