#help-36
1 messages · Page 52 of 1
the answer to the question of whether the point
(p,0) is an x-intercept is the same answer to
is g(p) equal to 0
gotcha
so the only point they have here that is simple is the y int and the hole
how do you go about getting the other points
sub in values of x (whatever you want, as many as you want)
into your function equation
to get the respective y values
so any other number would also give the same graph
the same with all other graphs
if you want to find the y-coord when x=1, you sub x=1 into the equation
is there any logic
if you for some reason wanted the y-coord when x = 420,
sub that into the equation
like pick the number closest to y int
pick whatever you want
pick nice meaningful values if you don't want to make life hard for yourself
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I am not sure how to approach this question.
I know that tension will face upwards the string, the weight acts downwards.
I'm guessing that I'd have to resolve forces and equate.
@tranquil pine Has your question been resolved?
@tranquil pine Has your question been resolved?
@tranquil pine Has your question been resolved?
i did is as g=10 and found that f =1kg*g so if g=10 it would be 10 but if its 9,81 the asnwer would be 9,81
tension of string is 2sqrt3*a which is sqrt3 of g so tension would be sqrt3 kg g where g represents gravitinial acceleration
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Could someone please explain structural induction
like whats the difference between structural and regular induction
and when do we use structural induction
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i wanna show that this series converge
i know that the same sum but with k=1 converge
if you start at n+1 you're summing the tail of the series
any tail of a convergent series is also convergent
because it differs from the whole series by only finitely many terms
why do you have to calculate the sum
you just want to know if the sequence R_n converges
the exercie ask for it x)
where? show the whole question
no it's the next question
yes
i don't see how to apply taylor here
to be precise i said calculate the sum, not the limit which is not the same
try using
x=1?
yes?
ah you mean from that?
yes
i know what it is don't worry
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can someone help
Yeah for x
But we want the value for y
But take the real value for x before rounding and apply it to the equation then round
okay so what would that equal to
Apply it the function
To get the maximum profit
,calc -25001.91.9 + 9500*1.9 - 7426
Result:
1599
okay that was pretty easy bgl idk why it went over my head
yes imma put it in the system now n see how it’s gonna rest
say
so
for c it’s b
and for for d
what would i do then
To solve the third question
Obviously the first choice won't output the same maximum profit as the x value would still be the same but the maximum profit is less by 3 dollars
So it is the second one
To test that out just substitute (x-3) to x and apply what you applied already to get a and b
Can you compare between the maximum profit
And the best price that produces the best profit?
i’m
The second one is what you get out of applying the derivative to the function and equating it to zero to get the x value
The first one is applying that x value to the function to get the maximum profit
okay
so
it’s the same thing we did for the first question but plug in (x-3)?
it’s 4.90?
$$-2500(x-3)^2 + 9500(x-3) - 7426$$
$$-2500x^2 + 15000x - 22500 + 9500x - 28500 - 7426$$
Take derivative
$$-5000x + 15000 + 9500$$
Equate to zero
$$-5000x + 24500 = 0$$
$$-5000x = -24500$$
Sherif Player
,calc 24500/5000
Result:
4.9
Yeah correct
And for the final question
It will be the same as b
But add 50
As x doesn't change and we are adding to the whole profit
no that’s it ty
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so these are the problems i need to do and im like 99.9% sure the answer is x but i dont know how to get there
for f(g(x)), you and remove the parentheses around the cuberoot of x - 2, then the 2's will cancel each other out. Then you have the cube root to a cubic power, so then you're just left with x. Similar logic with g(f(x))
is there a way u could like write that down
like so i can visually see it but if u cant thats fine
actually nevermind its alright and thank u so much!!
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How would you differentiate this?
$$1+\ln(5xy)=e^{5x-y}$$
What should I do
@tranquil pine Has your question been resolved?
Respect to which variable are you trying to differentiate?
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This is a graph of a rational function. Use the function's graph to determine the equation for its formula
I do know that the function for rational functions is (ax+b) / (cx + d), and got some understanding of asymptotes, but I struggle to find the way of finding the values for the variables
$\frac{ax+b}{cx+d}$
are you familiar with limits?
