help-36

[pine axle]

Nope

[signal vector]

Okay, we know our needs to have remainder 2 when divided by 3

[pine axle]

Yeah…

[signal vector]

Let's call the number a

[signal vector]

Can you write "a" in an alternate form given this information?

[pine axle]

Absolutely not, I tried but I couldn’t

[signal vector]

What about a=3k+2 for some integer k

[pine axle]

Yeah but does that help?

I was trying to not use another integer

[signal vector]

It does, since you know the number if between 81 and 80

You only need to check numbers of the form 3k+2 now

[pine axle]

Butttt originally I didn’t

Like could I have solved this without simply guessing?

[signal vector]

No

[pine axle]

What about that theorem you mentioned?

[signal vector]

Yes, you can use it

[pine axle]

Without guessing it would have worked?

[soft zealot]

smidgin

[pine axle]

Well… I get none of that so I assume my teacher just wanted us to use deductive reasoning

Thanks anyway

[signal vector]

Okay you know the following information:
a=3j+2
a=5k+3
a=11l+6
for some integers j, k and l

[pine axle]

Yes

Solid so far

[signal vector]

Right so you have 3j+2=5k+3

[pine axle]

Yes

[signal vector]

Right so now, multiply through by 7 to get
21j+14=35k+21
=>20j+j+14=35k+21
=>j+14=5(7k-4j)+21
=> j=5(7k-4j)+7=5(7k-4j+1)+2
7k-4j+1 is some integer, say m
So =>j=5m+2

[pine axle]

Why by 7

[signal vector]

Because 7 is the inverse of 3 mod 5, what this means is that when you multiply 3 by 7 and divide by 5, you get a remainder of 1

This is why it is helpful to know modular arithmetic here

[pine axle]

Oh ok

And what is this hole => stuff

[signal vector]

=> just means "implies" or next step. For example

=>x=3```

[pine axle]

Oh ok

What does mod mean

[signal vector]

"mod" by itself has no meaning

[pine axle]

In this sense

[signal vector]

In this sense it means this

[pine axle]

But that’s the inverse?

What would 3 mod 5 be by itself

[signal vector]

3 mod 5 is the remainder you get when you divide 3 by 5

[pine axle]

Oh ok

[signal vector]

7 is the inverse of 3 mod 5 means "when you multiply 3 by 7 and divide by 5, you get a remainder of 1"

[signal vector]

Anyways let's get back to here

[pine axle]

Ok

[signal vector]

We know j = 5m+2 for some integer m

[pine axle]

Yes

[signal vector]

And since
a=3j+2, you have a=3(5m+2)+2=15m+8

[pine axle]

Ok

Yeah

[signal vector]

Now we had a third equation that said a=11l+6

Let's use that

[pine axle]

Ok

[signal vector]

So you have
15m+8=11l+6

=>11m+4m+8=11l+6
=> 4m+8=11(l-m)+6

[pine axle]

Yeah ok

[signal vector]

And do you remember what we did last time?

We multiplied through by the inverse

[pine axle]

Yes

I don’t know how to find inverse tho

[signal vector]

This time we want the inverse of 4 mod 11

[pine axle]

I’m doing this on FOM 10 math as it’s the last actual course I took

[signal vector]

So find a number "b" so that when you multiply 4 by b and divide by 11, you get a remainder 1

The number b will be smaller than 11, so we only need to try 10 numbers

[pine axle]

Hm ok

[signal vector]

You will notice that b=3 works

[pine axle]

Yes

[signal vector]

4x3=12 and when you divide 12 by 11 you get a remainder of 1

[pine axle]

Yeah

[signal vector]

So multiply throughout by 3

You will get 12m+24=33(l-m)+18

[pine axle]

Ok

[signal vector]

=>11m+m+24=11(3(l-m))+18
=>m+24=11(3(l-m)-m)+18
=>m=11(3l-4m)-6

[pine axle]

Yeah

[signal vector]

m=11(3l-4m)-11+11-6=11(3l-4m-1)+5

3l-4m-1 is some integer say n so you have m=11n+5

[pine axle]

Ok

Following so far

[signal vector]

From here we knew a=15m+8

And now we know m=11n+5

So a=15(11n+5)+8

[pine axle]

But we don’t know n do we?

[signal vector]

We don't, but dont worry

[pine axle]

Ok…

[signal vector]

So from here a=165n+75+8=165n+83

@pine axle

[pine axle]

Yeah I’m here

[signal vector]

So we have this right?

a must be a number of the form 165n+83

[pine axle]

Yes

[signal vector]

Now they asked for the smallest postive integer, so set n=0

You get a=83

[pine axle]

wow

That was majestic

Solid answer

[signal vector]

Im not sure how you can "deductively reason" this

[pine axle]

I did I using the 11 part

It wasn’t too bad

But thanks

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[rotund ledge]

cos(x)=x

[rotund ledge]

I need solution 10 min

write in terms x=...

