#help-36

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brittle gazelle
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looks like most geometry libraries would model these as multi-linestrings

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muted fox
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How to calculate all possibilities is a equation ?

final saddleBOT
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@muted fox Has your question been resolved?

muted fox
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Is it 144

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@muted fox Has your question been resolved?

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astral basalt
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Hi, there

final saddleBOT
astral basalt
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My question is, I want to make a working model on Mathematics, can anybody help me by giving some ideas?

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What can we make?

runic remnant
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What exactly are you trying to do?

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what do you mean by a "working model"?

astral basalt
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Project

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Working one

sand spear
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your question isn't clear, could you give some more details?

astral basalt
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For example - previous year I made 7 bridges problem for exhibition

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Which was a working model

runic remnant
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So you want to construct a mathematical model of a real world problem? Like has been done with the 7 brides of Königsberg?(https://en.wikipedia.org/wiki/Seven_Bridges_of_Königsberg )

The Seven Bridges of Königsberg is a historically notable problem in mathematics. Its negative resolution by Leonhard Euler in 1736 laid the foundations of graph theory and prefigured the idea of topology.The city of Königsberg in Prussia (now Kaliningrad, Russia) was set on both sides of the Pregel River, and included two large islands—Kneiphof...

astral basalt
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Yeah

runic remnant
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What problem are you looking at?

astral basalt
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Can you give me an idea, I don't know, I am short in time?

runic remnant
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So for a school assignment?

astral basalt
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No, for college, I am pursuing B.Sc B.Ed Maths

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It is for Mathematics day, which we are celebrating on 22 December

runic remnant
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How related to the real world does it have to be? Are you doing some engineering?

astral basalt
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No, not much High Tech but more than Average

astral basalt
runic remnant
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I have worked on a couple of applied mathematics problems in the last year. But most of them are within a combination of math, programming and chem. Like when i worked on a program to balance chemical equations using linear algebra, or the time i used Newtons method combined with the titration equation to solve for points on a teoretical titration kurve.

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Doesn't seam like something fitting though

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So maybe someone else has a good idea

astral basalt
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Yeah, Thank you so much @runic remnant

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But can you share about how you used linear algebra to balance chemical equations

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<@&286206848099549185>

final saddleBOT
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@astral basalt Has your question been resolved?

astral basalt
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Can you help @runic remnant

runic remnant
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do you by any chance read danish?

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Pretty straitforward

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@astral basalt

final saddleBOT
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@astral basalt Has your question been resolved?

final saddleBOT
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@astral basalt Has your question been resolved?

final saddleBOT
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@astral basalt Has your question been resolved?

astral basalt
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@runic remnant can you share a link or screenshot of the document

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Because it doesn't get downloaded

astral basalt
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peak ice
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Is the solution I'm pointing to missing a +C?

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lethal estuary
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yes, and "dx" shouldn't be there

peak ice
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yes teacher typo

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shut marsh
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Which of the following is an equivalent expression to 8 · (1 + 0.10)^2x?

64 · (1.1)^x
8 · (2.2)^x
8 · (1.21)^x
16 · (1.1)^x

shut marsh
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ping when answered

shadow aspen
shut marsh
shadow aspen
shut marsh
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(1.21)^x?

shadow aspen
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ye

shut marsh
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so its c

shadow aspen
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ye

shut marsh
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thank you

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eager junco
final saddleBOT
eager junco
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Would the solution from a - c be correct?

fallow wren
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it is all almost correct

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however the last set is not a basis (they are not linear independent)

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just delete one (0 1 0)

eager junco
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and for part d it isnt invertible i believe

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since each row and col doesnt have a pivot

fallow wren
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invertible iff linear+ one to one

eager junco
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so its not?

fallow wren
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but is not injective because ker is not only {0}

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yes it isnt

eager junco
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ok, i had two more similar questions i wanted to check

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mostly concerned with part e and if i am doin is right

fallow wren
eager junco
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what do you think?

fallow wren
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i don't understand the first very step

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have you done R2=R2-2R1, have you?

eager junco
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r2 = r2 - r1(2)

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to get REF

fallow wren
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i get these figure

eager junco
# fallow wren

sorry i forgot to include another step there: r2/-3 and thats how i got:
1 - 1 1 1
0 -1 1 0

fallow wren
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oh ok

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then i think you can solve the simplified system ..but then you have to do all your raw transformation backward, so that you get the solution for the original system

eager junco
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isnt that what i did?

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basically what im asking for is that: are my steps for step e correct?

fallow wren
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i don t see the -3 factor nowhere

eager junco
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except that lol

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is the solution correct

fallow wren
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your final vector is (3, 4, 4), why did you write (1 1 1)

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?

eager junco
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where are you getting (3,4,4) from

fallow wren
eager junco
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i dont see 3,4,4

fallow wren
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because you are not doing the sum..

eager junco
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[x,y,z] = [1,z,z] + z[1,1,1]

fallow wren
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ah they are z's

eager junco
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yes...

