help-36

[austere spire]

this is how the book proved the same statement previously

[dense coral]

manipulating sides independently is the same thing as starting from one side and getting the other

because I could have kept going by transforming 1 to r^0 for instance

[dense coral]

That’s okay, the manipulations were independent

they didn’t set the two sides equal and deduce a true statement

[austere spire]

i see so that's why they explicitly say left hand side this right hand side that

but cant you just treat this like a shortcut for independently manipulating the left hand side and right hand side?

like you're just putting the equality in advance

[dense coral]

that’s what you would think, but the book provides an example as to why you really don’t want to do that

in this case, it was true, but it need not always be

especially when the equalities are not between numbers, but weirder objects

then you can run into serious trouble if you start with the equality

[austere spire]

alright so then to prove equalities, i could either:

1. to start from one side of the equality, transform it to look like the other side
   or
2. to independently transform one side, then independently transform other side, then in the end show that they are equal
   is this correct

[dense coral]

yes, the two methods are actually identical, just dressed up in different clothes

[austere spire]

got it, that's all i wanted to ask

thanks

[dense coral]

no problem

[austere spire]

.close

[final saddle]

Channel closed

Closed by @austere spire

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ebon lance]

Here's how I'm currently trying to work it out:

363570: (units x 9600)+(12 x 3840)

I also can't figure this question out

I just did that now on the calculator and got 'June'

[final saddle]

@ebon lance Has your question been resolved?

[ebon lance]

<@&286206848099549185>

[final saddle]

@ebon lance Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle blaze]

-4,-5 find the magnitude and direction

[idle blaze]

I get the magnification of the square root of 41

n for direction I do tan-1(5/4) to get 51 then 270-51

For some reason it says it’s wrong

.close

[final saddle]

Channel closed

Closed by @idle blaze

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white ether]

can someone explain to me where I went wrong?

[willow granite]

y= - x^2 / 2(x-1)

@white ether

Correct?

[final saddle]

@white ether Has your question been resolved?

[white ether]

?

[willow granite]

Is my answer correct?

Then I could explain you where you went wrong

[white ether]

well, there has to be c

caluclator says this

[willow granite]

Are allowed to do this S(x-y)dx = S -x dy ?

[willow granite]

you need the e-function

[white ether]

hmm

well I just know that we are supposed to use subsitution at least for this problem

and I don't see where I went wrong

<@&286206848099549185>

[final saddle]

@white ether Has your question been resolved?

[final saddle]

@white ether Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slow blaze]

i need help understanding why this "dimension" refers to counting the non-zero elements while other dimension problems i've had seem to be related to counting the linearly independent vectors

im not understanding what dimension is i guess

same with the polynomial one, I thought it's n+1, but in this case its just 6

[dense coral]

the dimension of a finite dimensional vector space refers to the number of elements in any basis for that vector space

[dense coral]

it should be 7...?

[slow blaze]

answer key says 6

[dense coral]

huh. strange

[slow blaze]

i also dont understand c

and also, in previous problems the dimension has been related to the linear indep columns, so what's going on there

[final saddle]

@slow blaze Has your question been resolved?

[slow blaze]

<@&286206848099549185>

[naive tapir]

Earlier you must have seen matrices playing the role of things that act on column vectors

In this question however, matrices themselves are thought of as elements of a vector space

If it helps to visualize, imagine stretching that 5x5 matrix into a 25x1 column vector

So the space of 5x5 matrices has dimension 25

[final saddle]

@slow blaze Has your question been resolved?

[slow blaze]

i still dont really understand what's going on with these, so in earlier questions I would have a 3x3 matrix for example, and the number of columns with lead variables was the dimension, how is it different now for part b

[naive tapir]

"the space of all 3x3 matrices has dimension 9" are you okay with this statement, first of all?

[slow blaze]

No, i think that's where the confusion comes from

cause i mean, a 3x3 matrix is just [a,b,c],[d,e,f],[g,h,i]

let me give you another problem for comparison

i think maybe im confusing rank and dimension

heres a definition i wrote earlier that is correct

[naive tapir]

That's nine different numbers that can all vary freely

When you have a collection of 9 independent variables, you can call that a vector space of dimension 9

For this particular problem, don't think of a matrix as a linear transformation acting on vectors with a column space and all that. Just think of it as a bunch of numbers

[slow blaze]

Ok, that's where i think im messing up, thanks

.close

[final saddle]

Channel closed

Closed by @slow blaze

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wild gust]

I used the FTC to get -(x/3+6x^2)

but its incorrect and I don't know where I went wrong

[celest crane]

You need to apply the Chain Rule.

[wild gust]

but isnt the derivative of x just 1

[celest crane]

The Chain Rule needs to be applied to sqrt(x).

[wild gust]

yeah but the derivative of the inside part is just x

and the derivative of that is 1 right

or am I missing something

[celest crane]

One moment, let me write something out.

[wild gust]

okay I see

thanks

.close

[final saddle]

Channel closed

Closed by @wild gust

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique dome]

to be honest im reading this and just have no idea what it means or where to even start lol

[oblique dome]

<@&286206848099549185>

[final saddle]

@oblique dome Has your question been resolved?

[final saddle]

@oblique dome Has your question been resolved?

[final saddle]

@oblique dome Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen comet]

theres no diagram but the question explains it

i dont rly know how ur meant to do this

[dense coral]

use conservation of momentum twice

in fact, this is a special case called a perfectly inelastic collision

my only question is: are the second and third masses stationary, as my instinct tells me?

