#help-36

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steel gale
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i know you probably have to use factorials here but i dont know how to

steel gale
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formulate this

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the consonants can be arranged in 5! ways

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the vowels can be arranged in 4! ways

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but i dont get how to apply the whole

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vowels cant be next to each other

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c_c_c_c_c_

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so 6

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possible places for vowels to be

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sorry im just saying whatever i can think of

trail mango
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there are 4 vowels, so the structure of the word will be like V_V_V_V with 2 extra _ inserted between or before any of those 7 positions

robust mulch
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have you ever heard of stars and bars?

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layla's method also works

grim nebula
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i think it should rather be like

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_C_C_C_C_C_

steel gale
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okay so

grim nebula
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and you fill in the holes with vowels

steel gale
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thats what i was thinking but it doesnt really seem to matter

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either way should work right

grim nebula
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there is a difference

steel gale
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so

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then

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oh

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um

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in that case

grim nebula
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its possible to have VCCVCVCVC for example

steel gale
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so then i have to account for

trail mango
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wouldn't that come up with my method?

grim nebula
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would it

steel gale
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V_V_V_V and C_C_C_C_C_

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thats just

grim nebula
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your holes need to be filled with either 1 or 2 consonants

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not as straightforward to count i think hmmCat

trail mango
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I may not have said it very well

steel gale
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its fine i appreciate the help

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so then in that case

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the different

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the consonants can be arranged in

trail mango
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the _ was supposed to represent positions filled by constants

steel gale
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the vowels can be arranged in 6C4

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ways?

trail mango
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V _ _V _ V _ V _ would be considered

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it's V_V_V_V with 2 _ added in somewhere

steel gale
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seems easier to work around with consonants then

grim nebula
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so ig its more like

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__VC_VC_VC_V__

steel gale
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the last one has to be a consonant too, right?

trail mango
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does that not count double constants at the end?

steel gale
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im -

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kinda lost

grim nebula
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should probably put another _ then

steel gale
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to nbe honest

grim nebula
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pick one of the ways you want to count it

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then go from there

steel gale
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it seems easier to work around consonants

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so then yeah the vowels can be arranged in 6C4 ways right?

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along with

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4!

grim nebula
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yes

steel gale
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so 6C4 x 4! ?

grim nebula
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dont forget to arrange the consonants too

steel gale
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ah

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yes

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so then x5!

grim nebula
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yeah

steel gale
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okk thank you guys

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final saddleBOT
spring lava
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Let's take the question one sentence at a time

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For the first sentence we have a farm that's split into 3 pieces for 3 people

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Afterwards we read that John's part is equally divided into 3 for his children

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Im pretty sure if paul sells his it wouldnt matter as all of them are being sold in the end,

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Jim owns 1/3 of the property but that isnt the common fraction

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it's simplified down to that but if common fraction means you need to have it equivalent to everyone elses you need to find a common denominator

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so jim would own 3/9 of the property

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@tranquil pine does this help?

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jovial ermine
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Hello, I would appreciate any hints to solve the following question. I'm unsure how to start.

Need to work out the pdf and cdf using the variables.

Thank you!

coarse yacht
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Write $F_{e^{X}}(x) = \mathbb{P}(e^{X} \leq x)$

soft zealotBOT
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black_couscous

coarse yacht
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Then describe this set $ (e^{X} \leq x) $

jovial ermine
coarse yacht
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No $X$ is a random variable and $x$ is a real number. If you want you can chose $y$ instead of $x$ to make things clearer.

soft zealotBOT
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black_couscous

jovial ermine
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ok and because of the sign '≤' this is the cdf right? if so then i guess for the pdf it would be just <?

coarse yacht
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For the PDF it's different

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Let's focus on the CDF first because it's easier

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Try what I told you and then come back for the pdf

jovial ermine
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ok

jovial ermine
coarse yacht
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Like $X$ is a rv that goes from a universe to the real numbers

soft zealotBOT
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black_couscous

coarse yacht
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And the probability is a measure of sets

jovial ermine
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hmm is that like the range of values which rv can take? if so then after writing the cdf I should describe its range of values?

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I just wrote these

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I suppose for the pdf I need a way to express adding all the individual probabilities being added.

jovial ermine
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muted basalt
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how do I find the inverse?

final saddleBOT
muted basalt
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The answer I keep getting is (-x-5)/2(x-1)

tranquil flume
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f(x)=y right?

