#help-36

1 messages · Page 36 of 1

onyx sand
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the answer should be 9arctan(9x)

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i think its this step

supple mantle
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Yeah it has to be (9x)^2

onyx sand
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yeah

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and then all of it would flip

supple mantle
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Yep

onyx sand
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cool

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thanks

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cerulean relic
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Say we throw two fair die simultaneously, we keep on throwing until both die show the same number. We are interested in how many times we must throw until the die show the same number. The sample space of this experiment is $\Omega = {1, 2, 3, 4, .....} = \mathbb{N}$. What is the event space $\Euscript{F}$? Is it the power set or something else?

soft zealotBOT
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O2daP
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dusk pecan
final saddleBOT
dusk pecan
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Hi can someone help me with b)

ocean lintel
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Also do a piecewise function

dusk pecan
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ok

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domain and codomain will be reversed right?

ocean lintel
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Oh course, it's N -> Z

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wild venture
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wild venture
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How to solve this differential equation?

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Just the general mrthod no need to do the calculation. Or if someone knows how to find a solution id be grateful

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,w solve (1-t)^2y''-ty'+y=0 for t in (-1,1)

wild venture
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viral shoal
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P(X >= 2) = 2/3 P(X <= 2) find lambda of X ~ EXP(lambda)

viral shoal
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Process is completely wrong I know

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But I don’t see how to proceed otherwise

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@viral shoal Has your question been resolved?

viral shoal
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<@&286206848099549185>

viral shoal
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tranquil pine
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I have no idea on how to do this

final saddleBOT
rain compass
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did you graph them?

tranquil pine
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how do I

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I was never taught how to graph circles yet

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its in my next geometry class

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but i wanna be ahead

last acorn
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ok

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so

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circles have equations

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(x-a)² + (y-b)² = r²

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where (a,b) is the coordinate of the center of the circle

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and r the radius

supple mantle
rain compass
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consider plugging the equations into desmos

rain compass
last acorn
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computing that by yourself point per point is a pain

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and it's porbably useless

tranquil pine
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ok thanks

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wait so

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ohh

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thanks

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tame karma
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is this function integrable over [0,1]? i tried using the riemann criterion but didnt get anywhere

tame karma
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$f(x) = \begin{cases} x\ x\in\bQ\ -x\ x\in \bR\setminus\bQ\end{cases}$

soft zealotBOT
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CoolShot

neon wadi
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I think it's reasonable to guess that it is not Riemann integrable for the same reason the indicator function of the rationals is not

final saddleBOT
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@tame karma Has your question been resolved?

neon wadi
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It will be discontinuous at every irrational point as by the construction of the real numbers we can pick a sequence of rational numbers approaching that irrational number, and this shows that f is not continuous in any irrational point. As it is discontiuous on a set of positive measure, it can't be Riemann integrable. It is Lebesgue integrable with Lebesgue integral -1/2 as f(x)=-x a.e.

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eager stirrup
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is there a hint for this i could use?

final saddleBOT
eager stirrup
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when does the game end as well?

earnest temple
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presumably the game ends when there's only one pile, since at that point there are no more moves

eager stirrup
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that you could possibly give

final saddleBOT
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@eager stirrup Has your question been resolved?

eager stirrup
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anyone?

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is it parity?

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should i work backwards?

eager stirrup
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<@&286206848099549185>

tranquil pine
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Hmm

eager stirrup
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ill try to start with 10 piles

eager stirrup
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so i think the first player player will win

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since i assume optimal play means that each player adds the largest amount that is possible to make

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empty plaza
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Help

final saddleBOT
empty plaza
final saddleBOT
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@empty plaza Has your question been resolved?

empty plaza
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<@&286206848099549185>

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@empty plaza Has your question been resolved?

empty plaza
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.close

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tranquil pine
final saddleBOT
tranquil pine
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Quick question why is it that they choose the angle in blue instead of the angle in red

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Wouldn't it be the same answer?

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wait wait wait

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nvm

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oak kraken
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why does e^x remain the same with infinite derivatives?

amber holly
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By definition

oak kraken
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d/dx [e^x] = e^x

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But what is the definition exactly? What is going on

gritty solar
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3B1B has an excellent video on this

oak kraken
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OK

rancid prairie
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actually if you check its graph and calculate the derivative of each point it comes out to be e^x

amber holly
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There are several definitions

oak kraken
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What is e? And why are exponentials proportional to their own derivatives?
Help fund future projects: https://www.patreon.com/3blue1brown
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amber holly
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But one of them defined e to be a number such that d/dx (e^x) = e^x

oak kraken
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OK

gritty solar
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Generally the rate of change of an exponential is proportional to itself, and for the base e, this proportionality constant equals 1

amber holly
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That video covers the definition I mentioned

oak kraken
gritty solar
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Ikr

fresh star
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@oak kraken

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first principles

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shows you that youll get e^x

