#help-36
1 messages · Page 57 of 1
Or more like
A property of its curve representation
The function is a process, not a curve
The curve is just a certain representation of the function itself
And in order to interpret it geometrically, a geometrical representation is needed
Which is why we talk about the graph of the function
so how would i obtain a geometrical representation of say this function?
It's defined analytically, with a function, but the object is the set of points (x,c(x)) in the plane constituted of all the (x,y) points
Hmmmmmm
Plotting ?
It would not be accurate for sure
Ah alright
Yeah i guess i could just use the fact that c(x) = c(-x)
"explain this geometrically" is basically "explain how this relation translates in a geometrical level on the curve of the function c"
So if you talk about a reflection along the y axis, I think you get all the points
Which in this case would be a reflection which was proved by the fact that c(x) = c(-x)
Right?
Yup
If you want to compare it with the general case
The curve of a function f has an axis of symmetry of equation x=a iff for all x, f(a-x)=f(a+x)

So the general idea is that if a function c(x) is equal to c(-x) that proves that the function is symmetrical and it can be reflected over x=0
I'm gonna accept this one but x and c(x) are numbers, c is a function,
Other than what I mentioned this is perfect you know
Good job !
But im just a bit confused on this part, isnt the "looks identical part" the important part because can't any function be reflected across the y axis? Is there more specific terms?
Sorry u may have answered this before im unsure could u explain it one more time?
Reflection. That's the specific term. And not every function f have the property f(x)=f(-x), thus not every function has a reflection along the y axis. For example, f(x)=(x-1)² is centered at x=1, and not at x=0
Oh so "has a reflection" essentially says that it looks identical when reflected.
The function f(x)=x doesn't even follow that property anywhere
Don't take "has a reflection"
Apart from
The actual reflection
"a reflection along the x axis"
That's the actual reflection
Yep
Now
Let's say, we can see "looks identical" as an undefined term in maths basically
It is either identical or not
Oh okay sure, ill just use reflection across x=0
Yes, that's the geometric property of ... what already ?
What is reflected across x=0 ?
C(x)?
It's still a number, has always been
isn't c(x) reflected across x=0?
"Isn't 3 reflected across x=0 ?", that's an equivalent of what you just said
What you are saying doesn't make sense
c(x) is a number, not a geometric object
Then the geometric representation of c(x) has reflection over the line x=0?
Almost there YES !
c(x) is a number
I still don't know what is the representation of a number in a plane
A point, sure
A number, no
Oh wait
It's just that tiny bitty thing you have to change
Really, just 3 characters that have to be deleted
Is it the geometric representation of the function C has a reflection over the lime x=0?
Np np 
Helped me a lot hahah
"the line of equation x=0"
But you did the hardest
Yeeeeeeeessssssssss
It's such a thing students hardly understand
I'm actually so glad you did
Yeah ur a great helper ngl
Just curious what r u studying in math?
@rare marlin Has your question been resolved?
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Yeah
When discriminant = 0 it has "1" root
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im not sure how to do B
same thing but you plug in (1+h) where x goes.
wait so the x is 1 and then i plug the x into the h?
what?
so for example you did f(2) = 7 - (2)^2 for the first part for f(2)
same exact thing, but instead of 2, you plug in (1+h).
ohhhhh ok
its okay to have h in the answer if they don't notate a limit. if its still wrong then they expect you to find it when h = 0.
generally, you never want to just make h = 0 until after you've found the simplified expression.
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hellp
!da2a
No need to ask "Can I ask...?" or "Does anyone know about...?"—it's faster for everyone if you just ask your question! See https://dontasktoask.com/
huh?
read
this
@blissful pelican Has your question been resolved?
