#help-36

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sonic crystal
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its fuzzy but i think independent events are events that do not influence eachother, as for the formulaic definition werent there multiple

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something like P(A or B) = P(A u B)

tired walrus
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so you forgor.

sonic crystal
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basically

tired walrus
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do you not have any notes either?

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P(A n B) = P(A) * P(B)

this is the definition of independence for the events A and B.

sonic crystal
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oh

tired walrus
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compute the left-hand side. separately from that, compute the right-hand side. check whether or not the two results are equal.

sonic crystal
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well P(A) = 1/2 and P(B) = 1/3

tired walrus
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ok, and what is P(A n B)? and most importantly show how you get the value.

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bc there is a right way and a common-mistake wrong way.

sonic crystal
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if they are independent then it is 1/2 * 1/3 = 1/6

tired walrus
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that's IF they are independent

severe hawk
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you said "if". You dont know that

tired walrus
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you do not yet know that they are.

sonic crystal
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so what should i do beforehand

tired walrus
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you must find P(A n B) without assuming their independence.

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first figure out what A n B means as an event.

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for this you will need to use your brain, sorry

sonic crystal
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P(AnB) refers to the probability of it occuring at the same time?

tired walrus
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"it"-overuse.

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try again.

sonic crystal
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P(AnB) refers to the probability of event A and event B occuring simultaneously

tired walrus
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sure does.

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but you need to

figure out what A n B means as an event.

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like what does it mean for event A and event B to occur simultaneously?

sonic crystal
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for it to happen at the same time? hmmCat

tired walrus
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what dice rolls fall under event A?

sonic crystal
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the numbers need to be even

tired walrus
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list them.

sonic crystal
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2,4,6

tired walrus
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ok

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and which rolls fall under event B?

sonic crystal
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if the dice rolls a 5 or 6

tired walrus
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list them

sonic crystal
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5,6

tired walrus
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so then which rolls fall under both events at once?

sonic crystal
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6

tired walrus
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6 and only 6?

sonic crystal
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yes

tired walrus
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correct

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so then what is the probability of AnB?

sonic crystal
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1/6?

tired walrus
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correct

sonic crystal
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ohh

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and that matches with P(A) and P(B) as well so it is independent then?

tired walrus
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that matches with P(A) times P(B).

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so these events are independent.

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"it"-overuse again, unfortunately.

sonic crystal
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what would be the dependent definition?

tired walrus
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two events are dependent if and only if they fail to be independent.

sonic crystal
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i see

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thanks

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strange swan
final saddleBOT
strange swan
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Is this right? Do I find the union of their domain? Because it is +

final tangle
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you want the intersection of the individual domains, not union

strange swan
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oh okay okay but how do i right the final answer in interval notation

final tangle
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well first identify the intersection from what you drew

strange swan
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should i still use the 'U'?

final tangle
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only for the domain of the first root,
but for the intersection of the domains, no

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$\cap$ for intersection

soft zealotBOT
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ℝαμΩℕωⅤ

final tangle
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you also made a sign error here

strange swan
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oh why?

final tangle
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inequalities don't work like that

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the interval notation you have below is correct though

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(-inf,-1] is representative of x<=-1, not x>=-1

strange swan
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how does the inequalities work?

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hollow wolf
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Every bounded sequence has convergent sub sequence

hollow wolf
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Can anyone give me a perfect example for understanding this statment

desert mantle
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what counts as a "perfect example"

worldly vale
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Yeah the issue is any example.isnt going to he very enlightening, someone is just going to give you a bounded sequence and a convergent subsequence, so what? The power of the statement is that no matter what the bounded sequence is, there will be some convergent subsequence, even if we don't know what it is

hollow wolf
desert mantle
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(-1)^n

hollow wolf
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1/n...it is bounded sequence right?

desert mantle
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every convergent sequence is bounded

hollow wolf
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Because it's limit is 0

hollow wolf
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So what will be convergent subsequence in it?

desert mantle
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wrong language but yes

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bounded by (number)

hollow wolf
desert mantle
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not bounded by (set)

hollow wolf
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(-1,1) u mean this?

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Yes bounded by -1 to 1

hollow wolf
desert mantle
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the constant sequence 1

hollow wolf
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Ohh

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And -1 also

desert mantle
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yes

hollow wolf
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Right?

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Ohh now i am understanding

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Every sequence which is bounded needs 2 numbers

desert mantle
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do you mean upper and lower bound?

hollow wolf
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Yes

desert mantle
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bounded means that |a_n| <= M. so you take care of both upper and lower bounds with a single number

hollow wolf
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I guess no??

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We need upper and lower both no?

desert mantle
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if numbers are bigger than -47 and smaller than 93, then |a_n| <= 93

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so you just need one number

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no

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the sequence 1/n is bounded by 1

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it doesnt even include a constant subsequence

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it itself is a converging subsequence

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which converges to 0

lyric summit
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the sequence (1/n) also has its subsequences, but they all converge to the same number 0, to which the sequence (1/n) converges

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$a_{n}=\frac{1}n{}\\\text{examples:}\\a_{2k}=\frac{1}{2k}\longrightarrow 0\\a_{k^{2}}=\frac{1}{k^{2}}\longrightarrow 0$

soft zealotBOT
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Joanna Angel

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@hollow wolf Has your question been resolved?