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its no different than x^2 going to 2x. or sin(x) going to cos(x)

amber holly
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(Note: Another definition of e says that it is the limit of (1 + h)^(1/h) as h -> 0, although the limit is usually written as (1 + 1/x)^x as x -> infinity)

gritty solar
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Because bank

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$$$

fresh star
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who uses the infinity version, its kinda impractical

amber holly
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Right

gritty solar
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And it has something to do with interest

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There's a Numberphile video on it I think

final saddleBOT
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feral veldt
#

Got a question about set theory, if I'm asked to give the intersection between 2 relations it's asking me to give the elements that are in both relations and not the pairs that are in both right?

nocturne peak
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so lets say you have to sets A and B
A = {1,2,3,4,5,6}
B = {2,4,6}

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and you want the intersection

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$A \cap B$

soft zealotBOT
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barış

nocturne peak
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lets call this C

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C contains all elements that are both in A and at the same time in B

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does that answer your question ?

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so in this case it would be C = {2,4,6}

feral veldt
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sorry I think I misphrased my question, let me write down an example

nocturne peak
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sure

feral veldt
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for example if I have
N = {1; 2; 3; 4}
R ⊂ N × N, R = {(1, 2); (2, 4)}
S ⊂ N × N, S = {(1, 2); (3, 4); (4, 4)}

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and now I want the intersection of R and S

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would it be for example K = {1, 2, 3, 4}?

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or K = {(1, 2)}

nocturne peak
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from my understanding you would wanna select the pairs

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since R and S are binary relations

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but I might be wrong

worldly vale
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Yeah you never change the "type" of the elements when taking an intersection

feral veldt
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so K = {(1, 2)} would be correct right?

nocturne peak
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imo ye

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yes

feral veldt
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okay thanks :)

nocturne peak
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nw

feral veldt
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tranquil pine
#

Prove that the medians of a triangle are concurrent?

final saddleBOT
#

Please don't occupy multiple help channels.

tranquil pine
tulip coyote
tranquil pine
tulip coyote
#

Thank you catThumbsUp

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carmine plaza
#

How do you solve a continuous exponential thing like
5^5^5^5^5

amber holly
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Are you curious about the order of operations here?

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midnight sparrow
#

can someone gives me a hint on this : find all couples (a; b) of strictly positive integers that satisfy the equation : $a^{b^{2}} = b^{a}$

soft zealotBOT
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phoestaclies

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@midnight sparrow Has your question been resolved?

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@midnight sparrow Has your question been resolved?

midnight sparrow
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<@&286206848099549185>

final saddleBOT
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@midnight sparrow Has your question been resolved?

loud sundial
midnight sparrow
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I didn't want the answer, but that should do the trick, I will look at partial solution ty

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modern sail
#

How do I find the zero of a quadratic function

modern sail
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Specifically f(x)=-4x^2-4x+24

supple mantle
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Hmm

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Have you heard of quadratic formula?

modern sail
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Yeah, but I haven’t learned it

supple mantle
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Well lemme show you a nice song that introduces you to it

modern sail
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It gave me a huge dcemal

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And gave me a very wrong answer

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oak kraken
final saddleBOT
oak kraken
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I'm using Product Rule, for the second line

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why do I need to differentiate twice for the third line? and add another (4) to the end?

magic sparrow
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because what is the derivative of f(g(x))

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in this case you have g(x)=4x+5 and f(x)=x^4

oak kraken
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oh, I see, I'm skipping a step, that's why I think I'm doing it twice

magic sparrow
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so f'(g(x)) * g'(x)

oak kraken
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I should really write it out as inside, outside d/dx

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that will help me to see what's going on

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instead of doing two d/dx on the same line

hybrid heath
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The practice will all pay off one day

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I expect to see avidrunner written in green one day

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tranquil pine
#

How do I selected the correct interval for each integral?

tranquil pine
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The integral of that is 1/4(x)^4-1/2(x)^2

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What do you mean equation? The function is there and the norm is what needs to be calculated

worldly vale
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What's f(x)?

tranquil pine
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That’s a typo, that f(x) should be a p(x)

worldly vale
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Okay, you need to figure out when f(x) is positive and when it is negative inside [-3,5]

tranquil pine
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Is it positive when it gives a result of 0?

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From bounds 5 to -1 the result is positive, then from -2 to -3 it gives negative values

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Since it goes negative as seen in the graph, the abs value acts on that integral and the result will be positive ?

worldly vale
vital crag
carmine plaza
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😂

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Sry I'm still in this channel whoops

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this is awkward

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could someone quickly explain that to me

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or i can go in a separate help channel again sry for inconvenience

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clever jetty
#

I’m not exactly sure how to start off, is it asking for the degree?

I thought originally thought that it was asking what the x intercept was but it’s asking how many it has and I’m not knowing how to execute it.

