#help-36
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yes
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How do I reflect it?
i tend to use a mirror
however the angle of the mirror may put you off
however you maybe be able to do it with matricies
im sure there is a reflection matrix
count the units it took to get to that line and then put that point next to however many units you counted
or this ^
yeah you got it
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Scores in golf can be positive or negative integers. For example, a score of 5 over par can be represented by +5 and a score of 4 under par can be represented by -4. If Donna has scores of 3 over par, 5 under par, and 4 over par for three games of golf, what was her total score?
@rotund warren Has your question been resolved?
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hello
What have you tried? 🙂
Good idea
havent had any success
Yes, what do you think is a suitable common basis?
18?
whats common for all those numbers?
Yes 👍
ok
try converting everything to base 3
18 and 6 cancel
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im doing y = mx + c in class and i forgot how to do it need some help
c is the intersection with the y axis
1?
Yes 👍
3 then
Yes
y= 3x + 1
yes
Very good
y = 2x + x?
no
0.5
since every 1x y passes 0.5
and +2 since y intercept is 2
@woven isle Has your question been resolved?
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if we have an increase of 85 percent, we start with 100 so we add them
- 85% increase
100 + 85 = 185.%
move the decimal over two places to get
1.85
great question: here is an example
Example) 60% decrease
100 ||- 60 = 40.% ||
move the decimal over two places to get
||0.40||
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How do we know the RHS is referring to x=0 or y=0?
Yeah
use complwtw the square
It’s a constant, so a straight line right?
hm y=0 then
x^2-3x-10<=0
(x-3/2)^2-9/4-10<=0
(x-3/2)^2<=49/4
x-3/2<= +- 7/2
x<=(3 +- 7)/2
Ugh.. syntax
I wish discord would automatically write math to be more readable using keyboard math syntax
I look at this and my brain melts
yeah we have a latex bot but im on mobile
I don’t think I would need to do all this math each and every time to know if x=0 or y=0 on the right hand side of the inequality?
The question itself seems so simple
It’s asking when the parabola is below the x axis
But I just don’t understand from glancing at it whether it’s below the x axis or left of the y axis
I know for sure it’s looking for when it’s equal to 0 and below 0, just don’t know if it’s for x axis or y axis
Oh
i.e. the points below the x-axis
Interesting.. would a better way to write this question be with f(x)= in front of LHS and RHS?
it literally does not matter
OK
you can use the quadratic formula to quickly get the roots and use the roots as your bounds
also wtf martin
the last 2 lines are complete nonsense
yeah and thats wrong
how so?
alright this latex is just not working
this is straight up not how you solve quadratic inequalities
i guess finding roots and then looking which areas are under 0
here we have only 2 roots so that is quick
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help
Bring z to one side
ok
First multiply the bracket out
start by simplifying the right part
What does it give?
uhh
move z to one side
so subtract 8 form both
8z yeah
so z+4
No
so 0z
4?
both the left and the right
What is the equation
idk
+4?
you're not typing the left side
so 0z=4
0=4
Does this make sense?
Can 0 be equal to 4?
no?
what would i write for the answer
or that z has no real solutions
yeah
Like 8th grade I think
I think I did this in like 8th grade yeah
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find where the derivative of the equation is equal to 0
so I found the derivative of -2sinx + 2cos2x
but how do I solve for x
I can cancel out a 2 but then I still dunno
remember that sinx/cosx=tanx
mhhm how can that help me tho
wait, giveme a second to think
this is pretty much unhelpful here
yeah I realized that after lol
The function will have horizontal tangents at x = pi/6, x = (5pi)/6 and x= (3pi)/2. The tangent will be horizontal when the slope (or the derivative) equals 0. By the product and chain rules, we have: f'(x) = -2sinx + 2cos(2x) Set this to 0 and solve for x. 0 = -2sinx + 2cos(2x) 0 = -2sinx + 2(1- 2sin^2x) 0= -2sinx+ 2 - 4sin^2x 4sin^2x + 2sinx -...
its just this
@supple copper Has your question been resolved?
quadratic in sin(x)
use a substitution jutsu if youd like
thought not 100% necessary
@supple copper Has your question been resolved?
thanks!