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mellow vale
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hi

final saddleBOT
mellow vale
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i got a question in discrete math

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is {1} ⊆ {1, {2}}?

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i thought yes but the answer key said no

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AK said No, because {1} is a set and there are no sets as elements in {1, {2}}

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but i thought

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{1} is a set with element 1

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and {1,{2}} is another set

hollow iron
mellow vale
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and it has the element 1

mellow vale
hollow iron
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{1} does not belong in {1, {2}}, but it is a subset of {1, {2}}

mellow vale
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that is true yes

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just threw me off

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that the answer key said that

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ig they made a mistake

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alr thanks

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tranquil pine
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What exactly is the benefit that is realised from the fact that the eigenfunctions of a Sturm-Liouville problem are complete with respect to mean convergence as compared to like being complete with respect to pointwise convergence thonk

tranquil pine
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i just want some clarification on this

desert mantle
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pointwise convergence isnt that strong

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and I mean its always nice if the convergence fits with your topology

tranquil pine
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oh wait i guess like

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eigenfunctions that are complete with respect to mean convergence are complete for the set of functions that are square integrable on 0 <= x <= 1

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and the set of square integrable functions is much bigger than the set of continuous functions

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i assume

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ok thanks

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snow solstice
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can someone explain some machine learning formulas to me in an easy way

final saddleBOT
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@snow solstice Has your question been resolved?

snow solstice
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no

final saddleBOT
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@snow solstice Has your question been resolved?

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@snow solstice Has your question been resolved?

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ionic hound
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Im a little confused on this question

final saddleBOT
ionic hound
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so at first I found cylinder volume, divided it by 2. Found sphere volume, and added that to the cylinder volume. I realized this was wrong as it wants how far the water rized

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So then I found the volume before the sphere was dropped (cylinder volume divided by 2). Then found the volume after the sphere was added (sphere volume + original volume). Then bc it asks how far the water level raised, I did the volume of after the sphere was added, subtracted by the original volume. I get 26.1279

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However, the answer key says 6.8cm which doesnt make sense

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I was wondering if one of you could confirm

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@spring depot

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man

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light wren
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Hey, im taking a look at this theorem in my notes , and in the proof there are some steps that are confusing me a fair bit, would anyone be able to explain them?

light wren
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so for y' = f(x,y)

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what is the cause for introducing s in 3.5?

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and where tf does y0 come into play in finding g(y)

worldly vale
light wren
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ah

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😖

light wren
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amber junco
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how would i Know the b in (a+b)^2 is a complex number

amber junco
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i could do (s+1/2)^2 +7/4 but i need to rewrite in laplace form

tidal pumice
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what is the connection between the text and the image?

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where is the (a+b)^2 ?

amber junco
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I need to rewrite (s^2+s+2) in the form (a+b)^2

tidal pumice
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why?

amber junco
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to get this

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nvm its a bs problem anyway

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timid gyro
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Hello

final saddleBOT
timid gyro
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Can someone help me with this

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???????

final saddleBOT
# timid gyro
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
timid gyro
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1

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Simplify into simplest radical form

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Oh yeah I got it

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I have one last one

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I am on level 1

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??

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dark bough
#

How do I find the reflections of points A,B,C in respect to the plane x+2y-3z=0? (plane acts like a mirror)
ABC are (1,0,0), (0,1,0) and (0,0,1)

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fervent quiver
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How would I do this?

final saddleBOT
fervent quiver
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I know that I can say that say one side is x

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So second would be x + 9

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area = (x) (x + 9)

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Oh oops-

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But idk what to do after I get x^2 + 9x

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Should I convert it to vertex form?

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Oh I forgot teh area existed

shut gazelle
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You know the area

fervent quiver
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Yeah...

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Sorry 😭 Thanks!

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Okay got it

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I'll close this now

#

Tyyy

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.close

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buoyant perch
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Can anyone help me with this?

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The task states

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Show that the line h through the points P(0/12) and Q(13/4) is parallel to a tangent to the graph of f at a point (u/f(u) for 0<x<4

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And idk what im supposed to do

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nvm i had an idea

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turns out

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it was rigjht

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forest flume
#

Need to find all the asymptotes of f(x) = x/lnx. x>0 and
x |= 1. First vertical: should i calculate the limit in 0? The horizontal: limx->+inf x/lnx [inf/inf] = lim x->+inf 1/1/x = +inf
So no horizontal
Lastly diagonal: a= lim x->inf x/lnx/x = 0
b also will be 0
That mean that diagonal is y=0?

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abstract moth
#

Let G be a group. is $H=\left{ g^{2} | g\in G \right}$ a subgroup of G?

