help-36

[past bluff]

The b part specifically

For a I got 0.6m/a and 0.9J

[final saddle]

@past bluff Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac stratus]

Just want to confirm the answer.
Quest: No. Of all possible matrices of order 3x3 with each entry 0 or 1 is?
My ans: 2^9

[tranquil pine]

yes.

[lilac stratus]

Ok tysm

[faint locust]

This has been asked on Math StackExchange before:
https://math.stackexchange.com/questions/941135/number-of-possible-3x3-matrices-with-0-1-entries

[lilac stratus]

Oh

[ocean lintel]

It's in bijection to {0,1}^9

[lilac stratus]

What does that mean?

[ocean lintel]

Two sets A and B are said to be in bijection iff there is a function phi such that phi is injective and surjective (i.e. bijective) such that phi(A)=B

[lilac stratus]

Oh

[lilac stratus]

Okay, what does {0,1}^9 mean though?

You raised a power to the set of 2 elements

[ocean lintel]

see cartesian product

[lilac stratus]

Oh

Which is all possible pairs of 9 elements from set {0,1}

And no of those 9's pair is 2^9

[lilac stratus]

You said it's in bijection to {0,1}^9. Can you say what is set A, set B and phi here? I can understand B is {0,1}^9 but what is A and phi?

[ocean lintel]

A = your matrices
B = {0,1}^9
phi = map the matrix to the list of its coefficients (I won't write that in math language on my phone)

[lilac stratus]

Alright thank you

.close

[final saddle]

Channel closed

Closed by @lilac stratus

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant gull]

How would you do this <@&286206848099549185>

[final saddle]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[sleek token]

test?

[pliant gull]

?

It’s not a test

in terms of degrees or radians

It’s rtheta

This has no relevance to velocity or distance

[sleek token]

arc length for vector function?

[pliant gull]

Don’t know what you mean bro

[final saddle]

@pliant gull Has your question been resolved?

[pliant gull]

Yes

[final saddle]

Channel closed

Closed by @pliant gull

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly vale]

Don't spam your own help channel if you genuinely want help

<@&268886789983436800>

[bleak granite]

https://tenor.com/view/rip-bozo-ripus-bozus-nik0321-unlive2774-potato-chip-smoker-bozo-gif-21079712

[agile nacelle]

.close

[final saddle]

Channel closed

Closed by @agile nacelle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crisp raven]

Hi quick question, why does AX+B=A <=> X=I-A^(-1) * B

[crisp raven]

talking about matrices

[junior radish]

$$AX + B = A$$
$$AX + B - B = A - B$$
$$AX = A - B$$
$$A^{-1}AX = A^{-1}(A-B)$$
$$IX = A^{-1}A - A^{-1}B$$
$$\boxed{X = I - A^{-1}B}$$

[soft zealot]

Rub05

[crisp raven]

ah im stupid

thanks

also

(AB)^-1 = B^-1 * A^-1 right?

[junior radish]

Yes

[crisp raven]

why do they switch places

[junior radish]

$$(AB)^{-1} = (AB)^{-1}I$$
$$(AB)^{-1} = (AB)^{-1}AA^{-1}$$
$$(AB)^{-1} = (AB)^{-1}AIA^{-1}$$
$$(AB)^{-1} = (AB)^{-1}ABB^{-1}A^{-1}$$
$$(AB)^{-1} = IB^{-1}A^{-1}$$
$$\boxed{(AB)^{-1} = B^{-1}A^{-1}}$$

[soft zealot]

Rub05

[crisp raven]

wait any matrix times by identity matrix is equal to the matrix right? A * I = A?

[junior radish]

Yes

Is the same as, in normal numbers, multiplying by 1

[crisp raven]

why does ABB^-1 replace AI in line 4?

ah nevermind

i see

.close

[final saddle]

Channel closed

Closed by @crisp raven

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar wind]

Let B be obtained from a sequence of ero on A. Show there exists an invertible P s.t B=PA

[pulsar wind]

Can I simply just argue that the sequence of ero will have the form e_n…e_1=P, by product rule of det, det(P)=1 since each ero is invertible and has det(e_i)=1 hence P invertible.

[desert mantle]

you dont need the determinant here

also not all elementary row operations have det 1

the product of invertible matrices is again invertible

because the inverse is given by (AB)^-1 = B^-1 A^-1

show that this is indeed the inverse

[pulsar wind]

Okay, det(e_i)=1 is false but we’ve already proven eros are invertible in my course so can I not just apply det(P) and Show it’s non-zero

[desert mantle]

dont use dets when not necessary

they are a crutch here

if you only ever use dets then you wont be able to do anything when a problem actually requires something else

[pulsar wind]

I mean, I could just say the inverse of P is equal to e_1^-1…e_n^-1 which exists since all Eros are invertible

[desert mantle]

yes

see

no dets in sight

and if we look at that it really just says that to get A back from B (aka A=P-1 B) we only have to apply all the eros backwards

which is what you'd expect

[final saddle]

@pulsar wind Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure trellis]

i dont really have a starting point for this question

so far i thought maybe I could use the dot product of bd and ba

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

.close

[final saddle]

Channel closed

Closed by @azure trellis

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final saddle]

@nimble frost Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[past ibex]

I have no clue on how prove these 2

[final saddle]

@past ibex Has your question been resolved?

