#help-36

1 messages · Page 8 of 1

fallen reef
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Is this true

void valley
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yes

fallen reef
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Great

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Thanks

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fierce swift
final saddleBOT
fierce swift
#

How do I reflect it?

tawdry sable
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oh

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i see

wanton glacier
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first draw the line y = -2

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then for each individual point

tawdry sable
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i tend to use a mirror

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however the angle of the mirror may put you off

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however you maybe be able to do it with matricies

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im sure there is a reflection matrix

wanton glacier
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count the units it took to get to that line and then put that point next to however many units you counted

tawdry sable
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or this ^

wanton glacier
#

it'd be a bit easier to explain if we were in a vc lol

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it aint that difficult

fierce swift
#

is it like this?

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wait the line is slightly off

wanton glacier
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yeah you got it

fierce swift
#

ok thanku

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rotund warren
#

Scores in golf can be positive or negative integers. For example, a score of 5 over par can be represented by +5 and a score of 4 under par can be represented by -4. If Donna has scores of 3 over par, 5 under par, and 4 over par for three games of golf, what was her total score?

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rotund warren
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near thistle
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hello

final saddleBOT
near thistle
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pls help :D

deft ravine
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What have you tried? 🙂

near thistle
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converting it into same bases

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tried messing with the sq root to ^0.5

deft ravine
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Good idea

near thistle
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havent had any success

deft ravine
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Yes, what do you think is a suitable common basis?

near thistle
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18?

cedar cipher
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whats common for all those numbers?

near thistle
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oh 3

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uh

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is that wrong?

deft ravine
near thistle
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ok

cedar cipher
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try converting everything to base 3

near thistle
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oh alr ty

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how would the bottom 6 be converted into 3? its 3^1.63..

deft ravine
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18 and 6 cancel

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woven isle
#

im doing y = mx + c in class and i forgot how to do it need some help

deft ravine
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c is the intersection with the y axis

woven isle
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1?

deft ravine
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Yes 👍

woven isle
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whats the gradient

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2?

deft ravine
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No

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m = Delta y / Delta x

near thistle
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so basically

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its y2-y1/x2-x1

woven isle
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3 then

deft ravine
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Yes

woven isle
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y= 3x + 1

near thistle
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yes

deft ravine
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Very good

woven isle
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y = 2x + x?

tired walrus
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this is definitely not y = 3x

woven isle
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thT=at was a different question

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that*

near thistle
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0.5

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since every 1x y passes 0.5

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and +2 since y intercept is 2

woven isle
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yeah i get that now

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y = 4x -3?

near thistle
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yes

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:D you got it!

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stoic mural
#

if we have an increase of 85 percent, we start with 100 so we add them

wise pond
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  1. 85% increase

100 + 85 = 185.%

move the decimal over two places to get

1.85

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great question: here is an example

Example) 60% decrease

100 ||- 60 = 40.% ||

move the decimal over two places to get

||0.40||

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oak kraken
final saddleBOT
oak kraken
#

How do we know the RHS is referring to x=0 or y=0?

near spoke
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what rhs

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the 0?

oak kraken
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Yeah

stoic mural
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use complwtw the square

oak kraken
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Right hand side

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I mean just by looking at it

near spoke
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just a restriction on x

oak kraken
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It’s a constant, so a straight line right?

near spoke
stoic mural
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x^2-3x-10<=0
(x-3/2)^2-9/4-10<=0
(x-3/2)^2<=49/4
x-3/2<= +- 7/2
x<=(3 +- 7)/2

oak kraken
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Ugh.. syntax

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I wish discord would automatically write math to be more readable using keyboard math syntax

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I look at this and my brain melts

stoic mural
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yeah we have a latex bot but im on mobile

dark flax
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Can someone help me out?

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The domain and range

oak kraken
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I don’t think I would need to do all this math each and every time to know if x=0 or y=0 on the right hand side of the inequality?

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The question itself seems so simple

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It’s asking when the parabola is below the x axis

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But I just don’t understand from glancing at it whether it’s below the x axis or left of the y axis

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I know for sure it’s looking for when it’s equal to 0 and below 0, just don’t know if it’s for x axis or y axis

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Oh

soft zealotBOT
grim nebula
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i.e. the points below the x-axis

oak kraken
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Interesting.. would a better way to write this question be with f(x)= in front of LHS and RHS?

grim nebula
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it literally does not matter

oak kraken
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OK

cedar cipher
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you can use the quadratic formula to quickly get the roots and use the roots as your bounds

grim nebula
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the last 2 lines are complete nonsense

stoic mural
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wdym?

