#help-36

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#
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final saddleBOT
royal gust
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a² = b?

silver dew
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{1,a,b} is cyclic group of order 3 under multiplication

royal gust
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I am convinced

silver dew
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?

royal gust
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So then yeah, it would have to follow that a³ = b³

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= 1

silver dew
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So it’s generated by , say x, either a=x, b=x^2, or a=x^2, b=x, either case a^2=b

#

Because x^4=x

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split crown
final saddleBOT
split crown
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what is a power function end behavior model

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need some help

final saddleBOT
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@split crown Has your question been resolved?

mint orbit
split crown
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i figured out the end behavior

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it approaches 0 on both sides

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but what would i put as the answer

mint orbit
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hrm i mean

split crown
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yea im' confused

mint orbit
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how about

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1/x

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wait

split crown
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i just tried that

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it's wrong

mint orbit
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thats not gonna fit the signs is it

split crown
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idk it's wrong anyway

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what do u think

mint orbit
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the other option

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1/3x

split crown
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can u explain to me why it's that

mint orbit
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$\frac{x-2}{3x^2+2x-3}$

soft zealotBOT
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jan Niku

mint orbit
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here is your function

split crown
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yep

mint orbit
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the first thing youll do is say

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well x is gonna be really really large

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in magnitude

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itll be some really positive or really negative number

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point being

split crown
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🤔

mint orbit
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if you take some really positive or really negative number right

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i mean were talking end behavior here

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say x= a million

split crown
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yea

mint orbit
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or x= negative a million

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so whats it matter if you do like

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a million minus 2

split crown
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yea ik

mint orbit
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or a million plus three

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so lets say its

split crown
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x=1 mil gets around 0

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same thing for x=-1mil

mint orbit
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$\frac{x}{3x^2+2x}$

soft zealotBOT
#

jan Niku

mint orbit
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lets just ignore the constants

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now, you reapply the argument

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well if x=a million

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a million squared is an enormous number

split crown
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it's gonna be like 0 ik

mint orbit
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i mean just look at the terms

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dont worry about the entire function

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,w 1000000^2

mint orbit
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this number is big compared to a million

split crown
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yea

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but it's at the bottom

mint orbit
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thats fine

split crown
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so it becomes 1/mil

mint orbit
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we just say this

split crown
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which is around 0

mint orbit
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$3x^2 +2x \approx 3x^2$

soft zealotBOT
#

jan Niku

mint orbit
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for really large x

split crown
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mhm

mint orbit
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okay, so lets replace

split crown
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so it's x/3x^2

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OH

mint orbit
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yup

split crown
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so that's where u get it form

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from

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i see

mint orbit
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yea happy

split crown
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yep

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thank you

mint orbit
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np

split crown
#

.close

final saddleBOT
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worldly furnace
final saddleBOT
worldly furnace
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could I get some help with this?

final saddleBOT
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@worldly furnace Has your question been resolved?

fossil geyser
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You still here? @worldly furnace

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The problem says that the interest is calculated every day but isn't added until the end of the month.

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June has 30 days. It looks like for the first 21 days, the account had a balance of $900, and for the final 9 days, it had a balance of $600.

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(I think. The $900 is a little hard to read)

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From the annual rate of 17%, you can calculate a daily rate. Just divide it by 365.

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That should let you find the interest owed for each day. 21 days at a balance of $900, 9 days at a balance of $600.

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Then just add it all up

final saddleBOT
#

@worldly furnace Has your question been resolved?

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final saddleBOT
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tranquil pine
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chrome cove
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What did you try? where did you get stuck?

tranquil pine
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i don't understand how to solve it

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where do i begin

grim badger
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Product rule

chrome cove
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Yes it's a product rule, but it's quite messy

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tip: at the beginning, it's easier if you write cos³x as (cosx)³, so you don't loose any chain rules

tranquil pine
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ok

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how do you start to solve the question though?

grim badger
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By using product rule

tranquil pine
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would i seperate into (4cos^3x)(sinx)

grim badger
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Yeah, you can do that

tranquil pine
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ok

#

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tranquil pine
final saddleBOT
tranquil pine
#

Need help with C

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how do i set it up?

final saddleBOT
#

@tranquil pine Has your question been resolved?

final saddleBOT
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thin leaf
#

I need help with absolute value equations

final saddleBOT
thin leaf
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Idk what to do

worn mortar
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do you know at least how to approach 17)?

thin leaf
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Yes

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However

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25

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Is kicking my ass

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Is it distributing?

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Is it +

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Is it 2n together?

