help-36

[languid adder]

ramonov

can u help

[final tangle]

you're not following the instructions

[languid adder]

ok refresh

so

[final tangle]

I'm saying raise e to those numbers
if you have thing 1 = thing 2
then e^(thing 1) = e^(thing 2)

can you apply that and only that to what you have

[languid adder]

so

[final tangle]

do not apply any of the log rules yet

[languid adder]

e^1.39=e^4

right?

[final tangle]

no

[languid adder]

?

[final tangle]

that's the same thing you had before that we said was incorrect

[languid adder]

i just followed this

[final tangle]

you did not

what's thing 1 here

[languid adder]

i meant 4

[final tangle]

no

thing 1 isn't 4

the equation you're given isn't
4 = 1.39

[languid adder]

lnbase e of 4?

[final tangle]

yes

[languid adder]

ohh

e^lnbase e of 4 = e^1.39

[final tangle]

also log base e of 4
if you're going to use ln, no need to say the base

[languid adder]

oh ye

cuz we already know it

[final tangle]

but yes

and only now should rule 7 be applied

[languid adder]

yea

how would u apply it

what would u do after

[final tangle]

there's nothing much else to do after applying it

[languid adder]

thats my answer?

.close

[final saddle]

Channel closed

Closed by @languid adder

Use .reopen if this was a mistake.

[languid adder]

.reopen

[final saddle]

✅

[languid adder]

@final tangle

and thats in exponential form right?

[final tangle]

show me your final result

[languid adder]

that was it

[final tangle]

then you haven't applied rule 7
so you're not done

[languid adder]

so what do i do

[final tangle]

apply rule 7

what's your issue with applying rule 7 here

[languid adder]

i have it in that form already

[final tangle]

yeh, and what is it equal to according to the rule

[languid adder]

k

[final tangle]

yes

and applying that law, what would
e^(ln(4)) be?

[languid adder]

just 4?

[final tangle]

yes

[languid adder]

so 4=e^1.39

[final tangle]

yes

[languid adder]

oh alr

i see

thanks

.close

[final saddle]

Channel closed

Closed by @languid adder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eternal crypt]

I honestly am so lost please if someone can help

[frosty bolt]

When you guys are done cab someone help me on number 32

Can*

[final saddle]

Please stick to your channel.

[eternal crypt]

<@&286206848099549185>

[final saddle]

@eternal crypt Has your question been resolved?

[eternal crypt]

No

[final saddle]

@eternal crypt Has your question been resolved?

Channel closed

Closed by @eternal crypt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom coyote]

What’s stored in MONTHS

[fathom coyote]

What does it mean in the loop when it’s count < MONTHS

My guess is it’s 31?

[tranquil pine]

is this javascript?

Im not 100% sure cause I know more python and other languages but isn't it telling the for loop to continue while the count is less than months? you will have to fact check this though

[marsh temple]

i would bet money that's exactly what it means

[tranquil pine]

its first setting the int count to 0

then making sure that the count is < than months

if it is its adding 1 to count

and doing the rest in the for loop

Im pretty sure

At least thats how python works

[fathom coyote]

that doesn’t answer my question really but

it’s ok

it adds one to count regardless I think???

Might be wrong

@marsh temple what’s your chess rating

[tranquil pine]

count < MONTHS is checking and making sure count is less than months to do whats in the for loop

[marsh temple]

1400-ish chess.com

[tranquil pine]

MONTHS = 12 so it should continue the loop until count is equal or greater than 12

[fathom coyote]

Oh okay

I get that

[fathom coyote]

how long have you been playing

[marsh temple]

a few years

[dry light]

I can beat steakanator if you give me his IP and a zip bomb

[final saddle]

@fathom coyote Has your question been resolved?

Channel closed

Closed by @fathom coyote

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pine]

How would I find the value of tan(-135)

[tranquil pine]

in degrees

[sturdy cypress]

it's sin of that divided by cos

that's how

the definition

[tranquil pine]

yeah but my unit circle is in positive degree values

[sturdy cypress]

well you go down instead of up

and you can add 360 too

[tranquil pine]

oh yeaa

ur right

because it would be at the same position, leading to the same value

[sturdy cypress]

yep

[tranquil pine]

-135+360= 225

tan225=sin225/cos225

[sturdy cypress]

that's right

[tranquil pine]

ahhh makes sense thanks

thank you

.close

[final saddle]

Channel closed

Closed by @deep wraith

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final saddle]

@tranquil pine Has your question been resolved?

[final saddle]

@tranquil pine Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak kraken]

WA and Symbolab can't solve this

[oak kraken]

I'm having a hard time with it as well

any ideas?

[rancid prairie]

have you tried Lhopita rule?

[oak kraken]

I haven't learned that yet

is it required to solve?

[rancid prairie]

thats too easy

it maybe able to solve thiw

this*

[oak kraken]

this one?

[rancid prairie]

yes

[oak kraken]

this works for any limit?

