#help-36

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final saddleBOT
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wind river
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I understand that S is an element of the power set of [n]

fossil geyser
# final saddle

Hey the bot is gonna lock this channel, you should make a new one

final saddleBOT
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wind river
#

gotcha

final saddleBOT
wind river
steep sequoia
final saddleBOT
# wind river
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
wind river
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1

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i dont know where to begin

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the idea i have rn is

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ik that i have to use

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simple induction

steep sequoia
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Yeah. That's what i did.

wind river
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and that S is an element of the power set of [n]

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and that the summation

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is adding up all the elements

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in the power set

steep sequoia
wind river
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phi?

steep sequoia
steep sequoia
wind river
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ah yeah

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since its nonempty

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so for

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the example they gave

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{{1}, {2}, {3}, {1,2}, {1,3}, {2,3}, {1,2,3}}

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so 1/1 + 1/2 + 1/3 + 1/1x2 + 1/3x1 + 1/2x3 + 1/2x3x1

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uhh

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so the base case is easy

steep sequoia
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Yeah.

wind river
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the IH would be the summation of [k] where Sk = [a1 a2 a3 ... ak]

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and 1/S! = k

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now i need to show the [k+1] holds

steep sequoia
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Yes.

wind river
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how i do this is where

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im lost

subtle lava
wind river
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uh

steep sequoia
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So, [k+1] is just [k] U {k+1}.

wind river
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@subtle lava wrong channel friend

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yeah

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thats what i was thinking

steep sequoia
wind river
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so Sk U Sk+1

steep sequoia
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Umm... why are you doing that?

wind river
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i was thinking

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that

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for the summation

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we would need

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the elements that doesnt include k+1

steep sequoia
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Sk+1 already includes Sk.

wind river
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oh yeah

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mb

steep sequoia
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You know that Summation(S!) for [k+1] will have all the terms of summation(S!) for [k].

wind river
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yeah

steep sequoia
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So, you write {Summation(S!) for [k+1]} as {summation(S!) for [k]} + <some extra terms>.

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Then you show that those extra terms sum up to exactly 1.

wind river
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hm

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yea hsince

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Sk! = k

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by IH

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uhh

steep sequoia
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Yes

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So, we'll show that S! for [k+1] is k+1.

wind river
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yeah

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the extra terms

steep sequoia
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Now, you can easily write those extra terms if you notice what is special about them.

wind river
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would be all the summations that include k+1

steep sequoia
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Yes.

wind river
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uh the power set of k+1?

steep sequoia
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All those terms which have k+1.

wind river
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yeah

steep sequoia
wind river
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the powerset not including the empty**

steep sequoia
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you can say it this way: Power set of [k+1] - Power set of [k]

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However, this notation doesn't really help us much.

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Try to think about them in terms of combinations.

wind river
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uhh

wind river
steep sequoia
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Yes

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Think about it. All the set that are in Power set of [k] - if we just add (k+1) to them, we get almost all the terms which have (k+1).

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Only one term is left. Which one?

wind river
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k+1?

wind river
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like if k+1 was 3

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the original power set is

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{1} {2} {1 2}

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and then adding in k+1

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we get

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{1 k+1} {2 k+1} {1 2 k+1}

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so k+1 is missing?

steep sequoia
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Yes

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So, after all, You have -
{S! for [k+1]} = {S! for [k]} + S! for sets in [{k+1} {1 k+1} {2 k+1} {1 2 k+1}]

wind river
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mhm

steep sequoia
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Now, try writing product for those sets.

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You'll see something magical happen. 😌

wind river
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uh

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S! for k simplifies to k

steep sequoia
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Why not?

wind river
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{k+1} {1 k+1} {2 k+1} {1 2 k+1}

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{k+1} should be missing no?

steep sequoia
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Why should it be missing?

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Is that not a set having k+1 ?

wind river
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since the empty set isnt included?

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am i being dumb

steep sequoia
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{k+1} isn't an empty set.

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It has one element.

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Empty sets have no element.

steep sequoia
wind river
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right

steep sequoia
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Why won't you take {3} ?

wind river
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this

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oooog

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wait your right mb

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i get it we have to include k+1

steep sequoia
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Good.

steep sequoia
wind river
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which is

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uhh

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3/k+1

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and since k is 2

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3/3 = 1

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in the case where k is arbitrary

wind river
steep sequoia
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Yes

wind river
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how do i derive this properly?

steep sequoia
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But you need to show it using variables.

wind river
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using variables

steep sequoia
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Can't do using some values.

wind river
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yeah

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it'd be

steep sequoia
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Let me write it out for you and it should give you some hint.

