#help-36

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plucky umbra
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<@&286206848099549185>

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pls help

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now this question pls what is answer

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ffs

hearty zephyr
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how would you solve 3k+8 = 26?

plucky umbra
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idkdkdkdkkdd

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Pls answer

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idc abt method

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this was due 1 min ago pls

hearty zephyr
charred fulcrum
plucky umbra
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omfg

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wheere do i get the answer then

plucky umbra
hearty zephyr
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because the question isn't asking for an equality

plucky umbra
hearty zephyr
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since the original is asking for >=, and you didn't multiply or divide by a negative, the sign doesn't change.
the method for solving it is, otherwise, the same as solving an equality.

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but the answer maintains the original inequality sign

plucky umbra
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useless bitch

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.closew

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tranquil pine
#

hello!

why are multiples of dx ignored ?

eg. $\frac{d}{dx}x^2= \frac{2(dx \cdot x) + dx^2}{dx} = 2x + dx = 2x$

why does the dx in $2x + dx$ dissapear ?

i know that it is an "infinitely small" value, and that it is infinitely small compared to any number - but still, it is not zero, thus it should still count

soft zealotBOT
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trololol !

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

<@&286206848099549185>

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@tranquil pine Has your question been resolved?

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pine garden
#

I don't understand how to solve this

final saddleBOT
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@pine garden Has your question been resolved?

pine garden
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<@&286206848099549185> hi

pine garden
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<@&286206848099549185>

open oxide
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look at unit circle

pine garden
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ok i got it. thank you

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oak arrow
#

could someone please help me with 16

final saddleBOT
oak arrow
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i just dont really know how to find the directional vector

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because (6,1,3) when dotted with v is not 0

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what if i add the vector (0,-1,0). adding those two dot products together would yield 0

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would that work?

pine root
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the vector equation of a plane is usually its normal vector

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and thats just v by the definition

final saddleBOT
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@oak arrow Has your question been resolved?

oak arrow
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eager trellis
#

Direction: write a rule for g described by the transformations of the graph of f f(x) = x^2; vertical stretch by the factor of 2 and a reflection in the x axis , followed by a translation 3 units down

eager trellis
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I’m stuck on everything

rare halo
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I don't know the topic but I guess
2x² --> -2x² --- -2x²-3

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Should be the thing

hot patrol
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ok first

#

@eager trellis

eager trellis
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OH OKAY THANKS YALL

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eager trellis
#

.reopen

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eager trellis
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Direction: write a rule for g described by the transformations of the graph of f f(x) = x^2; vertical shrink by a factor of 1/2, followed by a translation 3 units left

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now im confused on this question

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where would I put the parentheses?

hot patrol
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Well

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if you look at the sheet i gave you

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h represents horizantial translations

eager trellis
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so plus 3

hot patrol
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so y= 1/2(x+3)^2

eager trellis
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THANK YOUU

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wait what’s with the other plus 3?

hot patrol
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mb

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ignore that

eager trellis
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oh okayyyy

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thank youuu

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ure a life savior

#

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raven bridge
#

how can i calculate rank of this matrix?

final saddleBOT
raven bridge
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<@&286206848099549185>

worldly vale
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Find the number of linearly independent columns

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Or rows

raven bridge
worldly vale
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Do you know what linear independence means?

raven bridge
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no

worldly vale
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Okay

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Weird

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Well what ways have you been taught to calculate the rank of a matrix

raven bridge
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well, lastly i didn't pay much attention to university due to depression

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and now i'm trying to make it up

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soo, i'm figuring it out now

worldly vale
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And your first port of call was calculating the rank of a matrix? You should cover some background first

raven bridge
worldly vale
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Okay then use one of them

raven bridge
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but those methods don't really work in this case

worldly vale
#

Show your work

raven bridge
raven bridge
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rz is for rząd, what is polish name for rank

worldly vale
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Okay and so...

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Whats the point of doing the row reduction? (Its the correct thing to do but you need to recall the point of doing it)

raven bridge
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the point of this is to get Identity matrix

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the longest possible one

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but i don't see the way how to get one longer than 3x3

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<@&286206848099549185>

mellow cedar
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could you give us the original matrix ?

mellow cedar
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you can reduce it to
$\begin{bmatrix}
1 & 0 & 0 & 0 \
1 & 5 & 0 & 6 \
1 & 0 & 7 & 0 \
1 & 8 & 0 & 9 \
1 & 0 & 0 & 0 \
\end{bmatrix}$

soft zealotBOT
#

Mehdi_Moulati

mellow cedar
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since the colmun 0 is the same as the 2 ,4 and 6

raven bridge
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oh, ok, so I can remove repeating columns

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i didn't know about this

mellow cedar
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yeah it's true

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let a and b vectors :

if vector a = K * b where K integer you can delete it

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in general :
if i could get a vector using other vectors i could delete it

raven bridge
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ok, with this knowledge the rest of this problem is trivial

