the candy bar
#help-36
ionic tulip
well is this for like a math question where you want to find the right answer or are you just drawing something and want to know how to make it accurate?
languid adder
yea
the label has to be accurate
do u understand my question lol?
it is 3d
just realized
ionic tulip
yea im kinda confused
languid adder
ok
ionic tulip
i have an idea but im not sure if what im thinking is the same as what you are thinking
mental kernel
final saddleBOT
robust mulch
what is the question?
ancient thistle
Find the value of n?
robust mulch
first thing you should do is multiply the numerator in the second term
mental kernel
huh
robust mulch
im here :I
mental kernel
idk what to do
robust mulch
do you know how to do foil?
robust mulch
this thing
robust mulch
you have $\frac{n^2-1}{n}$ which you can split into $\frac{n^2}{n}-\frac{1}{n}$
soft zealotBOT
GarlicBredFries
robust mulch
you can simplify the first term
robust mulch
ok thats a start
robust mulch
$\frac{n^2}{n}=?$
soft zealotBOT
GarlicBredFries
mental kernel
n
robust mulch
and you end with
mental kernel
-1
final saddleBOT
Available help channel!
nocturne peak
I have a question about SVD
final saddleBOT
I have a question about SVD
nocturne peak
given the SVD of a general quadratic matrix A
a) True
b) False
c) False
now my question is why. For c) I said this would only be true if sigma_i was an eigenvalue but in general sigma_i is not an eigenvalue of A
so its false
but for a) and b) I have no clue, maybe someone can explain to me how one could conclude these answers
I know that sigma_i is the eigenvalue for A^T A
So I could look at
$A^{T} A v_{i} = A^{T} \sigma_{i} u_{i}$
soft zealotBOT
barış
nocturne peak
but I couldnt draw any conclusion from that
final saddleBOT
@nocturne peak Has your question been resolved?
nocturne peak
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potent forge
I've calculated the volume of A to be 54,000*pi, I know the volume of B is pi*r^2*h, but I don't get the next step?
final saddleBOT
I've calculated the volume of A to be 54,000*pi, I know the volume of B is pi\*r...
potent forge
I know I'm supposed to rearrange the formula of pi*r^2*2r=54,000*pi, but how do I actually do that?
final saddleBOT
@potent forge Has your question been resolved?
final saddleBOT
@potent forge Has your question been resolved?
potent forge
no
final saddleBOT
@potent forge Has your question been resolved?
final saddleBOT
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Available help channel!
orchid crystal
3 and 5 for that status thingy
final saddleBOT
3 and 5 for that status thingy
soft zealotBOT
Darth Vader
ocean lintel
you evaluate the limit for half of the expression when you use that result
orchid crystal
Didn't they essentially do the same
ocean lintel
this isn't allowed, because lim of product = product of lim only if all things are defined and finite
which 1/t² isn't when t -> 0
ocean lintel
except they can legitimately split it as (numerator / t^4) and 1/ (sin² t / t²)
and both have a limit
orchid crystal
oh
The numerator also -> 0
If the numerator was some constant
Say 1
Then theirs would be wrong too?
But with the numerator and t^4 in denominator it becomes a completely different expression (0/0) which actually has a limit?
Yes?
ocean lintel
it doesn't lead to an undefined form so it would still work as inf*1 = inf
ocean lintel
this isn't allowed, because lim of product = product of lim only if all things a...
you probably saw in class when this holds
orchid crystal
I did
ocean lintel
what did it say ?
orchid crystal
if f and g are two functions such that lim x -> c f(x) = a and lim x -> c g(x) = b
Then lim x -> c fg(x) = ab
However the converse is not generally true
This is what you mean?
ocean lintel
they said it holds for finite limits
orchid crystal
yes
a and b are finite
So in my work I'd do (1/t)^2 * (t^2/sin^2(t)) so one of them is infinite (1/t^2) so it does work
But in their work too hey have (sin^2(t) - t^2)/(t^4) * the other term
So here it works because the first term I have is actually finite?
ocean lintel
then yes
ocean lintel
if f and g are two functions such that lim x -> c f(x) = a and lim x -> c g(x) =...
this holds more generally if it doesn't lead to an undefined form
which in this case would be 0*inf
orchid crystal
I see
orchid crystal
But in their work too hey have (sin^2(t) - t^2)/(t^4) * the other term
So here ...
is that right
ocean lintel
"here" would be their solution imo, so since you then say "I" I'm not sure what you're talking about
orchid crystal
You're right
Let me rephrase
In their work, solely the second solution mentioned above
there's (sin^2(t) - t^2)/t^4
Times the second term
Here it is allowed to individually calculate those limits because this first term is actually a finite quantity
Yes?