[final saddle]

@past ibex Has your question been resolved?

Channel closed

Closed by @past ibex

Use .reopen if this was a mistake.

[past ibex]

.reopen

[final saddle]

✅

[past ibex]

<@&286206848099549185>

[final saddle]

@past ibex Has your question been resolved?

[final saddle]

@past ibex Has your question been resolved?

[final saddle]

@past ibex Has your question been resolved?

[final saddle]

@past ibex Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glass veldt]

f(x)=−4x^2+10x−8

[glass veldt]

How many distinct real number zeros does f have?

is it zero

the value is -28

[tired walrus]

!15m

[final saddle]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[glass veldt]

mb

[tired walrus]

"value" is literally the vaguest way you could possibly describe your calculation.

you can't get any vaguer

[glass veldt]

What is the value of the discriminant of f?

is -28

[tired walrus]

okay so the discriminant is -28

yes that looks correct

yes there are no real roots then

[glass veldt]

yeah and i think the How many distinct real number zeros does f have?
is it zero

[tired walrus]

i already confirmed your answer.

[glass veldt]

so zero?

okay ty

[tired walrus]

yes! do you need me to say it 4 more times?

[glass veldt]

lmao mb

have a nice day

.close

[final saddle]

Channel closed

Closed by @glass veldt

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel saffron]

hello i need some help with hegarty matyhs

[final tangle]

did you watch that video guide provided to you

[gritty solar]

What's hegarty mayths

[zinc birch]

a website

[gritty solar]

I see

[novel saffron]

do you guys give answers

[final tangle]

no

[gritty solar]

no

[zinc birch]

we lead you to the answer

[novel saffron]

ah right okay

[zinc birch]

have you watched his video on this topic?

[novel saffron]

no

i came hear for answers

[zinc birch]

you won’t get them here

this is for ‘help’

hence the name ‘help’

would you like some help?

[novel saffron]

no thjanks

[zinc birch]

alright, so you can go ahead and close this channel

[novel saffron]

.close

[final saddle]

Channel closed

Closed by @novel saffron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal grove]

how do i solve this?

[dusty harbor]

there is nothing to solve but you can simplify

[vocal grove]

oh yeah

Thats what i mean mb

[spring haven]

make a common denominator

[vocal grove]

12

[spring haven]

so make the denominator of all fractions 12

[vocal grove]

What did I do wrong here

,rotate

[vocal grove]

anyone?

[vital crag]

why do you say it's wrong

[vocal grove]

did i do it right?

[vital crag]

yes, if you mean putting over a common denominator correctly

[vocal grove]

it should be a/3

Is this correct @vital crag

[final saddle]

@vocal grove Has your question been resolved?

[vocal grove]

.close

[final saddle]

Channel closed

Closed by @vocal grove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[craggy hedge]

say i want to sketch a graph of a function that has an interval of [-1, 4] for example, do i also want to test those points? if so, why don't they appear when i get the critical points

[vital crag]

depends on the question

show your actual problem

[final saddle]

@craggy hedge Has your question been resolved?

[craggy hedge]

determine the relative and absolute max and min for this function x^4-4x^3 on the closed interval of [-1, 4]

i dont really get what is the purpose of the interval here. is it for like, if i got a critical point of -2 i would just dismiss it?

[vital crag]

yes

[craggy hedge]

i see

thanks

.close

[final saddle]

Channel closed

Closed by @craggy hedge

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry cedar]

what did I get wrong?

[wintry cedar]

what did I do wrong*

[halcyon geode]

I think 8 and 14 are people who only have 1 pet

Cuz 8+5+14+23 =50

Which is the number of students

[wintry cedar]

right

so which one do you think is wrong?

With simple algebra I missed two

I've gone over this problem multiple times but still am unsure what I did wrong.

[halcyon geode]

First two

How many people have a cat: 8+5

[wintry cedar]

ohh

13

22 + 5 = 27

so 13 and 27?

[halcyon geode]

Yeah

[wintry cedar]

i've got another problem if you don't mind

[halcyon geode]

It’s alr

[halcyon geode]

I need someone to help me with my problem tho😂

[wintry cedar]

One is wrong for this one

[halcyon geode]

Ok

[wintry cedar]

I think it's the second one

[halcyon geode]

Wait

[wintry cedar]

I didn't know how to do it. My teacher flipped out on me when I asked for help. She said I could do it by myself but I didn't know how to start.

[spark zodiac]

i literally hate teachers like that😭

[wintry cedar]

😆

do you know how to do the problem?

[halcyon geode]

I don’t see a problem

It seems right

[wintry cedar]

this one

[halcyon geode]

Didn’t she tell you which ones are wrong?

[wintry cedar]

I'm guessing #2 is wrong

I don't know why though

[wintry cedar]

no.

it's an autograde system

I have another attempt after so I want to make sure it's right.

[halcyon geode]

God dammit idk sorry

Which grade are u!

[wintry cedar]

10th

I'm taking geometry

[celest crane]

is this a test?

[wintry cedar]

no.