Suppose H is closed under the operation of G. Let $a\in H$ then $a=g^{2}$, $aa=g^{2}g^{2}=g^{4}$, thus $aa\notin H$ therefore H is not a subgroup of G.

soft zealotBOT
#

marawrdr

abstract moth
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is this correct?4

tulip coyote
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(g^2)^2

royal gust
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H contains all elements which are the squares of some other element

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Naturally, g⁴ is a square of something. So, it's in H.

abstract moth
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I know its not a subgroup so i have to show one of these

  1. Show that the identity is not in the set.
  2. Exhibit an element of the set whose inverse is not in the set.
  3. Exhibit two elements of the set whose product is not in the set.
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I know 1 is a no go since the identity is in the set

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2 follows from 1

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so all i have to work with is coming up with two elements of the set whose product is not in the set

royal gust
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Why do you think it's not a subgroup?

abstract moth
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Cus i saw the answer online

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but

tulip coyote
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(You may want to specify an actual group if you want a counterexample)

abstract moth
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intuitively idk

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it must not satisfy one of the conditions for a group

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but its notclear which one

tulip coyote
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(If G were commutative, you would have the result true, so there's that...)

abstract moth
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It must not be associative since theres an identity and each element has an inverse

royal gust
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Damn you really do have to grab a non-abelian group as a counter-example, huh? That's kinda ugly

abstract moth
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Theres this

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but i dont even know how A4 relates the subgroup in question

final saddleBOT
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@abstract moth Has your question been resolved?

tulip coyote
abstract moth
#

?

tulip coyote
final saddleBOT
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@abstract moth Has your question been resolved?

abstract moth
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i thought i was supposed to show that in general a subset of that type will never be a subgroup

tulip coyote
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Yea it can be a bit confusing, whether their intention is that "there's at least one counterexample" and "it'll never work" NervousSweat

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At least for this one it was slightly clear that it's about a specific counterexample (in fact, you could think about the trivial group, where the subgroup is basically itself(!))

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rancid idol
#

I typed out a question in #help-28. I need it to unlock to access it again, so just recycling channels. Sorry for the spam & ignore

rancid idol
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mental roost
#

hey

final saddleBOT
mental roost
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i am working on a simulation problem

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i work in python

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i have a list/array/vector
ordered = [0,1,2,...,N]

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this means, this vector has N+1 entries

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now i want to shuffle the entries of this vector around

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but the problem gets difficult because:
-i want to not have 1-cycles, as in ordered[i]==i

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if we for example have the array Arr=[0,2,1]
then Arr[1]=2, Arr[2]=1
BUT Arr[0]=0

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i tried to solve this with minimal recursion, but that gets out of hand quickly

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so i am looking for a mathematical way that is efficient

desert mantle
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you could just generate a random permutation and reject it if it has a fixed point

mental roost
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yeah that is what i tried
but that adds recursion

desert mantle
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I mean I wouldnt call it recursion. but ok

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whats bad about that

mental roost
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when things get large, it makes it slower

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but i think my problem lies somewhere else

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i tried to make it more efficient but i think i made an oopsie

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this is the unholy junk i wrote

desert mantle
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you only need about three attempts on average

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which really isnt that bad

mental roost
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only 3?

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if the array gets large, the amount of attempts should increase as well, no?

desert mantle
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about a third of all permutations dont have a fixed point

mental roost
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oh

desert mantle
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no

mental roost
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huh

desert mantle
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in general it converges to about 37% of permutations have no fixed point

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which really isnt that bad

mental roost
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ok i think that worked, nice

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thank you^^

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molten ridge
#

hey

final saddleBOT
molten ridge
tired plume
#

Do you know how to solve an ODE of the form:
$\frac{dy}{dx}=f(x)g(y)$

soft zealotBOT
molten ridge
#

no

#

i know a little

tired plume
#

That's the easiest way IMO but there is another option

Have you seen how to solve ODEs of the form:
$\frac{dy}{dx}+f(x)y=g(x)$

soft zealotBOT
tired plume
molten ridge
#

what do you mean?

hazy panther
#

Am I cooked

tired plume
#

Wrong channel bro

tired plume
molten ridge
#

wait

#

i think i know what is the answer

tired plume
#

Because this could feature in like 3 different topics and so I don't know what hint to give you lmao

molten ridge
#

Ae−x 2?

#

.close

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gritty minnow
final saddleBOT
gritty minnow
ornate knot
#

u can break them down into 2 fractions which makes it easier to solve

#

(3-18/x) / (x-6)

#

like this

final saddleBOT
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remote crane
#

Hi 🙂

A statistics/R question. I'm trying to understand what and how does this function work. Can someone explain?

remote crane
#

For convenience:

This function returns the value of the__** inverse cumulative density function (cdf) of the binomial distribution**__ given a certain random variable q, number of trials (size), and probability of success on each trial (prob). And with the use of this function, we can find out the pth quantile of the binomial distribution.

Under this example, we are using the qbinorm function to get the 19th quantile of a binomial distribution with 30 trials with the prob of success to 0.6.

qbinom(.19, size=30, prob=.6)

#

I saw told that it some way it must return the inverse of binomial distribution, right? But tbh I don't see a connection there... Like, what does pth percentile has to do with the inverse?

#

If someone could provide some examples, that'd be awesome

#

@blissful condor, you may be interested in this 🙂
(please, let me know if you don't want to be pinged anymore; just thought statistics questions are of interest to you)

blissful condor
remote crane
blissful condor
final saddleBOT
#

@remote crane Has your question been resolved?

final saddleBOT
#

@remote crane Has your question been resolved?

final saddleBOT
#

@remote crane Has your question been resolved?

final saddleBOT
#

@remote crane Has your question been resolved?

final saddleBOT
#

@remote crane Has your question been resolved?