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thanks for help

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mellow cedar
#

@raven bridge you can delete the first and last row also

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raven bridge
final saddleBOT
mellow cedar
raven bridge
#

kk

mellow cedar
#

$\begin{bmatrix}
1 & 0 & 0 & 0 \
1 & 5 & 0 & 6 \
1 & 0 & 7 & 0 \
1 & 8 & 0 & 9 \
\end{bmatrix}$

soft zealotBOT
#

Mehdi_Moulati

raven bridge
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I knew that I can delete rows, but i just didn't know that I also can delete columns

mellow cedar
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also the column

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you just need to prove that the the vectors are all independent

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the rank is number of independent vectors

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i guess you will find the rank = 4

raven bridge
raven bridge
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wait, one column or one row is a vector, right?

raven bridge
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oh

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i actually didn't know this

mellow cedar
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two columns an test them if they are independent
or
two rows an test them if they are independent

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if two vectors (A and B) are dependent when
AX = B

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like
$\begin{bmatrix}
1 \
1\
1\
\end{bmatrix}$
X = $\begin{bmatrix}
3 \
3\
3\
\end{bmatrix}$

raven bridge
soft zealotBOT
#

Mehdi_Moulati

mellow cedar
raven bridge
#

is it a real, whole or literally random number?

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/variable

mellow cedar
mellow cedar
raven bridge
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yes, but i mean, can X be for example a complex number?

mellow cedar
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$\begin{bmatrix}
1 \
1\
1\
\end{bmatrix}$
X = $\begin{bmatrix}
1 * X \
1 * X\
1 * X\
\end{bmatrix}$

$\begin{bmatrix}
3 \
3\
3\
\end{bmatrix}$

soft zealotBOT
#

Mehdi_Moulati

mellow cedar
#

it's like a system of equations where
$\begin{cases}
1 * X = 3 \
1 * X = 3 \
1 * X = 3 \
\end{cases}$

soft zealotBOT
#

Mehdi_Moulati

mellow cedar
#

and you trying to find the value of the X

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if you find a solution then the vectors are dependent

mellow cedar
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so i could remove one of them

raven bridge
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ok, so for example if
$\begin{bmatrix}
1 \
1\
1\
\end{bmatrix}$
X = $\begin{bmatrix}
1 * X \
1 * X\
1 * X\
\end{bmatrix}$

$\begin{bmatrix}
3i \
3i\
3i\
\end{bmatrix}$

soft zealotBOT
#

Trenek

raven bridge
#

then X=3i

mellow cedar
#

yeah

#

$\begin{bmatrix}
1 \
2\
3\
\end{bmatrix}
X

\begin{bmatrix}
5\
10\
15\
\end{bmatrix}$

#

find the X in this example

soft zealotBOT
#

Mehdi_Moulati

raven bridge
#

X=5

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ok, now I fully understand it

mellow cedar
#

that right so the vector (1,2,3) and (5,10,15) are dependent

raven bridge
#

thanks a lot 😊

mellow cedar
#

wait

#

those examples are simple

raven bridge
#

huh, okay

mellow cedar
#

sometime you need to prove that
A = BX + CY + DZ
where
A ,B ,C and D are vectors
and X,Y and Y are variables

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$\begin{bmatrix}
1\
1\
0\
\end{bmatrix}
X
+
\begin{bmatrix}
1\
0\
1\
\end{bmatrix}
Y
+
\begin{bmatrix}
0\
1\
1\
\end{bmatrix}
Z

\begin{bmatrix}
8\
8\
8\
\end{bmatrix}$

soft zealotBOT
#

Mehdi_Moulati

mellow cedar
#

the vectors (1,1,0) (1,0,1) (0,1,1) and (8,8,8) are not independent if you find a solution to this system of equations

raven bridge
#

ok, so we've got
$\begin{bmatrix}
X+Y\
X+Z\
Y+Z\
\end{bmatrix}

\begin{bmatrix}
8\
8\
8\
\end{bmatrix}$

soft zealotBOT
#

Trenek

mellow cedar
raven bridge
#

ok, so it seems that X=Y=Z=4

mellow cedar
raven bridge
#

indeed

mellow cedar
#

but those vectors (1,1,0) (1,0,1) (0,1,1) are independent

#

and you can prove it by the same method

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$\begin{bmatrix}
1\
1\
0
\end{bmatrix}
X
+
\begin{bmatrix}
1\
0\
1
\end{bmatrix}
Y

=
\begin{bmatrix}
0\
1\
1
\end{bmatrix}$

soft zealotBOT
#

Mehdi_Moulati

$\begin{bmatrix}
1\\
1\\
0
\end{bmatrix}
X
+
\begin{bmatrix}
1\\
0\\
1
\end{bmatrix}
Y

=
\begin{bmatrix}
0\\
1\\
1
\end{bmatrix}$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.78 
     
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```
raven bridge
#

ok, so
$\begin{bmatrix}
X+Y\
X\
Y\
\end{bmatrix}

\begin{bmatrix}
0\
1\
1\
\end{bmatrix}$

soft zealotBOT
#

Trenek

raven bridge
#

and this has no solutions

mellow cedar
raven bridge
#

so those vectors are independent

mellow cedar
raven bridge
#

ok, now I fully understand it

#

thanks a lot for your help 😊

mellow cedar
raven bridge
#

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tranquil bone
#

If $a_0 = 0, a_n = a_{n-1} + 3 \ \text{or} \ a_{n-1} -2$ what are the possible values of a_{100}

soft zealotBOT
#

Faq
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

tranquil bone
#

I got that the maximum is 300

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Minimum is -200

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But not sure how to proceeed

hybrid heath
#

Can you fix your tex?

