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i know you probably have to use factorials here but i dont know how to
formulate this
the consonants can be arranged in 5! ways
the vowels can be arranged in 4! ways
but i dont get how to apply the whole
vowels cant be next to each other
c_c_c_c_c_
so 6
possible places for vowels to be
sorry im just saying whatever i can think of
there are 4 vowels, so the structure of the word will be like V_V_V_V with 2 extra _ inserted between or before any of those 7 positions
okay so
and you fill in the holes with vowels
thats what i was thinking but it doesnt really seem to matter
either way should work right
there is a difference
its possible to have VCCVCVCVC for example
so then i have to account for
wouldn't that come up with my method?
would it
your holes need to be filled with either 1 or 2 consonants
not as straightforward to count i think 
I may not have said it very well
its fine i appreciate the help
so then in that case
the different
the consonants can be arranged in
the _ was supposed to represent positions filled by constants
seems easier to work around with consonants then
the last one has to be a consonant too, right?
does that not count double constants at the end?
should probably put another _ then
to nbe honest
it seems easier to work around consonants
so then yeah the vowels can be arranged in 6C4 ways right?
along with
4!
yes
so 6C4 x 4! ?
dont forget to arrange the consonants too
yeah
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Let's take the question one sentence at a time
For the first sentence we have a farm that's split into 3 pieces for 3 people
Afterwards we read that John's part is equally divided into 3 for his children
Im pretty sure if paul sells his it wouldnt matter as all of them are being sold in the end,
Jim owns 1/3 of the property but that isnt the common fraction
it's simplified down to that but if common fraction means you need to have it equivalent to everyone elses you need to find a common denominator
so jim would own 3/9 of the property
@tranquil pine does this help?
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Hello, I would appreciate any hints to solve the following question. I'm unsure how to start.
Need to work out the pdf and cdf using the variables.
Thank you!
Write $F_{e^{X}}(x) = \mathbb{P}(e^{X} \leq x)$
black_couscous
Then describe this set $ (e^{X} \leq x) $
just to clarify, does this mean that e^x is less than or equal to all values of x? and do I treat this as the pdf or the cdf?
No $X$ is a random variable and $x$ is a real number. If you want you can chose $y$ instead of $x$ to make things clearer.
black_couscous
ok and because of the sign '≤' this is the cdf right? if so then i guess for the pdf it would be just <?
For the PDF it's different
Let's focus on the CDF first because it's easier
Try what I told you and then come back for the pdf
ok
also im not sure what this means?
This is a set
Like $X$ is a rv that goes from a universe to the real numbers
black_couscous
And the probability is a measure of sets
hmm is that like the range of values which rv can take? if so then after writing the cdf I should describe its range of values?
I just wrote these
I suppose for the pdf I need a way to express adding all the individual probabilities being added.
Need to go but thanks for the advice! 🙂
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how do I find the inverse?
The answer I keep getting is (-x-5)/2(x-1)
yeah but when I put it in an oline calculator I get somethin else
it gives me (x+5)/2(1-2x)
I dunno If I have to like factor the negative out or If mine is technically right
here a picture of my work
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stuck on how to start
Make x the subject in the first, z the subject ok the second and then plug in them to x/z to solve
Yeah
then just put both inthe teh fraction?
Ye
how do i isolate z?
What do you think
could i cross multiyplu?
Yes obviously
I call this algebraic manipulation
can I cancel the 7's in the denonminator before putting into frction
Yes
Do you have the correct answer
but II is going to end up with x^2-3x<0
nope i dont get an answer key
could brute force but i only have 1 reminaing attempt
What topic is this from if I may ask?
waiting
In x(x-3)<0 there are quite a few possiblies
there are?
So the product of x and x-3 has be negative right?
maybe?
You get negative when: - times + and + times -
yeah but the x^2 couldbe smth else
yeah ig?
So..
[x<0 and x>3] or [x>0 and x<3]
[False (makes no sense)] or [0<x<3]
Which is 0<x<3
So all of them are equal
ohhh
Sorry for terrible explanation
I used the logical equivalence method
Because it's what I am learning currently
Plenty of easier methods probably
So the answer is D
Unless they are sick and twisted and set E as correct
would thesse all be true tho?
worked
My gut says E
Becuss e
a + b > a-b
<-> a-a > -b-b
<-> 0 > - 2b
<-> 0 < b
@opaque herald you dead?
