#help-36

1 messages · Page 11 of 1

sweet summit
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but that's for another day 🙂

fathom walrus
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But doesn’t that mean u go from R^2 to something else

sweet summit
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well to go to something else we would have to make our matrix from 2 x n to (not 2 x n), so something like 3 x 2

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that would be R^3

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for example, say we had a function

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$f : \mathbb{R}^2 \rightarrow \mathbb{R}^3$ such that $f(<x, y>) = <x, y, x + y>$

soft zealotBOT
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MellowDramaLlama

sweet summit
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then that would take 2d Vectors and push them onto the 3d plane

fathom walrus
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How does that make sense logically tho

sweet summit
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what do you mean?

fathom walrus
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How am I allowed to make a line I draw on a page into a line that exists in 3D

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Man that sounds terribly phrased

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Idk how to ask it lol

sweet summit
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well keep in mind that the 3D plane is nothing more than us look at the x, y plane from straight above

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hold on let me draw some visual aids

fathom walrus
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Thanks

sweet summit
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okay so this is the vector <2, 1> in R^2

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right?

fathom walrus
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Yes

sweet summit
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ugh hold on

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I forgot how to work with 3d graphers

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one second

fathom walrus
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Sure

fathom walrus
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The nature of the vector being <2,3> doesn’t change

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It’s just popping out of the page now

sweet summit
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yep!

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well almost lol

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it's still on a flat plane

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oh wait

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for our function, it would be <2, 3, 5>

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yes that would be popping out of the page

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but <2, 3, 0> would be flat on the xy plane

fathom walrus
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Ah i c

sweet summit
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see? not so bad 🙂

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now when you get to dimensions >= 4, then it's really hard to visualize

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but the math checks out

fathom walrus
# sweet summit see? not so bad 🙂

yea, thats true. its hard to just understand from the textbook cuz unfortunately my college only offered the online course and its asychronous with no lectures, just textbook, webassigns, and tests, so its a bit tough to learn

sweet summit
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that's beyond my scope lmao

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alright, I gotta hit the hay

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best of luck to ya!

fathom walrus
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thanks so much man, i really appreciate the explanations

sweet summit
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of course, happy to help 🙂

fathom walrus
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💯

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peace

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gleaming mantle
final saddleBOT
gleaming mantle
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Can i get tips or advice to solve c

wary python
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How can I learn Graph Theory step by step?

gleaming mantle
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?

wary python
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Didn't you understand?

gleaming mantle
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Its my question

wary python
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No, I just asked something to people to help me.

gleaming mantle
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Yah but ure taking my space

wary python
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Oh, I am sorry.

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I didn't know about the rules here.

opal needle
final tangle
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split the shaded region into smaller regions

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parts a,b) will be helpful in calculating areas of those smaller regions

gleaming mantle
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How about the small semis

opal needle
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you shouldnt look at it like that i think

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seperate it into two pieces, DOA and AOB

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since you know the angles of each of the triangles, you can calculate their area and take away the shaded parts

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by treating them as smaller triangles

final tangle
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wdym by small semis

gleaming mantle
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Quads i mean

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The unshaded one on the left

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@final tangle

final tangle
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what unshaded quad on the left

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if quad was short for quadrilateral, the unshaded part isn't a quadrilateral

gleaming mantle
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@final tangle how to find that

final tangle
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applying the appropriate formulae for areas of sectors, triangles,segments

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the radius / relevant sides are known
you've pretty much already determined the angles you need as well in parts a,b

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#

@gleaming mantle Has your question been resolved?

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feral pivot
#

Normally wouldn't we say 400$ on a win, because we paid 100 and won 500, hence 400

feral pivot
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and thus the expected value would be 0

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@feral pivot Has your question been resolved?

final saddleBOT
#

@feral pivot Has your question been resolved?

fossil geyser
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The wording is kind of vague, but I agree with you.

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@feral pivot

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Maybe they meant that if she wins, she profits $500

feral pivot
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ahhh

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that would make sense

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thank you good sir

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barren saffron
#

Hey
Today we talked about sets but i didn't understand this:
let A be a set, then what is supA and infA?

fossil geyser
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If A is a subset of some ordered set, for example the real numbers

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Then sup(A) is the smallest element of the larger set, which is greater than every element of A

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For example if A is the set of all real numbers less than 2,
$A = {x \in \R: x < 2}$, then $\sup(A) = 2$

soft zealotBOT
#

tatpoj

fossil geyser
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inf is the same, but on the lower end instead

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bitter orbit
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can anyone explain to me how to determine if a relation is a function

bitter orbit
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I still dont understand it

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@bitter orbit Has your question been resolved?

bitter orbit
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i got it now

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eager stirrup
#

Heracles needs to fight the Lernean Hydra for one of his labors. A Hydra has many heads, and to defeat it, you must remove them all.
Heracles has two swords, and he can only use one of them at a time. The smaller sword will sever 21 of the Hydra’s heads with a single stroke. The larger one will sever 100 heads with each stroke, but then the Hydra (unless it has just been killed) will grow 2023 new heads! If the Hydra initially has 101 heads, is it possible for Heracles to defeat it with his present swords or does he need to procure another sword?
NOTE: A sword can only remove a particular number of heads, no fewer and no more. If, for example, the Hydra has just 5 heads, they cannot be cut off with either of the swords.

eager stirrup
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is this an invariant question?