[rancid prairie]

no

it works for some

that y i typed maybe above

i think it will work here

maybe

[oak kraken]

weird that WA can't use that

to solve

[onyx peak]

Works for indeterminate forms

infinity-infinity, infinity/infinity, 0/0, etc

[hybrid heath]

also infinity-infinity

You can also intuition solve this limit

LeHospital will prove it tho

[oak kraken]

My intuition is that the highest power in the numerator is 3 (-8x^9)^3 and the highest power is also 3 in the denominator (3x^3)
so therefor the limit as x approaches infinity, also known as the horizontal asymptote, is -8/3

[oak kraken]

would that be correct when you say "intuition to solve"?

or am I misreading this numerator

[hybrid heath]

I'm not seeing how you got the numerator

[oak kraken]

oh, -8x^9

is the last term in the cubic root

[hybrid heath]

yes

[oak kraken]

and to combine powers and roots, it's power/root in exponential form

so 9/3

=3

[hybrid heath]

yes. The power is ~3

[oak kraken]

-3 or 3?

[hybrid heath]

!nosols

[final saddle]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[onyx peak]

$lim_{x\to\infty}\frac{\sqrt[3]{-8x^{9}}}{3x^{3}}$

[soft zealot]

MathIsAlwaysRight

[onyx peak]

sorry, copied to much text

[onyx peak]

The limit is equal to this

[hybrid heath]

hah. It happens

[oak kraken]

so this would be the answer?

[onyx peak]

You would have to solve that

[oak kraken]

I thought you could write it as -8/3

if the powers are the same in numerator and denominator

[onyx peak]

but it's actually cube root(-8)/3

because the cube root also applies on -8

[oak kraken]

so this is correct?

[onyx peak]

No.

[oak kraken]

hmmmm...

[onyx peak]

Try to evaluate this

[oak kraken]

cube root (-8)... oh, right..

i am just looking at the variable but i need to also look at the constant too

so -2/3 is the correct answer for this limit

thanks!

that seems much easier to solve, and no L'Hôpital's rule required

if this was limit as x->0, or limit as x->3, etc.

I could still do the same thing?

or only for Infinity

[onyx peak]

I dont think so

[dry light]

End behavior

[magic sparrow]

only for infinity

The idea is that as x-> infinity the components of the function that most effect the output are those with the highest degree

[hybrid heath]

x->0 is just simple calculation here

[oak kraken]

well, 0 would be easy. 1/2

[onyx peak]

In this case (with -inf) yes, just keep track of the sign

[oak kraken]

but 3 i would just need to plug in 3 for x?

and solve

[oak kraken]

OK

[onyx peak]

Yeah, but in case it would result in 0/0 you would need to use Lhopital or sth

[oak kraken]

ah I see

whenever there is no way to factor

interesting..

I think I will be learning L'Hôpital's rule this month

our professor hasn't covered it yet

[magic sparrow]

the gist of L'Hopitals rule is that it is allowed for indeterminate forms

[oak kraken]

so for x->3 with this example, the only way to find the limit is to plug in 3? since there is no other way to factor this, and it doesn't equal indeterminate

[magic sparrow]

if you are able to substitute x=3 and the result isn't undefined or indeterminate then there is no reason that you shouldn't just plug it in, yes

[oak kraken]

alright

thanks!

[onyx peak]

btw Lhopital work ONLY with indeterminate forms

[oak kraken]

yeah

will keep that in mind

prob why we haven't learned it yet, to not get confused where to use it

but good to know

i keep reading it as L'Hospital's Rule

maybe that's a good way to think about it.. like the emergency room last effort to save something

[dry light]

L'Hospital is another way writing it

[oak kraken]

Oh ahha

[dry light]

Hopital is literally French for "hospital"

[oak kraken]

and Bernoulli's rule

Ahhh I see I see haha, so it kinda does mean that maybe?

nope it's the name of the mathematician

unusual last name. it's like Thomas Police Station

Guillaume de l'Hôpital

also known as:
Guillaume-François-Antoine Marquis de l'Hôpital,
Marquis de Sainte-Mesme,
Comte d'Entremont,
Seigneur d'Ouques-la-Chaise

.close

[final saddle]

Channel closed

Closed by @oak kraken

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pine]

how do i get pi/4 without a calc

[midnight sparrow]

It's a value that you need to know

[tranquil pine]

i just memorize those?

is there an easy way to remember

[midnight sparrow]

Yes with pi/6 and pi/3

All are divide by 2 and are like 1, sqrt2 and sqrt3

[tranquil pine]

Hes refering to the unit circle and soecial triangles

Special triangles*

so to be efficient with these topics i should memorize unit circle?

[midnight sparrow]

Yes

Like visualize it

[tranquil pine]

is it often to find someone that memorizes unit circle

Yes

A bunch of viseos on youtube

[midnight sparrow]

But with some exercises you will get it

[tranquil pine]

U got brian mclogan pratrickjmt

thats a good youtuber?

