#help-36

1 messages · Page 57 of 1

sand portal
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Yup !

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Or more like

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A property of its curve representation

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The function is a process, not a curve

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The curve is just a certain representation of the function itself

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And in order to interpret it geometrically, a geometrical representation is needed

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Which is why we talk about the graph of the function

rare marlin
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so how would i obtain a geometrical representation of say this function?

sand portal
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It's defined analytically, with a function, but the object is the set of points (x,c(x)) in the plane constituted of all the (x,y) points

sand portal
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Plotting ?

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It would not be accurate for sure

rare marlin
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Ah alright

sand portal
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But in any case

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I don't think you need to plot here

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No worries KEK

rare marlin
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Yeah i guess i could just use the fact that c(x) = c(-x)

sand portal
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"explain this geometrically" is basically "explain how this relation translates in a geometrical level on the curve of the function c"

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So if you talk about a reflection along the y axis, I think you get all the points

rare marlin
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Which in this case would be a reflection which was proved by the fact that c(x) = c(-x)

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Right?

sand portal
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Yup

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If you want to compare it with the general case

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The curve of a function f has an axis of symmetry of equation x=a iff for all x, f(a-x)=f(a+x)

rare marlin
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So the general idea is that if a function c(x) is equal to c(-x) that proves that the function is symmetrical and it can be reflected over x=0

sand portal
rare marlin
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Oh i see

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Yeah mb

sand portal
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Nw you get it !

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Super fast

sand portal
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Good job !

rare marlin
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But im just a bit confused on this part, isnt the "looks identical part" the important part because can't any function be reflected across the y axis? Is there more specific terms?

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Sorry u may have answered this before im unsure could u explain it one more time?

sand portal
rare marlin
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Oh so "has a reflection" essentially says that it looks identical when reflected.

sand portal
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The function f(x)=x doesn't even follow that property anywhere

sand portal
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Apart from

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The actual reflection

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"a reflection along the x axis"

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That's the actual reflection

rare marlin
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Yep

sand portal
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Now

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Let's say, we can see "looks identical" as an undefined term in maths basically

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It is either identical or not

rare marlin
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Oh okay sure, ill just use reflection across x=0

sand portal
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Yes, that's the geometric property of ... what already ?

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What is reflected across x=0 ?

rare marlin
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C(x)?

sand portal
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It's still a number, has always been

rare marlin
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isn't c(x) reflected across x=0?

sand portal
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"Isn't 3 reflected across x=0 ?", that's an equivalent of what you just said

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What you are saying doesn't make sense

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c(x) is a number, not a geometric object

rare marlin
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Then the geometric representation of c(x) has reflection over the line x=0?

sand portal
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Almost there YES !

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c(x) is a number

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I still don't know what is the representation of a number in a plane

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A point, sure

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A number, no

rare marlin
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Oh wait

sand portal
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It's just that tiny bitty thing you have to change

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Really, just 3 characters that have to be deleted

rare marlin
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Is it the geometric representation of the function C has a reflection over the lime x=0?

sand portal
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YES !!!

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LESGOOOOOOOOOOOOOOOOOO

rare marlin
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yesssirrr

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Thank you very much!!

sand portal
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Np np KEK

rare marlin
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Helped me a lot hahah

sand portal
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But you did the hardest

rare marlin
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yeah

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i actually completely understood it now

sand portal
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Yeeeeeeeessssssssss

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It's such a thing students hardly understand

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I'm actually so glad you did

rare marlin
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Yeah ur a great helper ngl

sand portal
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Stop

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Me emo now

rare marlin
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Just curious what r u studying in math?

sand portal
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The pedagogy of it

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I'm working on becoming a teacher

rare marlin
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damn ud definitely become a great teacher

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R u in uni or pre uni?

sand portal
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Uni

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2nd year of master

rare marlin
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Oh nice

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Oh sick

sand portal
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.close

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@rare marlin Could you close please ?

final saddleBOT
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@rare marlin Has your question been resolved?

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misty hemlock
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misty hemlock
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How do u do 27

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i think we use the discriminant formula to find it

shadow aspen
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When discriminant = 0 it has "1" root

misty hemlock
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so

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we subsitute

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the values?

shadow aspen
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Yes

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then solve for k

misty hemlock
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oh ok

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got it

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thx

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misty hemlock
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.reopen

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misty hemlock
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charred tiger
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im not sure how to do B

final saddleBOT
rotund citrus
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same thing but you plug in (1+h) where x goes.

charred tiger
rotund citrus
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what?