[grim badger]

Wouldn't it be q4 that's wrong? Because the population is still the overall population, you just want specifically a student who's in class B and likes carrots

[wintry cedar]

in class B would be out of 24

3 people like carrots

3/24

[grim badger]

No, as I said, it's still based on the overall total

Of all the students

[wintry cedar]

that wouldn't make any sense though, Why specify the student needing to be in class B?

[celest crane]

Pay attention to the wording in the question.

[grim badger]

To shrink the sample size smaller

[wintry cedar]

ohhh

"is in class B"

[grim badger]

You're looking the probability of a certain student in class B and likes carrots

[wintry cedar]

so 3/46?

?

.close

[final saddle]

Channel closed

Closed by @wintry cedar

Use .reopen if this was a mistake.

[wintry cedar]

.reopen

[final saddle]

✅

[wintry cedar]

I'm confused on this question

and this question

I don't know which one is wrong.

[timid pawn]

.

[wintry cedar]

right

but it doesn't feel right for num.2

youba said 1+2 is wrong

cat or dog =/ cat AND dog

[timid pawn]

Oh yeah

Wait

#2 looks right

8+14

[stone plover]

1 is wrong

[wintry cedar]

yeah

[stone plover]

So is second one

[wintry cedar]

what's wrong with the second one?

[stone plover]

Total is 23 not 22

Oh wait that's the reminder nevermind

[wintry cedar]

how'd you get 23?

is it 27? @stone plover

[stone plover]

Yes was just about to say

[wintry cedar]

could you explain?

[stone plover]

There are 50 students, and 23 don't have anything

[wintry cedar]

right

[stone plover]

Means the rest has either a dog or a cat

50-23=27

[wintry cedar]

ohh alright

[timid pawn]

No cuz 5 have cat and dog

[wintry cedar]

^I was saying the same thing

[stone plover]

So what

[timid pawn]

Either or

[wintry cedar]

but he's right

[timid pawn]

You can’t have both

[stone plover]

???

Bruh

[timid pawn]

It’s bad wording

[wintry cedar]

what's wrong with this one?

[wintry cedar]

yeah ambiguous

[stone plover]

Or is quite strictly defined

[wintry cedar]

I think #2 is wrong but i'm not sure

[stone plover]

That's exclusive or (xor) btw

[wintry cedar]

xor?

[wintry cedar]

what's wrong with this one?

[grim badger]

Same logic with q3 that you mistaked with on q4

"in class A"

[wintry cedar]

so #3 is wrong?

[grim badger]

Yes

[wintry cedar]

in this question only one is wrong

I was originally told #4 was wrong

so I changed it

from 3/24 -> 3/46

so #3 would be 4/46?

[grim badger]

Wait

Never mind, 3 is fine

[wintry cedar]

so is everything good?

my original answer

what I changed it to:

@grim badger good?

[grim badger]

Submit it and see

[wintry cedar]

I only have one more attempt left dl

why do you do this to me 😦

@grim badger it's right 👍

thanks

.close

[final saddle]

Channel closed

Closed by @wintry cedar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raw sundial]

Is this correct yes is if it is possible to solve using law of cosines and no is if it is not

[tranquil pine]

windows + shift + s or PrtSc for screen shot

[raw sundial]

Give me a second

@tranquil pine

[strong egret]

Hey what's up

I can explain some things if ya want

[raw sundial]

could you tell me if I am right

[strong egret]

Ye u r

[raw sundial]

ok thanks

can you help me with more

[strong egret]

But don't tell me u used law of cosines there

[raw sundial]

I did

[strong egret]

I'll give it a try I guess I don't know math well though

[raw sundial]

how do you know its correct then

[strong egret]

If ya just doing homework and don't care let's go on or I can explain the other way

[strong egret]

U know 3 rules that say when triangles are equal ye?

[raw sundial]

uh

I think

[strong egret]

1. When one angle and 2 sides (of that angle) are equal to another triangles one angle and 2 sides ( of that angle)

2. When all the sides are equal

[raw sundial]

ok

[strong egret]

3. When one side and angles that are touching the side are equal to the other triangles one side and 2 angles that are touching that aide

Side*

Y'know what I'm talking about?

[raw sundial]

yea

[strong egret]

So these are the cases

When you know some things and you can BUILD the triangle

am I right?

[raw sundial]

yea

[strong egret]

that's why it can be equal to the other triangle

So in first case u had it was first rule ye?

[raw sundial]

yea

[strong egret]

So u could build the triangle that means u can answer anything about it

so answer is yes

[raw sundial]

yea

[strong egret]

In second case it was 2nd rule

build the triangle, know everything, and answer anything ya?

[raw sundial]

yea

[strong egret]

But In third case ya can't build triangle like that

So it's no

[raw sundial]

ok

can we do another one

[strong egret]

I'll try

[raw sundial]

is this correct

[strong egret]

ohh wait my battery dead almost I'll be back

[raw sundial]

ok

[strong egret]

Back

[raw sundial]

k

[strong egret]

I think it's same thing here

Yeah?

[raw sundial]

yea

kinda its asking what we need to find the area

[strong egret]

First 3 are correct for sure

[raw sundial]

how about last one

leaving it blank means neither

[strong egret]

And on 4th it's b

[raw sundial]

how come

[strong egret]

because you can't build triangle with A C a

so u can't find it's area if you can't build a triangle itself

[raw sundial]

you can build it with A C b?