Do I find the y intercept first? I did that I think and I got 0 out of that. I just plugged in 0 for x and got 0 for the y intercept.

Would I now put 0 where f(x) is and try to solve from there?

clever jetty
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This is what I’ve done so far

feral terrace
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so x-intercepts are where y=0, and so you would set your expression equal to 0

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f(x) is just another way of saying y, so another way to write the problem is y = -5x^2 (x^2 - 3)

clever jetty
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So like this?

feral terrace
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mm i suggest that you leave it in the first form, it will be easier

clever jetty
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Ok

feral terrace
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when you have two things multiplied together and they equal to zero, do you agree one of them must be equal to zero?

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right now, you have 0 = (-5x^2)(x^2-3)

empty steppe
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Guys need help rn

clever jetty
empty steppe
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Can you answer it for me?

feral terrace
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in the problem, they are being multiplied to each other

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don't be confused by the negative sign in front of 5x^2

clever jetty
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Okay so one of them just needs to equal 0

feral terrace
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@empty steppe please open your own help forum

clever jetty
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Because any number times 0 is 0

feral terrace
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yes!

empty steppe
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How @feral terrace

feral terrace
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so individually, set each of them equal to 0 and then you get the x-intercepts

feral terrace
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go to this channel for directions

clever jetty
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Sorry I forgot to do the thing on the other 0

feral terrace
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why is there a square root?

clever jetty
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Cause the x’s are squared

feral terrace
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when you set each of them equal to zero, you don't have to square root them

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it would simply be -5x^2=0

clever jetty
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Ooooh ok

feral terrace
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and then x^2-3=0

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and then you solve each of them for x

clever jetty
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So it’s 0 and square root of 3?

feral terrace
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yup, don't forget plus and minus sqrt of 3

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when you square root a number, it's always plus and minus

clever jetty
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Ooooh okay

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So in total there’s 2 x intercepts which are 0 and square root of positive 3

feral terrace
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close, let me clarify what i mean by plus and minus

clever jetty
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Oh ok

feral terrace
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that means that your intercepts are 0, +sqrt(3), -sqrt(3)

clever jetty
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Wait why are there now three

feral terrace
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so then you square root both sides

clever jetty
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Yeah

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Would that separate it to one negative and one positive?

feral terrace
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when you square root the 3, you have to account for the negative and positive

clever jetty
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So it would be like this instead?

feral terrace
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yup!

clever jetty
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Oooog okay awesome that makes so much sense

feral terrace
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mmhm

clever jetty
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So the answer would be three x intercepts, 0, -sqrt3, and +sqrt 3

feral terrace
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yes!

clever jetty
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Omg thank you sm

#

This makes so much sense

feral terrace
#

no problem :)

#

happy to help

clever jetty
#

🫶🏻🫶🏻🫶🏻

#

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#
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wild depot
#

Hello, could anyone please help me solve this problem, (b only) Thanks.

magic gyro
#

maybe it would help to find the area of the top face first

final saddleBOT
#

@wild depot Has your question been resolved?

wild depot
#

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high kelp
final saddleBOT
high kelp
#

how do i know which trig substitution to use?

#

i know that sqrt(a^2+x^2) is let x = atan(theta)

#

but in my problem it's sqrt(x^2+a^2)

#

would it still be the same one?

#

i guess i do

craggy plume
#

let me have a look

high kelp
#

but now i'm stuck

craggy plume
#

pretty sure you just need to use tan^2 + 1 = sec^2

high kelp
#

i dont know how to simplify from there

#

i could pull the constant 19/9 out of the integral?

craggy plume
#

i'm a little unsure why you've just got your 19 on your numerator

high kelp
craggy plume
#

the substitution should put a sec^2(theta) there

#

ah

#

there you are

high kelp
#

i see the tan2(x)

#

bc that would cancel my denominator?

#

tan

#

and leave the sqrt?

craggy plume
#

why'd this go to +3 in the sqrt?

high kelp
#

oh bc

#

my sub is let x=atan(theta)

#

i replace x with that

#

and x=3tan(theta) in my original integral

#

but i'm not sure if i'm right on that part

craggy plume
#

you are but the reason you choose 3 as your a is because of what happens in the sqrt

high kelp
#

right

#

what are u implying though?

#

i'm not quite following through

craggy plume
#

i got this with my atan(theta) substitution

high kelp
#

whered ur 19 go?

craggy plume
#

take it out

#

its a constant

#

this is all 19* the integral

#

and the 19 has no bearing on what we choose

high kelp
#

confused how u got +9 in the sqrt

craggy plume
#

the x^2 in the sqrt --> a^2tan^2(theta)

high kelp
#

wait i did an error

craggy plume
#

the +9 stays

high kelp
#

i wrote down +9

#

and my 9 looked like an a.....