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dense garnet
#

I'm reading about orthogonal projections and inner products, specifically in regards to least squares approximation, and suddenly I'm encountering this formula; $$\left\lVert u-v\right\rVert ^2=\left\lVert u\right\rVert ^2-\left\lVert v\right\rVert ^2.$$ Is this simply Pythagoras theorem? I know how to prove with a plus sign, but I don't know how to derive it when there's a minus sign. Any ideas?

soft zealotBOT
#

Philip

dense garnet
#

.close

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unique talon
#

withou math jargon can any1 tell me what does interpolation mean

unique talon
#

i cant undertsnad

bold badge
#

it just means to estimate something

#

like find the value of something good enough for what ur working with

granite anvil
#

so what does extrapolate mean compared to that

bold badge
#

it's like taking the data u have to guess about data you don't hvae

#

interpolation is usually referring to guess about something within the bounds of ur data

#

extrapolation is that same idea but for a value outside of ur range of data that you have

unique talon
bold badge
#

hmmmmmmmmmmmm

#

well

#

i think in a sense, you could do something like that

#

but interpolate and extrapolate usually are terms used in stats when talking about trends and patterns and stuff

granite anvil
#

so say a line of best fit would be extrapolating?

bold badge
#

I'd aruge it's both

#

tbh

#

argue*

unique talon
#

ok got u, is hroner method /synthetic divion can also be done by dividing polynomial with all non real rooots

#

@bold badge

#

last ques

#

plz

bold badge
#

I'm not sure so I can't say

unique talon
#

oh ohk np

bold badge
#

I haven't done polynomial divinsion since MS

#

and I'm now a junior in college sooo

#

lol

unique talon
#

ohh i see , nw , i will close her and ask sepratly , will get reply easily there

#

thanks

#

.close

final saddleBOT
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verbal steppe
#

Consider the points A = (10, 4, −1), B = (12, 5, −3) and C = (6, 5, 9) and let L be the line through the points
A and B. Calculate the coordinates of the point P on the line L so that the triangle P CB becomes right-angled with angle π/2 at point P.

barren hound
#

right angled means dot product = 0, that probably helps

verbal steppe
#

Yeah i had a suspicion that was the case

#

however

#

This is what i think it should be like

#

I calculated the vector between the two points AB = L = B - A

#

But i need a vector from P to C and we don't know P?

#

So i'm not sure what to do

barren hound
#

if P is on the line L

#

then P is like (10 + x, 4 + x, -1 + x) or something

#

probably with more coefficients

verbal steppe
#

How did you come to that conclusion?

#

L: (10, 4, -1) + t( 2, 1, -2) @barren hound Is this what you mean?

barren hound
#

yeah

#

so if you've got a point P on L then you know that P can be described by (10 + 2t, 4 + t, -1 - 2t)

#

and then you can just figure out what t is so that PCB is right angled

verbal steppe
#

(x, y, z) = (5, 8, 11) + t(3, 14, 12)
With this equation no matter the t it will always be on the line however
@barren hound

barren hound
#

i don't understand what those numbers are coming frmo

verbal steppe
#

yeah sorry that's my bad

#

one sec

#

(x, y, z) = (10, 4, -1) + t(2, 1, -2)

barren hound
#

right

#

so that's on the line

#

now

verbal steppe
#

Yeah

barren hound
#

so P = (10 + 2t, ... )

verbal steppe
#

what about the condition that it has to be pi/2 ?

barren hound
#

that just means right angle

#

now find PC

verbal steppe
#

PC = C-P = (6-x, 5-y, 9-z) ?

#

I'm not sure if that is what you mean

final saddleBOT
#

@verbal steppe Has your question been resolved?

verbal steppe
#

@barren hound sadcat

barren hound
#

so now you have PC and you have PB

#

or you can get PB at least

#

and you know that if angle CPB is a right angle then those two have a dot product of 0

verbal steppe
#

So we take the vector PC and PB and the dot product of those should be = 0?

#

so PB = B - P = (12-x, 5-y, -3-z)

#

What now?

opal plinth
#

What's wrong? You have PB and PC so do their dot product

verbal steppe
#

Here is my paint sketch :)

#

Am i thinking correct?

opal plinth
#

Yeah, now solve for x,y,z

verbal steppe
#

x = 12 and 6
y = 5
z = -3 and 9

opal plinth
#

Uh no

#

Definition of dot product

verbal steppe
#

x1 = 12-x
x2 = 6-x
x1*x2 = (12-x)(6-x) = 0
x has to be 12 or 6

opal plinth
#

No

#

It doesn't say x1*x2 = 0

verbal steppe
#

(12-x)(6-x) + (5-y)(5-y) + (-3-z)(9-z) = 0

opal plinth
#

Yes, now there's one more thing you know about x,y,z

verbal steppe
#

(12-(10+2t))(6-(10+2t)) + (5-(4+t))(5-(4+t)) + (-3-(-1-2t))(9-(-1-2t)) = 0

#

(12-10-2t)(6-10-2t) + (5-4-t)(5-4-t) + (-3+1+2t)(9+1+2t) = 0

#

(2-2t)(-4-2t) + (1-t)(1-t) + (-2+2t)(10+2t) = 0

opal plinth
#

Continue

verbal steppe
#

yeah i'm doing it on paper getting rough

#

One sec sadcatthumbsup

#

i got t to be 1, -3

#

,w (12-(10+2t))(6-(10+2t)) + (5-(4+t))(5-(4+t)) + (-3-(-1-2t))(9-(-1-2t)) = 0

opal plinth
verbal steppe
#

What conclusion can i draw from this ? That i get two possible coordinates for P?