[fallen comet]

they are stationary until they get hit

[dense coral]

nice

that makes our lives easier

so let's use conservation of momentum, which i'll abbreviate to COM

do you know the COM equation?

we can do it one step at a time

[fallen comet]

is it m1v1initial = m1v1final or something

im not sure

i dont remember

[dense coral]

close

it's actually m1v1 + m2v2 = m1v1' + m2v2'

where the ' is just indicating final velocity

read it as "prime"

[fallen comet]

oh so if theres no second mass is my thing right

[dense coral]

v2 is 0 yes, but m1 and m2 stick

which means they have the same final velocity

[fallen comet]

so then is this m1v1+m2v2+m3v3=m1v1'+m2v2'+m3v3'

[dense coral]

woah, careful there

thats not going to work

because the first two masses stick together first, gain a new velocity while doing so, and then collide with the 3rd mass

as i said earlier, we need to do this in steps

its not possible to rush the calculation

there are a total of two collisions here, so we must apply COM twice

let's start with the first collision, shall we?

[fallen comet]

ohh

i gotchu

let me fin dmy pen

is this right

[dense coral]

looks good to me

okay, so this vf is going to become our new "vi" in the second collision

and the "m1" in our next collision is actually going to be m1 + m2

[dense coral]

here

you've missed this

[fallen comet]

Ohhh irght

mb

[dense coral]

because the combined two masses are colliding with the 3rd mass

not just the first mass, m1

[fallen comet]

oops

wait

is that right

[dense coral]

looks good to me, but i would highly advise against using the same variables over and over

if i had to mark this, i'd be very confused by your notation lol

its right, but it makes the life of your teacher harder

it also makes it much easier for you to make a mistake too

[fallen comet]

even if i put step 1 and 2?

[dense coral]

no the steps are good

i mean that in step 2, you should write

[fallen comet]

i thought if the grader has the solution they just need to find it

[dense coral]

(m1+m2)vi2 + 0 = vf2(m1+m2+m3)

[fallen comet]

oh i get it

[dense coral]

then vf2 = (m1+m2)vi2/(m1+m2+m3)

[fallen comet]

okk

[dense coral]

also, i highly recommend leaving everything in variable form and only plugging in numbers at the very end

it makes physics, especially high school physics, a lot easier to do

[fallen comet]

ok ill start doing that

do u know how to do this

i think its the same time

[dense coral]

if you choose to do any physics in uni, they usually dont give you any numbers to begin with

so its best to get used to it now

[fallen comet]

wdym?

[dense coral]

there are no numbers given in questions

[fallen comet]

like just variables?

[dense coral]

for instance, something like this

this is actually a problem i just solved like 3 hrs ago lol

there are no numbers here

[fallen comet]

one time we had a question like that on our test i liked that question

[dense coral]

thats good

[fallen comet]

i think i figured this out nvm its the same bc the impulse is the same the force is the same and if the momentum is the same then the time has to be the same because the change in momentum is force times time

she didnt put an answer tho

[fallen comet]

this is also kind of like that right

[dense coral]

should be the same yeah

[dense coral]

yes, do you have an answer for this?

[fallen comet]

i think its D

because ft = mv

[dense coral]

wait lemme actually check my thought process lol

[fallen comet]

2mv=2ft

[dense coral]

you'd be right

i'd be too

but i wasnt confident enough to just state my answer without checking lol

is there anything else?

[fallen comet]

is the 60 degrees in this question relevant?

is there no difference between impulse and momentum if nothing is changing?

cuz then i think its C

[dense coral]

the 60 degrees is indeed useless

it only matters if you wish to state the direction of the resulting momentum vector

[fallen comet]

they fr trying to trick me

[dense coral]

if your only concern is the magnitude, then no

the word "magnitude" does show up in this question

so that's your clue

now, if they wanted you to find the momentum in the x/y direction, then the 60 degrees would be relevant

60% of a physics problem is understanding wth is going on lmao

[fallen comet]

see im worried on my test that shes gonna give us some problem where i have to remember something from another unit

[dense coral]

physics is only seperated from math by that one point

[fallen comet]

invidivudally usually im ok but she always brings stuff back

from like kinematics and stuff

and then i lose the question

[dense coral]

this is very common, and very important to know too

imo, one should not forget the older, more foundational units

especially not kinematics/dynamics

[fallen comet]

and conservation of energy

[dense coral]

that too

[fallen comet]

i dont really forget it i just dont remember how to use it

[dense coral]

i know it can be difficult to remember everything, but the truth is that there arent many interesting physics problems that dont integrate other units, especially in hs

the most fun i've had in physics in hs was from topics like charge deflection in a parallel plate capacitor

because it called back kinematics and dynamics along with using concepts in E&M

[fallen comet]

we didnt learn e and m yet

[dense coral]

yeah ik

[dense coral]

thats normal, but unfortunately theres not much to be done about it

you simply have to be comfortable with the foundations of the older units

you may not need to remember all of the specific details, but the basic principles cant be lost from unit to unit

do you have any other concerns?

[fallen comet]

yes

one second

thank you for helping me btw

[dense coral]

no worries

[fallen comet]

i understand this problem but do u know how come

the velocity of the center of mass at the start is the same as it is at the end

and if its always that way

i didnt write that my teacher did

[dense coral]

ah, the velocity of the centre of mass isnt going to change unless theres a net external force on the system

does that make sense?

or would you like a further explaination

[fallen comet]

i understand

[dense coral]

okay then

i was about to ask you to consider the whole system as one big box lol

[fallen comet]

theres only one last thing im worried about

everything else is good

theres these kind of questions

and its very confusing to me

[dense coral]

okay, whats the issue?