#

.-.

#

right

craggy plume
#

thats what i figured

high kelp
#

i seee now

craggy plume
#

but wasn't 100%

high kelp
#

and now my sqrt just becomes

craggy plume
#

if you ignore that though the logic is very close to where we are

#

what do we want a^2tan^2(theta) + 9 to turn into?

#

to easily cancel out the sqrt

high kelp
#

uh

#

dont we evaluate the sqrt?

#

and use a trig identity

craggy plume
#

we can use a trig identity to make a^2tan^2(theta) + 9 just (something)^squared

#

which will just evaluate to (something) after we sqrt it

high kelp
#

what would the something be?

#

i'm not seeing that part

craggy plume
high kelp
#

this is where i get stuck in the integrals

#

oh right

craggy plume
#

we have +9

#

so

#

if a=3, for instance

#

9tan^2(tehta) + 9 = 9sec^2(theta)

high kelp
#

multiply by

craggy plume
#

which cancels out nicely

high kelp
#

9

#

yeah

#

i pulled out my constants (a)tho

#

so i can just directly plug in the identity?

high kelp
craggy plume
#

this is all i did to get to what i showed you

#

with a = 3 you'd get uhh

#

which should be a known integral?

#

oh, sorry

#

that turns into sec not sec^2

#

just a sec

#

wow, i'm rushing through steps a bit

high kelp
#

ohhh

craggy plume
#

forgot to write the 1/9 on the outside

#

imagine that there o_o

high kelp
#

so i guess my work on the problem is sort of in the wrong direction

craggy plume
#

i think the idea of this question is

#

'what substitution would help me break through the square root simply?'

#

and as shown, a=3 and tan let you use that sec identity

#

to solve it from where i got you'd just do another substitution

high kelp
#

now watch me forget all of this within the next 10mins 😄

#

then from here i'd use soh cah toa?

#

to convert theta into x ?

craggy plume
#

not yet uh

#

just hang on

#

the outside fraction should just be 19/9 i think?

high kelp
#

ya if we simplify by 3

craggy plume
#

howd you get a big 57 there

high kelp
#

i removed the 3 as a constant

craggy plume
#

well despite that one line having a weird fraciton yeah sure 57/27 = 19/9

#

oh you just

#

didnt do it all at once

#

okay sure

high kelp
#

yeah

#

baby steps or i get confused

craggy plume
#

that aside

high kelp
craggy plume
#

(nw lmao)

#

you dont want to un-substitute just yet

high kelp
#

o power reducing formula..

#

on the sin^2(x)?

craggy plume
#

if i just said

#

'hey, how would you evaluate this'

#

what would you do?

high kelp
#

power reducing formula

#

sin^2(x) = (1-cos(2x))/2

craggy plume
#

unfortunately you cant really go anywhere from there

high kelp
#

hmmm

craggy plume
#

i'll give you a hint

high kelp
#

last section was trig integrals

#

where we replace a trig function + dx

#

into du

craggy plume
#

what happens to sin when we differentiate it

high kelp
#

a single sin turns into

#

-cos(x) + c

craggy plume
#

thats integration

high kelp
#

o sorry

craggy plume
#

differentiation would just be d/dx(sinx) = cosx

high kelp
#

cosx

#

yes

craggy plume
#

so

#

if we said x=sinu as a substitution

#

du/dx = cosu

high kelp
#

cos(u)/u^2 du

craggy plume
#

=> du = 1/cos(u) * dx

high kelp
#

let me write this on paper

#

hold on

high kelp
craggy plume
#

yep

#

which is real easy

high kelp
#

u^(-2)du

craggy plume
#

=> integrates to -u^(-1) = -1/u

= -1/sin(x)

high kelp
#

19/9 * -(1/u^1)

craggy plume
#

well forget the constant for now

#

the idea is 'using substitution, we can solve the integration of cosx/sin^2(x)

#

so we can apply this within our original substitution

high kelp
#

i see

#

now soh cah toa for sin?

craggy plume
#

well

#

now you'd undo the theta substitution

high kelp
#

to get it in terms of x right

craggy plume
#

theta = arctan(x/3)

#

sin (arctan(x/3))

#

which has a known idetntiy iirc

#

or rather sin(arctan(x)) does

high kelp
#

we cant use this?

craggy plume
#

its been a while since ive used a method that wasnt known values

#

lmk what you get with that method

high kelp
#

(-19sqrt(9+x^2))/9x

#

@craggy plume

#

+c

#

o.o

#

@craggy plume tysm for the help!!!

#

and for being patient w me

craggy plume
#

👍 nw

high kelp
#

these problems scare me

craggy plume
#

not too used with evaluating arctans and such so you got me beat there and all lol

high kelp
#

lmao the prof showed us

craggy plume
#

this question required pretty abstract applications of substitution

high kelp
#

yeah...