wind river
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gotcha

steep sequoia
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$k + \left( \left[\frac{1}{k+1}\right] + \left[\frac{1}{(k+1) \cdot 1} + \frac{1}{(k+1) \cdot 2} + \cdots\right] + \left[\frac{1}{(k+1) \cdot (1\cdot2)} +\frac{1}{(k+1) \cdot (1\cdot3)} + \cdots\right] + \cdots \text{ so on for 3 terms taken with k+1 in S! and then 4 and so on...} + \left[\frac{1}{1\cdot 2\cdot 3\cdot 4 \cdots k \cdot k+1}\right]\right)$

wind river
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damn

steep sequoia
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Gosh.

wind river
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right

steep sequoia
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Open that in browser and see in bigger fonts.

wind river
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yeah i got u

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OH

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since theres k+1 terms

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the 1s add up to k+1?

steep sequoia
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No.

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You are trying to create ways to get 1. 😐

wind river
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lol i thought i had something there

steep sequoia
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Properly look at the expression and see if you manipulate it somehow.

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Maybe factor something out.

wind river
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do i have to use the IH again?

steep sequoia
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Remember - First k is S! for [k] so you can ignore that.

steep sequoia
soft zealotBOT
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Enemagneto

wind river
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uhhh

steep sequoia
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Ah. Fixed finally.

steep sequoia
wind river
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hm

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can i say

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that

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everything after the inital 1/k+1

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simplifies to k+1?

steep sequoia
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How are you saying that?

wind river
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by the IH

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or rather sorry

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nvm

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we were trying to get to that

steep sequoia
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Do thus.

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Which factor do you see in all the terms inside the parentheses?

wind river
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k+1

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oh k?

steep sequoia
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Not k+1. All the terms are in denominator.

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How are you getting k+1 ?

steep sequoia
wind river
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no

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uhhhh

steep sequoia
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It's just not k+1.

wind river
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is it 1?

steep sequoia
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EVERYTHING IS IN DENOMINATOR.

wind river
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hmm

steep sequoia
wind river
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never

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sorry factors

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in the denominator?

steep sequoia
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Come on. (1/(k+1)) is the factor.

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not k+1.

wind river
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right mb

steep sequoia
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Take that as factor from the parentheses.

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What do you get inside the parentheses?

wind river
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1/k+1([1] + [1/1 + 1/2 + ...] + [1/2 + 1/3 + ....] + .... + [1/1x2x3x4xk])

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ohh

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the

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parantheses

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simplifies now

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to k

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by IH

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and (1/k+1)*k

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or wait

wind river
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to k+1

steep sequoia
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Yes

wind river
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since its 1/k+1 ( 1 + k)

steep sequoia
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So that becomes 1.

wind river
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which is now 1

steep sequoia
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Overall k + 1

wind river
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yeah

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ok i just gotta write this out in latex now

wind river
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sorry for being slow lmao

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.close

final saddleBOT
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fringe holly
#

Use continuity to evaluate the limit.
lim
𝜃→3𝜋⁄2
sin(tan(cos(𝜃)

fringe holly
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How do I got about solving this

tired walrus
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$\lim_{\theta \to 3\pi/2} \sin(\tan(\cos(\theta)))$

soft zealotBOT
tired walrus
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this?

fringe holly
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yes

tired walrus
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well, sin, cos and tan are continuous functions (except tan at odd multiples of pi/2...)

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do you know what continuity means for limits

fringe holly
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that it will go to -infinity or positive infinite

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like you can draw the graph without lifting your pencil

tired walrus
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not quite the answer i was looking for...

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continuity means that $\lim_{x \to c} f(x) = f(c)$

soft zealotBOT
tired walrus
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meaning you can just plug shit in

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mostly

fringe holly
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so the limit of that function wouldn't be continuous because of tan and the 3 is making it an odd number

final saddleBOT
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@fringe holly Has your question been resolved?

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near sedge
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This is a lagrange function, but how he goes from this to this:

near sedge
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I didnt get that lambda_t+1

final saddleBOT
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@near sedge Has your question been resolved?

final saddleBOT
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@near sedge Has your question been resolved?

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sonic thistle
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Can I just put these all under one sqrt?

final saddleBOT
brave cloak
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No

sonic thistle
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Sqrt of -x^2 +x +28

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So how do you add them together?

brave cloak
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I don't think you can add them you just leave them like that

sonic thistle
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Ohhh

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But you can add them under certain conditions right? If they have the same something?

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Sorry I am trying to remember stuff from 9 months ago

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Oh its when its multiplied

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They can all go under

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Sorry thank you!

brave cloak
brave cloak
sonic thistle
#

.close

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sullen warren
#

Ok this is more just making sure I did the diagram right than anything at the moment
So the question is
Draw a Venn-style diagram, which displays the relation aRb , for a∈A and b∈B, where R maps each digit to the vowel(s) which occurs in the name of the digit.

