#help-36

1 messages · Page 52 of 1

final tangle
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namely multiply stuff by something potentially 0, ignoring domain restrictions etc

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the answer to the question of whether the point
(p,0) is an x-intercept is the same answer to
is g(p) equal to 0

glad basalt
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gotcha

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so the only point they have here that is simple is the y int and the hole

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how do you go about getting the other points

final tangle
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sub in values of x (whatever you want, as many as you want)
into your function equation
to get the respective y values

glad basalt
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so any other number would also give the same graph

final tangle
#

the same with all other graphs

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if you want to find the y-coord when x=1, you sub x=1 into the equation

glad basalt
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is there any logic

final tangle
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if you for some reason wanted the y-coord when x = 420,
sub that into the equation

glad basalt
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like pick the number closest to y int

final tangle
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pick whatever you want

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pick nice meaningful values if you don't want to make life hard for yourself

glad basalt
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cool thank you

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tranquil pine
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I am not sure how to approach this question.

tranquil pine
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I know that tension will face upwards the string, the weight acts downwards.

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I'm guessing that I'd have to resolve forces and equate.

final saddleBOT
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@tranquil pine Has your question been resolved?

final saddleBOT
#

@tranquil pine Has your question been resolved?

final saddleBOT
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@tranquil pine Has your question been resolved?

muted trout
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i did is as g=10 and found that f =1kg*g so if g=10 it would be 10 but if its 9,81 the asnwer would be 9,81

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tension of string is 2sqrt3*a which is sqrt3 of g so tension would be sqrt3 kg g where g represents gravitinial acceleration

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fathom stream
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Could someone please explain structural induction

fathom stream
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like whats the difference between structural and regular induction

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and when do we use structural induction

final saddleBOT
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@fathom stream Has your question been resolved?

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violet rune
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i wanna show that this series converge

final saddleBOT
violet rune
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i know that the same sum but with k=1 converge

tiny gorge
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if you start at n+1 you're summing the tail of the series

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any tail of a convergent series is also convergent

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because it differs from the whole series by only finitely many terms

violet rune
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ye true

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is there a way to calculate its limit?

tiny gorge
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probably

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do you need to, though?

violet rune
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yes i have to calculate it

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calculate the sum

tiny gorge
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why do you have to calculate the sum

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you just want to know if the sequence R_n converges

violet rune
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the exercie ask for it x)

tiny gorge
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where? show the whole question

violet rune
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no it's the next question

tiny gorge
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ahh

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ok

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what's the context, do you know about taylor series and such

violet rune
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yes

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i don't see how to apply taylor here

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to be precise i said calculate the sum, not the limit which is not the same

tiny gorge
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try using

violet rune
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where do u see ln(1+x)?

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maybe it's because sum of 1/k equivalent of ln(n)

tiny gorge
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your series is the right hand side

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with x=1

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so it sums to ln(1+1) = ln(2)

violet rune
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x=1?

tiny gorge
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yes?

violet rune
tiny gorge
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yes

violet rune
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i know what it is don't worry

final saddleBOT
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@violet rune Has your question been resolved?

final saddleBOT
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@violet rune Has your question been resolved?

final saddleBOT
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chilly beacon
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can someone help

final saddleBOT
chilly beacon
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i’m trying so hard

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i got a and e right

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otherwise

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i’m confused asf

wet warren
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Did you try calculus to solve the a ?

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@chilly beacon ?

chilly beacon
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bro

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i’ve been confused

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help me

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what do i do

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is it 1.90

wet warren
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Yeah for x
But we want the value for y
But take the real value for x before rounding and apply it to the equation then round

chilly beacon
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okay so what would that equal to

wet warren
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Apply it the function

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To get the maximum profit

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,calc -25001.91.9 + 9500*1.9 - 7426

soft zealotBOT
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Result:

1599
chilly beacon
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okay that was pretty easy bgl idk why it went over my head

wet warren
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That's it

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It is not hard

chilly beacon
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yes imma put it in the system now n see how it’s gonna rest

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say

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so

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for c it’s b

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and for for d

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what would i do then

wet warren
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To solve the third question

Obviously the first choice won't output the same maximum profit as the x value would still be the same but the maximum profit is less by 3 dollars

So it is the second one
To test that out just substitute (x-3) to x and apply what you applied already to get a and b

chilly beacon
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yeah

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and for d we do (1.90-3)v

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?

wet warren
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Can you compare between the maximum profit
And the best price that produces the best profit?

chilly beacon
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i’m

wet warren
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The second one is what you get out of applying the derivative to the function and equating it to zero to get the x value

The first one is applying that x value to the function to get the maximum profit

chilly beacon
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okay

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so

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it’s the same thing we did for the first question but plug in (x-3)?