#

trig sub.. then u sub

craggy plume
#

also yeah its one of the only times ived subbed within a sub lmao

#

try and make sure you really get why you do especially that trig sub

#

and how to spot similar subs in the future

high kelp
#

how did u instantly recongize it was a u sub?

#

i didnt really catch it until u mentioned it

craggy plume
#

for this one,

#

idea: it would be beneficial if this was just -one- trig function

#

can you get rid of 'cosx'?

#

yes, u=sinx means we divide by cosx during the substitution

#

is my mental process

craggy plume
high kelp
#

ohhh i see

craggy plume
#

we can just do the u substitution

high kelp
#

so u worked the math in advance

#

and saw that derv of sin is cos

#

meaning u can u sub to cancel it out

craggy plume
#

yes

high kelp
#

that makes sense

craggy plume
#

that is how you pick a good substitution

#

see how it affects the dx when you sub in du

#

and try and pick a u that simplifies your expression down

#

it does just like

#

take an annoying amount of practice though

high kelp
#

🫠

#

it does

craggy plume
#

calc does kind of suck 💀

high kelp
#

i failed my last exam

#

💀

#

need to do good on this one

craggy plume
#

at least you're asking for help in the right places

#

wish you good luck, im gonna head off for now and stare at my own math ☠️

high kelp
#

lmao np

#

ty once again!

#

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#
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final saddleBOT
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golden birch
#

this triangle contains 6 cyclic quadrilaterals

golden birch
#

i was only able to find BDEH and CDEH and AEFH

#

any hints?

midnight sparrow
#

H is the orthocenter here ?

golden birch
#

yes

#

oh forgot to mention it

midnight sparrow
#

If it is you have a lots of right angle

golden birch
#

yea

#

but i think there are only 3 cyclic quadrilaterals which contain H as vertex

#

and for example

midnight sparrow
#

So do you know some properties with right angle and cocyclique points

golden birch
#

not really

#

or maybe

#

not sure

#

wait ill look it up what that is

#

and tell you if i know

midnight sparrow
#

like if I take HC I have 2 triangle with right angle

#

yes take your time

golden birch
#

ah yes

midnight sparrow
#

and show your work after 🙂

golden birch
#

since HDC = HEC = 90

midnight sparrow
#

ok and so what can we conclude about points HDCE

golden birch
#

which are not next to each other

midnight sparrow
#

yes great with the diameter HC

#

ok we have 1

#

do you see more like this

golden birch
#

BDFH

#

AFHE

#

thats what i was able to do but i cant find more

midnight sparrow
#

yes

golden birch
#

there are six cyclic quadrilaterals with vertices in
{A, B, C, D, E, F, H}.

#

forgot to mention this with the vertices

midnight sparrow
#

ok we can use this right angle in a different way

#

do you see something with AEB and ADB

golden birch
#

one sec

#

both are right

midnight sparrow
#

yes

#

and they are link to what side

golden birch
#

what do you mean by link to side?

#

(sry i dont know some names in english)

midnight sparrow
#

like we have the right angle in E and D but what is the hypothenuse

golden birch
#

like the line DE?

#

ah

midnight sparrow
#

yes sorry my english's bad too

golden birch
#

for E

midnight sparrow
#

t ?

golden birch
#

AB or AH?

midnight sparrow
#

yes for AB but no for AH

#

do you see the two right triangle

#

what is their name

golden birch
#

do you mean AEB and ABD?

midnight sparrow
#

yes this are the right triangles, so what is their hypothenuse

golden birch
#

AB for AEB and AB for ABD

#

the same

midnight sparrow
#

ok so they have AB in common, can we conclude something

golden birch
#

AB has to be a side of the quadrilateral then ?

midnight sparrow
#

yes, we can also say that AB is the diameter of a circle in which E and D pass

golden birch
#

oh

midnight sparrow
#

so A,B,D and E are cocyclique

golden birch
#

so ABDE?

#

oh

#

ah

#

i think i understodd it

midnight sparrow
#

yes it's the same properties as before

golden birch
#

since they both lay on the same circle

midnight sparrow
#

but before the two triangles were opposite on the diameter

#

here it's on the same arc

golden birch
#

ah

#

ah

#

so if i have 2 right triangles with the same hypotenuse, the quadrilateral of the 4 points is cyclic right?

midnight sparrow
#

yes

#

and the hypothenuse is the diameter of the circle

edgy path
#

oi gente

#

tudo bem?

#

eu sou do brasil galera

#

prazer Gabs

midnight sparrow
#

not here @edgy path

edgy path
#

aonde então?

midnight sparrow
#

if you want to get help go to another channel

edgy path
#

eu não tenho um canal para matematica

edgy path
midnight sparrow
golden birch
edgy path
#

eu não falar em ingles cara

#

2 trangulos

midnight sparrow
#

<@&268886789983436800>

edgy path
#

whats happened

midnight sparrow
#

don't understand pls talk in english

edgy path
golden birch
#

like

midnight sparrow
#

sorry Affe

edgy path
#

a mano..