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can someone explain how they did this step?
I believe multiplying by gcd of (x+h)^2 * x^2, but can you just flip the fraction? and how it's the 1-1=0*everything = 0?
combine fractions, common denominator etc
I assume this is an inbetween step, but where did the 1-1 go? where did the (x+h)^2x^2 come from, or is that multiplying by gcd?
no, what you just wrote is completely illegitimate
recall how you'd simplify
$$\frac12 - \frac13$$
you wouldn't say that's $\frac{1-1}{2-3}$ (which is 0) would you?
ℝamonov
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How does this happen
x/2 is the same as (1/2)x
Ig that makes sense so would I put the 1/2 outside of the square root or inside
Actually i think its inside nvm
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Could someone please help me with this, this is due at 11:59
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@lucid heart Has your question been resolved?
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what is the pattern from 3, 7, 15?
well
what was the one u got
This one
ah k
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Is there a good explanation about vectors?
a explanation video
vectors are a quite broad topic, is there anything more specific you want the video to be about? or just an introduction to vectors?
at which level? high school or undergrad?
undergrad
well I saw the one of 1blue3brown and the ones of the organic chem tutor.. but i dont really understand it still
From MIT OpenCourseWare: https://ocw.mit.edu/courses/18-02sc-multivariable-calculus-fall-2010/pages/1.-vectors-and-matrices/part-a-vectors-determinants-and-planes/
in this section (1-A) there are good explanation videos with examples about vectors
you're welcome
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hey guys I have atleast I think some what of a niche problem im trying to solve im trying to fit squares in A4 format (in pixels) used 6 squars to start can explane all details in channel
so basically Im working with the format of 5906x4134 pixels that I later trimmed to 5906x3638 pixels since I was able to successfully fit 6 squares of initial size of 126x126 each upscaled to the canvas size
now im trying to figure out the cleanest way to increase the square amount to around 900ish +/- with the cleanest numbers basically with no more then 2 decimals (the size of square side in pixels)
eh
yep
just find an equ for numb of squares u can fit for some length x in pixels
solve for that =900 n round up or down as u like it
whelp is there a more simple way to do it I have been trying but decimals are a problem
sorry im not here xd I have lost it a bit for how long I have spent on this and its late mb
.
thats the one I used 126x126 6 squares and upscaled to fit exactly the size
,w solve 5906/x +3638/x=900
,calc 2386/225
Result:
10.604444444444
wait wut
hm
,calc sqrt(5371507)/15
Result:
154.51007877949
154.51?
.
so that worked?
i think use this but plug in the approriate sizes
whelp not exactly as close as I would like to
ok ty
len1/x * len2/x = numsquares
,calc solve 5906/x *(4134/x)=900
The following error occured while calculating:
Error: Invalid left hand side of assignment operator = (char 23)
o well just enter that val into a calculator or similar ig
ok ill try ty for the help
@vivid tendon Has your question been resolved?
,w solve 5906/x *(4134/x)=1000
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$f_1 \in F^E$
What does it mean?
f_1 is a function from E to F
A function not an element?
functions can be elements of sets
even as simply as {f}
f is a function, its also inside a set
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what does the phrase "all elements that have one" mean?
not all elements of a field have a multiplicative inverse
for the ones that do, t hey want you to write it down
okay thanks, i was thinking they wanted the elements that have the value "1" lol
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,rotate
What are factors of 2009
@odd parrot Has your question been resolved?
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I have no idea how to proceed
,rotate
You have the formula pH = -log("concentration H+"
can you help me
Yea, but like
2.5*10^-8=PH?
Here you already know the concentration. So all you need to do is plug the number into the log
-log(2.5*10^-8)= pH
You can open a new channel 🙂
- Log is usually short for log base 10
I must be stupid, or something
Because it’s not really making a lot of sense what I need to do
Do I remove what’s in the parentheses, or convert to exponential?
What is your result?