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i solved for it above

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are you sure you know how to do this?

fallow wren
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no 😭

eager junco
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can you ping maybe one of your more advanced helpers for this topic?

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I just need to know if im doing this right

fallow wren
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i can learn the method in 1 min

eager junco
fallow wren
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ok i got it

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this claim that i said is false "....but then you have to do all your raw transformation backward, so that you get the solution for the original system"

eager junco
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ok i also realized i kinda did it wrong

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it should be [x,y,z] = [1,z,z] + z[0,1,1]

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not [x,y,z] = [1,z,z] + z[1,1,1]

fallow wren
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so you have only to reduce your matrix to a scale matrix

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then solve the last matrix equation and that is your solution

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these are two simply solution you can get from the last system

eager junco
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i dont understand

fallow wren
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do you agree with me that the orange vectors are solutions for the last system ?

eager junco
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im not sure how you got [ 1 1 -1]

fallow wren
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i just solve visually the equation -y+z=0

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these equation are pretty simple

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to get the last two numbers of (1 1 -1)

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how ever you can view that these are in fact solution

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lol

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i m just tired

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i mean (1 1 1)

eager junco
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uhh

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yea im lost

fallow wren
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@hybrid heath can you help this kind guy?

hybrid heath
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no time, sadly

fallow wren
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😭

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and i have no energy

eager junco
fallow wren
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yes is correct but you have give no reason for thso

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and they ask you a basis (not tthe span of that basis)

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so because dim(range)<=2

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just give two vector lineary independent vector in the range 🙂

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now i must go

eager junco
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i thought you only give vectors when its not onto

fallow wren
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they ask you a basis ... stop... R^2 is not a basis

eager junco
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oh ok but 2 of the original matrix vectors not the RREF ones

eager junco
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fluid isle
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can anyone tell me how the equation became this? i think my prof did the work in his head

worldly vale
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distribute the x^(-1/3)

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(a+b)c = ac + bc

fluid isle
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oh im dumb af

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why didnt i think of that

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thanks

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what about this?

worldly vale
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what precisely

fluid isle
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how did the equation = (integral)x^1/3dx + (integral)x^4/3dx

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let me show the whole thing

worldly vale
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what is $x^{\frac13}\cdot x$

soft zealotBOT
fluid isle
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oh x^4/3

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i didnt see that x

worldly vale
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yea

fluid isle
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on the right of x^1/3

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my fault

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thanks

final saddleBOT
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jagged abyss
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I’m just totally confused here

final saddleBOT
mortal wadi
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so you want to find out the factored form

jagged abyss
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Ye

mortal wadi
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write down the general form

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that is shown in the pic

jagged abyss
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The standard form?

mortal wadi
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sure

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wait

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no

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above that one

jagged abyss
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What’d I use to fill in the s, r and a constants?

mortal wadi
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okay so you have
y = a(x-r)(x-s)

jagged abyss
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Ye

mortal wadi
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what does it mean for the zeros to be x = -5 and x = 3?

jagged abyss
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That the value of x and is equal to them?

mortal wadi
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not quite

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the zeros of a quadratic are when y is equal to 0

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so when x is -5

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y = 0

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and when x = 3

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y = 0

jagged abyss
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O so they’re the x intercepts

mortal wadi
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yes

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now notice in our factored form

jagged abyss
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And 2,56 would be the vertex?

mortal wadi
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that part is for a bit ahead

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but notice in the factored form

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we have y = a(x-r)(x-s)

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when x-r = 0

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the entirity of the right hand side is equal to 0 because they are multiplying by 0

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so we get y=0

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yes?

jagged abyss
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Ye

mortal wadi
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and the same for x-s

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is that clear?

jagged abyss
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Ye

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So the equation would start off with 0=, in place of the y=?

mortal wadi
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not quite because that wouldn't help us

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if we did 0 = a(x-r)(x-s)

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it would be like us trying to find the values of x

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that are zeros

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which we already know are -5 and 3

jagged abyss
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Oooo

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It’d be like -5-r=0

mortal wadi
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kind of

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so the factored form contains the information of the zeros

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in these x-rand x-sparts

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and we already know the zeros

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so we can conclude what the r and s values are

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which ends up being

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what you just said

mortal wadi
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gives you the value of r

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and similarly for s

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but with the 3

jagged abyss
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So the r is 5?

mortal wadi
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yes

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so now filling out the factored form with the updated information we have
y = a(x+5)(x-3)
yes?

jagged abyss
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So far I understand it being y=a(-5+5)(3-3)

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Or that ye

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Forgot about the point of (2,56)

mortal wadi
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now we use the (2,56) information

jagged abyss
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The x values would be 2 and y=56

mortal wadi
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exactly

jagged abyss
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What about the a

mortal wadi
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well

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now you solve for a

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when x= 2 and y = 56

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56 = a(2+5)(2-3)

jagged abyss
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A=-8?

mortal wadi
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by replacing x and y with 2 and 56 we are finding out the a value that allows for the point (2, 56) to be on the quadratic

mortal wadi
jagged abyss
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This seem right?