opal plinth
#

Yes, though usually when you get two solutions one is degenerate

verbal steppe
#

if t = 1 i get that P = B

opal plinth
#

Right

verbal steppe
#

So it has to be -3?

opal plinth
#

To have a triangle PBC, yes

verbal steppe
#

That makes sense because otherwise we dont get the triangle, only a straight line

#

Let me insert -3 and see what i get

#

P = (4,1,5)

opal plinth
#

You can use Pythagoras if you want to confirm that this makes a right triangle

verbal steppe
#

I'm aware on how pythagoras works but i'm not sure how to apply it in this context

#

Or rather apply Pythagoras on points in a 3d envir

opal plinth
#

Pythagoras only deals with distances, it doesn't matter how many dimensions you work with

#

By distances I mean triangle side lengths

verbal steppe
#

For figuring out the length of the vector, would this work?

opal plinth
#

Yeah

verbal steppe
#

So i use Pythagoras to calculate the length of each side of the triangle and then utilize trigonometry to see if they create a pi/2 angle?

opal plinth
verbal steppe
#

No

#

that gives the length of the vector u

opal plinth
#

... is that not how you calculate the length of each side?

verbal steppe
#

Yes

opal plinth
#

So what do you use Pythagoras for

verbal steppe
#

To find the length of each side in a triangle

opal plinth
# verbal steppe

You just said this is how you do that, and that it's not Pythagoras

verbal steppe
#

a^2+b^2 = c^2

#

okay i'm very sleep

#

Forget what i just said

#

If lhs = rhs = a pi/2 exists

#

:)

#

🙂

opal plinth
#

Ok that's not trigonometry though, no need to say pi/2 or whatever

#

If a^2+b^2 = c^2 then the triangle with sides a,b,c is a right triangle

verbal steppe
#

Yes

#

I just completely forgot about that and thought that Pythagoras was used for only calculating the length of a side in a triangle

opal plinth
#

Ok so you actually use Pythagoras multiple times

opal plinth
# verbal steppe

Once for the triangle at the end, but also this is actually Pythagoras

#

(or a generalization)

verbal steppe
#

Aah that makes sense

opal plinth
#

FYI, in software, when you want to know if a 2D point (x,y) is inside a circle with center (z,w) and radius r, you just do (x-z)^2 + (y-w)^2 < r^2

#

Similarly for a 3D point inside a sphere, there's just one more term on the left

final saddleBOT
#

@verbal steppe Has your question been resolved?

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tranquil pine
final saddleBOT
tranquil pine
#

how would i go about solving this?

#

anybody

#

i dot know how i shud about this

vital crag
#

Integration by parts

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

ok yea thanks

final saddleBOT
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forest flume
#

.close

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normal juniper
#

can someone please help me with c?

final saddleBOT
versed shuttle
normal juniper
#

🤔

versed shuttle
#

it's given that a + b is itself a root

normal juniper
#

right

#

but how can I use that

#

oh wait

#

A/2 is a root?

#

so I sub it back into the original equation

versed shuttle
#

try it out :)

normal juniper
#

ok so far im on -A^3 + 24A = 0

#

-A(A^2 - 24) = 0

#

so A^2 = 24

#

so A = 2sqrt(6)

#

does that track

versed shuttle
#

ok that's correct but i'd just like to let you know that that's technically not the only possible value of A in our case

normal juniper
#

oh yeah A can also be 0

#

hmm

#

wait

versed shuttle
#

and it could also be -2sqrt(6)

#

however ...

normal juniper
#

the question says A > 0

#

yeah

versed shuttle
#

yes

normal juniper
#

too easy

#

thanks for the help

#

.close

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floral hazel
final saddleBOT
floral hazel
#

hey i have a controls problem, im not sure if you'll be able to help but all i need to do is lable this correctly and im having trouble

#

there are a couple that i'm pretty sure are correct like signal 1 is the reference speed

final saddleBOT
#

@floral hazel Has your question been resolved?

floral hazel
#

no it hasnt......

floral hazel
#

okay yes it has... flip u guys for not responding...

#

.close

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marsh horizon
final saddleBOT
marsh horizon
#

,rotate

soft zealotBOT
final saddleBOT
#

@marsh horizon Has your question been resolved?

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prisma lantern
final saddleBOT
neon slate
#

so, can you write any equations from the info given?