B = five vowels of the English alphabet```
Are the sets respectively. This is what I have right now for my diagram. 
          A                    B          
 ----------------------------------------
|        0= E,O         |          A = a   |
|        1= E,O         |          E = e    |
|        2= O            |          I = i       |
|        3= E             |         O = o     |
|        4= O,U        |         U = u     |
|        5= E,I           |                       |
|        6= I              |                       |
|        7= E             |                       |
|        8= E,I           |                       |
|        9= E,I           |                       |
|                             |                       |
 -----------------------------------------
sullen warren
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I just want to make sure that I did the diagram properly is all really, idk if this is the right place for this or not

final saddleBOT
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@sullen warren Has your question been resolved?

sullen warren
#

No

final saddleBOT
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soft jewel
final saddleBOT
soft jewel
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is this wrong j cuz i forgot m

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should it have been m * this

final saddleBOT
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@soft jewel Has your question been resolved?

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gilded apex
#

rearange to H

final saddleBOT
steady olive
#

I’m not sure how to do this do I do it by integration of parts and how do I start

gilded apex
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rearange to H

final saddleBOT
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@gilded apex Has your question been resolved?

gilded apex
#

help pls 🙂

final saddleBOT
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@gilded apex Has your question been resolved?

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lusty charm
#

how come 6 is not a correct answer

final saddleBOT
tired walrus
#

is 36i+2j parallel to 36i-2j?

lusty charm
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i dont rlly understand how a vector component works.

i thought the coeffficient of i is like the slope and coefficient of j is like the y-intercept?

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pulsar surge
#

Hey guys. I need to help to control if my answer is correct

pulsar surge
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(picture of my calculation, it's a little a messy but hope someone can help me)

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I got 19

glad glacier
#

correct

pulsar surge
#

Thanks😊

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obtuse pulsar
#

i need help

final saddleBOT
obtuse pulsar
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.close

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grave hinge
#

Can anyone confirm this is correct (turning velocity time graph to acceleration time graph) got a test with this question in 10 mins 😭

fossil geyser
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Yeah for a sketch without a scale that seems fine

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Acc is positive when vel is increasing, etc

grave hinge
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Is the part where I made the acceleration higher then normal also good?

fossil geyser
#

Yeah the slope of the velocity seems higher there so that checks out

grave hinge
#

Alr thx

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slender tide
#

I'm needing helpi with this exercise. I will be translating since it is in portuguese:

"If cotgx + tgx = 8, when 0 < x < π/2, so which is the value of: (sinx + cosx)² "

slender tide
#

I did an exercise similar to that one some time ago by equaling the denominators, so that's what I tried here:

cosx/ sinx + sinx/ cosx = 8 (now multiplying cosx/sinx by cosx and sinx/cosx by sinx)

cosx² + sinx² / sinx . cosx = 8

1 / sinx . cosx = 8

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have i done anything wrong until this point?

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and if i'm right, how can I continue this?

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the template says that the answer is 5/4 but I don't know how to get to that number

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@unkempt moon

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Sorry, wrong ping

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<@&286206848099549185>

final saddleBOT
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@slender tide Has your question been resolved?

slender tide
#

<@&286206848099549185>

final saddleBOT
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upper sigil
#

im second guessing myself

final saddleBOT
upper sigil
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but

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i would just plug in 28 and solve

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right

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or would i do the irc at 28? or does it literally just want

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at 28

fierce mesa
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i would say m(v)=28

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and go from there yes

upper sigil
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yeah so plug in 28 for v

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right

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or are you saying solve for v

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thats the same thing isnt it

fierce mesa
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given 28 is the height needed to throw, m=28 in this case as opposed to v=28, as v represents the velocity instead of height

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so m(v), as a function of v, will be substituted to be 28, following which you will solve for v

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as stated: 'find the ideal velocity of Romeo's throw'

upper sigil
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ah

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that makes sense

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because its max height as a functuion of velocity

fierce mesa
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yeps

upper sigil
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if it said what is the max height if romeo throws the flowers at 28 feet per second or something

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then id plug in

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got it

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.close

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supple copper
#

Yes

final saddleBOT
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tranquil pine
final saddleBOT
tranquil pine
#

Need help to prove Q2c wih strong induction

final saddleBOT
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obtuse pagoda
final saddleBOT
obtuse pagoda
#

Can someone explain the highlighted part

#

Don't know what I'm doing wrong

final saddleBOT
#

@obtuse pagoda Has your question been resolved?

obtuse pagoda
#

<@&286206848099549185>

barren galleon
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atomic spindle
final saddleBOT
atomic spindle
#

the dum program is so specific

#

idk which step it wants

novel rover
#

It wants which piecewise function to execute

#

As x approaches 0 from the left which equation do you use?