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Swap x and y

muted basalt
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yeah but when I put it in an oline calculator I get somethin else

tranquil flume
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Then make y the subject

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What did you out in?

muted basalt
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it gives me (x+5)/2(1-2x)

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I dunno If I have to like factor the negative out or If mine is technically right

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here a picture of my work

tranquil flume
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Bot correct

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Both

muted basalt
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Oh alright thanks lol

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opaque herald
final saddleBOT
opaque herald
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stuck on how to start

tranquil flume
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Make x the subject in the first, z the subject ok the second and then plug in them to x/z to solve

opaque herald
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wdym

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by subjey

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subject

tranquil flume
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Isolate x

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Like x = 9y/7

opaque herald
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ohhh

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then isolate z?

tranquil flume
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Yeah

opaque herald
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then just put both inthe teh fraction?

tranquil flume
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Ye

opaque herald
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how do i isolate z?

tranquil flume
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What do you think

opaque herald
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could i cross multiyplu?

tranquil flume
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Yes obviously

opaque herald
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ohh alr

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z=5y/7?

tranquil flume
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I call this algebraic manipulation

tranquil flume
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See

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It's easy

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Don't be shy

opaque herald
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can I cancel the 7's in the denonminator before putting into frction

tranquil flume
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Yes

opaque herald
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and for htiss idk why b is wrong?

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since II would invovle squares woulndt it

tranquil flume
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Hmm not sure about this one

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Are these even statements?

opaque herald
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probably?

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since 0<x<3 is just -5<x-5<-2 simplifed so their the same

tranquil flume
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Do you have the correct answer

opaque herald
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but II is going to end up with x^2-3x<0

opaque herald
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could brute force but i only have 1 reminaing attempt

tranquil flume
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What topic is this from if I may ask?

opaque herald
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uhh inequalities and stuff?

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but some is review

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algebra II honors

tranquil flume
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OOHH

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wait

opaque herald
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waiting

tranquil flume
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In x(x-3)<0 there are quite a few possiblies

opaque herald
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there are?

tranquil flume
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So the product of x and x-3 has be negative right?

opaque herald
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maybe?

tranquil flume
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You get negative when: - times + and + times -

opaque herald
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yeah but the x^2 couldbe smth else

tranquil flume
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[x < 0 and x-3>0] or [x>0 and x-3<0)

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So far good?

opaque herald
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yeah ig?

tranquil flume
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So..

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[x<0 and x>3] or [x>0 and x<3]

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[False (makes no sense)] or [0<x<3]

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Which is 0<x<3

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So all of them are equal

opaque herald
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ohhh

tranquil flume
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Sorry for terrible explanation

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I used the logical equivalence method

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Because it's what I am learning currently

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Plenty of easier methods probably

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So the answer is D

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Unless they are sick and twisted and set E as correct

opaque herald
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would thesse all be true tho?

opaque herald
tranquil flume
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My gut says E

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Becuss e

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a + b > a-b
<-> a-a > -b-b
<-> 0 > - 2b
<-> 0 < b

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@opaque herald you dead?

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Our comrade has fallen

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Rip

opaque herald
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but like, is a and b were option a, and a=2 b=1 the its stillwork

tranquil flume
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I don't understand

opaque herald
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might just try e tho

tranquil flume
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Try a=-3 and b=1

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Don't work for A

opaque herald
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worked ty

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but idk this? sorry for having so many 😭 auestions

tranquil flume
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y = a(x-p)(x-q) where p and q are roots you know this form?

opaque herald
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yeah i think, just never had the a

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ive done lkie (x-y)(x-p) and stuff like that

tranquil flume
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a is the coefficient of x^2 in the form ax^2 + bx + c

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So use that

opaque herald
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wait so i pu he entire thing infromt of x?

tranquil flume
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Huh?

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What is a here?

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It's clearly stated

opaque herald
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the (-1-√2)/3 ??

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but whats he p and q

tranquil flume
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HUHH

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I once again ask you that.look up quadratic intercept form

opaque herald
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or is x^2 the coeeficient

tranquil flume
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Sorry I'm a little bit drunk

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My man ballerinarata has passed away

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Yohojo

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@opaque herald you riding???

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MD??

opaque herald
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still confused

tranquil flume
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Oh no no

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Do you know

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a(x-p)(x-q)

opaque herald
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not really? idk

tranquil flume
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Otherwise google "quadratic slope intercept form"

opaque herald
#

that didnt help

tranquil flume
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I'm about to pass out

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Super drunk

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Peace ✌️

opaque herald
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idk how toplug things in or how touse it

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are p and q roots???

tranquil flume
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YES

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and a smis given as 1

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Cleanly

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So it can be invisible

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YOU GOR IT

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@opaque herald

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Do you still need helppp

opaque herald
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wait so i plug the 2 things the question gives in>

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and solve????

tranquil flume
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Yes

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Esau

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Peacy

opaque herald
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alr will do

tranquil flume
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Lemon

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Squeezy

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Any more questions

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Before I did

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Die

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@opaque herald

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MD MY MA

opaque herald
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porbably but goin to do his first

tranquil flume
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MAN

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I ain't got eholee dayyyyy

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MDddddd is myyyy fiaaanncceee

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clutch

opaque herald
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are you alright lol

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im stuck here

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ill be back after i eat smth

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<@&286206848099549185>

final saddleBOT
#

@opaque herald Has your question been resolved?

opaque herald
#

.close

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flat tangle
#

Given the function y = 2x3 – 3x2 – 5x + 1, which finite differences will be equal (or constant)?

spiral quail
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What does finite difference even mean??

flat tangle
#

like would it be the third difference or fourth ?