#

@prisma lantern

prisma lantern
#

Find dA/dt, but I'm using the formula A=1/4πD^2

neon slate
#

sounds good

prisma lantern
#

But I get 157

neon slate
#

so what did you get for dA/dt?

prisma lantern
#

dA/dt=1/4π(2•20)(dD/dt), dD/dt=5, so I get 157

#

And 157 isn't even an option

neon slate
#

is it multiple choice?

prisma lantern
#

Yeah

neon slate
#

!original

final saddleBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

neon slate
#

(including answer choices)

#

are the answers in different units or something?

prisma lantern
#

I think 600?

neon slate
#

oh i see your problem, dD/dt is given in terms of inches \ minute, while the width of the patch is given in feet

prisma lantern
#

Ohh

neon slate
#

so you'll need to convert the 20 feet to inches

prisma lantern
#

Oh ok ok

neon slate
#

since answers are in inches

prisma lantern
#

Thank you

neon slate
#

other than that, your logic is sound

prisma lantern
#

Alright, thank you bro!

neon slate
#

careful with those units, theyll get you on the AP test 😄

prisma lantern
#

I know, I'm nervous about that exam

neon slate
#

well you seem to be getting things fine

#

just remind yourself to double check when the problem involves units, it isnt that many of them

prisma lantern
#

Truee, luckily

final saddleBOT
#

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heady wing
#

I need help.

final saddleBOT
heady wing
#

well fractions

#

so basically

#

u gotta find felles nevner

#

im from Norway

#

And im struggling with it

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@heady wing Has your question been resolved?

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amber junco
#

how is x^5y^2 a potential

final saddleBOT
formal trail
#

if you take the gradient of x⁵y² it gives you the given vector field

amber junco
#

.close

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#
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amber junco
#

.reopen

final saddleBOT
#

amber junco
#

@formal trail I dont get it do i need to compute the partial derivatieves f(x,y,z)?

#

also i dont know how to do it with this intergral with dx and dy

#

normally i just got this to deal with

#

how do i get the vector field out of that intergral?

#

ooh

#

wait

#

nvm

#

.close

final saddleBOT
#
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amber junco
#

.reopen

final saddleBOT
#

amber junco
#

@formal trail one last thing. How can i see that the vector field is conservative

#

how can i see that this vector field is conservative

formal trail
#

a vector field is conservative if a potential function exists (i.e. $f$ exists such that $\grad f = \vb{F}$. you can alternatively use the fact that $\curl (\grad f) = \vb{0}$ since that means $\vb{F}$ is conservative if $\curl \vb{F} = \vb{0}$

soft zealotBOT
formal trail
#

if you don't know that yet, you can also just try and find a potential function and see if it works or not

amber junco
#

how do i compute the grdiant of f?

#

just do partial derivates?

formal trail
#

yes

amber junco
#

but what is F then?

#

the vector field?

formal trail
#

gradient is an operator that takes a scalar function and returns a vector field. so F is the vector field you already have, and f is a potential function of F if $\grad f = \vb{F}$

soft zealotBOT
amber junco
#

@formal trail my gradiant is 20x^3y^2 +2x^5

formal trail
#

gradient of what?

formal trail
#

you can't take the gradient of a vector field

#

you're trying to find a potential function f whose gradient is the vector field you already have

amber junco
formal trail
#

you need to find a potential function f, and take the gradient of f, and if that gradient is your original vector field F, then F is conservative

amber junco
#

okay thank you!

#

.close

final saddleBOT
#
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fallow sky
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Is this logic correct

final saddleBOT
fallow sky
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Is that the reason it’s positive 6/x

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Antideriv

final tangle
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,rotate

soft zealotBOT
final tangle
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are you integrating $\frac{6}{x^2}$ or $-\frac{6}{x^2}$

soft zealotBOT
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ℝαμΩℕωⅤ

fallow sky
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Second one

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Mb

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Didn’t include in pic

final tangle
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then yes

fallow sky
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Logic is good?

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The answer is right but idk if my explanation was right

final tangle
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missing the dx

fallow sky
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If I added dx, would it be good?

final tangle
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application of power rule is fine

fallow sky
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What about when I move x to bottom

final tangle
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don't forget the constant of integration

fallow sky
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+C?

final tangle
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that's the application of the negative exponent law, which you also applied at the start, is also fine

fallow sky
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Oh ok

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Tysm

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.close

final saddleBOT
#
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supple atlas
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pls

final saddleBOT
supple atlas
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ty

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Ms. Kitts works at a music store. Last week she sold 6 more than 3 times the number of CDs that she sold this week. Ms. Kitts sold a total of 110 CDs over the 2 weeks. Create a system of equations that can be used to find the number of CDs she sold last week, and the number of CDs she sold this week. Then use your equations to solve for each.