ocean lintel
this holds more generally if it doesn't lead to an undefined form
you can always "isolate" a nonzero finite limit
ivory adder
How to evaluate the limit $x\to 0(\frac{e^{x} - 1}{x})^{\frac{1}{x}}$
tired walrus
$\lim_{x \to 0} \left( \frac{e^x - 1}{x}\right)^{1/x}$
soft zealotBOT
Ann
ivory adder
Yes
tired walrus
take the log of the function, to get 1/x * log( (e^x-1)/x )
you will of course take the exponential of the result at the very end
but in the mean time, write log( (e^x - 1)/x ) as log( 1 + (e^x - 1 - x)/x )
then expand e^x into its taylor series up to x^2, so that the fraction becomes (1+x+x^2/2 + o(x^2) - 1 - x)/x, or x/2 + o(x)
so you have that you're taking the limit of 1/x * log(1 + x/2 + o(x))
unborn roost
I got a quadratic equation
f(t) = -4.9t^2+100t
now at t = 0, it the y-value will be 0, but how can i edit the equation so that at t = 100, y = 0?
gritty solar
Is this a position function
unborn roost
Is this a position function
that's indeed correct
It's a physics problem I'm doing. I can provide with additional information for why I want my graph to start as 0 when t = 100 instead of t = 0, but that wouldn't be relevant to the question here
gritty solar
Then I find it odd that at t = 100 you want it to be at y = 0
unborn roost
Haha, seems like I'll have to get into details
gritty solar
Nah you don't have to
You need to simply modify the equation such that 0 and 100 are roots but you won't preserve the structure of it being an equation of motion I suppose
I guess you could start from scratch
unborn roost
You need to simply modify the equation such that 0 and 100 are roots but you won...
mind clarifying?
gritty solar
Write the equation in factored form such that 100 and 0 are roots
$f(t) = t(t - 100)$
soft zealotBOT
NEONPerseus
soft zealotBOT
NEONPerseus
unborn roost
i'll just paste the entire thing here ig
A rocket is shot vertically upwards. The fuel lasts for 4.00 s. The rocket has an acceleration of 25.0 m/s2 upwards as long as it has fuel. Ignore air resistance.
the motion that the rocket has when it has fuel, is different from the motion it has when it doesn't have fuel
gritty solar
Sucks for me, fun for you
gritty solar
i don't even know what it is
The mass changes over time so that would affect the speed
gritty solar
well it's simpler
Yup
unborn roost
The mass changes over time so that would affect the speed
yeah no
anyways, the motion during the first four seconds is not the same as the motion after the four seconds
gritty solar
Alright so basically the rocket accelerates for 4 seconds up until whatever height and then freefalls
What are you meant to find?
unborn roost
that's correct
so the first equation we got is
s(t) = 12.5t^2
i'm meant to graph it's general position
like put the two graphs into one positiongraph
gritty solar
that's correct
so the first equation we got is
s(t) = 12.5t^2
I don't think that's right
Because the net acceleration on the rocket is 25 - g
unborn roost
don't overcomplicate it
gritty solar
$\dv{v}{t} = 25 - g$
gritty solar
don't overcomplicate it
Are you sure, because gravity still acts on it
soft zealotBOT
NEONPerseus
unborn roost
Yes, I'm sure, this is the first chapter of a basic physics book
gritty solar
Alright then
unborn roost
However I do have no doubt that you can do it with or without complexities
My apologies, could you excuse me for two minutes?
There's just something quick I need to do, I really apologise.
I'll get back to you as soon as possible, shouldn't take more than five minutes
while that's happening you can try to get an understanding of the problem, if you want
gritty solar
However I do have no doubt that you can do it with or without complexities
Ahahah that's not what this is about
gritty solar
There's just something quick I need to do, I really apologise.
I'll get back to ...
No worries, ping me and if I'm available I'll come back
unborn roost
No worries, ping me and if I'm available I'll come back
Thanks for your patience, I'm back
gritty solar
Yup
unborn roost
What we're basically being told to do is to graph out its position from the point it's launched to the point it reaches the ground
gritty solar
Alright
unborn roost
that would involve putting the graph where it's accerlation is 25, and then making it between 0 and 4 seconds, and filling the rest with the second graph
unborn roost
We got the first graph to be s(t) = 12,5t^2 (in simple terms)
unborn roost
You're meant to graph the trajectory?