mortal wadi
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eehhh

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not quite

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remember we want it to be an equation

jagged abyss
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Do I have to minus the 56 to the other side?

mortal wadi
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no, we just don't put any value for x and y

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y = -8(x+5)(x-3)

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is just the equation in factored form

jagged abyss
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O Alr

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It was correct

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Ty

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Sorry I was being slow, i over think a lot

mortal wadi
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no worries

jagged abyss
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Have a good day

mortal wadi
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you too 🙂

jagged abyss
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split quiver
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I need help with the ambiguous case

I solved it, and one of the angles were 153...which seems wrong

then I move the line and...153 + 153 isnt less than 180...

split quiver
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(sorry cam sucks like garbage)

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Basically angle a was 153

I did sine law

sin C / 24 = sin 16 / 17

17 sin 16 / 24 = sin C

C = about 11

so 11 angle and 16 angle...take that away from 180 is 153...

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then i move the arm side ways...which makes the isoceles triangle that i remove from the triangle, which is 153 and 153...

unreal anvil
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sinC/24 = sin16°/17

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sinC=24*sin16°/17

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i think that's the part you did wrong?

split quiver
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how did i miss that

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open heath
final saddleBOT
open heath
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I don't get why the force of 33.23 results in a negative moment

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They're both positive forces

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My teacher said to follow the line of action but I don't get what that means

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that's the question

final saddleBOT
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@open heath Has your question been resolved?

open heath
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<@&286206848099549185>

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bold finch
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Hey so I have this problem where I have to figure out the possible amount of time this people can spend in a room, and ill have the question below

bold finch
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I found out that after the fee, they can spend up to 5 hours exactly to not go past their 63.50 budget, but would I say less than or equal to? or just less than

tired walrus
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well

vestal sentinel
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well can they rent it for 5 hours exactly?

tired walrus
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^

vestal sentinel
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and still be within budget?

bold finch
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it turns out exact but the wording I don't understand

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because it says less

vestal sentinel
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...hm, yeah that's true. weird wording

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because in mathematical terms...that is they want to spend $63.49 or less
but in normal conversation terms, that's $63.50 or less

bold finch
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I don't get it

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so did I choose the correct symbol or should I switch it

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in your opinion

vestal sentinel
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I think because it happens to be exact, then they mean $63.50 or less

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so then it would be t <= 5

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it would be very very strange for them to write this question to have exactly $63.50 but actually they want you to assume the film company has a budget of $63.49

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lol

tired walrus
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it says the film club wants to spend LESS THAN 63.50

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they don't want to spend all of their 63.50

bold finch
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so I should remove the equal sign then?

vestal sentinel
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if someone says they have a budget of $10 and you offer them a solution for $10.00 they would not say "oh sorry I can only spend $9.99"

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this question is written very badly.

livid ice
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They would say "no more than"

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If it was not strict

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Or some other similar phrasing

tired walrus
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this is news to me

bold finch
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i'm still confused so what are you guys saying

livid ice
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If it just says "less than" you assume it's stated correctly as a strict inequality

vestal sentinel
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"I want to spend less than $20" is "where x <= 20" in english even if "less than 20" directly means "x < 20"

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two people saying that it's a strict inequality and just me on the <= train - I'd assume it's therefore meant to be a strict inequality

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I hate this question though

livid ice
worldly vale
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I agree with you in informal English we'll say less than to mean "less than or around x" but in a maths question you would expect the language to not depend on colloquialisms

vestal sentinel
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I would expect a maths question to not be written such that these misunderstandings can happen

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like give the film club $64 or something.

livid ice
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Let's just all donate 5 dollars and forget about the question

bold finch
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I have another question I think it's simple enough but maybe not

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basically just fine the area, did I calculate the sides correctly of these two rectangles to get the area of the two?

livid ice
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Looks good to me

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You split them up appropriately

bold finch
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alright thanks for confirming

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bold finch
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can someone explain to me how to solve this question?

bold finch
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it seems just all bunched up

tired walrus
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do you know exponent laws

bold finch
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so when multiplying exponents you just multiply them? for exmaple v^5 times v^2 would be v^10?

tired walrus
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no

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would you like to have it explained to you why v^5 * v^2 = v^10 is nonsense?

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or would you like to think about it yourself first

bold finch
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oh I think I was confusing it with this:

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if the v^5 was in parenthesis then if you multiply it by 2 then I think it would turn to v^10

tranquil pine
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no

tired walrus
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$(v^5)^2$ would simplify to $v^{10}$ yes.

soft zealotBOT
bold finch
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yea so I had it confused so that means you just add it I think?