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Can someone help help me solve this using linar systems its been a minute and this is my practice question totaly forgotten how it worka

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works

clear hearth
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What have you done so far

supple atlas
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nothing

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i am stuck

clear hearth
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So you absolutely can not remember anything?

supple atlas
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well i can start the question

clear hearth
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How would you?

supple atlas
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she sold total of 110 cds

clear hearth
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Yes

supple atlas
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idk bro

clear hearth
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Okay

supple atlas
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lowkey

clear hearth
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So let the no of CDs she sold this week be x

supple atlas
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lemme get my calc

clear hearth
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They say she sold 6 MORE than 3 TIMEs the no of (CDs she sold this week)

clear hearth
supple atlas
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okok

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so 6 times 3

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3 different times?

clear hearth
supple atlas
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6 x 6 x 6?

clear hearth
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Not quite

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Okay forget this

supple atlas
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alr

clear hearth
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Say John had y apples

supple atlas
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ok

clear hearth
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Laurence had 3 more than 2 times the no of apples than John

supple atlas
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can you show me how it looks solved and ill do the next question

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like fr

clear hearth
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How many apples does Laurence have?

supple atlas
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pretty please

clear hearth
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You're here to learn bro

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😭

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You could try

supple atlas
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yes but i dont know what the formula looks like

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its been a min

clear hearth
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Ok I'll give examples

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You learn

supple atlas
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it was the first unit i had

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ok

clear hearth
supple atlas
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not really

clear hearth
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Ok, Bob has twice the nos of apples than John

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So Bob has 2y apples right?

supple atlas
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ok

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yes

clear hearth
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If Laurence had 3 MORE than 2 TIMES the no of apples than John

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Laurence should have 2y+3 apples

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Or 3+2y

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Same thing

vagrant tundra
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@supple atlas is this from khan academy algebra 1?

supple atlas
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so what 3 + 2y aint the the formula bro

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your making 0 sense

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telling me

clear hearth
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I was helping you to make equations

supple atlas
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this guy has 2 apples

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aint the formula

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i want to kknow how to do it

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not make the question

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😭

clear hearth
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Ok tell me this, you understood how to frame relations now right?

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You understand the above examples right?

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They're not related to your question at all they were just to help you frame relations

supple atlas
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ok so for my question where do i start

idle dune
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May I also provide an explanation?

supple atlas
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Ms. Kitts works at a music store. Last week she sold 6 more than 3 times the number of CDs that she sold this week. Ms. Kitts sold a total of 110 CDs over the 2 weeks. Create a system of equations that can be used to find the number of CDs she sold last week, and the number of CDs she sold this week. Then use your equations to solve for each.

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please

clear hearth
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Assume Mrs Kitts sold x CDs this week

supple atlas
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yes

clear hearth
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So according to the question, she sold 6 MORE than 3 TIMES the number of CDs than THIS WEEK

idle dune
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Let y be number of CDs sold last week

idle dune
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And total CDs sold in both weeks add upto 110

clear hearth
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Yes

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x+y=110

idle dune
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Which means x+y=110

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So put the value of y in this equation

supple atlas
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okok

idle dune
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Basically the question is teaching you the method of substitution of solving linear equations in 2 variables

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You substituted the value of y from one relation in the other relation

clear hearth
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It's important to know how to form relations

idle dune
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Always remember a correct question will always have two meaningful relations to solve 2 variables

supple atlas
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can you show me how its written i have the question and all that but in the formula i don’t understand substitution

idle dune
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See what does substitution here mean?

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It means we are using the obtained value of y (from one equation in terms of x) in another equation involving both x and y

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Are you following?

clear hearth
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@supple atlas

final saddleBOT
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@supple atlas Has your question been resolved?

supple atlas
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sorry bro thanks

candid dome
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who can help

final saddleBOT
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final saddleBOT
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naive shoal
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Last 2 times my ticket got cloed without an answer so lets try this again...
But can someone explain each of the different types of angles and how they relate (not just ones in here but all types I would find) and bow they relate?

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i want to know the anme all of types of angles that can be related and like how you can get there degress based on that other one its releted to

static fractal
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unless you have parallel lines, these angles generally don't relate to each other at all

final saddleBOT
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@naive shoal Has your question been resolved?

final saddleBOT
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naive shoal
static fractal
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corresponding will be on the same side of the transversal

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so 1 and 3 are transverse in Q6, for example

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eh, let me find something

naive shoal
final saddleBOT
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@naive shoal Has your question been resolved?

static fractal
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you need to react with ❌ or the channel will close

final saddleBOT
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final saddleBOT
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amber junco
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how do i use polar coordinates here?

final saddleBOT
vital crag
amber junco
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and can i factor them out of the intergral of r?

vital crag
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Depends on D

amber junco
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this is the region

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can i do it or nah

amber junco
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I got this now

vital crag
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You're missing dA

amber junco
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can you give me a hint how to proceed further? @vital crag

amber junco
vital crag
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And you're missing your limits in theta and r

amber junco
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yeah but which one is easier to intergrate first

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then i can write them

vital crag
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Just do it

amber junco
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@vital crag cmon mannnnn

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okay

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ill do it

vital crag
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Don't even know what you're asking for

amber junco
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well. over which limit should i intergrate first to be easier

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but nvm that

vital crag
amber junco
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how long are you online @vital crag ?

vital crag
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Stop pinging me

amber junco
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@vital crag im stuck

vital crag
final saddleBOT
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@amber junco Has your question been resolved?

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final saddleBOT
#
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Ask your math question in a clear, concise manner.
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lilac oxide
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hey could someone help with this problem please

lilac oxide
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<@&286206848099549185>

versed crater
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What have you tried

lilac oxide
versed crater
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If 2 vectors aren’t parallel then yes they span a plane

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But what’s that got to do with this question?