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if so, whats the invariant

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also, i dont think its possible, because every time he severs some heads, they increase by 2023

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with is much larger than the largest amount taken away

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so it will always be larger

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unless im missing smth

crisp plover
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The heads only grow if you use the larger sword.

eager stirrup
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oh

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is this an invariant question?

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then

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tis

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ok i think i got it

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crude lagoon
final saddleBOT
crude lagoon
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oops

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am i in a wrong channel

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ill leave

stoic mural
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no

crude lagoon
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sorry

stoic mural
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you are not

crude lagoon
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ooh

stoic mural
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@outer storm get to your channel pls

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thanks

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we have
4,12,36,...

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do you see what sequence this is?

crude lagoon
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so my way of thinking was: 4 x 3 = 12, 12 x 3 = 16, so i thought it was like multiples of 3 so i divided the 708 number by 3 and got that n = but its wrong

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yes i think the sequence is times 3

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not sure

stoic mural
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we start with 4

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4*3=12

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12*3=36

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but notice

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4 * 3 * 3=36 as well

crude lagoon
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right

stoic mural
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so 4*3^2=36

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in general we see that

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4 * 3^0 = 4
4 * 3^1 = 12
4 * 3^2= 36

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so in general

crude lagoon
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right

stoic mural
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4*3^(n-1)

crude lagoon
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but for the number they gave - like would it be 4 ^ 3

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oh

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yeah

stoic mural
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the n-1 is because our first element of the sequence has exponent of 0 in this notation

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but we want to start n from 1

crude lagoon
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yes that makes sense

stoic mural
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since it is the first element

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so we have 4*3^(n-1)

crude lagoon
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it says that n isnt defined

stoic mural
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?

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the n is just saying which term it is

crude lagoon
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and yeah cuz 4^3(4-1)

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OHH

stoic mural
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n=1 means we look at the first element

crude lagoon
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YEAH

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ok

stoic mural
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it is given that 708588 is an element of the sequence

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so we can set them equal

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4*3^(n-1)=708588

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3^(n-1)=177147

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log_3(177147)=n-1

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n=log_3(177147)+1

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,w log_3(177147)+1

stoic mural
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we get n=12

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lets check

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,w 4*3^(12-1)

stoic mural
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looks good

stoic mural
crude lagoon
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yes it does

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cuz ur replacing the

stoic mural
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great

crude lagoon
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4^3 by log 3

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right ?

stoic mural
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$a^{b}=c \ log_{a}(c)=b$

soft zealotBOT
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~Martin

stoic mural
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i always read the log as

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a equals c if taken to the power of b

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base equals () if taken to power of result

crude lagoon
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rightt yeahhh

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um wait

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it says its wrong??

stoic mural
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?

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that's odd

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we checked

crude lagoon
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yaeh

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did i type it correctly

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i think so

stoic mural
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oh no

crude lagoon
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oohno

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no?

stoic mural
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n=log_3(177147)+1

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this is what we have

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however

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we can calculate this

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,w log_3(177147)+1

stoic mural
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n=log_3(177147)+1=12

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so n=12

crude lagoon
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OH

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JUST

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Okok

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ysses

stoic mural
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you spooked me for a second haha

crude lagoon
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spooky season

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fr

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idk if i can continue using this channel but heres the next (if i can)

stoic mural
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sure thing

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what do they mean with common ratio?

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im not used to english terms here

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but a_n are easy

crude lagoon
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right lol

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um its ok im not good at math

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handshake

stoic mural
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$a_{1}=\frac{9^{1+3}}{6}=\frac{9^{4}}{6}=\frac{6561}{6}=1093.5$

soft zealotBOT
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~Martin

stoic mural
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odd that it is not a nice number

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,w (9^4)/6

crude lagoon
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i think its 3

crude lagoon
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because they are all divisible by 3

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ok 3 is not correct

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lol

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i have unlimited tries btw so

stoic mural
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i think with common ratio they mean a_n/a_n-1

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or something like that

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oh great

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$\frac{9^{n+3}}{6}:\frac{9^{n+4}}{6}=1:9$

soft zealotBOT
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~Martin

stoic mural
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so it is either 9 or 1/9

crude lagoon
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9 is correct

stoic mural
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awesome

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it is basically meaning

crude lagoon
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do i just replace 1 for 1