#

a classificação esta em 2x2

#

2x2=4

golden birch
#

ty

edgy path
#

10$ Questions

golden birch
#

you did nothing wrong

edgy path
#

ué mano

midnight sparrow
golden birch
edgy path
#

A hipótese de Riemann foi proposta pela primeira vez por Bernhard Riemann em 1859. A teoria afirma que a distribuição de números primos não é aleatória (como é classificada), mas pode seguir um padrão descrito por uma equação chamada "função zeta de Riemann".

midnight sparrow
#

<@&268886789983436800>

edgy path
#

Is it mandatory to speak in English?

midnight sparrow
golden birch
#

and then ABCD should be cyclic

edgy path
edgy path
#

se soubesse falaria

midnight sparrow
#

yes it's that

golden birch
#

oh ok ty

edgy path
golden birch
#

❤️

edgy path
#

eu estou perguntando como faz os calculos = I'm asking how to do the calculations

#

oi como você esta? = Hi how are you

Aula de portugues para você = Portuguese class for you

#

aprendeu?

midnight sparrow
#

don't know where is the moderators but please come opencry

golden birch
edgy path
#

............

edgy path
midnight sparrow
#

use .close if you have finished

edgy path
#

i don't speak english

golden birch
#

.close

final saddleBOT
#
Channel closed

Closed by @golden birch

Use .reopen if this was a mistake.

edgy path
#

account

edgy path
final saddleBOT
#
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edgy path
# golden birch

i really work, but i'm taking english classes in los angeles

edgy path
#

aeee

#

ativict

#

I'm taking classes and working in the studio, don't blame me for not learning English since I was a child.

#

and series That Girly lay lay, Danger force

final saddleBOT
#

@edgy path Has your question been resolved?

final saddleBOT
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tranquil pine
final saddleBOT
tranquil pine
#

answer key is wrong, right?

#

can any1 confirm?

#

Send your work

tranquil pine
#

No

#

Show your work

soft zealotBOT
tranquil pine
#

I can't

#

.close

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oak kraken
final saddleBOT
oak kraken
#

when you see log_a(b), do you automatically visualize it as an exponent? full stop

tired walrus
#

not with such an absolutist attitude you don't.

oak kraken
#

it doesn't matter what the log base is (aside from 1 or 0), or what the log argument is (aside from negatives and 0)

oak kraken
tired walrus
#

you think there is something sacred about the letter x...?

oak kraken
#

like an exponent turned inside out, kinda?

tired walrus
#

you bring up the x in log_a(b) = x as if it holds some kind of sacred meaning which you consider a trigger to Visualize The Logarithm As An Exponent, Full Stop™️

oak kraken
#

yes

#

that's literally what log_a(b) means

#

or = c

#

doesn't need to be x

ruby bramble
#

what are you even trying to show here?

tired walrus
#

so there is in fact no sacred meaning to the letter x specifically, despite your claim.

#

you are being inconsistent here.

oak kraken
#

just trying to get a feel for how to visualize logs, whenever they come up in weird places

oak kraken
tired walrus
#

no, i meant that you could not give a consistent answer to whether there was something sacred about the letter x.

oak kraken
#

isn't that the idea of a variable? it can hold any value

tired walrus
#

which you first made it seem like there was, but then it wasn't.

oak kraken
#

I don't follow?

tired walrus
#

i tried to ask you: is there something sacred about the letter x? [as opposed to any other letter]

#

you said yes

oak kraken
#

should I have written it
log_a(b) = c?

tired walrus
#

and then, in the same breath, said "it doesn't need to be x"

tired walrus
oak kraken
ruby bramble
tired walrus
#

this one of your overthinking trains again?

#

log_a(b) is log_a(b).
if you want to "visualize" it, you could think of it as the answer to "a to what power gives b?"

#

which can help put some log laws on solid ground.

oak kraken
# tired walrus

"yes" is only one word, from everything else that I wrote afterwards

oak kraken
tired walrus
#

okay, whatever, neither you nor i want to pursue that line of interrogation further.

tired walrus
#

maybe if you gave us some actual problems you've encountered we could see what can be done with those

#

but it is probably a matter of symbol-pushing more than it is a matter of any visuals

oak kraken
worldly vale
#

Should we always view "2" as an exponent because it appears as an exponent in 2² = 4?

ruby bramble
worldly vale
oak kraken
#

the superscript is the exponent

tired walrus
# oak kraken

yeah, ok, those don't sound like "weird" places, but this also looks like something that doesn't require any fancy "visual" shit to comprehend.

tranquil pine
oak kraken
#

I am getting crapped on right now haha

tranquil pine
#

it tests ur knowledge on logs and exponents

ruby bramble
#

u do know properties of log right?