[strong egret]

Yeah

It's one of the rules wait I'll show ya

[strong egret]

This

Third rule

[raw sundial]

oh ok

[strong egret]

2 angles 1 side

So has to be that

[raw sundial]

so this is good

[strong egret]

Probably

[raw sundial]

bruh wdym proably

[strong egret]

Idk I'm here with ya

Ya suspect anything wrong?

[raw sundial]

not rlly

[strong egret]

Same

So we're correct probably

PROBABLY

[raw sundial]

ok

can we do another

[strong egret]

Was it right

did ya check it somehow like quiz or something

[raw sundial]

im not sure

[strong egret]

Okk lets do another

[raw sundial]

it gives me the correct answers after I finish all of em

[strong egret]

how many left

[raw sundial]

11 😢

[strong egret]

DANG

Ok let's do 1 more

[raw sundial]

ok

let me try it

[strong egret]

Send me too I gotta think aswell

[raw sundial]

ok

[strong egret]

I don't have paper rn but we need angle between the sides ye?

[raw sundial]

yea

so B

right

[strong egret]

In ABC yeah

[raw sundial]

I got 161 for area

[strong egret]

I don't have a pen sadly 😦

How did ya calculate it can u show me

I'll check it rq so we're not wrong

If u on PC that's alr

[raw sundial]

with law of cosines formula

[strong egret]

Yeah that it cool

[raw sundial]

I just plugged in to this

[strong egret]

Ok ok

Nice than

Make sure calculation not wrong

[raw sundial]

ok

im trying to figure out last one

[strong egret]

You can find h i guess?

And probably find e with h

[raw sundial]

what

[strong egret]

what I'm saying is ah/2=area so ah=300 and h(on d side)=300/17

h is perpendicular

[raw sundial]

ok

[strong egret]

Do we get something with it tho?

Orrr wait

it will be better if we get h that's on f side

because h on f side will always be in the triangle

Because f side isn't smallest side

and it will probably be shorter way

on d side perpendicular might go out the triangle

[raw sundial]

so what would it be

@strong egret ?

[strong egret]

no jdea

Idea

[final saddle]

@raw sundial Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal beacon]

Help

[vital crag]

Just enter blue - red curve into your plot

[muted prairie]

Ye or do the same process for the red curve and then subtract

Though it looks like you didn't start in exactly the right place

[final saddle]

@vernal beacon Has your question been resolved?

[vernal beacon]

Wdym

How

[vital crag]

blue = f(x)

red = g(x)

plot f(x) - g(x)

[vernal beacon]

Ohh alr

Thanks guys

[final saddle]

Channel closed

Closed by @vernal beacon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plush mason]

$0<x<1$
It will be $-\infty<ln(x)<0$
?

[soft zealot]

RulzerFly.

[vital crag]

yes

[plush mason]

Okay okay thanks

[final saddle]

@plush mason Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen crescent]

Help

[queen crescent]

25° + 90° right?

[bleak granite]

for the upper left triangle you do have 25º+90º+zº yes, then you can use your kite properties to figure out the rest of the angles

[final saddle]

@queen crescent Has your question been resolved?

[final saddle]

@queen crescent Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty sequoia]

y =\sqrt(x^(2)+9) - 6

[misty sequoia]

How to find the domain of the function?

[wind delta]

ok

so now within a given square root the valu must be positive

can u write down your question properly?

[misty sequoia]

Could you explain?

y = sqrt(x^(2)+9) - 6

Find the range of the function **

[wind delta]

so now the most important rule of square roots
never have a negative in it

[misty sequoia]

x^2 + 9 >= 0

[wind delta]

$$(x^2 +9)^{1/2} -6$$ am i right?

[soft zealot]

Ohio

[misty sequoia]

Yes

[wind delta]

yep correct

[misty sequoia]

What's next?

[wind delta]

so now

sry i was afk

[misty sequoia]

np

[wind delta]

$$x^2-9>0$$
$$x^2 > 9$$

[soft zealot]

Ohio

[wind delta]

right?

on solving x = +3 or -3

[misty sequoia]

No

Wait

y = sqrt(x^(2)+9) - 6

x^2 > -9

[wind delta]

then leave

its inifinty

the range

because the x^2 term always generates a positive output

this can never be negative

[misty sequoia]

Is the range infinity?

[wind delta]

0 to infinity

[misty sequoia]

Why? y = sqrt(x^(2)+9) - 6

-6

[wind delta]

ok ok wait

i am confused

one sec

i need to breath

[misty sequoia]

I can send you a graph

[wind delta]

are you familiar with derivatives?

[wind delta]

umm no worries i have opened with desmos

[misty sequoia]

Yeah

[wind delta]

cool

then u are set

calculate the derivative of the function

[misty sequoia]

I dont remember derivative of square root

[wind delta]

$$\frac{dy}{dx}=\frac{1}{2\sqrt{x^2+9}} + 2x$$

alr

ayo

the whole denominator is in sqr root

better

now equate to 0

[soft zealot]

Ohio

[wind delta]

finally

[misty sequoia]

sqrt(x) = 1/(2*sqrt(x)) ?

[wind delta]

nope

[wind delta]

this value

[misty sequoia]

I mean what is derivative of 1/x ?