[fallen comet]

thy dont stick if its perfectly elastic right

[dense coral]

indeed

perfectly elastic means both momentum and kinetic energy is conserved

[fallen comet]

i just dont understand cuz she wrote all of this stuff

and i dont know if im supposed to make a system or something

[dense coral]

looks like a derivation of the fact that the sum of velocities before the collision equal the sum of velocities after the collision

[fallen comet]

and then when im lookig at the work it just seems very confusing

i dont understand at all how she is doing it

[dense coral]

oh actually its a bit different

for elastic collisions, there are formulas that are equivalent to doing all of the hard work actually

[fallen comet]

i see she used the m1v1 +m2v2 = m1v1' +m2v2'

[dense coral]

yikes

[fallen comet]

oh wait

she did do a system

[dense coral]

these are the shortcut formulas to the whole system of equations stuff

elastic collisions are annoying in the sense that you either have to solve a system, or else remember these formulas

i prefer the formulas

but if you must, you may solve the system

[fallen comet]

i think it will bee asier to remmeber to do the system

[dense coral]

fair enough

i just really hated doing it lol

my teacher did too

[fallen comet]

ok i understand it now

i feel like the questions on the test are not gona be tlike these though

every time on the test the questions are different

[dense coral]

in my experience, the test questions for hs physics usually seem harder/different, but if you really understand the basic ideas of the unit and all of the ones previous, no problem is unapproachable

are there any other concerns you have?

[fallen comet]

not realy im gonna just keep practicing

i should probably sleep but if i sleep im gonna not practiced enough

i have like a problem focusing and then i do everything in the last minute

[dense coral]

i would not recommend staying up too late

its easy to underestimate how poorly a tired brain performs

[fallen comet]

and lots of hard life stuff happened recently so its hard to sleep too

[dense coral]

ah, i see

i'm sorry about that

[fallen comet]

it makes the focusing thing worse

[dense coral]

well, if you want to go practice, and have nothing else to ask

you can close the channel if you'd like

[fallen comet]

thanks for helping 🙂

[dense coral]

and focus on prepping for your test

[fallen comet]

im not so good at math and physics stuff

[dense coral]

best of luck! i'm sure you'll do well

[fallen comet]

im a right brained person

[dense coral]

honestly, i dont think i am either, but one's willingness to learn is more powerful than we imagine

[fallen comet]

i actually do so unbelievably well in english and history type subjects without even trying but even if i spend hours to study on math and physics and chemistry i still dont do that well

[dense coral]

as long as you are willing to learn, and take intiative in your learning, you'll see better results

i firmly believe that

it's alright if you're not "naturally good" at a subject

all that's important is that you try your best

because that's all you can ask from yourself

it's unfair to yourself to ask of more than what you're capable of

keep that in mind, and dont be too hard on yourself

[fallen comet]

thank you very much 🙂

i appreciate u

[dense coral]

just doing my best over here too haha

[fallen comet]

have a good night

[dense coral]

you too, i wish you the best of luck on your test

[fallen comet]

.close

[final saddle]

Channel closed

Closed by @fallen comet

Use .reopen if this was a mistake.

[fallen comet]

.reopen

[final saddle]

✅

[fallen comet]

.close

[final saddle]

Channel closed

Closed by @fallen comet

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant yarrow]

can someone explain why i'm getting a different answer

why is the surd x in the numerator not meant to to 1 over surd x

<@&286206848099549185>

[buoyant yarrow]

working over here

[final saddle]

@buoyant yarrow Has your question been resolved?

[soft stag]

im pretty sure you did it right

its just written in a different form

[buoyant yarrow]

ohk tysm for clearing it up for me

[soft stag]

im not too sure

but it happens a lot

for me

esp with online calculators

[buoyant yarrow]

alr

.close

[final saddle]

Channel closed

Closed by @buoyant yarrow

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone wagon]

no clue where to start

[silver maple]

We don't help with exam questions

[stone wagon]

it's a past paper

i'm just practising

[ocean lintel]

Question 2 is smart

[silver maple]

I am thinking of markov chain

[ocean lintel]

Don't play dodgeball with 3 players lmao

[stone wagon]

ikr

[desert mantle]

I would just start to bruteforce it. just go through all the options. there shouldn't be that many

[stone wagon]

good point. let me try

[ocean lintel]

The problem is if Paul goes out first, the length of the game is unbounded
So your probability space is garbage

[desert mantle]

but then you notice a pattern probably

[silver maple]

markov chains

[desert mantle]

well if they know what those are and how to use them, sure

[stone wagon]

i kinda know how to use them but we didn't study them and i feel like it should be much simpler than that

[desert mantle]

but just from the way this question is worded I would lean to no

[ocean lintel]

Make a tree
By turn 3 only 1 branch goes on
It's most likely geometric and you can find each player's odds

[stone wagon]

"each player always aims at the most skillful player still in the game"

so if we have just Mike and Bill and Bill is throwing, does he throw at Mike or himself lmao

[desert mantle]

I wanted to point out the same bad wording

[ocean lintel]

The most skilled besides him
Let's assume reasonable common sense from the players