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n for 1

stoic mural
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a_n = 9*a_n-1

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if we want a_1 we replace n with 1, correct

crude lagoon
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WAIT OMGG

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genius

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stuff

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ok i get it??

stoic mural
#

,w (9^(1+3))/6

stoic mural
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,w (9^(2+3))/6

stoic mural
#

,w 9*1093.5

stoic mural
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yep it works

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a_1 is 1093.5

crude lagoon
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got that correct!! thank you!!

stoic mural
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and for each a_n after that we just multiply by 9

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so

crude lagoon
crude lagoon
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lol

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great stuff

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so 5 more questions left!! almost there

stoic mural
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we start with 2.5

crude lagoon
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(in this homework...)

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right thats the first one

stoic mural
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multiply by 7 each time

crude lagoon
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2.5n+7

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?

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oo no

stoic mural
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multiply

crude lagoon
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2.5 n x 7

stoic mural
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for n=2: 2.5 * 7 * 7

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=2.5*7^2

crude lagoon
#

why would u multiply twice?

stoic mural
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oh wait

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yeah my bad

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2.5 * 7

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=2.5^1

crude lagoon
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nono if ur right i jus wanna know

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lol

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oh

stoic mural
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so 2.5*7^(n-1) should work

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btw

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we could avoid this (n-1)

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this comes up often

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we can avoid this if we say the sequence starts with the 0th term

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but in math that is uncommon

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that is a programming thing though

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there this is usual

crude lagoon
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ohh

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yeah

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its discrete math

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its correcttt

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v cool

stoic mural
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lets start with the first sequence

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we can split it up into 2 sequences

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the sequence of nominators and the sequeence of denominators

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3,4,5,6,...

crude lagoon
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so the numberator is +!

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+1

stoic mural
#

3
3+1
3+1+1=3+2

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and so on

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so we get

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3+n

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16,25,36,49,...

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do you notice something with these numbers?

crude lagoon
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yes its plus 9 i think

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so 1/9

stoic mural
#

25+9=34 which is not 36

crude lagoon
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like +1 for numerator and +9 for derminator

stoic mural
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so nope

crude lagoon
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oh

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i think...this might be not the right way

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but idk lol

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theyre prime?

stoic mural
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nope

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squares

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1,4,9,16,25,...

crude lagoon
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oH YEAHH

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they are

stoic mural
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is starts with 16

crude lagoon
#

perfect squares

stoic mural
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try to get a formula

crude lagoon
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4, 5, 6, 7

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it goes up by 1

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the squares

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so um

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+1

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crude lagoon
#

hiya

final saddleBOT
crude lagoon
#

stuck on this question now:

stoic mural
#

lets call this rule f

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f(12)=81
f(6)=9
f(8)=25
f(10)=49
and so on

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notice that 81,9,25,49 and so on are all perfect squares

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f(12)=9^2
f(6)=3^2
f(8)=5^2
f(10)=7^2

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notice something else here?

final saddleBOT
#

@crude lagoon Has your question been resolved?

crude lagoon
#

oops sorry jus saw this

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yes so everything is to the second power

stoic mural
#

not quite

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12^9 and 9^2

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6^2 and 3^2

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8^2 and 5^2

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there is a pattern

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f(x)=(x-3)^2

crude lagoon
#

oh

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ysyes that makes sense

#

thank you

crude lagoon
crude lagoon
#

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dry light
#

Is there an easier way to do this?

Basically, I was given this stupid problem:

For Triangle ABC, $\frac{\sin(0.5(A-B))}{\cos(0.5C)} = \frac{12}{15}$. Sides $BC$ and $AB$ are 40 and 50, respectively. Find the exact length of AC

soft zealotBOT
#

Umbraleviathan

dry light
#

Now I got 16 from a graphing calculator

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Is there an easier to get 16

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@dry light Has your question been resolved?

dry light
#

<@&286206848099549185>

#

The forbidden role trol

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@dry light Has your question been resolved?

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@dry light Has your question been resolved?

dry light
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.close

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tired oyster
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tired oyster
#

Can someone explain the factoring?