tranquil pine
#

^

#

do u know what else u can write "3" as?

oak kraken
worldly vale
tired walrus
ruby bramble
oak kraken
#

Now I just find, 3 to the 3rd power equals (3x/x^5)?

tired walrus
#

well, answer your own question

#

3 to what power equals 3?

oak kraken
#

wrote that wrong

#

fixed it now

tired walrus
#

no, you were actually on the right track.

oak kraken
#

so 3x/x^5 has to equal 27?

tired walrus
#

ah, no.

ruby bramble
tired walrus
#

hold on,

#

fuck now i've gotten my shit confused.

tired walrus
oak kraken
#

I mean 27

tired walrus
#

oh yeah

#

so every time you say 9 we should be treating that as 27

#

i wonder if that also applies to you saying 8+1 or something

ruby bramble
#

so 1/x^4 = 3^2

oak kraken
#

I feel like I am doing this wrong

#

for this question:

tired walrus
#

well, you're taking a bit of a roundabout route.

#

for one, you're for some reason refusing to simplify x/x^5 into x^4.

#

for two, you're for some reason refusing to divide out by 3 to have less numbers to deal with.

#

and for three, you're for some reason refusing to put a stroke through your sevens like normal people do.

oak kraken
ruby bramble
oak kraken
tired walrus
#

yes, sorry. typo.

#

or 1/x^4, whatever.

tranquil pine
#

ok np

tired walrus
#

that sad little hook of yours is very easy to mistake for a 1.

oak kraken
tranquil pine
ruby bramble
tired walrus
oak kraken
#

i dunno if I would mistake this for a 21

#

maybe the top could be a bit more straight

ruby bramble
#

draw a straight line for 1

tranquil pine
tired walrus
#

straight line for 1?

ruby bramble
#

yes

tranquil pine
#

yes

tired walrus
#

y'all gonna suffer with absolute value bars.

ruby bramble
#

|

oak kraken
#

the top of the 7 could be more straight instead of sloped

ruby bramble
#

i make them much taller

tranquil pine
oak kraken
#

I do my ones with a very small hook at the top, usually

tranquil pine
#

and I switch to the normal 1 when I do absolute values anyways

tired walrus
#

sevens should still be crossed imo

ruby bramble
#

na

tranquil pine
#

nope

#

why waste ur time with a cross

oak kraken
#

aside from computers, do you see anybody write 0 with the slash?

#

just curious

tranquil pine
#

I would rather do this tbh

tranquil pine
neat prawn
oak kraken
#

0 with slash feels too similar to theta

tired walrus
tired walrus
#

the correct way to write phi is $\varphi$

soft zealotBOT
tired walrus
#

and for $\theta$ you should have the line go clearly as a horizontal

soft zealotBOT
tranquil pine
#

$\phi$

soft zealotBOT
ruby bramble
tranquil pine
oak kraken
#

but 0 and O can get confused sometimes, without the slash
1 and | as well... and l

tired walrus
#

the what now

neat prawn
tired walrus
#

no, the symbol for partial derivatives is $\partial$

soft zealotBOT
tired walrus
tranquil pine
#

oh they look similar

tired walrus
#

do they now

tranquil pine
#

yeah

tired walrus
#

they look nothing alike in my book

#

one goes below the baseline while the other goes above

#

i guess they both have a loopy part but thats about it...?

oak kraken
#

lmao this got way off the rails from the comment about 7 could use a slash. i think I will just make a point to make sure my 7 has a straight line at the top

tired walrus
#

∂ is basically lowercase russian д, or one of the two ways of handwriting it that is common

neat prawn
#

this is bad

ruby bramble
#

^

#

kinda inhumane too

oak kraken
tired walrus
#

i also think the best way to write nines is from the bottom upward, perhaps starting a little bit below the baseline for extra flair, but i'm not that particular on that one, only enough to write them that way myself.

oak kraken
#

I almost always write from the bottom to the top, people comment on it, abnormal but they say they also like it

neat prawn
tired walrus
#

how the hell do you write g that it gets confused with that

oak kraken
#

I think my favourite for really really good writing is Krista King

neat prawn
#

standard g basically

tired walrus
#

the way i've always written g, there's a clear bend to it, which the nine lacks.

oak kraken
#

I'm not sure what writing software she is using, but the lines are always so clean
https://youtu.be/T-J7SkiE39Y

► My Integrals course: https://www.kristakingmath.com/integrals-course

The fundamental theorem of calculus is the most important theorem in all of calculus because it's the one theorem that shows a relationship between the derivative and the integral. Since the derivative and the integral are the two main parts of calculus, the fundamental theo...