[stone wagon]

good point

progress so far

there are 2 ways to get to the same state (Mike; Bill) with Mike's turn

idk how to account for that

[stone wagon]

yeah precisely

[desert mantle]

well generally these types of trees shouldnt meet again

just compute the probabilities for each way separately

of course you can reuse parts of the calculation for that

[stone wagon]

wait wdym

is it wrong

[desert mantle]

no I just mean that I wouldnt draw it as meeting again

[stone wagon]

ah okay

[desert mantle]

you could instead draw it as a whole map of all the possible states and how they relate to each other. but then you are basically in markov chain territory

[stone wagon]

i see

okay so

OKAY

one by one

i'll start with Bill

since all of these routes are independent, Bill's probability of winning is P(leftmost branch) + 2P(GP) where GP denotes geometric probability (case between Mike and Bill)

[desert mantle]

it would help to draw a separate tree just for GP

[stone wagon]

i will

[stone wagon]

$P(\text{leftmost branch}) = 0.5\cdot 0.7 = 0.35$

[desert mantle]

0.35

[stone wagon]

oh

conditional probability?

,calc 0.5 * 0.7

[soft zealot]

Result:

0.35

[stone wagon]

oh nvm

[soft zealot]

artemetra

[stone wagon]

oooohhh h hh h h hh

[stone wagon]

okay i figured the values out

Mike winning in GP case is $0.5+0.5\cdot 0.3 + 0.5\cdot0.3^2 + \cdots = \frac{0.5}{1-0.3}$

wait no

huh

ohhh

Mike winning in GP case is $0.5+0.5\cdot (0.5\cdot 0.3) + 0.5\cdot(0.5\cdot 0.3)^2 + \cdots = \frac{0.5}{1-(0.5\cdot 0.3)}$

[soft zealot]

artemetra

[desert mantle]

you should be able to set up a simple equation for the probability

you dont need a series

[stone wagon]

why not

[desert mantle]

if you call it p, then you should have something like p=prob(other branches)+something*p

[stone wagon]

oh yeah

[stone wagon]

well that's what i get on the RHS anyways

so it's fine

[desert mantle]

yes just interpreted differently

and imo easier

[stone wagon]

$P(\text{mike}) = 0.35 + (0.5\cdot 0.3 + 0.5\cdot 0.7)\frac{0.5}{1-(0.3\cdot 0.5)}$

[soft zealot]

artemetra

[stone wagon]

$P(paul) = 0.5\cdot 0.3\cdot 0.5$

[soft zealot]

artemetra

[stone wagon]

so $P(\text{bill}) = 1-P(\text{paul})-P(\text{mike})$

[soft zealot]

artemetra

[stone wagon]

fuck my laptop is so unnecessary slow rn

okay that should be it

[final saddle]

@stone wagon Has your question been resolved?

[stone wagon]

.close

[final saddle]

Channel closed

Closed by @stone wagon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe cove]

im using the quotient rule and idk whats going wrong

i calculated

,tex $ \frac{dy}{dx} = \frac{x}{(1+x)^2}

[soft zealot]

suds
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[severe cove]

but -y^2 is

[tardy vortex]

what is the quotient rule

recall it

derivative of top function or bottom function we find first in the numerator?

[severe cove]

f'(x)g(x) - f(x)g'(x) / (g(x))^2

[tardy vortex]

right

so what is f'(x)

[severe cove]

0

sorry this is for f(x) / g(x)

[tardy vortex]

right

so youd get 0- something

so you get a negative right there

where is your negative

[severe cove]

bro i am so so sorry

[tardy vortex]

lmao

[severe cove]

you probably think im so dumb

i am just so tired omg

[tardy vortex]

no

i am

in same

boat

im dying

!!

[severe cove]

i did 0(1 + x) = 1 + x

thank you so much again

[tardy vortex]

i did 3x3=6

it happens

[severe cove]

but 0!

[tardy vortex]

it happens

this is math

[severe cove]

i love math but i do too much of it in a day

i have 2 maths classes and then i go home and do like 2 hrs of work so its like 4hrs of maths

and i have physics and economics which is mathy too

[tardy vortex]

what are you doing rn?

[severe cove]

yr 12

[tardy vortex]

SAME

[severe cove]

ay!

where r u from>

[tardy vortex]

i have phy chem math eng and cs

[tardy vortex]

india

[severe cove]

english is compulsory here

[tardy vortex]

https://tenor.com/view/disintegrating-aughhh-gif-24532719

[severe cove]

im australian

[tardy vortex]

yes here also

but we have

competitive exams

[severe cove]

u wanna do engineering?

[tardy vortex]

unfortunately yes

[severe cove]

same technically (atar)

SAME

can i add you?

[tardy vortex]

life wouldve been so much easier if i just chose anything humanities related

yes ofc

[severe cove]

my nickname in yr 8 used to be rattus mctattus so similar names

[tardy vortex]

i couldve chilled w gender studies degree or sum

agh

[severe cove]

SAME my mums a lawyer and im pretty good at that sort of stuff

[tardy vortex]

I WANTED TO BE A LAWYER

[severe cove]

MY MUM WANTS ME TO BE A LAWYER

[tardy vortex]

my dad said i wouldnt make it

so

i gave up lolz

[severe cove]

naw

u couldve done it!

maths is harder imo

[tardy vortex]

hes right tho

i hate memorising stuff

plus idt i could defend obviously guilty ppl

[severe cove]

yeah but my mum does commercial law for like businesses

[tardy vortex]

ok idt we can use this

server

for this

[severe cove]

no

add me back, i'll close this

[tardy vortex]

what if like a mafia boss

targets u

cause u

ruined his business

idk

[severe cove]

more like rio tinto tho

[tardy vortex]

he blasts ur family

[severe cove]

not many mafia bosses here lmao

.close

[final saddle]

Channel closed

Closed by @severe cove

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal comet]

We haven’t learnt this and I’m stuck

[gentle barn]

Are you aware of a * a = a^2, and (a^2)/a = a?