[desert mantle]

there is no closed form solution for that

why do you need it in 10 min

[viscid fossil]

Use newton's method

[rotund ledge]

math homework

[rotund ledge]

teach me

[rotund ledge]

Class is in 5 mins, but i can get away with another 5

5 mins!

Not enough time

.close

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[sturdy lodge]

Hi

[sturdy lodge]

I need help with this

And I think the problem's wrong

[astral moss]

the pin should be stationary

the bowling ball is the one with 1m/s velocity

[sturdy lodge]

Yea?

What's my mistake here

[astral moss]

u_1 should be 1

and u_2 should be 0

[sturdy lodge]

Why

[astral moss]

m_1 is the mass of the bowling ball which is 2kg

which is rolling at 1m/s

thus u_1, which is the velocity of the bowling ball, should be 1

[sturdy lodge]

Ohh

[astral moss]

similar mistake on the right hand side

[sturdy lodge]

Then 2×1?

[astral moss]

correct, and you have to fix all the others

[sturdy lodge]

And u2 would be 0

Why?

[astral moss]

yeah

[sturdy lodge]

Why

[astral moss]

it says the bowling pin is stationary

m_2 is mass of bowling pin, u_2 is velocity of bowling pin

[sturdy lodge]

Didn't it said

Stationary pin

Approaching a stationary pin

[astral moss]

It says the bowling ball is approaching a stationary pin

[sturdy lodge]

So the pin

Was stationary

[astral moss]

yeah

[sturdy lodge]

Not the ball as it was approaching

Then u2 is for pin?

But u said the ball

It's for ball

[astral moss]

u is for the initial velocity of each the bowling ball and the pin

(m_1 * u_1) is the bowling ball initially

[sturdy lodge]

That's how it confuses me

[astral moss]

(m_2 * u_2) is the bowling pin initially

[sturdy lodge]

Ohh

V1 is m/s right?

[astral moss]

yeah, u and v are velocities, which are measured in m/s

[sturdy lodge]

So what is V2

[astral moss]

Well the new equation would be'

[sturdy lodge]

Do I ultimately make V2 the

Subject

[astral moss]

Well notice m_1, u_1, and v_1 are the properties of the bowling ball

and its asking you to find the velocity of the ball after impact

so you need to end up with v_1 as the subject

[sturdy lodge]

Then

What about V2

[astral moss]

v_2 is known

[sturdy lodge]

0.5?

[astral moss]

it says the pin flies away with velocity 0.5m/s

yea

[sturdy lodge]

So v1 is actually about what?

[astral moss]

v1 would be the velocity of the bowling ball

[sturdy lodge]

And V2 is the velocity in what sense

[astral moss]

Pretty much at the start, you just pick any object to be object 1, and the other to be object 2

[sturdy lodge]

Ohh

[astral moss]

in this case we choose object 1 as the bowling ball

and object 2 as the pin

so v_1 is velocity of the ball after impact

and v_2 is velocity of the pin after impact

[sturdy lodge]

Yea so V1 is the velocity before it hit the pin

[astral moss]

u means before, v means after

[sturdy lodge]

Its asking what was the velocity

Befoew

[astral moss]

u_1 is the velocity of the ball before

[sturdy lodge]

Beforw

[astral moss]

u_2 is the velocity of the pin before

[sturdy lodge]

Yea

If it was the velocity before

Then what is V1

About

[astral moss]

velocity of the bowling ball after the impact

v_1 is what you want to find

[sturdy lodge]

Ohh after the impact the pin's velocity is 0.5 but we don't know the balls velocity

[astral moss]

yeah

your solving for the balls velocity after impact

v_1

[sturdy lodge]

Wait

Lemme show u

U here

[astral moss]

yeah

[sturdy lodge]

Is it okay

@astral moss

[astral moss]

Not quite

[sturdy lodge]

Why not

[astral moss]

the left hand side of equation is right

but you put down the bowling ball velocity as 0.5 after collision

but its meant to be the pin

(2*v1)+(0.5*0.5)

[sturdy lodge]

Yea I gave it for the pin

@astral moss

So I make V1 the subject

[astral moss]

yes, the question is asking for you to find the velocity of the ball

[sturdy lodge]

Ye

[astral moss]

which is v_1, thats the unknown

[sturdy lodge]

Ye

[astral moss]