that word is new to me
unborn roost
yes, then it would be graphing the trajectore of the rocket
s(t) = 12,5t^2
after that
s(t) = -4.9t^2+100t
i got no idea btw why i chose to name it f(t) on the start of my discord message and not s(t), which is the common symbol for position
unborn roost
oh wait, it's a bit wrong
s(t) = -4.9t^2+100t + 521.6
s = -4.9t^2 (half of the acceleration) + 100t (the starting velocity is 100) + 521.6 (starting position of the graph at 521.6, which is the place where the rocket ended)
gritty solar
But it's not at 521.6 at t = 0 right :P
gritty solar
But according to this equation, the rocket is at 521.6 at t = 0
unborn roost
this is because if we were to move the entire s(t) graph of the acceration of 25 m/s^2 four x-units to the left, then t = 0 should be a correct representation of the graph
nevertheless the entire trajectory would make absolutely no sense
in other words; because i don't know how to make it so that it's 521.6 t = 4
gritty solar
You don't need to though as you pointed out
Your position time graph should just be two halves of parabolas stuck to one another
unborn roost
i'm unsure what you exactly mean by that
gritty solar
You basically wanna have two sections right?
gritty solar
One with the acceleration upwards, and the other in free fall
unborn roost
yeah
gritty solar
should the equation be changed? How can I do this in Geogebra?
I don't use geogebra myself so I can't help you with that
gritty solar
yeah
So you can set t = 0 when the rocket finishes accelerating again as you said and shift the graph
Seems good to me
unborn roost
i need to be able to represent this in a graph in geogebra
i can't have half of the sector in a negative part of the plane
gritty solar
Geogebra should allow you to specify boundaries for the graph?
Your equations seem alright to me but I really don't know how to use Geogebra, I think it's best if we wait for another Helper to come to the rescue
unborn roost
it's quite difficult for me to find that
the only thing i know is to delineate the graph
unborn roost
Your equations seem alright to me but I really don't know how to use Geogebra, I...
I can try to get a helper by posting this in another period, but isnt there a way of making it so that 521.6 when t = 4?
gritty solar
I mean it's not impossible but I don't know the specifics
You basically set it so that you get that answer
You can plug in s(4) and then modify the constant term for the answer that you get
But again that would fuck with the initial position
You can't have everything you want in a quadratic :P
unborn roost
had it been a linear equation then it would've been way better
but it's not
I'll eat dinner for now to post the question again. I thank you a lot for the assistment @gritty solar
.close
final saddleBOT
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fast nebula
How am I supposed to find a derivative when it now has a variable in the top?
soft zealotBOT
Hack With Techno Boy
coral kindle
help in Question 10, have no idea what to do here.
final saddleBOT
help in Question 10, have no idea what to do here.
tired walrus
it tells you exactly what set H is in each subproblem no?
coral kindle
right
tired walrus
in a, H consists of all those permutations which map 3 to 3
and in b, it's instead the set of all those permutations which map 3 to 1
coral kindle
right
so what about the rest?
is it just the same
so in a, 1 to 1, 2 to 2, etc?
tired walrus
no
coral kindle
then how do we know?
is the set just (3)?
because i don't see how else 😭
erm?
help?
?
final saddleBOT
@coral kindle Has your question been resolved?
final saddleBOT
@coral kindle Has your question been resolved?
gritty zodiac
Well, how do you check if something is a subgroup?
If (U,) is a group, when will (V,) be its subgroup, what conditions must it satisfy?
(U, °) and (V,°)
@coral kindle
Do you know the definition of a subgroup?
coral kindle
if you read up, that isn't my problem 😭
gritty zodiac
Well they have to tell you the definition of a subgroup before tasking you to find one
But okay ill throw you a bone , (V,°) is a subgroup of (U,°) if V is a subset of U and youll never guess, (V,°) is also a group when it comes to the operation °
In your problem H is already a subset of the permutation group
coral kindle
Well they have to tell you the definition of a subgroup before tasking you to fi...
oh i know the def of a subgroup.
i just seem to struggle with symmetric groups
in that form
gritty zodiac
So you just gotta check if its closed for the sigma operator
coral kindle
I struggle to see what the set is
gritty zodiac
It inherits other properties such as association...associativnes...umm the thing with brackets, sorry English aint my first language
coral kindle
like what is set H in part (a)
gritty zodiac
Well in this case H is a set of functions
coral kindle
It inherits other properties such as association...associativnes...umm the thing...
i get what you mean but i still don't see
gritty zodiac
Yes that can be a bit hard to wrap your head around
gritty zodiac
Well think of it this way
Symetric group is group of all permutations, in your case its S5
coral kindle
right
gritty zodiac
And you know you can write those permutations with 12345 and their values below
coral kindle
yes
gritty zodiac
Now H is if you Took all those permutations where 3 gets sent into 3
coral kindle
sigma(3)=3 would be (3)?
coral kindle
okay okay
coral kindle
so all the elements of S3 would be (), (1 2), (2 3), (3 1), (1 2, 3) , etc
gritty zodiac
Yes
coral kindle
basically with cardinality of 3!
gritty zodiac
Now lets say im tasking you to only take the permutations where sigma(2) = 2 and put them in a set A, and leave all others
coral kindle
right so set A = {(2)}
gritty zodiac
In set A 2 gets sent to 2, since we have only 6 elemts to Pick from, do you know which elements we select
Can you write them out explicitly?
