#help-33
1 messages · Page 245 of 1
wait but
but what do i do with the 2t
👍
wait i dont have to differentiate between t and t^2?
You mean where you have sqrt(t²)?
yes
Well the only differente cases are if t is positive or negative
What do you think sqrt(t²) is when t>0
its also above 0
Do you remeber the definition of the square root
yeah
And numbers r such that r²=t² coukd only be t or -t
But keep in mind it has to be positive
So if t is positive, then it is t
If t is negative then it is -t
Replece x by t²
To remember quickly sqrt(t²) is t but positive
altmond help channel arc
The difference is that if t is negative, the positive version of t is -t, not t
Trying to understand on a small scale what itmeans to be a teacher lol
wait what
i dont understand
so if t<0 then t>0
what
bro
No
you said sqrt of t ^2 is always positive
Altmond 💜
yes its t
$\abs{t}$
1 divided by 0 equals Infinity
$\text{if t is positive, then} \sqrt{t^2}=t \ \text{if t is negative, then} \sqrt{t^2}=-t$
Altmond 💜
if $t = 0$?
1 divided by 0 equals Infinity
yes, i just didn't know if you knoew what it means
oh what that's a diff person
oof
you need to understand that $t^2 = (-t)^2$
1 divided by 0 equals Infinity
and $\sqrt{\text{ }}$ is called the principal square root, meaning it will take the value that's non-negative
it's both the same, but their expression compared to the value you put in initially is not the same
hm okay
1 divided by 0 equals Infinity
if you replace -2 by t in the first line and 2 by t in the second line, you'll see the expression i gave you appear

🥀
?
2t + 2
-# on god did i just help someone help OP understanding square roots on a calc question 😭
but here t is -2 and $\sqrt{(-2)^2} = 2 \neq -2 = t$
Altmond 💜
wut?
why does he give us stuff to do
we hve never done shti like this before
seriously fuck him
the only thing you have to remember is that and apply it
$t \in \mathbb R^+$
you knew you had to do a case disjunction from the getgo, o you had the right intuition
1 divided by 0 equals Infinity
1 divided by 0 equals Infinity
Altmond 💜
yeah
okay but how do i actualyl come to my x valeu now
it's written there
yeap
can you show me you're nex expression now
i mean your expressions for x1 and x2
wait am i dumb
h
yes so x1 is 3t
and x2 is 3t
no
wait
and x3 is t
NO
x
x2 is T
no
i mean
x2 is 1t
okay
yes
holy yes
fuck yeah
okay
now i need the y values
so just plug this shit into the f(x)
right
mhm
no thats what i struggle with
you have to have the same bottom part for all of them
following
then you can add them together
ok wait
is this correct
hell yea
okay
then 3 t
omgg
im so fulfilled tysm
you still gotta find what kind of extrema this is
wait what did i do wrong here
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I need some help, I am unsure what to do with the information I have gathered (calc 1) question is written in red
You're asked to find a time for a given speed. Do you know how velocity and speed are related?
speed is the absolute value of velocity ,right? |v(t)|
Can you answer the question now
remember, t is for time (in seconds) so you can't substitute a number for speed into that equation
try setting v(t)=24 and solving for t
i think your diffrentiation is wrong on the first term
ryz gave you the correct equation representing this first sentence
following
oh would the 1 cancel out due to the 0?
believe i see solution, will follow
recheck differentiation on 96t
thank you fox I didn't think about the 96 like that 😅
perfect
32*
wait
yes
looks right
,calc 96 - 32 * 2.25
Result:
24
great thx
if done, can use . close with no space
.close
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any idea how to show this?
do i need to use the digamma function then?
yeah this looks promising
But you only need that part since that part is asymptotic to the gamma function, so the other terms vanish in the limit
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yo can someone help me here im tryna figure out the zeropoints
also a>0
this doesnt make sense
theres no way im wrong in this
<@&286206848099549185> sorry i dont like to ping but i need help
It’s been longer than 15 minutes, you are fine
They can't be solved algebraically
huh
why did my teacher give me this as a homework
this doenst make sense at all
there must be some way
What's the original question?
wait omg
its determine the extremepoints
not zeropoints
but still
wouldnt the derivative just be
a-e^-x
but then a = 0
because e cant go to 0
You're thinking of factoring. If it were:
0 = ae^(-x)
Then you could just eliminate the e^(-x)
Like,
0 = 1 - 1
Can I just get rid of that 1?
damn
so
ive never dealt with this before
hmm
oh
wait
so -a= -e^-x
then -ln(-a) = x?