#

You put it in the space

atomic spindle
#

^-

atomic spindle
novel rover
#

Oh it's the derivative mb, just put the derivative in the space

atomic spindle
#

like ik the derivative equation

#

does it want me to substitute in

vital crag
atomic spindle
#

f'(x) = lim h->0 [f(x+h) - f(x)]/h

vital crag
#

yea apply that to both functions in f(x)

atomic spindle
#

so just substitute

atomic spindle
#

so idk

vital crag
#

you're supposed to find f'(x)

#

and input that to the box

#

not limit definitions

atomic spindle
#

um

#

well f'(x) = lim h->0 [(4(x+h)-6(x+h)^2)-(4x-6x^2)]/h

#

im not sure what im supposed to do w that

vital crag
#

find the limit!

#

also, that's only for x < 0. you'll need to find f'(x) for x>=0

atomic spindle
#

4-12x

#

i believe

vital crag
#

this means x < 0

#

so you differentiate this piece of the function

atomic spindle
#

it doesn't like that either

vital crag
#

what did you input

#

screenshot it

atomic spindle
#

._.

vital crag
atomic spindle
#

f'(x) = lim h->0 [(4(0+x)-6(0+x)^2)-(4(0)-6(0)^2)]/x

#

(4x-6x^2)/x

#

4-6x

#

oh that was it

#

ok i got it thx

#

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vocal atlas
#

guys

final saddleBOT
vocal atlas
#

mistake ?

#

they didnt put -

severe canyon
#

They used the minus on the exponent to swap numerator and the denominator

#

(they did what is usually called reciprocal of a fraction)

vocal atlas
#

fr

severe canyon
#

$${\left(\frac{a}{b}\right)}^{-1} = \frac{b}{a}$$

soft zealotBOT
#

Alberto Z.

vocal atlas
#

ye like

#

oh shit

#

oh shit

#

sometimes my brain malfunction

#

like im slow rn

#

and i lose 33% of skill

#

and therefore i didnt catch this

#

make it 500x and i lose all skill gg

#

🇮🇱 Israeli military wins and dominates whole world gg

#

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jolly vector
final saddleBOT
jolly vector
#

what does this mean

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hushed musk
#

Help I get how 16 comes from 2 but how do i know how many places to move the decimal.

winter sleet
#

represent as a fraction

hushed musk
#

Omg tysm 😭

#

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haughty grove
#

can someone help me wotht he following calculation! 2+2=?

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shell plover
#

so i got the points (0,3) and (3,0) but idk where that what seems to be (-1.5, 0) comes from on the left

shell plover
#

ping if you know it

brave cloak
shell plover
brave cloak
#

if the function is given let f(x)=0 and solve for x

shell plover
#

wdym f(x) isnt = to 0 here

brave cloak
#

(-1.5,0) means that f(x)=0 at x=1.5 so if you can't tell what the value of x is from the graph or the graph is not give use the function

shell plover
#

im sorry i really dont get it so my thing is if f(x) = 0 and f(x) = 2x +3 then 0 = 2x + 3 then x = 3/2

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#

@shell plover Has your question been resolved?

shell plover
#

how is that related

vital crag
#

also that doesn't equal 9

#

2 (3/2) = 3

#

3 + 3 = ?

#

use a calculator to verify

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warm ether
#

When you used the product rule you forgot the ln on the sin

royal gust
#

Don't forget to chain-rule the ln(sin

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#

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woven girder
#

Given: limit as h approaches 0 of [4(h-2)^2+8(h-2)]/h

woven girder
#

I have identified that this is the h-gap method of dinging the derivative. I need to find f(x) and what is the value of x in question.

#

I am unsure of what to do.

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#

@woven girder Has your question been resolved?

woven girder
#

@vast sonnet

#

<@&286206848099549185>

woven girder
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woven girder
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vagrant wraith
#

i was wondering whether to solve lim sin x/x=1 as x approaches 0, we could use small angle approximation on sin x?

vagrant wraith
#

but a friend told me this is circular since small angle approximation is defined using lim sin/x as x approaches 0

#

is this right?

tired walrus
#

yeah it is circular

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regal sail
#

что такое отношение чисел?

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open shore
#

how do you solve $4x^3-10x^2-1=0$

final saddleBOT
hazy sequoia
open shore
#

oh oops one

soft zealotBOT
#

annyeong

hazy sequoia
#

no way of factoring it that I can see

open shore
#

the answer is a very long decimal

hazy sequoia
#

Does the question ask you to solve it a certain way?