A permutation that sends 1 to 1, 2 to 3 and 3 to 2 is one that doesn't to into A
For example
(123->123) goes to A
I wish i had a paper rn
gritty zodiac
Well, im not certain what you mean by those 2, is (1 2 3) same as
I'll write 2 lines
1 2 3
1 2 3
Imagine if there were brackets around them
gritty zodiac
Okay but what about 1 and 3? You have 2 of those
gritty zodiac
When you write (1) do you mean that 1 goes to 1 and other two are mixed?
coral kindle
it's (1)(2)(3)
this as set A
coral kindle
oh okay
coral kindle
oh if we assume sigma is an element of S3
gritty zodiac
Sigma is a permutation
And when you write example
1 2 3
1 2 3
That is a convention for writing permutations , you basically mapped the domain and codomain of sigma
That means sigma(1)=1 sigma(2)=2 etc
123
321
Means sigma(1)=3
coral kindle
uhuh
coral kindle
okay so back to the question, would it be
1 2 3 4 5
1 2 3 4 5
gritty zodiac
Thats one sigma that goes into your set
Thers many more , you know the cardinality of s5
So dont bither writng them all
But know you know how elements of H look like
All that you need to check is if you compose 2 sigmas from H, will the New sigma you get also be from H or not
And youll find the solution very simple
coral kindle
so all the elements of S3 would be (), (1 2), (2 3), (3 1), (1 2, 3) , etc
ahhh so if we were to check this?
with 2 to 2
gritty zodiac
Well yeah but you wont check all combimations obviously
But Heres how you should think
Lets look at the S3 example
Lets say we picked two functions from that A set
Lets call them sigma1 and sigma2
We know that sigma1(2)=2
Same for sigma 2
Now the question is is sigma1 o sigma2 (2) = 2
o Being the composition
Are you able to follow me?
coral kindle
so now for (1 2)o(2 3)
how do we do that?
is it just ... erm....
i can do it for (2)o(2) obvs go to 2
gritty zodiac
Well think of it this way
Dont check specific cases
Check in general
As i Said
Your only goal is to check is sigma1 o sigma2= 2
Or in your case 3
So you dont check individual combimations Like (12) o (23)
coral kindle
hmmmm
coral kindle
So you dont check individual combimations Like (12) o (23)
yes but if the permutations are like (1 2)
how do we find the composition of them?
gritty zodiac
Like this
Well
I wont answer, think, what do you know about composition of functions in generađ
General
What is f o g(x)?
coral kindle
well that would be f(g(x))
gritty zodiac
So what is sigma 1 o sigma2 (x)
coral kindle
so as an example (12) o (23) = (123)?
gritty zodiac
No
coral kindle
So what is sigma 1 o sigma2 (x)
erm sigma1(sigma2(x))
coral kindle
composition is when we put one into the other
gritty zodiac
To this part
coral kindle
erm which part?
coral kindle
oh okay
gritty zodiac
1 2 3
3 2 1
Is an example of how we can write permutations
The upper numbers are all possible x
And the Lower row values are sigma (x)
coral kindle
yes
gritty zodiac
So sigma (1) = 3 sigma (2) = 2
Okay
So
Sigma1 o sigma2 is as you Said sigma1 (sigma2 (x))
coral kindle
yup
coral kindle
yh
gritty zodiac
What do you know about them? Well you know that sigma(3) =3
And thats the only thing you know
In general
You dont know or care what sigma(1) is or sigma(5)
gritty zodiac
Now lets say we Took two Random sigmas from H
And their composition is sigma1 (sigma2 (x))
coral kindle
yes
gritty zodiac
Our only worry is will sigma1 o sigma2 (3) be equal to 3
So try plugging in 3
And tell me what you get
coral kindle
well i get 3 back
gritty zodiac
And that would mean that for every 2 permutations from H
Lets call them sigma1 and sigma2
Their composition when taking the variable 3 would give 3
Which means that their composition is some other sigma in that set H
Meaning that H is a subgroup
Its okay if its confusing, things should be clearer after you solve b altho i think youll need help
But the main gist is
No mater which sigma you take from H
Sigma(3) will be 3
And their composition(3) will also Always be 3
coral kindle
oh so we only check it for Sigma(3)= 3
gritty zodiac
Because the first one will be 3 and then the second will have 3 for argument
Yes
Only that
coral kindle
ahhhh that clears everything up
gritty zodiac
You dont care about sigma (1) or any other number
final saddleBOT
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viral chasm
y=a|x|+b|x-c|, for x=-1 and x=3 the function takes the value 0. The largest value of this function is 2. Find a,b,c and draw the graph. can anybody help me please
final saddleBOT
y=a|x|+b|x-c|, for x=-1 and x=3 the function takes the value 0. The largest valu...