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@flat tangle Has your question been resolved?

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static jungle
#

why does x + |ax + b| = k have one value for k

sweet summit
#

can you elaborate on what you mean?

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why would it have more than 1 answer?

static jungle
summer raptor
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no

static jungle
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for example in a normal modulation ax + b, ax + b = +/- k

static jungle
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okay i think i got it on my own

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basically it needs to work both ways

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k nvm

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modest canopy
#

Yo

final saddleBOT
modest canopy
#

I did bad on a test

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And I just wanna go over it

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75 - 3 times 7 to the power of 2 + 6 to the power of 3 divided by 12

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= -48 right

spiral quail
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Yo are u using PEMDAS as order of operations, or something else?

modest canopy
#

Pemdas

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Yeah

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Nvm

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Gotta go sleep

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See ya

#

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dreamy snow
#

can someone explain what this means

final saddleBOT
dreamy snow
#

someone explained it to be like

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but I'm so confused as to how they got -12x + 12 = 0

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and then how did the deduce that 100 items is maximum profit?

calm laurel
#

hello

dreamy snow
#

hi

calm laurel
#

@dreamy snow

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do you know how to do this?

final saddleBOT
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@dreamy snow Has your question been resolved?

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dull wadi
final saddleBOT
fossil geyser
#

For a dilation from the origin, just multiply all the coordinates by the scale factor

dull wadi
#

Ok

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So

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Is the A y 4?

fossil geyser
#

Yeah looks like A is (2,4)

dull wadi
#

And it's (6,12) dilated right?

fossil geyser
#

Yep

dull wadi
#

Ok

fossil geyser
#

You'd usually label the new point A'

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(A prime)

dull wadi
#

Yeah my teacher was saying something about that

fossil geyser
#

If you do it right, it should look like a scaled up version of the same triangle

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Same shape, just bigger

dull wadi
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Is B 1,2?

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Wait no

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4,3

fossil geyser
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Well, the y-coordinate is negative

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Looks to me like (4,-2)

dull wadi
#

Ohhh

fossil geyser
#

The graph is labeled in 5's but the grid lines are in 2's

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Kinda weird

dull wadi
#

So 12 -6 dilated

fossil geyser
#

yep

dull wadi
#

Imma finish the rest and I'll send a picture tell me if it's right

fossil geyser
#

You should plot and label those points A', B', and C'

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Then connect them to form the dilated triangle

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Wait

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B is not correct

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Didn't we say B is (4,-2), so B' is (12, -6) ?

dull wadi
#

Yeah I forgot to change that sorr6b

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Can you help me with a few more questions ?

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Please

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@fossil geyser

fossil geyser
#

Go ahead and post them. If I can't, somebody will

final saddleBOT
#

@dull wadi Has your question been resolved?

final saddleBOT
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@dull wadi Has your question been resolved?

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agile jacinth
final saddleBOT
half summit
#

what's the range of cosine wave

agile jacinth
#

1 and -1

half summit
#

yeah

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so what's the range of 8*cos wave

agile jacinth
#

8 n -8

half summit
#

mhm, velocity is 4 + 8cos 2t

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so it's 8 cos 2t shifted up 4

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so what would the range of that be?

agile jacinth
#

i just dont see how cos t can be substituted for 1 or -1

half summit
#

cos and son oscilliate between 1 and -1

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derived from the unit circle

agile jacinth
#

right

half summit
#

so what don't you understand

agile jacinth
#

sorry im just not seeing it

half summit
#

you didn't ask a question

half summit
#

idk what you mean by that

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and it's not a question

agile jacinth
#

from my diagram

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they substituted cos 2t with 1 and -1

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so i dont get that part

half summit
#

yeah they just did that to illustate

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that it's the maximum and minimum

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-1 is the smallest value cos x can take

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so 4 + 8(-1) would be the miniumum

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and same thing for positive 1

agile jacinth
#

but if it was just to find the range of values of that eq

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what would the minimum value stand for

half summit
#

range is the just the values the velocity can take

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so the range is all the values between minimum velocity and maximum velocity inclusive

agile jacinth
#

i mean like if we ignore the velocity part

agile jacinth
half summit
#

range is the set of y values a function can be

agile jacinth
#

ok nvm im being dumb

#

thanks i get it now

half summit
#

👍

final saddleBOT
#

@agile jacinth Has your question been resolved?