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Why is 2x - 2 = 2x (x - 1)

final tangle
#

it's not

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$2x-2 \redneq 2x(x-1)$

soft zealotBOT
#

ℝamonov

tired oyster
#

well if you look at the image

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it says 2x - 2 factors INTO 2x (x - 1)

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uhh?

final tangle
#

that's not what the question says

tired oyster
#

it says to find the asymptote, but it says to factor it out

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and in the video he says 2x - 2 factors into 2x * (x - 1)

final tangle
#

note that the x^2+x was factored too

tired oyster
#

well before that

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I don't understand what factoring means then

final tangle
#

I'm pretty sure they don't say that

tired oyster
#

because it doesn't make sense to me why that is true

final tangle
#

factoring is the reverse of expanding

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it's still the application of the distributive property

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are you able to expand
a(b+c)?

tired oyster
#

well it would be ab + ac

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right?

final tangle
#

yes

tired oyster
#

cause I am distributing a

final tangle
#

basic factoring is just going reverse

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ab+ac to a(b+c)

tired oyster
#

oh I see

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which is why 2x - 2 is 2 * x - 1

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because 2 * x - 2x

final tangle
#

missing ()

tired oyster
#

yea i'm writing it fast

final tangle
#

write slow and properly

tired oyster
#

but ok that helps so much because in the video he just says oh yea that factors into that

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without explaining what it means

final tangle
#

otherwise the default assumption is misunderstanding

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2x-2 = 2(x-1)
x^2+x = x(x+1)
overall (2x-2)(x^2+x) = 2 * (x-1) * x * (x+1)
= 2x(x-1)(x+1)

tired oyster
#

ok so the other side

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x^2 + x is just x (x + 1)

tired oyster
#

so that would just make it 1/0? how does he arrive that both x are either 0 or -1

final tangle
#

by solving
2x(x+1) = 0

tired oyster
#

oh wait

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he set to 0

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ok not replacing the whole equation to 0

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I got confused

#

.close

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wicked skiff
#

No clue on how to start

final saddleBOT
#

@wicked skiff Has your question been resolved?

final saddleBOT
#

@wicked skiff Has your question been resolved?

restive falcon
#

use these formulas

#

After that you can reduce and you should get tan

wicked skiff
restive falcon
#

no the first one and the fourth one: sin(6x) + sin(4x) = 2 sin(6x + 4x / 2) cos(6x-4x / 2)

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do the same of the denominator

wicked skiff
#

how would i do it for the denominator if its 2

restive falcon
#

no I mean the cos(6x) + cos(4x)

wicked skiff
#

so im using 2 different formulas

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wicked skiff
#

.reopen

final saddleBOT
#

wicked skiff
#

ok 2cos(6x+4x/2)cos(6x-4x/2)

gleaming bramble
wicked skiff
#

2cos(8x)cos(4x)

gleaming bramble
#

yeah thats it

wicked skiff
#

2 sin(6x + 4x / 2) cos(6x-4x / 2)= 2sin(8x)cos(4x)

olive bramble
restive falcon
#

now plug it into the original equation and reduce you see the numerator and denominator have both cos(4x)

gleaming bramble
#

mmk

olive bramble
#

If you expand this all the way you should end up@with a simple term tan(__)

wicked skiff
#

so sin8x+sin4x/cos8x+cos4x

#

which is 1

restive falcon
#

how do you get sin8x + sin4x?

#

and no it is not one

#

write it down and show it to me your paper

wicked skiff
wicked skiff
restive falcon
#

the denominator too

#

okay

#

now take 2sin(5x)cos(x) / 2 cos(5x) cos(x)

#

reduce it what do you get

wicked skiff
#

tan(5x)

restive falcon
#

there is your answer

wicked skiff
#

thank you very much

#

.close\

#

.clse

#

.close

final saddleBOT
#
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#
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vague gull
#

Hello

final saddleBOT
vague gull
#

I’m doing a question on related rates and it’s asking me to find how the fast the angle of a triangle is changing

#

I tried to do it on my own and this is what I got

#

Does this seem correct?

#

Also dx/dt and dy/dt are given

#

X is 6 and y is 8 too

#

I thought it would be easier to just leave them as variables so that’s what I did

#

<@&286206848099549185>

#

.close

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void crest
final saddleBOT
void crest
#

f - f(x+z0) + C1 + C2 = sum of residues

#

thats what i got but idk what theorem to apply to do this

#

like idk how we can find C1, C2 or show they vanish

final saddleBOT
#

@void crest Has your question been resolved?

grim nebula
#

hmm

#

that's weird

#

@void crest

void crest
#

yeshh

grim nebula
#

you need more assumptions i think

#

like o(1)

void crest
#

so

#

bad question

grim nebula
#

yeah

#

otherwise f doesn't vanish on the vertical bits

#

but also

void crest
#

like this

grim nebula
void crest
#

it was a random

grim nebula
#

ok

grim nebula
void crest
grim nebula
#

the notation is so bad

void crest
#

:O

#

:c

grim nebula
grim nebula
void crest
#

uk

#

ill just randomly run thru

#

n get the answers

#

n hope its right

grim nebula
void crest
#

.close

final saddleBOT
#
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void crest
#

ty

grim nebula
final saddleBOT
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barren saffron
tired walrus
#

no, the infimum of {x ∈ R : x < 2} is not 0. it either doesn't have an infimum at all or its infimum is -∞ depending on who you ask

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#

@barren saffron Has your question been resolved?