@viral chasm Has your question been resolved?
viral chasm
<@&286206848099549185>
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@viral chasm Has your question been resolved?
viral chasm
help pls 😦
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@viral chasm Has your question been resolved?
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@viral chasm Has your question been resolved?
clever meadow
almost there
clever meadow
help pls 😦
still up?
final saddleBOT
@viral chasm Has your question been resolved?
round nova
hi again. i was wondering if any of u guys could help me with the ambiguous case of the law of sines. im having a hard time understanding it with there being like a certain amount if solutions and triangles u can have
final saddleBOT
hi again. i was wondering if any of u guys could help me with the ambiguous case...
round nova
no yeah i get that
like i already solved for angle N angle u and side u
its just i dont get how its ambiguous
azure trellis
Sin is positive between 0 and 180
So you technically can get two solutions
E.g
sin(45)=sin(135)
warm frigate
,w plot y=sinx and y=1/2 from 0 to pi
soft zealotBOT
warm frigate
you can see it has two intercept points, meaning you can get two solutions
azure trellis
You differentiate between the solutions using stuff like angle laws
I.e. a triangle has an angle sum of 180
azure trellis
You would get two values for your angle
warm frigate
since you are given one angle and the measure of it's corresponding side, you can define the radius of the circumcircle, right?
think of it as ur constructing a triangle that's incribed in a single circle
first construct a chord that has a measure of 23
warm frigate
the inscribled angle of that chord will always be 62degrees, so you just need to define one side that has a measure of 8cm
warm frigate
💀
just know that you can't define a triangle with two sides and an angle that is not the contained angle of those two sides
round nova
??
i dont think i ever learned it this way
here let me send a copy of my teachers notes
warm frigate
you're just asking why there's two answers for this aren't you?
maybe this will help you understand
assume you are constructing the triangle
first construct the angle 62degrees, and the side with a measure of 8cm
now you need to construct a side that has a measure of 23cm
warm frigate
,w plot y=sinx and y=0.307 from 0 to pi
soft zealotBOT
warm frigate
two intercept points, meaning you'll get two values for N
,w solve sinx=0.307 from 0 to pi
soft zealotBOT
round nova
right
but like why
like if we just disregard the graph
how does that work
bc we’re not supposed to graph them to figure it out
like i literally have no idea why u graphed sinx and 0.307
but dont worry abt it
unfortunately its very late for me and i gtg but if u guys like have anything else just ping me
warm frigate
how does that work
sine=y/r by definition
in a unit circle, the sine value is the y coordinate
you can see that there are two points on a unit circle that has the same y coordinates
final saddleBOT
@round nova Has your question been resolved?
weary trellis
does it make sense to sin(radians)
final saddleBOT
does it make sense to sin(radians)
weary trellis
like when question asks u to convert to radians
are u meant to sin (radians) or sin(degrees)
tiny gorge
can you paste the question
converting an angle from degrees to radians doesn't involve sine
weary trellis
i dont have a question in mind just a generality
no yeah ik
but like when they say convert answer to radians
do u just convert the angle from degrees to radians
but sin(degrees)
tiny gorge
well like what is an example of this
weary trellis
cause sin(radians) doesnt make sense does it?
weary trellis
it does?
tiny gorge
it's not the same sine function that you use for sin(degrees)
tiny gorge
the two functions are related of course:
if I write sin_d to denote the degree version and sin_r to denote the radian version,
then sin_r(angle in radians) = sin_d(180/pi x angle in radians) = sin_d(angle in degrees)
weary trellis
right makes sense
tiny gorge
if you use a calculator for example, then when you are in degrees mode, it'll use sin_d
and when in radians mode it'll use sin_r
same for the other trig functions
other software usually assumes radians unless you say otherwise
and in math contexts (at least any class after high school), radians is assumed unless stated otherwise
weary trellis
so when say if a question says have answer in radians? say have sin 60 in radians? does that mean sin(60 * pi/180)?
ik this kinda doesnt make sense cause i remember the teacher vaguely saying it
weary trellis
and in math contexts (at least any class after high school), radians is assumed ...
ah okay
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@weary trellis Has your question been resolved?
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fiery chasm
fiery chasm
<@&286206848099549185>
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@fiery chasm Has your question been resolved?
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fiery chasm
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@fiery chasm Has your question been resolved?
fiery chasm
from what I see the second one is d
wait nvm I see
could you help me do this last one then @clever meadow
clever meadow
jesus fuck english
fiery chasm
jesus fuck english
?
clever meadow
- D
- L
- J
I have no clue what 1. might be
they are obviously parallel
so constituting that would be... algebra?