(2*1)+(0.5*0) = (2*v_1)+(0.5*0.5) and solve for v1

[astral moss]

That looks good yes

[sturdy lodge]

Is it correct

@astral moss

[astral moss]

yeah

[sturdy lodge]

Yay

Now lemme practice more

And will u be here

If I have problems

@astral moss

[astral moss]

Sure, im happy to help

[sturdy lodge]

Kk

Plz be here when I pin then

[astral moss]

Got u on my second monitor 😉

[sturdy lodge]

Omg thnz

Thnx

And will the unit

Be on Kg/m/s

Kgm/s

0.875

[astral moss]

Not for that answer because what we found is a velocity only

it is kgm/s when its a momentum

p=mv

[sturdy lodge]

Ohh

Can I add u as a friend

So I can pin u anytime

[astral moss]

If you wanna, there's probably people much more helpful than me but im fine with it lol

[sturdy lodge]

Kk

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[neon slate]

so i think the relevant theta are pi/2 and 3pi/2 and I'm trying to use the equation tan(chi) = r / (dr/dtheta) to find the angle chi, which is the angle between the tangent line and ray from origin to the point on the graph, but im a bit confused on the geometry of what that angle is exactly and especially since we'd be considering a point at the origin with r = 0

(for the record not interested in trying to do this by converting to cartesian since i'm specifically trying to work out my confusion of polar coordinate stuff, if someone could help me out with it)

[barren hound]

3pi/2 isn't relevant, just pi/2

[neon slate]

oh im dumb yeah i forgot my basic sin values

😐

[barren hound]

this cusp is what you're calculating

[neon slate]

looks undifferentiable 🤔

[barren hound]

it is yeah

but it's one-side differentiable or whatever? it's a sharp point but because of that there's an angle

like how the angle for y = |x| would be 90º

[neon slate]

hm

so for example, lets say we wanted to find the equation of the like tangent to 1 side of it

for the sake of argument, how would you go about that

[barren hound]

i'd probably convert it to rectangular coordinates but there may be a way to keep it in polar

[neon slate]

i'm trying to understand this tan(chi) = r / (dr/dtheta) where chi is that angle shown in the diagram but i find it a bit confusing and the examples in the book are just "find chi" instead of using it to actually find the equation of the tangent or whatever

i guess if P is on the graph, then chi is the angle between OP and the tangent

[barren hound]

yeah

not sure this will work exactly like you want it though since the tangent line will run through O

[neon slate]

what if we just took like equation r = 1 as a simple example and we wanted to try to find the equation of the tangent at theta = pi/4

erm dr/theta of that is 0

[barren hound]

and \Chi is pi/2 so that tracks

[neon slate]

ah, good point

[barren hound]

you may be able to do something and then take its limit as theta approaches pi/2

[neon slate]

ok guess i'm just finding it hard to understand why the book introduced this tan chi thing, because the examples they provided didn't show them really using it for anything or motivating it in particular, but i think i'll think about it later, or maybe it will be clarified with some other problems thanks for the input, 🙏

also though, how would you see analytiically that the cardoid is undifferentiable at that point

at pi/2

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[verbal steppe]

If i'm given the plane 3x + 2y + 5z = 0. how can i create a transformation matrix out of it which is mirrored on the plane

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[twilit snow]

Hi I need help with planes I couldnt find help the last time

[final saddle]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

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[twilit snow]

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[vagrant tundra]

How do all - change to a + and the - before 9x^2 goes infront of the bracket?

[west berry]

That - is equivalent to a -1 multiplied with the entire thing inside the brackets

In other words, they have factored -1

[vagrant tundra]

what do you mean by factored by -1?

[west berry]

-x-y = (-1)x + (-1)y = (-1)(x+y)
= -(x+y)

That's another example

[vagrant tundra]

so thats multiplying every polinomial with -1?

when they are negative

[west berry]

Yeah, so you can take the -1 common with all terms within the brackets

So -1 comes outside

[vagrant tundra]

and -1 can be written as - right

before the brackets

[west berry]

Yes

[vagrant tundra]

so like 16z^2 -1*(bracket content) == 16z^-(bracket content) ?

[west berry]

Yup

You can verify it too

If you wanna remove the brackets you'll have to multiply -1 with each of the terms within(coz there's a -1 multiplied outside the brackets)

Doing so will get you back to the original thing

[vagrant tundra]

alright thanks for elaborating i got it now

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[west berry]

Np

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[acoustic oar]

let a be the root of x^3+x-1=0, find a polynomial of int coefficients which has root (a-1)/(a+1), I used cardano's method and got a, but its expression is very messy. I tried subbing a in terms of the equation but that didnt help much either do I have to expand x - (a-1)/(a+1) = 0 ? or is there a more clever way.