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i took squate root

grim nebula
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yeah and thats wrong

stoic mural
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how so?

oak kraken
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OK not just me looking at that and brain going

stoic mural
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oh

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oh yeah

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totally

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didnt think about that

grim nebula
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alright this latex is just not working

soft zealotBOT
grim nebula
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this is straight up not how you solve quadratic inequalities

stoic mural
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i guess finding roots and then looking which areas are under 0

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here we have only 2 roots so that is quick

oak kraken
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frigid oasis
#

help

final saddleBOT
frigid oasis
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<@&286206848099549185> 8z=4(2z+1)

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what is z

paper ginkgo
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Bring z to one side

frigid oasis
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ok

paper ginkgo
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First multiply the bracket out

steep maple
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start by simplifying the right part

paper ginkgo
frigid oasis
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so 8z

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=4

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+4*

paper ginkgo
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8z = 8z+4 yes

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Now?

frigid oasis
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uhh

steep maple
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move z to one side

frigid oasis
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so subtract 8 form both

steep maple
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8z yeah

frigid oasis
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so z+4

paper ginkgo
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No

steep maple
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no?

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subtract 8z from both sides

frigid oasis
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so 0z

paper ginkgo
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Whole equation

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What is it now

frigid oasis
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4?

paper ginkgo
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This is not an equation

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This is a number

steep maple
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both the left and the right

paper ginkgo
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What is the equation

frigid oasis
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idk

paper ginkgo
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8z-8z = 8z-8z + 4??

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What is this

frigid oasis
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+4?

paper ginkgo
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Equation

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Keep the = sign

steep maple
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you're not typing the left side

frigid oasis
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so 0z=4

steep maple
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0=4

paper ginkgo
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Does this make sense?

frigid oasis
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ohh

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so the answer is 0=4?

paper ginkgo
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Can 0 be equal to 4?

frigid oasis
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no?

paper ginkgo
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Yeah so the equation is impossible

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It’s an inequality

frigid oasis
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what would i write for the answer

paper ginkgo
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8z < 8z+4

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That’s all you can say here

steep maple
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or that z has no real solutions

frigid oasis
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ok

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so its -0?

steep maple
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no

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z isn't equal to anything

frigid oasis
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ok

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so its like undifeinde

steep maple
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yeah

frigid oasis
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ok

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what level math was that

paper ginkgo
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Like 8th grade I think

steep maple
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I think I did this in like 8th grade yeah

frigid oasis
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ok

#

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supple copper
final saddleBOT
latent cloak
#

find where the derivative of the equation is equal to 0

supple copper
#

so I found the derivative of -2sinx + 2cos2x

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but how do I solve for x

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I can cancel out a 2 but then I still dunno

latent cloak
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remember that sinx/cosx=tanx

supple copper
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mhhm how can that help me tho

soft zealotBOT
latent cloak
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wait, giveme a second to think

grim nebula
latent cloak
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yeah I realized that after lol

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grim nebula
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bruh

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its

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just a quadratic in sin(x)

grim nebula
final saddleBOT
#

@supple copper Has your question been resolved?

supple copper
#

ohh -sinx + 1 - 2sin^2(x)

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okay I think I can solve that

grim nebula
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quadratic in sin(x)

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use a substitution jutsu if youd like

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thought not 100% necessary

final saddleBOT
#

@supple copper Has your question been resolved?

supple copper
#

thanks!

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ocean lagoon
#

can someone explain how they did this step?

ocean lagoon
#

I believe multiplying by gcd of (x+h)^2 * x^2, but can you just flip the fraction? and how it's the 1-1=0*everything = 0?

final tangle
#

combine fractions, common denominator etc

ocean lagoon
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I assume this is an inbetween step, but where did the 1-1 go? where did the (x+h)^2x^2 come from, or is that multiplying by gcd?

final tangle
#

no, what you just wrote is completely illegitimate

#

recall how you'd simplify
$$\frac12 - \frac13$$
you wouldn't say that's $\frac{1-1}{2-3}$ (which is 0) would you?

soft zealotBOT
#

ℝamonov

ocean lagoon
#

ahh, you'd get the gcd, my brain farted lmao

#

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stark apex
#

How does this happen

final saddleBOT
latent cloak
#

x/2 is the same as (1/2)x

stark apex
#

Ig that makes sense so would I put the 1/2 outside of the square root or inside

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Actually i think its inside nvm

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lucid heart
#

Could someone please help me with this, this is due at 11:59

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@lucid heart Has your question been resolved?