Well, it says the answer is 7.60
In terms of result, I don’t know what to do
That makes sense
I’m gonna try plugging it into a calculator
I got the answer from the calculator
I was just overthinking it lol
Thanks
You're welcome
@deft ravine I have another question, if you don’t mind
Yes?
How do you solve B?
Don't like the wording of the question, but ok
Yea, it’s kind of weird
Have you already tried anything?
Well, I know it’s 6.93 because I tried it in the calculator
I just wanna know if there’s another way
You can say 5 = 10 * e^(-0.1t) and solve for t
Alright, thanks
You're welcome. I can't answer another question as I go to bed now.
Good night, then
Thanks
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1/3 is the coefficient in h(t)=t/3, why?
um
its the coe of t
like
coe is like
kt
k is the coe of t
in this case weve
t/3 = (1/3) t
namely k or the coe =3
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Nothing. I don't know how to do it.
that doesn’t give a solution lol
if you solve for y in the second equation you’ll find that the two equations are actually the same. so their intersection is the entire line y = 3x + 1
bruh I wish I understood this fully 
So if I do it by doing the reg equation for graphs with the second one ill get my answer?
if i asked you for the set of values that satisfy the two equations y = x and 2y = 2x, you’ll notice it’s just the line y = x
so you can say any point (x,x) satisfies the system of equations
similarly, the set of points for your system take the form (x,3x+1)
you can graph them if you want, but to show it rigorously you’ll need some kind of math
in general, a system of linear equations will have no solution if the lines don’t intersect, 2 solution if they intersect but aren’t parallel, and infinite solutions if the equations are equal (same line)
(1, 4) is one of infinitely many points of intersection between the two lines
any point (x, 3x + 1) will work
for x=1 you get (1,4
for x =2 you get (2, 7)
for x = -pi you get (-pi, -3pi + 1)
what are your possible answer choices for this question
i’m talking about on the software
here just substitute y = -x + 5 into the first equation
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Hi can someone help me with this problem? I don't understand how q < sqrt (n / p)
@fiery pendant Has your question been resolved?
I think it should be a ≤ sign
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For d why did they make it negative
um
|z-c| = a^2
means a circle of radii a
centered about c
so they put it in the form of z-something
so they can tell what point is the center of the circle
@feral siren
@feral siren Has your question been resolved?
So |z-c| always has to be negative?
um
no
it can be positive or negative
consider
|z-1|
its a circle centred at 1
then consider
|z+1|
its a circle centred at -1
|z-(-1)|
this is just rewriting it
doest do anything
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can someone explain how to solve this one?
im pretty sure im supposed to find the derivative of the function and then plug in 1 for x?
first you can find derivative
yeah but I feel like I got it wrong
then sub x=1 into your y equation to find your y-coordinate
then substitute x and y coordinate to find C
in your tangent equation
I got as the derivative
oh wait
no need
since they only want slope
oh wait I remember that in the book
ok just the slope tho
does the derivatrive look correct?
looks okay to me
but I’m doing it in my head
so idk HAHA
,w derivative of e^(-x) / x+1
ok I got the answer its -3/4e
oops didn’t type correctly
yeah when you plug in 1 you get -3/4e
okay then it shd be the answer
alr but
ok
thanks
srry I was gonna say on the real test im not gonna be allowed a calculator but that doesnt really matter if im plugging in one
thanks for the help cya
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no prob!
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how do i approach this
ik its something to do with elimination
i cant figure out the equations needed
i have let x be the amount of 30%
and y be the 50%
and x+y=5
but whats the second equation
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<@&286206848099549185>
@icy ice Has your question been resolved?