[wind delta]

-1/x^2

[wind delta]

apply the power rule

[misty sequoia]

WHattt?

[wind delta]

okay

let me explain

this may take a while to type

$$y = a^n$$
$$\frac{dy}{dx} =n\cdot a^{n-1}$$

[soft zealot]

Ohio

[wind delta]

nice

[misty sequoia]

Oh, I understood, thank you

[wind delta]

got it right?

[misty sequoia]

2 * sqrt(x^2 + 9) isn't equal to 0

But how to find the range?

[misty sequoia]

Sure

[wind delta]

equate this to 0

the definition of dy/dx means slope

this means that when the slope of the graph is zero then is attains the maximum or minimum value

[tired walrus]

is this meant to be the derivative of sqrt(x^2 + 9) - 6? @wind delta

[misty sequoia]

(1/(2 * sqrt( x^2 + 9 )) + 2x = 0 ?

[wind delta]

yea

[tired walrus]

shame on you

[wind delta]

?

[tired walrus]

you fucked it up

[wind delta]

how ?

[tired walrus]

it's 2x/sqrt(x^2+9)

not what you wrote

[wind delta]

ayo ayo

sqrt(x^2 + 9) only these terms are in the square root

oh shit

shit

oh my god

[tired walrus]

@misty sequoia исходное условие задачи есть?

[wind delta]

$$\frac{dy}{dx}=\frac{1}{2\sqrt{x^2+9}} \cdot 2x$$

[soft zealot]

Ohio

[tired walrus]

так

а при этом ожидается ли, что от функции мы будем брать производную?

а то решается задача и без нее...

[misty sequoia]

Неа, там такого не написано

[wind delta]

@tired walrus @misty sequoia i am really sorry
i am not haivng a good day
so yea bear

really sorry imma hop of

[tired walrus]

x^2 + 9 ∈ [9, +∞) => sqrt(x^2 + 9) ∈ [3, +∞) ...

[misty sequoia]

no problem, have a good day

[wind delta]

sorry
and thanks

[misty sequoia]

А как вы нашли область значений?

[tired walrus]

область значений x^2 есть множество всех неотрицательных чисел

формально я не сказала ничего про область значений как таковую, то мне лень писать полностью

[misty sequoia]

Интересный вариант, но он неверный

[tired walrus]

?!

так, секунду

так, стоп.

мб трудности перевода?

[misty sequoia]

Вот, я даже не знаю как эту функцию нарисовать

[tired walrus]

что такое "область значень"?

[misty sequoia]

Область значень - это range

[tired walrus]

точно?

[misty sequoia]

Да

[tired walrus]

потому что у этой функции точно range [-3, +∞), но ваша система верный ответ отвергает

[misty sequoia]

Неа, зеленым правильный ответ показывает

[tired walrus]

попробуйте вариант Д, вдруг они domain имели в виду...

[misty sequoia]

Это я не выбирал просто

[tired walrus]

??

[misty sequoia]

Я вариант ответа не выбирал

[tired walrus]

тогда чего вы мне втираете, что мой ответ неверный

из того, что я написала, [-3, +∞) следует

я остановилась в шаге от ответа, ессно

[misty sequoia]

[3; infin. ) ....

[tired walrus]

а вы посмотрите, КТО ему принадлежит.

sqrt(x^2+9), а не sqrt(x^2+9)-6.

[misty sequoia]

А как мне нарисовать этот график?

Я просто с такой функцией не сталкивался

И как найти ее область значений тоже не знаю

[tired walrus]

1. график опционален
2. я рисовала на http://desmos.com/
3. я дала в общих чертах способ нахождения области значений

[misty sequoia]

Нет, а как его от руки построить?

[tired walrus]

эээ

ну блин

асимптоты и экстремумы посчитать

[misty sequoia]

Как??

[tired walrus]

епрст

вас не учили совсем?

[misty sequoia]

Я просто не понимаю как это все в этой функции найти

Только по графику знаю

[tired walrus]

вы знаете, что такое "асимптота" и что такое "экстремум"?

[misty sequoia]

Асимтота это прямая, которую функция никогда не пересечет, но будет к ней стремиться

[tired walrus]

про "никогда не пересечет" -- вранье

[misty sequoia]

А экстремум - это точка где функция меняет знак

[tired walrus]

тоже вранье

[misty sequoia]

Чего?

Я могу заскринить

[tired walrus]

ну скриньте...

экстремум -- точка, где функция меняет МОНОТОННОСТЬ, или где меняет знак ее производная. знак самой функции не канает вообще.

а асимптоту пересекать можно, причем сколько угодно раз.

[misty sequoia]

Асимптота у y = 1/x это оси x и y

[tired walrus]

прекрасно

[misty sequoia]

И на нуле значение нельзя получить

[tired walrus]

конкретно в этом случае кривая асимптоты не пересекает

вы утверждаете, что из одного этого примера следует, что кривая НИКОГДА не может пересечь свою же асимптоту?

[misty sequoia]

Скажите пример, когда может

[tired walrus]

x(x-1)(x-2)(x-3)/(1+x^6)

вот у этой функции горизонтальная асимптота y=0

[misty sequoia]

Офигеть

[tired walrus]

пересекается с графиком ажно четырежды

в точках x=0, x=1, x=2, x=3

[misty sequoia]

Мы такое не проходили )

[tired walrus]

полиномы степени выше 2 -- темный лес, о существовании которого даже задумываться запрещено, ага...