Use the internet

Ya

https://tenor.com/view/hi-ryan-ryan-gif-26197244

[midnight sparrow]

Google it

But you need to know all these values

To work efficiently

[tranquil pine]

i need to watch brian i think

.close

[final saddle]

Channel closed

Closed by @viral comet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hushed stump]

how do I “crack” this code

[worldly vale]

What's on the "previous page"

[hushed stump]

this is one

this is the other thi bbg

thing*

these are all of them

.close

[final saddle]

Channel closed

Closed by @hushed stump

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[undone idol]

why is 5^3 and not 125? someone can explain me?

[desert mantle]

well they wrote 5^3 cause thats just x=5 plugged into x^3

no need to actually calculate it, later on it will cancel anyway

[final saddle]

@undone idol Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit jetty]

anyone free to help me plz?

[twilit jetty]

idk how to do this, i need a waklthro plz

[vital crag]

write two equations. one for perimeter and one for the length and width relationship

[twilit jetty]

so using 5,280?

using multiplacation?

[vital crag]

you'll need to use every piece of information given

yes

[twilit jetty]

ok lemme get a pencil and paper

ok

5,280 ft

x 3?

for the width

@vital crag

so, if i do 5,280 x 2 for the length

cuz its 2 sides

and then 5,280 x 3 for width

cuz it also says the width is 3x larger

and that would be 15,840

so that x 2 for the 3 sides

???

😭 💀

[final saddle]

@twilit jetty Has your question been resolved?

Channel closed

Closed by @twilit jetty

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet rune]

what's the name of this operation : v ^ q
v and q are vector

[tranquil pine]

any context?

[violet rune]

in physic we define the magnetic force as q(v^B)

[tranquil pine]

do you have a screenshot of it?

[violet rune]

but don't remember how to perform this operation so i would like to have the name to do so research

[tranquil pine]

maybe you are looking for the cross product https://en.wikipedia.org/wiki/Cross_product

[tranquil pine]

maybe ask in the physics server in #old-network

[final saddle]

@violet rune Has your question been resolved?

[tranquil pine]

$m\vec a = e\vec v\wedge \vec B$ is an alternative way to write the cross product.

[soft zealot]

Landau08

[tranquil pine]

(see https://en.wikipedia.org/wiki/Cross_product)

$\vec v \wedge \vec B$ is perpendicular to both $\vec v$ and $\vec B$ and has the length $|\vec v|\cdot|\vec B| \cdot\sin\phi$, where $\phi$ is the angle between $\vec v$ and $\vec B$. The formula quoted ist the Lorentz force on a charge e flying with velocity $\vec v$ through a magnetic field of strength $\vec B$

[soft zealot]

Landau08

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[late glen]

I need help

[tired walrus]

@late glen http://dontasktoask.com/

[late glen]

I again need help with quadratics

[tired walrus]

you should post your question

[final saddle]

@late glen Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[languid adder]

how do u solve this

idk what equation to use

[uneven thistle]

This is a physics question, but probably E = mgh

[languid adder]

oh

[uneven thistle]

But you need to use suvat equations to figure out how far it fell

(h)

[languid adder]

what suvat

[uneven thistle]

Is this A-Level physics? You're provided them on your formula sheet

This feels like A-Level physics

[languid adder]

nah

just reg physics

[uneven thistle]

So you want s and you have u, a, v

So you want an equation with these four

[languid adder]

would i use conservation of energy equation

oh alr

[uneven thistle]

I think they will both give the same answers

because physics works this way

i suppose that is an easier method though

it's been a while since I did physics

[languid adder]

yea

lol its fine

[light wren]

I would just think of it as all of the potential is 'used' up

[languid adder]

wdym

[light wren]

at some height h

[languid adder]

yea

[light wren]

there is $E_p=mgh$ amount of potential energy for that object

[soft zealot]

Clarkie

[languid adder]

yea

[light wren]

taking the ground to be the 'zero' point, it has x amount at the top, and 0 at the bottom

[languid adder]

yea

[light wren]

meaning x amount of energy went into moving it

[languid adder]

yea

[light wren]

or in other words $E_k=E_p$

[soft zealot]

Clarkie

[light wren]

should be able to solve it from there

[languid adder]

?

so the kinetic and potential energy are 0

[light wren]

no.

potential energy was some amount, and it's 'used up' giving the object kinetic energy whilst its moving towards the ground

[uneven thistle]

maybe useful to remember $E_k = \frac{1}{2}mv^2$ and $E_p = mgh$

[languid adder]

hm

[soft zealot]

Alfie

[languid adder]

ye ik that

[uneven thistle]

so then substitute them in

[light wren]

if all of the potential energy is used up in moving the object, at the final point before it touches the ground it has Ep amount of kinetic energy

[languid adder]

so what would the equation without the numbers look like

[light wren]

just substitute,

[uneven thistle]

$E_k = E_p$

[soft zealot]

Alfie

[uneven thistle]

so replace both with their definitions in this context

and see for yourself 😄

[languid adder]

so ik the mass is 7.7

[uneven thistle]

don't put the numbers in

keep the variables

and see what it looks like

[languid adder]

?