#

Maybe with a graphing calculator?

rich tide
#

wait I have seen this polynomial

open shore
#

nope

#

im guessing you can use a normal calculator but not sure how

desert mantle
#

there is the cubic formula. it's painful to use but it does work

open shore
#

hmm

desert mantle
#

can you give us a picture of the problem statement

rich tide
#

Okay the roots are highly irrational. You need to use cubic formula

hazy sequoia
#

It seems likely that they mean for you to solve it with a graphing calculator, but who knows

open shore
#

ok thanks at least i know that im not stupid

#

.close

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dim laurel
#

Something that’s always confused me is how can you multiply a function without x

dim laurel
#

For example

#

If f: x → y then f = f(x)/x which is not true but yet fx ≠ f(x) so then how is fg possible

#

g isn’t defined because in this case g can be anything

#

I am confused on this notation and what it means

jade laurel
#

f = f(x)/x?

dim laurel
#

right which isn’t true

jade laurel
#

yes

#

what are u doing

dim laurel
#

so then what do they mean when they write a homomorphism like f * g

jade laurel
#

i mean

dim laurel
#

Is it just a shorter version of the same thing

jade laurel
#

f * g

#

f: x-> y

dim laurel
#

f(x) * g = f * g?

jade laurel
#

g: z -> y

#

ur writing composition right

#

or

dim laurel
#

I guess what I’m trying to ask here is what’s the origin of f(x) and how does it differ from f cause you also have cases like ℤ[x]

jade laurel
#

what do you mean differ?

#

how are u defining f?

#

like as the function right?

dim laurel
#

Defined as a homomorphism that maps x to y

jade laurel
#

then fg means the compsition

dim laurel
#

Could you elaborate I’m unfamiliar with that term

jade laurel
#

if u have two maps

#

f: x->y

#

g: y->z

dim laurel
#

Ohhh

jade laurel
#

their composition g \circ f

dim laurel
#

Would it be then fg: x -> z?

jade laurel
#

gf

#

but change the domains and yeah

#

basicly

dim laurel
#

But I thought fg starts with x

#

fg would be z -> x then?

#

.close

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wispy plank
#

how do i calculate percent equations (G:350,00€ %: 5) we gotta find out what W is

tired walrus
#

i don't think anybody knows what the letters G and W stand for.

#

can you show the original problem?

#

even if it is not in english.

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sonic crescent
#

Whats the domain and range of this?

The domain would be Z -> Z right

severe canyon
#

The domain is a set, it can't be "Z -> Z"

#

Anyway, the domain is Z, and the range is also Z

sonic crescent
#

ohh ok, so what does Z -> Z really mean?

severe canyon
sonic crescent
#

ohh

severe canyon
#

The arrow stands for "from Z to Z"

sonic crescent
#

so R -> Z would mean the function takes in a real number and only spits out an integer?

severe canyon
#

Yep

sonic crescent
#

thank you!

severe canyon
#

You're welcome 😊

sonic crescent
#

.close

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slender ridge
final saddleBOT
slender ridge
#

im confused on how im supposed to write the formula

languid yoke
#

basically you're just solving for the shaded area in terms of theta

#

you would do that by doing
[area of triangle] - [area of sector]

slender ridge
languid yoke
#

you just write an expression in terms of theta

#

do you get what that means

slender ridge
#

would it be this?

#

@languid yoke

languid yoke
#

yes!

#

except you can use r=10 for the pi*r^2

#

but yeah that's basically the idea just make sure to simplify

slender ridge
#

bruh

#

did I do smth wrong

#

this is the answer apparently

#

idk how

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zenith quarry
#

Why is it 1/3 as the constant that spills out and not 1/9?

charred chasm
#

what's u here?

zenith quarry
#

okay i just thought about that- i guess u=1/3 x

charred chasm
#

that's right

zenith quarry
#

but then where does the 9 constant term come from?

charred chasm
#

that was the original problem, no?

#

or are you asking where it went?

zenith quarry
#

where it went sorry

#

like if i distribute the 3 it looks like it doesn't work

charred chasm
#

ah, then try factoring out 9 from the denominator

#

start with 1/(x^2 +9)

#

factor out 9 from the denominator

zenith quarry
#

i feel like i get 1/9 * 1/(x^2/9 + 1)

charred chasm
#

great

#

now do u -sub

manic herald
charred chasm
#

with u = x/3

zenith quarry
#

oooooooooooooooooooooh okay okay

charred chasm
#

does that make sense now?

zenith quarry
#

thank u sm!!! yes yes

charred chasm
#

cool

#

gl

zenith quarry
#

i am so . rusty with my calc 2 crying

#

its ok ill get there 🙏

#

.close

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chrome zinc
#

how does someone solve the a/b part i don't even know what a binary operation is

winter sleet
#

takes two inputs

chrome zinc
#

i can use any number on this right?

#

as long as it's not 0?

warm ether
#

any 2 rational numbers that are non-zero

winter sleet
#

Q - rational

chrome zinc
#

so do i something else after i give a number to the entire equation?