I don't really know
by the way
try typing
fiery chasm
its g
clever meadow
angles forming linear pair sum to 180
and use google graphics
lot's of examples that are already done
fiery chasm
ok thanks for all your help
clever meadow
?
in my native language it's so clear, but when I read mathematical relation definition in english I think I'd rather kill myself
final saddleBOT
@fiery chasm Has your question been resolved?
drifting laurel
$integral$
final saddleBOT
$integral$
drifting laurel
Using calculus, prove that, for all $a, b, \in R^+$ and $n \in Z^+$
$\int_{1}^{n}(a+b)^x dx \ge \int_{1}^{n}a^x +b^x dx$
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autumn urchin
someone pls help me do basic integration ;;
final saddleBOT
someone pls help me do basic integration ;;
tranquil pine
someone pls help me do basic integration ;;
show the question
autumn urchin
integration of
dx/sqrt(9+x^2)
dx/sqrt(9-x^2)
the first seems like cancer
Also is it bad that my answer is by Maxima and not manual integration for some of the questions im answering
(for y^3/(y^2-5x-6)
versed crater
Can you take a picture of the original question
tranquil pine
is this the question?
autumn urchin
autumn urchin
yeh
versed crater
Also is it bad that my answer is by Maxima and not manual integration for some o...
What is this about
autumn urchin
also integration
if i put the question into integration-calculator.com it matches answer by maxima rather than answer by manual integration and idk why
tranquil pine
if i put the question into integration-calculator.com it matches answer by maxim...
don’t do maxima
rustic sandal
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fast nova
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fast nova
Can someone help me with this problem?
I know that they are countable and there is that visualization proof
but that is only for the set of positive rational numbersss
gritty solar
I know that they are countable and there is that visualization proof
Cantor's diagonal argument?
gritty solar
I think that should work
fast nova
like so in the first row we have the denominator as -1 and the second row -2 and so on
tranquil pine
(alternatively you could map positive/negative Q to positive/negative Z. Then map whole of Z to N)
final saddleBOT
@fast nova Has your question been resolved?
fast nova
(alternatively you could map positive/negative Q to positive/negative Z. Then ma...
that is like a transitive relation
that also sounds good
tranquil pine
that is like a transitive relation
yeah, bijections are transitive
oblique portal
This would fit in a more computer logic/hardware design area, but nonetheless
I am currently trying to design a 256 bit latch matrix, edited by 2 4-16 decoders. Unfortunately for me, im running this in a digital simulation, meaning i have to compartmentalize a whole lot more. So, i split each column of the 16x16 matrix into 1 chip, with a specific 4-16 decoder to select whatever lies in the specific register.
Then, i proceeded to arrange those 16 bit columns into another 16 long Row, to create the entire matrix.
But how would i access one specific latch?
Because i first need to access 1 column, then in that column i need to access the latch on the row given by the 8 bit address (4 for col. and 4 for row).
How would i know to select the row address only to the collumn i need?
do i just and each individual imput with the enable signal?
I thought it would have some low level logic connection or something, because the CS server doesnt deal with this stuff so i dont know where exactly to ask
final saddleBOT
This would fit in a more computer logic/hardware design area, but nonetheless
I...
tranquil pine
This would fit in a more computer logic/hardware design area, but nonetheless
I...
so you are basically trying to implement a 16x16 memory array using latches, decoders, and selectors?
if i understood what u mean correctly?
oblique portal
16bit x 16bit yes
cause each collumn and row has 16 total bits
stored in the adresses
tranquil pine
you can use the column address to select the 4 to-16 decoder chip, which will output a set of 16 signals corresponding to the row address then you can use these 16 signals to select the latch in the column i believe
oblique portal
would there be an issue if i send the row address to all columns and only use the collumn i need
tranquil pine
would there be an issue if i send the row address to all columns and only use th...
it might work?
oblique portal
you can use the column address to select the 4 to-16 decoder chip, which will ou...
yeah i did that\
tranquil pine
but i dont think its efficient?
oblique portal
anding everything is definitely less efficient
hmm
oh wait
haha
that might work
i think i got it
tranquil pine
oh really?
oblique portal
i was worried if i send it to every row and enable writing it would write the bit to all the registers in the row
but i specifically made the collumn selector select which collumn is enabled
tranquil pine
oh yeah then you wont have any issues writing multiple latches in the same row
oblique portal
unless i just select the row
but thats kinda intentional
wait i dont think i have that implemented
i think i just put a general enable
yeah i should add a registry enable too
hmm
tranquil pine
noice
oblique portal
i've been getting into this stuff lately and ngl its super interesting
welp
more wiring work now
ty for the help
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rich kindle
Tom and Cindy play a game where they alternately flip a fair coin equally likely to land
either heads or tails. The winner is the first person to flip a “heads”. Determine the
probability Tom will win when Cindy goes first.