а про экстремум вы просто неправильно выучили / забыли определение

[misty sequoia]

Это универ походу

[misty sequoia]

Что такое экстремум?

[tired walrus]

экстремум -- точка, где функция меняет МОНОТОННОСТЬ, или где меняет знак ее производная.

во всех экстремумах производная функции равна 0 (а наоборот -- не всегда, например x^3)

[misty sequoia]

Так, а что такое производная тогда?

А то я только понял как ее находить

А что это, не понял

[tired walrus]

епрст

как вас там учат, что производные вы находить умеете, а что они значат -- от вас скрывают????

это как учить китайский язык исключительно по начертаниям иероглифов

[misty sequoia]

Ну это я конкретно про себя говорю, что не понял, потому что недавно это начал учить

[misty sequoia]

Я просто до 11 класса не учился особо

И не слушал на уроках, что означает производная

Ну в плане

[tired walrus]

и зря

[misty sequoia]

На нескольких слышал, но не понял

[misty sequoia]

Ну я это только сейчас понимаю )

[tired walrus]

совсем образно: производная -- скорость изменения значения функции при малых изменениях ее аргумента.

[misty sequoia]

Это по типу slope?

[tired walrus]

slope of the tangent line

у прямых этот самый slope постоянен, а для нелинейных функций производная дает slope касательной прямой к графику

[misty sequoia]

В этом моменте можно поподробнее?

По типу у не линейных функций склон не постоянен, и в каждой точке разный?

[tired walrus]

хоспаде

ну да

https://www.youtube.com/watch?v=9vKqVkMQHKk

честное слово, это такие азы, что лично мне немного лень объяснять.

[misty sequoia]

Это секантная?

[tired walrus]

аааа

[misty sequoia]

Я конечно понимаю, что в России образование получше в математике )

[tired walrus]

учебник по матану хоть какой-нибудь при себе есть?

[misty sequoia]

По алгебре и геометрии

[tired walrus]

нет, именно по матану, он же математический анализ.

матан -- дифференциальное исчисление, интегральное исчисление и иже с ними

вот, короче, Зорич. почитайте. глава про дифференциальное исчисление начинается на странице 202.

[misty sequoia]

Неа, у нас только книжка по алгебре и геометрии, но она useless, в интернете за 30 минут больше понять можно чем за 2 часа в этой книге

[misty sequoia]

Спасибо, сейчас прочту

[tired walrus]

не сейчас прочтете, а хотя бы несколько дней уделите

не в одночасье постигаются такие вещи

вот еще демидович

[misty sequoia]

Да, но лучше сразу прочитать, а потом мозг начнет обдумывать уже

[misty sequoia]

Это книги для какого курса?

[tired walrus]

привязки к курсу не имеют

первый том Зорича вроде 1-2 курс университета покрывает

демидович вообще вечен

[misty sequoia]

Русского?

[tired walrus]

сферического в вакууме

[misty sequoia]

В плане?

Хорошая шутка

[misty sequoia]

А что читать то?

[tired walrus]

так я ж сказала

[misty sequoia]

А, стоп, там страницы не так расписаны

[tired walrus]

я не знаток образовательных программ всех университетов мира

согласно моему опыту, материал 1-го тома Зорича -- примерно первые полтора или два года курса матана, на котором училась я

[misty sequoia]

Я только знаю что производная расстояния = скорость, производная скорости = ускорение

[tired walrus]

полезная аналогия

[misty sequoia]

Ну скорость изменения функции, все равно не понял что это

Я только знаю что такое скорость изменения линейных функций

[misty sequoia]

Но там по физике рассказывается

[tired walrus]

мозг не отсохнет

[misty sequoia]

Так я ничего не понимаю

Вот читаю, но непонятно

[tired walrus]

тогда я не знаю, как еще помочь.

[misty sequoia]

Но я не понял, как найти область значений данной функции: y = sqrt(x^(2)+9) - 6, если я не понимаю, как ее рисовать

[final saddle]

@misty sequoia Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glacial ruin]

Can somebody confirm the mistake in this working? (image deleted)

[tired walrus]

there is no mistake here

[glacial ruin]

[tired walrus]

other than a missing theta in the middle of the second line

[glacial ruin]

Nvm, my brain is playing dumb

.close

[final saddle]

Channel closed

Closed by @glacial ruin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal thistle]

Use Division rule

[random niche]

is there another way I can look at this?

these look hard to multiply and square

[elder prawn]

yes

factor out

[lethal thistle]

I think any other way would be too complicated

[elder prawn]

factor out 1/2sqrt(x)

[lethal thistle]

And long

[elder prawn]

in the num

[random niche]

wym factor out

just "get rid" of them

are you saying there is a 1/2sqrt(x) in denom?

[elder prawn]

no the numerator

can be simplfied to

$\frac{3}{2\sqrt(x)}$

[soft zealot]

candies

[elder prawn]

because theres a common factor $\frac{1}{2\sqrt(x)}$

[soft zealot]

candies

[random niche]

hmm i'm not sure how you got there

can you draw on my picture?

[random niche]

.