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finite chasm
#

.

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,, y = x

final saddleBOT
soft zealotBOT
#

Off_set

finite chasm
#

,, y = x + 10 / 4

soft zealotBOT
#

Off_set

finite chasm
#

,, y = x + 4 // 2

soft zealotBOT
#

Off_set

finite chasm
#

.close

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wraith crater
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tranquil pine
#

How would the function, f(sqrtx) look like with a shift 2 units to the left and 3 units up? Also with a. Reflection over y axis

tranquil pine
#

Would it be -(sqrtx+2)+3

ionic glacier
#

yeah, with correct brackets, you're right

tranquil pine
#

Thanks

tranquil pine
ionic glacier
#

-[(sqrt(x+2))+3]

tranquil pine
ionic glacier
#

no, -a+b is not equal to -(a+b) because the latter is -a-b

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

It’s supposed to be inside because it’s a reflection across y

ionic glacier
#

ah i see, yeah, I misread it

#

so my equation is wrong, but so is yours

#

reflection across y axis only flips the negativity of x

#

so try to come up with the final answer

tranquil pine
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tranquil pine
final saddleBOT
ionic glacier
#

that's not true

tranquil pine
#

Should I add brackets

ionic glacier
#

how did you come to that conclusion?

tranquil pine
#

Because I since were reflecting y

#

We add a - outside of the

#

Parentheses

#

@ionic glacier

ionic glacier
#

can you write down each progression?

tranquil pine
#

Is it plus three?

#

Since it’s going left 3

ionic glacier
#

just write down each change and show me pls

final saddleBOT
#

@tranquil pine Has your question been resolved?

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tranquil pine
#

Find the tangent to the curve y=e^x + x^2 at x=2.

tranquil pine
#

I got y = 2(e^2 + 4)(x - 2)

#

But I feel like it's wrong

ionic glacier
#

how do you find the tangent?

tranquil pine
#

Derivative, then plug in x = 2 to find the gradient of the tangent at x = 2

ionic glacier
#

ok that's accurate

#

so what's the derivative?

tranquil pine
#

e^x + 2x

ionic glacier
#

ok that's correct too

tranquil pine
#

Then sub in 2

#

to get

ionic glacier
#

idk why you didn't get the correct answer at this point 🙂

tranquil pine
#

e^2 + 4

tranquil pine
ionic glacier
#

yeah that's the answer

ionic glacier
tranquil pine
#

yeah I knew it

#

lol

#

What I did was: I found the value of y by subbing in x = 2 in the original equation

tranquil pine
#

So then I used y-y1 = m(x-x1)

#

y-(e^2+4)=(e^2+4)(x-2), then solved for y to get y = 2(e^2 + 4)(x - 2)

#

@ionic glacier Could you tell me where my mistake is?

ionic glacier
#

y = kx + c

#

and when x =2, we know what y value is

#

then calculate c

#

because we already know k, it's possible to get c

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

thanks

final saddleBOT
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slate garnet
#

I figured out the zero, sin(x)=-4/5, but I don't know where to go from there

final saddleBOT
#

@slate garnet Has your question been resolved?

slate garnet
#

<@&286206848099549185>

final saddleBOT
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@slate garnet Has your question been resolved?

slate garnet
#

.close

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zinc fractal
#

Hi

final saddleBOT
zinc fractal
#

Did I do this correctly?

arctic kelp
#

ugh I hate proofs

#

suck at them

final saddleBOT
#

@zinc fractal Has your question been resolved?

zinc fractal
#

Same

granite walrus
#

It is the reflexive property

final saddleBOT
#

@zinc fractal Has your question been resolved?

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sweet summit
#

abstract algebra

final saddleBOT
sweet summit
#

I"m getting a bit stuck

silk wing
#

Is the red bit something you've written? A solution? What am I looking at?

sweet summit
#

it's just the set up

silk wing
#

What is the fundamental theorem in this context?

sweet summit
#

it's also called the 1st isomorphism theorem

#

basically that the quotient group $S_n / A_n \cong \mathbb{Z}_2$

soft zealotBOT
#

MellowDramaLlama

silk wing
#

Borderline offended by that, but okay

sweet summit
#

hmm?