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[acoustic oar]

<@&286206848099549185>

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[tranquil pine]

What is the degree of the polynomial

Whose root is a+1/a-1

[acoustic oar]

it is not known

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[acoustic oar]

.reopen

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✅

[tranquil pine]

Then can't be done

[acoustic oar]

why not

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[elfin bough]

Just need clarification, how/why does the equation get inversed to sin^-1

[zenith pollen]

that's how you move sine from one side to another, sin^-1 is the inverse of it

like how for x+5=2/3 you'd make it x=2/3-5 or how you'd square root to get rid of a square exponent

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[elfin bough]

Ahh I see

Thanks a lot

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[remote island]

what's the best way to write it in trigonometric form?

[pseudo knot]

Multiply the conjugate and get rid of iota from denominator

The standard way

[remote island]

aight

doing it rn

b ut i'm not sure what do after

[spark kettle]

Send what you get when you finish that

[remote island]

(29-39i)/29

[spark kettle]

So you are looking to turn it into $r(\cos \theta + i \sin \theta)$?

[soft zealot]

Pluton

[remote island]

ye

[spark kettle]

For $z = a + bi$ we have $r = \sqrt{a^2 + b^2}$ and $\theta = \tan^{-1} \frac{b}{a}$

[soft zealot]

Pluton

[remote island]

sure but it will get really ugly

[spark kettle]

Just the angle could maybe be a little in the wrong place

So make sure that is right

[remote island]

sqrt(29^2 + 39^2)/29^2)

[spark kettle]

The range of $\tan^{-1}$ is $\left< - \frac{\pi}{2} , \frac{\pi}{2} \right>$

[soft zealot]

Pluton

[spark kettle]

Make sure to take in account if your angle is not in that range

[remote island]

ok dude

but how is this supposed to be neat

[spark kettle]

It wont be

[remote island]

by dividing the whole thing into z_1 / z_2 you have sqrt(56)

well anyway

[remote island]

let's finish this

[spark kettle]

Well just calculate r

And angle

[remote island]

sqrt(2362)/841

[spark kettle]

Ok now the angle

[remote island]

angle = tan(-1) -39/29

[remote island]

isn't that incorrect

it's < -1

so in a unit circle no angle corersponds to it as it ranges from -1 < x < 1

[spark kettle]

This is tan

[remote island]

dude

[remote island]

oh rgiht

i forgot

the ratio

well

how do i calculate tan(-1) -39/29?

[spark kettle]

With a calculator

,w arctan(-39/29)

[soft zealot]

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[spark kettle]

,w (7 - 3i)(5 - 2i)

[soft zealot]

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[spark kettle]

This is wrong

Therefore everything after that was also wrong

[remote island]

oh yeah i see what's the issue

i wrotesomethign that looks like both 24 and 14

it's i-1

[spark kettle]

1 - i

[remote island]

thus we have: r = 1

[remote island]

oh yefah lol

[spark kettle]

r = sqrt 2

[remote island]

wtf dude

oh wait

i'm stupid

[remote island]

i need your ehlp one last time

help this charity case

[spark kettle]

Ask

[remote island]

i got sqrt(2) * (cos sqrt(2)/2 - sin sqrt(2)/2)

how does one get to here from there

i think i made a mistake

but like

a/|z| = 1/sqrt(1^2 +(-1)^2) = 1/sqrt(2) = sqrt(2)/2

b/|z| = -1/sqrt(1^2 +(-1)^2) = -1/sqrt(2) = -sqrt(2)/2

oh i see what i did

but that only fixes sine

why is cos negative

it's 1 - i after all

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[real marsh]

d)

quick question when im finding the derivative of this function should i not touch anything outside of the bracket until everything is simplified or do i need to get rid of the exponent of 3 asap

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[fathom walrus]

@real marsh

did u get ur answer or r u still working

id do: ln y = 3 ln(sin^2) - 3ln(1+cos^2)

then

ln y = 6 ln(sinx) - 3ln(1+cos^2)

[real marsh]

yes i got my answer

thank u

=close

.close

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[formal wren]

urgh i need help

[formal wren]

i need help with fining p(w) and then the total for the part under it

[low cargo]

probabilities are normally a number between 0 and 1, have you tried just changing it to 0.76 instead of 76

also, reread the question carefully, 78% of people purchase the extended warranty for the washer, and 76% purchase it for the dryer

[formal wren]

OH i see yea i was using the wrong value

and then to find the second one for the total here what do i do

1,000 - 0.30 times 1,000 again? or just 1,000- 300?