▶ Play video
neat prawn
# tired walrus

I don't always pay that much attention to detail when writing a nine .... sometimes my 9 gets more curled up

tired walrus
#

one particularly bad sin i've seen people commit handwriting-wise is drawing 8 as two circles superposed.

oak kraken
# tired walrus

professors can be particularly bad with this one. is it a 9 or a g?

tired walrus
#

that's a 9, followed by two g's.

#

written once with the self-intersection and once without.

oak kraken
#

but when they write it I have no clue

tired walrus
#

well, at least i have the luxury of having graph paper and a clear baseline to follow lmao

oak kraken
#

hopefully I can get to that level of mastery, writing very good, with or without lines, perfect legibility every time, Krista King is the best imo

#

because this is just torture...

#

I don't even know why they upload this crap

#

can't see shit

neat prawn
#

that's good handwriting

neat prawn
# oak kraken

this much amount of beauty was not supposed to exist in our dimension

#

Is that a gamma(x), can't really understand, horrible resolution/handwriting

oak kraken
#

potato microphone too

#

.close

final saddleBOT
#
Channel closed

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#
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Show your work, and if possible, explain where you are stuck.
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sharp estuary
final saddleBOT
sharp estuary
#

How do i calculate this

#

I got the average by .2550+.1580+.05*200 =34.5

#

Oh

dry light
#

Post-work clarity?

sharp estuary
#

I got the average by .25×50+.15×80+.05×200 =34.5

sharp estuary
dry light
#

Nvm

sharp estuary
#

They want √(s^2)

#

And i thought u just do √(50-34.5)^2×0.25+(80-34.5)^2×0.15+(200-34.5)^2×0.05)

#

But wrong answer (41.71)

#

@dry light dont give me a cryptic question and then leave :c

dry light
#

I thought you did your work and realized your mistake, when I saw the "oh"

#

I also legit have to go rn

sharp estuary
#

Okok

#

Can anyone else spot the mistake?

uncut mulch
#

You forgot to include the 55% of getting 0€

sharp estuary
#

34.5 is the right mean ?

uncut mulch
#

Yes

sharp estuary
#

Did i misscalculate?

uncut mulch
#

Yeah

#

Show your work

sharp estuary
#

We r only allowes to use one line calculators

uncut mulch
#

Is this for a test?

sharp estuary
#

Yea i train w the shit calculator

uncut mulch
#

I'm sorry, but we're not allowed to give out help for tests.

sharp estuary
#

Its not a test

#

Its the old midterms we train with

uncut mulch
#

Okay, gotcha

sharp estuary
#

Otherwise i would be sweating in a teat hall rn not on discord

#

Test*

uncut mulch
sharp estuary
#

Ok i spotted the error it was a shitty calculator problem

#

Other thing

#

1.Are the given mean, variance and covariance even relevant for the task
2. what does the task even want to find out, i know it wants to draw a line most fitted to something but idk if fitted to bitcoin or etherium or how it plays together
3. how did u figure out which one is correct

#

@uncut mulch if you dont know i have an easier one

final saddleBOT
#

@sharp estuary Has your question been resolved?

final saddleBOT
#

@sharp estuary Has your question been resolved?

final saddleBOT
#
Channel closed

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final saddleBOT
#
Available help channel!

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winged drum
final saddleBOT
#

Please don't occupy multiple help channels.

winged drum
#

Can someone help me with #8

#

.close

final saddleBOT
#
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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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languid adder
#

how do u put this into exponential form ln4=1.39

languid adder
#

ln is natural log btw

modest birch
#

try doing e^ to both sides

languid adder
#

uhhh

#

wdym

#

lne⁴=lne^¹.39

modest birch
#

no idea what that is doing

#

you have to do the same thing to both sides of the equation

languid adder
#

can u show me

modest birch
#

no

#

because then you wouldn't have to think about it

languid adder
#

true

#

ok so

#

ur telling me to raise those numbers to e

modest birch
#

no

#

I'm saying raise e to those numbers

#

if you have thing 1 = thing 2

#

then e^(thing 1) = e^(thing 2)

grim badger
#

Pretty much apply the last rule

#

e is the base

languid adder
#

b is the base

#

right?

#

in the pic

grim badger
#

Yes

#

But Saccharine is saying do e^ on both sides

languid adder
#

sooo

#

is that wrong?

grim badger
#

So e is the base

languid adder
#

yea

#

soo

#

e⁴=e^1.39

#

right?

grim badger
#

No

#

The left side is wrong

languid adder
#

hmmmm

grim badger
#

ln is the same as log base e

languid adder
#

yea

grim badger
#

You're just left with the inside part

languid adder
#

im not sure

#

i applied the 7th rule

#

and got e^(logbase e of 4) = 1.39

grim badger
#

e^(logbase e gets canceled, if you look at the 7th rule

#

All you end up with is k, which is the inside

final tangle
#

you can't just raise e to the left and set it equal to the right

languid adder
#

yea