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how can i solve this
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help

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im not sure how to do this
are you familiar with properties of logarithms
yea kinda
how would you simplify $y \log_b x$ or $\log_b x + \log_b z$
LordNwahs
umm i think wouldnt it be like logb^(x * z)?
how about $y \log_b x$
LordNwahs
yep
just apply those properties to get the RHS to some expression $log_b (something)$
LordNwahs
wait then do u multiply the 2/3 and 1/2 together then?
no?
wut
how do you simplify $2/3 \log 27$
LordNwahs

^
logb27^2/3
yes... and what is 27^(2/3)?
3^2
o
yep!
okeee thanks :D
cheers
i got 3 🫣
yep looks good to me
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is this right?
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Factor 3xy + my - 6nx - 2mn
what have you tried
if you can't find a common variable in all the terms, try finding commons in two or more terms
I'll try grouping them
yeah, that should help
ye
So I came up with the answer y(3x + m) - 2n(3x - m), is that right?
That's one way to factorize it, but it is not fully factorized, right?
See if you can group them differently, while still being able to have commons and factorize
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What actually is this red line?
In Line Integration
The space curve or the path?
@rugged sigil Has your question been resolved?
Sorry I didn't see.
I might've been misunderstanding
Is the red line the curve and the blue line just follows the surface and we're finding the area between the curve and surface?
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Domain is so confusing
I need help
in your first one youre saying x cant be 6, when in reality x cant be -6
so you need to fix that
Ok I changed that
What about the rest
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Hello everyone, I solved a rational inequality and ended up with
X³-7X²+7X+15<0
I have to factor this polynomial, but I don't know how to rewrite some terms (as example -7X=-9X+2X) is there a rule?
try subbing in values for x?
Randomly?
yes
And how would that help?
i think if u sub in x = 1 the polynomial should equal 0
then make x = 1 into a factor and divide it into the polynomial
to get a quadratic and then solve the quadratic to get remaining two factors
1 is not a solution
Intresting, but If I have to be honest it doesn't look efficent.
Some zeroes could be irrational, and i would just waste time.
Also, as said above, 1 isn't a solution
can you do a rational root test?
Sorry, what is?
hm, look it up then, it gives us the options what to try as a guess
basically you have two sets A,B
Oh okay I just searched on wikipedia
So basically i get some numbers, and within them there are zeroes of the polynomial, right?
and then try every b/a where b is in B and i is in A
yes
if you have rational roots
it will find it
and now you have 3 nice roots so its gonna work
the guessing should work in this case too cuz - 1 will be a hit already
with this method, no
but i doubt they give you one where every root is irrational
you would need the solving formula then i guess
which is far from your topic i think
Yeah you are right
and if you have one nice root, you are left with a quadratic which is easy at that point
So I find the root, as example x=1. Then I know my A(x)=(x-1)(usually a quadratic) and I just have to factor x-1 out of the terms until i find this quadratic, right?
yea
I have this inequality
(X²-1)²>9/4
I would like to avoid to solve this quadratic term
But idk if I can take the root from both terms
X²-1>3/2 looks wrong, since the first term can be negative, while in the original form it cannot
also you could just substitute in y=x^2
and then you have a quadratic
just at the end you need to substitute back
Is there a way to solve it in that way?
Oh do i have to use absolute value?
Like |x²-1|>3/2?
since we are just searching for the roots i think both are okay
it will give us the intervals between them anyway
and if you are unsure at that point try a random number from every interval
In that case what should I do?
Do i have to rewrite it as
X²-1=±3/2 to find roots?
And then take the exterior intervals
Failed to get a response from Wolfram Alpha.
If the problem persists, please contact support.