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@lucid heart Has your question been resolved?

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long palm
#

what is the pattern from 3, 7, 15?

final saddleBOT
lean magnet
#

well

fathom walrus
#

what type of pattern

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i spot a few

lean magnet
#

yeah

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theres numerous

fathom walrus
#

*2 + 1

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or +4(1) then +4(2) then next could be 27 with +4(3)

long palm
#

I think I got it

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Thanks guys

fathom walrus
#

what was the one u got

long palm
fathom walrus
#

ah k

final saddleBOT
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@long palm Has your question been resolved?

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potent cobalt
#

Is there a good explanation about vectors?

potent cobalt
#

a explanation video

wary helm
#

vectors are a quite broad topic, is there anything more specific you want the video to be about? or just an introduction to vectors?

potent cobalt
#

introduction

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with the cross and the dot stuff

wary helm
#

at which level? high school or undergrad?

potent cobalt
#

undergrad

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well I saw the one of 1blue3brown and the ones of the organic chem tutor.. but i dont really understand it still

wary helm
#

From MIT OpenCourseWare: https://ocw.mit.edu/courses/18-02sc-multivariable-calculus-fall-2010/pages/1.-vectors-and-matrices/part-a-vectors-determinants-and-planes/
in this section (1-A) there are good explanation videos with examples about vectors

potent cobalt
#

ooh awesome!

#

thanks!

wary helm
#

you're welcome

potent cobalt
#

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vivid tendon
#

hey guys I have atleast I think some what of a niche problem im trying to solve im trying to fit squares in A4 format (in pixels) used 6 squars to start can explane all details in channel

vivid tendon
#

so basically Im working with the format of 5906x4134 pixels that I later trimmed to 5906x3638 pixels since I was able to successfully fit 6 squares of initial size of 126x126 each upscaled to the canvas size

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now im trying to figure out the cleanest way to increase the square amount to around 900ish +/- with the cleanest numbers basically with no more then 2 decimals (the size of square side in pixels)

void crest
#

eh

vivid tendon
#

yep

void crest
#

just find an equ for numb of squares u can fit for some length x in pixels

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solve for that =900 n round up or down as u like it

vivid tendon
#

whelp is there a more simple way to do it I have been trying but decimals are a problem

void crest
#

r u working with 5906 by 4134

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or 5906 by 3638

vivid tendon
#

sorry im not here xd I have lost it a bit for how long I have spent on this and its late mb

vivid tendon
#

thats the one I used 126x126 6 squares and upscaled to fit exactly the size

void crest
#

,w solve 5906/x +3638/x=900

void crest
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,calc 2386/225

soft zealotBOT
#

Result:

10.604444444444
void crest
#

eh

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10.6 pixels ig

vivid tendon
#

wait wut

void crest
#

hm

vivid tendon
#

that will be like 9000 squares no?

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im losing it xd

void crest
#

oh wait

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mb

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,w solve 5906/x *(3638/x)=900

void crest
#

,calc sqrt(5371507)/15

soft zealotBOT
#

Result:

154.51007877949
void crest
#

154.51?

vivid tendon
#

ok ill try that

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one moment

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what about the other canvas size

vivid tendon
void crest
#

so that worked?

void crest
vivid tendon
#

whelp not exactly as close as I would like to

vivid tendon
void crest
#

len1/x * len2/x = numsquares

vivid tendon
#

,w solve 5906/x *(4134/x)=900

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0_0

void crest
#

,calc solve 5906/x *(4134/x)=900

soft zealotBOT
#

The following error occured while calculating:
Error: Invalid left hand side of assignment operator = (char 23)

void crest
#

o well just enter that val into a calculator or similar ig

vivid tendon
#

ok ill try ty for the help

void crest
#

np

final saddleBOT
#

@vivid tendon Has your question been resolved?

vivid tendon
#

,w solve 5906/x *(4134/x)=1000

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violet rune
#

$f_1 \in F^E$

final saddleBOT
soft zealotBOT
violet rune
#

What does it mean?

worldly vale
#

f_1 is a function from E to F

violet rune
#

A function not an element?

worldly vale
#

functions can be elements of sets

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even as simply as {f}

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f is a function, its also inside a set

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royal idol
#

what does the phrase "all elements that have one" mean?

worldly vale
#

not all elements of a field have a multiplicative inverse

#

for the ones that do, t hey want you to write it down

royal idol
#

okay thanks, i was thinking they wanted the elements that have the value "1" lol

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odd parrot
final saddleBOT
odd parrot
#

,rotate

soft zealotBOT
odd parrot
#

I dont know what to do past this

#

I am stuck

#

I missed out on the lecture

wraith crater
#

What are factors of 2009

odd parrot
#

7 is one?