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it’s 4.90?

wet warren
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$$-2500(x-3)^2 + 9500(x-3) - 7426$$
$$-2500x^2 + 15000x - 22500 + 9500x - 28500 - 7426$$
Take derivative
$$-5000x + 15000 + 9500$$
Equate to zero
$$-5000x + 24500 = 0$$
$$-5000x = -24500$$

soft zealotBOT
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Sherif Player

wet warren
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,calc 24500/5000

soft zealotBOT
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Result:

4.9
chilly beacon
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okok

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W

wet warren
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And for the final question
It will be the same as b
But add 50
As x doesn't change and we are adding to the whole profit

chilly beacon
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YESS

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okay

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wow

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bro ngl

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the question just threw me off

wet warren
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Any other questions?

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@chilly beacon

chilly beacon
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no that’s it ty

wet warren
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Don't forget to close the channel using
.close@chilly beacon

chilly beacon
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.close

final saddleBOT
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timid estuary
final saddleBOT
timid estuary
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so these are the problems i need to do and im like 99.9% sure the answer is x but i dont know how to get there

sweet summit
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for f(g(x)), you and remove the parentheses around the cuberoot of x - 2, then the 2's will cancel each other out. Then you have the cube root to a cubic power, so then you're just left with x. Similar logic with g(f(x))

timid estuary
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is there a way u could like write that down

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like so i can visually see it but if u cant thats fine

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actually nevermind its alright and thank u so much!!

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tranquil pine
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How would you differentiate this?
$$1+\ln(5xy)=e^{5x-y}$$

soft zealotBOT
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What should I do

tranquil pine
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I did this but it seems tedious

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must be an easier way right?

final saddleBOT
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@tranquil pine Has your question been resolved?

regal hamlet
final saddleBOT
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@tranquil pine Has your question been resolved?

final saddleBOT
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@tranquil pine Has your question been resolved?

final saddleBOT
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@tranquil pine Has your question been resolved?

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unborn roost
#

This is a graph of a rational function. Use the function's graph to determine the equation for its formula

unborn roost
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I do know that the function for rational functions is (ax+b) / (cx + d), and got some understanding of asymptotes, but I struggle to find the way of finding the values for the variables

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$\frac{ax+b}{cx+d}$

hidden kernel
steep sequoia
soft zealotBOT
unborn roost
unborn roost
stark lotus
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Do you know homographique function ?

unborn roost
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it's the vertical asymptote, and it's a sign that we have a denominator that is equal to zero when x = -2

unborn roost
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i have at least not heard the name

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if you're refering to the functions for the vertical and horizontal asymptote, where horisontal is equal to a/c, and vertical is -b/a then yes i they are familiar

stark lotus
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Ok no pb, it tells you that $\dfrac{ax+b}{cx+d}$ can be rewritten as $\dfrac{\alpha}{x-\beta}+\gamma$

soft zealotBOT
#

Joseph.P

unborn roost
soft zealotBOT
unborn roost
stark lotus
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$\gamma$ is the limit of the function, $\beta$ the value when $x=\frac{-d}{c}$ and I forgot what is $\alpha$

soft zealotBOT
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Joseph.P

unborn roost
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okay

stark lotus
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Here what would be beta and gamma ?

final saddleBOT
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@unborn roost Has your question been resolved?

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abstract mango
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.this is cool

final saddleBOT
ancient thistle
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Not sure where to start

final saddleBOT
#

@ancient thistle Has your question been resolved?

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final saddleBOT
stark lotus
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Replace x by -4

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Then you’re finished

final saddleBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

stark lotus
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What did I do ?

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@winter sleet what did I do wrong ?

winter sleet
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nothing, just the guy saying you have to solve sounds a bit off

worldly vale
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Substitute 4 for x, then simplify/evaluate and end up with a number for your final answer

stark lotus
worldly vale
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^^

final saddleBOT
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glad basalt
#

I am super fucking confused

final saddleBOT
glad basalt
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Wtf am I missing

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Look at this

fickle crater
glad basalt
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So?

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Jk still sending

fickle crater
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🗿🗿

glad basalt
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5

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4

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3

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9

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7

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Tell me I did something wrong

fickle crater
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damn

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so you got 2x+4/x+2

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what can you describe about the function

glad basalt
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It became 2(x+2) at the top

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When I put -2

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Thats a hole

fickle crater
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ye

glad basalt
fickle crater
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what's a hole

glad basalt
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Brooo its graphed in there

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-2, -2 wherein

fickle crater
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before we continue

stark lotus
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You’re telling me there is no value of f(x) when x=4 ?

fickle crater
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is this college or highschool or middle school

glad basalt
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Why would I think of doing x = 4 tho

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I mean I got 4 points kind of

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Is it supposed to be symmetric

fickle crater
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geo

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what class is this from

glad basalt
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College

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Precalc

fickle crater
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okay so you know limits

glad basalt
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No

stark lotus
fickle crater
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not yet alright

glad basalt
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To know the graph

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Isnt what I have already plenty

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How do I know when enough is enough

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In future graphs

fickle crater
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@glad basalt you know what you call the ratio function where x is in the denominator?