,w X²-1>3/2
,w (X²-1)² > 9/4
How is that possible? Doesn't taking the root from both members change things?
it does, the first has 4 solution to begin with
but we lost the 2 complex one
i wont try this now, but i think if you follow the y=x^2 line
which i really recommend
you would end up with 2 scenarios and one would be something like: negative number =x^2
The only thing i don't understand is how can
|x²-1|>3/2 ("correct" form i think)
be equal to
x²-1>3/2
so that would be the dead end which we lost
ahh
we have this
the || only flips our graph between -1 and 1
the roots stay
did you try the y=X^2 substitution?
it will help you in the future too
Intresting, is that a coincidence? Take as example the vertex , what if its y coordinate was bigger in module?
i dont understand the question
Yeah I already used it with polynomials in the form of x^(2n)+x^(n)+c=0
but we are sidetracking now i think
okay, then you can solve this in that way too
and we dont need to think about anything that could go wrong
cuz maybe there could be sth just we dont see it in this case
Thing "under" x axis get reflected. So if the vertex had coordinates as (0, -2) with the absolute value it would have been (0,2), therefore i would have 4 solutions
Yeah I asked cause i am studying a chapter about absolute values and maybe in the test i will have to do in that specific way
Wait give me a second
You can see that the red equation is bigger than y=14.1 for different intervals
Red equation > y=k has this region in which it is verified, while blue doesn't
@echo needle i tried with desmos and found out that absolute value is necessary
Anyways, thank you very much for all the help
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how do i proceed with this
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how do i proceed with the integral on the bottom
Try cancelling and sub maybe?
Or use a trig identity once you get to only sines and cosines
I tried on the top
I don’t see anything that appears evident
!show
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Oh wait I see it
Is this right ?
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@tranquil pine Has your question been resolved?
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I don't understand what these are asking
@plush stag Has your question been resolved?
<@&286206848099549185>
Amplitude means (max-min)/2
So what are the max and min for -sin(2x)
Is it just the -pi/2 and pi/2?
No
I mean like
Minimum output maximum output
What is the most -sin(2x) can be
And what is the least
1 and -1?
Yeah
So (1—1)/2
Amplitude is 1
Now what are the minimum and maximum of -tan(x-pi/2)
-tan gives me an error
Ok
Do you know the period of just sin(x)
Idk
So
There’s 2pi radians in a circle right
So no matter where I pick on the unit circle
If I turn 2pi radius clockwise or counter clockwise
I will get back to where I was
And if I get back to where I was I will have the same length opposite the angle (definition of sine)
So we say for all x
sin(x)=sin(x+2pi)
Which means every sine value will repeat after 2pi
And the definition of period is basically how long it takes to repeat
So the period of sin(x) is 2pi
So does it work that way for 2x as well?
Well
Except multiply by 2?
No
If you thing about it
With sin(2x)
You’re gonna reach values twice as fast
So it takes half as long to repeat
So the period is pi
In general
If you have sin(ax)
The period is 2pi/a
No
Cuz think about it
If you have -sinx
It’s gonna take the same amount of time to repeat
Period is always positive
Yeah
Ok
So phase shift is how far it goes from the parent function
So if we have sin(x-1)
The phase shift is 1
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You can factor out the x in the denominator
limit exists because you have a hole there
doesn't matter if the function isn't defined there
$\lim_{x\to 7} \frac{x-7}{x^2-7x}=\lim_{x\to 7} \frac{x-7}{x(x-7)}=\frac{1}{x}=\frac{1}{7}$
bla
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Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help
Type .help <command name> for more info on a command.
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Can not solve this stupid question
@dusky vigil Has your question been resolved?
So
V=4/3pir^3
If you take the derivative with respect to t
You get
90=4pir^2*dr/dt
Then solve form there
I think you got a similar thing but kinda did it in reverse or smth
Cuz the pi should be in the denominator in the final answer
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help
Please don't occupy multiple help channels.
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hi i tried before in a different channel to no success could someone check over this integration question please?
@tiny gorge i couldnt type in that other one for some reason
what is your question?
no point opening and closing channels without actually showing the question
horrifying numbers
legit
ive been trying so long
cant spot the error/s
bungo brother are you looking or...?
@static crypt Has your question been resolved?
@static crypt Has your question been resolved?