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[somber pollen]

<@&286206848099549185>

.close

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[somber pollen]

.reopen

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✅

[somber pollen]

actually nm i want to go over this

lmao i got it no worries

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[grizzled token]

If there’s any chance can someone give me similar problems to review for my exam

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[tranquil pine]

Hi

[tranquil pine]

How do I do this #2

[summer shoal]

write each number under the root as a product of prime numbers and see which ones come squared

example: 12 = 3x4 = 3*2^2

[soft zealot]

dqvidutzul

[summer shoal]

do the same for all of them

[narrow geyser]

no one is helping me and i have been waiting for so long

can you help

[vagrant vector]

Basically prime factorization for all of them, and those with squares u can just pull put if the square root

[final saddle]

@tranquil pine Has your question been resolved?

[tranquil pine]

Okay thank you

How do I do this

5

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[tranquil pine]

Hello how do I do explain and simplify radicals

[tranquil pine]

This

[silver roost]

i did the first one for you

the rest are the same

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[weary sluice]

getting the wrong answer for uf(p)

answer sheet says 15/16

but im getting 39/32 which is the S*(P)

<@&286206848099549185>

[hallow cipher]

could you show the original problem? @weary sluice

[weary sluice]

here ya go

@hallow cipher

[hallow cipher]

oh sorry I don't know how to solve it

but showing the original problem is always just a good rule of thumb

[weary sluice]

.close

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[uncut charm]

can you walk me through the process of solving this

[warm ether]

you may want to write the line equation as y=mx+c first

[uncut charm]

is my m the slope?

[warm ether]

yeah

[uncut charm]

it would be -3=-2/3(3) + c

and solve for c? on the first one?

[warm ether]

sure

[uncut charm]

i get -1 for c

is that correct?

[warm ether]

seems fine

[uncut charm]

ok so my equation for x is x=-2/3(s)-1?

[warm ether]

that would be y

[uncut charm]

oh that is my y equation

how do i solve for x

[warm ether]

just say x=s

is the simplest way

[uncut charm]

oh why is x=s

[warm ether]

you had y=-2/3x-1

you then replaced x with s

so x=s

[uncut charm]

oh thank u!

u always help me have a good day

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[tidal wharf]

I already did part a got the equation x(50-2x)(30-2x) what do I do for part b

[ivory sandal]

condense it and solve

[tidal wharf]

It says I have to use a table so I do make an interval chart?

[night onyx]

How do I keep going

What’s the next step

Finding x and y intercept is the question

[final saddle]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

@tidal wharf Has your question been resolved?

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[ashen sandal]

Helloo

[ashen sandal]

Could I ask for a guide 😭

[manic herald]

!da2a

[final saddle]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[ashen sandal]

Okay so it wasn't properly taught to us

The teacher was like just answer this bla blah bla

😭

[serene cloud]

I can help you dm me

[ashen sandal]

Okay! Thank you

[manic herald]

sus

[ashen sandal]

Can anyone else volunteer TT

Helloi

SUMMM1 PLS HELP ME TT

[north eagle]

On number 1, ACB is referring to the larger triangle and the hypotenuse in a right triangle is opposite of the right angle and is the longest side.

Sometimes it can help to draw the shape out on the side to make it less cluttered.

[ashen sandal]

Which is

CAD?

[north eagle]

CAD is the one on the left of the inside

[ashen sandal]

CDB

[ashen sandal]

OKAY

[ashen sandal]

CAN I DM YOU

[north eagle]

Sure

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[sick pulsar]

im not sure how to take the integral with two diff boundaries

because i need to put a boundary on the y axis at y=1 and i also need to put a boundary on the x axis at x=e but I can only use one set of variables in the integral

rlly not sure how to solve it :/

[silver maple]

You can always break up the integral

[royal gust]

You're looking to find those two separate areas

Hopefully you generally know how to get the area under a curve

[sick pulsar]

yeah yeah, wait lemme try to write the equation now

[royal gust]

The person who suggested solving this in DM, they didn't know how to solve?

[sick pulsar]

no, they started asking for my name and age…

[royal gust]

Gotcha. I'll bring that to some people's attention.

[sick pulsar]

thankss

ok, i relabeled it, do u know if i did it right?

.close

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[silk ibex]

hey

[silk ibex]

can we add negation before sets

just to proove something

[trail mango]

wdym

[silk ibex]

like if there's a qus that says that proove x is a subset of (a union b )complimentus equall to x subset of (a)comliement intersect b compliment

so can I just convert them into simple proof statement and put negation before them

yk

just to proove them

[trail mango]

not sure what you're saying, you might have to just try it/start it and ask if what you did was ok

[silk ibex]

ahh
hey

you study discrete mathematics right?