[uneven thistle]

then put the numbers in

[light wren]

solve this for h

[languid adder]

oh

u cant solve that

is it just k = p

[light wren]

?

[uneven thistle]

$E_k$ is not at all related to $E_p$ in that way, they're both just two different names

I see what you mean though

[soft zealot]

Alfie

[languid adder]

ohhh wait

so

all i do is

1/2mv²+mgh

right?

solve for h

[uneven thistle]

Closer

[languid adder]

bruh

[uneven thistle]

You can't solve that because it's not equal to anything, also

[languid adder]

yea

[uneven thistle]

1/2mv^2 + mgh = ?

You have $E_k = E_p$

[soft zealot]

Alfie

[languid adder]

mhm

[uneven thistle]

And you have $E_k = \frac{1}{2}mv^2$ and $E_p = mgh$

[soft zealot]

Alfie

[languid adder]

yea

[uneven thistle]

So replace $E_k$ and $E_p$ in $E_k = E_p$ with their definitions from here

[soft zealot]

Alfie

[languid adder]

thats what i did

[uneven thistle]

Not quite

[languid adder]

i just didnt set it equall to anything

[uneven thistle]

There is no + anywhere in this equation

You have $E_k$ EQUALS $E_p$

[soft zealot]

Alfie

[languid adder]

oh

sooo

[uneven thistle]

Think about it like this:

The object starts still. It is not moving. $E_k = 0$, right? It is at height h, so $E_p = mgh$.

Then, you drop it. $E_k$ increases as it gains velocity accelerating toward the ground, and $E_p$ decreases as the height decreases

[soft zealot]

Alfie

[languid adder]

yea

[uneven thistle]

Due to conservation of energy, the total energy in the system is the same. This is how we come to the conclusion that $E_p$ at the start = $E_k$ at the end

[soft zealot]

Alfie

[uneven thistle]

Because height is 0 at the end, so $E_p$ is now 0

[soft zealot]

Alfie

[languid adder]

ohh

[uneven thistle]

So all the energy is now in $E_k$

[soft zealot]

Alfie

[languid adder]

i got

9.161m

can some1 check

[light wren]

yes that's correct

[languid adder]

Thanks

Appreciate it

[final saddle]

@languid adder Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weak tartan]

using l'hopitals rule idk how far i should go

[weak tartan]

they all look incomplete to me lol

[tulip coyote]

until evaluating gives you a nonzero denominator

[also make sure you can convince yourself why lopital's still applies from line to line]

[weak tartan]

are any of the values gonna change and is anything gonna cancel out

or is this a game of plug and try

[bold badge]

"until evaluating gives you a nonzero denominator
"

that's what u got here btw

-0(0)+2(1) = 2

[weak tartan]

oh shit i see

ty

im not great at squeeze theorem need a lil help starting this off

[final saddle]

@weak tartan Has your question been resolved?

[weak tartan]

nvm im chillin

[final saddle]

@weak tartan Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful pilot]

Alice and Bob begin at points (1, 0) and (0, 1). They both want to reach the point (10, 10) and can do so by moving an an integer amount of units right or up. What is the chance that Alice and Bob meet each other before they reach the point (10, 10)?

[blissful pilot]

basically each person's path can consist of any combination of some moves to the right and some moves upwards

[final saddle]

@blissful pilot Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[blissful pilot]

.reopen

[final saddle]

✅

[final saddle]

@blissful pilot Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[blissful pilot]

.reopen

[final saddle]

✅

[blissful pilot]

bruh

[sudden creek]

One way I can think of is computing the probability of Alice/Bob arriving at (a, b), then multiplying said probabilities(so long as the steps are the same). Since they can only move up or right, that should simplify the calculations.

[sudden creek]

Oh! They can only meet if the steps they take are the same, so I think that reduces the possibilities of (a, b) as well

[final saddle]

@blissful pilot Has your question been resolved?

[final saddle]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fluid bay]

logarithm

[fluid bay]

help

[sudden creek]

what have you done so far?

[fluid bay]

sending pic

the quality of pic is shit

i know

[sudden creek]

Alright so you cancelled 2020, how did that get log_x(2021)?

[fluid bay]

i think thats wrong

[sudden creek]

It is

Ngl I can barely tell what you're trying to do here

Can you like, show what you're trying to do step by step?

[fluid bay]

me too

[fluid bay]

ok let me do it again

See now

sending

pic

[sudden creek]

Nah, you can't assume that. What if 2020^a = x and x^a = 2020? Then you get 2020^(a^2) = 2020, which gets a = -1. You can also do 1010^a = x etc.

I mean, the method you took can indeed get all solutions eventually, maybe ig

[fluid bay]

sorry i didnt catch you

i think its fine whats wrong with it

[sudden creek]

What happens if 2020^a = x and x^a = 2020?

[fluid bay]

then

[sudden creek]

What value of a do you get?