[royal comet]

Nope

[gentle barn]

Then that's something to learn.

[royal comet]

Okay

[gentle barn]

$$a \cdot a = a^2$$ $$\frac{a^2}{a} = a$$

[soft zealot]

Good

[royal comet]

I can see the reasoning

[gentle barn]

Alright, start with this then $\frac{16 \cdot a^7 \cdot b}{(2 \cdot a^2 \cdot b)^5}$

[soft zealot]

Good

[gentle barn]

You expand the denominator, divide the common ones out, and continue with $(-2a^3b^2)^2$

[soft zealot]

Good

[royal comet]

Okay

.close

[final saddle]

Channel closed

Closed by @royal comet

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pine]

whats happening between first and second step

[hardy yew]

they're taking stuff common

[tranquil pine]

but they moved the 8

why

[hardy yew]

because they took the (2t+1)^3*(t^3+1) common and not 8 multiplied by that thing

[tranquil pine]

what?

and not 8 multiplied by that thing

okay they took the common then what

can u please be more specific

[hardy yew]

okay if you have x^3 + 5x^2 and you take x^2 common, what do you get?

[tranquil pine]

x^2 (x+5)

[hardy yew]

correct

so now let 2t+1 be x and t^3+1 be y

so what is your equation? 8x^3 * y^2 + 6t^2 * y * x^4

[tranquil pine]

x^3 y (8y+6t^2x)

is it

[hardy yew]

now if you take x^3 * y common, what is left?

[hardy yew]

right

so substitute x and y right back in there

[tranquil pine]

?

oh

[hardy yew]

so now let 2t+1 be x and t^3+1 be y

[tranquil pine]

yeh

alright thanks

[hardy yew]

no worries

run .close when done

[tranquil pine]

.close

[final saddle]

Channel closed

Closed by @rancid flint

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby lake]

is it correct to first integrate on z

and then using polar cordinates for x and y

bu integration on z i get 3sqrt(x^2 +y^2) -1

then using polar coordinates i get double integral of (3r^2 -r)

theta going from 0 to 2pi and r from 2 to 4

but i don't get any of those alternatives

[scarlet sequoia]

can you show your work?

With your technique I get to one of the results

[ruby lake]

ok

so i get 2pi r^3(evaluated from 2 to 4)- 2pir^2

[ruby lake]

.

you got a 100?

yeah that should be correct

thank you

[scarlet sequoia]

yes

[ruby lake]

thank you

i forgot to divide by 2

.close

[final saddle]

Channel closed

Closed by @ruby lake

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow hearth]

alright im in this calculus class currently stuck on a limits problem.
original problem is
lim x -> -1 x^2+3x+2 / x^2+4x+3

im on the second step where i factored x out from the first part of each side of the fraction
x(x+2)+x+2 / x(x+3)+x+3

i really dont know where to go from here, photomath suggests i factor out x+2 from the expression, but i dont fully understand how that works and turns into (x+2)(x+1) / x(x+3)+x+3

[hollow hearth]

i can take a picture if needed if my typing cant be understood

[indigo dragon]

you have a(x+2)+x+2 = a(x+2)+1(x+2) = (a+1)(x+2)

here a is x

[compact breach]

(x+1) will be a factor

[hollow hearth]

how is (x+1) a factor though

how do you get that from x(x+2)+x+2

[indigo dragon]

do you get this?

[hollow hearth]

not really

[indigo dragon]

lets say you have ab+b, you can factor b and get (a+1)b

[hollow hearth]

ah ok so i would get uhhh

so to get (x+2)(x+1) i would

to get from x(x+2)+x+2

i factor 1 out of x+2? i dont understand how to get to (x+1) at the end

[indigo dragon]

yes

you can write it like x(x+2)+(x+2)

[hollow hearth]

x(x+2)+x+2 / x(x+3)+x+3 thats where i am right now

right

so

id make it

x(x+2)(x+2) / x(x+3)(x+3)

?

[compact breach]

You could have just written a as x

,w x^2 + 3x + 2

[indigo dragon]

yes

[compact breach]

(x+1)(x+2)

,w x^2 + 4x + 3

[hollow hearth]

what is going on 😭

[compact breach]

(x+1)(x+2)/(x+1)(x+3)

[hollow hearth]

yeah but im confused as to how we get to

x+1

in both of them

[indigo dragon]

@compact breach plz delete the Wolfram alpha it's getting messy

[hollow hearth]

x(x+2)+x+2 / x(x+3)+x+3 is where i am at

i am confused as to how we get to x+1 from x+2 and x+3

without making it like x(1+3/x)

[indigo dragon]

replace b by x+2 here

and a by x

[hollow hearth]

x(x+2)+x+2

ok

so

then i would do

(x+1)x+2

[indigo dragon]

with parentheses around x+2

[hollow hearth]

on god i still dont understand it im not trying to be difficult

[indigo dragon]

tbh I might be a bad explainer but I have no idea how to explain it more

[hollow hearth]

so what am i trying to factor out of x+2

[fallen comet]