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for example what's 1/x called

glad basalt
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x^-1

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No?

fickle crater
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🗿🗿

glad basalt
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Idk

stark lotus
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Man I just saw something

fickle crater
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anyway

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if you simplify

stark lotus
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Try simplifying your function

fickle crater
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you get y=2

stark lotus
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No

glad basalt
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Simplify what

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x + 2?

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Whats the ratio function

stark lotus
fickle crater
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bro with the emojis 😭

glad basalt
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Teach me monkagigagun

fickle crater
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you said it yourself

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2(x+2)/(x+2)

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simplify what you can after you find your holes

glad basalt
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Can I simplify more

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Oh divide x + 2

fickle crater
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x+2=x+2

glad basalt
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Fucki

fickle crater
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so you are left with y=2 for any x expect x = -2

glad basalt
fickle crater
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bro it was a way to say they can cancel

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it's like 2x/x

glad basalt
fickle crater
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idk what that means

glad basalt
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When u div same stuff they cancel cmon

fickle crater
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but you are already dividing initially

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yeah but no extra division just simplicify the function after factoring

glad basalt
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Damn that is

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Hella

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Fucking

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Interesting

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So I don’t need to annoy myself with plugging x’s

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How do I pick my points

fickle crater
glad basalt
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What do I do to fix it

fickle crater
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you delete it all

glad basalt
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Ok

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That was sending

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It is deleted

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Now what

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??

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My x int is 0 -2

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y int 2,0

stark lotus
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I have a question, what are all the points ?

glad basalt
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Wait so whats my hole

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Is it -2, 2

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But that can’t be possible ??

stark lotus
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What is the dotted line ?

glad basalt
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Horizontal asym

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I am dying of confusion

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Wtf

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What is the hole

stark lotus
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The "hole" is the value of x when the denominator of your function is equal to 0

glad basalt
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Is it-2, 2

stark lotus
glad basalt
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I was taught that to find the y of the hole’s x

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You remove what creates the hole

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I.e. x + 2

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Then all I have left is 2

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Why doesn’t that work here

stark lotus
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This just simplifying the fraction no ?

glad basalt
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Ye

stark lotus
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But you can’t simplify a fraction of the denominator is equal to 0

glad basalt
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So if it was 2(x+2) divided by 2(x+2) it would work?

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Bc there is 2 at bottom

stark lotus
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No it wouldn’t work either, what if x=-2 ?

glad basalt
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Fucking

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So I should say no to simplifying

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And just plug in my x

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Into the function

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is it -2, 0?

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0/0

stark lotus
glad basalt
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Is it equal to zero after you simplify?

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But if you were to divide x + 2 and x + 2 you would get 1 right

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Why is it zero

stark lotus
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It’s not defined when x=-2

glad basalt
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So dem is zero when x = -2

stark lotus
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In this example yes

glad basalt
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Do I not plot a hole anywhere?

stark lotus
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Yes you do plot one when the denominator is equal to 0 for a certain value of x that you just said

glad basalt
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But its undefined

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0/0

stark lotus
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For which value of x (2x+4)/(x+2) is 0/0 ?

glad basalt
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-2

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Is thst cuz a hole is undefined so it doesnt matter

glad basalt
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Okkk now what

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@stark lotus

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Thats wrong

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-2 still produces y = 2

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The hole is -2, 2

stark lotus
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Show your work please

glad basalt
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Thats the answer

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No work to show

stark lotus
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I mean the graph

stark lotus
glad basalt
stark lotus
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I sais you plot a hole when the denominator is equal to 0

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Is it to hard to understand ?

glad basalt
glad basalt
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That the y value of -2 is not 2

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You said not to simplify

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But if I did

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I would get 2

stark lotus
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I thought you meant x=-2 and x=2 so I didn’t understand

glad basalt
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Y = 2 for any x expect -2

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By y is 2 for -2

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This is not making any sense

stark lotus
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It’s not 2 for -2 this point is the hole

glad basalt
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What difference does it make

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The hole is at -2, 2

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Its placed there

final saddleBOT
#

@glad basalt Has your question been resolved?

final saddleBOT
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tranquil pine
#

A quantum particle can be trapped in a one-dimensional potential well if the equation:

tranquil pine
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has a solution for 0<y<lambda