Be careful after this step. If you do take the ln here, you get:
ln(-a) = ln(-e^(-x))
Dealing with the - beside e^(-x) is awkward.
So instead, we're gonna get the negatives off first, before applying ln to both sides
oh so then we have ln(a) = ln(e^-x)
yea but now what
wait so ln(e^-x) is -x?
@gaunt lynx Has your question been resolved?
Yeah exactly
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how do you solve the integral of a function like this?
change pfp pls
oh my golly goodness 
,rcw
Find the area of the rectangles and triangles
thats it?
The areas underneath the x axis count as negative
Yes integrals of straight lines are some of the simplest
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root2+48/2 + 4+root6/4 whole divided by 9
help
!status
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7. None of the above
might be helpful if you have a pic as well!
I can’t understand
May you latex or send an image pls
$\frac{\frac{\sqrt{2} + 48}{2} + \frac{4 + \sqrt{6}}{4}}{9}$
USS-Enterprise
This?
srry but i dont have a mobile
There's your image
What is there to simplify in this 
oh my god bro
Try getting thins to common bases
ur a undergraduate??
Lotta liars nowadays
am class 6
That means you’re under 13 brotha
how old are you, just curious?
no 14
Dayum you must be a genius doing UG at 14
so indian
nvm find the ans
omg guys
me?
im a one woman army
right so, what progress have you made?
Bro get to the point
gng no one fails till the 8th gradr
What help do you need
unlrss ur rlly stupid
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What just happened bru
ok so <@&268886789983436800> this isn't helping to move the conversation forward and it's bloody condescending
and are you still interested in the problem or?
Blud closed it
I can see it. but if OP closed merely as a knee-jerk reaction to the other user then he might actually want to continue
but how is 6th grade 14 yrs old is my question
please dont be elitist. if you cant participate without being condescending, you dont need to be trying to help anyone.
please don't be rude to other people as i already reminded you before
You are like 900 years old, what do you care 🙂
✅ Original question: #help-33 message
@orchid fox continue here
he opened a new channel
🥀
oh it was closed
I saw you trying to open a channel with the latexed message
:(
try to simplify the numerator first
again OP, what progress have you made?
@orchid fox You want to try and combine the numerator's fractions by putting them under a common denominator — can you see how to do that?
no and didnt i closed?
.close
Closed by @orchid fox
Use .reopen if this was a mistake.
I reopened it because you were porting the same question over to another channel
you've closed it already, and sure
if you say so then none of us will reopen it
have a great day
Absolutely zero idea
should i apply for the mods ngl
ong I’m so confused rn
Well that's your choice to make
should i?
If you think you'd do good, then yes
!redir?
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
I am not active enough here to opinionate
that justifies using it as a discussion channel, how exactly...?
my bad
im sorry
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Sorry, like this
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Use the second derivative test
to identify any critical points and determine whether each
critical point is a maximum, minimum, saddle point, or
none of these.
!show
Show your work, and if possible, explain where you are stuck.
im getting f_x = 2y(e^...) (1-2x^2)
now im kinda confused abt finding the critical pts here
cuz f_x will be zero for all points (x,y) where x = 1/root2
thats a lot of points
so im stuck
yes it is f_y = 2x(e^...) (1-2y^2)
You have to check at points where both f_x and f_y are zero
For the point to be critical you need both f_x and f_y to be 0.
That will narrow it down.
oh i see
alr guys so i am getting these three cnditions from setting f_x = 0:
x = 1/root2
x = -1/root2
y = 0
now how do i proceed?
Well now you set f_y = 0
Check those conditions and see in which cases you get BOTH = 0
but setting f_y=0 i get:
y= 1/root2
y = -1/root2
x = 0
im js gettin a bunch of values
what do i do now
You have to consider which pairs work.
Say for f_x to be 0
If x = 1/sqrt(2), we know f_x = 0.
We want f_y = 0 as well.
Clearly x != 0. So the only way f_y = 0 in this case is if y=1/sqrt(2) or y=-1/sqrt(2)
That gives you 2 critical points.
Then you try the other conditions for f_x = 0
I have made some candidate points to check
alr so i checked them, and i get these final critical pts:
(0,0)
(+-1/root2, +-1/root2)
5
yeah 5
now i gotta check all
fokn hell
@brave marsh now the next step to do is hessian matrix right?
Yes you need to classify them
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<@&286206848099549185>
!15m
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Hallo
!noai
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
!show
Show your work, and if possible, explain where you are stuck.
it's that
!status
What step are you on?