\frac{(ax+b)}{(cx+d)}
Seed
thanks mate
Not that much, but I am aware that the x-value -2 cannot be present in the equation
Do you know homographique function ?
it's the vertical asymptote, and it's a sign that we have a denominator that is equal to zero when x = -2
i do not know that
i have at least not heard the name
if you're refering to the functions for the vertical and horizontal asymptote, where horisontal is equal to a/c, and vertical is -b/a then yes i they are familiar
Ok no pb, it tells you that $\dfrac{ax+b}{cx+d}$ can be rewritten as $\dfrac{\alpha}{x-\beta}+\gamma$
Joseph.P
Ye this
$\dfrac{\alpha}{x-\beta}+\gamma is unfamiliar to me$
Seed
it is my first time seeing the equation, but i am familiar of the ones i've writte
$\gamma$ is the limit of the function, $\beta$ the value when $x=\frac{-d}{c}$ and I forgot what is $\alpha$
Joseph.P
okay
Here what would be beta and gamma ?
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.this is cool
Not sure where to start
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
nothing, just the guy saying you have to solve sounds a bit off
Substitute 4 for x, then simplify/evaluate and end up with a number for your final answer
Ok, sorry for the ping then
-4
^^
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I am super fucking confused

🗿🗿
ye

before we continue
You’re telling me there is no value of f(x) when x=4 ?
is this college or highschool or middle school
Why would I think of doing x = 4 tho
I mean I got 4 points kind of
Is it supposed to be symmetric
okay so you know limits
No
To know the graph maybe
not yet alright
Why does x = 4 matter
To know the graph
Isnt what I have already plenty
How do I know when enough is enough
In future graphs

@glad basalt you know what you call the ratio function where x is in the denominator?
for example what's 1/x called
🗿🗿
Idk
Man I just saw something
Try simplifying your function
you get y=2
No
You get y=2
bro with the emojis 😭
Teach me 
you said it yourself
2(x+2)/(x+2)
simplify what you can after you find your holes
x+2=x+2
Fucki
so you are left with y=2 for any x expect x = -2
What do you do so you can move x + 2 there
So this
idk what that means
When u div same stuff they cancel cmon
but you are already dividing initially
yeah but no extra division just simplicify the function after factoring
Damn that is
Hella
Fucking
Interesting
So I don’t need to annoy myself with plugging x’s
How do I pick my points
what does that mean
you delete it all
Ok
That was sending
It is deleted
Now what
??
My x int is 0 -2
y int 2,0
I have a question, what are all the points ?
What is the dotted line ?
The "hole" is the value of x when the denominator of your function is equal to 0
Is it-2, 2
Is 2+2=0 ?
I was taught that to find the y of the hole’s x
You remove what creates the hole
I.e. x + 2
Then all I have left is 2
Why doesn’t that work here
This just simplifying the fraction no ?
Ye
But you can’t simplify a fraction of the denominator is equal to 0
No it wouldn’t work either, what if x=-2 ?
Fucking
So I should say no to simplifying
And just plug in my x
Into the function
is it -2, 0?
0/0

No you can simplify but you need to be careful of when the denominator is equal to 0
Is it equal to zero after you simplify?
But if you were to divide x + 2 and x + 2 you would get 1 right
Why is it zero
It’s not defined when x=-2
So dem is zero when x = -2
In this example yes
Do I not plot a hole anywhere?
Yes you do plot one when the denominator is equal to 0 for a certain value of x that you just said
For which value of x (2x+4)/(x+2) is 0/0 ?
Ye
Okkk now what
@stark lotus
Thats wrong
-2 still produces y = 2
The hole is -2, 2
Show your work please
I mean the graph
Ye
Lol what?
You just said
I sais you plot a hole when the denominator is equal to 0
Is it to hard to understand ?