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Wtf?!?

worn mortar
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ok before doing 25) were u able to do 22)

thin leaf
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Yes

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@worn mortar ?

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<@&286206848099549185>

wary helm
thin leaf
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Ok so

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Can u please help

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With

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25

wary helm
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What have you tried

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?

thin leaf
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Idk ig its gotta be 2n - 5?

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= 20?

wary helm
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You have
2|n-5|=20

thin leaf
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Wait no

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Ifs

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2|n-5|=20

wary helm
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Ok so
2|n-5|=20

thin leaf
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yes

wary helm
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The absolute value is like a parentheses, so the 2 multiplies both n and -5

thin leaf
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WHAAAAAAAAAAAAAAT

wary helm
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It's like having 2(|n+5|)=20

thin leaf
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nONOnOnaoanOnOanOnOno

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o God

worn mortar
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how would you solve for n if there was no absolute sign so 2(n+5)=20

thin leaf
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a-a-a-alright

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Ill try that

wary helm
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https://youtu.be/_cHbhzQVd7Y
You should watch this short video to understand how absolute value equations work before attempting to solve these equations

This algebra video tutorial provides a basic introduction into absolute value equations. it explains how to solve absolute value equations the easy way. It contains plenty of examples and practice problems for you to learn the concept.

New Algebra Playlist:
https://www.youtube.com/watch?v=nTn9gVqRfKY&list=PL0o_zxa4K1BUeF2o-MlNpbRiS-oE2Kn6J&...

▶ Play video
thin leaf
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Holy jesus

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Grade plz

wary helm
final saddleBOT
#

@thin leaf Has your question been resolved?

#
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alpine kraken
final saddleBOT
alpine kraken
#

Find the values of the variable x for which the difference of the expressions 5x + 3 and 9x+3 is equal to 2?

wary helm
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Try to rewrite all of that in an equation

alpine kraken
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like together?

wary helm
wary helm
alpine kraken
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ok wait

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like

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5x+9x+3+3?

wary helm
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It's 5x²

alpine kraken
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ohh yes

wary helm
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And it tells you the difference is 2, not the sum

alpine kraken
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so um

wary helm
alpine kraken
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i have no idea where to start

wary helm
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You have 2 expressions

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5x²+3 and 9x+3

alpine kraken
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yes

wary helm
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You know the difference between them is 2

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You want to put everything into a single equation to solve for x

alpine kraken
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ok

wary helm
alpine kraken
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okay

wary helm
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And the problem tells you the result of that subtraction is 2

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If you have m and n and want to find the difference between them, you do m-n. Here you don't have single variables or numbers, but short expressions. That doesn't change anything though, it works in the same way as a normal subtraction

alpine kraken
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so then 5x(squared) + 3 - 9x +3?

wary helm
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5x²+3-(9x+3)

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So it becomes 5x²+3-9x**-**3, not +3

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Right?

wary helm
alpine kraken
wary helm
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If you subtract 9x+3 from 5x²+3, you're doing
(5x²+3) - (9x+3), right?

alpine kraken
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yeah

wary helm
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That minus sign changes the sign of 9x and 3, not just 9x

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So it becomes 5x²+3-9x-3, not 5x²+3-9x+3

alpine kraken
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oh alright

wary helm
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Ok, then it tells you that the difference is equal to 2

wary helm
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5x²+3-9x-3 becomes just 5x²-9x

alpine kraken
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3 dissapears?

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oh no

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stop

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gpt it

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got it

wary helm
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Ok

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So 5x²-9x

alpine kraken
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ok

wary helm
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That difference is equal to 2, right?

alpine kraken
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yeah

wary helm
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So do you know what's the next step?

alpine kraken
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we should find x

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by dividing

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?

wary helm
wary helm
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You can't really find x right now, you just have 5x²-9x

alpine kraken
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ok

wary helm
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You know that 5x²-9x is the difference between the two expressions though

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And you know that difference is equal to 2

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So you should try to write an equation knowing those two things

alpine kraken
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like x=?

wary helm
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Not necessarily x=?, just something=something else

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Think about what you've found so far

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And what the problem tells you

alpine kraken
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5x²-9x from this i should make equation?

wary helm
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Yes, with that and 2, which is the difference

wary helm
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In the context of the problem

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What does it represent

alpine kraken
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um

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sorry I don't know honestly

wary helm
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Go back reading how you found it and where you started from

alpine kraken
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expression?

wary helm
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This was your problem:
"Find the values of the variable x for which the difference of the expressions 5x² + 3 and 9x+3 is equal to 2?"