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@robust rampart Has your question been resolved?
alphabeta=1+1/a
Ye
nice try simplify this now
N then i js dk what to do
well its a limit and ur numerator is a polynomial
maybe try factorise it
yep
so
Nr is x-1[(1+a)x^2+ax+a)
denominator also has x-1
as a factor
so u cancel
nice
then u get
now can u apply lopital? are the conditions met?
yep now use those relations u wrote above
Idts lhspital cuz not 0/0 or infinite/inf
to put it into the form required
its 0/0 wdym
e^1-alphax -1 = 0
and numerator is also 0
yeah nice ur close
final step just get it in that form
np
.close
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I need help with the task below.
Find all values for $b > 0$ so that $\int_{0}^{b}\sin(\pi x) dx = 0.$ Comment.
Thanks in advance!
Is that sin(pi x) dx?
Yesss
Have you sketched the graph of that?
(I am not sure what i need to write so that there are space between pi*x and dx)
Just use parentheses...
Try doing it then, just a rough sketch should do (just mark the zero points)
dream
Like this?
Well the integral of a function would give us the area under the graph
Of the function
more specifically, the signed area
And if the integral is zero, then the area is zero
Well the area is zero there
because the area under x-axis is counted negatively
the mountains and valleys cancel out when x = ?
blue gets counted in +, red -
uh well can you generalise it
Ohh i meant when y = 1 and y = -1
also no its not -1/1
let k be any integer then what can x be
When b = 2x the integral would be zero?
whats x
dream
Okay, yeah, that is true
Wait
generalise the answer
i think your idea is right, but you phrased it quite poorly
You probably want x to be a natural number here
$\int_{0}^{4}f(x) dx = 0$ as well
dream
Where x is a natural number
Yesss
Yes
and i'd replace that x with n or k, that's a bit more conventional for naturals
Oh okai
Well this helped a loot
Thanks for the help
So b = 2k where k is an element of the natural elements
can't it include negatives
Ohh you are right
b > 0
ok
Thats why k is an element of the natural numbers
Oh okai
@solid crest Has your question been resolved?
this guy naturals
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Quick question, but my answer was correct, no?
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If the problem persists, please contact support.
no
how did you get your answer
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
love your pfp
thank you !!!
1
i dont remember ever learning about writing this stuff as a “product of three matrices” or whatever so i havent tried the question at all. ive tried looking online for solutions or a formula or whatever and i couldnt find anything
have you ever seen diagonalization of a matrix
uhh yesss i think so
icl the labels or names of stuff throws me off
is that the one with D = (eigenvalue 1 0 0 eigenvalue 2) ?
You try to say that A is similar to D
the same but with a 3rd i assume ?
So yes, you try to show A is similar to a diagonal matrix (A is diagonalizable)
but A is not necessarily equal to a diagonal matrix
what will A look like?
i have not a clue i dont think im understanding 😓
wait do you want to see my workings / attempts
i did TRY it but its all a whole load of hooberdash im ngl
Imagine A has eigenvalues r1 and r2
and $D = \begin{pmatrix} r_1 &0\ 0 &r_2\end{pmatrix}$
Rafilouyear2026
And say I even had the eigenvectors associated to A
how can I write A in terms of D?
Is this only uni and highschool?
im ngl i think i lack the like fundamental knowledge for this 😓😓😓 but uhm
well isnt there that other matrix you can write using eigenvectors and the corresponding eigenvalues and stuff ?
how do i write / explain what im talking about
i dont know if thats relevant st all
Yes, there is one of those matrices involved
Say P is the "basis of eigenvectors" matrix
ohh yes P !
so first column is the eigenvector of A linked to r1
yes yes yes thats whatimeant
second column is the eigenvector linked to r2
and so on if there are more dimensions
mhm
uhh i think my teacher said theres a formula thing
aaah hold on
i didnt understand WHY it was what it was, it felt more like i was just meant to memorise it
is it like A = PDP^-1 ?