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so for example you did f(2) = 7 - (2)^2 for the first part for f(2)

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same exact thing, but instead of 2, you plug in (1+h).

charred tiger
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ohhhhh ok

rotund citrus
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its okay to have h in the answer if they don't notate a limit. if its still wrong then they expect you to find it when h = 0.

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generally, you never want to just make h = 0 until after you've found the simplified expression.

charred tiger
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ohhh ok i see

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thanks!

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blissful pelican
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hellp

final saddleBOT
blissful pelican
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hh

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hmm?

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anybody here?

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...

vital crag
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!da2a

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blissful pelican
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huh?

vital crag
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west plover
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how can i solve this

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jovial spoke
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help

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vital crag
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charred tiger
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im not sure how to do this

final saddleBOT
astral grotto
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are you familiar with properties of logarithms

charred tiger
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yea kinda

astral grotto
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how would you simplify $y \log_b x$ or $\log_b x + \log_b z$

soft zealotBOT
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LordNwahs

charred tiger
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umm i think wouldnt it be like logb^(x * z)?

astral grotto
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how about $y \log_b x$

soft zealotBOT
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LordNwahs

charred tiger
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hmmm

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logbx^y

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?

astral grotto
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yep

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just apply those properties to get the RHS to some expression $log_b (something)$

soft zealotBOT
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LordNwahs

charred tiger
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wait then do u multiply the 2/3 and 1/2 together then?

astral grotto
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no?

charred tiger
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wut

astral grotto
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how do you simplify $2/3 \log 27$

soft zealotBOT
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LordNwahs

charred tiger
astral grotto
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do each term separately

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you already know the rules

astral grotto
charred tiger
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logb27^2/3

astral grotto
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yes... and what is 27^(2/3)?

charred tiger
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3^2

astral grotto
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yep

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or just 9

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lol

charred tiger
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o

astral grotto
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yea

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you see how to do it now?

charred tiger
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yaaa

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an then for the other one i do same thingy and then put it tigether

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?

astral grotto
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yep!

charred tiger
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okeee thanks :D

astral grotto
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cheers

charred tiger
astral grotto
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yep looks good to me

charred tiger
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.close

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charred tiger
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is this right?

final saddleBOT
charred tiger
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im not sure about the point slope form bc of the 0

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gritty matrix
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Factor 3xy + my - 6nx - 2mn

final saddleBOT
tranquil pine
gritty matrix
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I don't really know what to do

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I've tried GCMF but it's not applicable

cedar cove
gritty matrix
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I'll try grouping them

cedar cove
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yeah, that should help

small zodiac
gritty matrix
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So I came up with the answer y(3x + m) - 2n(3x - m), is that right?

cedar cove
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See if you can group them differently, while still being able to have commons and factorize

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rugged sigil
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What actually is this red line?

final saddleBOT
rugged sigil
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In Line Integration

jagged cosmos
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The space curve or the path?

final saddleBOT
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@rugged sigil Has your question been resolved?

rugged sigil
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I might've been misunderstanding

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Is the red line the curve and the blue line just follows the surface and we're finding the area between the curve and surface?

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quiet garden
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Domain is so confusing

final saddleBOT
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Please don't occupy multiple help channels.

quiet garden
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I need help

warm ether
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in your first one youre saying x cant be 6, when in reality x cant be -6

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so you need to fix that

quiet garden
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What about the rest

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shell hatch
#

Hello everyone, I solved a rational inequality and ended up with

X³-7X²+7X+15<0
I have to factor this polynomial, but I don't know how to rewrite some terms (as example -7X=-9X+2X) is there a rule?

neat sable
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try subbing in values for x?

shell hatch
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Randomly?

neat sable
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yes

shell hatch
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And how would that help?

neat sable
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i think if u sub in x = 1 the polynomial should equal 0

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then make x = 1 into a factor and divide it into the polynomial

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to get a quadratic and then solve the quadratic to get remaining two factors

echo needle
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1 is not a solution

shell hatch
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Intresting, but If I have to be honest it doesn't look efficent.
Some zeroes could be irrational, and i would just waste time.
Also, as said above, 1 isn't a solution

echo needle
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maybe the signs are incorrect?

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this doesnt have any nice roots

shell hatch
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Oh you are right, I transcribed it wrongly, sorry

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X³-7X²+7X+15<0

echo needle
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can you do a rational root test?

shell hatch
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Sorry, what is?

echo needle
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hm, look it up then, it gives us the options what to try as a guess

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basically you have two sets A,B

shell hatch
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Oh okay I just searched on wikipedia

echo needle
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A consists of the diveders of 1 (coeff. of the highest)

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B is the dividers of 15

shell hatch
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So basically i get some numbers, and within them there are zeroes of the polynomial, right?

echo needle
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and then try every b/a where b is in B and i is in A

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yes

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if you have rational roots

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it will find it

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and now you have 3 nice roots so its gonna work

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the guessing should work in this case too cuz - 1 will be a hit already

shell hatch
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What if I had a polynomial which has irrational roots?