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so v^2 times v^5 would be v^7?

civic mulch
bold finch
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ok so then let me try to solve it and you can tell me if I just missed or maybe got some of it right

tired walrus
final saddleBOT
tired walrus
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ping me i guess

bold finch
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@tired walrus

tired walrus
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how did $10y^5 + 3v^7$ happen?

soft zealotBOT
tired walrus
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$10 says it's a misapplication of the "you add it" phrasing.

bold finch
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oh do you not add the 1

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wait

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if it doesnt have an exponent what do you even do then?

tired walrus
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imo you should not try to think in terms of "you do this" or "you do that"

bold finch
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for example 2y times 5y^4

tired walrus
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like here you have a product of several things: $$3 \cdot v^2 \cdot 2 \cdot y \cdot 5 \cdot y^4 \cdot v^5$$

soft zealotBOT
tired walrus
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do you understand this is what you are starting with?

ONLY say yes or no, don't attempt to do anything else with it until i tell you to.

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@bold finch

bold finch
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one second i'm thinking

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no

tired walrus
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do you understand that 3v^2 means the same thing as 3 * v^2?

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Y/N

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(again dont try to jump ahead)

bold finch
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oh i see

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yes

tired walrus
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ok right

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do you understand the prev point then?

bold finch
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yes but is that just font issue

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or on purpose

tired walrus
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font issue?

bold finch
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yea why not keep it together with the variable

tired walrus
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well heres what im gonna do next:

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in this product you have some raw numbers, some y's and some v's.

#

because multiplication is associative and commutative, you can reshuffle them as follows to organize them by ``type'': $$(3 \cdot 2 \cdot 5) \cdot (v^2 \cdot v^5) \cdot (y \cdot y^4)$$

soft zealotBOT
bold finch
#

ok so you separated all like terms into parenthesis

tired walrus
#

it's not quite "like terms" but the idea is somewhat similar yes

#

the parentheses here don't serve any purpose beyond visual organization

bold finch
#

ok so now that you've organized it whats the next step?

tired walrus
#

well now look at each parenthesis separately

#

what does 3 * 2 * 5 simplify into

bold finch
#

30

tired walrus
#

right

bold finch
#

?

tired walrus
#

what does v^2 * v^5 simplify into?

bold finch
#

oh ok

#

v^7

tired walrus
#

right

#

and finally what does y * y^4 simplify into?

bold finch
#

i'm not sure

tired walrus
#

then let's think about the meaning of exponents

#

when you first learned exponentiation, how was it introduced to you?

bold finch
#

It's blurry

#

but what mostly confuses me is there being no exponent at all

#

is it a one or perhaps just nothing

#

idk

tired walrus
#

well no, let's go over it again.

#

so that you don't just learn a special exception for how to treat an exponent that's not there,

#

but understand WHY it's treated that way

#

it is most likely you have been taught that exponentiation is repeated multiplication (in the case that the exponent is a positive integer, which for us they are)

#

so x^8 is the product of eight copies of x

#

a^3 is the product of three copies of a

#

a^3 = a * a * a

#

and so on

#

does this ring any bells?

bold finch
#

yes now that you mention I know all of this, I just don't know what to do in a situation where it's missing an exponent to begin with

tired walrus
#

well now let's think

tired walrus
#

what is y^4?

bold finch
#

four copies of y

#

all multipied

tired walrus
#

right.

#

the product of four copies of y.

#

what happens when we multiply that by another y?

bold finch
#

Y^5

tired walrus
#

lowercase y

#

but yes, exactly

bold finch
#

so whats next?

tired walrus
#

bring it all together

#

3 * 2 * 5 simplified into 30
v^2 * v^5 simplified into v^7
y * y^4 simplified into y^5

bold finch
#

so basically you should treat "y" as "y^1" similarly to how you should treat "x" as "1x" ?

#

also I would have never thought to separate everything

tired walrus
#

i don't like such "should"-statements.

bold finch
#

what?

tired walrus
#

"you should treat this as that and this as that"

#

i don't like such statements

#

lone y can be thought of as y^1, if viewing it like that helps you.

bold finch
#

ok so would this be the correctly final answer?

tired walrus
#

yes, but i have an issue with the way you handwrite the digit seven.

bold finch
#

but I had another question

#

does it matter how I order it?

tired walrus
#

order what?

bold finch
#

my solution

tired walrus
#

do you mean like 30 v^7 y^5 vs. 30 y^5 v^7?

bold finch
#

yes

tired walrus
#

no, it does not matter. unless you're the kind of person who hates the commutative law of multiplication, which i don't think you are.
raw numbers usually go at the front though.

bold finch
#

alright

#

so can I ask a theoretical question now

#

I'

tired walrus
#

sure

bold finch
#

I'll actually write it down it'll be easier to see that way

#

what if it asked this

#

and asked to simplify

tired walrus
#

there would be nothing to do, this is already as simplified as it gets.

#

this is a sum of four unlike terms,

#

and there doesn't look to be any kind of clever factorization that could be done

bold finch
#

and for this one it also wouldn't matter what order it was in?

#

for some reason I remember having to order something similar like this from highest exponent to lowest

tired walrus
#

as in there was an instruction to order from highest to lowest exponent?

bold finch
#

I'm not sure I think if I typed in the answer any other way it would count it wrong

#

but I doubt they would ask me this anyways.

tired walrus
#

ok so it is an imagined thing

#

so like, ok

#

polynomials in general are usually presented with their terms organized from highest to lowest exponent.