The one is there because if we have (x+2) then behind it there's a 1 no matter what because anything times 1 = itself

[hollow hearth]

okay i get that

but my assumption is to factor out x to make it (1+2/x)

thats incorrect though right

x(1+2/x)

[fallen comet]

Send the original thing again please

[fallen comet]

I will probably need to leave in a minute my bus stop is soon but maybe someone else can help

[hollow hearth]

thats the original problem

this is the step i am on

i am wondering how to get to this point (i photomathed it)

obviously you cancel the xs on top and bottom at the end but how do i get to that pointis what i'm wondering

[fallen comet]

Do you know how to get here

[hollow hearth]

somewhat yes

you make 3x 2x+x

then factor x^2+2x+x+2

x(x+2) +x+2

thats where i am

[fallen comet]

Ok with x(x+2)+(x+2) you can treat it like factoring by grouping

[hollow hearth]

i follow you

[fallen comet]

Then it's equal to (x+1)(x+2) it's really just one step

[hollow hearth]

alright i lost you

x(x+2) + (x+2) gets to (x+2)(x+1) how

[fallen comet]

Remember the one behind x+2

[hollow hearth]

yes

x(x+2) + 1(x+2)

how do ya get from 1(x+2) to (x+1)

[fallen comet]

Yeah so you can combine the x+2s if rhey are multiplies by the x and 1 in front of each of the other two parts

You can prove it yourself by expanding the factors

[hollow hearth]

im so real i dont understand

can you put it in like

step 1 step 2

1: x(x+2)+(x+2)
2: combine ___

[fallen comet]

Ok step 2 identify the factor you see twice, that will be one of the factors you end with

Then step 3 the numbers in front of each of the repeated factors are put together

If you can't understand why expand each step yourself and you'll get what you started with

[hollow hearth]

alright step 2 identify what i see twice

i see x+2 twice

so i just get x(x+2)

and since i have an x in front of that and a 1 in front of the other one i get

(x+2)(x+1)

?

[fallen comet]

Yes

[fallen comet]

This never existed though

This is just so you can understandn

[hollow hearth]

but it does exist im so confused

this is the og problem

factor out x from everything

x(x+2) +x+2
x(x+3) +x+3

[fallen comet]

Yeah you need both x+2 until you finish what I told you

Its one step

That's why putting it in steps is weird

Here is another example

Maybe the colors will help

[hollow hearth]

but why do you cancel the (x-2)s i thought you could only cancel from the numerator and the denominator

what i understand is that if i had like 12(x+2)(x+2) i could just cancel the x+2's?

[fallen comet]

You aren't cancelling x^2 and 5 are each being separately multiplies by x-2 this is just being condensed

In the example I showed u

[fallen comet]

They are being added

Not multiplied

Neither of the x+2 are ever being multiplied by each other

[hollow hearth]

OK

i understand a little better

so cancelling the uhhh

in my situation

[fallen comet]

Nothing is cancelled you are just rewriting

[hollow hearth]

x(x+2)+(x+2) cancels the +

rewrites it into (x+2)(x+1)

[fallen comet]

The + is the 1

[hollow hearth]

yes

[fallen comet]

Yes

[hollow hearth]

thank you

im still extremely fuzzy on this but

i barely understand it

but i guess i get it?

are there any other examples you can show me with stuff like that

is there a name for that type of thing

[fallen comet]

I have to go

[hollow hearth]

alright, thank you

.close

[final saddle]

Channel closed

Closed by @hollow hearth

Use .reopen if this was a mistake.

[fallen comet]

Would try more

[hollow hearth]

thank you for your help anyways

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pine]

hi there i was watching this video "can force change the velocity of a particle moving perpendicular to it". it mostly dealt with why centripetal force is able to change the direction of tangential velocity of a particle in circular motion whereas if we have projectile motion, the y-component of force cannot affect the velocity in x.

[tranquil pine]

and i found this comment underneath

Actually the key thing is that when we work with Cartesian coordinates, the motion in one axis is independent of the motion in other axis and that is why in the case of projectile the motion in the x-axis is independent of the motion in the y-axis, so the z-axis velocity remains unaffected. But in the case of circular motion, WE ARE NOT USING CARTESIAN COORDINATES, instead we are using POLAR COORDINATES. In this case also if we use cartesian coordinates, there will be no issue and the motion of different axes will be independent, but it is difficult to use cartesian coordinates in circular motion.

can someone help me understand whats going on

i dont mind linking the video but i think it's a mix between english and hindi so might not be that effective

[foggy badger]

there is an acceleration vector going inward due to centripetal motion

you are mixing up linear velocity and angular velocity

if you find a vector from a point on the circle to the center youll find it is in the same direction as the acceleration vector

just a quick way to check

[tranquil pine]

oh i am sorry i meant direction of tangential velocity

[final saddle]

@tranquil pine Has your question been resolved?

[final saddle]

@tranquil pine Has your question been resolved?

[final saddle]

@tranquil pine Has your question been resolved?

[cold gorge]

@tranquil pine

What are you asking, again?

$\vec{a} = \dv{|\vec{v}|}{t}\hat{v} + \omega \cross \vec{v}$

[soft zealot]

! What the hell am I doing here?

[tranquil pine]

tbh at this point im so confused that idek myself

[cold gorge]

The first one is parallel to velocity, the other is perpendicular to velocity. This is always true.