#

7x7x41

#

in this case is a 41?

#

wow thank you

final saddleBOT
#

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#
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quiet tangle
#

I have no idea how to proceed

final saddleBOT
deft ravine
#

,rotate

soft zealotBOT
deft ravine
#

You have the formula pH = -log("concentration H+"

fossil stream
#

can you help me

quiet tangle
#

2.5*10^-8=PH?

deft ravine
#

Here you already know the concentration. So all you need to do is plug the number into the log

#

-log(2.5*10^-8)= pH

quiet tangle
#

Oh, ok

#

So that’s the base?

deft ravine
deft ravine
fossil stream
quiet tangle
#

Because it’s not really making a lot of sense what I need to do

#

Do I remove what’s in the parentheses, or convert to exponential?

deft ravine
#

What is your result?

quiet tangle
#

In terms of result, I don’t know what to do

deft ravine
#

That makes sense

quiet tangle
#

I got the answer from the calculator

#

I was just overthinking it lol

#

Thanks

deft ravine
#

You're welcome

quiet tangle
#

@deft ravine I have another question, if you don’t mind

deft ravine
#

Yes?

quiet tangle
deft ravine
#

Don't like the wording of the question, but ok

quiet tangle
#

Yea, it’s kind of weird

deft ravine
#

Have you already tried anything?

quiet tangle
#

Well, I know it’s 6.93 because I tried it in the calculator

#

I just wanna know if there’s another way

deft ravine
#

You can say 5 = 10 * e^(-0.1t) and solve for t

quiet tangle
#

Alright, thanks

deft ravine
#

You're welcome. I can't answer another question as I go to bed now.

deft ravine
#

Thanks

final saddleBOT
#

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lapis forge
#

1/3 is the coefficient in h(t)=t/3, why?

final saddleBOT
void crest
#

um

#

its the coe of t

#

like

#

coe is like

#

kt

#

k is the coe of t

#

in this case weve

#

t/3 = (1/3) t

#

namely k or the coe =3

lapis forge
#

t/3 = 1/3*t, 1/3 = coe

#

not 3 right?

void crest
#

yes

#

and yes

lapis forge
#

ok ty

#

.close

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void crest
#

np

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tranquil pine
final saddleBOT
tranquil pine
#

Nothing. I don't know how to do it.

rain compass
#

that doesn’t give a solution lol

rain compass
tranquil pine
#

So if I do it by doing the reg equation for graphs with the second one ill get my answer?

rain compass
#

if i asked you for the set of values that satisfy the two equations y = x and 2y = 2x, you’ll notice it’s just the line y = x

#

so you can say any point (x,x) satisfies the system of equations

#

similarly, the set of points for your system take the form (x,3x+1)

#

you can graph them if you want, but to show it rigorously you’ll need some kind of math

#

in general, a system of linear equations will have no solution if the lines don’t intersect, 2 solution if they intersect but aren’t parallel, and infinite solutions if the equations are equal (same line)

tranquil pine
#

this is 1,4 right?

#

Im sorry my math is really really bad

rain compass
#

(1, 4) is one of infinitely many points of intersection between the two lines

#

any point (x, 3x + 1) will work

#

for x=1 you get (1,4

#

for x =2 you get (2, 7)

#

for x = -pi you get (-pi, -3pi + 1)

tranquil pine
#

yeah thats all stuff I havent learned yet

#

this is algebra II

rain compass
#

what are your possible answer choices for this question

tranquil pine
#

I guess (1,4)

#

but can you help me with this one, I'm coming back to the last

rain compass
#

i’m talking about on the software

tranquil pine
#

doesn't show

#

its weird

rain compass
#

here just substitute y = -x + 5 into the first equation

final saddleBOT
#

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fiery pendant
#

Hi can someone help me with this problem? I don't understand how q < sqrt (n / p)

final saddleBOT
#

@fiery pendant Has your question been resolved?