#

however it's just that, organization

#

for example 7x + x^2 + 11 and x^2 + 7x + 11 aren't different polynomials, and one is not a priori more "correct" than the other.

bold finch
#

ok I have another question if you don't mind.

tired walrus
#

sure

bold finch
#

This time I have to evaluate a problem Ill send it

#

so when you first look at this what's the first thing you think of doing? for me it was taking care of the (-2)^3

#

but I'm not sure if thats the right step

tired walrus
#

it's a fine step

#

what jumps out at me personally is that and also the 5*3

#

independently of each other

#

doesn't really matter which of those operations you do first

bold finch
#

ok let me try to write down what I have so far

#

so far I have it down to this:

tired walrus
#

yeah that's fine, keep going

bold finch
#

should I distribute the "-" sign outside the parenthesis to the -8 and -4?

tired walrus
#

definitely not

#

especially because that ^2 is in the way

#

you should calculate inside the parentheses

bold finch
#

wait can you clarify more on how the exponent gets in the way

tired walrus
#

$-(a)^2 \neq (-a)^2$

soft zealotBOT
bold finch
#

so whenever a parenthesis has any type of exponent outside of it, you cant distribute?

#

unless it's a number with an exponent?

tired walrus
#

distribution is specifically for stuff that looks like a * (b + c)

#

i.e. something multiplied by a sum (or by a difference)

#

like, that is the content of the distributive law

bold finch
#

ok. I'll try to proceed with the problem can you let me know if I get it right

tired walrus
#

sure

bold finch
#

here is my solution:

#

@tired walrus

tired walrus
#

yeah seems fine

bold finch
#

ann I have another question if you don't mind

#

this is the problem:

#

I'll try to solve it

#

is this a valid solution:

#

is this valid? <@&286206848099549185>

fleet pewter
#

Yes

tired walrus
#

yeah sure it's ok

#

does exactly what they ask you to do

bold finch
#

wow you can go a long way when you know the exponent rules

#

thanks for confirming

#

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pearl roost
final saddleBOT
pearl roost
#

i need helping proving that second statement

#

but i don't really see a way to build up the induction

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#

@pearl roost Has your question been resolved?

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@pearl roost Has your question been resolved?

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@pearl roost Has your question been resolved?

jaunty mantle
#

@pearl roost still need it?

vital crag
final saddleBOT
# jaunty mantle

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

jaunty mantle
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#

@pearl roost Has your question been resolved?

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opaque scroll
final saddleBOT
opaque scroll
#

why is F_b not $R_2^3-R_1^3?$

soft zealotBOT
#

lily9369
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

formal trail
#

bouyant force only depends on the volume of water displaced. that doesn't depend on whether the object is hollow or not

#

(if this wasn't the case then most boats wouldn't be able to float at all!)

opaque scroll
#

oh ok makes sense

#

ty

#

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acoustic birch
final saddleBOT
acoustic birch
opaque scroll
#

dont know it by name, but im learning the entire topic rn

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celest valley
final saddleBOT
celest valley
#

how to solve this one?

final saddleBOT
#

@celest valley Has your question been resolved?

celest valley
#

.ckose

#

.close

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wraith summit
final saddleBOT
wraith summit
#

what is the result of this sum if you know that the limit of f(n) is 5

#

I said that it was f(12) - 5 , cause this is a mengoli series

#

and p = 1

#

so i got f(4x3) - 1 x lim f(n) = f(12) - 5

#

But we cant find out the value of f(12) right ?

final saddleBOT
#

@wraith summit Has your question been resolved?

hybrid heath
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plush mason
#

it makes not sense

final saddleBOT
tranquil pine
#

which part you don’t understand?

plush mason
solar glade
#

Which part?

plush mason
solar glade
#

What is bigger. 2sqrt(n) or sqrt(n) + sqrt(n+1)?

tranquil pine
#

$\sqrt{n+1}-\sqrt{n}=\frac{(\sqrt{n+1})^{2}-(\sqrt{n})^{2}}{\sqrt{n+1}+\sqrt{n}}$

soft zealotBOT
tranquil pine
#

is the issue with this?

plush mason
#

what about the 2

tranquil pine
plush mason
#

thanks for help !!

final saddleBOT
#

@plush mason Has your question been resolved?

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dense garnet
#

Find the Fourier series of $h(t)=e^{3it}f(t-4)$, when $f$ has period $2\pi$ and satisfies $f(t)=1$ for $|t|<2$, $f(t)=0$ for $2<|t|<\pi$.

soft zealotBOT
#

Philip

#

Philip

dense garnet
#

From this, the coefficients of $h(t)$ should be $(e^{-i(n-3)4}c_{n-3})$, right? so I need to find $(c_n)$.

soft zealotBOT
#

Philip

dense garnet
#

.close

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fallow wren
#

let f a real increasing function s.t. f(f(x))=x, what is f?

fallow wren
#

i want to prove that f(x)=x is the only solution

#

there is also f(x)=-x but it is not incrising

#

@desert mantle

fresh relic
#

Pick arbitrary x, and set y = f(x). Then if x < y, is f(x) < f(y)?

fallow wren
#

mhh..