silk wing
#

That's just a weird thing to call the 1st isomorphism theorem

sweet summit
#

oh yeah

#

that's my professor lol

silk wing
#

But the problem statement gives away the whole game

#

you know exactly what theorem to use

#

You need a map from G to Z/2Z that is surjective and has kernel K

sweet summit
#

right. So then our kernel would have to be the even permutations

#

but I'm not sure if I"m seeing the connection there

silk wing
#

connection between what and what? just want to make sure I understand exactly where the disconnect is

sweet summit
#

well according to the hint, all even permutation of S_n map to 0 in Z_2. I'm just trying to show that's the case, but I'm not sure how

#

other than just proclaiming it does lol

silk wing
#

Oh I see. The problem is that the text didn't actually define the homomorphism they're using

#

There's literally only one option, so maybe the author is just being a dick

sweet summit
#

if they elements are composed with themselves?

silk wing
#

But you need to send everything in the kernel to 0 and everything not in the kernel to not 0 for obvious reasons

#

but there's only one option fornot 0

#

so the map is completely determined

sweet summit
#

hmmm

zinc fractal
#

Srry

sweet summit
#

OH I THINK I SEE IT. Yeah if we do something like f((12)(12)) = f((12))f((12)), then f(()) = f(12)f(12)

silk wing
#

So the statement you're proving is "there exists a homomorphism from S_n to Z/2Z with kernel exactly A_n". This statement forces the definition of this homomorphism on you -- there is only one set map that can do the thing you want it to do. What you have to prove is that this is a homomorphism

sweet summit
#

so yeah the evens composed with themselves sends them to the kernel

#

oh okay

#

sorry I'm typing it out

#

okay I think I got the first justification down the fact that A_n = ker(f)

silk wing
#

Okay so the red is your solution. You never defined your homomorphism from S_n to Z/2Z. You can't just take "a homomorphism", you need to present a specific one that does what you wany

sweet summit
#

oh sorry first line

#

G = S_n

#

and (Z_2, +)is the same as Z/2Z I think

#

(and yes sorry red is my answer)

silk wing
#

You can't just say "let f be a homomorphism" because I will come back and say "okay let f be the map sending everything to 0"

#

then everything you say afterwards will be totally wrong

#

You need to point to a specific homomorphism and say "this particular function is surjective with kernel A_n"

#

your job is to define that function

sweet summit
#

oooh I see

#

okay

#

So how about something like if the permutation is odd map it to 1 and if it's even map it to 0?

#

like a piecewise function

silk wing
#

cool, that certainly has the correct kernel. But is it actually a homomorphism? You can only apply the first isomorphism theorem to homomorphisms

sweet summit
#

yeah I think so! To prove that we would need to prove that f(xy) = f(x)f(y) for x, y in S_n right?

silk wing
#

yup

sweet summit
#

hmmm

#

yeah I guess that works
if x and y are both even, then their composition is even, which maps to the kernel
if x and y are both odd, then their composition is even, which maps to the kernel
if x is odd and y is even (or vice versa), then their composition is odd which maps to not the kernel (lol)

#

...I think that works

#

so then f(xy) for example, if they're even would be 0 + 0 = 0

silk wing
#

you are correct. The idea is that homomorphisms to Z/2Z are sort of like identifying parity in your group

#

the same way odd + odd = even and even + even = even, etc

#

odd and even permutations have that same relationship, so they define a hom to Z/2Z

sweet summit
#

okay cool!

#

I'm gonna write that down one sec

final saddleBOT
#

@sweet summit Has your question been resolved?

sweet summit
#

hey so I haven't finished yet

#

but I want to make sure the logic I have so far is sound

#

I still need to do the final case

#

mostly I wanted to see if the 0 = 1 + 1 could be inferred. The goal is to show the two sides are equivalent

#

or is that weirdly put?

silk wing
#

no you need to also do even * odd, doesn't follow from the others

sweet summit
#

no I know

#

I'm working on that one right now

#

I just wasn't sure if the 0 = 1 + 1 made sense or it was weird

silk wing
#

Oh I see what you mean. No that's weird

sweet summit
#

ah lol

silk wing
#

just remove the implication arrow

sweet summit
#

is there a better way to phrase that?

#

okay

#

also this shows that this is surjective too yeah? Since all elements of S_n are accounted for and they all map to every element of Z_2

silk wing
#

What you've written has no clear logical flow. "So 0 = 0" is cool and all, because that is in fact true, but it's not actually a conclusion that you are proving

#

f(x) + f(y) = 1 + 1 = 0

#

f(xy) = 0 because xy is even

#

so f(xy) = f(x) + f(y)

sweet summit
#

ah

#

yeah that's a lot better

#

oooookay

#

I think I got everything together

silk wing
#

modulo irrelevant nitpicking, what you have here makes sense

sweet summit
#

just curious, what's the nitpick? 😛

silk wing
#

Why is (1) "f is a surjective homomorphism" and (2) " ker f i s A_n" ? Why aren't t homomorphism and surjective two different points?