Our comrade has fallen
Rip
but like, is a and b were option a, and a=2 b=1 the its stillwork
I don't understand
might just try e tho
y = a(x-p)(x-q) where p and q are roots you know this form?
wait so i pu he entire thing infromt of x?
or is x^2 the coeeficient
Sorry I'm a little bit drunk
My man ballerinarata has passed away
Yohojo
@opaque herald you riding???
MD??
still confused
not really? idk
Otherwise google "quadratic slope intercept form"
that didnt help
YES
and a smis given as 1
Cleanly
So it can be invisible
YOU GOR IT
@opaque herald
Do you still need helppp
alr will do
Lemon
Squeezy
Any more questions
Before I did
Die
@opaque herald
MD MY MA
porbably but goin to do his first
are you alright lol
im stuck here
ill be back after i eat smth
<@&286206848099549185>
@opaque herald Has your question been resolved?
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Given the function y = 2x3 – 3x2 – 5x + 1, which finite differences will be equal (or constant)?
What does finite difference even mean??
like would it be the third difference or fourth ?
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why does x + |ax + b| = k have one value for k
when we modulate x theres a possibility for both a negative and a positive value for k right
no
for example in a normal modulation ax + b, ax + b = +/- k
no?
okay i think i got it on my own
basically it needs to work both ways
k nvm
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Yo
I did bad on a test
And I just wanna go over it
75 - 3 times 7 to the power of 2 + 6 to the power of 3 divided by 12
= -48 right
Yo are u using PEMDAS as order of operations, or something else?
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can someone explain what this means
someone explained it to be like
but I'm so confused as to how they got -12x + 12 = 0
and then how did the deduce that 100 items is maximum profit?
hello
hi
@dreamy snow Has your question been resolved?
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For a dilation from the origin, just multiply all the coordinates by the scale factor
Yeah looks like A is (2,4)
And it's (6,12) dilated right?
Yep
Ok
Yeah my teacher was saying something about that
If you do it right, it should look like a scaled up version of the same triangle
Same shape, just bigger
Ohhh
So 12 -6 dilated
yep
You should plot and label those points A', B', and C'
Then connect them to form the dilated triangle
Wait
B is not correct
Didn't we say B is (4,-2), so B' is (12, -6) ?
Yeah I forgot to change that sorr6b
Can you help me with a few more questions ?
Please
@fossil geyser
Go ahead and post them. If I can't, somebody will
@dull wadi Has your question been resolved?
@dull wadi Has your question been resolved?
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what's the range of cosine wave
1 and -1
8 n -8
mhm, velocity is 4 + 8cos 2t
so it's 8 cos 2t shifted up 4
so what would the range of that be?
i just dont see how cos t can be substituted for 1 or -1
right
so what don't you understand
so how does this explain my question
sorry im just not seeing it
you didn't ask a question
yeah they just did that to illustate
that it's the maximum and minimum
-1 is the smallest value cos x can take
so 4 + 8(-1) would be the miniumum
and same thing for positive 1
right so in this case minimum velocity
but if it was just to find the range of values of that eq
what would the minimum value stand for
range is the just the values the velocity can take
so the range is all the values between minimum velocity and maximum velocity inclusive
i mean like if we ignore the velocity part
than what does that range of values mean
range is the set of y values a function can be
👍
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Off_set
,, y = x + 10 / 4
Off_set
,, y = x + 4 // 2
Off_set
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How would the function, f(sqrtx) look like with a shift 2 units to the left and 3 units up? Also with a. Reflection over y axis
Would it be -(sqrtx+2)+3
yeah, with correct brackets, you're right
Thanks
Wym by that? Brackets like around it?
-[(sqrt(x+2))+3]
Is that necessary? It results in the same thing
no, -a+b is not equal to -(a+b) because the latter is -a-b
@tranquil pine Has your question been resolved?
Wouldn’t that be a reflection over x axis? Since that’s outside the bracket
It’s supposed to be inside because it’s a reflection across y
ah i see, yeah, I misread it
so my equation is wrong, but so is yours
reflection across y axis only flips the negativity of x
so try to come up with the final answer
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@ionic glacier
that's not true
how did you come to that conclusion?
Because I since were reflecting y
We add a - outside of the
Parentheses
@ionic glacier
can you write down each progression?
Oh I made a mistake
Is it plus three?
Since it’s going left 3
just write down each change and show me pls
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Find the tangent to the curve y=e^x + x^2 at x=2.
how do you find the tangent?