#

interesting

#

f(x)<f(y)=x

#

but now just apply f to both sides

#

we get

#

x<f(x)

fresh relic
#

you've already gotten a contradiction

fallow wren
#

so f(x)=x

#

true

#

gg thank you mate

fresh relic
#

the y < x case is similar

fallow wren
#

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tranquil pine
final saddleBOT
tranquil pine
#

Why is it when I do the equation, I get for (a) -125

#

But in thousands it would be -125k?

final saddleBOT
#

@tranquil pine Has your question been resolved?

shadow tartan
tranquil pine
#

How would I find out maximum possible annual profit

#

100k?

shadow tartan
#

That is the highest point on the graph

tranquil pine
#

Fair enough

#

Thank you

#

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strange crag
#

Hello,Could you help with that?

final saddleBOT
strange crag
#

Chat gpt responds strangely and photomath doesn't solve it

tired walrus
#

!nogpt

final saddleBOT
#

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

tired walrus
#

anyway

#

what do you think happens with (4-sin(x))/(1+sin(x)) at infinity?

strange crag
#

uncertainty?

tired walrus
#

wdym by "uncertainty"

tawny halo
strange crag
#

yeah

#

I use a translator as my English is very bad.

tawny halo
#

She can speak Russian fr

strange crag
tawny halo
#

1/x⁵ what is it

#

Will be equal

tired walrus
#

incorrect

tired walrus
strange crag
tawny halo
tired walrus
#

for the record

tawny halo
tawny halo
tired walrus
#

now you do

#

anyway the trig fraction doesn't have a limit

#

(ie its limit doesn't exist)

#

brb

tawny halo
#

Somehow

strange crag
# tired walrus now you do

In general I divided by the higher degree this is x and sin are annihilated and as a result it turns out 4x/1x=4+0=4.

#

but I'm not sure it's right.

tawny halo
#

No way

tired walrus
#

......

strange crag
#

)

tawny halo
#

You can't touch this x in sinx

tired walrus
#

this is x and sin are annihilated
this does not make any sense

tawny halo
#

Короче, это не существует

#

Ты же сам сказал в самом начале

tawny halo
strange crag
#

Я был не уверен в своих ответах

tawny halo
#

undefined-неопределен
D.N.E Does not exist - не существует

strange crag
#

там я поделил дробь на икс и ответ совпал с photomath

tawny halo
#

Там х к чему стремился

strange crag
#

infinity

tawny halo
#

Странно

#

Скинь предыдущий как фотку

strange crag
tawny halo
#

мне кажется, это тож не существует

strange crag
#

Но mathway и photomath выдают ответ

#

такой же как и у меня

#

1/2

tawny halo
#

Ah

#

Makes sense

#

If you take out x

#

You'll get sinx/x

#

Есть же вот эти

#

Замечательные пределы

#

Без них бы не решалось

#

А так да решаемо

strange crag
tawny halo
#

Да они уникальные

#

Короче, когда х->∞, то sinx/x=0

#

А если стремится к 0, то sinx/x=1

tawny halo
#

Вытащив x

#

Попробуй

#

Ой

#

Там +

#

Внизу

strange crag
#

(4/x)/(1/x)=4

tawny halo
strange crag
tawny halo
#

Не

#

Тут получается 0/0

tawny halo
#

Погоди

#

Хотя да

#

4

#

x сократить

#

Будет 4 indeed

#

Так что ответ 4?

tawny halo
strange crag
#

Такое же мнение было до того как нашел этот сервер)

tawny halo
#

Ну короче да

strange crag
#

Okay, thank you very much for the explanation and help.

tawny halo
#

Да мы ниче не сделали

tawny halo
#

Вот это просто уже доказано

#

Поэтому нужно было просто тут использовать

strange crag
#

You've explained and spent your time + you're using a translator which is a huge favour.

#

So thanks anyway.

tawny halo
#

Не

#

Я русский знаю

#

🙂

strange crag
#

а

#

понял

#

.close

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sacred lynx
#

with some money people are trying to buy some tons of sugar but then the sugars price went up by 25% and with the same amount of money they bought 1 ton less sugar how many tons did they buy

sacred lynx
#

<@&286206848099549185>

#

<@&286206848099549185>

#

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crystal pine
#

hi

final saddleBOT
crystal pine
#

this should be correct right?