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"the difference of the expressions 5x² + 3 and 9x+3 is equal to 2"

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We found the difference of those two expressions before, right?

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We did (5x²+3)-(9x+3) before, that's the difference between those two expressions

alpine kraken
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so

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um

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we should

wary helm
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Write here what you were thinking, it's not a problem if you get it wrong

alpine kraken
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idk to be honest what to do

wary helm
alpine kraken
#

yeah

wary helm
alpine kraken
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difference?

wary helm
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Wdym by 2 differences?

wary helm
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5x²-9x is the difference between 5x²+3 and 9x+3, right?

wary helm
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Do you understand why?

wary helm
alpine kraken
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im here

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just trying to understand all this

wary helm
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Where do you get stuck?

alpine kraken
wary helm
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What do I need to explain?

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We didn't get to the solution yet, we're trying to understand what the problem is asking to find the solution

alpine kraken
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alright, can u give hint what i should do next?

wary helm
wary helm
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I'm trying to make sure everything we did is clear

alpine kraken
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we subtracted

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to find difference

wary helm
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Yes

wary helm
alpine kraken
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yes

wary helm
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So if 5x²-9 is equal to 2 and you want to write that as an equation to solve for x, what do you do?

alpine kraken
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here not sure

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um

wary helm
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a is equal to 2. write that as an equation

alpine kraken
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a?

wary helm
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It's an example

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To help you understand what to do

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You know a variable called a is equal to 2. How do you write that as an equation?

alpine kraken
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a = 2 ?

wary helm
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Yes

wary helm
alpine kraken
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ohhhhhh

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5x(squared)-9x = 2?

wary helm
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Yes, 5x²-9x=2

wary helm
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It's 9x

alpine kraken
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right, sorry

wary helm
#

👍

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Now you can solve for x

alpine kraken
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i should square up?

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5x

wary helm
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5x²-9x=2
Bring 2 to the left side
5x²-9x-2=0

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It's a normal quadratic equation

alpine kraken
#

oh

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wait min

wary helm
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Btw a good idea would be to go through this problem again making sure you understand well why we did what we did in each step of the solution

alpine kraken
#

41

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?

alpine kraken
wary helm
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,w 5x^2-9x-2=0

wary helm
wary helm
#

How did you solve it?

alpine kraken
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D=

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b2 - 4ac

wary helm
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Then?

alpine kraken
#

then

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we

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-b

wary helm
soft zealotBOT
#

Andrea276

wary helm
alpine kraken
soft zealotBOT
#

Andrea276

alpine kraken
wary helm
#

Sure?

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b²-4ac

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b is -9

alpine kraken
#

yeah

wary helm
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a is 5

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And c is -2

alpine kraken
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ohh

wary helm
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You have 5x²-9x-2=0

alpine kraken
#

ye ye

wary helm
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ax²+bx+c=0
5x²-9x-2=0

alpine kraken
#

i got it

wary helm
wary helm
alpine kraken
#

121?

wary helm
#

Yes

alpine kraken
wary helm
#

√121=11

wary helm
soft zealotBOT
#

Andrea276

#

Andrea276

alpine kraken
#

do i subtract or sum

wary helm
#

Both, you'll find two solutions since it's a quadratic equation. You add first and find the first solution, then subtract to find the second

alpine kraken
#

ohhh right

soft zealotBOT
#

Andrea276

alpine kraken
#

now i need to write this all in my exercise book xd

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sir, thank you so much, I really appreciate your kindness, patience

wary helm
#

You're welcome : )

alpine kraken
#

you are smart]

wary helm
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I just really enjoy doing math, so I practice it more. It's fun for me

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With enough practice you can become really good at math

alpine kraken
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i have two tasks to do more

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you may help me if you would not be against it

wary helm
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Sorry, it's almost midnight here so I was about to go to bed... Try to do them by yourself, and in case you need help you can always open another help channel here and someone will come to help

alpine kraken
#

yeah for me too, I understand, good night

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thank you again 🙂

#

.close

final saddleBOT
#
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tranquil pine
final saddleBOT
tranquil pine
#

Stuck on this one

desert mantle
#

ok so the "unique" in the question gives you a hint

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cause usually you would expect there to be several solutions

tranquil pine
#

Mhm

desert mantle
#

if P(x) gets slightly smaller then Q(y) could get slightly smaller and it works out again