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Proof that there is at least one solution in the interval

soft zealotBOT
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The following error occured while calculating:
Error: Colon : expected after object key (char 14)

tranquil pine
#

<@&286206848099549185>

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can anyone help me?

final saddleBOT
#

@tranquil pine Has your question been resolved?

wet warren
#

First I think we need to define what tan(lambda) is
@tranquil pine
Cause you can easily set
y = √(lambda) and say that lambda has any 2nπ value (as n is an integer) that makes the equation correct

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upper sigil
#

how would i do part 2

final saddleBOT
upper sigil
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i need to approximate

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but i forgor

tired walrus
#

wtf is this notation

upper sigil
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is for radioactive decay of something

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instantious rate of change

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at 12

tired walrus
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why not just write P'(12) lmao

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are we allergic to the word "derivative" here

upper sigil
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havent even learned that

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fuck

tired walrus
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you have learned of "instantaneous rate of change" but not derivatives?

upper sigil
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my teacher told us its like the average rate of change but at a single moment

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yeah

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i guess so

tired walrus
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well ok like. maybe you are in a calculus class that's about to get to that

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idk how you are expected to find its exact value tho!

upper sigil
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well usually i think id plug in values approaching p(12) from - and +

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so like

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y1(12) - y(11.999) / .001

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or something

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and then the same for the other direction and then find within 2 decimal of accuracy

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or something like that

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but when i do it for this it doesnt make sense

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i get a positive value

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when this is a decreasing function

worn knot
upper sigil
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yes

worn knot
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That should be negative

upper sigil
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its not

#

ok

#

well it is

#

but its like

#

-74840...

#

which do not make sense

worn knot
#

This is what desmos gives me

upper sigil
#

im not the smartest

#

i forgot a parenthesis

#

oopsie

upper sigil
#

preciate u

#

.close

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#
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valid atlas
final saddleBOT
valid atlas
#

I don't know where I am going wrong

vital crag
final saddleBOT
valid atlas
valid atlas
#

Never mind i was trying to skip too steps ugh

#

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fathom stream
#

@tired walrus this is what I ended up doing for the question earlier

fathom stream
#

is this good

tired walrus
#

i mean, extra work ig

tranquil pine
#

hello

tired walrus
final saddleBOT
tranquil pine
#

it's a good question

fathom stream
#

and instead

#

just put it as my claim

tired walrus
#

idk meh

#

no glaring faults

fathom stream
#

alr rt

#

ty

#

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valid atlas
final saddleBOT
#

Please don't occupy multiple help channels.

valid atlas
#

need help

final saddleBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

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@valid atlas Has your question been resolved?

valid atlas
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woeful anchor
#

i need help with this sheet

final saddleBOT
worthy shale
#

!status

final saddleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
woeful anchor
#

2

worthy shale
#

what about it?

woeful anchor
#

i have finished halfway through but i think got everything wrong

worthy shale
#

thanks

#

you might've differentiated s(t) wrong

#

try splitting up the terms and differentiating them separately

#

$s(t)=\frac2t-\frac4{t^2}$

soft zealotBOT
#

chlamydia

woeful anchor
#

i tried that too and i got this

#

is this right?

worthy shale
#

yeah

#

so that's your velocity, and the question asks for units too

woeful anchor
#

ok give me 2 mins

#

is this correct?

worthy shale
#

$-2t^{-2}+8t^{-3}$

soft zealotBOT
#

chlamydia

worthy shale
#

the negative in front of 2t^-2?

#

also units for the function

woeful anchor
#

what about now

worthy shale
#

do you understand what the units are?

woeful anchor
#

uhh idk

worthy shale
#

it means that distance is measured in feet, and time in seconds

#

so your s(t), which measures distance, is in feet

#

what about velocity?

woeful anchor
#

is it seconds?

worthy shale
#

just seconds?

#

when you talk about speed, it'd be something like miles/hour right?

woeful anchor
#

yeah

worthy shale
#

so the velocity here is feet/second?

woeful anchor
#

gotcha

#

but i dont get how would u indicate the units in this question

worthy shale
#

you could just write feet/s beside v(t) i guess

woeful anchor
#

does this work?

final saddleBOT
#

@woeful anchor Has your question been resolved?

woeful anchor
#

<@&286206848099549185>

#

@worthy shale

#

.close

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#
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woeful anchor
#

.reopen

final saddleBOT
#

woeful anchor
#

<@&286206848099549185>

#

someone avaiable pls help me out

worthy shale
#

what else

worthy shale
woeful anchor
#

ok cool also i corrected 3b can u check if its right

worthy shale
#

looks right

#

and the units?

woeful anchor
#

idk how to indicate the units for acceleration

worthy shale
#

velocity (ft/s) is the change in position (ft) over time

#

and acceleration is the change in velocity over time

woeful anchor
#

so acceleration ft/sec^2 ?

worthy shale
#

yeah

gritty drift
#

Imagine calculating in feet 🤢

worthy shale
#

fr

gritty drift
#

Meter >>>>>

woeful anchor
#

ok bet also i dont get c d e f i tried doing them when u were gone

worthy shale
#

c and d look good

#

now apply the same logic to e

woeful anchor
#

ok give me like 6 mins

#

Does this answer look good?

worthy shale
#

yeah

woeful anchor
#

ok

worthy shale
#

does your teacher care about show all working?