#

Also not sure why you're bothering to cite that the kernel is normal. I feel like that's baked in to the 1st isom theorem

sweet summit
sweet summit
#

I'm sure it's not needed but since the B in A/B has to be normal I figured it warranted mentioning 😛

silk wing
sweet summit
#

oh my professor said that the homomorpism has to be surjective

silk wing
#

and yes, definitely can only quotient by normal. it's certainly not wrong to mention that, just feels weird since I think of "all kernels are normal" as a part of the 1st isom thm

sweet summit
#

at least in my definition notes

sweet summit
#

oh lol

silk wing
#

oh wait has to be surjetive to apply the 1st isom theorem?

#

in that case, yes

sweet summit
#

yeah I think so

silk wing
#

but those are still two separate thoughts

#

1st isom theorem is 3 criteria

#
  1. hom 2) surjective 3) has correct kernel
#

I thought you meant they said all homs had to be surjective and I was afraid

sweet summit
#

oh no no no lol.

#

but the homomorphism for the isomorphism is surjective

#

which I think we we need since we need to show that the quotient groups form a bijective mapping

#

(I think)

silk wing
#

I mean really the isom theorem is "f:G -> H gives an isomorphism from G/ Ker(f) to Image (f)" and f surjective is a special case of that

sweet summit
#

we breezed through this lecture for the sake of time and it wasn't making a lot of sense

#

okay I appreciate your help! I gotta get some food in me

#

.close

final saddleBOT
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agile jacinth
#

A car travels from a point A with position vector (60i - 40j) km to a point B
with position vector (—50i + 18j) km.
The car travels with constant velocity and takes 5 hours to complete
the journey.
Find the velocity vector.

agile jacinth
#

im not sure how to get to the answer

true escarp
#

what have you tried

agile jacinth
#

adding the position vectors

#

then dividing by time

true escarp
#

why would you add them

agile jacinth
#

cz i need to get from a to b

proven patrol
#

So yoy add them?

true escarp
#

so you want to find the distance in between them?

agile jacinth
#

then find the velocity vector for the whole journey

agile jacinth
true escarp
#

if you want to find the distance between 2 and 5 would you do 2 + 5

proven patrol
agile jacinth
#

so divide both vectors by the hour first then add?

true escarp
#

no..

true escarp
#

and v = d/t

#

how would you find the distance between 2 and 5

agile jacinth
#

bruh

#

im dumb asl

true escarp
#

consider a ruler

#

how many cm between 2cm and 5cm

agile jacinth
#

no i mean ya i get it

#

js realized how stupid of a question im asking

#

mb

true escarp
#

oh ok

agile jacinth
#

sry for wasting ur time

#

hv a good day

true escarp
#

its all g

agile jacinth
#

At 12 00 hours, a tanker sails from a point Pwith position vector (5i + 12j)
km relative to an origin O. The tanker sails south-east with a speed of
I2root2 kmh-^
a Find the velocity vector of the tanker

#

ok im rly not seeing this one

#

@true escarp

true escarp
agile jacinth
#

ignore the working above

true escarp
#

uhh

#

well the idea is

#

you have a direction

#

and magnitude

#

you can use it to break the vector back down into components

#

or you can just express it with the magnitude and direction

final saddleBOT
#

@agile jacinth Has your question been resolved?

final saddleBOT
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oblique sable
#

In the text below this definition it states that conditions (2)-(4) are needed in order to make sure both sides of the equation $y' = X(t,y)$ are well-defined. What exactly does it mean that the equation is well-defined?

soft zealotBOT
#

Anders

final saddleBOT
#

@oblique sable Has your question been resolved?

robust sedge
#

Maybe you can reverse it to have that being well-defined means those things. y needs to be differentiable for the first order DE to make sense. Not sure what D_x means though.

#

I think (3) means that all the points (y, y(t)) are points of the domain of the solution.
(4) means it actually satisfied the DE.

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lofty kindle
final saddleBOT
lofty kindle
#

i tried multiply from the left (ab)^-1 to get rid of the ab and then multiply from the right (ab) to get rid of the inverses but that leaves me with X=(AB)^-1(I+A)(AB) which i dont think is right

wraith crater
#

(AB)^-1 ≠ A^-1B^-1

#

Your first step is right tho

#

Consider just getting rid of A^-1 and B^-1 one by one

#

Then you can do some simplification

lofty kindle
#

so instead a^-1 then b^-1

#

and then from the right, b and then a

#

so = a^-1b^-1(i+a)ba

wraith crater
#

Yes

lofty kindle
#

alright thank you

wraith crater
#

In fact (AB)^-1 = B^-1A^-1

#

Is the formula

wraith crater
lofty kindle
#

how so, would it just be simplifying the a^-1 and b^-1 into (ab)^-1

wraith crater
#

Distribute the A^-1B^-1(I+A)

lofty kindle
#

ah, that too

#

.solve

wraith crater
#

.close

final saddleBOT
#
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tranquil pine
final saddleBOT
tranquil pine
#

um

#

im really stuck on this one

ionic glacier
#

which one? d?