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what does the red thing mean in this equation
it's hard to read, does it say m_tan ?
yes
i guess "slope of tangent line"
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could someone look over my work to see if i did this right?
finding the determinant of a 4x4 matrix
,w determinant {{2,-3,0,1},{5,4,2,0},{1,-1,0,3},{-2,1,0,0}}
ok so apparently you fucked up somewhere
yeah i just dont know where
btw all these [] should be | | instead
it looks right
gotcha
i used the first line to calculate these
does it matter which line
so i did the first line as required
it doesn't matter
oh okay
oh shit
in the last 3 by 3 thing, 1(1) - (-1)(-2) = 1 - 2 = -1 not -2
not that this would fix the apparent discrepancy still
fuck i can't see where else you fucked up lol
yeah.... its strange
is there maybe just a way i can redo it but get the right answer?
ok hang on lemme try to reproduce...
also would getting the determinant of a 5x5 matrix be the same as this just like repeating the steps over again but adding another step to it
if that makes sense
yes determinants can be calculated recursively like that
ok thought so
omg
yeah you need to be super careful with copying
a missed minus sign can REALLY screw you over like this
i see that
wow
lol
thanks for noticing my problem
i have another question with this real quick
,w determinant {{2,-3,1,0,4},{0,3,2,5,7},{0,0,1,6,0},{0,0,0,5,2},{0,0,0,0,-1}}
@dreamy gull Has your question been resolved?
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90% - 99% - 112
80% - 89% - 66
69% - 79% - 19
how to find the median of the given data if the mean is 89.69%
gonna need a bit more context to these chief
its ok if its not accurate
just an estimated value
i asked ChatGPT its giving me 74 which litrally isnt possible
it has to lie between 90 and 99
i just want an estimate
@frigid drift Has your question been resolved?
yea don't' use chatgpt for math
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Why are they not taking phi as common?
Cuz each & every set belonging in the universe already has null set as common
Morever, null set (phi) isn't considered as an element
@eternal wharf
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@eternal wharf Has your question been resolved?
This is one of the cases where I think the solution is wrong
The empty set will always be an element of any power set
So if you take the intersection of two power sets, it will ALWAYS have the empty set in it, which is a valid element
So emptyset and {-7} constitute 2 common elements of P(A) and P(B)
See@scarlet sequoia
<@&286206848099549185>
Empty set IS an element... that's where I disagree with the first helper
$\mathcal{P}(A)\cap\mathcal{P}(B) = {\emptyset, {-7}}$, thus $|\mathcal{P}(A)\cap\mathcal{P}(B)| = 2$
rafilou2003
The argument "$\emptyset$ is not counted as an element" is invalid. If it were true, then the set ${\emptyset}$ would be a set with no elements, ie. the empty set itself. However $\emptyset \neq {\emptyset}$
rafilou2003
I suggest you take the matter to your teacher if you're still unsure
thats a cool font
For your concern. There is no teacher. I am graduated poorly
And i am learning all the things through online sources and discord(maths,english)
Thanks
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hello
how do i find the domaine of Arctan((x-1)/(1+x)) ?
i need to do -∞<x-1/1+x <+∞ and x =/= -1 so domf = R/{-1} ?
<@&286206848099549185>
@unkempt fern Has your question been resolved?
<@&286206848099549185>
Yes sir!
look up
this @tranquil pine
Ay Ay Captain!
what ay ay
I mean yes sir
no problem sir
i will do this for u
but it will take some time coz I am pc so can just do it and take pic and send you
ok
@unkempt fern Has your question been resolved?
Okay, we're dealing with the function, (arctan(u)), which works for all real numbers, but here's the thing - we can't divide by zero.
In this case, the problem is in the denominator, (1 + x), so we solve for when that's zero:
[1 + x = 0]
Solving for (x), we get (x = -1). That's the issue; we can't have (x = -1) because it makes the denominator zero.