Derivative, then plug in x = 2 to find the gradient of the tangent at x = 2
e^x + 2x
ok that's correct too
idk why you didn't get the correct answer at this point 🙂
e^2 + 4
Oh, I'm not sure if it is the correct answer lol
yeah that's the answer
this is wrong though
oh
yeah I knew it
lol
What I did was: I found the value of y by subbing in x = 2 in the original equation
Got this again
So then I used y-y1 = m(x-x1)
y-(e^2+4)=(e^2+4)(x-2), then solved for y to get y = 2(e^2 + 4)(x - 2)
@ionic glacier Could you tell me where my mistake is?
y = kx + c
and when x =2, we know what y value is
then calculate c
because we already know k, it's possible to get c
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I figured out the zero, sin(x)=-4/5, but I don't know where to go from there
@slate garnet Has your question been resolved?
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@slate garnet Has your question been resolved?
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Hi
@zinc fractal Has your question been resolved?
Same
It is the reflexive property
@zinc fractal Has your question been resolved?
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abstract algebra
Is the red bit something you've written? A solution? What am I looking at?
it's just the set up
What is the fundamental theorem in this context?
it's also called the 1st isomorphism theorem
basically that the quotient group $S_n / A_n \cong \mathbb{Z}_2$
MellowDramaLlama
Borderline offended by that, but okay
hmm?
That's just a weird thing to call the 1st isomorphism theorem
But the problem statement gives away the whole game
you know exactly what theorem to use
You need a map from G to Z/2Z that is surjective and has kernel K
right. So then our kernel would have to be the even permutations
but I'm not sure if I"m seeing the connection there
connection between what and what? just want to make sure I understand exactly where the disconnect is
well according to the hint, all even permutation of S_n map to 0 in Z_2. I'm just trying to show that's the case, but I'm not sure how
other than just proclaiming it does lol
Oh I see. The problem is that the text didn't actually define the homomorphism they're using
There's literally only one option, so maybe the author is just being a dick
if they elements are composed with themselves?
But you need to send everything in the kernel to 0 and everything not in the kernel to not 0 for obvious reasons
but there's only one option fornot 0
so the map is completely determined
hmmm
OH I THINK I SEE IT. Yeah if we do something like f((12)(12)) = f((12))f((12)), then f(()) = f(12)f(12)
So the statement you're proving is "there exists a homomorphism from S_n to Z/2Z with kernel exactly A_n". This statement forces the definition of this homomorphism on you -- there is only one set map that can do the thing you want it to do. What you have to prove is that this is a homomorphism
so yeah the evens composed with themselves sends them to the kernel
oh okay
sorry I'm typing it out
okay I think I got the first justification down the fact that A_n = ker(f)
Okay so the red is your solution. You never defined your homomorphism from S_n to Z/2Z. You can't just take "a homomorphism", you need to present a specific one that does what you wany
oh sorry first line
G = S_n
and (Z_2, +)is the same as Z/2Z I think
(and yes sorry red is my answer)
You can't just say "let f be a homomorphism" because I will come back and say "okay let f be the map sending everything to 0"
then everything you say afterwards will be totally wrong
You need to point to a specific homomorphism and say "this particular function is surjective with kernel A_n"
your job is to define that function
oooh I see
okay
So how about something like if the permutation is odd map it to 1 and if it's even map it to 0?
like a piecewise function
cool, that certainly has the correct kernel. But is it actually a homomorphism? You can only apply the first isomorphism theorem to homomorphisms
yeah I think so! To prove that we would need to prove that f(xy) = f(x)f(y) for x, y in S_n right?
yup
hmmm
yeah I guess that works
if x and y are both even, then their composition is even, which maps to the kernel
if x and y are both odd, then their composition is even, which maps to the kernel
if x is odd and y is even (or vice versa), then their composition is odd which maps to not the kernel (lol)
...I think that works
so then f(xy) for example, if they're even would be 0 + 0 = 0
you are correct. The idea is that homomorphisms to Z/2Z are sort of like identifying parity in your group
the same way odd + odd = even and even + even = even, etc
odd and even permutations have that same relationship, so they define a hom to Z/2Z
@sweet summit Has your question been resolved?
hey so I haven't finished yet
but I want to make sure the logic I have so far is sound
I still need to do the final case
mostly I wanted to see if the 0 = 1 + 1 could be inferred. The goal is to show the two sides are equivalent
or is that weirdly put?
no you need to also do even * odd, doesn't follow from the others
no I know
I'm working on that one right now
I just wasn't sure if the 0 = 1 + 1 made sense or it was weird
Oh I see what you mean. No that's weird
just remove the implication arrow
is there a better way to phrase that?
okay
also this shows that this is surjective too yeah? Since all elements of S_n are accounted for and they all map to every element of Z_2
What you've written has no clear logical flow. "So 0 = 0" is cool and all, because that is in fact true, but it's not actually a conclusion that you are proving
f(x) + f(y) = 1 + 1 = 0
f(xy) = 0 because xy is even
so f(xy) = f(x) + f(y)
modulo irrelevant nitpicking, what you have here makes sense
Why is (1) "f is a surjective homomorphism" and (2) " ker f i s A_n" ? Why aren't t homomorphism and surjective two different points?