[fluid bay]

2020^a^2 = 2020

a =

+- 1

[sudden creek]

Yup

So you get a different solution

[fluid bay]

heres a better pic

[sudden creek]

That's why you can't assume a = 1 just by comparing x and 2020

[fluid bay]

ok

so how would you do it

[sudden creek]

one sec

[fluid bay]

ok

[sudden creek]

Take log_2020 on the last equation

[fluid bay]

you mean log 2020 in the base?

[sudden creek]

yup

[fluid bay]

is this ok too?

[sudden creek]

Yup

[fluid bay]

thanks

[sudden creek]

That works too

[fluid bay]

solved

.close thanks again @sudden creek appreciate the help

[final saddle]

Channel closed

Closed by @fluid bay

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh mountain]

i have a quick latex question

[marsh mountain]

i have no idea why im getting an error

this is the current source code

this is the finished code

and it says im missing a $ but i dont think i am?

like

what

[final saddle]

@marsh mountain Has your question been resolved?

[marsh mountain]

<@&286206848099549185>

[weak cloud]

yes?

[marsh mountain]

nvm

we chillin

.close

[final saddle]

Channel closed

Closed by @marsh mountain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant hollow]

Any help?

[stoic mural]

9/4 can be interpreted as 9 quarters
you could visualize this with pizza slices

[pliant hollow]

So

Whats a way I Can draw my model?

[stoic mural]

draw a pizza

we are dealing with quarters (indicated by the /4)

[pliant hollow]

Kk

[stoic mural]

therefore it is a good start to divide the pizza in to 4 slices

for example if we had 3/4, we would color in 3 of the 4 slices

we have 9/4 but only have 4 slices
do you know how we can fix this?

[pliant hollow]

Add?

[stoic mural]

yes

we add more pizzas

[pliant hollow]

ye

and so what?

[stoic mural]

then color in 9 slices

[pliant hollow]

It does not make sense

[stoic mural]

here is some reasoning why this works

here i divided the fraction into two

so we have 2 whole pizzas and 1 quarter of a pizza

[pliant hollow]

I can’t understand in a model

[stoic mural]

9/4 means nine quarters
so if we have pizzas, each divided into 4 slices (quarters)
then in total we have 9 of these slices

[pliant hollow]

.close

[final saddle]

Channel closed

Closed by @pliant hollow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hoary kraken]

how to find this out without plotting?

[tired walrus]

the x coordinates of these points ought to satisfy f(x) = f^-1(x), yes?

[hoary kraken]

yup

x^3 = x^1/3

[amber holly]

Note that generally a function intersects its inverse only on the line y = x

[hoary kraken]

generally?

[amber holly]

Yes

Or you don't know what generally means?

[rustic wedge]

What would the y be tho?

1 ig?

[hoary kraken]

i mean i know but i meant to ask what in what cases does that not hold true

[amber holly]

What I said is always true

Assuming the inverse exists, of course

[hoary kraken]

but you said generally 🥲

not always

[amber holly]

In maths "generally" means in all cases

Unlike in plain English

[hoary kraken]

ohhh

i see

then what do i do next?

do i find all values of x where x^3 = x?

[modest birch]

wait is this actually true

[amber holly]

Yeah

[modest birch]

why is that true

[amber holly]

Or you could simply pick the options where the coordinates have the same value and check if they lie on y = x^3

[modest birch]

what about something like y = 7-x which is its own inverse

it intersects itself everywhere, but only once on y = x

[hoary kraken]

ahh got it

[amber holly]

Forgot the proof, one moment

Well the points on y = f(x) have a form (x, f(x)) and the points on y = f^-1(x) have the form (f(t), t)

So, when the points are the same, you have x = f(x)

I guess there are exceptions

[final saddle]

@hoary kraken Has your question been resolved?

Channel closed

Closed by @hoary kraken

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weary lantern]

Can someone explain how to find the rate of change of a function

[final tangle]

differentiate

[weary lantern]

Okay

so, 4sin^2(x) would become 4cos^2(x) ?

Is that rate of change?

[final tangle]

no

[weary lantern]

Oh chain rule

okay ill try

8cosx^1 ?

aka 8cos(x)?

oh ok

wait

8cos(x)^2

[tulip coyote]

Might help to write it as $4 (\sin(x))^{2}$

[soft zealot]

@tulip coyote

[weary lantern]

yeah okay hold on

8sin(x)cos(x)?

is that the rate of change?

it seems too simple

[sand egret]

no

[weary lantern]

thought so

so now..

[sand egret]

8sin(x)cos(x) is 4sin^2(x)

[weary lantern]

huh

[tulip coyote]

tf

[sand egret]

sin^2(x) = 2sinxcosx

[weary lantern]

f(x) = 4sin^2(x) f'(x) = 8sin(x)cos(x)

[sand egret]

oh wait that's sin(2x) lol silly me

[weary lantern]

ok so after using chain rule, what do i do?