How do I solve this? I tried to just count it but they could both keep getting tails for like a long time so u cant do casework can you?
final saddleBOT
Tom and Cindy play a game where they alternately flip a fair coin equally likely...
tranquil pine
You can do casework for a bit and try to see a pattern.
rich kindle
C T C T C T
H ? (50% chance Cindy wins)
T H (25% chance tom wins)
T T H (12.5% Cindy wins)
T T T H (6.25% Tom wins)
T T T T H (3.125% Cindy wins)
T T T T T H (1.5625% Tom wins)
tranquil pine
Right.
rich kindle
Cindy has 2/3 tom has 1/3
tranquil pine
That's what i got.
tranquil pine
$\sum_{k=1}^\infty \left(\frac{1}{2}\right)^{2k} = \frac{1}{3}$.
soft zealotBOT
Landau08
rich kindle
ohh infinite geometric
wait why 2k?
well cuz tom is the second one to go
$\sum_{k=1}^\infty \left(\frac{1}{2}\right)^{k} = \frac{2}{3}$.
soft zealotBOT
Jobo
rich kindle
but a1 = 1/2 and r = 1/2 as well
tranquil pine
right, Tom wins after TH, TTTH, TTTTTH, ....
tranquil pine
$\sum_{k=1}^\infty \left(\frac{1}{2}\right)^{2k} = \sum_{k=1}^\infty\left(\frac{1}{4}\right)^{k} = \sum_{k=2}^\infty \left(\frac{1}{4}\right)^{k-1}$.
soft zealotBOT
Landau08
rich kindle
ohh its 2k for both of them
tranquil pine
$= \sum_{k=1}^\infty\left(\frac{1}{4}\right)^{k}-1$
soft zealotBOT
Landau08
rich kindle
because they dont flip the coin on every single k , only half
tranquil pine
Tom wins for TH, TTTH, TTTTTH etc that's always even powers of 0.5
now I can use your formula
$=\frac{1}{1-\frac14}-1=\frac13$
soft zealotBOT
Landau08
rich kindle
**Landau08**
oh did you make it k=2 and k-1 to indicate tom starts on the 2nd flip
tranquil pine
I just wanted to use your screenshot
there the exponent was n-1 which is why I shifted...
rich kindle
thanks a lot i got it now
tranquil pine
but there are multiple ways to come to the same result.
final saddleBOT
tranquil pine
you're welcome
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burnt dirge
Hi
burnt dirge
I don’t get it
final saddleBOT
@burnt dirge Has your question been resolved?
burnt dirge
<@&286206848099549185>
flat iris
Start with b
burnt dirge
I don’t need to do B
burnt dirge
Yeah just A
flat iris
Ok
burnt dirge
I’ve never learned this shit, I moved from set 4 to set 3 maths and I haven’t learned half the stuff they teach. They were like 6 topics ahead of us
flat iris
Try to find the line
burnt dirge
I didn’t draw it
flat iris
Yea ok
So it was there
Just find the slope and y intercept of the orange line
I think that is it
Actually
Yea
I need to rethink
Cuz it is a trend line
You know what a trend line is?
burnt dirge
Nope
flat iris
Then how tf are u getting this hw
burnt dirge
Oh somehow I got it right
flat iris
Bruhhhh
flat iris
What did u put?
burnt dirge
-1/3 and 5
flat iris
How tf did those numbers come in mind
flat iris
Well
burnt dirge
Thanks for the help anyways man
flat iris
Just make sure u understand ur math class cuz guessing won’t help in the future
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fresh patio
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fresh patio
I can't figure what to use for this integral
robust mulch
do you remember your inverse trig derivatives
fresh patio
I do
robust mulch
which one does it look like?
fresh patio
tan?
robust mulch
not quite
manic flame
I can't figure what to use for this integral
Start by conjugating the root on the bottom
It should allow you to have an easier time playing around with the integral
fresh patio
I tried but I don't know where to go from there either
manic flame
I tried but I don't know where to go from there either
Once you get to that point, try integration by parts $\int 1/{1+(\sqrt[3]{x}^2)} * {\sqrt{1-cbrt{x}}$
You know Im not gonna use latex I suck at it
Try integration by parts once you congugate
grand bronze
use $u=\sqrt[3]{x}+1$
soft zealotBOT
Duh Hello
grand bronze
its reasonably simple from there
i dont think int by parts will be very nice at all
manic flame
i dont think int by parts will be very nice at all
Well Im probably not as smart as you so ur probably right
Try whatever he is saying
final saddleBOT
@fresh patio Has your question been resolved?
fresh patio
does this look right?
grand bronze
yep thats right
fresh patio
misplaced the 3 in the top step oop
fresh patio
yep thats right
uhhh I still can't figure out where to go from there
grand bronze
expand the numberator and spread it out into 3 fractions
grand bronze
👍
fresh patio
use $u=\sqrt[3]{x}+1$
what should have been my cue to do this?
usually when I think to do u-sub, there's a function and its derivative present inside the integral
grand bronze
honestly i couldnt tell you, anytime i see a square root i just u sub it and see what happens unless its an obvious trig integral
final saddleBOT
grand bronze
np, coulda probably gotten away with doing $u=\sqrt[3]{x}$ as well
soft zealotBOT
Duh Hello
grand bronze
but would require some extra knowledge
fresh patio
what knowledge? I'll try it out if I recognise the concepts
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Available help channel!
ocean stratus
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ocean stratus
I tried putting this into the calculator
soft zealotBOT
keto11
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indigo veldt
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indigo veldt
I am confused with the concept of derivatives, and I have tried solving this before, did not work out.