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Will I find them?

echo needle
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with this method, no

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but i doubt they give you one where every root is irrational

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you would need the solving formula then i guess

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which is far from your topic i think

shell hatch
echo needle
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and if you have one nice root, you are left with a quadratic which is easy at that point

shell hatch
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So I find the root, as example x=1. Then I know my A(x)=(x-1)(usually a quadratic) and I just have to factor x-1 out of the terms until i find this quadratic, right?

echo needle
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yes

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polinom division

shell hatch
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Thank you so much, this was so helpful 🙏

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May i ask you another thing?

echo needle
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yea

shell hatch
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I have this inequality

(X²-1)²>9/4

I would like to avoid to solve this quadratic term

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But idk if I can take the root from both terms

echo needle
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hm

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i think u can, but make a note to not lose any solutions wrongly

shell hatch
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X²-1>3/2 looks wrong, since the first term can be negative, while in the original form it cannot

echo needle
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also you could just substitute in y=x^2

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and then you have a quadratic

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just at the end you need to substitute back

shell hatch
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Oh do i have to use absolute value?

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Like |x²-1|>3/2?

echo needle
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since we are just searching for the roots i think both are okay

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it will give us the intervals between them anyway

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and if you are unsure at that point try a random number from every interval

shell hatch
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And then take the exterior intervals

echo needle
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no just leave it pos

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,w (X²-1)²>9/4

soft zealotBOT
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Failed to get a response from Wolfram Alpha.
If the problem persists, please contact support.

echo needle
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,w X²-1>3/2

echo needle
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,w (X²-1)² > 9/4

shell hatch
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How is that possible? Doesn't taking the root from both members change things?

echo needle
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it does, the first has 4 solution to begin with

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but we lost the 2 complex one

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i wont try this now, but i think if you follow the y=x^2 line

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which i really recommend

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you would end up with 2 scenarios and one would be something like: negative number =x^2

shell hatch
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The only thing i don't understand is how can

|x²-1|>3/2 ("correct" form i think)
be equal to
x²-1>3/2

echo needle
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so that would be the dead end which we lost

echo needle
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we have this

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the || only flips our graph between -1 and 1

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the roots stay

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did you try the y=X^2 substitution?

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it will help you in the future too

shell hatch
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Intresting, is that a coincidence? Take as example the vertex , what if its y coordinate was bigger in module?

echo needle
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i dont understand the question

shell hatch
echo needle
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but we are sidetracking now i think

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okay, then you can solve this in that way too

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and we dont need to think about anything that could go wrong

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cuz maybe there could be sth just we dont see it in this case

shell hatch
shell hatch
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Wait give me a second

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You can see that the red equation is bigger than y=14.1 for different intervals

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Red equation > y=k has this region in which it is verified, while blue doesn't

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@echo needle i tried with desmos and found out that absolute value is necessary

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Anyways, thank you very much for all the help

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trim lance
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trim lance
#

how do i proceed with this

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@trim lance Has your question been resolved?

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trim lance
#

how do i proceed with the integral on the bottom

vital crag
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Try cancelling and sub maybe?

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Or use a trig identity once you get to only sines and cosines

trim lance
#

I don’t see anything that appears evident

vital crag
final saddleBOT
vital crag
#

Oh wait I see it

trim lance
#

Yeaaa

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On top of the page

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Unless if I split

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Not sure

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Sec^3teta csc teta

trim lance
final saddleBOT
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@trim lance Has your question been resolved?

trim lance
#

nvm

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.close

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trim lance
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yes^

#

ask

final saddleBOT
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@tranquil pine Has your question been resolved?

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plush stag
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plush stag
#

I don't understand what these are asking

final saddleBOT
#

@plush stag Has your question been resolved?

plush stag
#

<@&286206848099549185>

robust trellis
#

So what are the max and min for -sin(2x)

plush stag
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Is it just the -pi/2 and pi/2?

robust trellis
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I mean like

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Minimum output maximum output

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What is the most -sin(2x) can be

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And what is the least

plush stag
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1 and -1?

robust trellis
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Yeah

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So (1—1)/2

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Amplitude is 1

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Now what are the minimum and maximum of -tan(x-pi/2)

plush stag
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-tan gives me an error

robust trellis
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Yeah

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There’s no maximum or minimum

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So the function doesn’t have an amplitude

plush stag
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Ahh, ok

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And what about periods and phase shifts?