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normal hill
#

2 B please

#

im a bit lost on how to do this without just subbing in numbers

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#

@normal hill Has your question been resolved?

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hallow sail
#

How do I get better at math

final saddleBOT
hallow sail
#

I'm in college algebra, yet I'm behind by years because I was lazy and my high school was shit

summer vale
#

aye aye

#

wassup

#

eh

#

tbh

#

practice

#

understand

#

and repeat

#

ye

hallow sail
#

ok

final saddleBOT
#

@hallow sail Has your question been resolved?

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signal ginkgo
#

can anyone help me

final saddleBOT
signal ginkgo
#

i think i have the right answer

vital crag
#

how old are you?

signal ginkgo
#

13

#

could i have help

#

???

vital crag
#

what grade are you in ?

signal ginkgo
#

7th

vital crag
#

use this rule

signal ginkgo
#

i did

vital crag
#

you're dividing by (-1/5), so instead, you multiply by the reciprocal

#

where?

signal ginkgo
#

kk

#

u can close this now btw @vital crag

vital crag
#

.close

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#
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regal vector
#

Anyone tell me about, how can I PDE by solve neural network?

final saddleBOT
#

@regal vector Has your question been resolved?

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keen frigate
final saddleBOT
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fleet rain
#

We toss coin until either the sequence of HHT appears, or HTH. WHat is probability that HHT appears first. How about unfair coin with probability p

sturdy cypress
#

first why it's 2/3

fleet rain
#

did you use the abracadbra theorem?

sturdy cypress
#

never heard of it

#

sounds mildly interesting

#

i win if hht comes first
skip the Ts at the start however many
then
HHT: i win
HTH: i lose
HHH: i win
HTT: we start over
there's 2 ways for me to win and 1 to lose, the fourth option doesn;t change my odds

#

it probably works the same for arbitrary p

#

$\frac{p²(1-p) + p³}{p²(1-p) + p²(1-p) + p³}$

soft zealotBOT
#

frownyfrog

#

frownyfrog

sturdy cypress
#

hm

fleet rain
#

we start all over at HTT since we didn't get either options we're looking for?

sturdy cypress
#

that's too short it scares me

fleet rain
#

?

#

why do we start all over at HTT?

sturdy cypress
#

like it's the same procedure to determine who wins from that point

#

because it ends with T we have the same chances as in the beginning from that point

fleet rain
#

so itll be a waste of a turn?

#

thats why we start all over at that turn?

#

@sturdy cypress

sturdy cypress
#

i don't know what you mean sorry

#

i probably can't help

fleet rain
#

im just tryna understand why we start all over when we get HTT

#

<@&286206848099549185>

fleet rain
sturdy cypress
#

the probability doesn't change from the initial

#

htt helps neither of us to win later

#

it doesn't start with H

fleet rain
sturdy cypress
#

i don't understand what you mean

fleet rain
#

since HTT helps neither of us win, thats why we would start all over if any of us flip that sequence HTT right?

sturdy cypress
#

we read the text from the beginning

fleet rain
#

why would you lose if you flip HTH?

sturdy cypress
#

what

#

it's in the text of the problem

#

HTH is the sequence that keeps HHT from appearing first if it appears first

#

i'm sorry i couldn't help, srsly

fleet rain
#

its okay at least you tried, ty

final saddleBOT
#

@fleet rain Has your question been resolved?

final saddleBOT
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tranquil pine
#

whats 2 plus 2 and 1 divided by 2

final saddleBOT
dreamy shadow
tranquil pine
#

1 divided by 2 please?

#

also how much toes do i have

quaint sail
#

Type .close

tranquil pine
#

.close

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tranquil pine
#

.repopen

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dull dirge
#

do any of you know how to find an optimal curve based on certain parameters?

dull dirge
#

i need to find the quadratic that best fits some parameters

#

like

smoky shore
dull dirge
#

all good xD

#

@rain star u mind deleting the msgs u broke my flow

smoky shore
dull dirge
#

one sec

#

its hard to explain

#

essentially i am doing a model, where i have 675.46cm^2 of surface area (material)

#

and i need to make a curve that gives me the highest maximum, with the volume of revolution from 0-that maximum being 750cm^3

#

heres a picture

smoky shore
#

ah i get it now

dull dirge
#

and im changing the curve accordingly

#

if u want the bigger picture, I have to model a wine jug, where 750ml of wine has the biggest surface area touching air, where i have 675.46cm^2 of glass for the bottom part

smoky shore
#

so do you know the equation for the surface area of a solid of revolution?

dull dirge
#

yes i do, I have the equations all down

#

one sec

#

first one is SA of a solid of revolution, the second one is volume of revolution and the third is an expression for how "tall" (y component) the jug is

smoky shore
#

so really what you want to do here is make a system of equations to solve for a and b, right? that's what it looks like at first glance

dull dirge
#

yes

#

but would that output the widest possible r? or just any r?