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however what happens when Q(y) can't get smaller

tranquil pine
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And as they did not comment about x and y i would think the combinations could be infinite

desert mantle
#

more like 7*4, 7.01*3.99.. and so on

desert mantle
#

whoops

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I meant if P(x) gets slightly bigger

tranquil pine
#

Oh

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Yes

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Agreed

desert mantle
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so but this only works if Q(y) can get smaller

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can Q(y) always get smaller?

tranquil pine
#

It is the least at its vertex

desert mantle
#

ok then maybe it's a good idea to calculate that

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to see what we are working with

tranquil pine
#

,w 4x²+6x+4

tranquil pine
#

Sso vertex is 7/4 here

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,w 4y²-12y+25

tranquil pine
#

And here at 16

desert mantle
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ok so the two minimums are 7/4 and 16. can't get smaller than that

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so what is the absolute minimum that P(x)*Q(y) can be

tranquil pine
#

28

desert mantle
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and for which x,y do we have that?

tranquil pine
#

7/4 ,16

desert mantle
#

no that's P(x) and Q(y)

tranquil pine
#

Nu

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Yes

desert mantle
#

but not the x,y

tranquil pine
#

-3/4,3/2

desert mantle
#

good so for (x,y)=(-3/4, 3/2) we have P(x)*Q(y)=28

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what happens if we take any other x or y

tranquil pine
desert mantle
#

and why not?

tranquil pine
#

As the minimum is at only one single point

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That is the vertex

desert mantle
#

yes so if we have any other x or y then we have P(x)*Q(y) > 28

tranquil pine
#

Ooh yes!

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But what if

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Q(y)=-4y²-12y+25

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🤔

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Then there would be infinite possibilities?

desert mantle
#

yeah

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P(x) can get bigger and Q(y) can get smaller

tranquil pine
#

Ohh yes i gett it now

desert mantle
#

oh hmm

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there could actually be a problem if the signs don't match

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for example if P(x) is always positive and Q(y) is always negative

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it's not in this case but it could be

tranquil pine
#

,w -4y²-12y+25

tranquil pine
desert mantle
#

which is why I said there could be a problem but in this case it's fine

tranquil pine
#

So all i have to think while dealing with these questions is the minimum value

desert mantle
#

well not all

#

but it's a start

tranquil pine
desert mantle
#

I don't know atm but in general I don't like agreeing to statements of the form "all I have to do everytime and it will always work"

#

there could always be some weird counterexample

tranquil pine
#

Understandable

#

Anyways thanks for your help and time!

#

Really appriciate it ❤️

#

.close

final saddleBOT
#
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glacial shadow
#

How does one write a system of differential equations in polar form?

glacial shadow
#

Actually, I might've asked in the wrong channel. I don't particularly want help for a problem, just help understanding a process.

#

.close

final saddleBOT
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final saddleBOT
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edgy wyvern
final saddleBOT
edgy wyvern
#

How do I do this

stoic mural
#

i would advise to just guess

#

i mean, you want to guess a such that P(a)=0

#

good guesses are always divisors of the constant, in this case it is 3

final saddleBOT
#

@edgy wyvern Has your question been resolved?

edgy wyvern
#

@stoic mural nah like i dont know how to do it all bro

#

i completely forgot synthetic division and how to even start factoring this

#

can you run through it with me in a discord call?

stoic mural
#

lets just do it here

edgy wyvern
#

alright

stoic mural
#

my first step would be to factor out the 2
this makes it not that pretty but having the leading coefficient be 1 is always nice imo

#

so we get
2(x^3-2.5x^2-2x+1.5)

edgy wyvern
#

ah ok

stoic mural
#

now we want to factorize the polynomial in the brackets

edgy wyvern
#

right

stoic mural
#

to do so we try good guesses

#

ok nevermind

#

lets not factor out the 2

edgy wyvern
#

should we factor it by grouping?

#

oh ok

stoic mural
#

2x^3-5x^2-4x+3

#

as i said earlier, commonly, the roots our divisors of the constant

edgy wyvern
#

$2x^3-5x^2-4x+3$

soft zealotBOT
#

illusion

stoic mural
#

divisors of 3 are:
-3,-1,1,3

edgy wyvern
#

yes

stoic mural
#

if we for example put in 3, we get P(3)=0

#

so 3 is a root

edgy wyvern
#

ok

stoic mural
#

thus, (x-3) is a factor

#

now we do polynomial division

#

what do we get?

edgy wyvern
#

give me a sec

#

so

$2x^3-5x^2-4x+3/(x-3)$ ?

soft zealotBOT
#

illusion

stoic mural
#

yes

#

do you know how to do this?

edgy wyvern
#

one sec

final saddleBOT
#
Channel closed

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Use .reopen if this was a mistake.

edgy wyvern
stoic mural
#

.reopen

edgy wyvern
#

something like this?