#

the left limit does not exist ig

tawny halo
#

No way you did it

#

:/

crystal pine
tawny halo
#

i think it's illegal to split

#

We can do it only if + or -

#

Am i gay or am i Right

tawny halo
crystal pine
#

it should be valid for multiplication too

tawny halo
#

Answer is correct ig

tawny halo
tawny halo
#

Dunno

crystal pine
#

hm

deft ravine
green arch
#

separe $\frac{4}{x^2}\cdot cos( \frac{\pi x}{2} )=\frac{4}{x} \cdot \frac{cos( \frac{\pi x}{2} )}{x}$ and recall that $\lim_{x\rightarrow \infty} \frac{cosx}{x}=0$

crystal pine
soft zealotBOT
deft ravine
crystal pine
#

dass du deutsch sprechen kannst

#

deutschsprachig

#

so

deft ravine
#

Ok. Wie schon gesagt, kannst du das nicht splitten, weil der eine GW nicht existiert.

crystal pine
#

hmh

deft ravine
#

Du kannst aber benutzen, dass -1 <= cos u <= 1 für alle u gilt und dann das Sandwich theorem benutzen

crystal pine
#

höre ich gerade zum ersten mal ig

#

tbh ich bin halt noch in der "10" und kenne mich nicht breitgiebig damit aus

#

wills aber lernen sadcatthumbsup

deft ravine
#

Der sagt quasi falls f <= g <= h für Funktionen oder wahlweise auch Folgen gilt und f,h konvergieren gehen eine konstante c. Dann muss auch g gegen c konvergieren

green arch
deft ravine
#

Und f,h sind dann quasi die Brotscheiben bei unserem Sandwich und g ist das dazwischen

crystal pine
deft ravine
crystal pine
#

passt sadcatthumbsup

deft ravine
crystal pine
#

Bin 07 wenn du das meinst was ich denke xd

#

ja sollte es sein

#

"geburtsjahr"

#

2007

deft ravine
#

Nur so. Habe nicht nachgedacht, dass du in der 10 logischerweise ein bisschen jünger bist. Dachte wir sind annähernd gleich alt

crystal pine
#

Ne, "Mathe Student" in der Bio

deft ravine
crystal pine
#

.close

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sacred lynx
#

In a isosceles trapezoid the diagnal splits the sharp corner into two equal parts the big side is 18 and the perimeter is 48 need to find the trapezoids middle line

lucid parrot
#

wdym by sharp corner

#

@sacred lynx

sacred lynx
#

idk how to say it in enlish

lucid parrot
#

oh

#

which language are you speaking

sacred lynx
#

like 90 degrees is a right corner and less then that

lucid parrot
#

oh riiight

#

okay

#

so its an angle less then 90 degrees

#

and by big side
is it like the side of the trapezoid which is at the bottom

sacred lynx
#

i did it its ok

#

.close

final saddleBOT
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lunar forum
final saddleBOT
lunar forum
#

am i missing something with this integral

#

i dont know where the 1- comes from

#

i get its an improper integral

tulip coyote
#

Integrating and evaluating e^{-2st} between the given limits

lunar forum
#

im a moron

#

been reading too long sorry

tulip coyote
#

Does happen catThimc

lunar forum
#

hah thanks it makes a bit more sense now

#

.close

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final saddleBOT
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sonic crescent
#

how do you do these, i forgot

final saddleBOT
sonic crescent
#

i got 71.08

dense coral
#

show what you did

sonic crescent
# dense coral show what you did

used SOH CAH TOA

tan theta = opposite over adjacent

tan theta = 5 / 7
atan(5/7) = theta
theta = 0.620249486 rad
0.620249486 rad = 71.08 degrees

tired walrus
#

hold up

#

how did that last conversion happen?

dense coral
#

the radian to degree conversion is not correct

sonic crescent
#

for the last step i did
(0.620249486 / pi) * 360

tired walrus
#

180 not 360

sonic crescent
#

i thought that was the formula woops

tired walrus
#

a circle is 2pi radians not 1pi

#

1 radian is 57 and change degrees

sonic crescent
#

oo okie, i see now!!
i have not studied this stuff in a while and i am going off of memory

#

thank you both

#

.,close

#

.close

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worldly bough
#

is this sheet correct?
Does 0 to the power of Complex infinity equal 0 or is it indeterminate ?

worldly bough
#

Wolfram's forum or something

rapid sky
#

It probably depends on the limit you use to do it.

worldly bough
#

bruh

#

I'm using no limit

final saddleBOT
#

@worldly bough Has your question been resolved?

final saddleBOT
#

@worldly bough Has your question been resolved?

worldly bough
#

<@&286206848099549185>

final saddleBOT
#

@worldly bough Has your question been resolved?

final saddleBOT
#

@worldly bough Has your question been resolved?

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shell plover
#

Friend sent me this problem. Only doing part A and B. Idk what to do because it is asking for the applied force one part A but the answer is the friction and idk how they got 103N ever. They never mention any acceleration either

shell plover
#

Pls ping if yk how to do it

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#

@shell plover Has your question been resolved?

brisk charm
final saddleBOT
#

@shell plover Has your question been resolved?

shell plover
#

did everything

#

but asnwer is never 103

brisk charm
#

Can you show your work

shell plover
#

gimme like 15min

final saddleBOT
#

@shell plover Has your question been resolved?