robust trellis
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Do you know the period of just sin(x)

plush stag
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Idk

robust trellis
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There’s 2pi radians in a circle right

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So no matter where I pick on the unit circle

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If I turn 2pi radius clockwise or counter clockwise

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I will get back to where I was

#

And if I get back to where I was I will have the same length opposite the angle (definition of sine)

#

So we say for all x

#

sin(x)=sin(x+2pi)

#

Which means every sine value will repeat after 2pi

#

And the definition of period is basically how long it takes to repeat

#

So the period of sin(x) is 2pi

plush stag
#

So does it work that way for 2x as well?

robust trellis
plush stag
#

Except multiply by 2?

robust trellis
#

No

#

If you thing about it

#

With sin(2x)

#

You’re gonna reach values twice as fast

#

So it takes half as long to repeat

#

So the period is pi

#

In general

#

If you have sin(ax)

#

The period is 2pi/a

plush stag
#

Ahh, ok

#

And then for -sin, the answer just becomes negative, right?

robust trellis
#

Cuz think about it

#

If you have -sinx

#

It’s gonna take the same amount of time to repeat

#

Period is always positive

plush stag
#

Ah, ok

#

So then -sin(2x) would still be pi

robust trellis
#

Yeah

plush stag
#

That makes sense

#

So then what about phase shifts?

robust trellis
#

So phase shift is how far it goes from the parent function

#

So if we have sin(x-1)

#

The phase shift is 1

plush stag
#

So does multiplication affect the phase shift?

#

Like the 2x

#

Or the pi x

final saddleBOT
#

@plush stag Has your question been resolved?

plush stag
#

whatever

#

.close

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tranquil pine
#

You can factor out the x in the denominator

final tangle
#

limit exists because you have a hole there

#

doesn't matter if the function isn't defined there

tranquil pine
#

$\lim_{x\to 7} \frac{x-7}{x^2-7x}=\lim_{x\to 7} \frac{x-7}{x(x-7)}=\frac{1}{x}=\frac{1}{7}$

soft zealotBOT
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tulip gyro
#

.open

#

.help

final saddleBOT
#

Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

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dusky vigil
#

Can not solve this stupid question

final saddleBOT
dusky vigil
final saddleBOT
#

@dusky vigil Has your question been resolved?

robust trellis
#

V=4/3pir^3

#

If you take the derivative with respect to t

#

You get

#

90=4pir^2*dr/dt

#

Then solve form there

#

I think you got a similar thing but kinda did it in reverse or smth

#

Cuz the pi should be in the denominator in the final answer

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#

@dusky vigil Has your question been resolved?

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winter sky
#

help

final saddleBOT
#

Please don't occupy multiple help channels.

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@winter sky Has your question been resolved?

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static crypt
#

hi i tried before in a different channel to no success could someone check over this integration question please?

static crypt
#

@tiny gorge i couldnt type in that other one for some reason

tiny gorge
#

what is your question?

#

no point opening and closing channels without actually showing the question

static crypt
tiny gorge
#

horrifying numbers

static crypt
#

legit

#

ive been trying so long

#

cant spot the error/s

#

bungo brother are you looking or...?

final saddleBOT
#

@static crypt Has your question been resolved?

final saddleBOT
#

@static crypt Has your question been resolved?

static crypt
#

FUCK YES I GOT IT

#

.close

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tardy ridge
final saddleBOT
tardy ridge
#

what does the red thing mean in this equation

tiny gorge
#

it's hard to read, does it say m_tan ?

tardy ridge
tiny gorge
#

i guess "slope of tangent line"

tardy ridge
#

m sub tan

#

oh ok

#

thx

#

.close

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dreamy gull
#

could someone look over my work to see if i did this right?

dreamy gull
#

finding the determinant of a 4x4 matrix

tired walrus
#

,w determinant {{2,-3,0,1},{5,4,2,0},{1,-1,0,3},{-2,1,0,0}}

tired walrus
#

ok so apparently you fucked up somewhere

dreamy gull
#

yeah i just dont know where

tired walrus
#

btw all these [] should be | | instead

dreamy gull
#

it looks right

#

gotcha

#

i used the first line to calculate these

#

does it matter which line

dry light
#

Vertical bar is determinant

#

So yeah

dreamy gull
#

so i did the first line as required

tired walrus
dreamy gull
#

oh okay

tired walrus
#

usually you go for the line with the most zeros

#

but anyway

dreamy gull
#

oh shit

tired walrus
#

not that this would fix the apparent discrepancy still

#

fuck i can't see where else you fucked up lol

dreamy gull
#

yeah.... its strange

#

is there maybe just a way i can redo it but get the right answer?