#

.reopen

final saddleBOT
#

stoic mural
#

huh

#

interesting

#

thats not how i do it

#

but as long as it works

edgy wyvern
#

oh

stoic mural
#

this is how i do it

edgy wyvern
#

remainder is 0

stoic mural
#

and then so forth

#

yes, remainder is 0

#

this is because 3 is a root

edgy wyvern
#

so that means (x-3) is a root bc we have 0 remainder?

stoic mural
#

yes

edgy wyvern
#

ok i see

stoic mural
#

also, we already showed that 3 is a root by showing that P(3)=0

#

as you calculated, you got 2, 1, -2, 0

#

so we end up with

#

(x-3)(2x^2+x-1)

edgy wyvern
#

2, 1, -1, 0

stoic mural
#

now on to factorize this polynomial

edgy wyvern
#

ah

#

ok

stoic mural
#

in this example it is easy, if it isn't we can always use complete the square

#

but in this case we can see that -1 works

edgy wyvern
#

hmm

#

what if we have

#

$x^3-x^2-16x+16$

soft zealotBOT
#

illusion

edgy wyvern
#

what if we're just given this ^

stoic mural
#

here we can see a root already

edgy wyvern
#

we're not given any other info

stoic mural
#

one obvious root is 1

#

1-1-16+16=0

edgy wyvern
#

oh

#

ohhh

#

I see now

stoic mural
#

and if that is not obvious, we should first of always try divisors of the constant

#

which is 16

#

so we have:
-16,-8,-4,-2,-1,1,2,4,8,16

edgy wyvern
#

oh

stoic mural
#

although this seems tedious, with a bit of practice you will be able to do it quickly

#

lets say we try out number a

edgy wyvern
#

so now we have our root, which would be (x-1)

stoic mural
#

once you have some practice you will e able to tell if a need to be bigger or smaller

#

correct

#

well

edgy wyvern
#

now what would we do

stoic mural
#

(x-1) is a factor

#

the root is 1

#

we would divide the polynomial by (x-1)

edgy wyvern
#

ok

#

and then after that we just factorize?

stoic mural
#

yes

edgy wyvern
#

ok imma try it out real quick

#

(x-1)(x^2-16)

#

$(x-1)(x^2-x+15)$

soft zealotBOT
#

illusion

stoic mural
#

uhm

edgy wyvern
#

did i do something wrong

stoic mural
#

you got 1,0,-16,0 though

#

so

#

(x-1)(x^2-16)

edgy wyvern
#

oh right

#

oh

#

ok

#

yea

#

i see now

#

ty

#

yo martin, you know for the first question, $2x^3-5x^2-4x+3$

soft zealotBOT
#

illusion

edgy wyvern
#

how did you know you needed to plug in the 3 into P(3)=0?

stoic mural
#

our constant is 3

#

so we want to check divisors

#

so

edgy wyvern
#

so our constant just goes in there

stoic mural
#

-3,-1,1,3

edgy wyvern
#

oh

#

so we plug like all of those in and find which one works?

stoic mural
#

yes

edgy wyvern
#

ah

#

ty martin

stoic mural
#

with a constant like 32 this becomes annoying

edgy wyvern
#

lol

stoic mural
#

but you will get good with it and be able to tell if the number should get higher or lower

#

for example

#

if we ahve

#

x^2-16

#

we know that x^2 has to be big

#

nevermind bad example

#

ok i cant think of a good example

#

just trust me that you will get a feeling for it haha

edgy wyvern
#

lol ok

#

im just gonna take down notes from this channel and then close

#

ty for your help

#

@stoic mural you're a legend

#

.close

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hasty fossil
final saddleBOT
hasty fossil
#

for 34. can someone help me find the equation i can use for using summation

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#

@hasty fossil Has your question been resolved?

hasty fossil
#

<@&286206848099549185>

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cunning ledge
#

How would I find the domain of this equation?

cunning ledge
#

for context, here is full question

grim badger
#

Literally tells you what to do

cunning ledge
#

so for 2x it would be 2(0) = 0?