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brazen breach
#

don't occupy multiple channels

#

oh wait

#

you closed all of them

#

The server must be lagging

tired walrus
#

|A+B| is not equal to |A|+|B| so that just does not work at all

#

what do you mean?

#

determinant is product of eigenvalues

#

so find the eigenvalues of A^100

#

then those of A^100 + I

#

yes

cosmic warren
#

Find the eigenvalues of I + A^100

#

If A^100x = lambda*x then (I + A^100)x =?

white shard
#

This is somewhat correct. The values |1 + lambda^100| that you computed don't need the absolute value.
Can you see why?

#

Why do you compute these values and than multiply them?

#

No, it was a leading question, but I'll elaborate:

The eigenvalues of I + A^{100} are the values 1 + lambda^{100} for lambda an eigenvalue of A, without any absolute value.

The notation |X| for the determinant of a matrix X might be confusing you in thinking there should be absolute value somewhere.

#

Yes, so the eigenvalues of I + A^{100} are 1 + 1^{100}, 1 + (-1)^{100}, 1 + 0^{100}, which are 2,2,1 as you wrote, and the determinant of I+A^{100} is indeed their product which is 4. You just don't need the absolute values.

final saddleBOT
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eternal zinc
final saddleBOT
eternal zinc
#

,rotate

soft zealotBOT
eternal zinc
#

Very confused

cunning glen
#

Use trig identities to simplify, something like sin(x) = sin(pi-x), similar ones like this

rapid sky
final saddleBOT
# eternal zinc Very confused
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
eternal zinc
#

Number 1

lyric summit
#

plus, eventually, periodicity

eternal zinc
#

Well we can use that

rapid sky
#

Well, the first step is to notice that the tangent argument is over 2 pi.

#

So, subtract 2 pi from it until you get something under 2 pi.

#

The other ones are fine.

eternal zinc
#

Hm

rapid sky
#

So, what is 5 pi/2 if you put it between 0 and 2 pi?

eternal zinc
#

2.5

rapid sky
#

No.

#

What's 5 pi/2 - 2 pi?

eternal zinc
#

Ah

rapid sky
#

Well, I guess you can do it that way.

eternal zinc
#

5pi/2 - 4pi/2

rapid sky
#

You meant 2.5 pi.

#

You subtract 2 pi from that to get 0.5 pi.

eternal zinc
#

Yes

rapid sky
#

OK, so what is the tangent of pi/2?

#

If you don't know, what is sin(pi/2)/cos(pi/2)?

eternal zinc
#

Tan = sin/cos?

rapid sky
#

Yes.

eternal zinc
#

hmm

#

Ahh

#

So like I do it instead of a fraction

rapid sky
#

I'm not sure what you mean.

eternal zinc
#

Wait its irrelevant

#

Its more confusing

#

Ah combine like terms

rapid sky
#

What do you mean with like terms?

eternal zinc
#

Then we divide it?

rapid sky
#

There shouldn't be a polynomial or anything.

#

Did you find tan(pi/2)?

eternal zinc
#

,rotate

soft zealotBOT
rapid sky
#

OK, what's sin(pi/2)?

eternal zinc
#

Sin(90)

rapid sky
#

Which is what?

eternal zinc
#

1

rapid sky
#

OK, what's cos(pi/2)?

eternal zinc
#

0

rapid sky
#

OK, so tan(pi/2) = sin(pi/2)/cos(pi/2) = 1/0.

#

So, it's undefined.

eternal zinc
#

Undefined

rapid sky
#

Right, so that's the answer for the whole problem.

eternal zinc
#

So thats why ive been racking my brain on a sjngle problem for the past hour

#

My 1st answer was 8 then it turned into decimals

#

.close

final saddleBOT
#
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tranquil pine
final saddleBOT
tranquil pine
#

How do I solve

rich tide
#

are you aware of the legendary pythagoras theorem?

tranquil pine
#

yes

rich tide
#

can you apply it on this triangle?

tranquil pine
#

Yea

tired walrus
#

then do it

rich tide
tranquil pine
#

a^2+b^2=c
6^2+8^2=c^2

#

Sorry my computer died

rich tide
#

may it rest in peace

tranquil pine
#

😐

rich tide
tranquil pine
#

Alr

#

Sorry how do I do that I’m looking at an example and I’m confused

rich tide
#

can you write 6^2 as a two digit number?

tranquil pine
#

Yea

#

12

#

Ohh

rich tide
tranquil pine
#

I’m dumb

#

Myb

#

12+16=c*2

#

C^2

rich tide
tranquil pine
#

What is is not right

rich tide
#

can you EXACTLY state the pythagoras theorem?

tranquil pine
#

Bro idk what ur saying ur talking in emojis

#

I told u I didn’t know how to simplify it further

rich tide
#

Like what I asked and what you responded

#

I asked you to write out the pythagoras theorem and STATE IT

tranquil pine
#

Ok then say that

final saddleBOT
#

@tranquil pine Has your question been resolved?

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#
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final saddleBOT
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tranquil pine
final saddleBOT
tiny gorge
#

well two of the faces should be very easy as they are rectangles