tranquil bone
#

Wait why?

boreal bluff
#

$a_0 = 0 \text{ and } a_n = a_{n-1} + 3 \text{ or } a_n = a_{n-1} - 2$

soft zealotBOT
tranquil bone
#

Yeah that’s what I said

hybrid heath
#

Oh I only saw the compile error. I didn't know the bot allowed fixing it

boreal bluff
#

so I believe you have 100 different "slots" each of which are either 3 or -2

#

if it's all 3, then you have 300

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all -2, you have -200

tranquil bone
#

Yep

boreal bluff
#

so if a is the number of 3's, b is the number of -2's, you're solving for a + b = 100 right?

grim nebula
#

you can trade them in multiples of 5

robust mulch
#

Yeah

tranquil bone
#

Yeah right

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So the possible values are

robust mulch
#

If you switch one from -2 to +3, its like adding 5

tranquil bone
#

5n

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nbetween -40 and 60

robust mulch
#

Ye

tranquil bone
#

Inclusive

boreal bluff
#

I guess that's one way of doing it too

#

with a + b = 100 you can think of 100 balls separated by a line, and there are 101 slots the line can go in

#

think a + b = 5, you have balls (O) separated by line (/)

/ O O O O O
O / O O O O
...
O O O O O /

the no. of balls to the left of the line is a, no. of balls to the right is b

grim nebula
#

3a - 2b given the constraint a + b = 100 is 5a - 200

tranquil bone
#

Tbh I have no clue what you’re talking about

#

I think I’ll leave it here

#

Thanks

#

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trim jolt
#

Small follow up question, i posted a question earlier and received answer:

Q: Im trying to show a row given by b_n = (3n+1)/(n+2) converges. I know the definition and how to apply it when the limit is already known. But we havent done an example in class for when the limit is unknown. Im not sure how to tackle this

A: plug large values of n into a calc and guess the limit

I was wondering whether i could guess the limit by defining a function from R-->R given by b(n) = (3n+1)/(n+2) and applying the limit as defined in calculus to guess the limit for my row.

trim jolt
#

I think it should be okey since "guessing" isnt all that formal so yk why not use calc, but i cant show that the limit of the function is always a good guess for the limit of the row

dusty harbor
#

just look at the largest powers of n

worldly vale
#

are you required to use an epsilon-N proof?

trim jolt
dusty harbor
#

for large n its practically 3n/n = 3

trim jolt
#

wait nvm

#

im not sure if do? Im supposed to apply the definition of the limit of a row

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which is an epsilon definition

#

i can type it out if thats necessary

worldly vale
#

not sure what you mean by "of a row"

dusty harbor
#

sequence

trim jolt
#

Oh sorry in english its a sequence

worldly vale
#

ah gotcha

dusty harbor
#

in dutch a direct translation would also be row

worldly vale
#

well if you have to use epsilon-N then you need to figure out the limit by other means (algebra of limits) or long term behaviour like what Gijs said and then do an epsilon-N proof with that value

trim jolt
#

So calculus wont suffice for a guess for a candidate limit

worldly vale
#

well you need to know what the limit is to use the definition

#

so im not sure how you'd use the definition to guess a limit

trim jolt
#

just take the limit for n to infinity of the function b(n). b(n) being a function from R to R given by b(n) = (3n+1)/(n+2)

#

then you have a candidate limit and can prove it using epsilon-N

worldly vale
#

theres no need to consider it as a function

#

just find the limit of the sequence in any way you know how

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for example dividing the top and bottom by n

trim jolt
#

Hmm okey, that follows from the algebra of limits then?

#

specifically that the limit of the qoutient of two sequences is the limit of the dividend divided by the limit of the divisor

worldly vale
#

yes as long as everything converges

#

limit of quotient is quotient of limit

#

limit of sum is sum of limit

trim jolt
#

But then dont i have to prove that the numerator and denominator are sequences aswell

trim jolt
worldly vale
trim jolt
#

No but thats not the issue, i can see and i know that the limit is 3. Im just asking about how to guess that as a candidate.

Where im stuck is that, if i divide the top and bottom by n, im implying that both the numerator and denominator are sequences. Dont i have to prove that before i can divide by n?

worldly vale
#

why would you have to prove anything before dividing by n?

#

(3n+1)/(n+2) on its own is just an expression, we can do what we want to it

trim jolt
#

Can i claim its still the same sequence then?... We've never really defined operations on sequences in class.

#

But ig we defined them as functions so that works

#

But still, then id have to plug in large values to estimate the limit. Imagine i had a differrent sequence say a_n given by 1/a. Then i cant use the algebra of limits to guess a limit.

#

Using calculus for the function a: R-->R: a-->1/a i can guess a limit tho

#

Okey i think im just going to far with this. I'll rethink it tommorow when im not so sleepy haha

#

thanks for the help!