#

and just replace all of the x's

grim badger
#

No

#

You set the equation equal to 0 and solve for x

cunning ledge
#

ooh

#

ok i think ill be able to figure it out

#

thanks

#

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tranquil pine
final saddleBOT
tranquil pine
#

From these points I have to write the equation in standard form

#

They said this answer is wrong though

#

I got -59/9 by using the calculator

#

this is what i get when i try the other points

#

nvm ig ot it

#

.close\

#

.close

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hazy path
#

find an equation of the line through the intersection of the lines
x + 2y + 3 = 0
3x + 4y + 7 = 0
and making equal intercepts on the axes.

hazy path
#

I know the l : l1 + kl2 formula but what does equal intercepts on the axes mean?

near spoke
#

means y at x=0 is equal to x at y=0

#

or u can use the slope intercept form, x/a+y/a=1

#

u just need to find a,
put the intersection point to find a

spark kettle
hazy path
#

Ok so when I get the required equation with the variable k in it, I put x as 0 for the y intercept and y as 0 for the x intercept.
Then I make an equation using those 2 equations?

#

I'll do it on paper so you can understand it easily

near spoke
#

you can find k by using that equation and put it in L1+kL2 to get the equation of line

hazy path
#

So as for equal intercepts on the axes.
Let me talk about it a bit more to see if I understand the concept correctly...

#

So... the points (for example)
(3, 0) and (0, 3) on a graph would be called making equal intercepts on the axes?

near spoke
#

and k=-3/7 can also give a possible line

near spoke
hazy path
#

Ok thanks

#

for the help

#

.close

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ocean roost
final saddleBOT
ocean roost
#

For b do I use all the numbers from a and b to find the angle between a and b

loud sundial
ocean roost
#

ohhh ok

#

thank you

#

wait actually

loud sundial
#

?

ocean roost
#

am i suppoosed to use sin or cos

#

to solve for the angl;e

loud sundial
#

either works

ocean roost
#

ohhh

#

ok thanks

#

.close

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upper sonnet
#

Is it 40 degrees ?

final saddleBOT
#

@upper sonnet Has your question been resolved?

final saddleBOT
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@upper sonnet Has your question been resolved?

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sterile maple
final saddleBOT
celest crane
#

They are supplementary angles, therefore both angles must sum to 180 degrees.

sterile maple
#

Yes

#

Oh right I wasn’t thinking

#

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whole remnant
final saddleBOT
whole remnant
#

i dont know why but i am confused on how to do this

#

i know 105km/h=110min

#

75km/h=t?

#

then t-110min should be the answer correct?

#

nvm i figured it out

#

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fossil geyser
#

Do you want the factors to have integer coefficients?

paper galleon
#

yes

#

so let’s say i was factoring a quadratic that has 71x^2 as the leading term

#

ik the factored pair would be

#

(71x + something)(x+something)

#

but how can i easily find out what the something is

fossil geyser
#

the "something"s would have to be a factor pair for the constant term

paper galleon
#

is there any way you could give an example?

fossil geyser
#

Yeah sure

paper galleon
#

ryan

#

*tysm

fossil geyser
#

no problem

#

so

#

$71x^2+430x+24$

soft zealotBOT
#

tatpoj

fossil geyser
#

Like you said it must be of the form $(71x+a)(x+b)$

soft zealotBOT
#

tatpoj

fossil geyser
#

If it's factorable at all, that is.

paper galleon
#

yep

fossil geyser
#

And that's because (71x)(x) is the only way to make 71x^2 with integer coefficients

#

The same logic applies to the 24

#

a*b must equal 24

paper galleon
#

i see

#

yep i get that

fossil geyser
#

Well, there are only so many factor pairs for 24

#

It shouldn't take too long to try them all

paper galleon
#

ohh ok so you just try them out

#

ok that’s easier than i expected

#

tysm

fossil geyser
#

That's what I would do, yes

#

If none of them work, then it's not factorable with integers

paper galleon
#

👍

final saddleBOT
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random wigeon
#

I need to express one vector as a sum of 3 non-coplanar vectors. How do I solve for the right coefficients? How this topic is called? I study in other language, can't find the theme in English. Thanks!

void crest
#

vector addition?

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halcyon imp
#

i have to negate this. I. get not r but the answer is wrong why is that?

halcyon imp
quaint ivy
#

Let's first see why it's wrong

#

If "not this formula" is "not r", then the formula is equivalent to r

#

however, if p is true, then the formula is true. So clearly the formula can't just be r.

halcyon imp
#

makes sense

#

but i cant see where i made a mistake

quaint ivy
#

Ok, so now let me check your calculation

#

Ah, it's on the last line, you didn't put parenthesis.