Also not sure why you're bothering to cite that the kernel is normal. I feel like that's baked in to the 1st isom theorem
I tried to discern that with the last line. We proved that it was a homomorphism, but as a consequence, the cases accounted for all possible elemnts of S_n and they map to all elements of Z_2, so that should showcase that it's surjective, right?
this is our first HW over the 1st isomorphism theorem, so I wanted to confirm all explicit points
I'm sure it's not needed but since the B in A/B has to be normal I figured it warranted mentioning 😛
I mean those are just two separate statements. I showed this thing is a homomorphism, and then for another unrelated reason, it is also surjective
oh my professor said that the homomorpism has to be surjective
and yes, definitely can only quotient by normal. it's certainly not wrong to mention that, just feels weird since I think of "all kernels are normal" as a part of the 1st isom thm
at least in my definition notes
I'm sorry what
no
oh lol
yeah I think so
but those are still two separate thoughts
1st isom theorem is 3 criteria
I thought you meant they said all homs had to be surjective and I was afraid
oh no no no lol.
but the homomorphism for the isomorphism is surjective
which I think we we need since we need to show that the quotient groups form a bijective mapping
(I think)
I mean really the isom theorem is "f:G -> H gives an isomorphism from G/ Ker(f) to Image (f)" and f surjective is a special case of that
OOOOOH yeah that definition just clicked for me lol
we breezed through this lecture for the sake of time and it wasn't making a lot of sense
okay I appreciate your help! I gotta get some food in me
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A car travels from a point A with position vector (60i - 40j) km to a point B
with position vector (—50i + 18j) km.
The car travels with constant velocity and takes 5 hours to complete
the journey.
Find the velocity vector.
im not sure how to get to the answer
what have you tried
why would you add them
cz i need to get from a to b
So yoy add them?
so you want to find the distance in between them?
then find the velocity vector for the whole journey
mb ig
if you want to find the distance between 2 and 5 would you do 2 + 5
so divide both vectors by the hour first then add?
no..
refer to this
and v = d/t
how would you find the distance between 2 and 5
you cant do this?
consider a ruler
how many cm between 2cm and 5cm
oh ok
its all g
At 12 00 hours, a tanker sails from a point Pwith position vector (5i + 12j)
km relative to an origin O. The tanker sails south-east with a speed of
I2root2 kmh-^
a Find the velocity vector of the tanker
ok im rly not seeing this one
@true escarp
try a diagram
uhh
well the idea is
you have a direction
and magnitude
you can use it to break the vector back down into components
or you can just express it with the magnitude and direction
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In the text below this definition it states that conditions (2)-(4) are needed in order to make sure both sides of the equation $y' = X(t,y)$ are well-defined. What exactly does it mean that the equation is well-defined?
Anders
@oblique sable Has your question been resolved?
Maybe you can reverse it to have that being well-defined means those things. y needs to be differentiable for the first order DE to make sense. Not sure what D_x means though.
I think (3) means that all the points (y, y(t)) are points of the domain of the solution.
(4) means it actually satisfied the DE.
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i tried multiply from the left (ab)^-1 to get rid of the ab and then multiply from the right (ab) to get rid of the inverses but that leaves me with X=(AB)^-1(I+A)(AB) which i dont think is right
(AB)^-1 ≠ A^-1B^-1
Your first step is right tho
Consider just getting rid of A^-1 and B^-1 one by one
Then you can do some simplification
so instead a^-1 then b^-1
and then from the right, b and then a
so = a^-1b^-1(i+a)ba
Yes
alright thank you
Also you can simplify this further
how so, would it just be simplifying the a^-1 and b^-1 into (ab)^-1
Distribute the A^-1B^-1(I+A)
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which one? d?
@tranquil pine Has your question been resolved?
yes
but where do i get the 25 16 from
luckydongdong
you can apply sqrt to numerator and denominator
100 and 80
so
i need to divide then by 2?
and them simplify it?
so the anwser should be 1,25
right?
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I understood the (cos X)2 + (sin X)2 =1, not sure how to prove it using the given values. please help.