You literally said its not 2
That the y value of -2 is not 2
You said not to simplify
But if I did
I would get 2
I thought you meant x=-2 and x=2 so I didn’t understand
Look at this
Y = 2 for any x expect -2
By y is 2 for -2
This is not making any sense
It’s not 2 for -2 this point is the hole
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A quantum particle can be trapped in a one-dimensional potential well if the equation:
has a solution for 0<y<lambda
Proof that there is at least one solution in the interval
The following error occured while calculating:
Error: Colon : expected after object key (char 14)
@tranquil pine Has your question been resolved?
So i don't know anything about quantum physics
But I can help you solve the equation
First I think we need to define what tan(lambda) is
@tranquil pine
Cause you can easily set
y = √(lambda) and say that lambda has any 2nπ value (as n is an integer) that makes the equation correct
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how would i do part 2
wtf is this notation
my teacher told us its like the average rate of change but at a single moment
yeah
i guess so
well ok like. maybe you are in a calculus class that's about to get to that
idk how you are expected to find its exact value tho!
well usually i think id plug in values approaching p(12) from - and +
so like
y1(12) - y(11.999) / .001
or something
and then the same for the other direction and then find within 2 decimal of accuracy
or something like that
but when i do it for this it doesnt make sense
i get a positive value
when this is a decreasing function
It should be (y(12) - y(11.999)) / 0.001
yes
That should be negative
This is what desmos gives me
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I don't know where I am going wrong
!show
Show your work, and if possible, explain where you are stuck.
This is my best picture
Never mind i was trying to skip too steps ugh
.close
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@tired walrus this is what I ended up doing for the question earlier
is this good
i mean, extra work ig
hello
!occupied
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it's a good question
should I exclude the "modifying the rref" part
and instead
just put it as my claim
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need help
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i need help with this sheet
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
2
what about it?
thanks
you might've differentiated s(t) wrong
try splitting up the terms and differentiating them separately
$s(t)=\frac2t-\frac4{t^2}$
chlamydia
$-2t^{-2}+8t^{-3}$
chlamydia
what about now
do you understand what the units are?
uhh idk
it means that distance is measured in feet, and time in seconds
so your s(t), which measures distance, is in feet
what about velocity?
is it seconds?
yeah
so the velocity here is feet/second?
you could just write feet/s beside v(t) i guess
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✅
what else
it might be better to put the units at the end
ok cool also i corrected 3b can u check if its right
idk how to indicate the units for acceleration
velocity (ft/s) is the change in position (ft) over time
and acceleration is the change in velocity over time
so acceleration ft/sec^2 ?
yeah
Imagine calculating in feet 🤢
fr
Meter >>>>>
ok bet also i dont get c d e f i tried doing them when u were gone
yeah
ok
does your teacher care about show all working?
because then you should show how you found positive speed t<4, etc.
yea she put in directions that said " Answer each question below, showing all work as described in class. Include units where appropriate"
how does she describe it?
ill show u my notes from class
yup
thanks man
np
i alr finished the first page of the hw could u j check my answers before i leave
chlamydia
second question is good
it says 3^x ln(3) + 1/(xy) (y+y'x)
$\frac d{dx}log_2(xy)=\frac1{ln2}\frac d{dx}ln(xy)$
chlamydia
the logarithmic derivative only works for natural log
so from here it'd be more convenient to do:
$\frac d{dx}(lnx+lny)=\frac1x+\frac{y'}y$
chlamydia
so you're missing a factor of $\frac1{ln2}$
chlamydia
where do i add it? im confused
times this
yeah
so question #1 is good now?
after you fix that throughout the question, it should be fine
wait do i have to fix the other lines too?
yeah because it's the same derivative?
what do i do? just add (1/ln(2) to every line?
you know what, it might be better to just redo the question
keep the photo so you know what to do
okay
could u help me do it step by step cus i have no clue how to solve this question
oh ok
i'll try to fix problem with log_2 and get back to you in few minutes
yea i tried solving question #1 didn't get an answer for some reason
what do you mean
i did it halfway through and i was stuck
$\frac{y'}{yln2}=-3^xln3-\frac1{xln2}$
chlamydia
did you get this?