#

my teacher said i could use optimization as in using differentiation but i dont see how

#

i wanna find the values of a and b that make r the largest

smoky shore
#

hm that's a tough question, but you should probably try solving the equations for a and b to start off
If a and b are variable, then maybe you can model an equation to show how the r changes with respect to a and b and then differentiate that to find the maxima?

dull dirge
#

i guess thats what im trying to do

#

but this comes out

#

oh no thats broken

smoky shore
#

that's not right

dull dirge
smoky shore
dull dirge
#

and yeah a and b are variable so maybe i can think of something there?

#

i equalled the two eqn

dull dirge
dull dirge
#

and started simplifying

#

but idk it doesnt seem to be very nice

#

or doable

smoky shore
# dull dirge i equalled the two eqn

maybe a better option would be to solve the second (easier) integral for a or b by integrating it, and then plug that value into the first integral so you only have one of them

#

hm

dull dirge
#

i solved them both, and yeah the first one is simpler

#

but i dont know if i can solve for either a or b

#

one second

smoky shore
#

it looks like you can solve it for a

dull dirge
#

$-\frac{b^3}{24a^2}+\frac{b^3}{8a^2}-\frac{2.61155b}{a}$

soft zealotBOT
dull dirge
#

this is the answer for i think

#

without accounting for pi or 750

smoky shore
#

yeah i got that too, so you can just multiply both sides by a^2 and then use the quadratic formula?

dull dirge
#

one sec

#

u can simplify it

#

$750a^2=\frac{\pi :b^3}{12}-\pi :2.61155ab$

soft zealotBOT
smoky shore
#

$a=\frac{-\left(12\left(5.2231\right)b\right)\pm\sqrt{\left(12\left(5.2231\right)b\right)^{2}-4\left(\frac{18000}{\pi}\right)\left(2b^{3}\right)}}{2\left(\frac{18000}{\pi}\right)}$

soft zealotBOT
dull dirge
#

how did u get there lol

#

am i dumb

smoky shore
#

quadratic formula

#

right?

smoky shore
dull dirge
#

but apply the quadratic formula to what

smoky shore
#

to a

#

you use the quadratic formula to solve for a

dull dirge
#

yeah but theres an a on the oter side too...

smoky shore
#

move them all to one side

dull dirge
#

ooooh im otist

#

whered the 180000 come from? why multiply it thru by 24

smoky shore
#

i just did that to preserve the 5.2231, if you simplify my expression you should get the same thing that you would get by doing the quadratic formula on the expression you got

dull dirge
#

ah i see

#

how would i adjust a and b then tho?

smoky shore
#

i would assume after solving for a like this, you can probably plug it in to the equation for the radius? and then just find the maxima by differentiating with respect to change in b?

dull dirge
#

ah okay ill try

#

and id incorporate the other eq by plugging a= there?

smoky shore
#

yeah i suppose so

dull dirge
#

well here goes nothing

#

ill try rq so ill leave this open

#

for now tho tysm u saved my adhd ass

smoky shore
#

hah i hope it works man. i have no idea if it will but it should i think

dull dirge
#

i hope it will

#

if not ill turn this in and figure it out with my teacher

#

its only a first draft so

dull dirge
smoky shore
#

hm, you might be right about that, if you think it's supposed to be negative just make it negative ill double check my work

dull dirge
#

ill redo mine too xD

fleet rain
#

sorry

final saddleBOT
#

@dull dirge Has your question been resolved?

dull dirge
#

wait but @smoky shore this is still a in terms of b

smoky shore
dull dirge
#

confusion

#

oh

#

i get it

#

oh nooo

#

thats gonna be pain

#

dont i need to integrate the other eqn then too

#

oh noooo

#

$\frac{\pi \left(5.2231\left(-0.5b\sqrt{b^2+1}-0.5\ln \left|b+\sqrt{b^2+1}\right|\right)+\frac{b\sqrt{b^2+1}+\ln \left|b+\sqrt{b^2+1}\right|-2b\left(b^2+1\right)^{\frac{3}{2}}-4b^2\left(-b\sqrt{b^2+1}-\ln \left|b+\sqrt{b^2+1}\right|\right)}{32\cdot \frac{-12\cdot :5.2231b\pm \sqrt{\left(12\cdot :5.2231b\right)^2-4\cdot \frac{18000}{\pi }\left(-2b^3\right)}}{2\cdot \frac{18000}{\pi }}}\right)}{\frac{-12\cdot :5.2231b\pm \sqrt{\left(12\cdot :5.2231b\right)^2-4\cdot \frac{18000}{\pi }\left(-2b^3\right)}}{2\cdot \frac{18000}{\pi }}}$

soft zealotBOT
dull dirge
#

hmm

#

delicious

#

<@&286206848099549185> anyone know a site that can find b for me from this soup?