tired walrus
#

ok hang on lemme try to reproduce...

dreamy gull
#

also would getting the determinant of a 5x5 matrix be the same as this just like repeating the steps over again but adding another step to it

#

if that makes sense

tired walrus
#

yes determinants can be calculated recursively like that

dreamy gull
#

ok thought so

tired walrus
#

ah

#

just noticed the fuckup

dreamy gull
#

where is it

#

or whatd ya find

tired walrus
dreamy gull
#

omg

tired walrus
#

yeah you need to be super careful with copying

#

a missed minus sign can REALLY screw you over like this

dreamy gull
#

i see that

#

wow

#

lol

#

thanks for noticing my problem

#

i have another question with this real quick

#

,w determinant {{2,-3,1,0,4},{0,3,2,5,7},{0,0,1,6,0},{0,0,0,5,2},{0,0,0,0,-1}}

dreamy gull
#

if i do this would the easiest route to go with the bottom row

#

like this

final saddleBOT
#

@dreamy gull Has your question been resolved?

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frigid drift
#

90% - 99% - 112
80% - 89% - 66
69% - 79% - 19

how to find the median of the given data if the mean is 89.69%

frigid drift
#

i want to find the median of the date

#

mean is 89.69%

tired walrus
#

gonna need a bit more context to these chief

frigid drift
#

just an estimated value

#

i asked ChatGPT its giving me 74 which litrally isnt possible

#

it has to lie between 90 and 99

#

i just want an estimate

final saddleBOT
#

@frigid drift Has your question been resolved?

vital crag
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eternal wharf
final saddleBOT
eternal wharf
#

Why are they not taking phi as common?

tight void
#

Cuz each & every set belonging in the universe already has null set as common

#

Morever, null set (phi) isn't considered as an element

#

@eternal wharf

final saddleBOT
#

@eternal wharf Has your question been resolved?

final saddleBOT
#

@eternal wharf Has your question been resolved?

final saddleBOT
#

@eternal wharf Has your question been resolved?

scarlet sequoia
#

This is one of the cases where I think the solution is wrong

#

The empty set will always be an element of any power set

#

So if you take the intersection of two power sets, it will ALWAYS have the empty set in it, which is a valid element

#

So emptyset and {-7} constitute 2 common elements of P(A) and P(B)

eternal wharf
#

<@&286206848099549185>

scarlet sequoia
#

Empty set IS an element... that's where I disagree with the first helper

#

$\mathcal{P}(A)\cap\mathcal{P}(B) = {\emptyset, {-7}}$, thus $|\mathcal{P}(A)\cap\mathcal{P}(B)| = 2$

soft zealotBOT
#

rafilou2003

scarlet sequoia
#

The argument "$\emptyset$ is not counted as an element" is invalid. If it were true, then the set ${\emptyset}$ would be a set with no elements, ie. the empty set itself. However $\emptyset \neq {\emptyset}$

soft zealotBOT
#

rafilou2003

scarlet sequoia
#

I suggest you take the matter to your teacher if you're still unsure

sonic crystal
#

thats a cool font

eternal wharf
#

And i am learning all the things through online sources and discord(maths,english)

final saddleBOT
#

@eternal wharf Has your question been resolved?

eternal wharf
#

.close

final saddleBOT
#
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unkempt fern
#

hello

final saddleBOT
unkempt fern
#

how do i find the domaine of Arctan((x-1)/(1+x)) ?

#

i need to do -∞<x-1/1+x <+∞ and x =/= -1 so domf = R/{-1} ?

#

<@&286206848099549185>

final saddleBOT
#

@unkempt fern Has your question been resolved?

unkempt fern
#

<@&286206848099549185>

tranquil pine
unkempt fern
#

look up

unkempt fern
tranquil pine
unkempt fern
#

what ay ay

tranquil pine
unkempt fern
#

yeah i need help for this

#

need help sir

tranquil pine
#

i will do this for u

#

but it will take some time coz I am pc so can just do it and take pic and send you

unkempt fern
#

ok

final saddleBOT
#

@unkempt fern Has your question been resolved?

tranquil pine
# unkempt fern i need to do -∞<x-1/1+x <+∞ and x =/= -1 so domf = R/{-1} ?

Okay, we're dealing with the function, (arctan(u)), which works for all real numbers, but here's the thing - we can't divide by zero.

In this case, the problem is in the denominator, (1 + x), so we solve for when that's zero:

[1 + x = 0]

Solving for (x), we get (x = -1). That's the issue; we can't have (x = -1) because it makes the denominator zero.