#

do i solve it or i just leave it like that?

warm ether
#

what you have showed is a definition, theres no working to be done from what youve shown

chrome zinc
#

oh wait so i just replace it and that's it??

warm ether
#

wdym replace it

chrome zinc
#

ill just give a number and thats it

warm ether
#

what are you using this definition for

chrome zinc
#

nothing

#

that's the entire thing

warm ether
#

or are you trying to prove it maps back to the rationals

chrome zinc
#

there's nothing else attached to the original question despite being homework

#

u just have to define it and that's it

#

oh when i meant nothing it's homework

#

alright i think i got it thanks mate

#

.close

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faint wing
#

I need help with this: A parallelogram has a height of 3 ft and a base of 8 ft. Find the area of each shape that composes the parallelogram. What is the total area of thes special quadrilateral?
8 ft x 3 ft x 3 ft x 4.25 ft.

faint wing
#

<@&286206848099549185>

mental roost
#

!15m

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#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

winter sleet
#

stop opening new channels and spamming helpers

mental roost
faint wing
#

i need help but noone coming

rancid idol
#

!patience

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Please wait patiently, and do not interrupt other channels with your question. Helpers in this server are volunteers, and the server cannot guarantee that someone will be able to help you. By being impatient or begging, you will only turn potential helpers away.

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faint wing
#

ok imma wait

#

if i dont get help in 10 mins imma be mad

#

A parallelogram has a height of 3 ft and a base of 8 ft. Find the area of each shape that composes the parallelogram. What is the total area of thes special quadrilateral?
8 ft x 3 ft x 3 ft x 4.25 ft.

mental roost
#

remember that people help here, they dont work here

unique eagle
#

Lol, none of us are getting paid to help, you can get mad all you want

faint wing
#

ik im just saying

mental roost
#

kindness often leads to quicker help

winter sleet
#

better draw a diagram in the mean time

faint wing
#

????

iron mist
#

You don’t even have a diagram 💀

faint wing
#

i do

grim badger
# faint wing i do

In the meantime, please make sure your channel contains the original question, clearly describes what you have already tried, and states exactly what you are having trouble with. This increases your chances of getting a good response.

iron mist
#

Can’t help here when we have no idea what the figure looks like

faint wing
#

i alr had it written 10 mins ago 💀

#

imma show it

#

gimme a sec

#

here.

#

.close

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ornate harness
#

how would i solve this

final saddleBOT
ornate harness
#

initial velocity = 0 m/s

#

t isnt given

#

acceleration is what i would have to solve for right?

#

oh wait

#

i solve

#

nvm i got it chat

#

if i set final velocity to 18

#

initial to 0

#

it will give me the acceleration

#

which i can use to figure out the final velocity for the last car as it passes the railway worker

#

chat is this right?

vestal frigate
#

Yeah you want to find its acceleration and then figure out how fast it would be going 180+75 meters from t=0

ornate harness
#

cuz the dude is 180m away

#

so i can set displacement to 180+75

#

solve for vf

final saddleBOT
#

@ornate harness Has your question been resolved?

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lusty charm
#

can someone explain where the vector projection formula comes from? like for this example, why square the bottom and multiply by v?

rancid idol
#

it can be restated as v hat

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v hat is v / |v|

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v hat being the unit vector in the direction of v

winged python
#

Oh, I'm learning about this stuff rn, here's a page from my online textbook that might help

lusty charm
#

that makes so much sense

lusty charm
#

i'll save this

winged python
#

I can dm you the full chapter's link too (it's free + online) if you're interested

lusty charm
#

yooo that's great

winged python
#

You can find explanations for other calc III stuff there, like cross product and etc.

lusty charm
#

please do

#

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tacit knot
#

How do I know which to subtract by without seeing the graph

tacit knot
#

Or do I have to visualize it every time..

warm ether
#

i mean, its probably the most efficient way to go about it, if you do them the wrong way round youll get negative area for said integral so just change the sign

winged python
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nimble quartz
#

I have a really annoying thing to prove

final saddleBOT
nimble quartz
#

0 and 1 are in a set

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and for any two elements in the set, their average is also in it so it is inductive

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i need to prove if 1/6 is in the set

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<@&286206848099549185>

vital crag
#

Can you prove that any numbers of the form 2^(-n) are in the set?

#

n>=1

nimble quartz
#

I think so yeah

vital crag
#

Hmm nevermind I'm not sure if that's useful

nimble quartz
#

I’m not sure about how to structure the proof too

#

i think it’s supposed to be structural induction

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@nimble quartz Has your question been resolved?

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slender ridge
final saddleBOT
slender ridge
#

how do I make the bottom not x so it not undefined

strange shore
#

you cant

slender ridge
#

bruh

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slender ridge
#

what do I do?