#

because then you should show how you found positive speed t<4, etc.

woeful anchor
#

yea she put in directions that said " Answer each question below, showing all work as described in class. Include units where appropriate"

worthy shale
#

how does she describe it?

woeful anchor
#

ill show u my notes from class

worthy shale
#

looks like it's fine

#

and you've noted how to do f

woeful anchor
#

it's there in the bottom of my notes

#

could u check question 3f if it's right

worthy shale
#

yup

woeful anchor
#

thanks man

worthy shale
#

np

woeful anchor
#

i alr finished the first page of the hw could u j check my answers before i leave

worthy shale
#

i'm having trouble reading what the first line says

#

$\frac1{xy}(y+y'x)$?

soft zealotBOT
#

chlamydia

worthy shale
#

second question is good

woeful anchor
worthy shale
#

$\frac d{dx}log_2(xy)=\frac1{ln2}\frac d{dx}ln(xy)$

soft zealotBOT
#

chlamydia

worthy shale
#

the logarithmic derivative only works for natural log

#

so from here it'd be more convenient to do:

#

$\frac d{dx}(lnx+lny)=\frac1x+\frac{y'}y$

soft zealotBOT
#

chlamydia

worthy shale
#

so you're missing a factor of $\frac1{ln2}$

soft zealotBOT
#

chlamydia

woeful anchor
#

oh

#

do i have to erase everything and start over for question 1

worthy shale
#

just add the 1/ln2 in

#

but it might be a hassle

woeful anchor
#

where do i add it? im confused

worthy shale
woeful anchor
#

liek this

worthy shale
#

yeah

woeful anchor
#

so question #1 is good now?

worthy shale
#

after you fix that throughout the question, it should be fine

woeful anchor
#

wait do i have to fix the other lines too?

worthy shale
#

yeah because it's the same derivative?

woeful anchor
#

what do i do? just add (1/ln(2) to every line?

worthy shale
#

you know what, it might be better to just redo the question

#

keep the photo so you know what to do

woeful anchor
#

okay

#

could u help me do it step by step cus i have no clue how to solve this question

worthy shale
#

it seems like you did it fine before though

#

it's just the problem with the log_2

woeful anchor
#

oh ok

#

i'll try to fix problem with log_2 and get back to you in few minutes

#

yea i tried solving question #1 didn't get an answer for some reason

worthy shale
#

what do you mean

woeful anchor
#

i did it halfway through and i was stuck

worthy shale
#

$\frac{y'}{yln2}=-3^xln3-\frac1{xln2}$

soft zealotBOT
#

chlamydia

worthy shale
#

did you get this?

woeful anchor
#

nah that wasn't my answer

#

can we go through the question together?

final saddleBOT
#
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tranquil pine
#

physics question, is this correct?

final saddleBOT
tranquil pine
#

i drew this on MS paint, i want to know if this is correct in terms of if its speeding up or slowing down (acceleration

#

ping if you have answer thank you

worthy shale
#

are those v-t graphs?

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

not sure

#

either vt or at

#

@worthy shale

worthy shale
#

you drew these?

#

what are they supposed to depict?

tranquil pine
#

sorry i dont know

#

im trying to check my notes but no idea

#

i think it might be PT. sorry for wasting ur time my questoin doesnt make sense if i dont know what it is

worthy shale
#

what is pt

#

they're most likely velocity graphs:
keeping in mind that speed is the magnitude of velocity, all that matters is how far the curve moves away from the x-axis

#

if it moves away from the axis like in the first graph, then it's speeding up

#

but in the green part, it's moving towards 0, so it's slowing down

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tranquil pine
final saddleBOT
tranquil pine
#

why isnt p(x<=6) also = (probability 7 students wont pass) + (probability 8 students wont pass) + (probability 9 students wont pass)