So, the domain of f(x)= ((x-1)/(1+x)) is all real numbers, except for (x = -1). Think of it as covering every real number except -1, it goes from negative infinity right up to -1 (but not including -1), and from just after -1 to positive infinity. Avoid -1, and you're good to go homie. 😛

unkempt fern
#

Ok

#

but

#

@tranquil pine -∞<x-1/1+x <+∞ how we can prove it with that

#

we cant have x = -1

#

so -∞<x<+∞

#

with x =/= -1 ?

tranquil pine
final saddleBOT
#

@unkempt fern Has your question been resolved?

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oblique turret
#

would the answer for a) be 6 years?

final saddleBOT
candid hull
#

,calc log(0.25)/log(0.8)

soft zealotBOT
#

Result:

6.2125674390108
candid hull
#

yeah so 6 or so years indeed

#

@oblique turret

oblique turret
#

id assume it would eb 6 years

#

as she is gonna sell it one it becomes over 6.2

#

@candid hull

candid hull
#

some kind of rounding above probably

#

"she wants to keep it until its value is less than 25% blablabla"

#

i.e. if it's not less than 25% I don't sell this kind of deal

#

that's how I interpret that at least

#

@oblique turret

oblique turret
#

but your looking at how long she wants to keep it for @candid hull

candid hull
#

well yeah

#

isn't that what the question is asking

#

@oblique turret

oblique turret
#

so she would keep it for 6years?

#

@candid hull did u use the value of a to be 1 or 0.1?

candid hull
#

re I was disconnected for some reason

oblique turret
#

oh

oblique turret
#

when you work it our did u use ar^n <0.25

#

0.8^n <0.25

candid hull
oblique turret
candid hull
#

just supposing the original value of the car is 1

#

if we start at 1, then 1/4 of the orig value is 0.25

oblique turret
#

but then ur use 1 as a percentage

#

but u use 25% as a decimal

candid hull
#

does it matter

oblique turret
#

nvm it doesnt

#

thank you for your help

#

.close

final saddleBOT
#
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mortal bison
#

Find m so that there is a unique solution to the system

thorn grotto
#

Try subbing in z

#

and factoring

mortal bison
#

in the sec eq?

thorn grotto
#

Yes

mortal bison
#

i didnt get anything

#

x(x+1) +y(y+1)=m

thorn grotto
#

If you have something like a^2 + b^2 = 0, then you can solve for a and b

#

Would there be any way of getting to there

mortal bison
#

is that a rhetoric question

thorn grotto
#

Yeah, it's definitely possible

#

Complete the square

mortal bison
#

z=(x+2)^2-2xy
(x+y)(x+y+1)-2xy-m=0

#

I didnt get anywhere

thorn grotto
#

Try completing the square on x and y independently to get the sum of two squares

mortal bison
#

with 1 for example? to get something like (x+1)^2+(y+1)^2?

thorn grotto
#

You want to get rid of the x as well, so try 1/2

mortal bison
#

oh

#

thanks

#

m=-1/2

#

.close

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frosty vector
#

need help understanding how to plot the x<1

#

x>1 thing

#

like why is it 1,2 and 1,-4?

#

this is piecewise

#

stuff

final saddleBOT
#

@frosty vector Has your question been resolved?

frosty vector
#

.close

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rain star
#

can someone please tell me how to continue or if I used the wrong method while solving the problem?

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@rain star Has your question been resolved?

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@rain star Has your question been resolved?

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@rain star Has your question been resolved?

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red leaf
#

how do i make formulas for non geometric and arithmetic sequences

final saddleBOT
#

@red leaf Has your question been resolved?

vital crag
vital crag
#

notice they're all divisible by 3

#

try factoring that out and find a pattern

red leaf
#

1,4,9,16

#

+3 +5 +7

#

their secoond difference is 2

#

so ur gone?

vital crag
vital crag
red leaf
red leaf
vital crag
#

uh huh

red leaf
#

second difference is 6

#

so how can i write a form?

vital crag
#

the next term is 25

red leaf
vital crag
#

nth term is ?

red leaf
vital crag
#

yes

#

like 2,4,6,8,10, ... the general term is 2n

#

or 1, 2, 4, 8, 16, .... the general term is 2^n

red leaf
vital crag
#

yes

red leaf
#

but wait

#

im not getting it

vital crag
#

why

red leaf
#

if i had a number like

2 6 12

vital crag
#

plug into your calculator

red leaf
#

do i find second difference

vital crag
#

it depends

#

you try different things and see if it works

red leaf
#

so how did u do it?

vital crag
#

do what

red leaf
#

,calc 2^3

soft zealotBOT
#

Result:

8
red leaf
#

,calc 2^2

soft zealotBOT
#

Result:

4
red leaf
vital crag
#

ok bye

final saddleBOT
#

@red leaf Has your question been resolved?

red leaf
#

.close

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deft crater
#

Can anyone help with this

final saddleBOT
warm ether
#

do you have an idea of what the average rate of change would mean?

deft crater
#

yes its slope right

warm ether
#

yeah, how would you get an average

deft crater
#

not sure im really confused

#

do you have to get points from x=1 to x=5?

warm ether
#

it would basically be the slope of a straight line joining those points

deft crater
#

ohh

#

but some of the points arent there

#

i think i have to use y2 - y1 / x2-x1

warm ether
#

yup

deft crater
#

but the thing is the point for 1 is a random decimal

#

as well as for 5

warm ether
#

youre gonna have to estimate the y values by eye roughly

deft crater
#

ohh

final saddleBOT
#

@deft crater Has your question been resolved?

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#

@deft crater Has your question been resolved?

deft crater
#

.close

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pseudo kite
#

a

final saddleBOT
pseudo kite
#

i understand why 4x4 matrices are mathematically used to transform 3d points, but i dont understand why you wouldnt just directly add to the components one by one

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rather than having to do unnecessary matrix multiplication

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like if you want to move (0,0,0) to (5,5,10)

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why not just add 5 to x 5 to y and 10 to z

vital crag
#

what is the context

pseudo kite
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well im rendering 3d shapes onto a canvas

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and im implementing a setPosition function

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to move them around

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but my question is more general

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i just dont see the reason to use a matrix over basic addition

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vs

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x+a, y+b, z+c

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no one knows?

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pov every channel gets help but you even though linear algebra is a 100 level college class

eternal lichen
#

Try to think about transformations that are more complicated than translation

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Can you stretch an object in one direction and squeeze it in another using basic addition?

final saddleBOT
#

@pseudo kite Has your question been resolved?

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rotund warren
final saddleBOT
tight void
final saddleBOT
rotund warren
#

i dont know where to start, i tried a method but i dont know if its correct

3 tan^2A – sec^2A + tan^2A = 0
= 4tan^2A-sec^2A = 0
= (4*sin^2A-1)/cos^2A = 0

fathom walrus
#

Just isolate tan A in left eqn and find A

rotund warren
fathom walrus
#

Yea

rotund warren
#

ah alr got it

fathom walrus
#

Just sub into right eqn from there

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And u shd be good

rotund warren
#

alr tysm

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.close

final saddleBOT
#
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candid loom
#

Can someone help me with a math problem?

final saddleBOT
sleek token
#

post it

candid loom
#

Can someone explain to me how to find the area of this parallelogram?

candid loom
sleek token
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do you know the area formula?

candid loom
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Yes

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B x H right?

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Do I just multiply the numbers by each other?

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Like 16 x 22 x 14?

ember flicker
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No

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as u can see, the 16 inches is the H

candid loom
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Yes

ember flicker
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so u have to multiply 14 * 16

candid loom
#

224?

ember flicker
#

yes

candid loom
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So that is the answer?

ember flicker
#

yes

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but did u understand why?

candid loom
#

Why did I not multiply 22?

ember flicker
#

take the parallelogram and put it horizontally, with the base of 22 inches on the floor.

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ok?

candid loom
#

Ok

ember flicker
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So, the 14 inches is not the H, because it's not perpendicular to the base of 22 inches

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right?

candid loom
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Yes

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I think I get it

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So it would just be 224?

ember flicker
#

The same thing happens when you put it vertically.
22 inches isn't the H, but it's 16/sin(angle)

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so it's 224

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because the H is 16

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The H is always perpendicular to the Base

candid loom
#

Oh ok

ember flicker
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If it's not perpendicular, it's not the H

candid loom
#

So with this would the 14 feet not be multiplied?

ember flicker
#

Look at the picture.

14 feet is the Base, right?

candid loom
#

Yes

ember flicker
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Which measure segment isn't perpendicular to the Base?
10 feet or 8 feet?

candid loom
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8

tranquil pine
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perpendicular to the base means it forms a 90 degree angle with the base

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does 8 do that?

ember flicker
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Perpendicular means that forms an angle of 90° with the Base.
A 90° angle is like the angle of the letter "L"

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10 feet forms an angle < 90°

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with the base

tranquil pine
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yeah

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but 8 forms a 90° angle with the base

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and the formula is b•h

ember flicker
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yes, so u have to multiply 14 times 8 and u get the answer

candid loom
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Ohhh ok!