#

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rare glen
final saddleBOT
fallen reef
rare glen
#

English

#

我只会说英语

final saddleBOT
#

@rare glen Has your question been resolved?

rare glen
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vestal kestrel
#

hi

final saddleBOT
vestal kestrel
#

how to go from top to the bottom one?O.o

torn thicket
#

I don't know that exactly but u can factor our x^2 and get the same answer

vestal kestrel
#

thats the way i understand

#

no idea how the other one i supposed to work though :(!

#

also thank you

paper zodiac
#

You can do L'hopitals rule but this checks out

paper zodiac
# torn thicket

since he tried to factor out x^2, he was able to cancel it
Then it produced an equation with x as a denominator and anything divided by infinity is 0

#

So this one also checks out

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#

@vestal kestrel Has your question been resolved?

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heavy laurel
final saddleBOT
heavy laurel
#

The work for this might be this, right:

#

<@&286206848099549185>

vital crag
#

,w diff sqrt(x) sin(x)

heavy laurel
hearty zephyr
#

it's the same

heavy laurel
#

So for a problem like this, I’d use chain rule?

hearty zephyr
#

yes

heavy laurel
#

For a problem like this, I know my f(x) and thus also my f’(x), but how do I get my g(x)..?

#

Anyone?

heavy laurel
hearty zephyr
#

g(x) is the inside function

#

you have root(g(x))

heavy laurel
#

So 5x^2+4x+2? is the g of x?

hearty zephyr
#

yes

heavy laurel
hearty zephyr
#

f(x) is root(g(x))

heavy laurel
#

🤔

heavy laurel
hearty zephyr
#

oh i see what you're asking

#

f(x) is root(x)

#

so f(g(x)) is your function

heavy laurel
hearty zephyr
#

to do chain rule you have an inside function and an outside function.

#

you have root(g(x))

#

the root( ) is the outside function

#

so when you take the derivative, you'll take the derivative of the root( ), leaving the inside function alone.
and then multiply by the derivative of the inside

heavy laurel
hearty zephyr
#

look through some of the worked examples there

heavy laurel
#

Why do we decide that it’s radical z?

hearty zephyr
#

it's the function 5z-8 was plugged into

#

f(g(x)) = root(5z-8)

heavy laurel
hearty zephyr
#

yes

heavy laurel
hearty zephyr
#

yes

heavy laurel
#

So it would be something like this?:

#

So it would be like this right?

#

Like, I’d my process here correct?

#

As in, I’d get 5x+2/(radical (5x^2+4x+2))?

final saddleBOT
#

@heavy laurel Has your question been resolved?

heavy laurel
#

<@&286206848099549185>

vital crag
#

,w diff sqrt(5x^2+4x+2)

vital crag
#

yup

final saddleBOT
#

@heavy laurel Has your question been resolved?

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heavy laurel
#

How would I solve this?

final saddleBOT
surreal elbow
#

so here

#

it gives you f(0) = 0

#

and its asking for the derivative of the total composition derivatigve

#

try substituting 0 in for x in the composition and see what you get

#

so you'll have f(3f(4f(0)))

final saddleBOT
#

@heavy laurel Has your question been resolved?

heavy laurel
#

And f(0)=0, therefore I’d get f(3f(4(0)?

heavy laurel
surreal elbow
#

yes

#

and then you have f(3f(0))

#

and then what?

heavy laurel
surreal elbow
#

and then.. ?

heavy laurel
surreal elbow
#

and you are given the derivative at x = 0

heavy laurel
surreal elbow
#

👍🏿

#

wrong emoji 😂

#

sorry if I didn't explain it well

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half marsh
#

hey i need help

final saddleBOT
grim badger
# half marsh hey i need help
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.```
half marsh
#

4 8/8 - 9 8/8 =

grim badger
#

That's terribly typed. Can you present the question better?

remote cargo
#

I need help

south vine
#

asking for help in every channel wont help

grim badger
half marsh
final tangle
#

eights or eighths

half marsh
#

eights]

half marsh
final tangle
#

several people are attempting to assist by getting clarification of your question

#

eight: 8
eighth: 1/8
which one is you question saying

half marsh
#

eight

grim badger
#

Can you post an image of the question you are asking?

half marsh
#

6/2 - 1/2

final tangle
#

image

#

none of your expressions / descriptions resemble each other

grim badger
#

You just presented 3 different expressions when people were asking you for clarification

final tangle
#

are you spamming us with multiple questions

half marsh
#

oh srry

#

no am tryna help myself

#

uk what nvm

final saddleBOT
#

@half marsh Has your question been resolved?