#

thinking about alternative ways to solve it

serene cradle
#

Unless I misunderstood your question

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#

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indigo plover
final saddleBOT
indigo plover
#

uh i am having some trouble

#

So i found the distance between ab bc and ac

#

Using the formula for distance

#

and i recently found out a^2+B^2=c^2 is the therom

#

But i dont understand what they want here for the conclusion

serene cradle
indigo plover
#

I plug them in

#

and i got 10, 40, and 26

serene cradle
#

Your value for AC seems wrong

indigo plover
#

Ah

#

I see

#

I fix brb

serene cradle
# indigo plover I plug them in

But also no, you don't have to plug them in just yet, you just have to find which distances are equal to a, b, and c in the formula

indigo plover
#

oh

serene cradle
#

And there's one main restriction that you have to respect: c must be the hypotenuse, which is defined as the longest edge in the triangle, or the side that is directly opposite the right angle

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#

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tawny frigate
final saddleBOT
tawny frigate
#

How do I find the parametric equations?

final saddleBOT
#

@tawny frigate Has your question been resolved?

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#

@tawny frigate Has your question been resolved?

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@tawny frigate Has your question been resolved?

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@tawny frigate Has your question been resolved?

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tepid forum
#

I dont need help with a problem per say, but in general I know if you have polynom you can turn x^4 and x^2 into t^2 and t.

tepid forum
#

What if you have an uneven x among these, like x^3 ?

#

what do you do then?

#

.close

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glad mango
#

Hello! I have to show using the power method, which of these converge and their lambdas / eigenvalues throughout the iterations

glad mango
#

For the top 1, I get this plot:

#

And for the bottom one:

#

My question is then: Using the power method, what determines whether they will converge or not? I have run the simulation with 10mil iterations with no apparent convergence.

So far, I've read that it depends on the start vector and the complexity of the eigenvalues, but I am not sure how any of those apply to my example. The second one has a pretty fractionized eigenvalue, but I need some clarity / help please

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#

@glad mango Has your question been resolved?

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#

.close

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dense garnet
#

Consider $F(x)=(x,\sqrt{1+x^2})$. What conditions on $x$ do I need to impose in order for $F$ to be Lipschitz continuous on some $A\subseteq\mathbb R$?

soft zealotBOT
#

sunside

teal hamlet
#

Can I get some help with these questions pls

dense garnet
#

.close

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keen dragon
#

hellooo

final saddleBOT
keen dragon
#

im not really sure how to start

#

;-;

final saddleBOT
#

@keen dragon Has your question been resolved?

final saddleBOT
#

@keen dragon Has your question been resolved?

keen dragon
#

.close

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charred pebble
#

Hi

final saddleBOT
charred pebble
rancid idol
#

,calc 8 + 9 * 6

soft zealotBOT
#

Result:

62
rancid idol
#

youve swapped the positions of both numbers in both diagonals

#

thats not how the 2x2 inverse works

charred pebble
#

Wait sorry

#

One sec

rancid idol
#

youve misremembered

charred pebble
#

Okay no so

#

Finding the inverse cant you just find matrix of cofactors

#

Then multiple by 1/det

rancid idol
#

uh maybe!? but i sure as hell wouldnt be doing that for a 2x2 matrix

charred pebble
#

Or that doesnt work for 2x2

rancid idol
#

ofc it would work

charred pebble
#

But the matrix of cofactors for this matrix is not that

rancid idol
#

in practice, most people do not use that method to compute determinants, i dont

#

i would personally row reduce, if anything

rancid idol
strange palm
charred pebble
#

Okay but look

#

Is this not the matrix of cofactors for that matrix

drowsy scroll
#

you only have to swap across one diagonal

rancid idol
#

i dont know this method, honestly

drowsy scroll
#

not the other one

charred pebble
#

The first pic is the matrix of cofactors for the second

#

Wait what

drowsy scroll
#

the one with the negation doesn’t swap

charred pebble
#

Can some call?

worldly vale
#

one step in the cofactor method is you transpose the matrix

charred pebble
#

Okay the method I was taught

drowsy scroll
#

the top row is d, -b
the bottom row is -c, a

#

if the matrix is
a b
c d

charred pebble
#

Is that the matrix of minor is all the entries that are not in the row and column of the entry your finding the minor for

#

Then the cofactor is just differing signs of the minor

worldly vale
#

you're just forgetting to transpose

#

to get adj(A)

charred pebble
#

You have to transpose to find inv?