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I get it, thank you for the help!

tranquil pine
#

yup

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can you close this

ember flicker
tranquil pine
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by typing .close

#

ntplush

#

@candid loom

#

?

final saddleBOT
#

@candid loom Has your question been resolved?

final saddleBOT
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#
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royal fractal
#

Anyone know how to do this?

final saddleBOT
#

Please don't occupy multiple help channels.

royal fractal
#

Or this:

hallow topaz
#

the radius and height of the smaller cone and original cone are proportional

royal fractal
#

Oh yeah so for that its 5 but what about the other question?

royal fractal
hallow topaz
#

u can write out the formula of the volume of a cylinder = 8, and surface area of cylinder = 24

multiply the volume by 3 and solve for radius

royal fractal
#

I thought year 16 is university..?

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year 13 is the final year of a levels isn't it

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oh so you should be in year 12 which is final year of GCSE

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no lol

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no.

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/close

final saddleBOT
#

@royal fractal Has your question been resolved?

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final saddleBOT
ancient zodiac
#

We think its d but we dont know how to do e

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#

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quasi plinth
final saddleBOT
quasi plinth
#

hi guys

#

can someone help me or hint me with this (?

#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
quasi plinth
#

1

grizzled tusk
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it's just a system you have to work with, you won't find the solution just by looking, write some stuff
like 5^(b/a) = 2 so 5^b = 2*5^a
then square it and 25^b = 4*25^a

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work with the equations until you find some things

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the exponents are the variables of interest too, so you may need to use log

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especially on the first equation

quasi plinth
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is this even solvable?

grizzled tusk
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you don't need to actually solve it

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only to work with it until you can deduce 25^b/a²

quasi plinth
#

5^(b/a) = 2 so 5^b = 2*5^a

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25^b = 4*25^a?

grizzled tusk
#

I just squared it

quasi plinth
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alright , understood

grizzled tusk
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and that was just an example

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Idk if the smartest is trying to get rid of some a or b to get to the answer

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or smt else

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just write things and deduce stuff

quasi plinth
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when is log being used though?

grizzled tusk
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since you need a² on denom

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I was thinking of writing something like
(a+1)/b log(4) = 3log(5)
so (a+1) = b*3log(5)/log(4)

quasi plinth
#

alr, one sec

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omg this is not a nice problem

grizzled tusk
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this is from olympiads right ? it's meant to take time

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and it's indeed not nice

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you're supposed to try stuff until the good way to work with the equations pops out

quasi plinth
#

Rs_Perroromantico @grizzled tusk is this valid ?

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!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
quasi plinth
#

2

#

<@&286206848099549185>

grizzled tusk
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yes

#

in fact you can already solve the system

#

you got a/b = log(5)/log(2) and (a+1)/b = 3log(5)/2log(2) so 1/b = log(5)/2log(2)
so b = 2log(2)/log(5)

#

so a*log(5)/2log(2) = log(5)/log(2)
and a = 2

quasi plinth
#

wtf

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ohhh

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i see

grizzled tusk
#

I'm too lazy to check I didn't make any mistake but I think it's right

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,w 4^((a+1)/b) = 125, 5^(b/a) = 2

soft zealotBOT
grizzled tusk
#

why you doin' this to me wolfram

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then I'll check my sol by hand I guess uuuuuuuuh

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64 = 125*4^b and 5^b = 50
and it's supposed to not be a contradiction

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gosh

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I did something wrong at some point

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I hate calculations so much

quasi plinth
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This is fine, I think this is manageable

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I thought It wasnt solvable

grizzled tusk
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ok so this is true

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this is too

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then a/b = log(5)/log(2) = log(25)/log(4)
and (a+1)/b = log(125)/log(4)
so 1/b = log(5)/log(4)
b = log(4)/log(5)

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then a = log(25)/log(5) = 2

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it's supposed to be the solution

quasi plinth
#

I think maybe I should use my tablet one sec

quasi plinth
#

I solved for a but I think we maybe can still simplify further

grizzled tusk
#

log(4) = 2log(2)

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you'll find a = 2

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but what my brain is too lazy to check is if it's coherent with the first equation

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like, what happens when I plug back a and b in it

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I get 3/b = 3log(5)/log(4)
so b = log(4)/log(5)

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it is coherent

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that should be the answer

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so 25^b/a² is 25^(log(4)/log(5))/4

quasi plinth
#

k, let me solve for b, but this is manageable

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oh yes

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I see what you said earlier goddess

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can you check if what i did is legal? @grizzled tusk

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wow this seems illegal

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<@&286206848099549185>

grizzled tusk
#

too lazy to check everything but you found the same answers as me

final saddleBOT
#

@quasi plinth Has your question been resolved?