[tulip coyote]

Yea you can equivalently write 8 cos(x) sin(x) as 4 sin(2x)

Is there any more detail to the question? That would be the rate of change of y with respect to x

[weary lantern]

Oh yeah

it involves radians

oh my god

i did

i did ^2... and the question is ^3

[tulip coyote]

[pretty much any differentiation/integration with trig will be in radians]

[weary lantern]

ill redo it, with ^3

[tulip coyote]

Oh, as in they asked to differentiate $4\cos^{3}(x)$ then?

[soft zealot]

@tulip coyote

[weary lantern]

Like this

hold on ill try start it

[rustic wedge]

I think u have to evaluate the derivative at 5pi/6

[tulip coyote]

[was about to say that they probably meant x=]

[weary lantern]

yea okay

so far

12(sin(x))^2 . cos(x) ?

[rustic wedge]

Okay one sec, how?

[weary lantern]

chain rule

[rustic wedge]

Shouldn't it be 12(sin(x)cos(x))

[weary lantern]

no theres still a ^2

as it was cubed, then i took n-1

leaving it with squared

[tulip coyote]

We have $4(\sin(x))^{3}$

[soft zealot]

@tulip coyote

[weary lantern]

now i sub x= 5pi/6 ?

which is 5.180/6

150 is my degree

and then i use CAST to solve sin 150, cos 150

for cos 150, do i do 360 - 150?

as its positive in C, A

[tulip coyote]

Erm, I wouldn't

[weary lantern]

what do i do for it

as i got 30 for sin

and that gave 1/2

but cos...

[tulip coyote]

Well if you draw it out on a CAST, you should get 30 as the acute angle, right?

[weary lantern]

yes

[tulip coyote]

So then you want cos(30), but then remember you're where cos is negative

[weary lantern]

so in T,S

But why would i use cos 30?

[tulip coyote]

Yep, it's in the S in particular

[weary lantern]

How come?

[tulip coyote]

Draw it out on a diagram - the angle 150 lands in the S region

[weary lantern]

yes

180-150?

Okay

but its negative meaning..

[tulip coyote]

Yea that's it, and then you get sin(30) and cos(30) you look for

The former is 1/2, the latter sqrt{3}/2

[weary lantern]

• rt3/2

?

okay

[tulip coyote]

Then you can put all that into your expression before

[weary lantern]

I have 3(root3)/2

is that a rate of change?

[tulip coyote]

Think that should be -ve?

[tulip coyote]

And yep, the rate of change of y with respect to x

[weary lantern]

oh yes you're right i forgot to put that in

-3(root3)/2 ?

but you cant have -sqrt

[tulip coyote]

You don't - it's $-\frac{3\sqrt{3}}{2}$, which is fine, and not $\frac{ 3\sqrt{-3} }{2}$ (which isn't really fine)

[soft zealot]

@tulip coyote

[weary lantern]

but wouldnt -1(3(sqrt3)/3) = -1 x 3(sqrt3) = -3(sqrt3) = - sqrt9

sorry i know its wrong but im trying to understand why it wouldnt become a negative sqrt (which cant happen)

[tulip coyote]

Well let's take a slightly different example, let's try solving something like $x^{2} = 4$ - you're happy that $x = 2$ and $x = -2$ are both solutions to that?

[soft zealot]

@tulip coyote

[weary lantern]

yes

[tulip coyote]

Now if we change it slightly, we could try solving $x^{2} = 5$ - that has $x = \sqrt{5}$ as a solution, but also there's the solution $x = - \sqrt{5}$, right?

[soft zealot]

@tulip coyote

[weary lantern]

yes, but is that not a invalid solution?

[tulip coyote]

[note that the - is outside the square root, and that $-\sqrt{5} = (-1)\sqrt{5}$, and that $(ab)^{2} = a^{2} b^{2}$]

[weary lantern]

leaving us with x= root5 and thats it?

[soft zealot]

@tulip coyote

[weary lantern]

Okay

[tulip coyote]

No, not unless there's a restriction on the range that x can be in

[weary lantern]

Oh okay

thats much clearer

[tulip coyote]

anyways, from here, you get that $(-\sqrt{5})^{2} = (-1)^{2} (\sqrt{5})^{2} = 1\cdot 5 = 5$

[soft zealot]

@tulip coyote

[tulip coyote]

But, if, instead we wanted to do something like $x^{2} = -4$, we would have problems as we would want $x = \sqrt{-4}$, and also we know that any real number squared is non-negative

[soft zealot]

@tulip coyote

[tulip coyote]

[and so unless you're considering x to be complex, that would have no solutions]

[weary lantern]

Ok that makes sense

Thanks so much

.close

[final saddle]

Channel closed

Closed by @weary lantern

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit jetty]

can someone come help check my answers (and explain if they are wrong)

[rustic wedge]

It's 9.3

[twilit jetty]

oh

[fresh star]

pretty sure its 12.4

[rustic wedge]

Wait..one sec

Yeah he's right

[twilit jetty]

oooh i

[rustic wedge]

It's 12.4

[twilit jetty]

okok i see why i was looking at it the wrong way

hb this

[rustic wedge]

I believe it's correct

[fresh star]

wdym, how is that a positive correlation

[twilit jetty]

it goes in a straight line tho-

[fresh star]

a correlation means that it goes in a straight line

[rustic wedge]

If one decreases the other one decreases

[fresh star]

positive correlation means that

[twilit jetty]

Ooooh

[fresh star]

pretty sure temperature is increasing?