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tranquil pine
#

this is gonna make me seem stupid but can someone please explain calculus to me

supple copper
#

basically don’t forget +C KEK

#

do you have a specific question?

tranquil pine
#

so like

supple copper
#

I’m taking calc rn

tranquil pine
#

i dont know anything about calc

#

im not really a jock

#

but also yeah

#

i dont understand the concept

supple copper
#

I mean calculus has so many concepts

#

wdym “the concept”

tranquil pine
#

i dont know where to start

#

with learning it

supple copper
#

oh

#

well the first unit is limits

#

so it may be a good idea to start learning that from khanacademy or something

#

if you’re trying to self learn

tranquil pine
#

ok dude thanks

#

i just got a shit ton of stuff on my plate

supple copper
#

yeah np

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quick bronze
#

Ok one more question I swear

final saddleBOT
quick bronze
#

(56)I'm pretty sure it's right but if it's not I'm screwed

violet widget
#

your method is good

#

but I don’t have a calculator with me to check

quick bronze
#

Yk that's good enough for me

#

The method is all that matters atm 😁

#

Tyy

#

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dark crest
#

help

final saddleBOT
dark crest
quick bronze
#

Ok so m is parallel to m

dark crest
#

okok

quick bronze
#

And they are being intercepted by the same line

#

So a good way to start would be to find the angle like to the right yk right next to the one which is 142°

#

(It's been so long I forgot the names)

dark crest
#

ok

#

<@&286206848099549185>

raw adder
#

can someone check me on this adjacent angle of 142 is 180-142 = 38 since they are linear pair

dark crest
#

make ur own chat

#

lmao

raw adder
#

x = 38 because alternate angle

dark crest
#

o

#

my b

#

i also need help on a few more

raw adder
#

and again solving for y we get 180-38(linear pair) = 142

dark crest
#

i thought u were asking for someone elses herlp here

#

sry

quick bronze
#

Oh well u got it?

dark crest
#

@raw adder

quick bronze
#

Ok so same process as the other, because they are parallel and being intercepted by the same line

#

They are like corresponding angles or whatever they are called

#

Y is a vertical angle to 59° so that will be the same

#

x is a special angle and will also be the same as angle 59°

dark crest
#

so do i just ad thosre two

#

i dont get it

#

bro

#

.close

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tranquil pine
#

An upside down conical container has 1L of water in it, the water is 15cm deep in the container.
How high will the water level be if another 1L is added to the container?

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

.close

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whole ermine
final saddleBOT
whole ermine
#

<@&286206848099549185>

#

<@&286206848099549185>

stoic mural
#

what have you tried?

#

@whole ermine

#

which step are you struggling with

#

also dont ping helpers before 15 minutes

#

and if you do, only ping once

#

@whole ermine
you there?

#

alright, i got to go
before i go let me give you some hints:
1)
rewrite the left hand side as a sum
2)
prove it for n=1
3)
now look at n+1
on the left we will have a sum from i=1 up to n+1
rewrite this sum by pulling out the last term, the one with i=n+1
that will give you a sum from i=1 up to n, for which we already proved it, thus we can substitute something in
then show equality by rearranging

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stark apex
#

Determine the exact values of the six trig function values for the angle Ø where the terminal arm of Ø in standard position extends through (-7,1)

stark apex
#

help what does this mean

#

.close

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lethal totem
#

kinda dumb question

final saddleBOT
lethal totem
#

let's say you have 4 teams in a tournament and you want each team to play each other team exactly once

#

how do you approach this from a combinatorics perspective

flint mist
#

Idk wtf combinatorics is but u can just

#

Lemme draw it out

lethal totem
#

is the correct calculation just:
(4-1) + (4-2) + (4-3) + (4-4)

flint mist
#

Hang on

#

There would be 6 games

lethal totem
#

Matches for A: B,C,D
Matches for B excluding A: C,D
Matches for C excluding A and B: D
Matches for D: (none)

#

yeah that checks out

#

so in general we could just say

flint mist
lethal totem
#

ooh

#

thanks for that that's actually very helpful

#

it did not occur to me to treat this geometrically

flint mist
#

does it answer ur question

lethal totem
#

so now we have transformed the combinatorics problem into a geometry problem. so just the number of side lengths of an n sided polygon plus the number of diagonals

flint mist
#

im not sure what ur tryna calculate rn lmao

lethal totem
#

so now the question is just how many diagonals a polygon has

#

i'm just trying to generalize here

flint mist
#

Wait

#

I have an idea

flint mist
#

or at least it could be yk

lethal totem
#

$\sum_{k=1}^n (n-k) = n^2 - \frac{1}{2}(n)(n+1)$

soft zealotBOT
#

Mr. Gamer

lethal totem
#

ok there we go that's the formula

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#

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whole ermine
final saddleBOT
whole ermine
#

Hi can you tech me how to solve this

finite hound
#

induction looks reasonable

whole ermine
#

can you explain how to do the step?

finite hound
#

well what do you have so far?

whole ermine
#

i dont understand it

#

so i cant do

finite hound
#

can you be more specific on what you don't understand?

whole ermine
#

the questions

finite hound
#

do you know what induction is? is there another method you're being asked to use to prove it?

whole ermine
#

my madam said we need to do the calculation, but idk how

#

can you explain to me or not?

finite hound
#

i mean it doesn't really look like you've thought about this problem much so far

#

i am happy to explain, but you have not given me much context on what you do know or what you think you may need to do to prove it

whole ermine
#

assume that P(k) was true, then would proceed to show that P(k+1) must also be true too?