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hey
It's 5
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how to get intuition of this
why are we able to cross multiply
first you multiply both sides by 4, and then (x+2)
that’s all cross multiplying is
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how come when they factor out the minus from the arg the isin stays -pi/4 isntead of pi/4
It's wrong
Hejsan
Are you sure?
,w arg(cos pi/4 - i sin(-pi/4))
,w arg(cos(-pi/4) + i sin(-pi/4))
Yes
It's clear since cos is even and sin is odd
@lucid wasp Has your question been resolved?
Yes
thank you :P
A + doesn't juste become a - at random. Unless it was adding 0 in the first place
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How do you factor
X^4-x^2-12
OH wow that’s rlly good TYSM
np
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I was wondering how to integrate 2+tan^2 is it tanx - x
i first thought maybe it's 2tan x because of 1+ tan^2 x = tan x but that doesnt make much sense to me
so i wanted to make sure
but I think it's the first one
use tan^2(x) = sec^2(x) - 1
ohh my bad, I did to many deritiv tasks recently oppsi
i did the deritiv instead
so 2 becomes 2x then
2x + tan x as final answer
,w integral 2 + tan^2(x)
you missed a -x from integral of tan^2(x)
oh so 2x + tan x - x which is x + tan x then?
yeah i think so 🙂
Thanks for clearing it up 🙂

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how would i solve further
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is this ratio test valid? im unsure about the end part and the formatting of that
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Can someone explain why this is wrong
@limpid minnow Has your question been resolved?
I was trying to solve the one in the left. The one in the right is my answer
Original question
D
But why
the 8 goes on top
yea 8 is 8^1
Ahhhhhhh
Okay
Yes
Thanks a lot guys thanks 🙏
Btw I love Kevin durant and go for okc
Thank you
No i hate okc
Thank you
W
Lol
Im going to boston
impossible
Watch
Im aleady 100% snake i cant become more snake
Lol
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anyone have a clue how to prove this?
@unborn rune Has your question been resolved?
what did you try?
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@hybrid raptor Has your question been resolved?
<@&286206848099549185>
@hybrid raptor Has your question been resolved?
why does x even matter
it's a triangle with one leg twice the other
oh wait it's not 90°
i hate geometry
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hello does any of you provide help in french?
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so if i know that f(1) = 3 and f'(1) = 7, and also that g(x)=f(x^3), how would i find g'(1)?
chain rule
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$1.1 = \frac{500 + 1.2x}{500 + x} \implies 550 + 1.1x = 500 + 1.2x$
P0lyAga1n
multiply both sides by (500+x) then expand 1.1(500+x) on the left
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,w 500 * 1.1
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GOOD MORNING, COULD YOU PLEASE HELP ME WITH THE FOLLOWING EXERCISE?
a bucket with water rotates in the form of a conical pendulum, suspended from the ceiling by a rope of 2 meters whose angle with the vertical is 30 degrees. If the bucket is dripping, find the radius of the circle described by the drops on the floor 4 meters below the ceiling.
@torn vale Has your question been resolved?
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@tranquil pine please open another channel
@tranquil pine it's unclear what we're looking at
what are these arrows and circles
it’s just a system of equations in disguise
ah, so 4 different people took 3 shots at the same target
and each shot scores based on what ring it lands in
right
well we could assign letters to the three parts of the target
for example, a for the outer ring, b for the middle ring and c for the center
then the first target shows that a + 2b = 29, the second shows that a + 2c = 43 and the third shows that b + 2c = 47
and we need to find a+b+c
do you know in general how to solve systems of equations?
there are some tricks that we can pull here
so i suppose that won't be a huge obstacle
from b + 2c = 47 and a + 2c = 43, we can get that b - a = 4
i.e. that the middle zone scores 4 more points than the outer
we can of course also write that as b = a+4
and we can plug that into the equation for the first target, a + 2b = 29, to get a + 2(a+4) = 29
do you understand how to continue from here?
you missed the a at the beginning
yes, you copied the last equation correctly :p
the equation a + 2(a+4) = 29 is an equation in one variable (a). you can solve it to find the value of a
from this and what we have discussed above you can find b
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what's your slope and coords of which point have you chosen
a
you've already answered mb
it should be
Modus
check your slope
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.reopen
✅
still wrong
it is
but P = (-sqrt(11), 15)
Oh sorry yes
I did that kek
Oh
But I didn’t include that in the final answer
My bad
😭 brainfart
Thanks a lot ❤️
You are breathtaking
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