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
ionic glacier
#

a ratio is simply a division

#

so you can re-write it to $\sqrt{10000\over 6400}$

tranquil pine
#

but where do i get the 25 16 from

soft zealotBOT
#

luckydongdong

ionic glacier
#

you can apply sqrt to numerator and denominator

tranquil pine
#

100 and 80

#

so

#

i need to divide then by 2?

#

and them simplify it?

#

so the anwser should be 1,25

#

right?

ionic glacier
#

yeah, but try to make it a whole number

#

and switch it back to the ratio notation

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#

@tranquil pine Has your question been resolved?

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runic frost
#

I understood the (cos X)2 + (sin X)2 =1, not sure how to prove it using the given values. please help.

deft ravine
#

Do you know a theorem involving a, b and c?

#

In a right triangle

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#

@runic frost Has your question been resolved?

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tranquil pine
#

hey

final saddleBOT
tranquil pine
#

is the anwser 5

amber holly
#

It's 5

tranquil pine
#

phew

#

then i did right

final saddleBOT
#

@tranquil pine Has your question been resolved?

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uncut totem
#

how to get intuition of this

final saddleBOT
uncut totem
#

why are we able to cross multiply

supple copper
#

first you multiply both sides by 4, and then (x+2)

#

that’s all cross multiplying is

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#

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lucid wasp
final saddleBOT
lucid wasp
# lucid wasp

how come when they factor out the minus from the arg the isin stays -pi/4 isntead of pi/4

ocean lintel
#

It's wrong

tranquil flume
#

Hejsan

tranquil flume
ocean lintel
#

,w arg(cos pi/4 - i sin(-pi/4))

soft zealotBOT
ocean lintel
#

,w arg(cos(-pi/4) + i sin(-pi/4))

soft zealotBOT
ocean lintel
#

Yes

tranquil flume
#

Sorry for doubting you

#

I'm L

#

You W

ocean lintel
#

It's clear since cos is even and sin is odd

final saddleBOT
#

@lucid wasp Has your question been resolved?

lucid wasp
#

so was i correct?

ocean lintel
#

Yes

lucid wasp
#

thank you :P

ocean lintel
#

A + doesn't juste become a - at random. Unless it was adding 0 in the first place

lucid wasp
#

ya i was confused too

#

ty ima close

#

<3

#

.close

final saddleBOT
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tranquil pine
#

How do you factor

final saddleBOT
tranquil pine
#

X^4-x^2-12

supple copper
#

maybe let u = x^2, and it should be easier to factor

#

so u^2 - u - 12

tranquil pine
#

OH wow that’s rlly good TYSM

supple copper
#

np

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small mortar
#

I was wondering how to integrate 2+tan^2 is it tanx - x

small mortar
#

i first thought maybe it's 2tan x because of 1+ tan^2 x = tan x but that doesnt make much sense to me

#

so i wanted to make sure

#

but I think it's the first one

vital crag
small mortar
#

so this is wrong

vital crag
#

i don't understand your work

#

how'd you go from top to the bottom here

small mortar
#

ohh my bad, I did to many deritiv tasks recently oppsi

#

i did the deritiv instead

#

so 2 becomes 2x then

#

2x + tan x as final answer

vital crag
#

,w integral 2 + tan^2(x)

vital crag
#

you missed a -x from integral of tan^2(x)

small mortar
#

oh so 2x + tan x - x which is x + tan x then?

#

yeah i think so 🙂

#

Thanks for clearing it up 🙂

#

.close

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hexed atlas
#

how would i solve further

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hexed atlas
#

fixed the equation

#

am i able to simplify 2(2n-2)! to (4n-4)! ?