#

$(a\wedge b)\vee c\neq a\wedge(b\vee c)$

soft zealotBOT
#

Blaxapate

halcyon imp
#

ohh the parenthesis has to be from the other p to r right?

quaint ivy
#

Last line should be $(\neg (p\vee q))\wedge((p\vee q)\vee \neg r)$

soft zealotBOT
#

Blaxapate

quaint ivy
#

Now you can distribute, one term will cancel, but something more than not r will remain

halcyon imp
#

yes i got it now!

#

thanks!

#

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abstract tapir
#

Hi is this answer correct?

final saddleBOT
harsh cove
#

define invertible

abstract tapir
harsh cove
#

Ohhh I see

#

well isn’t any trigonometric function inversible over it’s entire domain?

#

There’s no chance for a hole or asymptote here

#

Can you select all 4?

loud sundial
#

Inverse means one to one tho

#

, graph y=sin x

#

Counterexample

brisk charm
final saddleBOT
#

@abstract tapir Has your question been resolved?

tranquil pine
#

and then see what of this options have the same length as the period if I am not wrong

brisk charm
#

No, sine is not invertible over its period

#

Graphing the function (which you can do fairly easily by hand) is the easiest way to do this question

tranquil pine
#

ah right you are correct

tranquil pine
#

can't he still do that and do let's say period/4

#

to find the length?

tranquil pine
brisk charm
#

No there's no length where the interval being that length guarantees it is invertible

brisk charm
# abstract tapir

yes and what does it look like graphically if the function is invertible in the interval [0, pi/2]

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plush holly
final saddleBOT
plush holly
#

Hey quick question, to solve question 9, would I have to set up a table and plug in numbers that get close to 9? Just wanna know if I'm on the right track

#

Like 8.9,8.99,8.999 and then 9.1,9.01,9.001 and plug in for each of those

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#

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sharp herald
#

Ping helpers they will help you

plush holly
#

<@&286206848099549185>

eternal quest
#

not a helper but u can approach the limit from the left side to find negative absolute and approach the limit from the right to find the positive absolute

#

actually i would use LH but a good mathematician would call it overkill just wait for a helper to answer

#

but if the limit when u approach it from right to left is equal then the limit x tends to 9 exists u cant find the value of the limit tho without using LH rule , might be wrong eager to hear what someone else has to say

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lone parrot
#

hello

final saddleBOT
lone parrot
#

can someone help me to détermine the nature of this séries :

#

$\sum tan(\dfrac{1}{n})sin(n)$

soft zealotBOT
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timber turret
#

Hello. I have an issue understanding what this sheet titles "The Tangent and Velocity Problems". When we learned this concept in class, we were given an equation first (in this case y(x) = x^2 - 4 at x = 2). The next step is to "Pick an interval containing 2", which I don't really understand fully what that means or how to do it. From there, you find the average rate of change between two numbers substituting for x (like 2 and 2.1), then shrink that interval and repeat until you get a clear idea as to where the instant rate of change is approximately. In this case, having 2 and 2.1 would give 4.1, having 2 and 2.01 would give 4.01, having 2 and 2.001 would give 4.001, and so on.

The problem I'm having an issue with now that I'm doing homework on my own is with this equation: s = 2 sin(𝜋t) + 4 cos(𝜋t), where t is measured in seconds. I am then given 4 intervals, [1,2], [1,1.1], [1,1.01], and [1,1.001]. I need to find the average rate of change for these intervals, and then estimate the instantaneous velocity of the particle when t=1.

All answers are expected in cm/s, as well as being rounded to two decimal places. I believe I am particularly having issues picking intervals but the intervals are given so it's more than that obviously. So for the first interval, we have [1,2]. Plugging 2 into the equation first since it's the second value gives me 4.194, and plugging in 1 gives me 4.1035. Subtracting these gives me 0.0912. Then we need the bottom part of the rate of change formula, so 2-1, which is 1. Meaning my answer should be 0.09 cm/s when rounded, but the computer system says that I am incorrect. Where is my mistake?

jagged seal
#

You might need to be in radians?