it's exactly that
nooo wayyy
I can take some time to explain it if you want
Ok, so first thing you need to understand is that diagonal matrices, and more generally diagonalizable matrices, scale vectors
so take for example $A = \begin{pmatrix} 2 &0\ 0 &3\end{pmatrix}$
Rafilouyear2026
what A does for any vector (x,y)
is that it splits it into (x,0) + (0,y)
it looks at the first vector, and scales it by 2
it looks at the second vector, scales it by 3
mhm
you get (2x,0) + (0,3y) = (2x,3y) = A(x,y)
mhm right
so that's what diagonalizable matrices do, they split according to some basis (called eigenbasis), and scales each component by some factor (called eigenvalue)
Second big idea, is that this matrix P
allows you to change the referential basis
let me explain, say you have P = (v1, v2) with v1 and v2 written in column
now, how can I write the vector "three times v1 minus one time v2"
well I could for once just write it as "3v1 - v2"
but I could also say that, in the basis (v1 , v2)
it's the vector with first (v1) coordinate = 3 and second (v2) coordinate = -1
so, in the basis {v1,v2}, the vector is written as (3, -1)
so the vector in the usual basis is P(3,-1)
sorry what do you mean by the usual basis ? 😓
So what we did more generally is input some "coordinates"
apply the matrix P
and it outputs the vector with those coordinates in basis {v1,v2}
i think im following
And vice versa
since P^-1 is the inverse of P
if you INPUT a vector and apply P^-1
it outputs the coordinates it has in basis {v1,v2}
what P does : coordinates -> vector
what P^-1 does : vector -> coordinates
so, if A has eigenvectors v1, v2 with eigenvalues r1, r2
how to compute the image of any vector (x,y):
- Write the vector in coordinates in the basis v1, v2 : P^-1 (x,y)
- Scale each coordinate accordingly : DP^-1 (x,y)
- From the coordinates in basis v1, v2 extract back the image vector : PDP^-1 (x,y) = A(x,y)
sorry just give me a sec whilst i try to wrap my head around this
wait okay i lowkey just googled a few things cuz im finding everything a bit hard to understand
with P and P^-1
this might have to do with like the rules of associativity or whatever, but are they meant to cancel eachother out or does it not work because the D is between them
Multiplication is not commutative for matrices
oh the word is commutative not associative whoopsie
associativity means (AB)C = A(BC) so you can just write ABC
commutativity means AB = BA, not true in general for matrices
so you can't pretend the D is somewhere else, if it's in the middle then P and P^-1 can't cancel each other
oh i see i see
oh right LOL
aah i think im still finding it hard to understand :(
Tell me if some parts are harder than others
maybe ill go watch up on a video about eigenvalues and vectors and all the rest of it later 😓
ik its really annoying when you ask “what do you need help with” and people say “everything” but i dont think ive grasped all that much 😓😓
im really trying to
Otherwise, very good video https://www.youtube.com/watch?v=PFDu9oVAE-g
A visual understanding of eigenvectors, eigenvalues, and the usefulness of an eigenbasis.
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omgg 3b1b !!!
will watch later hopefully
so wait what does this all have to do with my original question ?
well
you have the eigenvectors (P) and the corresponding eigenvalues (D)
so A = ?
exactly like that
does it matter which i multiply with which first ?
cuz i swear i got told like
its like when you have fgh(x)
yes, you can start computing PD or DP^-1 first, it doesn't matter
matrix multiplication is associative
ah okay okay
okay okay thank you so much !
ill go back over what you wrote another time but thank you again !
.close
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can someone explain why when I take the arcsin(rad2/2) its pi/4 and not negative pi/4 ?
wait
nevermind
its cause its in the first quadrant
I was thinking of if it was arcsin(-rad2/2)
if it was arcsin(-rad2/2) then it would be -pi/4
.close
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Help brp
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"ABCDEF is a regular hexagon, and ABKL is a square. Find the measure of the angle FMD."
hi there.
What have you tried
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How does this show reflection😢
@steel current Has your question been resolved?
I think this is a bad question in general
Cuz u can achieve the transformation with just a translation
Or u can reflect it accepts the y axis and translate it up
So how is it reflection?
It can be if that’s how u do the transformation
Reflect across the y axis
Then translate
But it doesn’t have to be
Which is why the question is bad
so....
Doesn’t that answer the question?
well you do know what reflection and translation are right?
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note that 0.5<1, so what can we ay about (0.5)^n as n gets really large?
it gets smaller
close to 0
yes
ohh so its 2
perfect
try writing it in exponent form
okay so first we find the limit of inside form i believe?
okay
(3^7+3n)^1/n
sry i dont know how to use bot
where is n/2 coming from?
lol
there
3^(7/n+3
it approaches 3
yes
np
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lots of things, i 've found the answer as 60°, but it' s wrong.
@marsh citrus
this is still an occupied channel
please go to an available one
|| What is FAL? How are AFL and FLA related? Figure out EFM. Now the solution should be clear.||
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hey im trying to draw isoclines with direction markers and solution curves for dy/dx = -x/y and Im really lost. I was thinking it would be a bunch of left/right half circles since if c=0 x/c would be undefined but thats not it. Im being told its top bottom half circles but that doesnt make sense to me
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I haven't been able to figure out how to use this hint to show whether the summation is convergent or not - I also tried bounding above by 1/x^2, which should work for large enough n, but the algebra has been a complete mess so I don't think I can go that route
x^x grows faster than x! and a^x
can you use stirling's approximation?