So, the domain of f(x)= ((x-1)/(1+x)) is all real numbers, except for (x = -1). Think of it as covering every real number except -1, it goes from negative infinity right up to -1 (but not including -1), and from just after -1 to positive infinity. Avoid -1, and you're good to go homie. 😛
Ok
but
@tranquil pine -∞<x-1/1+x <+∞ how we can prove it with that
we cant have x = -1
so -∞<x<+∞
with x =/= -1 ?
ttyl gotta go
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would the answer for a) be 6 years?
,calc log(0.25)/log(0.8)
Result:
6.2125674390108
so would it round up or down? or stay as 6.2
id assume it would eb 6 years
as she is gonna sell it one it becomes over 6.2
@candid hull
some kind of rounding above probably
"she wants to keep it until its value is less than 25% blablabla"
i.e. if it's not less than 25% I don't sell this kind of deal
that's how I interpret that at least
@oblique turret
so u would round up?
but your looking at how long she wants to keep it for @candid hull
yes
so she would keep it for 6years?
@candid hull did u use the value of a to be 1 or 0.1?
re I was disconnected for some reason
oh
wdym a ?
yeah
waht happened to the value of a?
just supposing the original value of the car is 1
if we start at 1, then 1/4 of the orig value is 0.25
does it matter
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Find m so that there is a unique solution to the system
in the sec eq?
Yes
If you have something like a^2 + b^2 = 0, then you can solve for a and b
Would there be any way of getting to there
is that a rhetoric question
Try completing the square on x and y independently to get the sum of two squares
with 1 for example? to get something like (x+1)^2+(y+1)^2?
You want to get rid of the x as well, so try 1/2
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need help understanding how to plot the x<1
x>1 thing
like why is it 1,2 and 1,-4?
this is piecewise
stuff
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can someone please tell me how to continue or if I used the wrong method while solving the problem?
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how do i make formulas for non geometric and arithmetic sequences
@red leaf Has your question been resolved?
if you're working on a problem, just show its original form
3,12,27,48
their seccond difference is 6?
1,4,9,16
+3 +5 +7
their secoond difference is 2
so ur gone?
this is a pattern
now you're gone?
im here
their second difference is the same
uh huh
yea
like a formula?
yes
like 2,4,6,8,10, ... the general term is 2n
or 1, 2, 4, 8, 16, .... the general term is 2^n
so the equation is 3n^2?
yes
why
if i had a number like
2 6 12
plug into your calculator
do i find second difference
so how did u do it?
do what
,calc 2^3
Result:
8
,calc 2^2
Result:
4
find the form?
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Can anyone help with this
do you have an idea of what the average rate of change would mean?
yes its slope right
yeah, how would you get an average
it would basically be the slope of a straight line joining those points
yup
youre gonna have to estimate the y values by eye roughly
ohh
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a
i understand why 4x4 matrices are mathematically used to transform 3d points, but i dont understand why you wouldnt just directly add to the components one by one
rather than having to do unnecessary matrix multiplication
like if you want to move (0,0,0) to (5,5,10)
why not just add 5 to x 5 to y and 10 to z
what is the context
well im rendering 3d shapes onto a canvas
and im implementing a setPosition function
to move them around
but my question is more general
i just dont see the reason to use a matrix over basic addition
vs
x+a, y+b, z+c
no one knows?
pov every channel gets help but you even though linear algebra is a 100 level college class
Try to think about transformations that are more complicated than translation
Can you stretch an object in one direction and squeeze it in another using basic addition?
oh true true :)
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!show
Show your work, and if possible, explain where you are stuck.
i dont know where to start, i tried a method but i dont know if its correct
3 tan^2A – sec^2A + tan^2A = 0
= 4tan^2A-sec^2A = 0
= (4*sin^2A-1)/cos^2A = 0
Just isolate tan A in left eqn and find A
got that as 1/√3
Yea
ah alr got it
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Can someone help me with a math problem?
post it
Can someone explain to me how to find the area of this parallelogram?
I posted it
do you know the area formula?
Yes
B x H right?
Do I just multiply the numbers by each other?
Like 16 x 22 x 14?
Yes
so u have to multiply 14 * 16
224?
yes
So that is the answer?