solar swift
#

.w $\frac{\pi \left(5.2231\left(-0.5b\sqrt{b^2+1}-0.5\ln \left|b+\sqrt{b^2+1}\right|\right)+\frac{b\sqrt{b^2+1}+\ln \left|b+\sqrt{b^2+1}\right|-2b\left(b^2+1\right)^{\frac{3}{2}}-4b^2\left(-b\sqrt{b^2+1}-\ln \left|b+\sqrt{b^2+1}\right|\right)}{32\cdot \frac{-12\cdot :5.2231b\pm \sqrt{\left(12\cdot :5.2231b\right)^2-4\cdot \frac{18000}{\pi }\left(-2b^3\right)}}{2\cdot \frac{18000}{\pi }}}\right)}{\frac{-12\cdot :5.2231b\pm \sqrt{\left(12\cdot :5.2231b\right)^2-4\cdot \frac{18000}{\pi }\left(-2b^3\right)}}{2\cdot \frac{18000}{\pi }}}$

soft zealotBOT
#

internet

solar swift
#

yikes

dull dirge
#

hmm

solar swift
#

wolfram alpha lol

dull dirge
#

does wolfram take latex

solar swift
#

oh wait its past the max chars

dull dirge
#

i havent been able to

#

no... fffffffffffffffff

#

can i DL a wolfram alpha with more max chars

solar swift
#

not sure

#

i know symbolab takes latex

dull dirge
#

yeah symbolab is just deding on this

#

idk what the problem is

#

its just b with a bunch of things around it

#

solve!

#

@solar swift can u think of another way to put this

#

into that

solar swift
#

id have to see the original expression

dull dirge
#

for what one

#

there all here

#

i can link u them

dull dirge
solar swift
dull dirge
#

@solar swift

#

i did the integration, rearranged it and did a quadratic formula

#

now i need to put it into that other integral

#

but symbolab and wolfram just die if i try

solar swift
solar swift
#

ive never used the math input

dull dirge
#

wait what is this?

solar swift
#

the 2nd integral you sent?

#

heres the wolfram page

dull dirge
#

no but the way ur writing in wolfram

solar swift
#

the int stuff is latex but the rest is just words

dull dirge
#

well shit

#

this absolutely doesnt give me the right answer

#

could u help me out from the start? i am hopeless at this point

solar swift
#

depends on what it is tbh

dull dirge
#

essentially i am doing a model, where i have 675.46cm^2 of surface area (material), and i need to make a curve that gives me the highest maximum, with the volume of revolution from 0-that maximum being 750cm^3. The y intercept is fixed at 5.2231.

#

so what i did is make 3 equations

#

and im adjusting a and b to get the highest r, but they need to follow the two equations so the parameters are followed

#

this is a drawing i made of it

#

if u want the bigger picture, I have to model a wine jug, where 750ml of wine has the biggest surface area touching air, where i have 675.46cm^2 of glass for the bottom part

solar swift
#

yeah ngl i dont really know revolution stuff, it doesnt get taught until 3rd year uni where i live

dull dirge
#

the revolution stuff is chill, idk how to do the optimization

#

its just 2 equations

#

<@&286206848099549185>

solar swift
dull dirge
#

?

#

omg im an idiot

#

doesnt change anything tho sadly

solar swift
#

yeah i mean i check wolframalpha for the first one and the a,b values never make the SA equation equal to what you want

#

i think it might either be the curve of the interval points

dull dirge
#

yeah

#

im fucked

#

theres no way im gonna solve this

#

i dont even know how i could possibly create an equation for r out of this

#

cos thats what i need really

#

a way to express r that incorporates the volume and SA

solar swift
#

also the r equation is wrong

dull dirge
#

wym how

solar swift
#

nvm no it isnt

dull dirge
#

<@&286206848099549185>

coarse yacht
#

What can I do for you?

dull dirge
#

hey

#

I'm working on an optimization question, where I am trying to find the optimal quadratic maximizing the y component of the maximum, with 2 parameters

#

The surface area of the solid of revolution = 675.46cm^2, and the volume of revolution from 0-maximum =750cm^3

#

The y intercept must = 5.2231

#

i did a fancy illustration

#

i can show u what ive done already

#

i somehow need to combine these i think, though im not really sure

#

@coarse yacht u got any idea?

coarse yacht
#

Okay

#

So you'll end up with an equation with a and b

coarse yacht
#

In function of a and b

coarse yacht
dull dirge
#

but im trying to adjust a and b to get the optimal r

#

or is that not possible?