[tranquil pine]

why the omega cross v?

[cold gorge]

Well

[tranquil pine]

oh yes

[cold gorge]

...

Yes?

(Omega is also a vector)

Forgot to add that.

[tranquil pine]

yes i understand

i understand what you have done here yes

but what difference does it make if we use polar coordinates or not

[cold gorge]

It doesn't really, it seems like you're paraphrasing and missed their point.

Or they're just not sure what they're saying either.

[tranquil pine]

idk it sounded pretty confident though lol

[cold gorge]

In something like a uniform circular motion the first component is zero, so it's always perpendicular to the velocity.
In something like a projectile, both of these accelerations are individually variable but their sum is the same as gravitational potential.

I guess that's about I can tell you with given context.

[tranquil pine]

understand

thank you very much

i'll be off for now

you have a good day

.close

[final saddle]

Channel closed

Closed by @raven blade

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout plaza]

hi is there a way to solve for the area enclosed by this curve without double integrals?

[vital crag]

Double integrals are just integrals of integrals

So solve the first integral of the double integral, then you just have a single integral

[devout plaza]

how do i set that up for this problem? we havent learned double integrals yet

what if i define a piecewise function

f + g (orange + blue) from 0 - 1

integral of that from 0 to 1

then subtract the integral of the green

<@&286206848099549185>

[final saddle]

@devout plaza Has your question been resolved?

[devout plaza]

<@&286206848099549185>

[final saddle]

@devout plaza Has your question been resolved?

[devout plaza]

<@&286206848099549185>

[devout plaza]

<@&286206848099549185>

[devout plaza]

<@&286206848099549185>

[vital crag]

Just find the top function and subtract the bottom function

,tex .quadratic formula

[soft zealot]

riemann

[vital crag]

And integrate the difference

[devout plaza]

ok but how do i find the top and bottom functions

just randomly adjust x^2 or some trig function till i get it?

time to wait 2 more hours :/

[vital crag]

Use this

Solve for y in terms of x

[vital crag]

Nothing about this problem is random

[devout plaza]

you cannot isolate y with y^2 -2xy + x^3 = 0

[vital crag]

You can't

I can

[vital crag]

.

[devout plaza]

yeah you can use quadratic formula on a cubic function

whatever

.close

[final saddle]

Channel closed

Closed by @devout plaza

Use .reopen if this was a mistake.

[vital crag]

Not on x

Read above

[vital crag]

.

[vital crag]

.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom sonnet]

how would i use the direct comparison test to show that the series is divergent

[final saddle]

Please don't occupy multiple help channels.

[vital crag]

Close one of your channels

[fathom sonnet]

done

didnt realize i was using 2

[vital crag]

Compare the largest powers of each numerator and denominator

As n gets large, only the highest powers matter

[fathom sonnet]

i see so compare with 1/n

how would i know which series is bigger now

[vital crag]

This series is divergent

So how do you show something is also divergent

[fathom sonnet]

comparing?

if 1/n is bigger than our original series i know that An and Bn are both divergent

but idk 1/n is bigger

[vital crag]

Showing 1/n is bigger than a series doesn't prove anything about the series

[final saddle]

@fathom sonnet Has your question been resolved?

[fathom sonnet]

i thought that if Bn diverges An also diverges

[vital crag]

What do you think An and Bn are

[fathom sonnet]

An is the picture i sent, Bn is 1/n?

[vital crag]

Yes just show An >= 1/n

[fathom sonnet]

but i thought Bn is supposed to be the bigger series

sorry im confused about this whole thing

[vital crag]

No

[vital crag]

Read the comparison test again

[fathom sonnet]

it says An <= Bn

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[outer dove]

Could someone help me explain how they got these answers? Or what I would do to get to these answers?

[outer dove]

<@&286206848099549185>

Where are they getting these red answers from?

[final saddle]

@outer dove Has your question been resolved?

[final saddle]

@outer dove Has your question been resolved?

[outer dove]

no

[final saddle]

@outer dove Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final saddle]

@strong flower Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ebon peak]

Help

[distant ridge]

ok

[ebon peak]

Im confuse about this one

[fringe pecan]

revise the properties of parallelogram

[final saddle]

@ebon peak Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hoary oxide]

So lokey I don't understand how to do the second part of the problem

[hoary oxide]

We know that, because we cannot divide by zero, that 7t^2-3 != 0

getting us that T0 can't be sqrt(3/7) plus or minus

but I don't get how the found out the y0 part?? Y = 1/6 doesn't break the derivative, just makes it zero?? Why is that bad haha

[vital crag]

Solve for y'=0

[hoary oxide]

why is y'0 mean that existence and uniqueness is not guarnteed tho?

[vital crag]

No idea what you just said

[hoary oxide]

so the question is asking

[vital crag]

?

[hoary oxide]

"Existence and uniqueness is guaranteed at all points except those with..."

and you said solve for y'=0

but why does y'=0 mean that existence / uniqueness is not guaranteed?

[hoary oxide]

Basically I want the intuitive understanding why that is the case, instead of just the formula

[vital crag]

You can only find the general solution when y' is not 0 for all t

[hoary oxide]

ohhh I got it

wait so if y' = y * t, would t = 0 and y = 0 be the answer?

[vital crag]

?

[hoary oxide]

Did I do something confusing?