fiery pendant
#

<@&286206848099549185>

#

i only struggle with understanding q < sqrt (n/p)...

muted prairie
#

I think it should be a ≤ sign

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feral siren
#

For d why did they make it negative

final saddleBOT
void crest
#

um

#

|z-c| = a^2

#

means a circle of radii a

#

centered about c

#

so they put it in the form of z-something

#

so they can tell what point is the center of the circle

#

@feral siren

final saddleBOT
#

@feral siren Has your question been resolved?

feral siren
void crest
#

um

#

no

#

it can be positive or negative

#

consider

#

|z-1|

#

its a circle centred at 1

#

then consider

#

|z+1|

#

its a circle centred at -1

#

|z-(-1)|

#

this is just rewriting it

#

doest do anything

feral siren
#

Oh ok

#

Thanks I understand now ty

void crest
#

np

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thick estuary
#

can someone explain how to solve this one?

thick estuary
#

im pretty sure im supposed to find the derivative of the function and then plug in 1 for x?

vale silo
#

first you can find derivative

thick estuary
#

yeah but I feel like I got it wrong

vale silo
#

then sub x=1 into your y equation to find your y-coordinate

#

then substitute x and y coordinate to find C

#

in your tangent equation

thick estuary
#

I got as the derivative

vale silo
#

oh wait

vale silo
#

since they only want slope

thick estuary
#

ok just the slope tho

#

does the derivatrive look correct?

vale silo
#

looks okay to me

#

but I’m doing it in my head

#

so idk HAHA

#

,w derivative of e^(-x) / x+1

thick estuary
#

ok I got the answer its -3/4e

soft zealotBOT
vale silo
#

oops didn’t type correctly

thick estuary
#

yeah when you plug in 1 you get -3/4e

vale silo
thick estuary
#

ok

#

thanks

#

srry I was gonna say on the real test im not gonna be allowed a calculator but that doesnt really matter if im plugging in one

#

thanks for the help cya

#

.close

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#
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vale silo
#

no prob!

final saddleBOT
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odd parrot
final saddleBOT
odd parrot
#

how do i approach this

#

ik its something to do with elimination

#

i cant figure out the equations needed

#

i have let x be the amount of 30%

#

and y be the 50%

#

and x+y=5

#

but whats the second equation

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#

@odd parrot Has your question been resolved?

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icy ice
final saddleBOT
icy ice
#

<@&286206848099549185>

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tranquil pine
#

why is this proof incorrect?

final saddleBOT
tranquil pine
#

is it because it does induction in the wonrg order?

#

through circular logic

dusty harbor
#

because the base case is wrong

tranquil pine
#

.close

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tranquil pine
#

why is this proof wrong

final saddleBOT
sinful orbit
#

how do you find a_2 using the base case and the recurrence

tranquil pine
#

don't you prove that p(n) -> p(n+1)

grim nebula
#

the original proposition doesnt even make sense

#

whats a2?

sinful orbit
#

a_2 would be 4a_1 - 4a_0 but a_0 is ??

tranquil pine
#

oh yeah i see it now

#

theres another thing

grim nebula
#

and also

#

even if they give a_0

#

the proof is still wrong

tranquil pine
#

these past two questions

#

i dont understand the structure of the proposition

#

in induction im usually given p(n) as a premise and am left on my own to forge a conclusion by making a base case and proving that p(n) -> p(n+1)

#

but here im given a base case as a premise and p(n+1) and am asked to show that p(n)

#

which makes no sense to me

#

am i just reading it wrong

grim nebula
#

well youre misunderstanding

#

this is a definition of the recurrence

#

this is what you're trying to prove

#

the definition has nothing to do with the proposition

#

you could have just written

soft zealotBOT
tranquil pine
#

oh so are propositions that invite induction just written weirdly

grim nebula
#

no its not written weirdly

#

you're just not used to it

tranquil pine
#

where i prove the premises in the "if" part to show that the then is true

#

aka just proving the base case and then proving that p(n) -> p(n+1)

#

to show that p(n) is true

grim nebula
#

no

#

you're trying to show that p(n) holds for all n

#

so you show that p(k) -> p(k+1) for some arbitrary integer k

#

and that p(base case) holds

tranquil pine
#

yeah ok i think i understand now

#

i was just confused about how the propositions were writtent

#

thanks

#

.close

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novel bone
#

What happened at the place i circled? 7x-3x=4x not -4x?