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hexed atlas
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.close

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west valley
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west valley
#

is this ratio test valid? im unsure about the end part and the formatting of that

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limpid minnow
#

Can someone explain why this is wrong

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sturdy cypress
#

that's the answer for 8^-1 8^-5 8^-4

#

it's not the same answer for both

limpid minnow
#

I was trying to solve the one in the left. The one in the right is my answer

#

Original question

granite walrus
#

D

limpid minnow
obtuse grail
granite walrus
#

Because -5 + -4 is -9

#

So -9 power

#

Add power

#

It is 8

obtuse grail
#

yea 8 is 8^1

granite walrus
#

-8

#

Then move denom

limpid minnow
#

Ahhhhhhh

#

Okay

#

Yes

#

Thanks a lot guys thanks 🙏

#

Btw I love Kevin durant and go for okc

limpid minnow
granite walrus
#

No i hate okc

limpid minnow
obtuse grail
limpid minnow
#

Lol

granite walrus
#

Im going to boston

obtuse grail
#

impossible

granite walrus
#

Watch

limpid minnow
#

Yea won’t happen

#

Plus you will just lose more credibility

granite walrus
#

Im aleady 100% snake i cant become more snake

limpid minnow
#

Lol

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unborn rune
#

anyone have a clue how to prove this?

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ionic glacier
#

what did you try?

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hybrid raptor
final saddleBOT
hybrid raptor
#

How do I calculate the angles

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hybrid raptor
#

<@&286206848099549185>

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sturdy cypress
#

why does x even matter

#

it's a triangle with one leg twice the other

#

oh wait it's not 90°

#

i hate geometry

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graceful island
#

hello does any of you provide help in french?

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@graceful island Has your question been resolved?

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foggy otter
#

so if i know that f(1) = 3 and f'(1) = 7, and also that g(x)=f(x^3), how would i find g'(1)?

tired walrus
#

chain rule

foggy otter
#

chain rule on what?

#

.close

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eternal temple
#

$1.1 = \frac{500 + 1.2x}{500 + x} \implies 550 + 1.1x = 500 + 1.2x$

soft zealotBOT
#

P0lyAga1n

eternal temple
#

someone explain to me how that exactly happened

#

please

tired walrus
#

multiply both sides by (500+x) then expand 1.1(500+x) on the left

eternal temple
#

THANK YOU

#

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eternal temple
#

,w 500 * 1.1

soft zealotBOT
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torn vale
#

GOOD MORNING, COULD YOU PLEASE HELP ME WITH THE FOLLOWING EXERCISE?
a bucket with water rotates in the form of a conical pendulum, suspended from the ceiling by a rope of 2 meters whose angle with the vertical is 30 degrees. If the bucket is dripping, find the radius of the circle described by the drops on the floor 4 meters below the ceiling.

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torn vale
#

.close

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tired walrus
#

@tranquil pine please open another channel

#

@tranquil pine it's unclear what we're looking at

#

what are these arrows and circles

astral ice
#

it’s just a system of equations in disguise

tired walrus
#

ah, so 4 different people took 3 shots at the same target

#

and each shot scores based on what ring it lands in

#

right

#

well we could assign letters to the three parts of the target

#

for example, a for the outer ring, b for the middle ring and c for the center

#

then the first target shows that a + 2b = 29, the second shows that a + 2c = 43 and the third shows that b + 2c = 47

#

and we need to find a+b+c

#

do you know in general how to solve systems of equations?

#

there are some tricks that we can pull here

#

so i suppose that won't be a huge obstacle

#

from b + 2c = 47 and a + 2c = 43, we can get that b - a = 4

#

i.e. that the middle zone scores 4 more points than the outer

#

we can of course also write that as b = a+4

#

and we can plug that into the equation for the first target, a + 2b = 29, to get a + 2(a+4) = 29

#

do you understand how to continue from here?

#

you missed the a at the beginning

#

yes, you copied the last equation correctly :p

#

the equation a + 2(a+4) = 29 is an equation in one variable (a). you can solve it to find the value of a

#

from this and what we have discussed above you can find b

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keen lodge
#

Um…
Wat

final saddleBOT
keen lodge
#

y-y1 = m(x-x1)

#

?

#

I do it but doesn’t work

void valley
#

what's your slope and coords of which point have you chosen

#

a

#

you've already answered mb

#

it should be

soft zealotBOT
void valley
#

check your slope

final saddleBOT
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keen lodge
#

.reopen

final saddleBOT
#

keen lodge
#

@void valley Thanks a lot for answering!

#

How did you get slope as such a number?

void valley
#

rise/run then I simplified

#

and rationalize the denominator

keen lodge
void valley
#

still wrong

keen lodge
#

I found Q (2,8) and P(sqrt(11),15)

#

Isn’t it y2-y1/x2-x1

#

😭

void valley
#

it is

keen lodge
#

15-8/sqrt11-2

#

Isn’t that right bleak

void valley
#

but P = (-sqrt(11), 15)

keen lodge
#

Oh sorry yes

#

I did that kek

#

Oh

#

But I didn’t include that in the final answer

#

My bad

#

😭 brainfart

#

Thanks a lot ❤️

#

You are breathtaking

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tranquil pine