#

like that or how

finite hound
#

yes, that is induction

whole ermine
#

.closed

vital crag
#

.close

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west brook
#

Can someone tell me how this can be a one-one function?

tranquil pine
#

if g(x1) = g(x2) implies x1=x2 only then g(x) will be one-one

final saddleBOT
#

@west brook Has your question been resolved?

west brook
#

If so, how do I solve the equation with that

tranquil pine
#

some terms will get cancelled

#

like x1x2

west brook
#

(4x1 - 7) x (2x2 + 3) right?

tranquil pine
#

maybe we can simplify the function

#

g(x) = 2 -13/(2x+3)

#

2-13/(2x1+3)= 2-13/(2x2+3)

#

then you get

#

2x2+3 = 2x1+3

#

x1=x2

west brook
#

Thankss

#

.close

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hard mist
#

How does this derivative get 'simplified' ? Where does the 8 suddenly come from?

hard mist
#

^ This is 'simplified'

worn mortar
#

do you know all the derivative rules?

hybrid heath
#

Have you tried working out the derivative at all?

hard mist
#

Ah, I see now, the ^3 gets distributed between num and denom

hybrid heath
#

Are you familiar with chain rule, product and quotient rules?

hard mist
#

Yea i am, simply overlooked something lol

#

.close

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wanton sentinel
#

does taking a derivative here affect the 1/2?

hybrid heath
#

nope

#

constants are unchanged

final saddleBOT
#

@wanton sentinel Has your question been resolved?

wanton sentinel
#

derivative of a constant is 0

worldly vale
#

Differentiation is a linear operation, it doesn't matter if you times by a constant before or after differentiating

#

You can "pull the constant out" of the derivative

wanton sentinel
#

how

#

ik that when differentiating a constant we replace it with a zero

wanton sentinel
worldly vale
#

Doesnt matter what the function is

#

What's the derivative of 5x²?

wanton sentinel
#

ah i seee

#

constants are zero if they are alone?

worldly vale
#

Yes which is 5(2x)

wanton sentinel
#

1+x for example

worldly vale
#

Yes the derivative of a constant is zero

#

But obviously 5x² is not a constant

#

Nor is a constant times ln(2x+1)

wanton sentinel
#

yes yes i got it now

#

so whenever there is a constant multiplied i can just put it out of the differentiation

worldly vale
#

You can indeed

wanton sentinel
#

Alright thanks

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#

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worldly vale
#

.close

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tiny forge
#

$\int \frac{2x+1}{x^2-1}$

final saddleBOT
soft zealotBOT
#

Derek ♡

slow tapir
#

split numerator

#

2x/x^2-1 is f'(x)/f(x) = log(f(x))
1/x^2-1 is direct formula 1/2(log(x-1)/(x+1))

tiny forge
#

why on sloving partial fraction and doing simply give diffrent answers

tiny forge
slow tapir
#

bro its integrals

#

diff ans is ok

#

unless they are incorrect

tiny forge
#

ohh

final tangle
#

expressions may differ by a constant

tranquil pine
#

Rational exponent anyone

tiny forge
#

i think they are diffrent

final tangle
#

show work

tiny forge
#

lemme show you my answer and what i need

#

this is what is required

slow tapir
#

ah they did by partial frac

tiny forge
#

and i am getting log |x^2 -1 | + 1/2 log (x-1)/(x+1)

tiny forge
final tangle
#

solution shouldn't have that x^2/2 in there

tiny forge
#

ohh ignore that

#

x^2/2 is from another part of question

final tangle
#

and then log laws should get something equivalent

tiny forge
#

i tried

final tangle
#

prod to sum
and quotient to difference

tranquil pine
#

I was wondering what topic is that

final tangle
#

logs

#

which is a pre-requisite for calculus

tiny forge
#

yeah ik that

#

coefficient goes to power

#

and that stuff

#

but if i solve just by splitting terms is my answer right?

#

why to overthink catThin4K

#

.close

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heavy lichen
#

Hello, can someone please help me understand why this result is true ?

heavy lichen
tranquil pine
heavy lichen
#

Sure

heavy lichen
#

"Définie par" means defined on

#

I’m fairly sure i have the right expression but i don’t really understand the logic behind it.

tranquil pine
#

well this is just chain rule isn't it

heavy lichen
#

Oh shit i think i got it

#

Yeah got it lets goooo

#

.close

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keen haven
#

I am once again asking for help

final saddleBOT
wise crescent
#

yo @keen haven

#

jack can read 5 novels in 1 month

#

so the number of novels = N
number of months = M

so we get N = 5M

final saddleBOT
#

@keen haven Has your question been resolved?

keen haven
#

Kariok

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keen haven
#

Thank you

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tranquil pine
#

where did they get tan60 from the equation? i recognize that tan60 = sqrt3 but im not sure how i can get to that

unique aspen
#

@tranquil pine

tranquil pine
#

hi

unique aspen
#

you need to post the question or we don't know what's going on

tranquil pine
unique aspen
#

yeah so if t is the angle BAC

#

then tan(BAC) = BC/AC

#

opposite over adjacent

tranquil pine
#

uh huh

unique aspen
#

like, BC is opposite to the angle

#

and AC is adjacent

#

so yeah

tranquil pine
#

yes i get that part but then they get sqrt3

#

and then get tan60

unique aspen
#

yes

tranquil pine
#

how do you go from sqrt3 to tan60

unique aspen
#

BC = 12sqrt(3)