[random niche]

yes

what happens to them? and how do they affect the others?

[elder prawn]

combine them wdym

ab-ac = a(b-c)

[random niche]

so the numerator just becomes sqrt(x) + 3 - (sqrt(x)) ?

[grim badger]

Factoring meaning like this $2x^2 + x = x(2x + 1)$. In that example, I factored the GCF of x

[soft zealot]

dldh06

[elder prawn]

do you know basic algebra

[random niche]

yes, but looking at these terms is giving me a hard time visually

[elder prawn]

ok sure

[grim badger]

Then sub in a variable, something like $a = \frac{1}{2\sqrt{x}}$

[soft zealot]

dldh06

[grim badger]

If that helps

[elder prawn]

actually the solution is so

unclean

[grim badger]

Then the numerator becomes $a(\sqrt{x} + 3)-a(\sqrt{x})$

[soft zealot]

dldh06

[random niche]

not fully confident with sqrt rules, why did those 2 sqrt(x)'s cancel out?

[elder prawn]

what

are you even

[grim badger]

Then you can visually see that a is the GCF, factor that out, then sub back in the $\frac{1}{2\sqrt{x}}$

[soft zealot]

dldh06

[elder prawn]

why are you doing calculus

[random niche]

i dont need the comments about my skill

im trying

[elder prawn]

ok so

do you know that a and -a cancels out

[random niche]

nvm i see

[grim badger]

Because it's the same but opposite. Sqrt applies the same logic as any other value. If you had (a + 3 - a), you'll see that the a's cancel

[elder prawn]

yes

[random niche]

I thought the 1/2sqrt(x) was multiplying with the sqrt(x)'s

didnt recognize - sign

at first

ok now what should I do after I have 3/2sqrt(x) over (sqrt(x) + 3) ^2

[random niche]

this is (sqrt(x) + 3)^2

.close

[final saddle]

Channel closed

Closed by @random niche

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[past bluff]

How do I go about solving "Find the values of x, given that x+1, 2x, 2x+3 are consecutive terms of an AP

[random loom]

@past bluff you there?

[past bluff]

Yes

[random loom]

do you know what's common difference is?

[past bluff]

In general? Yes

[random loom]

so,
2x -( x+1) (is common difference in your question right?)

[past bluff]

yes

[random loom]

and 2x+3 - 2x is also common difference right?

[past bluff]

yes

[random loom]

since common difference is equal
2x-(x+1) = 2x+3-2x

[past bluff]

so x=4?

[random loom]

now just find x

[past bluff]

huh?

[random loom]

yes

[past bluff]

then i put 4 into all the values

[random loom]

yup, and you get your arthimitc series

or sequence

did you understand thou ?

[past bluff]

well, i got 5, 8 and 11 but their common differrence is 3

[random loom]

yeah, what's the question asking to find?

[past bluff]

the values of x

oh wait nvm

dyk how to do this?

[random loom]

huh?

[past bluff]

The 8th term of an AP is 18 and the 12th term is 26. Find the first term, the common difference and the 20th term

I already started by equating 18 = a + 7d

oh wait

god

I know how to do it

[random loom]

by any chance are you in grade 10?

[past bluff]

Nevermind

[random loom]

okay

[past bluff]

Nope

[random loom]

which grade are you in?

i remember doing series in grade 10

[past bluff]

11th

I did it in grade 10 yeah but under advanced maths

i'm repeating it now

[random loom]

oh, where are from since I am grade 11 to from this year

[past bluff]

UK

[random loom]

oh, Nepal i think our course is lil bit harder then yours since competition thing anyway .close

[past bluff]

ohh i see

well thanks for the help

.close

[final saddle]

Channel closed

Closed by @past bluff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid tinsel]

I am determining if this series is absolutely convergent, convergent, or divergent. I did the alternating series test and got that it's convergent, and now I'm trying to test absolute convergence, but my mind went blank on what to do here ( I kinda forgot the techniques)

[vivid tinsel]

also, for other problems i do, is there an online calculator that I can use to check my work that can determine either CC,AC, or divergence for series?

[vivid tinsel]

seems like symbolab can do this, no steps tho, so not very useful

[past bluff]

No steps as in you don't have premium or it just doesn't have steps?

[vivid tinsel]

yeah i dont have premium

[past bluff]

I could help you put it in

I have

[vivid tinsel]

well i'm going to be studying a lot today so ill need it throughout the day

[past bluff]

oh damn

[vivid tinsel]

rn i just need help with this

[past bluff]

Sorry

[past bluff]

What do you want me to input into symbolab

[vivid tinsel]

oh i guess that would probably tell me how to do it

just the initial series then, (-1)^nlnn/n

but if any <@&286206848099549185> know how i test absolute convergence here that would be good

[odd sleet]

Could you type in the series in question?

In latex

[final saddle]

@vivid tinsel Has your question been resolved?

Channel closed

Closed by @vivid tinsel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral nebula]

What are the chances to win in the fruit machine?

[odd sleet]

7

[spiral nebula]

I mean to get identical 3 fruits

I don't know how to explain

There is 5 fruits in a wheel

[onyx peak]

and 3 wheels?

[spiral nebula]

Yeah, 3 wheels and each has 5 fruits

[rain crane]

7 donuts?