[trail mango]

i dunno how to answer this

yes i guess?

[silk ibex]

so listen

you must be knowling about sets and proofs

right?

[trail mango]

sure

[silk ibex]

so ok

yk about de morgans rule

?

yeah yeah that old guy

[trail mango]

yes

[silk ibex]

so

please do reply here

[hallow cipher]

yo are you listening to boys on repeat?

[trail mango]

yes

[hallow cipher]

amazing

[silk ibex]

if we somehow convert the de morgans equation into proof statement and apply negation infront of it

is it allowed

[silk ibex]

and why?

[trail mango]

because i like it

[trail mango]

do you mean e.g. $$\neg (P \vee Q) \iff (\neg P)\wedge (\neg Q)$$

[soft zealot]

chmonkey #1 simp

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[limber isle]

dis ri

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@limber isle Has your question been resolved?

[limber isle]

<@&286206848099549185>

[final saddle]

@limber isle Has your question been resolved?

[limber isle]

<@&286206848099549185>

[silver roost]

Probably

Goofy ambiguous question

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[vast heart]

How do you solve this exponential equation

I just started learning this and don't understand enough to know how

If I could be walked through the properties I'm missing to understand this that would be great

[spark anchor]

do you know about logarithmic representation of exponents?

[vast heart]

I don't think so what is that?

[spark anchor]

its a way of representing exponent

[vast heart]

oh that

yeah I know I think

[spark anchor]

https://en.wikipedia.org/wiki/Logarithm

[vast heart]

Did you convert the equation into log form?

[spark anchor]

yesh

[vast heart]

the right side becomes log 8

What has to happen to the left side?

I raise the 5?

[spark anchor]

take log_{2}

[vast heart]

How is it log_2?

[spark anchor]

base 2 log

[vast heart]

log_2 3x?

[spark anchor]

uh

[vast heart]

can you take log_2 of both sides?

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[languid sky]

How to solve this limit? Can someone point in the right direction?

[floral nova]

Think about how you can treat the limit of x_n as a riemann sum

[languid sky]

Do you mean as a summation?

[languid sky]

Do you mean like this (1/n)*\sum_{j=1}^{n} (j/n)^a

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@languid sky Has your question been resolved?

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@languid sky Has your question been resolved?

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[quick fable]

dont really need any help but i got this question and people are choosing the other option than what i choose so i just wanna check

you dont have to show your work, u can just send your answers

https://cdn.discordapp.com/attachments/1175531119807049861/1215282809271353344/f2d60b99.png?ex=65fc2f50&is=65e9ba50&hm=d855c3fdcad579d9d7a562e05e27a36aa36f22251245afa080db91ee40149311&

[quick fable]

i choose A because the vertex is (7,3), meaning in 7 seconds, the height is 3

because the parabola is open up, it must mean it's a minimum

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[grand anchor]

A driver is tested by the alcohol machine, if it shows that he has more than 0.3 g/L of alcohol in his blood, it means he is drunk. A 33cL beer and 4% alcohol by volume was drunk. If this person has 6L of blood, was he drunk or not? alcohol density: 0.79g/mL

[grand anchor]

with conversion factors

[indigo willow]

close

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[grand anchor]

<@&286206848099549185>

[cerulean radish]

oh isnt that

bal

blood alcohol level stuff

[grand anchor]

the translator, sorry

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[novel lion]

slap 611 times per second with 15% faster
how many slap do i get without 15% faster?

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@novel lion Has your question been resolved?

[novel lion]

@livid pulsar

<@&286206848099549185>

[craggy plank]

Wrong one lol

[craggy plank]

Set your original slap as x

[novel lion]

okay
611 = 15%
x = 0% ?

[craggy plank]

???

Your original slap is x

x * (1+15%) = 611

[novel lion]

owh

i have no idea the formula at all

[craggy plank]

It’s not related to any formula

[novel lion]

sooo 1,15 * x = 611?

[craggy plank]

yes

[novel lion]

so how do i count it

@craggy plank

@craggy plank

<@&286206848099549185>

<@&286206848099549185>

[novel lion]

<@&286206848099549185>

<@&286206848099549185> <@&286206848099549185> <@&286206848099549185>

[final saddle]

@novel lion Has your question been resolved?

[novel lion]

<@&286206848099549185> <@&286206848099549185> <@&286206848099549185>

[final saddle]

@novel lion Has your question been resolved?