#

AC = 12

#

BC/AC = sqrt(3)

#

so tan(BAC) = sqrt(3)

#

then if tan of an angle is sqrt(3) and the angle is less than 180, the angle has to be 60 degrees

#

this is just a fact

tranquil pine
#

i see so i just need to know it

unique aspen
#

there's like certain very common values of sin, cos, tan

#

yeah

#

so it goes

tranquil pine
#

got it

#

thank you ♥

#

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tranquil pine
#

Integration of e^4x

final saddleBOT
tranquil pine
#

Or 4

#

Is it 4x on the deno

ashen shadow
#

Oh sry it was integration

tranquil pine
#

Yes

#

It's fine

ashen shadow
#

Only 4

#

Not 4x

cloud zephyr
tranquil pine
ashen shadow
cloud zephyr
tranquil pine
#

Thank u

ashen shadow
tranquil pine
#

.close

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humble jay
#

Help

final saddleBOT
humble jay
#

How would you write the prove to this?

#

A EQUIVALENT A

#

Equivalent being denoted by the three line equals

worldly vale
#

What are you even asking

humble jay
#

How would you write the mathematical prove for this statement

#

A|=A

#

Im assuming this. I say if A equivalent to itself then it can be said that A is a logical consequence of it self. 🤔

desert mantle
#

well on what level are you doing logic

#

this is either trivial or might be pretty hard

humble jay
#

I think it's trivial I'm probably over thinking it and just confusing myself

#

. Close

#

.close

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south prawn
#

can someone help me with this please

final saddleBOT
south prawn
#

To carry out a repair on the fifth floor, a plumber wants to bring up a 3 m pipe with the elevator.

The lift is 1.5 m by 1.75 m and 2.2 m high. Will the plumber succeed?

Make a drawing on paper and write the dimensions.

#

they want me too do something like this

#

any help please

alpine yacht
#

so basically they are asking if the diagonal of a rectangular prism with side lengths 1.5, 1.75, and 2.2 is greater or equal to 3 or not.

#

The formula for the length of the diagonal $d$ of a prism with side lengths a,b,c is $d=\sqrt{a^2+b^2+c^2}$ (3D distance formula)

soft zealotBOT
#

FireBlazer

alpine yacht
#

@south prawn Do you know how to continue?

south prawn
#

uhm

final saddleBOT
#

@south prawn Has your question been resolved?

south prawn
#

so

#

what id have too do

#

d= v-(1,5m^2 . 1,75^2 . 2,2^2)

south prawn
#

is that correcty

#

?

cloud zephyr
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tranquil pine
final saddleBOT
tranquil pine
#

for part b

#

i could to -2i +4j + 7k + lambda(AB) or -1i +3j + 8k + lambda(AB), right? (where lambda is just a scalar)

#

the answer only gives the latter

tranquil pine
#

just wantot make sure

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#

.close

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vagrant wigeon
#

Can anyonw help me

final saddleBOT
vagrant wigeon
#

Prove it when a + b = 90°

#

<@&286206848099549185>

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@vagrant wigeon Has your question been resolved?

vagrant wigeon
#

<@&286206848099549185>

final saddleBOT
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@vagrant wigeon Has your question been resolved?

vagrant wigeon
#

, , \frac {sin\alpha + sin\beta} {sin\alpha} = tan\alpha + 2tan\beta

soft zealotBOT
vagrant wigeon
#

<@&286206848099549185>

vital crag
#

Plug in beta = 90-alpha and use sum/difference formula

vagrant wigeon
#

i cannot understand

vital crag
vital crag
vagrant wigeon
soft zealotBOT
vagrant wigeon
#

what after it

vital crag
#

I'd work on the right side actually

vagrant wigeon
#

hmm then

vagrant wigeon
#

?

soft zealotBOT
vital crag
#

Right. You just need to express tan in terms of sine and cosine and then use difference angle formula

vagrant wigeon
#

wait lemme do

#

, , \frac {sin\alpha + sin\beta} {sin\alpha} = \frac { sin\alpha } { cos\alpha} + 2cot\alpha

soft zealotBOT
vagrant wigeon
#

see @vital crag

#

, , \frac {sin\alpha + sin\beta} {sin\alpha} = \frac { sin\alpha } { cos\alpha} + 2 \frac { cos\alpha } { sin\alpha}

soft zealotBOT
vagrant wigeon
#

now ?

final saddleBOT
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merry ridge
#

Given that P(A)=0.8 , P(B)=0.6 and P(AANDB)=0.40 . Are the events A and B independent?

trail lance
#

Because I got 0.48 for P(A and B)

merry ridge
trail lance
#

so they’re dependent

merry ridge
#

i got that too

#

this is a practice question

#

and im confusd

#

so y is it dependednt

trail lance
#

If they independent, then the probability would’ve been 0.48

#

But the question gave 0.4

merry ridge
#

ohhhh

#

one more question

#

this would be dependent right

#

since its 1/20 then 1/19

#

or wait

#

it would be independent since its replaced right?

trail lance
#

the probability for each turn would be the same

#

because it’s teplaced

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white rock
final saddleBOT
white rock
#

can i get help please i dont understand this

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white rock
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.reopen

final saddleBOT
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white rock
#

please help me

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twilit brook
#

Hi

final saddleBOT
twilit brook
#

In the picture i got a math solution for finding a impedance i wanna know why they used z1 =Xc//Xl and Z3 =Z2//xc i know what these letters stand for but can someone explain why they use this?