I have never heard of that, so I don't think I can use it in a proof for this course
yeah but from the graphs, when that divisor of x^x is e or larger, the series converges to 0
have you tried ratio test / root test?
it's great to know and would make this problem really easy but we can solve it without 
root test is the way to go here
isn't it the ratio test?
I'm assuming the nth root of a factorial as n goes to infinity blows out to infinity?
stirling's approximation says $n! \sim \sqrt{2 \pi n} \left(\frac{n}{e}\right)^n$ as n goes to infinity
bloubbloub
or yes sorry
of course
wow that makes it super easy. Ok the problem was that every other homework problem on this has been too complex to use the simple tests, so I was way overthinking this one
well, note that just (n!)^(1/n) -> infinity isn't enough
importantly, your sum converges but if 3 was replaced by a 2 it would diverge
it needs to be e or larger
indeed
I will take some time to reformat and come back if needed
Ok I’m stuck now
Also forgot to start writing limit notation
oh wait
this is a limit
all these other (a/n)^1/n would just go to zero I think
or no, they should all go to 1
yeah that's it
I believe the ratio test is easier here
I mean... I've already done the root test and am typing up the proof now
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am i doing something wrong in this optimization problem? i can see that x=y=0 certainly isnt the solution but there aren't other solutions?
Please don't occupy multiple help channels.
@scarlet ingot Has your question been resolved?
You have to work out the different cases.
For one, you can’t have x=y=0 simultaneously as then the point isn’t on the constraint.
You can fix, say, x=0. Then use your constraint to find y and check that the y-derivative vanishes there.
Then check what happens when the second factor is 0. (Spoiler alert : it forces y=0 and you can work with that)
not sure why i was thinking that the cases (x=0 and y=0) or (2R^2+4+lambda=0 and 2R^2-4+lambda=0) as completely sepreate
yeah that makes sense now
thanks <3
.close
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Hello i need help doing this problem.
calculate the surface area of a regular four-sided prism if D=42 and the side diagonal d=30
what is D?
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i got eqn ar^3 = 4
and a+ar^2+ar^4 = 813/7
putting a in equation 2,
4(1+r^2+r^4) = 813r^3/7
now how do i solve this?
First see what they have asked from you
ar^2(1+r^2+r^4)
ar^2 = 4 no?
it's a 4th degree right?
aight
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so i put the cordinates into a graphing calculator
and this is what i got
this should be your triangle
so can you find BC according to the pythagorean theorem?
A2 + B2 = C2?
missing ^
yeah don't worry
damn just use polygon() bro 💔
can you see the right triangle that i made here?
🥀
the 2 legs are the distance between the x coordinates and the y coordinates
yes
the question asks for the points after dilation around the origin
so we work out the size of the original triangle first, and then scale it by 1/2
yeah
how do i work out the original size?
pythagorean theorem
so do i add the x's or the y's?
how would you calculate the lengths of these legs
Pythagorean theorem
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can someone help me with my anser as it seems incorrect
Oh is the table you have is Z>z value
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its 3b i need help on. i dont even really know where to start. would also just like to clarify, this is an assignment but we ARE allowed help on these. i just dont want to message my teachers so late 😓
OOH WAIT
wait no
im gonna drop my line of thinking and lmk if im onto something or not
ignore that im being an idiot
@short arch Has your question been resolved?
you could maybe think of it as out of 5000 people, at least 2 need to have the antigen
but idk im not sure either
yeah i changed my workings to that
im not sure i did X~B(5000, 1/4000) and then found where P(X=2) and just said p<ans but i have no clue
i have no clue either lol 😔 im terrible at probability
all good :p
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.close
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detemine the mesure of the angle in radiant
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No...
740 deg = 20 degrees = 20pi/180 radians = pi/9 radians
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for the 1st one I got not atleast x for all y not(if Ox then Ey)
"atleast" is not a thing
its a backwards e
It means "there exists"
im not sure I thought that was the goal
The goal is to have an expression where negation symbols only appear directly before predicates
the predicates would be the thigns inside the parentheses or all the variables in the equasion?
O(x) and E(y) are predicates
Technically (not O(x) or E(y)) is also a predicate but in this context they mean the most simple ones
No, you have a negation before a quantifier and one before a parenthesis
so it has to be infront of everything?
No, the expression must still be equivalent
There is only one answer (without using other operators like implications)
im confused? by using other operators what do you mean?