???
.close
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physics question, is this correct?
i drew this on MS paint, i want to know if this is correct in terms of if its speeding up or slowing down (acceleration
ping if you have answer thank you
are those v-t graphs?
@tranquil pine Has your question been resolved?
sorry i dont know
im trying to check my notes but no idea
i think it might be PT. sorry for wasting ur time my questoin doesnt make sense if i dont know what it is
what is pt
they're most likely velocity graphs:
keeping in mind that speed is the magnitude of velocity, all that matters is how far the curve moves away from the x-axis
if it moves away from the axis like in the first graph, then it's speeding up
but in the green part, it's moving towards 0, so it's slowing down
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why isnt p(x<=6) also = (probability 7 students wont pass) + (probability 8 students wont pass) + (probability 9 students wont pass)
thinking about alternative ways to solve it
Well that's effectively the way you calculate it, isn't it? You find the probability that 7, 8, or 9 students (respectively) pass, and subtract it from 1 as we don't want to count those probabilities
Unless I misunderstood your question
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uh i am having some trouble
So i found the distance between ab bc and ac
Using the formula for distance
and i recently found out a^2+B^2=c^2 is the therom
But i dont understand what they want here for the conclusion
So for this theorem, c is the hypotenuse. You're essentially just substituting the letters (a, b, and c) with the corresponding edges from the triangle in the graph
Your value for AC seems wrong
But also no, you don't have to plug them in just yet, you just have to find which distances are equal to a, b, and c in the formula
oh
And there's one main restriction that you have to respect: c must be the hypotenuse, which is defined as the longest edge in the triangle, or the side that is directly opposite the right angle
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How do I find the parametric equations?
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I dont need help with a problem per say, but in general I know if you have polynom you can turn x^4 and x^2 into t^2 and t.
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Hello! I have to show using the power method, which of these converge and their lambdas / eigenvalues throughout the iterations
For the top 1, I get this plot:
And for the bottom one:
My question is then: Using the power method, what determines whether they will converge or not? I have run the simulation with 10mil iterations with no apparent convergence.
So far, I've read that it depends on the start vector and the complexity of the eigenvalues, but I am not sure how any of those apply to my example. The second one has a pretty fractionized eigenvalue, but I need some clarity / help please
@glad mango Has your question been resolved?
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Consider $F(x)=(x,\sqrt{1+x^2})$. What conditions on $x$ do I need to impose in order for $F$ to be Lipschitz continuous on some $A\subseteq\mathbb R$?
sunside
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hellooo
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Hi
,calc 8 + 9 * 6
Result:
62
youve swapped the positions of both numbers in both diagonals
thats not how the 2x2 inverse works
youve misremembered
Okay no so
Finding the inverse cant you just find matrix of cofactors
Then multiple by 1/det
uh maybe!? but i sure as hell wouldnt be doing that for a 2x2 matrix
Or that doesnt work for 2x2
ofc it would work
But the matrix of cofactors for this matrix is not that
in practice, most people do not use that method to compute determinants, i dont
maybe someone can help in #linear-algebra
i would personally row reduce, if anything
sir can u help me
not your channel.
wdym
you only have to swap across one diagonal
i dont know this method, honestly
not the other one
the one with the negation doesn’t swap
Can some call?
one step in the cofactor method is you transpose the matrix
Okay the method I was taught
Is that the matrix of minor is all the entries that are not in the row and column of the entry your finding the minor for
Then the cofactor is just differing signs of the minor
You have to transpose to find inv?
Oh shit
Yeah thats what I forgot
But thay is the cofactor rightt
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What us the length of the big hypotenuse using pythagorean theorem?
big hyptenuse = 3 × small hypotenuse
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Closed due to the original message being deleted
please send in png
,rotate
anyone working on it ?
what did you try?
idk u can see my working out there i had no idea what i was doing
you mean that work was just guessing ?