#

The Z1=Xc//Xl for example is shortened for (Xc*Xl)/Xc+Xl)

final saddleBOT
#

@twilit brook Has your question been resolved?

twilit brook
#

<@&286206848099549185>

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jovial wigeon
#

A connected graph with N nodes has at least N-1 edges. Does that imply that a non-connected graph with N nodes has at most N-1 edges?

jovial wigeon
#

my brain isn't braining anymore

hearty zephyr
#

it doesn't tell you anything about a disconnected graph

jovial wigeon
#

ah

#

glad i asked then, i was heading the wrong direction

#

thank you!

cobalt lodge
#

degenerate example: 3 nodes, and 50 edges between the same 2 nodes

jovial wigeon
#

i see, what if we restrict ourselves to simple graphs (no multiple edges)?

cobalt lodge
#

or a less stupid example for simple graphs: 5 nodes, 4 of the nodes form a complete graph K4 with 6 edges

jovial wigeon
#

makes sense, tyvm!

#

.close

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agile tangle
#

Heyy.

final saddleBOT
agile tangle
#

So I came to show my work for a answer, I know I could just calculate but I don’t have a calculator on my phone plus I can’t download it since don’t remember my AppStore password but here is my work.

#

Is this true?

magic gyro
#

Hmm let me check

#

,w 84 times 6

soft zealotBOT
magic gyro
#

yeah

agile tangle
#

oh mk ty

grim badger
agile tangle
grim badger
#

Yes, and?

agile tangle
#

I have a milestone benchmark practice next week.

grim badger
#

You do the problem like what you did and use google to check your answer

agile tangle
grim badger
#

Yes, and? Like I stated, you can do the work on your own, get some answer, then use a calculator to check

#

If you get what the calculator gets, then the work is correct

#

If it's different, either you typed it into the calculator wrong or you did the math wrong

agile tangle
#

Sorry, I don’t do that plus like I said I have a millestone benchmark graded practice next week and I can’t just calculate it I rather show my real work. discussion ended.

grim badger
#

Yes, and?

frigid sierra
#

what dldh is saying is that u can do ur own work

#

but to check if ur answer is right or not

#

use a calculator

#

it’s just for checking

agile tangle
#

k I’ll do that.

frigid sierra
grim badger
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timid tulip
#

Need a alternative to differntiation

final saddleBOT
vital crag
#

why can't you use derivatives

#

oh number of turning points

#

what's a turning point? local min/max?

timid tulip
#

both

#

also its coz i need to work it out to check if the roots of the derivative are real so

#

there's a lot of time thats wasted

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tawdry cloak
#

hey

final saddleBOT
tawdry cloak
#

if for a poission random variable Xn, the parater is lambda, what is the parameter for X^2 n l

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#

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jade shale
final saddleBOT
#

Please don't occupy multiple help channels.

dry light
#

I was just gonna reply to your tangent line question but then you closed it

#

And then it locked me out

jade shale
#

oh

#

i can also drop it here

#

it was an hour ago so i figured no1 was answering it

dry light
# jade shale

This one here I'm pretty sure you can find dp/dq and then raise everything to the -1 power

dry light
#

Implicit moment

jade shale
#

do i just

#

inverse it

dry light
#

Yeah

#

Well

jade shale
#

oh thx

dry light
#

Not inverse it

jade shale
#

never thought of that

dry light
#

Take the reciprocal

jade shale
#

yeah thats what I meant

jade shale
dry light
#

Chain rule

#

With quotient rule

jade shale
#

sec lemme try

dry light
#

Lmk what you got when you differentiate only e^(x/y)

jade shale
#

e^(x/y)(y-xy')/y^2

dry light
#

Yeah

jade shale
#

and on the other side i have 1-y'

jade shale
#

then i just plug the point in right?

dry light
#

Yes

jade shale
#

2

#

y=2x-1

#

yeah thats the answer

#

Thanks for the hel

#

help

#

appreciate it

#

.close

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ashen shadow
#

How many solutions a polynomial will have if it's degree is -1

amber holly
#

You mean the amount of solutions to a + b/x = 0?

ashen shadow
#

Yes you could say but not specifically a+b/x I was talking about any type of polynomial with highest power 1 and unique power -1

amber holly
#

So ax + b + c/x = 0?

ashen shadow
#

1/x=0

amber holly
#

1/x = 0 has no solutions

ashen shadow
#

But why?

ashen shadow
#

,w plot 1/x

soft zealotBOT
amber holly
ashen shadow
ashen shadow
amber holly
#

Then you'd be able to multiply both sides by x

#

Because x is nonzero

ashen shadow
#

Hm

amber holly
#

If it was zero, then 1/x wouldn't exist

#

So we're able to multiply both sides by x