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why is this proof incorrect?
because the base case is wrong
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why is this proof wrong
how do you find a_2 using the base case and the recurrence
what?
don't you prove that p(n) -> p(n+1)
a_2 would be 4a_1 - 4a_0 but a_0 is ??
these past two questions
i dont understand the structure of the proposition
in induction im usually given p(n) as a premise and am left on my own to forge a conclusion by making a base case and proving that p(n) -> p(n+1)
but here im given a base case as a premise and p(n+1) and am asked to show that p(n)
which makes no sense to me
am i just reading it wrong
well youre misunderstanding
this is a definition of the recurrence
this is what you're trying to prove
the definition has nothing to do with the proposition
you could have just written
oh so are propositions that invite induction just written weirdly
where i prove the premises in the "if" part to show that the then is true
aka just proving the base case and then proving that p(n) -> p(n+1)
to show that p(n) is true
no
you're trying to show that p(n) holds for all n
so you show that p(k) -> p(k+1) for some arbitrary integer k
and that p(base case) holds
yeah ok i think i understand now
i was just confused about how the propositions were writtent
thanks
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What happened at the place i circled? 7x-3x=4x not -4x?
It’s -7x -(-3x)
You got a minus sign in front
And also a minus sign in front of 7x
a minus sign not a negative?
so why would you make it a negative sign?
Maybe it'll be more intuitive if you factored in the minus, and added the negative
Minus sign and negative sign are the same thing
isnt minus like 4-3=1
Sure
negative is below zero
negative is a word not a number
4-3 is a fancy way of saying 4 + (-3)
Try to be precise
It still isnt clear....
so if i see a minus sign I can just make it a negative?
@rare cradle
Idk what u mean by "make it a negative"
idk what I mean as well anymore lol
^
what did we do with the minus in my question
wdym?
Did you see that minus too, yes?
if you distribute you get -x^2 + 3x
Yeah, now add* x² - 7x + 12 to that
lol
not add subtract right
So you have to do this
x² - 7x + 12 - (x² - 3x)
Do you agree?
Do synthetic division
not long
why?
so the minus sign changes the signs in the parenthesis and you get
x² - 7x + 12 - x² + 3x
ive started long
thx annywayy
yes
and that's where that -4x comes from (original question)
x^2-7x+12
-x^2+3x
i still get 4x
i do it vertically
-7x + 3x 
This thing is just x² - 7x + 12 - x² + 3x
yes
I don't understand your question
oh no i didn't mean to say yes lol
still dont get where -7x comes from
Here you are just adding (or subtracting) things
with numbers only, (unrelated example)
45 -
22
Is the same as 45 - 22
Or (another unrelated example)
56 +
12
Is the same as 56 + 12
yes
lol
it isn't negative in front of it, it is a minus?
7x
adding and subtracting things is the same thing, it's all sums
4 - 2 is 4 + (-2)
If you have
x² - 7x, then it's x² + (-7x)
🤦♂️
thanks
so much
if you didn't help me I would have spent my whole life on a grade 5 thing lol
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Hi I'm supposed to find the slope of the tangent line using implicit derivitive of:
It's D3 and i have started the process of finding the derivitive but i feel like im doing it wrong
In short, how do i do implicit differentiation right? and then apply that to finding the slope
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what's the question?
what he said
this
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:(
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How can I solve for x in this case?
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what is 3^3 * 3^1/2
you did the actually hard part this is just simple exponent rule
,rotate
Oh. I guess I was blanking on the adding a whole number to a fraction part and that was making it seem like I had gone the wrong route
Thanks for that! 🙂
How do I close this? 😄
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thanks
np
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Hey guys
Can someone please help me out with Euler's formula?
How do I get this to this?
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Can I get the line in some other from out of this? or if someone wants to just give the answer that would be great too
what other form are you looking for?
the exercise as-written is, in some sense, lying to you about these equations defining a line. this isn't a straight line but rather a curve.
...not that it stops you being able to find the intersections thereof with that plane, but still.
you know the form of the points on the line (which is not exactly a line but whatever):
x = -3t + 5 ; y = t + 2 ; z = t^2 + 5.
So anywhere on the line, x - 2y + z = ?
form of the points?
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c = 30, r = 6. Calculate the perimeter
what's c supposed to represent
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Hi.. another question.
I'm very unfamiliar with the idea of complex logarithms except for the basic knowledge of the formula.