[rustic wedge]

No, both are decreasing

[twilit jetty]

wait here look

[rustic wedge]

Ohhhh

[tulip coyote]

but here we have that as one decreases, the other increases, no?

[fresh star]

how is this decreasing

[rustic wedge]

Wait shit i got confused

[rustic wedge]

Accidents happen

[fresh star]

words you do not want to hear your pilot say

[rustic wedge]

Lol

[twilit jetty]

💀

[fresh star]

@twilit jetty anyway, so yh, correlation just means that there is a pattern, negative means that it goes down, and postive means that it goes up

[twilit jetty]

i didnt put negative tho

[twilit jetty]

👌

[fresh star]

you should

[twilit jetty]

ooh

so B

right?

[twilit jetty]

.

[fresh star]

yh

[twilit jetty]

hb the other problem?

[fresh star]

youre wrong

how did you get 4

[twilit jetty]

it goes +4

or is it 8?

is this right?

[fresh star]

what @twilit jetty?

why

would you do that

put your red dot

on the line itself

[twilit jetty]

💀 my b

16

[fresh star]

legit you just put it in some random place

[twilit jetty]

😭

forgot it had to be within the line

so its 16

[fresh star]

yh

[twilit jetty]

u up for one more?

im not sure on this one-

[fresh star]

what is the sqrt(8)

like you dont need to know the exact number

but generally

[twilit jetty]

ik what the sqrtis but what r u asking?

[fresh star]

i am literally asking

what is the number

[twilit jetty]

oh

u said i dont need to know the exact number

wdym

[fresh star]

its a number

with infinite decimels

[twilit jetty]

(im very slow in math bare with me lmao)

[fresh star]

you dont need to know all of them

well you cant anyway

[twilit jetty]

ohh ye

[fresh star]

but you just need to know the first 2 decimels

[twilit jetty]

2.82?

[fresh star]

yh

so where is 2.82

in the number line

[twilit jetty]

would be around here

?

like 2.8,2.81,2.82

[fresh star]

yh

[twilit jetty]

near Y

[fresh star]

so which option

suits that

[twilit jetty]

D?

[fresh star]

yh

[twilit jetty]

hb this

[fresh star]

how did you get 200

[twilit jetty]

im not sure- i took a break from the hw yesterday so

uh lemme redo it one sec

uh i gtg rq

ill come back if i cant solve it later

were going somewhere

.close

[final saddle]

Channel closed

Closed by @twilit jetty

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stray stump]

Why is P(B|R) not good?

You get 1/3 so a different answer

[final saddle]

@stray stump Has your question been resolved?

Channel closed

Closed by @stray stump

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dry light]

Ok what about g

[signal gust]

Let f(x) = x2 what’s the transition between f(x)and g(x)in each of the following?

This is the question above it

[dry light]

Graph them if you need a visual

[signal gust]

How would I?

Nvm'

[final saddle]

@signal gust Has your question been resolved?

Channel closed

Closed by @signal gust

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unique fox]

What is a good learning resource to solve this task?

[unique fox]

I dont really know where to start

[final saddle]

@unique fox Has your question been resolved?

Channel closed

Closed by @unique fox

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz cove]

I keep ending up with 2sinx=cos, for part a. But im not sure how to do proceed with it without calculator. Did I do it wrong, I tried to find the derivative, and then I set it to 0

[soft zealot]

Mortta
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[void valley]

it seems right

now just solve it, you can use fact that 2sinx = cosx ---> tanx = 1/2

[topaz cove]

ok thx

.close

[final saddle]

Channel closed

Closed by @topaz cove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final saddle]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal gazelle]

Hi im not sure how to do this question

[void valley]

apply ln (.) both sides in the 1st one

then you'll get simultaneous system of equations, solve it and plug (x,y) into e^x + e^y

[crystal gazelle]

so x + y = ln12

im not sure what u mean by plug in (x,y) though?

[void valley]

solve the system for x and y

[ocean lintel]

Btw here it's faster to make it a system in e^x and e^y if you know what you're doing

[crystal gazelle]

i have no idea what im doing

but is it 6?

@void valley ?

[ocean lintel]

Don't think so

e^x e^y = 12
e^x / e^y = 3

[crystal gazelle]

huh

[final saddle]

@crystal gazelle Has your question been resolved?

[ocean lintel]

when you know x+y and x-y, you know x and y because
x = 1/2 ((x+y) + (x-y))
y = 1/2 ((x+y) - (x-y))
That's Modus's solution

But there's a multiplicative equivalent;
If xy and x/y are known
x = sqrt(xy * x/y)
y = sqrt(xy / (x/y))

This is the more unusual method I pointed out

[ocean lintel]

With X = e^x, Y = e^y

[final saddle]

@crystal gazelle Has your question been resolved?