[vital crag]

No

[vital crag]

Answer to what question

If you make up questions and answers, you have to tell me the question if you want me to check the answer

[hoary oxide]

"Existence and uniqueness is guaranteed at all points except those with"

[hoary oxide]

sorry haha my brain it a little bit messed up right now

[vital crag]

Yes

[hoary oxide]

so if we had the equation:
y' = y * t
then the answer to "Existence and uniqueness is guaranteed at all points except those with"" would be y = 0 & t = 0

[hoary oxide]

got it!

[hoary oxide]

so to generalize this, "existence & uniqueness" thing holds whenever y' = 0 or Undefined

[vital crag]

?

[hoary oxide]

just curious, would existence hold if y' was equal to an irrational number?

[hoary oxide]

"Existence and uniqueness is guaranteed at all points except those with"

wait let me say my question again in one message

[vital crag]

...

Stop pinging me

[hoary oxide]

Oh sorry!

"theorem:
to figure out the points where "Existence and uniqueness is guaranteed at all points except those with..."
Then we find all points where y' is equal to 0 or Undefined

Would this be correct?

I just wanna generalize your statement to make sure I got all cases covered haha

[final saddle]

@hoary oxide Has your question been resolved?

Channel closed

Closed by @hoary oxide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pine]

solving for the slope of y=x^3-3x^2+4 at P(2,0) and figuring out the tangent line equation, doesn't -(8-12+4) cancel out to zero, leaving 8 as the sole constant? If so, do we remove the 8 from the numerator somehow? Only turned to gpt after trying to solve multiple times and getting 4/h (undefined slope) when the slope is really 0.

[unreal anvil]

this looks so weird, is it from gpt?

we would recommend not to use gpt for maths

[tranquil pine]

I almost never use it bc of stuff like this lol

I'm not sure what I'm doing wrong on my end though using the difference quotient

[unreal anvil]

do you mind showing what you have tried?

[tranquil pine]

sure

sorry give me a second to rewrite I scribbled it out in pen

😰

[unreal anvil]

no worries, if you dont mind you can show your draft too, but since you are already writing, i bet we dont need the draft now 😛

you can ping me after it's sent 🙂

[tranquil pine]

@unreal anvil

bottom part is what I basically rewrote apologies for the mess

[unreal anvil]

reading

i see

did you mistakenly wrote the +4(x+h) instead of just +4

[tranquil pine]

oh my god I think that's it

hell yeahhh solved it

ty bro

[unreal anvil]

cheers!

remember to plug the x=2 back in!

[final saddle]

@tranquil pine Has your question been resolved?

Channel closed

Closed by @surreal apex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt pond]

how would i figure out the arc

[burnt pond]

i have segment BC's length

[rich tide]

||notice that ABC is a right triangle||

[burnt pond]

so?

i knew that, its how i got BC's length

do i use trig ratios?

[rich tide]

yes

[burnt pond]

ok

so angle BCD is 176.86, how do i figure out the arc measure?

nvm

.close

[final saddle]

Channel closed

Closed by @burnt pond

Use .reopen if this was a mistake.

[rich tide]

if that is right then notice that angle ABC and ADC are right angles and sum of angles in q uadrilateral is 360 deg

[burnt pond]

i just used circum angle thm

[rich tide]

well that is another thing you can do to get to angle BAD

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pine]

Which of the following represents te result of multiplying 3.45 by 2.1 and rounding the answer to three significant figures? a) 7.245 b) 7.23 c) 7.28 d) 7.2

[tranquil pine]

i thought it was b

but when i realize if i calculate it its equal to 7.245

and after i round it to 3 significant figures

it's equal to 7.25

which is not an option

[scarlet lantern]

they might just mean 3 decimal places

[tranquil pine]

the question says significant figures though

[tranquil pine]

that dont mean much

it just wants 3 decimals

[scarlet lantern]

id just say a and if they say its wrong the other 2 are even worse answers as they are incorrect

[tranquil pine]

7.23 and 7.28 are 3 significant figures

if they said decimal points im sure they would say it

[scarlet lantern]

but they are wrong

[tranquil pine]

yes

[tranquil pine]

ah i see

[scarlet lantern]

so just put a and if your teachers says your wrong ask them what its supposed to be as it is none of the answers shes given

[tranquil pine]

maybe theyre just tryin to confuse you

[scarlet lantern]

or just write 7.25 on the side or something

[tranquil pine]

i don't know if this is a question to confuse, because it's just totally wrong

[tranquil pine]

yeah i will do that for sure

also tell them tomorrow

thanks!

both of you

.close

[final saddle]

Channel closed

Closed by @mossy bobcat

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tepid forum]

the book says the answer for this is (x,y,z)=(-4,2,9)

[tepid forum]

Im losing my mind because I did this 4 times and I got -6,2,11 every time

can someone else confirm

[robust mulch]

have you tried plugging in to see if youre correct?

[tepid forum]

oh. i didnt, one sec

[robust mulch]

also check your spot on the answer key just to be sure

[tepid forum]

Both works

is that possible?

.close

[final saddle]

Channel closed

Closed by @tepid forum

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hybrid prawn]

Plane Trigonometry! I have no clue how to even start this question.

If I had to describe where my confusion is coming from, it's probably that I don't understand where the x,y coordinates are, and even if I did I would have no idea what to do with them. Can anyone help me work through a problem like this?

[pale oracle]

the (x,y) coordinates are the points on the circle

this is the "Unit Circle", which has a radius of 1

the points shown are for some special right triangles that are drawn inside the circle