#

do I multiply by the congrugate

obtuse heath
#

You should first type .reopen so the channel doesn't become available

slender ridge
#

oh

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.reopen

final saddleBOT
#

slender ridge
#

thx

obtuse heath
#

Always do it when you can

slender ridge
#

how do I do that

#

like how do I go about that

obtuse heath
#

First subtract the fractions on the numerator

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Then use (a/b)/c=a/(bc)

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@slender ridge Has your question been resolved?

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kindred timber
#

how is this wrong

final saddleBOT
kindred timber
#

i ran out of submissions

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but i cant see how this is wrong

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dont you just integrate by component?

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or did i miss something

robust mulch
#

Do they want exact answers?

kindred timber
#

no but they never don't accept it

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wdym

robust mulch
#

Ok lemme check you number rq

kindred timber
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go for it

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i made sure to check it too

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just in case

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but these are the numbers I get

robust mulch
#

Hmm

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Perhaps they wanted you to use i j and k

kindred timber
#

made it wants it in not component form

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but its never marked me wrong for that before

#

its always been interchangeable

robust mulch
#

Is this cengage?

kindred timber
#

yes

robust mulch
#

I dont think they like <>

kindred timber
robust mulch
#

Oh

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Nvm then

kindred timber
#

ok i mean as long as I did it right its fine ig

runic oyster
#

Cengage doesn't like decimal answers sometimes

kindred timber
#

i see

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weird

robust mulch
#

Yeah ypu probably want to use fractions next time

#

I cant see what else would have been wrong

kindred timber
#

ok damn

#

thanks

#

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tranquil pine
#

<@&286206848099549185>

final saddleBOT
magic sparrow
#

!15mins

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#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

tranquil pine
#

he4lopp

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hello

magic sparrow
tranquil pine
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oh sorry

#

can u help me get ready for a retake test i will send pics

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are u there

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civic ether
#

@summer snow for the same question i posted prior

civic ether
#

now that i think about it

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can i never consider fractional powers of x?

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x = 2^(2.5) * 3^(1.5)

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in that case when squared it'll always have a 2^5 and 3^3 guanteed right

summer snow
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That would be true, yeah

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It shouldn't change our answer in this case however

civic ether
# summer snow It shouldn't change our answer in this case however

makes sense, but which is the actual right way to express your answer?

Would it be more valid for x = 2^(2.5) * 3^(1.5) or x = 2^3 3^2

in the first case, you'd have x^2 = 2^5 * 3^3 * k

in the second case, you'd have x^2 = 2^6 * 3^4 * k where the k could absorb the extras and also get to x^2 = 2^5 * 3^3 * k

#

they both yield correct answers then ig, but if i was teaching someone then which way would i imply

summer snow
#

If I were to describe all possible values of x, I might say:

$x$ equals $2^\frac{5+x}{2}\cdot 3^\frac{3+y}{2} \cdot \sqrt{k}$ for nonnegative integers $x$, $y$, and $k$.

soft zealotBOT
#

@summer snow

civic ether
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hmm okay

#

i think i kind of figured

summer snow
#

Or I suppose that could be simplified to just
[ x = 2^\frac{5}{2} \cdot 3^\frac{3}{2} \cdot \sqrt{k} ]
For some nonnegative integer $k$

soft zealotBOT
#

@summer snow

civic ether
#

u can't have fractional exponents as multiples because that would imply non integral multiplies and that usually isn't a thing unless you're working with ring theory and the like

summer snow
#

Yeah, exactly

civic ether
#

yeah so ig that should be it

civic ether
#

k is scaled

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u wouldn't sqrt(k) in anticipation that it'll be k after squaring imo

summer snow
#

If you wanted to include it as part of the definition of $x$, you would have to take the square root, otherwise $x^2 = 864 \times 2$ (a possibile multiple of 864) wouldn't have a corresponding valid $x$ value

soft zealotBOT
#

@summer snow

summer snow
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since no integer satisfies $n^2 = 2$

soft zealotBOT
#

@summer snow

summer snow
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Ah, though I suppose that messes with the ability for x to be negative and still satisfy the equation

#

A better definition would then be $x = \pm 2^\frac{5}{2} \cdot 3^\frac{3}{2} \cdot k^\frac{1}{2}$

soft zealotBOT
#

@summer snow

civic ether
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hmm okay fair enough

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thanks

#

one more question

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obviously i can just use the formula

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but how about if i don't want to use the formula

summer snow
#

I think we can intuit without the formula that B should be larger, since set A and set B both have equally evenly spaced elements, and set B has a larger range