#

Oh shit

#

Yeah thats what I forgot

#

But thay is the cofactor rightt

#

.close

final saddleBOT
#
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near gull
#

I'm tryna do a

#

I don't understand how to use the diagram to explain it

robust mulch
#

What us the length of the big hypotenuse using pythagorean theorem?

near gull
#

squrt of 45

#

sqrt 45

robust mulch
#

Yes

#

Now the two traingles in the diagram are similar with a scaling factor of 3

near gull
#

yeah

#

what next

robust mulch
#

big hyptenuse = 3 × small hypotenuse

near gull
#

ahh

#

tysm

#

.close

final saddleBOT
#
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Channel closed

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craggy orchid
#

can someone help with question 8 and 9

tranquil pine
plucky raptor
#

,rotate

soft zealotBOT
craggy orchid
#

anyone working on it ?

plucky raptor
#

what did you try?

craggy orchid
#

idk u can see my working out there i had no idea what i was doing

plucky raptor
#

you mean that work was just guessing ?

craggy orchid
#

yh ig

#

the t and t+1

#

is confusing

final saddleBOT
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plucky raptor
#

?

final saddleBOT
plucky raptor
#

idk why it closed

#

anyways

#

ok so he travels for some amount of hours, call it t, with an average of 90, then he travels for another hour, making the total driving hours t+1. and he traveled for 30 km. making the average 78

craggy orchid
#

yes

#

makes sense

rancid idol
plucky raptor
#

so consider the total hours he traveled

#

which t+1

craggy orchid
#

ohhh

plucky raptor
#

if you want to write the formula of the average speed for his entire journey

craggy orchid
#

i kept writing 2t+1

plucky raptor
#

how would you do it?

craggy orchid
#

so speed is distance over time so therefore its 30km added on with the last distance

#

over t+1

#

but we dont know

#

the last distance

plucky raptor
#

yeah that's correct

#

you can calcualte it

#

at least

verbal pendant
#

Are you on the first or second part rn?

craggy orchid
#

first

verbal pendant
#

Ok gotchu

plucky raptor
#

the question said, he travel for t hours, with an average speed of 90

#

can you get the distance from this?

#

an expression that eqauls the distance

craggy orchid
#

90t

plucky raptor
#

there you go

craggy orchid
#

totoal distance is 90t +30

plucky raptor
#

that's the last distance

#

exactly

#

so how would you write the whole formula now?

craggy orchid
#

90t+30 over

plucky raptor
#

for the average speed of the entire journey

craggy orchid
#

t+1

plucky raptor
#

which is equal to?

craggy orchid
#

uhhh

#

average speed

plucky raptor
#

look at the question again

craggy orchid
#

78

plucky raptor
#

yaeh

craggy orchid
#

but i m confised about the

#

90

plucky raptor
#

why?

craggy orchid
#

oh wait nvm

#

his average drops to 78

#

for ther Whole journey

plucky raptor
#

correct

#

it was 90 for the first t hours

#

then the next hour it became 78

craggy orchid
#

makes sense

#

yes

#

thank u very much

plucky raptor
#

now solve for t and continue

craggy orchid
#

can u help with 9 as well

verbal pendant
#

Do you have any ideas or no?

craggy orchid
#

not at all

#

nothing for 9

verbal pendant
#

All good

craggy orchid
#

i have no clue

#

i tried like

verbal pendant
#

Can we make the two amounts equal in some way

craggy orchid
#

making a formula

#

but odl

#

idk

verbal pendant
#

Well let’s try to find an equality here

#

Firstly, what’s the original cut per winner

craggy orchid
#

but we dont know the amount of winners

#

initially

verbal pendant
#

Let’s set x as the amount of winners

craggy orchid
#

ok

#

yes

verbal pendant
#

Can you write an expression for the amount of money each winner gets

craggy orchid
#

1540/x initally

#

and then

#

1540/x+3

verbal pendant
#

Yep

#

And then if we want to set them equal what do we have to do

#

Each person gets 66 less when there are 3 more winners

craggy orchid
#

lol i dont understand

#

thats the part where i get confused

#

do u take away 66 lots of 3 or something ?

verbal pendant
#

So what we want to do is what our two expressions be equal to each other

verbal pendant
#

Remember we are calculating per winner

#

So 1540/x = 1540/(x+3) + what

craggy orchid
#

x-(66x3) ?

verbal pendant
#

How did you get that number

craggy orchid
#

or is it

#

x-66

#

for one

#

winner

verbal pendant
#

I gtg for a few minutes sorry

craggy orchid
#

its okay

verbal pendant
#

Think about the difference per person, if you get 66 less with three more people how do you incorporate that into what we had above

#

Ok I’m back

verbal pendant
craggy orchid
#

yes

#

but its 66 less per person

#

so 66 less per winner right ?

verbal pendant
#

Huh

#

Yea it’s 66 less per winner

#

But why x - 66?

craggy orchid
#

oh wait

#

yh why

#

omg

#

x is the number of winners

#

not the amount of money

#

smh

verbal pendant
#

I was wondering if that was the mistake

#

So what is the equation now?

craggy orchid
#

is it plus

#

1540-66

#

on the end

verbal pendant
#

We had 1540/x = 1540/(x+3)