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tranquil pine
,tex The ciphertext OIKYWVHBX was produced by encrypting a plaintext message using the Vigen`ere cipher with key HOT. What is the plaintext message?
final saddleBOT
,tex The ciphertext OIKYWVHBX was produced by encrypting a plaintext message usi...
soft zealotBOT
tranquil pine
I am really not familiar with the Vigenere cipher yet. Any particular hints?
silk saddle
,w Vigenere ciphere
soft zealotBOT
Requested by DerpZ#9141
silk saddle
oh my god useless wolfram
silk saddle
is it just a shift cipher
i went to google it up
nah nah dont waste time
you decode it in blocks of 3
let f be the cipher function
so f ( (x,y,z) )
where x y z are numbers 0 thru 25
tranquil pine
The \textbf{Vigen'ere cipher} is a block cipher, with a key that is a string of letters with numerical equivalents $k_1 k_2 \hdots k_m$ where $k_i \in \vb{\Z_{26}}$ for $i =1,2,3,\hdots, m$. Suppose that the numerical equivalents of the letters of a plaintext block are $p_1 p_2 p_3 \hdots p_m$. The corresponding numerical ciphertext block is $(p_1 + k_1) \mod 26 (p_2 + k_2) \mod 26 \hdots (p_k + k_k) \mod 26$. Finally, we translate back to letters. For example, suppose that the key string is RED, with numerical equivalents 17 4 3. Then, the plaintext ORANGE, with numerical equivalents 14 17 00 13 06 04, is encrypted by first splitting it into two blocks 14 17 00 and 13 06 04. Then, in each block we shift the first letter by 17, the second by 4, and the third by 3. We obtain 5 21 03 and 04 10 07. The cipherext is FVDEKH.
soft zealotBOT
silk saddle
I mean you basically answered your own question 
also good strats
strats being deployed
tranquil pine
I mean you basically answered your own question <:opencry:586078614865444865>
no thats just the definition 
tranquil pine
strats being deployed
strats? 
tranquil pine
right
silk saddle
ofc mod 26
tranquil pine
right
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silk saddle
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mint turret
6+2=8
-1 *-6 + 6-4 = 8
-1-4=8
-5=8
Ik this is stupid, but i wanna know what exactly is wrong in this
final saddleBOT
6+2=8
-1 *-6 + 6-4 = 8
-1-4=8
-5=8
Ik this is stupid, but i wanna know what exa...
gritty solar
How did you get from step 2 to 3
warm frigate
a×(-b)+b ≠ a
mint turret
How did you get from step 2 to 3
-6 and +6 got cancelled
cerulean dragon
6+2=8
-1 *-6 + 6-4 = 8
-1-4=8
-5=8
Ik this is stupid, but i wanna know what exa...
Do you know why Order of operations is being used?
mint turret
chill. ik its wrong, i just wanted to k now what exactly is wrong
cerulean dragon
It's just a convention amongst the Mathematicians, to do a mathematical operation
cerulean dragon
chill. ik its wrong, i just wanted to k now what exactly is wrong
Just as jay. said, a * -b + b != a
final tangle
from the order of operations
a * b + c
the a * b (multiplication) takes priority over the b + c (addition)
cerulean dragon
doesn -b and +b get cancelled
Nah, bro. It can't be cancelled out for some reason
final tangle
(doesn't matter what / how similar the b and c look)
mint turret
oh dmn oh so something like bodmas?
cerulean dragon
Yeh
final tangle
yes
cerulean dragon
pemdas or bedmas whatever you prefer, you have to obey this order
mint turret
alright
cerulean dragon
6+2=8
-1 *-6 + 6-4 = 8
-1-4=8
-5=8
Ik this is stupid, but i wanna know what exa...
You can indeed perform this operation
mint turret
You can indeed perform this operation
well yeah, then i would end up where i started
cerulean dragon
Let jus think that you've made a new convention
dry light
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lilac fjord
Linear Multistep Method Question - can someone please check this for me?
final saddleBOT
Linear Multistep Method Question - can someone please check this for me?
@lilac fjord Has your question been resolved?
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@lilac fjord Has your question been resolved?
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onyx sand
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onyx sand
could someone show me where i went wrong with the integral on the left