Why did I not multiply 22?
take the parallelogram and put it horizontally, with the base of 22 inches on the floor.
ok?
Ok
So, the 14 inches is not the H, because it's not perpendicular to the base of 22 inches
right?
The same thing happens when you put it vertically.
22 inches isn't the H, but it's 16/sin(angle)
so it's 224
because the H is 16
The H is always perpendicular to the Base
Oh ok
If it's not perpendicular, it's not the H
So with this would the 14 feet not be multiplied?
Look at the picture.
14 feet is the Base, right?
Yes
Which measure segment isn't perpendicular to the Base?
10 feet or 8 feet?
8
perpendicular to the base means it forms a 90 degree angle with the base
does 8 do that?
Perpendicular means that forms an angle of 90° with the Base.
A 90° angle is like the angle of the letter "L"
10 feet forms an angle < 90°
with the base
yes, so u have to multiply 14 times 8 and u get the answer
You're welcome
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Anyone know how to do this?
Please don't occupy multiple help channels.
Or this:
the radius and height of the smaller cone and original cone are proportional
Oh yeah so for that its 5 but what about the other question?
This
u can write out the formula of the volume of a cylinder = 8, and surface area of cylinder = 24
multiply the volume by 3 and solve for radius
Thanks
I thought year 16 is university..?
year 13 is the final year of a levels isn't it
oh so you should be in year 12 which is final year of GCSE
no lol
no.
/close
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We think its d but we dont know how to do e
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
it's just a system you have to work with, you won't find the solution just by looking, write some stuff
like 5^(b/a) = 2 so 5^b = 2*5^a
then square it and 25^b = 4*25^a
work with the equations until you find some things
the exponents are the variables of interest too, so you may need to use log
especially on the first equation
is this even solvable?
you don't need to actually solve it
only to work with it until you can deduce 25^b/a²
I just squared it
alright , understood
and that was just an example
Idk if the smartest is trying to get rid of some a or b to get to the answer
or smt else
just write things and deduce stuff
when is log being used though?
since you need a² on denom
I was thinking of writing something like
(a+1)/b log(4) = 3log(5)
so (a+1) = b*3log(5)/log(4)
this is from olympiads right ? it's meant to take time
and it's indeed not nice
you're supposed to try stuff until the good way to work with the equations pops out
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
yes
in fact you can already solve the system
you got a/b = log(5)/log(2) and (a+1)/b = 3log(5)/2log(2) so 1/b = log(5)/2log(2)
so b = 2log(2)/log(5)
so a*log(5)/2log(2) = log(5)/log(2)
and a = 2
I'm too lazy to check I didn't make any mistake but I think it's right
,w 4^((a+1)/b) = 125, 5^(b/a) = 2
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
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why you doin' this to me wolfram
then I'll check my sol by hand I guess uuuuuuuuh
64 = 125*4^b and 5^b = 50
and it's supposed to not be a contradiction
gosh
I did something wrong at some point
I hate calculations so much
ok so this is true
this is too
then a/b = log(5)/log(2) = log(25)/log(4)
and (a+1)/b = log(125)/log(4)
so 1/b = log(5)/log(4)
b = log(4)/log(5)
then a = log(25)/log(5) = 2
it's supposed to be the solution
🤔
I solved for a but I think we maybe can still simplify further
log(4) = 2log(2)
you'll find a = 2
but what my brain is too lazy to check is if it's coherent with the first equation
like, what happens when I plug back a and b in it
I get 3/b = 3log(5)/log(4)
so b = log(4)/log(5)
it is coherent
that should be the answer
so 25^b/a² is 25^(log(4)/log(5))/4
k, let me solve for b, but this is manageable
oh yes
I see what you said earlier goddess

can you check if what i did is legal? @grizzled tusk
wow this seems illegal
<@&286206848099549185>
too lazy to check everything but you found the same answers as me
@quasi plinth Has your question been resolved?