Channel closed

Closed by @crystal gazelle

Use .reopen if this was a mistake.

[final saddle]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby bone]

How do I show the line 3x+y-4=0 cuts the parabola x^2+5x+3 at 2 points

[ruby bone]

I know I'll need to do simultaneous equations

I have y=-3x+4 for the line but I'm not sure where to go from here

[tranquil pine]

When two curves intersect at some point (x1, y1), what can you say about (x1, y1) and the two formulas of the curves?

[ruby bone]

Im not sure

I never really learnt how to graph lines and parabolas

Im not sure if thats really relevant

[tranquil pine]

Ok, forget this question.

Suppose I tell you that the point (x1, y1) lies on the line 3x + y -4 = 0.
What can you say about x1 and y1?

[tranquil pine]

That's not needed per se for this

[ruby bone]

Y is -4 and x is 3

?

[tranquil pine]

Bruh

How did you get to that?

[ruby bone]

Honestly have no clue

[tranquil pine]

Ok, let's start with even more fundamental stuff.

Consider the line y = x + 2

Do you know how this line looks on the graph?

[ruby bone]

No, sorry

Im looking at desmos

Both intersect points are 2 and -2

[tranquil pine]

Ok. Forget that.
When we say that " y = x + 2" represents a line, what we are saying is this:
"Consider all pairs (x1, y1) which satisfy the equation "y = x + 2". Mark each of those points on the graph. There will be infinitely many pairs of points which satisfy this equation, line (0, 2), (1, 3), (2, 4), (100, 102), (1.5, 3.5) etc. All these points, when you look at them, will lie on a straight line. And that straight line is what we call "the line y = x + 2" "

So a curve represented by a formula, is just the set of all points which satisfy that formula

[ruby bone]

Right ok

[tranquil pine]

And so when you want the points of intersection of two curves, you want those points which satisfy both the formulas

So in your original problem, what you want, are the points (x, y) which satisfy both 3x+y-4=0 and y = x^2+5x+3. Forget the fact that they are a line and a parabloa. THink of them as just algebraic equations for now. So you just need to solve these two equations simultaneiously

[ruby bone]

Right

Well I know I can rearrange the first

X will be -3/4

And then you plug in x right

So y should be 25/4

Is this right so far

[tranquil pine]

no..

[ruby bone]

Im so lost

[tranquil pine]

Are you aware of solving linear equations in one variable?
ie can you solve 2x + 6 = 10 ?

[ruby bone]

Yes

[tranquil pine]

Tell me the answer

[ruby bone]

2

[tranquil pine]

Cool

Now, can you solve x + y = 10?

[ruby bone]

Yes

8

Y is 8

[tranquil pine]

x is?

[ruby bone]

2

[tranquil pine]

Ok, I agree that (2, 8) is a solution to the equation x + y = 10

But why not x = 3 and y = 7?

[ruby bone]

I thought we were using the same x

But I guess that's also possible

Not given a variable

[tranquil pine]

Same x as what?

There's only 1 equation here: x + y = 10. There's nothing else

[ruby bone]

The previous question

Right

So its any value that equals 10

1 abd 9, 2 abd 8, 3 and 7 etc

[tranquil pine]

Yes

So there is no single answer to "solve x + y = 10"

There are infinite pairs of (x, y) which satisfy that equation

[ruby bone]

Right

So what now

[tranquil pine]

Get back to this

Do you know how to solve quadratic equations?

[ruby bone]

Yes

[tranquil pine]

Ok. So you have these two equations:
y = -3x + 4
y = x^2 + 5x + 3

You need x1 and y1, which satisfy both of these equations simultaneously

So you can just equate them, and get

-3x + 4 = x^2 + 5x + 3

This is now a quadratic equation

Solve it

[ruby bone]

I've never dealt with one like that I dont think

Sorry if this is frustrating for you

But couldn't I plug the second equation into the quadratic formula

[tranquil pine]

You can rearrange this as
x^2 + 8x - 1 = 0

[ruby bone]

Right

So you sub the question into it

And then you can put that in the quadratic formula?

[tranquil pine]

Yeah

And see how many solutions that gives

0, 1 or 2

That's the number of intersection points

Anyway, my suggestion to you would be that you are attempting significantly harder problems without a good foundation.
You should first read up more on, and understand "Solving simultaneous equations", and "plotting graphs" before attempting these problems

[ruby bone]

Alright

Well I appreciate your help

[tranquil pine]

👍

[ruby bone]

.close

[final saddle]

Channel closed

Closed by @ruby bone

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid torrent]

help

[void crest]

what do u not get

whats ur working

[limpid torrent]

ik I have to set r = 0 to get reference angles

[tranquil pine]

Yes.

[limpid torrent]

which would be pi/6 and 5pi/6

but after that my logic would be to use those angles as the bounds so I believe it to be either B or D

i know the equation is 1/2 of the integral from pi/6 to 5pi/6 r^2 dtheta

that is why I chose B

is this correct?