Trying to find the calculations for ln(i), the only proof I can find so far is one using Euler's identity. Is it possible to prove complex logarithms without it?
prove complex logarithms?
it's not really something you can prove, because it is a definition
perhaps explain is a better word? as in explain how the application of ln(i) produces its result
well firstly, ln(i) usually is preferred to as a weird notation, since natural log is only defined for positive real numbers. So this is where we would introduce the complex logarithms
the idea of this is to just have it as an inverse of the complex exponential funciton
but one problem is that, the complex exponential function is a single-valued function, its inverse on the other hand would be a multi-valued function if we dont put on a bound for the argument
so thats just why, it's because e^(z) may produce one unique complex number w, for infinitely many z. The inverse of this, ie log(z) produces a tons of numbers for just one value
now how the the derivation for log(z)=ln(r)+itheta came can be explained by the idea that we want an inverse, so this inverse when composed with the exponential function, i.e e^(z) gives us back z
so lets just give it a new notation, which in this case is log
now note that z can be represented as re^(itheta+2kpi) where r is the magnitude of z and theta is the principal argument of z, k is any integers
then $\log(z)=\log\left(re^{i(\theta+2k\pi)}\right) = ln(r)+i(\theta +2kpi)$
waler
this is the multivalued representation of the complex log funciton
for the principal branch, just set k=0
waler
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thank you !
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is 2^3(2^4) = 2^7 or 2^12?
2^7
ok
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Lol you're good.
Anyways, guys, this is an improper integral problem.
I used an U sub for e^3x
and it doesn't seem to work
Turns out it diverges but my Wolfram Alpha calculation says it converges to pi/6
Yeah, but not sure how to get there.
U Will use this
so split the integral into two parts?
And after i Think
Hm
No
Look at the interval
Anyway u Will use integral
the denominator
Defined integral
And limite
Sorry i study maths in French
So thats hard to explain
Im not a man
Okay got you
Idk im 15 yo
Ok so anyways.. do you know how to solve my improper integral
Yes i Know
So to to evaluate the improper integral rewrite it using a limit and a definite integral
Yes i think so
U Will calculate the indefinite integral
Ok so when you calculate the indefinite integral of it, you use the U-substitution right?
Um what
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Kimchi do u need help Again ?
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i have tried substituting the second equation into the first to find their intersection however i am confused as to where the (2k-1)x comes from in the given equation
equations are: y=2x^2-x-1, y=k(2x-3), 2x^2-(2k+1)x+3k-1=0
what i get is 2x^2-x-1-2kx+3k
yes
just need to factor x and a negative out
look at your -2kx-x
you can write as -x(2k+1)
which is -(2k+1)x
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Am I correct to say this should be 3?
Since A + B is 14
And they want the complement
Yeah I think so
Also I was wondering why this one is true
I put in false
Last time but it said it was incorrect but did not give an explanation
5 is a member not the set of 5
${5}\subset {1,2,3,4,5}$
black_tea
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wooo
to long
in the second last numerator you have -1+1 it isn't ?
sorry but you can say it is zero from the start i think..
the function is continuous in -1
lol
its continuous in the domain (-.inf, -1]u(1,+inf)
so just plug in -1
sorry
i am tired..i say it wrong
the domani is (-.inf, -1)u(1,+inf)
so you can t simply plug in
its wrong because you see from the graph that the answer is 0
ok lets try this:
What happened in the 4th step
$\lim \frac{x+1}{\sqrt{x^2-1}}=\lim -\sqrt{\frac{x+1}{{x^2-1}}}=\lim -\sqrt{\frac{(x+1)^2}{(x+1)(x-1)}}$
If i were u id do lhopital from the start
now just simplify and it should be trivial
everg
Shouldn’t the x+1 under the root be squared?
@astral sleet Has your question been resolved?
yes ikea
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I’m not sure how to go about writing this proof. I need to prove that m must be a prime number for mod m in order to have k=(m-1)/2, where k is the number of elements in the set D, and D is the set of nonzero squares of the elements of mod m
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@vale python Has your question been resolved?
number of squares mod m hmm
if you know group theory you can look at the group of equivalence classes from 1 to m-1 under multiplication
then the answer follows from lagrange's theorem
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