wraith crater
#

It’s -7x -(-3x)

#

You got a minus sign in front

#

And also a minus sign in front of 7x

novel bone
novel bone
wraith crater
#

I’m not following

#

What do you mean by a minus sign is not a negative

copper urchin
rare cradle
#

Minus sign and negative sign are the same thing

novel bone
rare cradle
#

Sure

novel bone
#

negative is below zero

rare cradle
#

negative is a word not a number

subtle solstice
#

4-3 is a fancy way of saying 4 + (-3)

rare cradle
#

Try to be precise

copper urchin
#

x^2 - 7x
-(x^2 -3x)

is same as

x^2 - 7x
+(-x^2 + 3x)

#

-7x - (-3x) = -7x + 3x

novel bone
#

so if i see a minus sign I can just make it a negative?

#

@rare cradle

rare cradle
#

Idk what u mean by "make it a negative"

novel bone
rare cradle
novel bone
novel bone
chrome cove
#

Did you see that minus too, yes?

novel bone
chrome cove
#

Yeah, now add* x² - 7x + 12 to that
lol

novel bone
rare cradle
#

What happened

#

Loll

chrome cove
#

So you have to do this
x² - 7x + 12 - (x² - 3x)

Do you agree?

harsh cove
#

not long

novel bone
harsh cove
#

it’s easier?

#

faster?

#

simpler?

chrome cove
novel bone
#

ive started long

novel bone
chrome cove
#

and that's where that -4x comes from (original question)

novel bone
#

-x^2+3x

novel bone
#

i do it vertically

chrome cove
#

-7x + 3x thonkstein

novel bone
#

and +3x?

chrome cove
#

x² - 7x + 12
__-x² +3x __

#

Sum those

novel bone
#

0 -4x+12

#

but why -7x

#

isnt it x^2 minus 7x

#

@chrome cove

chrome cove
novel bone
#

yes

chrome cove
#

I don't understand your question

novel bone
#

still dont get where -7x comes from

chrome cove
# chrome cove x² - 7x + 12 __-x² +3x __

sad_think Here you are just adding (or subtracting) things
with numbers only, (unrelated example)
45 -
22

Is the same as 45 - 22

Or (another unrelated example)
56 +
12
Is the same as 56 + 12

grim nebula
#

the -7x is right there

novel bone
grim nebula
#

what does this read?

novel bone
#

7x

grim nebula
#

im so confused

#

theres a - sign in front

#

why did you just drop it

novel bone
#

um isnt it a x^2 MINUS 7x?

grim nebula
#

yeah so?

#

its x^2 - 7x

#

so theres your -7x?

chrome cove
#

adding and subtracting things is the same thing, it's all sums
4 - 2 is 4 + (-2)
If you have
x² - 7x, then it's x² + (-7x)

novel bone
#

🤦‍♂️

#

thanks

#

so much

#

if you didn't help me I would have spent my whole life on a grade 5 thing lol

#

.close

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granite turtle
#

Hi I'm supposed to find the slope of the tangent line using implicit derivitive of:

granite turtle
#

It's D3 and i have started the process of finding the derivitive but i feel like im doing it wrong

#

In short, how do i do implicit differentiation right? and then apply that to finding the slope

final saddleBOT
#

@granite turtle Has your question been resolved?

granite turtle
#

<@&286206848099549185>

final saddleBOT
#

@granite turtle Has your question been resolved?

final saddleBOT
#

@granite turtle Has your question been resolved?

final saddleBOT
#

@granite turtle Has your question been resolved?

final saddleBOT
#

@granite turtle Has your question been resolved?

naive spire
#

what's the question?

humble panther
granite turtle
#

.close

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ebon dew
#

:(

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strange spire
#

How can I solve for x in this case?

final saddleBOT
strange spire
#

I can't seem to get past simplying it to [ 3 ^x = (3^3) * (3^1/2) ]

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#

@strange spire Has your question been resolved?

subtle solstice
#

you did the actually hard part this is just simple exponent rule

gleaming bramble
#

,rotate

soft zealotBOT
strange spire
#

Thanks for that! 🙂

#

How do I close this? 😄

subtle solstice
#

.close

strange spire
#

.close

final saddleBOT
#
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strange spire
#

thanks

subtle solstice
#

np

final saddleBOT
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formal harbor
#

unfortunately we cannot help you with your addictions

#

<@&268886789983436800> r

opaque ember
#

ty

#

.close

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gray harness
#

Hey guys

final saddleBOT
gray harness
#

Can someone please help me out with Euler's formula?