#

Which side are you gonna add/subtract 66

craggy orchid
#

right side

verbal pendant
#

Add or subtract

craggy orchid
#

subtract right

#

no

#

wait

verbal pendant
#

You would subtract from the left

craggy orchid
#

why?

verbal pendant
#

Subtracting from the right would mean when you add three winners, you gain 66 each. We subtract to equalize the equation

craggy orchid
#

confusing to understand

#

like the equating of the equations

verbal pendant
#

Kinda yeah

#

The left side, each person gets 66 more, so we would need to subtract 66, and vise versa on the right

craggy orchid
#

why does each person get 66 more on tje left

verbal pendant
#

It’s just how the problem was set up

#

1540/x - 66 = 1540/(x + 3)

#

This should give an answer

craggy orchid
#

i see okay thank you

final saddleBOT
#

@plucky raptor Has your question been resolved?

#
Channel closed

Closed by @plucky raptor

Use .reopen if this was a mistake.

#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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viscid badger
#

Im not understanding this question. I have f(x)=cot(x)-1/x. Now for all x ∈ R with x ̸ = nπ, n ∈ Z. how do i find lim x->π- ?
How am i do to it if x /= π?

viscid badger
#

<@&286206848099549185>

worthy shale
#

$\lim_{x\to\pi^-}(cotx-\frac1x)$

soft zealotBOT
#

chlamydia

worthy shale
#

it may help to consider the two terms separately

#

$\lim_{x\to\pi^-}cotx-\lim_{x\to\pi^-}\frac1x$

soft zealotBOT
#

chlamydia

viscid badger
#

Well. I have calculated it and gotten it to -infinity. But what is confusing me is for all x ∈ R with x ̸ = nπ, n ∈ Z

#

How would i write this in texit.

worthy shale
#

$\forall x\in\mathbb{R}, x\neq n\pi, n\in\mathbb{Z}$

soft zealotBOT
#

chlamydia

viscid badger
#

Just took at picture

worthy shale
#

yeah

#

what about it

viscid badger
#

Dosnt that mean anything?

worthy shale
#

the limit's -infinity

#

that there's an asymptote

#

like cotx has

#

are you concerned about limiting to x=pi when it says x/=pi?

viscid badger
#

So it doesnt change the fact that cot(pi) approaches 0 infinitively close, so -infinty?

#

idk honestly

worthy shale
#

cot(pi) goes to -infinity though?

viscid badger
#

wait are you asking me now?

worthy shale
#

cot(pi) approaches 0 infinitively close
what do you mean by this

viscid badger
#

Well limx→π- (cot(x))

worthy shale
#

is -infinity

viscid badger
#

how so

worthy shale
#

cotx=1/tanx

#

cotpi=1/tanpi=1/0

#

or you could look at graph

viscid badger
#

and 1/0 gives infinity

#

or what

worthy shale
#

the limit approaches 0 from negative, so it'll be -infinity

#

tanx: limit x->pi- means you get 0-

#

which turns into -infinity on cotx
but x->pi+ is +infinity

viscid badger
#

alright hmm

#

so would 1/0 always be +- infinty?

#

or just this one ?

worthy shale
#

typically assuming 0 is positive
but you can't be certain without knowing how it approaches limit

#

depending on the function

viscid badger
#

but wait

#

the 2nd picture you send makes sense, i can see it forever getting closer, but the first one goes thorugh it, does it not?

worthy shale
#

yeah, which becomes the asymptote

viscid badger
#

idk why im so confused

worthy shale
#

if a function f(x) goes through 0, 1/f(x) will have an asymptote at that same place

#

depending on whether f(x) reached 0 from positive side or negative side, 1/f(x) will shoot to +infinity or -infinity

#

for both sides

#

it's the difference between what happens when it approaches, and what's actually there

viscid badger
#

okay but then, shouldnt the answer be -0 since it hits?

#

and not - infinity

worthy shale
#

for cot?

viscid badger
#

yeah

worthy shale
#

cot(pi) doesn't approach 0

viscid badger
#

oh yeah

#

it approches pi

worthy shale
#

woah

#

tan(pi)=0, cot(pi)=1/tan(pi)=1/0- --> -infinity

viscid badger
#

I think i need to do some heavy reading on this, for i can for the love of god not understand

worthy shale
viscid badger
#

well isnt lim x->-pi that is goes towards pi-?

#

NO WAIT

worthy shale
#

for$\lim_{x\to\pi-}cotx$

soft zealotBOT
#

chlamydia

viscid badger
#

My x is pi

#

jesus

#

i think i need a break

#

@worthy shalehey man, thanks. Im sorry for being so burdensome

worthy shale
#

no it's ok

#

it's a lot to take in

final saddleBOT
#

@viscid badger Has your question been resolved?

#
Channel closed

Closed by @viscid badger

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.