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?
idk why it closed
anyways
ok so he travels for some amount of hours, call it t, with an average of 90, then he travels for another hour, making the total driving hours t+1. and he traveled for 30 km. making the average 78
.
ohhh
if you want to write the formula of the average speed for his entire journey
i kept writing 2t+1
how would you do it?
so speed is distance over time so therefore its 30km added on with the last distance
over t+1
but we dont know
the last distance
Are you on the first or second part rn?
first
Ok gotchu
the question said, he travel for t hours, with an average speed of 90
can you get the distance from this?
an expression that eqauls the distance
90t
there you go
totoal distance is 90t +30
90t+30 over
for the average speed of the entire journey
t+1
which is equal to?
look at the question again
78
yaeh
why?
now solve for t and continue
can u help with 9 as well
All good
Can we make the two amounts equal in some way
Well let’s try to find an equality here
Firstly, what’s the original cut per winner
Let’s set x as the amount of winners
Can you write an expression for the amount of money each winner gets
Yep
And then if we want to set them equal what do we have to do
Each person gets 66 less when there are 3 more winners
lol i dont understand
thats the part where i get confused
do u take away 66 lots of 3 or something ?
So what we want to do is what our two expressions be equal to each other
Close
Remember we are calculating per winner
So 1540/x = 1540/(x+3) + what
x-(66x3) ?
How did you get that number
I gtg for a few minutes sorry
its okay
Think about the difference per person, if you get 66 less with three more people how do you incorporate that into what we had above
Ok I’m back
Why the x here, remember x is the amount of winners
right side
Add or subtract
You would subtract from the left
why?
Subtracting from the right would mean when you add three winners, you gain 66 each. We subtract to equalize the equation
Kinda yeah
The left side, each person gets 66 more, so we would need to subtract 66, and vise versa on the right
why does each person get 66 more on tje left
It’s just how the problem was set up
1540/x - 66 = 1540/(x + 3)
This should give an answer
i see okay thank you
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Im not understanding this question. I have f(x)=cot(x)-1/x. Now for all x ∈ R with x ̸ = nπ, n ∈ Z. how do i find lim x->π- ?
How am i do to it if x /= π?
<@&286206848099549185>
$\lim_{x\to\pi^-}(cotx-\frac1x)$
chlamydia
it may help to consider the two terms separately
$\lim_{x\to\pi^-}cotx-\lim_{x\to\pi^-}\frac1x$
chlamydia
Well. I have calculated it and gotten it to -infinity. But what is confusing me is for all x ∈ R with x ̸ = nπ, n ∈ Z
How would i write this in texit.
$\forall x\in\mathbb{R}, x\neq n\pi, n\in\mathbb{Z}$
chlamydia
Dosnt that mean anything?
the limit's -infinity
that there's an asymptote
like cotx has
are you concerned about limiting to x=pi when it says x/=pi?
So it doesnt change the fact that cot(pi) approaches 0 infinitively close, so -infinty?
idk honestly
cot(pi) goes to -infinity though?
wait are you asking me now?
cot(pi) approaches 0 infinitively close
what do you mean by this
Well limx→π- (cot(x))
is -infinity
how so
the limit approaches 0 from negative, so it'll be -infinity
tanx: limit x->pi- means you get 0-
which turns into -infinity on cotx
but x->pi+ is +infinity
typically assuming 0 is positive
but you can't be certain without knowing how it approaches limit
depending on the function
but wait
the 2nd picture you send makes sense, i can see it forever getting closer, but the first one goes thorugh it, does it not?
yeah, which becomes the asymptote
idk why im so confused
if a function f(x) goes through 0, 1/f(x) will have an asymptote at that same place
depending on whether f(x) reached 0 from positive side or negative side, 1/f(x) will shoot to +infinity or -infinity
for both sides
it's the difference between what happens when it approaches, and what's actually there
for cot?
yeah
cot(pi) doesn't approach 0
I think i need to do some heavy reading on this, for i can for the love of god not understand
can you try to explain this?
for$\lim_{x\to\pi-}cotx$
chlamydia
My x is pi
jesus
i think i need a break
@worthy shalehey man, thanks. Im sorry for being so burdensome
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