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i.e., the regularity means that the larger range causes it to by definition deviate further from the mean

civic ether
#

ofc with the given fact that the spacing is consistent

summer snow
#

It's not necessarily that it increases with population size

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,w standard deviation {1, 2, 3, 4, 5, 6, 7}

summer snow
#

,w standard deviation {1, 3, 5, 7}

summer snow
#

It seems that standard deviation generally will increase as the distance from the maximum and minimum elements increases, and as the distance between each element increases

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So going from 1...7 to 1...8, our range increased, so std dev should increase

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from 1...7 to 1,3,...,7, our range stayed the same, but the space between elements increased, so our std dev increased, even though we had fewer elements

#

A proof as to why this might be a general trend would be interesting but is outside the scope of what I'm available to do right now

civic ether
#

.close

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broken fox
#

i don’t know what i did wrong here. it seems rigjt to me

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@broken fox Has your question been resolved?

inland ice
# broken fox i don’t know what i did wrong here. it seems rigjt to me

Hi there!

Statement 4 is incorrect because something like statement one where you have m <CBE = m<1 + m<3 (For this you're saying both those angles equal up to that entire angle labeled by the letters C B and E) is not the same as saying m<1 + m<2 = m<3 + m<4 (These angles added together separately make the same angles but they do not conclusively make the exact same bigger angle like statement 1.)

Statement 5 is wrong because if you look back at the problem you can see that your statement: m<2 = m<4 was given hence was reflexive property would be incorrect

Statement 7 is wrong because m<1 and m<3 do not have an adjacent line between them that make them the same, well symmetry wise

Hope that helps and makes sense!

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timber onyx
final saddleBOT
timber onyx
#

I’m confused on how to do this

final saddleBOT
#

@timber onyx Has your question been resolved?

timber onyx
#

<@&286206848099549185>

timber onyx
#

<@&286206848099549185> hello?

frank swan
timber onyx
#

the answer has it as y= 4x + 28

frank swan
#

Huh...?

timber onyx
#

Yeah

#

I’m just gonna ask my teacher

frank swan
#

K

timber onyx
#

Thanks though

frank swan
#

Welcome

timber onyx
#

.close

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grim hinge
#

Stuck on this question

final saddleBOT
grim hinge
#

Hello, not quite sure what to do

warm ether
#

what is marginal functions worksheet 9

grim hinge
#

its the worksheet the question is pulled from

warm ether
#

is this everything you have?

grim hinge
#

I have that too

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#

@grim hinge Has your question been resolved?

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#

@grim hinge Has your question been resolved?

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glad basalt
final saddleBOT
glad basalt
#

this is the original expression

#

Why is y-int 5, 0 not plotted in the graph?

final tangle
#

wdym

#

what's 5, 0 supposed to mean

glad basalt
#

y int?

final tangle
#

y int is plotted here, its -3/2

glad basalt
#

how come its not 5, 0?

final tangle
#

wdym by 5,0

glad basalt
#

I think its 5, 0

#

?

final tangle
#

did you mean (5,0)?

glad basalt
#

come on

final tangle
#

no

#

i did not

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-3/2 is -3/2

glad basalt
#

so

#

that means

final tangle
#

its fine to represent intercepts with a single numerical value

glad basalt
#

(-3/2, 0)

#

anyways

final tangle
#

you however are either listing two values

glad basalt
#

y int means y is 0

final tangle
#

or giving something implying you meant (5,0) which isn't a y-intercept at all

#

no

glad basalt
#

hm

#

fdsaaaaaaaaaaaaaaa

#

I guess I mean x intercept

final tangle
#

y-intercept as the name suggests is where the y-axis is intercepted

glad basalt
#

do they not plot the x intercept

final tangle
#

did you try evaluating this function at x=5?

glad basalt
final tangle
#

() are NOT optional when writing a point

glad basalt
#

lol

final tangle
#

anyway you have your answer

glad basalt
#

thats the x int

final tangle
#

no?

glad basalt
final tangle
#

your work indicates that you have a hole at (5,1)

#

supposedly you also reached that the function is undefined at x=5
and/or that f(x) isn't 0 when x=5

glad basalt
#

what does that tell us?

final tangle
#

yes thats a hole (5, 1)

glad basalt
#

why can't there be a hole there

#

and also be a x int

final tangle
#

technically you could

#

IF the function is 0 when x=5,

#

but f(5) isn't 0

#

its undefined

glad basalt
#

why do we only care about x = 5

#

and that being a hole

final tangle
#

because that's what you're asking about

#

specifically

glad basalt
#

OHHHHHHH

#

ok

#

so if there were not a hole at x = 5

final tangle
#

(5,0) isn't an x-interecept becaue
f(5) isn't 0

glad basalt
#

that'd be an x intercept

final tangle
#

no

glad basalt
#

why not I set the whole function to = 0

#

and got (5, 0)

final tangle
#

you can try

#

but you'd did some invalid stuff along the way to get that