#

How do I get this to this?

final saddleBOT
#

@gray harness Has your question been resolved?

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#

@gray harness Has your question been resolved?

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@gray harness Has your question been resolved?

gray harness
#

.close

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sudden osprey
#

Can I get the line in some other from out of this? or if someone wants to just give the answer that would be great too

tired walrus
#

what other form are you looking for?

#

the exercise as-written is, in some sense, lying to you about these equations defining a line. this isn't a straight line but rather a curve.
...not that it stops you being able to find the intersections thereof with that plane, but still.

sudden osprey
#

I'm not sure anymore

scarlet sequoia
#

you know the form of the points on the line (which is not exactly a line but whatever):
x = -3t + 5 ; y = t + 2 ; z = t^2 + 5.
So anywhere on the line, x - 2y + z = ?

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thorny barn
#

c = 30, r = 6. Calculate the perimeter

final saddleBOT
final tangle
#

what's c supposed to represent

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#

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frank swift
#

Hi.. another question.
I'm very unfamiliar with the idea of complex logarithms except for the basic knowledge of the formula.
Trying to find the calculations for ln(i), the only proof I can find so far is one using Euler's identity. Is it possible to prove complex logarithms without it?

inland bison
#

prove complex logarithms?

#

it's not really something you can prove, because it is a definition

frank swift
#

perhaps explain is a better word? as in explain how the application of ln(i) produces its result

inland bison
#

well firstly, ln(i) usually is preferred to as a weird notation, since natural log is only defined for positive real numbers. So this is where we would introduce the complex logarithms

#

the idea of this is to just have it as an inverse of the complex exponential funciton

#

but one problem is that, the complex exponential function is a single-valued function, its inverse on the other hand would be a multi-valued function if we dont put on a bound for the argument

#

so thats just why, it's because e^(z) may produce one unique complex number w, for infinitely many z. The inverse of this, ie log(z) produces a tons of numbers for just one value

#

now how the the derivation for log(z)=ln(r)+itheta came can be explained by the idea that we want an inverse, so this inverse when composed with the exponential function, i.e e^(z) gives us back z

#

so lets just give it a new notation, which in this case is log

#

now note that z can be represented as re^(itheta+2kpi) where r is the magnitude of z and theta is the principal argument of z, k is any integers

#

then $\log(z)=\log\left(re^{i(\theta+2k\pi)}\right) = ln(r)+i(\theta +2kpi)$

soft zealotBOT
inland bison
#

this is the multivalued representation of the complex log funciton

#

for the principal branch, just set k=0

soft zealotBOT
final saddleBOT
#

@frank swift Has your question been resolved?

frank swift
#

thank you !

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worthy stag
#

is 2^3(2^4) = 2^7 or 2^12?

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fathom tapir
#

2^7

worthy stag
#

ok

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rapid island
final saddleBOT
tranquil pine
#

So i need

#

Help

#

Oh sorry wrong channel

rapid island
#

Lol you're good.

#

Anyways, guys, this is an improper integral problem.

#

I used an U sub for e^3x

#

and it doesn't seem to work

#

Turns out it diverges but my Wolfram Alpha calculation says it converges to pi/6

tranquil pine
#

Its equal

#

Pi/6

rapid island
#

Yeah, but not sure how to get there.

tranquil pine
#

U Will use this

rapid island
#

so split the integral into two parts?

tranquil pine
#

Yes

#

Im not sure Tho

rapid island
tranquil pine
#

And after i Think

rapid island
#

Hm

tranquil pine
#

No not b

#

Its 0

rapid island
#

Would you use U sub for this

#

why is it 0

tranquil pine
#

No

tranquil pine
rapid island
#

Hm

#

so 1+e^6x is clearly greater than 0

tranquil pine
#

Anyway u Will use integral

rapid island
#

the denominator

tranquil pine
#

Defined integral

#

And limite

#

Sorry i study maths in French

#

So thats hard to explain

rapid island
#

It's okay man

#

Lol

#

I appreciate it anyway

tranquil pine
#

Im not a man

rapid island
#

Are u in calc 2 as well?