[rugged trellis]

do u still need help

u have a number of slaps, let's call x

and when x is 15% larger it becomes 611

so x(1 + 0.15) = 611

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[left bone]

please help me tell the doubling time of the red graph

[final saddle]

@left bone Has your question been resolved?

[left bone]

<@&286206848099549185>

[hidden gull]

tryna steal my helpers not cool

[left bone]

i need them too grrr

[hidden gull]

bro its simple just multiply it by 2.

[left bone]

what

what is "it"

[hidden gull]

is simple bro

[left bone]

TELL ME

remember x axis is being "time" here

[hidden gull]

Doubling Time=rln(2)​

[left bone]

how much time before the y axis number has doubled

[left bone]

i know but i cant see how its readable

from that graph

[hidden gull]

bro you need to think like the graph if you really want to sucsees

what would the graph do

[left bone]

um

go up

[hidden gull]

i actully dont know i just asked chatgpt

this is what you get for trying to steal my helpers!

[left bone]

loser

[hidden gull]

ok now thats actually just hurtful

you took it way to far bro

[left bone]

L O S E R

go away if ur not gonna help

[hidden gull]

ok i hope you learned your lession

[left bone]

i didnt

[hidden gull]

you could always read your text book

[left bone]

because you were going to help

[hidden gull]

like a good student would do

[left bone]

with anything

[left bone]

you think i went here before doing that?

please help me tell the doubling time of the red graph

<@&286206848099549185>

<@&286206848099549185>

[left bone]

God just help me

[left bone]

Okay sorry take your time

This assignment is due tomorrow tho and this the only thing i cant answer

And im ab tl head to bed

[magic sparrow]

you cannot find the doubling time based on just a graph

if the function is not given to you

[left bone]

This one in particular?

Or in general

[magic sparrow]

in general

if you do not know what the function is

[left bone]

It dont provide the function

[final tangle]

do not take revenge especially by intentionally misleading others

[magic sparrow]

the best you can do is approximate it then

[left bone]

Are you also certain that its impossible?

[final tangle]

if you know you hBe exponential growth
you can start with the exponential growth equation for doubling

[left bone]

Only info provided is the graphs

[final tangle]

yes

start with the equation for this growth model, use points from the graph to determine what's asked

[left bone]

We can use 1,3 and 0,2?

[final tangle]

yes

[final saddle]

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[cedar trout]

I got like 4 more questions and I ain’t tryna fail

😭

[rotund apex]

can you send a screenshot i cant read anything xD

[final saddle]

@cedar trout Has your question been resolved?

[cedar trout]

Idk how to screenshot

I’ll type it out

[rotund apex]

shift + windows + s

[cedar trout]

$410 is invested in an account earning 3.2% interest (APR), compounded quarterly. Write a function showing the value of the account after tt years, where the annual growth rate can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage of growth per year (APY), to the nearest hundredth of a percent.

It asks to write the function

The growth or decay and the percentage

[rotund apex]

yeah so basically if you have e.g. a annual interest you do something like this:
W(t) = P*(1+r)^t
with W being your value at point t
P being your being value so 410$
r is the interest rate
and t is the time factor

how would you change that to quarterly

[cedar trout]

No idea

I couldn’t attend most of school because of an incident

[rotund apex]

so we know that if we do it quarterly we get interest 4 times a year so we have to add that in the exponent -> n*t
but now we need to divide the interest rate by n too
so we get
W(t) = P*(1+r/n)^nt

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[torpid mauve]

HELPPPP

[polar basin]

wassup

[torpid mauve]

question 24

[polar basin]

wrong thing

1 sec

[torpid mauve]

which formula do i use

[polar basin]

,rccw

[torpid mauve]

[polar basin]

wait

can u delete the second pic rq

so i can rotate the first

,rccw

[soft zealot]

Couldn't find an attached image in the last 10 messages.

Mar 7, 2024, 11:59 PM

[polar basin]

send it again

the first pic

[polar basin]

,rccw

[polar basin]

aight

send the next one

[polar basin]

what grade are u in

[torpid mauve]

HELLPPPPP

😭

im in college...

[polar basin]

im thinking chill

[torpid mauve]

oh

ok 💀

[polar basin]

damn im in 10th

[torpid mauve]

oh

[polar basin]

i can do this tho

dw

[torpid mauve]

my gosh

im getting scooled by someone in highschool

king tbh

[polar basin]

im in 9th but supposed to be in 10th

started school a year latet

[torpid mauve]

LOL?????

[polar basin]

later

[torpid mauve]

r u like 15

😭

[polar basin]

but its fine cuz im 6' 4 at 15

[polar basin]

yup

[torpid mauve]

😭

[polar basin]

turning 16

[torpid mauve]

okay friend just pls

24

[polar basin]

so u see 22

do the same formula as u used there

[torpid mauve]

wrong

i think

[polar basin]

it is?

try it ou

out

[torpid mauve]

ya it comes out to 8143

the answer is 5153

[polar basin]

this is the correct one

?