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Let’s start with the first one

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How can you know if x lies in the plane spanned by u and v?

lilac oxide
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is it that each on of the numbers in the x vector are between the same numbers on u and v?

versed crater
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What do you mean by that

lilac oxide
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the first number in the x vector (1) is between or equal to the first numbers of the u and v vectors (0 and 1)

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and each of the numbers fit, so i would guess that the first one is correct?

scarlet sequoia
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I see what you mean, but this type of reasoning would be easier if you wrote x as a linear combination of v and w already

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You've very much almost found it, just need to formalize it

lilac oxide
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im not sure what you mean, i looked through the question and found every thing to be true which i dont think is right aswell

scarlet sequoia
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Since u and v are not colinear, they span a plane

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If u,v and w together spanned a plane

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Then w is immediately in the plane spanned by u and v

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So it's a linear combination of u and v

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So answers 3 and 5 are already incompatible...

lilac oxide
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mm ok. so i think 3 is wrong 5 is right

scarlet sequoia
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Just remember

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"c is in the plane spanned by a and b" exactly means "c is a linear combination of a and b"

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(Meaning c = xa + yb)

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So let's check answer 4

lilac oxide
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so what i said earlier was wrong, it doesnt mean that the numbers are in between?

scarlet sequoia
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There is a step in between

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And that is showing that x = av + bw

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So, if a and b exist, what are they?

lilac oxide
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uhhh

scarlet sequoia
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Focus on the 2nd and 3rd coordinates

lilac oxide
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not sure

scarlet sequoia
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Your remark that x's coordinates were "in between" those of v's and w's was practically on the spot...

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But "in between" as in what more precisely?

lilac oxide
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1/2?

scarlet sequoia
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Ah ha we're getting somewhere

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Did you find a and b?

lilac oxide
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is a and b both 1/2?

scarlet sequoia
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Yes

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you can now check that x = 1/2 v + 1/2 w

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What can we conclude?

lilac oxide
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it does

scarlet sequoia
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It does what?

lilac oxide
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the equation works

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i mean

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is there something else im suppose to conclude?

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that they are a linear combination?

scarlet sequoia
lilac oxide
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ok so they are

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do i do that for everyone?

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every one*

scarlet sequoia
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Pretty much if you wanna be sure.
If a and b don’t exist, then x cannot be in the plane spanned by such and such

lilac oxide
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also if 3 is right does that mean 2 is right? or are they different things?

scarlet sequoia
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Yes

lilac oxide
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ok

scarlet sequoia
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If w is in the plane of u and v, then u,v and w make a plane

lilac oxide
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so i unchecked the first one, and have the 3 middle ones checked, you think thats right?

scarlet sequoia
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Because if x = au + bv, we would need a = 1/2 and b = 1, which doesn't work...

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So 1 is wrong

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For 2 I suggest you try the same thing

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Find a and b such that w = au + bv

lilac oxide
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i dont think it works

scarlet sequoia
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Aye so if no a and b exist, what can we say?

lilac oxide
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its wrong

lilac oxide
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they are different things

scarlet sequoia
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No, what you said here was right.
3 and 2 are indeed equivalent statements

lilac oxide
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but we found 3 to be correct but 2 to be incorrect?

scarlet sequoia
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When did we say 3 was correct?

lilac oxide
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mm thought we did

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alr

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so 5 is right

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so the last 3

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are the correct ones

scarlet sequoia
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Which ones?

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3 4 and 5?

lilac oxide
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yes? or is 3 wrong since 2 is

scarlet sequoia
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We said 2 and 3 were equivalent

lilac oxide
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ok

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so its only the last 2

scarlet sequoia
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Sounds good to me

lilac oxide
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alright thank you

final saddleBOT
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@lilac oxide Has your question been resolved?

final saddleBOT
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final saddleBOT
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normal jasper
final saddleBOT
normal jasper
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Can someone help with 1)

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So it’s x^2

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And 5 times -5 right

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x^2 - 25 is answer?

vital crag
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,w expand (x+5)(x-5)

normal jasper
normal jasper
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how do i do 4

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3*

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(p-1 )^2

vital crag
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Foil Formula is the steps used to find the multiplication of two binomials while using the distributive property. Understand the foil formula using solved examples.

normal jasper
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Oh i learn about that

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but how do i do foil

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there’s only 1 of them

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1 polynomial

vital crag
final saddleBOT
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@normal jasper Has your question been resolved?

normal jasper
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for 3 its

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p^2 -1^2

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So it is

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P + 1

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P - 1

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?

vital crag
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,tex .freshman

normal jasper
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Oh

soft zealotBOT
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dr. matlab plot

vital crag
normal jasper
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OH

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IT IS

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xy

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2xy

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or something

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xy^2

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Right

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Or i’m wrong still

vital crag
final saddleBOT
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@normal jasper Has your question been resolved?

final saddleBOT
#

@normal jasper Has your question been resolved?

soft zealotBOT
final saddleBOT
#
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halcyon fog
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I got this wrong and want to know where I got off track my teacher said formulas and everything is correct