#

calculus 2

#

Ah ok

#

Sorry

tranquil pine
#

No im in Hugh school

#

High

#

The

rapid island
#

Okay got you

tranquil pine
#

Idk im 15 yo

rapid island
#

Ok so anyways.. do you know how to solve my improper integral

tranquil pine
#

Yes i Know

rapid island
#

I split it into 2 parts like the picture I'm going to show you.

tranquil pine
#

So to to evaluate the improper integral rewrite it using a limit and a definite integral

rapid island
#

Like this?

tranquil pine
#

Yes i think so

rapid island
#

Ok

#

then how do i evaluate the integral

tranquil pine
#

U Will calculate the indefinite integral

rapid island
#

Ok so when you calculate the indefinite integral of it, you use the U-substitution right?

tranquil pine
#

Yes

#

Or the t

#

Do u get it ?

#

The t substitution

rapid island
#

Yeah almost

#

Hold on

tranquil pine
#

U should have this

rapid island
#

how does it look like

tranquil pine
#

No

#

Thats not how u do it

#

Kimchi are u stupide

#

Stupid

rapid island
#

Um what

final saddleBOT
#

@rapid island Has your question been resolved?

tranquil pine
#

Kimchi do u need help Again ?

final saddleBOT
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near turret
#

i have tried substituting the second equation into the first to find their intersection however i am confused as to where the (2k-1)x comes from in the given equation

near turret
#

equations are: y=2x^2-x-1, y=k(2x-3), 2x^2-(2k+1)x+3k-1=0

#

what i get is 2x^2-x-1-2kx+3k

soft zealotBOT
vale silo
#

just need to factor x and a negative out

#

look at your -2kx-x

#

you can write as -x(2k+1)

#

which is -(2k+1)x

near turret
#

wow im fucking blind, 3 months off and im fried

#

cheers for the help mate

vale silo
#

HAHA it’s okay

#

no prob!

near turret
#

.close

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muted brook
final saddleBOT
muted brook
#

Am I correct to say this should be 3?

#

Since A + B is 14

#

And they want the complement

wraith crater
#

Yeah I think so

muted brook
#

Also I was wondering why this one is true

#

I put in false

#

Last time but it said it was incorrect but did not give an explanation

wraith crater
#

5 is a member not the set of 5

muted brook
#

Makes sense

sonic gulch
#

${5}\subset {1,2,3,4,5}$

soft zealotBOT
#

black_tea

muted brook
#

👌

#

.close

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fallow wren
#

wooo

#

to long

#

in the second last numerator you have -1+1 it isn't ?

#

sorry but you can say it is zero from the start i think..

#

the function is continuous in -1

#

lol

#

its continuous in the domain (-.inf, -1]u(1,+inf)

#

so just plug in -1

#

sorry

#

i am tired..i say it wrong

#

the domani is (-.inf, -1)u(1,+inf)

#

so you can t simply plug in

#

its wrong because you see from the graph that the answer is 0

#

ok lets try this:

inner spoke
#

What happened in the 4th step

fallow wren
#

$\lim \frac{x+1}{\sqrt{x^2-1}}=\lim -\sqrt{\frac{x+1}{{x^2-1}}}=\lim -\sqrt{\frac{(x+1)^2}{(x+1)(x-1)}}$

inner spoke
#

If i were u id do lhopital from the start

fallow wren
#

now just simplify and it should be trivial

soft zealotBOT
steel hill
#

Shouldn’t the x+1 under the root be squared?

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#

@astral sleet Has your question been resolved?

fallow wren
#

yes ikea

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vale python
#

I’m not sure how to go about writing this proof. I need to prove that m must be a prime number for mod m in order to have k=(m-1)/2, where k is the number of elements in the set D, and D is the set of nonzero squares of the elements of mod m

final saddleBOT
#

@vale python Has your question been resolved?

final saddleBOT
#

@vale python Has your question been resolved?

final saddleBOT
#

@vale python Has your question been resolved?

muted prairie
#

number of squares mod m hmm

muted prairie
#

then the answer follows from lagrange's theorem

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exotic ether
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exotic ether
#

.close

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exotic ether
#

.reopen

final saddleBOT
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exotic ether
#

<@&286206848099549185>

#

help please

final saddleBOT
#

@exotic ether Has your question been resolved?

exotic ether
#

<@&286206848099549185>

#

<@&286206848099549185>

exotic ether
#

<@&286206848099549185>

#

nvm.

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#

@exotic ether Has your question been resolved?

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