#

You're in degrees

timber turret
#

Ah, will try that

#

That was in fact the issue, thank you for the help

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near hollow
#

Write an equation for a function that has the given graph. (Give the equation and its domain. Let x be the independent variable and y be the dependent variable.)
Line segment connecting
(−2, 6)
and
(0, −4)

supple copper
#

then use y = mx+b and plug in the slope for m and a point for x and y

#

and find b

#

are you familiar with that?

near hollow
#

yes ill do rn

#

ok i got -5 as the slope then plugged in -2, and 6 and got y=-5x+16 for the equation

supple copper
#

slope is right, but can you show your work for finding b?

near hollow
supple copper
#

your slope was -5

near hollow
#

ohhh ok so now my equation is y=-5x-4

supple copper
#

yup looks right to me

#

also I just realized the y-intercept was given in the question lol

#

(0, -4)

near hollow
#

i see now

#

and would the domain just bee -infinity < x < infinity

supple copper
#

yep

near hollow
#

ok hold on ima submit

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dull drum
#

i know this is math server but any1 heree very good at physics

dull drum
#

physics is math in the end many of the concepts learned in math apply to physics for example cal 1 and kinematics, waves and optics need cal 1, and e & m need cal 2

#

so if some1 is good @ me and ill send me question

pine root
#

just ask the physics server?

#

also

dull drum
dull drum
#

just was wondering

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compact belfry
#

Hi please help me with that

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night bramble
#

I need to solve this using the quadratic formula,

night bramble
#

I placed the 1 on the other side so it made 1/1
made the common denominator 18, then multiplied the whole thing by 18 to cancel them out
left with this

chrome cove
#

It's not correct, how did the 1 become a 0 on the right side?
Also, as common denominator 18 will work, but why not 6?

night bramble
#

i did 6 times 3

#

this is what i eventually got

night bramble
night bramble
ivory pivot
#

Hi

#

X both sides b 6

#

X squares - 12x - 2- - 6 = 6

#

X squared - 14x + 6 = 6

#

X squares - 14x

#

Factor out x so you get x(x-14) = 0

#

X is 0 or 14

#

@night bramble don’t know what u did tbh

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@night bramble Has your question been resolved?

night bramble
#

still a bit confused on what my error is'

#

i made the common denominator 18

#

then multiplied the whole thing by 18

#

to cancel

#

then i used quadratic formula

#

18*18 = 324

#

idk

#

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supple copper
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supple copper
#

did my teacher mess up lol?

#

isn't -(2)^2 + 1 = -3

distant hawk
supple copper
#

I didn't miss something right

#

is b=-4?

#

oh you're trying to find the a and b values to make it continuous btw

#

ig thats obvious

distant hawk
#

Well if you understand the concept then it should be fine to not struggle for the actual figure on your teacher’s example. 😂

supple copper
#

true lmaoo

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alright thanks!

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hardy ledge
#

How do you write $\sqrt{2}$ as an exponent of 2?

soft zealotBOT
#

Tiger Asp

thorny peak
#

2^1/2

hardy ledge
#

Thanks !

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earnest cave
final saddleBOT
earnest cave
#

I don’t get it

#

Someone help

distant hawk
soft zealotBOT
#

jimmy1234

distant hawk
#

Simply makes good use on this rule, then you can solve your problem.

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tranquil pine
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tranquil pine
#

How should i proceed solving questions like this

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@tranquil pine Has your question been resolved?

tranquil pine
#

<@&286206848099549185>

#

This is what i am able to think atm

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true basin
#

how do I write this using rational exponents?

true basin
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tranquil pine
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tranquil pine
#

Not sure how to proceed further

#

<@&286206848099549185>

icy karma
#

I found the answer but...

#

Im using guess

tranquil pine
icy karma
#

I think there is something related to factors

tranquil pine
#

<@&286206848099549185>

lucid marsh
#

!15mi

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tranquil pine
lucid marsh
tranquil pine
lucid marsh
#

onvr

#

the entire time

tranquil pine
tranquil pine
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@tranquil pine Has your question been resolved?

tranquil pine
#

Nvm

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jovial ermine
#

Hi, is there anything special about the Maclaurin series compared to the taylor series. I understand that both are used to approximate functions centered around any point. And that the distinction between the 2 is that Maclaurin is for when the function is centered around 0.

My question is why is it so special when the function is centered around 0 for it to be given a new name (i.e maclaurin series)?

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jovial ermine
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<@&286206848099549185>

lucid marsh
#

there's no good answer

jovial ermine
#

i feel its more common to use maclaurin series for cos and sin. (at least thats what i've seen from my classes) Is there any particular reason for this? <@&286206848099549185>

jovial ermine
#

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warm summit
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warm summit
#

For this I got -21 and -15

#

-15 isn't greater than 0

#

So it would be -21 since it's less than or equal to 0 right?

terse dagger
#

f(2)

#

means x =2

#

when x = 2 in that function which bit do you use

warm summit
#

Wait what

#

I did sub in 2

terse dagger
#

f(x) is different when x is smaller than or equal to 0