coarse yacht
#

Oh

#

In that case

coarse yacht
soft zealotBOT
#

black_couscous

dull dirge
#

canonical what

#

oh

#

like standard form

#

is it like y=(x-4)^2+14

#

@coarse yacht

coarse yacht
#

Yes

dull dirge
#

how would i do that? like in terms of a and b

#

@coarse yacht

coarse yacht
#

You know you can express it that way $y = (x- \frac{b}{2a})^2 + smthg$

soft zealotBOT
#

black_couscous

dull dirge
#

really?

coarse yacht
#

You can use $r$ to express $\frac{b}{2a}$

#

Yes

soft zealotBOT
#

black_couscous

dull dirge
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wait but how would i find that lol

coarse yacht
soft zealotBOT
#

black_couscous

dull dirge
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okay, now that i have that how can i incorporate the other 2 eqns?

coarse yacht
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Yup

dull dirge
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but how

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$y=a(x+ \frac{b}{2a})^{2}+r$

soft zealotBOT
dull dirge
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this is what i got

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what do i do with this?

coarse yacht
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You can express b/2a as a function of r

dull dirge
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wait what

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im giga confused now

coarse yacht
dull dirge
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but where do i use that??

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$\frac{b}{2a}=\sqrt{r+5.2231}$ ????

soft zealotBOT
dull dirge
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@coarse yacht can u explain pls

coarse yacht
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Yes

coarse yacht
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And compute the integrals

dull dirge
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plug what?

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u mean i should use this as y?

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yo?

coarse yacht
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Yes

dull dirge
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ok i will try

final saddleBOT
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@dull dirge Has your question been resolved?

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tranquil pine
final saddleBOT
tranquil pine
#

I got the first part

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But not sure how to do the second one without multiplying and making the factors of f(x)

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Is there some other approach?

final saddleBOT
#

@tranquil pine Has your question been resolved?

grim nebula
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@tranquil pine possibly symmetry?

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you know f is symmetric in x=6

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so the roots should add to that maybe

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,w (x-1)(x-3)(x-5)(x-7)+15=0

grim nebula
void crest
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twerk

grim nebula
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im blind

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it's symmetric in x=4

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so yeah the average is 4

tranquil pine
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Hmm

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Ok so I have to look for symmetric expressions here

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Got it

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tranquil pine
#

.close

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gleaming mantle
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gleaming mantle
#

Need help with b

cold gorge
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Anything you've tried

thorny tendon
#

@gleaming mantle ^

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dull orchid
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dull orchid
#

ak is ksin(1/k)

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so how is the limt of ak =1 as k goes to inf?

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cuz it woul be inf *0

vital crag
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where's the question

vital crag
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instead of the series?

dull orchid
vital crag
dull orchid
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solid lance
#

I need help with my math. So the topic is, Finding the equation of a quadratic function. How to find the quotation of a quadratic function given: (a) table of value, (b) graph, (c) zeros; y= ax² + bx + c, is determined by 3 points. Point is named by its ordered pair (x,y). Find the value of a,b and c. To get the answer substitute 3 ordered pairs (x,y) in y=ax²+ bx + c.
I've already got the a and c now I can't get the value of b

solid lance
final tangle
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show work

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final saddleBOT
limpid orchid
#

Can you ask more clearly

final saddleBOT
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@outer storm Has your question been resolved?

lime bison
#

oh hey its you again!

placid bobcat
#

these would be θ/2 as well

limpid orchid
#

Use trig only for right triangles

placid bobcat
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you have to find the base and height values for the area right
so you use the shaded right triangle and find those values using trigonometry

you have to have a right triangle to write those things you know

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yeh sorry but i was just trying to say you have to use the same right triangle for the second case as well

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so it would be θ/2 only

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can u tell me the length of red line?

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are you sure

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ah yeh

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no no

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first

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before using trigonometry u need to have a right triangle

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can you outline the right triangle on it?

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right

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now do you see what x is

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yep

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similarly the perpendicular would be rsin(θ/2)

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now is it fine?

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i get that but

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that second triangle you wont have cosθ and sinθ right
those would be cosθ/2 and sinθ/2 no

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ah its fine then i will stop

final saddleBOT
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dull dirge
#

im bacl

final saddleBOT
dull dirge
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i got a problem

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where this turns into 0...

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which idk i think it should be impossible

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or better said i have to do simultaneous eqn of these 3 things

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<@&286206848099549185>

#

<@&286206848099549185>

final saddleBOT
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@dull dirge Has your question been resolved?

dull dirge
#

<@&286206848099549185>

final saddleBOT
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@dull dirge Has your question been resolved?

dull dirge
#

<@&286206848099549185>

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pleasee help

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<@&286206848099549185>

#

anyone please

dull dirge
#

<@&286206848099549185>

#

<@&286206848099549185>

dull dirge
#

.close

final saddleBOT
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trail osprey
final saddleBOT
vestal frigate
#

,rccw

soft zealotBOT