[torpid mauve]

yes

thats the corerct answer

[polar basin]

what about this formula

[torpid mauve]

oh...

alfie

i was looking at the wrong answer #

i was look at 19 when were on question 24

but u were still wrong

ik which form to use

t

y

[polar basin]

u know?

[torpid mauve]

.close

[final saddle]

Channel closed

Closed by @torpid mauve

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[polar basin]

ahh

[torpid mauve]

YEa

[polar basin]

u were doing nr 19

[torpid mauve]

i was douing 24

looking at

19

[polar basin]

ah

lmfao

happend to me on a final

but luckily i checked everything before i turned it in

[final saddle]

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[novel lion]

Thanks king, i hope u have better life than other helpers forever

[final saddle]

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[wanton spindle]

can somene help me find out what bounds would result in f being less than or equal to 0 or greater than or equal to 0

[final saddle]

@wanton spindle Has your question been resolved?

[zenith pollen]

basically when you convert things into squares like (...)^2 + (...)^2 it's easy to compare to zero

you can complete the square on both x and y, so for x you have -x^2 + x/sqrt(2) + 0

since -(x+a)^2= -x^2 - 2xa + a^2, apparently -2xa must look like x/sqrt(2), so a=-1/2sqrt(2), and the full simplification is (x-1/2sqrt(2))^2 - 1/8

you should get something like this

[final saddle]

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[wanton spindle]

Ah ok

.reopen

[final saddle]

✅

[wanton spindle]

Wait why the -1/4

[zenith pollen]

when you complete the square of something like x^2+c*x to (x+a)^2, you're adding an extra a^2 at the end that you need to subtract off

so each x and y completion of the square has a (1/2sqrt(2))^2 you have to subtract off

[final saddle]

@wanton spindle Has your question been resolved?

[wanton spindle]

I mean less than 1/4

[zenith pollen]

the 1/8's on the left add to 1/4 on the right

I guess I just chose a < but it's going to be two domains for the integral

inside and outside the circle at (x,y)=(1/2sqrt(2),1/2sqrt(2)) with radius sqrt(1/4)

[wanton spindle]

Alr bet

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[digital crescent]

💀

nvm

wait maybe

can someone tell me the answer

my firend sent me this and told me to solve i t

even tho im not in the classes he is in

s it A

[shut gazelle]

No

[shut gazelle]

From the balance point, you can calculate the forces on each side, by multiplying the weight by the distance

[digital crescent]

oh

oh

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[junior mason]

how did he get (c-1)

[junior mason]

fromthisp

to this

[final tangle]

initial synthetic division

that identified 1 as a zero

and (c-1) bring a factor of the original

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[hidden isle]

is the steady state solution basically Yp ?

[hidden isle]

In this case Yp = Asin2t + Bcos2t solve for A and B?

[final saddle]

@hidden isle Has your question been resolved?

[hidden isle]

<@&286206848099549185>

.close

[final saddle]

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[quasi lotus]

I tried making the equations equal to eachother, making one side zero, then plugging into quadratic formula but it was marked wrong

[olive topaz]

Try to simplify it

[quasi lotus]

wdym?

[olive topaz]

Just like 2/4 = 1/2

U can divide it by 2

[quasi lotus]

OHH

thank you so much

can I ask another or should I open another channel?

[olive topaz]

Ye sure

[random swift]

What equation did you find for g(x)?

and for f(x)?

[quasi lotus]

im pretty sure f(x)=28

I thought g(x) was 3/2x^2-9x+19/2 but im not sure

[random swift]

Compare the y-intercept of your g(x) with the plotted one

[quasi lotus]

ohh yeah

2x^2-12x+14?

but that gives me -6 and -7 again when I make the other side 28

[random swift]

You're right that the y-intercept of g(x) is 14. Since we now know g(x) = x^2 + bx + 14, how can we find b?

[quasi lotus]

Im not sure

[olive topaz]

How do u know a=1 for g(x)

[olive topaz]

I also get this eqn tho

[random swift]

Good point, we don't know that

[random swift]

Yeah I'm also getting that

[quasi lotus]

when I did it it became 2x^2-12x-14 is less than zero then divided by two which gave me x^2-6x-7 is less than 0

[olive topaz]

Ye

Maybe the answer wrong?

[quasi lotus]

yeah I can email my teacher ig

I have one more if thats okay

[olive topaz]

Sure