[spiral nebula]

What are the chances to get the same fruit in each wheel?

Like 777

When you win

[onyx peak]

so on the first wheel, there is some fruit. Now in order to win, you need the second wheel to spin same fruit. What's the prob of that happening? What's the prob of spinning one particular fruit on the second wheel?

there are 5 fruits in a wheel

It's just 1/5, right?

[spiral nebula]

In each wheel

[dreamy topaz]

its 5 * 1/5^3

i think

[spiral nebula]

He is talking@dreamy topaz

You can leave him to answer

[dreamy topaz]

sure, sorry

[onyx peak]

its alright, just dont give out answers that can be copied as homework solution

[final saddle]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[onyx peak]

its in rules

So whatever spins on first wheel, the probability that it also spins on second wheel is 1/5.

[spiral nebula]

Dont all the 3 wheels spin at same time?

[onyx peak]

It doesnt really matter

it doesnt affect the probability

[onyx peak]

the probability that it also spins on third wheel is again 1/5. So it's 1/5*1/5 which is just 1/5^2 or 1/25

[spiral nebula]

20% * 20% * 20% ?

[onyx peak]

That's probability that you spin some particular fruit on all wheels.

for example banana everywhere

but since there are 5 fruits, you can multiply this by 5 to get again the correct ans

5 * 20% * 20% * 20%

[spiral nebula]

Still dont get it

Look at this

It landed on apple

On all the wheels

There is 3 wheels

And each wheel has 5 fruits

What are the chances to get the same fruit on the 3 wheels at once ?

[onyx peak]

so you did 20% * 20% * 20%. But notice that at start, you were assuming it landed on apple.

Whats the probability that first wheel lands on apple? 20%. The second? 20%. The third? 20%. So the probability that everything is apple is 20% * 20% * 20%

But it could also land on bananas. The probability that all lands on bananas is again (20%)^3.

The probability that all wheels land on bananas or all on apples is therefore (20%)^3 + (20%)^3, since youre just adding the probabilities

but there are also 3 more fruits

[spiral nebula]

Thats 80%

20 x 20 x 20

[onyx peak]

(20%)^3 means 20% * 20% * 20%

[onyx peak]

That would be 8000

percents are multiplied in different way

you first need to convert them to the decimal form, basically division by 100.

So 0.2 * 0.2 * 0.2

now you can multiply them to get 0.008

and if you want you can convert back to percent by multiplying it by 100.
0.8%

so the real probability is 0.8%

(Of everything landing just on apples)

[spiral nebula]

Thank you so much @onyx peak

No i understand

Now

[tranquil pine]

#1105542653438873610 PLS HELP

[onyx peak]

from this to get probability of everything landing on same fruit, just do 0.8% + 0.8% + 0.8% + 0.8% + 0.8% or 5*0.8% since there are 5 fruits

[spiral nebula]

Yea but not on the same wheel

But the old way also works right?

The one yoy explained earlier

[onyx peak]

Probably nowhere

I think you're too young to be on discord, sorry

[high lotus]

he is

[onyx peak]

<@&268886789983436800>

srrsly

[high lotus]

you play too much

make a problem ticket

im new man maybe math knows

[onyx peak]

yeah. 1/5^2 when converted to percents is same as 5*0.8%

start by reading #❓how-to-get-help

[high lotus]

thanks man

[spiral nebula]

.close

[final saddle]

Channel closed

Closed by @spiral nebula

Use .reopen if this was a mistake.

[high lotus]

w tangerine fan

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[harsh socket]

Two vectors lying on the Cartesian plane (y,z), have the same module equal to 4 units. The first makes an angle of 25° with the y axis and the second makes an angle of 45° with the direction of the first vector. What is the dot and cross product of the first vector and the second? (indicate with \hat{i} , \hat{j} and \hat{k} the unit vectors of the x, y and z axes, respectively)

(a) scalar= 16 ; vector= -16 \hat{j}
(b) scalar=4 \hat{j} ; vector= 16

(c) scalar= 0 ; vector= 16 \hat{k}

(d) scalar= 0 ; vector= 0
(e) scalar= 8 \sqrt{2} ; vector= 8 \sqrt{2} \hat{i}

[harsh socket]

3

[final saddle]

@harsh socket Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight void]

the traingle created here is an equaliteral

which has 60 degrres angles & 8 cm sides

Now I've given a hint try to solve

[undone agate]

ok thankssssss

how can i calculate the area of the arc

wait i got it

thanks

[tight void]

ok

in case u wondering for any circular art the formula to get its area is theta/360 * pie * r^2

[undone agate]

ok thankssss

is the answer around 78.6

[tight void]

the area of the shadded?

[undone agate]

yes

[tight void]

Oay wait lemme grab a pen & notebook real quick

[undone agate]

ok ty

btw can u also give me some hint?

ty

[tight void]

Yea

I got the same

U r a genius tbh

[undone agate]

let's goooooooo

haha thanksssss

[tight void]

Note: It's the area okay?

And according to the ques

U have to get the perimeter of the shaded region as well

can u get that

[tight void]

lemme try

[undone agate]

yup

33.5

[tight void]

Okay nice

[undone agate]

ty

[tight void]

is EBCD rectangle?

[undone agate]

yes